JP2016169782A - Shear damper - Google Patents

Abstract

PROBLEM TO BE SOLVED: To provide an easy manufactured shear damper showing a high deformation capability and superior durability when a shearing force of external force is received.SOLUTION: A shear damper 1 is a plate-like member with a uniform thickness and has both side fixing parts 2 fixed to each of the two members 10 moved relatively by an external force at a building, both side damaged parts 3 damaged by bending by an external force subsequent to the fixing parts 2, and a connecting part 4 positioned between both side damaged parts 3. A direction of the thickness of the shear damper 1 and a direction in which a shearing force is applied are coincided to each other. An area S of the section is determined by a following formula, S=(6Q/(σ*t))*y, where [t] is a plate thickness, [b] is a width of section spaced apart by a distance [y] from the center of a direction Y between the members at the damaged parts 3, σis a yield strength of material and [Q] is a shear force determined for every building. An area of section perpendicular to a direction Y between the fixing parts 2 and the connecting part 4 is larger than the area S of section determined by the formula described above.SELECTED DRAWING: Figure 3

Description

  The present invention relates to a plate-like shear damper for energy absorption used between two members that move relative to each other by an external force such as an earthquake in a house or various other buildings.

  Conventionally, plate-like shear dampers that are damaged by bending with respect to shearing force are damaged by providing a notch in a part away from the joint so as not to cause damage to the joint at both ends due to welding, which can be a weak point. The place to do is limited to other than the joint. The magnitude of the moment acting on the shear damper due to the external force is determined by the distance from the center corresponding to the gradient of the antisymmetric bending moment in which the positive and negative of the moment are reversed across the center between the joints at both ends. In the case of the shear damper provided with the notch, damage is caused at a location where the cross-sectional performance is lower than the moment by the external force.

  In addition, there is an example in which damage is generated in a wide range by providing a notch in a part of the shear damper, but the position and size of the notch are only determined empirically.

JP 2006-207292 A JP-A 64-36840

  In the case of a type of shear damper that is damaged by conventional bending, damage can be generated at the position determined by the moment gradient and section modulus, but the damage is concentrated on the cross section at the determined position. Cracks due to bending. For this reason, the deformation capability is small, and the durability against repeated force is poor. Further, since the shape of the notch is not determined so as to have a section modulus that matches the moment gradient, it cannot be damaged most efficiently.

  An object of the present invention is to provide a shear damper that has a large deformation capacity, excellent durability, and is easy to manufacture by damaging a portion having a certain area with the same load when subjected to a shearing force due to an external force such as an earthquake. Is to provide.

The shear damper according to the present invention is a plate-like shear damper having a uniform energy absorbing thickness used between two members that move relative to each other by an external force in a building, and is a member that connects the two members. Fixed portions on both sides that are positioned at both ends in the inter-direction and fixed to the two members, and damaged portions on both sides that are positioned adjacent to the fixed portions between the fixed portions on both sides and are damaged by bending due to external force And a connecting part located between the damaged parts on both sides, and arranged so that the direction in which the shearing force is applied by the relative movement of the two members by the external force in the building coincides with the direction of the thickness Is done. The damaged portion has a rectangular cross-sectional shape perpendicular to the inter-member direction, a plate thickness t, and a width in a direction perpendicular to the thickness direction in a cross-section separated from the center of the inter-member direction by a distance y. Where b is the yield strength of the material and σ _y is the shearing force determined for each building, the area S of the cross section at a distance y from the center in the inter-member direction at the damaged portion is expressed by the following equation S = (6Q / (σ _y · t)) · y
Determined by
And the area of the cross section perpendicular | vertical to the direction between the said members of the said fixing | fixed part and the said connection part is larger than the area S of the said cross section determined by the said Formula.

