EP2382433B1 - Tunnel dryer for construction products such as bricks or tiles - Google Patents

Description

Field of the Invention

• la chaîne passant d'un trajet horizontal à un trajet vertical (ou inversement) à la jonction d'un tunnel ou d'un puits par un renvoi d'angle,
• les nacelles étant séparées de l'intervalle minimum nécessaire pour éviter la collision de deux nacelles successives à la jonction du trajet horizontal et du trajet vertical (ou inversement),
• la chaîne passant sur une poulie à chaque jonction,
• les nacelles ont globalement une section rectangulaire avec un point de fixation à la chaîne au milieu de leur largeur.

The present invention relates to a tunnel dryer for building products such as bricks or tiles comprising a lower tunnel and an upper tunnel, connected at each end by a well, forming a circulation path constituted by the succession of the lower tunnel, a well, the upper tunnel and a well, this loop path being traversed by a chain conveyor to which are suspended pods receiving products to dry,

• the chain passing from a horizontal path to a vertical path (or vice versa) at the junction of a tunnel or a well by an angle gear,
• the nacelles being separated from the minimum interval necessary to avoid the collision of two successive nacelles at the junction of the horizontal path and the vertical path (or vice versa),
• the chain passing on a pulley at each junction,
• the nacelles generally have a rectangular section with a point of attachment to the chain in the middle of their width.

State of the art

Such tunnel dryers (s) composed in fact of two superimposed tunnels, are known and used in the manufacture of construction products such as bricks or tiles.

These tunnels have a production capacity depending on the number of places available in the nacelle inside the tunnels for the products to be dried. This means that for the same length of tunnel, the capacity is limited by the number of nacelles that can equip the conveyor chain. However, the nacelles must respect a given interval between two successive nacelles so that, at the level of the corner references constituted by a pulley, between the exit (or the entry) of a tunnel and the well of descent / rise, two successive nacelles do not collide.

A tunnel dryer comprising the features of the preamble of claim 1 is disclosed in the document FR 2517417 ,

Purpose of the invention

The present invention aims to develop a tunnel dryer with a larger production capacity for otherwise identical dimensions or allowing a reduction of the dimensions of the dryer for the same capacity as that of known facilities.

The invention also proposes to create means for improving the capacity of existing dryers.

Description and advantages of the invention

To this end, the present invention relates to a tunnel dryer of the type defined above characterized in that at each corner of the rectangular path, at the well, the return pulley at the end of the horizontal path is complemented by a deflection pulley installed in the well so that the chain passing around the deflection pulley and the diverting pulley follows an inclined path substantially corresponding to the hypotenuse of the triangle constituted by the rectangle whose vertical side is equal to the height of the nacelle to its point of suspension to the chain and the horizontal side is equal to the half-width of the nacelle.

The dryer according to the invention allows a very significant increase in capacity of the order of 15 or even 25% by better occupation of the chain with closer nacelles without creating risk of collision of two successive nacelles at the level of a bevel gear.

Such an increase in production capacity is also possible by transforming existing tunnel dryers by simply modifying the return pulleys at the inlet or the outlet at both ends of each of the tunnels. This transformation, resulting in only comparatively small investments compared to those of the entire installation, allows an unexpected increase in the plant's production capacity which, as indicated above, will be increased by 15%. at 25% or more.

According to another advantageous characteristic, the nacelle comprises a single solid partition to close the airlock of a well connecting the two tunnels.

This solution simplifies the implementation of the installation because the nacelles do not necessarily have an upper bulkhead and a lower bulkhead to achieve the airlock.

Indeed, thanks to the important approximation of nacelles made possible by the invention, the airlock can be closed at the top and bottom only by the presence of a low or high full partition of two successive nacelles since they are sufficiently close together to ensure this seal.

This simplifies the realization of the nacelles, lightens each nacelle and consequently reduces the cost of installation and its cost of operation by reducing the dead weight transported.

According to another advantageous characteristic, the deflection pulley and the deflection pulley are completed by an auxiliary pulley, creating an outward deflection of the chain circulation path which would pass only on the return pulleys and the deflection pulleys. , to sufficiently separate the deflection pulleys from the well to create an airlock closed by one or two successive nacelles.

This solution makes it possible to transform the existing driers and whose height between the lower tunnel and the upper tunnel would not be sufficient so that, once equipped with the corner-bearings according to the invention, there remains a sufficient height at the level of the well. ascent, in the exit station to realize the airlock.

The invention also relates to a dryer comprising, for one of the tunnels, at the junction of the wells, a return pulley and a deflection pulley and, for the other tunnel, at each end, a return pulley combined with a deflection pulley and supplemented by an auxiliary pulley creating the outward deviation of the chain circulation path.

The invention, in its various characteristics, allows not only the realization and the first installation of tunnel dryers with reduced space between the nacelles but also the transformation of existing tunnel dryers to seriously increase the production capacity.

drawings

The present invention will be described in more detail with the aid of the accompanying drawings showing two embodiments of a tunnel dryer according to the invention as well as an embodiment of a tunnel known to allow comparisons.

• la figure 1 est une vue en coupe verticale schématique d'un séchoir à tunnel selon l'état de la technique,
• la figure 2 montre, de façon schématique, dans ses parties A et B respectivement,
  • * à la figure 2A, la jonction d'un tunnel et d'un puits à une extrémité quelconque d'un tunnel du séchoir de la figure 1,
  • * à la figure 2B, un schéma analogue à celui de la figure 2A de la jonction entre un tunnel et un puits d'un séchoir selon l'invention,
• la figure 3 est une coupe verticale schématique d'un séchoir à tunnel selon un premier mode de réalisation de l'invention,
• la figure 4 est une vue en coupe verticale schématique d'un séchoir à tunnel selon un second mode de réalisation de l'invention, adaptable aux séchoirs existants,
• la figure 5 montre de manière schématique la combinaison des deux solutions des figures 3 et 4,
• la figure 6 est une vue schématique de la jonction d'un tunnel et d'un puits, permettant le calcul de la distance minimale entre deux nacelles de l'installation connue de la figure 1,
• la figure 7 est un schéma de la jonction d'un tunnel et d'un puits du séchoir à tunnel de la figure 3, permettant le calcul de la distance minimale entre deux nacelles,
• la figure 8 est un schéma analogue à celui de la figure 7 se rapportant à la jonction d'un tunnel et d'un puits du séchoir à tunnel de la figure 4 permettant le calcul de la distance minimale entre deux nacelles.

In the drawings:

• the figure 1 is a schematic vertical sectional view of a tunnel dryer according to the state of the art,
• the figure 2 shows, schematically, in parts A and B respectively,
  • * to the Figure 2A , the junction of a tunnel and a well at any end of a tunnel of the dryer of the figure 1 ,
  • * to the Figure 2B , a scheme similar to that of the Figure 2A the junction between a tunnel and a well of a dryer according to the invention,
• the figure 3 is a schematic vertical section of a tunnel dryer according to a first embodiment of the invention,
• the figure 4 is a schematic vertical sectional view of a tunnel dryer according to a second embodiment of the invention, adaptable to existing dryers,
• the figure 5 schematically shows the combination of the two solutions of the figures 3 and 4 ,
• the figure 6 is a schematic view of the junction of a tunnel and a well, allowing the calculation of the minimum distance between two nacelles of the known installation of the figure 1 ,
• the figure 7 is a diagram of the junction of a tunnel and a tunnel dryer well of the figure 3 , allowing the calculation of the minimum distance between two nacelles,
• the figure 8 is a diagram similar to that of the figure 7 relating to the junction of a tunnel and a tunnel dryer shaft of the figure 4 allowing the calculation of the minimum distance between two nacelles.

Description of Embodiments of the Invention

Before describing the three embodiments of the invention, by way of comparison reference, a tunnel dryer (s) according to the state of the art will be described below in its general structure and for the principle of junction of a tunnel and a well ( Figure 2A ).

According to figure 1 , a tunnel dryer (s) 1 for drying construction products such as bricks or tiles consists of two horizontal tunnels, a lower tunnel and an upper tunnel, opening at each of their two ends 11, 12; 21, 22 in a vertical shaft 30, 40. The tunnels 10, 20 and the wells 30, 40 are traversed by a chain conveyor 50 passing over four return pulleys 51, 52, 53, 54 at each junction between a tunnel 10 , And a well 30, 40, both at the descent into the well and at the bottom end of the well as well as up a well to the entrance in the upper tunnel 20.

The chain conveyor or to simplify the chain 50, is equipped with nacelles 55 or swing in which one loads the products to be dried. These nacelles 55 are spaced a minimum distance (d) so as to make the best use of the space available in the dryer (1) to optimize the efficiency. The distance (d, d1) separating two nacelles 55 or their attachment points 56 to the chain 50 is limited to a minimum of because of the problem of collision between two successive nacelles at the junction of a tunnel and a well, when the nacelle 55 upstream, down in the well and the downstream nacelle comes from the tunnel, which is also true for a traffic in opposite.

This collision problem will be treated schematically using the Figure 2A .

The loading / unloading of the nacelles is done in one of the wells 40 equipped with a loading / unloading station 60.

The loading station 60 comprises, in the passage 61 followed by the nacelles 55, a double opening 62, 63 on either side, to access both sides of a nacelle stopped in this position.

The loading / unloading of the products are two operations that are done almost simultaneously. The loading device, not shown, pushes the products placed on a floor of the nacelle through for example the opening 62 and at the same time, deposits green products, that is to say products to be dried, in through the opening 63. This nacelle loading technique, known per se, does not require a more detailed description.

It should be noted that at the loading / unloading station, the nacelles provide a certain degree of tightness in order to prevent excessive outside air being sucked in by the vacuum cleaner 74 of the chimney 75.

Although for reasons of simplification, the description refers to a chain 50 driving the pods 55, this chain is actually doubled and the pods 55 are attached to the parallel chains 50 which follow the path described above. The chains 50 pass on the return pulleys 51-54 which may be toothed pulleys or chain wheels, at least some of which drive the chains. In the example shown, the pulley 54 is a driving pulley.

The nacelles 55 are attached to the chains 50 in the upper part substantially in their middle 56 for reasons of balance and in practice, the attachment points are located slightly below the top of the nacelle.

The sides of the nacelles are equipped with unrepresented rollers which circulate in lateral rails to the passage of the nacelles in the lower tunnel 10 and in the upper tunnel 20. On the other hand, in the descent and rise well 30, 40, the nacelles 55 are only hanging on the chains 50.

