CN111382452B - 一种汉字转图片的加密方法 - Google Patents

一种汉字转图片的加密方法 Download PDF

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CN111382452B
CN111382452B CN202010114699.XA CN202010114699A CN111382452B CN 111382452 B CN111382452 B CN 111382452B CN 202010114699 A CN202010114699 A CN 202010114699A CN 111382452 B CN111382452 B CN 111382452B
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CN111382452A (zh
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盛苏英
苏文博
曹倩瑜
黄文欢
张小美
陆平
卢成
任洁
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Nantong University
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Abstract

本发明公开了一种汉字转图片的加密方法,包括:首先将某段汉字逐个汉字转换成数值型数据,得到高位数值序列和低位数值序列;然后根据外部加密密钥以及某段待加密汉字,利用混沌系统生成混沌序列,按照混沌序列的降序、升序置乱规则分别对高位、低位数值序列进行置乱;再将置乱的高位、低位数值序列分别转换成二进制序列,按照自定义的两个二进制序列变换成一个数值序列的转换规则和自定义的R、G、B矩阵数据填放规则,将变换而成的数值序列中元素分别填放入R、G、B矩阵中,从而生成彩色图片,进而将彩色图片转换为二维码。本发明提供的方法具有良好的抵抗已知/选择明文攻击的性能,保证了汉字转图片加密方法的安全性和可行性。

Description

一种汉字转图片的加密方法
技术领域
本发明涉及数据加密领域,特别涉及一种汉字转图片的加密方法。
背景技术
随着现代网络技术的飞速发展,计算机网络已成为众多领域进行信息交换的手段。由于计算机网络是一个开放式网络,信息交换时往往面临信息被窃取、篡改和伪造等安全问题,此时信息加密技术的研究与应用势在必行。
目前大多数主流信息加密解密技术主要集中在如字母、数字、英文标点符号等单字节字符构成的信息,现有的中文字符加密算法很少,主要是根据汉字区位码进行的简单取反、区位码位置交换、异或,以及较为复杂的混沌加密等操作。现有的中文字符加密算法,所得的大多数密文可读性及可复制性太差,同时由于图片可包含的信息量较大,将汉字加密成图片不失为一种较好的密文承载方式。在此情况下,随着现代计算机技术的发展和安全性要求的不断提高,结合混沌信号的密码特性,寻求一种具有良好抗攻击性能的汉字转图片的加密方法,显得尤为重要。
发明内容
有鉴于此,本发明的目的是为了解决现有技术中的不足,提供一种汉字转图片的加密方法,利用混沌信号的密码特性对某段汉字转换而成的高位、低位数值序列分别进行置乱,并将置乱的数值序列分别转换成二进制序列,按照自定义的两个二进制序列变换成一个数值序列的转换规则、以及自定义的R、G、B矩阵数据填放规则,将变换而成的数值序列中元素分别填放入R、G、B三基色矩阵中以生成彩色图片,从而保证了汉字转图片加密方法的安全性和可行性。
本发明提供了一种汉字转图片的加密方法,包括如下几个步骤:
(1)转码:将某段汉字逐个汉字转换成数值型数据[P1i,P2i],得到高位数值序列P1={P11,P12,…,P1i,…,P1L}和低位数值序列P2={P21,P22,…,P2i,…,P2L},其中数值序列P1、P2的长度与该段汉字的长度一致,记为L,其中某段汉字来自于GB2312字符集中双字节编码的6763个汉字;
(2)产生混沌序列:
首先利用外部加密密钥(α,β),按照如下(1)-(5)公式分别计算得到混沌系统的初值x1、参数μ、初始迭代步数m、第一抽取间隔n1和第二抽取间隔n2
Figure GDA0003339914190000011
则可得,
x1=mod(KK+α,0.99998)+0.00002, (1)
μ=β+mod(KK,4-β), (2)
Figure GDA0003339914190000012
Figure GDA0003339914190000013
Figure GDA0003339914190000014
其中,α∈(0,1),β∈[3.75,4),
然后由初值(x1)、参数(μ),对如下公式(6)所示的Logistic混沌系统进行迭代,k表示迭代次数(k=1,2,…),xk+1表示第k次迭代得到的混沌信号,
xk+1=μ·xk·(1-xk) (6)
得到混沌序列X,从第m个元素开始每隔n1个元素取1个,从而形成长度为L的混沌序列Y1,并从第m个元素开始每隔n2个元素取1个,从而形成长度为L的混沌序列Y2;
(3)高位、低位数值序列置乱:
将混沌序列Y1按降序排序,根据序列Y1排序前、后的位置变化置乱规则,对高位数值序列P1={P11,P12,…,P1i,…,P1L}进行置乱,得到置乱后的高位数值序列
Figure GDA0003339914190000021
同时将混沌序列Y2按升序排序,根据序列Y2排序前、后的位置变化置乱规则,对低位数值序列P2={P21,P22,…,P2i,…,P2L}进行置乱,得到置乱后的低位数值序列
Figure GDA0003339914190000022
(4)彩色图片的生成:
首先,将置乱后的高位数值序列
Figure GDA0003339914190000023
中各元素逐个利用dec2bin(·,8)函数转换成8位二进制,得到高位二进制序列Q1,表示为Q1={Q11,Q12,Q13,..,Q18×L},同时将置乱后的低位数值序列
Figure GDA0003339914190000024
中各元素逐个利用dec2bin(·,8)函数转换成8位二进制,得到低位二进制序列Q2,表示为Q2={Q21,Q22,Q23,...,Q28×L},并按照自定义的两个二进制序列变换成一个数值序列的转换规则,得到数值序列Q3,表示为Q3={Q31,...,Q3j,...,Q32×L},其中,所述的按照自定义的两个二进制序列变换成一个数值序列的转换规则,是指依次从二进制序列Q1中取4个元素、从二进制序列Q2中取4个元素,组合成一个8位二进制序列,并利用bin2dec(·)函数将其转换成一个数值型数据,表示为Q3j=bin2dec({Q14j-3,Q14j-2,Q14j-1,Q14j,Q24j-3,Q24j-2,Q24j-1,Q24j}),其中j=1,2,...,2×L-1,2×L;
然后,确定彩色图片三基色R、G、B矩阵的大小,令R、G、B矩阵大小相等,且行数均为
Figure GDA0003339914190000025
同时按照如下公式(7)计算R、G、B矩阵的列数W,
Figure GDA0003339914190000026
接着,生成一个长度为3×W×H-2×L、各元素大小均为128的数值序列Q4={Q41,Q42,Q43,...,Q43×W×H-2×L}={128,...,128,...,128},并将数值序列Q3和数值序列Q4进行组合,得到数值序列PP={PP1,PP2,PP3,...,PP3×W×H}={Q31,Q32,...,Q32×L,Q41,Q42,...,Q43×W×H-2×L},
最后,按照自定义的R、G、B矩阵数据填放规则,将数值序列PP中元素分别填放入R、G、B矩阵中,从而生成彩色图片,并利用二维码生成器将彩色图片转换为二维码。
进一步地,步骤(1)中所述的将某段汉字逐个汉字转换成数值型数据[P1i,P2i],是指采用unicode2native(·)函数,将单个汉字转换为区位码数值数据,表示为[P1i,P2i]=[区数值序列,位数值序列]。
进一步地,步骤(4)中所述的按照自定义的R、G、B矩阵数据填放规则,将数值序列PP中元素分别填放入R、G、B矩阵中,是指:
R、G、B矩阵数据填放的初始位置参数和方向参数分别由如下所示公式(8)计算,其中R_position、G_position和B_position分别表示R、G、B矩阵数据填放的初始位置参数,R_direction、G_direction和B_direction分别表示R、G、B矩阵数据填放的方向参数,
Figure GDA0003339914190000031
当R_position=0、R_direction=0时,R矩阵从最左上角位置开始从左往右逐行填放数据,当R_position=0、R_direction=1时,R矩阵从最左上角位置开始从上往下逐列填放数据,当R_position=1、R_direction=0时,R矩阵从最右上角位置开始从右往左逐行填放数据,当R_position=1、R_direction=1时,R矩阵从最右上角位置开始从上往下逐列填放数据,当R_position=2、R_direction=0时,R矩阵从最左下角位置开始从左往右逐行填放数据,当R_position=2、R_direction=1时,R矩阵从最左下角位置开始从下往上逐列填放数据,当R_position=3、R_direction=0时,R矩阵从最右下角位置开始从右往左逐行填放数据,当R_position=3、R_direction=1时,R矩阵从最右下角位置开始从下往上逐列填放数据,其中填放的数据抽取自数值序列PP中相关元素,表示为{PP1,PP4,...,PP3t-2,...,PP3×W×H-2},其中t=1,2,3,...,W×H-1,W×H,
