KR880001877Y1 - 16-color display device - Google Patents

Abstract

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Description

16-color display

1 is a circuit diagram of the device.

2 is a bias voltage waveform diagram of an image driving transistor according to an input signal.

The present invention relates to a 16-color display device for displaying the color of the image by the digital input information.

In the conventional digital television system, there are various methods for displaying color by processing binary signals of color display, but the digital television system has a disadvantage in that the configuration is complicated, the number of components is not only high, and the accuracy and efficiency are inferior. The situation is not generalized.

The truth values of the 16 colors used in this system are as follows.

The present invention provides a simple 16-inch digital 16-color display device to eliminate these drawbacks, thereby improving the accuracy and efficiency of reproduction colors. Is as follows.

When red and green (R, G) signals are input from the above truth table, yellow color is usually reminiscent of yellow, but brown color should be displayed here. Can be.

In particular, the brown display condition is shown by connecting the resistors (R _1- R ₄ ) to the red, green, blue and OK (R, G, B, I) signal input terminals, respectively, and grounding the inverter (G _1- ). Brown driving circuit 2 consisting of inverter G ₉ -G ₁₂ and transistor TR ₄ while being connected to image driving stage 1 composed of transistors TR _1- TR ₃ through G ₈ ) ) Is connected to the base of the transistor TR ₂ of the image driving stage 1.

The effect of this configuration is that the condition 1) the no-signal (BLACK) signal input is at "0" level, so that the gate outputs (TP ₁ , TP ₂ , TP ₃ , and TP ₄ points) are set to "0" so that the resistance ( R ₉ , R ₉ ′, R ₉ '') are grounded and the resistors (R ₁₀ , R ₁₀ ′, R ₁₀ '') are nearly grounded.

Here, since the point TP _{8 is} also at " 0 " level, the transistor TR ₄ becomes non-conductive and the resistor R ₁₄ also becomes open.

Accordingly, when the bias voltage V _B0 of the image driving transistors TR ₁ , TR ₂ , and TR ₃ is W, it becomes as follows.

W = V _B0 = (R ₉ // R ₁₀ / R ₈ + R ₉ // R ₁₀ ) V

However, since the bias voltage W is not at a level sufficient to drive the transistors TR ₁ , TR ₂ , and TR ₃ , the image transistors become inoperative and eventually, each transistor TR ₁ , TR ₂ , and TR ₃ . There is no output.

Condition 2) When inputting the "R" signal without the luminance signal I (the same condition is used for the G and B inputs, here, the description key will be used only here). According to the "R" signal input, the TP ₁ point has a high level. Soon, the resistance (R ₉ ) is open, and the gate output of the gate (G ₉ ) is also "1", but the gate output level of the gate (G ₁₀ ) is "0", so TP _{The eight} points are at the "0" level, and the transistor TR ₄ is at the open states TP ₂ , TP ₃ , TP ₄ , and the points are also at the "0" level.

As a result, it can be seen that the bias X of the transistor TR ₁ is supplied by the division of the resistors R ₈ and R ₁₀ .

Bias voltage (V _BR ) of transistor TR ₁ 〓 (R ₁₀ / R ₈ + R ₁₀ ) V 〓 X

Therefore, only the R-stage transistor can be driven to reproduce red color.

Condition 3) Cyan color when the G and B signals are input without the luminance signal (I). (In this case, the same conditions are used for the R and B input. Only the G and B signals are considered.) TP ₂ , TP ₃ is at high level, resistance (R ₉ ′, R ₉ '') is open and TP ₈ is at “O” level so transistor (TR ₄ ) is not conducting and resistor (R ₁₄ ) is Open state.

After all of the bias transistor _{(TR 2, TR 3) (} X) is supplied is divided into a resistance (R ₈ ', and _{R 10', R 10 ''} ).

V _BG 〓 (R ₁₀ '/ R ₈ ' + R ₁₀ ') V

V _BB 〓 (R ₁₀ `` / R ₈ '' + R ₁₀ '') V

It becomes

Where V _BG is the bias of transistor TR ₂ and V _BB is the bias of transistor TR ₃ .

