WO2019240599A1

WO2019240599A1 - Redouble the power by the electric motors and hydraulic pistons

Info

Publication number: WO2019240599A1
Application number: PCT/OM2018/050010
Authority: WO
Inventors: Fouad AL-QUWAITAI
Original assignee: Al Quwaitai Fouad
Priority date: 2018-06-13
Filing date: 2018-10-26
Publication date: 2019-12-19
Also published as: WO2019239188A1; WO2019239207A1

Abstract

Redouble the power be electric motor which give the system power, then this motor will make the gearbox rotate, then this gearbox will reduce the rotation speed of the electric motor to by slow rotation speed in output axis of the gearbox with high torque, then the output axis of this gearbox will make the pinion rack system move, then this system will move linear slowly 2mm/s with high power and will push the rod of the hydraulic piston (driver piston), this piston will start push oil to another piston called driven piston, the diameter of the driver piston is smaller diameter of the driven piston 10 times, so the driven piston will be stronger than driver piston 100 times. The driven piston which connect to the driver piston is unidirectional piston with one rod, and there are 199 driven pistons, each driven piston of them is bidirectional piston with two rods for each one. We put the 200 driven pistons on horizontally line and we connect the rod of the first driven piston to the first rod of the second driven piston, then we connect the second rod of the second driven piston to the first rod of the third driven piston, then we connect the second rod of the third driven piston to the first rod of the fourth driven piston, then we connect the second rod of the fourth driven piston to the first rod of the fifth driven piston etc. So it is clear, the 200 driven pistons connect each other by their rods one by one until the last driven piston on the driven pistons line, that is mean, the first rod of the 198th driven piston connect to the second rod of the 197th driven piston, and the second rod of the 198th driven piston connect to the first rod of the 199th driven piston, and the second rod of the 199th driven piston connect to the rod of the last driven piston number 200, and this one in unidirectional piston with one rod. So when the electric motor start rotating the driver piston will move slowly but with high power, then it is will push oil to the first driven piston, because the driven piston is bigger than driver piston 10 times so the it is will be stronger than it 100 times, then the first driven piston will move with doubled power 100 times and will push the 199 driven pistons then all of them will push oil to the collector, then oil will move from this collector to the hydraulic motor, so this motor will start rotate and will make the generator rotate and produce electricity more than 1 GW.

Description

FIRST METHOD:

REDOUBLE THE POWER BY THE ELECTRIC MOTORS AND HYDRAULIC

PISTONS

- There are two systems work together, one is system A, second is

system B, each system has it is tools and devices which we will explain in this research.

- Two electric motors 10 MW for each one, one is for system A, second for system B.

- One 15 MW lithium battery for give the system power at the first time, then the system will supply itself by power, so this battery will stop supply the electric motor by electricity after the system start working.

- Two gearboxes for reduce rotation speed for make high torque, one is for system A, second for system B, and these gearboxes called main gearboxes, the input axis of each gearbox connect to one electric motor and the output axis of each gearbox connect to a pinion rack system for convert the rotation movement of the main gearbox to the linear one for push the driver piston.

Two hydraulic pistons (driver pistons), each driver piston with lm dimeter, 5 m length, 1 m thickness, unidirectional piston with one rod for each one, the capacity of each piston is 3926.5 liters, these pistons called (driver pistons).

- Each piston of the driver pistons with one input/output connect to other hydraulic cylinder (driven piston) bigger than driver piston, so the driver piston will push oil to the driven piston.

The driver piston will be moved by the pinion rack system which connect to the output axis of the main gearbox, then will convert the rotation movement of the main gearbox to be linear one to push the driver piston.

- 400 hydraulic pistons, 200 for system A, and 200 for system B, each one with 10 m diameter, 5 cm length, each one called (DRIVEN PISTON)

- 198 of A's 200 driven pistons are bidirectional pistons with tow rods for each one, each rod of each one move just for 5cm, same logic for the 200 driven pistons of system B, 198 driven pistons are bidirectional pistons with two rods for each one.

- When we said the length of the driven piston 5cm, we mean it is moving rod move for 5cm. - Two driven pistons of A's 200 driven pistons are unidirectional pistons with one rod for each one, same logic for B's 200 driven pistons, there are two pistons of the B's 200 driven pistons are unidirectional pistons with one rod for each one.

- So, A's 200 driven pistons including 198 bidirectional pistons with two rods and two unidirectional pistons with one rod for each one, same logic for the 200 driven pistons of B.

- We put the 200 driven pistons of A in one line, and we out the 200 driven pistons of B in one line too.

- We put one of the two unidirectional driven pistons on the front of the pistons line, it is will be the first driven piston, 5cm after first unidirectional driven piston we put the second driven piston, the second one is bidirectional piston with two rods, the driven pistons from number 2 to number 199 in each line are bidirectional pistons with two rods for each one, so, we connect the rod of the first unidirectional driven piston to the first rod of the second bidirectional driven piston, then 5cm after second driven piston on the pistons line we put the third driven piston and we connect the second rod of the second driven piston to the first rod of the third driven piston, then 5cm after we put the fourth driven piston and we connect the second rod of the third driven piston to the first rod of the fourth driven piston, then 5cm after we put the fifth driven piston and we connect the second rod of the fourth driven piston to the first rod of the fifth driven piston, so, it is clear, all driven pistons on the line connect each other by their rods one by one until the last one number 200 which connect to the second rod of the 199^th driven piston on the line as we explained here, first driven piston connect to the second driven piston, second one connect to the third one... 20^th driven piston connect by the first rod to the second rod of the 19^th driven piston and connect by the second rod to the first rod of the 21^th driven piston, first rod of the 85^th driven piston connect to the second rod of the 84^th driven piston and second rod of the 85^th driven piston connect to the first rod of the 86^th driven piston... first rod of the 199^th driven piston connect to the second rod of the 198^th driven piston and second rod of the 199^th driven piston connect to the rod of the last unidirectional driven piston on the driven pistons line number 200 etc....

So, when the system push oil from the driver piston to the first unidirectional driven piston, this piston will start move, then it is rod will move out too, so it is will push the first rod of the second bidirectional driven piston which connect with, so the second driven piston will start move and push oil, then the first rod of the second driven piston will push the second rod of the second driven piston, so, this rod will push the first rod of the third driven piston, so the third driven piston will start move in same time with first and second driven pistons, so, it is will start push oil, then the second rod of the third driven piston will move out and will push the first rod of the fourth driven piston ... etc.