The equation S = (6Q / (σ _y · t)) · y is the bending moment that is the yield strength of the cross section at a distance y from the center in the inter-member direction when a shear force in the thickness direction is applied to the shear damper. This is derived from the relationship with the bending moment generated at the position of the distance y from the center in the inter-member direction when the shear damper receives a shearing force. Thus, by defining the area S of the cross section that is separated from the center in the inter-member direction in the damaged portion by the distance y, the cross section of the cross section that is at the distance y from the center in the inter-member direction in the entire region in the inter-member direction of the damaged portion. The bending moment that becomes the proof stress coincides with the bending moment generated at the position of the distance y from the center in the inter-member direction when the shear damper receives the shearing force.
Since the plate thickness t is constant, if (6Q / (σ _y · t)) is replaced with α (constant), the equation S = α · y is obtained. That is, the area S of the cross section that is separated from the center in the inter-member direction in the damaged portion by the distance y is proportional to the distance y. In addition, the value of the shearing force Q may be in a range that is established in the design of the building, and may be arbitrarily set as a constant depending on the design of the building.

Since the area of the cross section perpendicular to the member-to-member direction of the fixed portion and the connecting portion is larger than the area S of the cross section determined by the equation S = (6Q / (σ _y · t)) · y, the shear damper is When relative movement occurs between the two members provided, the damaged portion is deformed to absorb energy. Since the area of the cross section of the damaged portion is a shape that satisfies the relationship of the formula S = (6Q / (σ _y · t)) · y, the damaged portion is damaged to the same extent in the entire region. That is, a part of the damaged part is not locally damaged but the whole part is damaged little by little. Therefore, the deformation ability is large and the durability is excellent.
Since the shear damper of the present invention is a plate having a uniform thickness, it can be easily manufactured by cutting a plate material by laser processing or the like.

  In this invention, the connecting portion may have a constant width in a direction perpendicular to the thickness direction in a cross section perpendicular to the inter-member direction over the entire length in the inter-member direction. In this case, the shapes of both side edges orthogonal to the inter-member direction and the thickness direction of the connecting portion are parallel, and processing is easy.

In this invention, when the allowable shear stress of the material is τ, the area of the cross section perpendicular to the inter-member direction of the connecting portion is expressed by the following equation: τ ≧ Q / (b · t)
Satisfy the conditions given in.
If it is only the yield strength against the anti-symmetric bending moment, it is only necessary to make it larger than the area of the cross section determined by the equation S = (6Q / (σ _y · t)) · y, but the shear damper between the two members In order to transmit the shearing force through, the area of the cross section of the connecting portion is determined as described above.

The shear damper of the present invention is a plate-like shear damper for energy absorption used between two members that move relative to each other due to external force in the building, and absorbs energy used between the two members that move relative to each other due to external force in the building. A plate-like shear damper having a uniform thickness for use, which is located at both ends in the inter-member direction, which is a direction connecting the two members, and fixed portions on both sides respectively fixed to the two members; The external force in the building is provided between the fixed parts on both sides, the damaged parts on both sides located adjacent to the fixed parts and damaged by bending due to external force, and the connecting parts located between the damaged parts on both sides. The direction in which the shearing force is applied by the relative movement of the two members by and the direction of the thickness coincide with each other, and the damaged portion is perpendicular to the direction between the members. In the form of rectangular cross section, the thickness of t, a width perpendicular to the direction of the thickness at spaced apart sectional distance y from the center of the member between the direction b, and the yield strength of the material sigma _y, buildings When the shearing force determined for each is Q, the area S of the cross section at a distance y from the center in the inter-member direction in the damaged portion is expressed by the following equation: S = (6Q / (σ _y · t)) · y
And the area of the cross section perpendicular to the inter-member direction of the fixed part and the connecting part is larger than the area S of the cross section determined by the above formula, and therefore, it receives a shearing force due to an external force such as an earthquake. In this case, by damaging a part having a certain area with the same load, the deformation capacity is large, the durability is excellent, and the manufacture is easy.

