CN101854727A - Method for configuring resource mapping indication information - Google Patents

Method for configuring resource mapping indication information Download PDF

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Publication number
CN101854727A
CN101854727A CN 200910130558 CN200910130558A CN101854727A CN 101854727 A CN101854727 A CN 101854727A CN 200910130558 CN200910130558 CN 200910130558 CN 200910130558 A CN200910130558 A CN 200910130558A CN 101854727 A CN101854727 A CN 101854727A
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fps
parameter
indication
bit number
pru
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CN101854727B (en
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宁丁
关艳峰
刘向宇
刘颖
方惠英
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ZTE Corp
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ZTE Corp
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Priority to PCT/CN2009/073922 priority patent/WO2010111859A1/en
Priority to PCT/CN2010/071554 priority patent/WO2010111974A1/en
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    • H—ELECTRICITY
    • H04—ELECTRIC COMMUNICATION TECHNIQUE
    • H04W—WIRELESS COMMUNICATION NETWORKS
    • H04W28/00—Network traffic management; Network resource management
    • H04W28/02—Traffic management, e.g. flow control or congestion control
    • H04W28/06—Optimizing the usage of the radio link, e.g. header compression, information sizing, discarding information
    • H—ELECTRICITY
    • H04—ELECTRIC COMMUNICATION TECHNIQUE
    • H04W—WIRELESS COMMUNICATION NETWORKS
    • H04W72/00—Local resource management

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Abstract

The invention discloses a method for configuring resource mapping indication information. The method comprises the following steps of: indicating at least one parameter for the resource mapping; and determining the bit number needed for indicating the parameter according to bandwidth, wherein the bit number needed for indicating the parameter is partially same or completely different as for a plurality of different bandwidths. By means of the technical scheme of the invention, the bit number needed for indicating the parameter is configured for each bandwidth supported by a system and the bit number for indicating the same parameter at different bandwidths are partially same or completely different, so the bit number used by a physical resource mapping indication signaling can flexibly change along with the bandwidth used by the system so as to reduce the bit number transmitted; therefore, the method avoids the problem of high expenditure of a control channel in the related technology and saves the downlink control expenditure on the premise of not affecting the normal running of the system so as to improve the working efficiency of the system.

Description

Configuring resource mapping indication
Technical field
The present invention relates to the communications field, relate in particular to a kind of configuring resource mapping indication.
Background technology
In wireless communication system, the base station typically refers in certain area of radio coverage can believe the radio station by the transceiving that mobile switching center and the terminal information of carrying out is transmitted.In actual applications, the base station can communicate by Uplink/Downlink and terminal, and wherein, down link is meant that the base station arrives the transmission direction of terminal, and up link is meant the transmission direction of terminal to base station.And a plurality of terminals can send data to the base station simultaneously by up link, also can receive data simultaneously from the base station by down link.In addition, between base station and terminal, can carry out relaying to the data of transmission by relay station.
Adopting the base station to realize in the wireless communication system of wireless resource scheduling control, the scheduling of system wireless resource distributes to be finished by the base station.Ascending resource assignment information of required use when employed downlink resource assignment information and terminal are carried out uplink in the time of for example, can being provided this base station and carried out downlink transfer by the base station etc.
In the radio communication system of commercialization, the base station is when the Radio Resource that scheduling is eated dishes without rice or wine, usually with a radio frames as a dispatching cycle, and Radio Resource (for example is divided into several radio resource unit, can be with a time slot or a code word as a Resource Unit) to dispatch, the base station provides data or multimedia service by the scheduling radio resource unit to the terminal of its covering.
Particularly, at second generation wireless communication system (for example, at global system for mobile communications (Global System for Mobile communication, abbreviate GSM as)) in, it is time division multiple access (the Time Division Multiple Address in cycle that the base station is divided into the Radio Resource on each frequency with 4.615ms, abbreviate TDMA as) radio frames, each radio frames comprises 8 time slots, time slot transmits the speech channel of a full rate or transmits the speech channel of two half rates, and also can be used to realize the data service of low speed; In 2.5 generation wireless communication systems (for example), by introducing the speed that can continue to promote data service based on the fixing packet switching of time slot wireless universal packet service (General Packet RadioService abbreviates GPRS as); And at third generation wireless communication system (for example, at TD SDMA (Time-Division Synchronous Code DivisionMultiple Address, abbreviate TD-SCDMA as) in, it is the radio frames in cycle that the base station can be divided into the Radio Resource of eating dishes without rice or wine with 10ms equally, each 10ms comprises 14 conventional time slots and 6 special time slots, conventional time slot is used to transmit concrete business and signaling, and on each conventional time slot, the user is distinguished by different code words in the base station.
By above description as can be seen, GSM and TD-SCDMA system mainly adopt TDMA and/or CDMA technology, and these technology are carried out resource mapping and resource allocation based on time slot and code word, and processing procedure is fairly simple.
Based on OFDM (Orthogonal Frequency DivisionMultiplexing, abbreviate OFDM as) and OFDM (Orthogonal FrequencyDivision Multiple Address, abbreviate OFDMA as) in the communication system of technology, for example, at Long Term Evolution (Long Term Evolution, abbreviate LTE as), Ultra-Mobile Broadband (Ultra Mobile Broadband, abbreviate UMB as) and wireless communication system such as IEEE 802.16m in, though Radio Resource also is divided framing and manages, but each OFDMA symbol all comprises a plurality of mutually orthogonal subcarriers, and terminal takies the parton carrier wave usually, thereby can adopt partial frequency multiplexing (Fractional Frequency Reuse, abbreviate FFR as) etc. technology reduce interference, improve to cover; Secondly, because wireless channel environment changes frequent, the base station is in order to obtain the gain of frequency diversity gain and frequency selective scheduling, the available physical subcarrier is divided into physical resource unit (Physical Resource Unit, abbreviate PRU as), and then physical resource unit is mapped as continuous resource unit (ContiguousResource Unit, abbreviate CRU as) and distributed resource unit (Distributed ResourceUnit, abbreviate DRU as), to improve transmission performance, wherein, the subcarrier in the continuous resource unit is all continuous, and the subcarrier in the distributed resource unit is discontinuous fully or not exclusively continuous; In addition, along with frequency resource is rare day by day, multiple different bandwidth (for example, 5MHz, 10MHz or 20MHz) or multi-carrier operation need be supported in the base station, to utilize different frequency resources and to satisfy the demand of different operators.
Owing to above reason, resource mapping process based on the wireless communication system of OFDM or OFDMA technology is complicated more, thereby the indication signaling expense that causes being used to controlling the resource mapping process is bigger, and the resource allocation information of terminal parses base station increases with the complexity of process of determining its reception and sending the physical resource position of data.
As seen, consider that the resource mapping process of the wireless communication system of OFDM or OFDMA technology will more complicated, in order to reduce the indication signaling expense of its resource mapping, optimization system information management and transmission method need carry out rational resource mapping.In order to ensure the efficient of wireless communication system, the base station is mapped as the Radio Resource of physics the Radio Resource of logic usually, for example, physical sub-carrier is mapped as the logical resource unit, and the scheduling of Radio Resource is realized in the base station by the scheduling logic Resource Unit.
Particularly, for wireless communication system based on OFDM or OFDMA, its Radio Resource mapping is mainly according to the frame structure and the resource structures of this wireless communication system, and frame structure is described the control structure of Radio Resource on time domain, and resource structures has been described the control structure of Radio Resource on frequency domain.Frame structure is divided into Radio Resource the unit of different brackets on time domain, as superframe (Superframe), frame (Frame), subframe (Subframe) and symbol (Symbol), by being set, different control channel (for example, broadcast channel, clean culture and Multicast Channel etc.) realizes scheduling controlling.
For example, shown in Figure 1, Radio Resource is divided into superframe on time domain, each superframe comprises 4 frames, each frame comprises 8 subframes, subframe is made up of 6 basic OFDMA symbols, and what OFDMA symbols are the factors such as circulating prefix-length of bandwidth that real system is supported as required and/or OFDMA symbol determine specifically to comprise in each grade unit in the frame structure; In addition, system is provided with broadcast channel (owing to be positioned at the superframe head, being also referred to as superframe head (Superframe Header)) in can first descending sub frame in superframe and sends system information such as resource mapping; And system can also be provided with clean culture and/control channel of multicast character sends scheduling control informations such as resource allocation.
According to factors such as networking technology, interference mitigation technology and types of service, resource structures is divided into a plurality of frequency partition (Frequency Partition with bandwidth available on the frequency domain, abbreviate FP as), and then the frequency resource in the frequency partition is divided into the continuous resource unit and/or the distributed resource unit is dispatched.For example, as shown in Figure 2, the available physical subcarrier of a subframe is divided into 3 frequency partition, and each frequency partition is divided into continuous resource and distributed resource unit, and the continuous resource unit is used for frequency selective scheduling, and the distributed resource unit is used for frequency diversity scheduling.
Method for mapping resource generally need be supported 5MHz, 7MHz, 8.75MHz, 10MHz and 20MHz system bandwidth (abbreviation bandwidth); and when the part when not considering multi-carrier operation protection subcarrier is used to shine upon PRU under 5MHz, 7MHz, 8.75MHz, 10MHz and the 20MHz bandwidth; the number of corresponding PRU is 24,48,48,48 and 96; therefore, the indication parameter difference of resource mapping under the different system bandwidth.For example, bandwidth is that each subframe of system of 5MHz has 24 PRU, when 4 PRU form a subband (Subband), 6 Subband are then arranged at most, and there are 48 PRU in 7MHz, 8.75MHz or 10MHz system, 12 Subband are then arranged at most, just need carry out different settings to pare down expenses subband allotment (Subband Allocation Count abbreviates SAC as) to these two kinds of systems.The following execution mode that illustrates the resource mapping according to different bandwidth:
The downlink resource mapping process generally includes: sub-band division (Subband Partitioning), little band displacement (Miniband Permutation), frequency partition is divided (FrequencyPartitioning), continuous resource unit/distributed resource unit distributes (Contigous ResourceUnit/Distributed Resource Unit Allocation, abbreviate CRU/DRUAllocation as) and subcarrier permutation (Subcarrier Permutation), comprise in the ascending resource mapping process: sub-band division, little band displacement, frequency partition is divided, continuous resource unit/distributed resource unit distributes and Tile displacement (Tile Permutation).Subband is made up of N1 continuous PRU, N1=4 for example, and Miniband is made up of the individual continuous PRU of N2, for example N2=1.Concrete, as shown in Figure 3, the descending sub frame resource mapping process of 5MHz OFDMA system has been described.Wherein, it is 512 that the FFT of 5MHz system counts, usable data subcarriers is 432 in the subframe, be divided into into N=24 PRU, each PRU size is 18x6, and promptly frequency domain is 18 carrier waves, and time domain is 6 symbols, owing to reasons such as Cyclic Prefix, superframe head, transfer point and control channels, the number of symbols on the time domain may be 5 or 7.
Below be each step that example is introduced physical resource mapping with the 5MHz bandwidth:
(1) sub-band division promptly, is that unit extracts a part of PRU and is mapped as Subband with a Subband.The number of descending Subband and the number of up Subband are respectively by descending allocation of subbands number (Downlink Subband Allocation Count, abbreviate DSAC as) and two parameter indications of up allocation of subbands number (Uplink Subband Allocation Count abbreviates USAC as).With descending 5MHz bandwidth is example, and when the number of the descending Subband of DSAC indication was 3,12 PRU were mapped as 3 Subband.As shown in Figure 4, Subband Partitioning is indicated with DSAC in the base station, obtains PRU SB(the shadow-free part among the figure) is mapped as Miniband with rest parts, as the PRU among the figure MB(dash area among the figure).
(2) little band displacement, that is, the PRU that will not be mapped as Subband is mapped as Miniband.Number at the descending Subband of 5MHz bandwidth and DSAC indication is 3 o'clock, has 12 PRU to be mapped as Miniband, as shown in Figure 5, these 12 PRU is replaced.This step does not need the additional parameter indication, finishes according to DSAC.Up little band displacement USAC finishes.
(3) frequency partition is divided, and, the Subband that divided and Miniband after the displacement is divided into each frequency partition that is.This step needs two parameters, a parameter is used to indicate each frequency partition number, size and/or ratio, descending and up respectively by downstream frequency zone configuration (Downlink Frequency Partition Configuration, abbreviate DFPC as) and upstream frequency zone configuration (Uplink Frequency PartitionConfiguration abbreviates UFPC as) indication; It (is FP except that first frequency partition that another parameter then is used for indication 0) number of Subband in addition the frequency partition, descending and up respectively by downstream frequency subregion allocation of subbands number (Downlink FrequencyPartition Subband Count, abbreviate DFPSC as) and upstream frequency subregion allocation of subbands number (Uplink Frequency Partition Subband Count abbreviates DFPSC as) indication.Under the size of the frequency partition except that first frequency partition condition equal with the number of the Subband that comprises, can carry out certain redundancy and delete, remove some impossible values.Fig. 6 shows that removing first frequency partition size is 24 PRU, and other frequency partition size is 0, and other frequency partition Subband number is 0 frequency partition dividing condition.
(4) continuous resource unit/distributed resource unit distributes, that is, each frequency partition is carried out continuous resource unit/distributed resource unit separately distribute.The downstream frequency subregion is by descending continuous resource unit allocated size (Downlink CRU Allocation Size, abbreviate DCAS as) indication, the upstream frequency subregion is indicated by up continuous resource unit allocated size (UplinkCRU Allocation Size abbreviates UCAS as).If the size of some frequency partition is 0, then can not need to carry this parameter.As shown in Figure 3, when system bandwidth is 5MHz, the number of the descending Subband of DSAC indication is 3, first frequency partition size is 24 PRU, other frequency partition size is 0, first frequency partition CRU number is 12 schematic diagram, and wherein last shadow-free that lists is partly represented CRU, and shade is then represented DRU.Need to prove, can indicate whether Subband acquiescence as CRU by 1 bit, and with the Miniband acquiescence as DRU, at this moment, can not send DCAS or UCAS further pares down expenses.
(5) subcarrier permutation or Tile displacement promptly, is carried out the displacement of subcarrier to the PRU that is used to be mapped as DRU in each frequency partition in the descending sub frame, and the PRU that is used to be mapped as DRU in each frequency partition in the sub-frame of uplink is carried out the Tile displacement.
Fig. 3 illustrates the instantiation that the 5MHz bandwidth situation has been descended the physical resource mapping, comprising the process of continuous resource unit/distributed resource unit distribution.Fig. 4 to Fig. 6 shows the processing procedure that sub-band division is divided to frequency partition, for the situation of resource mapping under other bandwidth more clearly is described, concrete mapping situation when Fig. 7 shows 10MHz (also comprising 7MHz, 8.75MHz) bandwidth, wherein, the Subband number is 5, and has 4 frequency partition, and each frequency partition size is 12 PRU, first frequency partition comprises 8 CRU and 4 DRU, and other frequency partition all comprises 4 CRU and 8 DRU.Fig. 8 shows the situation of the concrete mapping under the 20M bandwidth situation.
In Fig. 3～Fig. 8, PRU SBBe meant the PRU that is used for Subband, PRU MBBe meant the PRU that is used for Miniband, PPRU MBBe meant PRU through Miniband Permutation.
By above description as can be seen, in the resource mapping process, after bandwidth is determined, still need to determine other some parameters (for example, Subband on the definite Subband number of needs, frequency partition number, each frequency partition and CRU number etc.).
In communication system, resource mapping indication information is all given terminal by the base station by broadcast channel or superframe hair, and terminal determines to receive and/or send the resource location of data according to resource mapping indication information and resource allocation information.Resource mapping indication information has been indicated the division and the mapping of frequency resource, specifically can comprise following information: the number of the number of the number that the number that descending allocation of subbands number, up allocation of subbands number, downstream frequency zone configuration, upstream frequency zone configuration, downstream frequency subregion allocation of subbands number, upstream frequency subregion allocation of subbands number, descending continuous resource unit distribute, up continuous resource unit distribute, descending continuous resource unit based on Miniband, up continuous resource unit based on Miniband.
Because concrete resource mapping process is a lot, therefore, the setting of above-mentioned indication parameter has stronger flexibility, and needed bit number increases but this can cause indicating these parameters simultaneously, and then increased in the control channel expense of transmission during these bit waste large volumes of channels resource.Big at parameter indication and channel transmitted expense in the correlation technique, as to waste system resource problem does not propose effective solution at present as yet.
Summary of the invention
Consider exist in the correlation technique problem and the present invention is proposed, for this reason, main purpose of the present invention is to provide a kind of configuring resource mapping indication, to address the above problem.
According to an aspect of the present invention, provide a kind of configuring resource mapping indication.
Configuring resource mapping indication according to the present invention comprises: at least one parameter of indexed resource mapping, determine the required bit number of the described parameter of indication according to bandwidth; Wherein, for a plurality of different bandwidth, indicate the required bit number of described the parameter identical or complete difference of part each other.
By means of above-mentioned at least one technical scheme of the present invention, the required bit number of each band width configuration indication parameter for system's support, and the bit number part of the indicating identical or complete difference of same parameter under different bandwidth, the bit number that makes physical resource mapping indication signaling use can change flexibly according to the bandwidth that system uses, reduce the bit number of transmission as much as possible, avoided the big problem of control channel expense in the correlation technique, under the prerequisite that does not influence the normal running of system, save descending control expense, thereby improve the operating efficiency of system.
Description of drawings
Accompanying drawing is used to provide further understanding of the present invention, and constitutes the part of specification, is used from explanation the present invention with embodiments of the invention one, is not construed as limiting the invention.In the accompanying drawings:
Fig. 1 is the frame structure schematic diagram according to the wireless communication system of correlation technique;
Fig. 2 is the resource structures schematic diagram according to the wireless communication system of correlation technique;
Fig. 3 is the resource mapping process schematic diagram according to wireless communication system under the 5MHz bandwidth situation of correlation technique;
Fig. 4 is the sub-band division process schematic diagram according to wireless communication system under the 5MHz bandwidth situation of correlation technique;
Fig. 5 is the little band replacement process schematic diagram according to wireless communication system under the 5MHz bandwidth situation of correlation technique;
Fig. 6 divides schematic diagram according to the frequency partition of wireless communication system under the 5MHz bandwidth situation of correlation technique;
Fig. 7 is the resource mapping process schematic diagram of wireless communication system under 10MHz (can be 7MHz or the 8.75MHz) bandwidth situation according to correlation technique;
Fig. 8 is the schematic diagram according to the resource mapping process of wireless communication system under the 20MHz bandwidth situation of correlation technique;
Fig. 9 is the flow chart according to the configuring resource mapping indication of the embodiment of the invention;
Figure 10 is the configuring resource mapping indication of the embodiment of the invention of application schematic diagram signaling DSAC when adopting the bit indication parameter of varying number according to to(for) the 5MHz system bandwidth;
Figure 11 is the configuring resource mapping indication of the embodiment of the invention of application schematic diagram signaling USAC when adopting the bit indication parameter of varying number according to to(for) the 5MHz system bandwidth;
Figure 12 is the configuring resource mapping indication of the embodiment of the invention of application schematic diagram signaling DFPC when adopting the bit indication parameter of varying number according to to(for) the 10MHz system bandwidth;
Figure 13 is the configuring resource mapping indication of the embodiment of the invention of application schematic diagram signaling UFPC when adopting the bit indication parameter of varying number according to to(for) the 10MHz system bandwidth;
Figure 14 is the configuring resource mapping indication of the embodiment of the invention of application schematic diagram signaling DFPSC when adopting the bit indication parameter of varying number according to to(for) the 10MHz system bandwidth;
Figure 15 is the configuring resource mapping indication of the embodiment of the invention of application schematic diagram signaling UFPSC when adopting the bit indication parameter of varying number according to to(for) the 10MHz system bandwidth;
Figure 16 is signaling DCAS when adopting the bit indication parameter of varying number according to the configuring resource mapping indication of the embodiment of the invention for the 10MHz system bandwidth SBiThe application schematic diagram.
Figure 17 is signaling UCAS when adopting the bit indication parameter of varying number according to the configuring resource mapping indication of the embodiment of the invention for the 10MHz system bandwidth SBiThe application schematic diagram.
Figure 18 is signaling DCAS when adopting the bit indication parameter of varying number according to the configuring resource mapping indication of the embodiment of the invention for the 5MHz system bandwidth MB ÷The application schematic diagram.
Figure 19 is signaling UCAS when adopting the bit indication parameter of varying number according to the configuring resource mapping indication of the embodiment of the invention for the 5MHz system bandwidth MBThe application schematic diagram.
Embodiment
Functional overview
Consider in the correlation technique that the control channel expense is excessive in the parameter indication process, the problem of parameter indication bit transmission waste system resource, the present invention proposes: for the required bit number of each band width configuration indication parameter of system's support, and the bit number part of the indicating identical or complete difference of same parameter under different bandwidth, make and lack when little bandwidth situation is carried out bit that parameter when indication adopt than big bandwidth as far as possible, reduced the bit number that physical resource mapping indication signaling uses, can be under the prerequisite that does not influence the normal running of system, the bandwidth of using according to system changes the descending control expense of saving flexibly.Promptly the IE of transmission resource mapping indication information or message or son bag are determined according to system bandwidth in broadcast channel or superframe head, thereby improve the operating efficiency of system.
Describe the present invention in detail below in conjunction with accompanying drawing.
Method embodiment
According to the embodiment of the invention, provide a kind of configuring resource mapping indication.
