TWI382649B - Motor response control device, electric auxiliary device and motor drive control device response feedback control method - Google Patents

Motor response control device, electric auxiliary device and motor drive control device response feedback control method Download PDF

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TWI382649B
TWI382649B TW096144056A TW96144056A TWI382649B TW I382649 B TWI382649 B TW I382649B TW 096144056 A TW096144056 A TW 096144056A TW 96144056 A TW96144056 A TW 96144056A TW I382649 B TWI382649 B TW I382649B
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motor
rotational speed
speed
target
gain coefficient
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TW096144056A
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Chinese (zh)
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TW200836471A (en
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Wakabayashi Mitsuyuki
Ochiai Hiroshi
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Nifco Inc
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    • HELECTRICITY
    • H02GENERATION; CONVERSION OR DISTRIBUTION OF ELECTRIC POWER
    • H02PCONTROL OR REGULATION OF ELECTRIC MOTORS, ELECTRIC GENERATORS OR DYNAMO-ELECTRIC CONVERTERS; CONTROLLING TRANSFORMERS, REACTORS OR CHOKE COILS
    • H02P23/00Arrangements or methods for the control of AC motors characterised by a control method other than vector control
    • H02P23/03Arrangements or methods for the control of AC motors characterised by a control method other than vector control specially adapted for very low speeds
    • AHUMAN NECESSITIES
    • A47FURNITURE; DOMESTIC ARTICLES OR APPLIANCES; COFFEE MILLS; SPICE MILLS; SUCTION CLEANERS IN GENERAL
    • A47BTABLES; DESKS; OFFICE FURNITURE; CABINETS; DRAWERS; GENERAL DETAILS OF FURNITURE
    • A47B46/00Cabinets, racks or shelf units, having one or more surfaces adapted to be brought into position for use by extending or pivoting
    • A47B46/005Cabinets, racks or shelf units, having one or more surfaces adapted to be brought into position for use by extending or pivoting by displacement in a vertical plane; by rotating about a horizontal axis

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  • Engineering & Computer Science (AREA)
  • Power Engineering (AREA)
  • Control Of Electric Motors In General (AREA)

Description

馬達驅動控制裝置、電動輔助裝置及馬達驅動控制裝置之回應性反饋控制方法Responsive feedback control method for motor drive control device, electric auxiliary device and motor drive control device

本發明係關於馬達驅動控制裝置、電動輔助裝置及馬達驅動控制裝置之回應性反饋控制方法,特別有關能對馬達之旋轉速度,更具體言之,即馬達之轉子之旋轉速度,進行反饋控制之馬達驅動控制裝置,具備此馬達驅動控制裝置之電動輔助裝置及回應性反饋控制方法。The present invention relates to a responsive feedback control method for a motor drive control device, a power assist device, and a motor drive control device, and more particularly to feedback control of a rotational speed of the motor, more specifically, a rotational speed of a rotor of the motor. The motor drive control device includes the electric assist device and the responsive feedback control method of the motor drive control device.

一般裝備於廚房用以收納餐盤、食器或調理器具等之廚房用品之吊櫥,通常皆掛設在流理台之上面空間等高懸位置,因此,此種吊櫥或吊棚對較重用品或較大物品之取放不大方便。A cabinet that is generally equipped in the kitchen for storing kitchen utensils such as a plate, a food utensil, or a conditioning device, and is usually hung in a high hanging position above the flow table. Therefore, such a hanging cabinet or a hanging shed is a heavy product. Or the handling of larger items is not convenient.

為了使物品對吊櫥或吊棚之取放容易之技術,已有如日本特開2005-21298號專利公報(技術文獻一)所公開之電動昇降吊櫥,此種電動昇降吊櫥係由裝設在廚房等上面部之牆壁上之外櫥箱,組裝於外櫥箱內部之電動昇降機構,及由此電動昇降機構驅動而可上下移動之內櫥箱所構成。依此構成之電動昇降吊櫥,當使用者欲取放餐具、烹調器具等物品時,可按下操作部所設開關使內櫥箱自外櫥箱移出來並下降至下方位置,如此,可容易將所需物品自內櫥箱取出或放入,相當方便。An electric lift cabinet disclosed in Japanese Laid-Open Patent Publication No. 2005-21298 (Technical Document No. 1), which is incorporated in the utility of the present invention. The kitchen, such as a cabinet on the upper wall of the face, is an electric lifting mechanism assembled inside the outer cabinet, and an inner cabinet that can be moved up and down by the electric lifting mechanism. According to the electric lifting cabinet constructed as described above, when the user wants to take out items such as tableware and cooking utensils, the switch provided by the operation unit can be pressed to remove the inner cabinet from the outer cabinet and descend to the lower position, so that It is easy to remove or put the required items from the inner cabinet.

然而,上述專利文獻一所揭示之電動昇降吊櫥,如將內櫥箱之昇降速度設定為低速時,使內櫥箱下降至可取放物品之位置,及上昇回到收納於外櫥箱之位置所需時間頗長,使用上之方便性不太好。反之,如將內櫥箱之昇降速度設定為快速時,使用上之方便性雖可改善,但內櫥箱之單位時間之昇降移動距離變長,萬一,例如,物品尚未收納好郤因太快而夾於內櫥箱與外櫥箱之間之情形發生時,使用者從反應到對操作部指示內櫥箱之昇降動作停止所需之時間內,內櫥箱昇降之距離已相當長,往往物品已卡住甚至被壓損。However, in the electric lift cabinet disclosed in the above Patent Document, if the lifting speed of the inner cabinet is set to a low speed, the inner cabinet is lowered to a position where the articles can be taken out, and the cabinet is raised back to the position stored in the outer cabinet. The time required is quite long and the convenience of use is not very good. On the other hand, if the lifting speed of the inner cabinet is set to be fast, the convenience of use can be improved, but the moving distance of the inner box of the inner cabinet becomes longer, for example, if the item is not yet stored, it is too When the situation between the inner cabinet and the outer cabinet is fast, the distance between the inner cabinet and the outer cabinet is relatively long, and the distance between the inner cabinet and the outer cabinet is increased. Often the item is stuck or even crushed.

如是之故,欲使用專利文獻一所記載之電動昇降吊櫥時,不得不將其昇降速度設定為低速使用,是為現況。If the electric lift cabinet described in Patent Document 1 is to be used, it is necessary to set the lifting speed to a low speed.

為了解決上述問題,雖可考慮具備電動輔助裝置之電動吊櫥,按此種電動吊櫥之一例為,在內櫥箱裝設握桿等把手部,當使用者握住握桿而用力以便使內櫥箱昇降時,藉檢出裝置檢出該握桿所生應變(變形量)之方向及大小,並依此檢出結果求出馬達之目標旋轉速度,而進行控制馬達之旋轉速度與目標旋轉速度一致之反饋控制,藉此以使馬達能以反應使用者施加予握桿之力量之適當旋轉速度旋轉,而來輔助使用者對內櫥箱之昇降動作。In order to solve the above problems, an electric cabinet with an electric assist device may be considered. In one example of such an electric cabinet, a handle portion such as a grip is attached to the inner cabinet, and the user applies force to hold the grip. When the inner cabinet is lifted and lowered, the detection device detects the direction and magnitude of the strain (deformation amount) generated by the grip, and obtains the target rotational speed of the motor according to the detection result, thereby controlling the rotational speed and the target of the motor. Feedback control with uniform rotation speed, thereby enabling the motor to rotate at an appropriate rotational speed in response to the force applied by the user to the grip to assist the user in lifting the inner cabinet.

唯此種反饋控制之一典型例,有PID(比例積分微分)控制為業界所周知,按此種PID控制係併用P控制(比例控制),I控制(積分控制)及D控制(微分控制)三種之反饋控制,舉例言,分別求出馬達之旋轉速度對目標旋轉速度之速差,將此速差以時間積分之積分值,及將速差以時間微分之微分值,然後,將所求出之該速差與積分值及微分值加總起來,再用所定之增益係數乘以由上述加總而得之值,並根據該乘算所得之積值來控制馬達之旋轉速度。As a typical example of such feedback control, PID (Proportional Integral Derivative) control is well known in the industry. According to this PID control system, P control (proportional control), I control (integral control) and D control (differential control) are used. Three kinds of feedback control, for example, respectively determine the speed difference between the rotational speed of the motor and the target rotational speed, the integral value of the speed difference by time integral, and the differential value of the speed difference by time differential, and then, the desired The speed difference is summed with the integral value and the differential value, and the predetermined gain coefficient is multiplied by the summed value, and the rotational speed of the motor is controlled based on the multiplied product value.

此種PID控制,如將增益係數取較大之值時,因應速差之馬達之旋轉速度之單位時間內之調整量較大,其一例如第13圖(A)所示,目標旋轉速度變更之際,馬達之旋轉速度要到達目標旋轉速度之到達時間短,因此對速度之反應性高。In such a PID control, if the gain coefficient is taken to be a large value, the adjustment amount per unit time of the rotation speed of the motor according to the speed difference is large, and the target rotation speed is changed as shown in, for example, FIG. 13(A). At the time when the rotational speed of the motor reaches the target rotational speed, the arrival time is short, and therefore the reactivity with the speed is high.

然而,在此情形時,其一例如第13圖(B)所示,目標旋轉速度振動時,馬達旋轉速度隨著此振動而會發生振盪,是其一問題。However, in this case, for example, as shown in Fig. 13(B), when the target rotational speed vibrates, the motor rotational speed oscillates with the vibration, which is a problem.

