WO2010149094A1 - Method and system for synchronizing upward transmission in passive optical network - Google Patents

Method and system for synchronizing upward transmission in passive optical network Download PDF

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Publication number
WO2010149094A1
WO2010149094A1 PCT/CN2010/074705 CN2010074705W WO2010149094A1 WO 2010149094 A1 WO2010149094 A1 WO 2010149094A1 CN 2010074705 W CN2010074705 W CN 2010074705W WO 2010149094 A1 WO2010149094 A1 WO 2010149094A1
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update
maximum
updated
value
information
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PCT/CN2010/074705
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French (fr)
Chinese (zh)
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张伟良
耿丹
张德智
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中兴通讯股份有限公司
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    • H—ELECTRICITY
    • H04—ELECTRIC COMMUNICATION TECHNIQUE
    • H04J—MULTIPLEX COMMUNICATION
    • H04J3/00—Time-division multiplex systems
    • H04J3/02—Details
    • H04J3/06—Synchronising arrangements
    • H04J3/0635—Clock or time synchronisation in a network
    • H04J3/0682—Clock or time synchronisation in a network by delay compensation, e.g. by compensation of propagation delay or variations thereof, by ranging

Definitions

  • This paper deals with the field of communication wood, especially the method and system of medium synchronization uplink.
  • GPO Wood is an important wood branch in the (PO) family. Like other PO woods, GPO is also a god-like material.
  • the GPO consists of the optical terminal (p ca eTem a, O T), the user's light (p ca ewok , O J), and the light distribution ( p ca s b o ewok, O ), usually at most.
  • O consists of optical devices such as sheep chops, optical branches, and optical connectors. The physical connections between O T and O are provided.
  • the downlink direction is from OT to O)
  • the OJ receives all the OJ (OJ de ca o , O J- ) GPO encapsulation mode (GPO E caps ao ode, G )- ( o ), Assignment (A oca o ) - for yourself.
  • the upstream direction O J to O T
  • each O J is taught in the O T arrangement.
  • Each O J O T is the same, preventing the upstream teaching of each O J from O T, O T
  • the OOJOT is balanced, that is, each O is sent upstream, and the equalized segment that needs to be extended is sent back to the uplink, and all OJ uplinks are synchronized.
  • the OT first supports the most (most) OJ.
  • OT measurement The value of J ( od pdeay, RT ) , the value of the maximum equilibrium of all OJs ( qa za o eay, q )
  • the OJ is connected to the PO system, and OT measures the RT of OJ, and obtains the value of q of OJ (q, q ax-RT ,).
  • the wood problem to be solved is to provide a method and system for synchronizing uplinks, and to improve the uplink efficiency in the uplink synchronization.
  • this provides a medium-synchronous uplink, and the method includes the maximum value in (RT) of O).
  • the method Before the step of updating the RT q update information of the O T , the method includes the maximum value RT of the RT of all the previous O Js in the O T storage PO system and
  • OT periodically and/or irregularly measures some or all of the O in the PO system T, will be part or all of the O stored in the RT storage T ax comparison, if there is a measured RT greater than the OT stored, then the OT will store the RT update power greater than the stored RT in the measured RT
  • the maximum RT OT update RT q update information steps include the RT update, the OT update RT update maximum balance , updated maximum equilibrium
  • the q update of some or all of the O in the PO system will update the q work force q update information.
  • OT updated q Before the step of updating the information, the method includes
  • O T stores the maximum value of all RTs in all PO systems before the ax
  • the OT is connected to the O in the PO system to get the RT of the O and the RT and OT of the OT comparison O.
  • the RT of the core O is greater than the OT storage.
  • OT will store Xinli O's RT OT updated q
  • the method includes
  • O T stores the maximum value of RT in all RTs of all PO systems before RT ax
  • OT compares the RT of the O and the OT stores the RT.
  • the RT of the core O is equal to the RT of the OT.
  • the maximum value of all the RTs in the OT system is less than the OT. If yes, then OT will store the updated power in the PO system.
  • the maximum value of all RTs in the RT RT method is the same as T in the storage RT, storing the maximum equilibrium q of RT max
  • the steps of updating the TQ update information include the RT update, the maximum balance q of the RT update of the OT update, the maximum balance of the update q, the maximum balance of the update store, the maximum equilibrium of the update q, the q of all the OJs in the system.
  • Method includes T in storage Same, store the maximum equalization of RT ax q
  • the steps of the OT update RT q update information include the maximum balance of the maximum balanced update stored in the RT update of the RT update, the maximum balanced Eq update of the OT update. Maximum balance of stored updates Maximum balance before OT storage update The same to get q, will q force q update letter. OT will q update information all in the OJ step, OT is the same as Ra gg me) message will be updated q
  • O T will update the information in all the steps of O J , O T is the existing or new physical operation management P ) message will be q
  • All of the O P OAM4 messages in the at least include the following q and q values.
  • This provides a system for mid-synchronous uplinks, including terminals OT) and OTs, OTs including T and q, RT storage, and all RTs in the RT RT, q and RT ax updates, Will update the RT Eq
  • This terminal provides OT), which includes (RT) and equalization (q), where the RT stores the maximum value of all RTs in the PO system. q as well, RT update, will update RT q
  • the RT periodically and/or irregularly measures the RT of some or all of the O in the PO system, and compares the RT stored in the RT store. If there is a measured RT greater than the RT stored in the OT, the RT will be stored. The update power is greater than the maximum of the measured RT of the stored RT ax. RT near the new O or need PO and each O is connected to the PO system, received O in the PO system
  • Get the RT of O compare the RT of the O and the RT of the OT store.
  • the value of the RT of the core O is greater than the OT storage.
  • Update O RT and O or under the PO system compare O's RT and OT local storage , the RT of the kernel O is equal to the RT of the OT local storage.
  • the maximum RT q of all the OJ's RTs in the stored update power system is the value of the RT update maximum equalization q of the update mode update information update, all in the updated q PO system
  • the OJ's q update will update the q force q update information or, the updated RT update the maximum equilibrium q value, the updated maximum equilibrium q the maximum equilibrium before the update The same to get q, will q force q update letter.
  • the update of O T is all at the maximum RT of O J , and the maximum RT is updated by q of each O J , which can reduce the q of each O J and improve the uplink efficiency.
  • Step 301 OT PO system in all RT of the O, the maximum RT () maximum equilibrium , The value of q of each OJ Eq q ax-RT Step 302 In the PO system, the new update maximum balance of OT , update the q of each OJ.
  • the scheme OT stores all the OJ's T in the PO system, and stores the maximum RT TOT of all OJs in the PO system. Periodically and/or irregularly measuring all the OJ's RT in the PO system, the measurement result is in the PO system. Whether, if, new And out of the OJ's RT re-all in the o's q, will update the Eq all in the OJ
  • Solution O T stores all O J RTs in the PO system, and stores the maximum RT value of all O Js in the PO system and the maximum RT maximum q.
  • the new OJ needs OJ to PO system, OT measures the RT of OJ, compares the maximum RT of OJ's RT OT local storage, the RT of OJ is greater than the maximum RT of OT local storage, OT updates the maximum RT O of local storage.
  • RT, and OT update maximum RT maximal q, OT store updated maximum equalization q, OT pre-update and updated maximum Eq
  • OT compares the maximum RT of the RT OT local storage of OJ. If the RT of the OJ is equal to the maximum RT of the OT local storage, the OT compares the maximum RT value of the OJ with the maximum RT of the OT local storage. If the value of all the maximum RT in OJ is less than the maximum RT stored in OT local storage, OT updates the value of the maximum RT stored locally, the value of the maximum RT in OJ in the PO system, and the maximum RT of the OT update.
  • Maximum equalization q, OT storage Updated maximum equalization q, OT storage before update and updated maximum q OT updates the maximum stored RT and q values of the local storage, all the information in J, the updated Eq information OJ, the OJ that receives the updated q information updates the local q, and synchronizes the updated q according to the q.
  • the q information of O T O J may be the updated Eq of O J or the q required by O J . Among them, O T can update the q value of O J respectively, or all the q required in O J .
  • O T can create a new physical operation management (Physca aye Ope a o s Adm s a o a d a e a c , P OAM4) message in the same way as all q required in O J .
  • the method for synchronizing the uplink in the present element mainly includes the following step 101, the OT is completed every OJ, the OT stores the value of the OJ, and the OT stores the value of the maximum RT of the RT of all the previous OJs in the PO system.
  • Step 102 The OT periodically and/or irregularly measures all the OJ's RTs in the PO system, and compares all the OJ's RTs, the stored RTs, and the OJ's RTs, which are greater than the OT local storage. , then OT will locally store the maximum RT update power out of the value of RT, the value of step 103, the OT update RT update q, the updated and re-out RT, the value of q of each OJ is updated by the following formula Qq aX-RT Step 104, OT will update the value of q of each OJ all OJ, OJ in the synchronized q synchronization uplink.
  • the OT can also be used for the old cycle of each O, and the measurement of the partial O RT is required. The steps in the measurement step are exactly the same, and are not used here.
  • O T is completed by O, O T stores the RT of O, and O T stores the value of the maximum RT value RT and T of the RT in the RT of all PO systems.
  • Step O T is newly connected to O in the PO system, and gets the RT of O.
  • Step the OT stores the value of the RT of the O, compares the value of the RT of the O and the OT local storage , fruit O
  • the OT stores the updated value, and can store the updated q OT storage before the update q with the same value of the RT of the RT is less than or equal to the OT local storage, Then OT and O directly perform the steps
  • Step, O T can update the PO system in the next way.
  • the OT will store the updated q OT stored in the step with the q before the update, that is, the information of the q required by each O,
  • the P M4 message shown in 1 is all shown in the working O, d 1 , and the P OA message of qas includes the partial composition, the first part O
  • Step 2 the new OJ q of the PO system, the q OOJ of O receives the storage OT body q, the work steps, all the working OJs are synchronized according to the locally updated q .
  • the PO system has the OJ, OT and OJ methods to complete all the upstream OJ synchronization OT comparison OJ T, the value and OT local storage If the value of RT of OJ is equal to OT local storage, then OT compares all current RTs of working OJ, and OT stores RT, and the current maximum RT of all working O is less than OT. Locally stored RT OT will be local.
  • the stored RT update power is currently all working on the OJ RT, the largest RT in the update, Updated value, can, can store updated OT storage before the update q same, OT and O execution steps and steps and steps and steps and steps and steps and steps and steps
  • OJ's RT is less than the OT local storage RT, or the current maximum RT of all working OJs is equal to OT local storage. , then OT and OJ do nothing.
  • the medium provides a synchronous uplink system, including OT and OJ, the OT step includes RT and q, where RT stores PO) all the OJ's largest forest RT in the system), q and, Update, will update the RT q
  • OT which includes (RT) and equalization (Eq), where the RT stores a PO) all in the RT of the light
  • Eq equalization
  • the RT can store and update the RT of all OJs in the OT local storage PO system periodically and/or irregularly to measure some or all of the OJ's RT in the PO system, and the RT storage will be output. RT comparison, the value of the RT is greater than the OT local storage , then update the local storage The value of the RT.
  • the RT can also store and update all of the OJ's RTs in all PO systems before the OT local storage in the RT mode.
  • each OqJ is connected to the PO system.
  • the OJ in the PO system receives the value of the OJ RT, compares the value of the OJ RT and the OT local storage. , fruit core O
  • the PO system compare the value of RT of OJ and RT of OT local storage, and the value of RT of O core of OqJ is equal to the RT ax of OT local storage, then the maximum RT of all OJs in the PO system Is it less than the OT local storage RT, if it is, then update the local storage The maximum RT of all OJs in the PO system.
  • the next mode q update information updates the value of the RT update q, the updated q PO system all the OJ's q update, the updated q force q update information O or, the updated RT Update the value of q, updated Before the update In the same way, will be updated to update all the information in O.
  • the instructions are completed by hardware, and the program can be stored in a storable memory, only memory, or the like. Yes, all or part of the steps can also be used or integrated.
  • Each of the phases / sheep can be in the form of hardware or in the form of software functions. This is not limited to any specific form of hardware or software combination.
  • T updates all the maximum T in J
  • the maximum RT updates each q of q, which can reduce the q of each O J and improve the uplink efficiency.

