CN110212763A - One kind four is in parallel capacitance series formula Boost and its current equalizing method - Google Patents

One kind four is in parallel capacitance series formula Boost and its current equalizing method Download PDF

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CN110212763A
CN110212763A CN201910377796.5A CN201910377796A CN110212763A CN 110212763 A CN110212763 A CN 110212763A CN 201910377796 A CN201910377796 A CN 201910377796A CN 110212763 A CN110212763 A CN 110212763A
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phase
switching tube
duty ratio
shift angle
negative terminal
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CN110212763B (en
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陈章勇
赵玲玲
吴云峰
卢正东
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University of Electronic Science and Technology of China
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University of Electronic Science and Technology of China
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    • H02J3/382
    • HELECTRICITY
    • H02GENERATION; CONVERSION OR DISTRIBUTION OF ELECTRIC POWER
    • H02MAPPARATUS FOR CONVERSION BETWEEN AC AND AC, BETWEEN AC AND DC, OR BETWEEN DC AND DC, AND FOR USE WITH MAINS OR SIMILAR POWER SUPPLY SYSTEMS; CONVERSION OF DC OR AC INPUT POWER INTO SURGE OUTPUT POWER; CONTROL OR REGULATION THEREOF
    • H02M3/00Conversion of dc power input into dc power output
    • H02M3/02Conversion of dc power input into dc power output without intermediate conversion into ac
    • H02M3/04Conversion of dc power input into dc power output without intermediate conversion into ac by static converters
    • H02M3/10Conversion of dc power input into dc power output without intermediate conversion into ac by static converters using discharge tubes with control electrode or semiconductor devices with control electrode
    • H02M3/145Conversion of dc power input into dc power output without intermediate conversion into ac by static converters using discharge tubes with control electrode or semiconductor devices with control electrode using devices of a triode or transistor type requiring continuous application of a control signal
    • H02M3/155Conversion of dc power input into dc power output without intermediate conversion into ac by static converters using discharge tubes with control electrode or semiconductor devices with control electrode using devices of a triode or transistor type requiring continuous application of a control signal using semiconductor devices only
    • H02M3/156Conversion of dc power input into dc power output without intermediate conversion into ac by static converters using discharge tubes with control electrode or semiconductor devices with control electrode using devices of a triode or transistor type requiring continuous application of a control signal using semiconductor devices only with automatic control of output voltage or current, e.g. switching regulators
    • H02M3/158Conversion of dc power input into dc power output without intermediate conversion into ac by static converters using discharge tubes with control electrode or semiconductor devices with control electrode using devices of a triode or transistor type requiring continuous application of a control signal using semiconductor devices only with automatic control of output voltage or current, e.g. switching regulators including plural semiconductor devices as final control devices for a single load
    • H02M3/1584Conversion of dc power input into dc power output without intermediate conversion into ac by static converters using discharge tubes with control electrode or semiconductor devices with control electrode using devices of a triode or transistor type requiring continuous application of a control signal using semiconductor devices only with automatic control of output voltage or current, e.g. switching regulators including plural semiconductor devices as final control devices for a single load with a plurality of power processing stages connected in parallel
    • HELECTRICITY
    • H02GENERATION; CONVERSION OR DISTRIBUTION OF ELECTRIC POWER
    • H02MAPPARATUS FOR CONVERSION BETWEEN AC AND AC, BETWEEN AC AND DC, OR BETWEEN DC AND DC, AND FOR USE WITH MAINS OR SIMILAR POWER SUPPLY SYSTEMS; CONVERSION OF DC OR AC INPUT POWER INTO SURGE OUTPUT POWER; CONTROL OR REGULATION THEREOF
    • H02M3/00Conversion of dc power input into dc power output
    • H02M3/02Conversion of dc power input into dc power output without intermediate conversion into ac
    • H02M3/04Conversion of dc power input into dc power output without intermediate conversion into ac by static converters
    • H02M3/10Conversion of dc power input into dc power output without intermediate conversion into ac by static converters using discharge tubes with control electrode or semiconductor devices with control electrode
    • H02M3/145Conversion of dc power input into dc power output without intermediate conversion into ac by static converters using discharge tubes with control electrode or semiconductor devices with control electrode using devices of a triode or transistor type requiring continuous application of a control signal
    • H02M3/155Conversion of dc power input into dc power output without intermediate conversion into ac by static converters using discharge tubes with control electrode or semiconductor devices with control electrode using devices of a triode or transistor type requiring continuous application of a control signal using semiconductor devices only
    • H02M3/156Conversion of dc power input into dc power output without intermediate conversion into ac by static converters using discharge tubes with control electrode or semiconductor devices with control electrode using devices of a triode or transistor type requiring continuous application of a control signal using semiconductor devices only with automatic control of output voltage or current, e.g. switching regulators
    • H02M3/158Conversion of dc power input into dc power output without intermediate conversion into ac by static converters using discharge tubes with control electrode or semiconductor devices with control electrode using devices of a triode or transistor type requiring continuous application of a control signal using semiconductor devices only with automatic control of output voltage or current, e.g. switching regulators including plural semiconductor devices as final control devices for a single load
