JPS6083959A - Image processing device - Google Patents

Abstract

PURPOSE:To increase the number of degrees of freedom in image formation by performing image formation under different conditions for plural originals and providing a control means which can change the precedence of image formation. CONSTITUTION:An original placing part 2 is provided with plural original placing bins 4-8 where originals can be placed. When an original 9 is placed in the original placing bin 4, an original detecting microswitch SW1 is operated to indicate the copy number to a copy counter, and the original 9 is carried in the direction of an arrow A and is sent to an original carrying device 33. The original 9 is placed on an original glass 35 of a copying machine 34 and is subjected to optical scanning. Next, the original 9 is sent to an original receiving part 3. Original receiving bins 36-40 are provided in the original receiving part 3 in accordance with original placing bins 4-8, and the original 9 is returned to the original receiving bin 40. If there is an original to which priority is given, a belt 79 is driven reverse to evacuate temporarily the original on the glass 35. By this constitution, the number of degrees of freedom in image formation is increased.

Description

DETAILED DESCRIPTION OF THE INVENTION The present invention relates to image processing, and is capable of storing a different image output means 1 for each of a plurality of images, and furthermore, after interrupting the image output of image information by the image output means, an appropriate The present invention relates to an image processing device capable of outputting an image from image information.

Conventionally, a plurality of images have been obtained by performing processing such as copying an image of a document.

By improving such a device, we provide an image processing device that can easily tlt images even if there are multiple images to be processed.

The present invention includes a storage-r stage capable of storing different output conditions for each of a plurality of image information, and an image storage device for outputting the one image information based on the output condition for one of the plurality of image information. an output means, and means for interrupting image output of the image information by the image output means;
The present invention provides an image processing apparatus comprising means for interrupting image output of the image information among the plurality of image information and then causing image output of the interrupted image information for 11 hours.

Other objects of the present invention will become clear from the description of the embodiments given below in conjunction with the drawings.

FIG. 1 is an external view of an image processing apparatus according to the present invention.

In the figure, CDU is a copy requesting device, on which a document to be copied is placed. COP is a copying machine, and billing device C
The original placed on the DU is fed to the original table of the copying machine COP via the transport device W and the Car u. CDU is a copy paper sorting device, which sorts and places the documents placed on the copy request device @CDU.

A sectional view of the copy requesting device CDU and the conveying device Caru described above is shown in FIG.

In the same IΔ, ■ is the copy requesting device shown in FIG.

11
6.7.8. is installed.

When the original 9 is placed on the original pin 4, the original detection micro switch SWI that detects the presence or absence of the original is activated, and the detection lamp (Δn 1\) is lit. It is also possible to instruct a copy selector of a copying machine or the like to a copy counter, which will be described later, to copy the document 9 placed on the document tray 4.This electrical sequence control will be described later.

When the document detection microswitch SWI moves f1, the pickup rollers 10 on the three sides descend to the highest document 9 with the rotating shaft 11 as a fulcrum, and the IbL document 9 can be transported. The rotating shaft 11 and the pickup roller 10 are connected by a bell 1, '9, which is not shown in the figure, and when the rotating shaft 11 rotates around a specific point 115+, the document placement bin 4 is moved. Document 9 is sent out one by one from one side. The document 9 is conveyed in the direction of the arrow via the kite plates 12, 13, the driving rollers 14, and the rollers 15.

That is, the kite board 12, 1.3, the drive roller 14,
Roller 15, kite board 16, 17. Kakeru! I! IJ roller 18, roller 19, kite board 20, 21, drive roller 2
2, roller 23, kite' plate 24a.

24b, drive roller 25, roller 26, Kai I/plate 27
, 2+3, drive roller 29. The document passes through the roller 30 and the kite plates 31 and 32 11 and exits the document placement section 2.

Incidentally, the same applies to the original 'Pt, the placing plate 7b, and 6.7.8.

[, The original document that has left the original document placement section 2 as described above is sent to the document transport device 1i;i (original transport device Caru shown in FIG. 1). The document transport device 33 includes a document crow 35 which places the document on a copying machine or the like 34 and performs optical scanning.
It is configured to appear on.

''The original placed on the bipedal original crow 35 is then sent to the copy requesting device ``Guyu's original document receiver section 3.''

Therefore, corresponding to the document placement pens 4, 5, 6, 7, and 8, the document receivers are in 36, 37, 38, 39, and 40 pens.

Established: ;11. That is, when the original 9 placed on the original placement pin 4 reaches the IJ position at the original position 91 in the original transport device 33, the original holder is returned to the pin 40.

That is, the document 9 that has passed between the kite plate 41, roller 42, kite 43, and conveyance heald 44 has a kite L//<-45.
rotates with the lever 46 as a fulcrum by the 1'1 movement of the plank banyer as shown in the figure, and the document is not received 74.
You will be guided to 0.

The bell 149 installed on the pulleys 47 and 48 is the original 9
In order to smoothly feed the rear end of the document, especially to the document receiving pin 40, such healds are provided on each document receiving pin 40.

The pulley 47 presses against the conveyor belt 44 and rotates. By placing the heald pressing plate 50 on the front side of the conveyance bell I-44, the pulley 47 can press the conveyance heald 44 with an appropriate pressure.

Next, the drive system of this device will be explained with reference to FIG. 3.
3 is fixed. A sprocket 55 fixed to the drive roller 29 (Fig. 2) on which the chain 54 is hung, a sprocket 57 fixed to the support 56, a sprocket 58 fixed to the drive roller 25, a sprocket 60 fixed to +1+ 59, Sprocket I/61 fixed to drive roller 22
, sprocket 63° drive roller 18 fixed to shaft 62
A sprocket 64 fixed to the shaft 65, a sprocket 66 fixed to the shaft 65, a sprocket 67 fixed to the drive roller 14, a sprocket 69 fixed to the bottom 168, and then rotatable eye 1z Wrath brockets L-70 and 71 are connected. and then rotated. In this manner, the document placement section is driven.

