KR980012800A - Power generator using permanent magnet - Google Patents

Abstract

A power generator using a permanent magnet is disclosed. The device has first and second crank arms, first and second connecting rods, first and second pistons, and first and second cylinders. First, second and third permanent magnets, a shaft coupled to the first permanent magnet, a first gear coupled to the shaft, and the first gear to apply rotational force to the first and second crank arms A pair of second gears engaged with and coupled to the first and second crank arms, and a hydraulic cylinder for moving the second permanent magnet a predetermined distance when pressure is applied. A hydraulic valve is provided to apply a portion of the pressure generated by the movement of the first and second pistons to the first means, and a portion of the pressure generated by the first and second pistons is applied to the hydraulic cylinder. Apply to one side. When the second permanent magnet is separated from the initial position, the first permanent magnet is rotated and before the first permanent magnet enters the initial position, the second permanent magnet is returned to the initial position so that the first permanent magnet is rotated. The permanent magnet enters the initial position without being affected by the magnetic force, and the second permanent magnet is rotated by a predetermined angle to continuously rotate by applying magnetic force to the first permanent magnet. The power generating device according to the present invention may combine a permanent magnet and a crank arm to allow continuous rotational movement without using additional energy.

Description

Power generator using permanent magnet

The present invention relates to a power generator, and more particularly, to a power input device that can increase the efficiency using a permanent magnet.

Electricity, petroleum, nuclear and natural gas, which are used conveniently in modern civilization, are the advanced energy of human civilization, but it takes a lot of money to cause and use enormous problems with noise and pollution. In addition, due to air pollution caused by changes in the earth's weather, human and property damages are increasing day by day, which is a major problem in space, and is taking measures to prevent pollution around the world.

In addition, the cost of manufacturing such equipment and its facilities and facilities that use this energy is also very small. In the case of internal combustion engines, not only 72.5% is lost, but also the engine itself causes many defects. It is limited.

This circle uses the principle of permanent magnet and crank arm to rotate the 360 ° rotational motion by 100kg of rotational kinetic energy, while the crank arm rotates 100kg of rotational kinetic energy within 25 degrees from 25 degrees to 0 point every 1 rotation. In order to amplify 700kg-1000kg and recharge 100kg of rotational kinetic energy to this power top dead center, 150kg-170kg is reinvested to continuously rotate without using the second energy, and the remaining energy 837kg is used as the kinetic energy. The permanent power developed has developed high-quality kinetic energy with no noise pollution, and the explanation will be partially explained as follows.

The following description is based on the development of the crank arm, a deceleration structure with a special principle of power developed by the present application, and will be explained as follows.

Generally, the principle of deceleration, which is widely used, is used to move or move a large object using a small force, or to adjust a high speed to a low speed.

This structural principle uses 1/2 or 1/10 or dozens of work structures depending on the application and adjusts its speed in a free attitude.

Looking at the structure of the deceleration as described above, for example, if the gears of 1 and 10 form the structure of the deceleration, the gear of 10 moves 10 times when the gear of 1 rotates 10 times.

All of the above deceleration principles can amplify the force from 1 to 2 times to several hundred times depending on the application, but according to the energy law, the energy of 1 ends at 1 and the potential energy law.

If we rearrange the deceleration or energy law described above, for example, we drop 1000 tons of water from the top dead center to the bottom dead center (fall) and rotate the structure such as aberrations or turbines using the force of the water falling. If the kinetic energy of the horsepower is generated, the re-investment of the generated 100 horsepower kinetic energy does not raise 1000 tons of water back to the top dead center, so once used water flows out and becomes wastewater that cannot be used again.

Since all the energy used by modern civilization is the same as the principle described above, it causes noise pollution and so on, it is difficult to avoid the irreversible disaster caused by the destruction of the ecosystem due to weather change and the damage of life and property due to dashed pollution. In order to solve such problems at this point, we developed the following principle.

The main idea is that the principle of the crank arm of the internal combustion engine has lost 72.5% of the 100 kg of amplified energy at the piston top dead center in the process of converting the linear motion into the rotary motion. When investing 100kg of kinetic energy, when the crank arm rotates from the circumference of 50 degrees to the zero point during the rotation of 360 degrees, the deceleration principle of 2 increases the piston top dead center from 300kg up to 900kg-1000k. This article has been used to explain the principles of this principle, from which the crank arm, the principle of the internal combustion engine, is converted to rotational motion while moving in a straight line.

For the following explanation, I will first explain the principle of the crank arm principle.

When the crank arm rotates 360 degrees, it rotates while forming a circumference. The circumference is rotated 360 degrees every 10 degrees every 10 degrees, and the crank arm is drafted within the drafted circumference, and the circumference is rotated at 180 degrees. The connecting rod is formed around the zero point and the diameter line of the piston, and the crank arm is rotated by 10 mm snacks every 10 degrees from the zero point of the circumference. When the crank arm is rotated to the circumference of 50 degrees by calculating the number of pro-rotated pros, 72.5 pro is lost in the process of converting the energy of 1 to 100 at the top dead center of the piston and converting the linear motion to the rotational motion. Let's explain the principle that the remaining 27.5% is used as kinetic energy.

When the crank arm rotates 360 degrees, draft the circumference formed every 10 degrees with every 10mm 360mm, draw a crank arm within the drafted circumference, and connect the connecting rod (rod) starting from the piston top dead center in addition to the drafted circumference. According to the principle that the crank arm was rotated at the zero top dead center of the circumference, a 10mm-type rotational movement was carried out every 10 degrees, so that the force moved to the crank arm circumference of the crank arm circumference at the base crankshaft. Let's explain as follows.

When the crank arm is rotated 10 mm to 10 degrees circumference at the zero top dead center, the piston retracts 2 mm in a straight line by the connecting rod.

At this time, the decelerating principle of up to 2 is achieved while the crank arm rotates 10 mm from the circumferential zero point top to the circumferential I0 degree on a 1 mm circumferential slope with 1 mm lower than the movement distance 2 mm formed at the piston top dead center. By increasing the decelerated specific gravity of 7/10 percent, the force of 100 amplified at the top dead center of the piston reaches the crank arm circumference of 9/100 percent.

The principle of the crank arm was to rotate the 1 mm circumferential (inclined) inclined surface, which is 1 mm lower than the 2 mm movement distance formed at the piston top dead center from the zero top dead center to the 10th circumference described above.

Next, when the horizontal line is drawn in a horizontal line from 10 degrees of circumference to 350 degrees of circumference as described above, the distance from the center of the + type to the circumference 0 of the + type that intersects the diameter line from 0 to 180 degrees of the circumference is measured. The crank arm described above was rotated from 1 to 10 degrees on the circumferential (inclined surface) slope of 1 mm, which is less than 2 mm of movement distance formed at the piston top dead center.

In the following explanation, the piston moves backward 6 mm in a straight line by the connecting rod when the crank arm rotates 20 mm to 20 degrees circumference at the zero top dead center. At this time, 4mm smaller than 6mm of movement distance formed at piston top dead center and 20mm from circumferential top surface to 20 degrees circumference from circumferential top dead center to 20 degrees circumference, the crank arm rotates while deceleration principle of 2 By increasing the decelerated specific gravity of 16/20 percent, the force of 100 superimposed on the top dead center of the piston reaches the crank arm circumference of 16/100 percent.

The principle of the crank arm was to rotate the 4 mm low circumferential slope (small surface), which is 2 mm smaller than the 6 mm movement distance formed at the piston top dead center from the zero top dead center to the 20th circumference described above.

Next, when the crank arm described above draws a horizontal horizontal line from 20 degrees to 20 degrees of circumference to 340 degrees of circumference, this + type centerline and 7 points of sergeant with + shape intersecting the diameter line from 0 to 180 degrees When measuring the distance and the distance, the crank arm described above rotates the circumferential inclined plane 4 mm lower, which is 2 mm smaller than the 6 mm movement distance formed at the piston top dead center, from the circumference 0 point to the circumference 20 degrees.

In the following explanation, the piston moves backward 12 mm in a straight line by the connecting rod when the crank arm rotates 30 mm to 30 degrees circumference at the zero top dead center.

At this time, the decelerated principle of up to 2 is achieved while the crank arm rotates 30mm from the zero point top dead center to 30 degrees at the circumference of the 8mm circumference (combed surface), which is 4mm lower than the movement distance 12mm formed at the piston top dead center. By increasing the decelerated specific gravity of 22/30%, the force of 100 amplified at the piston top dead center is 22/100% of the crank arm circumference.

The principle of the crank arm was to rotate the 8 mm circumferential inclined plane, 4 mm lower than the 12 mm movement distance formed at the piston top dead center from the top dead center zero point to 30 degrees circumference described above.

