WO2010111859A1

WO2010111859A1 - Method for configuring resource mapping indication information

Info

Publication number: WO2010111859A1
Application number: PCT/CN2009/073922
Authority: WO
Inventors: 宁丁; 关艳峰; 刘向宇; 刘颖; 方惠英
Original assignee: 中兴通讯股份有限公司
Priority date: 2009-04-03
Filing date: 2009-09-14
Publication date: 2010-10-07
Also published as: WO2010111974A1; CN101854727A; CN101854727B

Abstract

A method for configuring resource mapping indication information is disclosed by the present invention, the method includes: indicating at least one parameter of resource mapping, and determining the number of bits required for indicating the parameter according to bandwidths; wherein, for a plurality of different bandwidths, the numbers of bits required for indicating the parameter are partially same or totally different with each other. By means of the technical solutions of the present invention, the number of bits required for indicating parameter is configured for every bandwidth supported by the system, and the numbers of bits for indicating the same parameter under different bandwidths are partially same or totally different, it enables the number of bits used by a physical resource mapping indication signaling to be varied flexibly according to the bandwidth used by the system, reduces the transmitted number of bits as much as possible, avoids the heavy overhead question of a control channel in correlative technique, saves downlink control overhead in the case of not influencing normal operation of the system and thus improves work efficiency of the system.

Description

Resource mapping indication information configuration method

The present invention relates to the field of communications, and in particular, to a method for configuring resource mapping indication information. BACKGROUND OF THE INVENTION In a wireless communication system, a base station generally refers to a radio transceiver station capable of transmitting information through a mobile communication switching center and a terminal in a certain radio coverage area. In practical applications, the base station can communicate with the terminal through the uplink/downlink, where the downlink refers to the transmission direction of the base station to the terminal, and the uplink refers to the transmission direction of the terminal to the base station. Moreover, a plurality of terminals may simultaneously transmit data to the base station through the uplink, or may simultaneously receive data from the base station through the downlink. In addition, the transmitted data can be relayed between the base station and the terminal through the relay station. In a wireless communication system in which a base station implements radio resource scheduling control, scheduling allocation of system radio resources is performed by a base station. For example, the downlink resource allocation information used by the base station for downlink transmission and the uplink resource allocation information required for the terminal to perform uplink transmission may be given by the base station. In a commercial wireless communication system, when scheduling a radio resource of an air interface, the base station usually uses one radio frame as a scheduling period, and divides the radio resource into several radio resource units (for example, one time slot or one codeword can be used as A resource unit is scheduled, and the base station provides data or multimedia services to the terminals it covers by scheduling the radio resource unit. Specifically, in the second generation wireless communication system (for example, in the Global System for Mobile communication (GSM), the base station divides the radio resources at each frequency point into a period of 4.615 ms. Time Division Multiple Address (TDMA) radio frame, each radio frame contains 8 time slots, one time slot transmits a full rate channel, or transmits two half rate channels, and can also be used To achieve low-speed data services; in the 2.5-generation wireless communication system (for example, in the General Packet Radio Service (GPRS), the introduction of fixed-slot-based packet switching can continue to enhance data services In the third-generation wireless communication system (for example, in Time-Division Synchronous Code Division Multiple Address (TD-SCDMA), the base station can also vacate the radio resources of the air interface. Divided into no cycles of 10ms Line frames, each 10ms contains 14 regular time slots and 6 special time slots. The regular time slots are used to transmit specific services and signaling. On each regular time slot, the base stations distinguish users by different code words. As can be seen from the above description, GSM and TD-SCDMA systems mainly use TDMA and

/ or CDMA technology, these technologies based on time slots and codewords for resource mapping and resource allocation, the processing process is relatively simple. In a communication system based on Orthogonal Frequency Division Multiplexing (OFDM) and Orthogonal Frequency Division Multiple Address (OFDMA) technologies, for example, in long-term evolution ( In the wireless communication systems of Long Term Evolution, called LTE), Ultra Mobile Broadband (UMB) and IEEE 802.16m, radio resources are also divided into frames for management, but each OFDMA symbol 卩A plurality of mutually orthogonal subcarriers are included, and the terminal usually occupies a part of subcarriers, so that techniques such as Fractional Frequency Reuse (FFR) can be used to reduce interference and improve coverage. Second, due to the wireless channel environment. In order to obtain frequent frequency diversity gain and frequency selective scheduling gain, the base station divides the available physical subcarriers into physical resource units (PTUs), and then maps physical resource units into contiguous resource units ( Contiguous Resource Unit, called CRU) and distributed resource unit (Distribu) a ted Resource Unit (referred to as DRU) to improve transmission performance, wherein subcarriers in consecutive resource units are continuous, and subcarriers in distributed resource units are completely discontinuous or incompletely continuous; As frequency resources become increasingly scarce, base stations need to support multiple different bandwidths (eg, 5 MHz, 10 MHz, or 20 MHz) or multi-carrier operation to take advantage of different frequency resources and meet the needs of different operators. For the above reasons, the resource mapping process of the OFDM or OFDMA-based wireless communication system is more complicated, so that the instruction signaling overhead for controlling the resource mapping process is large, and the terminal parses the resource allocation information of the base station to determine its receiving and transmitting data. The complexity of the process of physical resource location increases. It can be seen that the resource mapping process of the wireless communication system considering OFDM or OFDMA technology will be complicated. In order to reduce the indication signaling overhead of the resource mapping and optimize the system information management and transmission method, a reasonable resource mapping is needed. In order to ensure the efficiency of the wireless communication system, the base station usually maps the physical radio resources into logical radio resources, for example, mapping physical subcarriers into logical resource units, and the base station implements scheduling of radio resources by scheduling logical resource units. Specifically, for a wireless communication system based on OFDM or OFDMA, its wireless resource map The shot is mainly based on the frame structure and resource structure of the wireless communication system, the frame structure describes the control structure of the radio resource in the time domain, and the resource structure describes the control structure of the radio resource in the frequency domain. The frame structure divides the radio resources into different levels of units in the time domain, such as a superframe, a frame, a subframe, and a symbol, by setting different control channels (for example, a broadcast channel). , unicast and multicast channels, etc.) Implement scheduling control. For example, FIG. 1 is a schematic diagram of a frame structure of a wireless communication system according to the related art. As shown in FIG. 1, a radio resource is divided into super frames in a time domain, and each super frame includes 4 frames, and each frame includes 8 subframes. The subframe is composed of 6 basic OFDMA symbols, and the actual system determines how many OFDMA symbols are included in each level unit in the frame structure according to factors such as the bandwidth to be supported and/or the cyclic prefix length of the OFDMA symbol; A broadcast channel is set in the first downlink subframe in the superframe (because it is located in the superframe header, also called a superframe header) and system information such as resource mapping is sent; and the system can also set unicast and/or Or the multicast control channel transmits scheduling control information such as resource allocation. According to factors such as networking technology, interference suppression technology, and service type, the resource structure divides the available bandwidth in the frequency domain into multiple frequency partitions (Frequency Partitions, called FPs), and then divides the frequency resources in the frequency partition into consecutive resource units. And/or distributed resource units for scheduling. For example, FIG. 2 is a schematic diagram of a resource structure of a wireless communication system according to the related art. As shown in FIG. 2, available physical subcarriers of one subframe are divided into three frequency partitions, and each frequency partition is divided into continuous resources and distribution. The resource unit, the continuous resource unit is used for frequency selective scheduling, and the distributed resource unit is used for frequency diversity scheduling. The resource mapping method 1 1 needs to support 5 MHz, 7 MHz, 8.75 MHz, 10 MHz, and 20 MHz system bandwidth (barrel bandwidth), and 5 MHz, when partial protection subcarriers are used to map PRUs without considering multi-carrier operation. Under the 7MHz, 8.75MHz, 10MHz and 20MHz bandwidths, the number of corresponding PRUs is 24, 48, 48, 48 and 96. Therefore, the indication parameters of resource mapping are different under different system bandwidths. For example, a system with a bandwidth of 5 MHz has 24 PRUs per subframe. When 4 PRUs form a subband, there are up to 6 Subbands, while in a 7 MHz, 8.75 MHz, or 10 MHz system, there are 48 PRUs. There are 12 Subbands. For these two systems, the Subband Allocation Count (SAC) is set differently to save overhead. The following was Gen according to the different bandwidths illustrated embodiment resource mapping: the downlink resource mapping process generally includes: a sub-band division (Subband Partitioning), ^ evident band substitutions (Miniband Permutation), frequency partition Ge ¹ J min (Frequency Partitioning), Contigous Resource Unit/Distributed Resource Unit Allocation, the cylinder is called CRU/DRU Allocation) and subcarrier permutation; the uplink resource mapping process includes: subband division, start band permutation, frequency partition division, continuous resource unit/distributed resource unit allocation, and tile replacement ( Permutation). The Subband consists of N1 consecutive PRUs, for example N1 = 4, and the Miniband consists of N2 consecutive PRUs, for example N2 = 1. Specifically, FIG. 3 is a schematic diagram of a resource mapping process of a wireless communication system according to a related art 5 MHz bandwidth. As shown in FIG. 3, a downlink subframe resource mapping process of a 5 MHz OFDMA system is described. The PRU _SB refers to the PRU for the Subband, the PRU _MB refers to the PRU for the Miniband, the PPRU _MB refers to the PRU through the Miniband Permutation, and the PRUpPi refers to the PRU that belongs to the i (ii > 0) frequency partition. Among them, the Fast Fourier Transformation (called FFT) points of the 5MHz system is 512, and there are 432 available data subcarriers in a sub-frame, which are divided into N=24 PRUs, and each PRU is 18x6. That is, the frequency domain is 18 carriers and the time domain is 6 symbols. The number of symbols in the time domain may be 5 or 7 due to cyclic prefix, superframe header, transition point and control channel. The following takes the 5MHz bandwidth as an example to describe the steps of physical resource mapping: (1) Subband division, that is, extracting a part of the PRU mapping in units of one Subband

Subband. The number of downlink Subbands and the number of uplink Subbands are indicated by two parameters: Downlink Subband Allocation Count (Downlink Subband Allocation Count) and Uplink Subband Allocation Count (USAC). . For example, the following 5 MHz bandwidth is used. When the number of downlink Subbands indicated by the DSAC is 3, 12 PRUs are mapped to 3 Subbands. 4 is a schematic diagram of a subband division process of a wireless communication system according to the related art with a 5 MHz bandwidth. As shown in FIG. 4, the base station uses DSAC to indicate Subband Partitioning, and obtains PRU _SB (the unshaded portion in the figure), and the remaining Partially mapped to Miniband, as shown in the figure PRU _MB (shaded in the figure).

(2) Start band replacement, that is, map PRUs that are not mapped to Subband to Miniband. When the number of downlink subbands indicated by the DSAC is 3, 12 PRUs are mapped to Miniband. FIG. 5 is a schematic diagram of the encapsulation replacement process of the wireless communication system according to the related art 5 MHz bandwidth, as shown in FIG. , Replace the 12 PRUs. This step does not require additional parameter indications, which are done according to DSAC. Similarly, the upstream microstrip replacement is done according to USAC.

(3) Frequency partitioning, that is, dividing the divided Subband and the replaced Miniband into respective frequency partitions. This step requires two parameters, one for indicating the number, size, and/or proportion of each frequency partition, and the downlink and uplink are configured by Downlink Frequency Partition Configuration (Downlink Frequency Partition Configuration) and Upstream Frequency Partition Configuration ( Uplink Frequency Partition Configuration, the cartridge is called UFPC) indication; another parameter is used to indicate the number of Subbands in the frequency partition except the first frequency partition (ie FP.), and the downlink and uplink are respectively allocated by the downlink frequency partition subband. (Downlink Frequency Partition Subband Count, referred to as DFPSC) and Uplink Frequency Partition Subband Count (UFCSC). Under the condition that the size of the frequency partition other than the first frequency partition is equal to the number of Subbands included, a certain redundancy reduction can be performed, and some impossible values are removed. 6 is a schematic diagram of frequency partition division of a wireless communication system according to the related art with a 5 MHz bandwidth. As shown in FIG. 6, except that the first frequency partition size is 24 PRUs, the other frequency partition sizes are 0, and other frequency partitions Subband. The frequency partition division of the number 0.

(4) Continuous resource unit/distributed resource unit allocation, that is, separate resource unit/distributed resource unit allocation for each frequency partition. The downlink frequency partition is indicated by the number of downlink contiguous resource units (Downlink CRU Allocation Size, referred to as DCAS), and the uplink frequency partition is indicated by the number of uplink contiguous resource units (Uplink CRU Allocation Size, called UCAS). If the size of some frequency partitions is 0, you do not need to carry this parameter. As shown in Figure 3, when the system bandwidth is 5MHz, the number of downlink Subbands indicated by DSAC is 3, the size of the first frequency partition is 24 PRUs, the size of other frequency partitions is 0, and the number of CRUs of the first frequency partition is A schematic diagram of 12, where the unshaded portion of the last column represents the CRU and the shadow represents the DRU. It should be noted that one bit can be used to indicate whether the Subband is used as the CRU by default, and the Miniband is used as the DRU by default. In this case, the overhead can be further saved without sending DCAS or UCAS.