So, by this way all the 200 driven pistons on the pistons line will push each other until the last driven piston, the second rod of the 198^th driven piston will push the first rod of the 199^th driven piston, then the second rod of the 199^th driven piston will push the rod of the last driven piston, the last driven piston is unidirectional piston with one rod connect with the second rod of the 199^th driven piston.

All the 200 driven pistons will push each other in same time, same flow, same pressure to the main collector.

Each driven piston connects by steel pipe to one collector, this collector called main collector.

Same logic for B's driven pistons until the last driven piston on the line, so, each line of driven pistons has 200 driven pistons pushing each other when the first driven piston start moves and push the second driven piston.

- There is 5cm distance between driven piston and next one, for that, each rod of each driven pistons will move just for 5 cm.

- Each driven piston with about 3926 liters.

- System A has one line of 200 driven pistons, system B has one line of 200 driven pistons, each line of driven piston has 785200 liters.

The first driven piston is a unidirectional piston with one rod connected to the first rod of the second driven piston, the second rod of the second driven piston is connected to the first rod of the third driven piston, etc. First and last driven pistons are unidirectional piston with one rod for each one, the rod of the last driven piston connected to the second rod of the 199^th driven piston on pistons line.

- One line of the two driven pistons is for system A and one line is for system B. - The first side of the first driven piston has one inputs/outputs, connects by steel pipe to the input/output of the driver piston, the second side of the first driven piston has one input/output connects by steel pipe to the main collector.

- One driver piston for one line of 200 driven pistons, so, one driver piston in system A for one line of 200 driven pistons in same system, and one driver piston in system B for one line of 200 driven pistons, so we have 400 driven pistons in all the system.

- Each piston of the other driven pistons on the second side of each one has one input/output connect by steel pipe to the main collector, just the first driven piston on the first side of it has one inputs/output connect to the driver piston and one input/output on the second side connected to the main collector.

- There is one hydraulic motor with two inputs and two outputs.

- Two main collectors for driven pistons, one collector for system A, second collector is for system B.

- The A's main collectors has 202 inputs/outputs, first input/output in A's main collector is from A's main collector to the first input of the hydraulic motor, second one is from A's main collector to the hydraulic pump, and one input/output of the rest 200 input/outputs in A's main collector for each driven piston of system A, that is mean there is one input/output in A's main collector connect for one driven piston of A's 200 driven pistons, each input/output has switch valve.

- The B's main collectors has 202 inputs/outputs, same logic in A's main collector, first input/output in B's main collector is from B's main collector to the second input of the hydraulic motor, second one is from B's main collector to the hydraulic pump, and one input/output of the rest 200 input/outputs in B's main collector for each driven piston of system B.

The output of the main collector which connect to the hydraulic motor has switch valve for open or close it, the input of the main collector which connect to the pump has one switch valve for open or close it.

Each input/output of the 200 input/outputs in the main collector which connect to driven pistons has one switch valve with check valve for each one.

- When the main collector's output's which connect to the hydraulic motor is open for push oil to the hydraulic motor, the input of the main collector which connect to the pump will be closed, and when the input is open for push oil from the pump to the main collector then to the driven pistons the output of the main collector which connect to the hydraulic motor will be closed by sensor.

- When the pump push oil to the main collector, oil will flow from the main collector by the switch valves to each piston of the 200 driven pistons to make them full of oil, the first driven piston will receive oil from the second input/output in the second side of it, then oil in the first side of the first driven piston which came from driver piston will move out from the first input/output in the first side of the first driven piston to the driver piston for make it full of oil again when the system stop working, we said the driver piston is connected directly to the first driven piston by the first input/output of the first driven piston.

How this invention work?

THE PHYSICS RULE SAYS: WHEN WE REDUCE HIGH SPEED ROTATION OF AN ELECTRIC MOTOR BY GEARBOX, WE WILL GET HIGH TORQUE IN OUTPUT'S AXIS OF THIS GEARBOX.

ANOTHER PHYSICS RULE SAYS: IF THE DIMETER OF THE MASTER PISTON (DRIVER PISTON) SMALLER THEN DIMETER OF THE SLAVE PISTON 10 TIMES, THE POWER OF THE SLAVE PISTON WILL BE STRONGER THAN MASTER PISTON 100 TIMES WHEN THE MASTER PISTON (DRIVER PISTON) PUSH OIL TO THE SLAVE PISTON (DRIVEN PISTON)

SO, WE WILL USE THESE TWO PHYSICS RULES TOGETHER FOR REDOUBLE THE PWOER.

When we connect the output's axis of the electric motor to the input's axis of the main gearbox, this gearbox will reduce the high rotation speed of the electric motor to get high torque in output's axis of the gearbox, so, by this way we can make the driver piston move slowly but very strong so, it is will push oil with very high power.

The rod of each driver piston connects to pinion rack system for make it move linear, and this system connect to the output axis of the gearbox, so, when the electric motor start rotating, the gearbox will rotate too, then it is will reduce the rotation speed to be slow rotation with high torque in output axis of the gearbox, then the pinion rack system which connect to the output axis of the gearbox will start move linear in same power of the gearbox, so it is will push the rod of the driver piston.

As we said before, the 200 driven pistons on each driven pistons line pushing each other and push oil to the main collector.

The specification of the bidirectional driven pistons is they bi-stroke on one side, so when we relate the first unidirectional driven piston to the second bidirectional driven piston by the rod of the first driven piston and first rod of second driven piston and push the rod of the unidirectional first driven piston, this rod will push the first rod of the second driven piston to push the second rod of the second driven piston which push the first rod of the third driven piston and this one will push the second rod of same piston and this last one will push the first rod of fourth driven piston ... , the pistons pushing etch other until the last piston in the line, so there are 200 driven pistons in one line pushing each other by their rods , so when we use a N linear bidirectional pistons the first one will push the N one with the same pressure of the first.

As we said before the first and the last driven piston on the driven pistons line are unidirectional pistons with one rod for each one, and the 198 driven pistons between the first one and the last one is bidirectional pistons with two rods for each one.

