CN112464346A

CN112464346A - Wall brick stacking algorithm and operating system

Info

Publication number: CN112464346A
Application number: CN202011355429.4A
Authority: CN
Inventors: 张柏松; 周恩德
Original assignee: Zhongwu Zhijian Wuhan Technology Co Ltd
Current assignee: Zhongwu Zhijian Wuhan Technology Co Ltd
Priority date: 2020-11-27
Filing date: 2020-11-27
Publication date: 2021-03-09

Abstract

The invention discloses a wall brick stacking algorithm, which comprises the following steps: s1: acquiring length and height data of a wall to be built; s2: determining the mortar joint thickness when bricks are stacked according to the materials used for smearing the mortar joints; s3: calculating brick building data of two adjacent brick layers according to the brick wall building rule, the brick length, the mortar joint thickness and the length of the wall body to be built; s4: and calculating the number of layers of bricks required by the wall to be built according to the height of the wall to be built, the height of the bricks and the thickness of the mortar joints. Compared with the prior art, the wall brick stacking algorithm and the operation system do not need to manually calculate the type and the number of bricks and the length value of the bricks of non-integral bricks, the number of layers of the bricks to be built, the type and the number of the bricks required by each brick layer and the length of the bricks of non-integral bricks can be calculated by only acquiring the length and the height of the wall to be built, and the wall brick stacking algorithm and the operation system conform to various building specifications during building, so that the quality of the wall body after building is guaranteed.

Description

Wall brick stacking algorithm and operating system

Technical Field

The invention relates to the technical field of intelligent buildings, in particular to a wall brick stacking algorithm and an operating system.

Background

In order to avoid environmental pollution caused by the use of red bricks, the existing wall is generally built by using an air-adding block with the length of 600 mm. In order to make the quality of the masonry wall higher, the standard requirements for masonry wall surfaces generally include: the length of the air-entrapping block is not less than 240mm and not more than 600mm, and the serrated racking layers are arranged. The mortar joints between the upper layer brick and the lower layer brick are mutually staggered, and the staggered distance is 1/3-2/3 of the brick opposite to one mortar joint. Taking the brick with the right mortar joint facing each other as an example, as shown in fig. 2, the distance from the first mortar joint 61 to the second mortar joint 62 should be greater than 1/3 of the length of the second brick 2 and less than 2/3 of the length of the second brick 2. As also shown in fig. 3, the distance from first mortar joint 61 to second mortar joint 62 should be greater than 1/3 for the length of fourth brick 4 and less than 2/3 for the length of fourth brick 4.

Traditional manual masonry building construction, because the length and the height of each wall body to be built are inconsistent, the manual work is difficult to rapidly calculate the brick type, the brick quantity and the brick length value of the non-whole brick required by the wall body to be built, so that the masonry standard is difficult to strictly adhere to, and the quality of the masonry wall is easy to cause unqualified.

Disclosure of Invention

The invention aims to overcome the technical defects, provides a wall brick stacking algorithm and an operation system, and solves the technical problems that in the traditional manual masonry building construction in the prior art, because the length and the height of each wall body to be built are inconsistent, the type and the number of bricks required by the wall body to be built and the length and the number of bricks of non-whole bricks are difficult to calculate rapidly by manual work, the masonry standard is difficult to be strictly followed, and the quality of the masonry wall surface is easy to be unqualified.

A wall brick stacking algorithm comprises the following steps:

s1: acquiring length and height data of a wall to be built;

s2: determining the mortar joint thickness when bricks are stacked according to the materials used for smearing the mortar joints;

s3: calculating brick building data of two adjacent brick layers according to the brick wall building rule, the brick length, the mortar joint thickness and the length of the wall body to be built;

s4: calculating the number of layers of bricks required by the wall to be built according to the height of the wall to be built, the height of the bricks and the thickness of the mortar joints;

s5: and circularly copying and stacking the data of the two adjacent brick layers calculated in the step S3 in sequence until the number of the brick layers required by the wall body to be built calculated in the step S4 is matched, and outputting the brick stacking data of the whole wall body to be built.

In a preferred embodiment, the two adjacent brick layers in S3 are divided into an odd layer and an even layer, and bricks at two ends of the odd layer are zigzag.

In a preferred embodiment, in step S1, the length and height data of the wall to be laid is obtained by an image obtaining device.

In a preferred embodiment, in step S1, the length and height data of the wall to be laid is obtained using laser ranging.

In a preferred embodiment, in step S2, the material for plastering the mortar joints is mortar or adhesive.

In a preferred embodiment, in step S4, the calculation result is integer by using a tail-removing method.

In a preferred embodiment, in step S5, a remainder of the calculation result in step S4 is also output.

A wall brick stacking operation system, comprising:

the input module is used for acquiring length and height data of a wall to be built;

the selection module is used for providing selection of various materials for smearing the mortar joints and obtaining the mortar joint thickness according to the selection of a user;

the first calculation module is used for calculating brick building data of two adjacent brick layers;

the second calculation module is used for calculating the number of brick layers required by the wall to be built;

and the output module is used for outputting the brick stacking data of the whole wall to be built according to the calculation data of the first calculation module and the second calculation module.