(5) Subcarrier permutation or tile permutation, that is, subcarrier replacement for PRUs mapped to DRUs in each frequency partition in the downlink subframe, and PRUs for mapping to DRUs in respective frequency partitions in the uplink subframe Perform a Tile replacement. In addition, the CRU and DRU described herein refer to resource units that have not yet passed through step (5). After the fifth step, it is called Contiguous Logical Resource Unit (CLRU) and Distributed Logical Resource Unit (DLRU), without causing ambiguity. ^ ¹ CLRU and can be referred to as a CRU DLRU cylinder and DRU. FIG. 3 is a specific example of physical resource mapping in the case of a 5 MHz bandwidth, including a process of contiguous resource unit/distributed resource unit allocation. 4 to 6 show subband division to frequency division The process of partitioning, in order to more clearly explain the situation of resource mapping under other bandwidths, FIG. 7 is a schematic diagram of the resource mapping process of the wireless communication system according to the related technology of 10 MHz (which may be 7 MHz or 8.75 MHz) bandwidth. 7 shows the specific mapping situation when the bandwidth is 10MHz (including 7MHz, 8.75MHz). FPSi refers to the number of PRUs in the i (i > 0) frequency partitions, where the number of Subbands is 6, and there are 4 frequencies. Partition, each frequency partition size is 12 PRUs, the first frequency partition contains 8 CRUs and 4 DRUs, and the other frequency partitions contain 4 CRUs and 8 DRUs. 8 is a schematic diagram of a resource mapping process of a wireless communication system according to a 20 MHz bandwidth of the related art, and FIG. 8 shows a specific mapping situation in a case of a 20 M bandwidth, and UCAS _SBi refers to an i-th (i > 0) frequency. The number of uplink sub-band-based CRU allocations in the partition, and UCAS _MB refers to the number of uplink Miniband-based CRU allocations in each frequency partition. As can be seen from the above description, in the resource mapping process, after the bandwidth is determined, other parameters need to be determined (for example, the number of Subbands, the number of frequency partitions, the number of Subbands and CRUs on each frequency partition, etc.) need to be determined. In the communication system, the resource mapping indication information is sent by the base station to the terminal through the broadcast channel or the superframe, and the terminal determines the resource location of receiving and/or transmitting data according to the resource mapping indication information and the resource allocation information. The resource mapping indication information indicates the division and mapping of the frequency resources, and specifically includes the following information: downlink subband allocation number, uplink subband allocation number, downlink frequency partition configuration, uplink frequency partition configuration, downlink frequency partition subband allocation number, uplink The number of frequency partition subband allocations, the number of downlink contiguous resource unit allocations, the number of uplink contiguous resource unit allocations, the number of downlink contiguous resource units based on Miniband, and the number of contiguous resource units based on Miniband. Since the specific resource mapping process is many, the setting of the above indication parameters has strong flexibility, but at the same time, the number of bits required to indicate these parameters is increased, thereby increasing the control channel overhead when transmitting these bits. A lot of channel resources are wasted. In view of the problem that the resource mapping parameter indication in the related art and the channel overhead of transmission are large and the system resources are wasted, an effective solution has not been proposed yet. SUMMARY OF THE INVENTION The present invention has been made in view of the problem of an increase in the number of bits required to indicate a resource mapping parameter and a large control channel overhead during transmission, which wastes system resources, in which the setting of resource mapping indication parameters in the related art is flexible, and the main problem of the present invention is The purpose is to provide a configuration scheme of resource mapping indication information to solve at least one of the above problems. According to an aspect of the present invention, a method for configuring resource mapping indication information is provided. The method for configuring the resource mapping indication information according to the present invention includes: indicating at least one parameter of the resource mapping, and determining a number of bits required to indicate the parameter according to the bandwidth; wherein, for a plurality of different bandwidths, indicating the The number of bits required for the parameters is partially identical or completely different from each other. With the above at least one technical solution of the present invention, the number of bits required to indicate the parameter is configured for each bandwidth supported by the system, and the number of bits indicated by the same parameter under different bandwidths is the same or completely different, so that physical resource mapping is performed. The number of bits used for indicating signaling can be flexibly changed according to the bandwidth used by the system, and the number of transmitted bits is reduced as much as possible, thereby avoiding the problem of large control channel overhead in the related art, and saving the downlink without affecting the normal operation of the system. Control overhead, thereby increasing the efficiency of the system. The drawings are intended to provide a further understanding of the invention, and are intended to be a part of the description of the invention. In the drawings: FIG. 1 is a schematic diagram of a frame structure of a wireless communication system according to the related art; FIG. 2 is a schematic diagram of a resource structure of a wireless communication system according to the related art; FIG. 3 is a case of a 5 MHz bandwidth according to the related art. Schematic diagram of a resource mapping process of a wireless communication system; FIG. 4 is a schematic diagram of a subband division process of a wireless communication system in the case of a 5 MHz bandwidth according to the related art; FIG. 5 is a replacement process of a wireless communication system in a case of a 5 MHz bandwidth according to the related art FIG. 6 is a schematic diagram of frequency partition division of a wireless communication system according to a related art 5 MHz bandwidth; FIG. 7 is a resource mapping process of a wireless communication system according to a related technology of 10 MHz (which may be 7 MHz or 8.75 MHz) bandwidth; FIG. 8 is a schematic diagram of a resource mapping process of a wireless communication system in the case of a 20 MHz bandwidth according to the related art; FIG. 9 is a flowchart of a method for configuring resource mapping indication information according to an embodiment of the present invention; FIG. 10 is a configuration method of resource mapping indication information according to an embodiment of the present invention, using different numbers of bit indications for a 5 MHz system bandwidth. FIG. 11 is a schematic diagram of application of signaling USAC when a different number of bit indication parameters are used for a 5 MHz system bandwidth according to an embodiment of the present invention; FIG. The configuration method of the resource mapping indication information in the embodiment of the present invention is a schematic diagram of the application of the signaling DFPC when a different number of bit indication parameters are used for the 10 MHz system bandwidth. FIG. 13 is a configuration method of the resource mapping indication information in the embodiment of the present invention. FIG. 14 is a schematic diagram of application of signaling UFPC when a different number of bits are used to indicate a parameter; FIG. 14 is a schematic diagram of application of signaling DPFSC when a different number of bit indication parameters are used for a 10 MHz system bandwidth according to a method for configuring resource mapping indication information according to an embodiment of the present invention; FIG. 15 is a resource mapping indication in an embodiment of the present invention; FIG. 16 is a schematic diagram of the configuration of the resource mapping indication information in the embodiment of the present invention. The method for configuring the resource mapping indication information in the embodiment of the present invention uses a different number of bit indication parameters for the 10 MHz system bandwidth. Schematic diagram of the application of time signaling DCASssi. FIG. 17 is a schematic diagram of application of signaling UCASssi when a method for configuring resource mapping indication information according to an embodiment of the present invention uses a different number of bit indication parameters for a 10 MHz system bandwidth. FIG. 18 is a schematic diagram of application of signaling DCASMB when a method for configuring resource mapping indication information according to an embodiment of the present invention uses a different number of bit indication parameters for a 5 MHz system bandwidth. FIG. 19 is a schematic diagram of application of signaling UCAS _MB when a method for configuring resource mapping indication information according to an embodiment of the present invention uses a different number of bit indication parameters for a 5 MHz system bandwidth. DETAILED DESCRIPTION OF THE PREFERRED EMBODIMENTS The present invention provides a solution to the problem that the number of bits required to indicate a resource mapping parameter is increased, and the control channel overhead is large, and system resources are wasted. A configuration scheme of resource mapping indication information, and a processing principle of the scheme As follows: At least one parameter indicating the resource mapping, the number of bits required to indicate the parameter for each bandwidth supported by the system, and the number of bits indicated by the same parameter under different bandwidths is the same or completely different, so that the small bandwidth is performed. The number of bits used in the parameter indication is less than that of the large bandwidth. The number of bits used by the physical resource mapping indication signaling is reduced, and the downlink control overhead can be saved according to the flexible bandwidth change of the system without affecting the normal operation of the system. . That is, the information element (Information Element, referred to as IE) of the resource mapping indication information is transmitted in the broadcast channel or the superframe header, or the message or the sub-packet is determined according to the system bandwidth, thereby improving the working efficiency of the system. It should be noted that the embodiments in the present application and the features in the embodiments may be combined with each other without conflict. The invention will be described in detail below with reference to the drawings in conjunction with the embodiments. In the following embodiments, the steps illustrated in the flowchart of the drawings may be performed in a computer system such as a set of computer executable instructions, and although the logical order is illustrated in the flowchart, in some cases The steps shown or described may be performed in an order different from that herein. Method Embodiments According to an embodiment of the present invention, a method for configuring resource mapping indication information is provided. FIG. 9 is a flowchart of a method for configuring resource mapping indication information according to an embodiment of the present invention. As shown in FIG. 9, the method includes the following steps: Step S902, indicating at least one parameter of a resource mapping process, according to a bandwidth determination indication. The number of bits required by the parameter, the parameter includes at least one of the following: a downlink subband allocation number, an uplink subband allocation number, a downlink frequency partition configuration, an uplink frequency partition configuration, a downlink frequency partition subband allocation number, and an uplink frequency partition. The number of subband allocations, the number of downlink contiguous resource unit allocations, the number of uplink contiguous resource unit allocations, the number of downlink contiguous resource units based on Miniband, and the number of uplink contiguous resource units based on Miniband; Step S904, multiple supported by the system The different bandwidths (the bandwidth may be the system bandwidth), the number of bits required to indicate the parameters are partially identical or completely different from each other. Specifically, the multiple bandwidths may include the first bandwidth, the second bandwidth, and the third bandwidth, where One parameter in the indication information: corresponding to the first bandwidth, indicating The number of bits required for the parameter is M; corresponding to the second bandwidth, the number of bits required to indicate the parameter is N; corresponding to the third bandwidth, the number of bits required to indicate the parameter is P, and, M, N, The values of P are partially the same or completely different from each other. Preferably, the first bandwidth includes: 5 MHz, and the second bandwidth includes one of the following: 7 MHz, 8.75 MHz, 10 MHz, and the third bandwidth includes: 20 MHz. It should be noted that for the 40MHz bandwidth, the required parameters are indicated. The number of bits may be X, X+1 or X+2, where X is the number of bits required to indicate a parameter when the bandwidth is 20 MHz. Wherein, the values of M, N, and P are the same as the part of jt匕: N=M+1, JL P=M+1; or, N=M+2, and P=M+2; or, N= M, and P = M+1; or, N = M, and P = M + 2, where M is an integer greater than 0, preferably, M is 1 or 2 or 3 or 4. Wherein, the values of M, N, and P are completely different from each other: N=M+1, and P=M+2; or N=M+2, and Ρ=Μ+3, or N=M+1, And Ρ=Μ+3, where M is an integer greater than 0, preferably, M is 1 or 2 or 3 or 4. The specific indication manner is as follows: The number of bits indicating the number of downlink subband allocations in the system is the same as or different from the number of bits indicating the number of uplink subband allocations; indicating the number of bits in the downlink frequency partition configuration and indicating the uplink frequency partition in the system The number of configured bits is the same or different; the number of bits indicating the number of downlink frequency subband allocations in the system is the same as or different from the number of bits indicating the number of uplink frequency partition subband allocations; indicating the number of downlink continuous resource unit allocations in the system The number of bits is the same as or different from the number of bits indicating the number of uplink contiguous resource unit allocations. With the technical solution provided by the embodiment of the present invention, the number of bits used by the physical resource mapping indication signaling can be flexibly changed according to the bandwidth used by the system, and the number of transmitted bits is reduced as much as possible without affecting the normal operation of the system. The downlink control overhead is saved, thereby improving the working efficiency of the system. Various examples of the number of bits indicating the same parameter corresponding to different bandwidths will be described in detail below with reference to specific examples. In the following description, multiple indication signaling values of parameters (eg, DSAC, USAC, etc.) and physical indications indicated by the indicated signaling values are shown by a plurality of tables (eg, subbands described below) The specific correspondence of the number). It should be understood that, for each table that appears in the following, the correspondence between the indication value of the parameter indication signal and the physical meaning indicated by the value of the indication signaling may be changed according to actual needs, and is not limited to the correspondence shown in the table. relationship. In the table shown in the following description, the case where parameter indication is performed by various methods such as lbit, 2bits, 3bits, and 4bits is specifically given. For example, in the case where there are two Ibit JL optional values, the indication signaling uses a binary "0" to represent 0 in the table, a binary "1" to represent 1 in the table, and 2 bits for parameter indication and In the case where there are 4 optional values, the indication signaling uses the binary "00" to represent 0 in the table, and the binary "01" to represent 1 in the table. The system "10" indicates 2 in the table, and the binary "11" indicates 3 in the table. In the case where 3 bits are used for parameter indication and there are 8 optional values, the indication signaling is represented by a binary "000". 0 in the table, with the binary "001" for the 1 in the table, the binary "010" for the 2 in the table, the binary "011" for the 3 in the table, and the binary "100" for the table. 4, with binary "101" for 5 in the table, binary "110" for 6 in the table, binary "111" for 7 in the table; 4bits for parameter indication and optional values In the case of 16 cases, the indication signaling uses the binary "0000" to represent 0 in the table, the binary "0001" to represent 1 in the table, the binary "0010" to represent 2 in the table, and the binary "0011". " represents 3 in the table, with the binary "0100" for the 4 in the table, the binary "0101" for the 5 in the table, the binary "0110" for the 6 in the table, and the binary "0111" for the binary. 7 in the table, with the binary "1000" for the 8 in the table, and the binary "1001" for the 9 in the table. Use the binary "1010" to represent 10 in the table, the binary "1011" to represent 11 in the table, the binary "1100" to represent 12 in the table, and the binary "1101" to represent 13 in the table. "1110" represents 14 in the table, and binary "1111" represents 15 in the table. In addition, in some cases, because some values are unlikely or infrequent, some parts of the table may be reserved in some cases, as shown in Table 1.9 and Table 3.14, although n-bit indications may Indicates 2 ⁿ combinations, and the position to be reserved is filled with the actual value, but some values are not useful, so some values are set to be reserved. This method also applies to other forms of instructional information. Example for Configuring the Number of Downstream Subband Allocations FIG. 10 is a schematic diagram of application of signaling DSAC when a different number of bit indication parameters are used for a 5 MHz system bandwidth according to the method for configuring resource mapping indication information according to an embodiment of the present invention, as shown in FIG. As shown in the figure, when the DSAC values are different (that is, when the number of downlink Subbands indicated by the DSAC is different), the downlink Subband Partitioning process is different. The system bandwidth is 5MHz, 10MHz (also 7MHz or 8.75MHz), 20MHz as an example. The configuration of DSAC is divided into three types of bandwidth. The first type is 5MHz, and the second type is 10MHz or 7MHz or 8.75. MHz, the third category is 20MHz. The first type: When the system bandwidth is 5MHz, the number of bits required to indicate the DSAC parameters is 2bits; for 5MHz, the possible value set of the number of _Subbands is A _DSAC = {0,1,2,3,4,5,6} . 1.1 to Table 1.8 describes the correspondence between the value of DSAC and the number of Subbands when the system bandwidth is 5 MHz and the number of bits required for DSAC is 2 bits. 2bits represents the number of four different Subbands. The number of these four different Subbands is taken from the possible set of the number of Subbands at 5MHz, A _DSAC , and a total of C ₇ ⁴ = 35 combinations. For example, Table 1.1 takes {0, 1, 2, 3}, and other combinations are not listed one by one. It should be noted that n non-repeating elements from m different elements form a subset, regardless of the order of the elements, which is called no-recombination of n from m, and the total number of all possible combinations is used. C _m ^{n is} expressed. Table 1.1

Table 1.7

Or: When the system bandwidth is 5MHz, the number of bits required to indicate the DSAC parameters is 3bits. 3bits represents the number of 8 different Subbands, which can represent all the elements in the set A _DSAC . As shown in Table 1.9. Table 1.9

The second type: When the system bandwidth is 7MHz or 8.75MHz or 10MHz, the number of bits required to indicate the DSAC parameters is 3bits; for 7MHz or 8.75MHz or 10MHz, the possible value set of the number of Subbands is B _DSAC = {0,1, 2,3,4,5,6,7,8,9,10,11,12}. Tables 1.10 through 1.22 describe the relationship between the value of DSAC and the number of Subbands when the system bandwidth is 10MHz (also 7MHz or 8.75MHz) and the number of bits required for DSAC is 3bits. 3bits represents 8 different subband numbers. The 8 different Subband numbers are taken from 1 OMHz (also 7MHz or 8.75MHz). The possible value set of Subband number is B _DSAC , and C ₁₃ ⁸ = 1287 combinations. For example, Table 1.10 takes {0,1,2,3,4,5,6,7}, and other combinations than Tables 1.10 through 1.22 are no longer listed. Table 1.10

2 2 6 6

3 3 7 7 Table 1.11

DSAC corresponds to Subband number DSAC corresponds to Subband number

0 0 4 4

1 1 5 5

2 2 6 7

3 3 7 9 Table 1.12

DSAC corresponds to Subband number DSAC corresponds to Subband number

0 0 4 5

1 1 5 7

2 2 6 9

3 3 7 11 Table 1.13

DSAC corresponds to Subband number DSAC corresponds to Subband number

0 0 4 4

1 1 5 5

2 2 6 6

3 3 7 8 Table 1.14

DSAC corresponds to Subband number DSAC corresponds to Subband number

0 0 4 4

1 1 5 6

2 2 6 7

3 3 7 8 Table 1.15

DSAC corresponds to Subband number DSAC corresponds to Subband number

0 0 4 4

1 1 5 5

2 2 6 6

3 3 7 8 DSAC corresponds to Subband number DSAC corresponding Subband number

0 0 4 4

1 1 5 6

2 2 6 8

3 3 7 9 Table 1.17

DSAC corresponds to Subband number DSAC corresponds to Subband number

0 0 4 4

1 1 5 6

2 2 6 10

3 3 7 12 Table 1.18

DSAC corresponds to Subband number DSAC corresponds to Subband number

0 0 4 4

1 1 5 5

2 2 6 6

3 3 7 9 Table 1.19

DSAC corresponds to Subband number DSAC corresponds to Subband number

0 0 4 4

1 1 5 6

2 2 6 9

3 3 7 12 Table 1.20

DSAC corresponds to Subband number DSAC corresponds to Subband number

0 1 4 5

1 2 5 6

2 3 6 7

3 4 7 8 Table 1.21

DSAC corresponds to Subband number DSAC corresponds to Subband number

0 0 4 6 1 1 5 8

2 2 6 10

3 4 7 12 Table 1.22

DSAC corresponds to Subband number DSAC corresponds to Subband number

0 0 4 6

1 2 5 8

2 3 6 10

3 4 7 12 OR: When the system bandwidth is 10MHz or 7MHz or 8.75MHz, the number of bits required to indicate the DSAC parameters is 4bits. 4bits represents 16 different subband numbers, which are sufficient to represent all elements in the set B _DSAC . As shown in Table 1.23. Table 1.23

Third Bandwidth: When the system bandwidth is 20MHz, the number of bits required to indicate the DSAC parameter is

3bits. For 20MHz, the possible set of values for the number of _Subbands is C _DSAC = {0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17 , 18, 19, 20, 21, 22, 23, 24}. Table 1.24 to Table 1.27 describe the correspondence between the value of DSAC and the number of Subbands when the system bandwidth is 20 MHz and the number of bits required for DSAC is 3 bits. 3bits represents 8 different subband numbers. The 8 different subband numbers are taken from the possible value set of the number of Subbands at 20MHz C _DSAC , and a total of C ₂₅ ⁸ = 1081575 combinations. For example, Table 1.24 takes {0, 2, 3,4,6,8,9,12}, except for Tables 1.24 to 1.27, no longer - enumerated. Table 1.24

Table 1.25

Table 1.26

Table 1.27

Or, when the system bandwidth is 20MHz, the number of bits required to indicate the DSAC parameters is 4bits. 4bits represents 16 different subband numbers. The 16 different Subband numbers are taken from the set CDSAC, and a total of C ₂₅ ¹⁶ = 2042975 combinations. For example, Table 1.28 takes {0,1,2,3,4,5,6 , 7, 8, 9, 10, 11, 12, 13, 14, 15}, other combinations than Table 1.28 to Table 1.40 are not listed.

Table 1.28

2 2 10 10

3 3 11 11

4 4 12 12

5 5 13 13

6 6 14 14

7 7 15 15 Table 1.29

Table 1.30

Table 1.31

DSAC corresponds to Subband number DSAC corresponds to Subband number

0 0 8 8

1 1 9 9

2 2 10 10

3 3 11 12

4 4 12 14

5 5 13 15

6 6 14 18 Table 1.32

DSAC corresponds to Subband number DSAC corresponds to Subband number

0 0 8 8

1 1 9 9

2 2 10 10

3 3 11 12

4 4 12 14

5 5 13 16

6 6 14 18

7 7 15 20 Table 1.33

DSAC corresponds to Subband number DSAC corresponds to Subband number

0 0 8 8

1 1 9 9

2 2 10 10

3 3 11 12

4 4 12 14

5 5 13 15

6 6 14 18

7 7 15 21 Table 1.34

DSAC corresponds to Subband number DSAC corresponds to Subband number

0 0 8 8

1 1 9 9

2 2 10 10

3 3 11 12

4 4 12 13

5 5 13 15

6 6 14 18

7 7 15 21 Table 1.35

DSAC corresponds to Subband number DSAC corresponds to Subband number

0 0 8 8 1 1 9 9

2 2 10 10

3 3 11 12

4 4 12 15

5 5 13 18

6 6 14 21

7 7 15 24 Table 1.36

Table 1.37

Table 1.38

DSAC corresponds to Subband number DSAC corresponds to Subband number

0 0 8 10

1 3 9 11

2 4 10 12

3 5 11 13

4 6 12 14

5 7 13 15 6 8 14 16

7 9 15 18 Table 1.39

Table 1.40

Or, when the system bandwidth is 20MHz, the number of bits required to indicate the DSAC parameters is 5bits. 5bits represents 32 different subband numbers, and the number of these 32 different Subbands is sufficient to represent all elements in the set C _DSAC . As shown in Table 1.41. Table 1.41

DSAC corresponds to Subband number DSAC corresponds to Subband number

0 0 16 16

1 1 17 17

2 2 18 18

3 3 19 19

4 4 20 20

5 5 21 21

6 6 22 22 8 8 24 24

9 9 25 Reserved

10 10 26 Reserved

11 11 27 Reserved

12 12 28 Reserved

13 13 29 Reserved

14 14 30 Reserved

15 15 31 The number of bits required to indicate the DSAC parameters for each bandwidth can be determined from the above method, but for a plurality of different bandwidths supported by the system, the number of bits required to indicate the parameters is partially identical or completely different from each other. For example, when the system bandwidth is 5MHz, the number of bits required to indicate the DSAC parameter is 3bits; when the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 4bits; the system bandwidth is 20MHz. When the system bandwidth is 5 MHz, the number of bits required to indicate the DSAC parameter is 2 bits. When the system bandwidth is 10 MHz (also 7 MHz or 8.75 MHz) The required number of bits is 3 bits; when the system bandwidth is 20 MHz, the number of bits required to indicate the parameter is 4 bits; or, when the system bandwidth is 5 MHz, the number of bits required to indicate the DSAC parameter is 2 bits; the system bandwidth is 10 MHz (also When 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 3bits; when the system bandwidth is 20MHz, the number of bits required to indicate the parameter is 3bits; or, when the system bandwidth is 5MHz, the DSAC parameter is required. The number of bits is 2 bits; when the system bandwidth is 10 MHz (also 7 MHz or 8.75 MHz), the number of bits required to indicate the parameter is 4 bits; when the system bandwidth is 20 MHz, the number of bits required to indicate the parameter is 4 bits; Or, when the system bandwidth is 5MHz, the number of bits required to indicate the DSAC parameter is 3bits; when the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 4bits; when the system bandwidth is 20MHz , the number of bits required to indicate this parameter is 4 bits. It should be noted that in this method, even if two different bandwidths use the same number of bits to indicate the DSAC parameters, the corresponding tables may be different. For example, when the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate this parameter is 4bits, but The table should be Table 1.23; when the system bandwidth is 20MHz, the number of bits required to indicate this parameter is 4bits, but the corresponding table is Table 1.39. Since the system bandwidth is 10MHz (which can be 7MHz or 8.75MHz) and the system bandwidth is 20MHz, it can be considered that the ^{1 1} 10MHz (can be 7MHz or 8.75MHz) and 20MHz features can be unified, and the system bandwidth can be 10MHz ( The same DSAC value and correspondence can be used when the system bandwidth is 20MHz and the system bandwidth is 20MHz, which makes the device manufacturing more powerful. The same table is used, ie, the system bandwidth is 10MHz (which can be 7MHz or 8.75MHz) and the system bandwidth is 20MHz. For example, when the system bandwidth is 5MHz, the number of bits required to indicate the DSAC parameter is 2bits; and when the system bandwidth is 10MHz (also 7MHz or 8.75MHz) and 20MHz, the number of bits required to indicate this parameter is 4bits. The corresponding relationship between the value of the DSAC and the number of Subbands in the case where the system bandwidth is 5 MHz and the number of bits required for the DSAC is 2 bits is as described above. When the system bandwidth is 10MHz (also 7MHz or 8.75MHz) and 20MHz, and the number of bits required to indicate DSAC is 4bits, you can use 20MHz in one of the tables that require 4bits to indicate DSAC, for example, Use Table 1.28 or Table 1.29 to determine the correspondence between the value of DSAC and the number of Subbands. Through the above example 1, it can be seen that when the system bandwidth is 5MHz, 10MHz (which can be 7MHz or 8.75MHz), and the 20MHz system, the number of bits indicating the DSAC needs 2bits, 3bits, 4bits, respectively, or 2bits, 4bits, 4bits respectively. , or 3bits, 4bits, 4bits, or 3bits, 4bits, 5bits, etc., respectively, when the possible value of the DSAC is reduced, the redundant and unnecessary information indications are deleted, and the bit overhead is saved. And to ensure a certain flexibility. Example for Configuring the Number of Uplink Subband Allocations FIG. 11 is a schematic diagram of the application of signaling USAC when a different number of bit indication parameters are used for a 5 MHz system bandwidth according to the configuration method of the resource mapping indication information according to the embodiment of the present invention, as shown in FIG. 11 . As shown, when the values of USAC are different (that is, when the number of downlink Subbands indicated by USAC is different), the downlink Subband Partitioning process is different. In the following, the system bandwidth (or the bandwidth called the bandwidth) is 5MHz, 10MHz (also 7MHz or 8.75MHz), and 20MHz is taken as an example. The configuration of the USC is described in three types of bandwidth. The first type is 5MHz, the second. The class is 10MHz or 7MHz or 8.75MHz, and the third class is 20MHz. The first type: When the system bandwidth is 5MHz, the number of bits required to indicate the USAC parameter is 2bits; for 5MHz, the possible value set of the number of Subbands is A _USAC = {0,1,2,3,4,5,6} „ 2.1 to Table 2.8 describe the relationship between the value of USAC and the number of Subbands when the system bandwidth is 5MHz and indicates the number of bits required by USAC is 2bits. 2bits indicates the number of 4 different Subbands, these 4 different Subbands The number of possible values from the number of Subbands at 5 MHz is A _USAC , and C ₇ ⁴ = 35 combinations. For example, Table 2.1 takes {0, 1, 2, 3}, and other combinations are not listed one by one. , taking n non-repeating elements from m different elements to form a subset, regardless of the order of its elements, called no-recombination of n from m, the total number of all possible combinations using C _m ⁿ indicates. Table 2.1