譬如說,具備可輔助使用者操作內櫥箱之昇降動作之電動輔助裝置之電動吊櫥,利用PID控制以控制馬達旋轉速度,而增益係數若設定為較大值時,在此情形下,如使用者調整施加於握桿之力量意圖使內櫥箱緩慢昇降時,反應握桿之變形量之馬達旋轉速度之調整量大,隨著馬達之旋轉而昇降之內櫥箱之昇降速度往往快至比使用者握持握桿使內櫥箱昇降之手之昇降速度還快,造成手只是放空擱在握桿上毫無作用之情形。For example, an electric cabinet with an electric assist device that can assist the user in operating the lifting operation of the inner cabinet uses PID control to control the motor rotation speed, and if the gain factor is set to a large value, in this case, When the user adjusts the force applied to the grip bar to cause the inner cabinet to slowly move up and down, the adjustment amount of the motor rotation speed of the reaction grip deformation amount is large, and the lifting speed of the cabinet within the lift is often as fast as the motor rotates. Holding the grip bar more than the user makes the lifting and lowering of the inner cabinet faster and faster, causing the hand to just vacate and rest on the grip bar without any effect.

如此,手一變成放空,握桿之變形量即變小,目標旋轉速度隨之降下,內櫥箱之昇降速度亦降下。因為內櫥箱之昇降速度降低而使用者之手相對變成超越握桿之昇降速度而形成手力作用於握桿,使握桿之變形量增加,目標旋轉速度即再上昇,於是內櫥箱之昇降速度又變成比使用者之手之昇降速度快速,而再變成如前述之手對握桿又形成放空之狀態,如此反覆動作之結果,馬達旋轉速度即隨此目標旋轉速度之振盪變化而發生振盪現象。In this way, when the hand becomes empty, the deformation amount of the grip is reduced, the target rotation speed is lowered, and the lifting speed of the inner cabinet is also lowered. Because the lifting speed of the inner cabinet is lowered and the user's hand relatively becomes the lifting speed of the gripping rod, the hand force acts on the gripping rod, so that the deformation amount of the gripping rod is increased, and the target rotating speed is increased again, so that the inner cabinet is The lifting speed becomes faster than the lifting speed of the user's hand, and then becomes the state in which the hand-griping rod is vented as described above. As a result of the repeated action, the motor rotation speed occurs with the oscillation of the target rotation speed. Oscillation phenomenon.

如此一來,利用馬達之驅動力以輔助對需輔助對象物之使用者之動作之電動輔助裝置,在低速動作時,馬達旋轉速度隨著目標旋轉速度之振動而發生振盪時,即無法圓滑順暢輔助使用者對輔助對象物之操作動作。In this way, the electric assist device that assists the user of the object to be assisted by the driving force of the motor can not smoothly and smoothly oscillate when the motor rotational speed oscillates with the vibration of the target rotational speed during the low speed operation. Auxiliary user action on the auxiliary object.

相對於此,在PID控制時,如增益係數取為較小之值之情形時,因應速差之馬達旋轉速度之每單位時間內之調整量小之故,其一例如第14圖(B)所示,即使目標旋轉速度發生振動之情形,馬達旋轉速度較不易發生振盪。On the other hand, in the case of PID control, if the gain coefficient is taken to be a small value, the adjustment amount per unit time of the motor rotation speed in response to the speed difference is small, for example, FIG. 14(B). As shown, even if the target rotational speed vibrates, the motor rotational speed is less likely to oscillate.

但是,在此種情形下,例如第14圖(A)所示,目標旋轉速度經變更時,馬達旋轉速度要到達目標旋轉速度之經過時間變長,而有速度反應性緩慢之問題。以上各問題有待解決。However, in such a case, for example, as shown in Fig. 14(A), when the target rotation speed is changed, the elapsed time from the motor rotation speed to the target rotation speed becomes long, and there is a problem that the speed reactivity is slow. The above issues have yet to be resolved.

本發明主要為解決上述諸問題而開發者,目的在提供一種能抑制速度回應性之低落之同時,於低速動作時即使目標旋轉速度產生震動之情形時,也能抑制馬達之旋轉速度發生震盪之馬達驅動控制裝置、電動輔助裝置及馬達驅動控制裝置之回應性反饋控制方法。The present invention is mainly directed to a developer who solves the above problems, and aims to suppress the fluctuation of the speed responsiveness while suppressing the rotation speed of the motor even when the target rotational speed vibrates at a low speed. A responsive feedback control method for the motor drive control device, the electric auxiliary device, and the motor drive control device.

為達成上述目的,請求項1所述之本發明之馬達驅動控制裝置,包括:旋轉速度檢測裝置,用以檢測馬達之旋轉速度;目標旋轉速度取得裝置,用以取得上述馬達之目標旋轉速度;增益係數導出裝置,用以於根據上述馬達之旋轉速度對於上述目標之旋轉速度之速差,以進行控制上述馬達之旋轉速度期能與上述目標之旋轉速度成為一致之反饋控制之際,將用來在不使上述馬達之旋轉速度發生超過上述目標之旋轉速度之超控(超調)之範圍內放大上述馬達之旋轉速度之調控量之增益係數,隨著經由上述檢測裝置檢測出之上述旋轉速度愈快速係數之值則愈大之條件導出來;及控制裝置,根據由上述檢測裝置檢測出之上述旋轉速度對由上述取得裝置取得之上述目標旋轉速度之速差,及由上述導出裝置導出之增益係數,以進行反饋控制。In order to achieve the above object, the motor drive control device of the present invention according to claim 1 includes: a rotational speed detecting device for detecting a rotational speed of the motor; and a target rotational speed obtaining device for obtaining a target rotational speed of the motor; The gain coefficient deriving means is configured to control the speed difference of the rotational speed of the motor with respect to the rotational speed of the target to control the rotational speed of the motor to be the same as the rotational speed of the target And amplifying the gain coefficient of the control amount of the rotational speed of the motor within a range in which the rotational speed of the motor does not exceed the above-mentioned target rotational speed (overshoot), the rotation detected by the detecting device The condition that the value of the faster-speed coefficient is larger is derived; and the control device derives the speed difference of the target rotational speed obtained by the acquiring device based on the rotational speed detected by the detecting device, and is derived by the deriving device The gain factor is used for feedback control.

依請求項1之發明,於根據馬達之旋轉速度對於目標旋轉速度之速差,以進行控制馬達之旋轉速度期能與目標之旋轉速度成為一致之反饋控制之際,用來在不使馬達之旋轉速度發生超過目標之旋轉速度之超控(超調)之範圍內放大馬達之旋轉速度之調控量之增益係數,係藉由增益係數導出裝置,依由馬達之旋轉速度檢測裝置檢測出之旋轉速度愈快速係數之值則愈大之條件導出來。According to the invention of claim 1, the motor is not used in accordance with the speed difference of the rotational speed of the motor with respect to the target rotational speed to control the rotational speed of the motor in accordance with the rotational speed of the target. The gain coefficient of the regulation amount of the rotation speed of the amplification motor in the range of the over-control (overshoot) in which the rotation speed exceeds the rotation speed of the target is detected by the gain coefficient deriving means, and the rotation is detected by the rotation speed detecting means of the motor The condition that the faster the coefficient of speed is, the larger the condition is derived.

且本發明中,可藉由控制裝置,根據由檢測裝置檢測出之旋轉速度對由取得裝置取得之目標旋轉速度之速差,及由導出裝置導出之增益係數,以進行反饋控制。Further, in the present invention, the control device can perform feedback control based on the speed difference between the target rotational speed obtained by the acquisition device and the gain coefficient derived by the deriving device based on the rotational speed detected by the detecting device.

藉此構成,當馬達之旋轉速度比較低速之情形時,所導出之增益係數亦比較小,馬達之旋轉速度之單位時間內之調整量(調速量)較小之故,即使目標之旋轉速度發生振動之情形時,能有效抑制馬達之旋轉速度發生振盪。又,馬達之旋轉速度愈昇高,所導出之增益係數亦愈大,馬達之旋轉速度之單位時間內之調整量亦變大之故,亦能抑制速度回應(反應)性之降低。According to this configuration, when the rotation speed of the motor is relatively low, the derived gain coefficient is also relatively small, and the adjustment amount (speed adjustment amount) per unit time of the rotation speed of the motor is small, even if the rotation speed of the target is small. When vibration occurs, the rotation speed of the motor can be effectively suppressed from oscillating. Further, the higher the rotation speed of the motor is, the larger the gain coefficient is derived, and the adjustment amount per unit time of the rotation speed of the motor is also increased, so that the decrease in the speed response (reaction) can be suppressed.

依據請求項1所述之本發明,係藉由檢測出馬達之旋轉速度之同時,取得馬達之目標旋轉速度,且於根據馬達之旋轉速度對目標旋轉速度之速差值,以進行控制馬達之旋轉速度期能與目標旋轉速度一致之反饋控制之際,將用以在不使馬達之旋轉速度發生超過目標旋轉速度之超控之範圍內,放大馬達之旋轉速度之調控量之增益係數,根據檢測出之旋轉速度愈快速,係數值愈大之條件下導出來,然後根據檢測出之馬達之旋轉速度對取得之目標旋轉速度之速差值及導出之增益係數,以進行反饋控制之方法,因此,能一方面抑制速度回應性之降低,一方面,在低速動作時即使目標旋轉速度發生振動,也能抑止馬達之旋轉速度發生振盪之現象。According to the invention as recited in claim 1, the target rotational speed of the motor is obtained while detecting the rotational speed of the motor, and the motor is controlled based on the speed difference of the rotational speed of the motor with respect to the target rotational speed. When the rotation speed period is in accordance with the feedback control of the target rotation speed, the gain coefficient of the control amount of the rotation speed of the motor is amplified within a range that does not cause the rotation speed of the motor to exceed the target rotation speed, according to The faster the detected rotation speed is, the larger the coefficient value is derived, and then the feedback control method is performed according to the detected speed difference between the target rotational speed and the derived gain coefficient. Therefore, on the one hand, it is possible to suppress the decrease in the speed response, and on the other hand, even if the target rotational speed is vibrated at the time of the low speed operation, the phenomenon that the rotational speed of the motor oscillates can be suppressed.