If the crank arm described above draws a straight horizontal line horizontally from 30 degrees to 330 degrees of circumference, then measure the distance from this center to the center of the line and the center of the line between the zero and the circumference of 0 to 180 degrees. The crank arm described above rotates 30 mm from the circumference (one point top dead center to 30 degrees circumference) on a lower 8 mm circumferential slope (4 mm), which is 4 mm smaller than the 12 mm travel distance formed at the piston top dead center.

In the following description, the piston retracts 20 mm by the connecting rod when the crank arm rotates 40 mm to 40 degrees circumference at the zero top dead center.

At this time, the crank arm rotates 40mm from the zero circumference point to 40 degrees circumference of the lower circumferential (combed) slope of 13.5mm, which is 6.5mm smaller than the distance 20mm formed at the piston top dead center. By increasing the decelerated specific gravity of the 26.5mm / 40mm pro, the force of 100 amplified at the top dead center of the piston becomes 26.5 / 100 pro to 40 degrees circumference.

The principle of crank arm rotational movement of the lower circumferential (combed) slope of 13.5mm, which is 6.5mm smaller than the 20mm movement distance formed at the piston top dead center from the top dead center zero point to 30 degrees circumference described above, is as follows.

If you draw a horizontal horizontal line from 40 degrees of circumference to 320 degrees of circumference as described above, the distance from the center of the circumference to the circumference of this + type with the + shape intersecting the diameter line from the circumference of 0 to 180 degrees is measured. The crank arm described above rotates 40 mm from the top dead center point to 40 degrees from the circumferential zero point top dead center on a 13.5 mm lower circumferential slope (6.5 mm less than 20 mm of movement distance formed at the top dead center).

In the following description, the piston retracts 30 mm by the connecting rod (rod) when the crank arm rotates 50 mm to 50 degrees circumference at the zero top dead center.

At this time, the deceleration principle up to 2 is performed while the crank arm rotates 50mm from the circumference 0 point to the circumference 50 degrees on the lower circumferential (combed) slope of 20mm, which is 10mm smaller than the movement distance 30mm at the piston top dead center. By increasing the reduced specific gravity of 50mm pro, the force of 100 amplified at the top dead center of the piston becomes 30/100 pro to the circumference of 50 degrees.

The crank arm rotates 50 mm from the zero top dead center to 50 degrees from the circumferential zero top dead center to the circumference of 50 degrees to the circumference of 50 degrees to the circumference of 50 degrees. The principle of exercise is as follows.

If you draw a horizontal horizontal line from 50 degrees of circumference of the crank arm to 310 degrees of circumference as described above, the distance between this + type center point and the circumference 0 which is formed with the + shape intersecting the diameter line from 0 circumference to 180 circumference is measured. The 20mm lower circumferential (inclined) inclined plane, which is 10mm smaller than 30mm of movement distance formed at the top dead center, is rotated as described above.

Because of this principle, when the piston moves in a straight line and tries to rotate the crank arm, the crank arm is formed and rotated, so this 360 degree is snacked every 10 degrees. If you look at the angle of the inclined plane from the point to the circumference of 90 °, the angle is 0.-10 ° = 6 ° ... 10 ° → 20 ° = 13 ... 20 ° → 30 ° = 22 ° ... 30 ° → 40 ° = 29 ° ... 40 ° → 50 ° = 38 ° ... 50 ° → 60 ° = 46 ... 60 ° → 70 ° = 55 ° ... 70 ° → 80 ° = 64 °. Since every 10 degrees of the circumference of the circumference of .90 ° → 90 ° = 72 ° becomes the angle of the bevel, the acceleration value of the angle of the bevel described above can be obtained by the following formula.

Formula for calculating the circumferential slope acceleration every 10 degrees → a min from a = gsina → a = gsina · a acceleration · g = gravity acceleration = 9.8 (g is constant with gravitational acceleration value 9.8) sine = angle ... ex) 6˚ What is the acceleration when an object moves on a slope at an angle?

Formula ⇒ a = gsina g = 9.8 sina = ... Formula = a = 9.8 x sin = 0.1045 = 9.8 * 0.145

Acceleration multiplies g by the value of sin at the given angle gsin = g * sina

The circumference of the circumference of 10 degrees ... angular rate sina is equivalent to the reduction angle ... angle of circumference 0 degrees → 10 degrees → 6 degrees → sin 6 degrees = 0.1045 → 1.0241.

The circumference is 10 degrees → 20 degrees → 13 degrees → sin 13 degrees = 0.2250 → 2.205.

The circumference is 20 degrees → 30 degrees → 22 degrees → sin 22 degrees = 0.3746 → 3.67108.

The circumference of 30 degrees → 40 degrees → 29 degrees → sin 29 degrees = 0.48487 → 475104.

The circumference is 40 degrees → 50 degrees → 38 degrees → sin38 degrees = 0.6157 → 6.03386.

The circumference of 50 degrees → 60 degrees → 46 degrees → sin 46 degrees = 0.7193 → 7.04914.

The circumference of 60 degrees → 70 degrees → 55 degrees → sin 55 degrees = 0.8192 → 8.02816.

The circumference 70 degrees → 80 degrees → 64 degrees → sin 64 degrees = 0.8988 → 8.80824.

The circumference is 80 degrees → 90 degrees → 72 degrees → sin 72 degrees = 0.9511 → 9.32078.

The circumference of 90 degrees → straight line is 78 degrees → sin 78 degrees = 0.9781 → 9.58538.

The angle of the circumferential (inclined) slope between every 10 degrees from zero circumference of the crank arm as described above to 90 degrees circumference. The speed is significantly different from that of the acceleration (the piston moves in a straight line), i.e., the acceleration descending from the vertex top dead center to the variable bottom dead center.

In this way, the internal combustion engine described above amplifies the energy of 1 to 100 at the piston top dead center so that the amplified energy of 100 is not supplied to the crank arm as it is, and the energy of the piston top dead center 100 is the center of gravity (base) of the crankshaft. Load the entire force, and the crank arm starts the rotational movement (start) at zero top dead center and finishes 0 + 9 + 16 + 22 + 26.5 + 30 every 10 degrees. After 50 degrees of circumference, the crank arm causes a 360 degree rotational motion regardless of the force supplied at the piston top dead center.

At this time, when the crank arm is returned to the zero top dead center at the circumference of 50 degrees at the circumference, whenever the crank arm rotates every 17 degrees, the unit of piston top dead center pressure is 3 + 4 + 6 + 7.5 + 9. In turn, when the piston reaches the top dead center, the pressure is increased to the previously amplified 100 pressure.

At this time, when the crank arm is rotated to the zero top dead center at 50 degrees of circumference, the kinetic energy supplied to the crank arm circumference is in the order of 30-26.5-22-16-9. It becomes (-) 0.

This principle of the crank arm consumes 72.5% of the force in converting the linear motion to the rotary motion even if a large force is applied at the piston top dead center.

In addition, the rotational speed and the power of the kinetic energy are also insufficient because they are not affected by the overall force.

The present invention has been made in order to overcome the above problems, as a technology using the principle of the linear motion of the internal combustion engine as a rotational motion in reverse, the present invention is rotated by a crank arm by rotating the rotor 360 degrees Is a linear motion of the piston to decelerate from 20 degrees to 0 degrees when the piston reaches top dead center.

In addition, the internal combustion engine inputs the energy of 1 and increases it to 100, thereby taking advantage of the fact that 72.5 decreases in itself.In addition, by inducing a weightless state using a permanent magnet, the magnetic force between the magnets is zero to move the position of the magnet. By generating the momentary magnetic force, the rotor is rotated.

The power generating device according to the present invention can generate high quality energy without noise pollution, can be used in the field where industrial power is used, and can improve economics.

The present invention is a power generator developed using the principle of the permanent magnet and the crank arm is rotated 360 degrees by the kinetic energy 100, the kinetic energy 100 within 25 degrees from 25 degrees to 0 degrees circumferential every 1 revolution of the crank arm Can be amplified to 7OO to 100 to reinvest 150 to 170 to recharge the kinetic energy 100 at the top dead center so that it can be continuously rotated without using the second energy, and the remaining energy 830 can be used as the kinetic energy. As a result, high-quality kinetic energy without noise pollution can be generated.

In order to achieve the above object, the present invention provides a first and second crank arms, one end of which is extrapolated to the first and second crankshafts, which are arranged at a predetermined distance, respectively: at the other ends of the first and second crank arms, respectively. First and second connecting rods, one end of which is coupled: First and second pistons coupled to the other end of the first and second connecting rods, respectively: First and second guides for guiding movement of the first and second pistons. Second cylinder: first means for applying rotational force to the first and second crank arms; and second for applying a portion of the pressure generated by the movement of the first and second pistons to the first means. A power generating device having means is provided.

