CN104598690B - Conversion method of the style figure of one sleeve to pattern figure - Google Patents

Conversion method of the style figure of one sleeve to pattern figure Download PDF

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CN104598690B
CN104598690B CN201510050584.8A CN201510050584A CN104598690B CN 104598690 B CN104598690 B CN 104598690B CN 201510050584 A CN201510050584 A CN 201510050584A CN 104598690 B CN104598690 B CN 104598690B
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msubsup
mrow
prime
msub
sleeve
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CN104598690A (en
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邓咏梅
刘肖
陈金广
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Xian Polytechnic University
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Xian Polytechnic University
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Abstract

The invention discloses the conversion method of the style figure of one sleeve to pattern figure, sleeve length, sleeve mountain oblique line, sleeve suture and sleeve opening line segment end points regard the line between corresponding points as characteristic curve as key point first using in one sleeve；According to the corresponding relation of controlling position size in the length of characteristic curve in style figure and pattern figure, with reference to the distance between 2 points formula in coordinate system, pattern frame diagram is designed；Finally construct cap arc line and sleeve seam camber line respectively using B-spline curves, with reference to actual sleeve length, sleeve height and sleeve opening, obtain pattern figure, made a plate.The present invention utilizes parametric method, and the one-to-one corresponding for realizing one sleeve style figure to pattern figure is changed；Using curved portion in B-spline curves generation method construction pattern figure, the problem of big repetition amount, low efficiency and not high accuracy are worked during conventional cardboard is solved.

Description

Conversion method of the style figure of one sleeve to pattern figure
Technical field
The invention belongs to intelligent dress design field, and in particular to the conversion of the style figure of one sleeve to pattern figure Method.
Background technology
Traditional apparel pattern design is that pattern maker combines the plate-making design that human dimension completes garment fashion drawing, the process The human users of specialty are needed, work repeatability is high, inefficiency.And with the continuous innovation of production technology, traditional dressing Method can not meet existing dress designing and the demand made, with continuing to develop for clothing CAD technology, intellectuality clothes Dress is designed to a big study hotspot of current garment industry, and it mainly re-packs including intelligent clothing Design modelling, intelligence, style The part of intelligent conversion three designed and re-packed.Among this three, the conversion of garment fashion drawing to pattern figure is set in intelligent dress It is particularly important and difficulty is larger in meter.
The present invention is closed using relevant control point in style figure and characteristic curve and the mapping at relevant control position in actual pattern System, sets up both parametrization conversion methods, and combines curved portion in B-spline curves generation method construction pattern figure, so that The style figure of one sleeve is preferably realized to the conversion of pattern figure.
The content of the invention
It is an object of the invention to provide the conversion method of the style figure of one sleeve to pattern figure, traditional dress design is solved With the problem of repetition amount is big, efficiency is low that worked present in plate-making.
The technical scheme is that, the conversion method of the style figure of one sleeve to pattern figure, specifically according to following steps Implement：
Step 1：Choose the key point and characteristic curve in style figure；
Step 2：According to the corresponding relation of controlling position size in the length of characteristic curve in style figure and pattern figure, with reference to seat The distance between 2 points formula in mark system, obtain actual sleeve length in pattern figure, sleeve height, sleeve mountain oblique line, sleeve suture and sleeve opening Length, with reference to crucial point coordinates, design pattern frame diagram；
Step 3：Construct cap arc line and sleeve seam camber line respectively using B-spline curves, the actual sleeve with reference to obtained by step 2 Long, sleeve height and sleeve opening, obtain pattern figure.
It is of the invention to be further characterized in that,
In step 1, the name process of the mark of key point and characteristic curve is in style figure：
a：Sleeve length, sleeve mountain oblique line, sleeve suture and sleeve opening line segment end points are as key point using in one sleeve, between corresponding points Line be used as characteristic curve；
b：The key point to selection is marked respectively：A1(x1,y1)、A2(x2,y2)、A3(x3,y3)、A4(x4,y4), cross point A4(x4,y4) make line segment A4A5Make it perpendicular to line segment A1A2, intersection point is A5(x5,y5)；
c：The characteristic curve formed between corresponding points is named, A1A2For actual sleeve length, A1A5For sleeve height, A1A4For sleeve Mountain oblique line, A3A4For sleeve suture, A2A3For sleeve opening；Correlated characteristic is calculated according to the range formula of point-to-point transmission in plane coordinates The length of line, is denoted as a=| A1A2|, b=| A1A4|, d=| A2A3|。
In step 2, the design process of pattern frame diagram is：
a：The determination of sleeve height value：In the paper pattern design of one sleeve, fit degree and arm and the vertical direction of sleeve Angle α between the two is relevant, sleeve height c0Calculation formula is：
Wherein, AH is that armhole curve is long, and α is sleeve and the angle of vertical direction；
b：Corresponding and pattern frame diagram the design of characteristic curve and controlling position in pattern figure in style figure：In pattern figure In, if each control point is respectively in pattern figure：A′1(x′1,y′1)、A′2(x′2,y′2)、A′3(x′3,y′3)、A′4(x′4,y′4)、 A′5(x′5,y′5), actual sleeve length be in sleeve length and the wide difference of sleeve gram husband, style figure the actual sleeve length a and actual sleeve length t of pattern it Than for k1, obtainObtain remaining controlling position size in pattern figure：
Sleeve mountain oblique line：
Sleeve opening：
Actual sleeve length：|A′1A′2|=t,
Go out pattern frame diagram using above-mentioned size framework.
In step 3, use B-spline curves construct camber line process for：
a：The construction of cap arc line；
In foresleeve mountain oblique line A '1A′41/3rd at take point A '6(x′6,y′6), cross point A '6(x′6,y′6) make A '1A′4 Vertical segment, make | A '6A′7|=d1；Constructed using B-spline curves instrument while crossing point A '1、A′7With A '4Camber line, i.e., For preceding cap arc line；Cap arc line after being constructed using same method；
b：The construction of sleeve seam camber line；
In sleeve length A '1A ' 2 takes point A '11, makeCross point A '11Make A '1A′2Vertical line, Make itself and A '3A′4Meet at point A '8, in line segment A '8A′11On take point A '9, make | A '9A′11|=| A '8A′11| -7mm, i.e., | A '8A′9| =7mm, is constructed using B-spline curves instrument while crossing A '3、A′9With A '4Camber line, as foresleeve seam camber line；Using same Sleeve seam camber line after method construct.