当G_position=0、G_direction=0时,G矩阵从最左上角位置开始从左往右逐行填放数据,当G_position=0、G_direction=1时,G矩阵从最左上角位置开始从上往下逐列填放数据,当G_position=1、G_direction=0时,G矩阵从最右上角位置开始从右往左逐行填放数据,当G_position=1、G_direction=1时,G矩阵从最右上角位置开始从上往下逐列填放数据,当G_position=2、G_direction=0时,G矩阵从最左下角位置开始从左往右逐行填放数据,当G_position=2、G_direction=1时,G矩阵从最左下角位置开始从下往上逐列填放数据,当G_position=3、G_direction=0时,G矩阵从最右下角位置开始从右往左逐行填放数据,当G_position=3、G_direction=1时,G矩阵从最右下角位置开始从下往上逐列填放数据,其中填放的数据抽取自数值序列PP中相关元素,表示为{PP2,PP5,...,PP3t-1,...,PP3×W×H-1},其中t=1,2,3,...,W×H-1,W×H,
当B_position=0、B_direction=0时,B矩阵从最左上角位置开始从左往右逐行填放数据,当B_position=0、B_direction=1时,B矩阵从最左上角位置开始从上往下逐列填放数据,当B_position=1、B_direction=0时,B矩阵从最右上角位置开始从右往左逐行填放数据,当B_position=1、B_direction=1时,B矩阵从最右上角位置开始从上往下逐列填放数据,当B_position=2、B_direction=0时,B矩阵从最左下角位置开始从左往右逐行填放数据,当B_position=2、B_direction=1时,B矩阵从最左下角位置开始从下往上逐列填放数据,当B_position=3、B_direction=0时,B矩阵从最右下角位置开始从右往左逐行填放数据,当B_position=3、B_direction=1时,B矩阵从最右下角位置开始从下往上逐列填放数据,其中填放的数据抽取自数值序列PP中相关元素,表示为{PP3,PP6,...,PP3t,...,PP3×W×H},其中t=1,2,3,...,W×H-1,W×H。
有益效果:本发明利用混沌信号的密码特性对某段汉字转换而成的高位、低位数值序列分别进行置乱,并将置乱的数值序列分别转换成二进制序列,按照自定义的两个二进制序列变换成一个数值序列的转换规则、以及自定义的R、G、B矩阵数据填放规则,将变换而成的数值序列中元素分别填放入R、G、B三基色矩阵中以生成彩色图片,具有良好的抵抗已知/选择明文攻击的性能,从而保证了汉字转图片加密方法的安全性和可行性。
附图说明
图1为本发明的汉字转图片的加密流程示意图;
图2为本发明实施例1处理得到的彩色图片以及彩色图片转换的二维码。
具体实施方式
如图1所示,本发明提供了一种汉字转图片的加密方法,包括如下几个步骤:
(1)转码:将某段汉字逐个汉字转换成数值型数据[P1i,P2i],其中某段汉字来自于GB2312字符集中双字节编码的6763个汉字,逐个汉字转换成数值型数据是指采用unicode2native(·)函数,将单个汉字转换为区位码数值数据,表示为[P1i,P2i]=[区数值序列,位数值序列],从而得到高位数值序列P1={P11,P12,…,P1i,…,P1L}和低位数值序列P2={P21,P22,…,P2i,…,P2L},其中数值序列P1、P2的长度与该段汉字的长度一致,记为L;
(2)产生混沌序列:
首先利用外部加密密钥(α,β),按照如下所示公式分别计算得到混沌系统的初值x1、参数μ、初始迭代步数m、第一抽取间隔n1和第二抽取间隔n2
Figure GDA0003339914190000051
则可得,
x1=mod(KK+α,0.99998)+0.00002,
μ=β+mod(KK,4-β),
Figure GDA0003339914190000052
Figure GDA0003339914190000053
Figure GDA0003339914190000054
其中,α∈(0,1),β∈[3.75,4),
然后由初值(x1)、参数(μ),对如下公式所示的Logistic混沌系统进行迭代,k表示迭代次数(k=1,2,…),xk+1表示第k次迭代得到的混沌信号,
xk+1=μ·xk·(1-xk)
得到混沌序列X,从第m个元素开始每隔n1个元素取1个,从而形成长度为L的混沌序列Y1,并从第m个元素开始每隔n2个元素取1个,从而形成长度为L的混沌序列Y2;
(3)高位、低位数值序列置乱:
将混沌序列Y1按降序排序,根据序列Y1排序前、后的位置变化置乱规则,对高位数值序列P1={P11,P12,…,P1i,…,P1L}进行置乱,得到置乱后的高位数值序列
Figure GDA0003339914190000061
同时将混沌序列Y2按升序排序,根据序列Y2排序前、后的位置变化置乱规则,对低位数值序列P2={P21,P22,…,P2i,…,P2L}进行置乱,得到置乱后的低位数值序列
Figure GDA0003339914190000062
(4)彩色图片的生成:
首先,将置乱后的高位数值序列
Figure GDA0003339914190000063
中各元素逐个利用dec2bin(·,8)函数转换成8位二进制,得到高位二进制序列Q1,表示为Q1={Q11,Q12,Q13,...,Q18×L},同时将置乱后的低位数值序列
Figure GDA0003339914190000064
中各元素逐个利用dec2bin(·,8)函数转换成8位二进制,得到低位二进制序列Q2,表示为Q2={Q21,Q22,Q23,...,Q28×L},并按照自定义的两个二进制序列变换成一个数值序列的转换规则,得到数值序列Q3,表示为Q3={Q31,...,Q3j,...,Q32×L},其中,所述的按照自定义的两个二进制序列变换成一个数值序列的转换规则,是指依次从二进制序列Q1中取4个元素、从二进制序列Q2中取4个元素,组合成一个8位二进制序列,并利用bin2dec(·)函数将其转换成一个数值型数据,表示为Q3j=bin2dec({Q14j-3,Q14j-2,Q14j-1,Q14j,Q24j-3,Q24j-2,Q24j-1,Q24j}),其中j=1,2,...,2×L-1,2×L,
然后,确定彩色图片三基色R、G、B矩阵的大小,令R、G、B矩阵大小相等,且行数均为
Figure GDA0003339914190000065
同时按照如下所示公式计算R、G、B矩阵的列数W,
Figure GDA0003339914190000066
接着,生成一个长度为3×W×H-2×L、各元素大小均为128的数值序列Q4={Q41,Q42,Q43,...,Q43×W×H-2×L}={128,...,128,...,128},并将数值序列Q3和数值序列Q4进行组合,得到数值序列PP={PP1,PP2,PP3,...,PP3×W×H}={Q31,Q32,...,Q32×L,Q41,Q42,...,Q43×W×H-2×L},
最后,按照自定义的R、G、B矩阵数据填放规则,将数值序列PP中元素分别填放入R、G、B矩阵中,即R、G、B矩阵数据填放的初始位置参数和方向参数分别由如下所示公式计算,其中R_position、G_position和B_position分别表示R、G、B矩阵数据填放的初始位置参数,R_direction、G_direction和B_direction分别表示R、G、B矩阵数据填放的方向参数,
Figure GDA0003339914190000071
当R_position=0、R_direction=0时,R矩阵从最左上角位置开始从左往右逐行填放数据,当R_position=0、R_direction=1时,R矩阵从最左上角位置开始从上往下逐列填放数据,当R_position=1、R_direction=0时,R矩阵从最右上角位置开始从右往左逐行填放数据,当R_position=1、R_direction=1时,R矩阵从最右上角位置开始从上往下逐列填放数据,当R_position=2、R_direction=0时,R矩阵从最左下角位置开始从左往右逐行填放数据,当R_position=2、R_direction=1时,R矩阵从最左下角位置开始从下往上逐列填放数据,当R_position=3、R_direction=0时,R矩阵从最右下角位置开始从右往左逐行填放数据,当R_position=3、R_direction=1时,R矩阵从最右下角位置开始从下往上逐列填放数据,其中填放的数据抽取自数值序列PP中相关元素,表示为{PP1,PP4,...,PP3t-2,...,PP3×W×H-2},其中t=1,2,3,...,W×H-1,W×H,
当G_position=0、G_direction=0时,G矩阵从最左上角位置开始从左往右逐行填放数据,当G_position=0、G_direction=1时,G矩阵从最左上角位置开始从上往下逐列填放数据,当G_position=1、G_direction=0时,G矩阵从最右上角位置开始从右往左逐行填放数据,当G_position=1、G_direction=1时,G矩阵从最右上角位置开始从上往下逐列填放数据,当G_position=2、G_direction=0时,G矩阵从最左下角位置开始从左往右逐行填放数据,当G_position=2、G_direction=1时,G矩阵从最左下角位置开始从下往上逐列填放数据,当G_position=3、G_direction=0时,G矩阵从最右下角位置开始从右往左逐行填放数据,当G_position=3、G_direction=1时,G矩阵从最右下角位置开始从下往上逐列填放数据,其中填放的数据抽取自数值序列PP中相关元素,表示为{PP2,PP5,...,PP3t-1,...,PP3×W×H-1},其中t=1,2,3,...,W×H-1,W×H,