The dryer 1 whose structure is described above, is traversed by the boats 55 which circulate in a certain direction (arrow F) and by hot drying gases circulating against the current (arrow G). Hot gases are provided by equipment 70 consisting of burners and fans that blow hot gases into the lower tunnel 10 near its exit. The hot gases pass through the lower tunnel 10 to exit through a bypass 71 equipped with a vacuum cleaner 72 and bypassing the vertical descent shaft 30 to be injected again in the upper part of the well at the upper tunnel 20 in which the gases also flow against the current.

The hot gases circulating in the upper tunnel 20 can be partly recovered at point 73, near the entrance 21 of the tunnel to be recycled through the equipment generating the hot air 70. But the main part of the hot gases, charged humidity, is evacuated by the chimney 75 equipped with a vacuum cleaner 74.

The branch 71 is equipped with a fan 72 so as to blow the hot gases coming from the lower tunnel 10 into the outlet 22 of the upper tunnel 20. But to prevent the hot gases thus blown into the upper tunnel 20 from attempting to pass through the well 30 to circulate in a loop, the well comprises an airlock 31 closed by the nacelles 55.

This airlock 31 is formed by a cylinder 32 of rectangular section corresponding to the section of the nacelle 55 (width and depth, the depth is the dimension of the nacelle perpendicular to the plane of the figure 1 ). This cylinder 32 is closed on the sides. Its height is such that at least the bottom wall 551 of a nacelle and the upper wall 55S of the following nacelle are in the cylinder 32, in the closed parts around the entire periphery.

To form the cap defining the lock 31, each known nacelle has an upper wall 55S and a lower wall 551 constituted by a solid plate so that whatever the movement of the nacelles 55 in the cylinder 32, there will always be an upper wall 55S and a lower wall 551 belonging to the same nacelle or two successive nacelles, which will plug this cylinder 32.

The Figure 2A schematically shows the operation of the conveyor 50 carrying the n boats, at the junction between a horizontal tunnel 10, 20 and a vertical shaft 30, 40 for example the upper left corner of the installation of the figure 1 . To facilitate the presentation of the state of the art and its comparison with the invention, it will be assumed that the return pulley 51-54 has a zero diameter; it is represented by the point T2.

As indicated, the efficiency of the tunnel dryer 1 depending inter alia on the speed of circulation of the pods 55 in the tunnels and also the interval between two pods 55, we must bring the pods (or swing) as much as possible while avoiding the collision between two successive nacelles at the level of a reference angle between the horizontal direction and the vertical direction as presented to the Figure 2A . To simplify the presentation, specific references to the Figure 2A (or then the Figure 2B ) were used; thus the nacelle carries the reference N.

The path of the conveyor chain 50 driving the nacelles N is represented by the path T0, T1, T2, T3, T4 corresponding to the characteristic points of the path. By hypothesis, the horizontal path T0, T1, T2 joins the vertical path T2, T3, T4 of the chain at the pulley T2 which is of zero radius in this example of principle.

The nacelle N has a rectangular shape of vertices A, B, C, D; it is attached to the middle M of its upper side AB to the chain 50. The width of the nacelle N corresponds to the side AB and its height, the BC side. Half width is AM or MB.

The diagram shows the three characteristic positions N1, N2, N3 of a n-boat respectively upstream of the angle gear, in the angle gear and downstream thereof. These three positions are joined and highlight the problem of collision at the passage of the PC contact point.

The first position N1 of the nacelle is that of the end of its horizontal path in the tunnel, when the nacelle begins to penetrate into the vertical well continuing to flow in the horizontal direction to its position N2. The position N1 of the nacelle is defined by the points A1, B1, C1, D1 of the vertices.

The second position shown N2 is that of the point of attachment (M2) arrived on the pulley T2. The position of the tops of the nacelle are references A2, B2, C2, D2.

In the case of a pulley of non-zero radius, the pulley will be schematically tangential to the two segments T1 , T2 and T2 , T3 .

The positions N1 and N2 are joined so that the distance T1T2 is equal to the half-width of a nacelle.

The third important position in this context is the position N3 of the nacelle lowered from its position N2 of a nacelle height. In this position N3, the vertices bear the references A3, B3, C3, D3.

For two successive nacelles occupying the positions N1, N3 do not collide, it is necessary that if one of the nacelles occupies the position N1, the gondola which precedes occupies at least the position N3. If it occupies an intermediate position N2-3 between the positions N2 and N3, its vertex B3 will hinder the arrival of the summit D1 of the nacelle N1 in the zone represented by the rectangle A2, B2, C2, D2 which corresponds to the change of direction .

Conversely, if the nacelle were located lower than the N3 position, the interval between the attachment points of two successive nacelles would be unnecessarily increased.

In summary, the minimum possible distance separating the attachment points M of two successive nacelles is the length of the chain between the points M1 and M3, that is to say the distance M1, T2, T3, M3. Like the segment (M1T1) is half the width AB of a nacelle and that distance is equal to the distance (T1T2) , the minimum interval separating two nacelles in the known installation is equal to the sum of the width of the nacelle and its height.

This theoretical minimum distance does not take into account the radius of the pulley T2 and a precautionary interval which is reserved between two nacelles.

The precise calculation of this distance will be done using the diagram of the figure 5 .

The Figure 2B , positioned in relation to the Figure 2A shows the path of the chain at an angle gear according to the invention. The trajectory of the chain conveyor 50 is defined by the points T0, T1, T5, T6 and the characteristic positions of nacelles N11, N3, N4 as well as an intermediate position N 11-3 between the positions N11, N3.

The vertices A, B, C, D of the nacelle are not all referenced in the different positions to avoid cluttering the drawing.

The path of the conveyor T0, T1, T5, T6 according to the invention differs from the path T0, T1, T2, T3, T4 of the known installation according to the Figure 2A in that the path portion T1, T2, T3 is replaced by the diagonal T1, T5 which makes it possible to reduce the minimum spacing between two successive nacelles to avoid their collision at the PC angle feed.

The return pulley T2, known, is replaced by a return pulley installed at the point T1 and is completed by a deflection pulley installed at point T5. The two pulleys are of zero diameter in this example also for simplicity bear each time the reference points T1, T5.

The two characteristic positions around the point of contact PC, identical to that of the Figure 2A since the tunnel 10, 20 and the well 30, 40 are unchanged, allow to calculate the minimum chain length between two closest successive nacelles. The chain length between snap points M11 and M3 is equal to the sum of the diagonal T1T5 and the segment T1T11 .

The intermediate position N 11-3 is shown to show the bias displacement of the nacelle between the two characteristic positions N11 and N3.

The position N4 shows the nacelle which precedes the nacelle at the position N3, at the minimum distance defined according to the invention.

The comparison of Figures 2A, 2B linked by the return lines shows that the spacing gain between the fixing points M of the two successive nacelles is equal to the difference between the sum of the length of the diagonal T1-T5 (which is the diagonal of a half nacelle) and the sum of the width and the height of the nacelle this corresponds to the difference between, on the one hand, the sum of the height BC and ½ AB and, on the other hand, the hypotenuse of this right triangle. For this tracing of the chain 50 of the conveyor, there can not be a collision since the point of contact PC is bypassed.

Thus, in summary, the theoretical minimum distance between the attachment points of two successive nacelles is equal to the sum of the width of the half-nacelle and the length of the diagonal of a half-nacelle.

A simple numerical calculation (right triangle "2-3-4") shows that reducing the interval between successive nacelles can represent a gain of the order of 30 or even 40%, which is considerable.

In practice, this distance also takes into account the diameter of the pulleys T1, T5 and the guard distance that is to be added as a precautionary measure.

The figure 3 shows a tunnel dryer (s) 100 according to the invention in which the angle references 151-154 are made according to the principle presented in FIG. Figure 2B . This dryer 100 consists of two parallel tunnels, a lower tunnel 110 and an upper tunnel 120, open at both ends to open into connecting wells 130, 140. The circuit formed by the two tunnels 110, 120 and the two wells link 130, 140 is traversed by an endless conveyor 150 formed of two chains carrying nacelles or swing 155 in which the products to be dried are loaded. These nacelles 155 are laterally provided with rollers so as to roll in lateral rails inside the two tunnels whereas at the level of the wells in their downward or upward movement, the nacelles are suspended freely in the chain. These particular means are not represented.

The tunnel dryer 100 is traversed countercurrently by a hot air stream (arrow G) supplied by a hot air generator 170 provided with heating and driving means such as fans, not detailed, opening into the lower tunnel 110 near its exit to circumvent the descent well 130 of the nacelles by a bypass 171 provided with a vacuum cleaner or fan 172 to open into the upper tunnel 120, still against the current of the nacelles 155. Near the end by which the upper tunnel 120 opens into the mounting shaft 140, the hot gases are sucked by the vacuum cleaner 173 which discharges the main part of the hot gases loaded with moisture in the chimney 174. A fraction of the hot gases is taken near the exit of the tunnel 120 by the heating and circulating hot gas system 170 to be reinjected into the lower tunnel 110.

In this installation, the entry and exit of the products for the nacelles are at the loading / unloading station 160 integrated into the hoistway 140. The station comprises a passage through which the nacelles 155 with a double opening 162, 163 on both sides, to access both sides of a nacelle stopped in this opening for loading and unloading. These operations can be done simultaneously: the unloading through the opening 162 and the loading through the opening 163 with non-detailed means.

It is interesting to note that, moreover, this invention makes it possible to increase the free space between the upper and lower tunnels, thus offering the possibility, if necessary, of installing a loading station separate from the unloading (for example for special products or for high rates of handling).

The nacelles provide a certain seal at the loading / unloading station 160 vis-à-vis the depression created in the top of the well 140 by the vacuum cleaner 173.

In the well 130, between the deflection pulley 151B and the deflection pulley 152B, there is an airlock 131 formed by a cylinder constituting with the successive nacelles, a stopper preventing the passage of hot gases. As the distance W between the return pulleys 151B, 152B makes it possible to give the cylinder a sufficient length, there will always be two homologous parts 155i of two successive nacelles 155 inside the cylinder so as to form a stopper avoiding the passage hot gases forming the airlock 131 by cooperation with the bottom wall 155I full of each nacelle 155.

The pods 155 are sufficiently close to one another so that the cylinder can register in the height separating the top of the lower tunnel 110 and the bottom of the upper tunnel 120.

