CN102861840A - Three-roll cross rolling forming method for asymmetrical duel-step revolving body parts - Google Patents

Abstract

The invention relates to a three-roll cross rolling forming method for asymmetrical duel-step revolving body parts. The method comprises the following steps of: (1) determining the shape of a blank according to asymmetry degree of parts, and determining the volume distribution ratio according to metal flowing rules so as to determine the size of the blank; (2) according to three-roll cross rolling forming principle and equipment structure and size requirement of the blank and the parts, firstly designing the size and position on the working plane of a secondary roll, and then determining the size of a main roll; (3) according to three-roll cross rolling gripping conditions and roll size, blank size and part size, sequentially designing the rotating speed of the main roll, the feeding speed and rolling time of the main roll; and (4) rolling and forming the parts according to rolling parameters of the step (3). The three-roll cross rolling forming process parameters of the parts can be reasonably determined, the stable rolling forming of the parts can be ensured, the rate of the rolled waste and defective products can be decreased so as to realize low-consumption, high-efficient and high-quality forming manufacturing of mechanical parts such as a duplicate gear, a double-side supporting wheel body and a high-pressure valve body.

Description

A kind of asymmetric double step revolving parts three roller transverse rolling manufacturing process

Technical field

The present invention relates to a kind of asymmetric double step revolving parts three roller transverse rolling manufacturing process.

Background technology

Asymmetric double step revolving parts, as shown in Figure 1, its geometric properties consists of a deep trouth for the surface by length or highly asymmetric up/down steps, and center band aperture or not with holes typically is applied as duplicate gear in the engineering machinery, double-side thrust wheel body etc.The surperficial deep trouth of this type of part is difficult to by forging direct Accurate Shaping, normally adopt at present open die forging or die forging simply to be shaped, be shaped by machining again, power consumption of polymer processing is high, stock utilization is low, a large amount of machining are lost time and destructible part metallic fiber streamline not only, causes that production efficiency is low, cost is high, properties of product are poor.

Three roller transverse rollings are to utilize the revolution plastic deformation and a kind of plastic working new technology of many steps revolving parts that is shaped, and its principle as shown in Figure 2.Three roll axis are arranged in parallel, and king roller 1 is done initiatively to rotatablely move and do the straight-line feed motion simultaneously downwards; Left secondary roll 2, right secondary roll 3 are the fixing dummy roll in axle center, do passive rotatablely moving under part drives; The part pass that three rollers consist of of nipping under the rotation of drive roll and radial feed effect produces continuous rotation and local plastic deformation, and through too much changing the shape accumulation, the part section profile is full of rolling groove, finishes roll forming.In the three roller transverse rolling processes, the part deformation district is part and the regional area that three rolls contact, and belongs to partial plastic forming, thereby resistance of deformation is little, and the equipment needed thereby tonnage is little; In the operation of rolling, when the External Shape step profile was full of pass, distortion just finished, and does not produce overlap, and forming accuracy is high; The part groove is shaped through plastic deformation in addition, and its fibre flow and crystal grain distribute, and the part performance is high.Therefore, adopt three roller cross rolling process many steps revolving parts that is shaped to have significant technological and economical advantages.

Yet, the distortion of three roller transverse rollings is the complicated dynamic deformation process under the Multi-parameter coupling effect, and because the geometry asymmetry of asymmetric double step revolving parts, so that metal flow and geometrical figuration rule are very complicated in the part operation of rolling, affect parameter numerous, need the design rolling technological parameter of Proper Match, effectively controlled rolling process metal flow and motion deformation, otherwise, easily produce part in rolling and squeeze the defectives such as flat, that the cross section is not fully filled.Owing to not grasping effective milling method, various rolling defects often appear in the actual production, rolling useless, defect rate is high, causes such part still to be manufactured with traditional forging associating cutting working method at present.

Summary of the invention

The technical problem to be solved in the present invention is: for above-mentioned deficiency, a kind of asymmetric double step revolving parts three roller transverse rolling manufacturing process are provided, by the appropriate design rolling technological parameter, realize stable formation of asymmetric double step revolving parts three roller transverse rollings, effectively reduce such part and make the energy and material consumption, improved production efficiency and properties of product.

In order to solve the problems of the technologies described above, the technical solution adopted in the present invention is:

A kind of asymmetric double step revolving parts three roller transverse rolling manufacturing process is characterized in that: adopt a stable formation asymmetric double of three roller transverse rolling methods step revolving parts; Specifically comprise the steps: (1) according to accessory size and asymmetric degree, selected suitable blank shape is determined the capacity distribution ratio according to law of metal flow again, and then definite blank dimension and base; Described blank cross sectional shape is rectangle, frustum type or stepped ramp type; (2) according to three roller transverse rolling Forming Theories and device structure and blank, accessory size requirement, design first secondary rolling face size and position, determine again the king roller size; (3) design successively the roll forming parameter according to three roller transverse rolling bite conditions and dimension of roller, blank dimension, accessory size, described roll forming parameter comprises king roller rotating speed, king roller feed speed and rolling time; (4) by stable rolling of roll forming parameter of step (3) described part that is shaped; King roller is done initiatively to rotatablely move and do the straight-line feed motion simultaneously downwards when rolling; Left secondary roll, right secondary roll are the fixing dummy roll in axle center, do passive rotatablely moving under blank drives; The part pass that three rollers consist of of nipping under the rotation of drive roll and radial feed effect produces continuous rotation and local plastic deformation, and through too much changing the shape accumulation, the blank cross section profile is full of rolling groove, finishes roll forming.

By technique scheme: step (1) is carried out in the following order:

1) the asymmetric degree K of calculating part _D

If R ₁, R ₂, R ₃, r is respectively part top bar radius, groove radius, get out of a predicament or an embarrassing situation radius and interior pore radius; For solid class part, r=0; B ₁, B ₂, B ₃Be respectively part top bar height, groove height and the height of getting out of a predicament or an embarrassing situation, part total height B=B then ₁+ B ₂+ B ₃V _Lu, V _LdBe respectively part top bar volume and the volume of getting out of a predicament or an embarrassing situation;

Dissymmetryc coefficient

Asymmetric degree K _D=| K _L-1|;

Work as K _D, adopt the square-section blank at＜0.1 o'clock;

As 0.1≤K _D≤ 0.3, adopt the frustum type blank;

Work as K _D0.3 o'clock, adopt the stepped ramp type blank.

