WO2016123902A1 - Calculating method for maximum decoration weight of lift car - Google Patents

Calculating method for maximum decoration weight of lift car Download PDF

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WO2016123902A1
WO2016123902A1 PCT/CN2015/083841 CN2015083841W WO2016123902A1 WO 2016123902 A1 WO2016123902 A1 WO 2016123902A1 CN 2015083841 W CN2015083841 W CN 2015083841W WO 2016123902 A1 WO2016123902 A1 WO 2016123902A1
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weight
max
car
maximum
allowable
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PCT/CN2015/083841
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French (fr)
Chinese (zh)
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魏科
鲁江
魏晓波
葛余林
阮彦
范林玉
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江苏蒙哥马利电梯有限公司
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Publication of WO2016123902A1 publication Critical patent/WO2016123902A1/en

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    • BPERFORMING OPERATIONS; TRANSPORTING
    • B66HOISTING; LIFTING; HAULING
    • B66BELEVATORS; ESCALATORS OR MOVING WALKWAYS
    • B66B1/00Control systems of elevators in general
    • BPERFORMING OPERATIONS; TRANSPORTING
    • B66HOISTING; LIFTING; HAULING
    • B66BELEVATORS; ESCALATORS OR MOVING WALKWAYS
    • B66B1/00Control systems of elevators in general
    • B66B1/34Details, e.g. call counting devices, data transmission from car to control system, devices giving information to the control system
    • B66B1/3476Load weighing or car passenger counting devices
    • BPERFORMING OPERATIONS; TRANSPORTING
    • B66HOISTING; LIFTING; HAULING
    • B66BELEVATORS; ESCALATORS OR MOVING WALKWAYS
    • B66B11/00Main component parts of lifts in, or associated with, buildings or other structures
    • B66B11/02Cages, i.e. cars

Definitions

  • W P real +KQ
  • P the car's own weight
  • K the elevator balance coefficient
  • Q the rated load
  • W 1 Hn 1 mq 1
  • Medium H the lifting speed
  • n 1 the wire rope coefficient
  • m the traction ratio
  • q 1 the weight of the wire rope per unit length
  • W 2 Hn 2 q 2 , where H is the lifting speed, n 2 is the number of compensation chains, q 2 is the unit length compensation chain weight.

Abstract

Disclosed is a calculating method for maximum decoration weight of a lift car. The critical values of the dead weight of the lift car are calculated respectively from three aspects, namely the safety coefficient of a traction steel wire rope, the allowable radial load of a main shaft of a tractor and the allowable torque of a main machine or the allowable brake torque of a brake; the minimum value of the critical values of the dead weight of the lift car calculated from the three aspects is selected as the allowable maximum dead weight of the lift car; the maximum decoration weight of the lift car is calculated from a difference between the allowable maximum dead weight of the lift car and the actual dead weight of the lift car. By means of the calculating of the allowable maximum decoration weight of the lift car, the calculating method assures that the implementation of the decoration weight can be carried out to the maximum extent while normal operation of a lift is guaranteed, thus ensuring safety service lives of main components of the lift, and improving the maximum publicity effect and benefit of a business enterprise.

Description

一种电梯轿厢最大装潢重量的计算方法Method for calculating maximum decoration weight of elevator car 技术领域Technical field
本发明属于电梯生产技术领域,具体涉及一种电梯轿厢最大装潢重量的计算方法。The invention belongs to the technical field of elevator production, and particularly relates to a calculation method for the maximum decoration weight of an elevator car.
背景技术Background technique
随着社会的进步,电梯用户对轿厢的装潢也与时俱进,装潢的重量也不断增加,然而轿厢作为电梯曳引系统的重要部件,其自重是否可无限制的增加,回答是肯定的:不可以。既然不可以无限制的增加,那轿厢装潢重量何时才是尽头,就成为电梯制造厂和检验单位必须考虑的问题。With the advancement of society, the elevator users' decoration of the car is also advancing with the times, and the weight of the decoration is also increasing. However, as the important part of the elevator traction system, the car can increase its own weight without limit. The answer is yes. : No. Since it is not possible to increase without limit, when the weight of the car decoration is the end, it becomes a problem that the elevator manufacturer and the inspection unit must consider.
