JPS6083960A - Image processing device - Google Patents

Abstract

PURPOSE:To increase the number of degrees of freedom in image formation by performing image formation under different conditions for plural originals and providing a control means which changes the precedence of image formation. CONSTITUTION:An original placing part 2 is provided with plural original placing bins 4-8 where originals can be placed. When an original 9 is placed in the original bin 4, an original detecting microswitch SW1 is operated to indicate the copy number to a copy counter, and the original 9 is carried in the direction of an arrow A and is sent to an original carrying device 33. The original 9 is placed on an original glass 35 of a copying machine 34 and is subjected to optical scanning. Next, the original is sent to an original receiving part 3. The original receiving part 3 is provided with original receiving bins 36-40 in accordance with original placing bins 4-8, and the original 9 is returned to the original receiving bin 40. If there is an original to which priority is given, a belt 79 is driven reverse to evacuate temporarily the original on the glass 35. By this constitution, the number of degrees of freedom in image formation is increased.

Description

DETAILED DESCRIPTION OF THE INVENTION The present invention relates to image processing, and is capable of storing a different image output means 1 for each of a plurality of images, and furthermore, after interrupting the image output of image information by the image output means, an appropriate νJ
The present invention relates to an image processing device capable of outputting an image from image information.

Conventionally, a plurality of images have been obtained by performing processing such as copying an image of a document.

By improving such a device, we provide an image processing device that can easily process all images even if there are multiple images to be processed.

The present invention provides a storage system capable of storing different output conditions for each of a plurality of image information, and a register t0 for storing different output conditions for each of the plurality of image information. an image output means for outputting; a means for interrupting image output of the image information by the image output means; and an image output of the image information that has been interrupted after the image output of the image information among the plurality of image information has been interrupted. The object of the present invention is to provide a non-image JA device having means for opening +If.

Other objects of the present invention will become clear from the description of the embodiments given below in conjunction with the drawings.

FIG. 1 is an external view of an image processing apparatus according to the present invention.

In the figure, the CDU is a copy request bag y1, on which an original to be copied is placed. COP is a copying machine, and copy request device C
The original placed on the DU is fed to the original table of the copying machine COP via the transport device Caru. The C sentence U is a copy paper sorting device, which sorts and places the copies of manuscripts placed on the copy request device CDU.

11 of the above-mentioned copy requesting device CDU and conveying device Caru.
A first view is shown in FIG.

In the same figure, 1 is the copy requesting device shown in FIG.
The document placement section 2 and the document receiver are composed of a section 3.

To explain about the number of original stripes
．． is installed.

If the original 9 is not placed on the original loading platform 4, the original detection microswitch SW1, which detects the absence of the original, will be activated.
The detection lamp (not shown) is hot.

This can be done by instructing the number of copies of the original 9 placed on the original document tray 4 to a copy counter (described later) using a copy selector of a copying machine or the like. This electrical sequence control will be described later.

When the document detection microswitch SW is activated, the document 91 is lowered to the highest document 91- using the pickup rollers 10 or rotating shaft 11 on the three sides as fulcrums, and transport of the document j;j becomes possible. 1ijJ rotary shaft 11 and pick-up roller 10 are connected by a bell I-6° (not shown), and rotate 4ib 11 or 4. 'r'A: By rotating No. 4i, the originals 9 on the original placing ben 4 are sent out one by one from three sides. Kite board 12, . 13, a drive roller 14, and a roller 15, the document 9 is conveyed in the direction of arrow A.

That is, the kite boards 12, 13, the drive roller 14, the roller 15. Kite boards 16, 17, drive roller 18, roller 19, kite boards 20, 21, drive roller 22, roller 2
3. Kite board 24a.

24b, drive roller 25, roller 26, guide plate 27,
28, drive roller 29, roller 30, out 1'' guide plate 3
1.32, and exits the document placement section 2.

Note that the same applies to the document placement pins 5, 6, 7, and 8.

]--The original that has left the original document storage section 2 as described above is sent to the original transport device 33 (original transport device Car shown in FIG. 1). The document conveyance device 33 places the document on a copying machine or the like 34 and performs optical scanning.
It is configured to sit on top.

The original placed on the original crow 35 is then duplicated J'
The document receiver of the requesting device 1 is sent to the section 3.

So again. The document receiver is set at an angle of 36, 37, 38, 39, 40 pins corresponding to the document trays 4.5.6.7.8. In other words, the original & place in 4.
The original 9 that has been subjected to i+R is
``When the desired goal 1.1 is achieved, the original is returned to the receiving area 40.

That is, the document 9 that has passed between the guide plate 41, the rollers 42, the guides 43, and the conveyance heald 44 is rotated as shown in the figure by the action of the planer lever 45 with the lever shaft 46 as the fulcrum, and the document holder is rotated as shown in the figure. 40.

A belt 49 hooked on pulleys 47 and 48 is used to smoothly feed the document 9, especially the rear end of the document, to the document receiving pin 40. Such a heddle is provided at each document receiving hinge. There is.

The pulley 47 is pushed against the conveyor belt 44 and rotates.

By placing a belt presser plate 50 on the back side of the conveyor belt 44, it is possible to
can be pressed.

Next, the drive system of this device will be explained with reference to FIG.
be fixed. The chain 54 hung on this is connected to the drive roller 2.
9 (Fig. 2), sprocket 55, fljl+
Tin rocket 57 immersed in 56, drive roller 25
sprocket 58.41+ fixed to the sprocket 60 fixed to the drive roller 22, sprocket 61 fixed to the drive roller 22, sprocket 63 fixed to the shaft 62, subrocket I fixed to the drive roller 18, 64.41+6
A sprocket 66 fixed to the drive roller 14, a sprocket 67 fixed to the drive roller 14, and a rotatable eye via a sprocket 69 fixed to the shaft 68]・Wrath brocket 7
Rotated through 0.71. In this manner, the document placement section is driven.

Also, the document feeder 33 is the motor of the drive motor 51)
A sprocket is fixed to 11+52, a sprocket 72 is fixed to the shaft rotating 1-1, and a chain 73 is hung thereon. A gear 74 is fixedly mounted on the shaft, and several gears 76 are installed on the support 75 to mesh with the gear 74. A rubber conveyor heald 79 is hung from the shaft 78 of the pulley 77 to the roller 77.7B so as to mesh with the gear 76. A distribution plate 80 is attached to the inside of the conveyor bell I.79, and is moved by the action of a suction fan 81. , 'The inside of the J board is a suction box.