The first means is rotatably mounted to a pair of first permanent magnets rotatably mounted to a first disc, and a second disc disposed at a predetermined interval on one side of the first disc so as to be parallel to the first disc. Pair of second permanent magnets. A pair of third permanent magnets rotatably mounted to a third disc disposed to be spaced apart by a predetermined distance from the other side of the first disc so as to be parallel to the first win plate, and a connection member connecting the pair of first permanent magnets A shaft fixedly coupled to the center of the first gear, the first gear fixedly coupled to one end of the shaft, a pair of second teeth meshed with the first gear and fixedly coupled to the first and second crank arms, respectively. A gear and a hydraulic cylinder for moving the second permanent magnet a predetermined distance when pressure is applied, wherein the first and third permanent magnets are disposed so that their respective S poles face each other, and the first and second permanent magnets face each other. The magnet is disposed so that the S pole of the first permanent magnet and the N pole of the second permanent magnet face each other, and the first, second, and third permanent magnets are in an initial position in a straight line. The magnetic force acting on the magnet When a pressure is applied to one side of the hydraulic cylinder, a third piston slidably inserted into the fusion cylinder is moved, and a rocker arm having one end coupled to the third piston is pivoted and connected to the other end of the rocker arm. When the second permanent magnet is rotated by a predetermined angle, the first permanent magnet is rotated in a direction opposite to the rotation direction of the second permanent magnet by the repulsive force with the third permanent magnet so that the shaft rotates together.

The second means is connected to the first and second cylinders by a plurality of first high pressure pipes and includes a hydraulic valve for guiding the pressure generated by the movement of the first and second pistons in one direction. The hydraulic valve has a first and a second passage, when the first piston reaches its top dead center, the first passage is closed, the second passage is opened, and the second piston reaches its top dead center. The first passage is opened and the second passage is opened to apply a part of the pressure generated by the first and second pistons to a side of the hydraulic cylinder through the second high pressure tube, and not to the hydraulic cylinder. The remaining hydraulic pressure is applied to the outside through the bypass valve.

The ratio of the diameters of the first and second gears is such that the first permanent magnet is rotated when the second permanent magnet is separated from the initial position and again before the first permanent magnet enters the initial position. The permanent magnet is returned to the initial position so that the first permanent magnet enters the initial position without being influenced by magnetic force, and the second permanent magnet is at a predetermined angle again when the first permanent magnet leaves the initial position again. It is rotated and is set to rotate continuously by applying a magnetic force to the first permanent magnet.

According to a preferred embodiment of the present invention, one end of the rocker arm is coupled to the third permanent magnet, and the other end of the rocker arm is coupled to a third piston slidably inserted into the third cylinder, and the third piston on The third permanent magnet is rotated by a predetermined angle when the third piston moves by a predetermined distance, and the repulsive force acting on the first permanent magnet is changed when the first permanent magnet rotates, thereby changing the first permanent magnet. Adjust the rotation speed of the magnet.

The power generating device according to the invention can combine permanent magnets and crank arms to allow continuous rotational movement without the use of additional energy. In addition, the power generator can be freely manufactured according to the output and size according to the application and excellent in economic efficiency.

1 to 5 are sectional views illustrating the motion of the crank arm of the internal combustion engine according to the prior art,

6 is a cross-sectional view showing a power generating apparatus according to the present invention,

7 to 15 are cross-sectional views illustrating the interaction between the permanent magnets of the power generator according to the present invention,

16 to 21 are front and side views showing a permanent magnet of the power generator according to the present invention,

22 and 23 are cross-sectional views illustrating the operation of the power generating apparatus according to the present invention.

24 to 26 are cross-sectional views showing the internal structure of the cylinder of the power generator according to the present invention,

27 is a cross-sectional view for explaining the principle of acceleration of the power generator according to the present invention;

Figure 28 is a schematic diagram for explaining the motion of the permanent magnet of the power generating device according to the present invention.

* Explanation of symbols for the main parts of the drawings

32: S pole of permanent magnet A1 33, 34: S, N pole of permanent magnet B2

35: S pole of permanent magnet C3 46, 43 and 47: disc

55: rotor axis 52, 53 and 54: gear

9: crank arm 5: connecting rod

1: top dead center 61: needle valve

63, 64: high pressure pipe 66, 73: hydraulic valve

81, 83: hydraulic cylinders 57, 77: auxiliary oil tank

Hereinafter, a power generating apparatus according to the present invention will be described in detail with reference to the accompanying drawings.

This circle uses the principle of linear motion as the rotational movement to invest the 100kg of kinetic energy in the crank arm circumference to reversely rotate the crank arm and use it for the development of this power. When the crank arm is rotated to 50 degrees of circumference by force, as described above, when the crank arm circumference is supplied with only 30/100 percent of the amplified force, the invested 30 kg of kinetic energy is invested in the crank arm circumference. With the same force as / 1GO pro, the kinetic energy of the crank arm column becomes equilibrium and the crank arm column's force becomes zero.

At this time, when rotating the crank arm from 50 degrees of circumference to 40 degrees of circumference by the force of 70kg other than 30kg out of 100kg invested, 300kg is increased at the piston top dead center, and 70kg of the crank arm rotating movement is 3 + 70. At the same time, the 30kg that was supplied to the crank arm circumference of the 100kg amplified at the piston top dead center is 30-3.5 = 26.5kg.

When the 70kg lifts the crank arm up to 30 degrees circumference at 40 degrees circumference by the force raised to 73kg, 400kg rises at the piston top dead center, and the 73kg rotational movement of the crank arm rises to 4 + 73 = 77kg. Of the 100 kg amplified at the piston top dead center, the 30 kg supplied to the crank arm circumference is -30-3.5 = 26.5-4.5 = 22 kg.

When the 70kg is 73kg ... 77kg, when the crank arm is reverse fired from 30 degrees circumference to 20 degrees circumference, the weight of 60kg is increased by the piston top dead center and the 77kg of the crank arm rotational movement is 6 + 77 = The 30kg, which was raised to 83kg and supplied to the 100kg incremental crank arm circumference amplified at the piston top dead center, is -30-3.5 = 26.5-4.5 = 22-6 = 16kg.

When the 70kg is 73kg ... 77kg ... 83kg, when the crank arm reversely rotates from 20 degrees at the circumference to 10 degrees at the circumference, 705kg is raised at the piston top dead center and 83kg at the crank arm rotates. Of the 100 kg amplified at piston top dead center, the 30 kg supplied to the crank arm circumference would be 30-3.5 = 26.5-4.5 = 22-6 = 16-7 = 9 kg, rising to 7.5 + 8.3 = 90.5 kg.

When the 70kg is 73kg ... 77kg ... 83kg ... 90.5kg, when the crank arm is rotated back to the zero circumference at the circumference of 10 degrees by the force, the piston top dead center is increased by 905 kg. If the 100kg amplified + is increased to 100 + 905 = 1005kg, the 30kg supplied to the 100kg increase crank arm circumference amplified at piston top dead center becomes 0, and the 100kg amplified previously at the piston top dead center is raised as it is. The increased kinetic energy rises to 905kg + at the piston top dead center and rises to 1000kg.

As described above, 30kg invested by investing 100kg of kinetic energy in the crank arm circumference based on the crank arm principle using linear motion as the rotary motion is in equilibrium with the force on the crank arm circumference at the piston top dead center. When the force is set to 0, the 70kg other than the 100kg increase and the 30kg invested will cause the piston to rotate from 360 degrees to 0 circumference when rotating 360 degrees. Among the principles of raising up to 1005 kg, the application of this application is based on the principle developed by the company using the crank arm that used the 25 to 0 point of the circumference. Please refer to the following explanations for the following description when the crank arm is rotated in reverse and the piston top dead center rises from 300kg up to 1005kg. Let us explain in detail the principles that led to the increase.

Description 1 When the crank arm is rotated 10mm between 50 degrees and 40 degrees circumference, the crank arm moves the piston 10mm in a straight line to the top dead center by the connecting rod, The circumferential inclined surface, which has been rotated by 10 mm for 10 degrees up to 40 degrees, has a 7 mm lower circumferential (combed) inclined surface that is 3 mm smaller than the movement distance of 10 mm in which the piston moves in a straight line toward the top dead center. The 10-degree rotary motion of 10 degrees to the degree raises the number of decelerations 10-7 = 3mm at the piston top dead center.

Description # 2 When moving the crank arm 10mm from 50 ° to 40 ° circumference by 10mm, the piston moves in a straight line toward the top dead center 10mm distance. In the principle described, the crank arm rotates to raise the reduced specific gravity of 3mm to the piston top dead center.