A computer device, comprising:

a memory and a processor;

the memory is used for storing a computer program, and the processor realizes the steps in the wall brick coding algorithm when executing the computer program.

A computer-readable storage medium storing computer-executable instructions, wherein the instructions, when executed by a processor, implement the steps of the wall tiling algorithm described above.

Compared with the prior art, the invention has the following beneficial effects: the wall brick stacking algorithm and the operation system do not need to manually calculate the types and the number of the bricks and the length value of the bricks of the non-integral bricks, the number of the layers of the bricks to be built, the types and the number of the bricks of each brick layer and the length of the bricks of the non-integral bricks can be calculated by acquiring the length and the height of the wall to be built, the required bricks can be prepared in advance before building, various building specifications are met during building, and the quality of the wall after building is guaranteed.

Drawings

Fig. 1 is a schematic structural diagram of a wall brick stacking algorithm provided by the invention.

Fig. 2 is a schematic diagram of brick stacking when r is 0 in the wall stacking algorithm provided in fig. 1.

FIG. 3 is a schematic diagram of brick stacking when r is greater than 0 and less than or equal to 180 in the wall brick stacking algorithm provided in FIG. 1.

FIG. 4 is a schematic diagram of brick stacking when r is more than 180 and less than or equal to (420+ w) in the wall brick stacking algorithm provided in FIG. 1.

FIG. 5 is a schematic diagram of brick stacking when (420+ w) < r < 600 in the wall brick stacking algorithm provided in FIG. 1.

FIG. 6 is a schematic diagram of brick stacking when r is 600 ≦ r < (600+ w) in the wall brick stacking algorithm provided in FIG. 1.

Fig. 7 is a schematic structural diagram of a wall brick stacking operation system provided by the invention.

Description of the main elements

First brick	1
		Second brick	2
Third brick	3
		Fourth brick	4
Fifth brick	5
		First mortar joint	61
Second mortar joint	62

Detailed Description

In order to make the objects, technical solutions and advantages of the present invention more apparent, the present invention is described in further detail below with reference to the accompanying drawings and embodiments. It should be understood that the specific embodiments described herein are merely illustrative of the invention and are not intended to limit the invention.

Referring to fig. 1-7, fig. 1 is a schematic structural diagram of a wall brick stacking algorithm provided by the present invention. Fig. 2 is a schematic diagram of brick stacking when r is 0 in the wall stacking algorithm provided in fig. 1. FIG. 3 is a schematic diagram of brick stacking when r is greater than 0 and less than or equal to 180 in the wall brick stacking algorithm provided in FIG. 1. FIG. 4 is a schematic diagram of brick stacking when r is more than 180 and less than or equal to (420+ w) in the wall brick stacking algorithm provided in FIG. 1. FIG. 5 is a schematic diagram of brick stacking when (420+ w) < r < 600 in the wall brick stacking algorithm provided in FIG. 1. Fig. 6 is a schematic structural diagram of a wall brick stacking operation system provided by the invention.

Will the brick layer divide into odd number layer and even level layer, because the serrated raft needs the interlayer setting, for convenient the description, establish the fragment of brick at odd number layer both ends is serrated raft, even level layer both ends are ordinary fragment of brick. During actual use, the double-layer brick rack can also be formed by stacking double-layer double-.

When using the serrated raft to build the wall body, because the flute portion protrusion of serrated raft is outside the length scope of waiting to build the wall body, consequently when the calculation, does not consider the length of flute in the serrated raft.

Example 1:

as shown in fig. 1, the stacking algorithm of the wall bricks comprises the following steps:

s1: the method comprises the steps of obtaining length and height data of a to-be-built wall body, setting the length of the to-be-built wall body to be x and the height of the to-be-built wall body to be y, and setting the length of a brick block to be L and the height of the brick block to be h. The length and the height of the to-be-built wall body can be manually measured by using a measuring tool manually, and can also be automatically measured by a 3D camera or a laser range finder and other camera devices. In this embodiment, the fragment of brick adopts length to be 600mm, width 200mm and height 300 mm's standard air entrainment piece, and the standard serrated racking size of adoption is: length 240mm +60mm (alveolar length), width 200mm and height 300 mm. I.e., L600 mm and h 300 mm.

S2: and determining the mortar joint thickness when bricks are stacked according to the materials used for coating the mortar joints. The mortar joint thickness is w, and in this embodiment, the material for smearing the mortar joint is an adhesive. When the adhesive is used for plastering the mortar joints, the thickness standard of the mortar joints is 3mm, namely w is 3 mm.

the number of the whole bricks which can be built in each brick layer is n, and the remaining length of each brick layer after the whole bricks are built is r. Then n equals x/(L + w), i.e. n equals x/603, and n is an integer using tail-out. And r is x/(L + w), namely the remainder of x/603, namely r is x-603 n.