The four angle references 151-154 at the entrance and exit of the upper tunnel 120 and that of the lower tunnel 110 communicating with the two wells 130, 140, are produced according to the invention as shown schematically in FIG. Figure 2B . The chain (or pair of chains) 150 passes over a return pulley 151A-154A and a deflection pulley 151B-154B so as to tilt the path traveled by the chain 150 as has been described and shown with respect to the Figure 2B .

The nacelles or swings 155 are at the minimum distance defined above by means of the deflection pulleys 151B-154B provided at each angle gear 151-154.

The figure 3 also shows that it is in principle indifferent that the pods 155 flow from the right to the left in the upper tunnel or from left to right (arrow F), the operation of the angle references 151-154 according to the invention being necessary both for the connection of the upper tunnel 120 with the descent well 130 with the upwell 140 and vice versa for the lower tunnel 110 with the upwell 140 and the descent well 130. In this installation, one of the return pulleys is the driving part, for example the pulley 154A.

The tunnel dryer 100 shown in FIG. figure 3 comprises a lower tunnel 110 buried so that the loading / unloading station 160 of the products is at a height easily accessible to the handling equipment. The upper tunnel 120 is carried by a non-detailed frame. The burial of the lower tunnel 110 is also interesting for thermal insulation problems since the lower tunnel is the hottest part of the installation.

The invention relates not only to the design and construction of a tunnel dryer but also to the transformation of existing tunnel dryers.

Thus, to transform the existing dryers, it is enough to renew the wells at the entrance and exit and change the chains to ensure the hooking of the swings to the new attachment points without intervention on horizontal traffic.

The figure 4 shows another variant of kiln 200 of the invention which differs from the tunnel dryer of the figure 3 in that it concerns the transformation of existing tunnel dryers, the difference in height H between the lower tunnel 210 and the upper tunnel 220 is not sufficient to allow the installation of the deflection pulleys and to respect the minimum distance W between the two deflection pulleys 251B, 252B or 253B254B in the wells 230, 240, especially in the well 230 to realize the airlock avoiding the short-circuit by the hot gases between the upper tunnel 220 and the lower tunnel 210. For this , the two ends of the lower tunnel 210 and the upper tunnel 220 are transformed to allow to receive a deflection pulley 251B-254B by lowering or very locally raising the path of the chain 250 of the nacelles 255 just upstream (downstream) of the pulley 251A-254A.

For this purpose, in the four angle references 251-254, the return pulley 251A-254A and the deflection pulley 251B-254B are combined with an auxiliary pulley 251C-254C which gives the path followed by the chain 250 between the pulley and deflection pulley, an excursion outward, that is, down or up following the corner of the dryer.

Thus, the pairs of pulleys formed each time of a deflection pulley 251A-254A and a deflection pulley 251B-254B, are shifted out of the way that would follow the chain 250 if it passed over the return pulleys , usual so as to respect the minimum distance W.

It is thus possible to form an airlock 231 between the two deflection pulleys 251B, 252B by a cylinder 232 of section corresponding to the horizontal section of the nacelles 255 so that when passing through the cylinder, the nacelles form a plug. In addition, as the nacelles are very close together thanks to the provisions of the invention, it is sufficient that the nacelles 255 comprise a solid bottom as already indicated, consisting of a solid sheet, to automatically form a plug in the cylinder 232.

As in the previous installation, the hot gases flow in the direction of the arrow G. The hot gases are introduced near the outlet in the lower tunnel 210 to exit and take a bypass bypassing the airlock from outside to go through a vacuum fan 272 and be reintroduced into the upper tunnel 220 still against the current (G) relative to the direction of circulation of the boats 255. At the other end of the upper tunnel 220, the hot gases are extracted by a vacuum cleaner 273 who empties them into the chimney 274.

As in the previous example, the loading / unloading station 260 located in the well 240 comprises a passage 261 with two openings 262, 263 to allow the simultaneous unloading / loading of a nacelle.

The installation supplying the hot gases and driving them is not shown in this figure. It is simply noted that this installation introduces the wet gases at the entrance of the lower tunnel 210 and takes a fraction of the hot gases of the upper tunnel 220 near its outlet, the remainder being discharged through the chimney 274.

The dryer described above requires for training chains with the nacelles, a single driving pulley, for example the pulley 254C. The other elements of the dryer are identical or similar to those already described and bear the same references as the similar elements of the figure 3 , whose references are increased by 100.

The figure 5 shows another variant embodiment 300 of the invention which combines the two solutions given to the figures 3 and 4 . In the upper part, the tunnel 320 and the wells are those of the embodiment of the figure 3 and, in the lower part, the lower tunnel 310 and the wells are those of the embodiment of the figure 4 Or vice versa. This solution can be adapted for certain new or transformation installations, depending on the height H available between the lower tunnel 310 and the upper tunnel 320 and / or the depth of burial of the lower tunnel 310.

This installation 300 will not be described in detail. The different constituent elements bear the same references as figures 3 and 4 and which, as the case may be, have been increased by 200 for the references of the elements from the embodiment of the figure 3 and 100 for those elements from the embodiment of the figure 4 .

In this design, it is interesting to observe that the total height of the dryer, in current section, is significantly reduced compared to the figure 3 .

DIGITAL EXAMPLES

The invention will be explained below by the comparative calculation of the interval between two nacelles of a tunnel dryer, known, according to the figure 1 of a first embodiment of a tunnel dryer according to the invention shown in FIG. figure 3 and a second embodiment of a tunnel dryer shown in FIG. figure 4 .

These calculations are made at the junction of a horizontal tunnel and a vertical well and take into account the real data, that is to say the size of the nacelles (also called swings), namely their height and their width as well as the radius of the pulley and a guard distance which is usually applied in addition, as a precautionary measure.

The calculation concerning the known dryer will be made using the diagram of the figure 7 , the calculation of the first embodiment of the invention will be done using the diagram of the figure 6 and that of the second embodiment of the invention, using the diagram of the figure 7 .

1 °) Calculation of the minimum pitch of the nacelles on the existing installation (figures 1, 6)

The legend of the references of the figure 6 is the following : H = Platform height The = Platform width Ra = Radius of the pulley C = La - Ra T = Diameter of the pulley Ha = H + 20 mm of guard Y = tx Π / 4

• Exemple numérique
Dimensions de la nacelle : Hauteur = 1990 mm (H) Largeur = 860 mm (La) Diamètre de la poulie = 647,22 mm (T) (10 dents au pas chaîne 200 mm) Calcul de B $$\mathrm{B}=\mathrm{Ha}-\mathrm{Ra}$$

$$\mathrm{Ha}\mathrm{=}\mathrm{H}\mathrm{+}\mathrm{20}\mathrm{mm}\mathrm{=}\mathrm{1990}\mathrm{+}\mathrm{20}\mathrm{=}\mathrm{2010}$$

$$\mathrm{Ra}\mathrm{=}\mathrm{Ø}\mathrm{/}\mathrm{2}\mathrm{=}\mathrm{647}\mathrm{,}\mathrm{22}\mathrm{=}\mathrm{323}\mathrm{,}\mathrm{61}$$

$$\mathrm{B}=1686,30\mathrm{mm}$$

Calcul de Y $$Y=\frac{\mathit{T\; x}3,14}{4}=\frac{647,22\mathit{mm\; x}3,14}{4}=508,06\mathit{mm}$$

Calcul de C $$\mathrm{C}=\mathrm{La}-\mathrm{Ra}\mathrm{La}=860\mathrm{mm}\mathrm{Ra}=323,61\mathrm{mm}$$

$$\mathrm{C}=860-323,61=536,39\mathrm{mm}$$

$$\mathrm{Pas}\mathrm{=}\mathrm{B}\left(\mathrm{1686},\mathrm{30}\right)\mathrm{+}\mathrm{Y}\left(\mathrm{508},\mathrm{06}\right)\mathrm{+}\mathrm{C}\left(\mathrm{536},\mathrm{39}\right)$$

$$\mathrm{Pas}=2730,75\mathrm{mm}=273\mathrm{cm}$$

According to figure 6 , the minimum pitch between nacelles is as follows: $$\mathrm{Not}\mathrm{=}\mathrm{B}\mathrm{+}\mathrm{Y}\mathrm{+}\mathrm{VS}$$

• Numeric example
Dimensions of the platform: Height = 1990 mm (H) Width = 860 mm (The) Diameter of the pulley = 647,22 mm (T) (10 teeth with chain pitch 200 mm) Calculation of B $$\mathrm{B}=\mathrm{Ha}-\mathrm{Ra}$$

$$\mathrm{Ha}\mathrm{=}\mathrm{H}\mathrm{+}\mathrm{20}\mathrm{mm}\mathrm{=}\mathrm{1990}\mathrm{+}\mathrm{20}\mathrm{=}\mathrm{2010}$$

$$\mathrm{Ra}\mathrm{=}\mathrm{Ø}\mathrm{/}\mathrm{2}\mathrm{=}\mathrm{647}\mathrm{,}\mathrm{22}\mathrm{=}\mathrm{323}\mathrm{,}\mathrm{61}$$

$$\mathrm{B}=1686,30\mathrm{mm}$$

Calculation of Y $$Y=\frac{\mathit{T\; x}3,14}{4}=\frac{647,22\mathit{mm\; x}3,14}{4}=508,06\mathit{mm}$$

Calculation of C $$\mathrm{VS}=\mathrm{The}-\mathrm{Ra}\mathrm{The}=860\mathrm{mm}\mathrm{Ra}=323,61\mathrm{mm}$$

$$\mathrm{VS}=860-323,61=536,39\mathrm{mm}$$

$$\mathrm{Not}\mathrm{=}\mathrm{B}\left(\mathrm{1686},\mathrm{30}\right)\mathrm{+}\mathrm{Y}\left(\mathrm{508},\mathrm{06}\right)\mathrm{+}\mathrm{VS}\left(\mathrm{536},\mathrm{39}\right)$$

$$\mathrm{Not}=2730,75\mathrm{mm}=273\mathrm{cm}$$

The attachment points of the nacelles must take into account the length of the links of the chain and as for reasons related to the structure of the chains, a nacelle can be attached to only one link out of two, the real step of the nacelles taking into account the pitch of the links of the chain which is equal to 200 mm or 400 mm for two successive links. The actual pitch between two nacelles will be equal to 7 x 400 = 280 mm.

