JPH02296465A - Electronic equipment - Google Patents

Abstract

PURPOSE:To attain the control of synthesizing a binary picture from a computer or the like with, e.g., a multi-value picture by means of an electronic device such as a computer and of outputting it by transferring and registering the binary picture generated by the electronic equipment to a picture storage device, synthesizing it will the picture stored in the picture storage device and outputting it in a digital color copying machine. CONSTITUTION:A character data is stored in a bit map memory or the like in advance, a binary data of a character resulting from scanning the designated area is read from a memory and a character signal is formed. A selector 143 selects a data in RAMs 135, 136 and a decoder 146 outputs the data. Thus, a control instruction form the computer is used to synthesize a binary bit map picture with other color picture and to output it.

Description

[Detailed description of the invention]

[Industrial Application Field] The present invention relates to electronic equipment, such as a computer, which controls image information from a storage device that stores image information or an input device that inputs image information. [Prior Art] In recent years, digital color copying machines that digitally separate and read color images, perform desired processing on the digital image signals, and perform color recording based on the image signals have become popular. [Problems to be Solved by the Invention] Furthermore, the color image information input to the digital color copying machine is an image input from the scanner section of the copying machine, and it is difficult to handle color images or binary images from a computer or the like. I couldn't. In view of the above, the present invention provides a digital color copying machine that can control, for example, an electronic device such as a computer to combine and output a binary image from a computer or the like with a multivalued image. purpose. [Means for Solving the Problems] In order to achieve the above-mentioned problems, the present invention provides an input device for inputting image information, an image forming device for forming an image on a medium according to the image information from the input device, an electronic device for controlling an image storage device that stores an input image from the input device, and means for generating a command to transfer and register a binary image created by the electronic device to the image storage device; ,
The image stored in the image storage device and the registered 2
and means for generating a control command for outputting the composite image from the image forming apparatus. (The following is a margin) [Example] Hereinafter, an example of the present invention will be described using the drawings. Overall System Configuration> FIG. 1 is a system configuration diagram showing an example of a schematic internal configuration of a color image processing system according to an embodiment of the present invention.
Embodiment> As shown in FIG. 1, the stem includes a digital color image reading device (hereinafter referred to as "color reader") 1 for reading digital color images at the top and a digital color image reading device (hereinafter referred to as "color reader") 1 for printing out digital color images at the bottom. A printing device (hereinafter referred to as a "color printer") 2, an image storage device 3, and an Sv recording/playback device 31. It is composed of a monitor television 32, a host computer 33, and a film scanner 34. The color reader l of this embodiment includes a color separation means, which will be described later,
This device uses a photoelectric conversion element composed of a COD or the like to read color image information of a read document for each color and converts it into an electrical digital image signal. The color printer 2 is an electrophotographic laser beam color printer that limits color images by color according to the digital image signal to be output, and records the images by transferring them multiple times in the form of digital dots onto recording paper. . The image storage device 3 stores digital images read from a color reader 1 or a film scanner 34 and an sV recording/reproducing device 31.
This is a device that quantizes the analog video signal from the computer, converts it into a digital image, and then stores it. The SV recording/reproducing device 31 is a device that reproduces image information taken with an SV camera and recorded on an SV floppy, and outputs it as an analog video signal. In addition to the above, the SV recording/playback device 31 can also record on an SV floppy by inputting an analog video signal. The monitor television 32 is a device that displays the images stored in the image storage device 3 and the contents of the analog video signal output from the SV recorder/player 31. The host computer 33 has functions of transmitting image information to the image storage device 3 and receiving and receiving image information stored in the image storage device 3 from the color reader 1, Sv recorder/player, and film scanner 34. It also controls the color reader 1, color printer 2, and the like. The film scanner 34 is a device that converts a 35 mm film (positive/negative) into electrical color image information using a photoelectric converter such as a CCD. The details of each part will be explained below. Description of Color Reader 1> First, the configuration of the color reader 1 will be described. In the color reader l shown in Fig. 1, 999 is an original, 4 is a platen glass on which the original is placed, and 5 is a halogen exposure lamp IO that collects the reflected light image from the original that has been exposed and scanned. This is a rod array lens for inputting images to 6. The rod array lens 5, the same-magnification full-color sensor 6, the sensor output signal amplification circuit 7, and the halogen exposure lamp 1° together constitute the document scanning unit 11.
99 is exposed and scanned in the direction of arrow (A1). The image information to be read from the original document 999 is sequentially read for every l line by exposing and scanning the original scanning unit 11. The read color separated image signal is amplified to a predetermined voltage by the sensor output signal amplification circuit 7, and then input to the video processing unit via the signal line 501, where the signal is processed. Note that the signal line 501 has a coaxial cable configuration to ensure faithful signal transmission. A signal 502 is a signal line that supplies drive pulses for the same-magnification full-color sensor 6, and all necessary drive pulses are generated within the video processing unit 12. Reference numeral 8.9 denotes a white plate and a black plate for correcting the white level and black level of the image signal, and by irradiating them with the halogen exposure lamp 10, a signal level of a predetermined density can be obtained, and the signal level of the video signal is White level correction. Used for black level correction. 13 is the color of this embodiment having a microcomputer.
This is a control unit that controls the entire reader 1, and controls the display on the operation panel 2°, the manual control of keys, and the video processing unit via the bus 508! 2 control etc. Further, the position of the document scanning unit 11 is detected by position sensors St and S2 via signal lines 509 and 510. Further, a stepping motor drive circuit 15 for pulse-driving a stepping motor 14 for moving the scanning object 1 is connected to the halogen exposure lamp 10 by an exposure lamp driver 21 via a signal line 504.
Color reader section l that controls N10FF control, light amount control, digitizer 16 and display section via signal line 505, etc.
All controls are in place. Reference numeral 20 denotes an operation section of the color league section, which includes a liquid crystal display panel that also serves as a touch panel and keys for giving various instructions. Incidentally, display examples of such a display panel are shown in FIG. 47 and subsequent figures. The color image signal read by the above-mentioned original scanning unit 11 during original exposure scanning is sent to the sensor output signal amplification circuit 7. It is input to the video processing unit 12 via a signal line 501. Next, details of the above-mentioned original scanning unit (11° video processing unit 12) will be explained using FIG. The color image signal input to the video processing unit 12 is separated into three colors, G (green), B (blue), and R (red), by the sample and hold circuit S/H 43. Each separated color image signal is converted from analog to digital by an A/D converter 44 to become a digital color image signal. In this embodiment, the color reading sensor 6 in the document scanning unit 11 is arranged in a staggered manner divided into five areas, as also shown in FIG. Using this color reading sensor 6 and the deviation correction circuit 45, the reading position deviation of the 2nd and 4th channels being scanned in advance and the remaining 1 and 3.5 channels is corrected. The positional deviation correction flow signal from the deviation correction circuit 45 is input to the black correction circuit/white correction circuit 46,
Using signals corresponding to the reflected light from the white plate 8 and the black plate 9 described above, dark-time unevenness of the color reading sensor 6, light unevenness of the halogen exposure lamp 1O, variations in sensor sensitivity, etc. are corrected. Color image data proportional to the input light amount of the color reading sensor 6 is input to the video interface 201 and connected to the image storage device 3. This video interface 201 has the functions shown in FIGS. 3 to 6. That is, (1) black correction/
A function of outputting the signal 559 from the white correction circuit 46 to the image storage device 3 (FIG. 3), (2) a function of inputting the image information 563 from the image storage device 3 to the selector 119 (FIG. 4) (3) Function of outputting the image information 562 from the combining circuit 115 to the image storage device 3 (FIG. 5) (4) Function of inputting the binarized information 206 from the image storage device 3 to the combining circuit 115 (FIG. 6) 5) Control line 207 between image storage device 3 and color reader l (lines such as H3YNC, VSYNC, image enable EN) and communication line 561 between CPU
connection. In particular, the CPU communication line is connected to a communication controller 162 within the control unit 13, and exchanges various commands and area information. It has five functions. These five functions are selected by the CPU.
The control line 508 switches as shown in FIGS. 3-6. As explained above, the video interface 201 has five functions, including the signal lines 205, 206,
207 is capable of bidirectional transmission. This configuration enables bidirectional transmission, reduces the number of signal lines (and thinner cables), and makes it cheaper. Also, the interface connector (27th The signal line (4550) in Figure (A) is also capable of bidirectional transmission. Therefore, the number of connection lines between each device composing the system can be reduced, and furthermore, it is possible to communicate with each other at a high level. Further, the image information 559 from the black correction/white correction circuit 46 is input to a logarithmic conversion circuit 48 (FIG. 2) that performs processing to match the luminous efficiency characteristics of the human eye. Here, white = OOH, black = FFH (image source that is converted and further input to the image reading sensor,
For example, a normal reflective original, a transparent original such as a film projector, or even the same transparent original, the sensitivity of the negative film, positive film, or film, and the gamma characteristics input in the IT light condition are different. ),
As shown in (b), there are multiple LUTs (look-up tables) for logarithmic conversion, which are used depending on the purpose.Switching is done using the signal lines i' go, f gl, 1
g2, and as the I10 port of CPU22,
This is performed by inputting an instruction from an operation unit or the like. Here each B,
The data output for G and H corresponds to the density value of the output image, and is yellow and magenta for each signal of B (blue), G (green), and R (red), respectively. Since this corresponds to the amount of cyan toner, the subsequent color image data will be associated with Y, M, and C. Note that the color conversion circuit 47 is a circuit that detects a specific color from the input color image data R, B, and G and replaces it with another color. For example, it realizes a function of converting a red part of a document into blue or any other arbitrary color. Next, each color component image data from the original image obtained by logarithmic transformation 48, that is, the yellow component. The color correction circuit 49 performs color correction on the magenta and cyan components as described below. As shown in Figure 8, the spectral characteristics of the color separation filters arranged for each pixel in the color reading sensor have unnecessary transmission areas such as the shaded areas. toner(
It is well known that Y, M, C) also have unnecessary absorption components as shown in FIG. Note that the figure only shows R, G, Y, and M, respectively. Therefore, for each color component image data Yi, Ml, Ci, masking correction is known in which color correction is performed by calculating a linear equation for each color.Furthermore, by Yi, Mi, Ci, Min (Yi, Mi, Ci) (Yi,
The minimum value of Mi, Ci) is calculated, and this is sumi (minimum value of Mi, Ci).
As black), an operation of adding black toner later (smearing) and an undercolor removal (UCR) operation of reducing the amount of each coloring material added according to the added black component are also often performed. FIG. 10(a) shows a color correction circuit 4 that performs masking, smearing, and TJCR.
9 shows the circuit configuration of No. 9. The characteristics of this configuration are: ■ It has two masking matrices, and can be switched at high speed with one signal line "Ilo." ■ One signal line "Ilo" with and without UCR, Can be switched at high speed. 1) There are two circuits for determining the amount of smear, and "Ilo" can be switched at high speed. First, prior to image reading, a desired first matrix coefficient M H and a desired second matrix coefficient M2 are set via a bus connected to the CPU 22 . In this example, Ml is set in registers 50-52, and M2 is set in registers 53-55. Further, 56 to 62 are selectors, respectively, which select A when the S terminal is "1" and select B when the S terminal is "0". Therefore, when selecting matrix M1, the switching signal MAR
When EA566="1" and matrix M2 is selected, it is set to "0". Further, 63 is a selector, and selection signals C0°C, (
567, 568), outputs a, b, and c are obtained based on the truth table shown in FIG. 10(b). Selection signal CO+
CI and C2 correspond to color signals to be output, for example, in the order of Y, M, C, Bk (C2°CI + CG)
” (0,L O)+ (L Or 1)+
(Onl, 0), (1, 0, 0), and then (0, 1, 1) as a monochrome signal to obtain a desired color-corrected color signal. In addition, CON CI r C
2 is C depending on the image forming sequence of the color printer 2.
PU22 occurs. Now, (co * Cr t
02 ) = (0 + 0.0), and MAREA566 =
When set to “l”, the output of the selector 63 (a, b,
c), the contents of the registers 50a, 50b, and 50c, and therefore (ay+, -bMt. -CCI) are output. On the other hand, the input signals Yi, Mi. The black component signal 570 calculated from Ci as Min (Yi, Mi, C4) = Y = a at 64
It undergoes the -order transformation x-b (a, b is a constant) and is input (through the selector 60) to the B inputs of the subtracters 65a, 65b, and 65c. In each subtractor 65a, b, c, Y is used as undercolor removal.
= Y i - (ak - b), M = M
i-(ak-b). C=C1-(ak-b) is calculated, and the signal line 571a. The signals are input to multipliers 66a, 66b, and 66c for masking calculations via 571b and 571c. Selector 60 is controlled by signal UAREA572;
The UAREA 572 has a configuration that enables high-speed switching between UCR (undercolor removal), presence, and absence using "Ilo". The multipliers 66a, 66b, and 66c each have an A
Input (aYl, -bMl, -CC1)
, B input has the above-mentioned [Yi-(ak-b), Mi-(
ak-b), (j-(ak-b)) = (Yi,
As is clear from the figure, the output Dout has the condition of C2=0 (Y or
Yout=YiX (aYl
) +Mix (-bM+) +Cix (-cct)
is obtained, and yellow image data that has been subjected to masking color correction and undercolor removal processing is obtained. Similarly, Mout=YiX(-aY2)+MiX(bM2)+c
iX(-CC2)Cout=YiX(-aY3)+Mi
x(-bM3)+C1X(CC3) is output to Dout. Color selection is controlled by the CPU 22 according to the table in FIG. 10(b) by (Co, CI. C2) in accordance with the order of output to the color printer. Registers 67a, b, c,
68a. b and c are registers for monochrome image formation, and based on the same principle as the above-mentioned masking color correction, MONO=k
I Yi+ 1. Weighting of each color is obtained by addition using I Mi 10 m I Ci. Switching signal MAREA566, UAREA572°K
As mentioned above, AREA57p has high-speed switching between masking color correction coefficient matrix M and M2, and UARE.
A572 has high-speed switching with and without UCR, KAR
EA573 switches the primary conversion of the black component signal (signal line 574 → output to Dout through selector 61),
That is, K = M i n (Y i , M
i. Ci), Y=ck-d or Y=ek-f (c
. d, e, f are constant parameters) are signals that rapidly switch the characteristics of the image forming apparatus. It is configured. Therefore, this configuration can be applied when images obtained from image input sources having different color separation characteristics or a plurality of images having different black tones are combined as in this embodiment. Note that these area signals MAREA, UAREA,
KAREA (566°572, 573) is generated by an area generation circuit (69 in FIG. 2) which will be described later. Next, a black character processing circuit for reproducing black characters and thin lines in a document and improving color bleeding at the edges of black characters and black lines will be described with reference to FIGS. 11 and 12. The point correction/white correction circuit 46 shown in FIG.
R, G, B (red, green, blue) color signals 559R, 559G with white level correction. 559B is LOG conversion 48, masking, under color removal 49
After receiving the signal, the color signal to be output to the printer is selected and output to the signal fi565. In parallel with this, signals R, G, and B indicate the achromatic portion of the document and the edge portion, that is, the black characters. In order to detect the black thin line), luminance signal Y1 color difference signal 1. Q is calculated by Y, r, and Q calculation circuit 70 (FIG. 11). The luminance signal Y575 is processed by a well-known digital quadratic differentiator circuit 72 for extracting edge signals, and a line buffer circuit 7 for 5 lines is used to calculate a 5×5 matrix.
1, and the Laplacian operation is performed in the arithmetic circuit 72 as described above. That is, when the input luminance signal Y is a step-like input (for example, a character part) as shown in i) of FIG. signal). The look-up tables LUTA73a and LUTB73b are look-up tables for determining the printing mc (for example, toner ff1) at the edge portion of black characters (or thin black lines), and are as shown in FIGS. 12(a) and 12(b), respectively. It consists of a lookup table with characteristics. In other words, when LUTA acts on the edge signal 576, the amplitude becomes thicker (
This determines the amount of black toner in the black edge portion, as will be described later. Furthermore, when LUTB acts on the edge signal 576, the absolute value appears as a negative value, which determines the amount of Y, M, and C (yellow magenta, cyan) toner in the black edge portion. This is a signal as shown in FIG. 12(d) (iV), and when it passes through the smoothing (averaging) circuit 74, it becomes a signal as shown in FIG. 12(V). On the other hand, the achromatic color detection circuit 75 outputs, for example, the 12th
This is a circuit that outputs a signal according to the characteristics shown in the figure, and this signal is selected by the selector 76 during black toner printing by the signal 577 that becomes "bi" during black toner printing, and the signal 57
After being multiplied by the signal 579 (FIG. 12(d) (iii)) determining the amount of black toner in a multiplier 77, the signal is added to the original image signal in an adder 78. . On the other hand, when printing with Y, M, and C (yellow, magenta, and cyan) toners, it is desirable that the Y, M, and C toners not be printed on black characters and black lines.
In response to the color selection signal 577, the selector 76 outputs "l" to the multiplier, and the selector 79 outputs "l" to the LUTB 73.
The signal obtained by smoothing the output from 6 (Fig. 12(d)
(V)) is output, and the adder 78 outputs the voltage shown in FIG. 12(d).
The same signal as in (v) is input, and the signal only from the black edge portion is subtracted from the original signal. In other words, the signal that determines the amount of black toner for the black edge area is strong, and by increasing the amount of black toner and decreasing the amount of Y, M, and C toner for the same area, the black area can be reduced. This means expressing it more blackly. The signal 581 obtained by binarizing the achromatic color signal 580 by the binarizing circuit 80b becomes "l" when the color is achromatic, and "0" when the color is chromatic. When printing (577-"B") S input = "B", A input, that is, 579 (Fig. 12(d) (iii)
)) is output and the black edges are emphasized. Y, M, Cl
- When printing a car (577-“0゛), signal 581="
Therefore, if the color is achromatic, the S input is selected to reduce the Y, M, and C toners, and the S input is selected as shown in Figure 12 (d
)(V) is output, but in the case of chromatic colors, the signal 581=
O1 therefore 581=1. That is, S of selector 79
The input becomes l, A is selected, and the result is shown in Fig. 12(d)(ii
The signal of i) is output to adder 78 resulting in the usual well-known edge enhancement. The LUTA 73a has a LUT and a LUT that are zero when the edge signal value is less than or equal to ±n, as shown in FIG. 12(a).
Two types of LUTs are prepared so that the value becomes zero at m or less, and the value to be clamped to zero is selected depending on the level of the original signal 565, that is, the density of the document at this point. When the density level of the original is higher than the value set by the CPU 22 via the bus 508, that is, when it is dark, the output of the comparator 81 becomes "l", and the 12th
LLIT is clamped to zero at A'B' in figure (a), and when the concentration is below a certain level, that is, when the output of the comparator 81 is -"0", LIT is clamped to zero at A and B.
By selecting UT, the noise removal effect is changed depending on the density range. Furthermore, the output 583 of the AND gate 82 is obtained by further improving the edges of black characters, and when printing Y, M, and C, the output 583 (B
This is a signal for switching to select 585 for other inputs. Signal 58 input to AND gate 584
6 is the LUTC (Fig. 12 (C)) for the edge signal mentioned above.
The signal obtained by applying the characteristics of the edge signal is binarized by the binarization circuit 80a. That is, when the absolute value of the edge signal is above a predetermined value, it becomes "1", and when it is below, it becomes "0". Therefore, 5
87 = "l" 581 = "1", 588 = "L" is achromatic and when the edge signal is large, that is, at the edge of the black signal, and also at the edge of Y, M, and C. Only when printing with toner. Therefore, at this time, as explained earlier, only the parts corresponding to the black edges from the original signal are Y and M. The signal determining the amount of toner C is subtracted, and the remaining signal is smoothed by the averaging circuit 84, and when the signal ER="1" is outputted to the selector 83 through the selector 83. Otherwise, the normal edge-enhanced signal 585 is output at output 589. The signal ER is controlled by the CPU 22, and when ER=“l”, the output of the averaging circuit 84 becomes the output 589, and ER=“0”.