Also, that part is treated in the same way! A 1iIJ board 82 was previously installed, and the interior of the partition board became a suction box due to the action of a suction fan 81.

Original Jl:ii The original that left the loading section 2 is placed on the guide plate 83°84
Then, it passes between the suppression rollers 85 pressed by the conveyor belt 79, becomes the conveyor belt 79, and is conveyed in the direction of arrow 141JB. The document passes between the conveyance heald 79 and the kite belt 86 and reaches the document glass 35, and the paper leading edge detection device 87 stops the movement of the conveyance heel 79 by releasing an electromagnetic clutch (not shown). shi, compound “j’ 4
Scanning completion detection device 88 in the optical scanning and image creation process of step 1
To obtain a desired copy by detecting the image f1. When the image f1 formation step is completed, the document exits from the document conveying device 33 via exit guides 89 and 90 so as to be replaced with the next document.

The roller 91 located at 1Xh of the conveyor belt 79 is
This is provided so that 11+i of I output can be carried out smoothly.

Reference numeral 92 is equipped with a paper edge detection device, and when there is a copy of a document to be prioritized, the document placed on the document crow 35-1- is
This is a means for detecting the retracted position of the original Il island when the heald 79 is driven in reverse to retract it. FIG. 5 is a perspective view of the conveyance device. To explain the conveyance device further, there are two conveyance device side plates 92 on the outside to support the device δ. Inside it is a roller 93,
There is also a roller side plate 92a that mainly supports the roller 94. Conveyor bell for rollers 93 and 94)・95 or 5 For IN, 5
A book hanger is installed. The transport heald 95 is provided with small holes at appropriate intervals of 11. This means that the document cut out on the conveyor belt 95 is conveyed by the movement of the conveyor belt 95, but when the conveyor heald 95 reaches the lower part, it is sucked through the small hole in the conveyor belt 95 by the action of the suction fan 96. to prevent the original from falling.

A suction fan is provided in the center, and it is possible to transport the items using its suction power.

The roller 93 is driven by a drive source (not shown). mouth"
A roller pulley 98 is fixed to the roller shaft 97 of the roller 93. Further, a pulley 100 is fixed to the shaft 99. Rotation is transmitted by hanging Pel+-iot on roller pulley 98 and pulley 1.00.

The wire pulley 103 rotates under the action of the electromagnetic clutch 102. A wire 104 is wound around the wire pulley 103, and the movement of the wire 104 converts it into linear pressure motion.

Furthermore, one force of the wire 104 is hung on a pulley 106 that can be rotated by the car 105, and the other side of the wire 104 is connected to the shaft 1.
They are hung on boom reel 108 which can be rotated at 07, and are fixedly attached to slide number 109, respectively. The slide base 109 has a slide bearing on which the slide I/car 110 slides. The slide shaft 110 is
The roller side plate 124', which is not small in the figure, is provided with the slide F' 411110, which is fixed to the roller side plate 92a. The slide stand 111 has a slide bearing that allows the slide 4jhl12 to move.

A movable plate 113 is fixed to the slide bases 109 and 111. This movable plate presses the document against the stop roller 114.

1. 1.1. The plate 115 and the do plate 116 are the roller side plates 92
1-.1 is set in a.

On the transport heald 95, a stop roller 1]4 is rotatably attached to the roller side plate near the end f41j, and when the transport heald 95 rotates, the stop roller 1.14 rotates.
When the transport bell i.95 is stopped, the stop roller 114 also does not rotate.

There is a unit inside the roller side plate 92a to ensure the change in the direction of the document. That is, the direction changing side plate 1
16 or ++l? Rollers 117, 118, 11 on the side
9 is rotatably attached. Moreover, the end of the roller is also rotatably attached to the side plate 123 of the conveying device 4.

A heald 120 corresponding to the conveyor belt is hung over the rollers 117, 118, 119.

As shown in FIG. 6, the conveying device as described above is fixed at one end to the copying machine COP with a hinge TB. As shown in FIG. ” - You can place a manuscript that you want to make a copy of immediately.

Note that providing a large number of suction holes in the conveyance heald 79 in the document conveyance section 33 provides an extremely good conveyance force when the document reaches the lower blade, that is, the document crow 35. If the original is small, the shape of the hole may cause a defect in being easily copied. Considering this point, it is necessary to aim for effective conveyance with the minimum number of holes.

The document receiving unit 3 has rollers 4Ja and 4.4b on the conveyor heald 4.
4 is hung.

A gear 121 is fixedly provided to drive the original conveyance section 33.

Also, for copy 3, the document receiver has a sprocket l-
122 and roller 44. Sprockets +-124 are fixed and sunk into the shaft 123 of a, respectively, and a chain 125 is hung to drive it.

Referring to FIG. 4, the original document receiver will be explained with reference to FIG.

In addition, a solenoid lever 1 is fixed to the shaft 46 with a key 127 and a solenoid lever 1.
28 is connected to a solenoid; 129 by a pin 130. Activation of solenoid 129 causes the solenoid to move as shown in the figure.

A control circuit for performing these operations is shown below, but whether this circuit may be provided in the copying machine or in the copy requesting device 41 is not explained hereafter. A case will be explained in which the f-billing device l has a control I/roll circuit.

FIG. 7 is a block diagram of the control device. In the same figure, the ROM is a read-only memory in which the sequence contents of the automatic document handling device are arranged in advance and stored in each address, and the contents can be retrieved each time an address is set. +'Fly shown. In other words, the control contents (including not only the operating output of the device but also the control contents of other circuits) are stored in an 8-bit binary code in order from address 0 to the required final address, which is set in advance as a code in a known matrix circuit. do.

RAM is used for controlling the number of copies and processes - last control 1. A memory for reading and writing that stores bows, and a memory that stores one set of binary codes. ', and any M
1 is selected, and data is loaded into or read out from a plurality of flip-flops 11 therein. In addition, Figure 9B
For example, the memory address is expressed in the form rXO31J, which represents the last digit or string, l: 6i 2
The digit number represents the line, and rXO31J can store data for 4 hits.
data is stored. 110-1, 110-2 and 110-3 are input/output devices, and data such as whether there is a manuscript in &: or whether a copy has been taken, etc. It generates a signal to drive the clutch and solenoid I for feeding the
Input/output device l10-1゜l10-2, I/C13 in the figure
, l10-4. ! : A diagram showing connections with peripheral circuits.