2) calculate blank volume V

For the narrow meshed part in center, after three roller transverse rollings distortion, slight waist drum phenomenon can appear in endoporus, so blank dimension will design than inner bore of part undersized, needs when calculating the blank volume inner bore of part size is adjusted.The blanking inner hole radius r ₀Get (0.9 ~ 1) r, the part wall thickness is less, r ₀Value less.For solid parts, there is not above-mentioned phenomenon, i.e. r ₀=r=0;

Therefore required blank volume V=π R ₁ ²B ₁+ π R ₂ ²B ₂+ π R ₃ ²B ₃-π r ₀ ²B;

The inner bore of part radius r is got r ₀Revise, with K _rThe ratio of expression part groove radius and interior pore radius, namely

Take half At The Height of groove as the boundary, part is divided into up and down two parts, with V _u, V _dPart upper and lower part partial volume after expression is revised respectively, part upper and lower part volume ratio is after then revising:

$K_{\mathrm{ud}}=\frac{V_u}{V_d}=\frac{2B_1(R_1^2-r^2)+B_2(R_2^2-r^2)}{3B_3(R_3^2-r^2)+B_2(R_2^2-r^2)};$

The ratio of part the first half volume and cumulative volume after revising

The ratio K of blank the first half volume and cumulative volume _U'=kK _U, k gets 0.8 ~ 1, and asymmetric degree is larger, and correction factor k value is less;

3) determine blank dimension and base

The blank height B ₀B equates with part height, B ₀=B=B ₁+ B ₂+ B ₃

1. for Single Size Rectangular Blanks

The blank outer radius $R_0=\sqrt{\frac{V}{\mathrm{\π}{B}_0}+{r_0}^2}$

2. for the frustum type blank

Angle between blank outer surface and gyroaxis

Wherein $a=\frac{1}{9}{B}^2+\frac{1}{9}{B_m}^2-\frac{1}{9}{\mathrm{BB}}_m,$ $b=\frac{V(B_m-{\mathrm{BK}}_{\mathrm{ud}})}{\mathrm{\π}{B}_m(B-B_m)}-\frac{2V(B_m-B{K}_{\mathrm{ud}})(B+B_m)}{3\mathrm{\π}{\mathrm{BB}}_m(B-B_m)}-r^2-\frac{V}{\mathrm{\πB}},$

$c=\frac{V^2{(B_m-B_0{K}_{\mathrm{ud}})}^2}{{\mathrm{\&pi;}}^2{B_0}^2{B_m}^2{(B_0-B_m)}^2},$ $B_m=B_1+\frac{{\mathrm{<figure-callout\; id="2"\; label="B"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">B</figure-callout>}}_2}{2};$

Blank small end outer radius $R_0=\frac{V(B_m-{\mathrm{BK}}_{\mathrm{ud}})}{\mathrm{\&pi;}{\mathrm{BB}}_m(B-B_m)\tan \mathrm{\&theta;}}-\frac{1}{3}(B+B_m)\tan \mathrm{\&theta;}$

3. for the stepped ramp type blank

Blank small end outer radius $R_0=\sqrt{\frac{{r_0}^2(2B_1+B_2)+\frac{{2\mathrm{VK}}_{\mathrm{ud}}}{\mathrm{\&pi;}}}{2B_1+B_2}}$

Shoulder height V _L=B ₃

Length of bench $L=\frac{-B_L{R}_0+\sqrt{{B_L}^2{R_0}^2-({R_0}^2{B}_0-{r_0}^2{B}_0-\frac{V}{\mathrm{\&pi;}})}}{B_L}.$

By technique scheme, step (2) dimension of roller is determined as follows:

1) determines secondary rolling face size and position

Secondary roll is arranged symmetrically with take the home roll center of circle and blank circle center line connecting as axis, and initial when rolling, two secondary rolls are close to blank, for support part preferably, guarantees rolling motion stabilization, the line at the secondary roll center of circle and blank center and the angle theta of axis ₀Be designed to 45 °～60 °;

Two secondary Roller Design are the same, and secondary rolling face radius determines according to device space size usually, for prevent part from secondary roll shop building be extruded and two secondary rolling faces between mutually interfere secondary roll boss radius R _C2Satisfy following requirement:

$\frac{R_0^{\&prime;}-\sin {\mathrm{\&theta;}}_0-{\mathrm{<figure-callout\; id="2"\; label="R"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">R</figure-callout>}}_2}{1-\sin {\mathrm{\&theta;}}_0}<{\mathrm{<figure-callout\; id="2"\; label="R\; c"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">R</figure-callout>}}_c<\frac{R_0^{\&prime;}\sin \mathrm{\&theta;}}{1-\sin {\mathrm{\&theta;}}_0}+R_3-R_2-L_{\mathrm{cd}}$

R wherein ₀' be the initial contact radius of blank and roll, for square-section and stepped ramp type blank R ₀'=R ₀, for taper type cross section R ₀'=R ₀+ (B ₁+ B ₂) tan β;

Owing to adopting the enclosed pass, secondary roll lower impressions width L _CdShould satisfy: R ₃-R ₂＜L _Cd＜R ₃-r;

Can determine secondary roll upper impression width L by the physical dimension of part _Cu=L _Cd+ R ₁-R ₃,

R _C2After determining, can determine secondary roll upper impression radius surface R according to geometrical relationship _C1=R _C2-(R ₁-R ₂), secondary roll lower impressions radius surface R _C3=R _C2-(R ₃-R ₂);

In order to guarantee the ring sectional dimension precision that is shaped, according to the ring height B of topping bar ₁, groove height B ₂With the height B of getting out of a predicament or an embarrassing situation ₃Can determine secondary roll upper impression height B _C1, boss height B _C2, the lower impressions height B _C3For

B _c1=B ₁+0.3～0.6mm，B _c2=B ₂，B _c3=B ₃+0.3～0.6mm，

Secondary roll upper side wall height B _Cu, the lower wall height B _CdDetermine according to the concrete installation dimension of equipment, consider intensity, its height can not be too small.