”, 0” is output to the output 589. This completely sets the signals of the color toners (Y, M, C) around the edges of the black characters to "0" to further eliminate color blur, and these are selectable. FIG. 13 shows area signal generation (
The aforementioned MAREA566, UAREA572. KARE
A573, etc.). The area refers to, for example, the shaded area in FIG.
Timing chart in Figure 13(e))AR for each YNC
It is distinguished from other areas by a signal such as EA. Note that this area is specified by, for example, the digitizer 16 or the like. FIGS. 13(a) to 13(d) show the generation position 1 of this area signal.
This shows a configuration in which the number of sections having one section length is programmable by the CPU 22 and can be obtained in large numbers. In this configuration, one area signal is generated by one bit of RAM that can be accessed by the CPU, and for example, n area signals ARE
In order to obtain AO~AREAn, an n-bit configuration RAM is used.
(Fig. 13(d) 85A, 85B). Now, the area signal AREAO as shown in FIG. 13(b). and AREAn, the RAM address X
Set "1#" to bit 0 of l, x3, and set bit 0 of the remaining addresses to all 0. On the other hand, RAM address L
xl j X2 * Put “l” on x4,
All bits n of other addresses are set to θ''.H3YNC
When the data in the RAM is sequentially read out in synchronization with a constant clock with reference to , data "1" is read out at addresses X and x3, for example, as shown in FIG. 13(c). This read data is
FIG. 13(d) J- of flip-flops 86-0 to 86-n. I (Since it is connected to both terminals, the output is a toggle operation. That is, when "1" is read from the RAM and CLK is input, the output changes from "0" to "l" and from "l" to "0". As a result, an interval signal such as AREAO, and therefore an area signal, is generated.Also, if data = "Oo" across all addresses, no area interval is generated and no area setting is performed. (d) is this circuit configuration, 85A, 85B
is the RAM mentioned above. In order to switch the area section at high speed, for example, while data is being read from RAMA 35A line by line, RAM 35A
In contrast, the CPU 22 performs memory write operations for setting different areas, and alternately generates sections and
Switches memory writing from the CPU. Therefore, if you specify the shaded area in Figure 13 (''), A-B-A-
RAMA and RAMB are switched like +B-A,
This is shown in (C3, C4, C3) in Figure 13(d).
= (0°l, 0), the counter output counted by VCLK is given as an address to the RAM 35A through the selector 87A (Aa), and the gate 88A
The gate 88B is opened and the gate 88B is closed to read out from the RAM 35A, and the total bit width and n bits are input to the flip-flops 86-0 to 86-n to J-, and the section signals AREAO to AREAn are generated according to the set value. is generated. During this time, writing from the CPU to B is via address bus A-
Bus, data bus D-Bus, and access signal R
/W is used. Conversely, when generating section signals based on data set in RAM885B (C3, C4,
By setting C5)=(1,0,1), the same operation can be performed and data can be written from the CPU to the RAM 35A. Therefore, for example, image processing such as image cropping, frame removal, etc. can be easily performed based on this area signal. That is, the area signal 590 generated by the area generation circuit 69 in FIG. 2 as described above is I10.
Area switching signal ECH591 output from boat 25
is selected by the selector 89, and the AND gate 9
0 input. As is clear from the figure, for example, as shown in FIG. 13(b), the signal 59 is AREAO.
If 0 is formed, the image is cut out from X to X3, and if formed like AREAn, it is cut out from Xl to X
It will be easily understood that the area between 2 and 2 is a frame, and the image is cut out in the area from 1 to Xl+X2 to X4. FIGS. 14 and 15 show the configuration and control timing of the area restriction mask bitmap memory 91. As can be understood from FIG. 2, for example, by using the detection output 592 of the color conversion circuit, which will be described later, it is possible to create an area restriction mask that limits the area only to a specific color area in the document.
Video image signal 56 input from external image storage device 3
0, the signal 59 is binarized by the binarization circuit 92.
3, a region control mask corresponding to the density value (or signal level) can be created. FIG. 14(a) is a block diagram showing details of the area restriction mask bitmap memory 91 and its control. As shown in FIG. 15, the mask is constructed so that 4×4 pixels constitute one block, and one bit of the bitmap memory corresponds to one block, so for example, 16 pixels
For an image with a pixel density of e I / m m, 297 m
For mX420mm (A3 size), (297
X420X16X16) +16 # 2Mbit. That is, for example, IMBit's dynamic R
A.M. It can be configured with 2 chips. The signals 592 and 593 input to the selector 93 in FIG. 14(a) are data input lines for mask generation, as described above, and are connected to the binarization circuit of FIG. 2 by the switching line 594. When output 593 of 92 is selected,
First, in order to count the number of "1"s in a 4x4 block, the buffers 94A, 94B, 9
It is input to 4C and 94D. FIFOs 94A to 94D are connected as shown in the figure, with the output of 94A being connected to the input of 94B, and the output of 94B being connected to the input of 94C.
The output of FO is 4 bits parallel to latches 95A to 95C.
It is latched by VCLK (see the timing chart in FIG. 14(d)). FIFO output 595A and latch 95A, 95B9
Each output 595B, 595C1595D of 5C is added by adder 96A, 96B, 96C (signal 596
), by the CPU 22 in the comparator 97,

[1
0 port 25 (for example, “12”)
) and their sizes are compared. That is, here, 4×4
Determine whether the number of 1s in the block is greater than a predetermined number
do. In FIG. 14(d), the number of “1”s in block N is
14", the number of 1's in block (N+1) is 4"?
The output 597 of the comparator 97 in FIG. 14(a) is
When the signal 597 is “14”, it is “l” and when it is “4”, it is “0”.
Therefore, the latch pulse 598 in FIG. 14(d)
Therefore, latch 98 latches once per 4x4 block.
The Q output of the latch 98 is connected to the DIN input of the memory 99,
In other words, it becomes mask creation data. 100H is a mask
H address counter that generates addresses in the main scanning direction of memory.
It is a counter, and one address is allocated in a 4x4 block.
Therefore, the pixel clock VCLK is divided by the frequency divider 101.
Counting up is performed using a clock frequency divided by 4 by H. Similarly, 100V is the address of the mask memory in the sub-scanning direction.
The same reason applies to the address counter that generates responses.
synchronization signal HSYN of each line by frequency divider 101V
The clock is counted up by dividing C into 4, and the H address is counted up.
Address, ■Address operation is “1” in 4×4 block
The counting (addition) operation is controlled in synchronization with the counting (addition) operation. Also, ■lower 2 bits output of address counter, 599
, 600 is NOR'd by NOR gate 102, and 4 minutes
The signal 602 that gates the clock 601 is
, the first timing chart is set by the AND gate 103.
As shown in Figure 4 (C), there is only one latch per 4x4 block.
In order for this to occur, the latch signal 598 and
, 603 are the devices included in the CPU bus 508 (Fig. 2).
604 is also an address bus,
Signal 605 is write pulse WR from CPU 22
. WR (write) operation from CPTJ22 to memory 99
When activated, the light pulse becomes Lo, and the gate 104,
105 and 106 are opened, and the address bus from the CPU 22
, a data bus is connected to the memory 99, and randomly predetermined
The data of is written, and the H address Karan Yu, ■
The address counter allows sequential WR (writing).
), when performing RD read, connect to I10 boat 25.
Gate 1 is controlled by control lines of gates 107 and 108 connected to each other.
07,108 will open and the sequential address will be memorized.
99. For example, the output 593 of the binarized output 92 or the color conversion
16th output 592 or the CPU 22
Once the mask as shown in the figure is formed, the area within the bold line frame will be used as the base.
You can cut out images, combine them, etc. Next, the mask created in 4x4 pixel block units is
As shown in (i) of Fig. 17(b), the edge part (boundary part)
, the interpolation process shown in Figure 2 will be jagged in 4-pixel units.
By using Route 109, the jagged parts can be smoothed and the appearance improved.
Make it smooth. FIG. 17(a) shows a block diagram of the interpolation circuit. 110 is
It is a selector, and the input to it is a Hi clamp, that is,
If it is 8 bits, it is FF, but the B input is connected to GND, i.e.
In other words, 00H is input, and the bitmap map mentioned above is
Switch between them using the output 606 of the screen memory.
. As a result, the input of the interpolation circuit 111 includes a region mask.
The inside is FFH, and the area mask is 00. is output. child
This is as shown in (i) of FIG. 17(b). interpolation times
The path 111 is, for example, a one-fire interval method, a high-order interpolation method, a 5-inch
Any circuit, such as interpolation method, is fine (or if you are familiar with the circuit configuration)
All you have to do is apply what you learned. The output of the interpolation circuit is multivalued.
Since the input signal is input, the binarization circuit 112 binarizes the signal. to this
Therefore, as shown in (ii) of FIG. 17(b),
The smoothness of the boundary can be improved by changing the original boundary A to B.
I'm trying to secure it. Selector 113 is a mask memo
Either output Lee's output as is (select A), or use the above
Select a mask signal with smooth boundaries after interpolation like
Connected to the I10 port of CPU22 to output
A switching signal 608 is used to switch as necessary.
I can do it. Therefore, for example, by selecting the interpolation output with the signal 608,
Furthermore, selector 89 in Fig. 2 outputs the area restriction mask.
When switching ECH to select, AND gate 90
As shown in Figure 18(a) (a non-rectangular diagram with a mask)
It is possible to cut out shapes. Also, bitmap memory
91 mask memory output from the signal line 607 in FIG.
Take it out and select it with the selector 114, which will be described later.
When synthesized by the synthesis circuit 115, the result is as shown in FIG. 18(b).
It becomes. 116 in FIG. 2 is a density conversion circuit, for example, in FIG.
It became possible to change the density and gradation of each color, as in
It is composed of LUT (lookup table), etc.
Ru. 118 is a repeating circuit, as shown in Fig. 20 (F
Consists of IFO. 609 is H shown in the same figure (b)
3YNC, O pulse is applied once per line.
WR (write) inside the FIFO
Initialize a pointer (not shown). 611 is the input image
data, 612 is output image data, Repeat
Signal 6 initializes the FIFO RD (read) pointer
This is a signal to Therefore, the timing of FIG. 20(b)
As per the chart (, write sequentially to FIFO
The received data 1 to 1O are as shown in the figure (Repeat signal 6
By inputting 16, →l→2→3→4→l
→2→3→I→2→3″ (reading is performed repeatedly)
. In other words, Repeat
By applying the signal 616 to the FIFO, the result shown in FIG.
It is possible to repeat the same image repeatedly. subordinate
So, in the memory for forming the bitmap mask area mentioned above,
Write and read data “1” as shown in Figure 21 (A).
By compositing with the compositing circuit 115 in FIG.
, a dotted line (cut line) is formed. As mentioned above, the image is
The t signal is generated at points ■ and ■ in Figure 21 (A).
If controlled by the area generation circuit 69, it can be applied to repeated images.
Figure 21 (B)
By writing the data “1” as shown, the hanging line becomes (
C) (By writing, you can remove black lines from the image.)
It becomes possible to form. Output from the repeating circuit 118
The input image signal 612 is input to the image synthesis circuit 115.
Various image processing is performed. <Synthesis> Next, create a synthesis circuit using Figure 25 (A), although the figure numbers are different.
Explain the details. The editing process performed here is performed independently for each specified area.
Data set in RAM135, 136 shown in figure (A)
This is done programmably based on the data. That is, the area code generator 13 will be described in detail later.
Code number obtained from 0 (hereinafter referred to as area code)
Each is processed separately. Digitizer 1 is used to specify the above areas and specify various editing processes.
6. Instructions obtained from the operation unit 20 and image storage device 3
(command) through the CPU to the CPU bus 508.
Area code generator 130 and RAM in FIG. 25(A)
135, 1.3'6 and registers 140 to 142.
Parameters corresponding to the process are set. Also, in Fig. 25 (A), 132 is the area code generated.
circuit! 30, select one of the outputs of register 131
Selector to select. Note that 130 is the synchronization signal H3YNC and
An error code that automatically generates an area code according to CLK and
Rear code generator, register 131 is connected to CPU bus 508
This is a register into which signals from 135,136
is an area code and the processing corresponding to the area code or
RAM in which image data is stored as a table
It is. In addition, among the tables in RAM 135 and 136
As for the input address, as shown in Figure 25 (F),
a code input via the selector 132 as
A code that indicates the formed color when the printer is forming an image sequentially.
CO + CI is given, and the output is 3 bits.
It has a default function code and 8-bit data. Furthermore, this
The 3-bit function code is decoded via selector 137.
146. Such function codes will be described later.
For example, text add-on or ゛ is a specific image area.
This is a code for giving instructions such as masking, etc.
The bit data is, for example, the density adjustment data of the image signal 612.
data. 139143.145 is the output of the decoder respectively.
Force So, SL, S2°S3. Select according to S4
144 is a selector that changes the selected state.
This is a multiplier that performs multiplication of the outputs of the data input terminals 143 and 145. 1
46 is 6-bit data input via selector 132
The most significant bit MSB62L (such MSB is the second
At the edge of each area of the image as shown in Figure 5 (E)
“1°°” is output from the area code generator 130.
), the second illustrated signal 613. 614
Character signals input via selector 137
This is a decoder that decodes three function codes. Next, the above-mentioned area code will be explained. Eli
Accord is, for example, a document 147 as shown in Figure 25 (B).
Area 148 is specified using digitizer 16 etc.
When assigning a number or area code to each area.
This is a means of distinguishing each area. In this example, the original
The entire area of the manuscript should be area coded “0” (Figure 25 CB)
Now, let's take a rectangular area with points a and b as diagonals, for example.
Rear code “1”, rectangular shape with points c and d as diagonal lines.
The rear area is set as area code "2". here
For example, when scanning the A-B section shown in the figure, the scanning
At the same time as scanning, input the area code at the timing shown in the figure below.
It is occurring. The same applies to the CD and EF sections. child
An area code is generated at the same time as the document is scanned, as shown in
The area is distinguished by its area code and the territory is controlled in real time.
It realizes different image processing and editing for each area. The above settings are made using the digitizer 16 and operation as described above.
Part 20 has been doing this since. The number of areas that can be set is
Depends on the number of bits in the code, for example, do not set it to n bits.
2” area can be set. Next, Fig. 25(C) shows the area shown in Fig. 25(A) 130.
An example of a schematic internal configuration diagram of a rear code generation circuit is shown. Kaka
The generation circuit 130 generates the area code described above by operating the document.
This is a circuit that simultaneously generates data in real time.
The coordinates of the area obtained by area specifying means such as
Programmable by setting area code
It is designed to generate an area code. Details below
Explain the details. RAM153 and 154 are 7 bits! Each word structure
This memory has a capacity for one main scanning line. This RAM has CPU address bus 627, data bus 6
25, it is connected to the CPU. 149 is address card
To count Video CLK at counter
A RAM address is generated. Count again
Data 149 has been reset by HSYNC and the new
Selector 151 selects the same address every time a new line is scanned.
．． 152 to the RAM 153. Give to 154. Therefore, RAM 153 and 154 store data in response to a reset.
is read from the start. 155 is an interrupt generator that connects the CPU data bus 625 and
and chip select 624 in advance from the CPU.
Count HSYNC input by programmed number
When this occurs, an interrupt signal INT is generated to the CPU.
By toggling the flip-flop 158 to J-,
The RAM read by the address counter 149 is also
Switching. 151. 152°156 is a selector
-, the output of the flip-flop 158 causes A,
By selecting one of the B inputs, the RAM 153,
154 is selected. FIG. 25(D) shows the RAM 153. 154 data structures
FIG. M S B l b as shown
The MSB is divided into i t and the lower 6 bits, and the MSB is
represents the change point between the specified area and the unspecified area.
However, the lower 6 bits can store changing area codes.
Ru. The RAM address corresponds to the Y coordinate, which is the main scanning direction.
are doing. Figure 25 (D) is shown in Figure 25 (E), for example.
Specified area 159 (area code “20”) on original document 150
” ) represents the RAM data when scanning between A-8.
are doing. At this time, the entire area of the document has an area code of “0”.
”.The area set in the opposite direction has the area code “2”.
This is an example of setting the RAM to 0.
Figure 25 (C) Generated from address counter 149
RAM153,154 sequentially from address
Reads and generates area code. For example, the second
When scanning the section shown in Figure 5 (E) A-B, start scanning.
Immediately after, the RAM output is MSB "1" and the lower 6b is "0".
” (area code “0”) is read out, and as shown in Fig. 25 (C
), the latch that uses MSB627 as the latch signal
The lower 6 bits are latched by chip 157 and become the area code.
“0” is output. Also, when reaching the point a(0,P)
The output of the RAM is MSB "l", and the lower 6 bits are "
20” is read out and latched as above and becomes the area code.
“20” is output. The address continues and the next MS
Area code “20” is output until B becomes “l”.
Ru. In other words, address r is read and as mentioned above,
Area code “20” until data is newly latched
continues to be output from the latch 157. The scanning progresses further, and when the main scanning in the Y direction is completed,
HSYNC advances one step in the direction by the interrupt generator 155.
will be counted. At this time, as mentioned above, the address counter
The controller 149 is reset and the read address is also reset.
It starts from 0 and 0. Also, since the area is rectangular
Figure 25 (E) When the scanning of section C-D including point b is completed.
The same data, i.e. RAM + 53, 154, until
Either one of the RAMs continues to be read out, and the
The interrupt generator 155 has a counter of H5YNC in the X direction.
If you set the number of points, in this example (q-o), the interval A
- Interrupt when scanning from B to sections C and D is completed.
The interrupt generator 155 generates an interrupt signal INT, and at the same time
, FIG. 25(C) Toggle of flip-flop 158 to J-
RA read by selector 156 by
M is switched. This allows you to pre-program
The next area information is selected by the selector 156.
Output from RAM. Also, when the interrupt INT occurs,
Therefore, the CPU can occupy the area obtained by the above-mentioned means.
Interrupt generator 155, or
In other words, the idle RAM selected by the selector 156
The unselected RAM is re-created according to another specified area.
Set the signal. Such a set collects data from the CPU.
bus 625 and control of chip select signals C2 and C3.
It is done by God. The configuration described above, i.e. two
Switch RAM sequentially and use idle RAM by CPU.
By programming, the entire document can be stored with less memory capacity.
An area code 626 can be generated for the screen. As mentioned above, the area code shown in Figure 25 (A) is generated.
The area code 626 output from the circuit 130 is selected.
The area code is input to the data processor 132 together with the image signal.
Editing is performed for each area based on the code. The area code generator 130 generates an error code only for rectangular areas.
Accord could be generated, but in this example, a non-rectangular area
It is designed to be able to handle the area. Such a configuration
131 and 132 are provided. 131 shown in Fig. 25 (A) is a register that connects the CPU bus.
508. This register has a non-rectangular
Set an area code that corresponds to the shape area. At this time, as will be described later, a non-rectangular area signal from the image storage device 3
When 615 is input, the signal 615 is set as a select signal.
is set in the register 131 by the selector 132 as
The value corresponding to the non-rectangular area signal is selected.
Non-rectangular area codes can now be obtained. As mentioned above, the area code is 6 bits in this embodiment.
Yes, MS8621 1bit has decoder 146 and
and selector 137, and other signals are input to RAM 13.
5.136 is input in parallel. The RAMs 135 and 136 are connected to the CPU bus (data bus 62
5. CP by 508 (generally refers to address bus 627)
It is connected to U and has a programmable configuration. Figure 25 (F) shows the data structure of RAM135 and 136.
show. 133 is a schematic diagram of the RAM configuration and is used as an address input.