So, the driven pistons pushing each other ( pistons line work ) : so, the electric motor will make the gearbox rotate, then this gearbox will make the pinion rack system move linear , then the pinion rack system will makes the driver piston's rod move linear to inside driver piston then this piston will start push oil to the first driven piston, so the first driven piston will start move and push oil to the main collector, the rod of the first driven piston will move out and will push the first rod of the second driven piston so this rod will move to inside second piston then the second rod of the second piston will move out to push first rod of the third piston , so by this method all pistons pushing each other , so piston 1 (first driven piston ) push piston 2 , piston 2 push piston 3 , piston 3 push piston 4, piston 4 push piston 5 , piston 5 push piston 6, piston 6 push piston 7 , piston 7 push piston 8 piston, 8 push piston 9 , piston 9 push piston 10, piston 10 push pistonll , piston 11 push piston 12, piston 12 push piston 13 , piston 13 push piston 14 , piston 14 push piston 15 , piston 15 push piston 16, piston 16 push piston!7 , piston 17 push piston!8, piston 18 push piston 19, piston 19 push piston 20 piston, 20 push piston 21 , piston 21 push piston 22, piston 22 push piston 23 , piston 23 push piston 24, piston 24 push piston 25 piston 25 push piston 26 , piston 26 push piston 27 , piston 27 push piston 28, piston 28 push piston 29 , piston 29 push piston 30, piston 30 push piston 31 , piston 31 push piston 32 piston, 32 push piston 33 , piston 33 push piston 34, piston 34 push piston 35 , piston 35 push piston 36, piston 36 push piston 37 , piston 37 push piston 38 , piston 38 push piston 39 , piston 39 push piston 40, piston 40 push piston 41 , piston 41 push piston 42, piston 42 push piston 43, piston 43 push piston 44 piston, 44 push piston 45 , piston 45 push piston 46, piston 46 push piston 47 , piston 47 push piston 48, piston 48 push piston 49 , piston 49 push piston 50, piston 50 push piston 52, piston 52 push piston 52... piston 197 push piston 198, piston 198 push piston 199, piston 199 push piston 200, piston 200 is unidirectional piston with one rod connect to the second rod of piston number 199.

Same logic for B's 200 driven pistons line, each line has 200 secondary pistons and they all pushing each other as we explained before.

So, when the system make A's electric motor rotate by the 15 MW lithium battery, the A's gearbox will start rotating too by this motor, then this gearbox will reduce the high-speed rotation of the input's axis which connect to the output axis of the electric motor to be slow rotation in the output's axis of the A's main gearbox with high torque.

Then this main gearbox will transmit the rotation movement and power from the output axis of the gearbox to the pinion rack system, then the pinion rack system will make the rod of the A's driver piston move linear lmm/s, so, the A's driver piston will start move and push 0.788 LPS of oil to the first A's driven piston directly by the first input/output of the first A's driven piston.

So, the first driven piston will start move very slow but with very high power, so it is will start push 0.788 liter of oil to the A's main collector, then the rod of the A's first driven piston will move out and will push the first rod of the second driven piston, so the second one will push 0.788 LPS of oil to the main collector, then the second rod of the second driven piston will push the first rod of the third driven piston then all the driven pistons on the A's piston's line will push each other and will be moved by the A's first driven pistons, in same time, same flow and same pressure, so they all will push oil to the A's main collector, they will be moved by pushing each other as we explained before.

As we said before, the first driven piston on each line is a unidirectional piston with one rod and this driven piston will be moved by the driver piston, then the rod of this driven piston will move out and will push the first rod of the second driven piston, the driven pistons number 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19,20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49 ... 198, 199 are bidirectional pistons with two rods for each one, so, the second driven piston will be pushed by the rod of the first driven piston on the line, then this piston will push oil to the A's main collector, then the second rod of the second driven piston will move out and will push the first rod of the third driven piston, so this one will push oil to the A's main collector.

Then the second rod of the third driven piston will move out and will push the first rod of the fourth driven piston, so this piston will push oil to the A's main collector.

Then the second rod of the fourth driven piston will move out and will push the first rod of the fifth driven piston, so this piston will push oil to the A's main collector.

Then the second rod of the fifth driven piston will move out and will push the first rod of the sixth driven piston, so this piston will push oil to the A's main collector.

Then the second rod of the sixth driven piston will move out and will push the first rod of the seventh driven piston, so this piston will push oil to the A's main collector.

Then the second rod of the seventh driven piston will move out and will push the first rod of the eighth driven piston, so this piston will push oil to the A's main collector.

Then the second rod of the eighth driven piston will move out and will push the first rod of the ninth driven piston, so this piston will push oil to the A's main collector. Then the second rod of the ninth driven piston will move out and will push the first rod of the tenth driven piston, so this piston will push oil to the A's main collector.

Then the second rod of the tenth driven piston will move out and will push the first rod of the eleventh driven piston, so this piston will push oil to the A's main collector.

Then the second rod of the eleventh driven piston will move out and will push the first rod of the twentieth driven piston, so this piston will push oil to the A's main collector.

Then the second rod of the twentieth driven piston will move out and will push the first rod of the thirteenth driven piston, so this piston will push oil to the A's main collector.

Then the second rod of the thirteenth driven piston will move out and will push the first rod of the fourteenth driven piston, so this piston will push oil to the A's main collector.

Then the second rod of the fourteenth driven piston will move out and will push the first rod of the fifteenth driven piston, so this piston will push oil to the A's main collector.

Then the second rod of the fifteenth driven piston will move out and will push the first rod of the sixteenth driven piston, so this piston will push oil to the A's main collector.

Then the second rod of the sixteenth driven piston will move out and will push the first rod of the seventeenth driven piston, so this piston will push oil to the A's main collector.

Then the second rod of the seventeenth driven piston will move out and will push the first rod of the eighteenth driven piston, so this piston will push oil to the A's main collector. Then the second rod of the eighteenth driven piston will move out and will push the first rod of the nineteenth driven piston, so this piston will push oil to the A's main collector.

Then the second rod of the nineteenth driven piston will move out and will push the first rod of the twentieth unidirectional driven piston, so this piston will push oil to the A's main collector.