    • H02M3/1584Conversion of dc power input into dc power output without intermediate conversion into ac by static converters using discharge tubes with control electrode or semiconductor devices with control electrode using devices of a triode or transistor type requiring continuous application of a control signal using semiconductor devices only with automatic control of output voltage or current, e.g. switching regulators including plural semiconductor devices as final control devices for a single load with a plurality of power processing stages connected in parallel
    • H02M3/1586Conversion of dc power input into dc power output without intermediate conversion into ac by static converters using discharge tubes with control electrode or semiconductor devices with control electrode using devices of a triode or transistor type requiring continuous application of a control signal using semiconductor devices only with automatic control of output voltage or current, e.g. switching regulators including plural semiconductor devices as final control devices for a single load with a plurality of power processing stages connected in parallel switched with a phase shift, i.e. interleaved

Abstract

The invention discloses one kind four to be in parallel capacitance series formula Boost and its current equalizing method;Belong to electric circuit electronics technical field, is related to the equal Flow Policy application of multiphase interleaving DC-DC converter, the especially technical field in distributed new electricity generation system grid-connection converter.The control method is based on circuit topology mode, in conjunction with intermediate capacitance charge balance concept, by adjusting intermediate energy storage capacitor charging time and discharge time, so that inductive current size changes correspondingly, to realize each phase inductance current uniform.The current equalizing method increases the feedback such as current sensor, sample circuit without additional, it is freely measured without additional control is added, on the basis of primary circuit, it only needs to change circuit switch device timing, it is shared to can be achieved with converter electric current in full duty ratio region, to simplifying circuit control, circuit stability and application range are expanded, is a kind of high-performance, the solution of low cost.

Description

One kind four is in parallel capacitance series formula Boost and its current equalizing method
Technical field
The invention belongs to electric circuit electronics technical fields, are related to the equal Flow Policy application of multiphase interleaving DC-DC converter, especially It is the technical field in distributed new electricity generation system grid-connection converter.
Background technique
Modern society continues to increase the demand of the energy, and new energy is because having cleaning and regenerative nature to be increasingly subject to people Concern, distributed new electricity generation system is the important component of the following intelligent distribution system, is subtracted to propulsion energy-saving Row and realization energy sustainable development are of great significance.Since the output voltage of distributed new power supply is lower, open circuit electricity Pressure is usually no more than 50V, in order to meet the needs of distributed generation resource access, needs the DC-DC converter of high-gain.But single stage type Booster converter maximum voltage gain is generally limited to 5-8 times, it is difficult to the requirement for expeditiously meeting high-gain, using multiple electricity Source module parallel running provides the direction that high-power output is power technology development, in system each resume module compared with Small-power bears lesser electric stress, so that power supply keeps higher efficiency and faster dynamic response.Meanwhile more switches The output power of the parallel system of power supply has scalability, can meet different capacity by changing the quantity of parallel module Load, can also apply redundancy, improve system reliability.
The parallel technology of converter always is the hot spot of research in distributed new electricity generation system, but due to circuit knot The non-ideal factors such as structure, manufacturing process, component tolerance, environment influence exist, the stress for the voltage and current that certain module is born Larger, damage probability rises, and may be saturated the protection act for causing system in advance during operation, and then lead to entire taken in conjunction System cisco unity malfunction.So the power distribution between converter module always is the emphasis in parallel technology research.Power supply System is to Multiphase Parallel converter basic demand: (1) the electric current energy autobalance that each module is born, and realization is flowed;It (2) is to mention The reliability of high system does not increase the measure of external sharing control as far as possible;(3) when input voltage and/or load current change When, output voltage stabilization should be kept, and system has good transient response characteristic.
To solve the unbalanced influence to converter of input current, domestic and international correlative study person is in power-supply system in parallel Sagging control methods, master & slave control method, external circuit control methods, average current type current can be usually divided to bear automatically the research of equal Flow Technique Carry current-equalizing method, maximum current type automatic current equalizing method, forced balanced current method etc..Sagging control is poor in low current Shi Junliu effect, drop The load characteristic of low power supply output, is realized with sacrificing the technical indicator of electric current;Master & slave control Voltage loop working band is wide, easily Communication modes by noise jamming, and between main control unit and each slave unit are complicated, and reliability is only dependent upon main control unit;Outside Portion's each unit of circuit control method needs to add a current control circuit, and technical indicator and the work that otherwise can reduce unit are steady It is qualitative, it is not easy to maintenance upgrade;Average current model and maximum current method will usually limit maximal regulated range, individual module current limliting Operation irregularity can cause system unstable, and the contradiction that simultaneity factor stability flows transient response with load is difficult to solve;It forces Current-equalizing method, which lacks extremely to rely on monitoring module and cannot achieve if monitoring module fails, flows effect.