Further, the document conveyance device 33 has a sprocket fixedly attached to the motor shaft 52 of the drive motor 51,
A sprocket 72 is fixedly attached to the sprocket 72, and a chain 73 is hung thereon. A gear 74 is fixedly attached to the shaft, and the shaft 7 is meshed with the gear 74.
5 and gear 76 several times. A rubber conveyor belt 79 is attached to a shaft 78 of a pulley 77 and rollers 77, 78 so as to mesh with a gear 76. A suction plate 80 is provided inside the conveyor belt 79, and the inside of the plate serves as a suction box by the action of a suction fan 81.

Further, a partition plate 82 is similarly attached to the lower part, and the inside of the partition plate becomes a suction box due to the action of a suction fan 81.

The original document leaving the document/holding section 1 2 passes through the guy F plates 83 and 84, passes between the suppression rollers 85 pressed against the conveyor belt 79, is placed on the conveyor belt 79, and is conveyed in the direction of arrow B. The document passes between the conveyor belt 79 and the guide held 86, and then reaches the lath 35L, and the movement of the conveyor belt 79 is stopped by releasing an electromagnetic clutch (not shown) by the paper leading edge detection device 87. , upon completion of the image creation process to obtain the desired copy as detected by the scanning gamma detection device 88, i+)
The exit guide 89.9 allows the document to be replaced with the next document.
0 and exits from the document conveyance device 33.

The roller 91 inside the conveyor belt 79 is sunk so that the v1 output of the document can be carried out smoothly.

Reference numeral 92 denotes a paper leading edge detection device, which detects the document glass 351 when there is a copy of a bλ document to be prioritized. The manuscript posted on 1
Time! ! This is a detecting means for detecting the retracted position 16 of the original when the PEL I-79 is driven in reverse in order to retract the original. FIG. 5 is a perspective view of the conveying device. To further describe the conveying device, I@feeding device side plate 92 is 2
There are two plates supporting this device. Roller 9 inside
3. There is also a roller side plate 92a that mainly supports the roller 94.

Five conveyor belts are hung on the rollers 93 and 94 at the 51st Δ. The transport bell) 95 is provided with small holes at appropriate intervals. This is because the document placed on the conveyor heald 95 is conveyed by the movement of the conveyor heald 95, but when it reaches the lower part of the conveyor belt 95, the document is suctioned through the small holes of the conveyor belt 95 by the action of the suction fan 96. Make sure you don't fall.

A suction fan is provided in the center, and it is possible to convey the material by its suction force.

The roller 93 is driven by a drive source (not shown). A roller pulley 98 is fixed to a roller shaft 97 of a roller 93. Further, a pulley 100 is fixed to the support 99. A belt 101 is wrapped around the roller pulley 98 and the pulley 100 to transmit rotation.

゛The wire pulley 104 is activated by the action of the city magnetic clutch 102.
is wound and converted into a linear pressure motion by the movement of the wire 104.

Further, one end of the wire 104 is hung on a pulley 106 that can be rotated by a support 105, and the external force of the wire 104 is applied to the support 105.
07, one is hung on a belley 108 that can be rotated, and one is sunk on a slide bearing 1o9, respectively.
, I, died. Slide stand 109 is slide stand 11
I am fixing the slide bearing that slides 0. The slide shaft 110 is fixed to a roller side plate 124' (not shown), and the slide shaft 110 is fixed to a roller side plate 92a. Each fly 111 has a slide bearing that allows a slide shaft 112 to move.

A movable plate 113 is fixed to the slide bases 109 and 111. This movable plate presses the document against the stop roller 114.

Inside the conveyor heald 95 suspended on the rollers 93 and 94, a bottom plate 115 and a top plate 11'6 are firmly sunk into the roller side plate 92a.

The roller 114 is rotatably removed from the roller side plate,
When the transport heald 95 rotates, the stop roller 114 rotates, and when the transport heald 95 stops, the stop roller 114 rotates.
It doesn't rotate either.

There is a unit inside the roller side plate 92a to ensure the change in orientation of the document. That is, the direction changing side plate 1
16 are on both sides, and rollers 117, 118, 119 are rotatably mounted. Moreover, the ends of the rollers are also rotatably attached to the side plate 123 of the conveying device.

A bell 120 corresponding to a conveyor belt is hung from the rollers 117, 118, and 119.

- The above-mentioned conveyance device is used as a copier COP as shown in Fig. 6.
One end of the transport device Caru is fixed by a hinge TB, and as shown in the figure, the transport device Caru rotates around the hinge and can place an original to be copied immediately on the original glass of the four-machine COP.

Note that providing a large number of suction holes in the conveyance belt 79 in the document conveyance unit 33 provides an extremely good conveyance force when the document reaches the lower part, that is, the document crow 35, but the document is small compared to the copy paper. In some cases, there is a disadvantage that the shape of the hole is clearly reproduced. Taking this point into consideration, the goal is to achieve efficient conveyance with the minimum number of holes.

The document receiving unit 3 has a transport heald 44 on rollers 44a and 44b.
It is hung.

A gear 121 is fixedly provided to drive the original conveyance section 33.

Also, for copy 3, the document holder has sprocket 1 on foot 75.
22 Furthermore, the sprockets 124 are fixed and sunk into the M l 23 of the roller 44a, and the chain 125 is hung and driven.

Referring to FIG. 4, the guide lever of the document holder will be explained with reference to FIG. 4. There is a pulley 47 fixed to the +l+ 126 pressed against the conveyor belt 44.

In addition, a solenoid lever 128 is fixed to the shaft 46 with a key 127 to move the kite/toward 45, and a solenoid lever 128 is fixed to the shaft 46.
is coupled to the solenoid 129 by a pin 130. Activation of the solenoid 129 causes the solenoid lever 128 to move as shown.

The control circuit for performing these operations is shown below, but whether this circuit can be installed in the copying machine or hidden in the copy requesting device will be explained below. The case where a control circuit is included will be explained.

FIG. 7 is a block diagram of the control device. Same [4
In this case, the ROM is a read-only memory in which the sequence contents of the automatic document handling device are pre-ordered, and the contents can be read out each time the first address is set. It will be done. That is, the control contents (a
(including not only the operational output of the circuit but also the control contents of other circuits).