So, all driven pistons on the line will push each other as we said before until the last driven piston number 200.

Each driven piston will push 0.788 LPS of oil to the A's main collector, so there are 157 LPS of oil will be pushed from the A's 200 driven pistons to the A's main collector.

157 LPS of oil will move out under high pressure from the A's main collector to the A's first input of the hydraulic motor which make the generator rotate.

Then oil will move out from the first output of the hydraulic motor to the tank.

The A's driver piston will move lmm/s for 5m, so the system A will move for about 83min.

5cm before driver piston of A stop moving, the first sensor of this piston will switch on the B's electric motor by the electricity which is produced by the system A, so the system B will start work before system A stop working.

The B's gearbox will rotate by the B's electric motor, then this gearbox will reduce rotation speed of the B's electric motor to be slow in output axis of the B's gearbox, then this gearbox by the output axis will transmit the rotation movement to the pinion rack system which will push the rod of the B's driver piston lmm/s.

So, the B's driver piston will start move lmm/s same logic we explained in A's driver piston, then the B's driver piston will push 0.788 LPS of oil to the B's first driven pistons on the B's driven pistons line in same way we explained in A's system.

So, oil will move out in system B from B's driver piston under high pressure to the B's first driven pistons on the B's driven pistons line, then the B's first driven piston will move and will push 0.788 LPS of oil to the B's main collector, then all the 200 B's driven pistons will be moved by the B's first driven piston on the driven pistons line in same time, same flow, same pressure to the B's main collector in same way we explained in A's system , then oil will move out from the B's main collector to the second input of the hydraulic motor for keep it rotating before system A stop pushing oil to the motor.

Each B's driven piston will push 0.788 LPS of oil to the B's main collector, so, there are 157 LPS of oil will be pushed from the 200 driven pistons to the main collector of B, then from this collector to second input of the motor, so, the hydraulic motor still rotating.

Oil will move out from the second output of the hydraulic motor to the tank.

The B's electric motor after switched on will get power from the system not from the battery, the battery just for switch at first time.

When the driver piston's rod of the A's first driven pistons line reach to the last stopping point, the second sensor of this piston will switch off the A's electric motor, will close the output's switch valve of the A's main collector which connect to the first input of the hydraulic motor and will open the input of it which connect to the hydraulic pump.

10/s after, the timer of the second sensor of the A's driver piston will switch on the A's reload pump, then this pump will start push 218 LPS of oil from the tank to the A's main collector and from this collector to each piston of the A's 200 driven pistons to make them full of oil again.

Each input/output in main collector which connect to one driven piston has switch valve with check valve, check valve when the main collector receive oil from the driven piston, switch valve when the pump push oil from the main collector to the driven piston (see the drawing of the switch valve) The A's first driven piston will receive 1 LPS of oil from the A's main collector by the second input/output of it when the pump start pushes 218 LPS of hydraulic oil to the main collector of A, then 1 LPS of oil will move out from first side of the A's driven piston form the first input/output to the A's driver piston for make it full of oil again.

So, the A's driver piston will receive 1.09 LPS of oil from the first side of the A's first driven piston when it is receiving 1 LPS of oil from the A's main collector on the second side of the A's first driven piston.

Each driven piston of A will receive 1.09 LPS of oil from the A's main collector.

The 200 driven pistons will be full of oil again in one hour and the B's 200 driven pistons will stop moving in one hour sixty-six min, that is mean the 200 driven pistons of A will be full of oil again in one hour before B's 200 driven pistons stop moving

When the 200 driven pistons of A be full of oil the A's driver piston will be full of oil too, then the pressure sensor of A's driver piston will switch off the A's reload pump, will close the input of the A's main collector which connect to the hydraulic pump and will open the output of it which connect to the first input of the hydraulic motor for push oil again to the motor later.

So, A's driver piston and A's driven pistons are full of oil and system A is ready for work again, now system B is working.

So, when the first sensor of the A's driver piston made the B's electric motor rotate, the B's main gearbox start rotate too and this gearbox reduce the high-speed rotation of the input's axis to be slow rotation in the output's axis of the B's gearbox with high torque.

Then this gearbox will transmit the movement and the power by the pinion rack system to the rod of the B's driver piston as we said and it is will make it move, then the B's driver piston will push 0.788 LPS of oil to the B's first driven piston' then the B's first driven piston will push the 199 B's driven pistons on the B's driven pistons line and all of them will start push 157 LPS of oil to the B's main collector, in same time, same flow, same pressure as we explained in system A.

Each driven piston of B will push 0.788 LPS of oil to the B's main collector.

157 LPS of oil will move out under high pressure from the B's main collector to the B's second input of the hydraulic motor which make the generator rotate as we said.

Then oil will move out from the second output of the hydraulic motor to the tank.

The B's driver piston will move lmm/s for 5m, so it is will move for 83 min.

5cm before B's driver piston stop moving, the first sensor of this piston will switch on the A's electric motor, so the system A will start work before system B stop working.

So, the A's system will start work when the electric motor of A start rotating, then the A's gearbox will rotate by the A's electric motor, then the A's gearbox will reduce the high rotation speed of the A's electric motor to by slow rotation in the output axis of the A's gearbox with high torque, then the A's gearbox will make the A's driver piston move by the pinion rack system as we explained before, then the A's driver piston will push 0.788 LPS of oil to the A's first driven piston, so, the A's first driven piston will start move lmm, s and will push oil to the A's main collector.

Then oil will move out under high pressure from A's first driven piston to the A's main collector, then all the A's driven pistons will be moved by the A's first driven piston as we explained before in same time, same flow, same pressure and will push 157 LPS of oil to the A's main collector, then oil will move out from the A's main collector to the first input of the hydraulic motor for keep it rotating as we explained before.

So, the hydraulic motor will continue rotating. Oil will flow out from the first output of the hydraulic motor to the tank.

So, the hydraulic motor still rotating before system B stop working.

When the driver piston's rod of the B's driver piston reach to the last stopping point, the second sensor of this piston will switch off the B's electric motor, will close the output's switch valve of the B's main collector which connect to the second input of the hydraulic motor and will open the input of it which connect to the hydraulic pump.