又,本發明之控制裝置,如請求項2所述,係根據上述速差,將上述速差以時間積分之積分值,將上述速差以時間微分之微分值,及由上述導出裝置導出之增益係數進行PID控制(比例積分微分控制),以做為反饋控制裝置。Moreover, the control device of the present invention, as described in claim 2, is based on the speed difference, and integrates the speed difference as a time-integrated integral value, the differential value as a time differential differential value, and derived by the deriving device. The gain coefficient is PID controlled (proportional integral derivative control) as a feedback control device.

又,本發明之控制裝置,如請求項3所述,藉將上述速差與上述積分值及上述微分值相加,並對此相加所得之和值乘以上述增益係數後,根據此乘算所得之積以進行PID控制。Further, the control device according to the present invention, by adding the speed difference to the integral value and the differential value as described in claim 3, multiplying the sum of the sum values by the gain coefficient, and multiplying the gain coefficient Calculate the product for PID control.

一方面,為達成上述目的,依請求項4所述之電動輔助裝置,具備有依請求項1至請求項3中任一項所述之馬達驅動控制裝置,及由上述馬達驅動控制裝置所控制之用以驅動輔助對象物之馬達。In one aspect, the electric assist device according to claim 4, comprising the motor drive control device according to any one of claims 1 to 3, and controlled by the motor drive control device The motor for driving the auxiliary object.

因此,依請求項4所述之電動輔助裝置,因可發揮與請求項1之發明同樣之作用,故與請求項1之發明同樣可抑制速度回應性之降低之同時,在低速動作時即使目標之旋轉速度發生振動,亦能抑止馬達之旋轉速度發生振盪之現象。於是,可輔助使用者對輔助對象物之操作動作獲得圓滑而順暢之動作。Therefore, the electric assist device according to claim 4 can perform the same function as the invention of claim 1, and therefore, similarly to the invention of claim 1, it is possible to suppress the decrease in the speed response and the target even at the low speed. The rotation speed is vibrated, and the rotation speed of the motor can be suppressed from oscillating. Therefore, the user can assist the user to obtain a smooth and smooth movement of the operation of the auxiliary object.

一方面,為達成上述目的,依請求項5所述之馬達驅動控制裝置之回應性反饋控制方法,係藉由檢測出馬達之旋轉速度之同時,取得上述馬達之目標旋轉速度,且於根據上述馬達之旋轉速度對上述目標旋轉速度之速差值,以進行控制上述馬達之旋轉速度期能與上述目標旋轉速度一致之反饋控制之際,將用以在不使上述馬達之旋轉速度發生超過上述目標旋轉速度之超控之範圍內,放大上述馬達之旋轉速度之調控量之增益係數,依所檢測出之上述旋轉速度愈快速,係數之值則愈大之條件下導出來,並根據檢測出之上述旋轉速度對取得之上述目標旋轉速度之速差及導出之上述增益係數,以進行反饋控制之方法。In one aspect, in order to achieve the above object, the responsive feedback control method of the motor drive control device according to claim 5 is to obtain the target rotational speed of the motor while detecting the rotational speed of the motor, and according to the above a speed difference between the rotational speed of the motor and the target rotational speed for controlling the rotational speed of the motor to be consistent with the target rotational speed, and not for causing the rotational speed of the motor to exceed the above Within the range of the over-control of the target rotation speed, the gain coefficient of the control amount for amplifying the rotation speed of the motor is derived according to the detected rotation speed, and the value of the coefficient is larger, and is detected according to the condition The method of performing feedback control on the speed difference between the above-mentioned target rotational speed and the derived gain coefficient.

因此,根據請求項5之馬達驅動控制裝置之回應性反饋控制方法,因可發揮與請求項1之發明同樣之作用,故與請求項1之發明同樣可抑制速度回應性之降低之同時,在低速動作時即使目標之旋轉速度發生振動,亦能抑止馬達之旋轉速度發生振盪之現象。Therefore, according to the responsive feedback control method of the motor drive control device of the claim 5, since the same effect as the invention of the claim 1 can be exerted, the invention of the claim 1 can suppress the decrease in the speed response at the same time. Even if the target's rotational speed vibrates at low speeds, the motor's rotational speed can be suppressed from oscillating.

如上所述,根據本發明,因係藉由檢測出馬達之旋轉速度之同時,取得上述馬達之目標旋轉速度,且於根據上述馬達之旋轉速度對上述目標旋轉速度之速差值,以進行控制上述馬達之旋轉速度期能與上述目標旋轉速度一致之反饋控制之際,將用以在不使上述馬達之旋轉速度發生超過上述目標旋轉速度之超控之範圍內,放大上述馬達之旋轉速度之調控量之增益係數,依所檢測出之上述旋轉速度愈快速,係數之值則愈大之條件下導出來,並根據檢測出之上述旋轉速度對取得之上述目標旋轉速度之速差及導出之上述增益係數,以進行反饋控制,故具有可有效抑制速度回應性之降低之同時,在低速動作時即使目標之旋轉速度發生振動,亦能抑止馬達之旋轉速度發生振盪之現象之優異功效。As described above, according to the present invention, the target rotational speed of the motor is obtained while detecting the rotational speed of the motor, and the speed difference value of the target rotational speed is controlled based on the rotational speed of the motor. When the rotation speed of the motor can be controlled in accordance with the target rotation speed, the rotation speed of the motor is amplified within a range that does not cause the rotation speed of the motor to exceed the target rotation speed. The gain coefficient of the control quantity is derived according to the detected rotation speed, and the value of the coefficient is derived, and the speed difference of the target rotation speed obtained according to the detected rotation speed is derived and derived. Since the above-described gain factor is used for feedback control, it is effective in suppressing the decrease in speed response, and at the same time, even if the target rotational speed is vibrated at the time of low speed operation, the excellent effect of the phenomenon that the rotational speed of the motor oscillates can be suppressed.

茲參照附圖就本發明之實施形態詳細說明如下,在此說明以下係就本發明應用於電動吊櫥之一例加以說明。DETAILED DESCRIPTION OF THE PREFERRED EMBODIMENTS Hereinafter, embodiments of the present invention will be described in detail with reference to the accompanying drawings.

第1圖及第2圖表示本發明之實施形態之電動吊櫥10之概略示意圖,此電動吊櫥10之一使用例為系統化廚房用之天花板嵌置型吊櫥。此電動吊櫥10具有一收納在以假想線表示之外櫥箱內之內櫥箱12,內櫥箱12內可用以收納如食器、餐具等廚房用品。此內櫥箱12係可容納於固定在外櫥箱內之前、後面皆開放之箱架狀收納部14內。Fig. 1 and Fig. 2 are schematic diagrams showing an electric cabinet 10 according to an embodiment of the present invention, and one of the electric cabinets 10 is a ceiling-mounted ceiling cabinet for a systemized kitchen. The electric wall cabinet 10 has an inner cabinet 12 housed in a cabinet outside the imaginary line, and the inner cabinet 12 can be used to store kitchen utensils such as food utensils and tableware. The inner cabinet 12 is housed in a box-like accommodating portion 14 that is opened before and after being fixed in the outer cabinet.

收納部14之二側板16上設有一對樞軸18,支持內櫥箱12之一對搖臂20係藉一端樞接於該對樞軸18上而可以樞軸18為中心前後轉動自如。又,收納部14之二側板16上形成有以樞軸18為中心之圓弧狀導槽22,搖臂20之近樞接端部所設導銷24可沿導槽22滑動的嵌入該導槽22內,因此,搖臂20以樞軸18為中心轉動時,導銷24即被引導沿導槽22移動。The two side plates 16 of the accommodating portion 14 are provided with a pair of pivots 18, and one of the support cabinets 12 is pivotally connected to the pair of pivots 18 by one end of the rocker arm 20, and is pivotable about the pivot axis 18. Further, the two side plates 16 of the accommodating portion 14 are formed with an arc-shaped guide groove 22 centered on the pivot 18, and the guide pin 24 provided at the proximal pivot end of the rocker arm 20 is slidably guided along the guide groove 22 In the groove 22, when the rocker arm 20 is rotated about the pivot 18, the guide pin 24 is guided to move along the guide groove 22.

又,搖臂20之另一端樞接於內櫥箱12之側板26後側上部所設樞接部28上,因此,內櫥箱12能經由搖臂20以樞軸18為中心上下搖動。Moreover, the other end of the rocker arm 20 is pivotally connected to the pivoting portion 28 provided on the upper portion of the rear side of the side panel 26 of the inner cabinet 12. Therefore, the inner cabinet 12 can be rocked up and down around the pivot 18 via the rocker arm 20.

