TWI391495B - Rhodium recovery method - Google Patents

Rhodium recovery method Download PDF

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TWI391495B
TWI391495B TW97141953A TW97141953A TWI391495B TW I391495 B TWI391495 B TW I391495B TW 97141953 A TW97141953 A TW 97141953A TW 97141953 A TW97141953 A TW 97141953A TW I391495 B TWI391495 B TW I391495B
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ammonium
hexachloroantimonate
sponge
aqueous solution
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TW200940718A (en
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Syojiro Usui
Yoshio Ito
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Jx Nippon Mining & Metals Corp
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    • YGENERAL TAGGING OF NEW TECHNOLOGICAL DEVELOPMENTS; GENERAL TAGGING OF CROSS-SECTIONAL TECHNOLOGIES SPANNING OVER SEVERAL SECTIONS OF THE IPC; TECHNICAL SUBJECTS COVERED BY FORMER USPC CROSS-REFERENCE ART COLLECTIONS [XRACs] AND DIGESTS
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    • Y02P10/00Technologies related to metal processing
    • Y02P10/20Recycling

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Description

銠之回收方法Recycling method

本發明關於一種銠之回收方法,更詳而言之,係關於一種從含有Te之六氯銠酸銨水溶液,以海綿銠之形態來回收Rh之方法。The present invention relates to a method for recovering rhodium, and more particularly to a method for recovering Rh in the form of a sponge crucible from an aqueous solution of ammonium hexachloroantimonate containing Te.

以往,係一直進行著從銅之電解精製步驟所產生之銅電解沉澱物來回收貴金屬。屬於貴金屬其中一種的銠亦是回收對象,為了提高所回收之銠的純度,提出了各種方法。回收銠時的問題之一,係鍗會混入所回收之銠中。銅電解沈澱物中亦含有大量的鍗,故為了以高純度回收銠,必須將鍗加以去除。In the past, precious metal was recovered from copper electrolytic precipitates produced by the electrolytic purification step of copper. A ruthenium which is one of the precious metals is also a target for recycling, and various methods have been proposed in order to improve the purity of the recovered ruthenium. One of the problems when recycling cockroaches is that it will be mixed into the recovered cockroaches. The copper electrolytic precipitate also contains a large amount of ruthenium, so in order to recover ruthenium in high purity, ruthenium must be removed.

於日本特開2006-265677號公報中,揭示有一種從含有鍗及白金族金屬之銅電解沈澱物來回收銠的方法,係記載藉由在氯環境氣氛中對銅電解沈澱物進行氯化揮發處理,使鍗成為揮發性之氯化物後加以去除,接著,加入氯化鈉進行氯化焙燒處理,使白金族金屬成為可溶性之鹽後製成水溶液,接著藉由蒸餾、溶劑萃取及中和,來得到經去除銠以外之成分的銠溶液,接著在將鹽酸加入銠溶液之後,加入氯化銨,結晶為六氯銠酸銨((NH4 )3 RhCl6 )後,再經由還原及燒成等之步驟,以得到銠之海綿金屬。Japanese Laid-Open Patent Publication No. 2006-265677 discloses a method for recovering ruthenium from a copper electrolytic precipitate containing ruthenium and a platinum group metal, which is described by chlorinating a copper electrolytic precipitate in a chlorine atmosphere. After the treatment, the hydrazine is removed into a volatile chloride, and then, sodium chloride is added to carry out chlorination roasting treatment, and the platinum metal is made into a soluble salt to be made into an aqueous solution, followed by distillation, solvent extraction and neutralization. To obtain a cerium solution of the components other than cerium, and then add hydrochloric acid to the cerium solution, add ammonium chloride, crystallize into ammonium hexachloroantimonate ((NH 4 ) 3 RhCl 6 ), and then pass through reduction and firing. Wait for the steps to get the sponge metal.

於該公報中,記載有鍗由於在蒸餾、溶劑萃取、中和、結晶、還原等各分離步驟皆具有與銠相同的進行方式,因 此當銅電解沈澱物中之鍗的含量高達10質量%以上時,則上述方法並無法得到高純度的銠,故於結晶步驟中,藉由加入醇並進行加熱,使(NH4 )3 RhCl6 及Te析出,然後對該等進行過濾,以純水進行再懸浮(repulp)僅使(NH4 )3 RhCl6 溶解,並過濾分離出未溶解的Te,藉此可進一步提高銠的純度。In this publication, it is described that since each of the separation steps such as distillation, solvent extraction, neutralization, crystallization, and reduction has the same operation as that of ruthenium, the content of ruthenium in the copper electrolytic precipitate is as high as 10% by mass or more. In the above, the high purity ruthenium cannot be obtained by the above method. Therefore, in the crystallization step, (NH 4 ) 3 RhCl 6 and Te are precipitated by adding an alcohol and heating, and then the mixture is filtered and purified in pure water. Resuspension only dissolves (NH 4 ) 3 RhCl 6 and separates undissolved Te by filtration, whereby the purity of hydrazine can be further improved.