The present invention's is further characterized by,
The process of cap arc line is before being constructed using B-spline curves instrument：
During using cap arc line before B-spline curves instrument construction, mainly there is A ' at the control point of generation4(x′4, y ′4)、With A '1(x′1, y '1), wherein, A′6A′7Extended line on,Crossing point A '1(x′1,y′1) and A '1A′2On vertical horizontal line, then haveControl point WithCoordinate determination process be：
a：Point P is crossed respectively1、P3It is foresleeve mountain oblique line A '1A ' 4 vertical line, vertical point is set to P is obtained according to point-to-point transmission air line distance formula1P′1、P2A′6、P3P′3The distance between, i.e. l1=| P1P′1|, l2=| P2A′6|, l3=| P3P′3|；
If | A '6A′7|=d1, due to P2A′6In A '6A′7Extended line on, P1P′1And P3P′3With A '6A′7It is parallel, ifWill | A '6A′7|=d1Bring into, k ' is tried to achieve respectively1、k′2With k '3, then have l1=| P1P′1|=k '1d1, l2=| P2A′6|=k '2d1, l3=| P3P′3|=k '3d1；
b：Sleeve mountain oblique line length is afterwardsDue to | A '1A′6| length be after tuck inside the sleeve mountain oblique line length three / mono-, thenCross A '6Make parallel to A '4A′5Parallel lines hand over A '1A′2In point O6, according to Δ A '1O6A′6With Δ A′1A′5A′4Similar：
I.e.
Thus solve,Then
c：Obtained by the coordinate of each point | A '1P′3| and | A '1P′1Length value, cross P '3Make parallel to A '4A′5Parallel lines hand over A′1A′2In point O4, cross P '1Make parallel to A '4A′5Parallel lines hand over A '1A′2In point O5, according to Δ A '1O4P′3With Δ A '1A′5A ′4, and Δ A '1O5P′1With Δ A ' 1A '5A′4Similar proportionate relationship, ifSat according to Mark tries to achieve k2And k3Value, obtained by Similar Principle of Triangle：
WillPoint coordinates is brought into, is obtained：
Solve
Similarly have：
WillPoint coordinates is brought into, is obtained：
I.e.
Solve
Respectively willWith It is brought intoWithIn coordinate, obtain
d：Cross P2Make vertical line perpendicular to A '6O6Extended line, hang down point be O2, according to triangle Δ P2O2A′6With Δ A '1A′5A′4It is similar, obtain：
I.e.
Again | P2A′6|=k '2d1, obtain：
Each point coordinate is brought into, that is, solved：
Respectively willWithIt is brought into coordinateIn, obtain
e：Similarly, P is crossed1Make vertical line perpendicular to P '1O5Extended line, hang down point be O1, by Δ P1O1P′1With Δ A '1A′5A′4Phase Seemingly, and P1P′1With A '6A′7Between relation invocation point P1Coordinate value, i.e.,：
Cross P3Make vertical line perpendicular to P '3O4Extended line, hang down point be O3, according to Δ P3O3P′3With Δ A '1A′5A′4It is similar, with And P3P′3With A '6A′7Between relation, invocation point P3Coordinate value, i.e.,：
f：According to gained control point A '4(x′4,y′4)、
And A '1(x′1,y′1) coordinate, utilize B-spline curves approximating method structure Make preceding cap arc line.
Using B-spline curves instrument construct foresleeve seam camber line process be：
During using B-spline curves instrument construction foresleeve seam camber line, mainly there is A ' at the control point of generation4(x′4,y ′4)、With A '3(x′3,y′3), control pointWith The determination process of coordinate is：
a：Make l4=| P5P′5|, l5=| P6A′8|, | A '8A′9|=d2, due to | P5P′5| and | P6A′8| with | A '8A′9| it is flat OK, ifK ' is tried to achieve according to point coordinates4With k '5Value, i.e.,：|P5P′5|= k′4d2, | P6A′8|=k '5d2；
A′8Coordinate be represented byCross A '4Make vertical line perpendicular to A '2A′3Extended line, hang down Point is A '10, separately make A '8A′11Extended line and A '4A′10Meet at point O7, then A '10(x′4,y′2),
By Δ A '4O7A′8With Δ A '4A′10A′3Similar：
I.e.
Solve,Then
Again | P6A′8|=k '5d2, then obtained by proportionate relationship：
WillBring into, solve：
Then
b：IfAccording to Δ A '4P″5P′5With Δ A '4A′10A′3Similar：
I.e.
Solve,
Similarly have：
I.e.
Solve,Produce：
P′5(x′′+k4(x′3-x′4),y′4-k4(y′4-y′10)),
Then P5(x′4+k4(x′3-x′4)+k′4d2,y′4-k4(y′4-y′10))；
c：According to institute invocation point P0(x′4,y′4)、P5(x′4+k4(x′3-x′4)+k′4d2,y′4-k4(y′4-y′10))、Coordinate value, utilize B-spline curves approximating method construction Foresleeve stitches camber line.
The beneficial effects of the invention are as follows using parametric method, realize one sleeve style figure to one a pair of pattern figure It should change；Using curved portion in B-spline curves generation method construction pattern figure, the repetition that works during conventional cardboard is solved The problem of measuring big, low efficiency and not high accuracy.
Brief description of the drawings
Fig. 1 for one sleeve of the present invention style figure to the style figure in the conversion method embodiment of pattern figure；
Fig. 2 for one sleeve of the present invention style figure to the pattern figure in the conversion method embodiment of pattern figure；
Fig. 3 for one sleeve of the present invention style figure into the conversion method of pattern figure the fit degree of sleeve and arm and vertical Nogata is to angled relationships figure between the two；
Fig. 4 for one sleeve of the present invention style figure to the pattern frame diagram in the conversion method embodiment of pattern figure；
Fig. 5 for one sleeve of the present invention style figure into the conversion method pattern figure of pattern figure preceding cap arc line structural map；
Fig. 6 for one sleeve of the present invention style figure into the conversion method pattern figure of pattern figure foresleeve seam camber line structural map；
Fig. 7 pattern figures obtained by the style figure to the conversion method embodiment of pattern figure of one sleeve of the present invention.