The RAM is a memory for reading and writing that stores the number of copies and temporary control during process control, and a memory that stores one set of binary codes. - A set of flops is formed into a plurality of sets, and an arbitrary set is selected by an address designation signal, and data is loaded into or read from a plurality of flip-flops among the sets. In addition, in FIG. 9B, the memory address is expressed, for example, in the form of rXO31J,
The last 1 digit number represents the column, and the 11th and 2 digit numbers represent the row.
J data is stored. 110-1, 110-2 and 110-3 are input/output devices that receive data such as whether or not there is a document in the input, data such as whether a copy has been made, or human input signals for feeding the document A. A signal for driving the clutch and solenoid is generated, and FIG. 1O shows a miniature diagram thereof, and FIG. l10-4
FIG. 3 is a diagram showing connections between and peripheral circuits. In the figure, signals SWI to SW5 are microswitches that are means for detecting whether or not there is a document in the document placement ins 4 to 8, and optical detection may be used. sw6.

SW7 is a detection-r stage, which is a microswitch that detects whether the document has arrived at a predetermined position.

SW9 is a switch for detecting whether the transport device ff\tCar u is set in the copying machine COP.

The LD has a detector that detects, for example, the amount of light of exposure (2) in order to count the number of copies. The IRP is a detector for detecting loading (11), and performs other processing by detecting a signal generated by a switch (not shown) provided in the copying machine COP.

DEI is a decoder that decodes the output of the manual output device ξI/C)-1 and activates the backup code shown in FIG. For example, in the case of loading bin 4, the pickup roller 10 operates. DE2 is a decoder that decodes the output of the input/output device l10-2, and the document receiver drives a kite that guides the documents to the bins 36 to 4o. Plunger solenoid +; 5L-1-3L-5
to drive. Solenoid 5L-1 operates guide 45. EL is a warning device, and LR is a solenoid that controls the connection between the conveyance device and the copying machine 91, and releases the lock when turned on, and locks it when turned off.

TMR is a timer with one input/output device; it is activated by a signal from I/O-3, and after a predetermined time, it transmits the signal to input/output device l10-.
Return to 3. cl-f and cl-b are clutches, 7I',
J in the f-document transport section 33! If Document transport control is performed.

In addition, the input/output device l10-3 sends a copy signal to the copying machine.
-I Send from □.

The details 1Δ of another input/output device 110-4 in FIG. 7 are shown in FIG. For example, 1] Lu pD757 manufactured by Mokutanki Co., Ltd. can be used. In the figure, ro) "IJ-1---"9 is the number key, CL is the clear key, OK is the number setting completion key, 1! 4 way key F'liJ buffer for controlling register,
It has a shift register for storing display data, a digit signal generator for displaying display data in time division, etc. The CPU includes the above-mentioned memory, one or more registers AC for address specification of input/output devices, and one or more registers A for PCl and other IPX notes tα.

B, C, D, Overflow Pit l-OV F, Frog C
Control unit CT with addition/subtraction η logic control for decoding and processing data manually input from the FT data signal line, and arithmetic circuit A
The LU and the arithmetic circuit ALU have the functions of data lO base correction, addition, grab and other OR. Note that the contents of register A can be rotated to the right (right shift I.) or to the left (left shift). The CPU has the above circuits, and is connected to the distribution section circuit through a plurality of lines. To summarize, CPU
First, specify the address of the ROM where the sequence was written to Progera J1, and send the data of the contents of the specified address to the DBI line.
is read into the CPU through
Sometimes it processes data within the CPU itself, sometimes it stores data in the CPU to a specified address in RAM, or it stores data at a specified address in RAM to C
It manually inputs data into the PU, sometimes outputs data in the CPU to the signal line DB3 of the output sections l10-1 to l10-4, or inputs the contents of the signal line DB31- of the input/output section into the CPU. Sequence control is performed by

The control procedure according to the present invention will be explained in detail below.

First, the timing for sequence program processing will be explained with reference to the clock time chart in Fig. The designation of each code is the address code 1" +:) The n-tree code from m is decoded by the address decoder, and one of the 2n trees is selected and output. The ROM and the address where the instruction in the ROM is stored are specified by the ROM & location designation register (pc).This register (PC) has the function of adding +1 by the control signal αl, and thereby Programmed instructions are output one after another.This register PC is inputted to the ROM by multiplexer A-C at a predetermined time.

The ROM outputs the instruction code on eight lines, but since the data coat bus j line DBI is a four-tree line, it is time-divided and output to the data coat bus l line twice.

The command code SW9 and SW6 is output in two batches of 4 lines each using the 2.3 clock signal α.

The contents are latched into registers C and D by opening and closing of SW7, and the contents are decoded by the instruction decoder to generate a control belief -α for processing according to the contents of this instruction. In short, as shown in FIG. In between, the content of the instruction written in +iit is executed.Then, the programmed instruction following the above address is executed again at the same interval of 111r.Therefore, one execution in the programmed sequence order(
It takes time equivalent to 10 clocks to execute step 1). A 2-word instruction requires 20 clocks.

Note that registers A and B are for calculation, and are respectively ACC, .
It is called Tm. Also, each switch SW is controlled by a control signal α.
OVF is a well-known circuit for detecting overflow a- of register ACC.

The control unit CT decodes registers C and D and registers Acc,
This is a circuit for calculating Tm and outputting (1) a control signal α.

The operation of the control device having the configuration as described in 1-1 below will be explained with reference to the above-mentioned configuration diagram and operation explanatory diagrams shown in FIGS. 14 to 28.

First, the instructions for each step shown in FIGS. 14 to 27 will be explained using the case of pcOM4 manufactured by II Honden% Co., Ltd.

1, 0100 XlX2X3X41 location designation order YIY
2Y3Y4 Z section Z2Z3Z4 Transfer X1-4 to AC3, Yl-4 to AC2, and Zl-4 to Act.

During program execution, a certain address in the ROM is specified by the PC, and at time T1, code 0100 is output to the data coat bus line, and at T2, it is latched into register 0 by opening/closing SW6.9. At the same <T2, decode this and recognize that it is an address specification command, and continue at the same <T2.
Xi~4 is output to the bus bar, T3, SW9,
It is latched into register PB3 by opening and closing of SWI5. Next, add 1 to PC and output the codes Yl~4 and Zl~4 of the address following the above in the ROM, which are then converted to AC2 and Ac1.
Therefore, the new address that you want to use in a later program is stored in FB. This execution timing is as shown in Fig. 10.
Y2Y3Y4 212223Z4 When the jump condition of X is met, the destination address Y1-4,
Transfer zi~4 to each AC2 and Act, and then transfer AC2 to PC
2. Transfer Act to I'CI and complete, but do not jump if not established.).