Explanation 3 ... The principle of the low circumferential slope as described above is that when a straight horizontal line is drawn horizontally from the crank arm circumference of 50 degrees to the circumference of 310 degrees, a positive cross is formed between the zero point of the circumference and the circumference of 180 degrees. When measuring the distance from the positive + center and the center of the + type formed in a horizontal line from 40 degrees to 320 degrees of circumference, the lower circumference of 7mm, which is 3mm smaller than 10mm of the movement distance where the piston moves in a straight line toward the top dead center, is 50 degrees circumference. The crank arm rotates 10 mm for 10 degrees to -40 degrees to increase the deceleration of the decelerated pro number 10-7 = 3 mm to the piston top dead center.

As such, when the crack arm rotates 360 degrees by 100 kg of kinetic energy and rotates 10 degrees from 50 degrees to 40 degrees in circumference, the actual force of 300 deceleration is increased to the piston top dead center.

Description 1 ... When the crank arm is rotated 10 mm from 40 degrees to 30 degrees of the circumference by 10 mm, the piston moves the straight 8mm to the top dead center by the connecting rod, while the crank arm is 40 degrees in the circumference. The circumferential inclined plane, which rotates by 10 mm from 10 degrees to 30 degrees in circumference, has a 6 mm lower circumferential slope, which is 2 mm smaller than the 8 mm movement distance in which the piston is moved straight to top dead center. Rotational movement of 10mm for 10 degrees up to 30 degrees on the circumference causes the piston deceleration principle to 2 at piston top dead center to simultaneously raise 10-8 = 2 and 8-6 = 2 + 2 = 4mm to the piston top dead center simultaneously.

Description 2 ... When the crank arm makes a 10mm rotation from 40 degrees to 30 degrees in circumference of 10 degrees, the 6 mm lower circumferential incline of 2 mm smaller than the 8 mm movement distance in which the piston moves in a straight line toward the top dead center. One principle that the crank arm was rotating in the principle described above is as follows.

Explanation 3 ... The principle of the low circumferential slope as described above is that when a straight horizontal line is drawn horizontally from 30 degrees of the crank arm circumference to 330 degrees of the circumference, it forms a + shape that intersects the circumference of 0 to the circumference of 180 degrees. When measuring the distance from the + -shaped center point and the + -shaped center point formed in the horizontal line from 40 degrees of the circumference to 320 degrees of the circumference, the lower circumference of 6 mm, which is 2 mm smaller than the 8 mm movement distance where the piston moves in a straight line toward the top dead center, is 40 degrees to 30 degrees. The crank arm rotates 10mm up to 10 degrees, and the deceleration pros 10-10 = 2 and 8-6 = 2 + 2 = 4mm are combined to raise the piston top dead center simultaneously.

In this way, the crank arm rotates 400 ° from the circumference of 40 degrees to 30 degrees of the circumference while rotating by 100 kg of kinetic energy.

Description 1 ... When the crank arm is rotated 10mm between 30 degrees of circumference and 20 degrees of circumference by 10mm, the crank arm moves 6mm in a straight line toward the top dead center by the connecting rod. Crank arm 30 degrees circumference of 4mm lower circumference (cominclined surface) slope of 2mm smaller than 6mm of movement distance in which the circumferential (inclined surface) inclined plane rotated 10 mm from 20 degrees to 10 degrees Rotational movement of 10mm from 10 ° to 20 ° in circumference causes two deceleration principles to simultaneously raise 10-6 = 4 and 6-4 = 2 + 4 = 6mm to the piston top dead center.

Description 2 ... When the crank arm is rotated 10mm between 30 degrees and 20 degrees of circumference for 10mm, the 4mm lower circumferential slope of 2mm smaller than 6mm is obtained. One principle that the crank arm was rotating in the principle described above is as follows.

Explanation 3 ... The principle of the low circumferential slope as described above is that when a straight horizontal line is drawn horizontally from the crank arm circumference from 20 degrees to the 340 degrees circumference, a + shape is formed that intersects the diameter line from the circumference 0 to the circumference of 180 degrees. When measuring the distance from this + type center point to the + type center point formed in the horizontal line from 30 degrees of the circumference to 330 degrees of the circumference, a 4mm lower circumference less than 2mm less than 6mm of the movement distance in which the piston moves in a straight line toward the top dead center has a circumference of 30 °. The crank arm rotates 10mm between 10 degrees up to 20 degrees, and the deceleration pro numbers 10-6 = 4 and 6-4 = 2 + 4 = 6mm are combined to simultaneously raise the piston top dead center.

In this way, the crank arm rotates 360 degrees by 100 kg of kinetic energy while rotating 10 degrees from the circumference of 30 degrees to the circumference of 20 degrees.

Description 1 ... When the crank arm is rotated 10mm between 20 degrees of circumference and 10 degrees of circumference, the piston rotates 4mm in a straight line toward the top dead center by the curating rod, The circumferential inclined plane, which rotates 10 mm from 20 to 10 circumferences, has a 2.5 mm lower circumferential (compressed) slope that is 1.5 mm smaller than the 4 mm movement distance in which the piston moves in a straight line toward the top dead center. In the 10-degree circumference of 10mm, the two deceleration principles at the piston top dead center simultaneously raise 10-4 = 6 and 4-2.5 = 1.5 + 6 = 7.5mm to the piston top dead center simultaneously. .

Description # 2: 2.5 mm lower circumference (slope), 1.5 mm smaller than 4 mm of travel, in which the crank arm moves the piston in a straight line 10 mm from 20 degrees to 10 degrees in circumference. From the principle described above on the inclined plane, one principle that the crank arm has a rotary motion is as follows.

Explanation 3 ... The principle of the low circumferential slope as described above is that if you draw a straight horizontal line horizontally from 10 degrees of crank arm circumference to 350 degrees of circumference, the + shape is rigid with the diameter line intersecting from 0 points of circumference to 180 degrees of circumference. The distance between the + -shaped center point and the circumference from 20 degrees to 340 degrees is measured in the horizontal line, and the distance to the + -shaped center point is measured. Crank arm rotates 10mm up to 20˚ -10 degrees and decelerates 10 ~ 6 = 6 and 4-2.5 = 1.5 + 6 = 7.5mm. Compound rises.

In this way, the crank arm rotates 360 degrees by 100 kg of kinetic energy while rotating 10 degrees from 20 degrees to 10 degrees of the circumference, thereby increasing the actual speed of the 750 kg of the pro-numbered force to the piston top dead center.

Description 1 When the crank arm is rotated 10 mm from 10 degrees to 0 points of circumference, the crank arm moves 2 mm in a straight line to the top dead center by means of a curl rod. The circumferential (inclined) inclined plane that rotates 10 mm from 10 degrees to 10 circumferential points 10 degrees cranks the 1 mm lower circumferential (compressed) inclined plane that is 1 mm smaller than the movement distance of 2 mm in which the piston moves in a straight line toward the top dead center. In the figure, a 10mm rotational movement between 10 degrees to the zero point of the circumference causes two deceleration principles at the piston top dead center to simultaneously raise 10-2 = 8 and 2-1 = 1 + 8 = 9 to the piston top dead center simultaneously.

Description 2 ... When the crank arm moves 10 mm from 10 degrees to 0 points of circumference for 10 mm rotation, the 1 mm lower circumferential slope of 1 mm smaller than 2 mm of movement distance is obtained. In the principle described above, one principle that the crank arm was rotating was as follows.

Explanation 3 ... The principle of the low circumferential slope as described above is that the piston is similar to the zero point of the crank arm circumference and one distance from the 10 ° circumference to the + center point formed on the horizontal line from 350 ° to the circumference. The number of pros decelerated by rotating the crank arm 10mm from 10 degrees to 10 degrees from the circumference of the 1mm lower circumference 1mm smaller than the movement distance 2mm in a straight line movement to the point 10-2 = 8 and 2-1 Two deceleration principles simultaneously raise = 1 + 8 = 9mm to the piston top dead center.

As described above, the crank arm rotates 360 degrees by 100 kg of kinetic energy while increasing the actual 900 deg. Of the force of the decelerated professional number to the piston top dead center when rotating between 10 degrees from the circumference to 10 degrees from the circumference.

As described above, the difference between the rotational movement distance of the crank arm and the linear movement distance of the piston varies from 3/10 to 8/10. The same time as the crank arm rotates, the piston moves in a straight line. The difference between the circumference (inclined surface) and crank arm is also small at 3/10, because the crank arm rotates the (height) (-) lower circumference (compassed) slope of the circumferential (inclined surface) slope of the crank arm than the movement distance. The two deceleration principles, which are up to 5/10, are the principles of linear and rotary motion, and the structure itself is a structural deceleration principle that can only lose 72.5 kg of the energy of 100.