Dividing 0 to L into a plurality of intervals, and calculating the interval to which r belongs. In the present embodiment, the section to which r belongs is divided into four sections, i.e., r is 0 < r < 180, r is 180 < r < 423, and r is 423 < 600.

According to wall body length's difference, need use the serrated raft of the fragment of brick or nonstandard length of some whole bricks of non and half bricks when building by laying bricks or stones, for convenient the description, establish the length of this type of fragment of brick as d, the length that this type of serrated raft does not take the alveolus establishes as e. From left to right, the even number layer of the penultimate brick is defined as a first brick 1, the penultimate brick is defined as a second brick 2, the odd number layer of the penultimate brick is defined as a third brick 3, the penultimate brick is defined as a fourth brick 4, and the straight number first brick is defined as a fifth brick 5.

In this embodiment, the order of the masonry bricks is from left to right, and in other embodiments, the order of masonry bricks may also be from right to left.

As shown in fig. 2, when r is 0, an even number of courses can be constructed by using n bricks. Since r is x-603n, the number of vertical mortar joints is 1 less than that of bricks in the actual building process, that is, when r is 0, a gap with the width of w (3mm) is left in an even layer after n whole bricks are stacked (within the allowable error range during building). When bricks of odd-numbered courses are stacked, in order to make the lengths of the odd-numbered courses and the even-numbered courses flush, the actual masonry length of the odd-numbered courses is also (x-w) mm. Odd number layer's fragment of brick pile up puts the mode and divide into two kinds:

one is to cut few bricks and the simplest way to obtain bricks. Fix fifth fragment of brick 5 for 240mm +60 mm's (alveolus) standard serrated raft, third fragment of brick 3 is decided for whole brick, establishes the serrated raft that the fourth fragment of brick is e +60mm (alveolus). Namely, a piece of standard serrated racking with the length of 240mm +60mm (serrated trough), n-1 whole bricks with the length of 600mm and a serrated racking with the length of e +60mm (serrated trough) are sequentially adopted for construction, namely 240+ (n-1)600+3n + e ═ x-3, the formula is converted into e ═ x-603n +357, and the e ═ 357mm can be obtained through calculation due to the fact that r ═ x-603n and r ═ 0. I.e. the fourth brick 4 is serrated at a length of 357mm +60mm (flute). This building scheme need use three kinds of types fragment of brick, nevertheless only need cut out a length and be 357mm +60mm (alveolus) length's serrated racking, and other fragments of brick all can directly acquire, need not to process the cutting.

One mode is a symmetrical mode of left and right serrated branches. Decide third fragment of brick 3 for whole brick, fifth fragment of brick 5 all adopts the serrated racking of e +60mm (alveolus) with fourth fragment of brick 4. Namely, the step of constructing the brick sequentially adopts a step of e +60mm (tooth groove) length, n-1 whole bricks with 600mm length and e +60mm (tooth groove) step. That is, e + (n-1)600+3n + e is x-3, and since r is x-603n and r is 0, e is 298.5 mm. I.e. both the fourth brick 4 and the fifth brick 5 are serrated at 298.5mm +60mm (flute) length. This masonry scheme only requires the use of two types of bricks, but requires the cutting of two serrated racking of 298.5mm +60mm length (flute).

As shown in FIG. 3, when r is greater than 0 and less than or equal to 180, because the length of the brick cannot be less than 240mm and the length of the serrated racking brick cannot be greater than 540mm, the length of r is not enough to lay down a brick meeting the building requirement, and therefore, when r is greater than 0 and less than or equal to 180, the lengths of the first brick 1 and the second brick 2 need to be changed in even layers.

The length of the second bricks 2 of the even number of courses is fixed to 240mm, and the length of the first bricks is set to d. And n-1 whole bricks, a brick with the length of d and a brick with the length of 240mm are sequentially adopted for building the even layers. That is, x is (n-1)600+3n + d +240, and the formula is converted into x-603n is d-360, and since r is x-603n, d is calculated as r + 360. I.e. the length of the first brick 1 is (r +360) mm and the length of the second brick 2 is 240 mm.

Odd number layer fifth fragment of brick 5 decides as 240mm +60 mm's (alveolus) standard serrated racking, and third fragment of brick 3 decides as whole brick, and it is e +60 mm's (alveolus) serrated racking to set up fourth fragment of brick 4. Namely, the building of odd-numbered bricks adopts a standard serrated raft with the length of 240mm +60mm (serrated groove), n-1 whole bricks with the length of 600mm and a serrated raft with the length of e +60mm (serrated groove) in sequence for building. I.e. the length of the fifth brick 5 (without the tooth socket) is equal to the length of the second brick 2 and the number of whole bricks in odd courses is equal to the number of whole bricks in even courses. The length of the first brick 1 is therefore equal to the length of the fourth brick 4 (without the socket). I.e. d, since d is r +360, the fourth brick 4 is serrated in a length of (r +360) mm.