0 0 2 3

1 2 3 4 Table 2.6

USAC corresponds to Subband number USAC corresponds to Subband number

0 0 2 4

1 3 3 5 Table 2.7

USAC corresponds to Subband number USAC corresponds to Subband number

0 0 2 4

1 3 3 6 Table 2.8

USAC corresponds to Subband number USAC corresponds to Subband number

0 1 2 3

1 2 3 4 Or: When the system bandwidth is 5MHz, the number of bits required to indicate the USAC parameter is 3 bits. 3bits represents the number of 8 different Subbands, which can represent all the elements in the set A _USAC . As shown in Table 2.9. Table 2.9

The second type: When the system bandwidth is 7MHz or 8.75MHz or 10MHz, the number of bits required to indicate the USAC parameter is 3bits; for 7MHz or 8.75MHz or 10MHz, the possible value set of the number of Subbands is

BUSAC = {0, 1,2,3,4,5,6,7,8,9, 10,11, 12} „ Table 2.10 to Table 2.22 describe the system bandwidth as 10MHz (also 7MHz or 8.75MHz) And indicate the correspondence between the value of USAC and the number of Subbands when the number of bits required by USAC is 3 bits. 3bits indicates the number of 8 different Subbands, and the number of these 8 different Subbands is taken from 1 OMHz (may also be A possible set of values for the number of Subbands at 7 MHz or 8.75 MHz) B _USAC , a total of C ₁₃ ⁸ = 1287 combinations. For example, Table 2.10 takes {0,1,2,3,4,5,6,7}, and other combinations than Table 2.10 to Table 2.22 are not listed.

Table 2.10

Table 2.11

Table 2.12

Table 2.13

Table 2.14

Table 2.15

USAC corresponds to Subband number USAC corresponds to Subband number

0 0 4 4

1 1 5 5

2 2 6 6

3 3 7 8 Table 2.16

USAC corresponds to Subband number USAC corresponds to Subband number

0 0 4 4

1 1 5 6

2 2 6 8

3 3 7 9 Table 2.17

USAC corresponds to Subband number USAC corresponds to Subband number

0 0 4 4

1 1 5 6

2 2 6 10

3 3 7 12 Table 2.18

USAC corresponds to Subband number USAC corresponds to Subband number

0 0 4 4

1 1 5 5

2 2 6 6

3 3 7 9 Table 2.19

USAC corresponds to Subband number USAC corresponds to Subband number

0 0 4 4

1 1 5 6

2 2 6 9

3 3 7 12 Table 2.20

USAC corresponds to Subband number USAC corresponds to Subband number

0 1 4 5 1 2 5 6

2 3 6 7

3 4 7 8 Table 2.21

USAC corresponds to Subband number USAC corresponds to Subband number

0 0 4 6

1 1 5 8

2 2 6 10

3 4 7 12 Table 2.22

USAC corresponds to Subband number USAC corresponds to Subband number

0 0 4 6

1 2 5 8

2 3 6 10

3 4 7 12 OR: When the system bandwidth is 10MHz or 7MHz or 8.75MHz, the number of bits required to indicate the USAC parameter is 4bits. 4bits represents the number of 16 different Subbands, which are sufficient to represent all elements in the set B _USAC . As shown in Table 2.23. Table 2.23

Third Bandwidth: When the system bandwidth is 20MHz, the number of bits required to indicate the USAC parameter is

3bits. For 20MHz, the possible set of values for the number of Subbands is C _USAC = {0,1,2,3,4,5,6,7,

8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24}. Table 2.24 to Table 2.274 describe the system When the system bandwidth is 20 MHz, and the number of bits required by the USAC is 3 bits, the correspondence between the value of USAC and the number of Subbands is indicated. 3bits represents 8 different subband numbers. The 8 different subband numbers are taken from the possible value set of the number of Subbands at 20MHz C _USAC , and a total of C ₂₅ ⁸ = 1081575 combinations. For example, Table 2.24 takes {0, 2, 3,4,6,8,9,12}, other combinations than Table 2.24 to Table 2.27 are no longer - enumerated. Table 2.24

Table 2.25

Table 2.26

Table 2.27

Or, when the system bandwidth is 20MHz, the number of bits required to indicate the USAC parameter is 4bits. 4bits represents 16 different Subband numbers. The 16 different Subband numbers are taken from the set CUSAC, a total of C ₂₅ ¹⁶ = 2042975 combinations. For example, Table 2.28 takes {0,1,2,3,4,5,6 , 7, 8, 9, 10, 11, 12, 13, 14, 15}, other combinations than Table 2.28 to Table 2.40 are not listed.

Table 2.28

Table 2.29

Table 2.30

USAC corresponds to Subband number USAC corresponding Subband number

0 0 8 8

1 1 9 9

2 2 10 10

3 3 11 12

4 4 12 14

5 5 13 15

6 6 14 18

7 7 15 20 Table 2.32

USAC corresponds to Subband number USAC corresponds to Subband number

0 0 8 8

1 1 9 9

2 2 10 10

3 3 11 12

4 4 12 14

5 5 13 16

6 6 14 18

7 7 15 20 Table 2.33

USAC corresponds to Subband number USAC corresponds to Subband number

0 0 8 8

1 1 9 9

2 2 10 10

3 3 11 12

4 4 12 14

5 5 13 15

6 6 14 18

7 7 15 21 Table 2.34

USAC corresponds to Subband number USAC corresponds to Subband number

0 0 8 8

1 1 9 9

31 2 2 10 10

3 3 11 12

4 4 12 13

5 5 13 15

6 6 14 18

7 7 15 21 Table 2.35

Table 2.36

Table 2.37

USAC corresponds to Subband number USAC corresponds to Subband number

0 0 8 8

1 1 9 9

2 2 10 10

3 3 11 12

4 4 12 15 5 5 13 18

6 6 14 21

7 7 15 24 Table 2.38

Table 2.39

Table 2.40

Or, when the system bandwidth is 20MHz, the number of bits required to indicate the USAC parameter is 5bits. 5bits represents 32 different subband numbers, and the number of these 32 different Subbands is sufficient to represent all elements in the set C _USAC . As shown in Table 2.41. Table 2.41

The number of bits required to indicate the USAC parameter at each bandwidth can be determined from the above method, but for a plurality of different bandwidths supported by the system, the number of bits required to indicate the parameter is partially identical or completely different from each other. For example, when the system bandwidth is 5MHz, the number of bits required to indicate the USAC parameter is 3bits; when the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 4bits; the system bandwidth is 20MHz. When the number of bits required to indicate the parameter is 5 bits; or, when the system bandwidth is 5 MHz, the number of bits required to indicate the USAC parameter is 2 bits; when the system bandwidth is 10 MHz (which may also be 7 MHz or 8.75 MHz), the parameter is indicated. The required number of bits is 3 bits; when the system bandwidth is 20 MHz, the number of bits required to indicate the parameter is 4 bits; or, when the system bandwidth is 5 MHz, the number of bits required to indicate the USAC parameter is 2 bits; the system bandwidth is 10 MHz (also When it is 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 3bits; when the system bandwidth is 20MHz, the number of bits required to indicate the parameter is 3bits; or When the system bandwidth is 5MHz, the number of bits required to indicate the USAC parameter is 2bits; when the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 4bits; when the system bandwidth is 20MHz, the indication is The number of bits required for this parameter is 4 bits; or, when the system bandwidth is 5 MHz, the number of bits required to indicate the USAC parameter is 3 bits; when the system bandwidth is 10 MHz (also 7 MHz or 8.75 MHz), the required parameter is required. The number of bits is 4 bits; when the system bandwidth is 20 MHz, the number of bits required to indicate this parameter is 4 bits. It should be noted that in this method, even if two different bandwidths use the same number of bits to indicate the USAC parameter, the corresponding table may be different. For example, when the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 4bits, but the corresponding table is Table 2.23; when the system bandwidth is 20MHz, the number of bits required for the parameter is indicated. It is 4bits, but the corresponding table is Table 2.39. Since the system bandwidth is 10MHz (which can be 7MHz or 8.75MHz) and the system bandwidth is 20MHz, it can be considered that the ^{1 1} 10MHz (can be 7MHz or 8.75MHz) and 20MHz features can be unified, and the system bandwidth can be 10MHz ( The same USAC value and correspondence can be used when the system bandwidth is 20MHz and the system bandwidth is 20MHz, which makes the device manufacturing more powerful. The same table is used, ie, the system bandwidth is 1 OMHz (which can be 7MHz or 8.75MHz) and the system bandwidth is 20MHz. For example, when the system bandwidth is 5MHz, the number of bits required to indicate the USAC parameter is 2bits; and when the system bandwidth is 10MHz (also 7MHz or 8.75MHz) and 20MHz, the number of bits required to indicate this parameter is 4bits. The corresponding relationship between the value of USAC and the number of Subbands in the case where the system bandwidth is 5 MHz and the number of bits required for the USAC is 2 bits is as described above, and is not described here. When the system bandwidth is 10MHz (also 7MHz or 8.75MHz) and 20MHz, and the number of bits required for USAC is 4bits, one of the tables at 20MHz when 4bits is required to indicate USAC can be used, for example, Use Table 2.28 or Table 2.29 to determine the correspondence between the value of USAC and the number of Subbands. Through the above example 2, it can be seen that when the system bandwidth is 5MHz, 1 OMHz (which can be 7MHz or 8.75MHz), and the 20MHz system, the number of bits indicating the USAC needs 2bits, 3bits, 3bits, or 2bits, 3bits, respectively. 4bits, or 2bits, 4bits, 4bits, or 3bits, 4bits, 4bits, or 3bits, 4bits, 5bits respectively When combined, in the case that the possible value of the USAC is reduced, redundant and unnecessary information indications are deleted, bit overhead is saved, and certain flexibility is ensured. Configuration Method of Downlink Frequency Partition Configuration (DFPC) Example 3 The DFPC indicates the size and number of frequency partitions in the downlink subframe. 12 is a schematic diagram of application of signaling DFPC when a different number of bit indication parameters are used for a 10 MHz system bandwidth according to an embodiment of the present invention. As shown in FIG. 12, when DFPC takes different values, downlink Frequency Partitioning The process is different. The system bandwidth is 5MHz, 7MHz, 8.75MHz, 10MHz and 20MHz as an example, and it is divided into three types of bandwidth to explain the configuration of DFPC, the first type is 5MHz, the second type is 7MHz or 8.75MHz or 10MHz, The third category is 20MHz. Wherein, N _PRU is the number of _PRUs in one subframe, and in the case of ^:, the Np _RUs corresponding to 5 MHz, 7 MHz, 8.75 MHz, 10 MHz, and 20 MHz are 24, 48, 48, 48, and 96, respectively, but the method is not Jtb limit. And, in the expression of each frequency partition ratio (FP.: FP _{i :} FP ₂ : FP ₃ ) in the following tables, for the occurrence of N1 : N2: N3 : N4, where N1 to N4 can represent frequency partitioning The actual number can also represent the proportional relationship between the frequency partitions. The first type: When the system bandwidth is 5MHz, the number of bits required to indicate the DFPC parameter is 2bits. For 5MHz, the set of possible configurations for _DFPC is A _DFPC :

{ (1 frequency partition, frequency partition size is N _PRU ), (3 frequency partitions, each frequency partition size is N _PRU *l/3 ),

(4 frequency partitions, and FPSo = NPRU*3/24, FPSI = FPS ₂ = FPS ₃ = N _PRU *7/24 ),

(4 frequency partitions, and FPSo = NPRU*6/24, FPSi = FPS ₂ = FPS ₃ = N _PRU *l/4 ),

(4 frequency partitions, and FPSo = NPRU*9/24, FPSI = FPS ₂ = FPS ₃ = N _PRU *5/24 ),

(4 frequency partitions, and FPSo = NPRU* 1/2 , FPSi = FPS ₂ = FPS ₃ = N _PRU *l/6 ), (4 frequency partitions, and FPSo = NPRU* 15/24, FPSi = FPS ₂ = FPS ₃ = N _PRU *l/8 ),

(4 frequency partitions, and FPSo = NPRU* 18/24, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU*21/24, FPSj = FPS ₂ = FPS ₃ = Np _RU * l/24 ) }.

2bits represents 4 different frequency partition numbers and frequency partition sizes. The 4 different frequency partition numbers and frequency partition sizes are taken from the set A _DFPC , and a total of C ₉ ⁴ = 126 combinations. For example, Table 3.1 ~ Table 3.3 describe the correspondence between the value of DFPC and the number of frequency partitions and the size of the frequency partition. FPCT refers to the number of effective frequency partitions, and other combinations are no longer - enumerated. Form 3.1

Table 3.2

Table 3.3

Or, when the system bandwidth is 5MHz, the number of bits required to indicate the DFPC parameter is 3 bits. 3bits represents 8 different frequency partition numbers and frequency partition sizes. The 8 different frequency partition numbers and frequency partition sizes are taken from A _DFPC , and a total of C ₉ ⁸ = 9 combinations. For example, Table 3.4 ~ Table 3.5 describe the correspondence between the value of DFPC and the number of frequency partitions and the size of the frequency partition. Other combinations are not listed. Table 3.4

Table 3.5

Or, although 3bits can represent 8 different frequency partition numbers and frequency partition sizes, since some frequency partition sizes are basically not used, you can select the frequently used frequency partition size from A _DFPC , for example, 5 Species, 6 or 7 species, total C ₉ ⁵ = 126 combinations, C ₉ ⁶ = 84 combinations, C ₉ ⁷ = 36 combinations. For example, as shown in Table 3.6 ~ Table 3.8, the other combinations are no longer - 歹 '". Table 3.6

Table 3.7

The second type: When the system bandwidth is 7MHz or 8.75MHz or 10MHz, the number of bits required to indicate the DFPC parameter is 3bits.

The set of possible configurations for _DFPC is B _DFPC =

{ (1 frequency partition, the size of the frequency partition is N _PRU ),

(3 frequency partitions, and the size of each frequency partition is N _PRU *l/3),

(4 frequency partitions, and FPSo = NPRU*3/48, FPSi = FPS ₂ = FPS ₃ = NPRU*5/16),

(4 frequency partitions, and FPSo = NPRU*6/48, FPSi = FPS ₂ = FPS ₃ = NPRU*7/24),

(4 frequency partitions, and FPSo = NPRU*9/48, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU* 12/48, FPSi = FPS ₂ = FPS ₃ = N _PRU *l/4 ),

(4 frequency partitions FPSo = NPRU* 15/48, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions FPSo = NPRU* 18/48, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions FPSo = NPRU*21/48, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU*24/48, FPSI = FPS ₂ = FPS ₃ = N _PRU *l/6 ), (4 frequency partitions, and FPSo = NPRU*27/48, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU*30/48, FPSI = FPS ₂ = FPS ₃ = N _PRU *l/8 ),

(4 frequency partitions, and FPSo = NPRU*33/48, FPSj = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU*36/48, FPSj = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU*39/48, FPSj = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU*42/48, FPSj = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU*45/48, FPSj = FPS ₂ = FPS ₃ = Np _RU * l/48 ) }.

3bits represents 8 different frequency partition numbers and frequency partition sizes. The 8 different frequency partition numbers and frequency partition sizes are taken from the set B _DFPC , and a total of C ₁₇ ⁸ = 24310 combinations. For example, Table 3.9 ~ Table 3.11, others are no longer - enumerated. Table 3.9

Table 3.10

Table 3.1 1

Or, when the system bandwidth is 7MHz or 8.75MHz or 10MHz, the number of bits required to indicate the DFPC parameter is 4bits. 4bits represents 16 different frequency partition numbers and frequency partition sizes. The 16 different frequency partition numbers and frequency partition sizes are taken from the set B _DFPC , and a total of C ₁₇ ¹⁶ = 17 combinations. For example, as shown in Table 3.12 to Table 3.13. Table 3.12

Or, although 4bits can represent 16 different frequency partition numbers and frequency partition sizes, since some frequency partition sizes are basically not used, you can select the frequently used frequency partition size from B _DFPC to represent, for example, 12 kinds. , 13 species, 14 species or 15 species, a total of ₁₇ ¹² = 6188 combinations, C ₁₇ ¹³ = 2380 combinations, C ₁₇ ¹⁴ = 680 combinations, C ₁₇ ¹⁵ = 136 combinations. For example, as shown in Table 3.14, other combinations are no longer listed. Table 3.14

The third category: When the system bandwidth is 20MHz, the number of bits required to indicate the DFPC parameter is 3bits.

The set of possible configurations for _DFPC is C _DFPC =

{ (1 frequency partition, the size of the frequency partition is N _PRU ), (3 frequency partitions, and the size of each frequency partition is N _PRU *l/3),

(4 frequency partitions, and FPS, = NPRU*3/96 ' FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPS, = Np _RU *6/96 , FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPS, = N _PRU *9/96, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU* 12/96, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = Np _RU * 15/96 , FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU* 18/96, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU*21/96, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU*24/96, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSc = NPRU*27/96, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSc = NPRU*30/96, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSc = NPRU*33/96, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSc = Np _RU *36/96 , FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSc = NPRU*39/96, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU*42/96 FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = N _PRU *45/96 FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = N _PRU *48/96 FPS, = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = Np _RU *51/96 FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = Np _RU * 54/96 FPS! = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU*57/96 FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU* 60/96 FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU*63/96 FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU* 66/96 FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU*69/96 FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU* 72/96 FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = Np _RU *75/96 FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU* 78/96 FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU*81/96, FPSj = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU* 84/96, FPSj = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU* 87/96, FPSj = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU*90/96, FPSj = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU*93/96, FPSj = FPS ₂ = FPS ₃ =

NPRU* 1/96 ) }.