This circle invests 100 kinetic energy in the circumference of the crank arm described above, and when the crank arm rotates from the circumference of 50 degrees to the circumference 0 point during the 360-degree rotational movement, it is 700kg out of 300kg to 900kg. Permanent power developed by re-investing 170kg of the 700-900kg of oil generated by generating 700-900kg of oil using a Pascal hydraulic pump using a 900kg force to recharge the circumferential kinetic energy of the crank arm. The principle that causes continuous rotational motion without using the second energy will be explained as follows.

The permanent magnet used here is a super-strong magnet and the Gauss, which represents the magnetic force, is 4000 gauss.

The permanent power developed is a two-pole type, with zero circumference being 1 pole, 180 degrees circumference being 2 poles, and easy to explain.

We will explain the principle of A1 B2 C3 only for the zero point of the permanent magnet corresponding to the zero point and one pole of the circumference.

First, A1 will be a fixed magnet in this power and a magnet capable of freely adjusting the power rotation speed by moving in a fixed position according to the purpose (A1-1 is also the same). The B2 S pole will be a permanent magnet that generates kinetic energy that rotates 360 degrees by the repelling force (rotor).

(B2-2 is also the same.) C3 S pole is waiting to generate resistance repulsion against the A1 S pole in front of each other. Then, when B2 rotates 360 degrees and enters between A1 S pole and C3 S pole, When the force enters the state of zero, at the same time, it enters between the A1 S pole and the C3 S pole without any physical obstacle and enters the zero gravity state.

The principle that B2 is zero-gravity state is that the A1 S pole and B2 S pole generate resistance repulsion, and the B2 N pole and C3 S pole generate magnetic force that pulls each other, so that SS pole and NS pole are formed on both sides of B2. Since both pushing and pulling forces are generated equally, the magnetic force is in equilibrium so that B2 becomes the same principle as zero gravity in the centers of the A1 S and C3 S poles, without any influence of the magnetic force of A1 or C3 or any physical future. X ... and + form a reciprocating motion with zero force.

We have developed and ordered these techniques as the zero gravity principle. The developed power is based on zero gravity of A1B2C3, which corresponds to one pole with zero circumference, and A1-1 B2-2 C3-3, which corresponds to two poles with 180 degrees circumference. It is in the volume and the main force is at this time with the total force at zero.

At this time, if the rotor of B2-B2-2 is reciprocated to the left and right as in the X-shaped rotational movement principle, as described above, the rotor of B2-B2-2 is rotated from side to side at zero force without any influence of magnetic force or physical obstacles. Becomes

In this state, if you hold the non-ferrous metal disc equipped with A1-A1-1 and rotate it in the same way to the left and right of the X type, the rotary motion is driven by the strong propulsion force in the direction of twisting the X type by the resistance repulsion of the SS pole. I will try to.

In addition, when holding the base metal plate equipped with C3-C3-3 and trying to rotate the X-shaped movement, the N-S pole magnetic force is attracted by the strong force attracting each other.

In the mechanical engineering aspect, C3-C3-3 doubles in the opposite direction of B2-B2-2 when the rotor equipped with B2-82-2 is rotated 20 mm clockwise by the principle of rotational movement in terms of mechanical engineering. 40mm is reversed to X type at speed.

※ Note ... When explaining the principle of power developed above, the size is partially explained in order to facilitate this description. As it is commercialized, the permanent magnet is used in the production line according to the purpose. It does not matter in size.

At this time, SS pole of A1-A1-1 SS pole and SS pole of B2-B2-2 are rotated clockwise by strong driving force due to strong resistance repulsion. When the NN pole and the SS pole of C3-C3 are twisted to each other with X type, the NN pole and SS pole have the power to attract each other when C3-C3-3 reverses to type X. You will receive greatly.

However, B2-B2-2, on the other hand, is not related to the pulling force of the N-N and S-S poles.

In the front of B2-B2-2, that is, the direction of rotational movement, resistance repulsion occurs when the front of SS pole of A1-A1-1 and SS pole of B2-B2-2 is in close contact with within 0.5mm of 3/5. Since the SS pole of C3-C3 has 1/5 of the SS pole of A1-A1-1, the resistance repulsion is generated, so the rear side opposite to the B2-B2-2 rotational movement is not released from the zero gravity zone. B2-B2-2 is rotated clockwise by SS pole of A1-A1-1 and resistance repulsive force, and N pole of B2-B2-2 is C3- until it is completely separated from A1-A1-1. With the S poles of C3-3 at zero, independent of the pulling force, B2-B2-2 is rotating.

At this time, C3-C3-3 is affected by 100% of the pull force of the N-S poles when B2-B2-2 rotates.

As described above, A1-A1-1, B2-B2-2 and C3-C3-3 have the same poles and poles, so B2-B2-2 has A1-A1 = 1, SS pole and C3-C3 B2-B2-2 reverses C2-C3-3 to X-shape while destroying the law of zero gravity while B2-B2-2 rotates clockwise in zero gravity with zero force in the SS pole center of -3. Became the (gravity) of the zero-gravity zone, thereby revealing the impact of energy.

If we reorganize the principle described above, an object of no weight floats in the zero gravity space, which is the outer space.

If we recapitulate the principle described above, when an object of no weight floats in the zero gravity field, which is out of space, and escapes the zero gravity field, the attraction force is reduced by the force and weight that pulls the object by the law of universal gravity like Newton's law. A descending acceleration will cause the object to fall somewhere on Earth's surface.

Also, when the equilibrium of forces is the same on both sides, the object in the center of force will not be pushed to either side.

Also, for example, if a ball is placed in the center of a panel that has maintained its life, the ball will not roll in either direction.

However, if one of the horizontal panels is kept low on the slope, the ball will roll on the low slope to generate kinetic energy.

The principle developed here by using permanent magnets is the same principle.

In addition, the motive of the development of the principle of zero gravity due to the equilibrium of the permanent magnet is that the permanent magnet has the same force across the entire surface. This follows.

In addition, when the N-S pole is in close contact with each other, or when the N-N pole or S-S pole is in close contact with the larger force is required.

We developed this principle to develop the zero-gravity principle, which is the equilibrium of force, so that the NN pole and the SS-pole's resistance and repulsive magnetic force can be held within 0.5mm from the state of zero, and the crank arm of the internal combustion engine described above. Principle is based on the resistance repulsive force of SS pole of A1-A1-1 and SS pole of B2-B2-2, investing 100kg of kinetic energy of B2-B2-2 in the crank arm circumference to make the crank arm 360 degrees B2-B2-2 NN pole and C3-C3- by reinvesting 170kg of 700-900kg of force generated at the piston top dead center when rotating in the opposite direction and rotating from 25 circumference to zero circumference during 360-degree rotation. When the SS pole magnetic force of 3 is in close contact with each other, as described above, C3-C3-3 is reversed in the opposite direction of B2-B2-2 to form X so that B2-B2-2 in the zero gravity zone is A1-A1-1. SS pole is rotated 360 degrees by resistance reaction and B2 is circumferential 120 and B2-2 is circumferential 300 When C3 reaches 340 degrees in circumference, C3-3 returns to 160 degrees in circumference, B2 moves to 90-120 circumference, and B2-2 rotates to 270-300 degrees circumference. SS pole C3-3 coincides with A1-1 and SS pole in front and generates resistance repulsion. B2 is between SS pole of A1-1 and C3-3 and B2-2 is zero between SS pole of A1-C3. Will enter the state.

Based on the same principle as above, it becomes a moving body by continuous repetitive motion.

1-2-3-4-5 is omitted since it is described in detail above.

FIG. 6 is a schematic side view of a developed power line molded and assembled with permanent power.

The principle of FIG. 7 is to insert a permanent magnet of (33) S pole and (34) N of B2 into the center of the (balance) resistance repulsion force of the chip with the same A1 (32) S pole and C3 (35) S pole magnetic force. As shown in FIG. 7, the A1 (32) S poles generate resistance repulsions (30)-(30) around (28)-(29) and the (34) N pole and (35) S pole The principle of pulling is that both (32)-(33) SS poles and (34)-(35) NS poles are equal to each other and the pulling force is the same on both sides of B2, so B2 is in the center of (3D)-(31) of A1 and C3. In the same principle as weightlessness, B2 is freely reciprocating in both directions (36)-(37) from zero to zero, without any influence of the magnetic forces of A1 or C3 or any one physical disturbance.