作为产品的电梯,其轿厢允许装潢的最大重量P装max应该等于其轿厢允许的最大自重P max与轿厢实际自重P的差:An elevator product, which allows the car decorated maximum weight P max means that the car should be equal to the maximum allowable weight of the car and the actual P max allowed real difference between the weight P:
即:P装max=P允max-P.………………………….(1)Namely: P installed max = P to allow max - P real ..........................(1)
对曳引系统参数已确定的产品电梯,其轿厢的实际自重应该满足电梯曳引条件且在轿厢允许的最大自重范围内,否则将会缩短电梯及其相关零部件的使用寿命。因此轿厢允许的最大自重确定的合理与否,会牵涉到广大电梯用户的使用质量,会牵涉到电梯制造厂家的社会信誉,也会牵涉到法定检验单位检验质量的社会信誉。所以,如何确定轿厢允许的最大自重是电梯制造厂家尤其是法定检验单位必须认真关注的。For product elevators whose traction system parameters have been determined, the actual weight of the car should meet the elevator traction conditions and be within the maximum self-weight range allowed by the car, otherwise the service life of the elevator and its related components will be shortened. Therefore, the reasonableness of the maximum self-weight allowed by the car will involve the quality of the elevator users, which will involve the social reputation of the elevator manufacturer, and will also involve the social reputation of the statutory inspection unit. Therefore, how to determine the maximum allowable weight of the car is an important concern for elevator manufacturers, especially statutory inspection units.
电梯轿厢自重主要取决于以下几个因素:①曳引钢丝绳的安全系数;②曳引机主轴径向最大许用载荷;③减速箱或无齿轮主机的最大许用转矩或制动器的最大制动转矩。按照每一个影响因素都可以找到一个轿厢自重的临界值Pmax。分别将曳引钢丝绳的安全系数、曳引机主轴径向许用载荷、曳引机出轴许用转矩或制动器的许用制动转矩表达成各因素中所求轿厢自重临界值Pmax的函数,在给定的其他条件下即可求解,各影响因素下的轿厢自重临界值Pmax。如果轿厢自重超出某个临界值则可能使曳引钢丝绳的寿命,或者曳引机主轴的寿命,减速箱或无齿轮主机的寿命得不到保证,或者制动器不能使轿厢制停,或者引起电动机及变频器过载以至烧毁。所以选取上述临界值Pmax中最小值作为轿厢自重的最大值P允max,只要电梯在任何情况实际的轿厢自重不大于P允max,就能使驱动装置中的上述每个零部件都是安全的,长寿的。将选取的P允max和轿厢实际自重P代入式(1)便可确定P装maxThe self-weight of the elevator car mainly depends on the following factors: 1 the safety factor of the traction wire rope; 2 the maximum allowable radial load of the traction machine main shaft; the maximum allowable torque of the gearbox or the gearless main engine or the maximum brake system. Dynamic torque. According to each influencing factor, a critical value P max of the car's own weight can be found. The safety factor of the traction wire rope, the radial allowable load of the traction machine main shaft, the allowable torque of the traction machine output shaft or the allowable braking torque of the brake are respectively expressed as the self-weight threshold value P of each factor. The function of max can be solved under the given other conditions, and the car self-weight threshold value P max under each influencing factor. If the car's own weight exceeds a certain critical value, the life of the traction wire rope, or the life of the traction machine main shaft, the life of the gearbox or the gearless main engine may not be guaranteed, or the brake may not stop the car, or cause The motor and inverter are overloaded and burned. Therefore, the above-described threshold selecting the minimum value as the maximum value P max P max allowed weight of the car, as long as the actual elevator car in any case not greater than the weight P max allowed, can make the drive device each of said parts are It is safe and longevity. The selected P max and allow the weight of car P actual real into equation (1) means P max can be determined.