4-bit area code and color selection signal 62
9. 2 bits, a total of 6 bits, are input. At this time, color select signal C8+ CIt C2
From LSB to 2bitC (by setting it to 3, CI, it is possible to
Select which of the four colors the image signal to be sent is.
Select it to access each area code (brown).
I am changing the address. In this embodiment, as will be described later, the printer 2 does not form an image.
M (magenta), C (cyan), Y (yellow) for each color
, Bk (black) images are transferred in sequential order. child
, the type of color to be transferred is shown in Figure 25 (A).
-Select 629 signals C8, C1 (shown in Figure 10(a))
(This is the same signal as C0, C,). A detailed data structure diagram is shown at 134 in FIG. 25(F). figure
It has a function code from MSB to 3 bits like this.
Follow the code by decoding it
, each performs different image processing. Please note that this implementation
In the example, it can be expressed by representing the function code with 3 bits.
6 types of image editing possible for each area code or color
It is called Noh. The lower 8 bits are images according to the function code.
Stores various parameters when editing processing. Selected from area code and color select signal
The data is 3 bits starting from the MSB, that is, the function code is the second
Input to the selector 137 shown in FIG. 5 (A) 137,
Two RAs with area code MSB 621
Switch the 3-bit function code output from M.
There is. On the other hand, the lower 8 bits of data are also sent to the decoder 146.
Selected by selector 139 by select signal Sl from
and output. The function code selected above is input to the decoder 146.
character signal 622, and area code M S B b
i t621 to perform editing processing.
A control signal 623 is generated for this purpose. Each control signal
Used as a selector signal to change the signal flow
Edited by. In this embodiment, the control signal
This realizes the six editing functions described below. ■Within the area specified through area, the image signal is output without any processing.
This is a function that allows The input image signal is the negative shown in 138
It passes through a positive inversion circuit (described later) and is selected by S2.
-143 and input to a multiplier 144. On the other hand, RAM data is transferred from selector 139 by Sl.
Either one is selected, and then S3. Determined by S4
is passed through the selector 145 determined by the multiplier 144.
is calculated with the image signal and output. At this time, multiplier 1
The density of the image is determined from the RAM data input to 44.
a different count for each color.
By setting the number, the density and color balance can be adjusted independently for each area.
is variable. In other words, if the user sets the area using the operation panel.
Later, when you set the color balance for the area, the CPU will
1? via bus 508. AM135 again
is written to the RAM 136. Furthermore, the selector 145
B input is selected and the image signal 612 and multiplier 144
All you have to do is multiply. ■Intra-area masking: Paint the entire specified area uniformly with any other color.
This is a function that outputs a crushed image. For example, when scanning a certain area with this function set, S2
The RAM data is selected instead of the image signal and multiplied by
It is input to the calculator 144. On the other hand, the coefficient is the control signal S3.
Select register 142 from S4, not shown.
It is connected to CPtJ by bus, and CPtJ is connected in advance.
A more appropriate coefficient than U, for example "1", is stored. multiplier
It is calculated and output at 144. ■Insertion of characters within the area (1) For example, as shown in Figure 25 (G), the specified area 1 of the image
In the mode to insert characters like 160 into 59
be. For example, as shown in 161 in advance,
Store character data in memory, etc. of the specified area
At the same time as scanning, the binary data of the character is generated at the timing shown in the figure.
The character signal 62 is scanned and read out from memory.
Set it to 2. This signal is shown in the sentence shown in Fig. 25 (A) 622.
Input as a character signal and switch selector 143
. That is, when the character signal 622 is High, the select
The controller 143 stores data in the RAM 135 or 136.
5o that selects the image signal and selects the image signal when it is Low.
The decoder 146 performs insertion by outputting -84.
ing. In addition to the above character signal, 33. S4
also changes, and the coefficient of the multiplier 14/I becomes high when the character signal 622
At gh, register 140 is selected. This is also mentioned above
In the same way as above, it is connected to the CPU bus and
Set an appropriate coefficient. Usually 1 in register 140
(Especially for registers)
You can freely change the density of inserted characters by
I can do it. ■Insertion of characters within the area (2) As shown in Figure 25 (H), insert text into the specified area in a specified color.
and also as described above for that same area.
This function allows you to insert text in a different specified color. designated territory
While scanning the area, the selector 143 is set to R as described above.
AM data is selected. As mentioned earlier, at this time,
Obtained from the bitmap memory shown in Figure 25 (G)
The selector 139 is switched based on the character signal. Sunawa
If it is not a character, the data in RAM 135 is output and the text is
When it is a character, it is executed by selecting RAM136.
ing. Note that the RAM 136 is set up in advance as an area, for example.
For example, the density data of the characters within the area, 135, is the density data of the characters within the area.
The external concentration data is written via the CPU bus 508.
ing. Similarly to the above, registers are also available for coefficients as well as character signals.
Tar142. 140 is selectively output. The multiplier 144 calculates and outputs the result. In other words, since registers 140 and 142 are provided separately,
You can set the density for text and literature sections independently. ■ Negative/positive reversal within the area This is a function that outputs only the negative/positive images within the area.
The negative/positive inversion circuit 138 is switched by the control signal SO.
This is done by switching. The output from 138 is output with the same settings as the through function.
It will be done. ■ Inserting negative/positive inverted characters within an area The character insertion function (1) within an area described above and
Negative/positive inversion within the area by combining negative/positive inversion
This is a function to insert text into images. The character insertion method is
Since it is the same as the notation method, the explanation will be omitted. In the embodiment described below, the decoding of FIG. 25 (Δ)
The operation of the driver 146 is shown in FIG. 25(1). In the figure, 1 to 6 shown in the leftmost column are the above-mentioned ■ to ■.
It shows each function. It is also shown as ``1 input'' in the diagram.
The left side is the input of the decoder 146, and as the "output"
The right side shown is the output 5o-34 of the decoder 146. Images processed by the video processing unit 12 as described above
Information is sent to the color printer via the printer interface 56.
output to the printer 2. <Description of color printer 2> Next, the configuration of the color printer 2 will be explained using FIG.
Ru. In the configuration of the printer 2 in FIG. 1, 711 is a scanner.
and converts the image signal from the color reader l into an optical signal.
Laser output part, polygon of polyhedron (e.g. octahedron)
Mirror 712, rotate this polygon mirror 712
Motor (not shown) and f/θ lens (imaging lens) 7
It has 13 mag. 714 is the gap indicated by the dashed line in the figure.
Reflection mirror that changes the optical path of the laser beam from scanner 711
, 715 is a photosensitive drum. The laser beam emitted from the laser output section is passed through a polygon mirror.
712, the f/θ lens 713 and reflection mirror
-714 scans the surface of the photosensitive drum 715 in a linear manner.
star scan) to form a latent image corresponding to the original image.
Ru. In addition, 717 is a primary charger, 718 is a full exposure lamp,
723 is a cleaner that collects residual toner that was not transferred.
The inner part 724 is a pre-transfer charger, and these members are
It is arranged around the optical drum 715. 726 is Ray
formed on the surface of the photosensitive drum 715 by the exposure.
It is a developer unit that develops an electrostatic latent image, and is 731Y.
(for yellow), 731M (for magenta), 731C (
(for cyan) and 731Bk (for black) are photosensitive drums.
Developing sleeve that directly develops in contact with 715, 730Y
, 730M, 730C, 7308 have spare toner.
Hold the T-ner holder, 732, for developer transfer.
This is the screw that carries out the feeding. These sleeves 731Y
~7318, ) Nahotsuba-730Y~730Bk
And the developer unit 726 is installed by the screw 732.
These members rotate as the developing unit 726 rotates.
It is arranged around the axis P. For example, when forming a yellow toner image, use the position shown in this figure.
Develop with yellow toner. macenta toner image
When forming, center the developing unit 726 on the axis P in the figure.
and develop magenta at the position touching the photoreceptor 715.
The developing sleeve 731M inside the container is arranged. cyan, blue
Similarly, for rack development, move the developer unit 726 to the axis shown in the figure.
It operates by rotating around P. Further, 716 is a toner formed on the photosensitive drum 715.
7I9 is a transfer drum that transfers an image onto paper.
Actuator for detecting the moving position of ram 716
The plate 720 is in close proximity to this actuator plate 719.
As a result, the transfer drum 716 moves to the home position.
The position sensor 725 detects the movement of the transfer drive.
Ram cleaner, 727 is paper press roller, 728 is static neutralizer
729 is a transfer charger, and these members 719.
720.725.727°729 is the transfer roller 716
are placed around the area. On the other hand, 735 and 736 are paper feeders that collect paper (paper sheets).
Cassette, 737, 738 is cassette 735.736?
Paper feed roller that feeds paper from 739.740.741
is a timing roller that takes the timing of paper feeding and conveyance.
It is. Paper fed and conveyed via these
The tip is guided by the id 749 and held by the gripper described later.
while wrapping around the transfer drum 716 and moving on to the image forming process.
do. Further, 550 is a drum rotation motor, and the photosensitive drum 7
15 and the transfer drum 716 are rotated synchronously. 750 transfers the paper to the transfer drum 716 after the image forming process is completed.
The peeling claw 742 removes the removed paper from the
Conveyor belt 743 is conveyed by conveyor belt 742
This is the image fixing unit that fixes the paper that has been
In section 743, the motor is attached to section 748.
The rotational force of the motor 747 is transmitted through the transmission gear 746.
is transmitted to a pair of thermal pressure rollers 744 and 745,
The material transported between the heat pressure rollers 744 and 745
Fixes the image on paper. Printout processing of printer 2 with the above configuration
will be explained below with reference to the timing chart in Figure 22.
I will clarify. First, when the first fTOP comes, the photosensitive dome is exposed to laser light.
A Y latent image is formed on the ram 715, and this is the developing unit.
731Y, and then the paper on the transfer drum.
Transfer is performed to perform magenta printing processing. So
Then, the developing unit 726 rotates around the axis P in the figure.
. When the next ITOP551 arrives, the photosensitive drive is exposed to laser light.
An M latent image is formed on the image, and the same operation is performed thereafter to form an M latent image.
processing is performed. ITOP5 following this movement
Corresponding to 51, do the same for C and Bk, and
-Print processing and black print processing are performed. child
After the image forming process is completed, the peeling claw 7
50, the paper is peeled off, and the image fixing unit 743 fixes the paper.
The printing of the series of color images is completed. Next, description of the film scanner 34> Using FIG. 45 of the film scanner 34 shown in FIG.
explain. 3001 is a light source (lamp) for illuminating a transparent original; 3002
is a heat ray absorption method that removes heat rays from the light rays from the light source 300I.
Filter, 30o3 is the illumination that passed through filter 3002
This is an illumination optical system that converts light into a parallel beam. 3004 is transparent
A sub-scanning drive table 3005 moves the original in the sub-scanning direction.
A rotating table for rotating transparent originals, 3006 stores transparent originals.
Film holder, 3007 is for 35mm photographic film.
It is a transparent manuscript that looks like a blank page. 3008 is transparent original 300
A movable mirror that switches the optical path of the light beam (original image) transmitted through 7.
, 3009 is a mirror that deflects the optical path of the original image, 301O
is an imaging lens that forms an image of the original that has passed through the mirror 3009.
It is. 3017 is a lamp holding member that supports the light source 3001.
Ru. 3064 is a COD positioning mechanism and an imaging record, respectively.
The transparent original image formed by the lens 3010 is photoelectrically converted.
It has R, G, and B color separation filters for
CCD light using a COD (charge-coupled device) array
sensors 3061, 3062, and 3063. 3025 is CCD line sensor 3061.3062.3
Amplify the analog output of 063 and convert it to A/D (analog/
Analog circuit that performs digital) conversion, 3026 is analog
D that generates a standard signal for adjustment to the tuning circuit 3025
I adjustment signal generation source 3027 is analog circuit section 3025
For R, G, and H digital image signals obtained from
A dark correction circuit that performs dark correction, 3028 is a dark correction circuit.
Apply shading correction to the output signal of the positive circuit 3027
Shading correction circuit, 3029 is a shading correction circuit.
Pixel count in the main scanning direction with respect to the output signal of the positive circuit 3028
This is an image shift correction circuit that corrects the image shift. 3030 is R9G that has passed through the image shift correction circuit 3029;
For example, Y (yellow), M depending on the device that outputs the B signal.
(magenta) and C (cyan).
This is a color conversion circuit. Also, 3031 is the signal LOG
, a lookup table (LUT) that performs transformations and γ transformations.
It is. Output of lookup table (LUT) 3031
The force is the interface circuit 3038 and the minimum value detection circuit 3
032. 3032 is the output signal of the lookup table 3031
A minimum value detection circuit that detects the minimum value of , 3033 is the minimum value
Undercolor removal (UGR) according to the detection value of the detection circuit 3032
Look-up table (LUT) to obtain the control amount for
, 3034 is the output signal of the lookup table 3031
a masking circuit 303 that performs masking processing on
5 is a look for the output signal of the masking circuit 3034.
Undercolor removal processing is performed based on the output value of up table 3033.
This is a UCR circuit (undercolor removal circuit) that performs this. 3036 is U
Specify the recording density for the output signal of the CR circuit 3035.
3037 is a density conversion circuit 30
36 output signals are converted to the specified magnification ratio.
This is a variable magnification processing circuit. 3038 is the color reader l and image storage device 3 shown in Fig. 1.
Interface circuit (I/
F), 3039 is a controller that controls the entire device
There is a microcomputer inside the controller 3039.
CPU (Central Processing Unit) of computer, processing procedure
ROM (read-only) where is stored in program form.
memory), R used as data storage and work area
AM (Random Access Memory), etc. 3040 is an interface circuit from the scaling processing circuit 3037.
3038 and an output input via the controller 3039.
The peak detection circuit 3041 detects the peak value of the force value.
an operation unit 30 for giving various instructions to the controller 3039;
42 is a table displaying the control status of the controller 3039, etc.
This is the exhibition section. 3034 performs aperture control of the above-mentioned imaging lens 3010
A lens aperture control unit 3044 controls the focus of the imaging lens 301O.
Lens distance ring control unit that performs point adjustment, 3045 is a movable mirror
-3008. 3048 is a film feed control section, and a film holder
-3006 to feed the film. 3049 is a secondary runner
a sub-scanning control unit 30 that controls scanning of the scanning drive table 3004;
50 is a lamp that controls the amount of light from the light source (lamp) 3001
The light amount control circuit 3051 is connected via the lamp holding member 3017.
A lamp position driving source that adjusts the position of the light source 3001 by
be. 3052 is a timing control based on the control of the controller 3039.
Timing generator that generates clock signals (clocks)
, 3053 are the above-mentioned control units, processing circuits, and controllers.
3039 is connected to the bus, 3054 is for the output device.
Data line 3055 is an output device for inputting and outputting image data.
synchronization signal Hsync for the device. Synchronous signal line for inputting and outputting Vsync etc., and 3056
is a command with a given protocol between interfaces.
This is a communication line for exchanging codes. Next, the operation of each part will be explained. The light source 3001 is a light source such as a halogen lamp, for example.
The light emitted from the light source 3001 is passed through the heat absorption filter 30.
02 and the film holder through the illumination optical system 3003.
- Like the 35mm photographic film on 3006
A transparent original 3007 is illuminated. Image of transparent original 3007
The optical path is switched by the movable mirror 3008.
Accordingly, ■projection lens 3011 and mirror 3012. 3013
through the mirror 3009, the imaging lens 3010, and the three colors.
The CCD line sensor 302 passes through the resolution prism 3021.
2 to 3024. In the case of the above mode ■, the CCD line sensor
3022 to 3024 are timing generators 3052
Each CCD light is driven synchronously by the clock of
The output signal of the sensor is input to the analog circuit 3025.
Ru. The analog circuit 3025 includes an amplifier and an A/D converter.
The signal amplified by the amplifier is
For A/D conversion output from generator 3052
A/D converter performs A/D conversion in synchronization with the timing clock.
exchange. Next, RlG and H output from the analog circuit 3025
to the dark processing circuit 3027 for each digital signal.
Apply level correction for darker signals, then shading
The correction circuit 3028 performs shading correction in the main scanning direction.
The pixel shift correction circuit 3029 performs correction in the main scanning direction.
For example, FIFO (first-in-first)
Shifting the buffer write timing
Corrected by Next, in the color conversion circuit 3030, the color separation optical system 3021
%RIG, B signal depending on the output device.
to Y, M, C color signals, Y, I, Q color signals.
Convert it to a number. Next lookup table 303
1, by referring to the table, the luminance linear signal is LO
Convert to G or perform arbitrary γ conversion. 3032 to 3037 are mainly used for color laser copying machines.
Y, M, C, Bk (black) used in Una printer
Configures an image processing circuit to output images using four colors.
do. Here, the minimum value detection circuit 3032, the masking circuit
path 3034, lookup table 3033, and U
CR circuit 3035 combination, printer masking
and perform UCR (undercolor removal). Next, the density conversion circuit 3036 creates a table of each density signal.
After that, the magnification processing circuit 3037 performs main
Perform magnification processing in the scanning direction, and after the magnification processing Y',
Interfacing M', C', Bk' signals
is sent to the color reader l via the face circuit 3038. In addition, the interface circuit 3038 is
Lookup table in addition to M', C', Bk' signals
Image information R (retsu, de), G (gree) from
) and B (blue) can also be output. This depends on the device to which this film scanner 34 is connected.
Y' if determined and connected to color reader 1;
In the form M', C', Bk', and
, R, G, and B shapes when connecting to image storage device 3.
Output image data using a formula. Further, in the embodiment shown in FIG. 45, the film scanner 34
As shown in Figure 46, how to set the film on the
Two types are possible. The above figure shows the fill installed in mount M1 using auto change.
Image sample that you want to read by setting many images at once
If you enter which sample and how many sheets to read in the initial settings,
It is intended to operate automatically. The figure below shows how carriers are transferred to the magazine using autoloader M2.
Sensor for aligning the feeding mechanism and its carrier
It has been established. <Description of the image storage device 3> First, the image storage device 3 starts from the color reader l in this embodiment.
How to store data in device 3 and Sv, which is one of the input video devices.
Recording of video information from the recorder/player 31 into the image storage device W3
Let's talk about how to memorize. Also, film scanner 34
Regarding the method of storing the image information in the image storage device 3,
state Next, image information is read from the image storage device 3 and processed.
The present invention then forms an image using a color printer 2.
An example of this will be described in detail. (Image storage from color reader 1) Setting the reading area by color reader 1 is described below.
This is done with a digitizer. An external view of this digitizer 16 is shown in FIG. Transfer image data from color reader l to image storage device 3
The operating method for sending will be described later. The mode setting screen 420
, is for setting an arbitrary area on the scanned document.
be. The point pen 421 is used to specify the coordinates.
be. Transfer the image data of any area on the document to the image storage device 3.
To send images, first set the image registration mode using the operation unit 20.
, indicates the position to be read using the point pen 421. The operating method will be described later. The information in this reading area is transmitted to the communication line 505 in FIG.
to the video processing unit 12 via. In the video processing unit 12, this signal is sent to the CPU control
from the video interface 201 by the input 508;
Send it to the image storage device 3. Sends information on the specified area of the original 999 to the image storage device 3.
Describe the process. Figure 24 shows the point pen 421 of the digitizer 16.
was instructed. Example of address of area information (points A and B)
shows. Color reader l has VCLK signal, ITOP, EN signal
etc., along with the image data 205 on the signal line 207.
Output to image storage device 3. These output signal lines
A timing chart is shown in FIG. 26. The video interface 201 also includes the device shown in FIG.