一方面,收納部14上位於一對側板16之間平行橫設有二軸32、34,軸34配置在側板16之前方底部,對側板16固定不動。又,軸34之兩端各樞接有另一搖臂36之一端,而此搖臂36之另一端則樞接於內櫥箱12之側板26之略中央部所設另一樞接部38上,藉此構成,搖臂36可與搖臂20同步帶動櫥箱12上下搖動。On the other hand, the accommodating portion 14 is provided with two shafts 32 and 34 in parallel between the pair of side plates 16, and the shaft 34 is disposed at the front bottom of the side plate 16, and the side plate 16 is fixed. Moreover, one end of the rocker arm 36 is pivotally connected to one end of the rocker arm 36, and the other end of the rocker arm 36 is pivotally connected to the other central portion 38 of the side panel 26 of the inner cabinet 12. In this way, the rocker arm 36 can drive the cabinet 12 to swing up and down in synchronization with the rocker arm 20.

另一方面,軸32係對側板16可旋轉自如的以兩端軸支在側板16上,此軸32經由齒輪系42由可正反旋轉之馬達40驅動旋轉。On the other hand, the shaft 32 is rotatably supported on the side plates 16 so that the side plates 16 are rotatably supported at both ends, and the shaft 32 is driven to rotate by the motor 40 which can be rotated forward and backward via the gear train 42.

如第3圖所示,馬達40之驅動軸直結一蝸桿44,馬達40之驅動力直接傳達至此蝸桿44。此蝸桿44嚙合於一蝸輪46A,蝸輪46A由蝸桿44之旋轉傳動而旋轉。蝸輪46A上一體連設同心配置之小齒輪46B,此小齒輪46B乃與蝸輪46A一齊旋轉,小齒輪46B與大齒輪48A嚙合,小齒輪46B一旋轉,大齒輪48A即被驅動而旋轉。大齒輪48A與另一小齒輪48B一體形成,此小齒輪48B隨著大齒輪48A之旋轉一齊旋轉。小齒輪48B與另一大齒輪50A嚙合,大齒輪50A因此隨著小齒輪48B旋轉。此大齒輪50A一體連設一斜齒輪50B,斜齒輪50B則隨大齒輪50A一齊旋轉。此斜齒輪50B與固定在軸32上之被動斜齒輪58相嚙合,軸32因此藉此斜齒輪58由斜齒輪50B傳動旋轉。As shown in FIG. 3, the drive shaft of the motor 40 is directly coupled to a worm 44, and the driving force of the motor 40 is directly transmitted to the worm 44. The worm 44 is engaged with a worm wheel 46A which is rotated by the rotational transmission of the worm 44. A concentrically arranged pinion 46B is integrally connected to the worm wheel 46A. The pinion gear 46B rotates together with the worm wheel 46A, the pinion gear 46B meshes with the large gear 48A, and the pinion gear 46B rotates, and the large gear 48A is driven to rotate. The large gear 48A is integrally formed with another small gear 48B that rotates in unison with the rotation of the large gear 48A. The pinion gear 48B meshes with another large gear 50A, which thus rotates with the pinion gear 48B. The large gear 50A is integrally connected with a helical gear 50B, and the helical gear 50B is rotated together with the large gear 50A. The helical gear 50B meshes with a passive helical gear 58 fixed to the shaft 32, whereby the shaft 32 is thereby rotationally driven by the helical gear 50B.

馬達40之心軸設有一編碼器41,此編碼器41能輸出因應馬達40之正或反轉及其旋轉速度所產生脈衝信號。The spindle of the motor 40 is provided with an encoder 41 which is capable of outputting a pulse signal generated in response to the positive or negative rotation of the motor 40 and its rotational speed.

軸32之兩端部如第2圖所示,各固定有一動力傳達齒輪54,一方面,收納部14之二側板16上各設有一以樞軸18為中心旋轉之圓盤狀之搖臂搖動用軸板56,上述搖臂20上之導銷24貫穿此搖臂搖動用軸板56之外緣部,搖臂搖動用軸板56之外周面形成有與動力傳達齒輪54嚙合之搖臂搖動齒輪56A,此搖臂搖動齒輪56A因此可由動力傳達齒輪54驅動而旋轉。As shown in FIG. 2, the two ends of the shaft 32 are each fixed with a power transmission gear 54. On the one hand, the two side plates 16 of the accommodating portion 14 are respectively provided with a disk-shaped rocker arm that rotates around the pivot shaft 18. With the shaft plate 56, the guide pin 24 on the rocker arm 20 penetrates the outer edge portion of the rocker arm rocking shaft 56, and the rocker arm rocking shaft 56 is formed with a rocker arm for meshing with the power transmission gear 54. The gear 56A, this rocker rocking gear 56A can thus be rotated by the power transmitting gear 54.

搖臂搖動用軸板56於是藉動力傳達齒輪54經由搖臂搖動齒輪56A之驅動而以樞軸18為中心旋轉,並帶動導銷24沿導槽22滑動以驅使搖臂20旋轉,而使搖臂20一端所支持之內櫥箱12昇降移動,而另一搖臂36則追隨內櫥箱12之移動而旋轉。The rocker arm rocking shaft 56 is then rotated by the power transmission gear 54 via the rocker arm gear 56A to rotate around the pivot 18, and the guide pin 24 is slid along the guide groove 22 to drive the rocker arm 20 to rotate. The inner cabinet 12 supported by one end of the arm 20 moves up and down, and the other rocker arm 36 rotates following the movement of the inner cabinet 12.

內櫥箱12之前面兩側下緣向下垂設一對支持板60,此對支持板60支持一橫向延伸之桿狀把手部62於二支持板60之間。A pair of support plates 60 are downwardly disposed at the lower edges of the front sides of the inner cabinet 12, and the pair of support plates 60 support a laterally extending rod-shaped handle portion 62 between the two support plates 60.

如第4圖(A)、(B)所示,把手部62具有由樹脂成型之圓筒狀握套64,握套64內部設有一平板狀金屬板66,此金屬板66形成長於握套64之長度,金屬板66之兩端固定在二支持板60上。As shown in FIGS. 4(A) and 4(B), the handle portion 62 has a cylindrical sleeve 64 formed of a resin, and a sleeve-shaped metal plate 66 is formed inside the grip sleeve 64. The metal plate 66 is formed longer than the grip sleeve 64. The length of the metal plate 66 is fixed to the two support plates 60.

又,金屬板66與握套64之間留有間隙,握套64之長度方向之中央部設有分別面對金屬板66之表面及背面之凸部64A,此外,在握套64之兩端部位於金屬板66與握套64之內面之間之上下間隙內各設有一板片彈簧68,其一端壓接於金屬板66之表面或背面,另一端壓接於握套64之內周面,如此使握套64經常向外脹開之狀態,藉以保持握套64與金屬板66之位置關係。Further, a gap is left between the metal plate 66 and the grip sleeve 64, and a central portion of the grip sleeve 64 in the longitudinal direction is provided with a convex portion 64A facing the front surface and the back surface of the metal plate 66, respectively. Further, at both ends of the grip sleeve 64 A plate spring 68 is disposed in the upper and lower gaps between the metal plate 66 and the inner surface of the grip sleeve 64. One end of the metal plate 66 is pressed against the surface or the back surface of the metal plate 66, and the other end is crimped to the inner circumferential surface of the grip cover 64. Thus, the grip sleeve 64 is often inflated outwardly, thereby maintaining the positional relationship between the grip sleeve 64 and the metal plate 66.

又,握套64之中央部設有一金屬部70(任何導電性部件皆適用),金屬部70連接一觸摸傳感器71(參照第5圖),此觸摸傳感器71係用來檢出金屬部70之靜電電容。當觸摸傳感器71檢出之靜電電容不滿所定值時,即輸出低(Low)位準信號;而若超過所定值時,則輸出高(High)位準信號。上述所定值係設定為使用者之手接觸金屬部70時可檢出信號之適當值。Further, a central portion of the grip sleeve 64 is provided with a metal portion 70 (any conductive member is applicable), and the metal portion 70 is connected to a touch sensor 71 (refer to FIG. 5) for detecting the metal portion 70. Electrostatic capacitance. When the electrostatic capacitance detected by the touch sensor 71 is less than the predetermined value, the low level signal is output; and if the predetermined value is exceeded, the high level signal is output. The above-mentioned predetermined value is set to an appropriate value at which the signal can be detected when the user's hand touches the metal portion 70.

一方面,金屬板66如第4圖所示,其長度方向之中央部設有與凸部64A相面對之應變傳應器72,把手部62在使用者用手握持金屬部70使之昇降時凸部64A接觸到金屬板66而使該金屬板66產生變形(應變)。On the one hand, as shown in FIG. 4, the metal plate 66 is provided with a strain transmitter 72 facing the convex portion 64A at the central portion in the longitudinal direction thereof, and the handle portion 62 holds the metal portion 70 by the user. When the lifting portion 64A is brought into contact with the metal plate 66, the metal plate 66 is deformed (strained).

應變傳感器72內藏有未圖示之應變計,此應變計可因應變形之方向及大小而使電阻值變化。應變傳感器72將應變計所生電阻值之變化轉換為電壓之變化後,將此放大輸出。由於應變傳感器72係因應金屬板66之變形產生應變之故,所輪出之信號之電壓位準亦隨該應變之大小而變化。由應變傳感器72輸出之信號之電壓位準係隨著應變傳感器72向下變形時之變形量而降低,但隨著向上變形時之變形量而上昇。換言之,可藉由檢測出應變傳感器72輸出之電壓位準而檢測出作用於握套64之應力及方向。The strain sensor 72 incorporates a strain gauge (not shown) which changes the resistance value in accordance with the direction and magnitude of the deformation. The strain sensor 72 converts the change in the resistance value generated by the strain gauge into a change in voltage, and then amplifies the output. Since the strain sensor 72 is strained in response to deformation of the metal plate 66, the voltage level of the signal that is rotated is also varied depending on the magnitude of the strain. The voltage level of the signal outputted by the strain sensor 72 decreases as the strain sensor 72 deforms downward, but rises with the amount of deformation at the time of upward deformation. In other words, the stress and direction acting on the grip 64 can be detected by detecting the voltage level output by the strain sensor 72.