As can be seen that for reliability is low, complexity is high, efficiency existing for the equal stream process of Multiphase Parallel DC-DC converter The problems such as low, at high cost, currently no effective solution has been proposed.
Summary of the invention
In order to overcome the shortcomings of above-mentioned technology, the present invention is in parallel capacitance series formula DC-DC converter for four cannot be The problem of stream is run in full working region provides a kind of equal Flow Policy without any additional ancillary equipment, to solve related skill The problems in art.
Present invention provide the technical scheme that it is based on circuit topology mode in the not interior working region in shared electric current, Change converter topology operation mode, adjustment by modifying the duty ratio and phase of phase in conjunction with intermediate capacitance charge balance concept The ratio of intermediate energy storage capacitor charging time and discharge time, and then each phase current average value of change ensures that input current is divided equally, The equal Flow Policy does not need estimation phase current based entirely on the instantaneous duty ratio of converter, then increases current sense without additional Device.
Thus technical solution of the present invention is that one kind four is in parallel capacitance series formula Boost and its current equalizing method, institute Stating the four capacitance series formula Boosts that are in parallel includes: one inductance L of phase1, one switching tube S of phase1, one diode D of phase1, phase two Inductance L2, two switching tube S of phase2, two diode D of phase2, three inductance L of phase3, three switching tube S of phase3, three diode D of phase3, four inductance of phase L4, four switching tube S of phase4, four diode D of phase4, intermediate capacitance C1, intermediate capacitance C2, intermediate capacitance C3;One inductance L of phase1One end with Positive pole connection, the other end and one switching tube S of phase1Source electrode is connected, one switching tube S of phase1Drain electrode connects power supply negative terminal, outside grid Meet S1Driving signal, with one inductance L of phase1With one switching tube S of phase1Source electrode is total to junction series connection one diode D of phase1Anode, One diode D of phase1Negative terminal and intermediate capacitance C1Anode is connected;Two outputting inductance L of phase2One end connect positive pole after, the other end with Two switching tube S of phase2Source electrode is connected, switching tube S2Source electrode meets the external S of input power negative terminal, grid2Driving signal, Xiang Er electricity Feel L2With switching tube S2Drain contact and intermediate capacitance C altogether1Negative terminal is connected, C1Anode and one diode D of phase1Negative terminal is total to contact and connects phase Two diode D2Anode, two diode D of phase2Negative terminal and intermediate capacitance C2Anode is connected;Three outputting inductance L of phase3One end connection After positive pole, the other end and three switching tube S of phase3Source electrode is connected, switching tube S3It is external that source electrode connects input power negative terminal, grid S3Driving signal, three inductance L of phase3With switching tube S3Drain contact and intermediate capacitance C altogether2Negative terminal is connected, C2Anode and phase two or two Pole pipe D2Negative terminal is total to contact and meets three diode D of phase3Anode, three diode D of phase3Negative terminal and intermediate capacitance C3Anode is connected;Phase Four outputting inductance L4After one end connects positive pole, the other end and four switching tube S of phase4Source electrode is connected, switching tube S4Source electrode connects defeated Enter the external S of power supply negative terminal, grid4Driving signal, four inductance L of phase4With switching tube S4Drain contact and intermediate capacitance C altogether3It is negative End is connected, C3Anode and three diode D of phase3Negative terminal is total to contact and meets four diode D of phase4Anode, four diode D of phase4Negative terminal connect The anode of output, input and output are altogether;
The current equalizing method of the Boost are as follows:
When default duty ratio section be (3/4,1] when, one switching tube S of phase1, two switching tube S of phase2, three switching tube S of phase3, phase Four switching tube S4Driving signal interlock in succession π/4, duty ratio be D pwm signal;
When default duty ratio section be (0,3/4] when, according to the difference of duty ratio, sharing control strategy will be taken:
1. when default duty ratio section be (5/8,3/4] when, one switching tube S of phase1Phase shift angle is 0 °, duty ratio 2D- 3/4;Two switching tube S of phase2Phase shift angle is π/4, duty ratio D;Three switching tube S of phase3Phase shift angle is pi/2, duty ratio D;Phase Four switching tube S4Phase shift angle is 3 π/4, duty ratio D;
2. when default duty ratio section be (2/4,5/8] when, one switching tube S of phase1Phase shift angle is (2D-1/4) π, duty Than being 1/2;Two switching tube S of phase2Phase shift angle is π/4, duty ratio D;Three switching tube S of phase3Phase shift angle is that (2D-3/4) π is accounted for Sky is than being 5/4-D;Four switching tube S of phase4Phase shift angle is 3 π/4, duty ratio D;
3. when default duty ratio section be (1/4,2/4] when, one switching tube S of phase1Phase shift angle is 0 °, duty ratio D;Phase Two switching tube S2Phase shift angle is π/4, and duty ratio is adjusted to D/2+3/8;Three switching tube S of phase3Phase shift angle is (3/4-D) π, is accounted for Sky is than being 1/4+D;Four switching tube S of phase4Phase shift angle is 3 π/4, duty ratio 1/2;
4. when default duty ratio section be (0,1/4] when, four phase capacitance series formula crisscross parallel Boosts work exists Region four (0,1/4] when, equal Flow Policy adjusts four phase switching tubes and timing is connected are as follows: one switching tube S of phase1Phase shift angle is 0 °, is accounted for Sky is than being D;Two switching tube S of phase2Driving signal is in S1Shutdown moment conducting, i.e. phase shift angle are D π, duty ratio 1/2;Xiang Sankai Close pipe S3Phase shift angle is (1/4+D) π, duty ratio 1/2;Four switching tube S of phase4Phase shift angle is 3 π/4, duty ratio 1/4+D.