The flow of data is as follows. As shown in FIG. 26, press the start button on the operation section 20.
By pressing, the stepping motor 14 is driven,
The document scanning unit 11 starts scanning and reaches the leading edge of the document.
When the ITOP signal becomes “1”, the document scanning unit
11 reaches the area specified by the digitizer 16, and this
While scanning the area, the EN signal becomes "1". For this reason,■
When the signal is “read color image information (DATA2)”
05). As shown in Figure 26 above, the image from color reader l is
Image data transfer is performed using the video interface 201 as the third
By controlling as shown in the figure, ITOP, 1 signal
control signal and VCLK as signal 207.
Output from interface 201 and synchronize with said 207
R data 205R, G data 205G, B data 2
05B is sent to the image storage device 3 in real time. Next, using these image data and control signals, the image storage device
Figure 27 (A) ~ shows how 3 is specifically memorized.
This will be explained with reference to (F). The connector 4550 is connected to the bit inside the color reader I shown in FIG.
connected to the video interface 201 via a cable.
R data 205R, G data 205G. B data 205B are 9430R and 9430G, respectively.
. Connected to selector 425o via 94, 30B
There is. V sent from video interface 201
CLK, EN signal, ITOP are signal lines 9450S
is input to the selector 4250 through. Also, the manuscript
digitizer 16 before reading the
The area information is sent to the reader control via communication line 9460.
from there to the CPU bus 9610.
The data is read by the CPU 4360 via the CPU 4360. input to selector 4250 via connector 4550
R data 9430R, G data 9430G, B data
Selector 9430B is selected by selector 4250.
Signal lines 9421R, 9421G, 9421
B and input to the filter circuit 9500. FIG. 28(A) shows the filter circuit 9500 in detail.
FIG. Image signals 9421R, 9421G, 9421B are F
Enter IFO memory 4252R, 4252G, 4252B.
Powered. It also receives timing control signals from the system controller.
No. 9450. FIFO memory 4252R, 4252G, 4252B?
The outputs are image information 9421R, 9421G, 9
421B, it is a signal with l main scanning delay, and the signal line is
through the adders 9422R, 9422G, and 9422B.
4253R. It is input to 4253G and 4253B. Adder 4253
R. 4253B and 4253G have 2 pixels in the main scanning direction and 2 pixels in the sub-scanning direction.
The average of two pixels in the direction, that is, four pixels, is taken, and the signal line 9
Output to 423R, 9423G, 9423B. Selectors 4254R, 4254G, and 4254B are image signals.
No. 9421R, 9421G, 9421 white or additive average
Signals 9423R, 9423G, 9423B
Make selection and signal 9420R, 9420G, 9420
B and is input to each image memory. The above selector 4.254R, 4254G, 4254B
Although not shown, the select signal is generated by the CPU 4360.
It is controlled and programmable. As explained above, the filter circuit 9500, for example,
When a halftone image etc. is read from color reader 1, the model
Images are averaged to prevent image deterioration due to cracks.
It will be done. 28(B) and (C) show the internal structure of the selector 4250.
A block diagram showing the configuration is shown. Color reader as shown
1 or various video devices such as still videos as described later.
Any image signal from a video player or film scanner
It is now possible to switch to . These switching
Signal is programmable from CPU via decoder DC
can be controlled. For example, image information from the color reader 1 to the image storage device 3
When storing, control signal 5ELECT-A. 5ELECT-1) to 0 and set the triste pad.
'7774251R,G,B,HS,VS,CK,EN
Ohi 4252R, G, B, H8, VS, CK,
Taking advantage of EN(7), other tri-state buffers
By setting all to high impedance, color reader 1
Image signals 9430R, G, B and control signals 94 from
50S is 9421R, G, B and 9420 respectively
Combined with S. The image selected by selector 4250 as described above
The signal passes through filter 9500 and is sent to the system controller.
The information is stored in each memory under the control of the controller 4210. below
The details will be explained. The system controller 421O selector 4254R
. 4254G, 4254B and filter 9500
Image data 9420R, 9420G, 9420B
In other words, only the effective area of the image is stored in FIFO memory 4050AR.
. Transfer to 4050AG and 4050AB. Also, the system
At this time, the program controller 4210 performs trimming processing and
The scaling process is also performed at the same time. Furthermore, FIFO memories 4050AR and 4050AG. 4050AB is a color reader 1 and image storage device 3 clone.
absorb differences in the market. These processes of this embodiment are shown in the circuit diagrams of FIGS. 27 and 29.
, and the timing chart in Figure 30 below.
explain. Selectors 4253R and 4253G shown in FIG. 28(B)
. FI'F from 4253B through filter 9500
O memory 4050AR, 4050AG, 4050A
Prior to data transfer to B, the digitizer 16
The effective area of the area in the main scanning direction is sent to the CPU bus 9610.
Therefore, comparators 4232 and 423 shown in FIG.
Write in 3. In addition, Fig. 29 shows the system controller 4.
Configuration of 21O and FIFO memory in memory A-M
FIG. 3 is a diagram showing the configuration. Comparator 4232 is instructed by digitizer 16
Compare the start address of the area in the main scanning direction.
A stop address is set in the controller 4233. Also, the sub-scanning direction of the area specified by the digitizer 16 is
, controls the selector 4213 and selects the CPU/< processor 9610 side
Select and enable the area specified in RAM4212.
Write “O” data to the valid area, and write “O” data to the invalid area.
Write “l” data. The magnification processing in the main scanning direction is performed using the rate map shown in Figure 29.
The change is made to the multiplier 4234 via the CPU bus 9610.
Set the magnification. Also, the magnification processing in the sub-scanning direction is
This is possible depending on the data written to the RAM 4212. Figure 30 shows the timing chart when trimming processing is applied.
It is a chart. As mentioned above, use the digitizer 16 to
To store only the indicated area in memory (trimming)
processing), the trimming position in the main scanning direction is shown in Figure 29.
Set in comparators 4232 and 4233, sub-scanning direction
The trimming position in the direction is set by selecting the selector 4213 from the CPU bus.
961O side and write to RAM4212 by CPU
((Example) Main scan the trimming area from 1000 to 3047
, sub-scanning 1000 to 5095). That is, R.A.
M4212 is a counter 42 input via a selector.
14 in the area corresponding to each output address.
Or "0" is written by the CPU. here
As will be described later, “1” indicates the reading of memories 4050R, G, and B.
Extending is prohibited, and “0” is data that causes reading.
Ru. The trimming section signal 9100 in the main scanning direction is H3YN
Count in synchronization with CIN9452 and CLKIN9456
The counter 4230 operates, and the counter output 9103 becomes 10.
00, the output of comparator 4232 becomes 1.
Therefore, the output Q of the flip-flop 4235 becomes 1. Next, when the counter output 9103 becomes 3047, the command
The output of the comparator 4233 becomes 1, and the flip-flop
The output of step 4235 goes from 1 to 0. Also, in Figure 30
In the timing chart, since equal can processing is performed,
The output of rate multiplier 4234 is! It is. bird
FIFO memory 405 according to timing interval signal 9100
Color image information 1 that is manually input to 0AR, AG, AB
From address 000 to address 3047 is FIFO memory 40
Written to 50AR, AG, AB. Also, from comparator 4231) (SYNCIN9
Outputs signal 9107 delayed by one pixel with respect to 452.
. In this way, the FIFO memory 4050AR,AG. AB's old one-man power, "-1 to give a phase difference to one-man power"
As a result, the FIFO memory 4050AR, AG, AB is entered.
Powered by CLKIN9456 and CLK9453
Absorb the difference in cycles. Next, for trimming in the sub-scanning direction, first
Select the counter 4214 side that controlled the rector 4213.
Assuming that it is valid, VT' So n Kodama 9455, H3' Hyakumo Kodama
The interval signal 9104 synchronized with 9452 is stored in RAM4212.
Output from. The section signal 9104 is the flip-flop 4
211 to synchronize with signal 91.07, FIFO memory
Input to read enable of 4050AR, AG, AB.
Ru. That is, FIFO memory 4050AR,AG. The image information stored in AB is the trimming signal 9101
is output only in the 0° section (n - m'). Also, the signal 9101 is output from the counter as shown in Fig. 32.
The counter enable signal is input to the controller 9141.
and memory 4060A-R, G, B
This is a toy enable signal, and as mentioned above, the FIF
Output from O memory 4050A, R, G, B
Image information is the address output from counter 408OA-0.
Immediately write to memory 4060A-RG, B according to the response.
be included. In the above explanation, only the trimming process was explained.
However, scaling processing is also possible at the same time as trimming. Main scan
To change the magnification in the direction, set the magnification rate to the rate multiplier 4234.
Set via CPU bus 961O. Also, sub-scanning is RA
Variable magnification processing is possible depending on the data written to M4212.
Ru. Figure 31 shows the cropping process and scaling process (50%).
A timing chart is shown below. Figure 31 shows image data from selectors 4254R, G, and B.
The data is scaled and reduced by 50%, and the FIFO memory 405
Timing chart when transferring to 0AR, AG, AB
FIG. The CPU bus is connected to the rate multiplier 4234 in Figure 29.
9610 to set a setting value of 50% reduction. At this time, the output of the rate multiplier 9106 is the 31st
As shown in the figure, “0” and “l” are displayed for each pixel in the main scanning direction.
This results in a repeated waveform. Compare with this signal 9106
Data 4232. Section signal 9105 created by 4233
The AND signal 9100 is the FIFO memory 4050AR
, AG, AB by controlling the write enable.
Perform the reduction. Also, sub-scanning is performed on the RAM 4212 as shown in Figure 31.
write data (FrFO memory 4050/'R,A
G. Read enable signal to AB) to image data valid area
By setting it to “1” (reading prohibited), 50%
Only the reduced image data is stored in the image memory 406°AR,
AG, ABI: Sent. In the case of Figure 31,
The read enable signal 9101 receives “l” and “0” data.
50% reduction is performed alternately (returning). In other words, trimming in the main scanning direction and scaling processing are performed at F.
Write enable of IFO memory 4050AR, AG, AB
control, cropping and scaling in the sub-scanning direction
is FIFO memory 4050AR,AG. Controls AB read enable. Next, FIFO memory 4050AR, 4050AG,
4050AB to memory 4060AR, 4060AG,
Transfer of image data to 4060AB is shown in Figure 27 (C).
Counter control 9141A and counter 4 shown
Performed by 080A-0~3 and control line 9101
Ru. Note that 9101 is the comparator 4231 shown in FIG.
Output and read enable for FIFO4050R, G, and B.
Bull RE, the RAM of memory 406OA-R-8 shown in FIG.
It is used as a light enable. Counter control 914.1 shown in FIG. 27(C)
A is the address for memory 4060A-R, G, H
Controls counters 4080A-0 to 3 that generate
The main circuit described below is executed by commands from the CPU.
It has three types of functions. 1. CPU read/write mode → data at any address can be referenced by the CPU
. 2. Read mode → Read the stored image data by the control signal of the system controller.
Read the data and transfer it to color reader 1 to get a printout.
. 3. Light mode → Color reader by control signal of system controller
Store the image from l. In either case, count of counter 4080A-0 to 3
The start address can be set arbitrarily from the CPU.
. This allows reading and writing from any address.
becomes possible. Normally the start address is address 0. Control line 9101 is FIFO memory, 4050AR. This is a read enable signal for AG and AB, and also a counter
is input to the counter control 9141A and the counter is controlled.
It will be done. Furthermore, write memory 4060AR, AG, AB
It is also an enable signal. Counter control 9141A is in light mode
, input control signal 9101 to counter 4080A-
Used as a counter enable signal for 0 to 3.
Counter control is a counter that responds to CPU commands.
In some cases, you select all counters, and in other cases, you select all counters.
Ru. 9140A is a control line 9 which is a counter selection signal.
When 101 is “0”, FIFO memory 4050R,G,
The image data read from B is stored in memories 4060R and G.
, B. At this time, for example, counter 4080A-0 is selected.
counter 4080A-047) enable is “
O” and counts in synchronization with CLK9453.
The up signal 9120-0 is sent from the counter 4080-0.
is output and passes through the selector 4070 to the memory 4060AR.
. It is input to the ADR9110 of AG and AB. Also, at this time, the memory 4060AR, AG, AB write
Toy enable WE9101 is also “0”, so
Image data input to memory 4060R, G, B
9090R, G, and B are stored. Note that the memory capacity in this example is 1M bytes for each color.
Therefore, the image data of the reading area in Fig. 24
By reducing the size of the image by 50%, the read image data becomes
Convert data to maximum capacity of memory of image storage device 3
and is remembered. Further, in the above embodiment, the CPU 4360 handles the A3 document.
The effective area is determined from the area information specified by the digitizer 16.
The comparators 4231 to 423 shown in FIG.
3. Rate multiplier 4234 and RAM4
The data corresponding to 212 is set. In this embodiment, the image data capacity of the read image is
Since it is larger than the image memory capacity, it can be reduced and stored.
After converting it to a certain capacity, it was stored in the image memory. However, reading
The data capacity of the captured image is based on the image memory capacity.
If the area is small, take a note of the area specified by the digitizer 16.
Comparator 4232.42 that controls writing to the
331. :C, set the trimming information data, rate
The multiplier 4234 is set to equal magnification. Also,
The write data to RAM4212 is in the image effective area.
Set all to “O” and all others to “1” to set the same size.
. It also preserves the aspect ratio (vertical/width ratio) of the scanned image.
In order to store it in memory as it is, first the CPU 4360
is valid from the area information sent from the digitizer 16.
Find the number of pixels “X”. Next, up to 3 amounts of image storage memory
From "y", calculate 2 using the following formula. -XIOQ Tomi 2 As a result, (1) When z≧100, rate multiplier 42
The setting of 34 is 100% of the effective image area in RAM4212.
Set everything to “0” and store at the same size. (2) When z<100, rate multiplier 423
4 settings and! ? AM4212 both reduced by 2%
Write to maximum memory capacity while maintaining aspect ratio.
I remember. Even in this case, the data written to RAM4212 is
, timely data of “1” and “O” corresponding to reduction rate “2”
Just write it down. By controlling in this way, only the image storage device 3
control to maintain the aspect ratio of the input image.
Enables variable magnification processing with easy control, improving the effectiveness of scanned images.
effective recognition becomes possible. At the same time, memory capacity usage
It is possible to maximize efficiency. In addition, the settings described above in 1.
(A, B, C, D) and as shown in Figure 27 (E).
The display (memory M) can also be set independently.
When storing images, the same image is stored at different magnifications.
Sometimes separate memories are used, for example memories A, B, as mentioned above,
It can be stored in C, D, memory M, etc. <Description of Memory E> Memory E in FIG. 27(A) will be described. No.
Figure 27 (D-1) shows a schematic diagram of its internal configuration. memory
E is a binary image memory (hereinafter referred to as bitmap memory).
), and its operation is similar to memory A described in the previous section. bits in the image data read from the color reader.
The image data written to map memory E is explained in the previous section.
Similar selector 4250. memory through filter 9500
FIFO4050E- shown in Figure 27 (D-1) in E
Written to R. In such a case, as explained in Figure 29.
Similarly, writing is controlled by write enable 9100.
be controlled. At this time, in the embodiment, only the R signal is used as an image signal.
but anything else as long as it is represented by a luminance signal.
good. For example, G signal or R, G, B at a predetermined ratio.
The signal may be a weighted average signal. FIFO405
The image data written to 0ER is controlled as explained in the previous section.
It is read out by the control signal 9101 and shown in 4055-R.
The data is binarized by a binarization circuit and sequentially written to memory.
It will be done. At this point, "l" white becomes "0". The threshold value for this 2@I conversion is set by the CPU to a predetermined value via the bus.
is written to the register 4053. For example, Fig. 27 (D-
As shown in 2), a heart-shaped original with a certain density is drawn on a white background.
Prepare draft A and specify area B as shown by the dotted line in the figure. this
By reading the area into bitmap memory E
The bitmap memory contains two values: '0' and 'l#' as shown in the figure.
The image is stored. 4080E is the read/write access for memory 4060ER.
counter for controlling dress, 914. IE is
for controlling the count state of the counter 4080E.
It is a counter control and system controller 4
210 as described in FIG.
Read/write position is controlled by PU
. By reading this data sequentially as shown by the arrow,
Then, a non-rectangular area signal as shown in F in Figure 27 (D-2) is obtained.
, is output to the signal line 4072 and selected by the selector 4071.
! / is used as a signal. One of the selectors 4071
One input has an 8-bit capacity connected to the CPU bus.
A register 4074 is provided to set a predetermined output concentration in advance.
The other input has a fixed value.
For example, a value of 80H is input. Therefore signal 4o72
When the selector is “l”, the certain density value set above is 417.
2, and as a result, the above settings are displayed in the heart-shaped area in the figure.
The determined concentration value is output. Also, the most significant bit (MSB) of 4172 becomes 4173.
It is output (referred to as Bl signal) and used as a non-rectangular area signal.
I can stay. Also, the above-mentioned 4171.4172 is ([
○ is output to the part shown in FIG. 2 via the selector 4230.
is input to a video interface 201 shown in FIG. In the bitmap E shown in Fig. 27, the output is
For the binary image stored in the memory 4060E-R
FIG. 27 (D-1) The register 4074 shown in FIG.
By rewriting the density to be printed via the CPU, you can
It can be set at will. Also, in such register “
If you write data of 80H" or more, the signal shown in 4173 will be generated.
A bit image is output on the line. Image storage from the Sv recording/playback device 31> This embodiment system uses the Sv recording/playback device 31 as shown in FIG.
The video images from 31 are stored in the image storage device 3 and monitored.
It is also possible to output to a digital TV 32 or color printer 2.
It is. The image processing device 3 also handles the input image.
We also do rings. Below, the video image from the Sv recorder/player 31 is stored as an image.
Importing into the device 3 will be explained. First, an image storage device for storing video images from the Sv recording/playback device 31
FIG. 27(A) shows the control of import into the device 3. Referring to the block diagram of the image storage device 3 in (B),
Explained below. The video image from the Sv recorder/player 31 is an analog interface.
– NTSC composite signal via Face 4500
9000 type and separated by decoder 4000.
R, G, B signals, and composite 5YNC signals
9015R, G which are four signals of No. It is separated into B and S. In addition, the decoder 4000 has an analog interface
Y (luminance)/C (chroma) signal from 451O 901O
is also decoded in the same way as above. 9 to selector 401O
02OR, 9020G, 9020B, 9020
Each signal of 5 is a separate R, G, B signal and a controller.
The input signal is in the form of a positive 5YNC signal. Selector 4010 is connected to CPU bus 9610.
The selection of signals 9030R-S and 9020R-S is
It can be done programmably from 'U. Separate R and G selected by selector 4010
, 905OR, 9050G, 9050 as B signal
Each signal of B is sent to A/D converter 402OR, 4020
G. Analog/digital conversion is performed by 4020B. Also, the composite selected by the selector 4010
5YNC signal 9050Slt, TBC/HV separation circuit 4
030 and to the TBC/HV separation circuit 4030.
Therefore, the clock is output from the composite 5YNC signal 9050S.
clock signal 9060C, horizontal sync signal 9060H and vertical
The synchronization signal 9060V is further applied to the image shown in FIG. 28(C).
Image enable signal 9060EN is generated to selector 425.
0 is man-powered. Note that the enable signal EN is
This is a signal indicating the area. Selector 4250 selects the color image source as described above.
Images from reader 1 and various video devices (in this example,
Images and film skis from (temporarily using an Sv playback machine)
This is a selector that selectively outputs images from the scanner 34. No.