Fig. 9 is the flow chart according to the configuring resource mapping indication of the embodiment of the invention, and as shown in Figure 9, this method may further comprise the steps:
Step S902, at least one parameter of indexed resource mapping process, determine the required bit number of the described parameter of indication according to bandwidth, this parameter comprise following one of at least: descending allocation of subbands number, up allocation of subbands number, the downstream frequency zone configuration, the upstream frequency zone configuration, downstream frequency subregion allocation of subbands number, upstream frequency subregion allocation of subbands number, the number that descending continuous resource unit distributes, the number that up continuous resource unit distributes, the number of descending continuous resource unit based on Miniband, the number of up continuous resource unit based on Miniband;
Step S904, a plurality of different bandwidths (this bandwidth can be a system bandwidth) for system's support, the required bit number of indication parameter is the identical or complete difference of part each other, particularly, these a plurality of bandwidth can comprise first bandwidth, second bandwidth and the 3rd bandwidth, wherein, for a parameter in the resource indication information: corresponding to first bandwidth, indicating the required bit number of this parameter is M; Corresponding to second bandwidth, indicating the required bit number of this parameter is N; Corresponding to the 3rd bandwidth, indicating the required bit number of this parameter is P, and, the value of M, N, P is the identical or complete difference of part each other, preferably, above-mentioned first bandwidth comprises: 5MHz, it is one of following that second bandwidth comprises: 7MHz, 8.75MHz, 10MHz, the 3rd bandwidth comprise: 20MHz.Need to prove that for the bandwidth of 40MHz, the required bit number of indication parameter can be X, X+1 or X+2, wherein, X is bandwidth needed bit number of indication parameter when being 20MHz.
Wherein, part is identical each other is meant for the value of M, N, P: N=M+1 and P=M+1; Perhaps, N=M+2 and P=M+2; Perhaps, N=M and P=M+1; Perhaps, N=M and P=M+2, wherein M is the integer greater than 0, preferably, the value of M is 1 or 2 or 3 or 4.
Wherein, the complete each other difference of the value of M, N, P is meant: N=M+1 and P=M+2; Perhaps N=M+2 and P=M+3, perhaps N=M+1 and P=M+3, wherein M is the integer greater than 0, preferably, the value of M is 1 or 2 or 3 or 4.
And concrete indicating mode is as follows: the bit number of indicating downlink allocation of subbands number is identical or different with the bit number of the up allocation of subbands number of indication in system; The bit number of indication downstream frequency zone configuration is identical or different with the bit number of indication upstream frequency zone configuration in system; The bit number of indication downstream frequency subregion allocation of subbands number is identical or different with the bit number of indication upstream frequency subregion allocation of subbands number in system; The bit number of the number that indicating downlink continuous resource unit distributes in system is identical or different with the bit number of the number that the up continuous resource of indication unit distributes.
The technical scheme that provides by the embodiment of the invention, the bit number that physical resource mapping indication signaling is used can change flexibly according to the bandwidth that system uses, reduce the bit number of transmission as much as possible, under the prerequisite that does not influence the normal running of system, save descending control expense, thereby improve the operating efficiency of system.
Describe in detail corresponding to the various examples of indicating the bit number of same parameter under the different bandwidth situation below in conjunction with concrete example.
In describing hereinafter, show the concrete corresponding situation of the indicated physical meaning (for example, hereinafter described sub band number) of a plurality of indication signaling values of parameter (for example, DSAC, USAC etc.) and indication signaling value by a plurality of forms.Should be appreciated that each form that occurs for hereinafter, according to actual needs, the corresponding relation of the physical meaning that the indication signaling value of parameter and indication signaling value are indicated can change, and is not limited to the corresponding relation shown in the form.
In the shown form of description hereinafter, specifically provided the situation of carrying out the parameter indication by 1bit, 2bits, 3bits and four kinds of modes of 4bits.Adopting 1bit and optional value to have under two the situation, indication signaling is represented 1 in the form with 0 in binary " 0 " expression form with binary " 1 "; Have under 4 the situation adopting 2bit to carry out parameter indication and optional value, indication signaling is represented 0 in the form with binary " 00 ", with 1 in binary " 01 " expression form, with 2 in binary " 10 " expression form, with 3 in binary " 11 " expression form; Have under 8 the situation adopting 3bits to carry out parameter indication and optional value, indication signaling is represented 0 in the form with binary " 000 ", with 1 in binary " 001 " expression form, with 2 in binary " 010 " expression form, with 3 in binary " 011 " expression form, with 4 in binary " 100 " expression form, with 5 in binary " 101 " expression form, with 6 in binary " 110 " expression form, with 7 in binary " 111 " expression form; Have under 16 the situation adopting 4bits to carry out parameter indication and optional value, indication signaling is represented 0 in the form with binary " 0000 ", with 1 in binary " 0001 " expression form, with 2 in binary " 0010 " expression form, with 3 in binary " 0011 " expression form, with 4 in binary " 0100 " expression form, with 5 in binary " 0101 " expression form, with 6 in binary " 0110 " expression form, with 7 in binary " 0111 " expression form, with 8 in binary " 1000 " expression form, with 9 in binary " 1001 " expression form, with 10 in binary " 1010 " expression form, with 11 in binary " 1011 " expression form, with 12 in binary " 1100 " expression form, with 13 in binary " 1101 " expression form, with 14 in binary " 1110 " expression form, with 15 in binary " 1111 " expression form.
The collocation method of descending allocation of subbands number
Example 1
As Figure 10, shown in DSAC value (that is, the number of the descending Subband of DSAC indication is not simultaneously) not simultaneously, descending Subband Partitioning process is different.Be that 5MHz, 10MHz (also can be 7MHz or 8.75MHz), 20MHz are example below with the system bandwidth, the bandwidth that is divided three classes describes the configuring condition of DSAC, and the first kind is 5MHz, and second class is 10MHz or 7MHz or 8.75MHz, and the 3rd class is 20MHz.
The first kind: when system bandwidth was 5MHz, the required bit number of indication DSAC parameter was 2bits;
For 5MHz, the possible value set of Subband number is A DSAC=0,1,2,3,4,5,6}.1.1 having described system bandwidth to table 1.8 is 5MHz, and indication DSAC required bit number is when being 2bits, the corresponding relation of the value of DSAC and Subband number.2bits represents 4 kinds of different Subband numbers, the possible value set A of Subband number when these 4 kinds different Subband numbers are taken from 5MHz DSAC, be total to C 7 4=35 kinds of combinations.For example, table 1.1 got 0,1,2,3}, other combination is enumerated no longer one by one.Need explanation, from m different elements, get n unduplicated element and form a subclass, and do not consider the order of its element, be called the no recombination of from m, getting n, the sum C of all possible combination m nExpression.
Table 1.1
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??0 ??2 ??2
??1 ??1 ??3 ??3
Table 1.2
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??0 ??2 ??2
??1 ??1 ??3 ??4
Table 1.3
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??0 ??2 ??3
??1 ??1 ??3 ??4
Table 1.4
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??0 ??2 ??3
??1 ??1 ??3 ??5
Table 1.5
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??0 ??2 ??3
??1 ??2 ??3 ??4
Table 1.6
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??0 ??2 ??4
??1 ??3 ??3 ??5
Table 1.7
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??0 ??2 ??4
??1 ??3 ??3 ??6
Table 1.8
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??1 ??2 ??3
??1 ??2 ??3 ??4
Perhaps: when system bandwidth was 5MHz, the required bit number of indication DSAC parameter was 3bits.3bits represents 8 kinds of different Subband numbers, and these 8 kinds different Subband numbers can be represented set A DSACIn all elements.Shown in table 1.9.
Table 1.9
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??0 ??4 ??4
??1 ??1 ??5 ??5
??2 ??2 ??6 ??6
??3 ??3 ??7 Keep
Second class: when system bandwidth was 7MHz or 8.75MHz or 10MHz, the required bit number of indication DSAC parameter was 3bits;
For 7MHz or 8.75MHz or 10MHz, the possible value set of Subband number is B DSAC=0,1,2,3,4,5,6,7,8,9,10,11,12}.It is 10MHz (also can be 7MHz or 8.75MHz) that table 1.10 to table 1.22 has been described system bandwidth, and indication DSAC required bit number is under the situation of 3bits, the corresponding relation of the value of DSAC and Subband number.3bits represents 8 kinds of different Subband numbers, the possible value set B of Subband number when these 8 kinds different Subband numbers are taken from 10MHz (also can be 7MHz or 8.75MHz) DSAC, be total to C 138=1287 kinds of combinations.For example, table 1.10 has got that { 0,1,2,3,4,5,6,7} is except that table 1.10 to other combination the table 1.22 is enumerated no longer one by one.
Table 1.10
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??0 ??4 ??4
??1 ??1 ??5 ??5
??2 ??2 ??6 ??6
??3 ??3 ??7 ??7
Table 1.11
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??0 ??4 ??4
??1 ??1 ??5 ??5
??2 ??2 ??6 ??7
??3 ??3 ??7 ??9
Table 1.12
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??0 ??4 ??5
??1 ??1 ??5 ??7
??2 ??2 ??6 ??9
??3 ??3 ??7 ??11
Table 1.13
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??0 ??4 ??4
??1 ??1 ??5 ??5
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??2 ??2 ??6 ??6
??3 ??3 ??7 ??8
Table 1.14
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??0 ??4 ??4
??1 ??1 ??5 ??6
??2 ??2 ??6 ??7
??3 ??3 ??7 ??8
Table 1.15
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??0 ??4 ??4
??1 ??1 ??5 ??5
??2 ??2 ??6 ??6
??3 ??3 ??7 ??8
Table 1.16
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??0 ??4 ??4
??1 ??1 ??5 ??6
??2 ??2 ??6 ??8
??3 ??3 ??7 ??9
Table 1.17
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??0 ??4 ??4
??1 ??1 ??5 ??6
??2 ??2 ??6 ??10
??3 ??3 ??7 ??12
Table 1.18
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??0 ??4 ??4
??1 ??1 ??5 ??5
??2 ??2 ??6 ??6
??3 ??3 ??7 ??9
Table 1.19
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??0 ??4 ??4
??1 ??1 ??5 ??6
??2 ??2 ??6 ??9
??3 ??3 ??7 ??12
Table 1.20
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??1 ??4 ??5
??1 ??2 ??5 ??6
??2 ??3 ??6 ??7
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??3 ??4 ??7 ??8
Table 1.21
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??0 ??4 ??6
??1 ??1 ??5 ??8
??2 ??2 ??6 ??10
??3 ??4 ??7 ??12
Table 1.22
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??0 ??4 ??6
??1 ??2 ??5 ??8
??2 ??3 ??6 ??10
??3 ??4 ??7 ??12
Perhaps: when system bandwidth was 10MHz or 7MHz or 8.75MHz, the required bit number of indication DSAC parameter was 4bits.4bits represents 16 kinds of different Subband numbers, and these 16 kinds different Subband numbers are enough represented set B DSACIn all elements.Shown in table 1.23.
Table 1.23
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??0 ??8 ??8
??1 ??1 ??9 ??9
??2 ??2 ??10 ??10
??3 ??3 ??11 ??11
??4 ??4 ??12 ??12
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??5 ??5 ??13 Keep
??6 ??6 ??14 Keep
??7 ??7 ??15 Keep
The 3rd bandwidth: when system bandwidth was 20MHz, the required bit number of indication DSAC parameter was 3bits.
For 20MHz, the possible value set of Subband number is C DSAC=0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24}.It is 20MHz that table 1.24 to table 1.27 has been described system bandwidth, and indication DSAC required bit number is under the situation of 3bits, the corresponding relation of the value of DSAC and Subband number.3bits represents 8 kinds of different Subband numbers, the possible value set C of Subband number when these 8 kinds different Subband numbers are taken from 20MHz DSAC, be total to C 25 8=1081575 kinds of combinations, for example, table 1.24 has got that { 0,2,3,4,6,8,9,12} is except that table 1.24 to other combination the table 1.27 is enumerated no longer one by one.
Table 1.24
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??0 ??4 ??6
??1 ??2 ??5 ??8
??2 ??3 ??6 ??9
??3 ??4 ??7 ??12
Table 1.25
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??0 ??4 ??6
??1 ??1 ??5 ??9
??2 ??2 ??6 ??12
??3 ??3 ??7 ??15
Table 1.26
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??0 ??4 ??9
??1 ??3 ??5 ??12
??2 ??4 ??6 ??15
??3 ??6 ??7 ??18
Table 1.27
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??0 ??4 ??12
??1 ??3 ??5 ??15
??2 ??6 ??6 ??18
??3 ??9 ??7 ??21
Perhaps, when system bandwidth was 20MHz, the required bit number of indication DSAC parameter was 4bits.4bits represents 16 kinds of different Subband numbers, and these 16 kinds different Subband numbers are taken from set C DSAC, be total to C 25 16=2042975 kinds of combinations, for example, table 1.28 has been got { 0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15, }, except that table 1.28 to other combination the table 1.40 is enumerated no longer one by one.
Table 1.28
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??0 ??8 ??8
??1 ??1 ??9 ??9
??2 ??2 ??10 ??10
??3 ??3 ??11 ??11
??4 ??4 ??12 ??12
??5 ??5 ??13 ??13
??6 ??6 ??14 ??14
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??7 ??7 ??15 ??15
Table 1.29
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??0 ??8 ??8
??1 ??1 ??9 ??9
??2 ??2 ??10 ??10
??3 ??3 ??11 ??11
??4 ??4 ??12 ??12
??5 ??5 ??13 ??14
??6 ??6 ??14 ??16
??7 ??7 ??15 ??18
Table 1.30
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??0 ??8 ??8
??1 ??1 ??9 ??9
??2 ??2 ??10 ??10
??3 ??3 ??11 ??12
??4 ??4 ??12 ??14
??5 ??5 ??13 ??15
??6 ??6 ??14 ??16
??7 ??7 ??15 ??18
Table 1.31
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??0 ??8 ??8
??1 ??1 ??9 ??9
??2 ??2 ??10 ??10
??3 ??3 ??11 ??12
??4 ??4 ??12 ??14
??5 ??5 ??13 ??15
??6 ??6 ??14 ??18
??7 ??7 ??15 ??20
Table 1.32
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??0 ??8 ??8
??1 ??1 ??9 ??9
??2 ??2 ??10 ??10
??3 ??3 ??11 ??12
??4 ??4 ??12 ??14
??5 ??5 ??13 ??16
??6 ??6 ??14 ??18
??7 ??7 ??15 ??20
Table 1.33
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??0 ??8 ??8
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??1 ??1 ??9 ??9
??2 ??2 ??10 ??10
??3 ??3 ??11 ??12
??4 ??4 ??12 ??14
??5 ??5 ??13 ??15
??6 ??6 ??14 ??18
??7 ??7 ??15 ??21
Table 1.34
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??0 ??8 ??8
??1 ??1 ??9 ??9
??2 ??2 ??10 ??10
??3 ??3 ??11 ??12
??4 ??4 ??12 ??13
??5 ??5 ??13 ??15
??6 ??6 ??14 ??18
??7 ??7 ??15 ??21
Table 1.35
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??0 ??8 ??8
??1 ??1 ??9 ??9
??2 ??2 ??10 ??10
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??3 ??3 ??11 ??12
??4 ??4 ??12 ??15
??5 ??5 ??13 ??18
??6 ??6 ??14 ??21
??7 ??7 ??15 ??24
Table 1.36
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??0 ??8 ??8
??1 ??1 ??9 ??9
??2 ??2 ??10 ??10
??3 ??3 ??11 ??11
??4 ??4 ??12 ??12
??5 ??5 ??13 ??15
??6 ??6 ??14 ??18
??7 ??7 ??15 ??24
Table 1.37
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??0 ??8 ??8
??1 ??1 ??9 ??9
??2 ??2 ??10 ??10
??3 ??3 ??11 ??12
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??4 ??4 ??12 ??15
??5 ??5 ??13 ??18
??6 ??6 ??14 ??21
??7 ??7 ??15 ??24
Table 1.38
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??0 ??8 ??10
??1 ??3 ??9 ??11
??2 ??4 ??10 ??12
??3 ??5 ??11 ??13
??4 ??6 ??12 ??14
??5 ??7 ??13 ??15
??6 ??8 ??14 ??16
??7 ??9 ??15 ??18
Table 1.39
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??3 ??8 ??11
??1 ??4 ??9 ??12
??2 ??5 ??10 ??13
??3 ??6 ??11 ??14
??4 ??7 ??12 ??15
??5 ??8 ??13 ??16
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??6 ??9 ??14 ??18
??7 ??10 ??15 ??21
Table 1.40
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??1 ??8 ??9
??1 ??2 ??9 ??10
??2 ??3 ??10 ??11
??3 ??4 ??11 ??12
??4 ??5 ??12 ??13
??5 ??6 ??13 ??14
??6 ??7 ??14 ??15
??7 ??8 ??15 ??16
Perhaps, when system bandwidth was 20MHz, the required bit number of indication DSAC parameter was 5bits.5bits represents 32 kinds of different Subband numbers, and these 32 kinds different Subband numbers enough represent to gather C DSACIn all elements.Shown in table 1.41.
Table 1.41
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??0 ??0 ??16 ??16
??1 ??1 ??17 ??17
??2 ??2 ??18 ??18
??3 ??3 ??19 ??19
??4 ??4 ??20 ??20
??5 ??5 ??21 ??21
??DSAC Corresponding Subband number ??DSAC Corresponding Subband number
??6 ??6 ??22 ??22
??7 ??7 ??23 ??23
??8 ??8 ??24 ??24
??9 ??9 ??25 Keep
??10 ??10 ??26 Keep
??11 ??11 ??27 Keep
??12 ??12 ??28 Keep
??13 ??13 ??29 Keep
??14 ??14 ??30 Keep
??15 ??15 ??31 Keep
Can from said method, determine for the required bit number of indication DSAC parameter under each bandwidth, but, indicate the required bit number of described the parameter identical or complete difference of part each other for a plurality of different bandwidths that system supports.For example,
When system bandwidth was 5MHz, the required bit number of indication DSAC parameter was 3bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 4bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 5bits; Perhaps,
When system bandwidth was 5MHz, the required bit number of indication DSAC parameter was 2bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 3bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits;
When system bandwidth was 5MHz, the required bit number of indication DSAC parameter was 2bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 3bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 3bits; Perhaps,
When system bandwidth was 5MHz, the required bit number of indication DSAC parameter was 2bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 4bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits; Perhaps,
When system bandwidth was 5MHz, the required bit number of indication DSAC parameter was 3bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 4bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits;
Need to prove that in this method, even two different bandwidth have been used identical bit number indication DSAC parameter, but corresponding form also can be different.For example, when system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 4bits, but corresponding form is a table 1.15; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits, but corresponding form is a table 1.25.
Because system bandwidth is 10MHz (can be 7MHz or 8.75MHz) is the more similar characteristics unification that can consider 10MHz (can be 7MHz or 8.75MHz) and 20MHz of situation of 20MHz with system bandwidth, can be 10MHz (can be 7MHz or 8.75MHz) adopts identical DSAC during for 20MHz with system bandwidth value and corresponding relation with system bandwidth, thereby make device fabrication simpler, that is, system bandwidth is that 10MHz (can be 7MHz or 8.75MHz) adopts identical form during for 20MHz with system bandwidth.For example, when system bandwidth was 5MHz, the required bit number of indication DSAC parameter was 2bits; And system bandwidth is when being 10MHz (also can be 7MHz or 8.75MHz) and 20MHz, and indicating the required bit number of this parameter is 4bits.
It is 5MHz that the same table 1.1 to table 1.8 has been described system bandwidth, and indication DSAC required bit number is under the situation of 2bits, and the corresponding relation of the value of DSAC and Subband number repeats no more here.
When system bandwidth is 10MHz (also can be 7MHz or 8.75MHz) and 20MHz, and the required bit number of indication DSAC is under the situation of 4bits, can all adopt one of 20MHz form when needing 4bits indication DSAC, for example, all be to determine the value of DSAC and the corresponding relation of Subband number with table 1.28 or table 1.33.
By above-mentioned example 1, as can be seen, when system bandwidth is respectively 5MHz, 10MHz (can be 7MHz or 8.75MHz), 20MHz system, the bit number of indication DSAC needs 2bits, 3bits, 4bits respectively, perhaps need 2bits, 4bits, 4bits respectively, perhaps need 3bits, 4bits, 4bits respectively, when perhaps needing 3bits, 4bits, 5bits etc. to make up respectively, under the situation that the possible value of DSAC reduces, deleted redundant and unnecessary information indication, save overhead bit, and guaranteed certain flexibility.
The collocation method of up allocation of subbands number
Example 2
As shown in figure 11, the USAC value is (that is, the number of the descending Subband of USAC indication is not simultaneously) not simultaneously, and descending Subband Partitioning process is different.Be that 5MHz, 10MHz (also can be 7MHz or 8.75MHz), 20MHz be example with system bandwidth (or abbreviating bandwidth as) below, the bandwidth that is divided three classes describes the configuring condition of USAC, the first kind is 5MHz, and second class is 10MHz or 7MHz or 8.75MHz, and the 3rd class is 20MHz.
The first kind: when system bandwidth was 5MHz, the required bit number of indication USAC parameter was 2bits;
For 5MHz, the possible value set of Subband number is A USAC=0,1,2,3,4,5,6}.1.1 having described system bandwidth to table 2.8 is 5MHz, and indication USAC required bit number is when being 2bits, the corresponding relation of the value of USAC and Subband number.2bits represents 4 kinds of different Subband numbers, the possible value set A of Subband number when these 4 kinds different Subband numbers are taken from 5MHz USAC, be total to C 7 4=35 kinds of combinations.For example, table 2.1 got 0,1,2,3}, other combination is enumerated no longer one by one.Need explanation, from m different elements, get n unduplicated element and form a subclass, and do not consider the order of its element, be called the no recombination of from m, getting n, the sum C of all possible combination m nExpression.