10/s after, the timer of the second sensor of B's driver piston will switch on the B's reload pump, then this pump will start push 218 LPS oil to the B's main collector and from this collector the oil will move to each piston of the B's 200 driven pistons to make them full of oil.

Each B's driven piston will get 1.09 LPS of oil from the main collector of B, so, each B's driven piston will be full of oil in about 60 min.

The B's first driven piston will receive about 1.09 LPS of oil from the B's main collector by the second input/output of it because the pump pushing oil to the B's main collector then oil will flow from this collector to the second side of the first driven piston, so, 1,09 LPS of oil will move out under pressure of the pump from first side of the first driven piston to the B's driver piston for make it full of oil again in 60 min.

Is same capacity of the driver piston.

When the B's driver piston be full of oil, the B's 200 driven piston will be full of oil too, then the pressure sensor of B's driver piston will switch off the reload pump, will close the input which connect the main collector of B to the pump and will open output of the B's main collector to the second input of the hydraulic motor, then system B will be ready for work again later.

So, system B is ready for work 1 hour before system A stop working.

Now system A is working as we said in the first time and hydraulic motor rotating, 5 cm before driver's piston of A stop working the first sensor of this piston will switch on the B's electric motor for start working. So, system B will start working before system A stop working, by this way we keep the hydraulic motor always rotating without stopping.

First invention in steps:

- The system will switch on the A's electric motor by the 15 MW lithium battery, so it is will start rotating.

- Then the A's gearbox will rotate too by the A's electric motor, the A's gearbox will reduce the rotation speed of the A's electric motor, so we will get slow rotation in output axis of the gearbox with high torque.

- Then the gearbox will make the A's driver piston move lmm/s by pinion rack system, so the driver piston will start move lmm/s and push 0.788 LPM of oil to the first driven piston.

- Then the first driven piston will start move by the driver piston of A, so the first driven piston of A will start move and will push 0.788 LPS of oil to the A's main collector, then it is rod will push the first rod of the second driven piston.

- The second driven piston will start move and push 0.788 LPM of oil to the main collector of A.

- The second rod of the second driven piston will push the first rod of the third driven piston, so it is will start move and push 0.788 LPM of oil to the main collector.

- Then the second rod of the third driven piston will start move and will push the first rod of the fourth driven piston, so, the fourth driven piston will start push 0.788 LPM of oil to the A's main collector.

- Then the second rod of the fourth driven piston will move out and will push the first rod of the fifth driven piston.

- So, all the A's 200 driven pistons of A will start move in same time when the A's driver piston start push 0.788 LPS of oil to the A's first driven piston, and all of them will start push 157 LPS of oil to the A's main collector in same time, same flow, same pressure.

- 157 LPS of Oil will flow from the A's main collector to the first input of the hydraulic motor, so it is will start rotating.

- The hydraulic motor will make the generator rotating too and it is will produce electricity (2.8 GW).

- Oil will flow out from the first output of the motor to the tank.

- So, the A's electric motor will get power from the system which producing electricity. - So, system A now is working and producing power, it is will work for about 83 min because the A's driver piston will move for lmm/s for 5m.

- 5cm before A's driver piston reach to stopping point, the first sensor will switch on the B's electric motor by the electricity which is produced by A's system, so it is will start rotating.

- When the B's electric motor start rotating the B's, gearbox will start rotating too and reduce high rotation of the B's electric motor to be slow rotation with high torque in output axis of the B's gearbox.

- The B's gearbox will make the B's driver piston move linear by the pinion rack system, so the B's driver piston will start push 0.788 LPS of oil to the first B's driven piston, the diameter of the driven piston is bigger than diameter of the B's driver piston 10 times, so it is will be stronger than it 100 times.

- So, the B's driven piston will start move and push 0.788 LPS of oil to B's main collector, then the rod of the first driven piston will move out and will push the first rod of the second driven piston, so, the second one will start move and push 0.788 LPS of oil to the B's main collector.

- Then the second rod of the second driven piston will move out and will push the first rod of the third driven piston, so the third one will start move and will push 0.788 LPS of oil to the B's main collector.

- Then the second rod of the third driven piston will move out then will push the first rod of the fourth driven piston, so, the fourth one will start push 0,788 LPS of oil to the B's main collector.

- As we said, the B's 200 driven pistons will start move and push each other when the B's driver piston start push 0.788 LPS of oil to the first B's driven piston, then all the B's 200 driven piston will start push 157 LPS oil to the B's main collector.

- Each B's driven piston will push 0.788 LPS, so, all the B's 200 driven piston will push 157 LPS to the B's main collector, then oil will flow from this collector to the second input of the hydraulic motor, so this motor will continue rotating even system A stop working.

157 LPS of oil will flow out from the second output of the motor to the tank.

- When the A's driver piston reach to the stopping point, the A's second sensor will switch off the A's electric motor.

- Second sensor of A will close the output of the A's main collector to the first input of the motor and will open the input of it to the pumps.

- 10/s after, the timer of the second sensor of A will switch on the pumps.

- The pumps will start push 218 LPS of oil to the A's main collector, then 1.09 LPS of oil will flow from this collector to each piston of A's 200 driven pistons for make them full of oil in 60 min before system B stop working.

- When the 200 driven pistons of A be full of oil again in 60 min, the pressure sensor of A's driver piston will switch off the pumps, then will close the input of the A's main collector which connect to the pump and will open the output of it to the first input of the motor, so system A is ready for work before system B stop working.

- The 200 driven pistons of A will be full of oil one hour before B,s system stop working.

- System B is working now.

- 5cm before B's driver piston stop moving, the first sensor of B will switch on the A's electric motor, so it is will start rotating, so the A's gearbox will start rotating too, then the A's gearbox will make by the pinion rack system the A's driver piston move linear lmm/s, so, the A's driver piston will push 0.788 LPS of oil to the first driven piston of A as we said in the first time.

- So, the first driven piston of A will start move and will push the A's 200 driven pistons, so they will start push 157 LPS of oil to the A's main collector, then oil will flow under high pressure to the first input of the motor.

- The motor will continue rotating by system A even system B stop working.

- When the B's driver piston reach to the stopping point, the B's second sensor will switch off the B's electric motor, then will close the output of the main collector of B to the second input pf the motor and will open the input of the B's main collector to the pumps.