It is explanatory drawing of the fundamental view of this invention. It is a figure which shows an antisymmetric bending moment. (A) is the figure which added the figure of the cross section which exists in the distance of ± y to the direction between members from the center of the direction between members to the front view of the shear damper which concerns on 1st Embodiment of this invention, (B) is the side surface FIG. It is a graph which shows the yield strength test result of the shear damper of this invention. (A) is the figure which added the figure of the cross section which exists in the distance of ± y to the direction between members from the center of the direction between members to the front view of the shear damper which concerns on 2nd Embodiment of this invention, (B) is the side surface FIG. (A) is the figure which added the figure of the cross section which exists in the distance of +/- y from the center of the direction between members to the front view of the shear damper which concerns on 3rd Embodiment of this invention, and (B) is the side surface FIG. (A) is the figure which added the figure of the cross section which exists in the distance of ± y to the inter-member direction from the center of the inter-member direction to the front view of the shear damper which concerns on 4th Embodiment of this invention, (B) is the side surface FIG. (A) is the figure which added the figure of the cross section which exists in the distance of ± y to the direction between members from the center of the direction between members to the front view of the shear damper which concerns on 5th Embodiment of this invention, (B) is the side surface FIG. (A) is the front view of a composite shear damper, (B) is the side view. (A) is the front view of a different composite shear damper, (B) is the side view. (A) is the front view of the composite shear damper which bent the composite shear damper of FIG. 10, (B) is the side view, (C) is the top view. (A) is the front view of the composite shear damper which bent the composite shear damper of FIG. 10 different from FIG. 11, (B) is the side view, (C) is the top view. (A), (B), (C) is a schematic block diagram of a bearing wall using a shear damper.

  An embodiment of the present invention will be described with reference to the drawings. The shear damper of the present invention is used between two members that move relative to each other due to an external force such as an earthquake in a house such as a detached house or an apartment house or other various buildings. For example, in each bearing wall shown in FIGS. 13A, 13 </ b> B, and 13 </ b> C, the shear damper 1 is used at the joint between the panel frame 21 and the diagonal member 25. In the case of FIG. 13A, the vertical frame member 22 and the diagonal member 25 of the panel frame 21 are two members that move relatively. In the case of FIG. 13B and FIG. 13C, the horizontal frame of the panel frame 21 The material 23 and the diagonal material 25 are two members that move relative to each other. The “inter-member direction” to be described later is a direction connecting the members to which the shear dampers 1 of the two members are joined, and is indicated by an arrow Y in FIGS. 13 (A), (B), and (C).

Prior to the description of the embodiments, the basic concept of the present invention will be described. 1A to 1D show a state in which a plate-like shear damper 1 is provided between two members 10 and 10 that are relatively moved by an external force. The upper row is a side view and the lower row is a front view.
When a shearing force in the thickness direction acts on a shear damper 1 having a constant width as shown in FIG. 1 (A), as shown in FIG. 1 (B), the fixed portion 11 fixed to the two members 10 that move relative to each other. Will be damaged and damaged. Since the fixing portion 11 that is a welded portion is weaker than other portions due to the influence of heat input, the fixing portion 11 is damaged. If the fixing part 11 is damaged, the shearing force that the shear damper 1 can withstand cannot be predicted.

  Therefore, as shown in FIG. 1C, by providing a notch 12 in a part of the shear damper 1, the damaged portion is limited to other than the fixed portion 11. However, simply providing the notch 12 causes damage to the boundary portion 13 between the notch 12 and other portions, resulting in a shear damper having a small deformation capability and poor durability. The damage is concentrated on the boundary portion 13 for the following reason. The shear damper 1 is subjected to an antisymmetric bending moment M (see FIG. 2) in which the positive and negative moments are reversed at the center by an external force. Damage occurs at a location where the section modulus is less than the reverse symmetrical bending moment M. For this reason, damage concentrates on the boundary portion 13 farthest from the center in the longitudinal direction, where the largest bending moment acts within the range of the notch 12.

  The gist of the present invention is that, as shown in FIG. 1 (D), by devising the shape of the shear damper 1 so that the antisymmetric bending moment M and the section modulus coincide with each other, damage is generated to the same extent in a predetermined range 14. Let Thereby, the deformation capacity of the shear damper 1 is increased and the durability is improved.