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  • Engineering & Computer Science (AREA)
  • Computer Networks & Wireless Communication (AREA)
  • Signal Processing (AREA)
  • Small-Scale Networks (AREA)
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Abstract

Disclosed is a method for synchronizing upward transmission in passive optical network. The method includes the following steps: An Optical Line Terminal (OLT) determines a maximum Equalization Delay EqDmax according to the maximum RTDmax among Round trip delay (RTD) of all online Optical Network Units (ONU) in Passive Optical Network (PON) system and calculates values of Equalization delay (EqD) of all ONU according to the maximum Equalization Delay EqDmax; when the RTDmax is updated, the OLT calculates EqD update information according to the updated RTDmax; the OLT sends the EqD update information to all online ONU, and the ONU updates the value of EqD according to the received EqD update information and then synchronizes upward transmission according to the updated value of EqD. The present invention also provides a system for synchronizing upward transmission in passive optical network and an OLT. The present invention improves efficiency of upward transmission.

Description

中同步上行 的方法及 統  Method and system for synchronous uplink
木領域 Wood field
本 涉及通信 木領域， 尤其涉及 中同步上行 的 方法及 統。  This paper deals with the field of communication wood, especially the method and system of medium synchronization uplink.
背景 木 Background
比特 (Gg北 -C 北e assve Op ca ewok，  Bit (Gg North-C North e assve Op ca ewok,
GPO ) 木是 (PO )家族中 介重要的 木分支，和其它PO 木 似， GPO 也是 神采 到多 的元 接 木。 GPO) Wood is an important wood branch in the (PO) family. Like other PO woods, GPO is also a god-like material.
GPO 統的 1所示，GPO 由 的光 終端( p ca eTem a， O T) 、 用戶 的光 羊 ( p ca ewok , O J) 以及光分配 ( p ca s b o ewok， O ) 組成， 通常 到多 的 。 O 由羊 仟、 光分路 以及光 接器等 光器件組成， O T和O 同的物理連接提供 。 在GPO 統中，下行方向 由 O T到 O )的 用戶播方式， O J分別接收所有的 ， 再 O J (O J de ca o , O J- ) GPO 封裝模式(GPO E caps a o ode, G )- ( o ) 、 分配 (A oca o ) - 于 己的 。 然而， 于上行方向 (O J到 O T) 的 ， 由于各 O J需要共享 ， 因此各 O J 在O T安排 己的 內 上行教 。 各 O J O T 同的 不同， 防止各 O J 的上行教 同 到 O T, O T需要 As shown in the GPO system 1, the GPO consists of the optical terminal (p ca eTem a, O T), the user's light (p ca ewok , O J), and the light distribution ( p ca s b o ewok, O ), usually at most. O consists of optical devices such as sheep chops, optical branches, and optical connectors. The physical connections between O T and O are provided. In the GPO system, the downlink direction is from OT to O), and the OJ receives all the OJ (OJ de ca o , O J- ) GPO encapsulation mode (GPO E caps ao ode, G )- ( o ), Assignment (A oca o ) - for yourself. However, in the upstream direction (O J to O T), since each O J needs to be shared, each O J is taught in the O T arrangement. Each O J O T is the same, preventing the upstream teaching of each O J from O T, O T
O J ， 將 結果 得 O J的均衡  O J , will result in an equilibrium of O J
的O O J O T 的均衡 的 ，即O 各 送上行 ， 需要延退 身的均衡 的 段 同 再 送上行 ， 所有O J上行 的同步。 在現有的 各 O 上行 同步的相 木中， O T首先 身支持的 O J 己的最 ( 最 ) 。 O T 測量 J的 ( o d pdeay， RT ) 的值
Figure imgf000004_0001
， 所有O J的最大均衡 ( q a za o eay， q ) 的值
Figure imgf000004_0002
介O J接 到PO 統中 ，O T測量 O J的RT ，， 而得到 O J的 q ，的值 ( q ， q ax-RT ，) 。 在此 木中， RT ax 的值是不 的， 因此 q 的值是不 的， O J都 q 的值得 到 身的 q 的值， PO 統中 較大 ， O 的 q 的值也 較大， 致上行 的效率較低。 因此， 有必要提供 解決方案， 以解決 PO 統中 較大 ， 致上行 的效率較低的問題。 The OOJOT is balanced, that is, each O is sent upstream, and the equalized segment that needs to be extended is sent back to the uplink, and all OJ uplinks are synchronized. In the existing O-upstream synchronization, the OT first supports the most (most) OJ. OT measurement The value of J ( od pdeay, RT )
Figure imgf000004_0001
, the value of the maximum equilibrium of all OJs ( qa za o eay, q )
Figure imgf000004_0002
The OJ is connected to the PO system, and OT measures the RT of OJ, and obtains the value of q of OJ (q, q ax-RT ,). In this wood, the value of RT ax is not, so the value of q is not, the value of q of OJ is the value of q, the larger the PO system, the larger the value of q of O, the higher the The efficiency is lower. Therefore, it is necessary to provide a solution to solve the problem of a large, low-efficiency in the PO system.
內容 Content
本 要解決的 木問題是提供 中同步上行 的方法 及 統， 在 上行 同步的同 提高上行 效率。 了解決上 ， 本 提供了 中同步上行 的 ， 方法包括 O )的 (RT ) 中的最大值 T 最大均衡 q  The wood problem to be solved is to provide a method and system for synchronizing uplinks, and to improve the uplink efficiency in the uplink synchronization. In the solution, this provides a medium-synchronous uplink, and the method includes the maximum value in (RT) of O).
最大均衡
Figure imgf000004_0003
所有O J的均衡 ( q ) 的值 占所
Figure imgf000004_0005
更新 ， O T 更新 的
Figure imgf000004_0004
q 更新 信息 以及 Maximum equilibrium
Figure imgf000004_0003
The value of all OJ's equilibrium (q) accounts for
Figure imgf000004_0005
Update, OT updated
Figure imgf000004_0004
q update information and
O T Eq 更新信息 所有在 的 O J， O J 收到的 q 更新信息 q 的值 更新 ， 按照更新 的 q 的值同步上 行 。  O T Eq Update information All the values of the q update information q received by O J, O J are updated, and the values of the updated q are synchronized.
O T 更新 的RT q 更新信息的步驟 前， 方法近 包括 O T存儲 PO 統中 前所有在 的 O J的的RT 中的最大 值RT 以及  Before the step of updating the RT q update information of the O T , the method includes the maximum value RT of the RT of all the previous O Js in the O T storage PO system and
O T定期和/或不定期地測量 PO 統中部分或全部在 的 O 的 T ， 將 出的部分或全部在 的 O 的RT 存儲的 T ax 比較， 果存在大于O T存儲的 的測出的RT ， 則 O T將存儲的 RT 更新力 大于存儲的RT 的測出的RT 中的最大的RT O T 更新 的 RT q 更新信息的步驟包括 占所RT 更新 ， O T 更新 的RT 更新最大均衡
Figure imgf000005_0001
， 更新 的最大均衡
Figure imgf000005_0002
PO 統中部分或全部在 的O 的 q 更新 ， 將更新 的 q 作力 q 更新信息。 O T 更新 的
Figure imgf000005_0003