Embodiment
The present invention is described in detail with reference to the accompanying drawings and detailed description.
The style figure of one sleeve of the present invention is specifically implemented to the conversion method of pattern figure according to following steps：
Step 1：Choose the key point and characteristic curve in style figure；
Step 2：According to the corresponding relation of controlling position size in the length of characteristic curve in style figure and pattern figure, with reference to seat The distance between 2 points formula in mark system, obtain actual sleeve length in pattern figure, sleeve height, sleeve mountain oblique line, sleeve suture and sleeve opening Length, with reference to crucial point coordinates, design pattern frame diagram；
Step 3：Construct cap arc line and sleeve seam camber line respectively using B-spline curves, the actual sleeve of gained is obtained with reference to step 2 Long, sleeve height and sleeve opening, obtain pattern figure.
The style figure of one sleeve of the present invention is to the conversion method of pattern figure, and Fig. 1 is shirt one sleeve style figure, and Fig. 2 is Fig. 1 The conventional pattern figure of corresponding one sleeve, wherein, | B1B5| represent sleeve height；|B1B2| actual sleeve length is represented, | B1B2|=sleeve length- Gram husband that tucks inside the sleeve is wide；|B1B4| foresleeve mountain oblique line is represented, | B1B4|=preceding AH-5mm；|B1B′4| mountain oblique line of being tucked inside the sleeve after expression, | B1B′4|=after AH-5mm；|B6B′6| sleeve elbow line is represented, its position is that 1/2nd actual sleeve lengths move up 25mm；Cap arc line after expression, Vertically warp 10mm at sleeve mountain oblique line 1/3rd afterwards；Cap arc line before representing, the length of mountain oblique line 1/3rd of being tucked inside the sleeve after taking In on the oblique line of foresleeve mountain, and the vertical and 10mm that warps；WithSleeve suture before and after representing, that is, elbow line of tucking inside the sleeve enters 7mm inward, Wherein AH is armhole arc length.
Shirt basic money of the present invention using specification as 175/92A as embodiment, wherein armhole arc length AH=510mm, Sleeve length is 600mm, and cuff encloses 280mm.Specific implementation step is：
Step 1：The selection of key point and the name of characteristic curve in style figure.The key point in style figure is chosen, is set up Coordinate system, respectively the key point to selection be marked：A1(x1,y1)、A2(x2,y2)、A3(x3,y3)、A4(x4,y4)、A5(x5, y5), cross point A4(x4,y4) make line segment A4A5Make it perpendicular to line segment A1A2, intersection point is A5(x5,y5)；To what is formed between corresponding points Characteristic curve is named, as shown in figure 1, A1A2For actual sleeve length, A1A5For sleeve height, A1A4For sleeve mountain oblique line, A3A4For sleeve seam Line, A2A3For sleeve opening；Recognize that each point coordinates is respectively by software：A1(143.272,178.832), A2(59.738, 142.752)、A3(68.275,120.944)、A4(141.775,137.852) is according to the range formula of point-to-point transmission in plane coordinates The length of correlated characteristic line is calculated, a=is denoted as | A1A2|=90.1mm, b=| A1A4|=41.0mm, d=| A2A3|= 23.4mm。
Step 2：According to the corresponding relation of controlling position size in the length of characteristic curve in style figure and pattern figure, with reference to seat The distance between 2 points formula in mark system, obtain actual sleeve length in pattern figure, sleeve height, sleeve mountain oblique line, sleeve suture and sleeve opening Length, with reference to crucial point coordinates, design pattern frame diagram；
Step 1：The determination of sleeve height value；
In the paper pattern design of one sleeve, the angle α of the fit degree of sleeve with arm and vertical direction between the two has Close, as shown in figure 3, doing vertical line section downwards from shoulder point, make the vertical line segment length beThen sleeve height c0Calculation formula is：
Wherein, AH is that armhole curve is long, and α is sleeve and the angle of vertical direction.
Male money shirt-sleeve and the angle of vertical direction are 20 °, then when α values are 20 °, Therefore the value of the shirt one sleeve sleeve height is
Step 2：Corresponding and pattern frame diagram the design of characteristic curve and controlling position in pattern figure in style figure；
a:In pattern figure, if each control point is respectively in pattern figure：A′1(x′1,y′1)、A′2(x′2,y′2)、A′3(x′3, y′3)、A′4(x′4,y′4)、A′5(x′5,y′5), actual sleeve length is actual sleeve length a in the sleeve length difference wide with sleeve gram husband, style figure It is k with the ratio between the actual sleeve length t of pattern1, obtainThen thus obtain remaining controlling position size and control in pattern figure Point coordinates value processed is：
Sleeve mountain oblique line：
Sleeve opening：
Actual sleeve length：|A′1A′2|=t=60cm-6.50cm=535.00mm
A′1(380.320,574.084), A '2(380.320,39.054), A '3(241.390,39.054), A '4 (152.096,489.080), A '5(380.320,489.080)；
Go out pattern frame diagram using above-mentioned size framework, as shown in Figure 4；
Step 3：Construct cap arc line and sleeve seam camber line respectively using B-spline curves, the actual sleeve of gained is obtained with reference to step 2 Long, sleeve height and sleeve opening, obtain pattern figure.
Step 1：The construction of cap arc line；
As shown in figure 5, in foresleeve mountain oblique line A '1A′41/3rd at take point A '6(x′6,y′6), cross point A '6(x′6,y ′6) make A '1A′4Vertical segment, make | A '6A′7|=10mm；Constructed using B-spline curves instrument while crossing point A '1、A′7With A′4Camber line, be before cap arc line；Cap arc line after being constructed using same method；
During using cap arc line before B-spline curves instrument construction, mainly there is A ' at the control point of generation4(x′4,y ′4)、With A '1(x′1,y′1), wherein, In A '6A′7Extended line on；Crossing point A '1(x′1,y′1) and A '1A′2On vertical horizontal line, i.e.,Control pointWithCoordinate determination process be：
a：Point P is crossed respectively1、P3It is foresleeve mountain oblique line A '1A′4Vertical line, vertical point is set to P is asked according to point-to-point transmission air line distance formula1P′1、P2A′6、P3P′3The distance between, i.e. l1=| P1P′1|=0.17, l2=| P2A′6|=1.46, l3=| P3P′3|=0.59；
If | A '6A′7|=d1, due to P2A′6In A '6A′7Extended line on, P1P′1And P3P′3With A '6A′7It is parallel, ifWill | A '6A′7|=d1=10mm is brought into, is obtained：
Produce l1=| P1P′1|=0.17, l2=| P2A′6|=1.46, l3=| P3P′3|=0.59.
b：Sleeve mountain oblique line length is afterwardsDue to | A '1A′6| length be after tuck inside the sleeve mountain oblique line length three / mono-, thenCross A '6Make parallel to A '4A′5Parallel lines hand over A '1A′2In point O6, according to Δ A '1O6A′6With ΔA′1A′5A′4Similar：
I.e.