In the same figure), switches SW1 to SW5 are one-stage microswitches for detecting whether or not a document J is placed in the document placement ins 4 to 8, and optical detection may also be used. SW6 and SW7 are detection means, which are microswitches that detect whether the document has arrived at a predetermined position.

SW8 indicates that the transport device Caru carries out the copy M1. Sera I in coP
・This is a switch that detects whether the L.D.
The detector is used to detect, for example, light from the exposure process in order to count the number of copies. The IRP is a detector that detects an interrupt, and performs other processing based on the detection of an error generated by a switch (not shown) provided in the copying machine COP.

The DEI is a decoder that deciphers the output of the input/output device l10-t and operates the big up flow shown in Fig. 1 that sends out the originals placed on the placement pins 4 to 8. For example, in the case of the loading pin 4, the pickup roller 10 also operates.DE2 is a decoder that decodes the output of the input/output device l10-2, and the document receiver drives a kite that guides the document to the inputs 36 to 40. Plunger solenoid +: S L-1-3L
-5 is driven. Solenoid 5L-1 operates guide 45. EL is a warning device LR is a solenoid that controls the connection between the conveying device and the copying machine, and releases the lock when turned on and locks when turned off.

TMR is a timer that is activated by a signal from the input/output device 110-3, and returns a signal to the input/output device 110-3 after a predetermined time. Controls document transport.

The input/output device l10-3 also sends a copy signal to the copying machine from the terminal IQ.

A detailed diagram of another input/output device l10-4 in FIG. 7 is shown in FIG. 12, and the input/output device has a ghost key for setting the number of copies and a display to display the set number of copies. For example, pD757 from Ippon Denki Co., Ltd. can be used. In the figure, ``ro'', ``rl'', and ``r9'' are numerical keys.

CL indicates the clear key, and OK indicates the number of sheets setting completion key. This device is a buffer register for the circuit key control for the key Ak Soni Todoro 4, a shift register for storing data, and a display data for 111 I'r'ill.
It has a digit signal '-'F generator etc. for displaying the data. CP'
U represents the memory, one or more registers AC for redundant addresses of the input/output device, PCl, and one or more registers A for primary storage.

B, C, D, O/< 7 o Hila l-OV F, deciphering the data input from the flock CFT data transmission line,
Control s++ C with addition/subtraction η logic control to process data
'T, arithmetic circuit ALU, This arithmetic circuit ALU performs the functions of data decimal correction, addition, and exclusive OR.

The contents of register A are for right rotation (right shift) and left rotation (
(left shift). The CPU has the above circuit and is connected to the single distribution F45 circuit through a plurality of lines. Briefly, the CPU specifies the address of the ROM where the sequence is programmed, the contents of the specified address are read into the CPU through the data signal line DBI, and the C
The PU decodes this and, according to the decoded content, processes the data in the 11 "primary time series" from the input of the electric wire, sometimes processing the data within the C'PU itself, and sometimes processing the data in the CPU to the RAM. Storing data at a specified address = inputting data at a specified address in RAM into the CPU, or sometimes outputting data from the CPU to the output section I/C)-1-Ilo
Sequence control is performed by outputting the -4 signal to the mmDB3 and inputting the contents of the input/output section's Shinsou line D113-I': into the CPU.

Hereinafter, the control-r-11ff+ according to the present invention will be described as 1. cExplain in detail.

(This timing will be explained with reference to clock timing chart 1 in Figure 13.) The individual instructions of the program program are coded into 8 main lines in the ROM. is stored and remembered;
Individual codes can be specified using the address code 1' j from the JJ line.
The book's code is decoded by an address decoder, and one of the 21 trees is selected and output. This R,O
The address where the instruction is stored in M and the ROM is designated by a ROM address designation register (PC). This register (PC) has a function of incrementing it by one using a control signal α1, and thereby programmed instructions are outputted one after another. This register PC is input to the ROM by multiplexer A-C at a predetermined time.

The ROM outputs the instruction code to the 8-tree line, but since the data code Iff line DBI has 4 lines, it is time-divided and output to the data code 1'' Gi line twice.

The instruction code outputted twice for each 4th tree is SW9 and SW6 based on α that receives 2.3 clocks.

The contents are latched into registers C and D by opening and closing of SW7, and the contents are decoded by an instruction decoder to generate a control value -).alpha. for processing according to the contents of this instruction. In short, as shown in FIG. 1O, the designation of the address where the program is stored and the decoding of the instruction code stored at that address are completed in four basic clock cycles, and during the following six clock cycles, Execute the contents of the above instruction. Then, the programmed instructions following the address +1 and 1111 are executed at similar intervals of 11j. Therefore, to execute one execution instruction (l step) in a programmed sequence, it takes 1
This will result in a loss of 111 years. A 2-word instruction requires 20 clocks.

In addition, registers A and B are NIW rivers and are respectively ACC and
It is called Tm. Each switch SW is a gate circuit controlled by a control signal α, and OV and F are registers A'c
This is a circuit known per se for detecting an overflow of c.

The control unit CT decodes registers C and D and registers Acc,
This is a circuit for calculating Tm and outputting a control signal α.

The operation of the control device having the above-described configuration will be explained with reference to the above-mentioned configuration diagram and operation explanatory diagrams shown in FIGS. 14 to 28.

First, in FIGS. 14 to 27, the instructions for each step to be executed will be explained using the case of the C0M4 manufactured by Kokudenki Co., Ltd.

X1~4 to A□C3, Yl~4 to AC2, Zl~4
Transfer to Act.

While the program is being executed, a certain address in the ROM is specified by the PC, and at time T1, code 0100 is output to the data code ffJ line, and at T2, it is latched into register C by opening/closing SW6.9. At the same <T2, this is decoded and recognized as an address designation command, and at the same T2, the continuation <xi~4 is output to the H1 line, and T3, SW
9, it is latched into register PB3 by opening and closing of SWI 5. Next, add 1 to the PC and output the codes Yl~4 and Z1~4 of the following addresses in the ROM, which are then sent to AC2,
New atl that you want to store in ACI and thus use in later programs! +IFtPH. This execution timing is slightly different from that in FIG.

