JPH037951B2 - - Google Patents

Description

[Detailed description of the invention]

The present invention is an electronic calculation practice machine, in particular, allows learners such as children to calculate calculation problems automatically created and displayed inside the practice machine by hand, and then input the results using keys. The present invention relates to an electronic calculation training machine in which the input data is input into the training machine and the correct answer is compared with the correct answer. Various calculation practice machines have been proposed in the past, some of which are already commercially available. A typical example is the "Little Professor" (trade name) manufactured by Instruments Inc. in Texas, USA. In this device, practice questions are automatically created inside the device, the user solves the created practice questions by hand, inputs the results into the device from the key input section, and compares the correctness of the answers. When a predetermined number of questions are completed, the score for the correct answer is displayed. An object of the present invention is to improve the above conventionally proposed or commercially available devices to provide a calculation practice machine that is easy for users such as children to operate. More specifically, it is an object of the present invention to enable the user to select the difficulty level of a calculation problem by setting the number of digits of the calculation problem and the type of the four arithmetic problems, and To provide an electronic calculation practice machine which generates a temporary calculation problem in which the number of digits of the operand is displayed symbolically, and allows the user to check the items set by the user. According to an embodiment of the present invention, there is a display means for automatically creating a calculation problem and displaying the problem, an input means for inputting an answer calculated by the learner himself, and a determination as to whether the input answer is correct or incorrect. In a device equipped with a means for notifying the results, the display means has a two-stage structure of a multi-digit display section, and the display means is configured to display various information other than the question display. The score for the correct answer is displayed using a 100-point scoring system, as well as the specified number of questions, number of correct answers, and question group number. In addition, in order to make it easier to understand whether the answer is correct or incorrect, the display means blinks and an alarm sounds. Furthermore, all digits of the numerical value of the answer obtained by the learner by hand calculation etc. are input into the device using the key input section and stored, and then the correct/incorrect judgment instruction key (answer key) is used.
A comparative judgment is made by the operation of . A slide switch is provided to set the difficulty level of the calculation problem, and after setting the difficulty level using the slide switch, the number of digits of the calculation problem to be asked can be changed to "00+00" by operating the Diyun key. It is displayed by the display means as follows. A switch is provided to select the number of calculation problems, and the number of problems can be set to 10 by operating the selection switch.
A selection of "25" and "100" is made. A numeric key, an answer key, and a redo key are provided as an input means for the learner to input answers calculated by himself/herself, and the counting operation of the counting means that counts and stores the number of correct answers can be selectively performed in connection with the combined operation of these keys. Let's do it. Since the same practice problem group is repeatedly selected, a specific practice problem is generated depending on the combination of the numerical keys and the start key. An embodiment of the present invention will be described in detail below with reference to the drawings. FIG. 1 shows an external view of the electronic calculation practice machine of the present invention, which is a bookcase type practice machine consisting of a display section, a key operation section, a memo pad section, a difficulty level table, and a writing utensil section. In the figure, a main body cabinet 1 has a power supply section, an electronic circuit, etc. inside, and a multi-digit, two-level display section 2 for displaying calculation problems, answers, and other information on the inside surface, and a display section 2 for displaying calculation problems, answers, and other information, and addition, subtraction, multiplication, and division problems. Type selection switch 3, number of questions selection switch 4, power on/off and problem difficulty selection switch 5, input key section 6 consisting of numeric keys and function keys such as answer, redo, etc., problem type and difficulty level table 7. have. There is also a memo pad section 9 for storing magic notes etc. on the inside surface of the lid cabinet 8.
and a writing instrument 10, both cabinets 1
and 8 are connected by a hinge 12 so as to be openable and closable. Further, a power switch 11 is provided in the main body cabinet 1, which is turned on and off as the cabinets 1 and 8 are opened and closed, and the power switch 11 is turned on when the cabinets 1 and 8 are opened and closed. FIG. 2 shows a circuit configuration diagram of an embodiment of the present invention, and the main part is a one-chip integrated circuit device (LSI) having a processor, read-only memory (ROM), and random access memory (RAM), as described later. 21, the read-only memory (ROM) is microprogrammed according to the functions described later, and the ROM is programmed in a firmware manner. The integrated circuit device (LSI) 21 has power terminals GND,
V _DD , input terminals K ₁ to _{K 4} , display segment information output terminals S ₁ to _{S 7} and timing signal output terminals R ₀ to
It has R ₁₁ , R ₁₄ to R ₁₅ . The display section 2 has a two-stage structure of 10-digit fluorescent display elements DP1 and DP2, and the shape of the display segment electrode of each digit is shown in FIG. In FIG. 3, the display electrodes of the upper display DP1 are in the shape of a "Japanese" character for the lowest to fourth digits, the shape of a "〓*" character for the fifth digit, and the symbols for addition, subtraction, multiplication, and division, and the sixth to ninth digits. is in the shape of a ``Japanese'' character, and the most significant digit is a symbol ``○ ×'' that indicates whether the calculation result is correct or incorrect. Also, the lower display
The display electrode of DP2 has the lowest digit to the 6th digit in the form of a "Japanese" character, the 7th digit as a symbol "=", the 8th digit as a blank digit,
The 9th to 10th digits are arranged in the shape of a Japanese character.