When Xi~4 is 0010, it is a jump instruction when overflow ovF is detected as 1, and when Xi~4 is 0100, it is a jump instruction when the overflow ovF is detected as 1.
c,) is 0, 1ooo is unconditional, 1010 is O
When VF is 01100, it is a jump instruction when the register (Ace) is not 0. First, at the time Tl+T2,
An address in the ROM is specified by the PC, and at time Tl, code 0101 is output as data code It)tlla4, and at T2, it is latched into register C by opening/closing SW6.9. At the same <T2, continuation <Xi~4 is outputted to the bus line, and at T3, it is latched into the register D at SW7.9 1'A. Now, assuming that Xi~4=010'O,
At T4, IIJI decodes the code 0101.0100 and recognizes 11, which is a jump instruction, and 1JI, which determines the contents of register Acc.Continue < At time T5 to TIO, first, the contents of register ACC are zero. If it is not zero, add +2 to the PC and exit the jump command. If it is zero, add 1 to the PC and continue the code I in the ROM.
-Yl~4, Z, 1~4 as SW9, SWIl,
By opening and closing SWI 3, the jump destination address appears on the PC, and in the next Tl-Tl0 cycle, the new jump destination address is specified in the ROM and the jump is completed.

3.0110 1000 Transfer command (1) This stores (hereinafter referred to as load) the data of location J set by AC in register Ace. At time Tl+T2, the address in the ROM is specified by the PC, and at time Tl, it is output to the 9 data coat bus, and at T2, it is latched into register C by opening and closing SW6.9. Same as T2 < 1000
is output to the 40 line, and is latched into the register D by opening/closing SW7.9 at T3. The code of register CD is decoded at T4, and at 1111 from T5 to TIO, the code of AC is output to the address code DJ line, and the key register of the RAM, output device, and key display input/output device specified by this address is output. Either of the contents is output to the data code I:r+ line and stored in the register Ace by opening and closing SW9 and SW2.

Since it functions in a similar manner, it will be briefly described below.

The codes for setting the necessary input/output device J and the memory itself in the following procedure in which control is performed by making full use of the command codes shown in Table 3 onwards are as follows.

X means that the code is not limited.

Table 4, 12th address code 1" in the lid line", is a line for selecting 4 or memory, etc., and each memory,
The input/output device has a circuit known per se for decoding it. The other eight lines are further lines for specifying sub-addresses of the memory, and each memory has a circuit known per se for decoding it. Since each output section in the input/output device corresponds to each digit of 4-bit data in this example, a special designation circuit is required.

To explain the document handling operation, when the power switch (not shown) is set to on, the 5ta shown in FIG.
Pl starts.

First, a flag register, a set number of copies register, a register for storing the number of copies, etc. in the memory RAM are set to predetermined values. For example, the memory RA shown in FIG.
Registers WR(0), WR(1), WR(4), W in M
Clear R(7). Furthermore, address rXO20J of RAM.

rXO21”, “XO22”, rXO2:J+, rXO
24J, WA (0), rXO40J, rXO41J
Clear. Here, to explain the address again, for example, to explain the address X 0.20, the first "02" indicates the I1 device in the row, and the lowest digit "0" indicates the column position.

If there are no documents in bins 74-8, "OF" is displayed on the indicators DP5-DPI to indicate that there are no documents in bins 4-8, as shown in FIG.
RAM17) rOF'0FOFO to XO30 to XO39
FOFJ data is sent to each cell.

The contents of the RAM are determined in step 1 as described above.

In the next 5teP2, control is performed to send the contents of X030-XO39(7) to the display devices DPI-DP5, the details of which are shown in FIG. First, data "9" for selecting the display device DPI-DP5 is stored in the register WR(3).

Such “9” is the segment type table No. 1 < device DPI ~
This is determined because DP5 has 10 display bodies.

In this case, the lower digits of the display DP5 are selected sequentially and the current DP is selected.
The lower digit of 5 is selected. Address information X039 of the register to be displayed next is stored in register AC, and further in register WA (3).

11) and register WA The address data of rXO39J in (3) is set in register AC, and the data of the set address is set in register Acc. Next, the data “X500” for selecting the input/output device l10-4
'' is set in register AC, and the contents of register Ace are sent to a display register (not shown) of input/output device l10-4. In this case, the content displayed on the input/output device l10-4 is the aforementioned "F". Next, the contents of the register WR(3) are subtracted in order to select the 11th and 2nd display on the display device DP5, and the data to be displayed in the RAM is sent to the input/output device l10-4 as described above. It will be done.

” When the series of steps like “1-r” are performed 10 times, the transfer of the display data to the input/output device l10-4 is completed, and the human output unit @l10-4 displays the data rOFOFOF.
OFOFJ is carried out.

Next, control in Step 3 is performed to check whether there are documents in the document placement bins 4 to 8.

The detection "single stage microswitch 5WI-3W5 provided in each of the document placement bins 4 to 8 described above is connected to the input/output device l10-1.
, l10-2 converts the signal indicating the presence or absence of a document into an electrical signal to input/output devices l10-2 11 to ■3 and l10.
-2, ■3, respectively, and input °°l"'(H
HighLevel)"l" (Low Level) and decide that the condition is that a manuscript is contained in the case of "1 page", and
102 (X'200)' lo-I3 and l10-1
(X'l OO) '(7)I 3(7)ToVLka''
Distinguishing which order is the order in which it becomes "1" or "1", the first input document a, "It", and the pin NO are stored at address x020. That is, input/output device l10-2
If work 2 is manually operated first, 2 will be placed at address x'020'.
Store. The document placement bin number inputted in No. 2 11 is stored at address X021. In this way, the document placement pen numbers are stored in the RAM from x020 to X024 according to the order in which copies should be made, and the copy order is
'The cassette number of the address is 1st, X021 is 2nd, X02
Do 2 in 3rd place, X023 in 4th place, and X024 in 5th place.