第5圖表示本實施形態之電動吊櫥10之電路係統之要部構成方塊圖。Fig. 5 is a block diagram showing the configuration of essential parts of the circuit system of the electric wall cabinet 10 of the present embodiment.

如該圖所示,電動吊櫥10具有能將由應變傳感器72輸出之信號之電壓位準放大所定倍數(本實施例中為1x106 倍,但可從5000倍起放大)之放大電路80;根據編碼器41輸出之脈衝信號求出馬達40之旋轉速度及旋轉方向,並根據該旋轉速度及旋轉方向以及由放大電路80放大之信號之電壓位準輸出用以控制馬達40之旋轉速度之速度控制信號之微電腦82;及因應速度控制信號以驅動馬達40旋轉之驅動電路84。As shown in the figure, the electric wall cabinet 10 has an amplification circuit 80 capable of amplifying a voltage level of a signal output from the strain sensor 72 (in this embodiment, 1×10 6 times, but can be amplified from 5000 times); The pulse signal output from the encoder 41 determines the rotational speed and the rotational direction of the motor 40, and outputs a speed control for controlling the rotational speed of the motor 40 based on the rotational speed and the rotational direction and the voltage level of the signal amplified by the amplifying circuit 80. The signal microcomputer 82; and a drive circuit 84 for driving the motor 40 in response to the speed control signal.

又,應變傳感器72輸出之信號大約僅為數μ V(微伏)程度,無法取較大之該信號對傳送該信號之配線線路發生之雜訊之S/N(信號雜訊比)值,因此,本實施形態之電動吊櫥10中特別將放大電路80儘可能接近應變傳感器72設置以使放大電路80與應變傳感器72間之配線距離儘量縮短,而在儘量抑制配線發生之雜訊量之狀態下進行信號之放大,進而抑制雜訊造成之影響。Moreover, the signal outputted by the strain sensor 72 is only about a few μV (microvolts), and it is not possible to take a larger value of the S/N (signal noise ratio) of the noise generated by the signal to the wiring line transmitting the signal. In the electric ceiling cabinet 10 of the present embodiment, the amplifier circuit 80 is disposed as close as possible to the strain sensor 72 so that the wiring distance between the amplifier circuit 80 and the strain sensor 72 is as short as possible, and the state of the noise generated by the wiring is suppressed as much as possible. The signal is amplified to suppress the influence of noise.

微電腦82係將CPU、ROM、RAM等配置構成在一片晶片上,並在ROM中事先儲存有後文將述之驅動控制程式、電位差目標旋轉速度變換資料表、基準電壓位準等資料。The microcomputer 82 is configured such that a CPU, a ROM, a RAM, and the like are arranged on a single wafer, and data such as a drive control program, a potential difference target rotation speed conversion data table, and a reference voltage level which will be described later are stored in the ROM.

驅動電路84藉由根據速度控制信號改變對馬達40輸出之驅動信號之作用比(能率比)而改善馬達40之旋轉速度。The drive circuit 84 improves the rotational speed of the motor 40 by changing the action ratio (energy ratio) of the drive signal output to the motor 40 in accordance with the speed control signal.

第6圖表示本實施形態之微電腦82中所儲存電位差/目標旋轉速度變換資料表之一例。Fig. 6 shows an example of a potential difference/target rotation speed conversion data table stored in the microcomputer 82 of the present embodiment.

如該圖所示,此電位差/目標旋轉速度變換資料表儲存有每一位差所對應之目標旋轉速度,兩者之關係設定為電位差之絕對值愈大,目標旋轉速度愈快之值。又,在本實施形態中,旋轉速度設定為馬達40之旋轉軸向驅使內櫥箱12下降之方向旋轉時為負(“-”)值;向內櫥箱12上昇之方向旋轉時為正(“+”)值,藉此同時表示旋轉速度與旋轉方向。As shown in the figure, the potential difference/target rotation speed conversion data table stores the target rotation speed corresponding to each difference, and the relationship between the two is set such that the larger the absolute value of the potential difference is, the faster the target rotation speed is. Further, in the present embodiment, the rotational speed is set to a negative ("-") value when the rotational axis of the motor 40 drives the inner cabinet 12 to rotate downward, and is positive when the inner cabinet 12 is rotated in the upward direction ( The "+" value, thereby indicating both the rotational speed and the rotational direction.

第7圖表示本實施形態之微電腦82之功能作用之流程方塊圖。Fig. 7 is a flow chart showing the function of the microcomputer 82 of the present embodiment.

圖中,微電腦82包括:用以取得目標旋轉速度之目標旋轉速度取得部90;在一定時間內檢測出自編碼器41輸入之脈衝信號以求出馬達40之旋轉速度及旋轉方向,並依旋轉方向決定為正或負值檢測出該旋轉速度之旋轉速度檢測部92;根據旋轉速度檢測部92所檢測出之旋轉速度導出PID控制需用之增益係數KP 之增益係數導出部94;及使用導出之增益係數KP 進行PID控制以輸出速度控制信號之PID控制部96。In the figure, the microcomputer 82 includes: a target rotational speed acquiring unit 90 for acquiring a target rotational speed; detecting a pulse signal input from the encoder 41 for a certain period of time to obtain a rotational speed and a rotational direction of the motor 40, and depending on the rotational direction a rotation speed detecting unit 92 that determines the rotation speed for positive or negative values; a gain coefficient deriving unit 94 that derives a gain coefficient K P for PID control based on the rotation speed detected by the rotation speed detecting unit 92; The gain coefficient K P is PID controlled to output a speed control signal to the PID control unit 96.

又,目標旋轉速度取得部90預先儲存有基準電壓位準,此基準電壓位準係相當於應變傳應器72內藏之應變計未發生應變之狀態下,由該應變傳應器72輸出之信號經放大電路80放大後之電壓位準。此目標旋轉速度取得部90在自觸摸傳感器71輸入之信號為高位準時,即以基準電壓位準為基準求出其與自放大電路80輸入之信號之電壓位準之電位差,並根據此電位差從電位差目標旋轉速度變換資料表中取得目標旋轉速度。Further, the target rotational speed acquiring unit 90 stores in advance a reference voltage level corresponding to the state in which the strain gauge built in the strain transmitter 72 is not strained, and is outputted by the strain transmitter 72. The signal is amplified by the amplification circuit 80 to a voltage level. When the signal input from the touch sensor 71 is at a high level, the target rotational speed acquisition unit 90 obtains a potential difference between the voltage level of the signal input from the self-amplifying circuit 80 based on the reference voltage level, and based on the potential difference. The target rotation speed is obtained in the potential difference target rotation speed conversion data table.

又,應變傳應器72輸出之信號之電壓可能會因外部環境之變化等而慢慢有些許變化,為了此,目標旋轉速度取得部90在觸摸傳感器71輸入之信號為低位準之情形時,會根據自放大電路80輸入之信號之電壓位準將所儲存之基準電壓位準補正。Further, the voltage of the signal output from the strain transmitter 72 may be slightly changed due to a change in the external environment, etc., in order to prevent the signal input from the touch sensor 71 from being low. The stored reference voltage level is corrected based on the voltage level of the signal input from the amplifying circuit 80.

增益係數導出部94預先儲存有以旋轉速度做為輸出值,而以增益係數KP 做為輸出值之所定變換函數,而利用此變換函數從旋轉速度導出增益係數KPThe gain coefficient deriving unit 94 stores in advance a predetermined conversion function in which the rotational speed is used as the output value and the gain coefficient K P as the output value, and the gain coefficient K P is derived from the rotational speed using the transform function.

至於PID控制則如第8圖所示,如將增益係數KP 之值取大時,馬達40之旋轉速度會發生超過目標旋轉速度之振盪現象;但是,如將增益係數KP 之之最適值應為在不發生振盪現象之範圍內之最大值。As for the PID control, as shown in Fig. 8, if the value of the gain coefficient K P is taken large, the rotation speed of the motor 40 may exceed the oscillation speed of the target rotation speed; however, if the optimum value of the gain coefficient K P is It should be the maximum value within the range where oscillation does not occur.

因此,上述變換函數,預先設定為在進行PID控制時馬達40之旋轉速度不發生振盪之範圍內,馬達40之旋轉速度愈快速,導出之增益係數KP 之值亦愈大。又,在本實施形態中之增益係數導出部94係使用變換函數從旋轉速度導出增益係數KP ,唯如預先儲存已定妥旋轉速度與增益係數KP 之關係,使旋轉速度愈快速,在不發生振盪之範圍內導出之增益係數KP 之值亦變成愈大之旋轉速度/增益係數變換表,然後依據此旋轉速度/增益係數變換表從馬達40之旋轉速度導出增益係數KP 亦可行。Therefore, the above-described conversion function is set in advance so that the rotation speed of the motor 40 is faster in the range in which the rotation speed of the motor 40 does not oscillate when the PID control is performed, and the value of the derived gain coefficient K P is also larger. Further, in the gain coefficient deriving unit 94 of the present embodiment, the gain coefficient K P is derived from the rotational speed using the transformation function, and the relationship between the determined rotational speed and the gain coefficient K P is stored in advance, so that the rotational speed is faster. The value of the gain coefficient K P derived in the range where the oscillation does not occur also becomes the larger rotation speed/gain coefficient conversion table, and then the gain coefficient K P can be derived from the rotation speed of the motor 40 according to the rotation speed/gain coefficient conversion table. .