2) determine king roller working face size

For guaranteeing that pass is corresponding, can determine king roller upper side wall height B _Mu=B _Cu, king roller lower wall height B _Md=B _Cd, king roller upper impression height B _M1=B _C1, king roller boss height B _M2=B _C2, king roller lower impressions height B _M3=B _C3, king roller lower impressions width L _Md=L _Cd, king roller upper impression width L _Mu=L _Md+ R ₁-R ₃

In order to prevent that king roller from contacting interference with secondary roll, king roller boss radius R _M2Need to satisfy:

${\mathrm{<figure-callout\; id="2"\; label="R\; m"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">R</figure-callout>}}_m<\frac{{{\mathrm{<figure-callout\; id="2"\; label="R"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">R</figure-callout>}}_2}^2-R_2{R}_{c2}-\frac{1}{2}{(L_{\mathrm{cd}}+L_{\mathrm{md}}+2R_2-2R_3)}^2-R_{c2}(L_{\mathrm{cd}}+L_{\mathrm{md}}-2R_3)+R_2\sqrt{{(R_2+R_{c2})}^2-{(R_0^{\&prime;}+R_{c2})}^2\mathrm{si}{\mathrm{<figure-callout\; id="2"\; label="n"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">n</figure-callout>}}^2{\mathrm{\&theta;}}_0}}{{\mathrm{<figure-callout\; id="2"\; label="R\; c"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">R</figure-callout>}}_c+L_{\mathrm{cd}}+L_{\mathrm{md}}+R_2-2R_3-\sqrt{{(R_2+R_{c2})}^2-{(R_0^{\&prime;}+R_{c2})}^2{\sin }^2{\mathrm{\&theta;}}_0}}$

According to following formula, bonding apparatus bulk and requirement of strength can be determined R _M2

And then can determine king roller upper impression radius surface R according to geometrical relationship _M1=R _M2-(R ₁-R ₂), king roller lower impressions radius surface R _M3=R _M2-(R ₃-R ₂).

By technique scheme, step (3) is determined the roll forming parameter according to following manner:

1) king roller rotation speed n _m

In order to guarantee that the operation of rolling is stable, king roller linear velocity V _mGet 1.1～1.3m/s; According to king roller working face radius R _M2, calculating king roller rotating speed is

2) king roller feed speed v

Produce the continuous rolling distortion in order to guarantee that blank can be nipped by rolling groove, the king roller feed speed can not be excessive, designs according to following formula:

$v=(0.3~0.7)\frac{{\mathrm{\&mu;}}^2{n}_m{{\mathrm{<figure-callout\; id="2"\; label="R\; m"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">R</figure-callout>}}_m}^2{\mathrm{<figure-callout\; id="2"\; label="R\; c"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">R</figure-callout>}}_c{\mathrm{<figure-callout\; id="2"\; label="cos"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">cos</figure-callout>}}^2\mathrm{\&theta;}(2{\mathrm{<figure-callout\; id="2"\; label="R\; c"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">R</figure-callout>}}_c{\mathrm{<figure-callout\; id="2"\; label="cos"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">cos</figure-callout>}}^2\mathrm{\&theta;}({R_0}^{\&prime;}+R_{m2})+R_{m2}(R_0^{\&prime;}+R_{c2}))}{60{R_0}^{\&prime;2}{({\mathrm{<figure-callout\; id="2"\; label="R\; c"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">R</figure-callout>}}_c{\mathrm{<figure-callout\; id="2"\; label="cos"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">cos</figure-callout>}}^2\mathrm{\&theta;}+2R_{m2})}^2}$

In the formula, μ is part and roll shop building coefficient of friction;

3) rolling time

Rolling time is comprised of drive roll feeding time and rounding time two parts, and the operation of rolling adopts at the uniform velocity feeding, and rolling time T can be defined as T=T ₁+ T ₂

The drive roll feeding time

Wherein h is rolling total feed amount

$h=(R_0^{\&prime;}+R_{c2})\cos {\mathrm{\&theta;}}_0+R_0^{\&prime;}-R_2-\sqrt{{({\mathrm{<figure-callout\; id="2"\; label="R"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">R</figure-callout>}}_2+R_{c2})}^2-{(R_0^{\&prime;}+R_{c2})}^2{\mathrm{<figure-callout\; id="2"\; label="sin"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">sin</figure-callout>}}^2{\mathrm{\&theta;}}_0}$

The rounding time should guarantee at least that part rotates a week, gets the rounding time

By technique scheme, in the step (4), first roll is installed in the rolling equipment, then the blank of handling well is put into rolling equipment, the roll forming parameter of determining by step (3) is rolled into required part.

The asymmetric double step revolving parts three roller transverse rolling manufacturing process that the present invention proposes, can determine rational rolling blank, pass and forming parameter, avoid causing the metal flow unreasonable distribution and the rolling defect that causes by the part asymmetry, thereby realized the low consumption of asymmetric double step revolving parts, efficient, high-performance stable formation manufacturing.

Description of drawings:

Below in conjunction with accompanying drawing and each embodiment the present invention is described in further detail:

Fig. 1 is asymmetric double step revolving parts schematic cross-section of the present invention;

Fig. 2 is the present invention three roller transverse rolling Forming Theory figure (front view);

Fig. 3 is the present invention's three roller transverse rolling schematic diagrams (side view, blank stage);

Fig. 4 is the present invention three roller transverse rolling Forming Theory figure (side view, part is shaped);

Among Fig. 2-4, the Reference numeral correspondence is as follows: 1-king roller, the left secondary roll of 2-, the right secondary roll of 3-, 4-part blank, 5-part;

Fig. 5 is square-section of the present invention blank schematic cross-section;

Fig. 6 is frustum type of the present invention cross section blank schematic cross-section;

Fig. 7 is stepped ramp type of the present invention cross section blank schematic cross-section;

Fig. 8 is the structural representation of king roller of the present invention;

Fig. 9 is the structural representation of the secondary roll of the present invention;

Figure 10 be the present invention rolling initial with the finish time each roll and part position contrast schematic diagram (left part is divided into rolling initial time, and right part is divided into the rolling finish time).