3bits represents 8 different frequency partition numbers and frequency partition sizes. The 8 different frequency partition numbers and frequency partition sizes are taken from the set C _DFPC , a total of C ₃₃ ⁸ = 13884156 combinations. Any combination can be used to indicate the correspondence between the value of the DFPC and the number of frequency partitions and the size of the frequency partition. For example, as shown in Tables 3.15 to 3.17, other combinations are not listed. Table 3.15

Table 3.17

Or, when the system bandwidth is 20MHz, the number of bits required to indicate the DFPC parameter is 4bits. 4bits represents 16 different frequency partition numbers and frequency partition sizes. The 16 different frequency partition numbers and frequency partition sizes are taken from the set C _DFPC , a total of C ₃₃ ¹⁶ = 1166803110 combinations. Any combination can be used to indicate the correspondence between the DFPC value and the number of frequency partitions and the size of the frequency partition. For example, Table 3.18 ~ Table 3.19, other combinations are not - enumerated. Table 3.18

6

ZZ6£L0/600Z l3/13d 6S8lll/0l0Z OAV 14 66: 10: 10: 10 4 NPRU * 66/96 NPRU * 10/96

15 72: 8 : 8 : 8 4 NPRU * 72/96 NPRU * 8/96 Or, when the system bandwidth is 20MHz, the number of bits required to indicate the DFPC parameter is 5bits. 5bits represents 32 different frequency partition numbers and frequency partition sizes. The 32 different frequency partition numbers and frequency partition sizes are taken from the set C _DFPC , and a total of C ₃₃ ³² = 33 combinations. Any combination may be used to indicate the correspondence between the DFPC value and the number of frequency partitions and the size of the frequency partition, for example, as shown in Table 3.20, and other combinations are not-listed. Table 3.20

Or, although 5bits can represent 32 different frequency partition numbers and frequency partition sizes, since some frequency partition sizes are basically not used, you can select the frequently used frequency partition size from C _DFPC to represent, for example, M ( 1<M<32) species, a total of C ₃₃ ^M combinations. For example, as shown in Table 3.21~ Table 3.22, other combinations are no longer listed. Table 3.21

39

ZZ6£L0/600Z l3/13d 6S8lll/0l0Z OAV 10 33 : 21 : 21 : 21 4 NPRU * 33/96 NPRU * 21/96

11 36: 20: 20: 20 4 NPRU * 36/96 NPRU * 20/96

12 39: 19: 19: 19 4 NPRU * 39/96 NPRU * 19/96

13 42: 18 : 18 : 18 4 NPRU * 42/96 NPRU * 18/96

14 45 : 17: 17: 17 4 NPRU * 45/96 NPRU * 17/96

15 48 : 16: 16: 16 4 NPRU * 48/96 NPRU * 16/96

16 5 1 : 15 : 15 : 15 4 NPRU * 5 1/96 NPRU * 15/96

17 54: 14: 14: 14 4 NPRU * 54/96 NPRU * 14/96

18 57: 13 : 13 : 13 4 NPRU * 57/96 NPRU * 13/96

19 60: 12: 12: 12 4 NPRU * 60/96 NPRU * 12/96

20 63 : 11 : 11 : 1 1 4 NPRU * 63/96 NPRU * 11/96

21 66: 10: 10: 10 4 NPRU * 66/96 NPRU * 10/96

22 69: 9: 9: 9 4 NPRU * 69/96 NPRU * 9/96

23 72: 8 : 8 : 8 4 NPRU * 72/96 NPRU * 8/96

24 reservations reservations reservations reservations

25 reservations reservations reservations reservations

26 reservations reservations reservations reservations

27 reservations reservations reservations reservations

28 reservations reservations reservations reservations

29 reservations reservations reservations reservations

30 reservations reservations reservations reservations

31 Reserved Reservation Reserved The number of bits required to indicate DFPC parameters for each bandwidth can be determined from the above method, but for different bandwidths, the number of bits required to indicate DFPC parameters is partially identical or completely different from each other. For example, when the system bandwidth is 5MHz, the number of bits required to indicate the DFPC parameter is 2bits; when the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 3bits; when the system bandwidth is 20MHz , the number of bits required to indicate the parameter is 3 bits; or, when the system bandwidth is 5 MHz, the number of bits required to indicate the DFPC parameter is 2 bits; when the system bandwidth is 10 MHz (also 7 MHz or 8.75 MHz), the parameter is indicated. The number of bits required is 3 bits; when the system bandwidth is 20 MHz, the number of bits required to indicate the parameter is 4 bits; or When the system bandwidth is 5MHz, the number of bits required to indicate the DFPC parameter is 2bits; when the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 3bits; when the system bandwidth is 20MHz, the indication is The number of bits required for this parameter is 5 bits; or, when the system bandwidth is 5 MHz, the number of bits required to indicate the DFPC parameter is 2 bits; when the system bandwidth is 10 MHz (also 7 MHz or 8.75 MHz), the required parameter is required. The number of bits is 4 bits; when the system bandwidth is 20 MHz, the number of bits required to indicate the parameter is 4 bits; or, when the system bandwidth is 5 MHz, the number of bits required to indicate the DFPC parameter is 2 bits; the system bandwidth is 10 MHz (may also be 7 MHz) Or 8.75MHz), the number of bits required to indicate the parameter is 4bits; when the system bandwidth is 20MHz, the number of bits required to indicate the parameter is 5bits; or, when the system bandwidth is 5MHz, the number of bits required to indicate the DFPC parameter 3 bits; when the system bandwidth is 10 MHz (also 7 MHz or 8.75 MHz), the number of bits required to indicate the parameter is 3 bits; when the system bandwidth is 20 MHz, the number of bits required to indicate the parameter is 4 bits; or When the system bandwidth is 5MHz, the number of bits required to indicate the DFPC parameter is 3bits; when the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 3bits; when the system bandwidth is 20MHz, the indication is The number of bits required for this parameter is 5 bits; or, when the system bandwidth is 5 MHz, the number of bits required to indicate the DFPC parameter is 3 bits; when the system bandwidth is 10 MHz (also 7 MHz or 8.75 MHz), the required parameters are indicated. The number of bits is 4 bits; when the system bandwidth is 20 MHz, the number of bits required to indicate the parameter is 4 bits; or, when the system bandwidth is 5 MHz, the number of bits required to indicate the DFPC parameter is 3 bits; the system bandwidth is 10 MHz (may also be 7 MHz) Or 8.75MHz), the number of bits required to indicate the parameter is 4bits; when the system bandwidth is 20MHz, the number of bits required to indicate the parameter is 5bits; or, when the system bandwidth is 5MHz, the number of bits required to indicate the DFPC parameter 4 bits; when the system bandwidth is 10 MHz (also 7 MHz or 8.75 MHz), the number of bits required to indicate the parameter is 4 bits; when the system bandwidth is 20 MHz, the number of bits required to indicate the parameter is 5 bits; or When the system bandwidth is 5MHz, the number of bits required to indicate the DFPC parameter is 4bits; when the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 5bits; when the system bandwidth is 20MHz, the indication is The number of bits required for this parameter is 5 bits. It should be noted that in the above DFPC configuration method, when two different bandwidths use the same number of bits to indicate DFPC parameters, the corresponding tables may be the same or different. For example, the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate this parameter is 4bits, but the corresponding table is Table 3.13; when the system bandwidth is 20MHz, the number of bits required to indicate the parameter is 4bits, but corresponding The table is shown in Table 3.18. Since the system bandwidth is 10MHz (which can be 7MHz or 8.75MHz) and the system bandwidth is 20MHz, it can be considered that the ^{1 1} 10MHz (can be 7MHz or 8.75MHz) and 20MHz features can be unified, and the system bandwidth can be 10MHz ( The value of the same DFPC and the corresponding relationship can be used when the system bandwidth is 20MHz and the system bandwidth is 20MHz, so that the device manufacturing is stronger. The same table is used, ie, the system bandwidth is 10MHz (which can be 7MHz or 8.75MHz) and the system bandwidth is 20MHz. For example, when the system bandwidth is 5MHz, the number of bits required to indicate the DFPC parameter is 2bits; and when the system bandwidth is 10MHz (also 7MHz or 8.75MHz) and 20MHz, the number of bits required to indicate this parameter is 4bits. Tables 3.1 to 3.3 above describe the configuration method in the case where the system bandwidth is 5 MHz and the number of bits required for the DFPC is 2 bits, which is not mentioned here. When the system bandwidth is 10MHz (also 7MHz or 8.75MHz) and 20MHz, and the number of bits required to indicate DFPC is 4bits, you can use 20MHz in one of the tables when 4bits is required to indicate DFPC, for example, Use Table 3.18 or Table 3.19. In addition, it should be noted that in the above DFPC configuration method, for each table, the relationship between the value of the DFPC and the meaning indicated by the value of the DFPC can be changed, and each table is an embodiment, as long as one table The values of the DFPCs contained in the indications are the same and are considered to be the same table, all within the scope of protection. For example, Table 3.23 and Table 3.15 are both considered to be the same table, because the values of the DFPCs contained in the two tables are the same meaning. Table 3.23

Through the above example 3, it can be seen that when the system bandwidth is 5ΜΗζ, 10MHz (which can be 7MHz or 8.75MHz), and the 20MHz system, the number of bits indicating the DFPC needs to be 2bits, 3bits, 4bits, or 2bits respectively. 4bits, 4bits, or 3bits, 4bits, 4bits, or 3bits, 4bits, 5bits, etc., or other combinations, when redundant values of DFPC are reduced, redundant and unnecessary information indications are deleted. , saves bit overhead and guarantees a certain flexibility. Configuration Method of Upstream Frequency Partition Configuration (UFPC) Example 4 UFPC indicates the size and number of frequency partitions in an uplink subframe. FIG. 13 is a schematic diagram of application of signaling UFPC when a different number of bit indication parameters are used for a 10 MHz system bandwidth according to an embodiment of the present invention. As shown in FIG. 13 , when the UFPC takes different values, the uplink frequency partitioning is performed. The process is different. The system bandwidth is 5MHz, 7MHz, 8.75MHz, 10MHz and 20MHz as an example, and it is divided into three types of bandwidth to explain the configuration of UFPC, the first type is 5MHz, the second type is 7MHz or 8.75MHz or 10MHz, The third category is 20MHz. Wherein, N _PRU is the number of _PRUs in one subframe, and in the case of ^:, the N _PRUs corresponding to 5 MHz, 7 MHz, 8.75 MHz, 10 MHz, and 20 MHz are 24, 48, 48, 48, and 96, respectively, but the method is not This limit. The first type: When the system bandwidth is 5MHz, the number of bits required to indicate the UFPC parameter is 2bits. For 5MHz, the set of possible configurations for _UFPC is A _UFPC :

{ (1 frequency partition, the size of the frequency partition is N _PRU ),

(3 frequency partitions, each frequency partition has a size of N _PRU *l/3 ),

(4 frequency partitions, and FPSo = NPRU*6/24, FPSi = FPS ₂ = FPS ₃ = N _PRU *l/4 ), (4 frequency partitions, and FPSo = NPRU*9/24, FPSI = FPS ₂ = FPS ₃ = N _PRU *5/24 ),

(4 frequency partitions, and FPSo = NPRU* 1/2 , FPSi = FPS ₂ = FPS ₃ = N _PRU *l/6 ),

(4 frequency partitions, and FPSo = NPRU* 15/24, FPSi = FPS ₂ = FPS ₃ = N _PRU *l/8 ),

(4 frequency partitions, and FPSo = NPRU* 18/24, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU*21/24, FPSi = FPS ₂ = FPS ₃ = NPRU* 1/24) }.

2bits represents 4 different frequency partition numbers and frequency partition sizes. The 4 different frequency partition numbers and frequency partition sizes are taken from the set A _UFPC , a total of C ₉ ⁴ = 126 combinations. For example, Table 4.1 ~ Table 4.3 describe the correspondence between the value of UFPC and the number of frequency partitions and the size of the frequency partition. Other combinations are no longer - enumerated. Table 4.1

Or, when the system bandwidth is 5MHz, the number of bits required to indicate the UFPC parameter is 3 bits. 3bits represents 8 different frequency partition numbers and frequency partition sizes. The 8 different frequency partition numbers and frequency partition sizes are taken from A _UFPC , and a total of C ₉ ⁸ = 9 combinations. For example, Table 4.4 ~ Table 4.5 describe the correspondence between the value of UFPC and the number of frequency partitions and the size of the frequency partition. Other combinations are not listed. Table 4.4

5 12: 4: 4: 4 4 Np _RU * 1/2 Np _RU * 1/6

6 15: 3: 3: 3 4 NPRU * 5/8 NPRU * 1/8

7 21: 1: 1: 1 4 NPRU * 7/8 NPRU * 1/24 Or, although 3bits can represent 8 different frequency partition numbers and frequency partition sizes, some frequency partition sizes are basically not used, so From A _UFPC , you can choose the frequency partition size you use frequently, for example, 5, 6 or 7 types, total C ₉ ⁵ = 126 combinations, C ₉ ⁶ = 84 combinations, C ₉ ⁷ = 36 combination. For example, as shown in Table 4.6 ~ Table 4.8, the other combinations are no longer - 歹 '". Table 4.6

Table 4.7

Table 4.8

The second type: When the system bandwidth is 7MHz or 8.75MHz or 10MHz, the number of bits required to indicate the UFPC parameter is 3bits.

The set of possible configurations for _UFPC is B _UFPC = { (1 frequency partition, the size of the frequency partition is N _PRU ),

(4 frequency partitions, and FPSo = NPRU*3/48, FPSi = FPS ₂ = FPS ₃ = N _PRU *5/16 ),

(4 frequency partitions, and FPSo = NPRU*6/48, FPSi = FPS ₂ = FPS ₃ = N _PRU *7/24 ),

(4 frequency partitions, and FPSo = NPRU*9/48, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU* 15/48, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU* 18/48, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU*21/48, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU*24/48, FPSI = FPS ₂ = FPS ₃ = N _PRU *l/6 ),

(4 frequency partitions, and FPSo = NPRU*27/48, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions FPSo = NPRU*33/48, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions FPSo = NPRU*36/48, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions FPSo = NPRU*39/48, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions FPSo = NPRU*42/48, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions FPSo = NPRU*45/48, FPSi = FPS ₂ = FPS ₃ = NPRU* 1/48 ) }.

3bits represents 8 different frequency partition numbers and frequency partition sizes. The 8 different frequency partition numbers and frequency partition sizes are taken from the set B _UFPC , a total of C ₁₇ ⁸ = 24310 combinations. For example, Table 4.9 to Table 4.11, others are no longer - enumerated. Table 4.9

6 18 : 10: 10: 10 4 NPRU * 9/24 NPRU * 5/24

7 21 : 9: 9: 9 4 NPRU * 7/16 NPRU * 3/16 Table 4.10

Table 4.1 1

Or, when the system bandwidth is 7MHz or 8.75MHz or 10MHz, the number of bits required to indicate the UFPC parameter is 4bits. 4bits represents 16 different frequency partition numbers and frequency partition sizes. The 16 different frequency partition numbers and frequency partition sizes are taken from the set B _UFPC , a total of C ₁₇ ¹⁶ = 17 combinations. For example, as shown in Table 4.12 to Table 4.13. Table 4.12

Or, although 4bits can represent 16 different frequency partition numbers and frequency partition sizes, since some frequency partition sizes are basically not used, you can select the frequently used frequency partition size from B _UFPC to represent, for example, 12 kinds. , 13 species, 14 species or 15 species, a total of ₁₇ ¹² = 6188 combinations, C ₁₇ ¹³ = 2380 combinations, C ₁₇ ¹⁴ = 680 combinations, C ₁₇ ¹⁵ = 136 combinations. For example, as shown in Table 4.14, other combinations are not listed. Table 4.14

The third category: When the system bandwidth is 20MHz, the number of bits required to indicate the UFPC parameter is 3bits. The set of possible configurations for _UFPC is C _UFPC =

{ (1 frequency partition, the size of the frequency partition is N _PRU ),

(4 frequency partitions, and FPSo = NPRU*3/96, FPSj = FPS ₂ = FPS ₃ = N _PRU *31/96),

(4 frequency partitions, and FPSo = NPRU*6/96, FPSj = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = N _PRU *9/96, FPS) = FPS ₂ = FPS ₃ =

(4 frequency partitions and FPSo = NPRU* 12/96, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions and FPSo = NPRU* 15/96, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions and FPSo = NPRU* 18/96, FPSi = FPS ₂ = FPS ₃ = N _PRU *26/96 ),

(4 frequency partitions and FPSo = NPRU*21/96, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions and FPSo = NPRU*24/96, FPS = FPS ₂ = FPS ₃ =

(4 frequency partitions and FPSo = NPRU*27/96, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions and FPSo = NPRU*30/96, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions and FPSo = NPRU*33/96, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions and FPSo = NPRU*36/96, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = N _PRU *39/96 , FPSj = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = N *42/96 , FPSj = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = N _PRU *45/96, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU*48/96, FPSj = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = N _PRU *51/96, FPS = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU* 54/96, FPSj = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU* 57/96, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU*60/96, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU* 63/96, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU*66/96, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU* 69/96, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU* 72/96, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU* 75/96, FPSi = FPS ₂ = FPS ₃ =

(4 frequency partitions, and FPSo = NPRU*78/96, FPSj = FPS ₂ = FPS ₃

(4 frequency partitions, and FPSo = NPRU*81/96, FPSj = FPS ₂ = FPS ₃

(4 frequency partitions, and FPSo = NPRU* 84/96, FPSj = FPS ₂ = FPS ₃

(4 frequency partitions, and FPSo = NPRU* 87/96, FPSj = FPS ₂ = FPS ₃

(4 frequency partitions, and FPSo = NPRU*90/96, FPSj = FPS ₂ = FPS ₃

(4 frequency partitions, and FPSo = NPRU*93/96, FPSj = FPS ₂ = FPS ₃

NPRU* 1/96 ) }.