2, 0101 XlX2. X3X4 Jeep instruction YIY2Y3Y4 Z12223Z4 Address Yl to jump to when X jump condition is met ~4
．． Transfer Zl ~4 to 8AC2, Acl and continue 4. : A
Transfers C2 to PC2 and ACI to Pcl and completes, but does not jump if not established.

When Xi~4 is ooio, it is a jump instruction when overflow ovF is detected as 1, and when 0100 is a register (A
c c) is O(7)Il,'? , 1000 Te is unconditional, 1010 Teha 0VF-h<Ol l OO-t' is a jump instruction when the register (Ace) is not 0. First, between IIv of T 1 + T 2, RO on PC
An address in M is designated, and code 0101 is output to the data code 1;1 line at time Tl, and is latched into register C by opening and closing of SW6.9 at T2. At the same <T2,
<Xl-4 is output to the bus bar and latched into register D by opening/closing SW7.9 at T3. Now, X1~4=01
00, at time T4.

Decode the code of 0101.0100 and determine the contents of 1v and register Acc, which is a jump instruction. ・Recognize 11, and at the time from T5 to TIO, first register Acc.
Determine whether the content of e is zero and if it is not zero, increase the PC by +2
Then, delete the jump command. If it is zero, add +1 to the PC and continue the code in the ROM; yt ~ 4. Zl～
By opening and closing SW9, SWI l, and SWI 3, the jump destination address appears on the PC, and in the next 1' 1-TIO cycle, the new jump destination address is specified in the ROM and the jump is completed. do.

3.0110 1000 Transfer command (1) This stores (hereinafter referred to as load) the data at the address set by AC in register Acc. ROM on PC between 11ν of TI+T2
The address within is specified, and at the time of TI, the code OL l O performance data code 1
・It is output to line 11, and by opening and closing SW6.9 at T2,
Latched into register C. Continue with T2 <1000
is output to the bus bar, and is latched into register D by opening and closing SW7.9 at T3. At T4, the code of the register CD is decoded, and at the time from T5 to TlO, the code of AC is output to the address code I'J line, and the RAM and output device specified by this address are output.

The contents of any of the key registers of the key display input/output device are output to data code C71Q, and SW9,
By closing 1311 of SW2, it is stored in the register Acc.

Since it functions in a similar manner, it will be briefly described below.

The following code is used to set the necessary turnout arrangement and the memory itself in order to perform control by making full use of the instruction codes in Table 3 and above.

X means that the code is not limited.

Table 4: Address number 1 (1'7) of the 12th line
: There are four lines for selecting memories, etc., and each memory and input/output device has a circuit known in itself for decoding these lines. The other 8-tree lines are also lines for specifying sub-addresses of the memory, each memory having a circuit known per se for decoding them. Since each input/output unit in the input/output device corresponds to each digit of 4-bit data in this example, a special designation circuit is required.

To explain the document handling operation, when the power switch (not shown) is set to on, the 5ta shown in FIG.
Pl starts.

First, a flag register, a set number of copies register, a register for storing the number of copies, etc. in the memory RAM are set to predetermined values. For example, registers WR(0), WR(1), WR(4) in the memory RAM shown in FIG.
, clear WR(7). Furthermore, rX of RAM, 020
Address J.

rXQ21J, rx022J, rXO23J, rXo2
4'', WA (0), rXO40J, rXO41J are cleared. Here, to explain the 11f address, for example, to explain the XO20 address, the first "
02" indicates the row position, and the lowest digit "0" indicates the column 41.
“11ν1 is shown.

If there are no originals in pins 4 to 8, apply force to each pin 4 to 8 as shown in Figure 12 B'; (“OF” will be displayed on the indicators DP5 to DPI that indicate the bars that do not contain originals). For cell, RAM+7) rOFOFOF to XO30-XO39
OFO and FJ data are each set.

” as in the double series <l (the content of AM is determined in step l.

In the next 5tep2, control is performed to send the contents of X030-XO39+7) to the displays DPI-DP5, the details of which are shown in FIG. First, data "9" for selecting the display device DPI-DP5 is placed in the register WR(3). Such r9J is a table of segment types, 1< device DPI
~DP5 is determined from the display of 10491. In this case, the toy ☆ digits of the display DP5 are sequentially selected, and the lower digits of the current DP5 are selected. Address information X039 of the register to be displayed next is set in register AC and further in register WA (3).

The 7-trace data of rXO39J in (1) and register WA (3) are set in register AC, and the data at the addressed address is set in register Acc. Next, the data “x50” for selecting the input/output device l10-4
0j is set in register AC, and the contents of register Acc are sent to a display register (not shown) of input/output device l10-4. In this case, the content displayed on the input/output device l10-4 is the aforementioned "F". Next, the contents of the register WR(3) are subtracted in order to select the display unit in the tenth place of the table/j< device DP5, and the data to be displayed in the RAM is transferred to the input/output device l10-4 as described above. Sent.

When the above-mentioned operations are carried out 10 times, the transfer of the display data to the input/output device l10-4 is completed, and the input/output device l10-4 displays the data in -1- rOFOFOF.
"OFOF" is 91.

Next, control in step 3 is performed to check whether the original is placed in the original placing pins 4 to 8.

The above-mentioned original 11!1 is installed extensively on pins 4 to 8 (also detection 1
Stage microswitch 5WI-3W5 or input/output device l1
0-1, l10-2 converts the 41-no signal of the original into an electrical signal to If-+3 of input/output device l10-2.
and 13 of l10-2 respectively, and input “°1
’” (High Level) “l” (Low
Check the level) and decide that the condition is that there is a manuscript if it is °°1°゛, and set the lo- of l102 (X200)
+3 and l10-1 (X'100)'(7)+3(7)
The number of the original stripe number 71 pin input first is stored in the XO20 address, depending on which one is °゛l°' or which 111rl order is the one that becomes "1". In other words, if I2 of input/output device l10-2 is manually operated first, then
Store 2 at address 020'. Manuscript 4 & Placement No., which was manually loaded at No. 2 11, is stored at address XO 21.

In this way, the document placement number is stored in the RAM from XO20 to X024 according to the child order of copying, and the order of copying is X'02.
Set the cassette number at address 0' to number 1 and set X021 to number 2.
22 to 3rd X023 to 4th X O24wo5 & l
:l Do 2. If there is no original content in X020-XO24, store O's count.