As shown in FIG. 4, when 180 < r.ltoreq.423. The even number of courses still changes the length of the first brick 1 and the second brick 2.

The length of the first brick 1 in the even layers is set as d, the length of the second brick 2 is fixed to be 423mm, namely n-1 whole bricks, one brick with the length of d and one brick with the length of 423mm are sequentially adopted for building the even layers. That is, x is (n-1)600+3n + d +423, and the formula is converted into x-603n is d-177, and since r is x-603n, d is calculated to be r + 177. I.e. the length of the first brick 1 is (r +177) mm.

The lengths of a fourth brick placing position 4 (without tooth sockets) and a fifth brick placing position 5 (without tooth sockets) in the odd layers are respectively fixed to be 180mm and 240mm, namely the sum of the length of the fourth brick placing position 4 (without tooth sockets), the length of the fifth brick placing position 5 (without tooth sockets) and the thickness of the mortar joint is equal to the length of the second brick 2. That is, the fourth brick laying position 4 and the fifth brick laying position 5 are equal to the length of the second brick 2 when being laid together through a 3mm mortar joint. It is thus possible to make the number of even courses equal to the number of odd courses, i.e. the length of the 1 st brick is equal to the length of the third brick 3, i.e. the length of the third brick is (r +177) mm.

As shown in FIG. 5, when 423 < r < 600. The length of r can be used to individually construct a block in an even number of courses. In the odd layers, the length of r can also be divided into a standard serrated racking and a serrated racking of not less than 180mm (without a serration) length. Therefore, when r is in this interval, there is no need to change the length of the whole brick which can be laid.

And (3) setting the first brick 1 in the even number layer as a whole brick, namely sequentially adopting n whole bricks and a brick with the length of d for building. And d is x-603n, and r is x-603n, so that d is r. I.e. the second brick 2 is a brick of length r.

With third fragment of brick 3 surely for whole brick in the odd number layer, fifth fragment of brick 5 decides the standard serrated raft for 240mm +60mm (alveolus) length, the serrated raft of length for e +60mm (alveolus) length of establishing fourth fragment of brick 4, adopt the standard serrated raft that a length is 240mm +60mm (alveolus) in proper order when building by laying bricks or stones promptly, the whole brick of n piece and a serrated raft that length is e +60mm (alveolus) are built by laying bricks or stones. Since the number of whole bricks of the odd and even courses is equal, the sum of the length of the fifth brick 5 (without tooth space), the length of the fourth brick 4 (without tooth space) and the thickness of one mortar joint is equal to the length of the second brick 2, i.e., 240+ e + w-r, and since w-3 mm, e-r-243 is calculated. Namely, the fourth brick 4 is serrated with the length of (r-243) mm +60mm (tooth groove).

The required number of bricks, the type of bricks and the required length of bricks of the non-whole bricks of an odd layer and an even layer can be calculated according to the calculation method.

S4: and calculating the number of the brick layers required by the wall to be built according to the height of the brick, and setting the number of the brick layers required by the wall to be built as m, wherein m is y/(h + w). I.e. m is y/303, and m is integer by using a tail-removing method. And the value obtained by m is the value of the brick layer to be built of the wall body to be built.

Aiming at the brick layer which is not enough to build the whole brick at the topmost part of the wall body to be built. I.e. y/303 cannot be divided exactly, y/303 results in a brick layer of remainder height. The existing masonry method adopts inclined masonry and filling by using foaming materials, and the like, and the treatment modes are various. The calculation of the code brick for this brick layer is therefore not considered in the present invention.

S5: during building, an odd layer and an even layer are taken as a cycle, and the cycle is sequentially copied and stacked until the number of the brick layers is matched with the value of m, so that brick setting data of the whole wall to be built can be output. Preferably, when the brick stacking data of the whole wall body to be built is output, the height of the topmost part of the wall body to be built, which is not enough for building the whole brick, of the brick layer, namely the remainder of y/303, is output at the same time.

For masonry, the brick joints between the upper layer of bricks and the lower layer of bricks are staggered from each other by 1/3-2/3% of the bricks opposite to the mortar joints. According to the brick stacking scheme, taking the brick opposite to the right mortar joint as an example, the calculation is carried out for the example when r belongs to different intervals.

As shown in fig. 2, when r is 0, that is, the lengths of the first brick 1, the second brick 2 and the third brick 3 are all 600m, and the length of the fourth brick 4 is 357mm +60mm (tooth socket). The distance from the first mortar joint 61 to the second mortar joint 62 is equal to the length of the second brick 2 minus the length of the fourth brick 4 (without tooth sockets), i.e. 600-. Or when the fourth brick 4 and the fifth brick 5 are all branch joints with the length of 298.5mm +60mm (tooth groove), the distance from the first mortar joint 61 to the second mortar joint 62 is 600-298.5 mm-301.5 mm, which also meets the masonry requirement.