Further, each display electrode is classified into _S1 to _S7 , and the corresponding electrodes are commonly connected. In Figure 2, the heaters of display bodies DP1 and DP2
H ₁ and H ² are independent AC power supplies T ₁ and T ₂ respectively
However, the potential of the heater _H1 of the display body DP1 becomes -V only when the transistor _Tr1 is in a conductive state, and similarly, the potential of the heater _H2 of the display body DP2 becomes the potential of the transistor _Tr2 . It becomes the potential -V only when it is in a conductive state, and becomes the ground level through the resistors _R1 and _R2 when the potential -V is not applied. As described above, corresponding segment electrodes of the display electrodes of each digit of the display bodies DP1 and DP2 are connected to each other, and receive voltage supply of display information from the output terminals _S1 to _S7 of the LSI 21. The first digit grids _G10 and _G20 of the grids G10 to _G19 and _G20 to _G29 of the display bodies DP1 and _DP2 are the timing signal output _R0 of the LSI21.
Similarly, the grids G ₁₈ and G ₂₈ in the 9th digit are connected to the timing signal output R ₈ , and the grid G ₁₉ in the 10th digit is connected to the timing signal output R 8.
and _G29 are respectively connected to the timing signal output _R9 . Timing signal R ₀ to R ₉ output from LSI21
, and R ₁₀ and R ₁₁ are digit time signals that define each digit of numerical information, and as shown in FIG. 4, these signals are out of phase with each other. Further, the timing signals _R14 and _R15 are word time signals having different phases, which are inverted every 12 digit times of the timing signals _R0 to _R11 , as shown in FIG. ₁ and Tr ₂ are alternately turned on every word time, and the LSI
The display information outputted from the terminals S ₁ to _{S 7} of 21 is distributed and displayed on the display bodies DP1 or DP2 every word time. Power supply unit I includes an external power supply jack A, a battery power supply B, and a power switch _S1 connected in series to the power supply circuit.
(switch 11 in Fig. 1) and S ₂ (on/off contact of changeover switch 5 in Fig. 1), DC-
The switching transistor Tr ₃ that constitutes the DC converter, the oscillation transistor Tr ₄ , the starting resistor R ₇ , the limiting resistor R ₈ , the oscillation control Zener diode ZD, the efficiency increase capacitors C ₁ and C ₂ , the ripple capacitor C ₃ , rectifier diode D ₁ ~
_D3 , smoothing capacitors _C4 to _C6, etc., and is supplied with heater AC voltage and DC negative potentials _VDD , -V, -V' from the power supply section I. Note that the above-described power supply unit I has a generally well-known circuit configuration and is not directly related to the gist of the present invention, so further explanation thereof will be omitted. The changeover switches 3, 4, 5 and the input key section 6 shown in FIG. 1 adopt the strobe key system and are arranged in a matrix, and the numerical keys □0 to □9 are each connected to the timing output terminal R ₀ of the LSI 21. It is connected to receive the signal from ~ _R9 and to supply a timing signal corresponding to the pressed key to the input terminal _K1 . Similarly, the function keys have been redone,
Answer, start, stop, too much,
The digital keys are connected to receive timing signals from the output terminals _R0 to _R5 , respectively, and to supply a predetermined timing signal to the input terminal _K2 . In addition, problem difficulty level changeover switches 2 to 6 each receive timing signals from output terminals R ₀ to _{R 4} , and input terminals
K ₃ is connected to supply a predetermined timing signal. Similarly, question type changeover switches +, -, ÷ and problem number changeover switches 10 and 25 receive timing signals from output terminals R ₆ , R ₇ , R ₈ and R ₁₀ , R ₁₁ , respectively, and are set to input terminal K _4. is connected to supply a timing signal corresponding to the selected switch. Note that the output terminals R ₀ ~ R ₁₁ , R ₁₄
~R ₁₅ and input terminals K ₁ ~ _{K 4} are clamp resistors r ₀ ~ r ₁₁
and is clamped to the potential -V' by r ₁₂ to r ₁₅ . In the above configuration, for example, when key 2 is pressed, the timing signal output from output terminal R ₂ is input to terminal K ₁ , so that it is decoded inside the LSI 21 that key □ 2 has been pressed. Similarly, if switches □+ and 10 are set, the terminal
The timing signal output from R ₆ and R ₁₀ is the terminal
Since it is input to _K4 , it is determined that switches □+ and 10 are set inside the LSI 21.
Note that no timing signals are input to switches 1, □×, and 100, but the settings of these keys can be used to create a state in which no timing signals are input to terminals K ₃ and K ₄ inside the LSI 21, for example, when the power is turned on. As a result, it is recognized that the switch is set. An example of the internal configuration of the integrated circuit device (LSI) 21 shown in FIG. 2 is shown in FIG. In the same figure (LSI)
21 is a calculation control unit 5 for calculation and judgment control.
0, has an address counter 52 that specifies the address of a memory location in a read-only memory (ROM) 51 that stores microprogram instructions.