Under this control strategy, for intermediate capacitance C1, one electric current i of phaselIt is responsible for electric discharge, two electric current i of phase2It is responsible for charging, phase One electric current i1With two electric current i of phase2It is identical to capacitor action time, in intermediate capacitance C1Under the action of charge balance, Xiang Yi electricity is realized Flow i1With two electric current i of phase2Respectively;For intermediate capacitance C2, one electric current i of phaselWith two electric current i of phase2It is collectively responsible for discharging, three electric current of phase I3 is responsible for charging, in intermediate capacitance C2Appropriate time ratio is chosen under the action of charge balance, realizes three electric current i of phase3Equal to phase one Electric current i1With two electric current i of phase2;For intermediate capacitance C3, one electric current i of phasel, two electric current of phase2With three electric current i of phase3It is collectively responsible for discharging, Four electric current i of phase4It is responsible for charging, in intermediate capacitance C3Appropriate time ratio is chosen under the action of charge balance, realizes four electric current i of phase4 Equal to remaining each phase current.So far the stream operation of all phases is completed.
Compared with prior art, the beneficial effects of the present invention are:
One, the equal Flow Policy realizes that each phase current is divided equally on original circuit base, can reduce converter total losses, enhancing Converter stability expands converter applications range;
Two, the equal Flow Policy does not need estimation phase current based entirely on the instantaneous duty ratio of converter, i.e., increases without additional Any external equipment of such as current sensor and additional control is added freely to measure.
Three, in the operating area of equal Flow Policy effect, converter voltage gain characteristic is from the bipyramid about duty ratio Become the linear function about duty ratio, from expanding circuit stability and application range.
Present invention will be further explained below with reference to the attached drawings and specific embodiments.
Detailed description of the invention
Fig. 1 is four circuit structure diagrams for being in parallel serial capacitance formula Boost;
Fig. 2 is four to be in parallel serial capacitance formula Boost tradition timing diagram;
Fig. 3 is four 16 kinds of working conditions for being in parallel serial capacitance formula Boost;
Fig. 4 be four be in parallel serial capacitance formula Boost work in (3/4,1] current simulations waveform;
Fig. 5 be four be in parallel serial capacitance formula Boost work in (5/8,3/4] stream front and back current simulations waveform Comparison, wherein a is the simulation waveform of traditional Interleaved control, and b is using the simulation waveform after equal Flow Policy;
Fig. 6 be four be in parallel serial capacitance formula Boost work in (2/4,5/8] stream front and back current simulations waveform Comparison, wherein a is the simulation waveform of traditional Interleaved control, and b is using the simulation waveform after equal Flow Policy;
Fig. 7 be four be in parallel serial capacitance formula Boost work in (3/8,2/4] stream front and back current simulations waveform Comparison, wherein a is the simulation waveform of traditional Interleaved control, and b is using the simulation waveform after equal Flow Policy;
Fig. 8 be four be in parallel serial capacitance formula Boost work in (1/4,3/8] stream front and back current simulations waveform Comparison, wherein a is the simulation waveform of traditional Interleaved control, and b is using the simulation waveform after equal Flow Policy;
Fig. 9 be four be in parallel serial capacitance formula Boost work in (0,1/4] stream front and back imitate the true waveform pair of electric current Than wherein a is the simulation waveform of traditional Interleaved control, and b is using the simulation waveform after equal Flow Policy.
Specific embodiment
Further detailed description is done to the present invention below by specific example and in conjunction with attached drawing.