[專利文獻1]日本特開2006-265677號公報[Patent Document 1] Japanese Patent Laid-Open Publication No. 2006-265677

然而,已知即使採用日本特開2006-265677號公報所記載之方法,有時會在所回收之海綿銠含有無法忽視之含量的鍗。However, it is known that even if the method described in Japanese Laid-Open Patent Publication No. 2006-265677 is used, the recovered sponge must contain a content which cannot be ignored.

因此,本發明之課題,在於提供一種在從含有Te之六氯銠酸銨水溶液以海綿銠之形態來回收Rh時,可更確實得到鍗含量低之海綿銠的方法。Accordingly, an object of the present invention is to provide a method for more reliably obtaining a sponge having a low cerium content when Rh is recovered in the form of a sponge mash from an aqueous solution of Te hexachloroantimonate containing Te.

本發明人,為了解決上述課題經不斷研究後,得知可藉由控制六氯銠酸銨溶液中之Te/Rh比,來有效控制所得之海綿銠中之Te含量。六氯銠酸銨溶液中之Te/Rh比,係對該溶液中之Te/Rh含量進行分析,當其高於事先所預定之值時,係將鹽酸、氯化銨及醇添加於六氯銠酸銨溶液並進行加熱,使六氯銠酸銨及鍗析出,然後進行過濾、純水再懸浮,以將未溶解之Te加以過濾分離,藉此而可加以去除。The present inventors have continuously studied in order to solve the above problems, and have found that the Te content in the obtained sponge mash can be effectively controlled by controlling the Te/Rh ratio in the ammonium hexachloroantimonate solution. The Te/Rh ratio in the ammonium hexachloroantimonate solution is the analysis of the Te/Rh content in the solution. When it is higher than the previously predetermined value, hydrochloric acid, ammonium chloride and alcohol are added to the hexachloro group. The ammonium citrate solution is heated and precipitated with ammonium hexachloroantimonate and hydrazine, and then filtered and resuspended in pure water to filter and separate the undissolved Te, thereby being removed.

基於上述所完成之本發明,係一種方法,用以從含有 Te之六氯銠酸銨水溶液以海綿銠之形態來回收Rh,其包含下述步驟:(1)對該溶液中所含之Te對Rh之質量濃度比,亦即Te/Rh進行分析之步驟;(2)據步驟(1)之分析結果,當Te/Rh超過事先所預定之值時,重複以下之步驟(a)~(d)直至Te/Rh成為事先所預定之值以下;(a)將鹽酸、氯化銨及醇添加於該溶液,並進行加熱,使六氯銠酸銨及Te析出之步驟;(b)藉由過濾對所析出之六氯銠酸銨及Te進行回收之步驟;(c)以純水對所回收之六氯銠酸銨及Te進行再懸浮之步驟;(d)藉由過濾將未溶解之Te自純水加以分離,藉此得到Te/Rh降低之六氯銠酸銨水溶液之步驟;(3)據步驟(1)之分析結果,當Te/Rh在事先所預定之值以下時,或實施步驟(2)之後,藉由將還原劑添加於該水溶液並進行加熱,以得到銠黑(rhodium black)之步驟;及(4)藉由過濾將所得之銠黑加以回收後,於還原性或不活性環境氣氛中對銠黑進行燒成,藉此得到海綿銠之步驟。Based on the invention as described above, a method for containing The ammonium hexachloroantimonate aqueous solution of Te recovers Rh in the form of a sponge crucible, which comprises the following steps: (1) a step of analyzing the mass concentration ratio of Te to Rh contained in the solution, that is, Te/Rh (2) According to the analysis result of the step (1), when the Te/Rh exceeds the predetermined value, repeat the following steps (a) to (d) until the Te/Rh becomes below the predetermined value; a step of adding hydrochloric acid, ammonium chloride and an alcohol to the solution, and heating to precipitate ammonium hexachloroantimonate and Te; (b) recovering the precipitated ammonium hexachloroantimonate and Te by filtration a step of (c) re-suspending the recovered ammonium hexachloroantimonate and Te with pure water; (d) separating undissolved Te from pure water by filtration, thereby obtaining a reduced Te/Rh a step of an aqueous solution of ammonium hexachloroantimonate; (3) according to the analysis result of the step (1), when the Te/Rh is below a predetermined value, or after the step (2) is carried out, by adding a reducing agent to the Aqueous solution and heating to obtain rhodium black; and (4) recovering the obtained black by filtration, in a reducing or inactive atmosphere Rhodium black firing, thereby obtaining step rhodium sponge.

於本發明之一實施形態中,Te/Rh之事先所預定之值為150×10-6 以下。In an embodiment of the present invention, the predetermined value of Te/Rh is 150 × 10 -6 or less.

藉由本發明,可從含有Te之六氯銠酸銨水溶液更確實得到鍗含量低之海綿銠。According to the present invention, it is possible to more reliably obtain a sponge having a low cerium content from an aqueous solution of ammonium hexachloroantimonate containing Te.