q 更新信息的步驟 前， 方法近 包括OT periodically and/or irregularly measures some or all of the O in the PO system T, will be part or all of the O stored in the RT storage T ax comparison, if there is a measured RT greater than the OT stored, then the OT will store the RT update power greater than the stored RT in the measured RT The maximum RT OT update RT q update information steps include the RT update, the OT update RT update maximum balance
Figure imgf000005_0001
, updated maximum equilibrium
Figure imgf000005_0002
The q update of some or all of the O in the PO system will update the q work force q update information. OT updated
Figure imgf000005_0003
q Before the step of updating the information, the method includes
O T存儲 前所有 PO 統中所有在 的 O 的 RT 中的最大值 ax  O T stores the maximum value of all RTs in all PO systems before the ax
介新的O 或者常要 PO 並各的O 接 到 PO 統 中時， O T 接 到PO 統中的 O 得到 O 的RT 以及 O T比較 O 的RT 和O T存儲 ， 果核O 的RT 大于O T存儲的
Figure imgf000005_0005
則 O T將存儲的
Figure imgf000005_0004
新力 O 的RT O T 更新 的
Figure imgf000005_0006
q 更新信息的步驟 前， 方法近 包括 When a new O or a PO is required and each O is connected to the PO system, the OT is connected to the O in the PO system to get the RT of the O and the RT and OT of the OT comparison O. The RT of the core O is greater than the OT storage.
Figure imgf000005_0005
Then OT will store
Figure imgf000005_0004
Xinli O's RT OT updated
Figure imgf000005_0006
q Before the step of updating the information, the method includes
O T存儲 前所有 PO 統中所有在 的 O 的 RT 中的最大值RT ax O T stores the maximum value of RT in all RTs of all PO systems before RT ax
PO 統中的 O 或下 ， O T比較 O 的 RT 和O T存儲的RT 果核O 的RT 等于O T存儲的RT 則 O T PO 統中所有在 的 O 的 RT 中的最大值是否小于 O T存儲的
Figure imgf000005_0007
果是， 則 O T將本地存儲的 更新力PO 統中所有在 的O 的RT 中的最大值RT 方法近 T在存儲 RT 的同 ，存儲 RT max 的最大均衡 q T 更新 的 T q 更新信息的步驟包括 占所 RT 更新 ， O T 更新 的 RT 更新的最大均衡 q ， 更新 的最大均衡 q 更新存儲的最大均衡 q 更新 的最大均衡 q PO 統中所有在 的O J的 q 更新 ， 將更新 的 q 作力 q 更新信息。 方法近包括 T在存儲
Figure imgf000006_0001
的同 ，存儲 RT ax 的最大均衡 q O or lower in the PO system, OT compares the RT of the O and the OT stores the RT. The RT of the core O is equal to the RT of the OT. The maximum value of all the RTs in the OT system is less than the OT.
Figure imgf000005_0007
If yes, then OT will store the updated power in the PO system. The maximum value of all RTs in the RT RT method is the same as T in the storage RT, storing the maximum equilibrium q of RT max The steps of updating the TQ update information include the RT update, the maximum balance q of the RT update of the OT update, the maximum balance of the update q, the maximum balance of the update store, the maximum equilibrium of the update q, the q of all the OJs in the system. Update, update q to force q update information. Method includes T in storage
Figure imgf000006_0001
Same, store the maximum equalization of RT ax q
O T 更新 的 RT q 更新信息的步驟包括 占所 RT 更新 ， O T 更新 的 RT 更新的最大均衡Eq 更新 的最大均衡 更新存儲的最大均衡
Figure imgf000006_0003
存儲 更新 的最大均衡
Figure imgf000006_0002
O T存儲的更新前 的最大均衡
Figure imgf000006_0004
同的 以得到 q ， 將 q 作力 q 更新信 。 O T將 q 更新信息 所有在 的O J 的步驟中， O T 是通 同 Ra g g me)消息將 更新 的 q The steps of the OT update RT q update information include the maximum balance of the maximum balanced update stored in the RT update of the RT update, the maximum balanced Eq update of the OT update.
Figure imgf000006_0003
Maximum balance of stored updates
Figure imgf000006_0002
Maximum balance before OT storage update
Figure imgf000006_0004
The same to get q, will q force q update letter. OT will q update information all in the OJ step, OT is the same as Ra gg me) message will be updated q
。 。 O T將 q 更新信息 所有在 的O J 的步驟中， O T 是通 現有的或新建的物理 操作 管理P )消息將 q . . O T will update the information in all the steps of O J , O T is the existing or new physical operation management P ) message will be q
所有在 的O P OAM4消息的 中至少包括以下內容 q 和 q 值的 。  All of the O P OAM4 messages in the at least include the following q and q values.
本 近提供了 中同步上行 的 統， 包括 終 端 O T)和光 羊 O )， O T包括 T 和 q ， RT 存儲 PO ) 統中所有在 的 O 的RT 中的最大值RT ， q 以及， RT ax 更新 ， 將更新 的RT Eq This provides a system for mid-synchronous uplinks, including terminals OT) and OTs, OTs including T and q, RT storage, and all RTs in the RT RT, q and RT ax updates, Will update the RT Eq
q PO 統中 RT 最大均衡
Figure imgf000007_0001
最大均衡 q 所有 的 q 的值 以及，q PO system maximum RT equalization
Figure imgf000007_0001
Maximum equilibrium q all the values of q as well,
"  "
接收到的更新 的
Figure imgf000007_0002
q 更新信息， 所有在 的 O O 收到的 q 更新信息 q 更新 ， 按照更新 的 q 同步上行 。 Received updates
Figure imgf000007_0002
q Update information, all updates received in the OO q update information q, follow the updated q sync upstream.
本 近提供了 終端 O T)， 其包括 (RT ) 和均衡 ( q ) ， 其中 所迷RT 存儲 PO 統中所有在 的光 羊 O )的RT 中的最大值
Figure imgf000007_0003
q 以及， RT 更新 ， 將更新 的RT qThis terminal provides OT), which includes (RT) and equalization (q), where the RT stores the maximum value of all RTs in the PO system.
Figure imgf000007_0003
q as well, RT update, will update RT q
q RT " 最大均衡
Figure imgf000007_0004
， 所述最大均衡 q 所有O 的 q 的值 以及， 接收 到的更新 的
Figure imgf000007_0005
q 更新信息， 所有在 的O ， 以使 O 收到的 q 更新信息 q 更新 ， q RT "maximum equalization
Figure imgf000007_0004
, the maximum equalization q, the value of q for all O, and the received update
Figure imgf000007_0005
q update information, all in the O, so that O receives the q update information q update,
同步上行 。 "更新 的Eq Synchronous uplink. "Updated Eq
RT 近 定期和/或不定期地測量 PO 統中部分或全部在 的 O 的 RT ， 將 出的RT 存儲的RT 比較， 果存在大于O T存儲 的 RT 的測出的 RT ， 則將存儲的
Figure imgf000007_0006
更新力大于 存儲的 RT ax 的測出的RT 中的最大值。 RT 近 介新的 O 或者需要 PO 並各的 O 接 到 PO 統中 ， 接 到PO 統中的O The RT periodically and/or irregularly measures the RT of some or all of the O in the PO system, and compares the RT stored in the RT store. If there is a measured RT greater than the RT stored in the OT, the RT will be stored.
Figure imgf000007_0006
The update power is greater than the maximum of the measured RT of the stored RT ax. RT near the new O or need PO and each O is connected to the PO system, received O in the PO system