- 10/s, the timer of the B's second sensor will switch on the pumps, so the pumps will start push 218 LPS of oil to the B's main collector, then 1.09 LPS of oil will flow from this collector to each piston of the B's 200 driven piston for make then full of oil again in 60 min.

- When the 200 driven pistons of B be full of oil, the B's driver piston will be full of oil too, then the pressure sensor of B's driver piston will switch off the pumps, then will close the output of the B's main collector to the pumps and will open the output of it to the second input of the motor.

- So, system B is ready 60 min before system A stop working.

- 5cm before A's driver piston stop working, the first sensor of it will switch on the B's electric motor, so system B will start work as we explained at first time.

- So, B's 200 driven pistons will start push 157 LPS of oil to the motor and motor will not stop rotating even system A stop working. - When the A's driver piston stops working, the second sensor will switch off the A's electric motor and will close the output to the first input of the motor, then will open the A's main collector's output to the pump, then pump will start pumping 218 LPS of oil as we said at first time in these steps.

- By this way, we redouble the power and we have continuous power.

Calculations of the first method:

TrTorque

w: rotation speed

PrPower

p: pressure

frflow

Frforce

s: speed

D: diameter

Dr: driver piston

Dn: driven piston

We use HV series siemens electric motor with 10 MW and 2000KNm and. 50 RPM

In the output we use 10 to 1 gearbox

on the gearbox output w

e use rack system with

On the driver piston with lm diameter and linear speed

On the first driven piston with 10m diameter

On the 200 driven pistons with 10m diameter

Hydro motor calculation

the final power is

With lose

PIPING:

- Driver piston to the first driven piston: 2 inches.

- Driven piston to main collector: 2 inches.

- Main collector to hydraulic motor: 20 inches.

Calculations of the first method with 50 driven pistons:

TrTorque

w rotation speed

PrPower

p: pressure

frflow

Frforce

s: speed

D: diameter

Dr: driver piston

Dn: driven piston

We use HV series siemens electric motor with 10 MW and 2000KNm and. 50 RPM

In the output we use 10 to 1 gearbox

gearbox

on the gearbox output we use rack system with

On the driver piston with lm diameter and

linear speed

On the first driven piston with 10m diameter

On the 50 driven pistons with 10m diameter

Hydro motor calculation

this line will move an axial hydro motor with

the final power is

PIPING:

- Driver piston to the first driven piston: 2 inches.

- Driven piston to main collector: 2 inches.

- Main collector to hydraulic motor: 16 inches.

Additional to the first method:

We said in this method there are one pump for push oil to the main collector, but we can put one small pump for each driven piston to push 1 LPS to the driven piston as we will explain in the second method later, so each driven piston will be full of oil within 1 hour.

If we put one pump for each driven piston, we have to make each driven piston with two input/outputs, first one with switch valve for open or close it connect to one input with check valve in main collector, the switch valve of the first input/output of the driven piston close by the second sensor when the system stops working, and opened by the pressure sensor when the driver piston be full of oil

The second input/output connect to the pump and has switch valve opened by the second sensor and closed by the pressure sensor.

Second sensor close the switch valve of the first input/output, open the second one in same time. pressure sensor opens the switch valve of the first input/output, close the second one in same time.

SECOND METHOD / SOME CHANGEs:

No driver piston

Electric motor / Driven piston

Connect the moving rod of the first driven piston directly to the pinion rack system without driver piston which is smaller than first driven piston 10 times, then the pinion rack system will be moved by the gearbox which be moved by the electric motor.

The gearbox her will reduce the rotating speed of the electric motor to be slow rotation on the output axis of the gearbox.

In the second method there will be with 200 driven pistons.

All the 200 driven pistons will be same size, 10 m diameter, 50cm length for each one, each driven piston will be with two input/output, first one with switch valve connect to the main collector, second one with switch valve connect to the pump.

Each input/output with switch valve, there are two systems, one is for system A, second is for system B.

System A with one electric motor with 10 MW, 200 driven pistons, one main collector.

System B with one electric motor with 10 MW, 200 driven pistons, one main collector.

One hydraulic motor with two inputs and two outputs, first input with switch valve connects to the main collector of A, second input with switch valve connect to the main collector of B, the outputs of the motor connect to the tank.

The difference here is the output axis of the gearbox will rotate very slow to get high torque to push the first rod of the first driven piston directly without driver piston.

The first driven piston here is bidirectional piston with two rods for each one, first rod connects to the pinion rack system, the second rod connect to the first rod of the second driven piston.

Each collector with 200 input/outputs, each input/output with check valve, each input/output connect to the first input/output of each driven piston.

So, when the electric motor start rotating the gearbox will rotate by it, then then the gearbox will reduce the rotation speed of the electric motor to be slow rotating in the output axis of the gearbox with high torque, then this gearbox will make the pinion rack system move 0.5 mm/s, then this system will push the first rod of the first driven piston 0.5 mm/s, so this piston will move by doubled power and will push the 199 driven piston in same speed for push oil to the main collector, then oil will flow from this collector to the hydraulic motor, so the motor will star rotating. First system A will work, then 2cm before first driven piston of A stop moving for example the first sensor of A will switch on the B’s electric motor, so the B’s system will work and will push oil to the motor as we said before system A stop work.

The pressure sensor will be on the input/output of the first driven piston.

Each driven piston has one pump with 14 LPS, each pump connects to the second input/output of each driven piston, each one with switch valve for open or close it, the two input/outputs will be in the same side of each driven piston.

The A’s second sensor for example when the rod of the first driven piston reach to stopping point will close the switch valve of the main collector to the motor, will close the first input/output of each driven piston which connect to the main collector and will open each switch valve of each second input/output of each driven piston which connect to the own pump, then 10/s after the timer of the second sensor will switch each pump of each driven piston for push oil to the 200 driven pistons, each pump will push 14 LPS to each driven piston for make it full of oil in about 5 min or less.

Each main collector has pressure sensor for switch off the pumps when necessary.

The 200 pumps will switch off by the pressure sensor of the first driven piston when it be full of oil.

The first driven piston will move 0.5 mm/s.

SO, HOW THIS METHOD IS WORKS?