步驟(1) 為本發明處理對象之含有Te之六氯銠酸銨水溶液,並無特別限制,典型為藉由將氯化銨添加於含有Rh及Te之鹽酸溶液,使Rh以六氯銠酸銨((NH4 )3 RhCl6 )之形態結晶後,溶解於水者。係於上述結晶步驟中,藉由添加醇並進行加熱,使(NH4 )3 RhCl6 及Te析出,然後對此等進行過濾,並以純水進行再懸浮,僅使(NH4 )3 RhCl6 溶解,再將未溶解之Te加以過濾分離後之濾液。Step (1) The aqueous solution of ammonium hexachloroantimonate containing Te which is the object of the present invention is not particularly limited, and is preferably hexachloroantimonic acid by adding ammonium chloride to a hydrochloric acid solution containing Rh and Te. After the form of ammonium ((NH 4 ) 3 RhCl 6 ) is crystallized, it is dissolved in water. In the above crystallization step, (NH 4 ) 3 RhCl 6 and Te are precipitated by adding an alcohol and heating, and then filtering, and resuspending in pure water, only (NH 4 ) 3 RhCl 6 dissolve, then filter the undissolved Te After the filtrate.

含有Rh及Te之鹽酸溶液,並無特別限制,典型如日本特開2006-265677號公報所記載之,係於氯環境氣氛中對銅電解沈澱物進行氯化揮發處理,藉此使鍗成為揮發性之氯化物而加以去除,接著,添加氯化鈉並進行氯化焙燒處理,使白金族金屬成為可溶性之鹽後,製成水溶液,接著,藉由蒸餾、溶劑萃取及中和,得到已去除銠以外之成分的銠溶液,接著,將鹽酸添加於此銠溶液者。The hydrochloric acid solution containing Rh and Te is not particularly limited. For example, as described in JP-A-2006-265677, the copper electrolytic precipitate is subjected to chlorination treatment in a chlorine atmosphere, thereby causing the ruthenium to be volatilized. The chloride is removed, and then sodium chloride is added and chlorination is carried out to make the platinum group metal a soluble salt, which is then made into an aqueous solution, and then removed by distillation, solvent extraction and neutralization. A solution of hydrazine other than hydrazine, followed by addition of hydrochloric acid to the hydrazine solution.

為處理對象之六氯銠酸銨水溶液所含之Te/Rh並無特別限制,典型為10~5,000質量ppm,更典型則為10~500質量ppm。The Te/Rh contained in the ammonium hexachloroantimonate aqueous solution to be treated is not particularly limited, and is typically 10 to 5,000 ppm by mass, and more typically 10 to 500 ppm by mass.

於步驟(1),係對六氯銠酸銨水溶液中所含之Te對Rh之質量濃度比,亦即Te/Rh進行分析。係由於在此階段 之Te/Rh,會對最後所得之海綿銠中之Te含量造成決定性的影響。換言之,海綿銠中之Te含量,可藉由控制六氯銠酸銨水溶液中所含之Te/Rh來控制。Te及Rh之質量濃度,例如可藉由ICP發光分光分析裝置來進行分析。In the step (1), the mass concentration ratio of Te to Rh contained in the aqueous solution of ammonium hexachloroantimonate, that is, Te/Rh is analyzed. Because at this stage The Te/Rh will have a decisive influence on the Te content in the final sponge. In other words, the Te content in the sponge crucible can be controlled by controlling the Te/Rh contained in the aqueous solution of ammonium hexachloroantimonate. The mass concentration of Te and Rh can be analyzed, for example, by an ICP emission spectroscopic analyzer.

於六氯銠酸銨水溶液添加甲酸,得到銠黑之後,再控制海綿銠中之Te含量之方法,例如以鹽酸與氧化劑等將銠黑加以再溶解後,再進行精製之方法等雖亦被考量過,但是由於不易以高產率將Rh加以再溶解,因此並不適合。且,即使於蒸餾、溶劑萃取及中和後之銠溶液之階段對Te含量進行分析,並反覆進行蒸餾、溶劑萃取及中和,由於Te與Rh所進行之方式類似,因此幾乎無法期待所得之鹽酸溶液中之Te濃度之降低。After adding formic acid to an aqueous solution of ammonium hexachloroantimonate to obtain black, and then controlling the content of Te in the sponge, for example, a method of re-dissolving the blackened by hydrochloric acid, an oxidizing agent, etc., and then purifying it is considered. However, it is not suitable because it is not easy to re-dissolve Rh in a high yield. Moreover, even if the Te content is analyzed at the stage of distillation, solvent extraction, and neutralization of the ruthenium solution, and distillation, solvent extraction, and neutralization are repeated, since Te and Rh are similarly performed, it is almost impossible to expect. A decrease in the concentration of Te in the hydrochloric acid solution.