当B_position=0、B_direction=0时,B矩阵从最左上角位置开始从左往右逐行填放数据,当B_position=0、B_direction=1时,B矩阵从最左上角位置开始从上往下逐列填放数据,当B_position=1、B_direction=0时,B矩阵从最右上角位置开始从右往左逐行填放数据,当B_position=1、B_direction=1时,B矩阵从最右上角位置开始从上往下逐列填放数据,当B_position=2、B_direction=0时,B矩阵从最左下角位置开始从左往右逐行填放数据,当B_position=2、B_direction=1时,B矩阵从最左下角位置开始从下往上逐列填放数据,当B_position=3、B_direction=0时,B矩阵从最右下角位置开始从右往左逐行填放数据,当B_position=3、B_direction=1时,B矩阵从最右下角位置开始从下往上逐列填放数据,其中填放的数据抽取自数值序列PP中相关元素,表示为{PP3,PP6,...,PP3t,...,PP3×W×H},其中t=1,2,3,...,W×H-1,W×H,
从而生成彩色图片,并利用二维码生成器将彩色图片转换为二维码。
下面结合具体实施例对本发明作进一步说明:
实施例1
按照上述具体实施方式中一种汉字转图片的加密方法,步骤如下:
(1)取某段汉字为“一种汉字转图片的加密方法,是一种比较简单、可行的方法。图片是指由图形、图像等构成的平面媒体。图片的格式很多,但总体上可以分为点阵图和矢量图两大类。混沌的特征是原来遵循简单物理规律的有序运动形态,在某种条件下突然偏离预期的规律性而变成了无序的形态。混沌是指确定性动力学系统因对初值敏感而表现出的不可预测的、类似随机性的运动。又称浑沌。英语词源于希腊语,原始含义是宇宙初开之前的景象,基本含义主要指混乱、无序的状态。作为科学术语,混沌一词特指一种运动形态。极限点附近,这一系列分岔在参数空间和相空间都表现出尺度变换下的不变性,即自相似性。使用重正化群计算可得到这些分岔过程的一套普适常数,它们与实验事实相符。”,逐个汉字转换成数值型数据,从而得到高位数值序列P1={210,214,186,215,215,205,198,181,188,195,183,183,163,202,210,214,177,189,188,181,161,191,208,181,183,183,161,205,198,202,214,211,205,208,161,205,207,181,185,179,181,198,195,195,204,161,205,198,181,184,202,186,182,163,181,215,204,201,191,210,183,206,181,213,205,186,202,193,205,193,180,192,161,187,227,181,204,213,202,212,192,215,209,188,181,206,192,185,194,181,211,208,212,182,208,204,163,212,196,214,204,188,207,205,200,198,192,212,198,181,185,194,208,182,177,179,193,206,208,181,208,204,161,187,227,202,214,200,182,208,182,193,209,207,205,210,182,179,214,195,184,182,177,207,179,181,178,191,212,178,181,161,192,203,203,187,208,181,212,182,161,211,179,187,227,161,211,211,180,212,211,207,192,211,163,212,202,186,210,202,211,214,179,191,214,199,181,190,207,163,187,177,186,210,214,210,214,187,194,161,206,208,181,215,204,161,215,206,191,209,202,211,163,187,227,210,180,204,214,210,214,212,182,208,204,161,188,207,181,184,189,163,213,210,207,193,183,178,212,178,202,191,188,186,207,191,188,182,177,207,179,179,182,177,187,207,181,178,177,208,163,188,215,207,203,208,161,202,211,214,213,187,200,188,203,191,181,181,213,208,183,178,185,179,181,210,204,198,202,179,202,163,203,195,211,202,209,202,202,207,183,161}和低位数值序列P2={187,214,186,214,170,188,172,196,211,220,189,168,172,199,187,214,200,207,242,165,162,201,208,196,189,168,163,188,172,199,184,201,188,206,162,188,241,200,185,201,196,189,230,189,229,163,188,172,196,241,189,220,224,172,171,220,229,207,201,212,214,170,227,243,188,205,184,191,188,189,243,224,163,236,231,196,216,247,199,173,180,241,173,242,165,239,237,230,201,196,208,242,203,175,206,172,172,218,179,214,245,254,194,187,187,171,235,164,218,196,230,201,212,248,228,201,203,222,242,196,206,172,163,236,231,199,184,183,168,212,175,166,167,181,179,242,212,245,181,244,208,248,237,214,246,196,187,201,164,226,196,162,224,198,230,250,212,196,203,175,163,214,198,235,231,163,162,239,202,180,218,163,176,239,172,173,188,172,229,199,238,230,245,170,174,176,196,176,243,172,249,190,172,229,247,170,184,236,210,162,222,242,196,180,172,163,247,170,198,167,245,239,172,236,231,187,202,216,184,187,214,203,175,206,172,163,171,222,227,189,252,172,226,187,181,208,214,237,218,206,253,213,228,205,224,213,228,188,237,214,246,223,200,228,187,194,196,187,228,212,172,180,212,224,198,212,163,185,195,216,253,175,186,198,227,201,195,189,226,169,214,237,253,204,196,187,215,213,202,163,253,172,252,199,235,181,233,194,181,224,251,163},其中数值序列P1、P2的长度与该段汉字的长度均为302;
(2)首先利用外部加密密钥α=0.12345,β=3.75,分别计算得到混沌系统的初值x1=0.513197447411003、参数μ=3.889727447411003、初始迭代步数m=439和抽取间隔n1=10、n2=1,
然后由初值x1和参数μ,对Logistic混沌系统进行迭代,得到混沌序列X={x1,x2,...,xk,...},从混沌序列X的第439个元素开始每隔10个元素取1个,从而形成长度为302的混沌序列Y1={Y11,...,Y1k,...,Y1302},并从混沌序列X的第439个元素开始每隔1个元素取1个,从而形成长度为302的混沌序列Y2={Y21,...,Y2k,...,Y2302};
(3)将混沌序列Y1按降序排序,根据序列Y1排序前、后的位置变化置乱规则,对高位数值序列P1进行置乱,得到置乱后的高位数值序列
Figure GDA0003339914190000091
Figure GDA0003339914190000092
Figure GDA0003339914190000101
Figure GDA0003339914190000102
同时将混沌序列Y2按升序排序,根据序列Y2排序前、后的位置变化置乱规则,低位数值序列P2进行置乱,得到置乱后的低位数值序列
Figure GDA0003339914190000103
Figure GDA0003339914190000104
(4)首先,将置乱后的高位数值序列
Figure GDA0003339914190000105