Table 2.1
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??0 ??2 ??2
??1 ??1 ??3 ??3
Table 2.2
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??0 ??2 ??2
??1 ??1 ??3 ??4
Table 2.3
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??0 ??2 ??3
??1 ??1 ??3 ??4
Table 2.4
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??0 ??2 ??3
??1 ??1 ??3 ??5
Table 2.5
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??0 ??2 ??3
??1 ??2 ??3 ??4
Table 2.6
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??0 ??2 ??4
??1 ??3 ??3 ??5
Table 2.7
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??0 ??2 ??4
??1 ??3 ??3 ??6
Table 2.8
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??1 ??2 ??3
??1 ??2 ??3 ??4
Perhaps: when system bandwidth was 5MHz, the required bit number of indication USAC parameter was 3bits.3bits represents 8 kinds of different Subband numbers, and these 8 kinds different Subband numbers can be represented set A USACIn all elements.Shown in table 2.9.
Table 2.9
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??0 ??4 ??4
??1 ??1 ??5 ??5
??2 ??2 ??6 ??6
??3 ??3 ??7 Keep
Second class: when system bandwidth was 7MHz or 8.75MHz or 10MHz, the required bit number of indication USAC parameter was 3bits;
For 7MHz or 8.75MHz or 10MHz, the possible value set of Subband number is B USAC=0,1,2,3,4,5,6,7,8,9,10,11,12}.It is 10MHz (also can be 7MHz or 8.75MHz) that table 2.10 to table 2.22 has been described system bandwidth, and indication USAC required bit number is under the situation of 3bits, the corresponding relation of the value of USAC and Subband number.3bits represents 8 kinds of different Subband numbers, the possible value set B of Subband number when these 8 kinds different Subband numbers are taken from 10MHz (also can be 7MHz or 8.75MHz) USAC, be total to C 13 8=1287 kinds of combinations.For example, table 2.10 has got that { 0,1,2,3,4,5,6,7} is except that table 2.10 to other combination the table 2.22 is enumerated no longer one by one.
Table 2.10
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??0 ??4 ??4
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??1 ??1 ??5 ??5
??2 ??2 ??6 ??6
??3 ??3 ??7 ??7
Table 2.11
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??0 ??4 ??4
??1 ??1 ??5 ??5
??2 ??2 ??6 ??7
??3 ??3 ??7 ??9
Table 2.12
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??0 ??4 ??5
??1 ??1 ??5 ??7
??2 ??2 ??6 ??9
??3 ??3 ??7 ??11
Table 2.13
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??0 ??4 ??4
??1 ??1 ??5 ??5
??2 ??2 ??6 ??6
??3 ??3 ??7 ??8
Table 2.14
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??0 ??4 ??4
??1 ??1 ??5 ??6
??2 ??2 ??6 ??7
??3 ??3 ??7 ??8
Table 2.15
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??0 ??4 ??4
??1 ??1 ??5 ??5
??2 ??2 ??6 ??6
??3 ??3 ??7 ??8
Table 2.16
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??0 ??4 ??4
??1 ??1 ??5 ??6
??2 ??2 ??6 ??8
??3 ??3 ??7 ??9
Table 2.17
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??0 ??4 ??4
??1 ??1 ??5 ??6
??2 ??2 ??6 ??10
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??3 ??3 ??7 ??12
Table 2.18
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??0 ??4 ??4
??1 ??1 ??5 ??5
??2 ??2 ??6 ??6
??3 ??3 ??7 ??9
Table 2.19
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??0 ??4 ??4
??1 ??1 ??5 ??6
??2 ??2 ??6 ??9
??3 ??3 ??7 ??12
Table 2.20
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??1 ??4 ??5
??1 ??2 ??5 ??6
??2 ??3 ??6 ??7
??3 ??4 ??7 ??8
Table 2.21
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??0 ??4 ??6
??1 ??1 ??5 ??8
??2 ??2 ??6 ??10
??3 ??4 ??7 ??12
Table 2.22
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??0 ??4 ??6
??1 ??2 ??5 ??8
??2 ??3 ??6 ??10
??3 ??4 ??7 ??12
Perhaps: when system bandwidth was 10MHz or 7MHz or 8.75MHz, the required bit number of indication USAC parameter was 4bits.4bits represents 16 kinds of different Subband numbers, and these 16 kinds different Subband numbers are enough represented set B USACIn all elements.Shown in table 2.23.
Table 2.23
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??0 ??8 ??8
??1 ??1 ??9 ??9
??2 ??2 ??10 ??10
??3 ??3 ??11 ??11
??4 ??4 ??12 ??12
??5 ??5 ??13 Keep
??6 ??6 ??14 Keep
??7 ??7 ??15 Keep
The 3rd bandwidth: when system bandwidth was 20MHz, the required bit number of indication USAC parameter was 3bits.
For 20MHz, the possible value set of Subband number is C USAC=0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24}.It is 20MHz that table 2.24 to table 2.27 has been described system bandwidth, and indication USAC required bit number is under the situation of 3bits, the corresponding relation of the value of USAC and Subband number.3bits represents 8 kinds of different Subband numbers, the possible value set C of Subband number when these 8 kinds different Subband numbers are taken from 20MHz USAC, be total to C 25 8=1081575 kinds of combinations, for example, table 2.24 has got that { 0,2,3,4,6,8,9,12} is except that table 2.24 to other combination the table 2.27 is enumerated no longer one by one.
Table 2.24
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??0 ??4 ??6
??1 ??2 ??5 ??8
??2 ??3 ??6 ??9
??3 ??4 ??7 ??12
Table 2.25
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??0 ??4 ??6
??1 ??1 ??5 ??9
??2 ??2 ??6 ??12
??3 ??3 ??7 ??15
Table 2.26
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??0 ??4 ??9
??1 ??3 ??5 ??12
??2 ??4 ??6 ??15
??3 ??6 ??7 ??18
Table 2.27
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??0 ??4 ??12
??1 ??3 ??5 ??15
??2 ??6 ??6 ??18
??3 ??9 ??7 ??21
Perhaps, when system bandwidth was 20MHz, the required bit number of indication USAC parameter was 4bits.4bits represents 16 kinds of different Subband numbers, and these 16 kinds different Subband numbers are taken from set C USAC, be total to C 25 16=2042975 kinds of combinations, for example, table 2.28 has been got { 0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15, }, except that table 2.28 to other combination the table 2.40 is enumerated no longer one by one.
Table 2.28
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??0 ??8 ??8
??1 ??1 ??9 ??9
??2 ??2 ??10 ??10
??3 ??3 ??11 ??11
??4 ??4 ??12 ??12
??5 ??5 ??13 ??13
??6 ??6 ??14 ??14
??7 ??7 ??15 ??15
Table 2.29
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??0 ??8 ??8
??1 ??1 ??9 ??9
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??2 ??2 ??10 ??10
??3 ??3 ??11 ??11
??4 ??4 ??12 ??12
??5 ??5 ??13 ??14
??6 ??6 ??14 ??16
??7 ??7 ??15 ??18
Table 2.30
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??0 ??8 ??8
??1 ??1 ??9 ??9
??2 ??2 ??10 ??10
??3 ??3 ??11 ??12
??4 ??4 ??12 ??14
??5 ??5 ??13 ??15
??6 ??6 ??14 ??16
??7 ??7 ??15 ??18
Table 2.31
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??0 ??8 ??8
??1 ??1 ??9 ??9
??2 ??2 ??10 ??10
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??3 ??3 ??11 ??12
??4 ??4 ??12 ??14
??5 ??5 ??13 ??15
??6 ??6 ??14 ??18
??7 ??7 ??15 ??20
Table 2.32
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??0 ??8 ??8
??1 ??1 ??9 ??9
??2 ??2 ??10 ??10
??3 ??3 ??11 ??12
??4 ??4 ??12 ??14
??5 ??5 ??13 ??16
??6 ??6 ??14 ??18
??7 ??7 ??15 ??20
Table 2.33
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??0 ??8 ??8
??1 ??1 ??9 ??9
??2 ??2 ??10 ??10
??3 ??3 ??11 ??12
??4 ??4 ??12 ??14
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??5 ??5 ??13 ??15
??6 ??6 ??14 ??18
??7 ??7 ??15 ??21
Table 2.34
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??0 ??8 ??8
??1 ??1 ??9 ??9
??2 ??2 ??10 ??10
??3 ??3 ??11 ??12
??4 ??4 ??12 ??13
??5 ??5 ??13 ??15
??6 ??6 ??14 ??18
??7 ??7 ??15 ??21
Table 2.35
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??0 ??8 ??8
??1 ??1 ??9 ??9
??2 ??2 ??10 ??10
??3 ??3 ??11 ??12
??4 ??4 ??12 ??15
??5 ??5 ??13 ??18
??6 ??6 ??14 ??21
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??7 ??7 ??15 ??24
Table 2.36
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??0 ??8 ??8
??1 ??1 ??9 ??9
??2 ??2 ??10 ??10
??3 ??3 ??11 ??11
??4 ??4 ??12 ??12
??5 ??5 ??13 ??15
??6 ??6 ??14 ??18
??7 ??7 ??15 ??24
Table 2.37
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??0 ??8 ??8
??1 ??1 ??9 ??9
??2 ??2 ??10 ??10
??3 ??3 ??11 ??12
??4 ??4 ??12 ??15
??5 ??5 ??13 ??18
??6 ??6 ??14 ??21
??7 ??7 ??15 ??24
Table 2.38
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??0 ??8 ??10
??1 ??3 ??9 ??11
??2 ??4 ??10 ??12
??3 ??5 ??11 ??13
??4 ??6 ??12 ??14
??5 ??7 ??13 ??15
??6 ??8 ??14 ??16
??7 ??9 ??15 ??18
Table 2.39
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??3 ??8 ??11
??1 ??4 ??9 ??12
??2 ??5 ??10 ??13
??3 ??6 ??11 ??14
??4 ??7 ??12 ??15
??5 ??8 ??13 ??16
??6 ??9 ??14 ??18
??7 ??10 ??15 ??21
Table 2.40
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??1 ??8 ??9
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??1 ??2 ??9 ??10
??2 ??3 ??10 ??11
??3 ??4 ??11 ??12
??4 ??5 ??12 ??13
??5 ??6 ??13 ??14
??6 ??7 ??14 ??15
??7 ??8 ??15 ??16
Perhaps, when system bandwidth was 20MHz, the required bit number of indication USAC parameter was 5bits.5bits represents 32 kinds of different Subband numbers, and these 32 kinds different Subband numbers enough represent to gather C USACIn all elements.Shown in table 2.41.
Table 2.41
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??0 ??0 ??16 ??16
??1 ??1 ??17 ??17
??2 ??2 ??18 ??18
??3 ??3 ??19 ??19
??4 ??4 ??20 ??20
??5 ??5 ??21 ??21
??6 ??6 ??22 ??22
??7 ??7 ??23 ??23
??8 ??8 ??24 ??24
??9 ??9 ??25 Keep
??10 ??10 ??26 Keep
??USAC Corresponding Subband number ??USAC Corresponding Subband number
??11 ??11 ??27 Keep
??12 ??12 ??28 Keep
??13 ??13 ??29 Keep
??14 ??14 ??30 Keep
??15 ??15 ??31 Keep
Can from said method, determine for the required bit number of indication USAC parameter under each bandwidth, but, indicate the required bit number of described the parameter identical or complete difference of part each other for a plurality of different bandwidths that system supports.For example,
When system bandwidth was 5MHz, the required bit number of indication USAC parameter was 3bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 4bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 5bits; Perhaps,
When system bandwidth was 5MHz, the required bit number of indication USAC parameter was 2bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 3bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits;
When system bandwidth was 5MHz, the required bit number of indication USAC parameter was 2bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 3bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 3bits; Perhaps,
When system bandwidth was 5MHz, the required bit number of indication USAC parameter was 2bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 4bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits; Perhaps,
When system bandwidth was 5MHz, the required bit number of indication USAC parameter was 3bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 4bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits;
Need to prove that in this method, even two different bandwidth have been used identical bit number indication USAC parameter, but corresponding form also can be different.For example, when system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 4bits, but corresponding form is a table 2.15; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits, but corresponding form is a table 2.25.
Because system bandwidth is 10MHz (can be 7MHz or 8.75MHz) is the more similar characteristics unification that can consider 10MHz (can be 7MHz or 8.75MHz) and 20MHz of situation of 20MHz with system bandwidth, can be 10MHz (can be 7MHz or 8.75MHz) adopts identical USAC during for 20MHz with system bandwidth value and corresponding relation with system bandwidth, thereby make device fabrication simpler, that is, system bandwidth is that 10MHz (can be 7MHz or 8.75MHz) adopts identical form during for 20MHz with system bandwidth.For example, when system bandwidth was 5MHz, the required bit number of indication USAC parameter was 2bits; And system bandwidth is when being 10MHz (also can be 7MHz or 8.75MHz) and 20MHz, and indicating the required bit number of this parameter is 4bits.
It is 5MHz that the same table 2.1 to table 2.8 has been described system bandwidth, and indication USAC required bit number is under the situation of 2bits, and the corresponding relation of the value of USAC and Subband number repeats no more here.
When system bandwidth is 10MHz (also can be 7MHz or 8.75MHz) and 20MHz, and the required bit number of indication USAC is under the situation of 4bits, can all adopt one of 20MHz form when needing 4bits indication USAC, for example, all be to determine the value of USAC and the corresponding relation of Subband number with table 2.28 or table 2.33.
By above-mentioned example 2, as can be seen, when system bandwidth is respectively 5MHz, 10MHz (can be 7MHz or 8.75MHz), 20MHz system, the bit number of indication USAC needs 2bits, 3bits, 4bits respectively, perhaps need 2bits, 4bits, 4bits respectively, perhaps need 3bits, 4bits, 4bits respectively, when perhaps needing 3bits, 4bits, 5bits etc. to make up respectively, under the situation that the possible value of USAC reduces, deleted redundant and unnecessary information indication, save overhead bit, and guaranteed certain flexibility.
The collocation method of downstream frequency zone configuration (DFPC)
DFPC has indicated the size and the number of the frequency partition in the descending sub frame.When DFPC got different value, descending Frequency Partitioning process was different, as shown in figure 12.Be that 5MHz, 7MHz, 8.75MHz, 10MHz and 20MHz are example below with the system bandwidth, and be divided into three class bandwidth the configuring condition of DFPC is described that the first kind is 5MHz, second class is 7MHz or 8.75MHz or 10MHz, and the 3rd class is 20MHz.Wherein, NPRU is a PRU number on the subframe, and generally speaking, the NPRU of 5MHz, 7MHz, 8.75MHz, 10MHz and 20MHz correspondence is respectively 24,48,48,48 and 96, but this method is not limited.And, each frequency partition ratio in following each form (FP0: FP1: FP2: FP3) in the expression formula, for the N1 that occurs: N2: N3: N4, wherein, N1 to N4 can represent the actual number of frequency partition, also can represent the proportionate relationship between each frequency partition.
Example 3
The first kind: when system bandwidth was 5MHz, the required bit number of indication DFPC parameter was 2bits.
For 5MHz, the set of the possible configuration of DFPC is A DFPC:
{ (1 frequency partition, the size of frequency partition are N PRU),
(3 frequency partition, the size of each frequency partition are N PRU* 1/3),
(4 frequency partition, and FPS 0=N PRU* 3/24, FPS 1=FPS 2=FPS 3=N PRU* 7/24),
(4 frequency partition, and FPS 0=N PRU* 6/24, FPS 1=FPS 2=FPS 3=N PRU* 1/4),
(4 frequency partition, and FPS 0=N PRU* 9/24, FPS 1=FPS 2=FPS 3=N PRU* 5/24),
(4 frequency partition, and FPS 0=N PRU* 1/2, FPS 1=FPS 2=FPS 3=N PRU* 1/6),
(4 frequency partition, and FPS 0=N PRU* 15/24, FPS 1=FPS 2=FPS 3=N PRU* 1/8),
(4 frequency partition, and FPS 0=N PRU* 18/24, FPS 1=FPS 2=FPS 3=N PRU* 1/12),
(4 frequency partition are arranged, and FPS 0=N PRU* 21/24, FPS 1=FPS 2=FPS 3=N PRU* 1/24) }.
2bits represents 4 kinds of different frequency partition numbers and frequency partition size, and these 4 kinds different frequency partition numbers and frequency partition size are taken from set A DFPC, altogether C 9 4=126 kinds of combinations.For example, table 3.1～table 3.3 has been described the corresponding relation of value and frequency partition number and the frequency partition size of DFPC, and other combination is enumerated no longer one by one.
Table 3.1
Figure B2009101305580D0000431
Table 3.2
Figure B2009101305580D0000432
Table 3.3
Perhaps, when system bandwidth was 5MHz, the required bit number of indication DFPC parameter was 3bits.3bits represents 8 kinds of different frequency partition numbers and frequency partition size, and these 8 kinds different frequency partition numbers and frequency partition size are taken from A DFPC, be total to C 9 8=9 kinds of combinations.For example, table 3.4～table 3.5 has been described the corresponding relation of value and frequency partition number and the frequency partition size of DFPC, and other combination is enumerated no longer one by one.
Table 3.4
Figure B2009101305580D0000442
Table 3.5
Figure B2009101305580D0000443
Figure B2009101305580D0000451
Perhaps, although 3bits can represent 8 kinds of different frequency partition numbers and frequency partition size, owing to some frequency partition size can not be used substantially, so can be from A DFPC, select the frequency partition size of frequent use and represent, such as, 5 kinds, 6 kinds or 7 kinds, be total to C 9 5=126 kinds of combinations, C 9 6=84 kinds of combinations, C 9 7=36 kinds of combinations.For example, shown in table 3.6～table 3.8, other combination is enumerated no longer one by one.
Table 3.6
Figure B2009101305580D0000452
Table 3.7
Figure B2009101305580D0000453
Figure B2009101305580D0000461
Table 3.8
Figure B2009101305580D0000462
Second class: when system bandwidth was 7MHz or 8.75MHz or 10MHz, the required bit number of indication DFPC parameter was 3bits.
The set of the possible configuration of DFPC is B DFPC=
{ (1 frequency partition, the size of frequency partition are N PRU),
(3 frequency partition, and the size of each frequency partition is N PRU* 1/3),
(4 frequency partition, and FPS 0=N PRU* 3/48, FPS 1=FPS 2=FPS 3=N PRU* 5/16),
(4 frequency partition, and FPS 0=N PRU* 6/48, FPS 1=FPS 2=FPS 3=N PRU* 7/24),
(4 frequency partition, and FPS 0=N PRU* 9/48, FPS 1=FPS 2=FPS 3=N PRU* 13/48),
(4 frequency partition, and FPS 0=N PRU* 12/48, FPS 1=FPS 2=FPS 3=N PRU* 1/4),
(4 frequency partition, and FPS 0=N PRU* 15/48, FPS 1=FPS 2=FPS 3=N PRU* 11/48),
(4 frequency partition, and FPS 0=N PRU* 18/48, FPS 1=FPS 2=FPS 3=N PRU* 5/24),
(4 frequency partition, and FPS 0=N PRU* 21/48, FPS 1=FPS 2=FPS 3=N PRU* 3/16),
(4 frequency partition, and FPS 0=N PRU* 24/48, FPS 1=FPS 2=FPS 3=N PRU* 1/6),
(4 frequency partition, and FPS 0=N PRU* 27/48, FPS 1=FPS 2=FPS 3=N PRU* 7/48),
(4 frequency partition, and FPS 0=N PRU* 30/48, FPS 1=FPS 2=FPS 3=N PRU* 1/8),
(4 frequency partition, and FPS 0=N PRU* 33/48, FPS 1=FPS 2=FPS 3=N PRU* 5/48),
(4 frequency partition, and FPS 0=N PRU* 36/48, FPS 1=FPS 2=FPS 3=N PRU* 1/12),
(4 frequency partition, and FPS 0=N PRU* 39/48, FPS 1=FPS 2=FPS 3=N PRU* 1/16),
(4 frequency partition, and FPS 0=N PRU* 42/48, FPS 1=FPS 2=FPS 3=N PRU* 1/24),
(4 frequency partition, and FPS 0=N PRU* 45/48, FPS 1=FPS 2=FPS 3=N PRU* 1/48) }.
3bits represents 8 kinds of different frequency partition numbers and frequency partition size, and these 8 kinds different frequency partition numbers and frequency partition size are taken from set B DFPC, be total to C 17 8=24310 kinds of combinations.For example, shown in table 3.9～table 3.11, other is enumerated no longer one by one.
Table 3.9
Figure B2009101305580D0000471
Table 3.10
Figure B2009101305580D0000472
Figure B2009101305580D0000481
Table 3.11
Figure B2009101305580D0000482
Perhaps, when system bandwidth was 7MHz or 8.75MHz or 10MHz, the required bit number of indication DFPC parameter was 4bits.4bits represents 16 kinds of different frequency partition numbers and frequency partition size, and these 16 kinds different frequency partition numbers and frequency partition size are taken from set B DFPC, be total to C 17 16=17 kinds of combinations.For example, shown in table 3.12～table 3.13.
Table 3.12
Figure B2009101305580D0000483
Figure B2009101305580D0000491
Table 3.13
Figure B2009101305580D0000501
Perhaps, although 4bits can represent 16 kinds of different frequency partition numbers and frequency partition size, owing to some frequency partition size can not be used substantially, so can be from B DFPCSelect the frequency partition size of frequent use and represent, such as, 12 kinds, 13 kinds, 14 kinds or 15 kinds, be total to C 17 12=6188 kinds of combinations, C 17 13=2380 kinds of combinations, C 17 14=680 kinds of combinations, C 17 15=136 kinds of combinations.For example, shown in the table 3.14, other combination is enumerated no longer one by one.
Table 3.14
Figure B2009101305580D0000502
The 3rd class: when system bandwidth was 20MHz, the required bit number of indication DFPC parameter was 3bits.