步驟(2) 據步驟(1)對Te/Rh進行分析之結果,當Te/Rh超過事先所預定之值時,可藉由實施步驟(a)~(d)來有效降低Te/Rh。若1次循環之實施不夠充分,亦可重複2次循環以上直至Te/Rh成為事先所預定之值以下。Te/Rh,根據最後所得之海綿銠中所含之所欲Te含量來決定即可,惟在150×10-6 以下較佳,100×10-6 以下更佳。藉由此方式,可使海綿銠中之Te含量在ASTM規格(Rh等級99.95%)所定之Te含量50質量ppm。Step (2) According to the analysis of Te/Rh according to the step (1), when Te/Rh exceeds a predetermined value, Te/Rh can be effectively reduced by performing steps (a) to (d). If the implementation of one cycle is insufficient, the cycle may be repeated two times or more until the Te/Rh is equal to or less than the predetermined value. Te/Rh is determined according to the desired Te content contained in the finally obtained sponge crucible, and is preferably 150 × 10 -6 or less, more preferably 100 × 10 -6 or less. In this way, the Te content in the sponge crucible can be made 50 ppm by mass of the Te content determined by the ASTM specification (Rh grade 99.95%).

於步驟(a),係將鹽酸、氯化銨及醇添加於六氯銠酸銨水溶液,並進行加熱,使六氯銠酸銨及Te析出。In the step (a), hydrochloric acid, ammonium chloride and an alcohol are added to an aqueous solution of ammonium hexachloroantimonate, and the mixture is heated to precipitate ammonium hexachloroantimonate and Te.

由於可使溶液中之銠以六氯銠酸銨之形態析出,提高 過濾回收之回收率,因此,鹽酸之添加,較佳為使HCl在溶液中的濃度為2~6mol/L,更佳為3~4mol/L。Since the bismuth in the solution can be precipitated in the form of ammonium hexachloroantimonate, the increase is improved. The recovery rate by filtration is checked. Therefore, the addition of hydrochloric acid is preferably such that the concentration of HCl in the solution is 2 to 6 mol/L, more preferably 3 to 4 mol/L.

若HCl在溶液中的濃度低,則將會導致溶液中之銠無法以六氯銠酸銨之形態析出,使得溶液中所溶解之銠濃度變高,造成結晶後於溶液中之銠之損失増大。又即使過量添加HCl,亦僅會增加所處理之溶液量,並無優點。If the concentration of HCl in the solution is low, the ruthenium in the solution cannot be precipitated in the form of ammonium hexachloroantimonate, so that the concentration of ruthenium dissolved in the solution becomes high, resulting in a large loss of ruthenium in the solution after crystallization. . Even if HCl is added in excess, it only increases the amount of the solution to be treated, and there is no advantage.

氯化銨之添加量,可根據氯化銨相對於所欲結晶之Rh溶液中Rh物質量的反應當量來決定,較佳之氯化銨之添加量雖亦可根據Rh溶液中之Rh濃度,但是相對於Rh溶液中之Rh物質量為1.5~2.5當量。The amount of ammonium chloride added may be determined according to the reaction equivalent of ammonium chloride relative to the mass of Rh in the Rh solution to be crystallized. The preferred amount of ammonium chloride may be based on the Rh concentration in the Rh solution, but The mass of Rh in the Rh solution is 1.5 to 2.5 equivalents.

藉由添加醇,由於六氯銠酸銨相對於醇之溶解度小,因此可使溶液中所溶解之Rh易結晶成為(NH4 )3 RhCl6 ,且溶液中所溶解之Te可被醇還原而以單體之形態析出。醇之添加量,只要可將Te還原且可使(NH4 )3 RhCl6 結晶,則並無特別限制,基準上為六氯銠酸銨水溶液量之0.5~2倍液量。醇的種類,較佳為碳數為1~4之飽和脂肪族醇,特別是乙醇、甲醇,異丙醇或此等之混合物。高碳數之醇雖然還原力大,但將會同時還原生成未溶解於水之Rh,而與Te一起被分離,導致回收率降低。By adding alcohol, since the solubility of ammonium hexachloroantimonate with respect to alcohol is small, Rh dissolved in the solution is easily crystallized into (NH 4 ) 3 RhCl 6 , and Te dissolved in the solution can be reduced by alcohol. Precipitated in the form of a monomer. The amount of the alcohol to be added is not particularly limited as long as it can reduce Te and crystallize (NH 4 ) 3 RhCl 6 , and the amount is 0.5 to 2 times the amount of the aqueous solution of ammonium hexachloroantimonate. The type of the alcohol is preferably a saturated aliphatic alcohol having a carbon number of 1 to 4, particularly ethanol, methanol, isopropanol or a mixture thereof. Although the high carbon number alcohol has a large reducing power, it will simultaneously reduce to form Rh which is not dissolved in water, and is separated together with Te, resulting in a decrease in recovery rate.