得到 O 的RT ， 比較 O 的RT 和O T存儲的RT 果 核O 的RT 的值大于O T存儲的
Figure imgf000007_0008
，則將存儲的
Figure imgf000007_0007
更新力O RT 以及 PO 統中的O 或下 ，比較 O 的RT 和O T 本地存儲的
Figure imgf000007_0009
， 果核O 的RT 等于O T本地存儲的RT 則Get the RT of O, compare the RT of the O and the RT of the OT store. The value of the RT of the core O is greater than the OT storage.
Figure imgf000007_0008
, will be stored
Figure imgf000007_0007
Update O RT and O or under the PO system, compare O's RT and OT local storage
Figure imgf000007_0009
, the RT of the kernel O is equal to the RT of the OT local storage.
P 統中所有在 的O 的RT 中的最大RT 是否小于O T 存儲的 T 果是， 則將存儲的 更新力PO 統中所有在 的O J的RT 中的最大RT q 是 下方式 q 更新信息 更新 的 RT 更新最大均衡 q 的值， 更新 的 q PO 統中所有在 的 O J的 q 更新 ， 將更新 的 q 作力 q 更新信息 或者， 更新 的 RT 更新最大均衡 q 的值， 更 新 的最大均衡 q 更新前的最大均衡
Figure imgf000008_0001
同的 以 得到 q ， 將 q 作力 q 更新信 。 Is the maximum RT of all RTs in the P system less than OT? If the stored T is, then the maximum RT q of all the OJ's RTs in the stored update power system is the value of the RT update maximum equalization q of the update mode update information update, all in the updated q PO system The OJ's q update, will update the q force q update information or, the updated RT update the maximum equilibrium q value, the updated maximum equilibrium q the maximum equilibrium before the update
Figure imgf000008_0001
The same to get q, will q force q update letter.
本 明技木方案， O T 的更新所有在 O J的最大RT ， 最大RT 更新各 O J的 q ，可以減小各 O J的 q , 而提高上行 效率。  In the technical solution of this invention, the update of O T is all at the maximum RT of O J , and the maximum RT is updated by q of each O J , which can reduce the q of each O J and improve the uplink efficiency.
1 GPO 統的 示意 2力本 的元 中同步上行 的 統的示意1 GPO system diagram 2
3力本 的元 中同步上行 的方法的流程 。  The process of the method of synchronizing the uplink in the 3 yuan.
本 的較佳 方式 The preferred way of this
本 的 的元 中同步上行 的方法的流程 3所 示， 包括  The flow of the method for synchronizing the uplink in the meta-indicator 3, including
步驟301 O T PO 統中所有在 的O 的RT ，中的最大RT ( ) 最大均衡
Figure imgf000008_0002
，
Figure imgf000008_0003
各O J的 q 的值 Eq q ax-RT 步驟302 PO 統中的 ， O T 的新 的 更新最大均衡
Figure imgf000008_0004
， 更新各 O J的 q 的 。 步驟303 O T將各 的更新 的 q 信息， 或者， 各O 需要 的 q 的 的O O J按照更新 的 q 同步上行 。 Step 301 OT PO system in all RT of the O, the maximum RT () maximum equilibrium
Figure imgf000008_0002
,
Figure imgf000008_0003
The value of q of each OJ Eq q ax-RT Step 302 In the PO system, the new update maximum balance of OT
Figure imgf000008_0004
, update the q of each OJ. Step 303: The OT synchronizes each updated q information, or the OOJ of the q required by each O, according to the updated q.
休 ， 本 至少可以 下 方案  Hugh, this at least can be
方案 O T存儲PO 統中所有 O J的 T ， 存儲PO 統中所有 O J的最大RT T O T 定期和/或不定期的測量PO 統中所有在 的 O J的RT ， 測量結果 PO 統中的
Figure imgf000009_0001
是否 ， 果 ， 則 新的
Figure imgf000009_0002
和 出的O J的RT 重新 所有在 的O 的 q ， 將更新 的Eq 所有在 的O J The scheme OT stores all the OJ's T in the PO system, and stores the maximum RT TOT of all OJs in the PO system. Periodically and/or irregularly measuring all the OJ's RT in the PO system, the measurement result is in the PO system.
Figure imgf000009_0001
Whether, if, new
Figure imgf000009_0002
And out of the OJ's RT re-all in the o's q, will update the Eq all in the OJ
方案 O T存儲PO 統中所有 O J的 RT ， 存儲PO 統中所有 O J的最大RT 值及 最大RT 的最大 q  Solution O T stores all O J RTs in the PO system, and stores the maximum RT value of all O Js in the PO system and the maximum RT maximum q.
新的O J或需要 並各的O J 到PO 統 ， O T測量 O J的RT ， 比較 O J的RT O T本地存儲的最大RT , 果 O J的RT 大于O T本地存儲的最大RT , O T更新本地存儲 的最大RT O J的RT ， 且O T 更新 的最大RT 最大均衡 q , O T存儲更新 的最大均衡 q , O T 更新前和更新 的最大Eq 的 The new OJ needs OJ to PO system, OT measures the RT of OJ, compares the maximum RT of OJ's RT OT local storage, the RT of OJ is greater than the maximum RT of OT local storage, OT updates the maximum RT O of local storage. RT, and OT update maximum RT maximal q, OT store updated maximum equalization q, OT pre-update and updated maximum Eq
PO 統中 O J 或下 ， O T比較 O J的 RT O T本地存儲的最大RT ， 果 O J的RT 等于O T本地存儲的 最大RT ，則 O T比較所有在 O J的最大RT 的值和O T本地存儲的 最大RT ， 果所有在 O J的最大RT 的值小于O T本地存儲的最大RT , O T更新本地存儲的最大RT 的值 PO 統中在 O J的最大 RT 的值， 且O T 更新 的最大RT 更新最大均衡 q , O T存儲更新 的最大均衡 q ,O T存儲更新前和更新 的最大 q 的 O T更新本地存儲的最大RT 和 q 的值 ， 所有在 J的 q 信息， 將更新 的Eq 信息 O J， 接收到更新 q 信息的 O J更新本地的 q ， 按照更新 的 q 同步上行 。 In the PO system OJ or below, OT compares the maximum RT of the RT OT local storage of OJ. If the RT of the OJ is equal to the maximum RT of the OT local storage, the OT compares the maximum RT value of the OJ with the maximum RT of the OT local storage. If the value of all the maximum RT in OJ is less than the maximum RT stored in OT local storage, OT updates the value of the maximum RT stored locally, the value of the maximum RT in OJ in the PO system, and the maximum RT of the OT update. Maximum equalization q, OT storage Updated maximum equalization q, OT storage before update and updated maximum q OT updates the maximum stored RT and q values of the local storage, all the information in J, the updated Eq information OJ, the OJ that receives the updated q information updates the local q, and synchronizes the updated q according to the q.
其中， O T O J的 q 信息可以是 O J的更新 的Eq ， 也可以是O J需要 的 q 。 其中， O T可以將更新 的 q 值分別 O J， 也可以同 所有在 O J 需要 的 q 。  The q information of O T O J may be the updated Eq of O J or the q required by O J . Among them, O T can update the q value of O J respectively, or all the q required in O J .
步 ， O T可以 新建 介物理 操作管理 (Physca aye Ope a o s Adm s a o a d a e a c , P OAM4) 消息的方式同 所有在 O J 需要 的 q 。  Step, O T can create a new physical operation management (Physca aye Ope a o s Adm s a o a d a e a c , P OAM4) message in the same way as all q required in O J .
下面結合 休 本 明技木方案的 步 。 The following is a combination of the steps of the Hugh Benming technique.