又,PID控制部96可求出馬達40之旋轉速度對目標旋轉速度之速差e,將此速差e以時間積分之積分值及將此速差以時間微分之微分值,並將各該速差與積分值及微分值相加以得其總和之後,以增益係數KP 乘以該和值而得MV值,再根據此MV值輸出指示馬達40之旋轉速度之增加量或減少量之速度控制信號。又,第7圖所示PID控制部96係顯示以拉卜拉斯變換(Laplace transform)形式表示之PID控制之流程,Ti代表積分時間,Td代表微分時間,s代表拉卜拉斯演算子。速差e乘以1/(Ti.S)可求得積分值,速差e乘以Td.S可求出微分值,將速差e與積分值及微分值相加之後,將相加所得之值乘以增益係數KP 便可導出MV值,如此設定亦可行。Further, the PID control unit 96 can obtain a speed difference e between the rotational speed of the motor 40 and the target rotational speed, and integrate the speed difference e with the integrated value of the time integral and the differential value of the speed difference by time, and each of the points After the speed difference is added to the integrated value and the differential value to obtain the sum thereof, the MV value is obtained by multiplying the sum value by the gain coefficient K P , and the speed indicating the increase or decrease of the rotational speed of the motor 40 is output according to the MV value. control signal. Further, the PID control unit 96 shown in Fig. 7 displays the flow of PID control in the form of Laplace transform, where Ti represents the integration time, Td represents the differentiation time, and s represents the Laplacian operator. The speed difference e is multiplied by 1/(Ti.S) to find the integral value, and the speed difference e is multiplied by Td. S can obtain the differential value, add the speed difference e to the integral value and the differential value, and multiply the added value by the gain coefficient K P to derive the MV value.

在本實施形態之微電腦82係藉由實行驅動控制式以實現上述PID控制部96。In the microcomputer 82 of the present embodiment, the PID control unit 96 is realized by executing a drive control formula.

以下,就本實施形態之電動吊櫥10之作用加以說明:首先,參照第9圖及第10圖就使用者操作內櫥箱12昇降時之整體動作過程之流程詳細說明。Hereinafter, the operation of the electric clothes cabinet 10 of the present embodiment will be described. First, the flow of the overall operation process when the user operates the inner cabinet 12 is described in detail with reference to FIGS. 9 and 10 .

如第9圖(A)所示,當使用者欲使收納於收納部(外櫥箱)14內之內櫥箱12降下時,用手握持把手部62之金屬部70,並施力將把手部62往下方拉,藉由此操作,把手部62內部所設凸部64A(見第4圖)即接觸到金屬板66並往下壓而產生向下之變形,應變傳感器72隨著金屬板66之變形亦發生向下之變形(見第9圖(B))。As shown in FIG. 9(A), when the user wants to lower the inner box 12 housed in the storage portion (outer cabinet) 14, the metal portion 70 of the handle portion 62 is gripped by hand and the force is applied. The handle portion 62 is pulled downward, and by this operation, the convex portion 64A (see FIG. 4) provided inside the handle portion 62 contacts the metal plate 66 and is pressed downward to generate a downward deformation, and the strain sensor 72 follows the metal. The deformation of the plate 66 also undergoes a downward deformation (see Figure 9 (B)).

微電腦82即根據應變傳感器72輸出之電壓位準之大小取得目標旋轉速度,並經由PID控制以該目標旋轉速度使馬達40之旋轉軸向使內櫥箱12下降之方向旋轉,藉此輔助使用者將內櫥箱12拉下之動作(見第9圖(C))。The microcomputer 82 obtains the target rotational speed based on the magnitude of the voltage level output from the strain sensor 72, and rotates the rotational direction of the motor 40 in the direction in which the inner casing 12 is lowered by the PID control at the target rotational speed, thereby assisting the user. The action of pulling the inner cabinet 12 down (see Figure 9 (C)).

一方面,如第10圖(A)所示,使用者若欲使下降之內櫥箱12向上昇時,用手握持把手部62之金屬部70,並施力將把手部62向上推即可。On the other hand, as shown in Fig. 10(A), if the user wants to raise the cabinet 12 in the downward direction, the user holds the metal portion 70 of the handle portion 62 by hand and pushes the handle portion 62 upward. can.

藉此操作,把手部62內部所設金屬板66產生向上之變形,應變傳感器72亦發生向上之變形(見第10圖(B))。By this operation, the metal plate 66 provided inside the handle portion 62 is deformed upward, and the strain sensor 72 is also deformed upward (see Fig. 10(B)).

微電腦82即根據應變傳感器72輸出之電壓位準之大小取得目標旋轉速度,並經由PID控制以該目標旋轉速度使馬達40之旋轉軸向使內櫥箱12上昇之方向旋轉,藉此輔助使用者將內櫥箱12昇上之動作(見第10圖(C))。The microcomputer 82 obtains the target rotational speed based on the magnitude of the voltage level output from the strain sensor 72, and rotates the rotational direction of the motor 40 in the direction in which the inner casing 12 is raised by the target rotational speed via the PID control, thereby assisting the user. The action of raising the inner cabinet 12 (see Fig. 10(C)).

如上所述,依本實施形態之電動吊櫥10,使用者不必另行指定輔助動作之操作,僅藉單手握持把手部62之金屬部70,該電動吊櫥10即能進行配合內櫥箱12之上昇及下降動作之電動輔助動作,因此操作性甚佳。As described above, according to the electric wall cabinet 10 of the present embodiment, the user does not have to specify the operation of the auxiliary operation, and only the metal portion 70 of the handle portion 62 is held by one hand, and the electric cabinet 10 can be fitted with the inner cabinet. The motor-assisted action of the 12 rise and fall movements is therefore very operability.

又,依本實施形態之電動吊櫥10,因可藉使用者調整對金屬部70所施加力量改變應變傳感器72之變形量而調整內櫥箱12之昇降速度,使用上更方便更順暢。Further, according to the electric ceiling cabinet 10 of the present embodiment, the amount of deformation of the strain sensor 72 can be changed by the user's adjustment of the force applied to the metal portion 70, and the lifting speed of the inner cabinet 12 can be adjusted, which makes it easier and smoother to use.

以下,參照第11圖詳細說明,實施驅動控制程式時微電腦82之作用。又,該驅動控制程式係在電動吊櫥10之電源(未圖示)通(ON)時進行程式控制,而電源斷(OFF)時程式控制終了。Hereinafter, the function of the microcomputer 82 when the drive control program is executed will be described in detail with reference to Fig. 11. Further, the drive control program is programmed when the power (not shown) of the electric ceiling cabinet 10 is turned ON (ON), and the program control is terminated when the power is turned off (OFF).

在該圖中之步驟102,先判斷由觸摸傳感器71輸入之信號是否為高位準(電平),如果是肯定,即進入下一步驟106;但如果是否定,則移入步驟104進行電壓位準補正。In step 102 of the figure, it is first determined whether the signal input by the touch sensor 71 is at a high level (level). If yes, the process proceeds to the next step 106; but if not, the process proceeds to step 104 for voltage level. Correction.

即,在步驟104中,可將原儲存之基準電壓位準修正為自放大電路80輸入之信號之電壓位準之後,再回歸步驟102。換言之,步驟102至步驟104之動作會反覆進行,直到使用者之手接觸金屬部70為止。藉此可防止因例如振動等造成應變傳感器72發生應變之情形所引起之誤動作。又,因在此步驟104中會補正基準電壓位準之故,即使因周遭環境之變化等造成應變傳感器72發生應變之情形時,於後述之步驟106中,可正確檢測出因應使用者握持把手部62之金屬部70所生變形之電位差。That is, in step 104, the original stored reference voltage level can be corrected to the voltage level of the signal input from the amplifying circuit 80, and then the process returns to step 102. In other words, the actions of steps 102 through 104 are repeated until the user's hand contacts the metal portion 70. Thereby, it is possible to prevent malfunction caused by the strain sensor 72 being strained by, for example, vibration. Further, since the reference voltage level is corrected in this step 104, even if the strain sensor 72 is strained due to a change in the surrounding environment, etc., in the step 106 described later, the user can be correctly detected. The potential difference of the deformation of the metal portion 70 of the handle portion 62.

在步驟106中,可檢測出以所記憶(儲存)之基準電壓位準為基準之由放大電路80輸入信號之電壓位準之電位差。In step 106, a potential difference of the voltage level of the input signal from the amplifying circuit 80 based on the stored (stored) reference voltage level can be detected.

在下一步驟108中,可根據步驟106中所檢出之電位差,從所儲存之電位差,目標旋轉速度變換表中取得對應該電位差之目標旋轉速度,並於下來之步驟110中,檢測出在一定時間內由編碼器41輸入之脈衝值以檢測出馬達40之旋轉速度,然後,在下一步驟112中,使用上述之變換函數從上述步驟110中檢測出之馬達40之旋轉速度導出增益係數KPIn the next step 108, the target rotational speed corresponding to the potential difference can be obtained from the stored potential difference and the target rotational speed conversion table according to the potential difference detected in step 106, and in step 110, it is detected that the target rotational speed is constant. The pulse value input by the encoder 41 is detected in time to detect the rotational speed of the motor 40. Then, in the next step 112, the gain coefficient K P is derived from the rotational speed of the motor 40 detected in the above step 110 using the above-described transformation function. .