ROM 51 is programmed in a generally known manner according to the functions described below, and can be efficiently programmed in firmware form, for example by selectively retaining or omitting memory functions. The timing inside the LSI21 is controlled by the oscillator 53,
The timing signal is generated by the timing circuit 54 and the display control signal generation circuit 55 that generate the timing signal described above. Input signals from the key input section and each selection switch are given to the LSI 21 via terminals _K1 to _K4 ,
These signals are input using a generally known key strobe method, and the input signals are identified in the input section 56 according to the output from the ROM 51, and converted into code signals corresponding to each key.
LSI21 also has random access memory (RAM)
57, and stores data and the internal state of the LSI 21. The information stored in RAM57 is
Information on the memory address specified by the address counter 58 controlled by the ROM 51 is transmitted to the arithmetic control section 50, and if it is a display cycle,
Data introduced into the arithmetic control section 50 is output as display segment information from terminals S ₀ to S ₇ via a segment decoder section 59 and a buffer circuit 60. Pulses from output terminals R ₀ -R ₁₁ scan the display digits or key inputs and selection switches as shown in FIG. The pulses generated from this scanning operation are applied to the input section 56 of the LSI 21 via the pulse terminals _K1 to _K4 . FIG. 6 shows the internal configuration of the RAM 57 in FIG. 5, and the RAM 57 is composed of eight memories (A to H) each having a storage capacity of 16 digits (one digit is 4 bits). FIG. 7 further shows the internal states assigned according to each piece of memory information in the RAM 57 in FIG. 6 when practice problems are being generated and displayed, and FIG. RAM when the number of scores, number of questions, number of correct answers, and numbers are displayed after the practice questions have been completed.
The internal state of 57 is shown. In FIG. 7, the memories A ₀ to A ₉ of the RAM 57 and
B ₀ to B ₉ are used as display registers, with A ₀ and B ₀ corresponding to the first digit, and A ₉ and B ₉ corresponding to the tenth digit. The detailed breakdown is as follows: Register J (A ₉ ) for displaying symbols “○, ×” (○…Code 6, ×…Code 1), Register AD (A ₅ to _{A 8} ) for displaying operands, Register FD (A ₄ ) (+…
Code 10, −...Code 11, ×...Code 12, ÷...Code 13), register BD for displaying the number of operations (A ₀ to _{A 3} ), register MOD for displaying the number of questions (B ₈ to B ₉ ), “=” These are a symbol display register EQ (B ₆ ) (=...code 11) and an answer display register ASD (B ₀ to B ₅ ), and the contents of these registers are displayed on the display section 2. The answer storage register AS (G ₀ to _{G 5} ) stores the calculation result calculated in the calculation register. Each time a problem occurs, a number “1” is added to the problem number storage register MO (G ₈ to G ₁₀ ), and the contents are stored in the register.
Transferred to MOD and displayed. The practice number storage register L (H ₁₂ to _{H 15} ) is a register for saving a preset practice number (practice problem group number), and its contents can be changed by operating the numerical keys and start key as described later. It is set to "1" when the power is turned on. The register SE (F ₈ ~ F ₁₀ ) for storing the number of correct answers stores the number of correct answers.
A register is created in the arithmetic control unit 50 for each practice problem.
The contents of ASD and AD are compared, and if they match, a value "1" is added to register SE. The register TM (H ₈ to _{H 10} ) for storing the total number of questions stores the contents specified by the number of questions changeover switch 4. The random number storage register RM (H ₀ to _{H 7} ) stores the numerical values (random numbers) used to create the next problem even after creating one practice problem, and new random numbers are stored one after another each time a practice problem is created. Remember. The arithmetic function storage register FN (F ₄ ) contains the arithmetic symbol information specified by the problem type switch 3, with the (1010) code for addition, the (1011) code for subtraction, the (1100) code for multiplication, and the (1100) code for division. (1101) Each code is encoded and stored. Difficulty level storage register Z (F ₅ ) is problem difficulty level changeover switch 5.
Difficulty level information (grades 1 to 6) selected by the user is stored. Flag register FF ( _F6 to _F7 ) is LSI
21 is stored, and conditional flip-flops (hereinafter referred to as flags F ₆₁ , F ₆₂ , F ₆₃ ,
F ₆₄ , F ₇₁ , F ₇₂ ). The flashing registers TE (B ₁₄ ~ B ₁₅ , C ₀ ~ C ₁ ) are used for time control to flash the display when one practice question is answered correctly or when the score is 100. The contents of register TE are counted up until they reach a certain value. Remainder storage register AM
(E ₀ -E ₂ ) stores the remainder in division practice problems. Next, the internal state of the RAM 57 in the score display state will be explained with reference to FIG. In this figure, the contents of the display register are different from the state shown in FIG. 7, but the other parts are the same. In other words, when the score is displayed,
The data previously stored in the display registers (A ₀ to _{A 9} , B ₀ to _{B 7} ) is cleared, and the practice number information stored in the practice number storage registers (H ₁₂ to _{H 15} ) is changed to the practice number. Display register LD ( _A5 to _A8 )
will be forwarded to. Similarly, the register SE for holding the number of correct answers
100 based on the number of correct answers stored in (F ₈ ~ F ₁₀ )
The number of points out of a maximum score is calculated, and the result is transferred to the score display register TO (A ₀ to _{A 2} ). In addition, the register SED (B ₀ to _{B 2} ) for displaying the number of correct answers has a register.