28 Explain the specific operation using Figures (B) and (C)
do. For example, when selecting an image on the video equipment side, the control signal 5
Set ELECT-A and 5ELCT-B to 0 and try
State buffer 4253R, G, B, HS. VS, CK, EN Oyohi 4252R, G, B, H8
,VS. Making use of only CK and EN, 5ELECT-C, D, E. F, set to l and all other trisler buffers
By setting all of them to high impedance, it is possible to
Image signals 9051R, G, B and synchronization signal 9051
S is 9420R, G, B, 9420S respectively
is combined with The same applies when inputting image data from other devices.
. Furthermore, in this embodiment, a color reader L or a filer is used.
A two-way communication line is required for connection with the lume scanner 34.
3-state in selector 4250 to use
It is characterized by the use of a buffer. The output from the TBC/HV separation circuit 4030 of this embodiment is
In Lle9050 (7), TvCLK9060C signal
is a 12.27MHz clock signal, r■r is 9060
B signal has a pulse width of 63.5 HS (7) Signal, T, V
V S Y N C9060V signal has a pulse width of 16.
It is a 7mS signal. Selector 42 is configured so that such a video image signal is input.
50, the CPU switches between each of the filters 9500.
Turn switches 4254R, G, and B to the upper side in Figure 28.
Replace. Therefore, it is virtually unfiltered.
It is input to one of memory A, B, C, or D. Also, when importing images from a reader, halftone images
There are some images where moiré occurs, such as
Turn down each of the switches 4254R, G, and B corresponding to the image.
Prevents the occurrence of moiré when switching to the side. Then again the second
This will be explained using FIG. 7(C). FIFO memory 4050AR, 4050AG, 4050
AB is reset by the TVH3YNC9060H signal.
and the TVCLK9060C signal starts from address '0''.
Please check the data 9060R, 9060G, 9060B.
Write. C (7) FIFO memory 4050AR, 4
050AG. 4050AB is written by the system controller 42.
The WE signal 9100 output from 10 is activated.
It is done from time to time. This FIFO memory 4050 by this n signal 9100
AR, 4050AG, 4050AB write control
Details will be explained below. Sv recording/playback device 3 in this embodiment! is the NTSC standard.
Ru. Therefore, the video image from the Sv recording/playback device 31 is
When digitized, 640 pixels (H) x 480 pixels (V
) screen capacity. Therefore, first, C of the image storage device 3 is
PU4360 mainly uses comparators 4232 and 4233.
Write the setting value so that there are 640 pixels in the scanning direction. Next
Set the input of selector 4213 to the CPU bus 9610 side.
, “0” for 480 pixels in the sub-scanning direction is stored in this RAM 4213.
“ is written. Also, the rate multiplier that sets the magnification in the main scanning direction
100% data is set in the layer 4234. The image information of the Sv recording/playback device 31 is stored in the memory 4060AR. When storing data in AG and AB, the system controller 42
1O is output from the TBC/HV separation circuit 4030
TVVSYN is 9060V, Dingf is 9060H. TVCLK9060C is VSYNCIN shown in Figure 29.
9455°H3YNτhe9452. CLKIN9456
connected to. As mentioned above, the image control signal is transferred to the Sv recording/playback machine interface.
By placing it on the face side, the A/D converter 402
9 which is the output signal from 0R, 4020G, 4020B
1 main video image of 051R, 9051G, 9051B
The scanned data is input to the filter circuit 9500, and then
The output signals 9420R, G, B are the FIFO memory 405
Stored at the same size in 0AR, 4050AG, 4050AB
Ru. <Reading process from image storage device> Next, the memory 4060A of the image storage device 3 described above
Reading image data from R4060AG and 4060AB
The output process will be explained. The image output from this memory is converted into an image by color printer 2.
Instructions for inputting instructions when performing configuration are mainly shown in Figure 23 above.
This is performed by the digitizer 16 and operation unit 20 shown in
Ru. For example, use a digitizer to mark the area where you want to form an image as shown in Figure 37.
Color reader 1 will copy the position coordinates.
Control line 9460 connected to connector 4550
The data is sent to the CPU 4360 of the image storage device 3 via the image storage device 3. It takes
The position coordinates are output as 8-dot data, for example. The CPU 4360 is a system controller shown in FIG. 27(F).
Area signal generator 4210-2 (first
13(d)) shows the sent coordinate information.
Based on the information, the area signal generator should be activated to obtain the desired image output.
(Program. Specifically, R shown in FIG. 13(d)
Set data corresponding to coordinate information in AM85A, 85B.
to Figure 27 (F) shows the output from the area signal generator.
Each signal representing each area becomes a control signal for each area.
. When the above-mentioned program is finished, the image storage device 3 is
- It will wait for a command from the reader L, and then copy copy.
Image formation starts by pressing the start button.
. When the start button is pressed, color reader 1 connects the signal line
4550 to the CPU 4360 of the image storage device 3.
The CPU 436 sent the command and received the command.
0 causes the selector 4250 to switch instantly. 28th
In Figures (B) and (C), the color image is displayed from the image storage device 3.
The settings for sending images to reader 1 are 5ELECT-C, 5
Set ELECT-E and 5ELECT-F to “0” and gate
Open the other trisler buffers, all high-in
pedance. Furthermore, the CPU 4360
Reset the counter controller in the memory where the image is stored.
mode. Timing to start from color reader L with the above settings
Receives signals 1-TOr' and BD. On the other hand, the power rally leader l
is sent from the image storage device 3 in synchronization with the timing signal.
Image signal, CLK image enable signal can now be obtained.
ing. First, image formation is performed according to the size of the recording paper.
Example, then form an image in the area indicated by the digitizer
An example will be explained. Image forming process that corresponds to the size of recording paper> In this example
In this case, there are two color printers 2 as shown in FIG.
It has two cassette trays 735 and 736, and two types of recording.
Paper is loaded. Here, A4 size in the upper row,
A3 size recording paper is set in the lower row. This record
The recording paper is selected using the LCD touch panel of the scanning unit 20.
is input. The following explanation is based on multiple images on A4 size recording paper.
This is done in case of formation. First, prior to image formation, use the color reader l or film described above.
Image storage device from film scanner 34 or Sv recording/playback device
By inputting the read image data to
Memory 4060AR, 4060AG. 4060AB, for example, as shown in FIG.
Record a total of 16 image data from "Image O" to [Image 15J].
Make me remember. Next, press the start key on the operation panel. As a result, the CPU 22 shown in the second diagram detects this key human power.
automatically adjusts the image forming position on A4 size recording paper.
Configure settings. When forming the 16 images shown in FIG.
For example, set the image forming position as shown in Figure 34.
Ru. FIG. 27 shows details of the above image forming process in this embodiment.
The block diagram and timing chart shown in FIG.
This will be explained below with reference to the following. Printer interface from color printer 2 shown in Figure 2.
IT sent to color reader l via face 56
The OP signal 511 is the video signal in the video processing unit 12.
It is input to the interface 201 and the image is stored from here.
Sent to device 3. This ITOP signal is stored in the image storage device 3.
Image forming processing is started by No. 551. And the image
Each image sent to the storage device 3 is stored in the
System controller shown in Figure 27 (A) and (B)
Image is read from memory ABCD etc. by control of 42!0
It will be done. Area signal generator located within system controller 4210
(FIG. 27(F)) Control signal 9102-
0 to 3 are counter enable signals.
is input to the control 9141. The counter control 9141 receives the input control signal.
Enables the counter and selector based on the
4070's select signal 9140 is controlled. At this same time
When the counter control 9141 is read enabled
A signal 9103 is output, and this signal is also output to the next stage F[FO
This becomes a write enable signal for 4140-0 to 4140-3. With this access, each memory 4060AR, 4060A
G. The image data stored in the 4060AB is read out, and each
Read image signals 9160AR, 9160A from memory
G. 9160AB has a lookup table shown in Fig. 27(C).
cable (LUT) 4110R, 4110G, 4110B
This is where the luminosity characteristics of the human eye are adjusted.
A logarithmic transformation is performed. Conversion data from each LUT
9200AR, 9200AG, 9200AB are mass
The signal is input to a king/black extraction/UCR circuit 4120. So
Then, this masking/black extraction/UCR circuit 412OA
When performing color correction of the color image signal of the image storage device 3,
Also, when recording black, UCR/black extraction is performed. And these consecutively connected masking/black
The image signal 9210 from the extraction/UCR circuit 412OA is
The area is selected by the selector 4130 shown in FIG. 27(B).
Based on the select signal 9230 output from the signal generator
and is input to each FIFO memory 4140-0 to 4140-3.
. As a result, as shown in Figure 33, the
Each image that was lined up is stored in this FIFO4140-0 to 3.
This action enables parallel processing. Figure 35 is a timing chart showing the flow of the images mentioned above.
It is expressed as 9320-0 to 3 in Fig. 27(B) are expansion interpolation circuits.
Enable signal 9340 is a select signal of selector 4190.
Select the enlarged interpolator to be used in the signal. All are area beliefs
Output from the signal generator, up to 4 for each area.
It is now possible to perform enlargement processing independently. For example, the enable signal 9320-0 enables the enlarged interpolation circuit.
When circuit 4150-0 is enabled, expansion interpolator 4
150-0 read enable to FIFO4140-0
Outputs signal 9280-0 and receives image data from FIFO.
The receiver is set to perform enlargement processing. In addition, the true truth
In the example, the one-fire interval method is used. Other expansion interpolation circuits
Similarly, read to FIFO when enabled.
Issue an enable signal and read the data in F and IFO. FIG. 35 shows a timing chart. At this point, as mentioned above, the sequential
The image data read out is processed in parallel, and the final
Image layout is completed using selector 4190.
Then, each image data that has been processed in parallel so far is serialized again.
Al image data signal. By selector 4190
The image signal 9330 converted to serial image data is
The edge filter circuit 4180 performs edge enhancement and
and smoothing processing is performed. And L
through UT4200 and via signal line 9380.
4230. The selector 4230 has the bitmap memory data described above.
data (H) and image data from memory are input. mosquito
The details of these two types of switching will be described later using Fig. 41.
. The image signal 9380 output from the selector 4230 is
The data is inputted as
a video enable signal generated from the area signal generator;
, and the clock are sent to the color reader 1. Below, all image data formats of "Image O" to "Image 3" are shown below.
When the configuration is completed, next “Image 4” to “Image 7” and “Image
8" to "Image 11J", "Image 12" to "Image 15J"
The images are sequentially formed in the images shown in FIG. 34.
Sixteen images (image +5J) are formed. As mentioned above, in this embodiment, 16 images are stored.
Lay it out as shown in Figure 34 and print it out.
However, this number of images can be set arbitrarily. In addition, in the case of images from the SVD player 3I, the SV flop
It is possible to print out consecutive images of the
It also functions as an index print. Similarly, the film scanner 34 also uses an auto changer.
automatically memorizes images one after another and prints 24 or 36 images.
By printing, you can index print the film image.
Lint is possible. <Image formation by layout at any position> Above explanation
The image is automatically developed as shown in Figure 34.
, the control to form an image has been explained, but this embodiment is based on the above example.
It is not limited to
It is also possible to form an image. Hereinafter, as an example of this case, [Image 0] shown in FIG.
When "Image 3" is developed and formed as shown in the figure,
explain. First, control similar to the image input control to memory described above.
Color reader L or film scanner 34 or S
The four image information read from the v-recording/playback device 31 are
4060AR, 4,060AG memory. 4060AB as shown in FIG. Then, operate the point ben 421 to detect the coordinate detection plate 42.
Specify and input the desired deployment position from 0. For example, development area
is specified and input as shown in FIG. The image forming process in this case is shown in the blocks of FIGS. 27(A) to (F).
The lock configuration diagram and the timing shown in Figures 38 and 39
This will be explained below with reference to a running chart. Figure 38 shows the "I!1" line shown in Figure 37.
Timing chart during image formation, Figure 39 is Figure 37
“1□ Timing of image formation on line”
This is a chart. The ITOP signal 551 is output from the printer 2 in the same way as described above.
The system controller 4210 synchronizes this signal.
It will start operating as expected. Note that in the image layout shown in FIG. 37(A),
, "Image 3" is a color reader l or film scanner 34
Or the image from the Sv recorder/player 31 rotated 90 degrees.
It has become. This image rotation process is performed in the following steps. First, the DMAC (direct memory access) shown in Figure 27
access controller) 4060AR by 4380. Work memory 4390 from 4060AG, 4060AB
Transfer images to. Next, the CPU 4360
After performing known image rotation processing in the memory 4390
, the work memory 4390 by the DMAC4380
Images to 4060AR, 4'060AG, 4060AB
The image will be transferred and the image will be rotated.
. The layout is done by the digitizer 16, and instructions are input.
The position information of each image is stored in the video processing unit 1 in FIG.
2 to the image storage device 3 via the route described above.
It will be done. The above position information is transmitted to the CPU 4 via a signal line 9460.
360. CPU' 4.360 is the above
Programming the area signal generator based on position information
As already stated. The system controller that received the unfolding position information for each image
The controller 421O performs an enlargement/interpolation process corresponding to each image.
Operation permission signals 9320-0-3 and 4150-0-3
and counter enable signal 9102-θ~3, and each
Generates a selector control signal to obtain the desired image.
It has become. In the layout at any position in this example,
For example, counter 0 (4080-0) is
counter 1 (4080-1) is image 1, counter 2 (
4080-2') is image 2, counter 3 (4080
-3) operate corresponding to image 3, respectively. Controls during image formation on line “11” shown in Figure 37
The control will be explained with reference to FIG. Image memory 4060AR, 4060AG, 4060AB
Reading “image O” from counter 0 (408
0-0) from address “0” to address “0.5M” (
Read up to the "Image 0" storage area shown in Figure 36)
. The switching of the output of counters 4080-0 to 4080-3 is
Selector 4 under the control of counter controller 9141
070. Similarly, "Image l" is read by counter 1 (40
80-1) from “0.5M” address to “IM”’
The area up to the bottom (storage area of “Image l” shown in Figure 36) is readable.
Served. The timing of this readout is shown in Figure 38.
Shown as 60AR, AG, AB. The data of “Image 0” and “Image l” are stored in LUT411
Masked via 0AR, 4110AG, 4110AB
processing/black extraction/UCR circuit 4120A, where
This results in a frame-sequential color signal 921O. This frame sequential color signal 92
10 are parallelized by the selector 4120, and each pixel
FIFO memory 4140-0. 414
Sent to 0-1. And the system controller 42
Enlargement/interpolation circuit from 1O 4150-0.4150-1
Operation permission signal 9320-0.9320-1 is enabled.
When it comes to bulls, the expansion/interpolation circuit 4150-0.4150
-1 is FIFO read signal 9280-0°9280-
1 to enable and start read control. FIFO memory 4140-0. 4140-1 is this
Signal 9280-0. Expanded and supplemented by 9280-1.
Image data transfer to inter-circuit 4150-0.4150-1
Start sending. Then, this enlargement/interpolation circuit 4150-
0°4150-1, first use the digitizer 16 to
Layout and interpolation calculations are performed according to the indicated area.
Ru. This timing is 9300-0°930 in Figure 38.
Shown in 0-1. ``Image O'' and ``Image O'' with layout and interpolation calculations
1” data is selected by selector 4190.
, passes through the edge filter circuit 4180, and LUT 4200
is input. The subsequent processing up to connector 4550 is
Since this is the same as above, the explanation will be omitted. Next, referring to FIG. 39, the “I12 line” shown in FIG.
Explain the timing. Image memory 4060AR, 4060AG, 4060A
From B to enlargement/interpolation circuit 4150-1.4150-2
The processing is substantially the same as described above. However, in the “12 line,” “Image 1” and “Image 1”
Since "Image 2" is output, counter 1 (4080-
1) and counter 2 (4080-2), FIFO414
0-1, 4140-2, expansion/interpolation circuit 4150-1°
4150-2 operates. These controls are
This is done in accordance with a control signal from controller 4210. As shown in FIG. 37, in the "12" line, "Image l"
and “Image 2” overlap. In this overlapping part
to image either image, or both.
The system controller 421 determines whether to form an image of
It can be selected by a control signal 9340 from 0. The specific control is the same as in the above case. The signal from connector 4550 is colored by a cable.
- Connected to reader 1. For this reason, color readers
The video interface 201 of No. 1 has a video interface shown in FIG.
The image signal 205R from the image storage device 3 on the line path
is selectively output to the printer interface 56. Image storage device in image formation in this embodiment described above
Transfer processing of image information from printer 3 to color printer 2
Details are below with reference to the timing chart in Figure 40.
explain. As described above (by pressing the start button on the operation unit 20)
The printer 2 starts operating and starts conveying the recording paper.
Ru. Then, when the recording paper reaches the leading edge of the image forming section, [T
An OP signal 551 is output. This ITOP signal 551 is
, and sent to the image storage device 3 via the color reader l. The image storage device 3 stores each image file under set conditions.
Mori 4060AR. Image data stored in 4060AG and 4060AB
Read the data and perform the layout, enlargement, interpolation, etc. described above.
do the same thing. Memory expansion continuous shooting> The image data sent from the host computer 33 is transferred to the GP
Input via IB4580 and work memory 4390
The image is expanded once and written to image memories A, B, C, and D.
It is read out in the same way by the above-mentioned means, and printed on the printer.
output. For example, as shown in Figure 43
The image transferred to the image storage memory is shown in Figure 27 (C).
is read by counter O (4080-0) indicating
If it is a memory area, the image is similarly shown in Figure 37 (A).
is printed out in the area of image 0. In addition, layout coordinate information and enlargement can be obtained from the host computer.
By sending magnification and print commands,
It supports image formation with any layout as well as the
This can be done by computer control. Furthermore, since the magnification ratio can be set arbitrarily, printing paper
It is possible to obtain an enlarged output image beyond the limitations of . Figure 37 (G) shows, for example, that images stored in memory are printed on four
The following is an example of enlarged printing after dividing into two sheets of paper.
(referred to as continuous shooting). Details will be explained below. Figure 37 (F) is the counter 0 4 shown in Figure 27 (C).
Stored in the memory area read by 080A-0.
FIG. As shown in the figure, the magnification and paper size vary depending on the magnification and paper size.
Payment can be divided arbitrarily. host con
When the enlarged continuous shooting command is received from the computer, the CPU
Calculate the memory division size from the paper size and magnification ratio.
system controller and read counter O
Set to . In the figure, the division size is a in the H direction and b in the V direction.
These are used to calculate the first address that the counter reads.
I can stay. Also, for simplicity, in the figure, each of the four divided areas is
It is designed to support 4 printouts. Image formation processing is performed using the ITOP signal 551 shown in FIG.
is started and the counter is sent from the system controller 421O.
1 line to address a by tie enable signal 9130-0.
The image is read out, enlarged, and sent to the color reader l.
It will be done. The read counter will start the next row after reading is completed.
Calculate the start address of the input and repeat the readout again.
Reads up to the b line and finishes printing 10 sheets.
Complete. Then until the second ITOP signal 551 comes
The first address 2 of the second sheet is calculated, and the first address is repeated sequentially.
Continuously print up to the fourth sheet while calculating the amount. Most
Enlargement processing is performed later by stitching the printed images together.
You can now obtain a captured image. Non-rectangular image synthesis using bitmap memory E> Next, non-rectangular image synthesis using bitmap memory E
I will explain about it. For example, as shown in FIG. 37(B), the output area of image 0 is
A case of outputting a heart-shaped composite on a document will be explained. As mentioned above, first determine the size of the area of image 0 that you want to output.
Taking into consideration, a heart-shaped binary image is stored in bitmap memory E.
expand. Next, as in the previous section, use the color reader l to
Specify and input the image development area using the digitizer 16
. At this time, click the non-rectangular area selection button only for image 0.
Select from the operation panel. Location information for each of these specified images
The information and processing information is sent to the first video processing unit 12.