As shown in Figure 1, 2, 3, four four switching tube conventional operation modes of serial capacitance formula DC-DC converter are in parallel to hand over Wrong in parallel, i.e., a switching tube duty ratio is identical, adjacent alternate staggeredly π/4.According to the switch state of switching tube, topology shares 16 Working condition can be divided into four operating areas by converter switches pipe duty ratio by operation mode: region one be 3/4 < D≤ 1, or writing (3/4,1];Region two is 2/4 D≤3/4 <, or write (2/4,3/4];Region three is 1/4 D≤2/4 <, or is write Make (1/4,2/4];Region four is 0 D≤1/4 <, or write (0,1/4].
For operating area one (3/4,1], automatic current equalizing between each phase, converter voltage output gain is 4/ (1-D), right This does not do any stream operation.
For operating area two (2/4,3/4], circuit has eight working conditions under traditional timing under traditional timing: (1) S1S2S3S4=1011, as shown in Fig. 3 (5), C1Pass through i2Charging, C2Pass through i2Electric discharge, C3Flowing through electric current is 0, shared duration For (D-1/2) T;(2)S1S2S3S4=1001, as shown in Fig. 3 (7), C1Pass through i2Charging, C2Pass through i3Charging, C3Pass through i2And i3 Common electric discharge, (3/4-D) T a length of when shared;(3)S1S2S3S4=1101, as shown in Fig. 3 (3), C1It is 0, C by electric current2It is logical Cross i3Charging, C3Pass through i3Electric discharge, (D-1/2) T a length of when shared;(4)S1S2S3S4=1100, as shown in Fig. 3 (4), C1Pass through electricity Stream is 0, C2Pass through i3Charging, C3Pass through i4Charging, (3/4-D) T a length of when shared;(5)S1S2S3S4=1110, such as Fig. 3 (2) institute Show, C1It is 0, C by electric current2It is 0, C by electric current3Pass through i4Charging, (D-1/2) T a length of when shared; (6)S1S2S3S4= 0110, as shown in Fig. 3 (10), C1Pass through i1Electric discharge, C2It is 0, C by electric current3Pass through i4Charging, (3/4-D) T a length of when shared; (7)S1S2S3S4=0111, as shown in Fig. 3 (9), C1Pass through i1Electric discharge, C2It is 0, C by electric current3It is 0 by electric current, shared duration For (D-1/2) T;(8)S1S2S3S4=0011, as shown in Fig. 3 (13), C1Pass through i2Charging, C2Pass through i1And i2Electric discharge, C3Pass through Electric current is 0, (3/4-D) T a length of when shared.Two voltage gain of region is (128D under this working condition3-416D2+444D- 157)/64(1-D)4
Operating area be (5/8,3/4] when, one switching tube S of phase1Phase shift angle is 0 °, duty ratio 2D-3/4;Xiang Erkai Close pipe S2Phase shift angle is π/4, duty ratio D;Three switching tube S of phase3Phase shift angle is pi/2, duty ratio D;Four switching tube of phase S4Phase shift angle is 3 π/4, duty ratio D.Accordingly, S1S2S3S4=1011, (D-1/2) T, S a length of when shared1S2S3S4= 1001, (3/4-D) T, S a length of when shared1S2S3S4(D-1/2) T, S a length of when shared by=11011S2S3S4=1100, shared duration For (3/4-D) T, S1S2S3S4=1110, (2D-5/4) T, S a length of when shared1S2S3S4=0110, it is a length of when shared (3/2-2D) T, S1S2S3S4=0111, (D-1/2) T, S a length of when shared1S2S3S4=0011, (3/4-D) T a length of when shared.In intermediate capacitance C1Under the action of charge balance, one electric current i of phase is realized1With two electric current i of phase2Respectively;In intermediate capacitance C2Under the action of charge balance Appropriate time ratio is chosen, realizes three electric current i of phase3Equal to one electric current i of phase1With two electric current i of phase2;In intermediate capacitance C3Charge balance Under the action of choose appropriate time ratio, realize four electric current i of phase4Equal to remaining each phase current.The electricity in the region after stream operation Pressure gain is 16/ (7-8D).Operating area be (2/4,5/8] when, one switching tube S of phase1Phase shift angle is (2D-1/4) π, duty Than being 1/2;Two switching tube S of phase2Phase shift angle is π/4, duty ratio D;Three switching tube S of phase3Phase shift angle is (2D-3/4) π, Duty ratio is 5/4-D;Four switching tube S of phase4Phase shift angle is 3 π/4, duty ratio D.Accordingly, S1S2S3S4=1011, shared duration For (3/4-D) T, S1S2S3S4=1001, (3/4-D) T, S a length of when shared1S2S3S4(D-1/2) T a length of when shared by=1101, S1S2S3S4=1100, (D-1/2) T, S a length of when shared1S2S3S4=0110, (3/2-2D) T, S a length of when shared1S2S3S4= 0111, (D-1/2) T, S a length of when shared1S2S3S4=0011, (D-1/2) T a length of when shared.It is flat in three intermediate capacitance charges Under the action of weighing apparatus, one electric current i of phase is realized1, two electric current i of phase2, three electric current i of phase3With four electric current i of phase4Respectively.The stream operation area Hou Gai The voltage gain in domain is 8.