The contents of SE are transferred, and the contents of register MOD are retained. Next, the configuration and operation of the device of the present invention will be explained in detail in accordance with actual calculation practice operations. First, prior to this explanation, the functions of the selection switch group and each key in the key input section will be explained. The calculation type changeover switch 3 is composed of a four-position slide switch, and sets the types of four arithmetic calculations. The number of questions changeover switch 4 is composed of a three-position slide switch, and selectively sets the number of questions to 10, 25, or 100 questions. The difficulty level changeover switch 5 is composed of a six-position slide switch, and sets the difficulty levels corresponding to classes 1 to 6. The Jiyunbi key is used to newly set the four arithmetic calculations, difficulty level, and number of questions. If the key is pressed after each setting, each setting information will be displayed.
It is stored inside the LSI21. The start key is operated when starting a series of calculation exercises, and when the key is pressed, a problem generation mode is set, and problems are generated according to the contents of the set changeover switch and the exercise number. Numerical keys 0 to 9 are operated when setting the practice number and answer, and in the problem generation mode, the answer is set, and in other cases, the practice number is set. The remainder key is used to set the remainder in division, and the quotient and remainder are set by manipulating the quotient and the remainder. The answer key is operated to judge whether the answer entered is correct or incorrect. The stop key terminates problem generation, resets the problem generation mode, and displays the score and number of correct answers. The test key is operated when correcting the practice number and answer number, or when redoing calculations when an incorrect answer is displayed. Next, the configuration and operation of this device will be explained step by step from when the power is turned on. First, this device is configured so that the number of digits in a calculation problem is displayed as a numerical symbol such as "0" when the power is turned on or after the user operates the play key. In other words, when a learner studies on a training machine, it is necessary not only to select addition, subtraction, multiplication, and division, but also to select the operand and the number of digits of the operand. The operand and the number of digits of the operand of the problem that will occur in connection with this selection are displayed as "0". For example, multiply before or after power on,
The case where the setting is level 1, 25 questions and the game key is pressed will be explained with reference to the operation explanatory diagram in FIG. 9. First, when the power is turned on or by pressing the Start Key, the number of problems is 25, the multiplication code is 12, and the difficulty level is 1.
information is stored in registers TM, FN, and Z, respectively. Next, memory areas _D0-15 are cleared, and the function (X) stored in register FN ( _F4 ) is moved to memory area _D4 . Next, input "1111" into memory areas A _{0 to 15} and B _{0 to 15} to blank the display. Next, by determining the content of F ₄ , since the content of F ₄ is "12", it is determined that it is multiplication, and the difficulty level is determined to be level 1 because F ₅ = 1,
Based on the determination result, the contents of _D3-5 are moved to _A3-5 , and furthermore, the memory areas _H8-9 storing the set number of questions are moved to _B8-9 . Through the above operations, the display on the display unit 2 becomes as shown in FIG.
A temporary calculation problem "0x0" in which the number of operands and the number of digits of the number of operations are symbolically displayed, and the number of problems is 25 is displayed. Further, FIG. 11 shows an example in which a temporary calculation problem is displayed in which the number of digits of the operand and the number of digits of the operand are symbolically displayed using a symbol other than "0". The above operations are executed according to microprogram instructions stored in the ROM and sequentially output, and the operations described below are also performed using the ROM.
The control is executed by the output of In other words, in the device of the present invention, the ROM is programmed in firmware format in accordance with the operation explanatory diagrams described above and later. In order to generate practice problems, calculation problems are sequentially created and displayed by operating the start key. Next, the operation of generating practice questions will be explained with reference to the operation explanatory diagram of FIG. 12. There are two ways to start learning calculation problems: one is to operate the start key, and the other is to operate the start key after specifying a group of practice problems using numerical keys. In addition, in the device of the present invention, a series of practice problems are created using random numbers generated by the multiplicative congruence method, and this problem is created using a given initial value (a numerical value related to the numerical value representing the group of practice problems).
If the problem group has the same practice number, the same problem will always occur. First, by pressing the start key, all memory areas C ₀ to C ₁₅ are cleared. Next, the contents of flag register _F62 are determined. F ₆₂ is when the numerical keys are operated as described later (see Figure 15).
It is a flip-flop that is set when lead-in is performed, and is in the set state when the practice problem group number is input, and the input information is stored in memory areas B0 _{to B5} . Assuming that _F62 is now set, next the contents of _B0-5 are moved to _C0-5 , and the contents of _C0-5 are shifted to the right until there is no blank signal "15" in _C0 . By this operation, the lead-in numerical value as the practice problem group number is held in the memory areas C0 _{to C5} with _C0 as the first digit. On the other hand, if the start key is pressed without leading in a numerical value, "1" is input into C ₀ based on the determination that F ₆₂ =0.
As a result, practice number "1" is set. Next, input “1” to C ₅ , and write memory area C _{0 to 9} .