本 提供的元 中同步上行 的方法主要包括 下步驟 步驟101， O T 每 介O J完成 ，O T存儲 O J的 的值， 且O T存儲PO 統中 前所有在 的 O J的 RT ，中的最大 RT 的值 T ax The method for synchronizing the uplink in the present element mainly includes the following step 101, the OT is completed every OJ, the OT stores the value of the OJ, and the OT stores the value of the maximum RT of the RT of all the previous OJs in the PO system. Ax
步驟102,O T定期和/或不定期地測量PO 統中所有在 的 O J的 RT ，， 將 出的所有O J的RT ， 存儲的RT 比較， 果 出的 O J的RT ，的值大于O T本地存儲的
Figure imgf000010_0001
， 則 O T將本地存 儲的最大RT 更新力 出的O 的RT ，的值 步驟 103, O T 更新 的 RT 更新 q ， 更新 的 和重新 出的 RT ，的值， 利用以下公式更新各O J的 q 的值 q q aX-RT 步驟104,O T將更新 的各O J的 q 的值 所有在 的O J, O J按照更新 的 q 同步上行 。 此外， 本 中， O T也可以 各O 的老 周期， 需要重 新 的部分O RT 的測量， 其測量步驟 上 步驟完全相同， 在 此不再 。 Step 102: The OT periodically and/or irregularly measures all the OJ's RTs in the PO system, and compares all the OJ's RTs, the stored RTs, and the OJ's RTs, which are greater than the OT local storage.
Figure imgf000010_0001
, then OT will locally store the maximum RT update power out of the value of RT, the value of step 103, the OT update RT update q, the updated and re-out RT, the value of q of each OJ is updated by the following formula Qq aX-RT Step 104, OT will update the value of q of each OJ all OJ, OJ in the synchronized q synchronization uplink. In addition, in this case, the OT can also be used for the old cycle of each O, and the measurement of the partial O RT is required. The steps in the measurement step are exactly the same, and are not used here.
O T 介O 完成 ， O T存儲 O 的RT ， ， 且 O T存儲 前所有PO 統中在 的 O 的 RT ， 中的最大RT 的值 RT 及 T 的 q 的值。 O T is completed by O, O T stores the RT of O, and O T stores the value of the maximum RT value RT and T of the RT in the RT of all PO systems.
占有 介新的O 或者需要 PO 並各的OqJ接 到PO 統 ，O T和O 下 主要步驟完成所有上行O J的 同步  Occupy new O or need PO and each OqJ is connected to PO system, O T and O. Main steps to complete synchronization of all uplink O J
步驟 ， O T 新接 到 PO 統中 O ， 得到 O 的RT ,  Step, O T is newly connected to O in the PO system, and gets the RT of O.
步驟 ， O T存儲所述O 的 RT ，的值， 比較 O 的 RT 的值和O T本地存儲的
Figure imgf000011_0001
， 果 O Step, the OT stores the value of the RT of the O, compares the value of the RT of the O and the OT local storage
Figure imgf000011_0001
, fruit O
本地存儲的
Figure imgf000011_0002
Locally stored
Figure imgf000011_0002
的 RT ，的值， 更新 的 RT 更新 q 的值， O T存儲更新 的 的值， 且近可以存儲 更新 的 q O T存儲的更新 前的 q 同的 果 O 的RT 的值小于等于O T本地存 儲的 ， 則 O T和O 直接執行步驟 RT, the value of the updated RT update q, the OT stores the updated value, and can store the updated q OT storage before the update q with the same value of the RT of the RT is less than or equal to the OT local storage, Then OT and O directly perform the steps
步驟 ， O T可以 下 任 方式更新 PO 統中 于工作 的 的 q  Step, O T can update the PO system in the next way.
1) O T利用更新 的
Figure imgf000011_0003
所有 于工作 的 O 的 q 更新， 可以 力測 同 (Ra g g Tm ) 的P OA 消息將各 的更新 的 q 分別 的O ,O 收到 Ra g g Tme 的P OA 消息 更新本地的 q 1) OT utilizes updated
Figure imgf000011_0003
All the q updates of the work O can be tested with the same (Ra gg Tm ) P OA message to update each of the updated q O, O received Ra gg Tme P OA message update local q
2) O T將步驟 中 O T存儲的更新 的 q O T存儲的更 新前的 q 同的 ， 也即各O 需要 的 q 的 信息， 1所示的P M4消息 所有 于工作 的O ， d 1所示， q a s 的 P OA 消息包括 部分組成， 第 部分 O 2) The OT will store the updated q OT stored in the step with the q before the update, that is, the information of the q required by each O, The P M4 message shown in 1 is all shown in the working O, d 1 , and the P OA message of qas includes the partial composition, the first part O
( - ) 11111111， 表示此P OAM4消息是 所有 于工作 的O ， 第二部分消息 ( essage )的值 10000000 此 只是 介 ， 也可以取其他的值)， 表明此P OAM4消息的 q 調整， 第 三部分力P OAM4消息的數 ， 包括 aa 和 aa2, aa 表示所有 于 工作 的O 需要調整的 q ， a2表明 q 值的 ， 0 (1) 表明 的 q 需要 上 aa 表示的 q ， 1 (0) 表明 的 q 需要減去 aa 表示的 q 。 P OAM4消息的第 部 分力 序列。 于工作 的O 收到 q a山 s 的P OA 消息 ， 果 aa2的值 0， O 將本地的 q 上 aa 表示的 q ， 果 aa22的值 1， O 將本地的 q 減去 aa 表示的 q ， 完成本地 q 值的更新 1需要調整的 q 值的P OAM4消息 ( q a s )格式  ( - ) 11111111, indicating that this P OAM4 message is all O for work, the value of the second part of the message ( essage ) is 10000000. This is just a mediation, and other values can be taken, indicating the q adjustment of this P OAM4 message, third. The number of partial force P OAM4 messages, including aa and aa2, aa means that all the Os that need to be adjusted need to adjust q, a2 indicates the value of q, 0 (1) indicates that q needs to be represented by aa, q, 1 (0) indicates q needs to subtract q from aa. The first component of the P OAM4 message. At work O receives the P OA message of qa mountain s, if the value of aa2 is 0, O will be q on the local q on aa, the value of aa22 is 1, and O subtracts the local q from a to q, complete Update of local q value 1 needs to adjust q value of P OAM4 message ( qas ) format
O  O
( 11111111 向所有 的 消息) (11111111 to all messages)
e age  e age
( 10000000 表明消息 q ad ) ( 10000000 indicates the message q ad )
a  a
(所有 于工作 怎的O 需要 的 q ) (All that is needed for work O) q
aa22  Aa22
(表明 q 值的 0 表明 O 的 q 需要 a 表 示的 q 1 表明 O 的 q 需要減去 缸a 表示的 q (Indicating that the value of 0 of q indicates that q of O needs a to represent q 1 indicates that q of O needs to be subtracted from cylinder a.
) )
] 步驟 ， 新接 PO 統的 O J的 q ， 將 O 的 q O O J接收 存儲O T 身的 q ， 工作 步驟 ， 所有 于工作 的O J按照本地更新 的 q 同步上行 。 同 ， PO 統中有 介O J ， O T和O J 下 方法 完成所有上行 O J的 同步 O T比較 O J的 T ，的值和 O T本地存儲的
Figure imgf000013_0001
， 果 O J的RT ，的值等于O T本地存儲 的 ，則 O T比較目前所有 于工作 的O J的RT ， 和O T 存儲RT ， 果目前所有 于工作 的O 的最大RT 小于O T 本地存儲的RT O T將本地存儲的RT 更新力目前所有 于 工作 的 O J的 RT ，中的最大RT ， 更新 的
Figure imgf000013_0002
更新 的值， 可 ， 近可以存儲 更新 的
Figure imgf000013_0003
O T存儲的更 新前的 q 同的 ， O T和O 執行上 的步驟 和步驟 果] Step, the new OJ q of the PO system, the q OOJ of O receives the storage OT body q, the work steps, all the working OJs are synchronized according to the locally updated q . In the same way, the PO system has the OJ, OT and OJ methods to complete all the upstream OJ synchronization OT comparison OJ T, the value and OT local storage