The image is sent to the image storage device 3 via the image storage device 3. The information sent is
, the signal line 9460 is read by the CPU 4360,
Program the image output timing based on this information
What to do is as already stated. When it receives the I-TOP signal from color reader 1, it records the image.
The storage device 3 starts reading the image from the memory, and the 27th
Image synthesis is actually performed when passing through the selector 4230 in the figure.
It will be done. FIG. 41 shows an internal outline of the selector 4230 in FIG. 27(B).
It is a schematic configuration diagram. 3010 is the register for register 1.
bit by controlling the data set in the star.
8bit data from tomap memory or B!
Can be programmably selected from the double signal CPU. 302
0.3030 is such a selecting gate. For example 8
When the bth density data is selected, the OR gate 3040
The image signal and bitmap are combined. On the other hand, B! When a signal is selected, the selector 3050 select signal
and the register shown in the BI double signal 3050 is
The image data of the density of the data to be set and the image from memory are
Image data 9380 can be selectively output. When performing non-rectangular image composition, register 2 is normally set to “O”.
” is set.Image data 938 to be read out sequentially
0 is the non-rectangular area signal B output from the bitmap
Non-rectangular cutting with selector 3050 as l select signal
This makes it possible to synthesize non-rectangular images. The above Bl signal is sent alone to the color reader l.
It is also possible to perform processing using the BI multiplied signal in the carder l. That is, the above-mentioned Bl signal is input to the video interface shown in FIG.
used as the signal 206 input to the base circuit 201, and
The video interface circuit 201 is configured as shown in FIG.
If used in the
I can do it. In addition, in this embodiment, the reader 1 reads
The image storage device 3 stores the color images in real time.
It is also possible to combine images. In other words, as mentioned above, the ITOP signal of the color printer 2
551, the image is read from the image storage device 3.
However, at the same time, the color reader l also receives the above ITOP signal.
Full color sensor for reflective original 999 in synchronization with 551
Reading starts at 6. Color reader l processing is as above
Since this is the same as described above, the explanation will be omitted. The image information from the image storage device 3 mentioned above and the color
Synthesis with the image information from the data is performed at the timing shown in Figure 37 (C).
This will be explained below with reference to a running chart. FIG. 37(C) shows images O to 4 in FIG. 37(A).
The other parts are reflective originals read by reader 1.
When synthesized! ! Reflection original 999 in 1 and image recording
This is a timing chart in which signals from the storage device 3 are synthesized.
. Color correction read out in synchronization with ITOP signal 551
The image information of the digital camera is the output signal 5 of the black correction/white correction circuit.
59RGB, and H3YNC at lI in Figure 20.
is output in sync with. Also, from the image storage device 3
The image information 205RGB is indicated by the digitizer 16.
Only the area that was filled in is output. These two types of image information are
input to the digital interface 101 and the digitizer 1
The image of the color original is synthesized by the circuit except for the area specified in step 6.
Area output from ttS and indicated by digitizer 16
The information from the image storage device 3 is output. In the above embodiment, as a means of setting a non-rectangular area, the desired
Prepare a mask pattern of the shape of the area in advance,
By loading it into the reader, Bitmatupume
It was expanding rapidly. Furthermore, in this embodiment, as shown in FIG. 27 (D-1),
Connect the bitmap memory to the CPU bus and
mask pattern can be developed in bitmap memory.
I have to. For example, frequency of use of star, diamond, hexagon, etc.
In the case of a standard mask pattern that seems to have a high
or a program that generates data on a CPU processor.
Stored in gram ROM or font ROM4070
Leave it as it is, and when you use it, start the program and automatically
A mask pattern can be generated automatically. In the above configuration, a mask pattern is created and read.
Easily store mask patterns in bitmap memory without the need for
can be created, and an image like the one shown in Figure 37 (B) can be created.
Synthesis can be carried out even more easily. Further, in this embodiment, for example, from the computer 33,
The CPU 4360 generates a sentence from the sent code data.
Font ROM 4070 shown in Figure 27 (D-1)
Bitmap memory that refers to the character font and shows the character font in E.
It can also be expanded upwards. In this way, you can freely store character fonts in bitmap memory.
can be written, and furthermore, the AND of Fig. 41 mentioned above can be written.
Activate gate 3020 and AND gate 303
0 is inactive, image data 9380 and bitmap
The image on the memory is combined using the OR gate 3040.
Character composition with various stored image data
can be done easily. In addition, the CPU 4360 executes, for example, a bang generation program.
By starting the program, bitmaps can be added to the borders etc.
can be written to, and it takes as shown in Figure 37 (D).
It is also easy to combine ruled lines and image data. Various other
You can have fixed buttons as a CPU program.
. In addition, fonts written in advance in bitmap memory
Combine character data and image data from ROM4070
As shown in FIG. 37(E), each of the steps shown in FIG.
Now you can get an image with a message on the bottom of the image.
It has become. As mentioned above, these characters
Send the character code from the host computer to the
It is also possible to read the set from the reader
(It is also possible to do so.) Explanation of the monitor TV interface
The stem is connected to the image memory in the image storage device as shown in Figure 1.
The contents of the log can be output to the monitor television 32. Also
, it is also possible to output video images from the Sv recording/playback device 31.
It is possible. This will be explained in detail below. Image memory 4060AR406
Video image data stored in 0AG, 4060AB
The data is read by the DMAC4380 and
Ray Memory 4060M-R, 4060M-G4060M
- Transferred to B and stored. On the other hand, as described above, the system controller 421
Controls the control signal output from 0 to each memory
By storing the desired image in the image memory,
At the same time, it can also be stored in the display memory M. In addition, FIG. 27 (E
) as shown in the display memory 4060M-R,4
Video images stored in 060M-G and 4060M-B
Data is LUT4420R, 4420G, 4420
D/A converters 4430R, 4430G through B,
4430B, where the display controller
Alerts in synchronization with the 5YNC signal 4590S from the controller 4440.
Analog R signal 4590R, G signal 4590GSB signal 4
590B and output. On the other hand, from the display controller 4440, these
The 5YNC signal is synchronized with the output timing of the analog signal.
No. 9600 is output. This analog R signal 4590
RSG signal 4590G, B signal 4590B. By connecting 5YNC signal 4590S to monitor 4
The contents stored in the image storage device 3 can be displayed.
. In addition, in this embodiment, the host computer shown in FIG.
4580, GPI shown in FIG. 27(B) from the computer 33
Control to image storage device 3 via B controller 4310
The displayed image can be adjusted by sending commands.
Rimming is possible. The CPU 4360 is controlled by the host computer 33.
Based on the input area information, the data is
From spray memory 4410R, 4410G4410B
To image memory 4060AR, 4060AG4060AB
Trimming is possible by transferring only the valid area
It is. Also, in response to area instruction information from the host computer 33,
Accordingly, the CPU 4360 shown in FIG. 27(B) is
comparator 4.232.4233 and RAM42
In step 12, set the data in the same way as described above and try again.
image data from the color reader 1 and Sv recording/playback device 31.
By manually converting the cropped image data into 4
Can be stored in 060AR, 4060AG, 4060AB
I can do that. Next, image memories 4060R, 4060G, 4060
If multiple images are stored in B, the color printer
When recording in 2, the layout of each image also changes depending on the monitor TV.
32 and a host computer 33. First, display the size of the recording paper on the monitor TV 32, and
Host the laid out location information of each image while looking at the display.
By inputting data through the computer 33,
- It is possible to layout each image recorded with printer 2.
Ru. Image memory at this time 4060AR, 4060AG, 4
Reading of stored information from 060AB to color printer 2
The control and recording control on the color printer 2 are as described above.
Since this is the same as the embodiment, the explanation will be omitted. <Explanation of computer interface> The system of this example
The stem is connected to a host computer 33 as shown in FIG.
and is connected to the image storage device 3. Figure 27 (
B) is used to interface with the host computer 33.
Explain Ace. The interface with the host computer 33 is a connector.
GPIB controller connected by Kuta 4580
4310. GPrB controller is CPU
Connected to CPU4360 via bus 9610
, host computer 33 according to a determined protocol.
It is possible to exchange commands and transfer image data with
Ru. For example, from the host computer 33 via GP-NatsuB,
When image data is transferred using
The receipt is accepted by the GP-IB controller 4310.
, - are stored in the work memory 4390. stored
Data is transferred from the work memory to the image storage memory AB,
DMA transfer to CD and monitor display memory M
Then, a new data is sent from the GP-IB controller 4310.
The receiver receives the data and transfers the image by repeating the above steps.
ing. Figure 42 shows the work shown in Figures 27 (A) and (B).
Memory 4369, image storage memory A-C, and monitor
A block diagram showing the relationship of display memory M is shown.
. In addition, in FIG. 42, each component of the embodiment is shown.
The numbers have been renumbered. From the host computer 33
, First, the image size to be transferred is sent. sand
That is, input terminal 2401. GP-IB controller 24
02 from the host computer 33 to the CPU 240 via
The image size corresponding to 3 is read. Next, the image data
is read line by line, - time work memory 2404
is stored in The image data stored in the work memory is
, DRAM controller 2405 (hereinafter referred to as DMAC)
image storage memory 2406. display memo
are sequentially transferred to R 2407 (for simplicity, R,
G and B are grouped together). Details below
explain. Image storage memory 2406. display memo
For example, the library 2407 allocates addresses as shown in FIG.
The image is stored. In the figure, the arrow is pointing in the H direction.
The lower address corresponds to the ■ direction, and the upper address corresponds to the ■ direction. example
For example, point A is 100H in the H direction and 100H in the V direction.
Then, the address of point A becomes 100100H. Similarly, the display memory also has lower address, ■ direction.
The upper address is assigned to . Here, for example,
The incoming image is stored in the image storage memory 2402 at the same size,
Reduced to 3/4 and transferred to display memory 2407
It shall be. First, as mentioned above, the host computer sends
The image size and reduction rate of the image are set in DMAC.
On the other hand, the DRAM controllers 2408 and 2409
is the storage start address and the image size when reduced
is set. After completing the above settings, the DMA is executed by the CPU.
A command is sent to the C2405 and image transfer begins.
. The DMAC 2405 adds addresses to the work memory 2404.
The image data is read by giving the response and ■ signals. At this time, the address is incremented sequentially, !
When the reading of H is completed, the host computer
The next input is taken and stored in the work memory.
Ru. Meanwhile, at the same time, the DRAM controller 2408.24
09 is given l0WI,, l0W2 by DMAC.
, image data is written sequentially. child
At the time, the DRAM controller 2408.2409
■Count the signal twice and start from the start address set above.
The write address is incremented sequentially. H way
When writing in the direction is completed, the address in the V direction is input.
It is incremented and writing starts from the beginning of the next H.
. When the above transfer is performed, the DMAC will
It has the same function as a multiplier, so ■
The size is reduced by thinning out the cover. For example,
If 3/4 reduction is set as shown above, DMAC will be
For the direction, 10W is thinned out once every four times, and for the ■ direction,
In this case, it seems that the section weight of 1 line is not given for every 4 lines.
configuration, and as a result, IOW is used to store memory.
Reduction is performed by controlling writing. FIG. 44 shows a timing chart. Read as shown
The output address is input to the work memory 2404, and ■
The signal causes data to appear on the data bus. write at the same time
The current address is input to the storage address, and the "σW times signal
More data is written. At this time, if the signal is thinned out by a factor of σW,
The write address is not incremented and
It is also no longer done. <Description of man-machine interface> The system of this example
As mentioned above, the system (Figure 1) is a host computer.
33 and the operation section 20 of the color reader 1.
It has become. The following is a man-machine interface using this operation unit 20.
Let me explain about this. In the color reader l, press the external device key on the operation unit 20 (Fig.
(not shown), the diagram A in Figure 47 is operated.
displayed on the liquid crystal touch panel of section 20. FIG. 47 shows the color reader 11 to the image storage device 3.
from the film scanner 34 or the Sv recording/playback device 31.
FIG. 6 is a diagram showing operations when storing image data. When you press the image registration key in Figure 47A, the LCD touch panel
It looks like C, and is surrounded by the broken line shown as X in the C diagram.
Select the input source displayed in the area using the Imperial key
. In this embodiment, the input source is the color reader 11 screen.
There are three types: Lumskiyana 34 and SV recorder/player 31.
Selected by operating the Error key. This situation
Shown below in Figure 0. Next, press the image number key in Figure 0 to proceed to the next step. In the case of figure D, an image is already stored at the specified image number.
Indicates when The image shown in D is shown in FIG.
Displayed by turning on the area shown in . E diagram
, G, and H are input source selection c(]15 key in figure 0.
If you select a color reader from
is shown in figure E, and if film scanner 34 is selected, shown in figure G.
In the case where the Sv recording/reproducing device 31 is selected, the result is diagram H. When you select image registration for color reader 1, the screen shown in Figure 47E appears.
The state shown is shown. In such a state, the digital
The pointing ben 421 of Isa 16 allows color correction.
The reading error of original 999 on platen glass 4 of reader 1
Instruct the rear. When this instruction is completed, the F diagram will be displayed and confirmed.
A diagram for is displayed. There is a change in the reading area
If so, press the key to return to diagram E and set again.
can be determined. When the reading area is OK, press the adjustment key and the G diagram will appear.
Next, set the amount of memory to be used. The bar graph of the memory amount in diagram G is a memo in the image storage device 3.
By installing the report (memories A-D in Figure 27 (A))
The length of the bar graph changes. The image storage device 3 is the memory board (memory A-D) mentioned above.
) can be installed from one to a maximum of four. In other words, the bar graph is the longest when four memory boards are installed.
becomes. The bar graph in figure G indicates the memory capacity in the image storage device 3.
In addition, you can also set the amount of memory used when registering images.
Ru. [E] Determine the amount of memory used by registering with the El key,
By pressing the registration start key, the document scanning unit shown in Figure 1 is activated.
Knit 11 scans 1 and reads 999 originals. The image information from the document scanning unit 11 shown in FIG.
processed by the video processing unit 12 through the cable 501.
After that, the image is displayed via the video interface 201.
Output to image storage device 3. Image storage device 3 stores input images.
The image information is displayed on the monitor television 3. Storage method in the memory of the image storage device 3 (Figure 27 (C))
are the same as those described above, so they are omitted. As mentioned above, the memory amount setting for the G diagram can be made variable.
, even when storing images in the same area, the amount of memory set
By increasing the number of images, it becomes possible to store images with high image quality. Also, by reducing the amount of memory, many images can be stored.
It is also possible to input. Next, image registration from the film scanner 34 is shown in Figure G.
The registration method is the same as for color reader l.
Since they are similar, detailed explanation will be omitted. If you select image registration from the Sv player 31, the fourth
The display will be as shown in Figure H in Figure 7, and the direction of rotation will be changed before registration starts.
Whether it is registered or not AGC (Auto Gain Control)
0N10FF and field/frame settings.
conduct. After the above settings, press the registration start key.
The image information from the Sv recording/reproducing device 31 is stored in the image storage device 3.
is the image to the memory (Figure 27 (C)).
The storage method is the same as described above, so it will be omitted. FIG. 48 shows a color print from the memory in the image storage device 3.
This section shows how to print a layout to a printer.
It is a diagram. Figure 0 in Figure 48 selects three layout patterns.
This is the operation display. Fixed pattern layout is a predetermined pattern.
Print out the contents of the memory of image storage device 3 on the screen.
It is something to do. The free layout is based on the digitizer 16 shown in FIG.
Indicate the area to print using point ben 421
and prints the memory contents of image storage device 3 in that area.
It is something to be done. The synthesis is performed at point Ben 4 of the digitizer 16 shown in Figure 23.
The memory of the image storage device 3 is placed in the area indicated by 21.
The area other than the area specified for writing the memory contents will not be colored.
Combine images of original 999 on the platen glass 4 of the printer
and print it out. If the fixed layout is selected, the
Therefore, the number of print pages in fixed layout printing is
Make settings. Each image area of fixed layout has A-P.
Image area names are given, and each area (A-P)
The corresponding image numbers are shown in Figure 48, Figure B2 and Figure F, respectively.
Use this to configure settings. For example, in the 48th diagram, 16 strokes
When a surface is selected, the display shown in Figure 48E is displayed.
. For example, if you select the area shown in A in Figure F, then the table
The display moves to the diagram shown in F, and the image that should be formed in the set area is
Set the image number using the numerical keys in FIG. By repeating this specification, multiple images can be registered.
It can be done. The number of images to be registered is shown in Figure D.
automatically determined according to the type of fixed pattern selected.
be done. When this setting is completed, the color reader's CP
U depends on the type of external device selected in diagram B, e.g.
For example, if it is SV, the desired value selected in the F diagram of the SV playback machine
The image corresponding to the screen is stored in the storage device 3. Next, the start key (not shown) of the operation unit 20 in FIG.
Prompts you to specify the corresponding image number. Then the specified number
The fixed layout is fixed by pressing the switch on.
A hard copy is output from the printer 2. Fixed rail
The image output on page 16 of the Ioutprint is shown in Figure 34.
The layout will be printed as shown. Regarding the free layout print shown in Figure 48-1
I will explain. First of all, free layout printing
Each area is marked on the point base of the digitizer 16 shown in Fig. 23.
Each area is set in turn using the button 421. each at the same time
Enter the image number to be printed in the area using the numeric keypad shown in figure L.
and select. After setting each area, start the operation section 20 in Figure 1.
By pressing the key (not shown), Figure 1 and I (Figure
The memory contents of image storage device 3 are printed in the area set in
is thrown out. The composite layout shown in Figure 48G is based on the above-mentioned free layout.
The layout and area settings are the same. The reflective original image is output for areas other than the color ink area.
A color image is output. Figure 49 shows the state shown in Figure 47A.
If you turn on the "Monitor display" key, that is, the monitor
Display operation on the television 32 and in the state shown in the figure
If the "Color Balance" key is turned on, that is, the image
The image information in the image storage device 3 is printed by the color printer 2.
This section shows the operations for adjusting the color tone of each image when printing out.
vinegar. Figure 49 When you press the monitor display key in figure A, a table like figure C will appear.
Select the image number of image storage device 3 and monitor
Select either display on TV 32 or source display.
Ru. The details are omitted as they have been described previously. By pressing the color balance key in Figure 49A,
As shown in the figure, enter the image number for setting the color balance.
select. When you select the image number, the LCD touch panel will display E.
The display will be as shown in the figure, and the colors will be red, green, and blue.
A corresponding bar graph will be displayed. press red country key
The left side of the bar graph indicates a red luminance signal in terms of electrical signals.
The red color shown on the monitor works to amplify the
Ingredients become diluted. This is the monitor memory in Figure 27 (E).
Lookup table (LUT) 4420R within. The monitor screen can be adjusted by changing the G and B curves.
While changing the color of the label, the look in Figure 27 (C)
backup table (LUT) 4110A-R. -G and -B curves are also changed. In other words, Kara
-Communication from CPU of reader 1 to CPU in image storage device
is performed, and as a result, such LUT rewriting is performed using image memory.
This is performed by the CPU within the device 3. As mentioned above, 2
Monitor display by changing the LUT of seeds at the same time
Printed from color printer 2 with the same color tone as the image being printed.
It is possible to log out. Figure 50 shows the condition shown in Figure 47A when the "Naka" key is turned on.
displayed when In the display shown in Figure 50B, r
FIG. 7 is a diagram showing an example of a display when the sVl key is turned on. sand
In other words, the contents of the Sv disk played by the Sv recording/playback device 31
operation to display on the monitor TV 32 and color printer
This is an operation for printing out from 2. Diagram C in Figure 50 is an index display or index
Indicates an operation for selecting print. The Sv disc has 50 field recordings and frame recording.
It is possible to record 25 pages. Display of the 50th diagram Press the start key to record the field.
In this case, the first 25 screens of the Sv disk will be displayed on the monitor.