FIG. 19 shows the above control procedure (register Ace
, clear WR(3) and first write rX2 to register AC.
00J (this is the address data that selects the input/output device 110-2, and 020 is actually set in the register AC) is set to 7 I, and the microswitches SWI to SW4 of the input/output mounting 5ff I10-2 are turned on and off. The state, that is, the data of the document's A1 and NON state is entered into the register Acc.

Next, in order to view the contents of the register Acc, the overflow hit OVF is shifted one hit by rotating to the left. Then, it is determined whether the overflow hit OVF is not 1 or not. If it is not rlJ in this determination, the microswitch SWI notifies that there is no document on the document placement pin 4.

If the original document is not placed in the document tray 4, the address of the input/output device 110-2 is stored in the register AC in order to detect the state of the micro switch SW2 of the document tray 5.・Micro switch 5Wl-8W
4, a signal of "0" is set in the register Ace via the data bus DB3 in parallel. Next, the contents of register Acc are rotated twice to set the state of microswitch SW2 to overflow OVF. If not, it is "0", so the next microswitch SW3 is checked, followed by the microswitch SW4, in the same way as described in iii+.

In this example, the microswitch SW5 installed in the document placement in 8 is installed in the input/output device l10-1, so when changing the microswitch SW5 to N, register A
The address rXloOJ of the input/output device l10-1 is set in C.

If the manuscript is not included as described above, proceed to the next 5 steps.
4 key manual control is performed. FIG. 21 shows the detailed control procedure.

In the same IN, first register WA (
The contents of 0) are transferred to register WR (3) via register Ace.
) will be sent to. Now, WA (0) contains data of <rXO20J as explained in step 1, so rQJ of rXO20J is set in register WR (3).

Next, rset ADDJ is performed as shown in FIG. First, RAM address data "X0oc" is set in register AC.

L notation rXOocJ is register WR(3) (7).

Next, I'l+A'ccJ, that is, 1 is placed in register Acc.

Next, rAccΦAC-+ACCJ, that is, the contents of WR(3) and the contents of Ace are compared and controlled to be stored in Ace, and it is determined whether the contents of register Ace are not O. Since I am currently using rlJ, I will write “
The same thing as above is done by setting ``2J'' instead of ``1'', and the same thing is repeated until register Acc is knitted with 1'5Jwo-t = t'+ with I'Acc≠0''. After exiting set ADD, the address I'X0O3J of the least significant digit of register WA(0) is stored in register AC, "4" is set in register Ace, and register Ace is
The least significant digits of WA (0) and WA (0) are compared to determine whether it is register Ace or "0". In this case, it is not "o", so the next step is WA (0) → AC, ACL + A
The contents of the least significant digit of register WA (0) are stored in register WR (3) by c c , A'c c +W, R (3). Next, the number 7 flag is rlJ or “0”
Since it is not set in this case, the key manual control shown in FIG. 24 is entered.

First, put human power on the register AC, A I of Ii'll10-4.
- Set the response rX500J and take in the signal from the input/output device l10-4 to the register AcC. The above-mentioned input/output device l10-4 is, for example, 7zPD75 manufactured by NEC Corporation.
7, when such a device is selected, it first sends a 4-bit signal indicating whether a key is pressed, whether there is a key error, and which key force line it is. So first,
To determine whether a key is pressed down, turn Acc counterclockwise and send a signal indicating whether a key is pressed down to the overflow bit OVF. Since the key is not being operated now, OV
F≠1. Then, the data of rDJ which has been generated by 1 from the ROM is set in the register Ace.

The contents of register Ace are transferred to register WR(7). Therefore, the next T-1111i after Key in Fig. 21,
L/cis') W R(7) +7) 7 Tres'
r X OIC" is set in register AC, D obtained from ROM is set in register Ace,
The ALU compares the contents of register WR (7) with register Acc (υ1 other OR), sets register ACC to "0", and 5tep4 (7) KEY IN (
7) Finish the procedure.

Next, the procedure of determining whether the setting of the number of copies of the original placed in the original placing pin in step 5 is completed starts.

That is, the address rXO40 of the RAM where the one copy number setting flag is stored is set in the register AC,
The contents of address ``rXO40'' are set in register Acc. Then, the contents of register Ace are rotated counterclockwise (l hit
(left shift) and the contents of the overflow hit OVF are checked. I'm at rOJ now so 5Lep2 again
Return to the display control and press until the copy one sheet a setting is completed.
5Repeat step 2 to step 5.

Is it true that the 5 manuscripts now have original stripe numbers? If the document is placed in the document storage center 77, the microswitch SW4 is turned on and the document is placed in the document storage center 77 at step 5.
The following is detected at 5Lep3 in -5(7) repetitions. As described in 5 step 3 theory IJII 17), the micro switch SWI is sequentially side-stepped, and when the micro switch SW4 is detected, rX2 is input to the register AC.
00J is set and microswitches SWI to SW4
The state of is stored in register Acc. Next, in order to see the state layer 1 of the microswitch SW4, Acc is rotated clockwise (shifted to the right by 1 hit), and the state y of the microswitch SW4 is
A: The signal is set to the OVF (8 floppy) and judged. Now over floppy 1-OV F is "engine", so it is stored in address rXO36J or register AC.
The contents of address rXO36J are transferred to register ACC. The contents of the register Ace are then determined, and since they contain "0" as described by Ij et al., the contents of address rXO37J are then retrieved, which is "F" as described above. The complement "0" of "F" is stored in register Ace, and it is determined whether the contents of register Ace are rAcc≠0. Since it is "0" here as well, 4 is RO in register Acc.
Sent from M, stored in register WR (3), and the 20th
1.1 The details of M e mo are controlled in the figure.

First, the address rXOOOJ of WR (0) is the register AC
and then transferred to rQJ or register Acc. and v of the contents of 1/sister WR (0,) and Ace
A logical sum of 1 is taken by the ALU, and the result is stored in register Ac.
Enter e.

Next, it is determined whether the contents of register Acc are "0",
Since it is now “O”, register AC is address rXO
20j is stored and such address is further stored in register W
Transferred to A(3'). Next, r4J written in register WR, (3) is to be stored in WA (3),
WA (3) → A, C, WR (3) → Acc, Ac'c →
AC is performed, 1Memo control J11 is terminated, and address rXO36J is written to register WA (3) in order to indicate that the copy of the original placed in original placing bin 7 is the first one. Fertilize the soil and enter the SET control shown in Figure 20.