For region three (1/4,2/4], circuit has eight working conditions: (1) S under traditional timing1S2S3S4=1001, As shown in Fig. 3 (7), C1Pass through i2Charging, C2Pass through i3Charging, C3Pass through i2And i3Common electric discharge, it is a length of when shared (D-1/4) T; (2)S1S2S3S4=1000, as shown in Fig. 3 (8), C1Pass through i2Charging, C2Pass through i3Charging, C3Pass through i4Charging, when shared A length of (1/2-D) T;(3)S1S2S3S4=1100, as shown in Fig. 3 (4), C1It is 0, C by electric current2Pass through i3Charging, C3Pass through i4 Charging, (D-1/4) T a length of when shared;(4)S1S2S3S4=0100, as shown in Fig. 3 (12), C1Pass through i1Electric discharge, C2Pass through i3It fills Electricity, C3Pass through i4Charging, (1/2-D) T a length of when shared;(5)S1S2S3S4=0110, as shown in Fig. 3 (10), C1Pass through i1It puts Electricity, C2It is 0, C by electric current3Pass through i4Charging, (D-1/4) T a length of when shared;(6)S1S2S3S4=0010, such as Fig. 3 (14) institute Show, C1Pass through i2Charging, C2Pass through i1And i2Electric discharge, C3Pass through i4Charging, (1/2-D) T a length of when shared; (7)S1S2S3S4= 0011, as shown in Fig. 3 (9), C1Pass through i2Charging, C2Pass through i1And i2Electric discharge, C3It is 0 by electric current, it is a length of when shared (D-1/4) T;(8)S1S2S3S4=0001, as shown in Fig. 3 (13), C1Pass through i2Charging, C2Pass through i3Charging, C3Pass through i1、i2And i3Electric discharge, (1/2-D) T a length of when shared.It is (- 128D that the voltage gain for flowing operation is not taken in region three, which,3+384D2-396D+141)/64 (1-D)4
Region three (1/4,2/4] stream operation are as follows: one switching tube S of phase1Phase shift angle is 0 °, duty ratio D;Phase two switchs Pipe S2Phase shift angle is π/4, and duty ratio is adjusted to D/2+3/8;Three switching tube S of phase3Phase shift angle is π (3/4-D), and duty ratio is 1/4+D;Four switching tube S of phase4Phase shift angle is 3 π/4, duty ratio 1/2.Accordingly, operating area be (3/8,2/4] when, S1S2S3S4=1001, a length of 1/4T, S when shared1S2S3S4=1100, (1/2-D) T, S a length of when shared1S2S3S4=1110 institutes Account for Shi Changwei (2D-3/4) T, S1S2S3S4=0110, (3/4-D) T, S a length of when shared1S2S3S4=0111, it is a length of when shared (D/2-1/8) T, S1S2S3S4=0011, (3/8-D/2) T a length of when shared.Under the action of three intermediate capacitance charge balances, Realize one electric current i of phase1, two electric current i of phase2, three electric current i of phase3With four electric current i of phase4Respectively.Operating area be (1/4,3/8] when, S1S2S3S4=1001, a length of 1/4T, S when shared1S2S3S4=1100, (D-1/4) T, S a length of when shared1S2S3S4=0100 institute Account for Shi Changwei (3/4-2D) T, S1S2S3S4=0110, a length of DT, S when shared1S2S3S4=0111, it is a length of when shared (D/2-1/8) T, S1S2S3S4=0011, (3/8-D/2) T a length of when shared.Under the action of three intermediate capacitance charge balances, phase one is realized Electric current i1, two electric current i of phase2, three electric current i of phase3With four electric current i of phase4Respectively.The voltage gain in the region is 4/ (1- after stream operation D)。
For region four (0,1/4], circuit has eight working conditions: (1) S under traditional timing1S2S3S4=1000, such as Shown in Fig. 3 (8), C1Pass through i2Charging, C2Pass through i3Charging, C3Pass through i4Charging, a length of DT when shared;(2)S1S2S3S4= 0000, as shown in Fig. 3 (16), C1Pass through i2Charging, C2Pass through i3Charging, C3Pass through i4Charging, (1/4-D) T a length of when shared; (3)S1S2S3S4=0100, as shown in Fig. 3 (12), C1Pass through i1Electric discharge, C2Pass through i3Charging, C3Pass through i4Charging, shared duration For (D-1/4) T;(4)S1S2S3S4=0000, with mode 2;(5)S1S2S3S4=0010, as shown in Fig. 3 (14), C1Pass through i2It fills Electricity, C2Pass through i1And i2Electric discharge, C3Pass through i4Charging, (D-1/4) T a length of when shared;(6)S1S2S3S4=0000, with mode 2; (7)S1S2S3S4=0001, as shown in Fig. 3 (15), C1Pass through i2Charging, C2Pass through i3Charging, C3It is discharged by i1, i2 and i3, A length of DT when shared;(8)S1S2S3S4=0000, with mode 2.It is 4/ (1- that the voltage gain for flowing operation is not taken in region four, which, D)4