FIG. 3 shows a first embodiment of a shear damper based on the above concept. 3A is a front view of the shear damper 1 with a cross-sectional view at a distance of ± y from the center in the inter-member direction to the inter-member direction, and FIG. 3B is a side view thereof. The example of FIG. 3 shows the shear damper 1 used in the III part of FIG. 13 (B). A plurality of shear dampers 1 shown in FIG. 3 are provided in parallel so that the plate surfaces face each other. In FIG. 13B, the plurality of shear dampers 1 are arranged in the left-right direction on the paper surface.
The shear damper 1 is a plate having a uniform thickness, and is fixed to two members 10, 10 that are fixed to two members 10, 10 that are located at both ends in the longitudinal direction and move relative to each other by external force, It is comprised by the damage part 3 and 3 of the both sides which are located adjacent to the inside of the fixing parts 2 and 2 of both sides, respectively, and is damaged by bending, and the connection part 4 located between these damage parts 3 and 3 of both sides . The shear damper 1 is arranged so that the direction in which the shearing force is applied by the relative movement of the two members 10 and 10 due to the external force in the building coincides with the thickness direction, and the fixing portions 2 and 2 are welded to the respective members 10. , 10 respectively.

  In the case of the example of FIG. 3, the member 10 on one side (upper side in the figure) is a beam 23, and the member 10 on the other side (lower side in the figure) is a joining member 26 to which a pair of diagonal members 25 are joined. The longitudinal direction is a direction connecting the two members 10 and 10 and is hereinafter referred to as “inter-member direction Y”. A direction along the plate surface and orthogonal to the inter-member direction Y is referred to as a “width direction X”.

  As shown in FIG. 3A, the shear damper 1 of this embodiment is a front shape, that is, a direction perpendicular to the plate surface, when the inter-member direction Y is expressed in the up-down direction and the width direction X in the left-right direction. The shape seen from the out-of-plane direction is a shape obtained by cutting one of the left and right sides (for example, the right side) at the center in the inter-member direction Y into a predetermined shape symmetrical to the inter-member direction Y from a rectangular plate material. In other words, the left and right edges (for example, the left side) of the fixed portions 2 and 2, the damaged portions 3 and 3, and the connecting portion 4 are on the same straight line. The left and right end edges (for example, the right side) are composed of a plurality of straight lines that intersect each other. Accordingly, the shear damper 1 has an asymmetric shape in the width direction X and a symmetric shape in the inter-member direction Y. The width of the shear damper 1 (dimension in the width direction X) is the largest in the fixed portions 2 and 2, and becomes narrower as it goes to the damaged portion 3, and the narrowest in the connecting portion 4. The widths of the fixing portions 2 and 2 may be the same as the width of the rectangular plate material before processing. Since the shear damper 1 is a plate having a uniform thickness, it can be easily manufactured by cutting a plate material into the above shape by laser processing or the like.

This shear damper 1 is used for a portion that receives a shearing force in an out-of-plane direction, and the width b of the damaged portion 3 in a cross section separated from the center in the inter-member direction Y by a distance y is
b = α · y (Formula 1)
α: It is determined to be a constant. The reason will be described below.

The damaged portion 3 has a rectangular cross-sectional shape perpendicular to the inter-member direction Y. When the plate thickness t, the width center from the distance y apart lesion third member between the direction Y is b, the section modulus Z, and become bending moment M _y is strength of its cross-section, respectively formula 2, wherein It is represented by 3.
^{Z = b · t 2/6} ( Equation 2)
_{M y = Z · σ y =} σ y · b · t 2/6 = A · b · t 2 ( Equation 3)
However, σ _y is the yield strength, and A (= σ _y / 6) is a constant.

Further, when the length of the shear damper 1 in the inter-member direction Y is h and a shear force Q is applied in a state where both ends of the shear damper 1 are fixed, the shear damper 1 is generated at a distance y from the center of the inter-member direction Y. The antisymmetric bending moment M is
M = Q · (h / 2) · (y / (h / 2)) = Q · y (Formula 4)
And expressed by a linear function with the distance y from the center in the inter-member direction Y as a variable. The shearing force Q used here is a design shearing force determined for each building.