再下來之步驟114中,求出上述步驟110中檢測出之馬達40之旋轉速度對於上述步驟108中所導出之目標旋轉速度之速差e,及將此速差e以時間積分之積分值,與將此速差e以時間微分之微分值,然後,將求得之該速差e及積分值與微分值相加總合,再對該相加所得之總和值乘以增益係數KP 而算出MV值。In the next step 114, the speed difference e of the rotational speed of the motor 40 detected in the above step 110 to the target rotational speed derived in the above step 108, and the integral value of the time difference integral of the speed difference e are obtained. And the differential value e is differentiated by time differential value, and then the obtained speed difference e and the integrated value are added to the differential value, and the summed value is multiplied by the gain coefficient K P . Calculate the MV value.

下來之步驟116會輸出根據上述步驟114中算出之MV值指示旋轉速度之增加量或減少量之速度控制信號之後,再回到上述開始步驟102,繼續實施前述處理。The next step 116 outputs a speed control signal indicating the increase or decrease of the rotational speed based on the MV value calculated in the above step 114, and then returns to the above-described start step 102 to continue the above-described processing.

第12圖(A)及(B)即表示本實施形態之微電腦82之控制馬達40之旋轉速度時,馬達40之旋轉速度之變化情形之曲線圖。Fig. 12 (A) and (B) are graphs showing changes in the rotational speed of the motor 40 when the microcomputer 82 of the present embodiment controls the rotational speed of the motor 40.

依照本實施形態之驅動控制程式之PID控制,因由變換函數導出之增益係數之值將會隨著馬達40之旋轉速度之增加而增大,故可如第12圖(A)所示,可保持目標旋轉速度變更為快速旋轉速度時之馬達40之旋轉速度之良好速度回應(反應)性。According to the PID control of the drive control program of the present embodiment, since the value of the gain coefficient derived from the conversion function increases as the rotational speed of the motor 40 increases, it can be maintained as shown in Fig. 12(A). The target rotational speed is changed to a good speed response (reaction) of the rotational speed of the motor 40 at the fast rotational speed.

又,馬達40之旋轉速度低時,由變換函數導出之增益係數KP 會變成比較小之值之故,而如第12圖(B)所示,即使目標旋轉速度發生振動之情形時,亦能有效抑制馬達之旋轉速度發生振盪之情形。Further, when the rotational speed of the motor 40 is low, the gain coefficient K P derived from the conversion function becomes a relatively small value, and as shown in Fig. 12(B), even if the target rotational speed vibrates, It can effectively suppress the oscillation of the rotation speed of the motor.

又,依本實施形態之電動吊櫥10,即使使用者急於使內櫥箱12上昇而對金屬部70施加大之力量,遂使應變傳感器72發生大之變形量時,馬達40之旋轉速度在低速之情形,由變換函數導出之增益係數因係小值之故,內櫥箱12仍會開始緩慢移動,對高齡使用者等而言容易操作使用。Further, according to the electric ceiling cabinet 10 of the present embodiment, even if the user is eager to raise the inner cabinet 12 to apply a large force to the metal portion 70, and the strain sensor 72 is greatly deformed, the rotation speed of the motor 40 is In the case of low speed, the gain coefficient derived from the transformation function is small, so the inner cabinet 12 still starts to move slowly, and is easy to operate for elderly users and the like.

如上所述,依本發明之實施形態,因係藉由檢測裝置(在此為旋轉速度檢測部92)檢測出馬達之旋轉速度,及藉由速度取得裝置(目標旋轉速度取得部90)以取得馬達之目標旋轉速度,並藉由導出裝置(在此為增益係數導出部94),於根據上述馬達之旋轉速度對上述目標旋轉速度之速差值,以進行控制上述馬達之旋轉速度期能與上述目標旋轉速度一致之反饋控制之際,在不使馬達之旋轉速度發生超過目標旋轉速度之超調之範圍內,將放大馬達之旋轉速度之調整量之增益係數,以所檢出之旋轉速度愈快速,其值愈大的條件下導出,復藉控制裝置(PID控制部96)根據檢測出之旋轉速度對所取得之目標旋轉速度之速差,及所導出之增益係數以對對馬達之旋轉速度進行反饋控制之故,能抑制速度回應性之低落之同時,在低速動作時,即使目標旋轉速度發生振動之情形時,也能抑止馬達之旋轉速度發生震盪。As described above, according to the embodiment of the present invention, the rotation speed of the motor is detected by the detecting device (here, the rotation speed detecting unit 92), and the speed acquiring device (target rotation speed obtaining unit 90) obtains the speed. a target rotational speed of the motor, and a speed difference value of the target rotational speed according to a rotational speed of the motor by a deriving device (here, a gain coefficient deriving unit 94) to control a rotational speed of the motor When the target rotation speed is the same as the feedback control, the gain coefficient of the adjustment amount of the rotation speed of the motor is amplified to the detected rotation speed without causing the rotation speed of the motor to exceed the overshoot of the target rotation speed. The faster the value is, the larger the value is derived, and the multi-drop control device (PID control unit 96) corrects the speed difference of the obtained target rotational speed based on the detected rotational speed, and the derived gain coefficient to the motor. When the rotation speed is feedback control, it is possible to suppress the low speed response, and at the time of low speed operation, even if the target rotation speed vibrates, It can also suppress the vibration of the motor from oscillating.

在本實施形態中係就利用PID控制對馬達40之旋轉速度進行反饋控制之情形加以說明,但本發明並不限於此形態,唯如果採用PI(比例積分)控制等之其他反饋控制以控制馬達40之旋轉速度亦可行。在此情形時,仍可達成與本實施形態同樣之功效。In the present embodiment, the case where the feedback control of the rotational speed of the motor 40 is performed by the PID control will be described. However, the present invention is not limited to this embodiment, and other feedback control such as PI (proportional integral) control is employed to control the motor. 40 rotation speed is also possible. In this case, the same effects as in the present embodiment can be achieved.

又,在本實施形態中係就從馬達40之旋轉速度藉變換函數導出一個增益係數KP 之情形加以說明,但本發明並不限於此形態,如果,從旋轉速度將比例增益係數、積分增益係數、微分增益係數各個以不同之變換函數導出,並分別求出對上述速差乘以比例增益係數之乘積值,及將速度以時間積分之積分值乘以積分增益係數之乘積值,以及將速度以時間微分之微分值乘以微分增益係數之乘積值,再根據將上述各乘積值相加所得之值,以行控制馬達之旋轉速度,亦屬可行。藉此控制時,因可依馬達40之旋轉速度個別改變比例增益係數、積分增益係數及微分增益係數之故,可精細控制馬達40之速度回應性。Further, in the present embodiment, the case where one gain coefficient K P is derived from the rotational speed of the motor 40 by the transfer function will be described. However, the present invention is not limited to this form, and if the rotational speed is a proportional gain coefficient and an integral gain The coefficient and the differential gain coefficient are each derived by different transformation functions, and the product values of the above-mentioned speed difference multiplied by the proportional gain coefficient are respectively obtained, and the integral value of the time integral is multiplied by the product value of the integral gain coefficient, and It is also feasible to multiply the differential value of the time differential by the product of the differential gain coefficient and then control the rotational speed of the motor according to the value obtained by adding the above-mentioned respective product values. By this control, since the proportional gain coefficient, the integral gain coefficient, and the differential gain coefficient can be individually changed depending on the rotational speed of the motor 40, the speed response of the motor 40 can be finely controlled.

又,在本實施形態中,係就將內櫥箱12藉馬達40之驅動力以輔助其昇降動作為例加以說明,但本發明並不限於此例,凡藉由馬達40之驅動力以輔助使用者操作輔助對象物之動作之其他各種電動輔助裝置,本發明裝置亦可適用。Further, in the present embodiment, the inner cabinet 12 is exemplified by the driving force of the motor 40 to assist the lifting operation. However, the present invention is not limited to this example, and the driving force of the motor 40 is assisted. The device of the present invention can also be applied to other various electric assist devices in which the user operates the auxiliary object.

此外,在本實施形態中所說明之電動吊櫥10之構造(參照第1圖至第4圖),電動吊櫥10之電路系統之構成(參照第5圖),及微電腦82之功能性構成(參照第7圖)均為一例,在不脫離本發明之主旨之範圍內尚可作適當之變更與修飾,自不待言。Further, the structure of the electric ceiling cabinet 10 described in the present embodiment (see FIGS. 1 to 4), the circuit system configuration of the electric window cabinet 10 (see FIG. 5), and the functional configuration of the microcomputer 82. It is to be understood that the modifications and modifications may be made without departing from the spirit and scope of the invention.

又,在本實施形態中所說明之驅動控制程式(參照第10圖)之流程僅是一例,在不脫離本發明之主旨之範圍內尚可作適當之變更與修飾,自不待言。Further, the flow of the drive control program (see FIG. 10) described in the present embodiment is merely an example, and it is needless to say that modifications and modifications can be made without departing from the spirit and scope of the invention.