3bits represents 8 different frequency partition numbers and frequency partition sizes. The 8 different frequency partition numbers and frequency partition sizes are taken from the set C _UFPC , a total of C ₃₃ ⁸ = 13884156 combinations. Any combination can be used to indicate the correspondence between the value of the UFPC and the number of frequency partitions and the size of the frequency partition. For example, Tables 4.15 to 4.17, other combinations are not listed. Table 4.15

Table 4.16

Or, when the system bandwidth is 20MHz, the number of bits required to indicate the UFPC parameter is 4bits. 4bits represents 16 different frequency partition numbers and frequency partition sizes. The 16 different frequency partition numbers and frequency partition sizes are taken from the set C _UFPC , a total of C ₃₃ ¹⁶ = 1166803110 combinations. Any combination of UFPC values and the number of frequency partitions and the size of the frequency partition may be indicated by any combination, as shown in Table 4.18 to Table 4.19, and other combinations are not listed. Table 4.18

UFPC Frequency Division Ratio Effective Frequency Partition Number FPo Size Other Partition Size

(FP ₀ : FPi : FP ₂ : FPCT FPSo FPSi (i>0) 96/91 * Leg N 96/817 * Cerebral palsy 91 : 9 ΐ : 91 : 817 Π

96/81 *legs N 96/ 1 *brain Ν81 :8ΐ :81 -Z 01

96/0 B * Legs N 96/9 ε * Brain Ν 0Z -0Z -0Z -9£ 6

96I L * Leg Ν 96/0 ε * Brain Ν ZZ -ZZ -ZZ -0£ 8

96/1 B * Legs Ν 96/1 B * Brain Ν Z - Z - Z - Z L

961 τ * Legs Ν 96/1 * Brain Ν ςζ -ςζ -ςζ -ιζ 9

96/9 B * Leg Ν 96/81 * Brain Ν 9Z -9Z -9Z -SI ς

96ILZ * Legs Ν 96/51 * Brain Ν LZ -LZ -LZ -ςι

96/8B * Legs Ν 96/ 1 * Brain Ν SZ -SZ -SZ -Zl £

96/6 B * Legs Ν 96/6 * Brain Ν 6Z -6Z -6Z : 6 Z

96/B ε * Legs Ν 0 £ Z€ -Z€ -Z€ -0 I

0 cerebral _palsy I 0 -0 -0 :96 0

(0<ΐ) ^! S<M 丄dd ■ ^z dd - ^l dd -°dd)

,f, γ ^

ZZ6£L0/600Z l3/13d 6S8lll/0l0Z OAV 12 54: 14: 14: 14 4 NPRU * 54/96 NPRU * 14/96

13 60: 12: 12: 12 4 NPRU * 60/96 NPRU * 12/96

14 66: 10: 10: 10 4 NPRU * 66/96 NPRU * 10/96

15 72: 8 : 8 : 8 4 NPRU * 72/96 NPRU * 8/96 Or, when the system bandwidth is 20MHz, the number of bits required to indicate the UFPC parameter is 5bits. 5bits represents 32 different frequency partition numbers and frequency partition sizes. The 32 different frequency partition numbers and frequency partition sizes are taken from the set C _UFPC , a total of C ₃₃ ³² = 33 combinations. Any combination may be used to indicate the correspondence between the value of the UFPC and the number of frequency partitions and the size of the frequency partition. For example, as shown in Table 4.20, other combinations are not listed. Table 4.20

Or, although 5bits can represent 32 different frequency partition numbers and frequency partition sizes, since some frequency partition sizes are basically not used, you can select the frequently used frequency partition size from C _UFPC to express, for example, M ( 1<M<32) species, a total of C ₃₃ ^M combinations. For example, as shown in Table 4.21~ Table 4.22, other combinations are no longer listed. Table 4.21

ZL

ZZ6£L0/600Z l3/13d 6S8lll/0l0Z OAV 8 27: 23 : 23 : 23 4 NPRU * 27/96 NPRU * 23/96

9 30: 22: 22: 22 4 NPRU * 30/96 NPRU * 22/96

10 33 : 21 : 21 : 21 4 NPRU * 33/96 NPRU * 21/96

11 36: 20: 20: 20 4 NPRU * 36/96 NPRU * 20/96

12 39: 19: 19: 19 4 NPRU * 39/96 NPRU * 19/96

13 42: 18 : 18 : 18 4 NPRU * 42/96 NPRU * 18/96

14 45 : 17: 17: 17 4 NPRU * 45/96 NPRU * 17/96

15 48 : 16: 16: 16 4 NPRU * 48/96 NPRU * 16/96

16 5 1 : 15 : 15 : 15 4 NPRU * 5 1/96 NPRU * 15/96

17 54: 14: 14: 14 4 NPRU * 54/96 NPRU * 14/96

18 57: 13 : 13 : 13 4 NPRU * 57/96 NPRU * 13/96

19 60: 12: 12: 12 4 NPRU * 60/96 NPRU * 12/96

20 63 : 11 : 11 : 1 1 4 NPRU * 63/96 NPRU * 11/96

21 66: 10: 10: 10 4 NPRU * 66/96 NPRU * 10/96

22 69: 9: 9: 9 4 NPRU * 69/96 NPRU * 9/96

23 72: 8 : 8 : 8 4 NPRU * 72/96 NPRU * 8/96

24 reservations reservations reservations reservations

25 reservations reservations reservations reservations

26 reservations reservations reservations reservations

27 reservations reservations reservations reservations

28 reservations reservations reservations reservations

29 reservations reservations reservations reservations

30 reservations reservations reservations reservations

31 Reserved Reservation Reserved The number of bits required to indicate UFPC parameters for each bandwidth can be determined from the above method, but for different bandwidths, the number of bits required to indicate UFPC parameters is partially identical or completely different from each other. For example, when the system bandwidth is 5MHz, the number of bits required to indicate the UFPC parameter is 2bits; when the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 3bits; when the system bandwidth is 20MHz , the number of bits required to indicate the parameter is 3 bits; or, when the system bandwidth is 5 MHz, the number of bits required to indicate the UFPC parameter is 2 bits; when the system bandwidth is 10 MHz (also 7 MHz or 8.75 MHz), the parameter is indicated. The number of bits required is 3bits; when the system bandwidth is 20MHz, the number of bits required to indicate the parameter is 4bits; or, when the system bandwidth is 5MHz, the number of bits required to indicate the UFPC parameter is 2bits; the system bandwidth is 10MHz (also 7MHz or 8.75MHz) The number of bits required to indicate the parameter is 3 bits; when the system bandwidth is 20 MHz, the number of bits required to indicate the parameter is 5 bits; or, when the system bandwidth is 5 MHz, the number of bits required to indicate the UFPC parameter is 2 bits; When the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate this parameter is 4bits; when the system bandwidth is 20MHz, the number of bits required to indicate the parameter is 4bits; or, when the system bandwidth is 5MHz , the number of bits required to indicate the UFPC parameter is 2 bits; when the system bandwidth is 10 MHz (also 7 MHz or 8.75 MHz), the number of bits required to indicate the parameter is 4 bits; when the system bandwidth is 20 MHz, the required parameter is required. The number of bits is 5 bits; or, when the system bandwidth is 5 MHz, the number of bits required to indicate the UFPC parameter is 3 bits; when the system bandwidth is 10 MHz (also 7 MHz or 8.75 MHz), the number of bits required to indicate the parameter is 3bits; when the system bandwidth is 20MHz, the number of bits required to indicate the parameter is 4bits; or, when the system bandwidth is 5MHz, the number of bits required to indicate the UFPC parameter is 3bits; the system bandwidth is 10MHz (also 7MHz or 8.75MHz) The number of bits required to indicate the parameter is 3 bits; when the system bandwidth is 20 MHz, the number of bits required to indicate the parameter is 5 bits; or, when the system bandwidth is 5 MHz, the number of bits required to indicate the UFPC parameter is 3 bits; When the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate this parameter is 4bits; when the system bandwidth is 20MHz, the number of bits required to indicate the parameter is 4bits; or, when the system bandwidth is 5MHz , the number of bits required to indicate the UFPC parameter is 3 bits; when the system bandwidth is 10 MHz (also 7 MHz or 8.75 MHz), the number of bits required to indicate the parameter is 4 bits; when the system bandwidth is 20 MHz, the required parameter is required. The number of bits is 5 bits; or, when the system bandwidth is 5 MHz, the number of bits required to indicate the UFPC parameter is 4 bits; when the system bandwidth is 10 MHz (also 7 MHz or 8.75 MHz), the number of bits required to indicate the parameter is 4bits; when the system bandwidth is 20MHz, the number of bits required to indicate the parameter is 5bits; or, when the system bandwidth is 5MHz, the number of bits required to indicate the UFPC parameter is 4bits; the system bandwidth is 10MHz (also 7MHz or 8.75MHz) When the number of bits required to indicate the parameter is 5 bits; when the system bandwidth is 20 MHz, the number of bits required to indicate the parameter is 5 bits. It should be noted that in the above UFPC configuration method, when two different bandwidths use the same number of bits to indicate UFPC parameters, the corresponding tables may be the same or different. For example, when the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 4bits, but the corresponding table is Table 4.13; when the system bandwidth is 20MHz, the number of bits required for the parameter is indicated. It is 4bits, but the corresponding table is Table 4.18. Since the system bandwidth is 10MHz (which can be 7MHz or 8.75MHz) and the system bandwidth is 20MHz, it can be considered that the ^{1 1} 10MHz (can be 7MHz or 8.75MHz) and 20MHz features can be unified, and the system bandwidth can be 10MHz ( The value of the same UFPC and the corresponding relationship can be used when the system bandwidth is 20MHz and the system bandwidth is 20MHz, so that the device manufacturing is stronger. The same table is used, ie, the system bandwidth is 10MHz (which can be 7MHz or 8.75MHz) and the system bandwidth is 20MHz. For example, when the system bandwidth is 5 MHz, the number of bits required to indicate the UFPC parameter is 2 bits; and when the system bandwidth is 10 MHz (also 7 MHz or 8.75 MHz) and 20 MHz, the number of bits required to indicate the parameter is 4 bits. Tables 4.1 to 4.3 above describe the configuration method in the case where the system bandwidth is 5 MHz and the number of bits required for the UFPC is 2 bits, which is not mentioned here. When the system bandwidth is 10MHz (also 7MHz or 8.75MHz) and 20MHz, and the number of bits required to indicate UFPC is 4bits, you can use 20MHz in one of the tables when 4bits is required to indicate UFPC, for example, Use Table 4.18 or Table 4.19. In addition, it should be pointed out that in the above UFPC configuration method, for each table, the relationship between the value of UFPC and the meaning indicated by the value of UFPC can be changed, and each table is an embodiment, as long as one table The values of UFPC contained in the indications are the same meaning, and are considered to be the same table, all within the scope of protection. For example, Table 4.23 and Table 4.15 are both considered to be the same table, because the values of UFPC contained in the two tables are the same meaning. Table 4.23

Through the above example 4, it can be seen that when the system bandwidth is 5ΜΗζ, 10MHz (which can be 7MHz or 8.75MHz), and the 20MHz system, the number of bits indicating the UFPC needs to be 2bits, 3bits, 4bits, or 2bits respectively. 4bits, 4bits, or 3bits, 4bits, 4bits, or 3bits, 4bits, 5bits, etc., or other combinations are required. When the possible value of UFPC is reduced, redundant and unnecessary information indications are deleted. , saves bit overhead and guarantees a certain flexibility. Example for configuring the downlink frequency division subband number (DFPSC) Example 5 FIG. 14 is a schematic diagram of the application of the resource mapping indication information in the embodiment of the present invention, when a different number of bit indication parameters are used for the 10 MHz system bandwidth, as shown in the figure. As shown in Figure 14, when the DFPSC takes different values, the downstream Frequency Partitioning process is different. The system bandwidth is 5MHz, 7MHz, 8.75MHz, 10MHz and 20MHz as an example, and it is divided into three types of bandwidth to explain the configuration of DFPSC, the first type is 5MHz, the second type is 7MHz or 8.75MHz or 10MHz, The third category is 20MHz. The first type: When the system bandwidth is 5MHz, the number of bits required to indicate the DFPSC parameters is lbits. For 5MHz, the set of possible Subbands of DFPSC is: A _DFPS c={0,l,2} _o lbits represents the number of two different _Subbands , the number of these two different _Subbands is taken from the set A _DFPSC , A total of C ₃ ² = 3 combinations. For example, Table 5.1 to Table 5.3 are shown. Table 5.1

DFPSC FPi(i>0) corresponds to Subband number DFPSC FPi(i>0) corresponds to Subband number

0 0 1 1 Table 5.2

DFPSC FPi (i>0) corresponds to Subband number DFPSC FPi (i>0) corresponds to Subband number 0 1 1 2 Table 5.3

0 0 1 2 Or, when the system bandwidth is 5MHz, the number of bits required to indicate the DFPSC parameter is 2bits. As shown in Table 5.4. Table 5.4

The second type: When the system bandwidth is 7MHz or 8.75MHz or 10MHz, the number of bits required to indicate the DFPSC parameters is 2bits. For 7MHz or 8.75MHz or 10MHz, the set of possible Subbands for DFPSC is: B _DFPSC = {0, 1, 2, 3, 4}. 2bits represents the number of 4 different _Subbands , the number of these 4 different _Subbands is taken from the set B _DFPSC , and a total of C ₅ ⁴ = 5 combinations. For example, Table 5.5~ Table 5.9. Table 5.5

Table 5.8 DFPSC FPi (i>0) corresponds to Subband number DFPSC FPi (i>0) corresponds to Subband number

0 1 2 3

1 2 3 4 Table 5.9

0 0 2 3

1 2 3 4 Alternatively, when the system bandwidth is 7MHz or 8.75MHz or 10MHz, the number of bits required to indicate the DFPSC parameter is 3bits. Correspondence between the value of DFPSC and the number of Subbands of its corresponding frequency partition. Example, shown in Table 5.10. Table 5.10

The third category: When the system bandwidth is 20MHz, the number of bits required to indicate the DFPSC parameters is 2 bits. For 20MHz, the set of possible Subbands for DFPSC is: CDFPSC={0, 1,2,3,4,5,6,7,8}„ 2bits represents the number of 4 different Subbands, these 4 different The number of _Subbands is taken from the set C _DFPSC , a total of C ₉ ⁴ = 126 combinations. For example, Table 5.11 to Table 5.14 describe the case where the system bandwidth is 20 MHz and the number of bits required to indicate DFPSC is 2 bits, DFPSC Correspondence between the value and the number of Subbands of its corresponding frequency partition, other combinations are not - enumerated. Table 5.11

1 1 3 4 Table 5.13

0 0 2 4

1 2 3 6 Table 5.14

0 1 2 3

1 2 3 4 Alternatively, when the system bandwidth is 20MHz, the number of bits required to indicate the DFPSC parameter is 3 bits. 3bits represents the number of 8 different Subbands, and the number of these 4 different Subbands is taken from the set CDFPSO total C ₉ ⁸ = 9 combinations. For example, Table 5.15 to Table 5.17 describe the correspondence between the value of DFPSC and the number of Subbands of the corresponding frequency partition when the number of bits is 3 bits, and other combinations are not - 歹 '". Table 5.15

Table 5.16

Table 5.17

0 1 4 5

1 2 5 6

2 3 6 7

3 4 7 8 Or, when the system bandwidth is 20MHz, the number of bits required to indicate the DFPCS parameter is 4bits. For example, Table 5.18 describes the correspondence between the value of DFPSC and the number of Subbands of its corresponding frequency partition when the number of bits is 4 bits. Table 5.18

The number of bits required to indicate the DFPSC parameters for each bandwidth can be determined from the above method, but for different bandwidths, the number of bits required to indicate the DFPSC parameters is partially identical or completely different from each other. For example, when the system bandwidth is 5MHz, the number of bits required to indicate the DFPSC parameter is 1 bits; when the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 2bits; the system bandwidth is At 20 MHz, the number of bits required to indicate this parameter is 2 bits; or, when the system bandwidth is 5 MHz, the number of bits required to indicate the DFPSC parameter is 1 bits; when the system bandwidth is 10 MHz (also 7 MHz or 8.75 MHz), the indication The number of bits required for this parameter is 2 bits; when the system bandwidth is 20 MHz, the number of bits required to indicate the parameter is 3 bits; or, when the system bandwidth is 5 MHz, the number of bits required to indicate the DFPSC parameter is 1 bits; When 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 2bits; when the system bandwidth is 20MHz, the number of bits required to indicate the parameter is 4bits; or, when the system bandwidth is 5MHz, the DFPSC is indicated. The number of bits required for the parameter is 1 bits; when the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 3bits; when the system bandwidth is 20MHz, the required ratio of the parameter is indicated. The special number is 3 bits; or, when the system bandwidth is 5 MHz, the number of bits required to indicate the DFPSC parameter is 1 bits; when the system bandwidth is 10 MHz (also 7 MHz or 8.75 MHz), the number of bits required to indicate the parameter is 3bits; when the system bandwidth is 20MHz, the number of bits required to indicate the parameter is 4bits; or, when the system bandwidth is 5MHz, the number of bits required to indicate the DFPSC parameter is 1 bits; the system bandwidth is 10MHz (may also be 7MHz or 8.75) In MHz, the number of bits required to indicate the parameter is 4 bits; when the system bandwidth is 20 MHz, the number of bits required to indicate the parameter is 4 bits; or, when the system bandwidth is 5 MHz, the number of bits required to indicate the DFPSC parameter is 2 bits. When the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate this parameter is 2bits; when the system bandwidth is 20MHz, the number of bits required to indicate the parameter is 3bits; or, the system bandwidth is 5MHz The number of bits required to indicate the DFPSC parameter is 2 bits; when the system bandwidth is 10 MHz (also 7 MHz or 8.75 MHz), the number of bits required to indicate the parameter is 2 bits; when the system bandwidth is 20 MHz, the parameter is required. The number of bits is 4 bits; or, when the system bandwidth is 5 MHz, the number of bits required to indicate the DFPSC parameter is 2 bits; when the system bandwidth is 10 MHz (also 7 MHz or 8.75 MHz), the required parameters are indicated. The number of bits is 3 bits; when the system bandwidth is 20 MHz, the number of bits required to indicate the parameter is 3 bits; or, when the system bandwidth is 5 MHz, the number of bits required to indicate the DFPSC parameter is 2 bits; the system bandwidth is 10 MHz (may also be 7 MHz) Or 8.75MHz), the number of bits required to indicate the parameter is 3bits; when the system bandwidth is 20MHz, the number of bits required to indicate the parameter is 4bits; or, when the system bandwidth is 5MHz, the number of bits required to indicate the DFPSC parameter 2bits; When the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate this parameter is 4bits; when the system bandwidth is 20MHz, the number of bits required to indicate this parameter is 4bits. It should be pointed out that in the above DFPSC configuration method, when two different bandwidths use the same number of bits to indicate DFPCS parameters, the corresponding tables may be the same or different. For example, when the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 3bits, but the corresponding table is Table 5.10; when the system bandwidth is 20MHz, the number of bits required to indicate the parameter It is 3bits, but the corresponding table is Table 5.15. For example, when the system bandwidth is 10 MHz (also 7 MHz or 8.75 MHz) and 20 MHz, and the number of bits required to indicate DPFSC is 3 bits, one of the tables at 20 MHz when 3 bits is required to indicate DFPSC can be used, for example. , are all using Table 5.15. In addition, it should be pointed out that in the above DFPSC configuration method, for each table, the relationship between the value of DFPSC and the meaning of the value indicated by DFPSC can be changed, and each table is In one embodiment, as long as the values of the DFPSCs contained in one table are the same meaning, they are all considered to be the same table and are within the scope of protection. For example, Table 5.19 and Table 5.15 are both considered to be the same table, because the values of the DFPSCs contained in the two tables are the same meaning. Table 5.19

Through the above example 5, it can be seen that when the system bandwidth is 5MHz, 10MHz (which can be 7MHz or 8.75MHz) and 20MHz system, the number of bits indicating DFPSC needs lbits, 2bits, 2bits, respectively, or 2bits, 3bits, 3bits respectively. , or when 2bits, 3bits, 4bits or other combinations are needed respectively, in the case that the possible value of the DFPCS is reduced, redundant and unnecessary information indications are deleted, the bit overhead is saved, and a certain flexibility is ensured. Example for Configuring the Upstream Frequency Subband Number (UFPSC) Example 6 FIG. 15 is a schematic diagram of the application of the resource mapping indication information in the embodiment of the present invention, when a different number of bit indication parameters are used for the 10 MHz system bandwidth, as shown in the figure. As shown in Figure 15, when the UFPSC takes different values, the uplink Frequency Partitioning process is also different. The system bandwidth is 5MHz, 7MHz, 8.75MHz, 10MHz and 20MHz as an example, and it is divided into three types of bandwidth to explain the configuration of UFPSC, the first type is 5MHz, the second type is 7MHz or 8.75MHz or 10MHz, The third category is 20MHz. The first type: When the system bandwidth is 5MHz, the number of bits required to indicate the UFPSC parameter is lbits. For 5MHz, the number of possible Subbands for UFPSC is:

A _UF psc={0,l,2} _o lbits represents the number of two different _Subbands , the number of these two different _Subbands is taken from the set A _UFPSC , and the total C ₃ ² = 3 combinations. For example, Table 6.1 to Table 6.3 are shown. Table 6.1 UFPSC FPi (i>0) corresponds to Subband number UFPSC FPi (i>0) corresponds to Subband number

0 0 1 1 Table 6.2

UFPSC FPi(i>0) corresponds to Subband number UFPSC FPi(i>0) corresponds to Subband number