The set of the possible configuration of DFPC is C DFPC=
{ (1 frequency partition, the size of frequency partition are N PRU),
(3 frequency partition, and the size of each frequency partition is N PRU* 1/3),
(4 frequency partition, and FPS 0=N PRU* 3/96, FPS 1=FPS 2=FPS 3=N PRU* 31/96),
(4 frequency partition, and FPS 0=N PRU* 6/96, FPS 1=FPS 2=FPS 3=N PRU* 30/96),
(4 frequency partition, and FPS 0=N PRU* 9/96, FPS 1=FPS 2=FPS 3=N PRU* 29/96),
(4 frequency partition, and FPS 0=N PRU* 12/96, FPS 1=FPS 2=FPS 3=N PRU* 28/96),
(4 frequency partition, and FPS 0=N PRU* 15/96, FPS 1=FPS 2=FPS 3=N PRU* 27/96),
(4 frequency partition, and FPS 0=N PRU* 18/96, FPS 1=FPS 2=FPS 3=N PRU* 26/96),
(4 frequency partition, and FPS 0=N PRU* 21/96, FPS 1=FPS 2=FPS 3=N PRU* 25/96),
(4 frequency partition, and FPS 0=N PRU* 24/96, FPS 1=FPS 2=FPS 3=N PRU* 24/96),
(4 frequency partition, and FPS 0=N PRU* 27/96, FPS 1=FPS 2=FPS 3=N PRU* 23/96),
(4 frequency partition, and FPS 0=N PRU* 30/96, FPS 1=FPS 2=FPS 3=N PRU* 22/96),
(4 frequency partition, and FPS 0=N PRU* 33/96, FPS 1=FPS 2=FPS 3=N PRU* 21/96),
(4 frequency partition, and FPS 0=N PRU* 36/96, FPS 1=FPS 2=FPS 3=N PRU* 20/96),
(4 frequency partition, and FPS 0=N PRU* 39/96, FPS 1=FPS 2=FPS 3=N PRU* 19/96),
(4 frequency partition, and FPS 0=N PRU* 42/96, FPS 1=FPS 2=FPS 3=N PRU* 18/96),
(4 frequency partition, and FPS 0=N PRU* 45/96, FPS 1=FPS 2=FPS 3=N PRU* 17/96),
(4 frequency partition, and FPS 0=N PRU* 48/96, FPS 1=FPS 2=FPS 3=N PRU* 16/96),
(4 frequency partition, and FPS 0=N PRU* 51/96, FPS 1=FPS 2=FPS 3=N PRU* 15/96),
(4 frequency partition, and FPS 0=N PRU* 54/96, FPS 1=FPS 2=FPS 3=N PRU* 14/96),
(4 frequency partition, and FPS 0=N PRU* 57/96, FPS 1=FPS 2=FPS 3=N PRU* 13/96),
(4 frequency partition, and FPS 0=N PRU* 60/96, FPS 1=FPS 2=FPS 3=N PRU* 12/96),
(4 frequency partition, and FPS 0=N PRU* 63/96, FPS 1=FPS 2=FPS 3=N PRU* 11/96),
(4 frequency partition, and FPS 0=N PRU* 66/96, FPS 1=FPS 2=FPS 3=N PRU* 10/96),
(4 frequency partition, and FPS 0=N PRU* 69/96, FPS 1=FPS 2=FPS 3=N PRU* 9/96),
(4 frequency partition, and FPS 0=N PRU* 72/96, FPS 1=FPS 2=FPS 3=N PRU* 8/96),
(4 frequency partition, and FPS 0=N PRU* 75/96, FPS 1=FPS 2=FPS 3=N PRU* 7/96),
(4 frequency partition, and FPS 0=N PRU* 78/96, FPS 1=FPS 2=FPS 3=N PRU* 6/96),
(4 frequency partition, and FPS 0=N PRU* 81/96, FPS 1=FPS 2=FPS 3=N PRU* 5/96),
(4 frequency partition, and FPS 0=N PRU* 84/96, FPS 1=FPS 2=FPS 3=N PRU* 4/96),
(4 frequency partition, and FPS 0=N PRU* 87/96, FPS 1=FPS 2=FPS 3=N PRU* 3/96),
(4 frequency partition, and FPS 0=N PRU* 90/96, FPS 1=FPS 2=FPS 3=N PRU* 2/96),
(4 frequency partition, and FPS 0=N PRU* 93/96, FPS 1=FPS 2=FPS 3=N PRU* 1/96) }.
3bits represents 8 kinds of different frequency partition numbers and frequency partition size, and these 8 kinds different frequency partition numbers and frequency partition size are taken from set C DFPC, be total to C 33 8=13884156 kinds of combinations.Can adopt the corresponding relation of any one combination indication DFPC value and frequency partition number and frequency partition size, for example, shown in table 3.15～3.17, other combination is not enumerated one by one.
Table 3.15
Figure B2009101305580D0000521
Figure B2009101305580D0000531
Table 3.16
Figure B2009101305580D0000532
Table 3.17
Figure B2009101305580D0000533
Perhaps, when system bandwidth was 20MHz, the required bit number of indication DFPC parameter was 4bits.4bits represents 16 kinds of different frequency partition numbers and frequency partition size, and these 16 kinds different frequency partition numbers and frequency partition size are taken from set C DFPC, be total to C 33 16=1166803110 kinds of combinations.Can adopt the corresponding relation of any one combination indication DFPC value and frequency partition number and frequency partition size, for example, shown in table 3.18～table 19, other combination is not enumerated one by one.
Table 3.18
Figure B2009101305580D0000541
Table 3.19
Figure B2009101305580D0000542
Figure B2009101305580D0000551
Perhaps, when system bandwidth was 20MHz, the required bit number of indication DFPC parameter was 5bits.5bits represents 32 kinds of different frequency partition numbers and frequency partition size, and these 32 kinds different frequency partition numbers and frequency partition size are taken from set C DFPC, be total to C 33 32=33 kinds of combinations.Can adopt the corresponding relation of any one combination indication DFPC value and frequency partition number and frequency partition size, for example, shown in the table 3.20, other combination is not enumerated one by one.
Table 3.20
Figure B2009101305580D0000552
Figure B2009101305580D0000561
Perhaps, although 5bits can represent 32 kinds of different frequency partition numbers and frequency partition size, owing to some frequency partition size can not be used substantially, so can be from C DFPCSelect the frequency partition size of frequent use and represent, such as, M (1＜M＜32) plants, altogether C 33 MCombination.For example, shown in table 3.21～table 3.22, other combination is enumerated no longer one by one.
Table 3.21
Figure B2009101305580D0000571
Figure B2009101305580D0000581
Table 3.22
Figure B2009101305580D0000582
Can from said method, determine for the required bit number of indication DFPC parameter under each bandwidth, but, indicate the required bit number of DFPC the parameter identical or complete difference of part each other for different bandwidth.For example,
When system bandwidth was 5MHz, the required bit number of indication DFPC parameter was 2bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 3bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 3bits; Perhaps,
When system bandwidth was 5MHz, the required bit number of indication DFPC parameter was 2bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 3bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits;
When system bandwidth was 5MHz, the required bit number of indication DFPC parameter was 2bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 3bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 5bits; Perhaps,
When system bandwidth was 5MHz, the required bit number of indication DFPC parameter was 2bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 4bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits;
When system bandwidth was 5MHz, the required bit number of indication DFPC parameter was 2bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 4bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 5bits;
When system bandwidth was 5MHz, the required bit number of indication DFPC parameter was 3bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 3bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits;
When system bandwidth was 5MHz, the required bit number of indication DFPC parameter was 3bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 3bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 5bits;
When system bandwidth was 5MHz, the required bit number of indication DFPC parameter was 3bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 4bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits;
When system bandwidth was 5MHz, the required bit number of indication DFPC parameter was 3bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 4bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 5bits;
When system bandwidth was 5MHz, the required bit number of indication DFPC parameter was 4bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 4bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 5bits;
When system bandwidth was 5MHz, the required bit number of indication DFPC parameter was 4bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 5bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 5bits;
It may be noted that: in the collocation method of above-mentioned DFPC, used identical bit number indication DFPC parameter when two different bandwidth, corresponding form can be identical or different.For example, when system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 4bits, but corresponding form is a table 3.13; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits, but corresponding form is a table 3.18.
Because system bandwidth is 10MHz (can be 7MHz or 8.75MHz) is the more similar characteristics unification that can consider 10MHz (can be 7MHz or 8.75MHz) and 20MHz of situation of 20MHz with system bandwidth, can be 10MHz (can be 7MHz or 8.75MHz) adopts identical DFPC during for 20MHz with system bandwidth value and corresponding relation with system bandwidth, thereby make device fabrication simpler, that is, system bandwidth is that 10MHz (can be 7MHz or 8.75MHz) adopts identical form during for 20MHz with system bandwidth.For example, when system bandwidth was 5MHz, the required bit number of indication DFPC parameter was 2bits; And system bandwidth is when being 10MHz (also can be 7MHz or 8.75MHz) and 20MHz, and indicating the required bit number of this parameter is 4bits.
It is 5MHz that the same table 3.1 to table 3.3 has been described system bandwidth, and indication DFPC required bit number is the collocation method under the situation of 2bits, repeats no more here.
When system bandwidth is 10MHz (also can be 7MHz or 8.75MHz) and 20MHz, and the required bit number of indication DFPC is under the situation of 4bits, can all adopt one of 20MHz form when needing 4bits indication DFPC, for example, all be with table 3.13 or table 3.18.
In addition; it may be noted that: in the collocation method of above-mentioned DFPC; at each table; relation in the middle of the meaning of the value of DFPC and the indication of the value of DFPC can change; each form all is embodiment; the meaning that needs only the value indication of the DFPC that comprises in the table is identical, all is regarded as identical table, all within protection range.For example, table 3.23 all is considered as identical table with table 3.15, is identical because the value of the DFPC that comprises in two tables is the meaning of indication.
Table 3.23
Other form of listing and produce by said method but all do not follow this principle at this form of listing.
By above-mentioned example 3, as can be seen, when system bandwidth is respectively 5MHz, 10MHz (can be 7MHz or 8.75MHz), 20MHz system, the bit number of indication DFPC needs 2bits, 3bits, 4bits respectively, perhaps need 2bits, 4bits, 4bits respectively, perhaps need 3bits, 4bits, 4bits respectively, when perhaps needing combination such as 3bits, 4bits, 5bits or other combination respectively, under the situation that the possible value of DFPC reduces, deleted redundant and unnecessary information indication, save overhead bit, and guaranteed certain flexibility.
The collocation method of upstream frequency zone configuration (UFPC)
UFPC has indicated the size and the number of the frequency partition in the sub-frame of uplink.When UFPC got different value, up Frequency Partitioning process was different, as shown in figure 13.Be that 5MHz, 7MHz, 8.75MHz, 10MHz and 20MHz are example below with the system bandwidth, and be divided into three class bandwidth the configuring condition of UFPC is described that the first kind is 5MHz, second class is 7MHz or 8.75MHz or 10MHz, and the 3rd class is 20MHz.Wherein, N PRUBe a PRU number on the subframe, generally speaking, the N of 5MHz, 7MHz, 8.75MHz, 10MHz and 20MHz correspondence PRUBe respectively 24,48,48,48 and 96, but this method is not limited.
Example 4
The first kind: when system bandwidth was 5MHz, the required bit number of indication UFPC parameter was 2bits.
For 5MHz, the set of the possible configuration of UFPC is A UFPC:
{ (1 frequency partition, the size of frequency partition are N PRU),
(3 frequency partition, the size of each frequency partition are N PRU* 1/3),
(4 frequency partition, and FPS 0=N PRU* 3/24, FPS 1=FPS 2=FPS 3=N PRU* 7/24),
(4 frequency partition, and FPS 0=N PRU* 6/24, FPS 1=FPS 2=FPS 3=N PRU* 1/4),
(4 frequency partition, and FPS 0=N PRU* 9/24, FPS 1=FPS 2=FPS 3=N PRU* 5/24),
(4 frequency partition, and FPS 0=N PRU* 1/2, FPS 1=FPS 2=FPS 3=N PRU* 1/6),
(4 frequency partition, and FPS 0=N PRU* 15/24, FPS 1=FPS 2=FPS 3=N PRU* 1/8),
(4 frequency partition, and FPS 0=N PRU* 18/24, FPS 1=FPS 2=FPS 3=N PRU* 1/12),
(4 frequency partition are arranged, and FPS 0=N PRU* 21/24, FPS 1=FPS 2=FPS 3=N PRU* 1/24) }.
2bits represents 4 kinds of different frequency partition numbers and frequency partition size, and these 4 kinds different frequency partition numbers and frequency partition size are taken from set A UFPC, be total to C 9 4=126 kinds of combinations.For example, table 4.1～table 4.3 has been described the corresponding relation of value and frequency partition number and the frequency partition size of UFPC, and other combination is enumerated no longer one by one.
Table 4.1
Figure B2009101305580D0000641
Table 4.2
Figure B2009101305580D0000642
Table 4.3
Perhaps, when system bandwidth was 5MHz, the required bit number of indication UFPC parameter was 3bits.3bits represents 8 kinds of different frequency partition numbers and frequency partition size, and these 8 kinds different frequency partition numbers and frequency partition size are taken from A UFPC, be total to C 9 8=9 kinds of combinations.For example, table 4.4～table 4.5 has been described the corresponding relation of value and frequency partition number and the frequency partition size of UFPC, and other combination is enumerated no longer one by one.
Table 4.4
Table 4.5
Figure B2009101305580D0000652
Perhaps, although 3bits can represent 8 kinds of different frequency partition numbers and frequency partition size, owing to some frequency partition size can not be used substantially, so can be from A UFPC, select the frequency partition size of frequent use and represent, such as, 5 kinds, 6 kinds or 7 kinds, be total to C 9 5=126 kinds of combinations, C 9 6=84 kinds of combinations, C 9 7=36 kinds of combinations.For example, shown in table 4.6～table 4.8, other combination is enumerated no longer one by one.
Table 4.6
Figure B2009101305580D0000661
Table 4.7
Table 4.8
Figure B2009101305580D0000663
Figure B2009101305580D0000671
Second class: when system bandwidth was 7MHz or 8.75MHz or 10MHz, the required bit number of indication UFPC parameter was 3bits.
The set of the possible configuration of UFPC is B UFPC=
{ (1 frequency partition, the size of frequency partition are N PRU),
(3 frequency partition, and the size of each frequency partition is N PRU* 1/3),
(4 frequency partition, and FPS 0=N PRU* 3/48, FPS 1=FPS 2=FPS 3=N PRU* 5/16),
(4 frequency partition, and FPS 0=N PRU* 6/48, FPS 1=FPS 2=FPS 3=N PRU* 7/24),
(4 frequency partition, and FPS 0=N PRU* 9/48, FPS 1=FPS 2=FPS 3=N PRU* 13/48),
(4 frequency partition, and FPS 0=N PRU* 12/48, FPS 1=FPS 2=FPS 3=N PRU* 1/4),
(4 frequency partition, and FPS 0=N PRU* 15/48, FPS 1=FPS 2=FPS 3=N PRU* 11/48),
(4 frequency partition, and FPS 0=N PRU* 18/48, FPS 1=FPS 2=FPS 3=N PRU* 5/24),
(4 frequency partition, and FPS 0=N PRU* 21/48, FPS 1=FPS 2=FPS 3=N PRU* 3/16),
(4 frequency partition, and FPS 0=N PRU* 24/48, FPS 1=FPS 2=FPS 3=N PRU* 1/6),
(4 frequency partition, and FPS 0=N PRU* 27/48, FPS 1=FPS 2=FPS 3=N PRU* 7/48),
(4 frequency partition, and FPS 0=N PRU* 30/48, FPS 1=FPS 2=FPS 3=N PRU* 1/8),
(4 frequency partition, and FPS 0=N PRU* 33/48, FPS 1=FPS 2=FPS 3=N PRU* 5/48),
(4 frequency partition, and FPS 0=N PRU* 36/48, FPS 1=FPS 2=FPS 3=N PRU* 1/12),
(4 frequency partition, and FPS 0=N PRU* 39/48, FPS 1=FPS 2=FPS 3=N PRU* 1/16),
(4 frequency partition, and FPS 0=N PRU* 42/48, FPS 1=FPS 2=FPS 3=N PRU* 1/24),
(4 frequency partition, and FPS 0=N PRU* 45/48, FPS 1=FPS 2=FPS 3=N PRU* 1/48) }.
3bits represents 8 kinds of different frequency partition numbers and frequency partition size, and these 8 kinds different frequency partition numbers and frequency partition size are taken from set B UFPC, be total to C 17 8=24310 kinds of combinations.For example, shown in table 4.9～table 4.11, other is enumerated no longer one by one.
Table 4.9
Figure B2009101305580D0000681
Table 4.10
Figure B2009101305580D0000682
Table 4.11
Figure B2009101305580D0000691
Perhaps, when system bandwidth was 7MHz or 8.75MHz or 10MHz, the required bit number of indication UFPC parameter was 4bits.4bits represents 16 kinds of different frequency partition numbers and frequency partition size, and these 16 kinds different frequency partition numbers and frequency partition size are taken from set B UFPC, be total to C 17 16=17 kinds of combinations.For example, shown in table 4.12～table 4.13.
Table 4.12
Figure B2009101305580D0000692
Figure B2009101305580D0000701
Table 4.13
Perhaps, although 4bits can represent 16 kinds of different frequency partition numbers and frequency partition size, owing to some frequency partition size can not be used substantially, so can be from B UFPCSelect the frequency partition size of frequent use and represent, such as, 12 kinds, 13 kinds, 14 kinds or 15 kinds, be total to C 17 12=6188 kinds of combinations, C 17 13=2380 kinds of combinations, C 17 14=680 kinds of combinations, C 17 15=136 kinds of combinations.For example, shown in the table 4.14, other combination is enumerated no longer one by one.
Table 4.14
Figure B2009101305580D0000711
The 3rd class: when system bandwidth was 20MHz, the required bit number of indication UFPC parameter was 3bits.
The set of the possible configuration of UFPC is C UFPC=
{ (1 frequency partition, the size of frequency partition are N PRU),
(3 frequency partition, and the size of each frequency partition is N PRU* 1/3),
(4 frequency partition, and FPS 0=N PRU* 3/96, FPS 1=FPS 2=FPS 3=N PRU* 31/96),
(4 frequency partition, and FPS 0=N PRU* 6/96, FPS 1=FPS 2=FPS 3=N PRU* 30/96),
(4 frequency partition, and FPS 0=N PRU* 9/96, FPS 1=FPS 2=FPS 3=N PRU* 29/96),
(4 frequency partition, and FPS 0=N PRU* 12/96, FPS 1=FPS 2=FPS 3=N PRU* 28/96),
(4 frequency partition, and FPS 0=N PRU* 15/96, FPS 1=FPS 2=FPS 3=N PRU* 27/96),
(4 frequency partition, and FPS 0=N PRU* 18/96, FPS 1=FPS 2=FPS 3=N PRU* 26/96),
(4 frequency partition, and FPS 0=N PRU* 21/96, FPS 1=FPS 2=FPS 3=N PRU* 25/96),
(4 frequency partition, and FPS 0=N PRU* 24/96, FPS 1=FPS 2=FPS 3=N PRU* 24/96),
(4 frequency partition, and FPS 0=N PRU* 27/96, FPS 1=FPS 2=FPS 3=N PRU* 23/96),
(4 frequency partition, and FPS 0=N PRU* 30/96, FPS 1=FPS 2=FPS 3=N PRU* 22/96),
(4 frequency partition, and FPS 0=N PRU* 33/96, FPS 1=FPS 2=FPS 3=N PRU* 21/96),
(4 frequency partition, and FPS 0=N PRU* 36/96, FPS 1=FPS 2=FPS 3=N PRU* 20/96),
(4 frequency partition, and FPS 0=N PRU* 39/96, FPS 1=FPS 2=FPS 3=N PRU* 19/96),
(4 frequency partition, and FPS 0=N PRU* 42/96, FPS 1=FPS 2=FPS 3=N PRU* 18/96),
(4 frequency partition, and FPS 0=N PRU* 45/96, FPS 1=FPS 2=FPS 3=N PRU* 17/96),
(4 frequency partition, and FPS 0=N PRU* 48/96, FPS 1=FPS 2=FPS 3=N PRU* 16/96),
(4 frequency partition, and FPS 0=N PRU* 51/96, FPS 1=FPS 2=FPS 3=N PRU* 15/96),
(4 frequency partition, and FPS 0=N PRU* 54/96, FPS 1=FPS 2=FPS 3=N PRU* 14/96),
(4 frequency partition, and FPS 0=N PRU* 57/96, FPS 1=FPS 2=FPS 3=N PRU* 13/96),
(4 frequency partition, and FPS 0=N PRU* 60/96, FPS 1=FPS 2=FPS 3=N PRU* 12/96),
(4 frequency partition, and FPS 0=N PRU* 63/96, FPS 1=FPS 2=FPS 3=N PRU* 11/96),
(4 frequency partition, and FPS 0=N PRU* 66/96, FPS 1=FPS 2=FPS 3=N PRU* 10/96),
(4 frequency partition, and FPS 0=N PRU* 69/96, FPS 1=FPS 2=FPS 3=N PRU* 9/96),
(4 frequency partition, and FPS 0=N PRU* 72/96, FPS 1=FPS 2=FP S3=N PRU* 8/96),
(4 frequency partition, and FPS 0=N PRU* 75/96, FPS 1=FPS 2=FPS 3=N PRU* 7/96),
(4 frequency partition, and FPS 0=N PRU* 78/96, FPS 1=FPS 2=FPS 3=N PRU* 6/96),
(4 frequency partition, and FPS 0=N PRU* 81/96, FPS 1=FPS 2=FPS 3=N PRU* 5/96),
(4 frequency partition, and FPS 0=N PRU* 84/96, FPS 1=FPS 2=FPS 3=N PRU* 4/96),
(4 frequency partition, and FPS 0=N PRU* 87/96, FPS 1=FPS 2=FPS 3=N PRU* 3/96),
(4 frequency partition, and FPS 0=N PRU* 90/96, FPS 1=FPS 2=FPS 3=N PRU* 2/96),
(4 frequency partition, and FPS 0=N PRU* 93/96, FPS 1=FPS 2=FPS 3=N PRU* 1/96) }.