2 °) Calculation of the minimum pitch of the nacelles according to the first embodiment (FIGS. 3 and 7)

The references of the figure 6 have the following meaning: H = Platform height The = platform width Ra = Radius of the pulley ∅T1 = Pulley diameter N ° 1 ∅T2 = pulley diameter N ° 2 Ha = H + 20mm of guard α = Angle given by the two nacelles in minimum position with the 20mm of guard β = Angle formed by the chain with respect to the vertical = 180 ° + α O = center pulley N ° 1 O1 = Center pulley N ° 2

$$\mathrm{Pas}=\mathrm{AB}$$

$$\mathrm{BC}+\mathrm{La}$$

$$\mathrm{AC}\mathrm{+}\mathrm{Ha}\mathrm{=}\mathrm{H}\mathrm{+}\mathrm{20}\mathrm{mm}$$

$${\mathrm{AB}}^2={\mathrm{AC}}^2+{\mathrm{BC}}_2$$

$$\mathrm{AB}=\sqrt{{\mathit{AC}}^2+{\mathit{BC}}^2}$$

• Calcul de l'angle α $$\mathrm{Tangente\; de\; A}=\frac{\mathit{BC}}{\mathit{AC}}=\mathrm{\alpha }$$

• Calcul du centre O de la poulie T1 par rapport à l'attache de la nacelle A $$\mathrm{cos\alpha }\mathrm{=}\frac{\mathit{AE}}{\mathit{AO}}\mathrm{AE}\mathrm{=}\mathrm{cos\alpha \; x\; AO}\mathrm{AO}\mathrm{=}\mathrm{Ra}\mathrm{AE}\mathrm{=}\mathrm{cos\alpha \; x\; Ra}$$

$$\mathrm{sin\alpha }\mathrm{=}\frac{\mathit{OE}}{\mathit{AO}}\mathrm{OE}\mathrm{=}\mathrm{sin\alpha \; x\; AO}\mathrm{AO}\mathrm{=}\mathrm{Ra}\mathrm{OE}\mathrm{=}\mathrm{sin\alpha \; x\; Ra}$$

• Calcul du centre O1 de la poulie T2 par rapport à l'attache de la nacelle B Calcul de l'angle ω $$\mathrm{180}\mathrm{°}\mathrm{-}\mathrm{\alpha }\mathrm{=}\mathrm{\beta }$$

$$\mathit{CBD}=90°=\frac{\beta }{2}+\mathrm{\Omega }\mathrm{\Omega }=90°-\frac{\beta }{2}\mathrm{cos\Omega }=\frac{\mathit{BF}}{\mathit{BO}1}$$

$$\mathrm{BF}=\mathrm{COS\Omega \; x\; BO}1$$

$$\mathrm{BO}1=\mathrm{Ra}$$

$$\mathrm{BF}=\mathrm{cos\Omega \; x\; Ra}\mathrm{sin\Omega }\frac{O1F}{\mathit{BO}1}$$

$$\mathrm{O}\mathrm{1}\mathrm{F}\mathrm{=}\mathrm{sin\Omega \; x\; BO}\mathrm{1}\mathrm{BO}\mathrm{1}\mathrm{=}\mathrm{Ra}\mathrm{O}\mathrm{1}\mathrm{F}\mathrm{=}\mathrm{sin\Omega \; x\; Ra}$$

• Calcul de la distance horizontale des centres des deux poulies $$\mathrm{O}1-\mathrm{O\; horizontale}=\mathrm{La}-\mathrm{BF}+\mathrm{AE}$$

• Calcul de la distance verticale des centres des deux poulies $$\mathrm{O}\mathrm{1}\mathrm{=}\mathrm{O\; verticale}\mathrm{=}\mathrm{Ha}\mathrm{-}\mathrm{OE}\mathrm{+}\mathrm{O}\mathrm{1}\mathrm{-}\mathrm{F}$$

• Exemple numérique
Dimensions de la nacelle
Hauteur = 1990 mm (H)
Largeur = 860 mm (la)
Diamètre des deux poulies T1 et T2 = 647,22
• Calcul du pas minimum avec garde 20 mm $$\mathrm{Pas}=\mathrm{AB}$$

$$\mathrm{BC}=\mathrm{La}=860\mathrm{mm}$$

$$\mathrm{AC}=2010\mathrm{mm}$$

$$\mathrm{AB}=\sqrt{{2010}^2+{860}^2}=\sqrt{4779700}$$

$$\mathrm{AB}=2186,25\mathrm{mm}$$

Calcul de l'angle α $$\mathrm{Tangente\; de\; A}=\frac{\mathit{BC}}{\mathit{AC}}=\frac{\mathit{La}}{\mathit{Ha}}=\frac{860}{2010}=0,428=23°18$$

• Calcul du centre O de T1 à l'attache A de la nacelle supérieure $$\mathrm{cos\alpha }=\frac{\mathit{AE}}{\mathit{AO}}\mathrm{AO}=\mathrm{Ra}=323,61\mathrm{\alpha }=23°18$$

$$\cos 23°18=0,920$$

$$\mathrm{AE}\mathrm{=}\mathrm{cos\alpha \; x\; Ra}\mathrm{=}\mathrm{0}\mathrm{,}\mathrm{920}\mathrm{x}\mathrm{323}\mathrm{,}\mathrm{61}\mathrm{=}\mathrm{297}\mathrm{,}\mathrm{72}\mathrm{mm}\mathrm{\approx }\mathrm{298}\mathrm{mm}$$

$$\mathrm{sin\alpha }=\frac{\mathit{OE}}{\mathit{AO}}\mathrm{AO}=\mathrm{Ra}=323,61\mathrm{\alpha }=23°18\sin 23°18=0,394$$

$$\mathrm{OE}\mathrm{=}\mathrm{sin\alpha \; x\; Ra}\mathrm{=}\mathrm{0}\mathrm{,}\mathrm{394}\mathrm{x}\mathrm{323}\mathrm{,}\mathrm{61}\mathrm{=}\mathrm{127}\mathrm{,}\mathrm{60}\mathrm{\approx }\mathrm{127}\mathrm{,}\mathrm{5}\mathrm{mm}$$

• Calcul du centre O1 de T2 à l'attache B de la nacelle inférieure Calcul de l'angle Ω $$\mathrm{\beta }\mathrm{=}\mathrm{180}\mathrm{°}\mathrm{-}\mathrm{\alpha }\mathrm{=}\mathrm{180}\mathrm{°}\mathrm{-}\mathrm{23}\mathrm{°}\mathrm{18}\mathrm{=}\mathrm{156}\mathrm{°}\mathrm{82}$$

$$\mathit{CBD}=\frac{\beta }{2}+\mathrm{\Omega }\mathrm{=}90\mathrm{°}\mathrm{\Omega }=90°-\frac{156°82}{2}\mathrm{\Omega }=11°59$$

$$\mathrm{cos\Omega }=\frac{\mathit{BF}}{\mathit{B}01}\mathrm{BO}1=\mathrm{Ra}=323,61\mathrm{\Omega }=11°59$$

$$\cos 11°59=0,980$$

$$\mathrm{BF}=\mathrm{cos\Omega \; x\; Ra}=0,980x323,61$$

$$\mathrm{BF}=317\mathrm{mm}$$

$$\mathrm{sin\Omega }=\frac{O1F}{\mathit{BO}1}\mathrm{BO}1=\mathrm{Ra}=323,61\Omega =11°59\sin 11°59=0,201$$

$$\mathrm{O}\mathrm{1}\mathrm{F}\mathrm{=}\mathrm{sin\Omega \; x\; BO}\mathrm{1}\mathrm{=}\mathrm{0}\mathrm{,}\mathrm{201}\mathrm{x}\mathrm{323}\mathrm{,}\mathrm{61}\mathrm{=}\mathrm{65}\mathrm{mm}$$

• Calcul de la distance horizontale des centres des deux poulies $$\mathrm{O}\mathrm{1}\mathrm{-}\mathrm{O\; horizontale}\mathrm{=}\mathrm{La}\mathrm{-}\mathrm{BF}\mathrm{+}\mathrm{AE}$$

La = 860 mm BF = 317 mm AE = 298 mm $$\mathrm{O}\mathrm{1}\mathrm{-}\mathrm{O\; horizontale}\mathrm{=}860\mathrm{-}317\mathrm{+}298=841\mathrm{mm}$$

• Calcul de la distance verticale des centres des deux poulies $$\mathrm{O}\mathrm{1}\mathrm{-}\mathrm{O\; verticale}\mathrm{=}\mathrm{Ha}\mathrm{-}\mathrm{OE}\mathrm{+}0$$

Ha = 2010 OE = 127,5 mm O1-F = 65 mm $$\mathrm{O}\mathrm{1}\mathrm{-}\mathrm{O\; verticale}\mathrm{=}2010\mathrm{-}127,5\mathrm{+}65=1947,5\mathrm{mm}$$

According to figure 7 , the minimum pitch of the nacelles is the following: $$\mathrm{Not}=\mathrm{AB}$$

$$\mathrm{Not}=\mathrm{AB}$$

$$\mathrm{BC}+\mathrm{The}$$

$$\mathrm{AC}\mathrm{+}\mathrm{Ha}\mathrm{=}\mathrm{H}\mathrm{+}\mathrm{20}\mathrm{<figure-callout\; id="2"\; label="mm\; AB"\; filenames="imgf0002.png,imgf0006.png"\; state="\{\{state\}\}">mm\; </figure-callout>}$$

$${\mathrm{AB}}^{}$$$${}^2={\mathrm{<figure-callout\; id="2"\; label="AC"\; filenames="imgf0002.png,imgf0006.png"\; state="\{\{state\}\}">AC</figure-callout>}}^2+{\mathrm{<figure-callout\; id="2"\; label="BC"\; filenames="imgf0002.png,imgf0006.png"\; state="\{\{state\}\}">BC</figure-callout>}}_2$$

$$\mathrm{AB}=\sqrt{{\mathit{<figure-callout\; id="2"\; label="AC"\; filenames="imgf0002.png,imgf0006.png"\; state="\{\{state\}\}">AC</figure-callout>}}^2+{\mathit{<figure-callout\; id="2"\; label="BC"\; filenames="imgf0002.png,imgf0006.png"\; state="\{\{state\}\}">BC</figure-callout>}}^2}$$

• Calculation of the angle α $$\mathrm{Tangent\; of\; A}=\frac{\mathit{BC}}{\mathit{AC}}=\mathrm{\alpha }$$