0 1 1 2 Table 6.3

0 0 1 2 Or, when the system bandwidth is 5MHz, the number of bits required to indicate the UFPSC parameter is 2 bits. As shown in Table 6.4. Table 6.4

The second type: When the system bandwidth is 7MHz or 8.75MHz or 10MHz, the number of bits required to indicate the UFPSC parameter is 2bits. For 7MHz or 8.75MHz or 10MHz, the set of possible Subbands for UFPSC is: B _UFPSC = {0, 1, 2, 3, 4}. 2bits represents the number of 4 different _Subbands , the number of these 4 different _Subbands is taken from the set B _UFPSC , and a total of C ₅ ⁴ = 5 combinations. For example, Table 6.5-Table 6.9 shows. Table 6.5

Table 6.7 UFPSC FPi (i>0) corresponds to Subband number UFPSC FPi (i>0) corresponds to Subband number

0 0 2 3

1 1 3 4 Table 6.8

0 1 2 3

1 2 3 4 Table 6.9

0 0 2 3

1 2 3 4 Alternatively, when the system bandwidth is 7MHz or 8.75MHz or 10MHz, the number of bits required to indicate UFPSC parameters is 3bits. Correspondence between the value of UFPSC and the number of Subbands of its corresponding frequency partition. Example, as shown in Table 6.10. Table 6.10

The third category: When the system bandwidth is 20MHz, the number of bits required to indicate the UFPSC parameter is 2 bits. For 20MHz, the set of possible Subbands for UFPSC is: CUFPSC={0, 1,2,3,4,5,6,7,8}„ 2bits represents the number of 4 different Subbands, these 4 different The number of _Subbands is taken from the set C _UFPSC , which has a total of C ₉ ⁴ = 126 combinations. For example, Table 6.11 to Table 6.14 describe the UFPSC when the system bandwidth is 20 MHz and the number of bits required to indicate UFPSC is 2 bits. Correspondence between the value and the number of Subbands of its corresponding frequency partition, other combinations are not - enumerated. Table 6.11

1 1 3 3 Table 6.12

0 0 2 2

1 1 3 4 Table 6.13

0 0 2 4

1 2 3 6 Table 6.14

0 1 2 3

1 2 3 4 Or, when the system bandwidth is 20MHz, the number of bits required to indicate the UFPSC parameter is 3 bits. 3bits represents the number of 8 different Subbands, and the number of these 4 different Subbands is taken from the set CUFPSO total C ₉ ⁸ = 9 combinations. For example, Table 6.15 to Table 6.17 describe the correspondence between the value of UFPSC and the number of Subbands of the corresponding frequency partition when the number of bits is 3 bits, and other combinations are not-歹'. Table 6.15

Table 6.16

Table 6.17 UFPSC FPi (i>0) corresponds to Subband number UFPSC FPi (i>0) corresponds to Subband number

0 1 4 5

1 2 5 6

2 3 6 7

3 4 7 8 Or, when the system bandwidth is 20MHz, the number of bits required to indicate the UFPSC parameter is 4bits. For example, Table 6.18 describes the correspondence between the value of UFPSC and the number of Subbands of its corresponding frequency partition when the number of bits is 4 bits. Table 6.18

The number of bits required to indicate UFPSC parameters for each bandwidth can be determined from the above method, but for different bandwidths, the number of bits required to indicate UFPSC parameters is partially identical or completely different from each other. For example, when the system bandwidth is 5MHz, the number of bits required to indicate the UFPSC parameter is 1 bits; when the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 2bits; the system bandwidth is At 20 MHz, the number of bits required to indicate the parameter is 2 bits; or, when the system bandwidth is 5 MHz, the number of bits required to indicate the UFPSC parameter is 1 bits; when the system bandwidth is 10 MHz (also 7 MHz or 8.75 MHz), the indication The number of bits required for this parameter is 2 bits; when the system bandwidth is 20 MHz, the number of bits required to indicate the parameter is 3 bits; or, when the system bandwidth is 5 MHz, the number of bits required to indicate the UFPSC parameter is 1 bits; When 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 2bits; when the system bandwidth is 20MHz, the number of bits required to indicate the parameter is 4bits; or When the system bandwidth is 5MHz, the number of bits required to indicate the UFPSC parameter is 1 bits; when the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 3bits; when the system bandwidth is 20MHz, The number of bits required to indicate the parameter is 3 bits; or, when the system bandwidth is 5 MHz, the number of bits required to indicate the UFPSC parameter is 1 bits; when the system bandwidth is 10 MHz (also 7 MHz or 8.75 MHz), the parameter is indicated. The required number of bits is 3 bits; when the system bandwidth is 20 MHz, the number of bits required to indicate the parameter is 4 bits; or, when the system bandwidth is 5 MHz, the number of bits required to indicate the UFPSC parameter is 1 bits; the system bandwidth is 10 MHz (also When it is 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 4bits; when the system bandwidth is 20MHz, the number of bits required to indicate the parameter is 4bits; or, when the system bandwidth is 5MHz, the UFPSC parameter is required. The number of bits is 2 bits; when the system bandwidth is 10 MHz (also 7 MHz or 8.75 MHz), the number of bits required to indicate the parameter is 2 bits; when the system bandwidth is 20 MHz, the number of bits required to indicate the parameter is 3b. Or; when the system bandwidth is 5MHz, the number of bits required to indicate the UFPSC parameter is 2bits; when the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 2bits; the system bandwidth is At 20 MHz, the number of bits required to indicate the parameter is 4 bits; or, when the system bandwidth is 5 MHz, the number of bits required to indicate the UFPSC parameter is 2 bits; when the system bandwidth is 10 MHz (also 7 MHz or 8.75 MHz), the indication is The number of bits required for the parameter is 3 bits; when the system bandwidth is 20 MHz, the number of bits required to indicate the parameter is 3 bits; or, when the system bandwidth is 5 MHz, the number of bits required to indicate the UFPSC parameter is 2 bits; the system bandwidth is 10 MHz ( It can also be 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 3bits; when the system bandwidth is 20MHz, the number of bits required to indicate the parameter is 4bits; or, when the system bandwidth is 5MHz, the UFPSC parameter is indicated. The required number of bits is 2 bits; when the system bandwidth is 10 MHz (also 7 MHz or 8.75 MHz), the number of bits required to indicate the parameter is 4 bits; when the system bandwidth is 20 MHz, the required parameter is required. Special number 4bits. It should be noted that in the above UFPSC configuration method, when two different bandwidths use the same number of bits to indicate UFPSC parameters, the corresponding tables may be the same or different. For example, when the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate this parameter is 3bits, but the corresponding table is Table 6.10. When the system bandwidth is 20MHz, the number of bits required for the parameter is indicated. It is 3bits, but the corresponding table is Table 6.15. For example, when the system bandwidth is 10 MHz (also 7 MHz or 8.75 MHz) and 20 MHz, and the number of bits required to indicate UFPSC is 3 bits, one of the tables at 20 MHz when 3 bits are required to indicate UFPSC can be used, for example. , are all using Table 6.15. In addition, it should be pointed out that in the above UFPSC configuration method, for each table, the relationship between the value of UFPSC and the meaning of the value indicated by UFPSC can be changed, and each table is an embodiment, as long as one table The values of UFPSC included in the indications are the same meaning, and are considered to be the same table, all within the scope of protection. For example, Table 6.19 and Table 6.15 are both considered to be the same table, because the values of UFPSC contained in the two tables are the same meaning. Table 6.19

Follow this original shell|J. Through the above example 6, it can be seen that when the system bandwidth is 5MHz, 10MHz (which can be 7MHz or 8.75MHz), and the 20MHz system, the number of bits indicating the UFPSC needs lbits, 2bits, 2bits, respectively, or 2bits, 3bits, 3bits respectively. Or when 2bits, 3bits, 4bits, or other combinations are required, in the case that the possible value of the UFPSC is reduced, redundant and unnecessary information indications are deleted, the bit overhead is saved, and a certain flexibility is ensured. Example 7: Subsystem-based CRU allocation number (DCAS _SB ) configuration method

DCAS _SBi indicates the number of CRUs and/or DRUs in the i-th (i > 0) frequency partitions in Subband units. 16 is a schematic diagram of application of signaling DCASssi when a different number of bit indication parameters are used for a 10 MHz system bandwidth according to an embodiment of the present invention. As shown in FIG. 16, when DCAS _SBi takes different values, the downlink is performed. The CRU/DRU Allocation process is different. The system bandwidth is 5MHz, 7MHz, 8.75MHz, 10MHz and 20MHz as an example, and it is divided into three types of bandwidth to _explain the configuration of DCAS _SBi , the first type is 5MHz, the second type is 7MHz or 8.75MHz or 10MHz. The third category is 20MHz. The first type: When the system bandwidth is 5MHz, the number of bits required to indicate the DCAS _SBi parameter is 2bits. For 5 MHz, DCASssi indicates, in Subband, the possible number of CRUs and/or DRUs in the i-th frequency partition as: A _DCASSBi = {0, 1, 2, 3, 4, 5, 6}. 2bits represents 4 different numbers, these 4 different numbers are taken from the set A _DCASSBi , a total of C ₇ ⁴ = 35 combinations. The DCAS _SBi may be in any combination, for example, one of Tables 7.1 to 7.6, and the like, and is not listed. Table 7.1

Table 7.2

Table 7.3

Table 7.4

Table 7.5

Table 7.6

Or, when the system bandwidth is 5MHz, the number of bits required to indicate the DCAS _SBi parameter is 3 bits. 3bits represents 8 different numbers, which can represent all the values in the set AocAsssi. As shown in Table 7.7. Table 7.7

The second type: When the system bandwidth is 7MHz or 8.75MHz or 10MHz, the number of bits required to indicate the DCAS _SBi parameter is 2bits. For 7MHz or 8.75MHz or 10MHz, DCAS _SBi indicates the possible number of CRUs and/or DRUs in the i-th frequency partition in Subband: B _DCASSBi = {0, 1 , 2, 3, 4, 5 , 6, 7, 8, 9, 10, 11 , 12}. 2bits represents 4 different numbers, these 4 different numbers are taken from the set B _DCASSBi , a total of C ₁₃ ⁴ = 715 combinations. DCAS _SBi can be used in any combination. For example, one of the tables shown in Table 7.8 to Table 7.9, other similar, no longer - enumerated. Table 7.8

Table 7.9

Alternatively, when the system bandwidth is 7MHz or 8.75MHz or 10MHz, the number of bits required to indicate the DCAS _SBi parameter is 3 bits. 3bits represents 8 different numbers, these 8 different numbers are taken from the set B _DCASSBi , a total of C ₁₃ ⁸ = 1287 combinations. DCAS _SBi can be used in any combination, for example, one of Tables 7.10 to 7.13, and the like, no longer - no longer listed. Table 7.10

0 0 4 4

1 1 5 5

2 2 6 6

3 3 7 7 Table 7.11

Table 7.12

Table 7.13

Alternatively, when the system bandwidth is 7MHz or 8.75MHz or 10MHz, the number of bits required to indicate the DCAS _SBi parameter is _4bits . 4bits represents 16 different numbers, which can represent all the values in the set B _DCASSBi . For example, as shown in Table 7.14. Table 7.14

DCAS _SBl FPi (i ≥ 0) corresponds to the number of CRUs DCAS _SBl FPi (i ≥ 0) corresponds to the number of CRUs

0 0 8 8

1 1 9 9

2 2 10 10

3 3 11 11

4 4 12 12

5 5 13 Reserved 6 6 14 Reserved

7 7 15 Reserved for the third category: When the system bandwidth is 20MHz, the number of bits required to indicate the DCAS _SBi parameter is

3bits. For 20MHz, DCASssi indicates the possible number of CRU and I or DRU numbers in the i-th frequency partition in Subband: C _DCASSBi = {0,1,2,3, 4,5,6,7,8 9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24}. 3bits represents 8 different numbers, these 8 different numbers are taken from the set C _DCASSBi , a total of C ₂₅ ⁸ = 1081575 combinations. DCAS _SBi can be used in any combination. For example, one of the types shown in Table 7.15 to Table 7.21, other similar, is not listed. Table 7.15

Table 7.16

Table 7.17

Table 7.18

1 2 5 10

2 4 6 12

3 6 7 14 Table 7.18

Table 7.19

Table 7.20

Table 7.21

Alternatively, when the system bandwidth is 20 MHz, the number of bits required to indicate the DCAS _SBi parameter is 4 bits. 4bits represents 16 different numbers, these 16 different numbers are taken from the set C _DCASSBi , a total of C ₂₅ ¹⁶ = 2042975 combinations. DCAS _SBi can be used in any combination. For example, one of the tables shown in Table 7.22 to Table 7.25, other similar, no longer - enumerated. Table 7.22 DCAS _SBl FPi (i>0) corresponds to CRU number DCAS _SBl FPi (i>0) corresponds to CRU number

0 0 8 10

1 1 9 12

2 2 10 14

3 3 11 16

4 4 12 18

5 5 13 20

6 6 14 22

7 8 15 24 Table 7.23

Table 7.24

Table 7.25

3 4 11 16

4 5 12 18

5 6 13 20

6 7 14 22

7 8 15 24 Alternatively, when the system bandwidth is 20MHz, the number of bits required to indicate the DCAS _SBi parameter is 5 bits. 5bits represents 32 different numbers, and these 32 different numbers can represent all the values in the set C _DCASSBi . For example, as shown in Table 7.26. Table 7.26

The number of bits required to indicate the DCAS _SBi parameter for each bandwidth can be determined from the above method, but for different bandwidths, the number of bits required to indicate the DCAS _SBi parameter is partially identical or completely different from each other. For example, when the system bandwidth is 5MHz, the number of bits required to indicate the DCAS _SBi parameter is 2bits; when the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 2bits; the system bandwidth is At 20 MHz, the number of bits required to indicate this parameter is 3 bits; or When the system bandwidth is 5MHz, the number of bits required to indicate the DCAS _SBi parameter is 2bits; when the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 2bits; when the system bandwidth is 20MHz, The number of bits required to indicate the parameter is 4 bits; or, when the system bandwidth is 5 MHz, the number of bits required to indicate the DCAS _SBi parameter is 2 bits; when the system bandwidth is 10 MHz (also 7 MHz or 8.75 MHz), the parameter is indicated. The required number of bits is 3 bits; when the system bandwidth is 20 MHz, the number of bits required to indicate the parameter is 3 bits; or, when the system bandwidth is 5 MHz, the number of bits required to indicate the DCAS _SBi parameter is 2 bits; the system bandwidth is 10 MHz (also When it is 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 3bits; when the system bandwidth is 20MHz, the number of bits required to indicate the parameter is 4bits; or, when the system bandwidth is 5MHz, the DCAS _SBi parameter is indicated. The required number of bits is 2 bits; when the system bandwidth is 10 MHz (also 7 MHz or 8.75 MHz), the number of bits required to indicate the parameter is 3 bits; when the system bandwidth is 20 MHz, the number of bits required to indicate the parameter is 5 Or; when the system bandwidth is 5MHz, the number of bits required to indicate the DCAS _SBi parameter is _3bits ; when the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 3bits; System bandwidth When the frequency is 20MHz, the number of bits required to indicate the parameter is 4bits; or, when the system bandwidth is 5MHz, the number of bits required to indicate the DCAS _SBi parameter is _3bits ; when the system bandwidth is 10MHz (also 7MHz or 8.75MHz), The number of bits required to indicate the parameter is 4 bits; when the system bandwidth is 20 MHz, the number of bits required to indicate the parameter is 4 bits; or, when the system bandwidth is 5 MHz, the number of bits required to indicate the DCAS _SBi parameter is 3 bits; When it is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate this parameter is 4bits; when the system bandwidth is 20MHz, the number of bits required to indicate this parameter is 5bits. It should be noted that in the above configuration method of DCAS _SBi , when two different bandwidths use the same number of bits to indicate the DCAS _SBi parameter, the corresponding tables may be the same or different. For example, when the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate this parameter is 4bits, but the corresponding table is Table 7.14; when the system bandwidth is 20MHz, the number of bits required to indicate the parameter It is 4bits, but the corresponding table is Table 7.23. The same table means: Since the system bandwidth is 10MHz (can be 7MHz or 8.75MHz) and the system bandwidth is 20MHz, it can be considered similarly ^ ¹ 10MHz (can be 7MHz or 8.75MHz) and 20MHz features can be unified ^) Capture system bandwidth is 10MHz (can be 7MHz Or 8.75MHz) and the system bandwidth is 20MHz, the same DCAS _SBi value and corresponding relationship, that is, the system bandwidth is 10MHz (can be 7MHz or 8.75MHz) and the system bandwidth is 20MHz, the same table, for example, Use one of Table 7.22 to Table 7.25, or follow the configuration method at 20MHz. Alternatively, generate it as follows: Table 7.27

Jt匕, 5MHz can be 7MHz or 8.75MHz with 10MHz) Both use 2 bits or 3 bits. In addition, it should be pointed out that in the above configuration method of DCAS _SBi , for each table, the relationship between the value of _DCASsBi and the meaning indicated by the value of DCAS _SBi can be changed, and each table is an embodiment, as long as one table The values of DCAS _SBi contained in the indications are the same meaning and are considered to be the same table, 啫P is within the scope of protection. Through the above example 7, it can be seen that when the system bandwidth is 5MHz, 10MHz (which can be 7MHz or 8.75MHz), and the 20MHz system, the number of bits indicating the DCAS _SBi needs 2bits, _{3bits, 3bits} , or 2bits, 3bits, respectively. 4bits, or 3bits, 4bits, 4bits, or 3bits, 4bits, 5bits or other combinations, respectively, possible in DCAS _SBi In the case of reduced value, redundant and unnecessary information indications are deleted, bit overhead is saved, and certain flexibility is ensured. Example 8: Method for configuring the uplink sub-based CRU allocation number (UCAS _SB )

UCAS _SBi indicates the number of CRUs and/or DRUs in the i-th (i > 0) frequency partitions in Subband units. 17 is a schematic diagram of application of signaling UCAS _SBi when a method for configuring resource mapping indication information uses different numbers of bit indication parameters for a 10 MHz system bandwidth according to an embodiment of the present invention. As shown in FIG. 17, when UCAS _SBi takes different values, The upstream CRU/DRU Allocation process is different. The system bandwidth is 5MHz, 7MHz, 8.75MHz, 10MHz and 20MHz as an example, and it is divided into three types of bandwidth to _explain the configuration of UCAS _SBi , the first type is 5MHz, the second type is 7MHz or 8.75MHz or 10MHz. The third category is 20MHz. The first type: When the system bandwidth is 5MHz, the number of bits required to indicate the UCAS _SBi parameter is 2 bits. For 5 MHz, UCASssi indicates, in Subband, the possible number of CRUs and/or DRUs in the i-th frequency partition as: A _UCASSBi = {0,1,2,3,4,5,6}. 2bits represents 4 different numbers, these 4 different numbers are taken from the set A _UCASSBi , a total of C ₇ ⁴ = 35 combinations. UCAS _SBi may be in any combination, for example, one of Table 8.1 to Table 8.6, and the like, which are not listed. Table 8.1

Table 8.2

Table 8.3

UCASsBi FPi(i>0) corresponds to the number of CRUs UCASsBi FPi(i≥0) corresponds to the number of CRUs

0 0 2 3 1 2 3 4 Table 8.4

Table 8.5

Table 8.6

Or, when the system bandwidth is 5MHz, the number of bits required to indicate the UCAS _SBi parameter is 3 bits. 3bits represents 8 different numbers, which can represent all the values in the set A _UCASSBi . As shown in Table 8.7. Table 8.7

The second type: When the system bandwidth is 7MHz or 8.75MHz or 10MHz, the number of bits required to indicate the UCAS _SBi parameter is 2bits. For 7MHz or 8.75MHz or 10MHz, UCAS _SBi indicates the possible number of CRUs and/or DRUs in the i-th frequency partition in Subband: B _UCASSBi = {0, 1 , 2, 3, 4, 5 , 6, 7, 8, 9, 10, 11 , 12}. 2bits represents 4 different numbers, these 4 different numbers are taken from the set B _UCASSBi , a total of C ₁₃ ⁴ = 715 combinations. UCAS _Sbi can be used in any combination. For example, one of the tables shown in Table 8.8 to Table 8.9, other similar, no longer - enumerated. Table 8.8 UCAS _SBl FPi (i> 0) corresponding to the number of CRU UCAS _SBl FPi (i≥0) corresponding to the number of CRU

0 0 2 2

1 1 3 4 Table 8.9

Or, when the system bandwidth is 7MHz or 8.75MHz or 10MHz, the number of bits required to indicate the UCAS _SBi parameter is _3bits . 3bits represents 8 different numbers, these 8 different numbers are taken from the set B _UCASSBi , a total of C ₁₃ ⁸ = 1287 combinations. UCAS _SBi can be used in any combination, for example, one of Tables 8.10 to 8.13, and the like, no longer - no longer listed. Table 8.10

Table 8.11

Table 8.12

Table 8.13

UCASsBi FPi (i ≥ 0) corresponds to the number of CRUs UCASsBi FPi (i ≥ 0) corresponds to the number of CRUs

0 0 4 4 1 1 5 6

2 2 6 8

3 3 7 12 Alternatively, when the system bandwidth is 7MHz or 8.75MHz or 10MHz, the number of bits required to indicate the UCAS _SBi parameter is _4bits . 4bits represents 16 different numbers, which can represent all the values in the set B _UCASSBi . For example, as shown in Table 8.14. Table 8.14

The third category: When the system bandwidth is 20MHz, the number of bits required to indicate the UCAS _SBi parameter is

3bits. For 20MHz, the UCAS _SBi indicates the possible number of CRUs and I or DRUs in the i-th frequency partition in units of Subband: C _UCASSBi = {0,1,2,3, 4,5,6,7, 8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24}. 3bits represents 8 different numbers, these 8 different numbers are taken from the set C _UCASSBi , a total of C ₂₅ ⁸ = 1081575 combinations.