3bits represents 8 kinds of different frequency partition numbers and frequency partition size, and these 8 kinds different frequency partition numbers and frequency partition size are taken from set C UFPC, be total to C 33 8=13884156 kinds of combinations.Can adopt the corresponding relation of any one combination indication UFPC value and frequency partition number and frequency partition size, for example, shown in table 4.15～3.17, other combination is not enumerated one by one.
Table 4.15
Figure B2009101305580D0000731
Table 4.16
Figure B2009101305580D0000741
Table 4.17
Perhaps, when system bandwidth was 20MHz, the required bit number of indication UFPC parameter was 4bits.4bits represents 16 kinds of different frequency partition numbers and frequency partition size, and these 16 kinds different frequency partition numbers and frequency partition size are taken from set C UFPC, be total to C 33 16=1166803110 kinds of combinations.Can adopt the corresponding relation of any one combination indication UFPC value and frequency partition number and frequency partition size, for example, shown in table 4.18～table 19, other combination is not enumerated one by one.
Table 4.18
Figure B2009101305580D0000743
Figure B2009101305580D0000751
Table 4.19
Figure B2009101305580D0000752
Figure B2009101305580D0000761
Perhaps, when system bandwidth was 20MHz, the required bit number of indication UFPC parameter was 5bits.5bits represents 32 kinds of different frequency partition numbers and frequency partition size, and these 32 kinds different frequency partition numbers and frequency partition size are taken from set C UFPC, be total to C 33 32=33 kinds of combinations.Can adopt the corresponding relation of any one combination indication UFPC value and frequency partition number and frequency partition size, for example, shown in the table 4.20, other combination is not enumerated one by one.
Table 4.20
Figure B2009101305580D0000762
Figure B2009101305580D0000771
Perhaps, although 5bits can represent 32 kinds of different frequency partition numbers and frequency partition size, owing to some frequency partition size can not be used substantially, so can be from C UFPCSelect the frequency partition size of frequent use and represent, such as, M (1＜M＜32) plants, altogether C 33 MCombination.For example, shown in table 4.21～table 4.22, other combination is enumerated no longer one by one.
Table 4.21
Figure B2009101305580D0000772
Figure B2009101305580D0000781
Table 4.22
Figure B2009101305580D0000791
Can from said method, determine for the required bit number of indication UFPC parameter under each bandwidth, but, indicate the required bit number of UFPC the parameter identical or complete difference of part each other for different bandwidth.For example,
When system bandwidth was 5MHz, the required bit number of indication UFPC parameter was 2bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 3bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 3bits; Perhaps,
When system bandwidth was 5MHz, the required bit number of indication UFPC parameter was 2bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 3bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits;
When system bandwidth was 5MHz, the required bit number of indication UFPC parameter was 2bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 3bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 5bits; Perhaps,
When system bandwidth was 5MHz, the required bit number of indication UFPC parameter was 2bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 4bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits;
When system bandwidth was 5MHz, the required bit number of indication UFPC parameter was 2bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 4bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 5bits;
When system bandwidth was 5MHz, the required bit number of indication UFPC parameter was 3bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 3bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits;
When system bandwidth was 5MHz, the required bit number of indication UFPC parameter was 3bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 3bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 5bits;
When system bandwidth was 5MHz, the required bit number of indication UFPC parameter was 3bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 4bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits;
When system bandwidth was 5MHz, the required bit number of indication UFPC parameter was 3bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 4bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 5bits;
When system bandwidth was 5MHz, the required bit number of indication UFPC parameter was 4bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 4bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 5bits;
When system bandwidth was 5MHz, the required bit number of indication UFPC parameter was 4bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 5bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 5bits;
It may be noted that: in the collocation method of above-mentioned UFPC, used identical bit number indication UFPC parameter when two different bandwidth, corresponding form can be identical or different.For example, when system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 4bits, but corresponding form is a table 4.13; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits, but corresponding form is a table 4.18.
Because system bandwidth is 10MHz (can be 7MHz or 8.75MHz) is the more similar characteristics unification that can consider 10MHz (can be 7MHz or 8.75MHz) and 20MHz of situation of 20MHz with system bandwidth, can be 10MHz (can be 7MHz or 8.75MHz) adopts identical UFPC during for 20MHz with system bandwidth value and corresponding relation with system bandwidth, thereby make device fabrication simpler, that is, system bandwidth is that 10MHz (can be 7MHz or 8.75MHz) adopts identical form during for 20MHz with system bandwidth.For example, when system bandwidth was 5MHz, the required bit number of indication UFPC parameter was 2bits; And system bandwidth is when being 10MHz (also can be 7MHz or 8.75MHz) and 20MHz, and indicating the required bit number of this parameter is 4bits.
It is 5MHz that the same table 4.1 to table 4.3 has been described system bandwidth, and indication UFPC required bit number is the collocation method under the situation of 2bits, repeats no more here.
When system bandwidth is 10MHz (also can be 7MHz or 8.75MHz) and 20MHz, and the required bit number of indication UFPC is under the situation of 4bits, can all adopt one of 20MHz form when needing 4bits indication UFPC, for example, all be with table 4.13 or table 4.18.
In addition; it may be noted that: in the collocation method of above-mentioned UFPC; at each table; relation in the middle of the meaning of the value of UFPC and the indication of the value of UFPC can change; each form all is embodiment; the value that needs only the UFPC that comprises in the table is that the meaning of indication is identical, all is regarded as identical table, all within protection range.For example, table 4.23 all is considered as identical table with table 4.15, is identical because the value of the UFPC that comprises in two tables is the meaning of indication.
Table 4.23
Figure B2009101305580D0000821
Figure B2009101305580D0000831
Other form of listing and produce by said method but all do not follow this principle at this form of listing.
By above-mentioned example 4, as can be seen, when system bandwidth is respectively 5MHz, 10MHz (can be 7MHz or 8.75MHz), 20MHz system, the bit number of indication UFPC needs 2bits, 3bits, 4bits respectively, perhaps need 2bits, 4bits, 4bits respectively, perhaps need 3bits, 4bits, 4bits respectively, when perhaps needing combination such as 3bits, 4bits, 5bits or other combination respectively, under the situation that the possible value of UFPC reduces, deleted redundant and unnecessary information indication, save overhead bit, and guaranteed certain flexibility.
The collocation method of downstream frequency subregion Subband number (DFPSC)
When DFPSC got different values, descending Frequency Partitioning process was different, as Figure 14.Be that 5MHz, 7MHz, 8.75MHz, 10MHz and 20MHz are example below with the system bandwidth, and be divided into three class bandwidth the configuring condition of DFPSC is described that the first kind is 5MHz, second class is 7MHz or 8.75MHz or 10MHz, and the 3rd class is 20MHz.
Example 5
The first kind: when system bandwidth was 5MHz, the required bit number of indication DFPSC parameter was 1bits.
For 5MHz, the set of the number of the Subband that may indicate of DFPSC is: A DFPSC1=0,1,2}.1bits represents the number of 2 kinds of different Subband, and the number of these 2 kinds of different Subband is taken from set A DFPSC1, be total to C 3 2=3 kinds of combinations.For example, shown in table 5.1～table 5.3.
Table 5.1
??DFPSC ??FP i(i＞0) corresponding Subband number ?DFPSC ??FP i(i＞0) corresponding Subband number
??0 ??0 ??1 ??1
Table 5.2
??DFPSC ??FP i(i＞0) corresponding Subband number ?DFPSC ??FP i(i＞0) corresponding Subband number
??0 ??1 ??1 ??2
Table 5.3
??DFPSC ??FP i(i＞0) corresponding Subband number ?DFPSC ??FP i(i＞0) corresponding Subband number
??0 ??0 ??1 ??2
Perhaps, when system bandwidth was 5MHz, the required bit number of indication DFPSC parameter was 2bits.Shown in table 5.4.
Table 5.4
??DFPSC The corresponding Subband number of FPi (i＞0) ?DFPSC The corresponding Subband number of FPi (i＞0)
??0 ??0 ??2 ??2
??1 ??1 ??3 Keep
Second class: when system bandwidth was 7MHz or 8.75MHz or 10MHz, the required bit number of indication DFPSC parameter was 2bits.
For 7MHz or 8.75MHz or 10MHz, the set of the number of the Subband that may indicate of DFPSC is: A DFPSC2=0,1,2,3,4}.2bits represents the number of 4 kinds of different Subband, and the number of these 4 kinds of different Subband is taken from set A DFPSC2, be total to C 5 4=5 kinds of combinations.For example, shown in table 5.5～table 5.9.
Table 5.5
??DFPSC The corresponding Subband number of FPi (i＞0) ?DFPSC The corresponding Subband number of FPi (i＞0)
??0 ??0 ??2 ??2
??1 ??1 ??3 ??3
Table 5.6
??DFPSC The corresponding Subband number of FPi (i＞0) ?DFPSC The corresponding Subband number of FPi (i＞0)
??0 ??0 ??2 ??2
??1 ??1 ??3 ??4
Table 5.7
??DFPSC The corresponding Subband number of FPi (i＞0) ?DFPSC The corresponding Subband number of FPi (i＞0)
??0 ??0 ??2 ??3
??1 ??1 ??3 ??4
Table 5.8
??DFPSC The corresponding Subband number of FPi (i＞0) ?DFPSC The corresponding Subband number of FPi (i＞0)
??0 ??1 ??2 ??3
??1 ??2 ??3 ??4
Table 5.9
??DFPSC The corresponding Subband number of FPi (i＞0) ?DFPSC The corresponding Subband number of FPi (i＞0)
??0 ??0 ??2 ??3
??1 ??2 ??3 ??4
Perhaps, when system bandwidth was 7MHz or 8.75MHz or 10MHz, the required bit number of indication DFPSC parameter was 3bits.The corresponding relation of the Subband number of the frequency partition that the value of DFPSC is corresponding with it.For example, shown in the table 5.10.
Table 5.10
??DFPSC The corresponding Subband number of FPi (i＞0) ?DFPSC The corresponding Subband number of FPi (i＞0)
??0 ??0 ??4 ??4
??1 ??1 ??5 Keep
??2 ??2 ??6 Keep
??DFPSC The corresponding Subband number of FPi (i＞0) ?DFPSC The corresponding Subband number of FPi (i＞0)
??3 ??3 ??7 Keep
The 3rd class: when system bandwidth was 20MHz, the required bit number of indication DFPSC parameter was 2bits.
For 20MHz, the set of the number of the Subband that may indicate of DFPSC is: A DFPSC3=0,1,2,3,4,5,6,7,8}.2bits represents the number of 4 kinds of different Subband, and the number of these 4 kinds of different Subband is taken from set A DFPSC3, be total to C 9 4=126 kinds of combinations.For example, when table 5.11～table 5.14 has been described system bandwidth and is 20MHz, and the required bit number of indication DFPSC is under the situation of 2bits, the corresponding relation of the Subband number of the frequency partition that the value of DFPSC is corresponding with it, and other combination is not enumerated one by one.
Table 5.11
??DFPSC ??FP i(i＞0) corresponding Subband number ?DFPSC ??FP i(i＞0) corresponding Subband number
??0 ??0 ??2 ??2
??1 ??1 ??3 ??3
Table 5.12
??DFPSC ??FP i(i＞0) corresponding Subband number ?DFPSC ??FP i(i＞0) corresponding Subband number
??0 ??0 ??2 ??2
??1 ??1 ??3 ??4
Table 5.13
??DFPSC ??FP i(i＞0) corresponding Subband number ?DFPSC ??FP i(i＞0) corresponding Subband number
??0 ??0 ??2 ??4
??1 ??2 ??3 ??6
Table 5.14
??DFPSC ??FP i(i＞0) corresponding Subband number ?DFPSC ??FP i(i＞0) corresponding Subband number
??0 ??1 ??2 ??3
??1 ??2 ??3 ??4
Perhaps, when system bandwidth was 20MHz, the required bit number of indication DFPSC parameter was 3bits.3bits represents the number of 8 kinds of different Subband, and the number of these 4 kinds of different Subband is taken from set A DFPSC3, be total to C 9 8=9 kinds of combinations.For example, when table 5.15～table 5.17 has been described bit number and has been 3bits, the corresponding relation of the Subband number of the frequency partition that the value of DFPSC is corresponding with it, other combination is not enumerated one by one.
Table 5.15
??DFPSC ??FP i(i＞0) corresponding Subband number ?DFPSC ??FP i(i＞0) corresponding Subband number
??0 ??0 ??4 ??4
??1 ??1 ??5 ??5
??2 ??2 ??6 ??6
??3 ??3 ??7 ??7
Table 5.16
??DFPSC ??FP i(i＞0) corresponding Subband number ?DFPSC ??FP i(i＞0) corresponding Subband number
??0 ??0 ??4 ??4
??1 ??1 ??5 ??5
??2 ??2 ??6 ??6
??3 ??3 ??7 ??8
Table 5.17
??DFPSC ??FP i(i＞0) corresponding Subband number ?DFPSC ??FP i(i＞0) corresponding Subband number
??0 ??1 ??4 ??5
??1 ??2 ??5 ??6
??2 ??3 ??6 ??7
??3 ??4 ??7 ??8
Perhaps, when system bandwidth was 20MHz, the required bit number of indication DFPSC parameter was 4bits.For example, when table 5.18 has been described bit number and has been 4bits, the corresponding relation of the Subband number of the frequency partition that the value of DFPSC is corresponding with it.
Table 5.18
??DFPSC The corresponding Subband number of FPi (i＞0) ?DFPSC The corresponding Subband number of FPi (i＞0)
??0 ??0 ??8 ??8
??1 ??1 ??9 Keep
??2 ??2 ??10 Keep
??3 ??3 ??11 Keep
??4 ??4 ??12 Keep
??5 ??5 ??13 Keep
??6 ??6 ??14 Keep
??7 ??7 ??15 Keep
Can from said method, determine for the required bit number of indication DFPSC parameter under each bandwidth, but, indicate the required bit number of DFPSC the parameter identical or complete difference of part each other for different bandwidth.For example,
When system bandwidth was 5MHz, the required bit number of indication DFPSC parameter was 1bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 2bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 2bits; Perhaps,
When system bandwidth was 5MHz, the required bit number of indication DFPSC parameter was 1bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 2bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 3bits;
When system bandwidth was 5MHz, the required bit number of indication DFPSC parameter was 1bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 2bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits; Perhaps,
When system bandwidth was 5MHz, the required bit number of indication DFPSC parameter was 1bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 3bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 3bits;
When system bandwidth was 5MHz, the required bit number of indication DFPSC parameter was 1bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 3bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits;
When system bandwidth was 5MHz, the required bit number of indication DFPSC parameter was 1bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 4bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits; Perhaps,
When system bandwidth was 5MHz, the required bit number of indication DFPSC parameter was 2bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 2bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 3bits; Perhaps,
When system bandwidth was 5MHz, the required bit number of indication DFPSC parameter was 2bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 2bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits;
When system bandwidth was 5MHz, the required bit number of indication DFPSC parameter was 2bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 3bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 3bits; Perhaps,
When system bandwidth was 5MHz, the required bit number of indication DFPSC parameter was 2bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 3bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits;
When system bandwidth was 5MHz, the required bit number of indication DFPSC parameter was 2bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 4bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits;
It may be noted that: in the collocation method of above-mentioned DFPSC, used identical bit number indication DFPSC parameter when two different bandwidth, corresponding form can be identical or different.For example, when system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 3bits, but corresponding form is a table 5.10; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 3bits, but corresponding form is a table 5.15.
Again for example, when system bandwidth is 10MHz (also can be 7MHz or 8.75MHz) and 20MHz, and indication DFPSC required bit number is under the situation of 3bits, can all adopt one of 20MHz form when needing 3bits indication DFPSC, for example, all be with table 5.15.
In addition; it may be noted that: in the collocation method of above-mentioned DFPSC; at each table; relation in the middle of the meaning of the value of DFPSC and the indication of the value of DFPSC can change; each form all is embodiment; the value that needs only the DFPSC that comprises in the table is that the meaning of indication is identical, all is regarded as identical table, all within protection range.For example, table 5.19 all is considered as identical table with table 5.15, is identical because the value of the DFPSC that comprises in two tables is the meaning of indication.
Table 5.19
??DFPSC ??FP i(i＞0) corresponding Subband number ?DFPSC ??FP i(i＞0) corresponding Subband number
??0 ??0 ??4 ??4
??1 ??1 ??5 ??5
??2 ??2 ??6 ??7
??3 ??3 ??7 ??6
Other form of listing and produce by said method but all do not follow this principle at this form of listing.
By above-mentioned example 5, as can be seen, when system bandwidth is respectively 5MHz, 10MHz (can be 7MHz or 8.75MHz), 20MHz system, the bit number of indication DFPSC needs 1bits, 2bits, 2bits respectively, perhaps need 2bits, 3bits, 3bits respectively, when perhaps needing 2bits, 3bits, 4bits or other combination respectively, under the situation that the possible value of DFPSC reduces, deleted redundant and unnecessary information indication, save overhead bit, and guaranteed certain flexibility.
The collocation method of upstream frequency subregion Subband number (UFPSC)
Example 6
When UFPSC got different values, up Frequency Partitioning process also was different, as Figure 15.Be that 5MHz, 7MHz, 8.75MHz, 10MHz and 20MHz are example below with the system bandwidth, and be divided into three class bandwidth the configuring condition of UFPSC is described that the first kind is 5MHz, second class is 7MHz or 8.75MHz or 10MHz, and the 3rd class is 20MHz.
The first kind: when system bandwidth was 5MHz, the required bit number of indication UFPSC parameter was 1bits.
For 5MHz, the set of the number of the Subband that may indicate of UFPSC is: A UFPSC=0,1,2}.1bits represents the number of 2 kinds of different Subband, and the number of these 2 kinds of different Subband is taken from set A UFPSC, be total to C 3 2=3 kinds of combinations.For example, shown in table 6.1～table 6.3.
Table 6.1
??UFPSC ??FP i(i＞0) corresponding Subband number ?UFPSC ??FP i(i＞0) corresponding Subband number
??0 ??0 ??1 ??1
Table 6.2
??UFPSC ??FP i(i＞0) corresponding Subband number ?UFPSC ??FP i(i＞0) corresponding Subband number
??0 ??1 ??1 ??2
Table 6.3
??UFPSC ??FP i(i＞0) corresponding Subband number ?UFPSC ??FP i(i＞0) corresponding Subband number
??0 ??0 ??1 ??2
Perhaps, when system bandwidth was 5MHz, the required bit number of indication UFPSC parameter was 2bits.Shown in table 6.4.
Table 6.4
??UFPSC ??FP i(i＞0) corresponding Subband number ?UFPSC ??FP i(i＞0) corresponding Subband number
??0 ??0 ??2 ??2
??1 ??1 ??3 Keep
Second class: when system bandwidth was 7MHz or 8.75MHz or 10MHz, the required bit number of indication UFPSC parameter was 2bits.
For 7MHz or 8.75MHz or 10MHz, the set of the number of the Subband that may indicate of UFPSC is: B UFPSC=0,1,2,3,4}.2bits represents the number of 4 kinds of different Subband, and the number of these 4 kinds of different Subband is taken from set B UFPSC, be total to C 5 4=5 kinds of combinations.For example, shown in table 6.5～table 6.9.
Table 6.5
??UFPSC The corresponding Subband number of FPi (i＞0) ?UFPSC The corresponding Subband number of FPi (i＞0)
??0 ??0 ??2 ??2
??1 ??1 ??3 ??3
Table 6.6
??UFPSC The corresponding Subband number of FPi (i＞0) ?UFPSC The corresponding Subband number of FPi (i＞0)
??0 ??0 ??2 ??2
??1 ??1 ??3 ??4
Table 6.7
??UFPSC The corresponding Subband number of FPi (i＞0) ?UFPSC The corresponding Subband number of FPi (i＞0)
??0 ??0 ??2 ??3
??1 ??1 ??3 ??4
Table 6.8
??UFPSC The corresponding Subband number of FPi (i＞0) ?UFPSC The corresponding Subband number of FPi (i＞0)
??0 ??1 ??2 ??3
??1 ??2 ??3 ??4
Table 6.9
??UFPSC The corresponding Subband number of FPi (i＞0) ?UFPSC The corresponding Subband number of FPi (i＞0)
??0 ??0 ??2 ??3
??1 ??2 ??3 ??4
Perhaps, when system bandwidth was 7MHz or 8.75MHz or 10MHz, the required bit number of indication UFPSC parameter was 3bits.The corresponding relation of the Subband number of the frequency partition that the value of UFPSC is corresponding with it.For example, shown in the table 6.10.
Table 6.10
??UFPSC The corresponding Subband number of FPi (i＞0) ?UFPSC The corresponding Subband number of FPi (i＞0)
??0 ??0 ??4 ??4
??1 ??1 ??5 Keep
??2 ??2 ??6 Keep
??3 ??3 ??7 Keep
The 3rd class: when system bandwidth was 20MHz, the required bit number of indication UFPSC parameter was 2bits.
For 20MHz, the set of the number of the Subband that may indicate of UFPSC is: C UFPSC=0,1,2,3,4,5,6,7,8}.2bits represents the number of 4 kinds of different Subband, and the number of these 4 kinds of different Subband is taken from set C UFPSC, be total to C 9 4=126 kinds of combinations.For example, when table 6.11～table 6.14 has been described system bandwidth and is 20MHz, and the required bit number of indication UFPSC is under the situation of 2bits, the corresponding relation of the Subband number of the frequency partition that the value of UFPSC is corresponding with it, and other combination is not enumerated one by one.