10...電動吊櫥10. . . Electric wall cabinet

12...內櫥箱12. . . Inside cabinet

14...收納部14. . . Storage department

16,26...側板16,26. . . Side panel

18...樞軸18. . . Pivot

20,36...搖臂20,36. . . Rocker arm

22...導槽twenty two. . . Guide slot

23...導銷twenty three. . . Guide pin

28,38...樞接部28,38. . . Pivot

32,34...軸32,34. . . axis

40...馬達40. . . motor

41...偏碼器41. . . Partial encoder

42...齒輪系42. . . Gear train

44...蝸桿44. . . Worm

46A...蝸輪46A. . . Worm gear

46B,48B...小齒輪46B, 48B. . . gear

48A,50A...大齒輪48A, 50A. . . big gear

50B,58...斜齒輪50B, 58. . . helical gear

54...動力傳達齒輪54. . . Power transmission gear

56...搖臂搖動用軸板56. . . Rocker arm rocker

56A...搖臂搖動用齒輪56A. . . Rocker arm gear

60...支持板60. . . Support board

62...把手部62. . . Handle

64...握套64. . . Grip

64A...凸部64A. . . Convex

66...金屬板66. . . Metal plate

68...板片彈簧68. . . Plate spring

70...金屬部70. . . Metal department

71...觸摸傳感器71. . . Touch sensor

72...應變傳感器72. . . Strain sensor

80...放大電路80. . . amplifying circuit

82...微電腦82. . . Microcomputer

84...驅動電路84. . . Drive circuit

90...目標旋轉速度取得部90. . . Target rotation speed acquisition unit

92...旋轉速度檢測部92. . . Rotation speed detection unit

94...增益係數導出部94. . . Gain coefficient derivation unit

96...PID控制部96. . . PID control unit

102,104,106,108,110,112,114,116...驅動控制程式之各步聚102,104,106,108,110,112,114,116. . . Drive control program

KP ...增益係數K P . . . Gain coefficient

Ti...積分時間Ti. . . Integration time

Td...微分時間Td. . . Differential time

e...速差e. . . Speed difference

S...拉卜拉斯演算子S. . . Labras operator

第1圖表示實施形態之櫥箱收納於外箱內狀態之電動吊櫥之構成立體圖。Fig. 1 is a perspective view showing the configuration of an electric clothes cabinet in which the cabinet of the embodiment is housed in the outer casing.

第2圖表示實施形態之櫥箱自外箱下降狀態。Fig. 2 is a view showing a state in which the cabinet of the embodiment is lowered from the outer box.

第3圖表示實施形態之齒輪系之詳細構成之放大圖。Fig. 3 is an enlarged view showing a detailed configuration of a gear train of the embodiment.

第4圖(A)表示把手部之橫斷面圖,(B)表示把手部之縱斷面圖。Fig. 4(A) is a cross-sectional view showing the handle portion, and Fig. 4(B) is a longitudinal sectional view showing the handle portion.

第5圖表示實施形態之電動吊櫥之電路系之要部構成之方塊圖。Fig. 5 is a block diagram showing the configuration of a main part of a circuit system of an electric wall cabinet according to an embodiment.

第6圖表示實施形態之電位差/目標旋轉速度變換表之數據機制之一例之對照表。Fig. 6 is a comparison table showing an example of the data mechanism of the potential difference/target rotation speed conversion table of the embodiment.

第7圖表示實施形態之微電腦之功能構成之方塊圖。Fig. 7 is a block diagram showing the functional configuration of the microcomputer of the embodiment.

第8圖表示每一增益係數之馬達旋轉速度之變化關係之曲線圖。Fig. 8 is a graph showing the relationship of the rotational speed of the motor of each gain coefficient.

第9圖(A)~(C)表示實施形態之電動吊櫥放下櫥箱時之動作說明圖。Fig. 9 (A) to (C) are views showing the operation of the electric cabinet in the embodiment when the cabinet is lowered.

第10圖(A)~(C)表示實施形態之電動吊櫥收納櫥箱時之動作說明圖。Fig. 10 (A) to (C) are explanatory views showing the operation of the electric cabinet in the storage case of the embodiment.

第11圖表示實施形態之驅動控制程式之處理流程之流程圖。Fig. 11 is a flow chart showing the flow of processing of the drive control program of the embodiment.

第12圖(A)及(B)表示實施形態由PID控制方式控制馬達之旋轉速度時馬達之旋轉速度之變化一例之曲線圖。Fig. 12 (A) and (B) are graphs showing an example of a change in the rotational speed of the motor when the rotational speed of the motor is controlled by the PID control method.

第13(A)及(B)表示由習知技術之PID控制方式控制馬達之旋轉速度時馬達之旋轉速度之變化一例之曲線圖。13(A) and (B) are graphs showing an example of a change in the rotational speed of the motor when the rotational speed of the motor is controlled by the PID control method of the prior art.

第14(A)及(B)表示由習知技術之PID控制方式控制馬達之旋轉速度時馬達之旋轉速度之另一變化例之曲線圖。14(A) and (B) are graphs showing another variation of the rotational speed of the motor when the rotational speed of the motor is controlled by the PID control method of the prior art.

40...馬達40. . . motor

41...編碼器41. . . Encoder

71...觸摸傳感器71. . . Touch sensor

80...放大電路80. . . amplifying circuit

82...微電腦82. . . Microcomputer

84...驅動電路84. . . Drive circuit

90...目標旋轉速度取得部90. . . Target rotation speed acquisition unit

92...旋轉速度檢測部92. . . Rotation speed detection unit

94...增益係數導出部94. . . Gain coefficient derivation unit

96...PID控制部96. . . PID control unit

Claims (5)

一種馬達驅動控制裝置,包括:旋轉速度檢測裝置,用以檢測馬達之旋轉速度;目標旋轉速度取得裝置,用以取得上述馬達之目標旋轉速度;增益係數導出裝置,用以於根據上述馬達之旋轉速度對於上述目標之旋轉速度之速差,以進行控制上述馬達之旋轉速度期能與上述目標之旋轉速度成為一致之反饋控制之際,將用來在不使上述馬達之旋轉速度發生超過上述目標之旋轉速度之超控(超調)之範圍內放大上述馬達之旋轉速度之調控量之增益係數,隨著經由上述檢測裝置檢測出之上述旋轉速度愈快速係數之值則愈大之條件導出來;及控制裝置,根據由上述檢測裝置檢測出之上述旋轉速度對由上述取得裝置取得之上述目標旋轉速度之速差,及由上述導出裝置導出之增益係數,以進行反饋控制。 A motor drive control device includes: a rotation speed detecting device for detecting a rotation speed of the motor; a target rotation speed obtaining device for acquiring a target rotation speed of the motor; and a gain coefficient deriving device for rotating according to the motor The speed difference with respect to the rotational speed of the above-mentioned target is used to control the rotational speed of the motor to be the same as the rotational speed of the target, and is used to prevent the rotational speed of the motor from exceeding the above target The gain coefficient of the control amount for amplifying the rotational speed of the motor within the range of the overshoot (overshoot) of the rotational speed is derived as the condition that the value of the rotational speed faster than the coefficient of rotation is detected by the detecting means And the control device performs feedback control on the speed difference of the target rotational speed obtained by the acquisition device and the gain coefficient derived by the deriving device based on the rotational speed detected by the detecting device. 依據請求項1所述之馬達驅動控制裝置,其中該控制裝置係根據上述速差,將上述速差以時間積分之積分值,將上述速差以時間微分之微分值,及由上述導出裝置導出之增益係數進行PID控制(比例積分微分控制)以做為上述反饋控制。 The motor drive control device according to claim 1, wherein the control device derives the speed difference as a time differential integral value according to the speed difference, and derives the speed difference as a time differential differential value, and derives from the derivation device The gain coefficient is subjected to PID control (proportional integral derivative control) as the above feedback control. 依據請求項1所述之馬達驅動控制裝置,其中該控制裝置係將上述速差與上述積分值及上述微分值相加,並對此相加所得之和值乘以上述增益係數後,根據此乘算所得之積以進行上述PID控制。 The motor drive control device according to claim 1, wherein the control device adds the speed difference to the integral value and the differential value, and multiplies the sum obtained by the sum by the gain coefficient. The resulting product is multiplied to perform the above PID control. 一種電動輔助裝置,該裝置具備:依請求項1至請求項3中任一項所述之馬達驅動控制裝置,及由上述馬達驅動控制裝置所控制之用以驅動輔助對象物之馬達。 A motor-assisted device comprising: the motor drive control device according to any one of claims 1 to 3, and a motor controlled by the motor drive control device for driving the auxiliary object. 一種馬達驅動控制裝置之回應性反饋控制方法,係藉由檢測出馬達之旋轉速度之同時,取得上述馬達之目標旋轉速度;且於根據上述馬達之旋轉速度對上述目標旋轉速度之速差值, 以進行控制上述馬達之旋轉速度期能與上述目標旋轉速度一致之反饋控制之際,將用以在不使上述馬達之旋轉速度發生超過上述目標旋轉速度之超控之範圍內,放大上述馬達之旋轉速度之調控量之增益係數,依所檢測出之上述旋轉速度愈快速,係數之值則愈大之條件下導出來;並根據檢測出之上述旋轉速度對取得之上述目標旋轉速度之速差及導出之上述增益係數,以進行反饋控制之方法。A responsive feedback control method for a motor drive control device, which acquires a target rotational speed of the motor while detecting a rotational speed of the motor; and a speed difference value of the target rotational speed according to a rotational speed of the motor, When the feedback control for controlling the rotational speed of the motor to match the target rotational speed is performed, the motor is amplifying within a range that does not cause the rotational speed of the motor to exceed the target rotational speed. The gain coefficient of the control amount of the rotation speed is derived according to the detected rotation speed, and the value of the coefficient is larger; and the speed difference of the target rotation speed obtained according to the detected rotation speed is detected. And deriving the above gain coefficient to perform feedback control.
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