若同時添加氯化銨與醇,則由於醇會使氯化銨之溶解度下降,導致未反應之氯化銨析出,且,由於添加醇會使沸點下降,故將無法有效生成(NH4 )3 RhCl6 。因此,醇較佳為在(NH4 )3 RhCl6 生成後再添加。具體而言,係在添加氯化銨之後,以80~95℃加熱1~3小時生成(NH4 )3 RhCl6 後, 再加入醇,並且以50℃以上之溫度加熱1小時以上(例如50~70℃、1~3小時),充分將Te還原。When ammonium chloride and an alcohol are simultaneously added, the solubility of ammonium chloride is lowered by the alcohol, and unreacted ammonium chloride is precipitated, and since the boiling point is lowered by the addition of the alcohol, (NH 4 ) 3 cannot be efficiently produced. RhCl 6 . Therefore, the alcohol is preferably added after the formation of (NH 4 ) 3 RhCl 6 . Specifically, after adding ammonium chloride, heating at 80 to 95 ° C for 1 to 3 hours to form (NH 4 ) 3 RhCl 6 , then adding alcohol, and heating at a temperature of 50 ° C or higher for 1 hour or more (for example, 50) ~70 ° C, 1 ~ 3 hours), fully restore Te.

於步驟(b),係藉由過濾來對所析出之六氯銠酸銨及Te進行回收。藉此,可得到六氯銠酸銨及Te之混合物。然後,於步驟(c),若以純水對此混合物進行再懸浮,則僅會溶解對純水具有可溶性之(NH4 )3 RhCl6 ,對純水為不溶性之Te則不會溶解而殘留下來。試用純水係為了防止雜質的混入,例如可以離子交換水或蒸餾水作用純水來使用。In the step (b), the precipitated ammonium hexachloroantimonate and Te are recovered by filtration. Thereby, a mixture of ammonium hexachloroantimonate and Te can be obtained. Then, in step (c), if the mixture is resuspended in pure water, only (NH 4 ) 3 RhCl 6 which is soluble in pure water is dissolved, and Te which is insoluble to pure water does not dissolve and remains. Come down. In order to prevent the incorporation of impurities, the pure water system can be used, for example, by using ion-exchanged water or distilled water as pure water.

於步驟(d)中,藉由過濾將未溶解之Te加以分離,藉此可得到Te/Rh降低之六氯銠酸銨水溶液。於步驟(d)所使用之過濾材,由於未溶解之還原Te之粒子非常微細,因此較佳為使用孔徑在1微米以下之薄膜過濾器等。In the step (d), the undissolved Te is separated by filtration, whereby an aqueous solution of ammonium hexachloroantimonate having a reduced Te/Rh can be obtained. In the filter material used in the step (d), since the undissolved particles of the reduced Te are very fine, it is preferable to use a membrane filter having a pore diameter of 1 μm or less.

步驟(3) 據步驟(1)之分析結果得知Te/Rh為事先所預定之值以下之情形,以及藉由實施步驟(2)得到Te/Rh為事先所預定之值以下的六氯銠酸銨水溶液之情形,皆前進至步驟(3)。於步驟(3),係藉由將還原劑添加於六氯銠酸銨水溶液並進行加熱,以得到銠黑。還原劑,從沒有雜質混入的方面考量,較佳為甲酸、草酸、氫,由於Rh回收率高且處理容易,因此以甲酸為更佳。還原劑之添加量,為了得到高產率,較佳為相對於將銠還原所需之理論量,為1.5~5.0當量,更佳為2.0~4.0。加熱條件,為了得到高產率,較佳為80~90℃、1~3小時,更佳為90~95℃、1~3小時。Step (3) According to the analysis result of the step (1), it is found that Te/Rh is equal to or less than a predetermined value, and by performing step (2), an aqueous solution of ammonium hexachloroantimonate having a Te/Rh of a predetermined value or less is obtained. In the case, proceed to step (3). In the step (3), the reducing agent is added to an aqueous solution of ammonium hexachloroantimonate and heated to obtain a black pigment. The reducing agent is preferably a formic acid, oxalic acid or hydrogen from the viewpoint of no impurities being mixed in. Since the Rh recovery rate is high and the treatment is easy, formic acid is more preferable. The amount of the reducing agent to be added is preferably from 1.5 to 5.0 equivalents, more preferably from 2.0 to 4.0, in order to obtain a high yield, with respect to the theoretical amount required for reduction of rhodium. The heating conditions are preferably 80 to 90 ° C, 1 to 3 hours, more preferably 90 to 95 ° C, or 1 to 3 hours in order to obtain a high yield.