Generate random numbers using the multiplicative congruence method using the contents of as initial values. The multiplicative congruence method is a method of generating random numbers by X _i+1 = 23Xi (mod10 ⁸ + 1), and Xi is 23
The remainder after multiplying by 10 ⁸ +1 is set as X _i+1 . Specifically, first transfer the contents of memory area C _{0 to 9} to memory area D _{0 to 9} , then execute C _{0 to 9} + D _{0 to 9} → C _{0 to 9} , and then transfer the contents of C _{0 to} 9. Shift left by 1 digit and return to C _0~9
+D _0~9 → Execute C _0~9 three times, then clear D _0~9 , transfer C _8~9 to D _0~1 , further clear C _8~9 , then C _0~7 - Execute D _0~1 → C _0~7 , transfer C _0~7 to random number storage register H _0~7 , and generate a problem from this random number. In addition, if new problems arise
Random numbers for creating questions are sequentially generated by executing the above-mentioned calculations based on the values stored in H0 _{to H7} . For example, if the initial value is (100001), the following random numbers will be generated in sequence. (2300023), (52900529),
(16712155), (84379562), (40729907)...or if the practice problem group number is 7, the initial value is (100007), (2300161), (52903703),
Random numbers (16785157), (86058608), (79347965)... are generated in sequence. Next, the operation of creating and displaying a calculation problem from the random numbers will be explained with reference to the explanatory diagram of FIG. 13. When displaying a calculation formula in the device of the present invention, the operand and the operand are displayed adjacent to each other around the function symbol (+, -, ×, ÷). It is easy to read and matches the writing format of commonly used problem sets. As an example, the occurrence of a problem and the display of a calculation formula will be described for the case where the problem group number is "1", multiplication, and the difficulty level is set to level 1. First, as mentioned above, the first random number (2300023) is generated, but it is not used because the 4th or 5th digit is "0", and similarly the second random number is not used and the random number (16712155) is generated. Used to create the first calculation formula. First, the contents of random number storage registers _H0-7 are transferred to memory areas _D0-7 . Next, _D4 to D7 are shifted to the left once, and the contents of the previously stored function _F4 (x symbol) are transferred to _D4 . At this time, the contents of D0 _{to D7} are (671×2155). Further, a blank signal "15" is input to the memory areas A _{0 to 15} and B _{0 to 15} . Next, by determining the contents of _F4 and _F5 , it is determined that this is a first-class multiplication problem creation operation, and memory areas _D3-5 are selected and transferred to _A3-5 . Also
The code “11” that displays the “=” symbol is input to B ₆ , and the number 1 is added to the problem number storage registers C _{8 to 10} (G _{8 to 10} are initially cleared). Transfer the information on the number of questions G _8-9 to B _8-9 . By the above-described operation, the 14th
As shown in the figure, the calculation formula (1×2) and the number of problems "1" are displayed, and the operands and the number of operations are displayed centered on the multiplication symbol "x". The correct answer to this calculation problem is calculated by the calculation control unit 50 and then stored in the register AS (G _{0 to 5} ) such that the most significant digit is located at G ₅ . After that, the same operation is executed and the calculation problem (7×
9), (2×9), etc. are automatically created in sequence. Next, a description will be given of the operation when the user calculates the calculation problem displayed on the display section by hand, etc., and reads in the answer using the numerical keys. In the device of the present invention, even if the answer obtained by hand calculation etc. exceeds the display allowable digit N, it is possible to perform a lead-in of N digits, and the lead-in operation of the exceeded digit is stored internally, and the next answer key is used. It is configured to perform error detection during correct/incorrect processing during operation. In other words, if the answer the user solved by hand calculation or mental calculation exceeds the number of displayed digits, and the value of the displayed digit matches the correct answer, even though the user's calculation was incorrect. There may be cases where the answer is determined to be correct. For example, if the number of digits that can be entered in the answer is 6 digits, and you calculate 823×571, the correct answer is 469933.
However, if the user answers 4699330, which is one more digit, the displayed part will be the same as 469933, and there is a possibility that the answer will be apparently correct. On the other hand, in the apparatus of the present invention, the number setting operations for display digits or more are stored, and an error is determined at the subsequent correct/incorrect determination. FIG. 15 is an explanatory diagram of the operation when inputting the answer obtained by written calculation or mental calculation using the numerical keys.
means the operation of a numeric key; when the first numeric key is pressed, B ₅ =15 is determined, and the operation of storing the numeric value N in B ₅ and setting the flag register F ₆₂ are executed. At the next number, B ₅ ≠ 15, B ₄ =
15, the numerical value N is stored in _B4 , and the same operation is repeated thereafter to store the numerical value in B0 _{to B3} . Proceed with the number setting operation further and when the seventh number is entered,
Since B _{0 to 5} ≠ 15, a flag flip-flop F ₇₁ is set, and this F stores the fact that an answer with more than the display digits (significant digits) has been entered, and is used for subsequent correct/incorrect judgment processing. be done. Next, the function of the answer key will be explained. The answer key in the device of the present invention has two functions: a function of comparing the correct answer value with the input answer, and a function of calling up the correct answer value. These distinctions are made by the storage states of flag registers _F62 and _F64 , and the details will be explained below with reference to the operational diagram of FIG. 16. First, when the answer key is pressed, it is determined whether the content of _F62 is "0", and if a numeric key was pressed and _F62 was set before the answer key was pressed, _F62 is set. reset and then
Let's move on to determining the F ₇₁ flag. As mentioned above (explanation of Figure 15), the F ₇₁ flag is a flag that is set when a numerical value of 6 or more digits is entered, and if F ₇₁ is set, it is determined that the input answer is incorrect. After storing code 1 for displaying the incorrect mark "x" in _A9 , setting flags _F64 and _F72 , and resetting _F71 , the program moves to the display routine, and the most significant digit of the upper row of the display section is “×” signal lights up. If the flag _F71 is in the reset state, the next memory area _B0-5 where the answer input by the user is stored and the memory area where the correct answer value is stored.