Thus solve,Then
Bring related point coordinates into, can A '6(300.327,544.292)；
c：Obtained by the coordinate of each point | A '1P′3| and | A '1P′1Length value, cross P '3Make parallel to A '4A′5Parallel lines hand over A′1A′2In point O4, cross P '1Make parallel to A '4A′5Parallel lines hand over A '1A′2In point O5, according to Δ A '1O4P′3With Δ A '1A′5A ′4, and Δ A '1O5P′1With Δ A '1A′5A′4Similar proportionate relationship, ifThen k2= 0.66, k3=0.06；Obtained by Similar Principle of Triangle：
WillWithPoint coordinates is brought into, is obtained：
Solve
Similarly have：
Solve
Respectively willWith It is brought intoWithIn coordinate, P ' is obtained1(229.708,517.984), P '3(366.628, 568.984)；
d：Cross P2Make vertical line perpendicular to A '6O6Extended line, hang down point be O2, according to triangle Δ P2O2A′6With Δ A '1A′5A′4It is similar, obtain：
I.e.
Again | P2A′6|=l2=1.46d1, obtain
Each point coordinate is brought into, that is, solved：
Respectively willWithIt is brought into seat MarkIn, obtain P2(295.235,557.976)。
e：Similarly, P is crossed1Make vertical line perpendicular to P '1O5Extended line, hang down point be O1, by Δ P1O1P′1With Δ A '1A′5A′4It is similar, and P1P′1With A '6A′7Between relation invocation point P1Coordinate value, i.e., Reference point coordinate value is brought into：P1(229.114,519.577)；
Cross P3Make vertical line perpendicular to P '3O4Extended line, hang down point be O3, and according to Δ P3O3P′3With Δ A '1A′5A′4It is similar, And P3P′3With A '6A′7Between relation, invocation point P3Coordinate value, i.e.,：Meter Calculation result is P3(364.568,574.084)；
f：According to gained control point A '4(152.096,489.080)、P1(229.114,519.577)、P2(295.235, 557.976)、P3(364.568,574.084)、A′1The coordinate of (380.320,574.084), utilizes B-spline curves approximating method Cap arc line before construction.
Step 2：The construction of sleeve seam camber line；
As shown in fig. 6, in sleeve length A '1A′2Take point A '11, makeCross point A '11Make A '1A′2 Vertical line, make itself and A '3A′4Meet at point A '8, in line segment A '8A′11On take point A '9, make | A '9A′11|=| A '8A′11| -7mm, I.e. | A '8A′9|=7mm, constructed using B-spline curves instrument while crossing A '3、A′9With A '4Camber line, as foresleeve seam camber line； Sleeve seam camber line after being constructed using same method；
During using B-spline curves instrument construction foresleeve seam camber line, mainly there is A ' at the control point of generation4(x′4,y ′4)、With A '3(x′3,y′3), control pointWith The determination process of coordinate is：
a：Make l4=| P5P′5|, l5=| P6A′8|, | A '8A′9|=d2, due to | P5P′5| and | P6A′8| with | A′8A′9| it is parallel, thenDependent coordinate point is brought into and can tried to achieve：I.e.：|P5P′5|=0.80d2, | P6A′8|=1.24d2。
A′8Coordinate be represented byCross A '4Make vertical line perpendicular to A '2A′3Extended line, hang down Point is A '10, separately make A '8A′11Extended line and A '4A′10Meet at point O7, then A '10(x′4,y′2),
By Δ A '4O7A′8With Δ A '4A′10A′3Similar：
I.e.
Solve,Then
Reference point coordinate value is brought into, A ' is calculated8 (183.349,331.569)；
Again | P6A′8|=1.24d2, then obtained by proportionate relationship：
Solve：
By x '8=183.349 bring into
ThenCoordinate is determined：P6(192.029,331.569)
b：IfDependent coordinate is brought into and tries to achieve k4=0.16, according to Δ A '4P″5P′5With Δ A '4A′10A′3 It is similar, obtain：
I.e.
Solve,
Similarly have：
I.e.
Solve,Produce：
P′5(x′4+0.16(x′3-x′4),y′4-0.16(y′4-y′10))
Then P5(x′4+0.16(x′3-x′4)+k′4d2,y′4-0.16(y′4-y′10)),
Dependent coordinate is brought into and solves P '5(166.383,417.076), then have P5(171.983,417.076)；
c：According to gained P0(152.096,489.080), P5(171.983,417.076), P6(192.029,331.569), P7The coordinate value of (241.390,39.054), utilizes B-spline curves approximating method construction foresleeve seam camber line；Gained pattern figure, such as Shown in Fig. 7.
Finally, using gained pattern figure, made a plate.
The present invention utilizes parametric method, realizes one sleeve style figure to the one-to-one corresponding transfer problem of pattern figure, no The style figure of one sleeve is only completed to the conversion method of pattern figure, also to realize garment fashion drawing to the automatic conversion of pattern figure There is provided a kind of new approaches, meanwhile, the problem of repetition amount is big, efficiency is low that work during conventional graphic arts is solved, to realize clothes The intellectuality of dress plate-making provides a kind of new method.