• Calculation of the center O of the pulley T1 with respect to the attachment of the pod A $$\cos \mathrm{=}\frac{\mathit{AE}}{\mathit{AO}}\mathrm{AE}\mathrm{=}\mathrm{cos\alpha \; x\; AO}\mathrm{AO}\mathrm{=}\mathrm{Ra}\mathrm{AE}\mathrm{=}\mathrm{cos\alpha \; x\; Ra}$$

$$\mathrm{sina}\mathrm{=}\frac{\mathit{oE}}{\mathit{AO}}\mathrm{oE}\mathrm{=}\mathrm{sin\alpha \; x\; AO}\mathrm{AO}\mathrm{=}\mathrm{Ra}\mathrm{oE}\mathrm{=}\mathrm{sin\alpha \; x\; Ra}$$

• Calculation of the center O1 of the pulley T2 with respect to the attachment of the pod B Calculation of the angle ω $$\mathrm{180}\mathrm{°}\mathrm{-}\mathrm{\alpha }\mathrm{=}\mathrm{\beta }$$

$$\mathit{CBD}=90°=\frac{\mathrm{<figure-callout\; id="2"\; label="\beta "\; filenames="imgf0002.png,imgf0006.png"\; state="\{\{state\}\}">\beta </figure-callout>}}{2}+\mathrm{\Omega }\mathrm{\Omega }=90°-\frac{\mathrm{<figure-callout\; id="2"\; label="\beta "\; filenames="imgf0002.png,imgf0006.png"\; state="\{\{state\}\}">\beta </figure-callout>}}{2}\mathrm{cos\Omega }=\frac{\mathit{BF}}{\mathit{BO}1}$$

$$\mathrm{BF}=\mathrm{COS\Omega \; x\; BO}1$$

$$\mathrm{BO}1=\mathrm{Ra}$$

$$\mathrm{BF}=\mathrm{cos\Omega \; x\; Ra}\mathrm{sin\Omega }\frac{O1F}{\mathit{BO}1}$$

$$\mathrm{O}\mathrm{1}\mathrm{F}\mathrm{=}\mathrm{sin\Omega \; x\; BO}\mathrm{1}\mathrm{BO}\mathrm{1}\mathrm{=}\mathrm{Ra}\mathrm{O}\mathrm{1}\mathrm{F}\mathrm{=}\mathrm{sin\Omega \; x\; Ra}$$

• Calculation of the horizontal distance of the centers of the two pulleys $$\mathrm{O}1-\mathrm{O\; horizontal}=\mathrm{The}-\mathrm{BF}+\mathrm{AE}$$

• Calculation of the vertical distance of the centers of the two pulleys $$\mathrm{O}\mathrm{1}\mathrm{=}\mathrm{O\; vertical}\mathrm{=}\mathrm{Ha}\mathrm{-}\mathrm{oE}\mathrm{+}\mathrm{O}\mathrm{1}\mathrm{-}\mathrm{F}$$

• Numeric example
Dimensions of the nacelle
Height = 1990 mm (H)
Width = 860 mm (the)
Diameter of the two pulleys T1 and T2 = 647,22
• Calculation of the minimum pitch with guard 20 mm $$\mathrm{Not}=\mathrm{AB}$$

$$\mathrm{BC}=\mathrm{The}=860\mathrm{mm}$$

$$\mathrm{AC}=2010\mathrm{mm}$$

$$\mathrm{AB}=\sqrt{{2010}^2+{860}^2}=\sqrt{4779700}$$

$$\mathrm{AB}=2186,25\mathrm{mm}$$

Calculation of the angle α $$\mathrm{Tangent\; of\; A}=\frac{\mathit{BC}}{\mathit{AC}}=\frac{\mathit{The}}{\mathit{Ha}}=\frac{860}{2010}=0,428=23°18$$

• Calculation of the center O of T1 to the attachment A of the top nacelle $$\cos =\frac{\mathit{AE}}{\mathit{AO}}\mathrm{AO}=\mathrm{Ra}=323,61\mathrm{\alpha }=23°18$$

$$\cos 23°18=0,920$$

$$\mathrm{AE}\mathrm{=}\mathrm{cos\alpha \; x\; Ra}\mathrm{=}\mathrm{0}\mathrm{,}\mathrm{920}\mathrm{x}\mathrm{323}\mathrm{,}\mathrm{61}\mathrm{=}\mathrm{297}\mathrm{,}\mathrm{72}\mathrm{mm}\mathrm{\approx }\mathrm{298}\mathrm{mm}$$

$$\mathrm{sina}=\frac{\mathit{oE}}{\mathit{AO}}\mathrm{AO}=\mathrm{Ra}=323,61\mathrm{\alpha }=23°18\sin 23°18=0,394$$

$$\mathrm{oE}\mathrm{=}\mathrm{sin\alpha \; x\; Ra}\mathrm{=}\mathrm{0}\mathrm{,}\mathrm{394}\mathrm{x}\mathrm{323}\mathrm{,}\mathrm{61}\mathrm{=}\mathrm{127}\mathrm{,}\mathrm{60}\mathrm{\approx }\mathrm{127}\mathrm{,}\mathrm{5}\mathrm{mm}$$

• Calculation of the center O1 of T2 at the attachment B of the lower nacelle Calculation of the angle Ω $$\mathrm{\beta }\mathrm{=}\mathrm{180}\mathrm{°}\mathrm{-}\mathrm{\alpha }\mathrm{=}\mathrm{180}\mathrm{°}\mathrm{-}\mathrm{23}\mathrm{°}\mathrm{18}\mathrm{=}\mathrm{156}\mathrm{°}\mathrm{82}$$

$$\mathit{CBD}=\frac{\mathrm{<figure-callout\; id="2"\; label="\beta "\; filenames="imgf0002.png,imgf0006.png"\; state="\{\{state\}\}">\beta </figure-callout>}}{2}+\mathrm{\Omega }\mathrm{=}90\mathrm{°}\mathrm{\Omega }=90°-\frac{156°82}{2}\mathrm{\Omega }=11°59$$

$$\mathrm{cos\Omega }=\frac{\mathit{BF}}{\mathit{B}01}\mathrm{BO}1=\mathrm{Ra}=323,61\mathrm{\Omega }=11°59$$

$$\mathrm{<figure-callout\; id="11"\; label="cos"\; filenames="imgf0001.png"\; state="\{\{state\}\}">cos</figure-callout>}11°59=0,980$$

$$\mathrm{BF}=\mathrm{cos\Omega \; x\; Ra}=0,980x323,61$$

$$\mathrm{BF}=317\mathrm{mm}$$

$$\mathrm{sin\Omega }=\frac{O1F}{\mathit{BO}1}\mathrm{BO}1=\mathrm{Ra}=323,61\Omega =11°59\mathrm{<figure-callout\; id="11"\; label="sin"\; filenames="imgf0001.png"\; state="\{\{state\}\}">sin</figure-callout>}11°59=0,201$$

$$\mathrm{O}\mathrm{1}\mathrm{F}\mathrm{=}\mathrm{sin\Omega \; x\; BO}\mathrm{1}\mathrm{=}\mathrm{0}\mathrm{,}\mathrm{201}\mathrm{x}\mathrm{323}\mathrm{,}\mathrm{61}\mathrm{=}\mathrm{65}\mathrm{mm}$$

• Calculation of the horizontal distance of the centers of the two pulleys $$\mathrm{O}\mathrm{1}\mathrm{-}\mathrm{O\; horizontal}\mathrm{=}\mathrm{The}\mathrm{-}\mathrm{BF}\mathrm{+}\mathrm{AE}$$

The = 860 mm BF = 317 mm AE = 298 mm $$\mathrm{O}\mathrm{1}\mathrm{-}\mathrm{O\; horizontal}\mathrm{=}860\mathrm{-}317\mathrm{+}298=841\mathrm{mm}$$

• Calculation of the vertical distance of the centers of the two pulleys $$\mathrm{O}\mathrm{1}\mathrm{-}\mathrm{O\; vertical}\mathrm{=}\mathrm{Ha}\mathrm{-}\mathrm{oE}\mathrm{+}0$$

Ha = 2010 OE = 127.5 mm O1-F = 65 mm $$\mathrm{O}\mathrm{1}\mathrm{-}\mathrm{O\; vertical}\mathrm{=}2010\mathrm{-}127,5\mathrm{+}65=1947,5\mathrm{mm}$$

Calculation of the real pitch of the nacelles according to the pitch of the links of the chain
Chain step = 200 mm
Not mini- or AB = 2186.25 mm

The actual pitch of the nacelles will be optimized by a multiple of a single step of the chain.
Not real = 2200 mm

3 °) Calculation of the minimum pitch of the nacelles of the dryer according to FIGS. 4 and 8

• Calcul de AO (rayon de la poulie) $$\sin \frac{\alpha }{2}=\frac{\mathit{AB}}{\mathit{AO}}\frac{\alpha }{2}=11°25\sin 11°25=0,195$$

$$\mathrm{AO}=\frac{\mathit{AB}}{\sin \frac{\alpha }{2}}\mathrm{AB}=\frac{\mathit{AC}}{2}=\frac{200}{2}=100\mathrm{AO}=\frac{100}{0,195}=512,82$$

$$\mathrm{Ø\; de\; la\; poulie}=512,82x2=1025,64$$

• Calcul du pas minimum des nacelles et du positionnement des trois poulies ( figure 8 )
H = Hauteur nacelle
La = Largeur nacelle
RaT1 = Rayon poulie 1
RaT2 = Rayon poulie 2
RaT3 = Rayon poulie 3
∅T1 = Diamètre poulie T1
∅T2 = Diamètre poulie T2
Ha = H + 20 mm de garde
α = Angle donné par les deux nacelles en position minimum avec les 20 mm de garde
β = Angle formé par la chaîne par rapport à la verticale = 180° - α
Ω = Angle résultant de la bissectrice de β $$\mathit{CBD}=90\frac{\beta }{2}+\mathrm{\Omega }$$

$$\mathrm{\Omega }=90°-\mathrm{\beta }/2$$

O = Centre poulie N°1 Pas = AB O1 = Centre poulie N°2 BC = La O2 = Centre poulie N°3 AC = Ha = H + 20 mm ∅T3 = Diamètre poulie T3 AB² = BC² + AC² $$\mathit{AB}=\sqrt{{\mathit{AC}}^2+{\mathit{BC}}^2}$$