中各元素逐个利用dec2bin(·,8)函数转换成8位二进制,得到高位二进制序列Q1={1,0,1,1,0,0,1,0,1,0,1,1,1,0,1,0,1,0,1,1,0,1,0,1,1,0,1,1,1,1,0,0,1,1,0,1,0,0,1,0,1,0,1,1,0,1,0,1,1,1,0,0,1,1,0,1,1,1,0,1,0,0,1,1,1,0,1,0,0,0,0,1,1,1,0,1,0,0,0,0,1,1,0,0,0,0,0,1,1,1,0,0,1,1,0,0,1,0,1,1,0,1,0,1,1,1,0,0,0,1,1,0,1,1,0,0,1,0,1,0,1,1,0,0,1,1,0,0,1,1,0,0,1,1,1,1,1,1,0,1,0,0,1,0,1,0,1,0,0,0,0,1,1,0,1,1,0,1,0,1,1,0,1,1,0,1,0,0,1,1,0,0,0,0,0,1,1,1,0,1,0,0,0,0,1,1,0,0,1,1,1,1,1,0,1,1,0,1,0,1,1,0,1,0,0,0,1,1,1,1,0,1,0,0,0,1,1,1,0,0,0,0,0,1,1,1,0,1,0,1,1,0,1,1,0,0,1,0,1,0,1,1,0,1,0,0,0,0,1,1,0,1,0,1,1,0,1,0,1,1,0,1,0,1,1,0,1,1,0,0,0,1,1,0,1,1,1,0,1,1,1,1,0,1,0,0,1,1,1,1,0,1,0,1,1,1,1,0,1,1,1,0,1,0,1,1,0,0,1,1,0,0,1,0,1,1,1,1,0,0,1,0,1,1,1,1,0,0,1,1,0,0,1,1,1,1,1,0,1,1,0,1,0,1,1,0,1,1,1,1,0,1,1,0,1,1,1,0,1,0,1,0,1,1,1,1,0,0,1,0,1,1,0,0,1,0,1,0,1,1,0,1,0,0,1,0,1,1,0,1,1,0,1,1,0,0,1,1,1,1,1,0,1,1,1,0,1,0,1,0,1,1,1,0,1,0,1,1,0,0,1,1,0,1,1,0,1,1,1,1,1,1,1,1,0,1,0,0,1,1,1,0,1,0,0,0,0,1,1,1,0,0,1,1,1,0,1,0,1,1,0,0,1,0,1,0,1,0,0,0,1,1,1,0,1,1,0,0,0,1,1,1,0,1,0,1,0,0,1,0,1,1,0,1,0,1,1,1,0,1,0,1,1,1,1,1,0,1,0,1,0,0,1,0,1,1,0,1,1,1,1,0,1,1,1,1,0,0,1,1,0,0,0,0,1,0,1,0,1,1,0,0,1,1,1,1,0,1,0,1,1,1,1,0,1,1,0,1,0,1,1,1,0,1,0,0,0,0,1,1,0,1,0,0,1,1,1,1,0,1,0,0,1,0,1,1,0,1,0,0,1,0,1,1,0,0,1,1,0,1,1,0,1,1,0,1,1,0,1,0,1,1,1,0,0,1,1,0,1,1,0,1,1,0,1,1,0,0,0,1,1,1,1,1,0,0,0,1,1,0,1,1,0,1,0,1,1,0,1,1,0,1,0,1,1,0,1,0,1,1,1,0,1,1,1,1,0,1,0,0,1,1,1,1,0,0,1,0,1,0,1,1,0,1,0,1,0,0,1,1,0,0,0,1,1,0,1,1,0,1,0,1,0,1,1,1,0,0,0,0,0,1,1,0,1,1,0,1,0,1,1,1,0,0,1,0,1,0,1,0,1,0,0,0,1,1,1,1,0,0,1,0,1,0,1,0,1,1,0,0,1,0,1,0,1,1,0,1,1,0,1,1,0,0,1,0,1,0,1,0,1,1,0,1,1,1,1,0,1,1,0,0,1,1,1,1,1,0,0,0,1,1,1,0,1,1,1,0,1,1,1,0,1,1,1,1,1,1,1,1,0,0,1,0,1,0,1,0,1,0,0,0,0,1,1,0,1,1,0,0,1,0,1,1,0,0,1,0,1,0,1,1,0,0,1,0,0,0,1,0,1,0,0,0,0,1,1,1,0,0,0,1,1,0,1,1,0,0,0,0,0,0,1,1,0,0,1,1,0,0,1,1,0,1,0,0,1,0,1,1,0,1,0,0,0,0,1,1,0,0,1,1,1,1,1,1,0,0,1,0,1,0,1,0,1,0,0,0,0,1,1,1,0,0,1,0,1,0,1,0,1,0,0,0,0,1,1,1,0,0,1,1,1,1,1,1,0,1,0,1,0,0,1,1,0,1,0,0,1,1,1,1,0,0,1,0,1,1,1,1,0,0,1,1,0,1,1,1,0,1,0,1,1,1,1,1,0,1,0,1,0,1,1,0,1,0,0,0,0,1,1,1,0,1,0,1,0,1,1,1,0,0,0,0,1,1,1,1,0,0,1,0,1,0,1,1,0,1,0,0,0,0,1,1,0,0,1,1,1,1,1,1,0,0,0,0,1,0,1,1,0,0,1,1,1,1,1,1,0,0,1,1,0,1,1,1,0,1,0,0,1,1,1,0,1,1,0,1,0,1,1,0,1,1,1,1,1,1,1,0,1,1,0,1,0,1,1,0,1,0,0,0,1,1,1,1,0,1,0,0,0,0,1,1,0,1,0,0,0,0,1,0,1,1,1,1,1,1,1,1,0,0,1,1,0,0,1,0,1,1,1,0,1,1,1,1,0,1,0,0,0,0,1,1,0,0,1,1,0,0,1,1,0,0,0,0,1,1,1,0,1,1,1,1,0,0,1,1,0,1,0,1,1,0,1,1,0,1,0,1,1,0,1,0,1,1,0,1,1,1,1,0,1,0,0,0,1,1,1,1,0,0,1,0,1,1,1,1,0,1,0,1,1,0,1,1,0,1,0,1,0,0,1,0,1,1,1,0,0,1,1,1,0,0,1,0,0,0,1,1,0,0,1,1,0,1,1,0,1,1,1,1,0,0,1,0,1,1,1,1,1,1,1,0,1,1,0,1,0,1,1,1,0,1,0,0,1,1,1,0,1,1,0,1,1,0,1,0,1,1,0,0,1,1,1,1,0,0,1,1,1,0,1,1,0,1,0,0,1,1,1,0,1,1,0,1,1,0,1,1,0,1,0,0,1,0,1,1,0,1,0,1,0,0,1,1,0,1,0,0,1,0,1,0,1,1,0,0,0,1,1,1,0,1,0,0,0,1,1,0,1,1,1,0,1,1,1,0,1,1,0,1,1,1,1,1,0,1,0,0,0,0,1,1,0,0,1,0,1,1,1,0,1,1,0,1,1,0,1,0,1,1,0,0,0,1,1,0,1,1,0,0,1,1,1,1,0,0,1,0,1,1,1,0,1,1,1,1,1,1,1,1,0,1,0,0,1,1,1,1,0,0,1,0,1,1,1,1,0,1,0,1,1,1,1,0,1,1,0,1,0,0,1,0,1,1,1,1,1,1,1,0,1,1,0,1,0,1,1,0,1,1,0,1,1,1,1,1,0,0,1,1,1,1,1,1,0,0,1,0,1,0,1,1,0,1,0,1,1,0,1,0,1,1,0,1,1,0,1,0,1,1,1,1,1,0,1,1,0,0,0,0,1,1,1,0,1,0,0,0,1,1,1,0,1,1,1,1,0,1,1,0,1,1,0,1,0,1,1,0,1,0,0,0,1,1,1,1,0,1,0,1,0,0,1,0,1,0,0,0,0,1,1,1,0,1,0,0,1,0,1,0,1,1,1,0,0,0,1,1,0,0,1,0,1,0,1,0,1,1,1,1,1,1,1,0,1,0,0,0,0,1,1,0,1,1,1,1,0,0,1,0,1,1,1,0,0,1,1,1,0,1,0,1,1,1,1,1,0,0,1,1,0,0,1,0,1,1,0,1,1,0,1,0,1,1,0,0,1,0,1,0,1,1,0,1,1,1,1,0,1,0,0,0,1,1,1,1,0,0,0,0,0,0,1,0,1,1,1,1,0,0,1,1,0,0,1,0,0,1,1,1,0,0,1,1,0,0,1,0,1,1,0,0,1,1,1,1,0,1,0,1,0,1,1,0,1,1,0,1,0,1,1,1,1,0,0,0,1,1,1,0,1,1,0,1,1,0,1,0,1,1,0,1,0,1,1,1,0,0,0,0,0,0,1,0,1,1,0,1,0,1,1,1,0,0,1,0,1,0,1,0,1,1,1,0,1,1,1,1,0,0,1,1,0,1,1,1,0,1,0,0,0,0,1,0,1,1,0,1,1,1,1,1,0,1,0,1,1,0,1,1,0,0,1,0,1,0,1,0,1,1,1,0,0,0,1,0,1,0,0,0,1,1,1,1,0,1,0,0,1,1,1,1,0,1,0,0,0,0,1,1,0,0,0,1,1,0,1,0,1,1,0,0,1,1,1,1,0,0,1,0,1,0,1,1,0,0,0,0,1,0,1,1,0,0,1,1,0,0,1,0,1,1,0,1,0,1,1,1,0,1,0,1,1,1,1,1,0,0,1,1,1,1,1,1,0,0,1,1,0,1,1,1,0,1,0,0,0,1,1,1,0,1,0,1,0,0,1,1,0,0,1,1,0,0,1,1,1,0,0,0,1,1,1,0,1,1,1,0,1,1,1,1,0,0,1,1,1,1,1,0,1,0,0,0,0,1,1,0,1,1,0,0,0,1,1,0,1,1,0,1,0,1,1,0,1,1,1,0,0,0,1,0,1,1,0,1,0,1,1,0,1,1,0,0,1,1,1,1,0,0,0,0,1,1,1,1,0,1,0,0,0,0,1,1,0,0,0,1,1,0,1,1,0,0,1,1,1,0,1,0,1,1,1,0,1,1,1,1,0,0,0,0,0,0,1,1,0,0,0,0,0,1,1,0,1,0,0,0,0,1,1,1,0,1,0,1,1,0,1,0,1,1,0,1,0,1,1,1,0,1,0,0,0,1,1,1,0,1,0,1,0,0,1,0,1,1,0,0,1,1,1,1,0,0,1,1,1,0,1,0,1,1,0,0,1,1,1,1,1,0,0,0,1,1,1,1,0,1,0,1,1,0,1,0,1,1,0,0,1,1,1,0,1,1,0,1,1,0,1,0,1,1,0,1,1,1,1,0,1,1,1,0,1,0,1,0,1,0,0,0,0,1,1,1,0,0,1,1,1,1,1,0,1,1,1,0,1,1,1,1,0,1,0,1,1,0,1,1,0,0,1,1,1,1,1,1,0,0,1,0,0,0,1,1,0,0,0,0,0,0,1,1,0,1,0,1,1,0,1,1,0,1,0,1,0,1,1,0,1,1,0,0,0,1,1,1,0,1,0,0,1,0,1,0,1,1,1,0,0,1,1,1,0,0,0,0,0,0,1,1,0,1,0,0,1,0,1,1,0,0,0,1,1,0,1,0,1,1,0,0,0,1,1,1,0,1,0,0,1,0,1,1,0,0,1,1,0,1,1,1,0,1,0,1,0,0,1,0,1,0,0,0,0,1,1,1,0,0,0,1,0,0,1,1,0,0,0,0,1,1,1,0,1,1,0,1,0,1,1,1,0,1,0,0,0,0,1,1,0,0,1,1,1,0},同时将置乱后的低位数值序列
Figure GDA0003339914190000111