步驟(4) 在步驟(3)所得之銠黑可藉由過濾來進行回收。由於銠黑之粒子亦非常微細,因此較佳為使用孔徑在1微米以下之薄膜過濾器等。將銠黑回收後,可藉由在還原性環境氣氛中對其進行燒成,而以Te含量低之海綿銠的形態來回收Rh。還原性環境氣氛,為了充分進行去氧,因此以氫環境氣氛較佳。亦可將惰性氣體混合於氫來使用,所使用之惰性氣體,由於容易獲得,因此以氬、氮為佳。燒成條件,為了充分進行去氧、去氯化銨,且防止銠之燒結,以得到粉碎性佳之海綿銠,故較佳為以750~850℃進行1~2小時之燒成。Step (4) The blackening obtained in the step (3) can be recovered by filtration. Since the black particles are also very fine, it is preferable to use a membrane filter having a pore diameter of 1 μm or less. After the ruthenium is recovered, it can be recovered in a reducing atmosphere, and Rh can be recovered in the form of a sponge having a low Te content. In the reducing atmosphere, in order to sufficiently perform deoxidation, a hydrogen atmosphere is preferred. An inert gas may be used by mixing with hydrogen, and the inert gas to be used is preferably argon or nitrogen because it is easily available. In the firing conditions, in order to sufficiently perform deoxidation, ammonium chloride removal, and prevention of sintering of the crucible to obtain a sponge having excellent pulverizability, it is preferably calcined at 750 to 850 ° C for 1 to 2 hours.

[實施例][Examples]

係沿著圖1(實施例1)及圖2(實施例2)所示之流程圖來説明本發明之實施例。實施例及比較例之分析,溶液係藉由ICP發光分光分析裝置來進行,而海綿銠則是藉由輝光放電質量分析裝置來進行。Embodiments of the present invention will be described along the flowcharts shown in Fig. 1 (Embodiment 1) and Fig. 2 (Example 2). In the analysis of the examples and comparative examples, the solution was carried out by means of an ICP emission spectroscopic analyzer, and the sponge was carried out by a glow discharge mass spectrometer.

實施例1Example 1

實施例1所使用之銠鹽酸溶液之分析值示於表1。溶液中之HCl濃度為3.2mol/L。於此溶液加入生成(NH4 )3 RhCl6 所需之1.9當量(430g)的氯化銨後,以90℃加熱1小時。再加入400mL之乙醇,以70℃加熱1小時,待冷卻後,以濾紙(JISNo.5C)進行過濾,得到(NH4 )3 RhCl6 與還原Te之混合物。以純水(離子交換水)對此混合物進行再懸浮,以將(NH4 )3 RhCl6 溶解製成440mL之溶液後,以 孔徑0.1微米之薄膜過濾器進行過濾,將還原Te加以分離。表2係顯示Te分離後之溶液組成。Te/Rh為82×10-6 。於實施例1中,由於係使Te/Rh之目標值為150質量ppm,故於Te分離後之六氯銠酸銨水溶液添加還原Rh所需之3當量(25mL)的甲酸,以90℃加熱2小時後,對銠黑進行回收。然後將銠黑置於5%氫-氬混合氣體中以800℃進行2小時之燒成,製成Rh之海綿金屬。表3係顯示Rh之海綿金屬之分析結果。Rh中之Te為2質量ppm。The analytical values of the hydrazine hydrochloride solution used in Example 1 are shown in Table 1. The HCl concentration in the solution was 3.2 mol/L. To the solution was added 1.9 equivalents (430 g) of ammonium chloride required for the formation of (NH 4 ) 3 RhCl 6 , followed by heating at 90 ° C for 1 hour. Further, 400 mL of ethanol was added, and the mixture was heated at 70 ° C for 1 hour. After cooling, it was filtered with a filter paper (JIS No. 5C) to obtain a mixture of (NH 4 ) 3 RhCl 6 and reduced Te. This mixture was resuspended in pure water (ion-exchanged water) to dissolve (NH 4 ) 3 RhCl 6 into a 440 mL solution, and then filtered through a membrane filter having a pore size of 0.1 μm to separate the reduced Te. Table 2 shows the composition of the solution after Se separation. Te/Rh is 82×10 -6 . In Example 1, since the target value of Te/Rh is 150 ppm by mass, 3 equivalents (25 mL) of formic acid required for reducing Rh is added to the aqueous solution of ammonium hexachloroantimonate after Se separation, and heated at 90 ° C. After 2 hours, the black was recovered. Then, the black was placed in a 5% hydrogen-argon mixed gas and fired at 800 ° C for 2 hours to prepare a sponge metal of Rh. Table 3 shows the analysis results of the sponge metal of Rh. The Te in Rh is 2 mass ppm.