发明内容Summary of the invention
发明目的:本发明针对不足,提出一种在保证电梯安全运转的前提下又能最大限度的计算最大装潢重量的计算方法。OBJECT OF THE INVENTION: The present invention provides a calculation method for calculating the maximum decoration weight to the maximum extent under the premise of ensuring the safe operation of the elevator.
技术方案:本发明所述的一种电梯轿厢最大装潢重量的计算方法,包括如下步骤: Technical Solution: The method for calculating the maximum decoration weight of an elevator car according to the present invention includes the following steps:
(1)计算轿厢最大装潢重量轿厢P装max,如下公式1所示:(1) Calculate the maximum decoration weight of the car. The car P is installed as Max , as shown in the following formula 1:
P装max=P允max-P                  (1)P installed max = P to allow max - P real (1)
式中P装max为轿厢允许装潢的最大重量,P允max为轿厢允许的最大自重,P为轿厢实际自重;Wherein P max is the fitted decorated car allowed maximum weight, the maximum P max is the allowed permitted weight of the car, car P is the actual weight of the solid;
(2)轿厢允许的最大自重P允max的取值:选取轿厢自重临界值Pmax中的最小值作为P max的值;(2) the maximum allowable weight of the car P max allowed values: Select the minimum car weight threshold value P max is the max allowed as the value of P;
(3)计算轿厢自重临界值Pmax:分别从曳引钢丝绳的安全系数、曳引机主轴许用径向载荷以及主机许用转距或制动器的许用制动转矩三方面计算得出轿厢自重临界值Pmax(3) Calculate the car's own weight threshold P max : calculated from the safety factor of the traction wire rope, the allowable radial load of the traction machine spindle, and the allowable torque of the main engine or the allowable braking torque of the brake. Car weight threshold P max ;
(4)从步骤(3)中得出的轿厢自重临界值Pmax中选取最小值作为轿厢允许的最大自重P允max,并带入公式1得出最后的轿厢最大装潢重量轿厢P装max(4) Select the minimum value from the car self-weight threshold value P max obtained in step (3) as the maximum allowable self-weight P- max of the car, and bring in the formula 1 to obtain the final car maximum decoration weight car. P installed max .
作为优化,步骤(3)所述的从曳引钢丝绳的安全系数计算Pmax公式如下:As an optimization step (3) calculating the safety factor of the hoisting rope from the formula P max as follows:
Figure PCTCN2015083841-appb-000001
Figure PCTCN2015083841-appb-000001
推导得出
Figure PCTCN2015083841-appb-000002
Derive
Figure PCTCN2015083841-appb-000002
式中S为给定曳引系统悬挂绳安全系数实际值,T为钢丝绳的最小破断拉力,n为钢丝绳根数,m为曳引比,Q为额定载重量,H为提升速度,q为单位长度曳引钢丝绳重量,gn为重力加速度;其中根据曳引钢丝绳安全系数校核原则,S≥Sf≥Sm这里S的可取值中最小值是Sf,将S=Sf代入式2即可,Sf为考虑了曳引轮绳槽形状,滑轮数量与弯曲情况所得到的给定曳引系统钢丝绳许用安全系数计算值;Sm为GB7588一2003 9.2.2条款规定的曳引钢丝绳许用安全系数最小值。Where S is the actual value of the safety factor of the suspension rope of a given traction system, T is the minimum breaking force of the rope, n is the number of ropes, m is the traction ratio, Q is the rated load, H is the lifting speed, q is the unit the length of the hoisting rope by weight, g n is the gravitational acceleration; wherein the safety factor according to the principle of checking the hoisting rope, S≥S f ≥S m herein may be in the minimum value of S is S f, S = S f will be substituted into the formula 2, S f is the calculated safety factor of the wire rope of a given traction system obtained by considering the shape of the rope of the traction sheave, the number of pulleys and the bending condition; S m is the drag specified in clause 9.2.2 of GB7588-2003 The minimum safety factor for the wire rope is allowed.