中各元素逐个利用dec2bin(·,8)函数转换成8位二进制,得到低位二进制序列Q2={1,1,1,0,0,1,1,0,1,0,1,0,1,1,0,0,1,1,0,1,0,1,1,0,1,1,1,0,0,0,0,0,1,1,1,0,1,1,0,1,1,1,0,0,1,0,0,1,1,0,1,1,1,0,0,1,1,1,1,0,1,1,0,0,1,1,1,1,0,0,1,1,1,1,0,0,0,0,1,1,1,1,1,0,0,1,1,0,1,0,1,1,1,1,0,0,1,1,0,1,0,1,0,1,1,1,0,0,1,0,0,1,1,1,1,0,1,0,0,1,1,0,1,0,0,1,1,1,1,1,1,0,0,0,1,0,1,0,1,1,1,1,0,0,1,0,1,1,1,0,1,0,1,0,1,1,1,0,1,1,1,0,1,0,0,0,1,1,1,0,1,0,1,1,0,0,1,0,1,0,1,1,0,0,1,0,1,1,0,0,1,1,1,1,1,1,0,0,1,0,1,0,1,0,1,1,1,1,1,0,1,1,1,0,1,1,1,1,0,0,1,0,0,1,1,1,1,0,0,0,0,0,1,1,0,0,1,0,0,1,1,0,1,0,0,1,0,0,1,1,1,1,0,1,0,1,1,1,1,1,0,1,1,0,1,0,1,0,0,0,1,1,1,1,0,1,1,0,1,0,1,0,1,0,1,1,0,0,1,0,1,0,0,0,1,1,1,0,1,0,1,1,0,0,1,0,1,0,1,1,0,0,1,1,0,0,0,1,0,0,1,1,0,1,1,1,0,0,1,1,0,1,1,1,1,0,1,1,0,0,0,0,1,1,1,1,0,1,0,0,0,0,1,1,0,0,1,1,0,1,1,1,0,0,1,1,1,1,1,1,0,0,0,1,1,1,1,0,1,0,0,1,0,1,1,0,1,1,0,1,1,1,1,1,0,0,1,0,1,1,1,1,0,0,1,1,1,0,1,1,0,0,0,1,1,0,1,0,1,1,1,1,0,1,1,1,1,1,1,1,0,0,1,1,0,0,1,0,1,0,1,0,1,0,1,1,1,1,1,1,1,0,1,0,1,1,1,1,0,0,0,1,0,0,1,0,1,1,1,1,0,0,1,1,0,0,0,1,1,1,1,1,0,0,0,1,1,1,1,1,1,1,0,0,0,1,1,0,1,0,1,0,1,0,1,1,0,1,1,0,0,0,1,0,1,1,0,1,0,0,1,1,0,1,1,1,0,0,1,1,0,0,1,0,0,1,1,0,1,0,0,0,1,1,1,0,1,0,1,1,0,1,1,0,1,0,0,1,0,0,1,0,1,0,1,1,0,0,1,1,0,0,1,0,0,1,1,1,1,1,0,0,0,1,1,1,0,1,0,1,0,0,1,0,1,0,0,0,1,0,1,0,1,1,1,1,0,1,1,1,0,0,0,1,0,0,1,1,0,0,1,0,1,0,1,1,0,1,0,1,1,0,1,0,1,0,1,1,0,0,1,1,1,0,0,1,0,1,1,1,1,0,0,1,0,0,1,1,1,0,0,0,1,0,1,1,0,0,1,0,1,1,1,0,1,0,1,1,0,0,1,1,1,1,0,0,1,0,1,1,0,0,1,0,0,0,1,1,1,0,0,1,0,0,1,0,1,1,1,0,0,1,1,1,0,1,0,0,1,1,1,1,0,1,0,0,0,0,1,0,1,0,1,1,0,0,1,1,1,0,0,0,0,0,1,1,0,0,1,1,1,0,1,0,1,0,1,1,0,0,1,1,0,1,0,1,1,0,1,1,0,1,0,1,0,0,1,1,1,0,1,0,1,1,1,1,1,0,0,1,0,0,1,1,0,1,0,1,0,0,1,1,0,0,1,1,1,1,1,0,1,1,1,0,0,0,1,1,0,0,1,0,1,1,1,1,0,1,1,1,1,0,1,0,1,1,0,1,0,1,1,1,0,0,0,0,1,0,1,0,1,0,1,1,1,1,1,0,1,0,1,1,0,0,1,1,0,0,0,1,1,0,1,1,0,1,0,1,1,1,1,1,0,0,0,1,0,0,1,1,0,0,1,0,0,1,1,1,1,0,0,0,1,1,1,0,1,0,0,0,1,1,1,1,0,0,1,0,0,0,1,0,1,1,1,0,0,0,1,1,0,1,0,1,1,0,1,0,1,1,1,1,1,0,1,1,1,0,1,1,1,0,1,1,1,0,1,1,0,1,1,0,1,0,0,0,1,0,1,0,1,0,0,0,1,1,1,1,1,0,0,1,1,0,1,0,1,1,0,1,0,1,1,0,1,1,1,1,1,1,1,1,1,0,0,1,1,1,1,1,0,0,1,1,1,0,1,1,0,1,0,1,0,0,1,0,1,1,0,1,0,0,1,1,1,1,1,0,1,1,1,0,1,0,1,0,1,1,1,1,1,1,0,1,0,0,1,1,1,1,0,1,1,1,1,0,1,1,1,0,0,0,1,1,0,0,0,1,0,0,1,1,0,1,1,0,1,0,1,1,0,1,0,1,1,0,1,1,1,0,0,1,1,0,1,1,1,0,1,1,1,1,1,1,0,0,0,1,1,1,1,0,1,1,1,1,0,0,1,0,1,1,1,1,0,0,1,0,1,1,1,0,1,1,1,0,1,1,1,0,1,1,1,1,0,1,0,1,1,0,1,1,0,1,0,1,0,1,1,0,1,0,1,0,1,1,1,0,1,0,0,1,1,1,1,1,1,1,1,1,0,0,1,0,1,0,1,0,1,0,1,0,1,1,1,0,1,1,1,1,1,0,0,0,1,1,1,1,1,0,0,0,0,0,1,1,1,0,0,1,0,1,1,1,1,0,1,0,1,1,1,1,1,0,0,1,0,0,1,1,0,1,0,1,0,0,1,1,1,0,1,1,0,1,1,0,1,0,0,0,1,1,1,0,1,0,1,1,0,1,1,0,1,1,1,0,1,1,1,1,1,1,1,1,0,1,1,0,1,0,0,1,1,0,1,1,1,1,0,0,1,1,1,1,0,1,0,1,1,0,1,0,1,0,1,1,1,1,1,0,1,0,1,1,0,0,1,1,0,0,0,1,1,1,1,1,0,1,0,0,0,0,1,1,1,0,1,1,1,1,1,0,1,0,1,1,0,0,1,0,1,1,0,1,0,1,1,0,1,1,0,0,0,0,1,1,0,1,0,1,1,0,1,1,1,0,0,1,0,0,1,0,1,1,1,0,0,0,1,0,1,1,0,0,0,0,1,0,1,0,1,0,1,0,1,0,1,1,1,0,1,1,1,1,1,0,1,1,0,0,1,1,0,0,0,1,0,0,1,0,1,1,1,1,0,0,1,1,1,0,1,1,0,0,1,1,0,0,0,0,1,0,1,0,1,0,1,0,0,0,1,1,0,1,0,0,1,0,1,0,1,1,0,0,0,0,1,1,1,0,1,1,1,1,1,1,1,0,1,1,0,0,1,0,1,1,0,1,0,1,1,1,1,0,1,1,1,1,1,0,1,0,1,1,0,0,1,1,0,1,0,0,0,0,1,0,1,0,0,0,1,1,1,0,1,0,0,0,1,1,1,1,0,0,0,1,0,0,1,0,1,0,1,1,0,1,1,1,1,1,0,0,1,0,1,1,0,1,1,1,1,0,1,1,1,0,0,0,0,0,1,0,1,0,1,1,0,0,1,1,1,1,1,0,0,0,1,1,0,1,0,1,0,0,1,1,0,1,1,1,0,0,1,1,1,1,0,1,0,1,1,1,0,1,1,0,0,0,1,1,1,0,0,0,1,0,1,1,0,0,1,1,0,1,1,1,0,0,0,1,0,0,1,1,1,0,0,1,1,1,1,1,0,0,0,1,0,0,1,1,0,0,1,1,1,0,1,1,1,0,0,0,1,1,1,1,0,0,1,1,0,0,1,1,0,0,0,1,0,0,1,1,1,0,0,1,1,0,1,1,0,1,0,1,0,0,1,0,1,1,1,1,0,1,1,1,0,1,0,1,1,0,1,1,0,1,1,1,1,1,1,1,1,1,0,1,1,1,1,0,1,0,1,0,1,0,1,0,1,1,1,1,0,1,1,0,1,1,0,0,1,1,1,1,0,1,1,0,1,0,1,1,1,1,0,1,0,1,1,1,1,0,0,1,0,1,1,1,1,1,0,1,1,0,1,0,1,1,1,0,1,1,1,1,0,0,0,1,1,0,1,1,1,1,1,1,0,1,1,0,1,1,1,1,0,0,1,1,0,0,1,0,0,1,1,1,1,0,0,1,1,1,1,0,1,1,1,1,0,0,1,0,1,1,1,1,0,1,1,1,0,1,0,1,1,0,1,0,1,0,1,0,1,1,1,1,0,0,1,0,0,1,1,0,1,0,0,0,1,0,1,0,1,0,1,1,0,0,1,0,1,0,1,0,0,0,1,1,0,0,1,0,1,0,1,1,0,0,0,1,0,0,1,1,1,1,0,0,1,1,1,1,0,0,0,0,1,0,1,0,1,0,1,1,0,0,1,1,1,1,0,1,0,1,1,0,1,0,0,0,1,1,1,0,1,0,1,1,1,0,1,0,1,0,1,0,1,0,1,1,0,0,1,0,0,0,1,0,1,1,1,0,1,0,1,0,1,0,0,0,1,1,1,0,1,1,1,0,1,1,1,0,1,0,1,0,0,0,1,0,1,1,1,1,0,1,1,0,1,0,1,1,1,1,1,1,1,1,1,0,1,0,1,0,1,1,1,0,1,1,1,1,0,0,0,1,1,0,1,1,0,0,0,1,0,0,1,1,1,1,0,1,1,1,1,0,1,1,1,1,0,1,1,0,1,1,1,0,1,1,1,1,1,0,0,1,1,1,1,1,0,0,0,1,0,0,1,0,1,0,0,0,1,0,1,0,1,0,0,0,1,0,1,0,1,1,1,1,0,1,1,1,0,0,0,1,1,1