實施例2Example 2

實施例2所使用之銠鹽酸溶液之分析值示於表4。溶液中之HCl濃度為3。此溶液加入生成(NH4 )3 RhCl6 所需之1.6當量(420g)的氯化銨後,以90℃加熱1小時。再加入400mL之乙醇,以70℃加熱1小時,待冷卻後,以濾紙(JISNo.5C)進行過濾,得到(NH4 )3 RhCl6 與還原Te之混合物。以純水(離子交換水)對此混合物進行再懸浮,以將(NH4 )3 RhCl6 溶解製成410mL之溶液後,以孔徑0.1微米之薄膜過濾器進行過濾,將還原Te加以分離。表5係顯示Te分離後之溶液組成。Te/Rh為174×10-6 。於實施例2中,由於係使Te/Rh之目標值為150質量ppm,故於Te分離後之六氯銠酸銨水溶液添加160mL的鹽酸,將溶液中之HCl濃度調整至3.3mol/L後,再加入1.5當量(400g)的氯化銨,以90℃加熱1小時。再加入850mL之乙醇,以70℃加熱1小時,待冷卻後,以濾紙(JISNo.5C)進行過濾,得到(NH4 )3 RhCl6 與還原Te之混合物。以純水(離子交換水)對此混合物進行再懸浮,以將(NH4 )3 RhCl6 溶解製成380mL之溶液後,以孔徑0.1微米之薄膜過濾器進行過濾, 將還原Te加以分離。表6顯示Te分離後之溶液組成。Te/Rh降低至47×10-6 。由於已達成目標值之150質量ppm以下,故於Te分離後之六氯銠酸銨水溶液添加還原Rh所需之3當量(27mL)的甲酸,以90℃加熱2小時後,對銠黑進行回收。然後將銠黑置於5%氫-氬混合氣體中以800℃進行2小時之燒成,製成Rh之海綿金屬。表7之下半部係顯示Rh之海綿金屬的分析結果。Rh中之Te為19質量ppm。表7之上半部之結果,係不從Te/Rh為174×10-6 之六氯銠酸銨水溶液對(NH4 )3 RhCl6 進行再結晶,而是進行甲酸還原及還原燒成得到Rh之海綿金屬之情形之值。The analytical values of the hydrazine hydrochloride solution used in Example 2 are shown in Table 4. The concentration of HCl in the solution was 3. This solution was added to 1.6 equivalents (420 g) of ammonium chloride required for the formation of (NH 4 ) 3 RhCl 6 and then heated at 90 ° C for 1 hour. Further, 400 mL of ethanol was added, and the mixture was heated at 70 ° C for 1 hour. After cooling, it was filtered with a filter paper (JIS No. 5C) to obtain a mixture of (NH 4 ) 3 RhCl 6 and reduced Te. This mixture was resuspended in pure water (ion-exchanged water) to dissolve (NH 4 ) 3 RhCl 6 into a 410 mL solution, and then filtered through a membrane filter having a pore size of 0.1 μm to separate the reduced Te. Table 5 shows the composition of the solution after Se separation. Te/Rh is 174×10 -6 . In Example 2, since the target value of Te/Rh is 150 ppm by mass, 160 mL of hydrochloric acid is added to the ammonium hexachloroantimonate aqueous solution after Se separation, and the HCl concentration in the solution is adjusted to 3.3 mol/L. Further, 1.5 equivalents (400 g) of ammonium chloride was added and heated at 90 ° C for 1 hour. Further, 850 mL of ethanol was added, and the mixture was heated at 70 ° C for 1 hour. After cooling, it was filtered through a filter paper (JIS No. 5C) to obtain a mixture of (NH 4 ) 3 RhCl 6 and reduced Te. This mixture was resuspended in pure water (ion-exchanged water) to dissolve (NH 4 ) 3 RhCl 6 into a 380 mL solution, and then filtered through a membrane filter having a pore size of 0.1 μm to separate the reduced Te. Table 6 shows the composition of the solution after Se separation. Te/Rh is reduced to 47×10 -6 . Since the target value was 150 ppm by mass or less, 3 equivalents (27 mL) of formic acid required for reducing Rh was added to the ammonium hexachloroantimonate aqueous solution after Se separation, and the mixture was heated at 90 ° C for 2 hours, and then the black was recovered. . Then, the black was placed in a 5% hydrogen-argon mixed gas and fired at 800 ° C for 2 hours to prepare a sponge metal of Rh. The lower half of Table 7 shows the analysis results of the sponge metal of Rh. The Te in Rh is 19 mass ppm. As a result of the upper half of Table 7, the (NH 4 ) 3 RhCl 6 was not recrystallized from an aqueous solution of ammonium hexachloroantimonate having a Te/Rh of 174 × 10 -6 , but was subjected to formic acid reduction and reduction calcination. The value of the case of Rh sponge metal.

比較例1Comparative example 1

比較例1所使用之六氯銠酸銨水溶液之分析值示於表8。此溶液之Te/Rh比為222×10-6 。於六氯銠酸銨水溶液添加還原Rh所需之3當量(39mL)的甲酸,以90℃加熱2小時加熱後,對銠黑進行回收。然後將銠黑置於5%氫-氬混合氣體中以800℃進行2小時之燒成,製成Rh之海綿金屬。表9係顯示Rh之海綿金屬的分析結果。Rh中之Te為87質量ppm,並不滿足ASTM規格(Rh等級99.95%)Te50質量ppm以下之條件。The analytical values of the aqueous ammonium hexachloroantimonate solution used in Comparative Example 1 are shown in Table 8. The Te/Rh ratio of this solution was 222 × 10 -6 . To the aqueous solution of ammonium hexachloroantimonate, 3 equivalents (39 mL) of formic acid required for reducing Rh was added, and the mixture was heated at 90 ° C for 2 hours, and then the black was recovered. Then, the black was placed in a 5% hydrogen-argon mixed gas and fired at 800 ° C for 2 hours to prepare a sponge metal of Rh. Table 9 shows the results of analysis of the sponge metal of Rh. The Te in Rh is 87 mass ppm, and does not satisfy the conditions of ASTM specification (Rh grade 99.95%) Te50 mass ppm or less.