As shown in FIG. 3, when 0 < r.ltoreq.180. And (3) setting r to be greater than 0 but infinitely close to 0, and substituting the value of r as 0 into a formula for calculation. The length of the first brick 1 at this point is 360mm, the length of the second brick 2 is 240mm and the length of the fourth brick 4 is 360mm +60mm (socket). The distance from the first mortar joint 61 to the second mortar joint 62 is equal to the length of the fourth brick 4 without tooth grooves minus the length of the second brick 2, i.e. 360 and 240mm is 120 mm. And 1/3-2/3 of the length part of the fourth brick 4 (without tooth sockets) is 120-240 mm, which meets the masonry requirement. Let r be 180mm, when the length of the first brick 1 is 540mm, the length of the second brick 2 is 240mm, and the length of the fourth brick 4 is 540mm +60mm (tooth socket), the distance from the first mortar joint 61 to the second mortar joint 62 is equal to the length of the fourth brick 4 (without tooth socket) minus the length of the second brick 2, i.e. 540-. And 1/3-2/3 of the length of the fourth brick 4 (without tooth sockets) is 180-360 mm, which meets the masonry requirement.

As shown in FIG. 4, when 180 < r.ltoreq.423. And (3) setting r to be larger than 180mm but infinitely close to 180mm, and substituting the value of r to be 180mm into a formula for calculation. The length of the second brick 2 is 423mm, and the length of the fourth brick placing position 4 is 180 mm. The distance from the first mortar joint 61 to the second mortar joint 62 is equal to the length of the second brick 2 minus the length of the fourth brick 4 without tooth grooves, i.e. 423 and 180mm 243 mm. And the length 1/3-2/3 of the second brick 2 is 141-282mm, which meets the masonry requirement. Let r be 435mm, the length of second brick 2 still is 423mm this moment, and the length of fourth brick space 4 still is 180 mm. Therefore, the distance from the first mortar joint 61 to the second mortar joint 62 is still: 423 and 180 ═ 243 mm. The length 1/3-2/3 of the second brick 2 is also 141-282mm, which meets the masonry requirement.

As shown in FIG. 5, when 423 < r < 600. And if r is larger than 423mm but infinitely close to 423mm, substituting the value of r as 423mm into a formula for calculation. At this time, the length of the second brick 2 is 423mm, the length of the third brick 3 is 600mm, and the length of the fourth brick 4 is 180mm +60mm (tooth socket). The distance from the first mortar joint 61 to the second mortar joint 62 is equal to the length of the second brick 2 minus the length of the fourth brick 4 without tooth socket, i.e. 423mm-180 mm-243 mm. And the length 1/3-2/3 of the second brick 2 is 141-282mm, which meets the masonry requirement. And (3) setting r to be smaller than 600mm but infinitely close to 600mm, and substituting the value of r to be 600mm into a formula for calculation. The length of the second brick 2 is 600mm and the length of the fourth brick 4 is 357mm +60mm (alveolus). The distance from the first mortar joint 61 to the second mortar joint 62 is equal to the length of the second brick 2 minus the fourth brick 4 (length without tooth socket), i.e. 600-. The length 1/3-2/3 of the second brick 2 is 200-400mm, which meets the masonry requirement.

Example 2:

S2: and determining the mortar joint thickness when bricks are stacked according to the materials used for coating the mortar joints. The mortar joint thickness is w, and in this embodiment, the mortar joint is coated with mortar. When mortar plastering seams are used, the thickness standard of the mortar plastering seams is 15mm, namely w is 15 mm.

the number of the whole bricks which can be built in each brick layer is set to be n, and the remaining length of each brick layer after the whole bricks are built is set to be r. Then n ═ x/(L + w), i.e., n ═ x/615, where n is integers using the tail-out method. The r is a remainder of x/(L + w), i.e., a remainder of x/615, i.e., r is x-615 n.

Dividing 0 to L into a plurality of intervals, and calculating the interval to which r belongs. In the embodiment, the section to which r belongs is divided into four sections, namely, r is 0, r is more than 0 and less than 180, r is more than 180 and less than 435, and r is more than 435 and less than 600.

As shown in fig. 2, when r is 0, an even number of courses can be constructed by using n bricks. Because r is x-603n, but in the actual building process, the number of the vertical mortar joints is 1 less than that of the bricks, namely when r is 0, after n whole bricks are stacked in even layers, only a wall body with the length of (x-w) is built, and a gap with the length of w (15mm) is remained (within an allowable error range during building). When bricks of odd courses are stacked, the actual masonry length of the odd courses is also (x-w) in order to make the lengths of the odd courses flush with the lengths of the even courses. The odd number layer has two brick stacking modes:

one is to cut few bricks and the simplest way to obtain bricks. Fix fifth fragment of brick 5 for 240mm +60 mm's (alveolus) standard serrated raft, third fragment of brick 3 is decided for whole brick, establishes the serrated raft that the fourth fragment of brick is e +60mm (alveolus). Namely, a standard serrated raft with the length of 240mm +60mm (serrated groove), n-1 full bricks with the length of 600mm and a serrated raft with the length of e +60mm (serrated groove) are sequentially adopted for construction, namely 240+ (n-1)600+15n + e ═ x-15, the formula is converted into e ═ x-615n +345, and the e ═ 345mm can be obtained through calculation due to the fact that r ═ x-615n and r ═ 0. This building scheme need use three kinds of types fragment of brick, nevertheless only need cut out a length be 345mm +60mm (alveolus) length the horse tooth raft can, other fragments of brick all can directly acquire, need not to process the cutting.