The specific embodiment

According to asymmetric double step revolving parts three roller transverse rolling manufacturing process of the invention process,, by the appropriate design rolling technological parameter, realize asymmetric double step revolving parts three roller transverse rolling stable formations, specifically comprise following key step:

(1) determines blank shape and size

For asymmetric double step revolving parts, if the upper and lower step dimension difference of part is more greatly that asymmetry is remarkable, when adopting the cylindrical shape blank rolling, metal an end may occur and be not fully filled and the phenomenon of other end metal accumulation in filling pass process, finally cause obtaining the part of required physical dimension.Therefore, at first need to determine rational blank shape and size.

1) the asymmetric degree K of calculating part _D

As shown in Figure 1, establish R ₁, R ₂, R ₃, r be respectively the radius of topping bar, the groove radius of formation of parts, get out of a predicament or an embarrassing situation radius and interior pore radius (for solid class part, r=0), B ₁, B ₂, B ₃Be respectively ring top bar the height, groove height and get out of a predicament or an embarrassing situation the height, part total height B=B ₁+ B ₂+ B ₃V _Lu, V _LdBeing respectively part tops bar and gets out of a predicament or an embarrassing situation volume.(wherein, among Fig. 1 the little person of step volume for topping bar).

Dissymmetryc coefficient

Asymmetric degree K _D=| K _L-1|, K _DLarger, asymmetry is more remarkable, more is difficult to be shaped.

Work as K _D, adopt the square-section blank at＜0.1 o'clock; (such as Fig. 5);

As 0.1≤K _D≤ 0.3, adopt the frustum type blank; (such as Fig. 6);

Work as K _D0.3 o'clock, adopt the stepped ramp type blank.(such as Fig. 7).

2) calculate blank volume V

For the narrow meshed part in center, after three roller transverse rollings distortion, slight waist drum phenomenon can appear in endoporus, so blank dimension will design than inner bore of part undersized, needs when calculating the blank volume inner bore of part size is adjusted.General blanking inner hole radius r ₀Get (0.9 ~ 1) r, the part wall thickness is less, r ₀Value less; For solid parts, there is not above-mentioned phenomenon, i.e. r ₀=r=0.

Therefore required blank volume V=π R ₁ ²B ₁+ π R ₂ ²B ₂+ π R ₃ ²B ₃-π r ₀ ²B

The inner bore of part radius r is got r ₀Revise, with K _rThe ratio of expression part groove radius and interior pore radius, namely

Take half At The Height of groove as the boundary, part is divided into up and down two parts, with V _u, V _dPart upper and lower part partial volume after expression is revised respectively, part upper and lower part volume ratio is after then revising

$K_{\mathrm{ud}}=\frac{V_u}{V_d}=\frac{2B_1({\mathrm{<figure-callout\; id="1"\; label="R"\; filenames="120831110411.png,120831110417.png"\; state="\{\{state\}\}">R</figure-callout>}}_1^2-r^2)+B_2({\mathrm{<figure-callout\; id="2"\; label="R"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">R</figure-callout>}}_2^2-r^2)}{3B_3({\mathrm{<figure-callout\; id="3"\; label="R"\; filenames="120831110411.png,120831110417.png"\; state="\{\{state\}\}">R</figure-callout>}}_3^2-r^2)+B_2({\mathrm{<figure-callout\; id="2"\; label="R"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">R</figure-callout>}}_2^2-r^2)}$

After the correction, the ratio of part the first half volume and cumulative volume

The ratio K of blank the first half volume and cumulative volume _U'=kK _U, k generally gets 0.8 ~ 1, and asymmetric degree is larger, and correction factor k value is less.

3) determine blank dimension

The blank height B ₀B equates with part height, as shown in Figure 1, and B ₀=B=B ₁+ B ₂+ B ₃

1. for the cylindrical shape blank, as shown in Figure 5:

The blank outer radius $R_0=\sqrt{\frac{V}{\mathrm{\&pi;}{B}_0}+{r_0}^2}$

2. for the frustum type blank, as shown in Figure 6:

Angle between blank outer surface and gyroaxis

Wherein $a=\frac{1}{9}{\mathrm{<figure-callout\; id="2"\; label="B"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">B</figure-callout>}}^2+\frac{1}{9}{B_m}^2-\frac{1}{9}{\mathrm{BB}}_m,$ $b=\frac{V(B_m-{\mathrm{BK}}_{\mathrm{ud}})}{\mathrm{\&pi;}{B}_m(B-B_m)}-\frac{2V(B_m-B{K}_{\mathrm{ud}})(B+B_m)}{3\mathrm{\&pi;}{\mathrm{BB}}_m(B-B_m)}-r^2-\frac{V}{\mathrm{\&pi;B}},$

$c=\frac{V^2{(B_m-B_0{K}_{\mathrm{ud}})}^2}{{\mathrm{\&pi;}}^2{B_0}^2{B_m}^2{(B_0-B_m)}^2},$ $B_m={\mathrm{<figure-callout\; id="1"\; label="B"\; filenames="120831110411.png,120831110417.png"\; state="\{\{state\}\}">B</figure-callout>}}_1+\frac{{\mathrm{<figure-callout\; id="2"\; label="B"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">B</figure-callout>}}_2}{2};$

Blank small end outer radius $R_0=\frac{V(B_m-{\mathrm{BK}}_{\mathrm{ud}})}{\mathrm{\&pi;}{\mathrm{BB}}_m(B-B_m)\tan \mathrm{\&theta;}}-\frac{1}{3}(B+B_m)\tan \mathrm{\&theta;};$

3. for the stepped ramp type blank, as shown in Figure 7:

Blank small end outer radius $R_0=\sqrt{\frac{{r_0}^2(2{\mathrm{<figure-callout\; id="1"\; label="B"\; filenames="120831110411.png,120831110417.png"\; state="\{\{state\}\}">B</figure-callout>}}_1+B_2)+\frac{{2\mathrm{VK}}_{\mathrm{ud}}}{\mathrm{\&pi;}}}{2{\mathrm{<figure-callout\; id="1"\; label="B"\; filenames="120831110411.png,120831110417.png"\; state="\{\{state\}\}">B</figure-callout>}}_1+{\mathrm{<figure-callout\; id="2"\; label="B"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">B</figure-callout>}}_2}};$