First, the contents of register WR (0) are incremented by +l, and then the data rXO36J of WA (3) or register AC is (
yH" is obtained and stored at addresses rlJ or rXo3,6J of WR(0). At this time, "F" is set at address rXo 37J. Therefore rXO30J~rXO3
9'' is rOF, OFOF'l FOFJ.

Next, if no key is operated, step 4 as described above.
When step 5 is performed and 5tep2 is reached, the display DP
'Displays 4rlF, l, other displays are rOF'
is displayed.

After the original has entered the original stripe number M 7 as described in Hiba 11, when the original of No. 2] 1 is set on the document tray 74, as described above (in the control of Step 3), Turning on the microphone switch SWI is detected, and as shown in Fig. 20, ]:, M
Control of e m o is performed in the same manner as described above. Then, data "1" indicating the position of the pen 4 is stored in the register WR(3). When controlling M e mo, first the contents of register WR(0) are checked.

Since the original is already in the original placing bin 7, the contents of register WR (0) are set to rlJ, so M
e m o control's 2nd 1-; judgment is yes, AIL and S r
The data is stored at address 1J, and control of MemO ends.

Next, R is pressed to notify that the original has been placed in the original pen 4 and that the original in the original pen 4 has been placed in number 2 [1].
Set r2J to rXO30J of AM, and set "2" to register WR(0).

If nothing is done for a while after the original No. 2 [1 is placed in No. 4 as described above, the original is detected and the key is detected as described above, and display control is performed at 11f. r2FO will be located at addresses “X030” to rXO39J.
FOFI FOFJ data is included, so table small Z
:÷DPI is displayed as "2FJ," display device DP4 is displayed as "rLFJ," and others are displayed as "OF."

Next, when the numeric key is operated, 5tep4 KEY I
According to the control of N, first the original set in No. 1 and No.
The data for the number of copies of 7 is stored as follows:

First, in Sl a p l, register WA (0) is r
Since the data of XO20J is stored, WA(,0)−
"AC, AC-'A c c sets register Ace to "
4" data is set.

121st order'°5°t Enters ADD control.Address rXO37 where copy 1 sheet a setting data of document placement table 7 is entered.
J enters register WA(1).

Next, it is determined whether the number of copies per copy has been set, and if it has not been set, the KEY control shown in FIG. 24 is entered and the aMfi key is operated. 1. As mentioned above, at this time, the input/output device 110-4 first outputs whether there is a 4-hit key (1 bit), whether there is a key error (l bit), and whether there is a line 4i (2 hits representing KRO-KH2). , and determines whether the 4□V constant bit is set to 1 or not. If the input/output device 110-4 does not contain ``1'', the numerical key data ``2'' is entered into the register Acc, WR(7) from the input/output device 110-4.

Next, it is determined again which key f1 was operated by rl1, and if it is a numeric key, it is determined whether the current same amount is 1 柘11 by looking at the contents of register WR(1).

Next, the data “2” of register WR (7) is the register Ac.
The data of rXO37J, which is taken into e and stored in register WA(1), is put into register AC, and
Store "2" at address 37. Next, X036. % place “
F' is stored in register WR (1) to record that the number has been placed once, and CS is stored, and '2' is stored in register WR (1), and KE is
End YIN control. Since the setting is complete and 1'Gee OK has not been operated yet, is it flf? Move to Jll, this time r2FOFOFF2'OFJ (7) Data is displayed on display D
Table/Jζ is performed from PI to DP5.

Next, when the numeric key "3" is operated, @
The iJ+ control of K E Y shown in Figure 20 is performed,
After checking 2111 to see if the numerical key is pressed, the V1 number in 2111 or the register WR (
Transfer the content “2” of 1) to register Acc and rotate clockwise (
I-, shift] twice, and if it is Jluchi 1248 coat, ``2'' is rQ O10'', so as a result, ``1'' is A'f in overflow Hiso I・OVF, so it is as follows. Control is exercised.

First, “2” stored at address “X037” is rXo
36J, the data of F3J is stored at address rXO3'7, and "6" (that is, 0
110) and terminates KEYIN control. Due to the current key human resources, tableware DPI to DP5 are r2F.
OFI r.

Become F J r'23 J r OF J. Since the setting completion key has not been pressed yet, the steps 11)j of 5step 2, 3° 4.5 are repeated.

Next 1. The above-mentioned sheet count data setting completion key is operated f1. 11 is performed as described in 1111 up to the KEY control of the KEY IN control, and when it is determined that the completion key has been operated during the KEY control, "F" is set in register Ace, and further register WR (7) is set to The operation check for the completion key OK is checked to 21 in the same way as the G (+lIi key), and if the completion key is OK, ti
, determines the contents of register WR (1), determines whether numerical data is set, and if so, "7" is set in register WR (1), and then second to
In order to remember the operation error in Setflag shown in Figure 5, the one digit "0" of WA (0) ro 20J is used.
” in Acc, determine the content, and write rlJ in the first hit of address rXO40J to t0. Next, when KQ (+ri key, completion key) is operated, the contents of WA (0) will be r 02
' ] Since it is J, that do 1njrlJ is r.
"1" in the next bit of the most - place hit at address XO40J
Set.

1. As described above, a flag is set at address rXO40J, and 5Lep5 is controlled. That is, rXO40j
The most significant bit of the address is input to the overflow OVF, and the control circuit CT determines whether rOVF≠1.

Since it is currently 1, proceed to 5step 6. First, the register W'A (4) in which data can be stored is cleared.

Hi! Next, address rXO20J;

It is stored in the register WR (2). Numbers are given as 1 to 5 for numbers 4 to 8 in the original c' stripe device. Therefore, "4" is written as t0 in WR(2). next i,=st
Control of ep7 begins.

First, WR (2) (7) '71" reply rXo O8j
is set in register AC, then rf3J is transferred from ROM to register Acc, and Acc+WR(2)→A
cc is 91. Next, input/output device I/, 0-1 (7
) 7 dress r
” is the human output device position l1O-4iCJA9, l10-4
rlloOJ appears at the end of
ooj or decoder DEI to unj8-1 AC3
Since the signal is applied to the other input end of the clutch 0-4, the clutch 0-4 is driven, and one document is drawn out from the document placement pin 7.