  The shear force Q is calculated from the external force applied to the building. The value of the shearing force Q may be in a range that is established in the design of the building, and may be arbitrarily set as a constant depending on the design of the building. Specifically, the external force is determined in consideration of design conditions such as the size and specifications of the building, the construction site, and the like on the scale of the assumed earthquake, and as a result, the external force for each floor of the building is calculated. The load-bearing wall position is examined with respect to the calculated external force of each floor, and the shear force to be borne by each load-bearing wall is determined according to the arrangement. If the shear force to be borne by one bearing wall is determined and the position and orientation of the shear damper 1 disposed inside the bearing wall is determined, the design shear force of the damper portion of the bearing wall is determined, The number of shear dampers 1 to be arranged is determined. Thus, the design shear force required for each shear damper 1 is determined.

When become bending moment M _y and strength of the cross-section and antisymmetric bending moment M are equal, from Equations 3 and 4,
y = (A / Q) · b · t ² (Formula 5)
However, (A / Q) is a constant.

Since the plate thickness t is a constant, the above formula 1 is derived from the above formula 5 by collectively setting the constants to α = 1 / ((A / Q) · t ² ). Assuming the coordinate axis of the XY plane with the origin O as the center, the straight line that determines the left and right (for example, the right) edge of the damaged portion 3 is represented by x = ± α · y, and the other side (for example, the left) The straight line that determines the edge of is represented by x = 0.

Further, from the relationship of the equation (5) and A = σ _y / 6, the area S (= b · t) of the cross section separated from the center in the inter-member direction Y in the damaged portion 3 by the distance y is
S = (6Q / (σ _y · t)) · y (Formula 6)
It becomes. Therefore, by determining the area S of the cross section that is separated from the center in the inter-member direction Y in the damaged portion 3 by the distance calculated from Equation 6, the cross section in the entire region in the inter-member direction Y of the damaged portion 3 bending and moment M _y the strength of the anti-symmetric bending moment M matches.

  The area of the cross section perpendicular to the inter-member direction Y of the fixed portion 2 and the connecting portion 4 is larger than the area S of the cross section determined by the above equation 6. In the case of this embodiment, the widths of the fixed portion 2 and the connecting portion 4 are made wider than the width b determined by Equation 1. Thereby, when the shear force by external force acts on the shear damper 1, it is limited so that the fixing | fixed part 2 and the connection part 4 are not damaged, and the damaged part 3 is damaged.

In this embodiment, the width of the connecting portion 4 is the same dimension over the entire region in the inter-member direction Y, and the width b of the connecting portion 4 is a size that satisfies the condition given by Equation 7 below. ing.
τ ≧ Q / (b · t) (Formula 7)
However, τ: Allowable shear stress of the material If the proof stress against the antisymmetric bending moment M is sufficient, it is only necessary to make it larger than the area of the cross section determined by Equation 6, but the shear damper between the two members 10 and 10 In order to transmit the shearing force through 1, the area of the cross section of the connecting portion 4 is determined as described above. When the width of the connecting portion 4 is the same across the entire region in the inter-member direction Y, the shape of both side edges of the connecting portion 4 becomes parallel and easy to process. Note that the width of the connecting portion 4 may not be the same dimension over the entire region in the inter-member direction Y.

  In addition, at the boundary between the connecting portion 4 and the damaged portion 3 or the boundary between the damaged portion 3 and the fixed portion 2, the line forming the edge in the width direction X may be a gentle curve so that the cross section is continuous. In this case, the occurrence of stress concentration at the boundary can be suppressed.

  According to the configuration of the shear damper 1, when relative movement occurs between the two members 10 provided with the shear damper 1 due to an external force, the damaged portion 3 is deformed to absorb energy. Since the area S of the cross section of the damaged portion 3 has a shape that satisfies the relationship of Expression 6, the damaged portion 3 is damaged to the same extent in the entire region. That is, a part of the damaged portion 3 is not locally damaged, but the whole is damaged little by little. Therefore, the deformability is large and the durability is excellent.