In Figures 7-8, B2 maintains 0.5 mm between the fronts of the (32)-(33) SS poles and the (34)-(35) NS poles in the center of the A1 (32) S and C3 (35) S poles When reciprocating B2 in both (36)-(37) directions, the reciprocating motion is performed with zero force as described above.

At this time, when reciprocating to both the same principle (38)-(39) as A1 and B2, it tries to exercise by the force of resistance repulsive force toward the exercise.

At this time, when the C3 is to be reciprocated in both directions (41)-(42) in the same manner, the force of the magnetic force of the N-S poles of (34)-(35) is attracted by the force attracting each other.

In Fig. 7-8-9, when B2 rotates 10mm in the clockwise direction (37), C3 reverses 20mm in the X direction to position (41) opposite B2.

At the same time, the A1 (32) S pole and B2 (33) S pole (30) part have strong resistance repulsion, and B2 is (37) rotated 360 degrees clockwise, where B2 (34) N pole The magnetic force of the pole and C3 (35) S pole is attracted to each other between (31) and C3 is greatly influenced by the pulling force when reversing to position (41), but on the contrary, B2 is independent of the pulling force. B2 is the A1 (32) S pole and the B2 (33) S pole fires a resistance repulsion each other, B2 is (37) clockwise rotational movement.

When B2 rotates in the direction of (37), the principle that C3 (35) S pole and B2 (34) N pole become independent of the pulling force is that A1 (32) S pole and C3 (35) S pole are resistive. This is because parts (40) are firing against each other, so the opposite side of B2 (37) (36) is in the center of resistance (40) resistance.

7-8-9-10 degrees, B2 is completely out of zero gravity and A1 (32) S pole and B2 (33) S pole fire 100% of the repulsive force, causing B2 to rotate clockwise (37) clockwise ( C3, retracting 40mmX in position 41) coincides with A1 and 1/5 of the (33)-(35) SS poles in front of it and fires a resistive repulsion to stand in position (41).

As shown in Fig. 7-8-9-10-11, B2 continues to rotate (43) the circumference and (43) is affected by the resistance repulsion of the A1 (32) and S poles up to 90 degrees of the circumference. In the figure (43) when moving to 120 degrees of circumference, move 40mm again from the position (41) where C3 was 40mm backward as shown in 7-8-9-10-11-12 degrees and move to position (42) A1 (32) S pole and C3 (35) S pole coincide with the front, C3 stands in the position (42) and at the same time, C3-3 retreats 40mm even at 180 degrees. Move 40mm again from the previous (44) position and return to the (45) position.The A1-1 (45) S pole and the C3-3 (51) S pole fire the resistance repulsive force and the C3-3 and (45) Will be waiting at position.

At this time, (43) B2 rotated to 120 degrees of circumference continuously rotated and (43) 180 degrees of circumference, 2-pole A1-1 (48) S-pole and C3-3 (51) S-pole resistance to zero center force of resistance Enters the state of zero gravity and at the same time (43) B2-2 is rotated toward the 270 degree circumference by the force of the same principle resistance repulsion force at (2) circumference 180 degrees 2 poles (43) 0 circumference 1 pole 7-8--17-11-12-13 Degrees B2 and B2-2 rotate 360 degrees as they enter the center of resistance repulsion of 1 pole A1 (32) S pole and C3 (35) S pole and become zero gravity. It is a principle that the movement of (43) circumference 0 point 1 pole and (43) circumference 180 degree 2 pole alternately rotates 360 degrees continuously by the force of resistance and repulsion.

14, A1 is located at 0 on the circumference of A1, A1-1 is located at 180 degrees on the circumference, and B2 is rotated 20 mm in the clockwise direction and (37) clockwise on the A1 at (43) at the circumference of 0 °. B2-2 is also rotated clockwise 20mm (37) clockwise with the front of A1-1 located at (43) circumference 180 degrees.

In this figure, C3 is the position where 40 mm is reversed from (42) to (41) position in the opposite direction to B2, and C3-3 is also reversed by 4 mm from (45) to (44) position in the opposite direction of B2-2. In this power, (43) A1B2-C3 coincides with the front of the circumference 0 point, and (43) A1-1-B2-2-C3-3 coincides with the pole at 180 degrees of circumference, so that B2-B2-2 Figure 1 is a schematic front view of a single motion immediately before the motion for a 360-degree rotational motion in the center of resistance repulsive force (start).

Fig. 15 shows the (46) circumference with A1-A1-1 mounted on this permanent power in the same direction as C3-C3-3 at 40 mm driving speed (39)-(38), ) The principle that the rotation speed can be adjusted freely using the pedal is as follows.

In this figure, if the principle explanation is made with only one pole of zero circumference 0 point as follows, this power circumference of one pole C3 will be moved back to position 42 by moving 40 mm from position (41) which has been reversed 40 mm. When A1 is retracted from position 1 pole (39) to position 40mm (38), B2 rotates 360 degrees and attempts to enter the center of resistance repulsion between A1 (32) S and C3 (35) S Since A1 is back to the (38) position, the A1 (32) S pole and the B2 (33) S pole approach first and generate a resistance repulsion, which interferes with the rotational movement of B2, and B2 is the A1 (32) S A1 (32) S and C3 (35) The front of pole S2 passes through the zero gravity zone (40) where resistance front is generating 1/5 resistance.B2 (34) N and C3 (35) B2 is subjected to rotational movement disturbance due to the influence of the magnetic forces of the (34) N- (35) S poles attracting each other until the (31) which is completely out of the S pole front.

As such, B2 and B2-2 lighten two rotational obstacles in one pole and two poles in one rotation of 360 degrees, and A1-A1-1 is viewed according to the distance to advance the (39)-(38) times. The rotational speed of the power can be adjusted freely.

FIG. 16 shows that A1 is mounted on the 1 pole of the non-chuck metal (46) of the stainless steel plate with the (1) pole facing the (32) S pole. 17 is a side view of FIG. 16 and 16-17 are schematic sectional views separated from the main power.

18 is mounted on a non-ferrous metal (43) disc 0 point 1 pole of a stainless steel plate with the B2 (34) N pole in front (43) B2-2 at (180) disc with the (50) N pole in front (37) is a clockwise 360 degree rotational movement direction indication and (36) is a 360 degree (37) rotational direction opposite direction.

FIG. 19 is a side view of FIG. 18. FIG. 19 shows a disc of a stainless steel pipe 43 and a 180-degree pole of 1 pole and a 180-degree pole of 180 degrees, respectively. Likewise, the B2 (33) S poles and the B2-2 (49) S poles protrude in the same direction on the same side as the unevenness, and (43) disc 1 pole B2 (33) S pole opposite B2 (43) N pole And (43) disc 180 degrees 2-pole B2-2 (49) protruding poles B2 (50) N on the opposite side of the S-pole 18-19 is the front and side of the rotor of B2-B2-2 Schematic cross-sectional view of the structure by a line.

FIG. 20 shows the C3 (35) S pole mounted on the 1 pole of the non-ferrous metal 47 disc of the stainless steel plate in front (47) and the C3-3 (51) S pole mounted on the 2 pole 180 degrees in the circumference. Fig. 21 is a cross-sectional view of the front view of Fig. 20 taken along line.

22 shows A1 (32) S poles at (46) 1 disc zero point and (1) A1-1 (48) S poles at 180 degrees 2 pole circumference (43) B2 (33) at 1 pole 0 circumference. The B2-2 (49) S-pole fires a resistance repulsion against the S pole and (43) circumference 180 degrees two poles, so that the (43) rotor of the B2 (33) and B2-2 (49) SS poles is (37) clockwise. Direction B2 34 is (43) circumferential 30 degrees B2-2 (50) is (43) circumferentially formed at the rotor center 55 axis of the B2-B2-2 (43) The half gears (53)-(54) of the gear will rotate in the opposite direction of the center gear (52) .The crank arm (9) on the (A) side will be (14) the circumference (12) at 25 degrees ( 14) When rotating around the circumference (21) 0 point (5) When lowering the piston (6) in the hydraulic pump to (1) top dead center by the connecting rod (5) (56) (1) At the top dead center, the pressure of (oil) hydraulic pressure rises 1000kg and the oil of the elevated pressure is discharged simultaneously to the (62) and (60) spheres by opening the needle valve (61) in the (62) hole ( 63) and (64) It is assigned to each part by pressure pipe. First, when 2.5kg-3kg of hydraulic pressure is generated just before the 1000kg of hydraulic pressure is raised at the piston top dead center, if the hydraulic pressure of 2.5kg-3kg is raised in the (60) sphere, (66) As piston (67) moves in a straight line towards cylinder (73), the hydraulic passages (68)-(69) are blocked and at the same time the (71)-(72) hydraulic outlets are opened and closed.