Next 1. address r so that the original is sent to the copy machine.
x3oo4 is set in register AC, register Ac
Set 2 to e and drive clutch 0-f in the same way as l10-1.

! -Record C! :L-147) ON II! j
The interval is set to r by timer TMR, and it is turned off after sending out. Next, the lower detection stage SW6 detects whether the original has reached a predetermined position of 1 or not. Such detection r-stage SW6 is 87 shown in FIG. During the duration of this control, the setting for the number of copies of the document placed in the document tray 4 is detected. For example, when the numeric key is pressed to set the number of copies, 9, the address stored in the register WA (0) that stores the document II "111" that was placed on the document placement pin. “X
020'' is changed to rXO21J by the flag at address rXO40J.

Next, when you enter control of IIf and KEY IN, select "2" in the number of originals setting for originals in step 7.
However, since the data stored in register WA(0) is rXO21J, the data "9" is entered at address rXO31J, and the data of rFJ is entered at address rXO32J. Furthermore, if the setting completion key is operated, the RAM number setting flag r040 is set in the same way as the above operation.
r041. Put "rl" on +. This time, the copy order is second, so the bit with a weight of "4" at address r04oJ becomes rlJ.

- If it is determined in step 5 step 8 that the document has arrived at the predetermined position on the document table after the key operation as described above, clutch C-f is disengaged, movement of the document is stopped, and a copy start signal is input/output. The output is output from the implementation @l10-3, and the copying machine is made to copy the original.

In the next step 5 step 9, the copying device is charged.

Each process of exposure, development, transfer, and fixing continues, but the light from the light source of the copying machine is detected during the exposure process, and the flashing II! I
D Performs control to count 2 sentences per copy from 4 copies. This light detection signal (Lamp Det
ect).

Also, while checking in the same way as in 5tep8, input 1 large and small of the 1 fixed key of other cassettes. When the light from the light source L is detected, it means that one copy has been completed.

The above-mentioned copy detection control is performed by checking the input terminal r- of the input/output device I/'O-1 of the detection r stage LD, and when it is "l", 1 copy or complete
It shall be assumed that 1. The contents of the terminals I3 to ■0 of the input/output device l10-1 mentioned above are sent to the register Acc, and the contents are sent to the register A.
CC content? 21. ! ! When shifted right by 1, end T-1
If state 1 is set to overflop I/OVF and the content is rOVF≠Sil, then the document is newly entered into the document reception mode.
Were any key operations performed and the RAM rXo, 30J?
~rXO39J The size of the contents of the waste material is controlled by the detection means 1 as described above. This process is repeated until rlJ appears from D. When "l" appears on terminal 1 of l10-1, the contents of register Ace are rotated to the left (1 and 21), and the interrupts A and 1 sent from the copying machine are applied to terminal I (l). The state of is determined. If it is "l", then 11
．． When you urgently want to copy just one sheet or a number of sheets, press the copy button on the copying machine or press the 11'A request button to copy from the copying machine to the end flo of l10-1. Man-powered. When this is detected, the control device changes the current state to Hall I, waits for the completion of the 11 signal, and
After finishing, enter 5tepH. If there is no interrupt signal,
We will soon compare the number of copies per copy of 5 tepH / 1 operation and the set number of copies. 1. of CNTs. '1 details are shown in FIG. If we explain according to the figure, register W
A (4) is cleared in 5tep4, and the lowest digit "0" of the register WA (,4) is set in the register Ace, +l is executed in the ALU, the addition t'j result is stored in Acc, and further The ALU performs decimal correction on the contents of Acc, and the contents of Acc are sent to AC3 of register AC.

Next, it is determined whether the overflow bit OVF is "rOVF≠1". Now rOVF ≠ 1, so next copy rXO3 where the configuration data of the
In order to retrieve the data at addresses 0J to rXO39J, the contents of register WR (2) are retrieved, and the contents are 1 to 5.
Find out which of the following is the case. Now the data of "4" is WR (
2), so the rXO37J data is in WA
(2), further enters register AC, and rXO37
Data “3” stored at address J is in register Acc.
is derived.

Then, the data in the lower 1st digit of ILk of register WA4 is derived and compared with the contents of register Ace.

Now, since Ace≠O, it is 91 (■), Acc is cleared, and WR (3) is also cleared, and the control of CNT is ended. Next, transfer the contents of register WR (3) to Acc, and
- Perform f'tl ttli with Acc=O, l. In this case, it is YES, so the process returns to control of document detection, etc. in Step 9. Since the copy start button is currently on, the copying machine continues to copy the original placed on the document table, and when the content of the lowest digit of register WA (4) becomes "3", CNT (7) controlled “xO3
When comparing the contents of address 7'' and the contents of the lowest digit of WA4, it is no longer rAcc≠0'', so go to ■, WA
(2) cr) rXo 37J (7) Set the address data to rXO36J4. : and compares the contents of address rXO36J with the contents of address rXO12J of WA (2). As the result Acc=1, (1) Hi5tep9
, 10.11 (7) Control procedure '41' When the control procedure described in - is performed, the contents of register WA (4) are incremented by l. Manuscript! When copying 5 sheets 14 or 11 of the first document in the storage bin 7, the copier COP, for example, switches
When Δ) is operated 5 and an interrupt signal is generated, 5te
p9(7) entry i, 1. When the data IIy is read by the J horn unit 'aI/O-1, an interrupt signal is sent from the terminal ■0 along with the detected data of 5 copies of 11.
Confirm that the copy of t R, 543 (1:] has been performed by shifting the register ACc to the right twice to put it in the overflow bit OvF, and then shift the contents of the register Acc by l 1III no 1. By inputting the fil interference signal to the overflow hit OVF, the -jl interference control shown in FIG. 26 is performed.

First, address data X300 is input manually to select the input/output device l10-3 of the register AC. Next, output terminal 0
In order to select 2, input data ``4'' to register Acc, output a signal to drive clutch ci-b from terminal 02 of input/output device l10-3, and turn off the copy signal output from terminal Oo. 6. When the clutch an-b is driven, a drive means (not shown) rotates the rollers 77 and 78 in the reverse direction, and conveys the original on the original glass 35 onto the partition plate 80 and the heald of the partition plate 80. Of course, at this time, the suction fan 81 causes the belt 79 to suck the document r1. [-The original is detected by the operation as described above.
The movement continues until it is detected by stage 92. Detection means 9
2 detects a document, the switch SW7 is turned on, and a signal other than "1" is sent to the terminal IO of the input/output device l10-3.