One mode is a symmetrical mode of left and right serrated branches. Decide third fragment of brick 3 for whole brick, fifth fragment of brick 5 all adopts the serrated racking of e +60mm (alveolus) with fourth fragment of brick 4. Namely, the step of constructing the brick sequentially comprises the step of constructing a step of e +60mm (tooth groove), the step of n-1 whole bricks of 600mm in length and the step of e +60mm (tooth groove). That is, e + (n-1)600+15n + e is x-15, and since r is x-615n and r is 0, e is 292.5 mm. I.e. the fourth brick 4 and the fifth brick 5 are both serrated at 292.5mm +60mm (flute) length. This masonry scheme only requires the use of two types of bricks, but requires the cutting of two serrated racking of 298.5mm +60mm length (flute).

The length of the second bricks 2 of the even number of courses is fixed to 240mm, and the length of the first bricks 1 is set to d. Namely, n-1 whole bricks, a brick with the length of d and a brick with the length of 240mm are sequentially adopted for building even layers. That is, x is (n-1)600+15n + d +240, and the formula is converted into x-615n is d-360, and since r is x-603n, d is calculated to be r + 360. I.e. the length of the first brick 1 is (r +360) mm and the length of the second brick 2 is 240 mm.

Odd level fifth fragment of brick is 240mm +60 mm's (alveolus) standard serrated racking with, and third fragment of brick 3 is decided for whole brick, and it is e +60 mm's (alveolus) serrated racking to establish fourth fragment of brick 4. Namely, the building of odd-numbered bricks adopts a standard serrated raft with the length of 240mm +60mm (serrated groove), n-1 whole bricks with the length of 600mm and a serrated raft with the length of e +60mm (serrated groove) in sequence for building. I.e. the length of the fifth brick 5 (without the tooth socket) is equal to the length of the second brick 2 and the number of whole bricks in odd courses is equal to the number of whole bricks in even courses. The length of the first brick 1 is therefore equal to the length of the fourth brick 4 (without a flute), i.e. d ═ e, and since d ═ r +360, said fourth brick 4 is serrated at a length of (r +360) mm +60mm (flute).

As shown in FIG. 4, when 180 < r.ltoreq.435. The even number of courses still changes the length of the first brick 1 and the second brick 2.

Setting the length of the first brick 1 in the even layers as d, and fixing the length of the second brick 2 as 435mm, namely, sequentially adopting n-1 whole bricks, one brick with the length of d and one brick with the length of 435mm to masonry the even layers. That is, x ═ (n-1)600+15n + d +435, the formula is converted to x-615n ═ d-165, and since r ═ x-615n, d ═ r +165 is calculated. I.e. the length of the first block 1 is (r +165) mm.

The lengths of a fourth brick placing position 4 (without tooth sockets) and a fifth brick placing position 5 (without tooth sockets) in the odd layers are respectively fixed to be 180mm and 240mm, namely the sum of the length of the fourth brick placing position 4 (without tooth sockets), the length of the fifth brick placing position 5 (without tooth sockets) and the thickness of the mortar joint is equal to the length of the second brick 2. That is, the fourth brick laying position 4 and the fifth brick laying position 5 are just equal to the length of the second brick 2 when being laid together through a 15mm mortar joint. It is thus possible to make the number of whole bricks of an even course equal to the number of whole bricks of an odd course, the length of the first brick 1 being equal to the length of the third brick 3, i.e. the length of the third brick being (r +165) mm.

As shown in FIG. 5, when 435 < r < 600. The length of r can be used to individually construct a block in an even number of courses. In the odd layers, the length of r can also be divided into a standard serrated racking and a serrated racking of not less than 180mm (without a serration) length. Therefore, when r is in the interval, the length of the whole brick built does not need to be changed. I.e. both the first brick 1 and the third brick 3 may be whole bricks.

And (3) setting the first brick 1 in the even number layer as a whole brick, namely sequentially adopting n whole bricks and a brick with the length of d for building. That is, d is x-603n, and r is x-603 n. I.e. the second brick 2 is a brick of length r.