Figure imgf000013_0001
If the value of RT of OJ is equal to OT local storage, then OT compares all current RTs of working OJ, and OT stores RT, and the current maximum RT of all working O is less than OT. Locally stored RT OT will be local. The stored RT update power is currently all working on the OJ RT, the largest RT in the update,
Figure imgf000013_0002
Updated value, can, can store updated
Figure imgf000013_0003
OT storage before the update q same, OT and O execution steps and steps
O J的RT 的值小于O T本地存儲的RT ， 或者目前所有 于工作 的 O J的最大RT 等于 O T本地存儲的
Figure imgf000013_0004
， 則 O T和O J不執行任何操作。 2所示， 本 中近提供了 中同步上行 的 統， 包括O T和O J, O T中 步包括RT 和 q ， 其 中 RT 存儲 PO ) 統中所有在 的 O J的最 大林 RT )， q 以及，
Figure imgf000013_0005
更新 ， 將更新 的RT qThe value of OJ's RT is less than the OT local storage RT, or the current maximum RT of all working OJs is equal to OT local storage.
Figure imgf000013_0004
, then OT and OJ do nothing. 2, the medium provides a synchronous uplink system, including OT and OJ, the OT step includes RT and q, where RT stores PO) all the OJ's largest forest RT in the system), q and,
Figure imgf000013_0005
Update, will update the RT q
q PO ) 統中所有在 的O J的最大
Figure imgf000013_0006
q PO ) all the largest OJs in the system
Figure imgf000013_0006
的 q 的值 以及， 接收到的更新 的
Figure imgf000013_0007
q 更新信息， 所有在 的O O J 收到的 q 更新信息 q 更新 ， 按照更新 的 q 同步上行 。 The value of q as well, the received update
Figure imgf000013_0007
q Update information, all q updates received in the OOJ update q update, follow the updated q sync upstream.
本 近提供了 O T， 其包括 (RT ) 和均衡 (Eq ) ， 其中 所述RT 存儲 阿 PO ) 統中所有在 的光阿 羊 O )的RT 中的最大值 T ， q 以及， RT 更新 ， 將更新 的RT qThis near provides OT, which includes (RT) and equalization (Eq), where the RT stores a PO) all in the RT of the light A sheep O) the maximum value of T, q and, RT update, will update the RT q
q RT " 最大均衡
Figure imgf000014_0001
， 所述最大均衡
Figure imgf000014_0002
所有O J的 q 的值 以及， 接收 到的更新 的
Figure imgf000014_0003
q 更新信息， 所有在 的O 以使 O J 收到的 q 更新信息 q 更新 ，按照更新 的 q 同步上行 。 q RT "maximum equalization
Figure imgf000014_0001
, the maximum equilibrium
Figure imgf000014_0002
The value of all OJ's q as well, the received update
Figure imgf000014_0003
q Update information, all in the O to update the q update information q received by the OJ, and synchronize the uplink according to the updated q.
其中， RT 可 下方式 RT 行存儲及更新 在O T本地存儲PO 統中 前所有在 的O J的RT 定期和/或不定期地測量PO 統中部分或全部在 的 O J的RT , 將 出的 RT 存儲的 RT 比較， 果核 出的 RT 的值 大于 O T本地存儲的
Figure imgf000014_0005
， 則更新本地存儲的
Figure imgf000014_0004
出的RT 的值。 或者， RT 也可 下方式 RT 行存儲及更新 在O T本地存儲 前所有PO 統中所有在 的O J的RT Among them, the RT can store and update the RT of all OJs in the OT local storage PO system periodically and/or irregularly to measure some or all of the OJ's RT in the PO system, and the RT storage will be output. RT comparison, the value of the RT is greater than the OT local storage
Figure imgf000014_0005
, then update the local storage
Figure imgf000014_0004
The value of the RT. Alternatively, the RT can also store and update all of the OJ's RTs in all PO systems before the OT local storage in the RT mode.
介新的O J或者需要 PO 並各的OqJ接 到PO 統中 ， 接 到PO 統中的O J 得到 O J的RT 的值， 比較 O J的RT 的值和O T本地存儲的
Figure imgf000014_0006
， 果核O Introduce the new OJ or need PO and each OqJ is connected to the PO system. The OJ in the PO system receives the value of the OJ RT, compares the value of the OJ RT and the OT local storage.
Figure imgf000014_0006
, fruit core O
值大于O T本地存儲的
Figure imgf000014_0007
Value is greater than OT local storage
Figure imgf000014_0007
的RT 的值 Value of RT
占 PO 統中的O J 或下 ，比較 O J的RT 的值和O T 本地存儲的RT ，d果核OqJ的RT 的值等于O T本地存儲的RT ax ， 則再 PO 統中所有在 的O J的最大RT 是否小于O T本 地存儲的 RT ， 果是， 則更新本地存儲的
Figure imgf000014_0008
PO 統中 所有在 的O J的最大RT 。 q 近 接收到更新 的 ， 下方式 q 更新信息 更新 的 RT 更新 q 的值， 更新 的 q PO 統中所有在 的 O J的 q 更新 ， 將更新 的 q 作 力 q 更新信息 的O 或者， 更新 的RT 更新 q 的值， 更新 的
Figure imgf000015_0001
更 新前的
Figure imgf000015_0002
同的 ， 將 作力 更新信息 所有在 的O 。 OJ or lower in the PO system, compare the value of RT of OJ and RT of OT local storage, and the value of RT of O core of OqJ is equal to the RT ax of OT local storage, then the maximum RT of all OJs in the PO system Is it less than the OT local storage RT, if it is, then update the local storage
Figure imgf000014_0008
The maximum RT of all OJs in the PO system. q Nearly received the update, the next mode q update information updates the value of the RT update q, the updated q PO system all the OJ's q update, the updated q force q update information O or, the updated RT Update the value of q, updated
Figure imgf000015_0001
Before the update
Figure imgf000015_0002
In the same way, will be updated to update all the information in O.
指令相 硬件完成， 所述程序可以存儲于 可 存儲 中， 只 存儲器、 或 等。 可 ， 上 的全部或部分步驟也可以使用 介或多 集成 。 相 ， 上 中的各 /羊 可以 硬件的形式 ， 也可以 軟件功能 的形式 。 本 不限制于任 何特定形式的硬件和軟件的結合。 The instructions are completed by hardware, and the program can be stored in a storable memory, only memory, or the like. Yes, all or part of the steps can also be used or integrated. Each of the phases / sheep can be in the form of hardware or in the form of software functions. This is not limited to any specific form of hardware or software combination.
以上 ， 力本 的較佳 而已， 非 于限定本 的保 。 本 近可有其他多 ， 在不 本 精神及其 的情況 下， 熟悉本領域的 木 可 本 的 木方案及其 相 的 等同 或替換， 但 相 的 或替換都 于本 要求的 保 。 Above, Liben is better, not limited to the guarantee. There may be many others in the near future, and in the case of the spirit and its circumstances, familiar with the wood scheme of the field and its equivalent or replacement, but the phase or replacement is guaranteed by this requirement.
， 本 明技木方案， T 的更新所有在 J的最大 T ， 最大RT 更新各 O J的 q ，可以減小各 O J的 q , 而提高上行 效率。 The technical solution of this invention, T updates all the maximum T in J, and the maximum RT updates each q of q, which can reduce the q of each O J and improve the uplink efficiency.