By pressing the display start key of figure E, the second half
Display 5 screens. In such a case, the image storage device 3
The internal CPU puts the SV player in a remote state. In such a case, the color reader's CPU is an image storage device.
CPUI in 3: Images of multiple tracks from the SV player
Generates an instruction to store the image in @next memory. Then,
The CPU in the image storage device 3 performs the following operations for the Sv playback machine.
Generate instructions. In other words, it is recorded on the Sv disk.
The first 25 screens of 50 screens are stored in the memory in the image storage device 3.
Memorize sequentially. In such a case, the image storage device 3 will not be compatible with the Sv player.
All you have to do is to give instructions to move the head. Specifically, before storing the image signal in the image storage device 3,
, the playback head of the Sv player is positioned at the outermost circumference of the Sv disc.
Access the rack and then play from the outermost track
The video images to be stored are stored in the memory in the storage device 3 as described above.
to be memorized. Next, the CPU of storage device 3 is sent to the Sv playback machine.
On the other hand, the finger that moves the playback head one track inward.
Outputs an indication. The image storage device 3 then transfers the video image back into the storage device 3.
stored in memory. By repeating this operation
Therefore, the image storage device 3 sequentially stores the image signals in the memory.
and create a multi-index screen in internal memory.
. In addition, in the case of frame recording, press the display start key shown in figure D.
By pressing , all S■ disks will be displayed. The FSG diagram in Figure 50 shows the contents of the index mentioned above.
This is an operation to print out from the color balance 2. After making the settings shown in Figure F, press the start key on the operation panel 20.
As a result, the image storage device 3 first uses the Sv recording/playback device 31.
25 screens worth of images are stored in memory, and then,
Index on color printer 2 via color reader l
Do a sprint. Since the diagram G is similar, the explanation will be omitted. By operating the FSG diagram in Figure 50 as described above,
allows you to easily register images and print layouts.
Is possible. <Control by host computer> The system of this embodiment is controlled by a host computer as shown in Figure 1.
It has a computer 33 and is connected to the image storage device 3.
. An interface with the host computer 33 using the first σ diagram.
Describe the interface. The interface with the host computer 33 is a connector.
GP-IB controller connected by Data 4580
431O. GP-IB controller 431
O is connected to CPU4360 via CPU bus 9610
The host computer is
Exchanging commands and transferring image data with the data controller 33
It is possible. The image data of the color reader 1 and Sv recording/playback device 31 is
GP-IB controller connected by connector 4580
controller 4310 to the host computer 33.
, stored in the storage area of the host computer 33 and expanded.
Enlarge/reduce processing or cut out one part of image data
, layout of multiple image data has traditionally been
It was done. However, in that case, the amount of color image data
has a fairly large capacity, so general-purpose devices such as GP-IB
Color reader l also through the interface. Data between the Sv recording/playback device 31 and the host computer 33
The data transfer time is very long. So, the host
The input image data is directly sent to the computer 33.
determined by the host computer 33 rather than by
Send command to GP-IB controller of image storage device 3
, CPU 4360 decodes the instruction and reads the color reader.
! control the input image data of the Sv recording/playback device 31, and
By specifying only the image area you need, other parts can be saved.
minutes are not stored in memory, making efficient use of memory and
image data without having to transfer it to the storage computer 33.
nothing. Also, the input screen is inputted by commands from the host computer 33.
Store the image data in the storage area of the host computer 33
Even if not, the image storage device 3 can be used as an image memory 4060.
Multiple images in A-R, 4060A-G, 4060A-B
It is possible to memorize data and layout of each image
The host computer 33 performs image processing such as printing and enlarging/reducing images.
Only commands from the host computer can be sent, without having to be executed on the side.
Then, the CPU 4360 of the image storage device 3 executes the processing and instructions.
The display is performed on the input image data, so the host computer
Image transfer time between computer 33 and image storage device 3
This makes it possible to reduce processing time.
There is. As mentioned above, according to the instructions from the computer 33,
, how the image storage device 3 stores input and output images,
We will explain in detail how to handle it. All input and output image data stored in the image storage device 3 is
and is handled as an image file in the image storage device. Therefore, the image registration memory memory A (4060A
), Memory B (4060B), Memory C (4060C
), memory D (4060D) is a RAM disk.
At that time, the image file to be stored is
Image file management table 43 using the file name as a key
61 (Fig. 51). Image storage where image files function as RAM disks
When registered and stored in device 3, the registration memory
A basic block in which each of the memories 7A-D is divided into multiple parts.
The minimum image file management unit is the image file. The CPU 4360 uses the image file management table 4361
Therefore, by combining several of these basic blocks, one large
You can also manage to configure large image files.
Ru. At that time, the image file name and the image data size
, file protection, management of registration memory configuration, etc.
All data is stored in the image file management table 4361.
It will be remembered when you register. The image storage device 3 generally stores images in a reader as described above.
- When inputting from l, the image is the same size or reduced
Register it as an image file in the storage device. Therefore
, if you increase the size of the image to be registered and register it, it will be easier to read.
The original size of the original image from the printer is approximated and reduced.
Since the fractional ratio will be smaller, print that registered image file.
When outputting to a computer 2, etc., the quality improves. The CPU 4360 controls input devices such as reader 1 and the computer.
key when inputting image data from the computer 33.
The image file name is determined by the command of the computer 33.
File names are given in the structure shown in Figure 56. this
The file name is entered on the computer 33 and the image storage device 3.
It clarifies the management of image data between output devices.
, the computer 33 attaches an arbitrary image file.
is possible. The image file name consists of 8 characters of the image file name.
(ASCII code) and the image type of the image data
It consists of an extension indicating the . The type of image to be handled is distinguished by the extension.
The registration memory 40 has a structure that matches the image type.
60 and will be managed. The image type is RGB type when the extension is “,R”.
Luminance image data, CMYK type density when “,C”
167 of 8-bit palette type when image, “,P”
Image data that allows you to set any 256 colors from OR colors
means. Also, when “,S” is specified, the special file
has a special meaning in the image storage device 3 and has a special structure.
It shows the image file that is . The coordinate system for handling images in the image storage device is a standard.
the origin and the X direction representing the width direction of the paper,
Consists of the Y direction, which represents the height>direction.
(Figure 52). The image storage device stores data from each input device into the image storage device.
Processes within the location coordinate system and manages various image data. Analog input terminal (RGB, video) (4500, 4
Images from 510°452OR, G, B, S)
If you input the image and register it in the registration memory, the input image will be
It will be registered as an image as shown in Figure 53. Input at this time
The image is 600 pixels in the X direction (width) and 600 pixels in the Y direction.
The direction (height) is input with a size of 450 pixels.
It will be done. The coordinate system of the digitizer 16 is as seen from the image storage device.
, as shown in Figure 54. The coordinate system of the image storage device and
The digitizer coordinate system is the same, with each origin and
The X direction and the Y direction correspond. When viewed from the image storage device, the coordinate system of the reader l is the fifth
It will look like Figure 5. Image storage device coordinate system and reader
- The origin, X direction, and Y direction of each coordinate correspond to each other.
Ru. Next, we will explain the data exchange via GP-IB.
do. Image storage device 3 and computer are connected through GP-IB4310.
Types of data exchanged between computers 33
is classified as follows. ■Command (instruction) Command from the computer 33 to the image storage device 3 ■Paper
Various arguments accompanying the parameter command ■Data section/Image data Binary of color (monochrome) images such as RGB, CMYK, etc.
Redata/extended data Obtaining and setting the data set in the image storage device 3
This is data transferred when rewriting data.
. ■Response data: ACK/NAK, response with additional information (RET), i.e.
This is a response returned from the image storage device to the command. The above four types of data are stored in the computer 33 and image memory.
with device 3 via GP-IB controller 4310.
and exchanged. Below, using Figure 57 for these four types of data,
explain. As shown in FIG. 57, the image storage device 3 and each input/output device
controller 11 analog input 4500, 4510° 452O
R, G, B, S, between printers 20, and images
Image data handled between the storage device and the computer 33
Data is classified into the following four types. ■ RGB data type ■ CMYK data type ■ 8-bit palette data type ■ Binary bitmap data type These image data are extensions of the image file names mentioned above.
They are distinguished by their child parts. For example, on the computer 33 side
RGB image in the image file name accompanying the 5CAN command
When the extension “,R” indicating image data is attached,
, the CPU 4360 of the image storage device 3 receives the input from the input device.
The input is controlled as an RGB luminance image,
Registered as RGB type image data in the image storage device.
Record. Figure 60.61 shows the structure of RGB type image data.
vinegar. In the image storage device, registration is performed as shown in FIG. 27(A).
Basic block of memory A-D (4060A-D)
Configure the lock as shown in Fig. 60, memory A (40
60A), R image (4060A-R), 6 images
image (4060A-G), 8 images (4060A-B),
Combine each basic block. Image composition
The width is the horizontal length and the vertical length.
The number of pixels (dots) of the height of
It has become. Specifically, it is an RGB color image, each of R, G, and B
Each pixel has a depth of 8 bits (1 byte).
It has a three-frame configuration of R, G, and B.
ing. Therefore, one pixel on the R surface has 256 gradations (0 to 255).
So, the three sides of RψG-B are 256 x 256 x 2
56 #l It has a data structure of 6.7 million colors. Note that 0 represents low brightness and 255 represents high brightness. The data structure is arranged in order from the top left on the R side, and this structure is called RGB.
Continued in order. The image between the image storage device 3, input/output device, and computer 33
Image data is transferred using the transfer format shown in Figure 61.
It has become. In other words, data is transferred in frame sequential order. No. 62. Figure 63 shows the image of CMYK type image data.
This page shows the page structure and its transfer format. C is cyan;
M stands for magenta, Y stands for yellow, and K stands for black. In such a case, a memo in the registration memory in the image storage device 3
The basic blocks of Rear A-D (shown in Figure 27A) are the 31st
Create an image structure as shown in the diagram, and use basic blocks for each.
Assign. Specifically, it is a CMYK color image, C, M, Y. 8 bits (1 byte) per pixel for each K
It has four depths: C, M, Y, and K.
It has a frame structure. Therefore, it is possible to express 256 gradations with one pixel on the 0th plane.
The same applies to the M, Y, and other surfaces hereinafter. 0 represents low density and 255 represents high density. The data structure is arranged in order from the top left on page 0, and this structure is CM Y K
(Figures 64 and 65 show 8-bit palette type image data.
The image structure and its transfer format are shown. Memories A-D (27th memory) of the registration memory of the image storage device 3
The basic block in Figure A) is configured as shown in Figure 64, and the basic block is
Assign this block. An image with a depth of 8 bits (1 byte) per pixel.
It has a page configuration. The 8-bit data value of l pixel is as shown in Figure 66.
Color index of color palette table 4391
It corresponds to the color of the user and can be set arbitrarily by the user.
Can be attached. Therefore, it is possible to express 256 colors per pixel.
It is possible. FIG. 85 shows the relationship between image data and color palette. The data structure is in order of data starting from the top left of the image.
are lined up. Figures 67 and 68 show binary bitmap type image data.
The image structure and its transfer format are shown. The binary bitmap is stored in memory E (27th
Figure A). This image data has an image file name extension of “S”.
It is a special file, and the image file name is “B”.
ITMAP, S” and is a binary bitmap type.
For memory E (Fig. 27A) that can only register
be registered. Memory E (Fig. 27A) has basic blocks whose memory
It is not possible to register multiple items because the
stomach. Binary bit map type image data is
It has an image structure with a depth of 1 bit. Therefore, there are two expressions per pixel: “0” and “lH”.
Become. “0” means white (no printing), “bi” means maximum density.
(black). The data structure consists of 8 bits starting from the top left of the image.
In other words, to set data to 1 byte per 8 pixels.
Therefore, binary bitmap type image data is
It must be a multiple of 8 in the h direction. he
The light direction is arbitrary. Image file size is set in pixels.
Therefore, the amount of data transferred is as follows: <width>: Width of the image file (wtdth
) height>: Height of the image file (hei
ght) 8: 8 pixels equals 1 byte of data.
To do so. Next, a command is sent from the computer 33 to the image storage device 3.
Figure 69 is used for the structure of the response data to the code transmission.
I will explain.・Basically, response data excluding image data is of the following types:
There is. FIG. 69 shows the structure of response data. As you can see from the figure, which response data depends on the type of command.
The difference is whether data is received. A. CK and NAK are a pair, and the size of the command is
Either of these parts is used as response data.・ACK type response data is an affirmative response to each command, and is
This indicates that the data has been successfully transmitted and decoded to the storage device 3 side. head
3 bytes: 1 byte is 2EH, remaining 2 bytes are OOH
The fixed value/NAK type response data is a negative response to each command, and any error occurs.
In response to the occurrence, the first byte is 3DT (,
The remaining 2 bytes are an error code. (Error code) = (upper byte) x (100 (HEX
) + (lower byte)・RET type (response with attached information
) response data is sent to the command from the computer 33.
In response to this, the necessary information is attached to the image storage device 3.
It is sent from (.The structure is 8 bytes in total,
The first l byte is a fixed value of the header (02H)
. Following the header, 1 byte from 1st data to 7th data
The data content of each is changed by command.
different. The command is sent by the computer 33 to the image storage device 3.
You can control image data input/output, image file management, etc.
There is a command like the one shown in Figure 70 for this purpose.
. Commands are divided into those that perform a function with a single instruction, and those that perform a function with a single command.
The parameters following the command are divided into necessary ones. FIG. 58 shows an example of the configuration of command parameters. Commands and parameters are recorded as image strings.
Send to storage device 3 via GPIB controller 4310
If there is a numerical value in the parameter section,
It is necessary to convert the numerical value to a character string representing the lθ base number. Also, among the parameters is a string indicating the image file name.
There is also. These commands transfer image data to your computer.
33, image storage device 3, input device 1. :3i. Output device 2.3 How the flow flows between each device is explained below.
Shown in Figure 59. Command from computer 33 to image storage device 3
It is classified into seven types. (Figures 70 to 72) ■Initialization command: Performs various initializations. ■I/O selection command: Selects input/output devices. ■I/O mode setting command: Sets conditions for image input/output. ■I/O execution command: Executes image input/output operations. ■File operation commands: Perform operations related to image files ■Color setting commands: Configure color-related conditions ■Other commands: Other Each command will be explained next. The initialization command will be explained using FIG. 73. The INIT command sends initial data to the image storage device 3.
This is a command to set the data. The INITBIT command specifies a binary bitmap.
Clear the image in the digital file “BITMAP, S”
It is a command. The INITPALET command is used to change the palette of image storage device 3.
This is a command to initialize the cut table. The input/output selection command will be explained using Figure 74.
. 5SEL command is color reader 11 analog human power
4500.4510.452OR, 4520G, 45
20B. Select the input system of the 4520S. CPU4360 is n
. Selects the input system specified by the parameter when it is an analog input.
Kuta 4250. In the selector 4010, the reader 1 input
This is a command to be input and selected by the time selector 4250. The DSEL command is an image storage device for color printer 2.
This command sets the output of image data from the device. Explanation of input/output status setting command using Figure 75
do. DAREA command outputs from image storage device to printer
The upper left coordinate position (sx, sy) and output size (
With the command to set width
be. Also, set the unit at that time with type, m m
, i n h , d a etc. are set.
Can be determined. The 5AREA command is input from color reader 1.
This is a command that sets the rear in the same way as the DAREA command.
be. 5AREA/DAREA input/output range setting
is performed by the system controller 4210. DMODE command (the mode specified by the DAREA command)
Change magnification when outputting (for rear) 4150-0 to 41
This is a command to set the enlargement/interpolation circuit of 50-3.
. The 5M0DE command is specified by the 5AREA command.
The system controller changes the reading magnification when inputting to the area.
This is a command controlled by the controller 4210. The ASMODE command reads an image from the analog input terminal.
Input as field signal or frame signal.
system controller 4210 and the counter
Set what is to be done on roll 9141 on CPU 4360.
Ru. In addition, field signals and frame signals are used for television.
Since this is well known, the explanation will be omitted. The input/output execution command will be explained using Figure 76.
. The copy command reads the reflective original of reader l,
without registering it as an image file in the image storage device 3.
This is a command that causes the printer 2 to output directly. At that time
Printer by the parameter indicated as <count>
2. You can specify the number of sheets to be output. The 5CAN command causes the CPU 43 to
6011Is it the input device specified by the SSEL command?
Load the image data from the file and display it as <filename>.
Extended with the image file name specified by the specified parameter.
Width X height with child image type
The data is read in file size and stored in the image memory 4060.
hold At that time, the CPU 4360 selects the image file name, image
Information on type, image size, and which image memory it was registered in
Image file management table 4361 shown in FIG.
Set to . The PRINT command is the opposite of the 5CAN command.
Image file data already registered in storage device 3
With the parameter indicated as <filename>
This is a command to specify the image file.
From the file management table 4361, the image memory 4060
and output the data via the video interface 201.
output to the printer. At that time, it is indicated as <count>.
The printer repeats the number of times specified by the specified parameter.
Output. The MPRINT command is registered in the image storage device 3.
The parameter indicated as <filename>
Virtually output the specified image file data by
It is a command. This is a composite of multiple layouts and output.
This command allows multiple image files to be
are specified sequentially, and each time the CPU 4360 specifies the memory 4
Image file specified by MPRINT command in 370
Store the name and print or copy the frame.
By specifying the command, the CPU 4360
Image by MPRINT stored in Mori 4370
Combine files into multiple layouts and output to printer 2.
Ru. The PRPRTNT command is executed from the computer 33 to the CP
Image data sent via IB interface
(widthXheight (size), <fil
The file specified by the parameter indicated as
The CPU 4360 registers the file name in the image memory 4060.
, the following operation is similar to the PRINT command, and the printer is
This is a command that outputs directly to the computer. The DR3CAN command displays the image from the color reader l.
Read data of specified size (widthXheight)
<filename> on the image memory 4060
Register with the specified file name shown as
Set attribute data in the management table in the same way as the SCAM command.
to And further GPIB interface 45
80, the data is transferred to the computer 33. Next, the file operation commands shown in Figure 77 will be explained.
. The DELE command has already been registered in the image storage device 3.
Shown as <filename> in the image file that is
The image file specified by the specified parameter is converted into an image file.
Command to delete from management table 4361
It is. At that time, the free space in the image memory after deletion is
The PU 4360 determines from the management table 4361 that the RE
Set free size data to T type response data.
GP sends 8 bytes of RET response to computer 33.
Send via fB. The DKCHECK command checks the image memory in the image storage device 3.
The image file type specified by the type parameter is
type (CMYK, RGB, 8-bit palette, binary bit)
The image of Tomatopu) is of width x height.
The CPU 4360 checks whether the image size can be secured.
Judging from the file management table 4361, the RET type
Set the availability of reservation in the response data of
The amount is determined by the person who sent the DKCHECK command, for example.
GPIB is sent to the computer 33 as RET response data.
Send via. For example, by such a command or specific code, FIG.
The display shown in G can be performed. The FNCHECK command uses <filename> and
The image file specified by the parameter shown in
Check if it exists in the file management table 4361
and set presence/absence in RET response data.
It is returned to the computer 33. The FNLIST command sends the current image file to your computer.
This is a command to send the contents of the file management table.
. The REN command is set in the image file management table.
This command renames the image file that is
and change the image file name <Sfilename> before changing.
This is the command to change to the changed <Dfilename>.
Ru. Next, use the file operation command to create the image data using Figure 78.
This section explains commands that involve data input and output. The LOAD command loads frames registered in the image storage device.
In the command, the parameter indicated as (filename>
The data of the image file specified by the data is stored in the image memory 40.
60 to the computer 33 via GPIB.