,1,1,0,1,1,0,0,0,1,0,1,1,0,1,0,1,1,0,1,0,0,0,1,1,1,1,1,0,0,0,0,0,1,0,1,1,1,0,0,0,1,1,1,0,1,1,0,1,1,1,1,1,1,0,0,1,1,0,1,0,1,0,0,1,1,1,0,1,1,0,1,0,1,1,1,1,1,1,0,1,1,1,1,1,1,1,1,0,1,1,0,0,1,0,1,1,1,1,1,1,0,0,1,0,1,1,1,0,0,1,0,1,1,0,1,1,0,1,0,0,1,1,1,1,1,0,0,0,1,1,1,1,0,0,1,0,1,1,1,0,1,1,0,1,1,1,0,0,0,1,0,0,1,1,0,0,1,1,1,0,1,1,0,0,0,1,0,0,1,1,1,1,1,1,0,1,1,1,0,1,0,1,1,0,1,1,0,1,0,1,0,1,1,0,1,1,1,1,0,0,1,1,0,1,0,1,0,0,1,1,1,1,0,0,1,0,1,1,1,1,0,0,0,1,1,0,1,0,0,1,0,1,1,1,0,0,0,1,1,0,1,0,1,1,0,1,0,0},再依次从二进制序列Q1中取4个元素、从二进制序列Q2中取4个元素,组合成一个8位的二进制序列,并利用bin2dec(·)函数将此序列转换成数值型数据,从而得到数值序列Q3={222,28,206,216,219,54,222,160,246,89,218,99,229,227,246,90,221,7,242,5,244,22,229,240,219,51,240,105,244,201,228,181,244,174,231,88,205,70,207,103,206,37,228,82,230,80,229,175,223,38,204,95,231,71,240,67,246,40,240,201,230,16,247,57,223,54,206,7,219,206,230,90,230,47,206,216,228,240,218,176,219,240,241,254,218,39,219,162,218,217,218,245,218,29,206,49,207,61,240,239,218,220,218,156,229,243,223,250,242,78,204,87,244,237,218,24,205,90,218,23,242,53,223,35,230,110,243,96,207,58,219,240,240,73,206,15,230,123,206,50,230,80,242,75,247,9,243,24,228,166,207,121,218,146,218,108,241,62,228,120,246,57,246,56,222,142,242,79,228,216,247,36,240,104,246,50,229,67,219,39,241,136,204,90,244,136,218,92,206,120,241,156,219,58,222,79,252,26,219,154,218,255,229,200,216,71,219,92,229,153,240,132,204,87,228,120,240,20,241,181,242,24,242,65,244,175,228,141,216,66,229,200,217,22,229,254,246,116,246,91,228,142,228,167,246,62,231,51,205,87,246,55,240,94,241,152,231,16,245,239,228,77,245,186,245,183,231,74,218,50,219,238,219,54,220,30,246,85,242,21,207,250,229,240,207,207,231,69,241,180,241,27,206,229,230,61,247,120,206,110,205,79,244,143,246,40,246,49,222,199,244,144,241,178,222,241,206,175,206,115,231,79,223,121,206,30,245,173,243,30,206,125,230,88,242,53,243,8,222 87,230,82,207,155,207,42,243,20,244,154,207,104,207,2,206,78,229,207,222,250,242,26,229,218,246,122,218,36,206,234,219,38,207,42,244,255,244,216,231,57,222,125,206,248,241,10,204,15,206,167,218,50,204,91,247,36,217,86,246,8,206,208,245,200,219,186,217,82,223,177,219,194,246,46,240,241,218,56,222,29,218,58,216,94,244,5,218,240,240,146,244,180,219,26,231,115,219,54,249,95,223,61,206,102,229,81,207,39,241,204,223,155,244,179,247,20,207,111,242,60,245,217,207,208,216,75,246,31,231,80,229,121,219,30,228,205,240,73,228,164,206,114,230,106,240,238,240,178,247,7,242,36,228,240,253,27,206,143,228,254,204,70,218,66,207,102,206,133,207,103,206,74,229,91,230,85,245,108,229,237,218,158,240,16,245,23,205,83,231,109,222,55,242,18,230,36,206,14,229,249,218,31,249,74,231,57,206,15,222,40,207,106,222,217,221,67,228,235,219,206,247,121,245,254,240,197,245,4,246,57,231,50,223,66,247,12,222,211,240,16,242,92,240,56,223,83,243,28,241,179,231,112,217,18,245,36,245,11,206,51,242,20,229,184};
然后,确定彩色图片三基色R、G、B矩阵的大小,令R、G、B矩阵大小相等,且行数均为
Figure GDA0003339914190000131
列数均为W=H+1=14+1=15;
接着,生成一个长度为26、各元素大小均为128的数值序列Q4={Q41,...,Q4i,...,Q426}={128,...,128,...,128},并将数值序列Q3和数值序列Q4进行组合,得到数值序列PP={222,28,206,216,219,54,222,160,246,89,218,99,229,227,246,90,221,7,242,5,244,22,229,240,219,51,240,105,244,201,228,181,244,174,231,88,205,70,207,103,206,37,228,82,230,80,229,175,223,38,204,95,231,71,240,67,246,40,240,201,230,16,247,57,223,54,206,7,219,206,230,90,230,47,206,216,228,240,218,176,219,240,241,254,218,39,219,162,218,217,218,245,218,29,206,49,207,61,240,239,218,220,218,156,229,243,223,250,242,78,204,87,244,237,218,24,205,90,218,23,242,53,223,35,230,110,243,96,207,58,219,240,240,73,206,15,230,123,206,50,230,80,242,75,247,9,243,24,228,166,207,121,218,146,218,108,241,62,228,120,246,57,246,56,222,142,242,79,228,216,247,36,240,104,246,50,229,67,219,39,241,136,204,90,244,136,218,92,206,120,241,156,219,58,222,79,252,26,219,154,218,255,229,200,216,71,219,92,229,153,240,132,204,87,228,120,240,20,241,181,242,24,242,65,244,175,228,141,216,66,229,200,217,22,229,254,246,116,246,91,228,142,228,167,246,62,231,51,205,87,246,55,240,94,241,152,231,16,245,239,228,77,245,186,245,183,231,74,218,50,219,238,219,54,220,30,246,85,242,21,207,250,229,240,207,207,231,69,241,180,241,27,206,229,230,61,247,120,206,110,205,79,244,143,246,40,246,49,222,199,244,144,241,178,222,241,206,175,206,115,231,79,223,121,206,30,245,173,243,30,206,125,230,88,242,53,243,8,222 