At this time, when piston (67) from (66) moves toward cylinder (73), oil in cylinder (73) is discharged to outlet (74) by movement of piston (67) and (75) It is injected into the injection port (76) by the high pressure pipe (76) and injected into the oil auxiliary tank (77).

At the same time, the 1000kg of hydraulic pressure raised at piston top dead center (6) is discharged into the (62) port as the needle valve is opened and closed (61). When the hydraulic pressure of 150kg-170kg of the 1000kg hydraulic pressure is raised in the hydraulic cylinder (81) by the piston (82) in the linear movement to the (83) to the cylinder (81), the lower end of the rocker arm (84) (85) When (82) Piston moves to straight (86) by straight motion (84) Rocker arm upper end (87) When X moves towards (88) C3-C3 -3 A nonferrous metal (47) disc with permanent magnets is retracted by rotating 40 mm from position (42) to position (41).

At the same time, the oil in cylinder (83) is discharged to outlet (91) and is discharged to outlet (71)-(72) by means of high pressure pipes (94)-(95). It is discharged and injected into the auxiliary tank (77) by the injection port (97) by the high pressure tube (96).

At the same time, disc (83) with oil discharged to (91) outlet in cylinder (83) and needle valve (89) and outlet valve (47) with outlet port C90 blocked (90). When a 40 mm high speed rotation (41) stops momentarily (stop) at the (41) position, the excess oil between piston top dead center (92) and (93) The pressure is raised by piston # 83 and the shock is relieved.

In addition, the principle that disc (47) equipped with C3-C3-3 retracted 40mm and stood until the next operation at position (41) was carried out. The valve shuts off and the hydraulic valves (66)-(73) are blocked by the pistons (68) through the valves (68)-(69). Since the hydraulic pressure is raised, the (47) disc with C3-C3-3 is standing in the state of 40mm backwards, and then the piston (6) on the main road (B) descends to generate 1000 kg of hydraulic pressure. When it rotates again 40mm, it returns to the (42) side.

Next, the piston (6) of the main figure (A) produces 1000 kg of coalescing, and 150-170kg is supplied into the hydraulic cylinder (81) by the high pressure pipe (64), and the remaining 830 kg is the high pressure pipe (98). Is discharged by 125 safety valves in the following process.

In addition, the piston (6) side of the main road (6) descends to generate 1000kg of hydraulic pressure, and when it is reversed, oil is sucked into the (59) sphere and released.

Following 22-23 degrees, B2 (33) is continuously rotated at (43) circumference 30 degrees and reaches (43) circumference 120 degrees and main body B2-2 (49) is also continuously rotated at 210 degrees ( 43) When the circumference reaches 300 degrees, (C) side (14) Circumference (21) 0 to (9) Crank arm (43) in the opposite direction of the rotor (14) Circumference movement 180 degrees circumference Piston (6) is reversed from (1) top dead center by (5) connecting rod (rod).

At this time, when piston (C) of the (C) side retreats to the bottom dead center, the needle valve opens in the inlet (59), and oil enters into the inlet (59). When the piston (6) is reversed, the vacuum is released and the sucked oil is kept in the cylinder top dead center (56) in order to raise the hydraulic pressure 1000kg by linearly moving back to the top dead center with the piston (6). do

Crank arm (9) side (D) and (C) side (9) crank arm (D) side (14) Crank arm (9) at circumference 180 degrees (43) (14) Piston (6) will be lowered to (102) Cylinder (1) Top dead center by connecting rod (5) to (5) At the top dead center between (1) and (6), the hydraulic pressure of 1000kg is increased and the hydraulic pressure discharged to the discharge port (104) is discharged through the hydraulic outlet (76) and the needle valve (103). The next process is operated by the high pressure pipe and (94). First, when the hydraulic pressure of 2.5-3kg occurs just before the 1000kg oil pressure is raised at piston top dead center (6), If the hydraulic pressure of 2.5-3 kg is raised in the cylinder (73) by the inlet port of the hydraulic valve (74), the piston (67) in the cylinder (73) moves in the direction of the arrow (66). The hydraulic outlets (71)-(72) are blocked and the hydraulic outlets (68)-(69) are opened and closed.

At this time, the oil in the cylinder (66) is discharged to the outlet (65) and the oil injected into the inlet (60) by the high pressure pipe (63) is injected into the (57) auxiliary tank.

At the same time, the 1000kg hydraulic pressure generated between the piston (6) and the top dead center (1) on the (D) side was changed to the 1000kg hydraulic pressure as the needle valve (103) opened and closed the outlet (104) as before. When the hydraulic pressure of 150-170kg is raised in the hydraulic cylinder (83) when it is simultaneously injected into the (90)-(91) inlet by the high pressure pipe (94), the piston (82) in the cylinder (83) Arrow direction (81) Straight movement into cylinder (84) Rocker arm lower end (86) Move to (85) (84) Rocker arm upper end (88) (87) In case of X-axis movement toward the side, disc (47) equipped with C3-C3-3 rotates 40mm from (41) to (42).

At this time, when piston (82) moves in a straight line toward cylinder (81) by oil pressure in cylinder (83), oil in cylinder (81) is discharged into sphere (80) and high pressure (64)-(107) The hydraulic valves (66)-(73) (68)-(69) are discharged to the open and closed outlets by the pipe and injected into the inlet (109) by the high-pressure pipe (108) and into the (57) auxiliary tank. Is injected.

Also, piston (82) when (47) disc with C3-C3-3 is rotated at high speed from position (41) to position (42) to momentarily stop (stop) at position (42) ( 105) The excess oil between the tip and cylinder top dead center (106) (106) causes hydraulic pressure on piston (82) to alleviate the impact.

In addition, the principle that disc (47) with C3-C3-3 is stopped until the next operation is made at the position (42) is that the (D) outlet (104) has the needle valve (173) In the (94) and (83) hydraulic cylinders because the (66)-(73) hydraulic valves (73) (71)-(72) were blocked by the piston (67). The hydraulic pressure of 150-170kg is raised, so the disc (47) equipped with C3-C3-3 is lowered from the (42) position to the (C) side (56) hydraulic pump (6). It will stand until it generates hydraulic pressure.

In addition, (d) side (172), the hydraulic pump (6) generates 1000 kg and supplies 150-170 kg into the hydraulic cylinder (83) by the high pressure pipe (94), and the remaining 830 kg is the high pressure pipe (110). By the following process 125 is discharged by the safety valve.

At this time, when piston 82 moves in a straight line, disc 47 on which C3-C3-3 is mounted by rocker arm 84 rotates 4 mm from (41) to 42 (42). C3 (35) S pole coincides with the front of A1 (32) S pole when it is returned to position) and generates resistance repulsion. (46) C3-3 is located at (44) position at the circumference of 180 degrees. By moving 40mm up to (45), the C3-3 (51) S pole and A1-1 (48) S pole coincide with the front to generate resistance repulsion.

At the same time, the permanent magnets of the B2 (33)-(34) SN poles (46) rotated 120 degrees from one pole of the zero point of the circumference are the (46) circumference 180 degrees two poles A1-1 (48) S poles and C3. The -3 (51) S pole enters the zero state of force into the equilibrium center of force where the resistive force is generating resistance and is in zero gravity and at the same time (46) circumference of 180 degrees and (43) circumference of 300 degrees of circumference. The permanent magnets of the B2-2 (49)-(50) SN poles which also rotated up to (46) 0 point 1 pole A1 (32) S poles and C3 (35) S pole resistances. As described above, A1 (32) S pole and B2-2 (49) S pole generate resistance repulsive force at each one pole of zero point of circumference as described above. 2 is a fire-fighting movement from (46) zero pole of one pole to (43) 30 degrees of circumference. (46) A1-1 (48) S pole and B2 (33) S pole are also resistance to two poles of 180 degree circumference. The repulsive force is generated at the same time (46) circumference 180 degrees 2 poles (43) At the same time, the crank arm of No. 22 (A) (9) above (14) continuously rotates the circumference (14) 21) When moving to the zero point (1000), the piston (6) is lowered to the cylinder (1) top dead center by the connecting rod (5) in the hydraulic pump cylinder (56). Immediately before the hydraulic pressure of the gas is increased, 2.5-3kg hydraulic pressure is injected into the (65) inlet by the outlet (60) and the high pressure pipe (63). Piston # 67 moves straight into cylinder # 73, and outlets (71)-(72) open and close; piston (6) enters (1) top dead center to raise 1000 kg of hydraulic pressure ( When the needle valve (61) is opened and closed, the hydraulic pressure discharged to the outlet (62) is injected into the injection holes (79)-(80) by the high pressure pipe (64) and the hydraulic cylinder (81) When the hydraulic pressure of 150-170kg is raised in the (82) piston when the piston moves straight to the cylinder (83), the rocker arm (84) the lower part (85) moves to the (86) rocker (84) When the upper arm end (87) moves toward (88) and the (47) disc with C3-C3-3 rotates 40 mm in (42) and retracts to position (41) (46) ) B2-2 belonging to 0 poles of 1 pole A1 (32) S pole and (43) 2 poles of circumference (49 S poles and resistance repulsion are generated and B2-2 is continuously rotated and (46) circumference 180 degrees 2 A1-1 (48) S pole and (46) circumference 180 degrees two poles on the pole, A1-1 (48) S pole and (43) B2 (33) S pole belonging to the first pole B2 is continuously rotated in the direction of (37), and (46) is the same principle as described above toward the circumference of one pole. B2 and B2-2 are rotated 360 degrees by resistance repulsion while alternating one pole and 180 degrees two poles alternately. It becomes a principle that makes a rotary motion.