The contents of G _{0 to G 5} are compared and verified, and if they do not match, the routine shifts to the aforementioned 1→A ₉ and F ₆₄ and F ₇₂ set routines. Also, if the comparison result matches
After determining the _F72 flag and adding “1” to the correct answer number storage registers F8 to _F10 if _F72 has been reset, code 6 is used to display the correct answer symbol “○”.
is stored in _A9 , and the process moves to the correct answer blinking display routine. Also, if F ₇₂ is in the set state, it is determined that the correct answer has been input after a mistake has been displayed once, and the code 6 is directly stored in A ₉ and blinks without executing the operation of counting the number of correct answers "F _{8 ~ 10} + 1". Move to display routine. On the other hand, if you press the answer key and after the verification results in an incorrect display and F ₆₄ is set, if you press the answer key again, the correct answer will be determined by the determination of the reset state of F ₆₂ and the determination of the set state of F ₆₄ . The contents of memory areas G _{0 to 5} that store , are transferred to memory areas B _{0 to 5} , and the correct values are displayed. Next, a preprocessing operation for displaying the remainder when the practice problem is division will be explained. In the device of the present invention, the quotient and remainder in division are displayed simultaneously, and the boundary between the quotient and remainder is separated by a blank or a special symbol. Assuming that the integer answer to the current division problem is stored in G _{0 to} 5 and the remainder is stored in E _{0 to} 2, we will explain the preprocessing operation for displaying the quotient and remainder with reference to the operation explanatory diagram in Figure 17. . The integer answer (quotient) is stored in G0 to _G5 with the most significant digit located in _G5 , as described above. That is, the answer (Ans) calculated inside the integrated circuit device (LSI) 21 is shifted to the left until the numerical value reaches the most significant digit of the memory areas _{G0 to G5} , and a blank signal 15 is input to the least significant digit. After determining that a numerical value has arrived at _G5 , the contents of memory _F5 are determined, and it is determined whether the selected difficulty level is level 6 or not.
The difficulty level of division is 1st grade (2 digits ÷ 1 digit), 2nd grade (2 digits ÷ 1 digit), 3rd grade (3rd grade ÷ 1 digit), 4th grade (3 digits ÷ 2
digits), 5th grade (4 digits ÷ 2 digits), and 6th grade (4 digits ÷ 3 digits). When calculating for 5th grade, the integer answer is a maximum of 3 digits, the remainder is a maximum of 2 digits, and 6 When calculating classes, integer answers have a maximum of 2 digits and remainders have a maximum of 3 digits. Therefore, when displaying these contents within 6 digits, the remainder should be displayed in the order of 1 from the bottom for grade 5.
For the 6th grade, the 1st to 3rd digit from the bottom
Must be displayed in the digit. Therefore, in the device of the present invention, by changing the display position of the remainder for 6th grade and for other times, 6
The quotient and remainder can be displayed in digits. The specific process is to first judge the contents of memory F ₅ to determine whether the difficulty _level is level ₆ or _not . 0"
From the time when it is not "0", the contents of E ₂ to _{E 0} are transferred to G ₀ to 2 in order from G ₂ , and if it is other than grade 6, it is transferred in the order of E ₁ and E ₀ . Determine whether the memory content is “0” or not, and from the point where it is not “0”
Transfer the contents from G ₁ to G 0 to ₁ in order, and transfer the contents to memory G _{0 to 5} .
The quotient and remainder are stored adjacently via a blank digit. Therefore, as mentioned above, when the correct answer value is displayed by operating the answer key twice in succession, the contents of G _{0 to 5} are transferred to B _{0 to 5} , and the quotient and remainder are displayed on the display. . For example, difficulty level 3
In the calculation of 9876÷5, the quotient 1975 and the remainder 1 are displayed in a line with blank digits in between, as shown in Figure 18. Note that a special symbol other than a numerical value may be displayed in the blank digit separating the quotient and remainder. Next, the function of the Redo key will be explained. The redo key in the device of the present invention has a function of correcting the entered numeric value operation, for example, by leading in a numeric value, even if the number is 6 digits or more and the _F71 flag is set, the redo key can be operated next time. If F ₇₁ is reset and returns to its original state, it will lead in the numerical value again, and if the numerical value is the correct value, the correct answer will be displayed (○ symbol display) by the subsequent operation of the answer key, and the number of correct answers will be retained. A function to add "1" to the contents of a register, a function to clear the "x" display that indicates the answer and error by operating it when redoing a calculation, for example, by leading in a numerical value,
F ₇₁ is set when the number is lead-in by 6 digits or more, then operate the answer key, and after the incorrect display (x display) operates the redo key to clear the answer display, continue. It has a function that leads in the correct answer value and does not count it as the number of correct answers even if the answer key is operated and the correct answer is displayed (○ display). This operation will be explained with reference to the operation explanatory diagram of FIG. 19. Now, by leading in a numerical value, flag _F62 is set as shown in FIG. 15, and if a numerical value of 6 or more digits is further led in, flag _F71 is set. If you press the Redo key at this point,
The set state of _F62 is determined, _F71 is reset, blank signal 15 is input to display registers _B0-5 , and _F62 is reset. After that, a numerical value is read in, and if the value is the correct value, the answer keys are operated to set _F62 in the set state, _F71 in the reset state, and B0 _{to B0} , as explained in FIG. ₅ , the matching state of G _{0 to 5} , and the reset state of F ₇₂ are determined, and the number of correct answers is saved in the register.