Claims (2)

1. the style figure of one sleeve is to the conversion method of pattern figure, it is characterised in that specifically implement according to following steps：
Step 1：Choose the key point and characteristic curve in style figure；
Wherein, the mark of key point and the name process of characteristic curve are in style figure：
a：Sleeve length, sleeve mountain oblique line, sleeve suture and sleeve opening line segment end points are as key point using in one sleeve, the company between corresponding points Line is used as characteristic curve；
b：The key point to selection is marked respectively：A1(x1,y1)、A2(x2,y2)、A3(x3,y3)、A4(x4,y4), cross point A4 (x4,y4) make line segment A4A5Make it perpendicular to line segment A1A2, intersection point is A5(x5,y5)；
c：The characteristic curve formed between corresponding points is named, A1A2For actual sleeve length, A1A5For sleeve height, A1A4It is oblique for sleeve mountain Line, A3A4For sleeve suture, A2A3For sleeve opening；Correlated characteristic line is calculated according to the range formula of point-to-point transmission in plane coordinates Length, is denoted as a=| A1A2|, b=| A1A4|, d=| A2A3|；
Step 2：According to the corresponding relation of controlling position size in the length of characteristic curve in style figure and pattern figure, with reference to coordinate system In the distance between 2 points formula, obtain actual sleeve length in pattern figure, sleeve height, sleeve mountain oblique line, sleeve suture and sleeve opening length Degree, with reference to crucial point coordinates, designs pattern frame diagram；
Wherein, the design process of pattern frame diagram is：
Step 2.1：The determination of sleeve height value：In the paper pattern design of one sleeve, fit degree and arm and the Vertical Square of sleeve It is relevant to angle α between the two, sleeve height c0Calculation formula is：
<mrow> <msub> <mi>c</mi> <mn>0</mn> </msub> <mo>=</mo> <mfrac> <mrow> <mi>A</mi> <mi>H</mi> </mrow> <mn>2</mn> </mfrac> <mo>&amp;times;</mo> <mi>s</mi> <mi>i</mi> <mi>n</mi> <mi>&amp;alpha;</mi> <mo>,</mo> </mrow>
Wherein, AH is that armhole curve is long, and α is sleeve and the angle of vertical direction；
Step 2.2：Corresponding and pattern frame diagram the design of characteristic curve and controlling position in pattern figure in style figure：In pattern figure In, if each control point is respectively in pattern figure：A′1(x′1,y′1)、A′2(x′2,y′2)、A′3(x′3,y′3)、A′4(x′4,y′4)、 A′5(x′5,y′5), actual sleeve length be in sleeve length and the wide difference of sleeve gram husband, style figure the actual sleeve length a and actual sleeve length t of pattern it Than for k1, obtainObtain remaining controlling position size in pattern figure：
Sleeve mountain oblique line：
Sleeve opening：
Actual sleeve length：|A′1A′2|=t,
Go out pattern frame diagram using above-mentioned size framework；
Step 3：Construct cap arc line and sleeve seam camber line, actual sleeve length, sleeve with reference to obtained by step 2 respectively using B-spline curves Mountain height and sleeve opening, obtain pattern figure；
Wherein, use B-spline curves construct camber line process for：
Step 3.1：The construction of cap arc line；
In foresleeve mountain oblique line A '1A′41/3rd at take point A '6(x′6,y′6), cross point A '6(x′6,y′6) make A '1A′4It is vertical Line segment, makes | A '6A′7|=d1；Constructed using B-spline curves instrument while crossing point A '1、A′7With A '4Camber line, as foresleeve Mountain camber line；Cap arc line after being constructed using same method；
Step 3.2：The construction of sleeve seam camber line；
In sleeve length A '1A′2Take point A '11, makeCross point A '11Make A '1A′2Vertical line, make its with A′3A′4Meet at point A '8, in line segment A '8A′11On take point A '9, make | A '9A′11|=| A '8A′11| -7mm, i.e., | A '8A′9|=7mm, Constructed using B-spline curves instrument while crossing A '3、A′9With A '4Camber line, as foresleeve seam camber line；Utilize same method structure Sleeve seam camber line after making；
Wherein, the process of cap arc line is before described utilization B-spline curves instrument construction：
During using cap arc line before B-spline curves instrument construction, mainly there is A ' at the control point of generation4(x′4,y′4)、With A '1(x′1,y′1), wherein,In A '6A′7Extended line on,Crossing point A '1(x′1,y′1) and A '1A′2On vertical horizontal line, then haveControl pointWithCoordinate determination process be：
a：Point P is crossed respectively1、P3It is foresleeve mountain oblique line A '1A′4Vertical line, vertical point is set to P is obtained according to point-to-point transmission air line distance formula1P1′、P2A′6、P3P′3The distance between, i.e. l1=| P1P1' |, l2=| P2A′6|, l3=| P3P′3|；
If | A '6A′7|=d1, due to P2A′6In A '6A′7Extended line on, P1P′1And P3P′3With A '6A′7It is parallel, ifWill | A '6A′7|=d1Bring into, k ' is tried to achieve respectively1、k′2With k '3, then have l1=| P1P1' |=k '1d1, l2=| P2A′6|=k '2d1, l3=| P3P3' |=k '3d1；
b：Sleeve mountain oblique line length is afterwardsDue to | A '1A′6| length be after sleeve mountain oblique line length three/ One, thenCross A '6Make parallel to A '4A′5Parallel lines hand over A '1A′2In point O6, according to Δ A '1A′5A′4With Δ A '1A′5A′4Similar：
<mrow> <mfrac> <mrow> <mo>|</mo> <msubsup> <mi>A</mi> <mn>1</mn> <mo>&amp;prime;</mo> </msubsup> <msub> <mi>O</mi> <mn>6</mn> </msub> <mo>|</mo> </mrow> <mrow> <mo>|</mo> <msubsup> <mi>A</mi> <mn>1</mn> <mo>&amp;prime;</mo> </msubsup> <msubsup> <mi>A</mi> <mn>5</mn> <mo>&amp;prime;</mo> </msubsup> <mo>|</mo> </mrow> </mfrac> <mo>=</mo> <mfrac> <mrow> <mo>|</mo> <msubsup> <mi>A</mi> <mn>6</mn> <mo>&amp;prime;</mo> </msubsup> <msub> <mi>O</mi> <mn>6</mn> </msub> <mo>|</mo> </mrow> <mrow> <mo>|</mo> <msubsup> <mi>A</mi> <mn>4</mn> <mo>&amp;prime;</mo> </msubsup> <msubsup> <mi>A</mi> <mn>5</mn> <mo>&amp;prime;</mo> </msubsup> <mo>|</mo> </mrow> </mfrac> <mo>=</mo> <mfrac> <mrow> <mo>|</mo> <msubsup> <mi>A</mi> <mn>1</mn> <mo>&amp;prime;</mo> </msubsup> <msubsup> <mi>A</mi> <mn>6</mn> <mo>&amp;prime;</mo> </msubsup> <mo>|</mo> </mrow> <mrow> <mo>|</mo> <msubsup> <mi>A</mi> <mn>1</mn> <mo>&amp;prime;</mo> </msubsup> <msubsup> <mi>A</mi> <mn>4</mn> <mo>&amp;prime;</mo> </msubsup> <mo>|</mo> </mrow> </mfrac> <mo>=</mo> <mfrac> <mrow> <mi>a</mi> <mi>q</mi> </mrow> <mrow> <mn>3</mn> <mi>t</mi> <mi>b</mi> </mrow> </mfrac> <mo>,</mo> </mrow>
I.e.