24-25-26 are the rotational movements of the crank arm (9) described in FIGS. 22-23 (14) while rotating the circumference (14) from the circumference (12) 25 degrees to (21) 0 point Connecting rod (rod) end pin hole is formed on pin (111), piston (6) is inserted into (56)-(102) hydraulic pump cylinder (56)-(102) cylinder (1) Below is a description of the internal and external structure of the (Pascal) hydraulic pump which raises the hydraulic pressure of 1000 kg when descending to the following.

24 is a schematic cross-sectional view of a hydraulic pump by a line. FIG. 25 is a schematic front view of a hydraulic pump by a line. FIG. 26 is a half oblique view of a schematic frontal view of a three-dimensional hydraulic pump.

24-25-26 and the partial description above refer to the (reference) composite of the numbers used in FIGS. 22-23. (56)-(102) are hydraulic pump cylinders and (6) are pistons. (57)-(77) will be the oil auxiliary tank, (1) will be the cylinder top dead center of (56)-(102), (62)-(174) will be the hydraulic outlet and (113) will be (6) When the piston is reciprocating up and down, it is formed by a grooved groove and a wall to correct the center of the piston by the 112. Number 114 will be the inlet and outlet when the piston moves up and down.

FIG. 27 is to adjust the speed of B2 rotation by freely adjusting A7 from (46) position of circumference 0 point (39) to position (46) of circumference (38) in the description of FIG. 15 previously described. The principle of the accelerometer that adjusts at low speed is explained. In Fig. 27, the parts and their usage are described in (46), circumference (39) and 0 point position with A1 (32) and vice versa. The figure is equipped with A1-1 (48) and the center (55) will be the B2-B2-2 rotor center (55) shaft, and the main road (115) will be the axureta (footboard) delivery and the direction of the arrow When lowering the cylinder, the hydraulic cylinder (116) in the hydraulic cylinder (117) moves in the direction of the arrow, and the oil at the top dead center of cylinder (117) is hydraulically raised and discharged to the outlet (118). When the hydraulic pressure is increased in the cylinder (121) by the injection port (120) by the high pressure pipe (1) When piston 22 moves in the direction of the arrow (130), it is discharged to the oil (125) safety valve outlet within the hydraulic cylinder top dead center (122) and the rocker arm bottom (123) when the piston moves in the direction of the arrow (123). When the # 1 movement is toward (124), the (46) disc with A1-A1-1 is mounted (38) when the top of the rocker arm (127) moves up to (126). Rotation of 40mm to reach (39), the rotor of this power B2-B2-2 is the highest speed ... (115) (foot) when you step on the lung (98) When the hydraulic pressure is increased to the inlet (129) by the high pressure pipe (110) to the inlet (121) and the hydraulic pressure is increased within the cylinder top dead center (130), the piston (122) is retracted toward the (120) inlet Rocker arm lower part (124) when piston (122) retracts straight (128) rocker arm upper part (126) when (129) moves toward (123) When A1-A1-1 is mounted and the plate (46) rotates 40mm from (39) and retracts toward (38), B2-B2-2 rotates 360 degrees and A1-C3 and A1 When attempting to enter the zero force into the center of zero gravity of SS pole resistance repulsion of -3C3-3, the resistance repulsion of SS pole of 82-B2-2 and SS of A1-A1-1 occurs. The rotor is a schematic side view by means of principle diagrams, such as an automobile axeletta that is subjected to rotational movement obstacles.

In the description of FIGS. 22-23, the piston (6) to (6) (b) to (6) raises 1000kg and hydraulic pressure to move the (47) disc equipped with C3-C3-3. The remaining 830kg of hydraulic pressure was opened (130)-(131) needle valve by the inlet of Fig. 27 (129) by the high-pressure pipe of (98)-(110) and the safety valve (125). Discharged to the bulb.

In this way, the permanent magnet and the crank arm were synthesized and developed to develop a breakthrough power that continuously rotates without using the second energy. In addition, the power and volume can be freely produced and produced according to the purpose, and the economic and marketability are excellent. In addition, the economic growth can be drastically increased by becoming a reliable business structure with no competitors. I will.

The present invention has been described above using an embodiment, but the present invention is not limited to the above embodiments, and various modifications can be made within the spirit and scope of the present invention. Clear to

Claims (5)

First and second crank arms, one end of which is extrapolated to the first and second crankshafts spaced apart from each other by a predetermined distance: first and second ends of which are coupled to the other ends of the first and second crank arms, respectively. Connecting rod: First and second pistons coupled to the other ends of the first and second connecting rods, respectively: First and second cylinders for guiding movement of the first and second pistons: The first and second First means for applying a rotational force to the crank arm; and second means for applying a part of the pressure generated by the movement of the first and second pistons to the first means. Device. According to claim 1, wherein the first means is a pair of first permanent magnets rotatably mounted to the first disc, the second spaced apart at a predetermined interval on one side of the first disc to be parallel to the first disc A pair of second permanent magnets rotatably mounted to the disc, and a pair of third permanently rotatably mounted to the third disc disposed to be spaced apart from the other side of the first disc to be parallel to the first disc by a predetermined interval. A magnet fixedly coupled to a center of a connecting member connecting the pair of first permanent magnets, a first gear fixedly coupled to one end of the shaft, meshed with the first gear, A pair of second gears fixedly coupled to a second crank arm, respectively, and a hydraulic cylinder for moving the second permanent magnets a predetermined distance when pressure is applied, wherein the first and third permanent magnets are respectively S poles are placed facing each other The first and second permanent magnets are disposed such that the S pole of the first permanent magnet and the N pole of the second permanent magnet face each other, and the first, second, and third permanent magnets are in a straight line. When in position, the magnetic force acting on the first permanent magnet is in equilibrium, and when pressure is applied to one side of the hydraulic cylinder, a third piston slidably inserted into the hydraulic cylinder is moved and attached to the third piston. The first permanent magnet is rotated by the repulsive force with the third permanent magnet when the second permanent magnet connected to the other end of the rocker arm is rotated by a predetermined angle while the rocker arm coupled to one end rotates. And the shaft rotates in a direction opposite to the direction. 3. The hydraulic system of claim 2, wherein the second means is connected to the first and second cylinders by a plurality of first high pressure pipes and is configured to induce a pressure generated by the movement of the first and second pistons in one direction. A valve, wherein the hydraulic valve has first and second passages, and when the first piston reaches its top dead center, the first passage is closed, the second passage is opened, and the second piston is When the top dead center is reached, the first passage is opened and the second passage is opened to apply some of the pressure generated by the first and second pistons to one side of the hydraulic cylinder through a second high pressure pipe. The remaining hydraulic pressure not applied to the hydraulic cylinder is applied to the outside through the bypass valve, the power generating device. 4. The method of claim 3, wherein the diameter ratio of the first and second gears is such that the first permanent magnet is rotated when the second permanent magnet is displaced from the initial position and again the first permanent magnet is in the initial position. Before entering, the second permanent magnet is returned to the initial position so that the first permanent magnet enters the initial position without being influenced by magnetic force, and the first permanent magnet enters the initial position without being affected by magnetic force. And the second permanent magnet is set to rotate continuously by applying a magnetic force to the first permanent magnet again as soon as the first permanent magnet leaves the initial position again. 3. The rocker arm of claim 2, wherein one end of the rocker arm is coupled to the third permanent magnet, and the other end of the rocker arm is coupled to a third piston slidably inserted into the third cylinder. The third permanent magnet is rotated by a predetermined angle when the third piston moves by a predetermined distance, and the repulsive force acting on the first permanent magnet is changed when the first permanent magnet rotates, thereby rotating the first permanent magnet. A power generating device, characterized in that the speed is adjusted. ※ Note: The disclosure is based on the initial application.