In first time, the system switch on the A’s 10 MW electric motor by the 15 MW lithium battery, so this electric motor will start rotating, then it is will make the A’s gearbox rotating, then this gearbox will reduce the rotation speed of the A’s electric motor to be slow rotating in output axis of the A’s gearbox with high torque, then this gearbox will make the A’s pinion rack system move, so the system will start push the rod of the first driven piston 0.5 mm/s, then the first driven piston of A will start push oil to the A’s main collector, in same time it is will push the 199 A’s driven pistons as we explained in this research, so all the A’s 200 driven pistons will start move by pushing each other as we said before in this research, then all the driven pistons will push oil to the A’s main collector, so oil will move from this collector to the first input of the motor, so this motor will start rotating with doubled power.

Oil will flow from the first output of the motor to the tank... so the generator will rotate by the hydraulic motor and will produce electricity.

Then the system will supply itself by power.

2cm before A’s driven piston stop moving, the first sensor of it will switch on the B’s electric motor, so the system B will work same system A and will start push oil to the second input of the hydraulic motor by the B’s 200 driven pistons before system A stop rotating. When the rod of the A’s first driven piston reached to full stopping point, the second sensor of it will close the switch valve of each first input/output of each driven piston which connect to the main collector, will open each switch valve of each second input/output of each driven piston which connect to the pump, will close the switch valve of A’s main collector which connect to the first input of the motor, then 10/s after, the timer of the A’s second sensor will switch on the 200 pumps o the 200 driven pistons of A, so each pump will start push 14 LPS to each A’s driven piston for make them full of oil in about 5 min for make them full of oil before system B stop moving

The pressure sensor of the A’s first driven piston will switch off the 200 pumps when they be full of oil, will close the second input/output of each driven piston to the pump and oil open each switch valve of the first one to the main collector.

The system B will stop moving in 16 min.

So, the motor is rotating by system B.

2cm before the rod of the B’s first driven piston reach on full stopping point, the first sensor of B will switch on the A’s electric motor, will open the switch valve of the A’s main collector which connect to the first input of the motor, so system A will start work and push oil to the motor as we said before system B stop working.

When the B’s first driven pistons rod reached to the full stopping point the second sensor of B will do in system B what A’s second sensor did in system A.

When the rod of the B’s first driven piston reached to full stopping point, the second sensor of it will close the switch valve of each first input/output of each driven piston which connect to the main collector of B, will open each switch valve of each second input/output of each driven piston which connect to the pump, will close the switch valve of B’s main collector which connect to the second input of the motor, then 10/s after, the timer of the B’s second sensor will switch on the 200 pumps of the 200 driven pistons of B, so each pump will start push 14 LPS to each B’s driven piston for make them full of oil in about 5 min for make them full of oil before system A stop moving

The pressure sensor of the B’s first driven piston will switch off the 200 pumps of B when they be full of oil, will close the second input/output of each driven piston to the pump and oil open each switch valve of the first one to the main collector.

So, by this way the motor will not stop rotating. CALCULATIONS OF THE SECOND METHOD:

TrTorque

w rotation speed

PrPower

p: pressure

frflow

Frforce

s: speed

D: diameter

Dn: driven piston

We use HV series siemens electric motor with 10 MW and 2000KNm and. 50 RPM

In the output we use 10 to 1 gearbox

g

on the gearbox output we use rack system with

On the first driven piston with 10m diameter

On the 200 driven pistons with 10m diameter

Hydro motor calculation flow with and

the final power is

lose

P generator after lose 1. 305GIP

P produced ^~ 1- 305GIP

PIPING:

- Driver piston to the first secondary collector: 2 inches.

- Driven piston to main collector: 2 inches.

- Main collector to hydraulic motor: 16 inches.

Claims

Claims:

1. Put 200 short pistons (driven pistons) on one horizontally line, 198 driven pistons of them are bidirectional pistons with two rods for each one, and two driven pistons of them are unidirectional pistons with one rod for each one, then we put all the 198 bidirectional driven pistons on one horizontally line, the first driven piston and the last driven piston are the two unidirectional pistons, and between them we put the 198 bidirectional driven pistons, then we connect the rod of the first unidirectional driven piston to the first rod of the second driven piston and this piston is bidirectional piston with two rods, then we connect the second rod of the second driven piston to the first rod of the third driven piston, the driven pistons number 2 to number 199 are bidirectional pistons with two rods for each one.

So, we connect the second rod of the third driven piston to the first rod of the fourth driven piston, then we connect the second rod of the fourth driven piston to the first rod of the fifth driven piston etc.

We connect the first rod of the 70^th driven piston to the second rod of the 69^th driven piston, and we connect the second rod of the 70^th driven piston to the first rod of the 71^th driven piston ... we connect the first rod of the 109^th driven piston to the second rod of the 108^th driven piston, and we connect the second rod of the 109^th driven piston to the first rod of the 110^th driven piston, we connect the second rod of the 198^th driven piston to the first rod of the 199^th driven piston and we connect the second rod of the 199^th driven piston to the rod of the last piston number 200, and this piston is unidirectional pistons with one rod.

So, when the electric motor star rotating, the gearbox will rotate by it and will reduce the high rotation speed to be slow rotation speed in output axis of the gearbox, then this gearbox will make the pinion rack system move linear, so, this system will make the rod of the driver piston move, then it is will push oil from the first unidirectional driven piston on the pistons line, the rod of the first driven piston will move out and will push the first rod of the second driven piston then, the second rod of the second driven piston will move out and will push the first rod of the third driven piston, then all the 200 driven pistons will start push each other by their rods and all will push oil in same time, same pressure, same flow to the collector. In our invention the diameter of each driven piston is 10m diameter and 5cm length, so all rods of the 200 driven pistons will move just for 5cm in same time by the first driven piston when it is start receive oil from the driver piston.

2. Put a hydraulic cylinder horizontally (driver piston) with lm diameter, 5m length, and this driver piston for push oil to the first unidirectional driven piston on the 200 driven pistons line.

The driver piston is not form the 200 driven pistons.

The driver piston's diameter is smaller than diameter of the first unidirectional secondary piston 10 times, so, when the driver piston start push oil to the first unidirectional driven piston the first unidirectional driven piston will be stronger than driver piston 100 times.