  The shear force Q determined for each building is calculated from the external force applied to the building, and this external force is determined in consideration of the assumed earthquake scale and the building design conditions. It is possible to provide a shear damper 1 that meets various conditions such as the above.

  In order to confirm the above effects, a proof stress test was performed. FIG. 4 is a graph showing the proof stress test results of the shear damper of the present invention. From this test result, it can be seen that the shear damper of the present invention can withstand a load of many times.

FIG. 5 shows a second embodiment of the present invention. 5A is a front view of the shear damper 1 with a cross-sectional view at a distance of ± y from the center in the inter-member direction to the inter-member direction, and FIG. 5B is a side view thereof. The shear damper 1 of the first embodiment has an asymmetric shape in the width direction X and a symmetric shape (line symmetry) in the inter-member direction Y, but has a cross section separated from the center in the inter-member direction Y in the damaged portion 3 by a distance y. As long as the area S satisfies Expression 6, the shear damper 1 may be asymmetric in the width direction X and asymmetric in the inter-member direction Y, as in the shear damper 1 of the second embodiment. The shear damper 1 has a rotationally symmetric shape with the origin O as the center. Assuming the coordinate axis of the XY plane centered on the origin O, a straight line that determines the left and right edges of the damaged portion 3 on the upper side of the page (for example, the right side of the page), and the other left and right sides of the lower damaged portion 3 ( For example, the straight line that determines the edge of the left side is represented by x = α · y, and the straight line that determines the other left and right (for example, the left side) edge of the upper damaged portion 3 and the left and right sides of the lower damaged portion 3 A straight line that determines one edge (for example, the right side) is represented by x = 0.
Also in the following embodiments including this embodiment, the area of the cross section perpendicular to the member direction of the fixed portion 2 and the connecting portion 4 is made larger than the area S of the cross section determined by the equation 6 as described above. It is.

  FIG. 6 shows a third embodiment of the present invention. 6A is a front view of the shear damper 1 with a cross-sectional view at a distance of ± y from the center in the inter-member direction to the inter-member direction, and FIG. 6B is a side view thereof. If the area S of the cross section at a distance y from the center of the inter-member direction Y in the damaged portion 3 satisfies the equation 6, it is symmetric in the width direction X and symmetric in the inter-member direction Y as in the shear damper 1. The shape may also be Assuming the coordinate axis of the XY plane with the origin O as the center, the two straight lines that determine both the left and right edges of the damaged portion 3 are represented by x = ± (1/2) · α · y. The

  FIG. 7 shows a fourth embodiment of the present invention. 7A is a front view of the shear damper 1 with a cross-sectional view at a distance of ± y from the center in the inter-member direction to the inter-member direction, and FIG. 7B is a side view thereof. If the area S of the cross section at a distance y from the center in the inter-member direction Y at the damaged portion 3 satisfies Expression 6, the asymmetrical in the width direction X and the inter-member direction Y as in the shear damper 1 It may be asymmetric and non-rotationally symmetric about the origin O. Assuming the coordinate axis of the XY plane with the origin O as the center, the straight line that determines the left and right edges (for example, the right side) of the damaged portion 3 on the upper side of the paper is represented by x = α · y, and the upper side damage A straight line that determines the left and right edges (for example, the left side) of the portion 3 is represented by x = 0. In addition, a straight line that determines one of the left and right (eg, right) edges of the lower damaged portion 3 is represented by x = −β · y, and determines one of the left and right (eg, right) edges of the damaged portion 3. The straight line is represented by x = γ · y. In this example, the coefficients β and γ are both (½) α, but if the width b of the cross section at a distance y from the center in the inter-member direction Y in the damaged portion 3 satisfies the expression (1). , Β and γ may be different from each other.