Shoulder height B _L=B ₃

Length of bench $L=\frac{-B_L{R}_0+\sqrt{{B_L}^2{R_0}^2-({R_0}^2{B}_0-{r_0}^2{B}_0-\frac{V}{\mathrm{\&pi;}})}}{B_L};$

(2) determine rolling groove structure and size and processing roll

Consisted of by king roller 1 and two secondary rolls 2 and 3 such as Fig. 2-4,10 3 roller transverse rolling passes; In order to prevent that blank 4 from producing sunken end face because of axial metal flow in the operation of rolling, rolling groove all is designed to the enclosed pass; King roller 1 and two secondary rolls 2 and 3 working face die cavity corresponding with the part section shape (as shown in Figure 4), the dimension of roller design is as follows:

1) determines secondary rolling face size and position

Secondary roll is arranged symmetrically with take the home roll center of circle and blank circle center line connecting as axis, and initial when rolling, two secondary rolls are close to blank 4, for support part preferably, guarantees rolling motion stabilization, the secondary roll center of circle and the line at blank 4 centers and the angle theta of axis ₀Can be designed to 45 °～60 ° (such as Figure 10 left-half rolling zero hour);

Two secondary rolls 2 and 3 are designed to the same, and as shown in Figure 9, secondary rolling face radius determines according to device space size usually, for prevent part from secondary roll shop building be extruded and two secondary rolling faces between mutually interfere secondary roll boss radius R _C2Satisfy following requirement:

$\frac{R_0^{\&prime;}-\sin {\mathrm{\&theta;}}_0-{\mathrm{<figure-callout\; id="2"\; label="R"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">R</figure-callout>}}_2}{1-\sin {\mathrm{\&theta;}}_0}<{\mathrm{<figure-callout\; id="2"\; label="R\; c"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">R</figure-callout>}}_c<\frac{R_0^{\&prime;}\sin \mathrm{\&theta;}}{1-\sin {\mathrm{\&theta;}}_0}+R_3-R_2-L_{\mathrm{cd}}$

R wherein ₀' be the initial contact radius of blank and roll, for cylindrical in cross-section and stepped ramp type blank R ₀'=R ₀, for taper type cross section R ₀'=R ₀+ (B ₁+ B ₂) tan β; L _CdBe secondary roll lower impressions width;

Owing to adopting the enclosed pass, secondary roll lower impressions width L _CdShould satisfy: R ₃-R ₂＜Lcd＜R ₃-r

Can determine secondary roll upper impression width L by the physical dimension of part _Cu=L _Cd+ R ₁-R ₃,

R _C2After determining, can determine secondary roll upper impression radius surface R according to geometrical relationship _C1=R _C2-(R ₁-R ₂), secondary roll lower impressions radius surface R _C3=R _C2-(R ₃-R ₂);

In order to guarantee the annular part section dimensional accuracy that is shaped, according to the part height B of topping bar ₁, groove height B ₂With the height B of getting out of a predicament or an embarrassing situation ₃Can determine secondary roll upper impression height B _C1, boss height B _C2, the lower impressions height B _C3For

B _c1=B ₁+0.3～0.6mm，B _c2=B ₂，B _c3=B ₃+0.3～0.6mm，

Secondary roll upper side wall height B _Cu, the lower wall height B _CdCan determine according to the concrete installation dimension of equipment, consider intensity, its height can not be too small.

2) determine king roller working face size

As shown in Figure 8, corresponding for guaranteeing pass, can determine king roller upper side wall height B _Mu=B _Cu, king roller lower wall height B _Md=B _Cd, king roller upper impression height B _M1=B _C1, king roller boss height B _M2=B _C2, king roller lower impressions height B _M3=B _C3, king roller lower impressions width L _Md=L _Cd, king roller upper impression width L _Mu=L _Md+ R ₁-R ₃

In order to prevent that king roller from contacting interference with secondary roll, king roller boss radius R _M2Need to satisfy:

${\mathrm{<figure-callout\; id="2"\; label="R\; m"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">R</figure-callout>}}_m<\frac{{{\mathrm{<figure-callout\; id="2"\; label="R"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">R</figure-callout>}}_2}^2-R_2{R}_{c2}-\frac{1}{2}{(L_{\mathrm{cd}}+L_{\mathrm{md}}+2R_2-2R_3)}^2-R_{c2}(L_{\mathrm{cd}}+L_{\mathrm{md}}-2R_3)+R_2\sqrt{{({\mathrm{<figure-callout\; id="2"\; label="R"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">R</figure-callout>}}_2+R_{c2})}^2-{(R_0^{\&prime;}+R_{c2})}^2\mathrm{<figure-callout\; id="2"\; label="si\; n"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">si</figure-callout>}{n}^{}{}^2{\mathrm{\&theta;}}_0}}{{\mathrm{<figure-callout\; id="2"\; label="R\; c"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">R</figure-callout>}}_c+L_{\mathrm{cd}}+L_{\mathrm{md}}+R_2-2R_3-\sqrt{{({\mathrm{<figure-callout\; id="2"\; label="R"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">R</figure-callout>}}_2+R_{c2})}^2-{(R_0^{\&prime;}+R_{c2})}^2{\mathrm{<figure-callout\; id="2"\; label="sin"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">sin</figure-callout>}}^2{\mathrm{\&theta;}}_0}}$

According to following formula, bonding apparatus bulk and requirement of strength can be determined R _M2

And then can determine king roller upper impression radius surface R according to geometrical relationship _M1=R _M2-(R ₁-R ₂), king roller lower impressions radius surface R _M3=R _M2-(R ₃-R ₂)

(3) determine the roll forming parameter

The roll forming parameter comprises king roller rotating speed, king roller feed speed and rolling time, can determine by following:

1) king roller rotation speed n _m

In order to guarantee that the operation of rolling is stable, king roller linear velocity V _mUsually get 1.1～1.3m/s; According to king roller working face radius R _M2, can calculate the king roller rotating speed and be