87,230,82,207,155,207,42,243,20,244,154,207,104,207,2,206,78,229,207,222,250,242,26,229,218,246,122,218,36,206,234,219,38,207,42,244,255,244,216,231,57,222,125,206,248,241,10,204,15,206,167,218,50,204,91,247,36,217,86,246,8,206,208,245,200,219,186,217,82,223,177,219,194,246,46,240,241,218,56,222,29,218,58,216,94,244,5,218,240,240,146,244,180,219,26,231,115,219,54,249,95,223,61,206,102,229,81,207,39,241,204,223,155,244,179,247,20,207,111,242,60,245,217,207,208,216,75,246,31,231,80,229,121,219,30,228,205,240,73,228,164,206,114,230,106,240,238,240,178,247,7,242,36,228,240,253,27,206,143,228,254,204,70,218,66,207,102,206,133,207,103,206,74,229,91,230,85,245,108,229,237,218,158,240,16,245,23,205,83,231,109,222,55,242,18,230,36,206,14,229,249,218,31,249,74,231,57,206,15,222,40,207,106,222,217,221,67,228,235,219,206,247,121,245,254,240,197,245,4,246,57,231,50,223,66,247,12,222,211,240,16,242,92,240,56,223,83,243,28,241,179,231,112,217,18,245,36,245,11,206,51,242,20,229,184,128,128,128,128,128,128,128,128,128,128,128,128,128,128,128,128,128,128,128,128,128,128,128,128,128,128},
最后,计算得到R、G、B矩阵数据填放的初始位置参数分别为R_position=0、G_position=2和B_position=0,以及R、G、B矩阵数据填放的方向参数分别为R_direction=0、G_direction=1和B_direction=1,R、G、B矩阵填放数据的具体操作如下,
R矩阵从最左上角位置开始从左往右逐行填放数据,其中填放的数据抽取自数值序列PP中相关元素,表示为{222,216,222,89,229,90,242,22,219,105,228,174,205,103,228,80,223,95,240,40,230,57,206,206,230,216,218,240,218,162,218,29,207,239,218,243,242,87,218,90,242,35,243,58,240,15,206,80,247,24,207,146,241,120,246,142,228,36,246,67,241,90,218,120,219,79,219,255,216,92,240,87,240,181,242,175,216,200,229,116,228,167,231,87,240,152,245,77,245,74,219,54,246,21,229,207,241,27,230,120,205,143,246,199,241,241,206,79,206,173,206,88,243,87,207,42,244,104,206,207,242,218,218,234,207,255,231,125,241,15,218,91,217,8,245,186,223,194,240,56,218,94,218,146,219,115,249,61,229,39,223,179,207,60,207,75,231,121,228,73,206,106,240,7,228,27,228,70,207,133,206,91,245,237,240,23,231,55,230,14,218,74,206,40,222,67,219,121,240,4,231,66,222,16,240,83,241,112,245,11,242,184,128,128,128,128,128,128,128,128},得到R矩阵为
Figure GDA0003339914190000141
G矩阵从最左下角位置开始从下往上逐列填放数据,其中填放的数据抽取自数值序列PP中相关元素,表示为{28,219,160,218,227,221,5,229,51,244,181,231,70,206,82,229,38,231,67,240,16,223,7,230,47,228,176,241,39,218,245,206,61,218,156,223,78,244,24,218,53,230,96,219,73,230,50,242,9,228,121,218,62,246,56,242,216,240,50,219,136,244,92,241,58,252,154,229,71,229,132,228,20,242,65,228,66,217,254,246,142,246,51,246,94,231,239,245,183,218,238,220,85,207,240,231,180,206,61,206,79,246,49,244,178,206,115,223,30,243,125,242,8,230,155,243,154,207,78,222,26,246,36,219,42,244,57,206,10,206,50,247,86,206,200,217,177,246,241,222,58,244,240,244,26,219,95,206,81,241,155,247,111,245,208,246,80,219,205,228,114,240,178,242,240,206,254,218,102,207,74,230,108,218,16,205,109,242,36,229,31,231,15,207,217,228,206,245,197,246,50,247,211,242,56,243,179,217,36,206,20,128,128,128,128,128,128,128,128,128},得到G矩阵为
Figure GDA0003339914190000151
B矩阵从最左上角位置开始从上往下逐列填放数据,其中填放的数据抽取自数值序列PP中相关元素,表示为{206,54,246,99,246,7,244,240,240,201,244,88,207,37,230,175,204,71,246,201,247,54,219,90,206,240,219,254,219,217,218,49,240,220,229,250,204,237,205,23,223,110,207,240,206,123,230,75,243,166,218,108,228,57,222,79,247,104,229,39,204,136,206,156,222,26,218,200,219,153,204,120,241,24,244,141,229,22,246,91,228,62,205,55,241,16,228,186,231,50,219,30,242,250,207,69,241,229,247,110,244,40,222,144,222,175,231,121,245,30,230,53,222,82,207,20,207,2,229,250,229,122,206,38,244,216,222,248,204,167,204,36,246,208,219,82,219,46,218,29,216,5,240,180,231,54,223,102,207,204,244,20,242,217,216,31,229,30,240,164,230,238,247,36,253,143,204,66,206,103,229,85,229,158,245,83,222,18,206,249,249,57,222,106,221,235,247,254,245,57,223,12,240,92,223,28,231,18,245,51,229,128,128,128,128,128,128,128,128,128},得到B矩阵为
Figure GDA0003339914190000152
从而生成彩色图片,并利用二维码生成器将彩色图片转换为二维码,具体如图2所示,图2中左图为生成的彩色图片,图2中右图为由彩色图片转换而成的二维码。
实施例2
按照上述一种汉字转图片的加密方法,某段待加密的汉字仍为:“一种汉字转图片的加密方法,是一种比较简单、可行的方法。图片是指由图形、图像等构成的平面媒体。图片的格式很多,但总体上可以分为点阵图和矢量图两大类。混沌的特征是原来遵循简单物理规律的有序运动形态,在某种条件下突然偏离预期的规律性而变成了无序的形态。混沌是指确定性动力学系统因对初值敏感而表现出的不可预测的、类似随机性的运动。又称浑沌。英语词源于希腊语,原始含义是宇宙初开之前的景象,基本含义主要指混乱、无序的状态。作为科学术语,混沌一词特指一种运动形态。极限点附近,这一系列分岔在参数空间和相空间都表现出尺度变换下的不变性,即自相似性。使用重正化群计算可得到这些分岔过程的一套普适常数,它们与实验事实相符。”,其加密步骤与具体实施例1相似,仅加密密钥发生细微变化:α=0.12345000000001;或β=3.85000000000001,汉字转图片的加密结果如表1所示。由表1可知,加密密钥的细微变化会引起汉字转图片加密彩色图片发生很大的变化,由此可见本专利所提一种汉字转图片的加密方法对加密密钥具有敏感性。
表1 外部加密密钥发生微变时,汉字转图片加密结果
Figure GDA0003339914190000161