  FIG. 8 shows a fifth embodiment of the present invention. 8A is a front view of the shear damper 1 with a cross-sectional view at a distance of ± y from the center in the inter-member direction to the inter-member direction, and FIG. 8B is a side view thereof. The shear damper 1 includes a plurality of (for example, two) portions 2L, 2R, 3L, and 3R in which the fixed portion 2 and the damaged portion 3 are separated from each other in the width direction X. There is one connecting portion 4, and left and right portions 3 </ b> L and 3 </ b> R on the paper surface of the damaged portion 3 are connected to the one connecting portion 4. In this example, the cross-sectional area (S / 2) is symmetrical in the width direction X and symmetrical in the inter-member direction Y, and is equidistant from the center in the inter-member direction Y in each of the portions 3L and 3R of the damaged portion 3. ) Are equal to each other. However, if the sum of the cross-sectional areas separated from each other by the distance y from the center in the inter-member direction Y at each of the parts 3L and 3R of the damaged portion 3 satisfies Expression 6, the cross-sectional areas of the parts 3L and 3R are mutually May be different.

  The shear damper 1 of each of the above embodiments may have a combined shape. FIG. 9 shows a composite shear damper 1A in which two shear dampers 1 of FIG. 3 are used and the shear dampers 1 are combined in a symmetrical arrangement so that an opening 12 is formed at the center. As for the two shear dampers 1, the fixed portions 2 are coupled to each other. When the composite shear damper 1A is formed by connecting the two shear dampers 1 in this way, the two shear dampers 1 can be manufactured at the same time by simply drilling the central opening 12 from a rectangular plate material. Production efficiency is good.

FIG. 10 shows a composite shear damper 1B in which the fixed portions 2 of the respective shear dampers 1 in the composite shear damper 1A of FIG. This composite shear damper 1B can be formed into a shape in which two shear dampers 1 are arranged in parallel as shown in FIGS. 11 and 12 by bending the connecting portion 13.
The composite shear damper 1C of FIG. 11 is bent 180 ° at the connecting portion 13 so as to be U-shaped as a whole in plan view, and the two shear dampers 1 are arranged in parallel in a posture facing the same direction. . The composite shear damper 1D in FIG. 12 is bent at the connecting portion 13 so as to have a Z-shape as a whole in plan view, and the two shear dampers 1 are arranged in parallel in opposite postures. As described above, when the two shear dampers 1 are in opposite postures, it is possible to prevent the entire composite shear damper 1C from being twisted.

DESCRIPTION OF SYMBOLS 1 ... Shear damper 2 ... Fixed part 3 ... Damaged part 4 ... Connection part 10 ... Member which moves relatively by external force

Claims (3)

A plate-like shear damper with a uniform thickness for energy absorption used between two members that move relative to each other due to external force in the building,
Positioned at both ends in the inter-member direction, which is the direction connecting the two members, and fixed portions on both sides fixed to the two members, respectively, and adjacent to the fixed portions between the fixed portions on both sides A damaged portion on both sides damaged by bending due to external force, and a connecting portion located between the damaged portions on both sides,
The direction in which the shearing force is applied by the relative movement of the two members due to the external force in the building and the direction of the thickness are aligned with each other,
The damaged portion has a rectangular cross-sectional shape perpendicular to the inter-member direction, a plate thickness t, and a width in a direction perpendicular to the thickness direction in a cross-section separated from the center of the inter-member direction by a distance y. Where b is the yield strength of the material and σ _y is the shearing force determined for each building, the area S of the cross section at a distance y from the center in the inter-member direction at the damaged portion is expressed by the following equation S = (6Q / (σ _y · t)) · y
Determined by
And the area of the cross section perpendicular | vertical to the direction between the said members of the said fixing | fixed part and the said connection part is larger than the area S of the said cross section determined by the said Formula, The shear damper characterized by the above-mentioned.   2. The shear damper according to claim 1, wherein the connecting portion has a constant width in a direction orthogonal to the thickness direction in a cross section perpendicular to the inter-member direction over the entire length in the inter-member direction. damper. 3. The shear damper according to claim 1, wherein when the allowable shear stress of the material is τ, an area of a cross section perpendicular to the inter-member direction of the connecting portion is expressed by the following equation: τ ≧ Q / (b・ T)
Shear damper that satisfies the conditions given in.

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