If the contents of X020-XO24 do not have originals, the value of O is stored.

As shown in FIG. 19, the register Acc
, clear WR(3), and first write “X2” to register AC.
00'' (this is the address data that selects the input/output device I/'O-2, and 02'O is actually set in the register AC), and the microswitch 5WI of the input/output device l10-2 is set. -3W4's on/off state fQj, ie, the data indicating the presence or absence of a document, is input into the register Ace.

Next, in order to see the contents of register Ace, overflop l.
-Shift 1 bit by turning counterclockwise to OV F. Then, it is determined whether the OVF is l or Q~. If the result of this determination is not "l", the microswitch SWl is informing that there is no original in the original placing bin 4.

If the remaining original is not in the original loading bin 4, the address of the input/output device 110-2 is stored in the register AC in order to detect the state of the micro switch SW2 of the original loading bin 5 in the next step 1'. I・Micro switch 5Wl-5W
“L” and “O” signals indicating the state of 4 are connected in parallel to the data/
It is set in the register Ace via the DB3. Next, the contents of register Ace are rotated twice, and the state of microswitch SW2 is set in the overflow bit OVF. If 5& is not inserted, it is "O", so the next microswitch SW3 is the same as above, and the bow 1st switch SW5 is connected to the input/output device l10-1, so the microswitch is When determining SW5, the address rXl, 00'' of the input/output device l10-1 is set in the register AC.

If the manuscript is not included as described above, proceed to the next 5 steps.
4 key manual control is performed. FIG. 21 shows the detailed control procedure.

In the figure, first, register WA (0
) is transferred to register WR(3) via register Acc.
sent to. Now WA (0) contains the data of rXO20J as explained in step 1, so register W
R(3) is set to "0" of rXO20J.

Next, rset ADDJ is performed as shown in FIG. First, RAM address data rXo''ocJ is set in register AC.

” The bipedal rXOocJ is the register WR(3) (7).

Next, r l + A c c J, that is, cash register 4 Ace
is set to 1.

Next, rAccΦA C+ A c' c J, that is, WR
The contents of (3) and the contents of Ace are compared and control is performed to store them in Ace, and it is determined whether the contents of register Acc are not O. Since rlJ is now present, the melon sets "2" in register A and cc instead of rlJ, and the same process as above is performed.The same process is repeated until register Ace is set to "5", and rAcc≠0. ” then S
et ADD, the address rXOO3J of the least significant digit of register WA (0) is stored in register AC, register Ace is set to "4", and registers Ace and W are stored.
The least significant digit of A, (0) is compared and the register Ac
It is determined whether e is "0". In this case, it is not "O", so the next step is WA (0) → AC, ACL → Acc, A
The contents of the least significant digit of register WA (0) are stored in register WR (3) by ce-+WR' (3). Next, it is determined whether the sheet number set flag is "1" or "0", and since it is not set in this case, the key manual control shown in FIG. 24 is entered.

First, register AC is the address r of human-powered device I 10-4.
Set X500J and input/output device l to register AcC.
Take in the signal from 10-4. -[-Input/output device l
For example, when 10-4 is a kPD757 manufactured by NEC Corporation, when such a device is selected, it first sends a 4-bit signal indicating whether a key is pressed, whether there is a key error, and which key power line. Sent. First, in order to determine whether a key is being pressed down, Ace is rotated counterclockwise and a signal indicating whether a key is being pressed is sent to the overflow bit OVF. Since the key is not being operated now, OVF≠1
It is. Then, the data "D" generated from the ROM is set in the register Ace.

The contents of register Acc are transferred to register WR(7). Therefore, the next T' Il "i," of the Key in Figure 21 is
The address rXOIC of register WR (7) is set to register AC, D obtained from ROM is set to register Acc, and the ALU compares (exclusive OR) the contents of register WR (7) with register Acc. is taken, “0” is set in register ACC, and 5tep4
Complete the KEY IN procedure.

Next, in step 5, the procedure for determining whether the setting of the number of copies of the original placed in the original placement input is completed is started.

That is, the address "rXO40" of RA, M, where the one copy number setting flag is stored in register AC, is set to address rXO40J, and the contents of address rXO40J are set to register Ace. Then, the contents of register Ace are rotated to the left (shifted left by 1 pixel), and the contents of overflow bit OVF are checked. It's rOJ now so 5te again
Returning to the display control of p2, steps 5teP2 to 5teP5 are repeated until the setting of the number of copies is completed.

B.

Assuming that five originals are placed on the original placing pin 7, microswitch SW4 is turned on, and the originals are placed in the original placing pin 7 at 5tep2.
The following is detected at 5teP3 in the repetition of ~5. As explained in step 3 above, the microswitch SWI is examined sequentially, and the microswitch S
When W4 is detected, rX2oOJ is set in register AC, and the states of microswitches SWI to SW4 are stored in register ACC. Next, micro switch SW4
Ace rotates to the right (1 bit shift to the right) to see the state of
Then, the state signal of the microswitch SW4 is set to the overflow pin l-OVF, and a determination is made. Now Opafro Hits 1 - OV F is rlJA” (7), 7F
response rXO36” is stored in register AC, and “X03
6'' address is transferred to register ACC. The contents of the register Acc are then sorted by rIl, and since it contains "0" as described above, the contents of address rXO37J are retrieved next, which is "F" as described above. "F"
The complement "0" of is stored in register Ace, and register A
It is determined whether the contents of cc are "rAcc≠0". Since it is "0" here as well, 4 is sent from the ROM to the register Acc and stored in the register WR (3) to control M e mo whose details are shown in FIG.

First, the pulse rXOQOJ of WR'(0) is stored in the register AC, and "0" is first transferred to the register Ace. Then, the exclusive OR of the contents of register WR (0) and Acc is taken by the ALU, and the result is stored in register Acc.
to go into.

Next, it is determined whether the contents of register Acc is “0”,
Since it is now “0”, register AC is at address rXO2
0J is written t0, and such address is further written in register W.
Transferred to A (3). Next, "4" stored in register WR (3) is stored in WA (3) <, WA
(3) → AC, WR (3) → Ace, Acc → AC is performed, the control of M e m o is finished, and then the copy of the original placed in the original placing ben 7 is copied first. In order to indicate that the address is rXO36J, the address rXO36J is stored in the register WA (3), and the SET control shown in FIG. 20 is entered.