Thus solve,Remember m=x '5-x′4,Then
c：Obtained by the coordinate of each point | A '1P′3| and | A '1P′1| length value, cross P3' make parallel to A '4A′5Parallel lines hand over A '1A′2In point O4, cross P1' make parallel to A '4A′5Parallel lines hand over A '1A′2In point O5, according to Δ A '1O4P′3With Δ A '1A′5A′4, And Δ A '1O5P′1With Δ A '1A′5A′4Similar proportionate relationship, ifAsked according to point coordinates Obtain k2And k3Value, obtained by Similar Principle of Triangle：
<mrow> <msub> <mi>k</mi> <mn>2</mn> </msub> <mo>=</mo> <mfrac> <mrow> <mo>|</mo> <msubsup> <mi>A</mi> <mn>1</mn> <mo>&amp;prime;</mo> </msubsup> <msubsup> <mi>P</mi> <mn>1</mn> <mo>&amp;prime;</mo> </msubsup> <mo>|</mo> </mrow> <mrow> <mo>|</mo> <msubsup> <mi>A</mi> <mn>1</mn> <mo>&amp;prime;</mo> </msubsup> <msubsup> <mi>A</mi> <mn>4</mn> <mo>&amp;prime;</mo> </msubsup> <mo>|</mo> </mrow> </mfrac> <mo>=</mo> <mfrac> <mrow> <mo>|</mo> <msubsup> <mi>P</mi> <mn>1</mn> <mo>&amp;prime;</mo> </msubsup> <msub> <mi>O</mi> <mn>5</mn> </msub> <mo>|</mo> </mrow> <mrow> <mo>|</mo> <msubsup> <mi>A</mi> <mn>4</mn> <mo>&amp;prime;</mo> </msubsup> <msubsup> <mi>A</mi> <mn>5</mn> <mo>&amp;prime;</mo> </msubsup> <mo>|</mo> </mrow> </mfrac> <mo>=</mo> <mfrac> <mrow> <mo>|</mo> <msubsup> <mi>A</mi> <mn>1</mn> <mo>&amp;prime;</mo> </msubsup> <msub> <mi>O</mi> <mn>5</mn> </msub> <mo>|</mo> </mrow> <mrow> <mo>|</mo> <msubsup> <mi>A</mi> <mn>1</mn> <mo>&amp;prime;</mo> </msubsup> <msubsup> <mi>A</mi> <mn>5</mn> <mo>&amp;prime;</mo> </msubsup> <mo>|</mo> </mrow> </mfrac> <mo>,</mo> </mrow> 2
WillWithPoint coordinates is brought into, is obtained：
<mrow> <msub> <mi>k</mi> <mn>2</mn> </msub> <mo>=</mo> <mfrac> <mrow> <msubsup> <mi>x</mi> <mn>1</mn> <mo>&amp;prime;</mo> </msubsup> <mo>-</mo> <msubsup> <mi>x</mi> <msub> <mi>p</mi> <mn>1</mn> </msub> <mo>&amp;prime;</mo> </msubsup> </mrow> <mrow> <msubsup> <mi>x</mi> <mn>1</mn> <mo>&amp;prime;</mo> </msubsup> <mo>-</mo> <msubsup> <mi>x</mi> <mn>4</mn> <mo>&amp;prime;</mo> </msubsup> </mrow> </mfrac> <mo>=</mo> <mfrac> <mrow> <msubsup> <mi>y</mi> <mn>1</mn> <mo>&amp;prime;</mo> </msubsup> <mo>-</mo> <msubsup> <mi>y</mi> <msub> <mi>p</mi> <mn>1</mn> </msub> <mo>&amp;prime;</mo> </msubsup> </mrow> <mrow> <msubsup> <mi>y</mi> <mn>1</mn> <mo>&amp;prime;</mo> </msubsup> <mo>-</mo> <msubsup> <mi>y</mi> <mn>5</mn> <mo>&amp;prime;</mo> </msubsup> </mrow> </mfrac> <mo>,</mo> </mrow>
Solve
Similarly have：
<mrow> <msub> <mi>k</mi> <mn>3</mn> </msub> <mo>=</mo> <mfrac> <mrow> <mo>|</mo> <msubsup> <mi>A</mi> <mn>1</mn> <mo>&amp;prime;</mo> </msubsup> <msubsup> <mi>P</mi> <mn>3</mn> <mo>&amp;prime;</mo> </msubsup> <mo>|</mo> </mrow> <mrow> <mo>|</mo> <msubsup> <mi>A</mi> <mn>1</mn> <mo>&amp;prime;</mo> </msubsup> <msubsup> <mi>A</mi> <mn>4</mn> <mo>&amp;prime;</mo> </msubsup> <mo>|</mo> </mrow> </mfrac> <mo>=</mo> <mfrac> <mrow> <mo>|</mo> <msubsup> <mi>P</mi> <mn>3</mn> <mo>&amp;prime;</mo> </msubsup> <msub> <mi>O</mi> <mn>4</mn> </msub> <mo>|</mo> </mrow> <mrow> <mo>|</mo> <msubsup> <mi>A</mi> <mn>4</mn> <mo>&amp;prime;</mo> </msubsup> <msubsup> <mi>A</mi> <mn>5</mn> <mo>&amp;prime;</mo> </msubsup> <mo>|</mo> </mrow> </mfrac> <mo>=</mo> <mfrac> <mrow> <mo>|</mo> <msubsup> <mi>A</mi> <mn>1</mn> <mo>&amp;prime;</mo> </msubsup> <msub> <mi>O</mi> <mn>4</mn> </msub> <mo>|</mo> </mrow> <mrow> <mo>|</mo> <msubsup> <mi>A</mi> <mn>4</mn> <mo>&amp;prime;</mo> </msubsup> <msubsup> <mi>A</mi> <mn>5</mn> <mo>&amp;prime;</mo> </msubsup> <mo>|</mo> </mrow> </mfrac> <mo>,</mo> </mrow>
I.e.