Table 6.11
??UFPSC ??FP i(i＞0) corresponding Subband number ?UFPSC ??FP i(i＞0) corresponding Subband number
??0 ??0 ??2 ??2
??1 ??1 ??3 ??3
Table 6.12
??UFPSC ??FP i(i＞0) corresponding Subband number ?UFPSC ??FP i(i＞0) corresponding Subband number
??0 ??0 ??2 ??2
??1 ??1 ??3 ??4
Table 6.13
??UFPSC ??FP i(i＞0) corresponding Subband number ?UFPSC ??FP i(i＞0) corresponding Subband number
??0 ??0 ??2 ??4
??1 ??2 ??3 ??6
Table 6.14
??UFPSC ??FP i(i＞0) corresponding Subband number ?UFPSC ??FP i(i＞0) corresponding Subband number
??0 ??1 ??2 ??3
??1 ??2 ??3 ??4
Perhaps, when system bandwidth was 20MHz, the required bit number of indication UFPSC parameter was 3bits.3bits represents the number of 8 kinds of different Subband, and the number of these 4 kinds of different Subband is taken from set C UFPSC, be total to C 9 8=9 kinds of combinations.For example, when table 6.15～table 6.17 has been described bit number and has been 3bits, the corresponding relation of the Subband number of the frequency partition that the value of UFPSC is corresponding with it, other combination is not enumerated one by one.
Table 6.15
??UFPSC ??FP i(i＞0) corresponding Subband number ?UFPSC ??FP i(i＞0) corresponding Subband number
??0 ??0 ??4 ??4
??1 ??1 ??5 ??5
??2 ??2 ??6 ??6
??3 ??3 ??7 ??7
Table 6.16
??UFPSC ??FP i(i＞0) corresponding Subband number ?UFPSC ??FP i(i＞0) corresponding Subband number
??0 ??0 ??4 ??4
??1 ??1 ??5 ??5
??2 ??2 ??6 ??6
??3 ??3 ??7 ??8
Table 6.17
??UFPSC ??FP i(i＞0) corresponding Subband number ?UFPSC ??FP i(i＞0) corresponding Subband number
??0 ??1 ??4 ??5
??1 ??2 ??5 ??6
??UFPSC ??FP i(i＞0) corresponding Subband number ?UFPSC ??FP i(i＞0) corresponding Subband number
??2 ??3 ??6 ??7
??3 ??4 ??7 ??8
Perhaps, when system bandwidth was 20MHz, the required bit number of indication UFPSC parameter was 4bits.For example, when table 6.18 has been described bit number and has been 4bits, the corresponding relation of the Subband number of the frequency partition that the value of UFPSC is corresponding with it.
Table 6.18
??UFPSC The corresponding Subband number of FPi (i＞0) ?UFPSC The corresponding Subband number of FPi (i＞0)
??0 ??0 ??8 ??8
??1 ??1 ??9 Keep
??2 ??2 ??10 Keep
??3 ??3 ??11 Keep
??4 ??4 ??12 Keep
??5 ??5 ??13 Keep
??6 ??6 ??14 Keep
??7 ??7 ??15 Keep
Can from said method, determine for the required bit number of indication UFPSC parameter under each bandwidth, but, indicate the required bit number of UFPSC the parameter identical or complete difference of part each other for different bandwidth.For example,
When system bandwidth was 5MHz, the required bit number of indication UFPSC parameter was 1bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 2bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 2bits; Perhaps,
When system bandwidth was 5MHz, the required bit number of indication UFPSC parameter was 1bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 2bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 3bits;
When system bandwidth was 5MHz, the required bit number of indication UFPSC parameter was 1bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 2bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits; Perhaps,
When system bandwidth was 5MHz, the required bit number of indication UFPSC parameter was 1bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 3bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 3bits;
When system bandwidth was 5MHz, the required bit number of indication UFPSC parameter was 1bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 3bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits;
When system bandwidth was 5MHz, the required bit number of indication UFPSC parameter was 1bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 4bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits; Perhaps,
When system bandwidth was 5MHz, the required bit number of indication UFPSC parameter was 2bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 2bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 3bits; Perhaps,
When system bandwidth was 5MHz, the required bit number of indication UFPSC parameter was 2bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 2bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits;
When system bandwidth was 5MHz, the required bit number of indication UFPSC parameter was 2bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 3bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 3bits; Perhaps,
When system bandwidth was 5MHz, the required bit number of indication UFPSC parameter was 2bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 3bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits;
When system bandwidth was 5MHz, the required bit number of indication UFPSC parameter was 2bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 4bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits;
It may be noted that: in the collocation method of above-mentioned UFPSC, used identical bit number indication UFPSC parameter when two different bandwidth, corresponding form can be identical or different.For example, when system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 3bits, but corresponding form is a table 6.10; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 3bits, but corresponding form is a table 6.15.
Again for example, when system bandwidth is 10MHz (also can be 7MHz or 8.75MHz) and 20MHz, and indication UFPSC required bit number is under the situation of 3bits, can all adopt one of 20MHz form when needing 3bits indication UFPSC, for example, all be with table 6.15.
In addition; it may be noted that: in the collocation method of above-mentioned UFPSC; at each table; relation in the middle of the meaning of the value of UFPSC and the indication of the value of UFPSC can change; each form all is embodiment; the value that needs only the UFPSC that comprises in the table is that the meaning of indication is identical, all is regarded as identical table, all within protection range.For example, table 6.19 all is considered as identical table with table 6.15, is identical because the value of the UFPSC that comprises in two tables is the meaning of indication.
Table 6.19
??UFPSC ??FP i(i＞0) corresponding Subband number ?UFPSC ??FP i(i＞0) corresponding Subband number
??0 ??0 ??4 ??4
??1 ??1 ??5 ??5
??UFPSC ??FP i(i＞0) corresponding Subband number ?UFPSC ??FP i(i＞0) corresponding Subband number
??2 ??2 ??6 ??7
??3 ??3 ??7 ??6
Other form of listing and produce by said method but all do not follow this principle at this form of listing.
By above-mentioned example 6, as can be seen, when system bandwidth is respectively 5MHz, 10MHz (can be 7MHz or 8.75MHz), 20MHz system, the bit number of indication UFPSC needs 1bits, 2bits, 2bits respectively, perhaps need 2bits, 3bits, 3bits respectively, when perhaps needing 2bits, 3bits, 4bits or other combination respectively, under the situation that the possible value of UFPSC reduces, deleted redundant and unnecessary information indication, save overhead bit, and guaranteed certain flexibility.
Descending CRU allotment (DCAS based on Subband SB) collocation method
Example 7
DCAS SBiIt with Subband the number that unit has indicated CRU in the individual frequency partition of i (i 〉=0) and/or DRU.DCAS SBiWhen getting different values, descending CRU/DRUAllocation process is different, as shown in figure 16.
Be that 5MHz, 7MHz, 8.75MHz, 10MHz and 20MHz are example below with the system bandwidth, and be divided into three class bandwidth DCAS SBiConfiguring condition describe, the first kind is 5MHz, second class is 7MHz or 8.75MHz or 10MHz, the 3rd class is 20MHz.
The first kind: when system bandwidth is 5MHz, indication DCAS SBiThe required bit number of parameter is 2bits.
For 5MHz, DCAS SBiBe that unit has indicated the number possible number set of CRU in i the frequency partition and/or DRU to be with Subband:
Figure B2009101305580D0000991
Figure B2009101305580D0000992
2bits represents 4 different numbers, and these 4 different numbers are taken from set
Figure B2009101305580D0000993
Be total to C 7 4=35 kinds of combinations.DCAS SBiFor example can adopt any one combination, a kind of in shown in table 7.1～table 7.6, other is similar, enumerates no longer one by one.
Table 7.1
??DCAS SBi ??FP i(i 〉=0) corresponding CRU number ??DCAS ??FP i(i 〉=0) corresponding CRU number
??0 ??0 ??2 ??2
??1 ??1 ??3 ??3
Table 7.2
??DCAS SBi ??FP i(i 〉=0) corresponding CRU number ??DCAS ??FP i(i 〉=0) corresponding CRU number
??0 ??0 ??2 ??4
??1 ??2 ??3 ??6
Table 7.3
??DCAS SBi ??FP i(i 〉=0) corresponding CRU number ??DCAS ??FP i(i 〉=0) corresponding CRU number
??0 ??0 ??2 ??3
??1 ??2 ??3 ??4
Table 7.4
??DCAS SBi ??FP i(i 〉=0) corresponding CRU number ??DCAS ??FP i(i 〉=0) corresponding CRU number
??0 ??1 ??2 ??3
??1 ??2 ??3 ??4
Table 7.5
??DCAS SBi ??FP i(i 〉=0) corresponding CRU number ??DCAS ??FP i(i 〉=0) corresponding CRU number
??0 ??0 ??2 ??2
??1 ??1 ??3 ??6
Table 7.6
??DCAS SBi ??FP i(i 〉=0) corresponding CRU number ??DCAS ??FP i(i 〉=0) corresponding CRU number
??0 ??0 ??2 ??2
??1 ??1 ??3 ??4
Perhaps, when system bandwidth is 5MHz, indication DCAS SBiThe required bit number of parameter is 3bits.3bits represents 8 different numbers, can represent set In all numerical value.Shown in 7.7.
Table 7.7
??DCAS SBi ??FP i(i 〉=0) corresponding CRU number ??DCAS ??FP i(i 〉=0) corresponding CRU number
??0 ??0 ??4 ??4
??1 ??1 ??5 ??5
??2 ??2 ??6 ??6
??DCAS SBi ??FP i(i 〉=0) corresponding CRU number ??DCAS ??FP i(i 〉=0) corresponding CRU number
??3 ??3 ??7 Keep
Second class: when system bandwidth is 7MHz or 8.75MHz or 10MHz, indication DCAS SBiThe required bit number of parameter is 2bits.
For 7MHz or 8.75MHz or 10MHz, DCAS SBiBe that unit has indicated the number possible number set of CRU in i the frequency partition and/or DRU to be with Subband:
Figure B2009101305580D0001011
2bits represents 4 different numbers, and these 4 different numbers are taken from set
Figure B2009101305580D0001012
Be total to C 13 4=715 kinds of combinations.DCAS SBiCan adopt any one combination.For example, a kind of in shown in table 7.8～table 7.9, other is similar, enumerates no longer one by one.
Table 7.8
??DCAS SBi ??FP i(i 〉=0) corresponding CRU number ??DCAS ??FP i(i 〉=0) corresponding CRU number
??0 ??0 ??2 ??2
??1 ??1 ??3 ??4
Table 7.9
??DCAS SBi ??FP i(i 〉=0) corresponding CRU number ??DCAS ??FP i(i 〉=0) corresponding CRU number
??0 ??0 ??2 ??4
??1 ??2 ??3 ??6
Perhaps, when system bandwidth is 7MHz or 8.75MHz or 10MHz, indication DCAS SBiThe required bit number of parameter is 3bits.3bits represents 8 different numbers, and these 8 different numbers are taken from set
Figure B2009101305580D0001013
Be total to C 13 8=1287 kinds of combinations.DCAS SBiFor example can adopt any one combination, a kind of in shown in table 7.10～table 7.13, other is similar, enumerates no longer one by one.
Table 7.10
??DCAS SBi ??FP i(i＞0) corresponding CRU number ?DCAS SBi ??FP i(i＞0) corresponding CRU number
??0 ??0 ??4 ??4
??1 ??1 ??5 ??5
??2 ??2 ??6 ??6
??DCAS SBi ??FP i(i＞0) corresponding CRU number ?DCAS SBi ??FP i(i＞0) corresponding CRU number
??3 ??3 ??7 ??7
Table 7.11
??DCAS SBi ??FP i(i＞0) corresponding CRU number ?DCAS SBi ??FP i(i＞0) corresponding CRU number
??0 ??0 ??4 ??4
??1 ??1 ??5 ??5
??2 ??2 ??6 ??6
??3 ??3 ??7 ??8
Table 7.12
??DCAS SBi ??FP i(i＞0) corresponding CRU number ?DCAS SBi ??FP i(i＞0) corresponding CRU number
??0 ??1 ??4 ??5
??1 ??2 ??5 ??6
??2 ??3 ??6 ??7
??3 ??4 ??7 ??8
Table 7.13
??DCAS SBi ??FP i(i＞0) corresponding CRU number ?DCAS SBi ??FP i(i＞0) corresponding CRU number
??0 ??0 ??4 ??4
??1 ??1 ??5 ??6
??2 ??2 ??6 ??8
??3 ??3 ??7 ??12
Perhaps, when system bandwidth is 7MHz or 8.75MHz or 10MHz, indication DCAS SBiThe required bit number of parameter is 4bits.4bits represents 16 different numbers, can represent set
Figure B2009101305580D0001021
In all numerical value.For example, shown in table 7.14.
Table 7.14
??DCAS SBi ??FP i(i＞0) corresponding CRU number ??DCAS SBi ??FP i(i＞0) corresponding CRU number
??0 ??0 ??8 ??8
??1 ??1 ??9 ??9
??2 ??2 ??10 ??10
??3 ??3 ??11 ??11
??4 ??4 ??12 ??12
??5 ??5 ??13 Keep
??6 ??6 ??14 Keep
?7 ??7 ??15 Keep
The 3rd class: when system bandwidth is 20MHz, indication DCAS SBiThe required bit number of parameter is 3bits.
For 20MHz, DCAS SBiBe that unit has indicated the number possible number set of CRU in i the frequency partition and/or DRU to be with Subband:
Figure B2009101305580D0001031
Figure B2009101305580D0001032
3bits represents 8 different numbers, and these 8 different numbers are taken from set
Figure B2009101305580D0001033
Be total to C 25 8=1081575 kinds of combinations.DCAS SBiCan adopt any one combination.For example, a kind of in shown in table 7.15～table 7.21, other is similar, enumerates no longer one by one.
Table 7.15
??DCAS SBi ??FP i(i＞0) corresponding CRU number ?DCAS SBi ??FP i(i＞0) corresponding CRU number
??0 ??0 ??4 ??4
??1 ??1 ??5 ??5
??2 ??2 ??6 ??6
??3 ??3 ??7 ??7
Table 7.16
??DCAS SBi ??FP i(i＞0) corresponding CRU number ?DCAS SBi ??FP i(i＞0) corresponding CRU number
??0 ??0 ??4 ??4
??1 ??1 ??5 ??6
??2 ??2 ??6 ??8
??3 ??3 ??7 ??10
Table 7.17
??DCAS SBi ??FP i(i＞0) corresponding CRU number ??DCAS SBi FP i(i＞0) corresponding CRU number
??0 ??0 ??4 ??6
??1 ??1 ??5 ??8
??2 ??2 ??6 ??10
??3 ??4 ??7 ??12
Table 7.18
??DCAS SBi ??FP i(i＞0) corresponding CRU number ??DCAS SBi ??FP i(i＞0) corresponding CRU number
??0 ??0 ??4 ??8
??1 ??2 ??5 ??10
??2 ??4 ??6 ??12
??3 ??6 ??7 ??14
Table 7.18
??DCAS SBi ??FP i(i＞0) corresponding CRU number ?DCAS SBi ??FP i(i＞0) corresponding CRU number
??0 ??0 ??4 ??8
??1 ??2 ??5 ??10
??2 ??4 ??6 ??12
??DCAS SBi ??FP i(i＞0) corresponding CRU number ?DCAS SBi ??FP i(i＞0) corresponding CRU number
??3 ??6 ??7 ??14
Table 7.19
??DCAS SBi ??FP i(i＞0) corresponding CRU number ??DCAS SBi ??FP i(i＞0) corresponding CRU number
??0 ??0 ??4 ??8
??1 ??2 ??5 ??10
??2 ??4 ??6 ??12
??3 ??6 ??7 ??24
Table 7.20
??DCAS SBi ??FP i(i＞0) corresponding CRU number ?DCAS SBi ??FP i(i＞0) corresponding CRU number
??0 ??1 ??4 ??5
??1 ??2 ??5 ??6
??2 ??3 ??6 ??7
??3 ??4 ??7 ??8
Table 7.21
??DCAS SBi ??FP i(i＞0) corresponding CRU number ??DCAS SBi ??FP i(i＞0) corresponding CRU number
??0 ??1 ??4 ??6
??1 ??2 ??5 ??8
??2 ??3 ??6 ??10
??3 ??4 ??7 ??12
Perhaps, when system bandwidth is 20MHz, indication DCAS SBiThe required bit number of parameter is 4bits.4bits represents 16 different numbers, and these 16 different numbers are taken from set
Figure B2009101305580D0001051
Be total to C 25 16=2042975 kinds of combinations.DCAS SBiCan adopt any one combination.For example, a kind of in shown in table 7.22～table 7.25, other is similar, enumerates no longer one by one.
Table 7.22
??DCAS SBi ??FP i(i＞0) corresponding CRU number ??DCAS SBi ??FP i(i＞0) corresponding CRU number
??0 ??0 ??8 ??10
??1 ??1 ??9 ??12
??2 ??2 ??10 ??14
??3 ??3 ??11 ??16
??4 ??4 ??12 ??18
??5 ??5 ??13 ??20
??6 ??6 ??14 ??22
??7 ??8 ??15 ??24
Table 7.23
??DCAS SBi ??FP i(i＞0) corresponding CRU number ?DCAS SBi ??FP i(i＞0) corresponding CRU number
??0 ??0 ??8 ??8
??1 ??1 ??9 ??9
??2 ??2 ??10 ??10
??3 ??3 ??11 ??11
??4 ??4 ??12 ??12
??5 ??5 ??13 ??13
??6 ??6 ??14 ??14
??7 ??7 ??15 ??15
Table 7.24
??DCAS SBi FP i(i＞0) corresponding CRU number ??DCAS SBi ??FP i(i＞0) corresponding CRU number
??0 ??1 ??8 ??9
??DCAS SBi FP i(i＞0) corresponding CRU number ??DCAS SBi ??FP i(i＞0) corresponding CRU number
??1 ??2 ??9 ??10
??2 ??3 ??10 ??11
??3 ??4 ??11 ??12
??4 ??5 ??12 ??13
??5 ??6 ??13 ??14
??6 ??7 ??14 ??15
??7 ??8 ??15 ??16
Table 7.25
??DCAS SBi ??FP i(i＞0) corresponding CRU number ??DCAS SBi ??FP i(i＞0) corresponding CRU number
??0 ??1 ??8 ??10
??1 ??2 ??9 ??12
??2 ??3 ??10 ??14
??3 ??4 ??11 ??16
??4 ??5 ??12 ??18
??5 ??6 ??13 ??20
??6 ??7 ??14 ??22
??7 ??8 ??15 ??24
Perhaps, when system bandwidth is 20MHz, indication DCAS SBiThe required bit number of parameter is 5bits.5bits represents 32 different numbers, and these 32 different numbers can be represented set
Figure B2009101305580D0001061
In all numerical value.For example, shown in the table 7.26.
Table 7.26
??DCAS SBi FP i(i＞0) corresponding CRU number ??DCAS SBi ??FP i(i＞0) corresponding CRU number
??0 ??1 ??16 ??17
??1 ??2 ??17 ??18
??2 ??3 ??18 ??19
??3 ??4 ??19 ??20
??4 ??5 ??20 ??21
??5 ??6 ??21 ??22
??6 ??7 ??22 ??23
??7 ??8 ??23 ??24
??8 ??9 ??24 Keep
??9 ??10 ??25 Keep
??10 ??11 ??26 Keep
??11 ??12 ??27 Keep
??12 ??13 ??28 Keep
??13 ??14 ??29 Keep
??14 ??15 ??30 Keep
??15 ??16 ??31 Keep
For indicating DCAS under each bandwidth SBiThe required bit number of parameter can be determined from said method, but for different bandwidth, indicate DCAS SBiThe required bit number of parameter is the identical or complete difference of part each other.For example,
When system bandwidth is 5MHz, indication DCAS SBiThe required bit number of parameter is 1bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 2bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 2bits; Perhaps,
When system bandwidth is 5MHz, indication DCAS SBiThe required bit number of parameter is 1bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 2bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 3bits;
When system bandwidth is 5MHz, indication DCAS SBiThe required bit number of parameter is 1bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 2bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits; Perhaps,
When system bandwidth is 5MHz, indication DCAS SBiThe required bit number of parameter is 1bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 3bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 3bits;
When system bandwidth is 5MHz, indication DCAS SBiThe required bit number of parameter is 1bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 3bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits;
When system bandwidth is 5MHz, indication DCAS SBiThe required bit number of parameter is 1bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 4bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits; Perhaps,
When system bandwidth is 5MHz, indication DCAS SBiThe required bit number of parameter is 2bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 2bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 3bits; Perhaps,
When system bandwidth is 5MHz, indication DCAS SBiThe required bit number of parameter is 2bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 2bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits;
When system bandwidth is 5MHz, indication DCAS SBiThe required bit number of parameter is 2bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 3bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 3bits; Perhaps,
When system bandwidth is 5MHz, indication DCAS SBiThe required bit number of parameter is 2bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 3bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits;
When system bandwidth is 5MHz, indication DCAS SBiThe required bit number of parameter is 2bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 4bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits;
It may be noted that: at above-mentioned DCAS SBiCollocation method in, when two different bandwidth have been used identical bit number indication DCAS SBiParameter, corresponding form can be identical or different.For example, when system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 4bits, but corresponding form is a table 7.14; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits, but corresponding form is a table 7.23.
Identical form is meant: to be that the situation of 20MHz is more similar can consider the characteristics of 10MHz (can be 7MHz or 8.75MHz) and 20MHz are unified because system bandwidth is 10MHz (can be 7MHz or 8.75MHz) and system bandwidth, can be with system bandwidth 10MHz (can be 7MHz or 8.75MHz) with system bandwidth the identical DCAS of employing during for 20MHz SBiValue and corresponding relation, that is, system bandwidth is that 10MHz (can be 7MHz or 8.75MHz) adopts identical form during for 20MHz with system bandwidth, for example, can adopt in table 7.22～table 7.25, the collocation method during perhaps according to 20MHz produces.Perhaps, produce according to the methods below:
Table 7.27
Figure B2009101305580D0001091
In addition, 5MHz can all adopt 2 bits or 3 bits with 10MHz (also can be 7MHz or 8.75MHz).