作为优化,步骤(3)所述的曳引机主轴许用径向载荷计算Pmax公式如下:As an optimization, the allowable radial load calculation P max formula of the traction machine main shaft described in the step (3) is as follows:
Amax=(Pmax+1.25Q+W+W1+W2)/m,A max = (P max + 1.25Q + W + W 1 + W 2 ) / m,
推导得出Pmax=mAmax-1.25Q-W-W1-W2                   (3)Deduced that P max = mA max -1.25Q-W-W 1 -W 2 (3)
式中Amax为主机轴径向最大静载荷,m为曳引比,Q为额定载重量,W为对重重量,W1为曳引钢丝绳重量,W2为补偿链重量。Where A max is the radial maximum static load of the main shaft, m is the traction ratio, Q is the rated load, W is the counterweight, W 1 is the weight of the traction rope, and W 2 is the weight of the compensation chain.
作为优化,步骤(3)所述的主机许用转距或制动器的许用制动转矩计算Pmax公式如下:As an optimization step (3) the host allowable allowable brake torque or braking torque calculating P max following formula:
Figure PCTCN2015083841-appb-000003
Figure PCTCN2015083841-appb-000003
推导
Figure PCTCN2015083841-appb-000004
Derivation
Figure PCTCN2015083841-appb-000004
式中Mmax为制动器许用制动转矩,m为曳引比,D为实例中的Dt—曳引轮节圆直径,gn为重力加速度,η为机械传动总效率,Q为额定载重量,W为对重重量,W1为曳引钢丝绳重量,W2为补偿链重量。Where M max is the brake allowable braking torque, m is the traction ratio, D is the D t in the example—the traction wheel pitch circle diameter, g n is the gravity acceleration, η is the total mechanical transmission efficiency, and Q is the rated Load capacity, W is the counterweight, W 1 is the weight of the traction wire rope, and W 2 is the weight of the compensation chain.
作为优化,所述对重重量W的计算公式为W=P+KQ,式中P为轿厢自重,K为电梯平衡系数,Q为额定载重量;W1=Hn1mq1,式中H为提升速度,n1为钢丝绳系数,m为曳引比,q1为单位长度钢丝绳重量;W2=Hn2q2,式中H为提升速度,n2为补偿链根数,q2为单位长度补偿链重量。As an optimization, the formula for calculating the counterweight W is W=P real +KQ, where P is the car's own weight, K is the elevator balance coefficient, Q is the rated load; W 1 =Hn 1 mq 1 , Medium H is the lifting speed, n 1 is the wire rope coefficient, m is the traction ratio, q 1 is the weight of the wire rope per unit length; W 2 =Hn 2 q 2 , where H is the lifting speed, n 2 is the number of compensation chains, q 2 is the unit length compensation chain weight.
有益效果:本发明通过对轿厢允许最大装潢重量的计算,从而在保证电梯正常运转的同时又可以最大限度的进行装潢重量的实施,从而保证了电梯主要部件的安全长寿,同时提高了企业的最大化宣传效果,提高了企业效益。Advantageous Effects: The invention allows the maximum decorative weight of the car to be calculated, thereby ensuring the normal operation of the elevator and maximizing the implementation of the decoration weight, thereby ensuring the safety and longevity of the main components of the elevator, and at the same time improving the enterprise's Maximize the effectiveness of publicity and improve business efficiency.