Claims

要 求 1、 中同步上行 的方法， 方法包括 光域 終端 O T) PO ) 統中所有在 的光 羊 O )的 (RT ) 中的最大值 RT 最大均衡 q ， 最大均衡 Eq 所有O J的均衡 ( q ) 的值 占所
Figure imgf000016_0002
更新 ， O T 更新 的
Figure imgf000016_0001
q 更新 信息 以及 Requirement 1. The method of synchronous uplink, the method includes the maximum value of the optical domain terminal OT) in the (RT) of all the light horns O) RT maximum equilibrium q, the maximum equilibrium Eq, the balance of all OJs (q) Value
Figure imgf000016_0002
Update, OT updated
Figure imgf000016_0001
q update information and
O T將 q 更新信息 所有在 的 O J， O 收 到的 q 更新信息 Eq 的值 更新 ， 按照更新 的 q 的值同 步上行 。  O T will update the information of all q received in O J, O update information Eq , and follow the updated value of q to go up .
2、 要求 1 所述的方法， 其中， O T 更新 的
Figure imgf000016_0003
2. The method described in claim 1, wherein the OT is updated
Figure imgf000016_0003
Eq 更新信息的步驟 前， 所述方法近包括 Eq steps to update information, the method includes
O T存儲 PO 統中 前所有在 的 O J的 RT 中的最大值 RT 以及 O T stores the maximum value RT of all previous O J RTs in the PO system and
O T定期和/或不定期地測量 PO 統中部分或全部在 的 O 的RT ， 將 出的部分或全部在 的 O J的RT 存儲的RT ax 比較， 果存在大于 O T存儲的 RT 的測出的RT ， 則 O T將存 儲的 更新力大于存儲的
Figure imgf000016_0004
的測出的RT 中的最大的RTThe OT periodically and/or irregularly measures the RT of some or all of the O systems in the PO system, and compares some or all of the RT ax stored in the RT of the OJ. If there is a measured RT greater than the RT stored in the OT , then OT will store the updated power greater than the stored
Figure imgf000016_0004
The largest RT in the measured RT
3、 要求 2所述的方法， 其中， O T 更新 的
Figure imgf000016_0005
3. The method of claim 2, wherein the OT is updated
Figure imgf000016_0005
Eq 更新信息的步驟包括 The steps for Eq to update information include
占所 RT 更新 ， O T 更新 的RT 更新最大均衡 q ， 更新 的最大均衡 q PO 統中部分或 全部在 的 O J的 q 更新 ， 將更新 Eq 作力 q 更新信息。 For the RT update, the OT update RT update maximum balance q, the updated maximum equalization q PO system part or all of the OJ q update, will update the Eq effort q update information.
4、 要求 1 所述的方法， 其中， O T 更新 的
Figure imgf000017_0001
q 更新信息的步驟 前， 方法近包括 4. The method of claim 1, wherein the OT is updated
Figure imgf000017_0001
q Before the step of updating the information, the method includes
O T存儲 前所有 PO 統中所有在 的 O J的 RT 中的最大值 RT ax  O T stores the maximum value of all O's RTs in all PO systems before RT ax
介新的O J或者常要 PO 並各的O J接 到 PO 統 中時， O T 接 到PO 統中的 O J 得到 O J的RT 以及 O T比較 O J的RT 和O T存儲的RT 果核O J的RT 大于O T存儲的RT 則 O T將存儲的
Figure imgf000017_0002
更新力 O J的RTWhen a new OJ or a PO is required and each OJ is connected to the PO system, the OT is connected to the OJ in the PO system to get the OJ RT and the OT is compared to the OJ RT and the OT storage RT core OJ is greater than the OT storage. RT will be stored by OT
Figure imgf000017_0002
Update power OJ RT
5、 要求 1 所述的方法， 其中， O T 更新 的
Figure imgf000017_0003
5. The method of claim 1, wherein the OT is updated
Figure imgf000017_0003
q 更新信息的步驟 前， 方法近包括  q Steps to update the information
O T存儲 前所有 PO 統中所有在 的 O J的 RT 中的最大值 ax O T stores the maximum value of all O's RTs in all previous PO systems ax
PO 統中的 O J 或下 ， O T比較 O J的 RT 和O T存儲的RT 果核O J的RT 等于O T存儲的RT 則 O T PO 統中所有在 的 O J的 RT 中的最大值是否小于 O T存儲的
Figure imgf000017_0005
， 果是， 則 O T將存儲的
Figure imgf000017_0004
更新力PO 統中 所有在 的O J的RT 中的最大值。 OJ in the PO system or lower, OT compares the RT of the OJ and the RT of the OT storage. The RT of the OJ is equal to the RT of the OT. The maximum value of all the OJ RTs in the OT PO system is less than the OT storage.
Figure imgf000017_0005
, if yes, then OT will store
Figure imgf000017_0004
Update the maximum value of all OJ's RTs in the PO system.
6、 要求4或5 的方法， 其中 方法近包括 T在存儲
Figure imgf000017_0006
的同時，存儲 RT ax 的最大均衡 q 6. A method requiring 4 or 5, wherein the method includes T in storage
Figure imgf000017_0006
At the same time, store the maximum equilibrium q of RT ax
O T 更新 的 RT q 更新信息的步驟包括 占所 RT 更新 ， O T 更新 的 RT 更新的最大均衡 q 更新 的最大均衡 q 更新存儲的最大均衡
Figure imgf000017_0008
， 更新 的最大均衡時
Figure imgf000017_0007
PO 統中所有在 的O J的 q 更新 ， 將更新 的 q 作力 q 更新 " 。 The steps of updating the RT q of the OT update include the RT update, the maximum balance of the RT update of the OT update, the maximum balance of the update q, and the maximum equilibrium of the update store.
Figure imgf000017_0008
, updated maximum equilibrium time
Figure imgf000017_0007
All the OJ's q updates in the PO system will be updated with the q-power q update.
7、 要求4或5 的方法， 其中 所迷方法近包括 T在存儲 的同 ，存儲 RT max 的最大均衡 q 7. A method requiring 4 or 5, wherein the method includes the same as the storage of the same, and stores the maximum equilibrium of the RT max.
O T 更新 的
Figure imgf000018_0001
q 更新信息的步驟包括 占所 更新 ， O T 更新 的 RT 更新的最大均衡 q ， 更新 的最大均衡 更新存儲的最大均衡 OT updated
Figure imgf000018_0001
q The steps of updating the information include the update, the maximum equalization q of the RT update of the OT update, and the maximum equilibrium of the updated maximum balanced update storage.
， 存儲 更新 的最大均衡
Figure imgf000018_0002
O T存儲的更新前 的最大均衡
Figure imgf000018_0003
同的 以得到 q ， 將 q 作力 q 更新信 。, storing the maximum equilibrium of updates
Figure imgf000018_0002
Maximum balance before OT storage update
Figure imgf000018_0003
The same to get q, will q force q update letter.
8、 要求6 的方法， 其中 O T將 q 更新信息 所有在 的O J 的步驟中， O T 是通 同 Ra g g Tme)消息將 更新 的 q  8. The method of Requirement 6, where O T will update information. In the step of O J , O T is the same as the Ra g g Tme) message will be updated q
。 。 . .
9、 要求7 的方法， 其中 O T將 q 更新信息 所有在 的O J 的步驟中， O T 是通 現有的或新建的物理 操作 管理P )消息將 q  9. The method of claim 7, where O T will update the information in all the steps of O J , O T is the existing or newly created physical operation management P ) message will be q
所有在 的O 。  All in O.
10、 要求9 的方法， 其中 所迷P OAM4消息的 中至少包括以下內容10. The method of claim 9, wherein the P OAM4 message includes at least the following content
q 和 q 值的 。  The q and q values.
11、 中同步上行 的 統， 其包括 終端 O T) 和光 羊 O )， O T包括 (RT ) 和 均衡( q ) ， 其中11. A synchronous uplink system comprising a terminal O T) and a light goat O ), wherein the O T includes (RT ) and equalization ( q ) , wherein
RT 存儲 PO ) 統中所有在 的 O 的 T 中的最大值 T ， q 以及， RT max 更新 ， 將更新 的RT EqRT storage PO) all O in the system The maximum value of T in T, q and, RT max update, will update RT Eq
q PO 統中
Figure imgf000019_0001
最大均衡
Figure imgf000019_0002
最大均衡 q 所有O J的 q 的值 以及， 接收到的更新 的最大均衡
Figure imgf000019_0003
q 更新信息， q PO system
Figure imgf000019_0001
Maximum equilibrium
Figure imgf000019_0002
Maximum equalization q The value of q for all OJs and the maximum equilibrium of the received updates
Figure imgf000019_0003
q update information,
所有在 的O O J 收到的 q 更新信息 q 更新 ， 按照更新 的 q 同步上行 。 All updates received in O O J q update information, follow the updated q sync upstream.
12、 終端 O T)， 其包括 (RT ) 和均衡 ( q ) ， 其中 所述RT 存儲 同 PO ) 統中所有在 的光 羊 O )的RT 中的最大值RT ， q 以及， RT 更新 ， 將更新 的RT q12. Terminal OT), which includes (RT) and equalization (q), wherein the RT stores the maximum value RT, q and RT updates of all RTs in the PO system. RT q
q RT 最大均衡
Figure imgf000019_0004
， 所述最大均衡
Figure imgf000019_0005
所有O J的 q 的值 以及， 接收 到的更新 的
Figure imgf000019_0006
q 更新信息， 所有在 的O 以使 O J 收到的 q 更新信息 q 更新 ，按照更新 的 q 同步上行 。 q RT maximum equalization
Figure imgf000019_0004
, the maximum equilibrium
Figure imgf000019_0005
The value of all OJ's q as well, the received update
Figure imgf000019_0006
q Update information, all in the O to update the q update information q received by the OJ, and synchronize the uplink according to the updated q.
13、 要求 12 的O T， 其中 RT 近 : 定期和/或不定期地測量 PO 統中部分或全部在 的 O 的 RT ， 將 出的 RT 存儲的 RT 比較， 果存在大于 O T 存儲的 RT 的測出的 RT ， 則將存儲的
Figure imgf000019_0007
更新力大于 存儲的 的測出的RT 中的最大值。 13. Requires 12 OT, where RT is: Regularly and/or irregularly measuring the RT of some or all of the O in the PO system, comparing the RT stored in the RT store, if there is an RT greater than the OT stored RT will be stored
Figure imgf000019_0007
The update power is greater than the maximum of the stored measured RTs.
14、 要求 12 的O T， 其中 RT 近 介新的O J或者需要 PO 並各的OqJ接 到 PO 統 中 ， 接 到PO 統中的O J 得到 O J的RT ， 比 較 O J的 RT 和O T存儲 果核 O 的 RT 的值大于O T存儲的
Figure imgf000020_0002
則將存儲的
Figure imgf000020_0001
更新力 O J的RT 以及 PO 統中的O J 或下 ，比較 O 的RT 和O T 本地存儲的
Figure imgf000020_0003
， 果核O J的RT 等于O T本地存儲的RT 則14. Requires an OT of 12, where RT near the new OJ or need PO and each OqJ is connected to the PO system, the OJ in the PO system receives the OJ RT, compares the OJ RT and the OT storage core O RT value is greater than the OT storage
Figure imgf000020_0002
Will be stored
Figure imgf000020_0001
Update the power OJ's RT and the OJ or under the PO system, compare O's RT and OT local storage
Figure imgf000020_0003
, the RT of the core OJ is equal to the RT of the OT local storage.
PO 統中所有在 的O J的RT 中的最大RT 是否小于O T 存儲的 ， 果是， 則將存儲的
Figure imgf000020_0004
更新力PO 統中所有在 的O J的RT 中的最大RT 15、 要求 14 的 統， 其中 所迷 q 是 下方式 q 更新信息 更新 的
Figure imgf000020_0005
更新最大均衡
Figure imgf000020_0006
的值， 更新 的 P 統中所有在 的 O J的 q 更新 ， 將更新 的 q 作力 q 更新信息 或者， 更新 的 RT 更新最大均衡 q 的值， 更 新 的最大均衡 q 更新前的最大均衡
Figure imgf000020_0007
同的 以 得到 q ， 將 q 作力 q 更新信 " 。 Is the maximum RT of all OJ's RTs in the PO system smaller than the OT storage? If yes, it will be stored.
Figure imgf000020_0004
Update the maximum RT 15 in the RT of the OJ in the RT system, the requirement of 14 is the system, where the q is the next way q update information update
Figure imgf000020_0005
Update maximum equilibrium
Figure imgf000020_0006
The value of the updated P system in all OJ's q updates, the updated q force q update information or, the updated RT update maximum equalization q value, the updated maximum equalization q the maximum equilibrium before the update
Figure imgf000020_0007
The same as to get q, will q force q update letter ".
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Citations (4)