In addition, it may be noted that: at above-mentioned DCAS SBiCollocation method in, at each table, DCAS SBiValue and DCAS SBiThe meaning of value indication in the middle of relation can change, each form all is embodiment, as long as the DCAS that comprises in table SBiValue be the indication meaning be identical, all be regarded as identical table, all within protection range.
By above-mentioned example 7, as can be seen, when system bandwidth is respectively 5MHz, 10MHz (can be 7MHz or 8.75MHz), 20MHz system, indication DCAS SBiBit number need 2bits, 3bits, 3bits respectively, at DCAS SBiPossible value situation about reducing under, deleted that redundant and unnecessary information indicates, saved overhead bit, and guaranteed certain flexibility.
UCAS SBiWith Subband the number that unit has indicated CRU in i the frequency partition and/or DRU, as shown in figure 11, UCAS SBiWhen getting different values, descending CRU/DRU AUocation process is different.
Up CRU allotment (UCAS based on Subband SB) collocation method
Example 8
UCAS SBiIt with Subband the number that unit has indicated CRU in the individual frequency partition of i (i 〉=0) and/or DRU.UCAS SBiWhen getting different values, up CRU/DRUAllocation process is different, as shown in figure 17.
Be that 5MHz, 7MHz, 8.75MHz, 10MHz and 20MHz are example below with the system bandwidth, and be divided into three class bandwidth UCAS SBiConfiguring condition describe, the first kind is 5MHz, second class is 7MHz or 8.75MHz or 10MHz, the 3rd class is 20MHz.
The first kind: when system bandwidth is 5MHz, indication UCAS SBiThe required bit number of parameter is 2bits.
For 5MHz, UCAS SBiBe that unit has indicated the number possible number set of CRU in i the frequency partition and/or DRU to be with Subband:
Figure B2009101305580D0001111
Figure B2009101305580D0001112
2bits represents 4 different numbers, and these 4 different numbers are taken from set
Figure B2009101305580D0001113
Be total to C 7 4=35 kinds of combinations.UCAS SBiFor example can adopt any one combination, a kind of in shown in table 8.1～table 8.6, other is similar, enumerates no longer one by one.
Table 8.1
??UCAS SBi ??FP i(i 〉=0) corresponding CRU number ??UCAS ??FP i(i 〉=0) corresponding CRU number
??0 ??0 ??2 ??2
??1 ??1 ??3 ??3
Table 8.2
??UCAS SBi ??FP i(i 〉=0) corresponding CRU number ??UCAS ??FP i(i 〉=0) corresponding CRU number
??0 ??0 ??2 ??4
??1 ??2 ??3 ??6
Table 8.3
??UCAS SBi ??FP i(i 〉=0) corresponding CRU number ??UCAS ??FP i(i 〉=0) corresponding CRU number
??0 ??0 ??2 ??3
??1 ??2 ??3 ??4
Table 8.4
??UCAS SBi ??FP i(i 〉=0) corresponding CRU number ??UCAS ??FP i(i 〉=0) corresponding CRU number
??0 ??1 ??2 ??3
??1 ??2 ??3 ??4
Table 8.5
??UCAS SBi ??FP i(i 〉=0) corresponding CRU number ??UCAS ??FP i(i 〉=0) corresponding CRU number
??0 ??0 ??2 ??2
??UCAS SBi ??FP i(i 〉=0) corresponding CRU number ??UCAS ??FP i(i 〉=0) corresponding CRU number
??1 ??1 ??3 ??6
Table 8.6
??UCAS SBi ??FP i(i 〉=0) corresponding CRU number ??UCAS ??FP i(i 〉=0) corresponding CRU number
??0 ??0 ??2 ??2
??1 ??1 ??3 ??4
Perhaps, when system bandwidth is 5MHz, indication UCAS SBiThe required bit number of parameter is 3bits.3bits represents 8 different numbers, can represent set
Figure B2009101305580D0001121
In all numerical value.Shown in 8.7.
Table 8.7
??UCAS SBi ??FP i(i 〉=0) corresponding CRU number ??UCAS ??FP i(i 〉=0) corresponding CRU number
??0 ??0 ??4 ??4
??1 ??1 ??5 ??5
??2 ??2 ??6 ??6
??3 ??3 ??7 Keep
Second class: when system bandwidth is 7MHz or 8.75MHz or 10MHz, indication UCAS SBiThe required bit number of parameter is 2bits.
For 7MHz or 8.75MHz or 10MHz, UCAS SBiBe that unit has indicated the number possible number set of CRU in i the frequency partition and/or DRU to be with Subband: 2bits represents 4 different numbers, and these 4 different numbers are taken from set
Figure B2009101305580D0001123
Be total to C 13 4=715 kinds of combinations.UCAS SbiCan adopt any one combination.For example, a kind of in shown in table 8.8～table 8.9, other is similar, enumerates no longer one by one.
Table 8.8
??UCAS SBi ??FP i(i 〉=0) corresponding CRU number ??UCAS ??FP i(i 〉=0) corresponding CRU number
??0 ??0 ??2 ??2
??1 ??1 ??3 ??4
Table 8.9
??UCAS SBi ??FP i(i 〉=0) corresponding CRU number ??UCAS ??FP i(i 〉=0) corresponding CRU number
??0 ??0 ??2 ??4
??1 ??2 ??3 ??6
Perhaps, when system bandwidth is 7MHz or 8.75MHz or 10MHz, indication UCAS SBiThe required bit number of parameter is 3bits.3bits represents 8 different numbers, and these 8 different numbers are taken from set
Figure B2009101305580D0001131
Be total to C 13 8=1287 kinds of combinations.UCAS SBiFor example can adopt any one combination, a kind of in shown in table 8.10～table 8.13, other is similar, enumerates no longer one by one.
Table 8.10
??UCAS SBi ??FP i(i＞0) corresponding CRU number ?UCAS SBi ??FP i(i＞0) corresponding CRU number
??0 ??0 ??4 ??4
??1 ??1 ??5 ??5
??2 ??2 ??6 ??6
??3 ??3 ??7 ??7
Table 8.11
??UCAS SBi FP i(i＞0) corresponding CRU number ?UCAS SBi ??FP i(i＞0) corresponding CRU number
??0 ??0 ??4 ??4
??1 ??1 ??5 ??5
??2 ??2 ??6 ??6
??3 ??3 ??7 ??8
Table 8.12
??UCAS SBi ??FP i(i＞0) corresponding CRU number ??UCAS SBi ??FP i(i＞0) corresponding CRU number
??0 ??1 ??4 ??5
??1 ??2 ??5 ??6
??UCAS SBi ??FP i(i＞0) corresponding CRU number ??UCAS SBi ??FP i(i＞0) corresponding CRU number
??2 ??3 ??6 ??7
??3 ??4 ??7 ??8
Table 8.13
??UCAS SBi ??FP i(i＞0) corresponding CRU number ??UCAS SBi ??FP i(i＞0) corresponding CRU number
??0 ??0 ??4 ??4
??1 ??1 ??5 ??6
??2 ??2 ??6 ??8
??3 ??3 ??7 ??12
Perhaps, when system bandwidth is 7MHz or 8.75MHz or 10MHz, indication UCAS SBiThe required bit number of parameter is 4bits.4bits represents 16 different numbers, can represent set
Figure B2009101305580D0001141
In all numerical value.For example, shown in table 8.14.
Table 8.14
??UCAS SBi ??FP i(i＞0) corresponding CRU number ?UCAS SBi ??FP i(i＞0) corresponding CRU number
??0 ??0 ??8 ??8
??1 ??1 ??9 ??9
??2 ??2 ??10 ??10
??3 ??3 ??11 ??11
??4 ??4 ??12 ??12
??5 ??5 ??13 Keep
??6 ??6 ??14 Keep
??7 ??7 ??15 Keep
The 3rd class: when system bandwidth is 20MHz, indication UCAS SBiThe required bit number of parameter is 3bits.
For 20MHz, UCAS SBiBe that unit has indicated the number possible number set of CRU in i the frequency partition and/or DRU to be with Subband:
Figure B2009101305580D0001142
Figure B2009101305580D0001143
3bits represents 8 different numbers, and these 8 different numbers are taken from set
Figure B2009101305580D0001144
Be total to C 25 8=1081575 kinds of combinations.UCAS SBiCan adopt any one combination.For example, a kind of in shown in table 8.15～table 8.21, other is similar, enumerates no longer one by one.
Table 8.15
??UCAS SBi ??FP i(i＞0) corresponding CRU number ?UCAS SBi ??FP i(i＞0) corresponding CRU number
??0 ??0 ??4 ??4
??1 ??1 ??5 ??5
??2 ??2 ??6 ??6
??3 ??3 ??7 ??7
Table 8.16
??UCAS SBi ??FP i(i＞0) corresponding CRU number ??UCAS SBi ??FP i(i＞0) corresponding CRU number
??0 ??0 ??4 ??4
??1 ??1 ??5 ??6
??2 ??2 ??6 ??8
??3 ??3 ??7 ??10
Table 8.17
??UCAS SBi ??FP i(i＞0) corresponding CRU number ??UCAS SBi ??FP i(i＞0) corresponding CRU number
??0 ??0 ??4 ??6
??1 ??1 ??5 ??8
??2 ??2 ??6 ??10
??3 ??4 ??7 ??12
Table 8.18
??UCAS SBi ??FP i(i＞0) corresponding CRU number ??UCAS SBi ??FP i(i＞0) corresponding CRU number
??0 ??0 ??4 ??8
??1 ??2 ??5 ??10
??2 ??4 ??6 ??12
??3 ??6 ??7 ??14
Table 8.18
??UCAS SBi ??FP i(i＞0) corresponding CRU number ?UCAS SBi ??FP i(i＞0) corresponding CRU number
??0 ??0 ??4 ??8
??1 ??2 ??5 ??10
??2 ??4 ??6 ??12
??3 ??6 ??7 ??14
Table 8.19
??UCAS SBi ??FP i(i＞0) corresponding CRU number ?UCAS SBi ??FP i(i＞0) corresponding CRU number
??0 ??0 ??4 ??8
??1 ??2 ??5 ??10
??2 ??4 ??6 ??12
??3 ??6 ??7 ??24
Table 8.20
??UCAS SBi ??FP i(i＞0) corresponding CRU number ??UCAS SBi ??FP i(i＞0) corresponding CRU number
??0 ??1 ??4 ??5
??1 ??2 ??5 ??6
??2 ??3 ??6 ??7
??UCAS SBi ??FP i(i＞0) corresponding CRU number ??UCAS SBi ??FP i(i＞0) corresponding CRU number
??3 ??4 ??7 ??8
Table 8.21
??UCAS SBi ??FP i(i＞0) corresponding CRU number ??UCAS SBi ??FP i(i＞0) corresponding CRU number
??0 ??1 ??4 ??6
??1 ??2 ??5 ??8
??2 ??3 ??6 ??10
??3 ??4 ??7 ??12
Perhaps, when system bandwidth is 20MHz, indication UCAS SBiThe required bit number of parameter is 4bits.4bits represents 16 different numbers, and these 16 different numbers are taken from set
Figure B2009101305580D0001161
Be total to C 25 16=2042975 kinds of combinations.UCAS SBiCan adopt any one combination.For example, a kind of in shown in table 8.22～table 8.25, other is similar, enumerates no longer one by one.
Table 8.22
??UCAS SBi ??FP i(i＞0) corresponding CRU number ??UCAS SBi ??FP i(i＞0) corresponding CRU number
??0 ??0 ??8 ??10
??1 ??1 ??9 ??12
??2 ??2 ??10 ??14
??3 ??3 ??11 ??16
??4 ??4 ??12 ??18
??5 ??5 ??13 ??20
??6 ??6 ??14 ??22
??7 ??8 ??15 ??24
Table 8.23
??UCAS SBi ??FP i(i＞0) corresponding CRU number ?UCAS SBi ??FP i(i＞0) corresponding CRU number
??0 ??0 ??8 ??8
??UCAS SBi ??FP i(i＞0) corresponding CRU number ?UCAS SBi ??FP i(i＞0) corresponding CRU number
??1 ??1 ??9 ??9
??2 ??2 ??10 ??10
??3 ??3 ??11 ??11
??4 ??4 ??12 ??12
??5 ??5 ??13 ??13
??6 ??6 ??14 ??14
??7 ??7 ??15 ??15
Table 8.24
??UCAS SBi ??FP i(i＞0) corresponding CRU number ?UCAS SBi ??FP i(i＞0) corresponding CRU number
??0 ??1 ??8 ??9
??1 ??2 ??9 ??10
??2 ??3 ??10 ??11
??3 ??4 ??11 ??12
??4 ??5 ??12 ??13
??5 ??6 ??13 ??14
??6 ??7 ??14 ??15
??7 ??8 ??15 ??16
Table 8.25
??UCAS SBi ??FP i(i＞0) corresponding CRU number ?UCAS SBi ??FP i(i＞0) corresponding CRU number
??0 ??1 ??8 ??10
??1 ??2 ??9 ??12
??2 ??3 ??10 ??14
??UCAS SBi ??FP i(i＞0) corresponding CRU number ?UCAS SBi ??FP i(i＞0) corresponding CRU number
??3 ??4 ??11 ??16
??4 ??5 ??12 ??18
??5 ??6 ??13 ??20
??6 ??7 ??14 ??22
??7 ??8 ??15 ??24
Perhaps, when system bandwidth is 20MHz, indication UCAS SBiThe required bit number of parameter is 5bits.5bits represents 32 different numbers, and these 32 different numbers can be represented set
Figure B2009101305580D0001171
In all numerical value.For example, shown in the table 8.26.
Table 8.26
??UCAS SBi ??FP i(i＞0) corresponding CRU number ?UCAS SBi ??FP i(i＞0) corresponding CRU number
??0 ??1 ??16 ??17
??1 ??2 ??17 ??18
??2 ??3 ??18 ??19
??3 ??4 ??19 ??20
??4 ??5 ??20 ??21
??5 ??6 ??21 ??22
??6 ??7 ??22 ??23
??7 ??8 ??23 ??24
??8 ??9 ??24 Keep
??9 ??10 ??25 Keep
??10 ??11 ??26 Keep
??11 ??12 ??27 Keep
??12 ??13 ??28 Keep
??UCAS SBi ??FP i(i＞0) corresponding CRU number ?UCAS SBi ??FP i(i＞0) corresponding CRU number
??13 ??14 ??29 Keep
??14 ??15 ??30 Keep
??15 ??16 ??31 Keep
For indicating UCAS under each bandwidth SBiThe required bit number of parameter can be determined from said method, but for different bandwidth, indicate UCAS SBiThe required bit number of parameter is the identical or complete difference of part each other.For example,
When system bandwidth is 5MHz, indication UCAS SBiThe required bit number of parameter is 1bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 2bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 2bits; Perhaps,
When system bandwidth is 5MHz, indication UCAS SBiThe required bit number of parameter is 1bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 2bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 3bits;
When system bandwidth is 5MHz, indication UCAS SBiThe required bit number of parameter is 1bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 2bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits; Perhaps,
When system bandwidth is 5MHz, indication UCAS SBiThe required bit number of parameter is 1bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 3bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 3bits;
When system bandwidth is 5MHz, indication UCAS SBiThe required bit number of parameter is 1bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 3bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits;
When system bandwidth is 5MHz, indication UCAS SBiThe required bit number of parameter is 1bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 4bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits; Perhaps,
When system bandwidth is 5MHz, indication UCAS SBiThe required bit number of parameter is 2bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 2bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 3bits; Perhaps,
When system bandwidth is 5MHz, indication UCAS SBiThe required bit number of parameter is 2bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 2bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits;
When system bandwidth is 5MHz, indication UCAS SBiThe required bit number of parameter is 2bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 3bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 3bits; Perhaps,
When system bandwidth is 5MHz, indication UCAS SBiThe required bit number of parameter is 2bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 3bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits;
When system bandwidth is 5MHz, indication UCAS SBiThe required bit number of parameter is 2bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 4bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits;
It may be noted that: at above-mentioned UCAS SBiCollocation method in, when two different bandwidth have been used identical bit number indication UCAS SBiParameter, corresponding form can be identical or different.For example, when system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 4bits, but corresponding form is a table 8.14; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits, but corresponding form is a table 8.23.
Identical form is meant: to be that the situation of 20MHz is more similar can consider the characteristics of 10MHz (can be 7MHz or 8.75MHz) and 20MHz are unified because system bandwidth is 10MHz (can be 7MHz or 8.75MHz) and system bandwidth, can be with system bandwidth 10MHz (can be 7MHz or 8.75MHz) with system bandwidth the identical UCAS of employing during for 20MHz SBiValue and corresponding relation, that is, system bandwidth is that 10MHz (can be 7MHz or 8.75MHz) adopts identical form during for 20MHz with system bandwidth, for example, can adopt in table 8.22～table 8.25, the collocation method during perhaps according to 20MHz produces.Perhaps, produce according to the methods below:
Table 8.27
Figure B2009101305580D0001211
In addition, 5MHz can all adopt 2 bits or 3 bits with 10MHz (also can be 7MHz or 8.75MHz).
In addition, it may be noted that: at above-mentioned UCAS SBiCollocation method in, at each table, UCAS SBiValue and UCAS SBiThe meaning of value indication in the middle of relation can change, each form all is embodiment, as long as the UCAS that comprises in table SBiValue be the indication meaning be identical, all be regarded as identical table, all within protection range.
By above-mentioned example 8, as can be seen, when system bandwidth is respectively 5MHz, 10MHz (can be 7MHz or 8.75MHz), 20MHz system, indication UCAS SBiBit number need 2bits, 3bits, 3bits respectively, at UCAS SBiPossible value situation about reducing under, deleted that redundant and unnecessary information indicates, saved overhead bit, and guaranteed certain flexibility.
Descending CRU allotment DCAS based on Miniband MBCollocation method
DCAS MBBe that unit has indicated in the 0th frequency partition number based on the CRU of Miniband with Miniband.
Example 9
Be that 5MHz, 7MHz, 8.75MHz, 10MHz and 20MHz are example below with the system bandwidth, and be divided into three class bandwidth DCAS MBConfiguring condition describe, the first kind is 5MHz, second class is 7MHz or 8.75MHz or 10MHz, the 3rd class is 20MHz.
The first kind: indication DCAS MBThe required bit number of parameter is 2bits.
For 5MHz, DCAS MBBe that unit has indicated in the 0th frequency partition number possible number set based on the CRU of Miniband to be with Miniband:
Figure B2009101305580D0001221
Figure B2009101305580D0001222
2bits represents 4 different numbers, and these 4 different numbers are taken from set
Figure B2009101305580D0001223
Be total to C 25 4=12650 kinds of combinations.DCAS MBCan adopt any one combination, for example, a kind of in shown in table 9.1～table 9.3, other is similar, enumerates no longer one by one.
Table 9.1
Figure B2009101305580D0001224
Table 9.2
Figure B2009101305580D0001225
Table 9.3
Perhaps, when system bandwidth is 5MHz, indication DCAS MBThe required bit number of parameter is 3bits.3bits represents 8 different numbers, and these 8 different numbers are taken from set
Figure B2009101305580D0001232
Be total to C 25 8=1081575 kinds of combinations.DCAS MBCan adopt any one combination, for example, a kind of in shown in table 9.4～table 9.10, other is similar, enumerates no longer one by one.
Table 9.4
Figure B2009101305580D0001233
Table 9.5
Figure B2009101305580D0001234
Table 9.6
Figure B2009101305580D0001235
Table 9.7
Figure B2009101305580D0001242
Table 9.8
Figure B2009101305580D0001243
Table 9.9
Figure B2009101305580D0001244
Table 9.10
Figure B2009101305580D0001245
Table 9.11
Figure B2009101305580D0001251
Perhaps, when system bandwidth is 5MHz, indication DCAS MBThe required bit number of parameter is 4bits.4bits represents 16 different numbers, and these 16 different numbers are taken from set
Figure B2009101305580D0001252
Be total to C 25 16=2042975 kinds of combinations.DCAS MBCan adopt any one combination, for example, a kind of in shown in table 9.12～table 9.15, other is similar, enumerates no longer one by one.
Table 9.12
Figure B2009101305580D0001253
Table 9.13
Figure B2009101305580D0001261
Table 9.14
Figure B2009101305580D0001262
Table 9.15
Figure B2009101305580D0001263
Perhaps, when system bandwidth is 5MHz, indication DCAS MBThe required bit number of parameter is 5bits.5bits represents 32 different numbers, and these 32 different numbers can be represented set
Figure B2009101305580D0001264
In all numerical value.For example, shown in the table 9.16.
Table 9.16
??DCAS SBi ??FP i(i＞0) corresponding CRU number ?DCAS SBi ??FP i(i＞0) corresponding CRU number
??0 ??0 ??16 ??16
??1 ??1 ??17 ??17
??2 ??2 ??18 ??18
??3 ??3 ??19 ??19
??4 ??4 ??20 ??20
??5 ??5 ??21 ??21
??6 ??6 ??22 ??22
??7 ??7 ??23 ??23
??8 ??8 ??24 ??24
??9 ??9 ??25 Keep
??10 ??10 ??26 Keep
??11 ??11 ??27 Keep
??DCAS SBi ??FP i(i＞0) corresponding CRU number ?DCAS SBi ??FP i(i＞0) corresponding CRU number
??12 ??12 ??28 Keep
??13 ??13 ??29 Keep
??14 ??14 ??30 Keep
??15 ??15 ??31 Keep
Second class: when system bandwidth is 7MHz or 8.75MHz or 10MHz, indication DCAS MBThe required bit number of parameter is 4bits.