Solve
Respectively willWithIt is brought intoWithIn coordinate, P is obtained1′(x′1-k2m,y′1-k2c0), P3′(x′1-k3m,y′1-k3c0)；
d：Cross P2Make vertical line perpendicular to A '6O6Extended line, hang down point be O2, according to triangle Δ P2O2A′6With Δ A '1A′5A′4Phase Seemingly, obtain：
<mrow> <mfrac> <mrow> <mo>|</mo> <msub> <mi>P</mi> <mn>2</mn> </msub> <msub> <mi>O</mi> <mn>2</mn> </msub> <mo>|</mo> </mrow> <mrow> <mo>|</mo> <msubsup> <mi>A</mi> <mn>6</mn> <mo>&amp;prime;</mo> </msubsup> <msub> <mi>O</mi> <mn>2</mn> </msub> <mo>|</mo> </mrow> </mfrac> <mo>=</mo> <mfrac> <mrow> <mo>|</mo> <msubsup> <mi>A</mi> <mn>4</mn> <mo>&amp;prime;</mo> </msubsup> <msubsup> <mi>A</mi> <mn>5</mn> <mo>&amp;prime;</mo> </msubsup> <mo>|</mo> </mrow> <mrow> <mo>|</mo> <msubsup> <mi>A</mi> <mn>1</mn> <mo>&amp;prime;</mo> </msubsup> <msubsup> <mi>A</mi> <mn>5</mn> <mo>&amp;prime;</mo> </msubsup> <mo>|</mo> </mrow> </mfrac> <mo>,</mo> </mrow>
I.e.
Again | P2A′6|=k '2d1, obtain：
<mrow> <msup> <mrow> <mo>(</mo> <msub> <mi>y</mi> <msub> <mi>p</mi> <mn>2</mn> </msub> </msub> <mo>-</mo> <msubsup> <mi>y</mi> <mn>6</mn> <mo>&amp;prime;</mo> </msubsup> <mo>)</mo> </mrow> <mn>2</mn> </msup> <mo>+</mo> <msup> <mrow> <mo>(</mo> <msub> <mi>x</mi> <msub> <mi>p</mi> <mn>2</mn> </msub> </msub> <mo>-</mo> <msubsup> <mi>x</mi> <mn>6</mn> <mo>&amp;prime;</mo> </msubsup> <mo>)</mo> </mrow> <mn>2</mn> </msup> <mo>=</mo> <msup> <mrow> <mo>(</mo> <msubsup> <mi>k</mi> <mn>2</mn> <mo>&amp;prime;</mo> </msubsup> <msub> <mi>d</mi> <mn>1</mn> </msub> <mo>)</mo> </mrow> <mn>2</mn> </msup> <mo>,</mo> </mrow>
Each point coordinate is brought into, that is, solved：
<mrow> <msub> <mi>x</mi> <msub> <mi>p</mi> <mn>2</mn> </msub> </msub> <mo>=</mo> <msubsup> <mi>x</mi> <mn>5</mn> <mo>&amp;prime;</mo> </msubsup> <mo>-</mo> <mfrac> <mrow> <mi>a</mi> <mi>q</mi> <mi>m</mi> </mrow> <mrow> <mn>3</mn> <mi>t</mi> <mi>b</mi> </mrow> </mfrac> <mo>-</mo> <mfrac> <mrow> <msubsup> <mi>ak</mi> <mn>2</mn> <mo>&amp;prime;</mo> </msubsup> <msub> <mi>d</mi> <mn>1</mn> </msub> <msub> <mi>c</mi> <mn>0</mn> </msub> </mrow> <mrow> <mi>t</mi> <mi>b</mi> </mrow> </mfrac> <mo>,</mo> </mrow>
<mrow> <msub> <mi>y</mi> <msub> <mi>p</mi> <mn>2</mn> </msub> </msub> <mo>=</mo> <msubsup> <mi>y</mi> <mn>1</mn> <mo>&amp;prime;</mo> </msubsup> <mo>-</mo> <mfrac> <mrow> <msub> <mi>aqc</mi> <mn>0</mn> </msub> </mrow> <mrow> <mn>3</mn> <mi>t</mi> <mi>b</mi> </mrow> </mfrac> <mo>+</mo> <mfrac> <mrow> <msubsup> <mi>amk</mi> <mn>2</mn> <mo>&amp;prime;</mo> </msubsup> <msub> <mi>d</mi> <mn>1</mn> </msub> </mrow> <mrow> <mi>t</mi> <mi>b</mi> </mrow> </mfrac> <mo>,</mo> </mrow>
Respectively willWithIt is brought into coordinate In, obtain
e：Similarly, P is crossed1Make vertical line perpendicular to P1′O5Extended line, hang down point be O1, by Δ P1O1P′1With Δ A '1A′5A′4It is similar, with And P1P1' and A '6A′7Between relation invocation point P1Coordinate value, i.e.,：
Cross P3Make vertical line perpendicular to P '3O4Extended line, hang down point be O3, according to Δ P3O3P′3With Δ A '1A′5A′4It is similar, and P3P3' and A '6A′7Between relation, invocation point P3Coordinate value, i.e.,：
f：According to gained control point A '4(x′4,y′4)、 And A '1 (x′1,y′1) coordinate, utilize B-spline curves approximating method construction before cap arc line.