* Cited by examiner, † Cited by third party
Publication number Priority date Publication date Assignee Title
US20030048801A1 (en) * 2001-08-21 2003-03-13 Dolors Sala System, method, and computer program product for ethernet passive optical networks
CN1433192A (en) * 2002-01-17 2003-07-30 三星电子株式会社 Method and frame structure for realizing several functions in billion ethernet passive light network
CN1791039A (en) * 2004-12-17 2006-06-21 电子科技大学 Ether passive optical network uplink access method
CN101431385A (en) * 2008-08-26 2009-05-13 中兴通讯股份有限公司 Frequency and time synchronization method for passive optical network

Family Cites Families (4)

* Cited by examiner, † Cited by third party
Publication number Priority date Publication date Assignee Title
WO2003007518A2 (en) * 2001-07-10 2003-01-23 Salira Optical Network Systems, Inc Allocation of upstream bandwidth in an ethernet passive optical network
JP5028179B2 (en) * 2007-08-03 2012-09-19 株式会社日立製作所 PON system
EP2043286A1 (en) * 2007-09-26 2009-04-01 Nokia Siemens Networks Oy Method to equalize delays in an optical network
CN101582734B (en) * 2008-05-14 2013-04-24 上海贝尔阿尔卡特股份有限公司 Access control method in wavelength division multiplexing passive optical network and device thereof

Patent Citations (4)

* Cited by examiner, † Cited by third party
Publication number Priority date Publication date Assignee Title
US20030048801A1 (en) * 2001-08-21 2003-03-13 Dolors Sala System, method, and computer program product for ethernet passive optical networks
CN1433192A (en) * 2002-01-17 2003-07-30 三星电子株式会社 Method and frame structure for realizing several functions in billion ethernet passive light network
CN1791039A (en) * 2004-12-17 2006-06-21 电子科技大学 Ether passive optical network uplink access method
CN101431385A (en) * 2008-08-26 2009-05-13 中兴通讯股份有限公司 Frequency and time synchronization method for passive optical network

Non-Patent Citations (1)

* Cited by examiner, † Cited by third party
Title
"Broadband optical access systems based on passive optical networks(PON)", ITU-TG983.1, January 2005 (2005-01-01) *

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