2) king roller feed speed v

Produce the continuous rolling distortion in order to guarantee that blank can be nipped by rolling groove, the king roller feed speed usually can not be excessive, can design according to following formula:

$v=(0.3~0.7)\frac{{\mathrm{\&mu;}}^2{n}_m{{\mathrm{<figure-callout\; id="2"\; label="R\; m"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">R</figure-callout>}}_m}^2{\mathrm{<figure-callout\; id="2"\; label="R\; c"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">R</figure-callout>}}_c{\mathrm{<figure-callout\; id="2"\; label="cos"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">cos</figure-callout>}}^2\mathrm{\&theta;}(2{\mathrm{<figure-callout\; id="2"\; label="R\; c"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">R</figure-callout>}}_c{\mathrm{<figure-callout\; id="2"\; label="cos"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">cos</figure-callout>}}^2\mathrm{\&theta;}({R_0}^{\&prime;}+R_{m2})+R_{m2}(R_0^{\&prime;}+R_{c2}))}{60{R_0}^{\&prime;2}{({\mathrm{<figure-callout\; id="2"\; label="R\; c"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">R</figure-callout>}}_c{\mathrm{<figure-callout\; id="2"\; label="cos"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">cos</figure-callout>}}^2\mathrm{\&theta;}+2R_{m2})}^2}$

In the formula, μ is part and roll shop building coefficient of friction;

3) rolling time

Rolling time is comprised of drive roll feeding time and rounding time two parts, and the operation of rolling adopts at the uniform velocity feeding, and rolling time T can be defined as T=T ₁+ T ₂

Wherein, the feeding time

H is rolling total feed amount,

$h=(R_0^{\&prime;}+R_{c2})\cos {\mathrm{\&theta;}}_0+R_0^{\&prime;}-R_2-\sqrt{{({\mathrm{<figure-callout\; id="2"\; label="R"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">R</figure-callout>}}_2+R_{c2})}^2-{(R_0^{\&prime;}+R_{c2})}^2{\mathrm{<figure-callout\; id="2"\; label="sin"\; filenames="120831110401.png,120831111037.png"\; state="\{\{state\}\}">sin</figure-callout>}}^2{\mathrm{\&theta;}}_0}$

The rounding time should guarantee at least that part rotates a week, generally gets

The rounding time $T_{}$ ${}_2=(1~4)\frac{2\mathrm{\&pi;}{R}_2}{V_m}$

(4) roll forming: roll is installed in the rolling equipment, the blank of handling well is put into rolling equipment, be rolled into required part by the rolling forming parameter; King roller 1 is done initiatively to rotatablely move and do the straight-line feed motion simultaneously downwards; Left secondary roll 2, right secondary roll 3 are the fixing dummy roll in axle center, do passive rotatablely moving under part drives; The part pass that three rollers consist of of nipping under the rotation of drive roll and radial feed effect produces continuous rotation and local plastic deformation, and through too much changing the shape accumulation, the part section profile is full of rolling groove, finishes roll forming.

Below take duplicate gear shown in Figure 1 as specific embodiment this manufacturing process is described:

Require the part of the roll forming radius R of topping bar ₁, the groove radius R ₂, the radius R of getting out of a predicament or an embarrassing situation ₃Be respectively 95mm, 80mm, 105mm and 25mm with inside radius r, the part height B of topping bar ₁, groove height B ₂With the height B of getting out of a predicament or an embarrassing situation ₃Be respectively 15mm, 28mm, 13mm, its three rollers transverse rolling manufacturing process comprises following content:

(1) determines blank shape and size and base

1) the asymmetric degree K of calculating part _D=0.345〉0.3, therefore should adopt the stepped ramp type blank, its cross sectional shape is as shown in Figure 7.

2) get the blanking inner hole radius r ₀=0.92r=23mm, required blank volume V=1345468.74mm after revising ³, part the first half volume ratio K overall with part after revising _U'=0.959, get correction factor k=0.95, the ratio K of blank the first half volume and cumulative volume _U=0.465.

3) blank total height B ₀=B=56mm, blank small end outer radius R ₀=86.00mm, shoulder height B _L=B ₃=13mm, length of bench L=13.51mm.

By designed blank dimension, with bar section (concrete material is the Q345 steel) from the room temperature homogeneous heating to high-ductility, the heat distortion temperature (1150～1250 ℃) of low resistance, then hot bar section is carried out making the rolling blank of using through the forcing press forging;

(2) determine rolling groove structure and size and processing roll

1) secondary rolling face size and position

Such as Figure 10, with the line at the secondary roll center of circle and blank center and the angle theta of axis ₀Be designed to 60 °; According to secondary rolling face size design method, design secondary roll structure as shown in Figure 9, secondary roll boss face diameter R _C2, upper impression radius surface R _C1, lower impressions radius surface R _C3Be respectively 100mm, 85mm, 75mm, upper and lower die cavity width L _CuAnd L _CdBe respectively 50mm and 60mm, the upper impression height B _C1, boss height B _C2, the lower impressions height B _C3, the upper side wall height B _Cu, the lower wall height B _CdBe respectively 15.5mm, 28mm, 13.5mm, 20mm, 20mm.

2) king roller working face size

According to king roller working face size design method, design the king roller structure as shown in Figure 8, king roller boss face diameter R _M2, upper impression radius surface R _M1, lower impressions radius surface R _M3Be respectively 300mm, 285mm, 275mm, upper and lower die cavity width L _MuAnd L _MdBe respectively 50mm and 60mm, the upper impression height B _M1, boss height B _M2, the lower impressions height B _M3, the upper side wall height B _Mu, the lower wall height B _MdBe respectively 15.5mm, 28mm, 13.5mm, 20mm, 20mm.

(3) determine the roll forming parameter

1) king roller rotation speed n _m

Home roll linear velocity V _mGet 1.257m/s, determine the king roller rotation speed n according to king roller Design of Rotation formula _mBe 40r/min.

2) king roller feed speed v

Determine that according to king roller Design of Rotation formula the king roller feed speed is 1.5mm/s.