Calcul de l'angle α $$\mathrm{Tangente\; de\; A}=\frac{\mathit{BC}}{\mathit{AC}}=\mathrm{\alpha }$$

• Calcul du centre O de la poulie T1 par rapport à l'attache de la nacelle supérieure A $$\mathrm{cos\alpha }\mathrm{=}\frac{\mathit{AE}}{\mathit{AO}}\mathrm{AE}\mathrm{=}\mathrm{cos\alpha \; x\; AO}\mathrm{AO}\mathrm{=}\mathrm{RaT}\mathrm{1}$$
  
  $$\mathrm{AE}\mathrm{=}\mathrm{cos\alpha \; x\; RaT}\mathrm{1}$$
  
  $$\mathrm{sin\alpha }\mathrm{=}\frac{\mathit{OE}}{\mathit{AO}}\mathrm{OE}\mathrm{=}\mathrm{sin\alpha \; x\; AO}\mathrm{AO}\mathrm{=}\mathrm{RaT}\mathrm{1}$$
  
  $$\mathrm{OE}\mathrm{=}\mathrm{sin\alpha \; x\; RaT}\mathrm{1}$$
  
• Calcul du centre O1 de la poulie T2 par rapport à l'attache de la nacelle inférieure B Calcul de l'angle Ω $$180\mathit{°}\mathit{-}\mathit{\alpha }\mathit{=}\mathrm{\beta }\mathit{CBD}=90\mathrm{°}\mathrm{=}\frac{\mathrm{<figure-callout\; id="2"\; label="\beta "\; filenames="imgf0002.png,imgf0006.png"\; state="\{\{state\}\}">\beta </figure-callout>}}{2}+\mathrm{\Omega }\mathrm{\Omega }=90°-\mathrm{\beta }/2$$
  
  $$\mathrm{cos\Omega }=\frac{\mathit{BF}}{\mathit{BO}1}$$
  
  $$\mathrm{BF}=\mathrm{cos\Omega \; x\; BO}1\mathrm{BO}1=\mathrm{RaT}2\mathrm{BF}=\mathrm{cos\omega \; x\; RaT}2$$
  
  $$\mathrm{sin\Omega }=\frac{\mathit{O}1F}{\mathit{BO}1}$$
  
  $$\mathrm{O}\mathrm{1}\mathrm{F}\mathrm{=}\mathrm{sin\Omega \; x\; BO}\mathrm{1}\mathrm{BO}\mathrm{1}\mathrm{=}\mathrm{RaT}\mathrm{2}\mathrm{O}\mathrm{1}\mathrm{F}\mathrm{=}\mathrm{SIN\Omega \; x\; RaT}\mathrm{2}$$
  
• Calcul de la distance horizontale des centres des deux poulies $$\mathrm{O}\mathrm{1}\mathrm{-}\mathrm{O\; horizontale}\mathrm{=}\mathrm{La}\mathrm{-}\mathrm{BF}\mathrm{+}\mathrm{AE}$$
  
• Calcul de la distance verticale des centres des deux poulies $$\mathrm{O}\mathrm{1}\mathrm{-}\mathrm{O\; verticale}\mathrm{=}\mathrm{Ha}\mathrm{-}\mathrm{OE}\mathrm{+}\mathrm{O}\mathrm{1}-\mathrm{F}$$
  
• Calcul de la distance du centre O (poulie T1) au centre 02 (poulie T3) $$K=\mathit{Côte\; variable\; jamais\; inférieure\; à\; la\; largeur\; La}+640\mathit{mm\; de\; la\; nacelle}$$
  
• Calcul de la distance du centre O (poulie T1) au centre 02 (poulie T3) $$\mathrm{J}\mathrm{=}\mathrm{O}\mathrm{-}\mathrm{O}\mathrm{1}\mathrm{verticale}\mathrm{-}\left(\mathrm{RaT}\mathrm{2}\mathrm{-}\mathrm{raT}\mathrm{3}\right)$$
  
• Exemple numérique
  Dimensions de la nacelle :
  • Hauteur = 1990 mm (H)
  • Largeur = 860 mm (La)
  • Diamètre des poulies = ∅T1 = 1025,64 mm
    = ∅T2 = 647,22 mm
    = ∅T3 = 1025,64 mm
  • Distance K (O-O2 horizontale) La + 640 mm = 860 + 640 = 1500 mm
• Calcul du pas minimum avec garde de 20 mm $$\mathrm{Pas}=\mathrm{AB}$$
  
  $$\mathrm{BC}=\mathrm{La}=860\mathrm{mm}$$
  
  $$\mathrm{AC}\mathrm{=}\mathrm{Ha}\mathrm{=}\mathrm{H}\mathrm{+}\mathrm{20}\mathrm{mm}=1990+20$$
  
  $$\mathrm{AC}=2010\mathrm{mm}$$
  
  $$\mathrm{AB}=\sqrt{{2010}^2+{860}^2}=\sqrt{4779700}$$
  
  $$\mathrm{AB}=2186,25\mathrm{mm}$$
  
• Calcul de l'angle α $$\mathrm{Tangente\; de\; A}=\frac{\mathit{BC}}{\mathit{AC}}\mathit{=}\frac{\mathit{La}}{\mathit{Ha}}=\frac{860}{2010}=0,428$$
  
  $$\mathrm{Tangente\; de\; A}=0,428=23°18$$
  
• Calcul du centre O de T1 à l'attache A de la nacelle supérieure $$\mathrm{cos\alpha }=\frac{\mathit{AE}}{\mathit{AO}}\mathrm{AO}=\mathrm{RaT}1=512,82\mathrm{mm}\mathrm{\alpha }=23°18\cos 23°18=0,920$$
  
  $$\mathrm{AE}\mathrm{=}\mathrm{cos\alpha \; x\; RaT}\mathrm{1}\mathrm{=}\mathrm{0}\mathrm{,}\mathrm{920}\mathrm{x}\mathrm{512}\mathrm{,}\mathrm{82}=\mathrm{471}\mathrm{,}\mathrm{79}\mathrm{mm}$$
  
  $$\mathrm{AE}=472\mathrm{mm}$$
  
  $$\mathrm{sin\alpha }=\frac{\mathit{OE}}{\mathit{AO}}$$
  
  $$\mathrm{OE}\mathrm{=}\mathrm{sin\alpha \; x\; RaT}\mathrm{1}\mathrm{=}\mathrm{0}\mathrm{,}\mathrm{394}\mathrm{x}\mathrm{512}\mathrm{,}\mathrm{82}\mathrm{=}\mathrm{202}\mathrm{,}\mathrm{05}\mathrm{mm}\mathrm{\approx }\mathrm{202}\mathrm{mm}$$
  
• Calcul du centre O1 de T2 à l'attache B de la nacelle inférieure Calcul de l'angle Ω $$\mathrm{\beta }\mathrm{=}\mathrm{180}\mathrm{°}\mathrm{-}\mathrm{\alpha }\mathrm{=}\mathrm{180}\mathrm{°}\mathrm{-}\mathrm{23}\mathrm{°}\mathrm{18}\mathrm{=}\mathrm{156}\mathrm{°}\mathrm{82}$$
  
  $$\mathit{CBD}=\frac{\mathrm{<figure-callout\; id="2"\; label="\beta "\; filenames="imgf0002.png,imgf0006.png"\; state="\{\{state\}\}">\beta </figure-callout>}}{2}+\mathrm{\Omega }\mathrm{=}90\mathrm{°}\mathrm{\Omega }=90°-\frac{156°82}{2}=11°59$$
  
  $$\mathrm{cos\Omega }=\frac{\mathit{BF}}{\mathit{B}01}\mathrm{BOT}2=\mathrm{RaT}2=323,61\mathrm{\Omega }=11°59\mathrm{<figure-callout\; id="11"\; label="cos"\; filenames="imgf0001.png"\; state="\{\{state\}\}">cos</figure-callout>}11°59=0,980$$
  
  $$\mathrm{BF}=\mathrm{cos\Omega \; x\; RaT}2=0,980x323,61$$
  
  $$\mathrm{BF}=317\mathrm{mm}$$
  
  $$\mathrm{sin\Omega }=\frac{\mathit{O}1F}{\mathit{BO}1}\mathrm{BO}1=\mathrm{RaT}2=323,61\mathrm{\Omega }=11°59\mathrm{<figure-callout\; id="11"\; label="sin"\; filenames="imgf0001.png"\; state="\{\{state\}\}">sin</figure-callout>}11°59=0,201$$
  
  $$\mathrm{O}\mathrm{1}\mathrm{F}\mathrm{=}\mathrm{sin\Omega \; x\; BO}\mathrm{1}\mathrm{=}\mathrm{0}\mathrm{,}\mathrm{201}\mathrm{x}\mathrm{323}\mathrm{,}\mathrm{61}\mathrm{=}\mathrm{65}\mathrm{,}\mathrm{04}\mathrm{mm}\mathrm{\approx }\mathrm{65}\mathrm{mm}$$
  
• Calcul de la distance horizontale des centres des deux poulies $$\mathrm{O}\mathrm{1}\mathrm{-}\mathrm{O\; horizontale}\mathrm{=}\mathrm{La}\mathrm{-}\mathrm{BF}\mathrm{+}\mathrm{AE}$$
  
  • La = 860 mm
  • BF = 317 mm
  • AE = 472 mm
  • O1-O horizontale = 860 - 317 + 472 = 1015 mm
• Calcul de la distance verticale des centres des deux poulies $$\mathrm{O}\mathrm{1}\mathrm{-}\mathrm{O\; verticale}\mathrm{=}\mathrm{Ha}\mathrm{-}\mathrm{OE}\mathrm{+}\mathrm{O}\mathrm{1}-\mathrm{F}$$
  