First, the contents of register WR (0) are incremented by 1, and then (
7) WA(3)(') data rXO36J is register A
It is stored in C, and is stored in "1" of WR (0,) or address rXO36J. Also, at this time, “
F" is set. Therefore, "X030" ~ "Xo39"
” is [0FOFOFIFoF].

Next, if no key is operated, 5step 4, as described above.
When 5 is done and 5Lep2 is taken, the display DP
4rlFJ is displayed, and the other displays are displayed as "OF".

Hiba J - After the original enters the original placing pin 7 as described above, when the original ``No. 2 1'' is placed on pin 4 of the original holder, the microphone is Turning on the switch SWI is detected, and the M e shown in FIG.
Step 11 is performed in the same manner as described above up to the control of m o. however,
The data of rlJ, which informs the position of input 4, is stored in the register WR(3). When control of OMEMO is started, the contents of the register WR(0) are first checked.

Since the original is already placed on the original placing pin 7, the register WR (0) has its contents set to rlJ, so M
The judgment at the second port of the e m O control is yes, and the address "X021" is stored in register WA (3).
Register WR (3) (7) rlJ is written at address rXO21j. If nothing is done for a while after the second document is placed in the document placement bin 4, the document detection and key detection will be performed as described in step 11, and the single display control will be performed. is r2FO at address rXO30J ~ "X039"
Since the data of FOFI FOFJ is contained, the table DPI is displayed as "r2F", the display device DP4 is displayed as "rlF", and the others are displayed as "OF".

Next, when the numeric key is operated, St, ep4, EY
In accordance with the control of IN, data on the number of copies of the first set document 7 is stored as follows. Now assume that 23 copies are made for each original.

First, at 5tepl, register WA (0) is rXO2
Since 0J data is stored, WA(0)→AC,A
Data "4" is set in register Ace by C-+Acc.

Next, the Set ADD control is entered, and the address rXO3 where the data for setting the number of copies for document placement area 77 is entered.
7J enters register WA (1).

Next, it is determined whether the number of copies has been set, and if the number of copies has not been set, the KEY control shown in FIG. 24 is entered and the operation of the numerical key is determined. As mentioned above, at this time, the input/output device engineer/〇-4 first checks whether there is a 4-bit key (
1 hit].) Outputs whether there is a key error (1 bit) and the signal line (2 hits representing KRO-WR3), and judges whether 1 is set in the 41f constant bit or not. If it is not standing now, input/output device: l10-
4, the data "2" of the a value key is entered into the register Acc, WR (7).

Next, it is again determined which key has been operated, and if it is an a value key, it is determined whether the currently set number is 1 digit 11 by looking at the contents of register WR(1).

Next, data r2J of register WR (7) is stored in register Ac.
The data of rXO37J, which is taken into e and stored in register WA(1), is put into register AC, and
Store F2J at address 37. Next, write “F” at address X036.
” and note that the number has been placed once (t(E I), store “2” in register WR (1) to read
End control of IN. Since the settings have not been completed yet and the OK button has not been operated, we move on to display control again and this time select r2FOFOF.
The data of F20FJ is displayed on the indicators DPI to DP5.

Next, when the numeric key "3" was operated, the KEY control shown in Figure 20 was performed in the same way as described above, and a check was made to see if the a value key was pressed (2 + = n). After that, transfer the 21st smell II argument number or the contents "2" of register WR (1) to register Ace and perform right rotation (right shift) twice, that is, if it is a 1248 code, it will be "2".
is ro 010J, and as a result, the overflow bit OVF is set to "l", so the following control is performed.

First, the “2” card stored at address “X037”
O36J 4. : Transferred and “3” is transferred to address rXO37J.
” data is stored and “6” (
That is, 0110) is stored, and the KEYIN control is ended. With the current key human power, the display DPI-DP5 is
” “OF” “OF” “23” becomes “OF”.

Since the setting completion key has not been operated yet, proceed to 5 step 2.
, 3°4.5 is repeated.

Next, the sheet number data setting completion key described in ``-1'' is operated. The KEY control of the KEY IN control is performed as described above, and when it is determined in the KE and Y control that the completion key has been operated, "F" is set in the register Ace.
Roughly set in register WR (7). Complete r key O
To check the operation of K, 21 negative check is performed in the same way as with the numerical keys mentioned above, and if the completion key is OK, register WR (1
), and determines whether the G(lfi data is set to SeraI). If it is set, "7" is set in register WR (1), and then Setf shown in FIG. 25 is set.
WA (
"1" is stored in the digit bit of 0). Next, when the numeric key and complete r key are pressed, the contents of WA (0) will be ro 2
Since it is 1J, rXO40 is determined by that first digit "1".
Set rlJ to the next bit of the most significant hit at address J.

As described above, a flag is set at address rXO404,
5step5 control is performed. That is, the lowest-L hit at address rXO40J is input to the overflow bit OVF, and "0VFf-1" is determined by the control circuit CT.

Since it is now l, proceed to 5step 6. First, the register WA (4) in which count data of the number of copies is stored is cleared.

B Next is N of the document placement in address rXO20+.

The numbers 1 to 5 are given to the printer phones 4 to 8. Therefore, "4" is stored in WR(2). Next 5tep7
The control starts.

First, WR(2) ty) address "xOO8" is set in register AC, then "8" is set in register A'cc.
The data is transferred from the ROM, and ACC+WR(2)→Ace is performed. Next, input/output device l1O-1 (7) 7 trace “xloo” is set to register AC, and “12”, that is, “DJ” stored in register ACC is input/output device l
10-4, and rl is sent to terminals Q3 to Qo of l10-4.
loOJ appears and the top hitter No. 46 is Kate AG
I-AG5 is opened and rl OOj is applied to the ant gate input terminal by the decoder DEI, so clutch c9. Click on -4.

Then, one document is brought out from the document placement in 7.

Next, address rX so that the above original is sent to the copying machine.
300J is set in register AC, register Ace
2, set the clutch ci-f in the same way as in 10-1.
drive.