3) rolling time T

Rolling total feed amount h is 18.68mm, the feeding time

The rounding time $T_{}$ ${}_2=2.5\frac{2\mathrm{\&pi;}{R}_2}{V_m\&times;{10}^3}=1s$

Rolling time T can be defined as T=T ₁+ T ₂=13.45s.

(4) roll forming: roll is installed in the rolling equipment, the ring blank that processes is put into rolling equipment, be rolled into duplicate gear shown in Figure 1 by the rolling parameter.

The part three roller transverse rolling roll forming techniques such as the double-side thrust wheel body of other material and dimensions, smash valve body are identical with above-mentioned example, at this particularize embodiment not.

Claims (5)

1. asymmetric double step revolving parts three roller transverse rolling manufacturing process is characterized in that: adopt a stable formation asymmetric double of three roller transverse rolling methods step revolving parts; Specifically comprise the steps: (1) according to accessory size and asymmetric degree, selected suitable blank shape is determined the capacity distribution ratio according to law of metal flow again, and then definite blank dimension and base; Described blank cross sectional shape is rectangle, frustum type or stepped ramp type; (2) according to three roller transverse rolling Forming Theories and device structure and blank, accessory size requirement, design first secondary rolling face size and position, determine again the king roller size; (3) design successively the roll forming parameter according to three roller transverse rolling bite conditions and dimension of roller, blank dimension, accessory size, described roll forming parameter comprises king roller rotating speed, king roller feed speed and rolling time; (4) by stable rolling of roll forming parameter of step (3) described part that is shaped; King roller is done initiatively to rotatablely move and do the straight-line feed motion simultaneously downwards when rolling; Left secondary roll, right secondary roll are the fixing dummy roll in axle center, do passive rotatablely moving under blank drives; The part pass that three rollers consist of of nipping under the rotation of drive roll and radial feed effect produces continuous rotation and local plastic deformation, and through too much changing the shape accumulation, the blank cross section profile is full of rolling groove, finishes roll forming.

2. manufacturing process according to claim 1, it is characterized in that: step (1) is carried out in the following order:

1) the asymmetric degree K of calculating part _D

If R ₁, R ₂, R ₃, r is respectively part top bar radius, groove radius, get out of a predicament or an embarrassing situation radius and interior pore radius; For solid class part, r=0; B ₁, B ₂, B ₃Be respectively part top bar height, groove height and the height of getting out of a predicament or an embarrassing situation, part total height B=B then ₁+ B ₂+ B ₃V _Lu, V _LdBe respectively part top bar volume and the volume of getting out of a predicament or an embarrassing situation;

Dissymmetryc coefficient

Asymmetric degree K _D=| K _L-1|;

Work as K _D, adopt the square-section blank at＜0.1 o'clock;

As 0.1≤K _D≤ 0.3, adopt the frustum type blank;

Work as K _D0.3 o'clock, adopt the stepped ramp type blank;

2) calculate blank volume V

For the narrow meshed part in center, after three roller transverse rollings distortion, slight waist drum phenomenon can appear in endoporus, so blank dimension will design than inner bore of part undersized, needs when calculating the blank volume inner bore of part size is adjusted; The blanking inner hole radius r ₀Get (0.9 ~ 1) r, the part wall thickness is less, r ₀Value less; For solid parts, there is not above-mentioned phenomenon, i.e. r ₀=r=0;

Therefore required blank volume V=π R ₁ ²B ₁+ π R ₂ ²B ₂+ π R ₃ ²B ₃-π r ₀ ²B;

The inner bore of part radius r is got r ₀Revise, with K _rThe ratio of expression part groove radius and interior pore radius, namely

Take half At The Height of groove as the boundary, part is divided into up and down two parts, with V _u, V _dPart upper and lower part partial volume after expression is revised respectively, part upper and lower part volume ratio is after then revising:

$K_{\mathrm{ud}}=\frac{V_u}{V_d}=\frac{2B_1(R_1^2-r^2)+B_2(R_2^2-r^2)}{3B_3(R_3^2-r^2)+B_2(R_2^2-r^2)};$

The ratio of part the first half volume and cumulative volume after revising

The ratio K of blank the first half volume and cumulative volume _U'=kK _U, k gets 0.8 ~ 1, and asymmetric degree is larger, and correction factor k value is less;

3) determine blank dimension and base

The blank height B ₀B equates with part height, B ₀=B=B ₁+ B ₂+ B ₃

1. for Single Size Rectangular Blanks

The blank outer radius $R_0=\sqrt{\frac{V}{\mathrm{\&pi;}{B}_0}+{r_0}^2}$

2. for the frustum type blank

Angle between blank outer surface and gyroaxis

Wherein $a=\frac{1}{9}{B}^2+\frac{1}{9}{B_m}^2-\frac{1}{9}{\mathrm{BB}}_m,$ $b=\frac{V(B_m-{\mathrm{BK}}_{\mathrm{ud}})}{\mathrm{\&pi;}{B}_m(B-B_m)}-\frac{2V(B_m-B{K}_{\mathrm{ud}})(B+B_m)}{3\mathrm{\&pi;}{\mathrm{BB}}_m(B-B_m)}-r^2-\frac{V}{\mathrm{\&pi;B}},$

$c=\frac{V^2{(B_m-B_0{K}_{\mathrm{ud}})}^2}{{\mathrm{\&pi;}}^2{B_0}^2{B_m}^2{(B_0-B_m)}^2},$ $B_m=B_1+\frac{B_2}{2};$

Blank small end outer radius $R_0=\frac{V(B_m-{\mathrm{BK}}_{\mathrm{ud}})}{\mathrm{\&pi;}{\mathrm{BB}}_m(B-B_m)\tan \mathrm{\&theta;}}-\frac{1}{3}(B+B_m)\tan \mathrm{\&theta;}$

3. for the stepped ramp type blank

Blank small end outer radius $R_0=\sqrt{\frac{{r_0}^2(2B_1+B_2)+\frac{{2\mathrm{VK}}_{\mathrm{ud}}}{\mathrm{\&pi;}}}{2B_1+B_2}}$