The capacity of the driver piston is same capacity of the first driven piston because the driver piston length is 5m but the first driven piston length is 5cm and the diameter of the driver piston is lm but the diameter of the first driven piston is 10m, for that oil amount and flow will be same in each one 3926 liters in our invention.

When the driver piston start moves and reach to the last stopping point the all 3926 liters of oil will be pushed to the first driven piston, so the rod of the first driven piston will be in full out and pushed the second driven piston, so all the rods of the 200 driven pistons will be moved for 5 cm and pushed oil to the collector.

3. The 5m length rod of the driver piston will be moved by pinion rack system, and this system connect to the gearbox by the output axis of this gearbox and be moved by this gearbox when the gearbox start rotating by the electric motor.

4. The 200 driven pistons for push oil to the main collector, then from this collector to the hydraulic motor for make it rotate, then this motor will make the generator rotate and produce electricity. There are two lines of driven pistons, one line for system A, second line for system B, each line with 200 driven pistons.

The B's 200 driven pistons start work and push oil to the main collector then to the motor before A's 200 driven pistons stop working.

5. Put two driver pistons, one is for system A' second is for system B, each driver piston with lm diameter, 5m length, and it is for push oil to the first unidirectional driven piston in each system, the diameter of the driver piston is smaller than diameter of the first driven piston 10 times, so, the driven piston is stronger than driver piston 100 times.

6. There are some pumps for reload the driver pistons by oil before the main piston which move down reach full down.

7. The hydraulic motor has two input/outputs, one connects to the main collector of A, second connect in main collector of B in the first method.

8. 5cm before system A stop working, the B's system will start working by the first sensor of A, so the hydraulic motor will continue rotating before system A stop working.

9. Chang oil by water in driver piston which pushing to the motor, and change motor by turbine.

10.Put one driver piston in each system with lm diameter, 5m length, the rod of the driver piston will be moved by pinion rack system which connect to the output axis of the gearbox.

The input axis of this gearbox connect to the output axis of the electric motor for reduce the high rotation speed of the electric motor to get slow rotation speed with high torque in output axis of the gearbox, so when the electric motor start rotating, the input axis of the gearbox will start rotate too in same speed of the electric motor, then this gearbox as we said will reduce the high rotation speed to be slow rotation speed in the output axis of the gearbox but with very high toque, then the pinion rack system which connect to the output axis of the gearbox will start move linear slowly, then it is will push the rod of the driver piston, so, the driver piston will start move slowly with high power, then it is will push oil to the first driven piston, so the first driven piston will start move stronger than driver piston 100 times, then it is will push oil to the collector, then it is will push the 200 driven pistons, so all the 200 driven piston will start push oil to the collector, then oil will flow from this collector to the hydraulic motor.

The diameter of the driver piston is smaller than diameter of the first driven piston diameter 10 times, so the first driven piston will be stronger then driver piston 100 times, by this way we will produce about 1 GW.

The driven piston will move for short distance with very high power with little flow, for that we put many bidirectional driven pistons with two rods for each one, then we connect the rod of the first driven piston to the first rod of the second driven piston and we connect the second rod of the second driven piston to the first rod of the third driven piston, then we connect the second rod of the third driven piston to the first rod of the fourth driven piston etc.

So, the first driven piston will move for short distance but it is will push the second one which will move same distance of first one, then the second driven piston will push the third driven piston same distance, then the third driven piston will push the fourth driven piston same distance, so all the 200 driven pistons will push each other until the last driven piston on the line... etc.

Each driven piston's rod will move just for 5cm in our invention, so all the driven pistons will push each other one by one as we said for just 5cm, by this way we will get high flow and pressure to the collector, then oil will flow from this collector to the hydraulic motor for make it rotate.

11. Redouble the power two times, one when we make the gearbox reduce the high speed rotation of the electric motor to be slow speed in output axis of the gearbox which make the driver piston move by the power of the output axis of the gearbox and by the pinion rack system, then we make the driver piston which be moved by the pinion rack system push oil to the driven piston which it is diameter bigger than diameter of the driver piston 10 times, so, the power which we get in output axis of the gearbox will be in the driver piston, and this power will be in the driven piston when the driver piston push oil to it, and this power will be in the driven piston more or stronger than power in driver piston 100 times, so we will get much mush power.

12. There are two system, each system has one electric motor, one driver piston and 200 driven piston, 5cm before driver piston of A reach to the last stopping point the first sensor of it will switch on the B's electric motor for start push the B's driver piston, then the B's driver piston will make the 200 B's driven pistons move and push oil to the B's main collector, then from this collector to the second input of the motor.

When the A's driver piston stops moving the second senor will switch on the pumps for push oil to the 200 driven pistons of A to make them full of oil again.

When the second input/output of the first driven piston receive oil from the collector which receive oil form the pumps, oil will flow from the first input/output of the first driven piston to the driver piston for make it full of oil again.

5cm before B's driver piston reach to the last stopping point, the first sensor of B will switch on the A's electric motor, so system A will start work and push oil by the driver piston to the first driven piston of A, then all the A's 200 driven piston will start move and push oil to the A's main collector, then from this collector oil will flow to the hydraulic motor, so, the motor will not stop rotating even system B stop pushing oil to it.

13. The pumps will be switched on by the second sensor of the driver piston which stop moving for push oil to the collector, much of oil will flow to the collector, 218 LPS to the collector for make the 200 driven pistons full of oil, then oil will flow from this collector to each piston of the 200 driven pistons for make them full of oil again before the other system stop working as we explained before.

14. Connect the pinion rack system directly to the rod of the first driven piston in second method in this research, this piston is bidirectional piston with two rods, first rod connects to the pinion rack system, second rod connect to the first rod of the second driven piston as we said.

The pinion rack system connects to the output axis of the gearbox which connect by it is input axis to the output axis of the electric motor, this gearbox for reduce the high rotation speed of the electric motor to be slow one in the output axis of it with high torque for make the pinion rack system move slowly with high power, then this system will make the first rod of the first driven piston move to push oil and push the 99 driven pistons, so, the 100 driven pistons will push each other and all will push oil to the main collector then from this collector to the motor for make it rotating, then this motor will make the generator rotating too.

Put one pump for each driven piston for reload it by oil when the system stops working as we said, the 100 driven pistons will be full of oil before system B stop working.