實施例3Example 3

於具有各種Te/Rh比之六氯銠酸銨水溶液添加還原Rh所需之3當量的甲酸,以90℃加熱2小時後,對銠黑進行回收,然後,將銠黑置於於5%氫-氬混合氣體中以800℃進行2小時之燒成,得到Rh之海綿金屬,將此時之製品中之Te含量的變化表示於圖3。得知若Te/Rh比在150質量ppm以下,則可使所得之海綿金屬中的Te含量在50質量ppm以下。3 equivalents of formic acid required for reducing Rh were added to an aqueous solution of ammonium hexachloroantimonate having various Te/Rh ratios, and after heating at 90 ° C for 2 hours, the ruthenium was recovered, and then the ruthenium was placed at 5% hydrogen. In the argon mixed gas, firing was performed at 800 ° C for 2 hours to obtain a sponge metal of Rh, and the change in the Te content in the product at this time is shown in Fig. 3 . When the Te/Rh ratio is 150 ppm by mass or less, the content of Te in the obtained sponge metal can be made 50 mass ppm or less.

圖1,係實施例1所採用之用以回收Rh之處理流程圖。FIG. 1 is a flow chart of a process for recovering Rh used in Embodiment 1.

圖2,係實施例2所採用之用以回收Rh之處理流程圖。2 is a flow chart of a process for recovering Rh used in Embodiment 2.

圖3,係顯示六氯銠酸銨水溶液中之Te/Rh比與所得之海綿銠中之Te含量之關係。Figure 3 is a graph showing the relationship between the Te/Rh ratio in an aqueous solution of ammonium hexachloroantimonate and the Te content in the resulting sponge.

Claims (2)

一種方法,係用以從含有Te之六氯銠酸銨水溶液以海綿銠之形態來回收Rh,其包含下述步驟:(1)對該溶液中所含之Te對Rh之質量濃度比,亦即Te/Rh進行分析之步驟;(2)據步驟(1)之分析結果,當Te/Rh超過事先所預定之值,亦即150×10-6 時,重複以下之步驟(a)~(d)直至Te/Rh成為150×10-6 以下以下;(a)將鹽酸、氯化銨及醇添加於該溶液,並進行加熱,使六氯銠酸銨及Te析出之步驟;(b)藉由過濾對所析出之六氯銠酸銨及Te進行回收之步驟;(c)以純水對所回收之六氯銠酸銨及Te進行再懸浮之步驟;(d)藉由過濾將未溶解之Te自純水加以分離,藉此得到Te/Rh降低之六氯銠酸銨水溶液之步驟;(3)據步驟(1)之分析結果,當Te/Rh在150×10-6 以下時,或實施步驟(2)之後,藉由將還原劑添加於該水溶液並進行加熱,以得到銠黑之步驟;及(4)藉由過濾將所得之銠黑加以回收後,於還原性環境氣氛中對銠黑進行燒成,藉此得到Te在50質量ppm以下之海綿銠之步驟。A method for recovering Rh from a solution of ammonium hexachloroantimonate containing Te in the form of a sponge, comprising the following steps: (1) a mass concentration ratio of Te to Rh contained in the solution, That is, the step of analyzing the Te/Rh; (2) according to the analysis result of the step (1), when the Te/Rh exceeds the predetermined value, that is, 150×10 -6 , repeat the following steps (a)~( d) until Te/Rh becomes 150×10 -6 or less; (a) a step of adding hydrochloric acid, ammonium chloride and an alcohol to the solution, and heating to precipitate ammonium hexachloroantimonate and Te; (b) a step of recovering the precipitated ammonium hexachloroantimonate and Te by filtration; (c) a step of resuspending the recovered ammonium hexachloroantimonate and Te with pure water; (d) by filtering The dissolved Te is separated from the pure water to obtain a Te/Rh reduced ammonium hexachloroantimonate aqueous solution; (3) according to the analysis result of the step (1), when the Te/Rh is 150×10 -6 or less Or after the step (2), the step of obtaining a blackening by adding a reducing agent to the aqueous solution and heating; and (4) recovering the obtained black by filtration, in a reducing environment Firing atmosphere rhodium black, rhodium Te step thereby obtaining a sponge of 50 mass ppm or less. 如申請專利範圍第1項之方法,其Te/Rh之事先所預定之值為100×10-6 以下。As for the method of claim 1, the Te/Rh has a predetermined value of 100 × 10 -6 or less.
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