“1” is added to _F8-10 . On the other hand, if you enter a numerical value of 6 digits or more, or if you press the answer key after entering an incorrect answer, an incorrect answer will be displayed as described above (1 → A ₉ ).
Then, F ₆₄ and F ₇₂ are set, and F ₆₂ and F ₇₁ are reset. Next, when the redo key is pressed, the reset state of _F62 is determined, and blank signal 15 is input to answer display registers B0 to _B5 , and _F62 is reset, but _F72 and _F64 remain set. There is even. Therefore, the following numerical values are lead-in,
If that value is the correct value, the following answer key operation will determine the set state of F ₇₂ , and memory F _{8 to 10 will} be set.
is not counted up and shifts to the correct answer display operation of the ○ symbol. Next, the blinking display routine after operating the answer key will be explained. In the device of the present invention, whether or not the entered answer is correct is notified by blinking all the digits on the display.The detailed operation is shown in FIG. 20. This will be explained with figures. When moving to the blinking display routine, first the memory area is
C _0~15 and B _14~15 are cleared, then 13 to B ₁₅
(1101) is subjected to binary addition, and the result is stored in the accumulator AC in the arithmetic control unit 50, and the occurrence of carry is determined. Since no carry has occurred at this time, the process moves to the next step of adding "1" in binary to _B14 . In this case as well, since no carry occurs, the program moves to the display lighting routine, and in the display lighting routine, the contents of memories A _{0 to 9} and B _{0 to 9} are dynamically updated for one period (one period of timing signal R ₁₄ or R ₁₅ ). ) is displayed, and the process of adding 13 in binary to B ₁₅ again occurs, and this operation is repeated. At the 16th time of this repeated operation, set “1” to B ₁₄ by 2.
Carry occurrence is determined in the process of addition.
We will add 1 to B ₁₅ in binary. Further, when this repetitive operation is performed 32 times, the content of _B15 becomes 3, a carry occurs in the process of adding "13" in binary to _B15 , and the process changes to the process of adding "13" in binary to accumulator AC. At this time, the content of AC is “0”
Therefore, when adding "13", no carry occurs and the process moves to adding "1" in binary to _B14 . At this time, the content of _B14 becomes "1" and no carry occurs. Therefore, the process proceeds to the step of adding "1" to the memory _C0 . Since no carrier is generated at this time, the process moves to the display light-off routine, the display is turned off for the same time as the display light-on routine, and the process moves to the process of adding "13" to _B15 again. At this time, since the previous content "3" of _B15 has not changed, a carry occurs again, and the operation shifts to adding "1" in binary to _B14 again. This operation is repeated, and on the 16th time, a carry occurs in the process of adding "1" to B ₁₄ in binary,
Add 1 in binary to the contents of _B15 , and at this time the contents of _B15 become "4". Furthermore, if this repetitive operation is executed 32 times, a carry occurs when "13" is added in binary to B ₁₅ , and the accumulator AC becomes 3.
Therefore, a carry occurs when "13" is added in binary to the accumulator AC,
_B15 is reset to "0" and the display lighting routine is started again. By repeating the above display lighting routine and display lighting off routine once, the memory C ₁ becomes 3, and by repeating this lighting/extinguishing cycle three times, the content of C ₁ becomes "9". Therefore, when C ₁ becomes 10 in the fourth blinking routine, a carry occurs because 6 is added to C ₁ in binary, and the blinking display routine ends with the judgment of this carry, and the next problem number matching routine to move to. As a result of the above operations, the display area may change to 0.4, for example.
It flashes three times at intervals of seconds to notify the practitioner that the answer entered is correct. In this case, an alarm may be emitted. The number of questions matching routine compares the number of questions set in advance and the number of questions that have occurred up to now, and if they are different, moves the random numbers stored in memory H _{0 to 7} to calculation registers C _{0 to 9} and uses the next one. Shift to the problem creation routine (Figure 12*2). If the set number of questions matches the current number of questions, the process moves to the end routine (end of FIG. 21). In addition, the judgment of F ₆₃ is that the correct answer blinking display is made during practice, and the stop key is operated when a new problem occurs first, and after the blinking display routine is activated when all the questions are answered correctly, the correct answer blinking display is made. This is to make a decision to display and proceed to the display routine to continue learning. Next, a routine for displaying the number of questions, the number of points, the number of correct answers, and the practice number on both ends of the display section will be explained. The device of the present invention is configured to display the current score and number of correct answers together with the number of questions and the practice number at the end of an exercise or when the stop key is operated.