具体实施方式detailed description
下面结合具体的电梯运行实施例对本发明作进一步说明:The present invention will be further described below in conjunction with a specific elevator operating embodiment:
实施例1Example 1
某梯曳引系统参数如下:The parameters of a ladder traction system are as follows:
Figure PCTCN2015083841-appb-000005
Figure PCTCN2015083841-appb-000005
Figure PCTCN2015083841-appb-000006
Figure PCTCN2015083841-appb-000006
①从电梯曳引钢丝绳的安全系数方面计算轿厢自重的临界值Pmax1 Calculate the critical value P max of the car's own weight from the safety factor of the elevator traction wire rope:
首先计算Sf的值:First calculate the value of S f :
Figure PCTCN2015083841-appb-000007
Figure PCTCN2015083841-appb-000007
式中:
Figure PCTCN2015083841-appb-000008
In the formula:
Figure PCTCN2015083841-appb-000008
Nequiv=Nequiv(t)+Nequiv(p)Nequiv=Nequiv(t)+Nequiv(p)
带切口半圆槽切口角β=105°查GB7588-2003附录N表N1得:With a slit semicircular groove cut angle β = 105 ° check GB7588-2003 Appendix N Table N 1 to:
Nequiv(t)=15.2Nequiv(t)=15.2
Nequiv(p)=KP(NPS+4NPr)Nequiv(p)=K P (N PS +4N Pr )
Figure PCTCN2015083841-appb-000009
Figure PCTCN2015083841-appb-000009
曳引系统中无引起反向弯折的滑轮,NPr=0,NPS=2There are no pulleys in the traction system that cause reverse bending, N Pr =0, N PS = 2
Nequiv(p)=kp(NPS+4NPr)=2.25×(2+4×0)=4.5Nequiv(p)=k p (N PS +4N Pr )=2.25×(2+4×0)=4.5
Nequiv=Nequiv(t)+Nequiv(p)=15.2+4.5=19.7Nequiv=Nequiv(t)+Nequiv(p)=15.2+4.5=19.7
Figure PCTCN2015083841-appb-000010
Nequiv=19.7代入式(5)得:Sf=17.29再代入式(2)得:
will
Figure PCTCN2015083841-appb-000010
Nequiv=19.7 is substituted into (5): S f = 17.29 and then substituted into (2):
Figure PCTCN2015083841-appb-000011
这里取S=Sf=17.29;q=q1=0.347kg/m;
Figure PCTCN2015083841-appb-000011
Here, S = S f = 17.29; q = q 1 = 0.347 kg / m;
Figure PCTCN2015083841-appb-000012
Figure PCTCN2015083841-appb-000012
(注:电梯曳引绳槽表面比压不能反映曳引能力,更不能反映寿命,GB7588-2003标准中未作要求,免于这方面的计算。)(Note: The surface pressure of the elevator traction rope groove does not reflect the traction capacity, and it does not reflect the life. The GB7588-2003 standard does not require it, and is exempt from this calculation.)
②从曳引机主轴许用经载荷计算轿厢自重的临界值Pmax2 Calculate the critical value P max of the car's own weight from the allowable load of the traction machine main shaft.
将Amax=3500kg,m=2,Q=1000kg,K=48,W1=470kg,W2=432kg,代入式(3)得:A max = 3500kg, m = 2, Q = 1000kg, K = 48, W 1 = 470kg, W 2 = 432kg, substituted into formula (3):
Pmax=mAmax-1.25Q-W-W1-W2 P max =mA max -1.25Q-W-W 1 -W 2
=2×3500-1250-2030-470-432=2818kg=2×3500-1250-2030-470-432=2818kg
③从主机轴许用转矩或制动器的许用制动转矩,计算轿厢自重临界值Pmax(以制动器的许用制动转矩为例)3 Calculate the car's own weight threshold P max from the allowable torque of the main engine shaft or the allowable braking torque of the brake (take the brake braking torque as an example)
主机所配制动器一组部件的最大制动转矩为940Nm,代入式(4)得:The maximum braking torque of a set of components of the brakes of the main engine is 940Nm, which is obtained by substituting (4):
Figure PCTCN2015083841-appb-000013
Figure PCTCN2015083841-appb-000013
四、计算轿厢允许装潢的最大重量P装max Fourth, calculate the maximum weight of the car allowed to decorate the P installed max
以上从三方面计算得到的轿厢自重最大值分别为2165kg、2818kg、1663kg,从中选取最小值作为允许轿厢自重的最大值即:P允max=1663kg,将P允max=1663kg、P=1550kg代入式(1),得P装max=P允max-P=1663-1550=113kg,P装max=113kg。即允许例梯轿厢装潢的最大重量为113kg。Calculated from three or more maximum values for the car weight 2165kg, 2818kg, 1663kg, which allows the car to the minimum weight as a maximum value, i.e., selecting: P allowed max = 1663kg, will allow P max = 1663kg, P real = 1550kg substitution type (1), get P installed max = P to allow max - P real = 1663-1550 = 113kg, P installed max = 113kg. That is, the maximum weight of the elevator car allowed is 113kg.