With third fragment of brick 3 surely for whole brick in the odd number layer, fifth fragment of brick 5 decides the standard serrated raft for 240mm +60mm (alveolus) length, the serrated raft of length for e +60mm (alveolus) length of establishing fourth fragment of brick 4, adopt the standard serrated raft that a length is 240mm +60mm (alveolus) in proper order when building by laying bricks or stones promptly, the whole brick of n piece and a serrated raft that length is e +60mm (alveolus) are built by laying bricks or stones. Since the number of whole bricks of the odd and even courses is equal, the sum of the length of the fifth brick 5 (without tooth socket), the length of the fourth brick 4 (without tooth socket) and the thickness of one mortar joint is equal to the length of the second brick 2, i.e., 240+ e + w-r, and since w-15 mm, e-r-255 is calculated. Namely, the fourth brick 4 is serrated with the length of (r-255) mm +60mm (tooth grooves).

S4: and calculating the number of the brick layers required by the wall to be built according to the height of the brick, and setting the number of the brick layers required by the wall to be built as m, wherein m is y/(h + w). I.e., m is y/315, said m being integers using tail-removal. And the value obtained by m is the value of the brick layer to be built of the wall body to be built.

Aiming at the brick layer which is not enough to build the whole brick at the topmost part of the wall body to be built. I.e., y/315 cannot be divided exactly, y/315 yields a brick layer of remainder height. The existing masonry method adopts inclined masonry and filling by using foaming materials, and the like, and the treatment modes are various. The calculation of the code brick for this brick layer is therefore not considered in the present invention.

S5: during building, an odd layer and an even layer are taken as a cycle, and the cycle is sequentially copied and stacked until the number of the brick layers is matched with the value of m, so that brick setting data of the whole wall to be built can be output. Preferably, when the brick stacking data of the whole wall body to be built is output, the topmost amount of the wall body to be built is not enough to build the whole brick layer height, namely the remainder of y/315, is output at the same time.

For masonry, the brick joints between the upper layer of bricks and the lower layer of bricks are staggered from each other by 1/3-2/3% of a whole brick. According to the brick stacking scheme, taking the brick opposite to the right mortar joint as an example, the calculation is carried out for the example when r belongs to different intervals.

As shown in fig. 2, when r is 0, the lengths of the first brick 1, the second brick 2 and the third brick 3 are all 600m, and the length of the fourth brick 4 is 345mm +60mm (tooth socket). The distance from first mortar joint 61 to second mortar joint 62 is equal to the length of second brick 2 minus the length of fourth brick 4 (without tooth socket), i.e. 600 and 345 are 255mm, and the length 1/3-2/3 of second brick 2 is 200mm-400mm, which meets the masonry requirement. Or when the fourth brick 4 and the fifth brick 5 both adopt serrated racking with the length of 292.5mm +60mm (tooth groove), the distance from the first mortar joint 61 to the second mortar joint 62 is 600-292.5-307.5 mm, which also meets the building requirement.

As shown in FIG. 4, when 180 < r.ltoreq.435. And (3) setting r to be larger than 180mm but infinitely close to 180mm, and substituting the value of r to be 180mm into a formula for calculation. The length of the second brick 2 is 435mm, the length of the third brick 3 is 345mm, and the length of the fourth brick placing position 4 is 180 mm. The distance from the first mortar joint 61 to the second mortar joint 62 is equal to the length of the second brick 2 minus the length of the fourth brick 4 without tooth socket, i.e. 435-. And the length 1/3-2/3 of the second brick 2 is 145-290mm, which meets the masonry requirement. Let r be 435mm, the length of second brick 2 this moment is 435mm, the length of third brick 3 is 600mm, the length of fourth brick space 4 is 180 mm. The distance from first mortar joint 61 to second mortar joint 62 is equal to the length of second brick 2 minus the length of fourth brick 4 (without tooth socket), i.e. 435-. And the length 1/3-2/3 of the second brick 2 is 145-290mm, which meets the masonry requirement.

As shown in FIG. 5, when 435 < r < 600. And if r is larger than 435mm but infinitely close to 435mm, taking the value of r as 435mm and substituting the value into a formula for calculation. The length of the second block 2 is now 435mm, the length of the third block 3 is 600mm, and the length of the fourth block 4 is 180mm +60mm (alveolus). The distance from first mortar joint 61 to second mortar joint 62 is equal to the length of second brick 2 minus the length of fourth brick 4 without tooth socket, i.e. 435-180 mm 255 mm. And the length 1/3-2/3 of the second brick 2 is 145-290mm, which meets the masonry requirement. And (3) setting r to be smaller than 600mm but infinitely close to 600mm, and substituting the value of r to be 600mm into a formula for calculation. The length of the second brick 2 is then 600mm and the length of the fourth brick 4 is 345mm +60mm (alveolus). The distance from first mortar joint 61 to second mortar joint 62 is equal to the length of second brick 2 minus the length of fourth brick 4 without tooth socket, i.e. 600-. The length 1/3-2/3 of the second brick 2 is 200-400mm, which meets the masonry requirement.

In other embodiments, when the thickness w of the gray seam is not equal to 3mm or 15mm, the interval of r can be divided into four intervals of r-0, 0 < r ≦ 180, 180 < r ≦ 420+ w, and (420+ w) < r < 600, and the calculation method is the same as that of embodiment 1 and embodiment 2.