Operating area be (0,1/4] when, four phase capacitance series formula crisscross parallel Boosts work region four (0, When 1/4], equal Flow Policy adjusts four phase switching tubes and timing is connected are as follows: one switching tube S of phase1Phase shift angle is 0 °, duty ratio D;Phase Two switching tube S2Driving signal is in S1Shutdown moment conducting, i.e. phase shift angle are π/D, duty ratio 1/2;Three switching tube S of phase3It moves Phase angle is π/(1/4+D), duty ratio 1/2;Four switching tube S of phase4Phase shift angle is 3 π/4, duty ratio 1/4+D.Accordingly, Circuit mode is S1S2S3S4=1001, a length of DT, S when shared1S2S3S4=0100, a length of 1/4T, S when shared1S2S3S4= A length of 1/4T, S when shared by 01101S2S3S4=0010, (1/4-D) T, S a length of when shared1S2S3S4=0011, it is a length of when shared DT, S1S2S3S4=0001, (1/4-D) T a length of when shared.Under the action of three intermediate capacitance charge balances, phase one is realized Electric current i1, two electric current i of phase2, three electric current i of phase3With four electric current i of phase4Respectively.The voltage gain in the region is 4/ after stream operation (1-D)。
Simulation analysis result:
The switch periods simulation waveform of Fig. 4-9 embodiment, simulation parameter are as follows: input voltage Vin=10~50V, load electricity Hinder RL=240 Ω, intermediate capacitance C1=C2=C3=10uF, inductance L1=L2=L3=L4=500uH, output capacitance Co= 300uF, converter output voltage are 220V, output power 200W.
Fig. 4 be four be in parallel serial capacitance formula Boost work in (3/4,1] current simulations waveform, emulation adopted With parameter D=0.82, input voltage Vin=10V, output voltage 220V, the operating area can under traditional Interleaved control It automatically achieves and flows, be not necessarily to sharing control.
Fig. 5 be four be in parallel serial capacitance formula Boost work in (5/8,3/4] stream front and back current simulations waveform Comparison, true used parameter D=0.7, input voltage Vin=20, four phase currents can not flow under traditional Interleaved control, output Voltage is 225V, can achieve the effect that four phase automatic current equalizings, output voltage 220V in the case where this paper proposes equal Flow Policy control.
Fig. 6 be four be in parallel serial capacitance formula Boost work in (5/8,3/4] stream front and back current simulations waveform Comparison, true used parameter D=0.6, input voltage Vin=27.5V, four phase currents can not flow under traditional Interleaved control, defeated Voltage is 212V out, can achieve the effect that four phase automatic current equalizings, output voltage are in the case where this paper proposes equal Flow Policy control 220V。
Fig. 7 be four be in parallel serial capacitance formula Boost work in (3/8,1/2] stream front and back current simulations waveform Comparison, true used parameter D=0.456, input voltage Vin=30V, four phase currents can not flow under traditional Interleaved control, defeated Voltage is 151V out, can achieve the effect that four phase automatic current equalizings, output voltage are in the case where this paper proposes equal Flow Policy control 219V。
Fig. 8 be four be in parallel serial capacitance formula Boost work in (1/4,3/8] stream front and back current simulations waveform Comparison, true used parameter D=0.273, input voltage Vin=40V, four phase currents can not flow under traditional Interleaved control, defeated Voltage is 131V out, can achieve the effect that four phase automatic current equalizings, output voltage are in the case where this paper proposes equal Flow Policy control 218V。
Fig. 9 be four be in parallel serial capacitance formula Boost work in (0,1/4] stream front and back imitate the true waveform pair of electric current Than true used parameter D=0.1, input voltage Vin=50V, four phase currents can not flow under traditional Interleaved control, output electricity Pressure is 68V, can achieve the effect that four phase automatic current equalizings, output voltage 216V in the case where this paper proposes equal Flow Policy control.
To sum up, equal Flow Policy proposed by the invention can realize that each phase current is divided equally in full duty cycle range, without increasing Add additional devices, i.e., can solve four under the premise of increasing cost and be in parallel serial capacitance formula Boost Full operation region can not automatic current equalizing the problem of.And under the current equalizing method, voltage gain characteristic is from about duty ratio Bipyramid becomes the linear function about duty ratio, from expanding circuit stability and application range.
The foregoing is merely presently preferred embodiments of the present invention, is not intended to limit the invention, it is all in spirit of the invention and Made any modifications, equivalent replacements, and improvements etc., should all be included in the protection scope of the present invention within principle.