  • Ha= 2010 MM
  • OE = 202 mm
  • O1-F = 65 mm
  • O1-O verticale = 2010 - 202 + 65 = 1873 mm
• Calcul de la distance du centre O (poulie T1) au centre 02 (poulie T3) (O-O2 horizontale) $$\mathrm{K}\mathrm{=}\mathrm{La}\mathrm{+}\mathrm{640}\mathrm{jamais\; inférieure}$$
  
  $$\mathrm{K}=1500\mathrm{mm}$$
  
• Calcul de la distance du centre O (poulie T1) au centre 02 (poulie T3) (O-O2 verticale) $$\begin{array}{l}\mathrm{J}\mathrm{=}\mathrm{O}\mathrm{-}\mathrm{O}\mathrm{1}\mathrm{verticale}\mathrm{-}\left(\mathrm{RaT}\mathrm{2}\mathrm{+}\mathrm{raT}\mathrm{3}\right)\mathrm{RaT}\mathrm{2}\mathrm{=}\mathrm{323}\mathrm{,}\mathrm{61}\mathrm{mm}\mathrm{RaT}\mathrm{3}\mathrm{=}\mathrm{512}\mathrm{,}\mathrm{82}\mathrm{mm}\\ \mathrm{O}\mathrm{-}\mathrm{O}\mathrm{1}\mathrm{verticale}\mathrm{=}\mathrm{1878}\mathrm{mm}\end{array}$$
  
  $$\mathrm{J}\mathrm{=}\mathrm{1873}\mathrm{-}\left(\mathrm{323}\mathrm{,}\mathrm{61}\mathrm{+}\mathrm{512}\mathrm{,}\mathrm{82}\right)\mathrm{=}\mathrm{1036}\mathrm{,}\mathrm{57}\mathrm{\approx }\mathrm{1037}\mathrm{mm}$$
  
• Calcul du pas réel des nacelles
  Identique à la version N°2 $$\mathrm{Pas\; réel}=11x200=2200\mathrm{mm}$$
  

Before calculating the minimum distance between two nacelles, the pulley will be examined for the calculation of the pitch diameter of the pulley in the case of a 20 mm link chain and for a 16-tooth pulley.
200 mm chain step
Number of teeth 16 teeth
Α angle of each tooth $$\mathrm{\alpha }\mathrm{=}\frac{\mathrm{350}\mathrm{°}}{\mathrm{16}}\mathrm{=}\mathrm{22}\mathrm{°}\mathrm{50}$$

• Calculation of AO (radius of the pulley) $$\mathrm{<figure-callout\; id="2"\; label="sin\; \alpha "\; filenames="imgf0002.png,imgf0006.png"\; state="\{\{state\}\}">sin\; </figure-callout>}\frac{\alpha }{}\frac{}{2}=\frac{\mathit{<figure-callout\; id="2"\; label="AB\; AO\; \alpha "\; filenames="imgf0002.png,imgf0006.png"\; state="\{\{state\}\}">AB\; </figure-callout>}}{\mathit{AO}}\frac{\alpha }{}\frac{}{2}=11°25\mathrm{<figure-callout\; id="11"\; label="sin"\; filenames="imgf0001.png"\; state="\{\{state\}\}">sin</figure-callout>}11°25=0,195$$

$$\mathrm{AO}=\frac{\mathit{<figure-callout\; id="2"\; label="AB\; sin\; \alpha "\; filenames="imgf0002.png,imgf0006.png"\; state="\{\{state\}\}">AB\; </figure-callout>}}{\sin \frac{\alpha }{}}\mathrm{AB}=\frac{\mathit{<figure-callout\; id="2"\; label="AC"\; filenames="imgf0002.png,imgf0006.png"\; state="\{\{state\}\}">AC</figure-callout>}}{2}=\frac{200}{2}=100\mathrm{AO}=\frac{100}{0,195}=512,82$$

$$\mathrm{Ø\; pulley}=512,82x2=1025,64$$

• Calculation of the minimum pitch of the nacelles and the positioning of the three pulleys ( figure 8 )
H = Platform height
The = Platform width
RaT1 = Pulley radius 1
RaT2 = Pulley radius 2
RaT3 = Pulley radius 3
∅T1 = T1 pulley diameter
∅T2 = T2 pulley diameter
Ha = H + 20 mm of guard
α = Angle given by the two nacelles in minimum position with the 20 mm of guard
β = Angle formed by the chain with respect to the vertical = 180 ° - α
Ω = Angle resulting from the bisector of β $$\mathit{CBD}=90\frac{\mathrm{<figure-callout\; id="2"\; label="\beta "\; filenames="imgf0002.png,imgf0006.png"\; state="\{\{state\}\}">\beta </figure-callout>}}{2}+\mathrm{\Omega }$$

$$\mathrm{\Omega }=90°-\mathrm{\beta }/2$$

O = center pulley N ° 1 Pas = AB O1 = Center pulley N ° 2 BC = The O2 = Center pulley N ° 3 AC = Ha = H + 20 mm ∅T3 = T3 pulley diameter AB ² = BC ² + AC ² $$\mathit{AB}=\sqrt{{\mathit{<figure-callout\; id="2"\; label="AC"\; filenames="imgf0002.png,imgf0006.png"\; state="\{\{state\}\}">AC</figure-callout>}}^2+{\mathit{<figure-callout\; id="2"\; label="BC"\; filenames="imgf0002.png,imgf0006.png"\; state="\{\{state\}\}">BC</figure-callout>}}^2}$$

Calculation of the angle α $$\mathrm{Tangent\; of\; A}=\frac{\mathit{BC}}{\mathit{AC}}=\mathrm{\alpha }$$

• Calculation of the center O of the pulley T1 with respect to the attachment of the top nacelle A $$\cos \mathrm{=}\frac{\mathit{AE}}{\mathit{AO}}\mathrm{AE}\mathrm{=}\mathrm{cos\alpha \; x\; AO}\mathrm{AO}\mathrm{=}\mathrm{Rat}\mathrm{1}$$
  
  $$\mathrm{AE}\mathrm{=}\mathrm{cos\alpha \; x\; RaT}\mathrm{1}$$
  
  $$\mathrm{sina}\mathrm{=}\frac{\mathit{oE}}{\mathit{AO}}\mathrm{oE}\mathrm{=}\mathrm{sin\alpha \; x\; AO}\mathrm{AO}\mathrm{=}\mathrm{Rat}\mathrm{1}$$
  
  $$\mathrm{oE}\mathrm{=}\mathrm{sin\alpha \; x\; RaT}\mathrm{1}$$
  
• Calculation of the center O1 of the pulley T2 with respect to the attachment of the lower nacelle B Calculation of the angle Ω $$180\mathit{°}\mathit{-}\mathit{\alpha }\mathit{=}\mathrm{\beta }\mathit{CBD}=90\mathrm{°}\mathrm{=}\frac{\mathrm{<figure-callout\; id="2"\; label="\beta "\; filenames="imgf0002.png,imgf0006.png"\; state="\{\{state\}\}">\beta </figure-callout>}}{2}+\mathrm{\Omega }\mathrm{\Omega }=90°-\mathrm{\beta }/2$$
  
  $$\mathrm{cos\Omega }=\frac{\mathit{BF}}{\mathit{BO}1}$$
  
  $$\mathrm{BF}=\mathrm{cos\Omega \; x\; BO}1\mathrm{BO}1=\mathrm{Rat}2\mathrm{BF}=\mathrm{cos\omega \; x\; RaT}2$$
  
  $$\mathrm{sin\Omega }=\frac{\mathit{O}1F}{\mathit{BO}1}$$
  
  $$\mathrm{O}\mathrm{1}\mathrm{F}\mathrm{=}\mathrm{sin\Omega \; x\; BO}\mathrm{1}\mathrm{BO}\mathrm{1}\mathrm{=}\mathrm{Rat}\mathrm{2}\mathrm{O}\mathrm{1}\mathrm{F}\mathrm{=}\mathrm{SIN\Omega \; x\; RaT}\mathrm{2}$$
  
• Calculation of the horizontal distance of the centers of the two pulleys $$\mathrm{O}\mathrm{1}\mathrm{-}\mathrm{O\; horizontal}\mathrm{=}\mathrm{The}\mathrm{-}\mathrm{BF}\mathrm{+}\mathrm{AE}$$
  
• Calculation of the vertical distance of the centers of the two pulleys $$\mathrm{O}\mathrm{1}\mathrm{-}\mathrm{O\; vertical}\mathrm{=}\mathrm{Ha}\mathrm{-}\mathrm{oE}\mathrm{+}\mathrm{O}\mathrm{1}-\mathrm{F}$$
  
• Calculation of distance from center O (pulley T1) to center 02 (pulley T3) $$K=\mathit{Variable\; coast\; never\; less\; than\; the\; width\; The}+640\mathit{mm\; of\; the\; basket}$$
  
• Calculation of distance from center O (pulley T1) to center 02 (pulley T3) $$\mathrm{J}\mathrm{=}\mathrm{O}\mathrm{-}\mathrm{O}\mathrm{1}\mathrm{vertical}\mathrm{-}\left(\mathrm{Rat}\mathrm{2}\mathrm{-}\mathrm{rat}\mathrm{3}\right)$$
  
• Numeric example
  Dimensions of the platform:
  • Height = 1990 mm (H)
  • Width = 860 mm (The)
  • Diameter of the pulleys = ∅T1 = 1025.64 mm
    = ∅T2 = 647.22 mm
    = ∅T3 = 1025.64 mm
  • Distance K (O-O2 horizontal) The + 640 mm = 860 + 640 = 1500 mm
• Calculation of the minimum pitch with guard of 20 mm $$\mathrm{Not}=\mathrm{AB}$$
  
  $$\mathrm{BC}=\mathrm{The}=860\mathrm{mm}$$
  
  $$\mathrm{AC}\mathrm{=}\mathrm{Ha}\mathrm{=}\mathrm{H}\mathrm{+}\mathrm{20}\mathrm{mm}=1990+20$$
  
  $$\mathrm{AC}=2010\mathrm{mm}$$
  
  $$\mathrm{AB}=\sqrt{{2010}^2+{860}^2}=\sqrt{4779700}$$
  
  $$\mathrm{AB}=2186,25\mathrm{mm}$$
  
• Calculation of the angle α $$\mathrm{Tangent\; of\; A}=\frac{\mathit{BC}}{\mathit{AC}}\mathit{=}\frac{\mathit{The}}{\mathit{Ha}}=\frac{860}{2010}=0,428$$
  
  $$\mathrm{Tangent\; of\; A}=0,428=23°18$$
  
• Calculation of the center O of T1 at the attachment A of the upper nacelle $$\cos =\frac{\mathit{AE}}{\mathit{AO}}\mathrm{AO}=\mathrm{Rat}1=512,82\mathrm{mm}\mathrm{\alpha }=23°18\cos 23°18=0,920$$
  
  $$\mathrm{AE}\mathrm{=}\mathrm{cos\alpha \; x\; RaT}\mathrm{1}\mathrm{=}\mathrm{0}\mathrm{,}\mathrm{920}\mathrm{x}\mathrm{512}\mathrm{,}\mathrm{82}=\mathrm{471}\mathrm{,}\mathrm{79}\mathrm{mm}$$
  
  $$\mathrm{AE}=472\mathrm{mm}$$
  
  $$\mathrm{sina}=\frac{\mathit{oE}}{\mathit{AO}}$$
  
  $$\mathrm{oE}\mathrm{=}\mathrm{sin\alpha \; x\; RaT}\mathrm{1}\mathrm{=}\mathrm{0}\mathrm{,}\mathrm{394}\mathrm{x}\mathrm{512}\mathrm{,}\mathrm{82}\mathrm{=}\mathrm{202}\mathrm{,}\mathrm{05}\mathrm{mm}\mathrm{\approx }\mathrm{202}\mathrm{mm}$$
  