计算实例告诉我们,电梯轿厢的装潢重量是有限制的,因此电梯制造厂家在销售过程中应根据电梯轿厢允许的装潢的最大重量做合适的限制,不可盲目承诺客户要求装潢的重量。电梯检验单位在检验过程中也应考虑受检单位电梯装潢的重量,为保证电梯及其零部件的安全长寿把好最后一道关。 The calculation example tells us that the decoration weight of the elevator car is limited. Therefore, the elevator manufacturer should make appropriate restrictions according to the maximum weight of the decoration allowed by the elevator car during the sales process, and cannot blindly promise the weight of the decoration required by the customer. The elevator inspection unit should also consider the weight of the elevator decoration of the unit under inspection during the inspection process, in order to ensure the safety and longevity of the elevator and its parts and components.

Claims (5)

  1. 一种电梯轿厢最大装潢重量的计算方法,其特征在于:包括如下步骤:A method for calculating the maximum decoration weight of an elevator car is characterized in that it comprises the following steps:
    (1)计算轿厢最大装潢重量轿厢P装max,如下公式1所示:(1) Calculate the maximum decoration weight of the car. The car P is installed as Max , as shown in the following formula 1:
    P装max=P允max-P              (1)P installed max = P to allow max - P real (1)
    式中P装max为轿厢允许装潢的最大重量,P允max为轿厢允许的最大自重,P为轿厢实际自重;Wherein P max is the fitted decorated car allowed maximum weight, the maximum P max is the allowed permitted weight of the car, car P is the actual weight of the solid;
    (2)轿厢允许的最大自重P允max的取值:选取轿厢自重临界值Pmax中的最小值作为P max的值;(2) the maximum allowable weight of the car P max allowed values: Select the minimum car weight threshold value P max is the max allowed as the value of P;
    (3)计算轿厢自重临界值Pmax:分别从曳引钢丝绳的安全系数、曳引机主轴许用径向载荷以及主机许用转距或制动器的许用制动转矩三方面计算得出轿厢自重临界值Pmax(3) Calculate the car's own weight threshold P max : calculated from the safety factor of the traction wire rope, the allowable radial load of the traction machine spindle, and the allowable torque of the main engine or the allowable braking torque of the brake. Car weight threshold P max ;
    (4)从步骤(3)中得出的轿厢自重临界值Pmax中选取最小值作为轿厢允许的最大自重P允max,并带入公式1得出最后的轿厢最大装潢重量轿厢P装max(4) Select the minimum value from the car self-weight threshold value P max obtained in step (3) as the maximum allowable self-weight P- max of the car, and bring in the formula 1 to obtain the final car maximum decoration weight car. P installed max .
  2. 根据权利要求1所述的一种电梯轿厢最大装潢重量的计算方法,其特征在于:步骤(3)所述的从曳引钢丝绳的安全系数计算Pmax公式如下:According to an elevator car maximum calculated weight of the decoration to claim 1, wherein: step (3) calculating the safety factor of the hoisting rope from the formula P max as follows:
    Figure PCTCN2015083841-appb-100001
    Figure PCTCN2015083841-appb-100001
    推导得出
    Figure PCTCN2015083841-appb-100002
    Derive
    Figure PCTCN2015083841-appb-100002
    式中S为给定曳引系统悬挂绳安全系数实际值,T为钢丝绳的最小破断拉力,n为钢丝绳根数,m为曳引比,Q为额定载重量,H为提升速度,q为单位长度曳引钢丝绳重量,gn为重力加速度;其中根据曳引钢丝绳安全系数校核原则,S≥Sf≥Sm这里S的可取值中最小值是Sf,将S=Sf代入式2即可,Sf为考虑了曳引轮绳槽形状,滑轮数量与弯曲情况所得到的给定曳引系统钢丝绳许用安全系数计算值;Sm为GB7588一2003 9.2.2条款规定的曳引钢丝绳许用安全系数最小值。Where S is the actual value of the safety factor of the suspension rope of a given traction system, T is the minimum breaking force of the rope, n is the number of ropes, m is the traction ratio, Q is the rated load, H is the lifting speed, q is the unit the length of the hoisting rope by weight, g n is the gravitational acceleration; wherein the safety factor according to the principle of checking the hoisting rope, S≥S f ≥S m herein may be in the minimum value of S is S f, S = S f will be substituted into the formula 2, S f is the calculated safety factor of the wire rope of a given traction system obtained by considering the shape of the rope of the traction sheave, the number of pulleys and the bending condition; S m is the drag specified in clause 9.2.2 of GB7588-2003 The minimum safety factor for the wire rope is allowed.