This will be explained with reference to the operation explanatory diagram in the figure. The state of the registers when the device is currently experiencing a problem is, for example, memory A ₅ to _{A 3} [3C4] (C indicates code 12 indicating multiplication), B ₆ [=], B ₉ to B ₈
[11], F ₈ [8], F ₇

[0], G ₉ ~ _{G 8} [11], H ₁₅ ~ _{H 12}
[123F], H ₉ to _{H 8} [25]. (However, F indicates a blank code 1111.) If the stop key is operated in this state, problem generation ends and the number of problems, score, number of correct answers, and practice number are displayed.This process will be explained below. First, the contents of flag _F72 are determined. This judgment is made when a certain question occurs, and when you input the answer and press the answer key, if the answer is correct, it will automatically flash to notify you of the correct answer, and then the next question will occur and the device will stop working. It is in the state of waiting for input, and if the answer is wrong, it stops at that problem and the next problem does not occur. Therefore, when operating the stop key, if after an incorrect answer, the number of questions currently displayed indicates the number of questions that have already been executed, but if after a correct answer, the number of questions currently displayed The number of questions is one more than the number of executed questions. this state
Judging by the state of F ₇₂ , if F ₇₂ is set, proceed to the next step, if F ₇₂ is reset, G _8~9
The numerical value "1" is subtracted from this, and the contents of memories _G8-9 become "10" from "11". In the next step, memories C _{0 to 15} and D _{0 to 15} are cleared and memory
A blank signal 15 (1111) is input to A _{0 to 9} and B _{0 to 9} . In the next step 1, the contents of the registers _F8-10 for storing the number of correct answers are transferred to _B0-2 , and the number of correct answers is transferred to _C2-4 as pre-processing for calculating the score. In this explanatory example, the correct number is a single digit "8", so this numerical value is stored in B ₀ and C ₂ . Next, in step 2, the contents of the question number storage registers _G8-10 are transferred to _B8-10 , and also transferred to _D0-2 in preparation for calculating scores. In this explanatory example, the number of questions is 2 digits "10", so the numbers are B _{8 to 9} and
Moved to D _0-1 . Next, the program moves to step 3, and the contents of practice number storage registers _H12-15 are transferred to _A5-8 . Next, move on to step 4 and calculate the score.
C _2-4 /D _0-2 ×100 is executed and the result is found in E _0-2 . In this example, there are 10 questions and 8 correct answers.
Therefore, the number 80 is stored in E _0-1 . Next, the process moves to step 5, and the contents of _E0-2 are transferred to _A0-2 .
In this example, the score is 80 points, which is two digits, so
After being moved to the positions A _{0 to 1} , the next display routine is started, and the practice number, number of questions, score, and number of correct answers are displayed on both ends of the display, respectively, as shown in Figure 22. 10,” “80,” and “8” are displayed. Furthermore, when all the questions asked are correct and the score is 100 points, a transition is made to a blinking display routine based on the determination that E ₂ =1, and the score, etc. is displayed blinking. In the two-stage display section as described above,
The number of questions, score, number of correct answers, and practice number are displayed at the same time. According to the present invention, a user can arbitrarily change the difficulty level of a calculation problem from a simple problem with a small number of digits to an advanced problem with a large number of digits by setting the number of operations and the number of digits of the operand. This allows students to practice calculations with problems that are appropriate for their learning level. In addition, before the actual calculation problem is displayed, a temporary calculation problem is displayed in which the number of digits of the operand and operand are displayed symbolically based on the number of digits of the problem and the four arithmetic types. After viewing this display and confirming their own setting input, the user can begin practicing calculations. This allows the user to check for erroneous input of setting items or change the problem before the actual calculation problem is created, and allows the user to learn with efficient operations.

[Brief explanation of the drawing]

Fig. 1 is an external view of the device of the present invention, Fig. 2 is an electric circuit diagram of the device, Fig. 3 is a plan view showing the display section of the device, Fig. 4 is a timing signal waveform diagram, and Fig. 5 is a diagram of the timing signal waveform.
Block configuration diagram inside the LSI device, Figures 6 to 8
The figure is a configuration diagram of the random access memory in the LSI device, FIGS. Figure, Figure 11, Figure 14, Figure 18
22 and 22 are diagrams each showing the display state of the display unit. 1...Main body, 2...Display section, key input section 6, 2
1... Integrated circuit device (LSI), 50... Arithmetic control unit.

Claims (1)

[Scope of Claims] 1. Problem setting means for setting the type of the four arithmetic calculation problems, the number of operands, and the number of digits of the number of operations, and the four arithmetic calculation problems according to the number of digits and the type of the four arithmetic rules set by the problem setting means. an electronic calculation practice machine comprising: calculation problem creation means for automatically generating calculation problems to create calculation problems; display means for displaying the created calculation problems; Means is provided for creating a temporary calculation problem in which the number of digits of the number of operations and the number of digits of the number of operands are symbolically displayed based on the type of the four arithmetic and the number of digits of the number of operations and number of operands, and outputting it to the display means; After the provisional calculation problem is displayed on the display means, the calculation problem creation means, when an instruction to start problem creation is given, calculates the calculation problem according to the set number of operands, the number of digits of the operand, and the type of the four arithmetic rules. An electronic calculation practice machine that is characterized by creating calculation problems using the following methods.