This signal is taken into the register Acc, and the 11 shift I.
1 time, and OV F becomes 1 or not. If it becomes 111, the address rX 300J for selecting the input/output device l10-3 is set in the register AC, and the register Acc Set "0" to the input/output mounting (l I/0 3 terminal o (+-
The signal output from the IQ is set to 6, and the clutch C1-b that controls the drive of the conveyor belt 79 is turned off to stop the heald. The original is evacuated into the conveyance device as described above.

Next, select the input/output device l10-4, send data "3", use the warning device EL to indicate the completion of evacuation to the operator, and drive the solenoid LR to release the connection between the &Manki Cop and the transport device Caru. let

Next, Sohaku Nagisa holds the transport device Caru by one end as shown in Figure 6, places the original that needs to be copied immediately on the original crow 35-1, and starts the copying machine C op.
Operate the copy button provided on the screen to make the desired copy.

- The force control circuit continues to detect the state f of the end rIo of the input/output device l10-1 during the operation of the above-mentioned interrupt copy.

” - When the urgent copying work described above is completed, the operator returns the transport device Caru to its original state, and turns off the switch 11-1 again, the input/output device l1O
-1 (7) Since rO is applied to the terminal r-Io, the overflow OVF becomes 0, confirming that the interrupt has ended.

Next, the conveying device Caru force < 41) II to the original state y&;
When η is released, a signal is sent to the terminal IQ of the turnout device l10-4 from the switch SW8, and when the release 4rr t7 is confirmed by the overflow bit OVF, the next control is performed.

Next, in order to resume copying of the original that was omitted before the interrupt control, the input (address Then, the clutch C1-f is driven and the evacuated original is again moved onto the original glass 35 by the conveyor belt 79.The original sent onto the original glass 35 is detected again by the switch SV6. Then, the clutches C1-f are disengaged, the copying machine 11 is sent again to the copying machine COP, and the copying of the interrupted original is resumed, and the control starts at 5tepH. WA Contents of (4) 5
- Next, compare the set number of sheets "23" and see if it is the same, and since it is not the same, ORG again at 5tep9.

Repeat the control starting with KEY IN and 'DPY.

When "23" is stored in register WA (2), r
XO36" rXO37J ks Matches the stored "23", so in the last control of CNT, set Ace to 1, set this content to WR (3), and set 5tepH.
The last judgment of Acc=O is No, and 5tepi
Perform the second control. In other words, in order to send the copy signal OFF rQJ to the terminal 0 of the input/output device 10-3 and input the original for copying to the input/output device 10-3, the chi I/SHI/HE-45 etc. are connected to the solenoid 5L-.
1-3L-5 acts on protein 37. Now, place the aforementioned manuscript in place 7 & here.

The reception is stored in the input 39.

When the above-mentioned operation is completed, the control returns to Step 13, and first, the IQ of input device 110-1 is used to determine whether there is a document in the document placement input 7 currently being performed.

If, I2. Check the input of I3 and I3 of the manual device l1072, and now place the original with force (the document is in n7, so return to 5 step 7 and start the same operation as above). When copying is completed for the 5 originals included, 5step 14
First, register WR (0) that stores the number of document bins that currently contain documents.
-l the contents of. Now it is ``2'' and it is Hi゛, so it becomes l'lJ. Next, since there is no original in the original J/l placement pen 7, register WR (2) is used to change the "23" displayed on the display DP4 to rOFJ.
Take out "4" from register WA (1) L:
rXo 37J (7) 7 F'lz Suwo ADD's 11
Control is performed under Noj control, and based on the address of rXO37J, input "F", change rXO37J to "rXO36", and input "0" to address rXO36J.

Next iZ r X O20J -r
5jep, '14 is terminated by setting "0" to address J.

In the next sje p l 5, rXO40Jr
Set the contents of address XO41J by 1 hit (left shift control and the number of copies by 1/1), and if register WR (0) or "0", set register WA4
In this case, if the content of WR(2)hi1゜ is not 0, then the original is stored in one of the striped devices, so it is stored in 5Lep6 and then the h to be copied. (The number of stripes and the Iy fin document are controlled. In S Le 1114 mentioned above, the document placement in 9 is placed at address rXO20J, and
Because it includes data rlJ to taste! The document placement pen 4 is controlled as described in section B'. In the above example, the number of copies was shown as the copy line 1, but the copy density etc. line f1 can be set in the same way.

As described above, since the present invention is provided with means for changing the priority order of image formation, the degree of freedom of the image processing apparatus can be expanded.

[Brief explanation of the drawing]

11Δ is an external view of the image processing device according to the present invention, FIG. 2 is a cross-sectional view of the image processing bag according to the present invention, FIG. 3 is a cross-sectional view showing the drive section thereof, and FIG. Cross section, 5th
The figure is a perspective view of the transfer device, FIG. 6 is an external view of the transfer device, FIG. 7 is a block diagram of the control device, and FIG. 8 is a ROM
Block diagram of the device δl10-1, -Ilo-3, 1st
1 shows the input/output device l10-1. -110-3 external connection diagram, Fig. 12 is an external FAR connection diagram of input/output device l10-4, Fig. 13 is a basic timing diagram, Figs. 14 to 27 are control explanatory diagrams, and Fig. 28 is an external connection diagram. It is a timing explanatory diagram. 1 is the copy +:+11 requesting device, 2 is the manuscript placement unit, 33 is the applicant Canon Co., Ltd. 4 figure procedure amendment (method) 1982 P: 11 / 12i H 1981 Patent axis No. 129665 2 Name of the invention Image processing device 3 Person making the amendment Connection with the case HIIJI patent applicant (1 place Higashi III Tokyo 111 ward lζmaru J' 3-: IO
-2 Name (+00) Canon Co., Ltd. Representative Nagaku fl
Power, H':l:1tl-25, date of amendment order: October 60, 1980 (shipment date), 7th specification subject to amendment, details of amendment F3A details are printed as attached. (No change in content)

Claims (1)

[Scope of Claims] Storage means for recording a different output floor for each of the plurality of image information;
said one of said image information based on said output condition for one
an image output means for outputting two outputs; a means for interrupting image output of the image information by the image output means; and an image of the image information that is interrupted after the image output of the image information among the plurality of image information is interrupted. An image processing device comprising means for restarting output.