  3. 根据权利要求1所述的一种电梯轿厢最大装潢重量的计算方法,其特征在于:步骤(3)所述的曳引机主轴许用径向载荷计算Pmax公式如下:The method of calculating the maximum weight of one decor of the elevator car as claimed in claim 1, wherein: step (3) of the hoisting machine spindle permissible radial load P max is calculated using the following formula:
    Amax=(Pmax+1.25Q+W+W1+W2)/m,A max = (P max + 1.25Q + W + W 1 + W 2 ) / m,
    推导得出Pmax=mAmax-1.25Q-W-W1-W2              (3)Deduced that P max = mA max -1.25Q-W-W 1 -W 2 (3)
    式中Amax为主机轴径向最大静载荷,m为曳引比,Q为额定载重量,W为对重重量,W1为曳引钢丝绳重量,W2为补偿链重量。Where A max is the radial maximum static load of the main shaft, m is the traction ratio, Q is the rated load, W is the counterweight, W 1 is the weight of the traction rope, and W 2 is the weight of the compensation chain.
  4. 根据权利要求1所述的一种电梯轿厢最大装潢重量的计算方法,其特征在于:步骤(3)所述的主机许用转距或制动器的许用制动转矩计算Pmax公式如下: The method of calculating the maximum weight of one decor of the elevator car as claimed in claim 1, wherein: step (3) of the host or from the allowable rotation allowable brake braking torque calculating the following formula P max:
    Figure PCTCN2015083841-appb-100003
    Figure PCTCN2015083841-appb-100003
    推导
    Figure PCTCN2015083841-appb-100004
    Derivation
    Figure PCTCN2015083841-appb-100004
    式中Mmax为制动器许用制动转矩,m为曳引比,D是曳引轮节圆直径,gn为重力加速度,η为机械传动总效率,Q为额定载重量,W为对重重量,W1为曳引钢丝绳重量,W2为补偿链重量。Where M max is the brake allowable braking torque, m is the traction ratio, D is the traction wheel pitch circle diameter, g n is the gravity acceleration, η is the total mechanical transmission efficiency, Q is the rated load, W is the pair Heavy weight, W 1 is the weight of the traction wire rope, and W 2 is the weight of the compensation chain.
  5. 根据权利要求3或4所述的一种电梯轿厢最大装潢重量的计算方法,其特征在于:所述对重重量W的计算公式为W=P实+KQ,式中P实为轿厢自重,K为电梯平衡系数,Q为额定载重量;W1=Hn1mq1,式中H为提升速度,n1为钢丝绳系数,m为曳引比,q1为单位长度钢丝绳重量;W2=Hn2q2,式中H为提升速度,n2为补偿链根数,q2为单位长度补偿链重量。 The method for calculating the maximum decoration weight of an elevator car according to claim 3 or 4, characterized in that: the calculation formula of the counterweight W is W=P real+KQ, where P is the weight of the car. K is the elevator balance coefficient, Q is the rated load; W1=Hn1mq1, where H is the lifting speed, n1 is the wire rope coefficient, m is the traction ratio, q1 is the weight per unit length of the wire rope; W2=Hn2q2, where H is Increase the speed, n2 is the number of compensation chains, and q2 is the weight of the compensation chain per unit length.
PCT/CN2015/083841 2015-02-05 2015-07-13 Calculating method for maximum decoration weight of lift car WO2016123902A1 (en)

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