For 7MHz or 8.75MHz or 10MHz, DCAS MBBe that unit has indicated in the 0th frequency partition number possible number set based on the CRU of Miniband to be with Miniband:
Figure B2009101305580D0001271
4bits represents 16 different numbers, and these 16 different numbers are taken from set
Figure B2009101305580D0001272
Be total to C 49 16=3348108992991 kinds of combinations.DCAS MBCan adopt any one combination, for example, a kind of in shown in table 9.17～table 9.20, other is similar, enumerates no longer one by one.
Table 9.17
Figure B2009101305580D0001273
Figure B2009101305580D0001281
Table 9.18
Figure B2009101305580D0001282
Table 9.19
Table 9.20
Figure B2009101305580D0001284
Figure B2009101305580D0001291
Perhaps, when system bandwidth is 7MHz or 8.75MHz or 10MHz, indication DCAS MBThe required bit number of parameter is 5bits.5bits represents 32 different numbers, and these 32 different numbers are taken from set
Figure B2009101305580D0001292
Be total to C 49 32=6499270398159 kinds of combinations.DCAS MBCan adopt any one combination, for example, a kind of in shown in the table 9.21, other is similar, enumerates no longer one by one.
Table 9.21
Figure B2009101305580D0001293
Perhaps, when system bandwidth is 7MHz or 8.75MHz or 10MHz, indication DCAS SBiThe required bit number of parameter is 6bits.6bits represents 64 different numbers, can represent set In all numerical value.For example, shown in table 9.22.
Table 9.22
Figure B2009101305580D0001295
Figure B2009101305580D0001301
The 3rd class: for 20MHz, indication DCAS MBThe required bit number of parameter is 4bits.
DCAS MBBe that unit has indicated in the 0th frequency partition number possible number set based on the CRU of Miniband to be with Miniband:
Figure B2009101305580D0001311
Figure B2009101305580D0001312
4bits represents 16 different numbers, and these 16 different numbers are taken from set
Figure B2009101305580D0001313
Be total to C 97 16=793067310934425856 kinds of combinations.DCAS MBCan adopt any one combination, for example, a kind of in shown in table 9.17～table 9.20, other is similar, enumerates no longer one by one.
Perhaps, when system bandwidth is 20MHz, indication DCAS MBThe required bit number of parameter is 5bits.5bits represents 32 different numbers, and these 32 different numbers are taken from set
Figure B2009101305580D0001314
Be total to C 97 32Plant combination.DCAS MBCan adopt any one combination.For example, a kind of in shown in table 9.23～table 9.25, other is similar, enumerates no longer one by one.
Table 9.23
Figure B2009101305580D0001315
Table 9.24
Figure B2009101305580D0001321
Table 9.25
Figure B2009101305580D0001322
Perhaps, when system bandwidth is 20MHz, indication DCAS MBThe required bit number of parameter is 6bits.6bits represents 64 different numbers, and these 64 different numbers can be represented set
Figure B2009101305580D0001331
In all numerical value.For example, shown in the table 9.26.
Table 9.26
Figure B2009101305580D0001332
Figure B2009101305580D0001341
Perhaps, when system bandwidth is 20MHz, indication DCAS MBThe required bit number of parameter is 7bits.7bits represents 128 different numbers, and these 128 different numbers can be represented set
Figure B2009101305580D0001342
In except that 0 or 1 or 95 or 96 all numerical value.
For indicating DCAS under each bandwidth MBThe required bit number of parameter can be determined from said method, but for different bandwidth, indicate DCAS MBThe required bit number of parameter is the identical or complete difference of part each other.For example,
When system bandwidth is 5MHz, indication DCAS MBThe required bit number of parameter is 2bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 4bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits; Perhaps,
When system bandwidth is 5MHz, indication DCAS MBThe required bit number of parameter is 3bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 4bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits;
When system bandwidth is 5MHz, indication DCAS MBThe required bit number of parameter is 3bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 4bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 5bits; Perhaps,
When system bandwidth is 5MHz, indication DCAS MBThe required bit number of parameter is 3bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 5bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 5bits;
When system bandwidth is 5MHz, indication DCAS MBThe required bit number of parameter is 4bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 4bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 5bits;
When system bandwidth is 5MHz, indication DCAS MBThe required bit number of parameter is 4bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 5bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 5bits; Perhaps,
When system bandwidth is 5MHz, indication DCAS MBThe required bit number of parameter is 4bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 5bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 6bits; Perhaps,
When system bandwidth is 5MHz, indication DCAS MBThe required bit number of parameter is 5bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 6bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 6bits;
When system bandwidth is 5MHz, indication DCAS MBThe required bit number of parameter is 5bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 6bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 7bits; Perhaps,
It may be noted that: at above-mentioned DCAS MBCollocation method in, when two different bandwidth have been used identical bit number indication DCAS MBParameter, corresponding form can be identical or different.For example, when system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 5bits, but corresponding form is a table 9.22; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 5bits, but corresponding form is a table 9.23.
Identical form is meant: to be that the situation of 20MHz is more similar can consider the characteristics of 10MHz (can be 7MHz or 8.75MHz) and 20MHz are unified because system bandwidth is 10MHz (can be 7MHz or 8.75MHz) and system bandwidth, can be with system bandwidth 10MHz (can be 7MHz or 8.75MHz) with system bandwidth the identical DCAS of employing during for 20MHz MBValue and corresponding relation, that is, system bandwidth is that 10MHz (can be 7MHz or 8.75MHz) adopts identical form during for 20MHz with system bandwidth, for example, can adopt in table 9.23～table 9.25, the collocation method during perhaps according to 20MHz produces.Perhaps, produce according to the methods below:
Table 9.27
In addition, 5MHz can all adopt 3 bits or 4 bits or 5 bits with 10MHz (also can be 7MHz or 8.75MHz).
In addition, it may be noted that: at above-mentioned DCAS MBCollocation method in, at each table, DCAS MBValue and DCAS MBThe meaning of value indication in the middle of relation can change, each form all is embodiment, as long as the DCAS that comprises in table MBValue be the indication meaning be identical, all be regarded as identical table, all within protection range.
By above-mentioned example 9, as can be seen, when system bandwidth is respectively 5MHz, 10MHz (can be 7MHz or 8.75MHz), 20MHz system, indication DCAS MBBit number need 4bits, 5bits, 6bits respectively, at DCAS MBPossible value situation about reducing under, deleted that redundant and unnecessary information indicates, saved overhead bit, and guaranteed certain flexibility.
Up CRU allotment UCAS based on Miniband MBCollocation method
UCAS MBBe that unit has indicated in the 0th frequency partition number based on the CRU of Miniband with Miniband.
Example 10
Be that 5MHz, 7MHz, 8.75MHz, 10MHz and 20MHz are example below with the system bandwidth, and be divided into three class bandwidth UCAS MBConfiguring condition describe, the first kind is 5MHz, second class is 7MHz or 8.75MHz or 10MHz, the 3rd class is 20MHz.
The first kind: indication UCAS MBThe required bit number of parameter is 2bits.
For 5MHz, UCAS MBBe that unit has indicated in the 0th frequency partition number possible number set based on the CRU of Miniband to be with Miniband:
Figure B2009101305580D0001372
2bits represents 4 different numbers, and these 4 different numbers are taken from set
Figure B2009101305580D0001373
Be total to C 25 4=12650 kinds of combinations.UCAS MBCan adopt any one combination, for example, a kind of in shown in table 10.1～table 10.3, other is similar, enumerates no longer one by one.
Table 10.1
Figure B2009101305580D0001381
Table 10.2
Table 10.3
Figure B2009101305580D0001383
Perhaps, when system bandwidth is 5MHz, indication UCAS MBThe required bit number of parameter is 3bits.3bits represents 8 different numbers, and these 8 different numbers are taken from set
Figure B2009101305580D0001384
Be total to C 25 8=1081575 kinds of combinations.UCAS MBCan adopt any one combination, for example, a kind of in shown in table 10.4～table 10.10, other is similar, enumerates no longer one by one.
Table 10.4
Figure B2009101305580D0001385
Table 10.5
Figure B2009101305580D0001391
Table 10.6
Figure B2009101305580D0001392
Table 10.7
Figure B2009101305580D0001393
Table 10.8
Figure B2009101305580D0001394
Table 10.9
Figure B2009101305580D0001395
Table 10.10
Figure B2009101305580D0001402
Table 10.11
Figure B2009101305580D0001403
Perhaps, when system bandwidth is 5MHz, indication UCAS MBThe required bit number of parameter is 4bits.4bits represents 16 different numbers, and these 16 different numbers are taken from set
Figure B2009101305580D0001404
Be total to C 25 16=2042975 kinds of combinations.UCAS MBCan adopt any one combination, for example, a kind of in shown in table 10.12～table 10.15, other is similar, enumerates no longer one by one.
Table 10.12
Figure B2009101305580D0001405
Figure B2009101305580D0001411
Table 10.13
Figure B2009101305580D0001412
Table 10.14
Figure B2009101305580D0001413
Table 10.15
Figure B2009101305580D0001414
Figure B2009101305580D0001421
Perhaps, when system bandwidth is 5MHz, indication UCAS MBThe required bit number of parameter is 5bits.5bits represents 32 different numbers, and these 32 different numbers can be represented set
Figure B2009101305580D0001422
In all numerical value.For example, shown in the table 10.16.
Table 10.16
??UCAS SBi ??FP i(i＞0) corresponding CRU number ?UCAS SBi ??FP i(i＞0) corresponding CRU number
??0 ??0 ??16 ??16
??1 ??1 ??17 ??17
??2 ??2 ??18 ??18
??3 ??3 ??19 ??19
??4 ??4 ??20 ??20
??5 ??5 ??21 ??21
??6 ??6 ??22 ??22
??7 ??7 ??23 ??23
??8 ??8 ??24 ??24
??9 ??9 ??25 Keep
??10 ??10 ??26 Keep
??11 ??11 ??27 Keep
??UCAS SBi ??FP i(i＞0) corresponding CRU number ?UCAS SBi ??FP i(i＞0) corresponding CRU number
??12 ??12 ??28 Keep
??13 ??13 ??29 Keep
??14 ??14 ??30 Keep
??15 ??15 ??31 Keep
Second class: when system bandwidth is 7MHz or 8.75MHz or 10MHz, indication UCAS MBThe required bit number of parameter is 4bits.
For 7MHz or 8.75MHz or 10MHz, UCAS MBBe that unit has indicated in the 0th frequency partition number possible number set based on the CRU of Miniband to be with Miniband: 4bits represents 16 different numbers, and these 16 different numbers are taken from set
Figure B2009101305580D0001431
Be total to C 49 16=3348108992991 kinds of combinations.UCAS MBCan adopt any one combination, for example, a kind of in shown in table 10.17～table 10.20, other is similar, enumerates no longer one by one.
Table 10.17
Figure B2009101305580D0001432
Table 10.18
Figure B2009101305580D0001433
Table 10.19
Figure B2009101305580D0001434
Figure B2009101305580D0001441
Table 10.20
Figure B2009101305580D0001442
Perhaps, when system bandwidth is 7MHz or 8.75MHz or 10MHz, indication UCAS MBThe required bit number of parameter is 5bits.5bits represents 32 different numbers, and these 32 different numbers are taken from set
Figure B2009101305580D0001443
Be total to C 49 32=6499270398159 kinds of combinations.UCAS MBCan adopt any one combination, for example, a kind of in shown in the table 10.21, other is similar, enumerates no longer one by one.
Table 10.21
Figure B2009101305580D0001444
Figure B2009101305580D0001451
Perhaps, when system bandwidth is 7MHz or 8.75MHz or 10MHz, indication UCAS SBiThe required bit number of parameter is 6bits.6bits represents 64 different numbers, can represent set
Figure B2009101305580D0001452
In all numerical value.For example, shown in table 10.22.
Table 10.22
Figure B2009101305580D0001453
Figure B2009101305580D0001461
The 3rd class: for 20MHz, indication UCAS MBThe required bit number of parameter is 4bits.
UCAS MBBe that unit has indicated in the 0th frequency partition number possible number set based on the CRU of Miniband to be with Miniband:
Figure B2009101305580D0001462
Figure B2009101305580D0001463
4bits represents 16 different numbers, and these 16 different numbers are taken from set
Figure B2009101305580D0001464
Be total to C 97 16=793067310934425856 kinds of combinations.UCAS MBCan adopt any one combination, for example, a kind of in shown in table 10.17～table 10.20, other is similar, enumerates no longer one by one.
Perhaps, when system bandwidth is 20MHz, indication UCAS MBThe required bit number of parameter is 5bits.5bits represents 32 different numbers, and these 32 different numbers are taken from set
Figure B2009101305580D0001465
Be total to C 97 32Plant combination.UCAS MBCan adopt any one combination.For example, a kind of in shown in table 10.23～table 10.25, other is similar, enumerates no longer one by one.
Table 10.23
Figure B2009101305580D0001466
Figure B2009101305580D0001471
Table 10.24
Figure B2009101305580D0001472
Table 10.25
Figure B2009101305580D0001481
Perhaps, when system bandwidth is 20MHz, indication UCAS MBThe required bit number of parameter is 6bits.6bits represents 64 different numbers, and these 64 different numbers can be represented set In all numerical value.For example, shown in the table 10.26.
Table 10.26
Figure B2009101305580D0001483
Figure B2009101305580D0001491
Perhaps, when system bandwidth is 20MHz, indication UCAS MBThe required bit number of parameter is 7bits.7bits represents 128 different numbers, and these 128 different numbers can be represented set
Figure B2009101305580D0001492
In except that 0 or 1 or 95 or 96 all numerical value.
For indicating UCAS under each bandwidth MBThe required bit number of parameter can be determined from said method, but for different bandwidth, indicate UCAS MBThe required bit number of parameter is the identical or complete difference of part each other.For example,
When system bandwidth is 5MHz, indication UCAS MBThe required bit number of parameter is 2bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 4bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits; Perhaps,
When system bandwidth is 5MHz, indication UCAS MBThe required bit number of parameter is 3bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 4bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 4bits;
When system bandwidth is 5MHz, indication UCAS MBThe required bit number of parameter is 3bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 4bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 5bits; Perhaps,
When system bandwidth is 5MHz, indication UCAS MBThe required bit number of parameter is 3bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 5bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 5bits;
When system bandwidth is 5MHz, indication UCAS MBThe required bit number of parameter is 4bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 4bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 5bits;
When system bandwidth is 5MHz, indication UCAS MBThe required bit number of parameter is 4bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 5bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 5bits; Perhaps,
When system bandwidth is 5MHz, indication UCAS MBThe required bit number of parameter is 4bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 5bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 6bits; Perhaps,
When system bandwidth is 5MHz, indication UCAS MBThe required bit number of parameter is 5bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 6bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 6bits;
When system bandwidth is 5MHz, indication UCAS MBThe required bit number of parameter is 5bits; When system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 6bits; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 7bits; Perhaps,
It may be noted that: at above-mentioned UCAS MBCollocation method in, when two different bandwidth have been used identical bit number indication UCAS MBParameter, corresponding form can be identical or different.For example, when system bandwidth was 10MHz (also can be 7MHz or 8.75MHz), indicating the required bit number of this parameter was 5bits, but corresponding form is a table 10.22; When system bandwidth was 20MHz, indicating the required bit number of this parameter was 5bits, but corresponding form is a table 10.23.
Identical form is meant: to be that the situation of 20MHz is more similar can consider the characteristics of 10MHz (can be 7MHz or 8.75MHz) and 20MHz are unified because system bandwidth is 10MHz (can be 7MHz or 8.75MHz) and system bandwidth, can be with system bandwidth 10MHz (can be 7MHz or 8.75MHz) with system bandwidth the identical UCAS of employing during for 20MHz MBValue and corresponding relation, that is, system bandwidth is that 10MHz (can be 7MHz or 8.75MHz) adopts identical form during for 20MHz with system bandwidth, for example, can adopt in table 10.23～table 10.25, the collocation method during perhaps according to 20MHz produces.Perhaps, produce according to the methods below:
Table 10.27
Figure B2009101305580D0001511
Figure B2009101305580D0001521
In addition, 5MHz can all adopt 3 bits or 4 bits or 5 bits with 10MHz (also can be 7MHz or 8.75MHz).
In addition, it may be noted that: at above-mentioned UCAS MBCollocation method in, at each table, UCAS MBValue and UCAS MBThe meaning of value indication in the middle of relation can change, each form all is embodiment, as long as the UCAS that comprises in table MBValue be the indication meaning be identical, all be regarded as identical table, all within protection range.
By above-mentioned example 9, as can be seen, when system bandwidth is respectively 5MHz, 10MHz (can be 7MHz or 8.75MHz), 20MHz system, indication UCAS MBBit number need 4bits, 5bits, 6bits respectively, at UCAS MBPossible value situation about reducing under, deleted that redundant and unnecessary information indicates, saved overhead bit, and guaranteed certain flexibility.
As mentioned above, by means of configuring resource mapping indication provided by the invention, the required bit number of each band width configuration indication parameter for system's support, and the bit number part of the indicating identical or complete difference of same parameter under different bandwidth, the bit number that makes physical resource mapping indication signaling use can change flexibly according to the bandwidth that system uses, reduce the bit number of transmission as much as possible, avoided the big problem of control channel expense in the correlation technique, under the prerequisite that does not influence the normal running of system, save descending control expense, thereby improve the operating efficiency of system.
The above is the preferred embodiments of the present invention only, is not limited to the present invention, and for a person skilled in the art, the present invention can have various changes and variation.Within the spirit and principles in the present invention all, any modification of being done, be equal to replacement, improvement etc., all should be included within protection scope of the present invention.

Claims (10)

1. a configuring resource mapping indication is characterized in that, comprising:
At least one parameter of indexed resource mapping is determined the required bit number of the described parameter of indication according to bandwidth;
Wherein, for a plurality of different bandwidth, indicate the required bit number of described the parameter identical or complete difference of part each other.
2. method according to claim 1, it is characterized in that, described resource mapping comprises downlink resource mapping and/or ascending resource mapping, wherein, the mapping of described downlink resource one of comprises the steps or combination: sub-band division (Subband Partitioning), little band displacement (Miniband Permutation), frequency partition is divided (FrequencyPartitioning), continuous resource unit/distributed resource unit distributes (ContigousResource Unit/Distributed Resource Unit Allocation, abbreviate CRU/DRU Allocation as) and subcarrier permutation (Subcarrier Permutation), described ascending resource mapping one of comprises the steps or combination: sub-band division, little band displacement, frequency partition is divided, continuous resource unit/distributed resource unit distributes and Tile displacement (Tile Permutation).
3. method according to claim 1, it is characterized in that described a plurality of bandwidth comprise first bandwidth, second bandwidth and the 3rd bandwidth, wherein, for a parameter in the described resource indication information: corresponding to described first bandwidth, indicating the required bit number of this parameter is M; Corresponding to described second bandwidth, indicating the required bit number of this parameter is N; Corresponding to described the 3rd bandwidth, indicating the required bit number of this parameter is P, and the value of M, N, P is the identical or complete difference of part each other.
4. method according to claim 3 is characterized in that, part is identical each other is meant for the value of described M, N, P:
N=M+1 and P=M+1; Perhaps, N=M+2 and P=M+2; Perhaps, N=M and P=M+1; Perhaps, N=M and P=M+2, wherein M is the integer greater than 0.
5. method according to claim 3 is characterized in that, the complete each other difference of the value of described M, N, P is meant:
N=M+1 and P=M+2; Perhaps N=M+2 and P=M+3, perhaps
N=M+1 and P=M+3, wherein M is the integer greater than 0.
6. according to each described method in the claim 3 to 5, it is characterized in that the value of M is 1 or 2 or 3 or 4.
7. according to each described method in the claim 3 to 5, it is characterized in that,
Described first bandwidth comprises: 5MHz, it is one of following that described second bandwidth comprises: 7MHz, 8.75MHz, 10MHz, described the 3rd bandwidth comprise: 20MHz.
8. according to each described method in the claim 1 to 5, it is characterized in that, the parameter in the described resource indication information comprise following one of at least: the number of the number of the number that the number that descending allocation of subbands number, up allocation of subbands number, downstream frequency zone configuration, upstream frequency zone configuration, downstream frequency subregion allocation of subbands number, upstream frequency subregion allocation of subbands number, descending continuous resource unit distribute, up continuous resource unit distribute, descending continuous resource unit based on Miniband, up continuous resource unit based on Miniband.
9. method according to claim 8 is characterized in that,
The bit number of indicating downlink allocation of subbands number is identical or different with the bit number of the up allocation of subbands number of indication in described system;
The bit number of indication downstream frequency zone configuration is identical or different with the bit number of indication upstream frequency zone configuration in described system;
The bit number of indication downstream frequency subregion allocation of subbands number is identical or different with the bit number of indication upstream frequency subregion allocation of subbands number in described system;
The bit number of the number that indicating downlink continuous resource unit distributes in described system is identical or different with the bit number of the number that the up continuous resource of indication unit distributes.
10. according to each described method in the claim 1 to 5, it is characterized in that, described descending allocation of subbands number and/or up allocation of subbands number are meant: the number of subband in the sub-band division, downstream frequency zone configuration and/or upstream frequency zone configuration are meant the number of frequency partition division medium frequency subregion and/or the size or the ratio of each frequency partition, downstream frequency subregion allocation of subbands number and/or upstream frequency subregion allocation of subbands number average are the numbers of subband in the frequency partition except that frequency subregion 0 in the indication frequency partition, the number that number that descending continuous resource unit distributes and/or up continuous resource unit distribute all is meant the number that the continuous resource unit distributes in each frequency partition, in the number indicating downlink frequency partition 0 of descending continuous resource unit based on Miniband based on the number of the continuous resource unit of Miniband, in the number indication upstream frequency subregion 0 of up continuous resource unit based on Miniband based on the number of the continuous resource unit of Miniband, wherein, the unit of number is subband or little band or physical resource unit.
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