Therefore, the transistors TR ₂ and TR ₃ are driven to display the CYAN color.

Condition 4) When the luminance signal (I signal) is input (gray) In accordance with the input of the I signal, the point TP ₄ becomes high level and the resistors (R ₁₀ , R ₁₀ ′, R ₁₀ '') become open.

Since the points TP ₁ -TP ₃ and TP _{8 are} at the zero level, the bias X 'is supplied to the image driving transistors TR ₁ -TR ₃ by dividing the resistors R ₈ , R ₉ . Here, the division of degradations (R ₈ ′, R ₉ ′ and R ₈ ″, R ₉ '') is the same.

As a result, the transistors TR ₁ to TR ₃ are driven to obtain a gray color.

Condition 5) When R, I signal input (G, I input / B, I input is the same condition) R, I input is TP ₁ and TP ₄ point high level and resistor (R ₉ ) is open state resistance ( R ₁₀ ) is also open, so that the bias of the image driving transistor TR ₁ is deepened to the Z level (B ⁺ level), so that a brighter red color can be reproduced than in the case of the classical 1.

Condition 6) When R, G, B, and I signals are input, in this state, the TP ₁ , TP ₂ , TP ₃ , and TP ₄ points are at high level, and the TP ₈ points are at 0 level, resulting in the image driving transistors TR ₁ , TR ₂ , The bias of TP ₃ ) is deepened to the Z level, which is much brighter than under condition 4), so that white color can be reproduced.

Condition 7) When R, G input (Brown Brown) According to R, G input, TP ₁ , TP ₂ and TP ₈ points to high level, and the resistors (R ₉ and R ₉ ') are open and transistor (TR ₄ ) Is turned on until the collector point of transistor TR ₄ is grounded.

As a result, it can be seen that the biases of the transistors TR ₁ and TR ₂ are supplied differently.

The bias of the transistor _{(TR 1) V BR1 〓 (} R 10 / R 8 + R 10) · V 〓 X is supplied, and the transistor (TR ₂₎ Bias _{(V BG2) 〓 (R '} 10 // R 14 / R of ' ₈ + R ₁₀ // R ₁₄ ) · V 〓 Y is supplied.

In other words, the G driving bias TR ₂ is supplied with a lower level of the bias Y than the R driving bias TR ₁ and may display a brown color.

In this case, it can be seen that the conditions under which the transistor TR ₄ can be driven are that only R, G, B, and I, where the TP ₈ point becomes high, are driven only at the high level, that is, R and G inputs.

A bias potential between the - (TR ₄ TR ₁₎ the input transistor and the transistor described in the above-expressed in base potential of (TR ₁ TR ₄₎ shown in the table below.

Here, W, X, Y, and Z denote bias voltage levels for each state for convenience, and have an relationship of O <W <X <X'Y <Z = B ⁺ .

As described above, according to the present invention, 16 colors can be displayed as a simple configuration, and thus, 16 colors can be displayed easily and accurately.

Claims (1)

Red, green, blue, and luminance (R, G, B, I) signal input terminals are inverters (G ₁ , G ₂ ), (G ₃ , G ₄ ) (G ₅ , G ₆ ) (G ₇ , G ₈ ) To the base of the transistors (TR ₁ -TR ₃ ) to configure the image driving stage (1) and to connect the outputs of the inverters (G ₁ , G ₃ ) to the inverters (G ₉ , G ₀ ) respectively. , Blue and luminance (B, I) signal input terminals are connected to the inverters G ₁₁ and G ₁₂ , respectively, and the outputs of the inverters G ₉ and G ₁₂ are respectively connected through the reverse connection diodes D ₄ to D ₇ . the emitter with the connected to the base of the grounding transistor (TR ₄₎ brown driving circuit including (2), the transistors of a brown drive circuit (2) transistor video driver stage to the collector of the (TR ₄₎ (1) of the (TR ₂ ) 16 color display connected to the base.