2. the style figure of one sleeve according to claim 1 is to the conversion method of pattern figure, it is characterised in that described profit With B-spline curves instrument construct foresleeve seam camber line process be：
During using B-spline curves instrument construction foresleeve seam camber line, mainly there is A ' at the control point of generation4(x′4,y′4)、With A '3(x′3,y′3), control pointWithCoordinate Determination process be：
a：Make l4=| P5P′5|, l5=| P6A′8|, | A '8A′9|=d2, due to | P5P′5| and | P6A′8| with | A '8A′9| it is parallel, thenK ' is tried to achieve according to point coordinates4With k '5Value, i.e.,：|P5P′5|=k '4d2, |P6A′8|=k '5d2；
A′8Coordinate be A '8(x′8, y '8), wherein,Cross A '4Make vertical line perpendicular to A '2A′3Extended line, The point that hangs down is A '10(x′10, y '10), separately make A '8A′11Extended line and A '4A′10Meet at point O7, then x '10=x '4, y '10=y '2,
By Δ A '4O7A′8With Δ A '4A′10A′3Similar：
<mrow> <mfrac> <mrow> <mo>|</mo> <msub> <mi>O</mi> <mn>7</mn> </msub> <msubsup> <mi>A</mi> <mn>8</mn> <mo>&amp;prime;</mo> </msubsup> <mo>|</mo> </mrow> <mrow> <mo>|</mo> <msubsup> <mi>A</mi> <mn>3</mn> <mo>&amp;prime;</mo> </msubsup> <msubsup> <mi>A</mi> <mn>10</mn> <mo>&amp;prime;</mo> </msubsup> <mo>|</mo> </mrow> </mfrac> <mo>=</mo> <mfrac> <mrow> <mo>|</mo> <msubsup> <mi>A</mi> <mn>4</mn> <mo>&amp;prime;</mo> </msubsup> <msub> <mi>O</mi> <mn>7</mn> </msub> <mo>|</mo> </mrow> <mrow> <mo>|</mo> <msubsup> <mi>A</mi> <mn>4</mn> <mo>&amp;prime;</mo> </msubsup> <msubsup> <mi>A</mi> <mn>10</mn> <mo>&amp;prime;</mo> </msubsup> <mo>|</mo> </mrow> </mfrac> <mo>,</mo> </mrow>
I.e.
Solve,ThenAgain | P6A′8|=k '5d2, then obtained by proportionate relationship：
<mrow> <msub> <mi>x</mi> <msub> <mi>p</mi> <mn>6</mn> </msub> </msub> <mo>-</mo> <msubsup> <mi>x</mi> <mn>8</mn> <mo>&amp;prime;</mo> </msubsup> <mo>=</mo> <msubsup> <mi>k</mi> <mn>5</mn> <mo>&amp;prime;</mo> </msubsup> <msub> <mi>d</mi> <mn>2</mn> </msub> <mo>,</mo> </mrow>
WillBring into, solve：Then
b：IfAccording to Δ A '4P″5P′5With Δ A '4A′10A′3Similar：
<mrow> <msub> <mi>k</mi> <mn>4</mn> </msub> <mo>=</mo> <mfrac> <mrow> <mo>|</mo> <msubsup> <mi>P</mi> <mn>5</mn> <mrow> <mo>&amp;prime;</mo> <mo>&amp;prime;</mo> </mrow> </msubsup> <msubsup> <mi>P</mi> <mn>5</mn> <mo>&amp;prime;</mo> </msubsup> <mo>|</mo> </mrow> <mrow> <mo>|</mo> <msubsup> <mi>A</mi> <mn>3</mn> <mo>&amp;prime;</mo> </msubsup> <msubsup> <mi>A</mi> <mn>10</mn> <mo>&amp;prime;</mo> </msubsup> <mo>|</mo> </mrow> </mfrac> <mo>=</mo> <mfrac> <mrow> <mo>|</mo> <msubsup> <mi>A</mi> <mn>4</mn> <mo>&amp;prime;</mo> </msubsup> <msubsup> <mi>P</mi> <mn>5</mn> <mo>&amp;prime;</mo> </msubsup> <mo>|</mo> </mrow> <mrow> <mo>|</mo> <msubsup> <mi>A</mi> <mn>3</mn> <mo>&amp;prime;</mo> </msubsup> <msubsup> <mi>A</mi> <mn>4</mn> <mo>&amp;prime;</mo> </msubsup> <mo>|</mo> </mrow> </mfrac> <mo>,</mo> </mrow>
I.e.
Solve,
Similarly have：
<mrow> <msub> <mi>k</mi> <mn>4</mn> </msub> <mo>=</mo> <mfrac> <mrow> <mo>|</mo> <msubsup> <mi>A</mi> <mn>4</mn> <mo>&amp;prime;</mo> </msubsup> <msubsup> <mi>P</mi> <mn>5</mn> <mrow> <mo>&amp;prime;</mo> <mo>&amp;prime;</mo> </mrow> </msubsup> <mo>|</mo> </mrow> <mrow> <mo>|</mo> <msubsup> <mi>A</mi> <mn>4</mn> <mo>&amp;prime;</mo> </msubsup> <msubsup> <mi>A</mi> <mn>10</mn> <mo>&amp;prime;</mo> </msubsup> <mo>|</mo> </mrow> </mfrac> <mo>=</mo> <mfrac> <mrow> <mo>|</mo> <msubsup> <mi>A</mi> <mn>4</mn> <mo>&amp;prime;</mo> </msubsup> <msubsup> <mi>P</mi> <mn>5</mn> <mo>&amp;prime;</mo> </msubsup> <mo>|</mo> </mrow> <mrow> <mo>|</mo> <msubsup> <mi>A</mi> <mn>3</mn> <mo>&amp;prime;</mo> </msubsup> <msubsup> <mi>A</mi> <mn>4</mn> <mo>&amp;prime;</mo> </msubsup> <mo>|</mo> </mrow> </mfrac> <mo>,</mo> </mrow>
I.e.
Solve,Produce：
P5′(x′4+k4(x′3-x′4),y′4-k4(y′4-y′10)),
Then P5(x′4+k4(x′3-x′4)+k′4d2,y′4-k4(y′4-y′10))；
c：According to institute invocation point P0(x′4,y′4)、P5(x′4+k4(x′3-x′4)+k′4d2,y′4-k4(y′4-y′10))、Coordinate value, utilize B-spline curves approximating method construction Foresleeve stitches camber line.
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