As shown in FIG. 6, since r is the remainder of x/(600+ w), the numerical value of r ranges from 0 to (600+ w), i.e., there is also a case where r is 600. ltoreq. r < (600+ w). Since r means the remaining length after n whole bricks and n vertical mortar joints are built. Therefore, when the r is more than or equal to 600 and less than (600+ w), the even-numbered layer can be used for building one more whole brick, namely n +1 whole bricks are built in the even-numbered layer. And a gap with the length of r-600 is remained after the masonry is finished, and the length of the gap is set to be f. In order to make the length of the odd courses level with the length of the even courses, the actual masonry length of the odd courses is also x-f.

Similar to the code brick scheme of odd layers when r is 0. Adopt the fragment of brick cutting few, when the fragment of brick acquireed simplest mode, fixed the fifth fragment of brick 5 for the standard serrated raft of 240mm +60mm (alveolus), third fragment of brick 3 decides for whole brick, establishes the serrated raft that the fourth fragment of brick is e +60mm (alveolus). Namely, a piece of standard serrated raft with the length of 240mm +60mm (serrated groove), n pieces of integral bricks with the length of 600mm and a serrated raft with the length of e +60mm (serrated groove) are sequentially adopted for construction, namely, 240+600n + w (n +1) + e ═ x- (r-600) is converted into w + e + r-360 ═ x- (600+ w) n, and because r ═ x- (600+ w) n, e ═ 360-w is calculated. I.e. the fourth brick 4 is serrated with (360-w) mm +60mm (grooves).

When the mode of left and right tooth racking symmetry is adopted, the third brick 3 is fixed as a whole brick, and the fifth brick 5 and the fourth brick 4 all adopt the tooth racking of e +60mm (tooth groove). Namely, the step of constructing the brick sequentially comprises the step of constructing a step of e +60mm (tooth groove), the step of n-1 whole brick of 600mm length and the step of e +60mm (tooth groove). I.e., e +600n + w (n +1) + e ═ x- (r-600), converted to 2e + r-600+ w ═ x- (600+ w) n, and calculated to give e ═ 300-w/2. Namely, the fourth brick 4 and the fifth brick 5 are both (300-w/2) mm +60mm (tooth groove) length serrated racking.

As shown in fig. 7, an operating system for calculating the stacking of wall bricks comprises:

and the input module is used for acquiring the length and height data of the wall to be built.

And the selection module provides a plurality of choices for coating materials for the mortar joint and obtains the mortar joint thickness according to the choice of the user.

And the first calculation module is used for calculating brick masonry data of two adjacent brick layers.

And the second calculation module is used for calculating the number of the brick layers required by the wall body to be built.

A computer device, comprising:

a memory and a processor.

The memory is used for storing a computer program, and the processor realizes the steps of the wall brick-stacking algorithm when executing the computer program.

A computer readable storage medium storing computer executable instructions which, when executed by a processor, implement the steps of the wall tiling algorithm.

The embodiment of the invention has the following beneficial effects: the wall brick stacking algorithm and the operation system do not need to manually calculate the types and the number of the bricks and the length value of the bricks of the non-integral bricks, the number of the layers of the bricks to be built, the types and the number of the bricks of each brick layer and the length of the bricks of the non-integral bricks can be calculated by acquiring the length and the height of the wall to be built, the required bricks can be prepared in advance before building, various building specifications are met during building, and the quality of the wall after building is guaranteed.

The above description is only for the purpose of illustrating the preferred embodiments of the present invention and is not to be construed as limiting the invention, and any modifications, equivalents, improvements and the like that fall within the spirit and principle of the present invention are intended to be included therein.

Claims

1. A wall brick stacking algorithm is characterized in that: the method comprises the following steps:

s1: acquiring length and height data of a wall to be built;

2. The wall brick stacking algorithm according to claim 1, wherein the two adjacent brick layers in S3 are divided into an odd layer and an even layer, and bricks at two ends of the odd layer are zigzag.

3. The wall brick stacking algorithm according to claim 1, wherein in step S1, the length and height data of the wall to be laid are obtained by a camera.

4. The wall brick stacking algorithm according to claim 1, wherein in step S1, the length and height data of the wall to be laid is obtained by using laser ranging.

5. The wall brick stacking algorithm according to claim 1, wherein in step S2, the mortar or adhesive is used as the material for plastering the mortar joints.

6. The wall brick stacking algorithm according to claim 1, wherein in step S4, the calculation result is an integer by using a tail-removing method.

7. The wall brick coding algorithm according to claim 6, wherein in step S5, the remainder of the calculation result in step S4 is further output.

8. A wall brick stacking operation system, comprising:

9. A computer device, comprising:

a memory and a processor;

the memory is used for storing a computer program, and the processor implements the steps of the wall brick coding algorithm according to any one of claims 1 to 7 when executing the computer program.

10. A computer-readable storage medium storing computer-executable instructions, which when executed by a processor implement the steps of the wall tiling algorithm of any one of claims 1-7.