” - Clutch CA. -1 O N II! j period is set in advance by timer TMR, and it is turned off after sending out.
Next, the detection means SW6 detects whether the document has reached a predetermined position. Such detection means SW6 is 87 shown in FIG. During this control, the setting for the number of copies of the document placed in the document tray 4 is detected. For example, when a numeric key is operated to set the number of copies (9), the address rXO20J stored in the register WA (0), which stores the order in which originals were inserted into the original number M pin, is pressed.
KarrXO21J NirXO40J Changes depending on the address flag.

Next, when the KEY IN control is entered again, the setting for the number of originals in the original document placement area 7 is set to "2".
Similarly to the digits of (, +1. L, register WA(0)
Since the data stored in is rXO21J, rXO
Data ``9'' is entered at address ``31'' and data ``F'' is entered at address rXO32J. Furthermore, if the placement completion key is operated, the sheet a setting flag r040 of the RAM is set in the same manner as the above operation. + r041”. This time, copy number 11 is the second, so the weight bit of r4J at address ro 40J becomes rIJ.

If it is determined in step 5 that the document has arrived at the predetermined position on the document table after the key operation as described above, clutch cfL is activated.
-f is turned off, document movement is stopped, a copy start signal is output from the human output device e I/O-3, and the copying machine starts copying the document.

In the next step 5 step 9, the copying device is charged.

This light source detects the light from the light source of the copying machine during the exposure process and controls the number of copies by counting the number of blinks. Check the number of detection signals (Lamp Detect).

Also, as in 5tep8, while checking, the setting keys of other cassettes are manually operated and displayed. 1- When the light from the light source is detected, it means that one copy has been completed.

” The control of serial copy detection is performed by Il of input/output device I10-1.
This is done by looking at the signal from the detection stage LD that is manually input to the terminal of
When it is "1", it is assumed that one copy has been completed. The contents of the terminals I3 to 0 of the input/output device l10-1 mentioned above are sent to the register Acc, and the contents of the register ACC become 2.
When it is shifted to the right, the state of terminal 1 is set to OVF, and if the content is rOVF≠Hibari, then the document is newly inserted into the document holder.
Was any key operation performed and R, AM (7) rXO3?
The display control of the contents of addresses 0J to rXO39j is repeated as described above until "1" appears from the detection means LD. When rlJ appears at terminal 11 of l10-1, the contents of register Ace are rotated to the left (shifted once to the left) and transferred to terminal 0, to which the interrupt signal sent from the copying machine is applied.
The state of is determined. If it is rlJ, it means that there was an interrupt, and if you urgently want to copy one or more copies, press the copy button on the copying machine or press the interrupt request button to send the l10 from the copying machine.
-1 is input to the terminal IO. When this is detected, the control device 10 holds the current state as it is, waits for the interrupt signal to end, and enters 5tepH after the end.

If there is no interrupt signal, the 5tepH copy number counter I/operation is immediately compared with the set number of copies. C.N.T.
The 1-'F detail of is shown in Figure @27. To explain according to the same figure, register WA (4) is 5tep4
The register WA (4) is cleared in
The lowest digit “0” is set in register Ace and +l
is performed in ALU, the result is stored in Ace, and further ALU
The contents of Ace are corrected in decimal form, and the contents of Ace are sent to AC3 of register AC.

'It4 Nit -/< -7C1-Pi-OV F
It is determined whether rOVF≠l. Now rOVF≠l
'', the contents of register WR (2) are then extracted in order to retrieve the data at addresses rXO30J to rXO39, where the setting data for the number of copies is stored.
Check whether the content is from 1 to 5. Now "4"
data is in WR(2), so rXO37J
data enters WA (2), then enters register AC, and data "3" stored at address rXO37J
is derived to register Ace.

Next, the data of the least significant digit of register WA4 is derived and compared with the contents of register A c 'c.

Since ACC≠0 now, go to ■, clear Ace, further clear WR (3), and end the control of CNT.

Next, transfer the contents of register WR (3) to Ace and rA
Determine cc=OJ. In this case, yes, so +
The process returns to control of document detection, etc. in Steps 1 and 9. Copy Star now!・Since the button remains on, the copying machine continues copying the original placed on the document table, and the contents of the lowest digit of register WA (4) are r 3 J' f:
Nutney Toki, Control of CNT (7) rXO37”
When comparing the contents of the address and the contents of the lowest digit of WA4, it is no longer ``rA c c≠0'', so we do not go to
(2) rXO37J (7) Address data as “X0
36'' and the contents of address rXO36J and WA (2)
The contents of address rXo 12J are compared. As a result, Acc=1, the controller +++n of steps 9, 10' and 11 is executed again, and the contents of register WA(4) are incremented by 1 each time the control procedure described above is executed. When the copying machine COP, for example, a switch (not shown in the figure) is operated and an interrupt signal is generated while the fifth copy of the original 11 on the document placement pen 7 is being made, the Ste, P
Input/output device 9 ■ When data is taken in by 10-1, an interrupt signal is taken in from the terminal IQ along with the detection data of the copying of the 5th copy L1, and the register Acc is input twice to indicate that the 5th copy has been made. Confirm that it is placed in the overflow bit OVF by shifting, and then register Ac
By shifting the contents of e to the left by 1 and inputting the -III interrupt signal to the overflow bit OVF, the interrupt control shown in FIG. 26 is performed.

First, address data x300 is input to register AC in order to select input/output device l10-3. Next, output terminal 0
To select 2, data "4" is set in register Ace, and clutch 0 is connected from terminal 02 of input/output device l10-3.
A signal is output to drive statement-b, and the copy signal output from terminal OO is turned off.

When the clutch 0-b is driven, a drive means (not shown) reversely rotates the rollers 77 and 78 to finish the document on the document crow 35. ! It is conveyed to the bell I-1- on the ilJ board 80. Of course, at this time, the suction fan 81 is sucking the document onto the belt 79. Through the above-described operation, the document continues to move until it is detected by the detection-1 stage 92. When the detection means 92 detects the original, the switch SW7 is turned on.
The signal t) of rlJ is sent to the terminal IQ of the input/output device l10-3. This signal is taken into the register Acc, and it is shifted to the right once, and it is determined whether the overflow bit OVF becomes "L" or not. If it becomes "L", it is a turnout! l1
Address rX300J that selects 0-3 is register AC
, set oJ in register Acc, set the signal output from terminals oo to 0 of input/output device l10-3 to 6, and turn off clutch CJI-b, which controls the drive of conveyor belt 79. Then, the belt is stopped.The original is evacuated into the conveying device as described above.