Claims (1)

  1. Capacitance series formula Boost and its current equalizing method 1. one kind four is in parallel, described four are in parallel capacitance series formula Boost includes: one inductance L of phase1, one switching tube S of phase1, one diode D of phase1, two inductance L of phase2, two switching tube S of phase2, phase Two diode D2, three inductance L of phase3, three switching tube S of phase3, three diode D of phase3, four inductance L of phase4, four switching tube S of phase4, Xiang Si bis- Pole pipe D4, intermediate capacitance C1, intermediate capacitance C2, intermediate capacitance C3;One inductance L of phase1One end is connect with positive pole, the other end and phase One switching tube S1Source electrode is connected, one switching tube S of phase1Drain electrode meets the external S of power supply negative terminal, grid1Driving signal, with phase one Inductance L1With one switching tube S of phase1Source electrode is total to junction series connection one diode D of phase1Anode, one diode D of phase1Negative terminal and centre Capacitor C1Anode is connected;Two outputting inductance L of phase2After one end connects positive pole, the other end and two switching tube S of phase2Source electrode is connected It connects, switching tube S2Source electrode meets the external S of input power negative terminal, grid2Driving signal, two inductance L of phase2With switching tube S2Drain electrode is altogether Contact and intermediate capacitance C1Negative terminal is connected, C1Anode and one diode D of phase1Negative terminal is total to contact and meets two diode D of phase2Anode, phase Two diode D2Negative terminal and intermediate capacitance C2Anode is connected;Three outputting inductance L of phase3One end connect positive pole after, the other end with Three switching tube S of phase3Source electrode is connected, switching tube S3Source electrode meets the external S of input power negative terminal, grid3Driving signal, Xiang San electricity Feel L3With switching tube S3Drain contact and intermediate capacitance C altogether2Negative terminal is connected, C2Anode and two diode D of phase2Negative terminal is total to contact and connects phase Three diode D3Anode, three diode D of phase3Negative terminal and intermediate capacitance C3Anode is connected;Four outputting inductance L of phase4One end connection After positive pole, the other end and four switching tube S of phase4Source electrode is connected, switching tube S4It is external that source electrode connects input power negative terminal, grid S4Driving signal, four inductance L of phase4With switching tube S4Drain contact and intermediate capacitance C altogether3Negative terminal is connected, C3Anode and phase three or two Pole pipe D3Negative terminal is total to contact and meets four diode D of phase4Anode, four diode D of phase4Negative terminal connect the anode of output, input and output are total Ground;
    The current equalizing method of the Boost are as follows:
    When default duty ratio section be (3/4,1] when, one switching tube S of phase1, two switching tube S of phase2, three switching tube S of phase3, Xiang Sikai Close pipe S4Driving signal interlock in succession π/4, duty ratio be D pwm signal;
    When default duty ratio section be (0,3/4] when, according to the difference of duty ratio, sharing control strategy will be taken:
    1. when default duty ratio section be (5/8,3/4] when, one switching tube S of phase1Phase shift angle is 0 °, duty ratio 2D-3/4;Phase Two switching tube S2Phase shift angle is π/4, duty ratio D;Three switching tube S of phase3Phase shift angle is pi/2, duty ratio D;Phase four switchs Pipe S4Phase shift angle is 3 π/4, duty ratio D;
    2. when default duty ratio section be (2/4,5/8] when, one switching tube S of phase1Phase shift angle is (2D-1/4) π, duty ratio 1/ 2;Two switching tube S of phase2Phase shift angle is π/4, duty ratio D;Three switching tube S of phase3Phase shift angle is that (2D-3/4) π duty ratio is 5/4-D;Four switching tube S of phase4Phase shift angle is 3 π/4, duty ratio D;
    3. when default duty ratio section be (1/4,2/4] when, one switching tube S of phase1Phase shift angle is 0 °, duty ratio D;Xiang Erkai Close pipe S2Phase shift angle is π/4, and duty ratio is adjusted to D/2+3/8;Three switching tube S of phase3Phase shift angle is (3/4-D) π, duty ratio For 1/4+D;Four switching tube S of phase4Phase shift angle is 3 π/4, duty ratio 1/2;
    4. when default duty ratio section be (0,1/4] when, four phase capacitance series formula crisscross parallel Boosts work in region Four (0,1/4] when, equal Flow Policy adjusts four phase switching tubes and timing is connected are as follows: one switching tube S of phase1Phase shift angle is 0 °, duty ratio For D;Two switching tube S of phase2Driving signal is in S1Shutdown moment conducting, i.e. phase shift angle are D π, duty ratio 1/2;Three switching tube of phase S3Phase shift angle is (1/4+D) π, duty ratio 1/2;Four switching tube S of phase4Phase shift angle is 3 π/4, duty ratio 1/4+D.
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