Figure GDA0003339914190000171
Figure GDA0003339914190000181
实施例3
按上述一种汉字转图片的加密方法,其加密步骤与具体实施例1相似,仅某段待加密的汉字发生微变:第1个汉字“一”变为“二”;或第27个汉字“。”变为“!”;或第55个汉字“但”变为“旦”;或第100个汉字“种”变为“钟”;或第151个汉字“的”变为“地”;或第199个汉字“乱”变为“敌”;或第230个汉字“附”变为“符”;或第270个汉字“重”变为“童”;或第302个汉字“。”变为“合”,汉字转图片的加密结果如表2所示。由表2可见:某段待加密汉字的细微变化会引起加密彩色图片的“面目全非”,由此可见本专利所提一种汉字转图片的加密方法对某段待加密汉字的平文信息具有敏感性。
表2 某段待加密的汉字发生微变时,汉字转图片加密结果
Figure GDA0003339914190000182
Figure GDA0003339914190000191
Figure GDA0003339914190000201
由上述具体实施例2、3分析可知,本专利所提一种汉字转图片的加密方法所生成的彩色图片密文不仅与外部加密密钥密切相关,而且依赖于待加密汉字平文信息,因此本专利所提一种汉字转图片的加密方法可抵抗已知/选择明文攻击,具有很强的安全性。

Claims (3)

1.一种汉字转图片的加密方法,其特征在于,包括如下几个步骤:
(1)转码:将某段汉字逐个汉字转换成数值型数据[P1i,P2i],得到高位数值序列P1={P11,P12,…,P1i,…,P1L}和低位数值序列P2={P21,P22,…,P2i,…,P2L},其中数值序列P1、P2的长度与该段汉字的长度一致,记为L,其中某段汉字来自于GB2312字符集中双字节编码的6763个汉字;
(2)产生混沌序列:
首先利用外部加密密钥(α,β),按照如下(1)-(5)公式分别计算得到混沌系统的初值x1、参数μ、初始迭代步数m、第一抽取间隔n1和第二抽取间隔n2
Figure FDA0003339914180000011
则可得,
x1=mod(KK+α,0.99998)+0.00002, (1)
μ=β+mod(KK,4-β), (2)
Figure FDA0003339914180000012
Figure FDA0003339914180000013
Figure FDA0003339914180000014
其中,α∈(0,1),β∈[3.75,4),
然后由初值(x1)、参数(μ),对如下公式(6)所示的Logistic混沌系统进行迭代,k表示迭代次数(k=1,2,…),xk+1表示第k次迭代得到的混沌信号,
xk+1=μ·xk·(1-xk) (6)
得到混沌序列X,从第m个元素开始每隔n1个元素取1个,从而形成长度为L的混沌序列Y1,并从第m个元素开始每隔n2个元素取1个,从而形成长度为L的混沌序列Y2;
(3)高位、低位数值序列置乱:
将混沌序列Y1按降序排序,根据序列Y1排序前、后的位置变化置乱规则,对高位数值序列P1={P11,P12,…,P1i,…,P1L}进行置乱,得到置乱后的高位数值序列
Figure FDA0003339914180000015
同时将混沌序列Y2按升序排序,根据序列Y2排序前、后的位置变化置乱规则,对低位数值序列P2={P21,P22,…,P2i,…,P2L}进行置乱,得到置乱后的低位数值序列
Figure FDA0003339914180000016
(4)彩色图片的生成:
首先,将置乱后的高位数值序列
Figure FDA0003339914180000017
中各元素逐个利用dec2bin(·,8)函数转换成8位二进制,得到高位二进制序列Q1,表示为Q1={Q11,Q12,Q13,...,Q18×L},同时将置乱后的低位数值序列
Figure FDA0003339914180000021
中各元素逐个利用dec2bin(·,8)函数转换成8位二进制,得到低位二进制序列Q2,表示为Q2={Q21,Q22,Q23,...,Q28×L},并按照自定义的两个二进制序列变换成一个数值序列的转换规则,得到数值序列Q3,表示为Q3={Q31,...,Q3j,...,Q32×L},其中,所述的按照自定义的两个二进制序列变换成一个数值序列的转换规则,是指依次从二进制序列Q1中取4个元素、从二进制序列Q2中取4个元素,组合成一个8位二进制序列,并利用bin2dec(·)函数将其转换成一个数值型数据,表示为Q3j=bin2dec({Q14j-3,Q14j-2,Q14j-1,Q14j,Q24j-3,Q24j-2,Q24j-1,Q24j}),其中j=1,2,...,2×L-1,2×L,
然后,确定彩色图片三基色R、G、B矩阵的大小,令R、G、B矩阵大小相等,且行数均为
Figure FDA0003339914180000022
同时按照如下公式(7)计算R、G、B矩阵的列数W,
Figure FDA0003339914180000023
接着,生成一个长度为3×W×H-2×L、各元素大小均为128的数值序列Q4={Q41,Q42,Q43,...,Q43×W×H-2×L}={128,...,128,...,128},并将数值序列Q3和数值序列Q4进行组合,得到数值序列PP={PP1,PP2,PP3,...,PP3×W×H}={Q31,Q32,...,Q32×L,Q41,Q42,...,Q43×W×H-2×L},
最后,按照自定义的R、G、B矩阵数据填放规则,将数值序列PP中元素分别填放入R、G、B矩阵中,从而生成彩色图片,并利用二维码生成器将彩色图片转换为二维码。
2.根据权利要求1所述的一种汉字转图片的加密方法,其特征在于:步骤(1)中所述的将某段汉字逐个汉字转换成数值型数据[P1i,P2i],是指采用unicode2native(·)函数,将单个汉字转换为区位码数值数据,表示为[P1i,P2i]=[区数值序列,位数值序列]。
3.根据权利要求1所述的一种汉字转图片的加密方法,其特征在于步骤(4)中所述的按照自定义的R、G、B矩阵数据填放规则,将数值序列PP中元素分别填放入R、G、B矩阵中,是指:
R、G、B矩阵数据填放的初始位置参数和方向参数分别由如下所示公式(8)计算,其中R_position、G_position和B_position分别表示R、G、B矩阵数据填放的初始位置参数,R_direction、G_direction和B_direction分别表示R、G、B矩阵数据填放的方向参数,
Figure FDA0003339914180000031
当R_position=0、R_direction=0时,R矩阵从最左上角位置开始从左往右逐行填放数据,当R_position=0、R_direction=1时,R矩阵从最左上角位置开始从上往下逐列填放数据,当R_position=1、R_direction=0时,R矩阵从最右上角位置开始从右往左逐行填放数据,当R_position=1、R_direction=1时,R矩阵从最右上角位置开始从上往下逐列填放数据,当R_position=2、R_direction=0时,R矩阵从最左下角位置开始从左往右逐行填放数据,当R_position=2、R_direction=1时,R矩阵从最左下角位置开始从下往上逐列填放数据,当R_position=3、R_direction=0时,R矩阵从最右下角位置开始从右往左逐行填放数据,当R_position=3、R_direction=1时,R矩阵从最右下角位置开始从下往上逐列填放数据,其中填放的数据抽取自数值序列PP中相关元素,表示为{PP1,PP4,...,PP3t-2,...,PP3×W×H-2},其中t=1,2,3,...,W×H-1,W×H,
当G_position=0、G_direction=0时,G矩阵从最左上角位置开始从左往右逐行填放数据,当G_position=0、G_direction=1时,G矩阵从最左上角位置开始从上往下逐列填放数据,当G_position=1、G_direction=0时,G矩阵从最右上角位置开始从右往左逐行填放数据,当G_position=1、G_direction=1时,G矩阵从最右上角位置开始从上往下逐列填放数据,当G_position=2、G_direction=0时,G矩阵从最左下角位置开始从左往右逐行填放数据,当G_position=2、G_direction=1时,G矩阵从最左下角位置开始从下往上逐列填放数据,当G_position=3、G_direction=0时,G矩阵从最右下角位置开始从右往左逐行填放数据,当G_position=3、G_direction=1时,G矩阵从最右下角位置开始从下往上逐列填放数据,其中填放的数据抽取自数值序列PP中相关元素,表示为{PP2,PP5,...,PP3t-1,...,PP3×W×H-1},其中t=1,2,3,...,W×H-1,W×H,
当B_position=0、B_direction=0时,B矩阵从最左上角位置开始从左往右逐行填放数据,当B_position=0、B_direction=1时,B矩阵从最左上角位置开始从上往下逐列填放数据,当B_position=1、B_direction=0时,B矩阵从最右上角位置开始从右往左逐行填放数据,当B_position=1、B_direction=1时,B矩阵从最右上角位置开始从上往下逐列填放数据,当B_position=2、B_direction=0时,B矩阵从最左下角位置开始从左往右逐行填放数据,当B_position=2、B_direction=1时,B矩阵从最左下角位置开始从下往上逐列填放数据,当B_position=3、B_direction=0时,B矩阵从最右下角位置开始从右往左逐行填放数据,当B_position=3、B_direction=1时,B矩阵从最右下角位置开始从下往上逐列填放数据,其中填放的数据抽取自数值序列PP中相关元素,表示为{PP3,PP6,...,PP3t,...,PP3×W×H},其中t=1,2,3,...,W×H-1,W×H。
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