Shoulder height B _L=B ₃

Length of bench $L=\frac{-B_L{R}_0+\sqrt{{B_L}^2{R_0}^2-({R_0}^2{B}_0-{r_0}^2{B}_0-\frac{V}{\mathrm{\&pi;}})}}{B_L}.$

3. manufacturing process according to claim 1 and 2 is characterized in that: step (2) dimension of roller is determined as follows:

1) determines secondary rolling face size and position

Secondary roll is arranged symmetrically with take the home roll center of circle and blank circle center line connecting as axis, and initial when rolling, two secondary rolls are close to blank, for support part preferably, guarantees rolling motion stabilization, the line at the secondary roll center of circle and blank center and the angle theta of axis ₀Be designed to 45 °～60 °;

Two secondary Roller Design are the same, and secondary rolling face radius determines according to device space size usually, for prevent part from secondary roll shop building be extruded and two secondary rolling faces between mutually interfere secondary roll boss radius R _C2Satisfy following requirement:

$\frac{R_0^{\&prime;}-\sin {\mathrm{\&theta;}}_0-R_2}{1-\sin {\mathrm{\&theta;}}_0}<R_{c2}<\frac{R_0^{\&prime;}\sin \mathrm{\&theta;}}{1-\sin {\mathrm{\&theta;}}_0}+R_3-R_2-L_{\mathrm{cd}}$

R wherein ₀' be the initial contact radius of blank and roll, for square-section and stepped ramp type blank R ₀'=R ₀, for taper type cross section R ₀'=R ₀+ (B ₁+ B ₂) tan β;

Owing to adopting the enclosed pass, secondary roll lower impressions width L _CdShould satisfy: R ₃-R ₂＜L _Cd＜R ₃-r;

Can determine secondary roll upper impression width L by the physical dimension of part _Cu=L _Cd+ R ₁-R ₃,

R _C2After determining, can determine secondary roll upper impression radius surface R according to geometrical relationship _C1=R _C2-(R ₁-R ₂), secondary roll lower impressions radius surface R _C3=R _C2-(R ₃-R ₂);

In order to guarantee the ring sectional dimension precision that is shaped, according to the ring height B of topping bar ₁, groove height B ₂With the height B of getting out of a predicament or an embarrassing situation ₃Can determine secondary roll upper impression height B _C1, boss height B _C2, the lower impressions height B _C3For

B _c1=B ₁+0.3～0.6mm，B _c2=B ₂，B _c3=B ₃+0.3～0.6mm，

Secondary roll upper side wall height B _Cu, the lower wall height B _CdDetermine according to the concrete installation dimension of equipment, consider intensity, its height can not be too small;

2) determine king roller working face size

For guaranteeing that pass is corresponding, can determine king roller upper side wall height B _Mu=B _Cu, king roller lower wall height B _Md=B _Cd, king roller upper impression height B _M1=B _C1, king roller boss height B _M2=B _C2, king roller lower impressions height B _M3=B _C3, king roller lower impressions width L _Md=L _Cd, king roller upper impression width L _Mu=L _Md+ R ₁-R ₃

In order to prevent that king roller from contacting interference with secondary roll, king roller boss radius R _M2Need to satisfy:

$R_{m2}<\frac{{R_2}^2-R_2{R}_{c2}-\frac{1}{2}{(L_{\mathrm{cd}}+L_{\mathrm{md}}+2R_2-2R_3)}^2-R_{c2}(L_{\mathrm{cd}}+L_{\mathrm{md}}-2R_3)+R_2\sqrt{{(R_2+R_{c2})}^2-{(R_0^{\&prime;}+R_{c2})}^2\mathrm{si}{n}^2{\mathrm{\&theta;}}_0}}{R_{c2}+L_{\mathrm{cd}}+L_{\mathrm{md}}+R_2-2R_3-\sqrt{{(R_2+R_{c2})}^2-{(R_0^{\&prime;}+R_{c2})}^2{\sin }^2{\mathrm{\&theta;}}_0}}$

According to following formula, bonding apparatus bulk and requirement of strength can be determined R _M2

And then can determine king roller upper impression radius surface R according to geometrical relationship _M1=R _M2-(R ₁-R ₂), king roller lower impressions radius surface R _M3=R _M2-(R ₃-R ₂).

4. manufacturing process according to claim 3, it is characterized in that: step (3) is determined the roll forming parameter according to following manner:

1) king roller rotation speed n _m

In order to guarantee that the operation of rolling is stable, king roller linear velocity V _mGet 1.1～1.3m/s; According to king roller working face radius R _M2, calculating king roller rotating speed is

2) king roller feed speed v

Produce the continuous rolling distortion in order to guarantee that blank can be nipped by rolling groove, the king roller feed speed can not be excessive, designs according to following formula:

$v=(0.3~0.7)\frac{{\mathrm{\&mu;}}^2{n}_m{R_{m2}}^2{R}_{c2}{\cos }^2\mathrm{\&theta;}(2R_{c2}{\cos }^2\mathrm{\&theta;}({R_0}^{\&prime;}+R_{m2})+R_{m2}(R_0^{\&prime;}+R_{c2}))}{60{R_0}^{\&prime;2}{(R_{c2}{\cos }^2\mathrm{\&theta;}+2R_{m2})}^2}$

In the formula, μ is part and roll shop building coefficient of friction;

3) rolling time

Rolling time is comprised of drive roll feeding time and rounding time two parts, and the operation of rolling adopts at the uniform velocity feeding, and rolling time T can be defined as T=T ₁+ T ₂

The drive roll feeding time

Wherein h is rolling total feed amount

$h=(R_0^{\&prime;}+R_{c2})\cos {\mathrm{\&theta;}}_0+R_0^{\&prime;}-R_2-\sqrt{{(R_2+R_{c2})}^2-{(R_0^{\&prime;}+R_{c2})}^2{\sin }^2{\mathrm{\&theta;}}_0}$

The rounding time should guarantee at least that part rotates a week, gets the rounding time

5. according to claim 1 and 2 or 4 described manufacturing process, it is characterized in that: in the step (4), first roll is installed in the rolling equipment, then the blank of handling well is put into rolling equipment, the roll forming parameter of determining by step (3) is rolled into required part.

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