Next, select the input/output device l10-4, send data "3" to indicate the evacuation completion to the operator using the warning device EL, and drive the solenoid LR to connect the copying machine Cop and the transport device Caru. Let it be canceled.

Next, the operator Nagisa lifts one end of the transport device Caru as shown in FIG. I put a manuscript that I need to make a copy of urgently on it, and make a copy! Operate the copy button provided on 7mC0P to make the desired copy.

- The power control circuit continues to detect the state of the input/output device l10-1 (-10) during the operation of the above-mentioned interrupt copy.

” - The urgent copying work mentioned above! :(1,, When the operation name returns the transport device caru to its original state 1. When the IJ switch is operated f'1 to turn off again, the end f'Io of the input/output device l10-1 becomes " o” is applied, so
The overflow LOVF becomes 0, confirming that the interrupt has ended.

Next, when the transport device Caru is placed in its original state,
A signal is sent to the switch SW8 or the terminal IO of the input/output devices I10-4, and when this belief is confirmed by the overflow bit OVF, the next control is performed.

Next, in order to resume copying the original that was being performed before interrupt control, address
300 is added to register AC, and register AC
c is set to "2", the clutch 0-f is driven, and the evacuated original is moved to the IIf original crow 35-1- by the conveyor belt 79. When the original sent onto the original glass 35 is detected again by the switch SW6, the clutch 0-f is turned off, a copy signal is sent to the copying machine COP again, the copying of the original that was interrupted is resumed, control. First, the contents of the register WA (4) are set to 5 as the copying of the 5th sheet is completed, and then it is compared to see if it is the same as the set number of sheets "23". Since they are not the same, the ORG is performed again in Step 9.

When "23" is stored in register WA (2) that repeats control starting from KEY IN and DPY, rXo 3
6J rXo Since it matches "23" stored in 37J, set Ace to 1 by control after branching of CNT, set this content to WR (3), and 5tepH+7) Determine if the last Acc=O The result is No, and the control of 5tep12 is performed. That is, the original is sent to the end of the input/output device 110-3 with the copy signal turned off at rOJ and begins to move. Next, in order to put the copied original into the original document tray 736-40, the guide lever 36 is actuated, and the document tray 5L-2 acts on the pin pin 37. Now, the tray is stored in the input 39 of the document placement pin 7 mentioned above.

'', when the above-mentioned operation is completed, the control goes to 5tep13, and first, it is determined whether there is a document on the currently active document placement pin 7 through input device l10-1's 10°11, I2. , I
3 and 13 of the input device l10-2. Since the current document is in the document placement pin 7, go to step 5, return to step 7, and the operation of the document drive starts as described above. When the copying of the five originals in the document placement pin 7 is completed, the process goes to 5tep 14. , First, register WR (0) stores the number of M manuscripts aR that currently contains manuscripts.
-e the contents of. Now it's ``2'', so it becomes rlJ. Next, since there was no more original in the original tray 7, the ``2'' displayed on the display DP4.
3" to rOFJ, from register WR (2) to "
Take out 4 pieces and remove resin) pWA (1) +: IT
XO37J Noah F'+z is executed under the control of ADD, and rFJ is performed based on the address of rXo 37J mentioned above.
and change rXO37J to rXO36J, rXO3
Control is performed to insert "O" into address 6J.

Control is performed to shift the contents of rXo 20J to rXo 25J to the left, and finally, ``0'' is placed at address ``rXO24''.
” is set to end step 14.

In the next 5 step 15, rXO40, +rXO4
Control to shift the contents of address 1J to the left by l hits and reset the register WA4 that counts the number of copies, and if register WR (0) is [0], return to 5 tepl, and if the contents of WR (2) is not O. For example, the document is controlled by the document placement pin. At step 14 described above, the address rXO20J contains the data rlJ meaning b:I document placement pin 9, so the document placement pin 4 is controlled as described above. ” In the double example, we showed an example of the number of copies as a condition for copying,
Similarly, conditions such as copy density can also be set.

As described above, since the present invention is provided with means for changing the order of image formation, the degree of freedom of the image processing bag δ can be increased.

[Brief explanation of drawings]

Fig. 1 is an external view of the image processing bag according to the present invention;
3 is a sectional view of the image processing apparatus of the present invention, FIG. 3 is a sectional view showing its driving section, FIG. 4 is an enlarged sectional view of the document holder, FIG. 5 is a perspective view of the conveying device, and FIG. 6 is an external view of the transport device,
Figure 7 is a block diagram of the control device, Figure 8 is the RO
FIG. 11 is a block diagram of the equipment 7i 1/0 1,-I/O-3 of M. ~l10-
3, FIG. 12 is an external connection diagram of input/output device l10-4, FIG. 13 is a basic timing diagram, FIGS. 14 to 27 are control diagrams, and FIG. 28 is an external timing diagram. It is. 1 is the copy requesting device, 2 is the manuscript placement unit, 33 is the applicant Canon Co., Ltd. November 211'' 1. Indication of the case 1982 Patent layer No. 129664 2. Name of the invention Image processing device 3. Person making the amendment + Relationship with 11 cases Patent applicant (11su) Tokyo person 1. 11 Ward F Circle 1'-3-30-
2nd 1st name (+00) Representative of Canon Co., Ltd. Ryu Kogara 3rd Department 4 Agent 1, +,' +ili ITl 146 Tokyoite Il1
Ward Domaru 1' 3-:30-25, Date of the amendment order: October 60, 1980 (shipment date) 6. Specifications to be amended 7. Print out the details of the amendment as shown in the attached sheet. (Contents unchanged)

Claims (1)

[Scope of Claims] Storage means capable of recording different output conditions for each of the plurality of image information,
an image output means for outputting one piece of the image information; means for interrupting the image output of the image information by the image output means; and the image information among the plurality of image information. an image processing device Z1゜ having means for interrupting the image output of the image information and then listening to the image output of the interrupted image information 11 times.