UCAS _SBi can be used in any combination. For example, one of Table 8.15 to Table 8.21, other similar, is not listed. Table 8.15

Table 8.16 UCAS _SBl FPi (i>0) corresponds to the CRU number UCAS _SBl FPi (i>0) corresponds to the number of CRUs

0 0 4 4

1 1 5 6

2 2 6 8

3 3 7 10 Table 8.17

Table 8.18

Table 8.18

Table 8.19

Table 8.20

UCAS _SBl FPi (i>0) corresponds to the CRU number UCAS _SBl FPi (i>0) corresponds to the number of CRUs

0 1 4 5

1 2 5 6 2 3 6 7

3 4 7 8 Table 8.21

Alternatively, when the system bandwidth is 20 MHz, the number of bits required to indicate the UCAS _SBi parameter is 4 bits. 4bits represents 16 different numbers, these 16 different numbers are taken from the set C _UCASSBi , a total of C ₂₅ ¹⁶ = 2042975 combinations. UCAS _SBi can be used in any combination. For example, one of Table 8.22 to Table 8.25, other similar, no longer - enumerated. Table 8.22

Table 8.23

Table 8.24 UCAS _SBl FPi (i>0) corresponds to the CRU number UCAS _SBl FPi (i>0) corresponds to the number of CRUs

0 1 8 9

1 2 9 10

2 3 10 11

3 4 11 12

4 5 12 13

5 6 13 14

6 7 14 15

7 8 15 16 Table 8.25

Alternatively, when the system bandwidth is 20 MHz, the number of bits required to indicate the UCAS _SBi parameter is 5 bits. 5bits represents 32 different numbers, and these 32 different numbers can represent all the values in the set C _UCASSBi . For example, as shown in Table 8.26. Table 8.26

10 11 26 Reserved

11 12 27 Reserved

12 13 28 Reserved

13 14 29 Reserved

14 15 30 Reserved

15 16 31 The number of bits required to indicate the UCAS _SBi parameter for each bandwidth can be determined from the above method, but for different bandwidths, the number of bits required to indicate the UCAS _SBi parameter is partially identical or completely different from each other. For example, when the system bandwidth is 5MHz, the number of bits required to indicate the UCAS _SBi parameter is 2bits; when the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 2bits; the system bandwidth is At 20 MHz, the number of bits required to indicate this parameter is 3 bits; or, when the system bandwidth is 5 MHz, the number of bits required to indicate the UCAS _SBi parameter is 2 bits; when the system bandwidth is 10 MHz (also 7 MHz or 8.75 MHz), the indication The number of bits required for this parameter is 2 bits; when the system bandwidth is 20 MHz, the number of bits required to indicate the parameter is 4 bits; or, when the system bandwidth is 5 MHz, the number of bits required to indicate the UCAS _SBi parameter is 2 bits; When 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 2bits; when the system bandwidth is 20MHz, the number of bits required to indicate the parameter is 5bits; or, when the system bandwidth is 5MHz, the UCAS is indicated. _The number of bits required for the _SBi parameter is 2 bits; when the system bandwidth is 10 MHz (also 7 MHz or 8.75 MHz), the number of bits required to indicate the parameter is 3 bits; when the system bandwidth is 20 MHz, the ratio required for the parameter is indicated. The special number is 3 bits; or, when the system bandwidth is 5 MHz, the number of bits required to indicate the UCAS _SBi parameter is 2 bits; when the system bandwidth is 10 MHz (also 7 MHz or 8.75 MHz), the number of bits required to indicate the parameter is 3 bits. When the system bandwidth is 20MHz, the number of bits required to indicate the parameter is 4bits; or, when the system bandwidth is 5MHz, the number of bits required to indicate the UCAS _SBi parameter is 2bits; the system bandwidth is 10MHz (also 7MHz or 8.75MHz) When the system bandwidth is 20MHz, the number of bits required to indicate the parameter is 5bits; or, when the system bandwidth is 5MHz, the number of bits required to indicate the UCAS _SBi parameter is 3bits. When the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate this parameter 3bits; when the system bandwidth is 20MHz, the number of bits required to indicate the parameter is 4bits; or, when the system bandwidth is 5MHz, the number of bits required to indicate the UCAS _SBi parameter is _3bits ; the system bandwidth is 10MHz (it can also be 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 3bits; when the system bandwidth is 20MHz, the number of bits required to indicate the parameter is 5bits; or, when the system bandwidth is 5MHz, the number of bits required to indicate the UCAS _SBi parameter 3bits; when the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 4bits; when the system bandwidth is 20MHz, the number of bits required to indicate the parameter is 4bits; or, the system bandwidth When the _frequency is 5MHz, the number of bits required to indicate the UCAS _SBi parameter is _3bits ; when the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 4bits; when the system bandwidth is 20MHz, the indication is The number of bits required for the parameter is 5 bits. It should be noted that in the above UCAS _SBi configuration method, when two different bandwidths use the same number of bits to indicate the UCAS _SBi parameter, the corresponding tables may be the same or different. For example, when the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 4bits, but the corresponding table is Table 8.14; when the system bandwidth is 20MHz, the number of bits required for the parameter is indicated. It is 4bits, but the corresponding table is Table 8.23. The same table means: Since the system bandwidth is 10MHz (can be 7MHz or 8.75MHz) and the system bandwidth is 20MHz, it can be considered similarly ^ ¹ 10MHz (can be 7MHz or 8.75MHz) and 20MHz features can be unified ^) The system bandwidth is 10MHz (which can be 7MHz or 8.75MHz) and the system bandwidth is 20MHz. The same UCAS _SBi value and corresponding relationship are used, that is, the system bandwidth is 1 OMHz (can be 7MHz or 8.75MHz) and the system bandwidth is The same table is used at 20 MHz. For example, one of Table 8.22 to Table 8.25 can be used, or it can be generated according to the configuration method at 20 MHz. Alternatively, generate as follows: Table 8.27

PRU total 10MHz (can be 7MHz or 20MHzFPi (i>0)

UCAS

Number of copies 8.75MHz ) FPi (i ≥ 0) corresponds to CRU number CRU number

0 0/48 0 0

1 1/48 1 2

2 2/48 2 4

3 3/48 3 6

4 4/48 4 8

5 5/48 5 10 6 6/48 6 12

7 7/48 7 14

8 8/48 8 16

9 9/48 9 18

10 10/48 10 20

11 11/48 11 22

12 12/48 12 24

13 13/48 13 26

14 14/48 14 28

15 15/48 15 30 jt匕, 5MHz can be used with 10MHz (A can be 7MHz or 8.75MHz) with 2 bits or 3 bits. Further, to be noted: In the configuration above UCAS _SBI's, for each table, the relationship between the intermediate significance indicated by the value UCAS _SBI value and UCAS _SBI can vary, each form are one embodiment, as long as a The values of the UCAS _SBI contained in the table are the same meanings, and are considered to be the same table, 啫P is within the scope of protection. Through the above example 8, it can be seen that when the system bandwidth is 5MHz, 10MHz (which can be 7MHz or 8.75MHz), and the 20MHz system, the number of bits indicating the UCAS _SBI needs 2bits, 3bits, 3bits, respectively, or 2bits and 3bits respectively. 4bits, or 3bits, 4bits, 4bits, or 3bits, 4bits, 5bits, or other combinations respectively. When the possible value of the UCAS _SBI is reduced, redundant and unnecessary information indications are deleted, saving The bit overhead is guaranteed and a certain degree of flexibility is guaranteed. Downlink MiniC-based CRU Allocation Number (DCASMB) Configuration Method Example 9 DCASMB indicates Miniband-based frequency band based on Miniband in Miniband

The number of CRUs. 18 is a schematic diagram of application of signaling DCAS _MB when a different number of bit indication parameters are used for a 5 MHz system bandwidth according to an embodiment of the present invention. As shown in FIG. 18, when DCAS _MB takes different values, The downstream CRU/DRU Allocation process is different. The system bandwidth is 5MHz, 7MHz, 8.75MHz, 10MHz and 20MHz as an example, and it is divided into three types of bandwidth to explain the configuration of DCAS _MB . The first type is 5MHz. The second type is 7MHz or 8.75MHz or 10MHz, and the third type is 20MHz. The first type: The number of bits required to indicate the DCAS _MB parameter is 2 bits. For 5 MHz, the DCAS _MB indicates, in Miniband, the possible number of sets of Miniband-based CRUs in the 0th frequency partition as: A _DCASMB = {0 to 24 all integers on the closed interval}. 2bits represents 4 different numbers, these 4 different numbers are taken from the set A _DCASMB , a total of C ₂₅ ⁴ = 12650 combinations. The DCAS _MB can be any combination, for example, one of the tables shown in Table 9.1 to Table 9.3, and the like, no longer - enumerated. Table 9.1

Table 9.2

Table 9.3

Or, when the system bandwidth is 5MHz, the number of bits required to indicate the DCAS _MB parameter is 3 bits. 3bits represents 8 different numbers, these 8 different numbers are taken from the set A _DCASMB , a total of C ₂₅ ⁸ = 1081575 combinations. The DCAS _MB can be any combination, for example, one of Table 9.4 to Table 9.11, and the like, no longer - enumerated. Table 9.4

FP ₀ based on Miniband FP ₀ based on Miniband

DCASMB DCASMB

Number of CRUs for the number of CRUs 0 0 4 4

1 1 5 5

2 2 6 6

3 3 7 7 Table 9.5

Table 9.6

Table 9.7

Table 9.8

Table 9.9 FPo based on Miniband based on Miniband FPo

DCASMB DCASMB

Number of CRUs Number of CRUs

0 0 4 8

1 2 5 10

2 4 6 12

3 6 7 24 Table 9.10

Table 9.11

Or, when the system bandwidth is 5MHz, the number of bits required to indicate the DCAS _MB parameter is 4bits. 4bits represents 16 different numbers, these 16 different numbers are taken from the set A _DCASMB , a total of C ₂₅ ¹⁶ = 2042975 combinations. The DCAS _MB can be any combination, for example, one of the types shown in Table 9.12 to Table 9.15, other similar, no longer - enumerated. Table 9.12

6 6 14 22

7 8 15 24 Table 9.13

Table 9.14

Table 9.15

7 8 15 24 Alternatively, when the system bandwidth is 5MHz, the number of bits required to indicate the DCAS _MB parameter is 5 bits. 5bits represents 32 different numbers, and these 32 different numbers can represent all the values in the set ADCASMB. For example, Table 9.16 shows. Table 9.16

The second type: When the system bandwidth is 7MHz or 8.75MHz or 10MHz, the number of bits required to indicate the DCAS _MB parameter is 4bits. For 7 MHz or 8.75 MHz or 10 MHz, the DCASMB indicates, in Miniband, the possible number of sets of Miniband-based CRUs in the 0th frequency partition as: B _DCASMB = {0 to 48 for all integers on the closed interval}. 4bits represents 16 different numbers, these 16 different numbers are taken from the set B _DCASMB , a total of C ₄₉ ¹⁶ = 3348108992991 combinations. The DCAS _MB can be any combination, for example, one of the types shown in Table 9.17 to Table 9.20, and the like, no longer - 歹 '". Table 9.17 FPo based on Miniband based on Miniband FPo

DCASMB DCASMB

Number of CRUs Number of CRUs

0 0 8 8

1 1 9 9

2 2 10 10

3 3 11 11

4 4 12 12

5 5 13 13

6 6 14 14

7 7 15 15 Table 9.18

Table 9.19

Table 9.20

Number of CRUs for the number of CRUs

0 0 8 20

1 1 9 24

2 2 10 28

3 3 11 32

4 4 12 36

5 8 13 40

6 12 14 44

7 16 15 48 Alternatively, when the system bandwidth is 7MHz or 8.75MHz or 10MHz, the number of bits required to indicate the DCAS _MB parameter is 5bits. 5bits represents 32 different numbers, these 32 different numbers are taken from the set B _DCASMB , a total of C ₄₉ ³² = 6499270398159 combinations. The DCAS _MB can be any combination, for example, one of the types shown in Table 9.21, and the like, which are not listed. Table 9.21

Or, when the system bandwidth is 7MHz or 8.75MHz or 10MHz, the number of bits required to indicate the DCAS _MB parameter is 6bits. 6bits means 64 different numbers, which can represent the set B _DCASMB All the values in it. For example, as shown in Table 9.22. Table 9.22

30 30 62 Reserved

31 31 63 Reserved for the third category: For 20MHz, the number of bits required to indicate the DCAS _MB parameter is 4bits.

The DCASMB indicates, in Minpots, the possible number of sets of Miniband-based CRUs in the 0th frequency partition as: C _DCASMB = {0 to 96 all integers on the closed interval}. 4bits represents 16 different numbers, these 16 different numbers are taken from the set B _DCASMB , a total of C ₉₇ ¹⁶ = 793067310934425856 combinations. The DCAS _MB can be any combination, for example, one of the types shown in Table 9.17 to Table 9.20, other similar, no longer - enumerated. Alternatively, when the system bandwidth is 20 MHz, the number of bits required to indicate the DCAS _MB parameter is 5 bits. 5bits represents 32 different numbers, and these 32 different numbers are taken from the set C _DCASMB , a total of C ₉₇ ³² combinations. DCAS _MB can be any combination. For example, one of the tables shown in Table 9.23 to Table 9.25, other similar, no longer - enumerated. Table 9.23

Table 9.24 FPo based on Miniband based on Miniband FPo

DCASMB DCASMB

Number of CRUs Number of CRUs

0 0 16 16

1 1 17 18

2 2 18 20

3 3 19 22

4 4 20 24

5 5 21 26

6 6 22 28

7 7 23 30

8 8 24 32

9 9 25 34

10 10 26 36

11 11 27 38

12 12 28 40

13 13 29 42

14 14 30 46

15 15 31 48 9.25

15 16 31 64 Alternatively, when the system bandwidth is 20MHz, the number of bits required to indicate the DCAS _MB parameter is 6 bits. 6bits represents 64 different numbers, and these 64 different numbers can represent all the values in the set CDCASMB. For example, Table 9.26 shows. Table 9.26

28 28 60 60

29 29 61 61

30 30 62 62

31 31 63 63 Alternatively, when the system bandwidth is 20MHz, the number of bits required to indicate the DCAS _MB parameter is 7bits. 7bits represents 128 different numbers, and these 128 different numbers can represent all values in the set C _DCASMB except 0 or 1 or 95 or 96. The number of bits required to indicate the DCAS _MB parameters for each bandwidth can be determined from the above method, but for different bandwidths, the number of bits required to indicate the DCAS _MB parameters is partially identical or completely different from each other. For example, when the system bandwidth is 5MHz, the number of bits required to indicate the DCAS _MB parameter is 2bits; when the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 4bits; the system bandwidth is At 20MHz, the number of bits required to indicate this parameter is 4bits; or, when the system bandwidth is 5MHz, the number of bits required to indicate the DCAS _MB parameter is 3bits; when the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the indication The number of bits required for this parameter is 4 bits; when the system bandwidth is 20 MHz, the number of bits required to indicate the parameter is 4 bits; or, when the system bandwidth is 5 MHz, the number of bits required to indicate the DCAS _MB parameter is 3 bits; When 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate this parameter is 4bits; when the system bandwidth is 20MHz, the number of bits required to indicate the parameter is 5bits; or, when the system bandwidth is 5MHz, DCAS is indicated. number of bits required for the _MB parameters 3bits; when the system bandwidth is 10MHz (may be a 7MHz or 8.75MHz), indicating the number of bits required parameters 5bits; system bandwidth is 20MHz, required for the parameter bit indicates Is 5bits; Alternatively, when the system bandwidth is 5MHz, indicating the number of bits required DCAS _MB parameters 4bits; when the system bandwidth is 10MHz (or may be a 7MHz of 8.75 MHz), indicating the number of bits required parameters 4bits; system When the bandwidth is 20MHz, the number of bits required to indicate the parameter is 5bits; or, when the system bandwidth is 5MHz, the number of bits required to indicate the DCAS _MB parameter is 4bits; when the system bandwidth is 10MHz (also 7MHz or 8.75MHz) , the number of bits required to indicate the parameter is 5 bits; when the system bandwidth is 20 MHz, the number of bits required to indicate the parameter is 5 bits; or, when the system bandwidth is 5 MHz, the number of bits required to indicate the DCAS _MB parameter is 4 bits; When the bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 5bits; when the system bandwidth is 20MHz, the number of bits required to indicate the parameter is 6bits; or, when the system bandwidth is 5MHz, The number of bits required to indicate the DCAS _MB parameter is 5 bits; when the system bandwidth is 10 MHz (also 7 MHz or 8.75 MHz), the number of bits required to indicate the parameter is 6 bits; when the system bandwidth is 20 MHz, the required parameter is indicated. The number of bits is 6 bits; or, when the system bandwidth is 5 MHz, the number of bits required to indicate the DCAS _MB parameter is 5 bits; when the system bandwidth is 10 MHz (also 7 MHz or 8.75 MHz), the number of bits required to indicate the parameter is 6 bits. When the system bandwidth is 20MHz, the number of bits required to indicate this parameter is 7bits. It should be noted that in the above configuration method of DCAS _MB , when two different bandwidths use the same number of bits to indicate DCAS _MB parameters, the corresponding tables may be the same or different. For example, when the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 5bits, but the corresponding table is Table 9.21; when the system bandwidth is 20MHz, the number of bits required for the parameter is indicated. It is 5bits, but the corresponding table is Table 9.25. The same table means: Since the system bandwidth is 10MHz (can be 7MHz or 8.75MHz) and the system bandwidth is 20MHz, it can be considered similarly ^ ¹ 10MHz (can be 7MHz or 8.75MHz) and 20MHz features can be unified ^) The system bandwidth is 10MHz (can be 7MHz or 8.75MHz) and the system bandwidth is 20MHz. The same DCAS _MB value and corresponding relationship are used, that is, the system bandwidth is 10MHz (can be 7MHz or 8.75MHz) and the system bandwidth is 20MHz. The same table is used, for example, one of Table 9.23 to Table 9.25 can be used, or it can be generated according to the configuration method at 20 MHz. Alternatively, generate it as follows: Table 9.27