• Calculation of the center O1 of T2 at the attachment B of the lower nacelle Calculation of the angle Ω $$\mathrm{\beta }\mathrm{=}\mathrm{180}\mathrm{°}\mathrm{-}\mathrm{\alpha }\mathrm{=}\mathrm{180}\mathrm{°}\mathrm{-}\mathrm{23}\mathrm{°}\mathrm{18}\mathrm{=}\mathrm{156}\mathrm{°}\mathrm{82}$$
  
  $$\mathit{CBD}=\frac{\mathrm{<figure-callout\; id="2"\; label="\beta "\; filenames="imgf0002.png,imgf0006.png"\; state="\{\{state\}\}">\beta </figure-callout>}}{2}+\mathrm{\Omega }\mathrm{=}90\mathrm{°}\mathrm{\Omega }=90°-\frac{156°82}{2}=11°59$$
  
  $$\mathrm{cos\Omega }=\frac{\mathit{BF}}{\mathit{B}01}\mathrm{BOT}2=\mathrm{Rat}2=323,61\mathrm{\Omega }=11°59\mathrm{<figure-callout\; id="11"\; label="cos"\; filenames="imgf0001.png"\; state="\{\{state\}\}">cos</figure-callout>}11°59=0,980$$
  
  $$\mathrm{BF}=\mathrm{cos\Omega \; x\; RaT}2=0,980x323,61$$
  
  $$\mathrm{BF}=317\mathrm{mm}$$
  
  $$\mathrm{sin\Omega }=\frac{\mathit{O}1F}{\mathit{BO}1}\mathrm{BO}1=\mathrm{Rat}2=323,61\mathrm{\Omega }=11°59\mathrm{<figure-callout\; id="11"\; label="sin"\; filenames="imgf0001.png"\; state="\{\{state\}\}">sin</figure-callout>}11°59=0,201$$
  
  $$\mathrm{O}\mathrm{1}\mathrm{F}\mathrm{=}\mathrm{sin\Omega \; x\; BO}\mathrm{1}\mathrm{=}\mathrm{0}\mathrm{,}\mathrm{201}\mathrm{x}\mathrm{323}\mathrm{,}\mathrm{61}\mathrm{=}\mathrm{65}\mathrm{,}\mathrm{04}\mathrm{mm}\mathrm{\approx }\mathrm{65}\mathrm{mm}$$
  
• Calculation of the horizontal distance of the centers of the two pulleys $$\mathrm{O}\mathrm{1}\mathrm{-}\mathrm{O\; horizontal}\mathrm{=}\mathrm{The}\mathrm{-}\mathrm{BF}\mathrm{+}\mathrm{AE}$$
  
  • The = 860 mm
  • BF = 317 mm
  • AE = 472 mm
  • O1-O horizontal = 860 - 317 + 472 = 1015 mm
• Calculation of the vertical distance of the centers of the two pulleys $$\mathrm{O}\mathrm{1}\mathrm{-}\mathrm{O\; vertical}\mathrm{=}\mathrm{Ha}\mathrm{-}\mathrm{oE}\mathrm{+}\mathrm{O}\mathrm{1}-\mathrm{F}$$
  
  • Ha = 2010 MM
  • OE = 202 mm
  • O1-F = 65 mm
  • O1-O vertical = 2010 - 202 + 65 = 1873 mm
• Calculation of distance from center O (pulley T1) to center 02 (pulley T3) (O-O2 horizontal) $$\mathrm{K}\mathrm{=}\mathrm{The}\mathrm{+}\mathrm{640}\mathrm{never\; lower}$$
  
  $$\mathrm{K}=1500\mathrm{mm}$$
  
• Calculation of distance from center O (pulley T1) to center 02 (pulley T3) (O-O2 vertical) $$\begin{array}{l}\mathrm{J}\mathrm{=}\mathrm{O}\mathrm{-}\mathrm{O}\mathrm{1}\mathrm{vertical}\mathrm{-}\left(\mathrm{Rat}\mathrm{2}\mathrm{+}\mathrm{rat}\mathrm{3}\right)\mathrm{Rat}\mathrm{2}\mathrm{=}\mathrm{323}\mathrm{,}\mathrm{61}\mathrm{mm}\mathrm{Rat}\mathrm{3}\mathrm{=}\mathrm{512}\mathrm{,}\mathrm{82}\mathrm{mm}\\ \mathrm{O}\mathrm{-}\mathrm{O}\mathrm{1}\mathrm{vertical}\mathrm{=}\mathrm{1878}\mathrm{mm}\end{array}$$
  
  $$\mathrm{J}\mathrm{=}\mathrm{1873}\mathrm{-}\left(\mathrm{323}\mathrm{,}\mathrm{61}\mathrm{+}\mathrm{512}\mathrm{,}\mathrm{82}\right)\mathrm{=}\mathrm{1036}\mathrm{,}\mathrm{57}\mathrm{\approx }\mathrm{1037}\mathrm{mm}$$
  
• Calculation of the real pitch of the nacelles
  Same as version N ° 2 $$\mathrm{Not\; real}=11x200=2200\mathrm{mm}$$
  

NOMENCLATURE

1

Tunnel dryer

10

Lower Tunnel

11

End of the tunnel

20

Upper Tunnel

21

Tunnel entrance

22

Tunnel exit

30, 40

Well

31

Sas

32

Cylinder

50

Chain

51-54

Deflection pulleys

55

nacelle

55S

Upper wall

55I

Bottom wall

56

Point of attachment of the basket

60

Loading / unloading station

61

Cylinder

62

Unloading opening

63

Loading opening

70

Equipment generating hot air

71

Deviation

72

Fan

73

Vacuum

74

Fireplace

F

Direction of movement of the nacelles

BOY WUT

Direction of circulation of hot gases

NOT

nacelle

N1-N4

Parts of the basket

A-D

Peaks of the basket

100

Tunnel dryer

110

Lower Tunnel

120

Upper Tunnel

130, 140

Well

131

Sas

150

Chain

151-154

Deflection pulleys

155

nacelle

155I

Bottom wall

160

Loading / unloading station

162

Unloading opening

163

Unloading opening

170

Hot air generator

171

Derivation

172

Fan

173

Vacuum

174

Fireplace

200

Tunnel dryer

210

Lower Tunnel

220

Upper Tunnel

230.240

Well

231

Sas

232

Cylinder

250

Chain

251-254

Deflection pulleys

255

nacelle

260

Loading / unloading station

261

Cylinder

262

Unloading opening

263

Unloading opening

271

Derivation

272

Fan

273

Vacuum

274

Fireplace

300

Tunnel dryer

310

Lower Tunnel

320

Upper Tunnel

330, 340

Well

331

Sas

350

Chain

351-354

Deflection pulleys

355

nacelle

360

Loading / unloading station

371

Derivation

372

Fan

373

Vacuum

374

Fireplace

Claims (4)

1. A tunnel dryer for building products such as bricks or tiles comprising
   a lower tunnel (110) and an upper tunnel (120), connected at each end through a well (130, 140), forming a circulation path formed by the succession of the lower tunnel, of a well, of the upper tunnel and of a well, this looped path being covered by a conveyor with chains (150) from which are suspended nacelles (155) receiving products to be dried,

   - the chain (150) passing from a horizontal path to a vertical path (or vice versa) at the junction (151) of a tunnel (110, 120) or of a well (130, 140) by means of an angular member (151-154),

   - the nacelles (155) being separated by the minimum interval required for avoiding the collision of two successive nacelles at the junction (151-154) of the horizontal path and of the vertical path (or vice versa),

   - the chain (150) passing over a pulley (151A-154A) at each junction,

   - the nacelles (155, N) globally having a rectangular section with a point (M) for attachment to the chain (150) in the middle of their width,

   characterized in that
   at each angular member (151-154) of the rectangular path, at the well (130, 140), the return pulley (151A-154A) at the end of the horizontal path is completed by a deflection pulley (151B-154B) installed in the well (130, 140) so that the chain (150), which passes around the return pulley and the deflection pulley follows a tilted path (T1T5) substantially corresponding to the hypotenuse (M11D11) of the right-angled triangle (A11M11D11) taken in the rectangle (ABCD) formed by the nacelle, the vertical side (A 11 D 11) of which is equal to the height of the nacelle (N11, 155) and the horizontal side (A11M11) of which is equal to the half width (AM, ½ AB) of the nacelle (N 11, 155) as far as its point (M) of suspension from the chain (150).
2. The tunnel dryer according to claim 1,
   characterized in that
   the return pulley (251A-254A) and the deflection pulley (251B-254B) are completed by an auxiliary pulley (251C-254C), generating a deflection outwards of the circulation path of the chain (250) which would only pass over the return pulleys, in order to sufficiently move the deflection pulleys (251B-254B) away from the well (230), in order to generate an airlock (261) obturated by one or two successive nacelles (255) and blocking the passage of hot gases from the upper tunnel (220) to the lower tunnel (210).
3. The tunnel dryer according to claim 2,
   characterized in that
   it includes, for one of the tunnels (310, 320), at the junction of the wells (330, 340), a return pulley and a deflection pulley and, for the other tunnel (310), at each end, a return pulley combined with a deflection pulley and completed with an auxiliary pulley generating the outward deflection of the circulation path of the chain (350).
4. The tunnel dryer according to claim 1,
   characterized in that
   each nacelle (155, 255) includes a single solid partition (155I) for closing an airlock (131, 231) of the well connecting the lower tunnel (110) to the upper tunnel (120) in the circulation direction of the nacelles (155).

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