10MHz (can be 7MHz or 20MHz FP ₀ based on the total PRU

DCASMB 8.75MHz) FP. The number of copies of the CRU based on the Miniband Miniband

Number of CRUs

0 0/48 0 0

1 1/48 1 2

2 2/48 2 4

3 3/48 3 6

4 4/48 4 8

5 5/48 5 10

6 6/48 6 12

7 7/48 7 14 8 8/48 8 16

9 9/48 9 18

10 10/48 10 20

11 11/48 11 22

12 12/48 12 24

13 13/48 13 26

14 14/48 14 28

15 15/48 15 30 jt匕, 5MHz can be 3 bits or 4 bits or 5 bits with 10MHz (A can be 7MHz or 8.75MHz). Further, to be noted: In the DCAS _MB configuration process, for each table, the relationship between the intermediate meaning DCAS _MB value with the DCAS _MB values indicated may be varied, each form are one embodiment, as long as a The values of the DCAS _MB included in the table are the same meanings, and are considered to be the same table, all within the scope of protection. Through the above example 9, it can be seen that when the system bandwidth is 5MHz, 10MHz (which can be 7MHz or 8.75MHz), and the 20MHz system, the number of bits indicating the DCAS _MB needs 3bits, 4bits, 4bits, or 3bits, 4bits, respectively. 5bits, or 4bits, 5bits, 6bits, or 5bits, 6bits, 7bits or other combinations respectively, when the possible value of DCAS _MB is reduced, the redundant and unnecessary information indications are deleted, saving Bit overhead, and guarantees a certain flexibility. Example of configuring the uplink mini-based CRU allocation number (UCASMB) Example 10 UCASMB indicates the Miniband-based frequency band in the 0th frequency partition in Miniband

The number of CRUs. FIG. 19 is a schematic diagram of application of signaling UCAS _MB when a method for configuring resource mapping indication information uses a different number of bit indication parameters for a 5 MHz system bandwidth according to an embodiment of the present invention. As shown in FIG. 19, when UCAS _MB takes different values, The uplink CRU/DRU Allocation process is different. The system bandwidth is 5MHz, 7MHz, 8.75MHz, 10MHz and 20MHz as an example, and it is divided into three types of bandwidth to explain the configuration of UCAS _MB . The first type is 5MHz, and the second type is 7MHz or 8.75MHz or 10MHz. The third category is 20MHz. The first type: The number of bits required to indicate the UCAS _MB parameter is 2 bits. For 5 MHz, the UCAS _MB indicates, in Minpots, the possible number of sets of Miniband-based CRUs in the 0th frequency partition as: A _UCASMB = {0 to 24 all integers on the closed interval}. 2bits represents 4 different numbers, these 4 different numbers are taken from the set AUCASMB, a total of C ₂₅ ⁴ = 12650 combinations. UCAS _MB can be any combination, for example, one of the tables shown in Table 10.1 to Table 10.3, other similar, no longer - enumerated. Table 10.1

Table 10.2

Table 10.3

Or, when the system bandwidth is 5MHz, the number of bits required to indicate the UCAS _MB parameter is 3 bits. 3bits represents 8 different numbers, these 8 different numbers are taken from the set A _UCASMB , a total of C ₂₅ ⁸ = 108 1575 combinations. UCAS _MB can be any combination, for example, one of Table 10.4 to Table 10.1 1 , other similar, no longer - enumerated. Table 10.4

1 1 5 5

2 2 6 6

3 3 7 7 Table 10.5

Table 10.6

Table 10.7

Table 10.8

Table 10.9 FPo based on Miniband based on Miniband FPo

UCASMB UCASMB

Number of CRUs Number of CRUs

0 0 4 8

1 2 5 10

2 4 6 12

3 6 7 24 Table 10.10

Table 10.11

Or, when the system bandwidth is 5MHz, the number of bits required to indicate the UCAS _MB parameter is 4bits. 4bits represents 16 different numbers, these 16 different numbers are taken from the set A _UCASMB , a total of C ₂₅ ¹⁶ = 2042975 combinations. UCAS _MB can be any combination, for example, one of the tables shown in Table 10.12 to Table 10.15, other similar, no longer - enumerated. Table 10.12

6 6 14 22

7 8 15 24 Table 10.13

Table 10.14

Table 10.15

7 8 15 24 Alternatively, when the system bandwidth is 5MHz, the number of bits required to indicate the UCAS _MB parameter is 5 bits. 5 bits represents 32 different numbers, and these 32 different numbers can represent all the values in the set AUCASMB. For example, Table 10.16 shows. Table 10.16

The second type: When the system bandwidth is 7MHz or 8.75MHz or 10MHz, the number of bits required to indicate the UCAS _MB parameter is 4bits. For 7 MHz or 8.75 MHz or 10 MHz, UCASMB indicates, in Miniband, the possible number of sets of Miniband-based CRUs in the 0th frequency partition as: B _UCASMB = {0 to 48 for all integers on the closed interval}. 4bits represents 16 different numbers, these 16 different numbers are taken from the set B _UCASMB , a total of C ₄₉ ¹⁶ = 3348108992991 combinations. UCAS _MB can be used in any combination, for example, one of Tables 10.17 to 10.20, and the like, and is not listed. Table 10.17 FPo based on Miniband based on Miniband FPo

UCASMB UCASMB

Number of CRUs Number of CRUs

0 0 8 8

1 1 9 9

2 2 10 10

3 3 11 11

4 4 12 12

5 5 13 13

6 6 14 14

7 7 15 15 Table 10.18

Table 10.19

Table 10.20

Number of CRUs for the number of CRUs

0 0 8 20

1 1 9 24

2 2 10 28

3 3 11 32

4 4 12 36

5 8 13 40

6 12 14 44

7 16 15 48 Alternatively, when the system bandwidth is 7MHz or 8.75MHz or 10MHz, the number of bits required to indicate the UCAS _MB parameter is 5bits. 5bits represents 32 different numbers, these 32 different numbers are taken from the set B _UCASMB , a total of C ₄₉ ³² = 6499270398159 combinations. UCAS _MB can be used in any combination, for example, one of the tables shown in Table 10.21, and the like, which are not listed. Table 10.21

Or, when the system bandwidth is 7MHz or 8.75MHz or 10MHz, the number of bits required to indicate the UCAS _MB parameter is 6bits. 6bits means 64 different numbers, which can represent the set B _UCASMB All the values in it. For example, as shown in Table 10.22. Table 10.22

30 30 62 Reserved

31 31 63 Reserved for the third category: For 20MHz, the number of bits required to indicate the UCAS _MB parameter is 4 bits.

The UCASMB indicates, in Minpots, the possible number of sets of Miniband-based CRUs in the 0th frequency partition as: C _UCASMB = {0 to 96 all integers on the closed interval}. 4bits represents 16 different numbers, these 16 different numbers are taken from the set B _UCASMB , a total of C ₉₇ ¹⁶ = 793067310934425856 combinations. UCAS _MB can be any combination, for example, one of the tables shown in Table 10.17 to Table 10.20, other similar, no longer - enumerated. Or, when the system bandwidth is 20MHz, the number of bits required to indicate the UCAS _MB parameter is 5 bits. 5bits represents 32 different numbers, and these 32 different numbers are taken from the set C _UCASMB , a total of C ₉₇ ³² combinations. UCAS _MB can be any combination. For example, one of the tables shown in Table 10.23 to Table 10.25, other similar, is not listed. Table 10.23

FPo based on Miniband FPo based on Miniband

UCASMB UCASMB

Number of CRUs Number of CRUs

0 0 16 16

1 1 17 17

2 2 18 18

3 3 19 19

4 4 20 20

5 5 21 21

6 6 22 22

7 7 23 23

8 8 24 24

9 9 25 25

10 10 26 26

11 11 27 27

12 12 28 28

13 13 29 29

14 14 30 30

15 15 31 31 10.24

UCASMB FPo based on Miniband UCASMB FPo based on Miniband Number of CRUs for the number of CRUs

0 0 16 16

1 1 17 18

2 2 18 20

3 3 19 22

4 4 20 24

5 5 21 26

6 6 22 28

7 7 23 30

8 8 24 32

9 9 25 34

10 10 26 36

11 11 27 38

12 12 28 40

13 13 29 42

14 14 30 46

15 15 31 48 10.25

Or, when the system bandwidth is 20 MHz, the number of bits required to indicate the UCAS _MB parameter is 6 bits. 6bits represents 64 different numbers, and these 64 different numbers can represent all the values in the set CUCASMB. For example, Table 10.26. Table 10.26

30 30 62 62

31 31 63 63 Alternatively, when the system bandwidth is 20MHz, the number of bits required to indicate the UCAS _MB parameter is 7bits. 7bits represents 128 different numbers, and these 128 different numbers can represent all values in the set C _UCASMB except 0 or 1 or 95 or 96. The number of bits required to indicate the UCAS _MB parameters for each bandwidth can be determined from the above method, but for different bandwidths, the number of bits required to indicate the UCAS _MB parameters is partially identical or completely different from each other. For example, when the system bandwidth is 5MHz, the number of bits required to indicate the UCAS _MB parameter is 2bits; when the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 4bits; the system bandwidth is At 20MHz, the number of bits required to indicate this parameter is 4bits; or, when the system bandwidth is 5MHz, the number of bits required to indicate the UCAS _MB parameter is 3bits; when the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the indication The number of bits required for this parameter is 4 bits; when the system bandwidth is 20 MHz, the number of bits required to indicate the parameter is 4 bits; or, when the system bandwidth is 5 MHz, the number of bits required to indicate the UCAS _MB parameter is 3 bits; When 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 4bits; when the system bandwidth is 20MHz, the number of bits required to indicate the parameter is 5bits; or, when the system bandwidth is 5MHz, the UCAS is indicated. number of bits required for the _MB parameters 3bits; when the system bandwidth is 10MHz (may be a 7MHz or 8.75MHz), indicating the number of bits required parameters 5bits; system bandwidth is 20MHz, required for the parameter bit indicates Is 5bits; Alternatively, the system bandwidth is 5MHz, the number of bits required to indicate UCAS _MB parameter 4bits; when the system bandwidth is 10MHz (or may be a 7MHz of 8.75 MHz), indicating the number of bits required parameters 4bits; system When the bandwidth is 20MHz, the number of bits required to indicate the parameter is 5bits; or, when the system bandwidth is 5MHz, the number of bits required to indicate the UCAS _MB parameter is 4bits; when the system bandwidth is 10MHz (also 7MHz or 8.75MHz) , the number of bits required to indicate the parameter is 5 bits; when the system bandwidth is 20 MHz, the number of bits required to indicate the parameter is 5 bits; or, when the system bandwidth is 5 MHz, the number of bits required to indicate the UCAS _MB parameter is 4 bits; When the bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 5bits; when the system bandwidth is 20MHz, the number of bits required to indicate the parameter is 6bits; or When the system bandwidth is 5MHz, the number of bits required to indicate the UCAS _MB parameter is 5bits; when the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 6bits; when the system bandwidth is 20MHz, The number of bits required to indicate the parameter is 6 bits; or, when the system bandwidth is 5 MHz, the number of bits required to indicate the UCAS _MB parameter is 5 bits; when the system bandwidth is 10 MHz (also 7 MHz or 8.75 MHz), the parameter is indicated. The number of bits required is 6 bits; when the system bandwidth is 20 MHz, the number of bits required to indicate this parameter is 7 bits. It should be noted that in the above UCAS _MB configuration method, when two different bandwidths use the same number of bits to indicate UCAS _MB parameters, the corresponding tables may be the same or different. For example, when the system bandwidth is 10MHz (also 7MHz or 8.75MHz), the number of bits required to indicate the parameter is 5bits, but the corresponding table is Table 10.21; when the system bandwidth is 20MHz, the number of bits required for the parameter is indicated. It is 5bits, but the corresponding table is Table 10.25. The same table means: Since the system bandwidth is 10MHz (can be 7MHz or 8.75MHz) and the system bandwidth is 20MHz, it can be considered similarly ^ ¹ 10MHz (can be 7MHz or 8.75MHz) and 20MHz features can be unified ^) The system bandwidth is 10MHz (which can be 7MHz or 8.75MHz) and the system bandwidth is 20MHz. The same UCAS _MB value and corresponding relationship are used, that is, the system bandwidth is 10MHz (can be 7MHz or 8.75MHz) and the system bandwidth is 20MHz. The same table is used, for example, one of Table 10.23 to Table 10.25 can be used, or it can be generated according to the configuration method at 20 MHz. Alternatively, generate as follows: Table 10.27

10 10/48 10 20

11 11/48 11 22

12 12/48 12 24

13 13/48 13 26

14 14/48 14 28

15 15/48 15 30 jt匕, 5MHz can be 3 bits or 4 bits or 5 bits with 10MHz (A can be 7MHz or 8.75MHz). Further, to be noted: In the UCAS _MB configuration process, for each table, the relationship between the intermediate meaning UCAS _MB value with UCAS _MB values indicated may be varied, each form are one embodiment, as long as a The values of UCAS _MB included in the table are the same meanings, and are considered to be the same table, all within the scope of protection. Through the above example 10, it can be seen that when the system bandwidth is 5MHz, 10MHz (which can be 7MHz or 8.75MHz), and the 20MHz system, the number of bits indicating the UCAS _MB needs 3bits, 4bits, 4bits, or 3bits, 4bits, respectively. 5bits, or 4bits, 5bits, 6bits, or 5bits, 6bits, 7bits or other combinations respectively, when the possible value of UCAS _MB is reduced, the redundant and unnecessary information indications are deleted, saving The bit overhead is guaranteed and a certain degree of flexibility is guaranteed. In summary, with the configuration method of the resource mapping indication information provided by the present invention, the number of bits required to indicate the parameter is configured for each bandwidth supported by the system, and the number of bits indicated by the same parameter under different bandwidths is the same. Or completely different, so that the number of bits used by the physical resource mapping indication signaling can be flexibly changed according to the bandwidth used by the system, and the number of transmitted bits is reduced as much as possible, thereby avoiding the problem of large control channel overhead in the related art, without affecting the normal system. Under the premise of operation, the downlink control overhead is saved, thereby improving the working efficiency of the system. Obviously, those skilled in the art should understand that the above modules or steps of the present invention can be implemented by a general-purpose computing device, which can be concentrated on a single computing device or distributed over a network composed of multiple computing devices. Alternatively, they may be implemented by program code executable by the computing device, such that they may be stored in the storage device by the computing device, or they may be separately fabricated into individual integrated circuit modules, or they may be Multiple modules or steps are made into a single integrated circuit module. Thus, the invention is not limited to any specific combination of hardware and software. The above is only the preferred embodiment of the present invention, and is not intended to limit the present invention, and various modifications and changes can be made to the present invention. Any modifications, equivalent substitutions, improvements, etc. made within the scope of the present invention are intended to be included within the scope of the present invention.

Claims

Claim

A method for configuring resource mapping indication information, which is characterized by:

Determining at least one parameter of the resource mapping, determining a number of bits required to indicate the parameter according to the bandwidth;

Wherein, for a plurality of different bandwidths, the number of bits required to indicate the parameter is partially identical or completely different from each other.

The method according to claim 1, wherein the resource mapping includes a downlink resource mapping and/or an uplink resource mapping, where the downlink resource mapping includes one or a combination of the following steps: subband division, ^ Entity band permutation, frequency partition division, continuous resource unit/distributed resource unit allocation, and subcarrier permutation; the uplink resource mapping includes one or a combination of the following steps: subband division, ^ start band permutation, frequency partition division, continuous resource unit/ Distributed resource unit allocation and tile replacement.

The method according to claim 1, wherein the plurality of bandwidths comprise a first bandwidth, a second bandwidth, and a third bandwidth, wherein: one parameter in the resource indication information: corresponding to the The first bandwidth, the number of bits required to indicate the parameter is M; corresponding to the second bandwidth, the number of bits required to indicate the parameter is N; corresponding to the third bandwidth, the number of bits required to indicate the parameter It is P, and the values of M, N, and P are partially identical or completely different from each other.

4. The method according to claim 3, wherein the values of the M, N, and P are partially identical to each other:

N=M+1, and P=M+1; or, N=M+2, and P=M+2; or, N=M, JL P=M+1; or, N=M, and P= M+2, where M is an integer greater than zero.

5. The method according to claim 3, wherein the values of the M, N, and P are completely different from each other:

N=M+1, JL P=M+2; or N=M+2, JL P=M+3, or N=M+1, and P=M+3, where M is an integer greater than zero.

The method according to any one of claims 3 to 5, characterized in that the value of M is 1 or 2 or 3 or 4.

The method according to any one of claims 3 to 5, wherein the first bandwidth comprises: 5 MHz, and the second bandwidth comprises one of: 7MHz, 8.75MHz, 10MHz, The third bandwidth includes: 20 MHz.

The method according to any one of claims 1 to 5, wherein the parameter in the resource indication information includes at least one of the following: a downlink subband allocation number, an uplink subband allocation number, and a downlink frequency partition. Configuration, uplink frequency partition configuration, downlink frequency partition subband allocation number, uplink frequency partition subband allocation number, downlink continuous resource unit allocation number, uplink continuous resource unit allocation number, downlink based on Miniband-based continuous resource unit Number, number of consecutive contiguous resource units based on Miniband.

9. The method of claim 8 wherein:

The number of bits indicating the number of downlink subband allocations in the system is the same as or different from the number of bits indicating the number of uplink subband allocations;

The number of bits indicating the configuration of the downlink frequency partition in the system is the same as or different from the number of bits indicating the configuration of the uplink frequency partition;

The number of bits indicating the number of downlink frequency partition subband allocations in the system is the same as or different from the number of bits indicating the uplink frequency partition subband allocation number;

The number of bits indicating the number of downlink contiguous resource unit allocations in the system is the same or different from the number of bits indicating the number of uplink contiguous resource unit allocations.

The method according to any one of claims 1 to 5, wherein the downlink subband allocation number and/or the uplink subband allocation number are: the number of subbands in the subband division, The downlink frequency partition configuration and/or the uplink frequency partition configuration refers to the number of frequency partitions in the frequency partition division and/or the size or proportion of each frequency partition, the downlink frequency partition subband allocation number, and/or the uplink frequency partition subband allocation number. All indicating that the number of subbands in the frequency partition other than frequency partition 0 in the frequency partition, the number of downlink contiguous resource unit allocations, and/or the number of uplink contiguous resource unit allocations refer to the allocation of consecutive resource units in each frequency partition. Number, downlink based

The number of contiguous resource units of the Miniband indicates the number of contiguous resource units based on the Miniband in the downlink frequency partition 0, and the number of contiguous resource units based on the Miniband indicates the number of contiguous resource units based on the Miniband in the uplink frequency partition 0, where the number The unit is a subband or a starter or a physical resource unit.