It is a command. 5AVE command is the opposite of LOAD and is
widthXheight image size data, <f
ilename > Image storage device with parameter file name
Image data is registered in the location 3. First, CPU4
360 is a file in the image file management table 4361
Set the image name, image type, image size, and
sent from the computer to the free space of the memory 4060.
This is a command to set the received image data. The PUT command has already been registered in the image storage device 3.
specified by the parameter indicated as <filename>.
The upper left coordinates (sx,
sy) to width X heigbt size
Fit image data sent from a computer within the range of
can be included. The GET command is the opposite of PUT.
The image data of the image file with name> is located at the upper left coordinates (s
x, sy) widthXheight image range
Transfer the image data to the cutting computer 33 with
can do. FIG. 80 shows other commands. MONITOR near 7nd is in <type> parameter
corresponding to the analog input specified by the 5SEL command.
and send data directly to analog outputs 4590R, G, B, and S.
Display settings for through display
controller 4440. In addition, as a variable of type
For example, "0" (through display is set), "1" (monitor
) etc. Furthermore, the MONITOR command is
lower than the command and other DSCAN and SCAM commands.
Therefore, the through display setting is canceled. The PPRREQ command is used by the CPU 4360 to
Control unit 1 via interface 201
3, for the one currently set in color printer 2.
Obtain the paper size information and enter the paper discrimination data on the computer side.
send data. The PPR3EL command is executed by the control unit in the same way as above.
For knit 13, specified with the <no> parameter,
Command for selecting among multiple paper trays.
Yes, the image is output to the color printer 21 via the image storage device 3.
Powered. 5ENSE command is for image storage bag M3 and color reader.
-11 Regarding the status of each device of color printer 2, CP
U4360 controls via video interface.
Communicate with Roll Units) 13, obtain it, and send it to the computer side.
This is the command to send the data to. Next, data from the computer 33 to the image storage device 3 is
The command sending procedure will be described. A group of commands that are the basics of image input/output.
(i) Input/output selection commands 5SEL, DSEL (ii) Input/output status setting commands 5M0DE, 5AREA, , DMODE, DAREA. RPMODE, ASMODE (iii) Input/output execution commands 5CAN, DR8CAN, PRINT, MPRI
N.T. It becomes DRPRINT. As shown in Figure 82, input and output of image data
There is a basic procedure for sending commands. First, use the input/output selection command to select the input/output
Select the device and select C of the image storage device 3.
P U 4.360 parses the command and
ACK/NAK of response data to computer 3
Return to 3. Next, the computer 33 issues an input/output status setting command.
, to the image storage device 3, and send the result to the CPU 4360.
computes the ACK/NAK response data in the same way as above.
data 33. The input/output status setting command is executed by the input/output execution command.
Once the
Ru. Therefore, the input/output status setting command is not executed.
If the input/output execution command is executed, input/output status settings
is set to the default value. When performing input/output
If you want to set the input/output status, set it for each input/output execution (basic).
(for each type), it is necessary to execute the input/output status setting command.
be. Then, input/output that actually performs input/output of image data.
The CPU 4360 sends the execution command and in response
Return RET type response data and acknowledge (ACK)
In this case, the actual image data input/output is performed by the input/output device
Reader L 5V31, printer 2, monitor 32, etc. and images
It takes place between storage devices. This input/output is the same as in the embodiment described above, and a description thereof will be omitted. The CPU 4360 uses the image file management table 436
The following is a guide to registering image files from a computer.
Checks image file attributes in advance for commands.
or check the memory capacity (memo) that can be used to store files.
(A-D) Check the steps in Figure 27 A))
It is possible to perform the process and notify the computer 33 side.
be. The command for pre-checking this image file is:
There are FNCHECK and DKCHECK commands. The procedure for checking this image file is described in Section 82.
As shown in Figure 83, first, select the specified file of the image file.
The existence of the file and its file attributes are of RET type.
is sent to the computer 33 as response data, and further
, the remaining capacity of the image file or the desired image
The response as to whether the file size can be secured is the RET data.
It will be returned as ta. The basic form of this file check is the human output frame described above.
Incorporate it into the basic form of the
It is also possible to check and respond to image files in advance.
It has become a Noh performance. Next, the composition of image files will be explained. Image files are stored in the registration memory 4060 of the image storage device 3.
Create a color print by combining multiple registered images.
To output to Data 2, use MPRINT from the computer side.
This is possible by sending a command to the image storage device 3.
. The MPIINT command registers the image storage device as an argument.
Specify the image file name. MPRINT
The CPU 4360 interprets the command string
analysis and temporarily register the file name on the memory 4370.
Ru. This is for laying out multiple MPRINT command strings.
The data is sequentially transmitted from the computer 33 on the RAM.
The specified file name will be temporarily registered and multiple files will be registered!・
When the last image is displayed, the computer prints the PRINT frame.
Send the command string. CP TJ 4360 is this PR
When the INT command is parsed, the MPRI on the RAM is
In the order of image file names sent in the order of NT commands
, the CPU selects the image from the image file management table 4361.
Transfers the specified image data from the image memory to the color printer.
send and output. The composite output in this case is as described above.
Ru. Sending MPRINT from computer and PRIN
The superiority and inferiority of image composition using the T command is shown in Figure 88.
The image specified first will have priority. In addition, a binary bitmap memory (memory shown in FIG. 27A)
) and registered in the image storage device.
To combine the image file with the above-mentioned MP
Multiple specified image files for RINT and PRINT commands
The special file “BITMAP, S” appears in the file name.
If you set the file name on the computer side and send it, the CPU4
360, as mentioned above, combines multiple image files and
Performs synthesis with binary bitmap data. Please note that this implementation
In the example, the binary bitmap image has dots that are
However, the "O" part is basically black, and the "O" part is other images.
Switched to give priority to file output. mosquito
An example of this is shown in FIG. Such switching is performed by the video interface 2 of the reader 1.
Since 01 is used, the configuration of the image storage device is simplified.
. As an image composition function, image files and binary bits are
Map's 4BITMAP, S" special file and
, Reader] It is possible to combine and output the reflected originals of the
function, performs the compositing operation described above. The above-mentioned operations based on commands from the computer are performed by M
Execute with PRINT command and C0PY command
can be done. Command to specify multiple image files using MPRINT
Finally, send the C0PY command and use it as a trigger.
The CPU 4360 copies the data to the CPU on the color reader side.
- gives instructions for the operation and also uses the MPRINT command
The image file created by the card and the original reflected in the reader are combined.
can be output. At that time, the “BITMAP, S” screen is displayed in MPRINT.
If you specify an image file, you can also combine it with a binary bit map.
It can be carried out. In this embodiment, reader 1 is read by the C0PY command.
Reflective originals are automatically given the lowest priority.
, can be the background of the image. Commands sent from the computer and the actual printer
The output result from the data processor is as shown in FIG. In this embodiment, the color adjustment function is as shown in Fig. 79.
, color palette function, color balance function, gamma
As a command from a computer that supports the correction function.
, PALETTE command, BALANC command, respectively.
E command, GAMMA command, BrTOOLOR command
There is a mando. The color palette is an 8-bit palette tie as described above.
You can set the color of the map and the image of the binary bit map type.
Used to color data. To do this, add the color code to the palette number in the color palette.
Set the data. Specifically, 256 color data can be set.
and set 8-bit data for each of RGB. It is set in the color palette 4362 in the image storage device 3.
Transfer the color data stored in the host computer to the color data stored in the host computer.
- By making the image storage device 3 the same as the palette,
The color of the image to be output on the color printer via the host
It can be the same as a computer. The color palette table in the image storage device 3 is PAL.
Save the palette table as an image memory using the ETTE command.
Set for each image file registered in location 3.
I can do it. Therefore, the extension is 8-bit palette with P''.
Print or MPRINT image files of type
When outputting with the command, the PALETTE command is
from the computer and then, for example, as shown in Figure 91.
256X3 (768) RGB palette for hide
Print table data via GP-IB4580.
PRIN set on the palette table of image storage device 3
When the T/MPRINT command is executed, the current
R, G, of the set palette table 4362
B component respectively LUT4110A-R, 4110A-
G. 4110A-B to convert from brightness to density.
Perform the following operations on each table. At that time, if specified by the PRINT/MPRrNT command,
Convert palette type image file data to a palette template.
LUT4110A-R, 4110A-G with bull set
, 4110A-B to 8-bit palette brightness information.
is converted into density information and sequentially output to the image output system described above.
The image is then output using a color printer. 8-bit palette type images are sent via GP-IB.
Work memory 439 when sent from the computer
It is set to 0 one line at a time, and the registered memo is registered by DMA.
Same as 4060-R, 4060-G, 4060-B.
The same data is set and repeated sequentially. 8-bit parameters that can be set using the PALETTE command.
The maximum number of let tables is 16, allowing multiple lay tables.
When compositing by out, each 8-bit palette
It can be set for type image data. MPRINT multiple 8-bit palette type images
Before performing virtual output using the command, use the PALETTE command.
The color palette data (768 bytes) is
The CPU 4360 is stored in the memory 4370 of the image storage device 3.
Register at the time. Multiple 8-bit palette images that combine this into a layout
Repeat this and print PRIN when outputting the last image.
Execute the actual output using the T command. The image storage device 3 can be
The 8-bit data set by each MPRINT command
from the memory 4370,
When sequentially outputting a composite, select the color palette template for output.
4362, and multiple
It is possible to combine the images and output them to printer 2.
Ru. Next, set the color balance by RGB type and CMY
It is possible to set two types of color balance for K type.
They can be distinguished by the ype parameter. This setting
can be set using the BALANCE command. RGB color balance is LUT4110A-R. The brightness slope is B for 4110A-G and 4110-B.
CI, C2, C3 parameters of ALANCE command
Set with a value of ±50% and calculate the conversion from brightness to density.
Ru. CM Y K color balance for LUT4200
, the gradient of the concentration is the CI of the BALANCE command, C
2゜Set according to the values of C3 and C4 parameters ±50%
. Each image file data is converted by the above LUT,
Image quality can be changed from low to high brightness and low to high density. The GAMMA command is set to RG by the type parameter.
The B type image file data shows the CRT's light emitting characteristics.
For the data with γ=0.45 correction being considered, the
In order to be able to reproduce colors on CRT using linter 2 output,
of the LUT registered in the memory 4370 in advance.
Data 4110A-R. Set to 4110A-G, 4110A-B, and from the brightness
By adding the conversion operation to concentration, γ== 0,
Color reproduction of RGB image data with 45 CRT corrections
can be output. BITCOLOR command is a binary bitmap memory
(Special file “BITMAP, S”) (No. 27
For memory E) in figure (A), upper left (sx. sy) coordinates, size width x height range
The color parameter specified by the 1ndex parameter is
Change the color of index number of let 4362 to “BITM
A.P. S” binary bitmap output to color printer 2
Coloring can be done from the computer as mentioned above
This is possible with the command. BITOOLOR command
sx, sy, width, hei by code
ght. The parameter of 1ndex is that the CPU 4360 uses memory 4.
It is possible to hold more than one on 370. And the fruit
When using the MPRINT or PRINT command,
Set the file name “BITMAP, S” to ilename.
When specified, the CPU 4360 uses color reader l/color
- CPU 22 of the control unit 13 of the printer 2
Image storage via video interface
From device 3, sx, sy, width, h
The parameters of the eight area and the associated power
color palette index number (index parameter
in the color palette table 4362 corresponding to
Send 3-byte color data of RGB components,
IJ7 is specified by the BITCOLOR command.
(repeat in sequence), if the control unit
The port 13 is connected to a programmable synthesis unit 115.
Set these parameters to change the color of the binary bit map.
- You can color a specified area with a specified color when outputting to a printer.
shall be. In this way, you can change the area and color on the control unit 12 side.
After making the settings, the CPU 4360 of the image storage device 3
“BIT” by RINT or MPRINT command
Binary bitmap data of MAP, S'' (Figure 27 (A)
)'s memory E) via the video interface.
Commands from the computer can be output in color
This becomes possible. Coloring is for the bit “l” part of the binary bitmap.
will be carried out. Color reader/color printer with remote function
and image storage device 3 can be controlled by the host computer.
can be set to The above command from the computer doing the remote
There is a REMOTE command, and this command
, can be put into four states (Fig. 92). The system remote status is the color reader/color printer.
printer and image storage device 3 according to commands from the computer.
Therefore, it becomes possible to control. Only the image storage device 3 is controlled by the host computer 33.
It can be controlled by command. At this time, the color reader/color printer is
Copying operations can be performed by itself. The local state can also be accessed from the host computer.
local status (control) from both the printer/color reader
color reader 1) and the color reader 1 cannot be operated.
Remote specification from the production department or host computer
Instructions by REMOTE command from the controller
The remote state will be established as soon as possible. When the copying machine is in the remote state, the image storage device 3 is connected to the color reader.
-1 to remote mode and control according to instructions from the control panel.
It becomes possible to control the At this time, the computer
The command cannot execute the functions of the image storage device 3.
I can't. These remote/local states are
The type parameter of the REMOTE command from the
It can be specified by the data. The type parameter of the REMOTE command allows C
PU4360 has color printer 2 and color reader 1.
CPU 22 of control unit 13 and video interface
-By communicating via the face 201, the above-mentioned
Instruct 4 remote/local states from computer
can do. Next, Figures 84 to 87 show the command transmission procedure described above.
(A few examples are shown.) Figure 84 shows how to use the 5CAN command to input images from the input device.
Register the image data to the image storage device 3 as an image file.
This is the procedure. Basic part of file check in the diagram
As mentioned above, check in advance by performing the steps shown in Figure 83.
It is also possible to etch. Figure 85 shows how the image storage device is printed by the PRINT command.
Output the image data of the image file that has already been registered in 3.
This is an example of the procedure for Figure 86 shows how the input device is activated by the DR9CAN command.
input the image data into the image storage device, register it, and then
The procedure for transferring image data to the computer 33 is shown below.
vinegar. Figure 87 is the reverse of the DR3CAN command in Figure 86,
Output the image data on the computer 33 using the output device
This is an example. Next, we will give an example of an actual command. An image in the host computer as an example of a single image output
FIG. 93 shows an example of outputting to a color printer. example
For example, an RGB type image of 1024 x 768 pixels.
Move the image 277X from the top left (10,10) mm position of the paper.
Center within 190mm and print out
An example will be explained below. As an example of layout output of multiple images, the host computer
l in ta 3? Two GB type image data on one sheet of paper
This is an example of layout and output using color printer 2.
(Figure 94). In this example, 1280x1024 and 1024x768 pixels
Set each of the two RGB type images of the cell within the range shown in the diagram.
An example of how to interpret and print out is shown below. When outputting multiple images, one image at a time is sent from the host 3.
Register in storage device 3, perform virtual output, and output to printer 2
(as shown in Figure 96), and if the image data is
It is registered to the image storage device, and all virtual outputs are summarized.
There are cases where the data is output (the case shown in FIG. 95). Which
The output result is the same. Also, as an example of importing images from reader L to host 3,
This is shown in FIGS. 97 and 98. In such a case, first, for example, A4 size paper on the reader 1.
A corresponding area (297 x 210 mm) is covered by RGB tag.
The image data of 1000 x 707 pixels is
Read the size and import the data to host computer 3.
Get into it. As described above, according to this embodiment, the computer 3
3, without retaining image data for input/output.
Instructions (commands) between the image storage device 3 and the computer 33
Image data can be input and output simply by exchanging
Computers and input/output devices (reader 1, printer 2, etc.)
) can be reduced. In the above explanation, in this example, the target image is photoelectrically converted.
As a means of
Although a bed-type sensor was used, the sensor is not limited to this, for example,
A spot type sensor may be used, and the sensor
It is not limited to the type of In addition, in this embodiment, a so-called means for image formation is used.
A model that forms full-color images by plane-sequential image formation.
I used a color printer, but it is not compatible with such a color printer.
If you are using a non-plane sequential printer such as an inkjet printer,
It may be a printer, a thermal transfer printer, or a computer.
It may also be a printer called a color printer. In addition, in this embodiment, a host computer, an image storage device,
Color readers communicate with each other as independent devices
Since the various functions mentioned above are realized by performing
system can be provided. According to this embodiment, as a means to solve the above-mentioned problems,
, has the following configuration. In other words, the image input device and its
Image formation that forms an image from input image information on an image forming medium
an image storage device that stores the input image;
, controlled by control instructions from a control device that controls them.
Manually convert the binary bitmap image created on the device into an image.
means for storing in the image storage device;
Combines a multivalued color image and a binary bitmap image.
and means for outputting the image from the image forming apparatus. Therefore, according to this embodiment, control from the computer
Other colors can be added to binary bitmap images according to commands.
- It becomes possible to combine and output images. [Effects of the Invention] According to the present invention, a binary image and an image from an input device can be synthesized.
It is possible to provide electronic equipment that allows

[Brief explanation of the drawing]

1 is a block diagram showing the configuration of a system according to an embodiment of the present invention; FIG. 2 is a block diagram showing the configuration of the document scanning unit 11, video processing unit, and control unit 13 shown in FIG. 1; 6 to 6 are diagrams explaining the functions of the video interface 201 shown in the second diagram, and FIGS. 7(a) and 7(b) are the logarithmic conversion circuit 4 shown in the second diagram.
Figure 8 is a diagram showing the spectral characteristics of the color separation filter, Figure 9 is a diagram showing the absorption wavelength characteristics of color l and color, and Figure 10 (a).
10(b) is a diagram for explaining the operation of FIG. 10(a), and FIG. 11 is a block diagram showing the configuration of the color correction circuit 49 shown in the second diagram. Block diagram showing the configuration of Figure 12 (a), (b), (C), (d)
are diagrams explaining the operation of the circuit shown in Figure 11, Figures 13 (a), (b), (c), (d)
, (e), (f) are block diagrams showing the area signal generated by the area generation circuit 69 and the configuration of the generation circuit 29; FIGS. 14(a), (b), (c), (
d) is a diagram showing the configuration and control timing of the area restriction mask bitmap memory 91; FIG. 15 is a diagram showing the relationship between the masking bitmap memory 91 and the pixels of the original image; 161iU is the masking bitmap memory A diagram showing an example of a mask memory formed on 91, FIG. 17(a)
is a block diagram showing the configuration of the interpolation circuit 109 shown in FIG. 2, FIG. 17(b) is a diagram explaining the operation of the interpolation circuit shown in FIG. 17(a), and FIGS. 18(a) and (b) are FIG. 19 is a diagram showing an example of cutting out and combining according to the output of the mask memory 91, FIG. 19 is a diagram showing the characteristics of the density conversion circuit 116, and FIG.
20(a) is a block diagram showing the configuration of the repeating circuit 118, FIG. 20(b) is a timing chart explaining the operation of the repeating circuit 118, and FIG. 20(C) shows an output example of the repeating circuit 118. Figure 21 (A), (B), and (C) are (repetition circuit 118
FIG. 22 is a time chart showing the print sequence of the printer 2, FIG. 23 is a plan view of the digitizer 16, and FIG. Diagram showing addresses, Figure 25 (A)
is a block diagram showing the configuration of the synthesis circuit 115 in FIG. 2, FIG. 25(B) is a diagram showing the relationship between an area code and an example of an area on a document, and FIG. 25(D) is a diagram showing the configuration of the area code generator 130 shown in FIG. 25(C).
25 (E) is a diagram showing an area corresponding to the data shown in Figure 25 (D). Figure 25 (F) is a diagram showing an example of the data shown in Figure 25 (A). RAM135
Figure 25 (G) is a diagram explaining the state of composition shown in Figure 25 (A), Figure 25 (H) is a diagram showing the data structure of ゜136,
Furthermore, FIG. 25 (1) is a diagram showing a state in which characters from the bitmap memory are synthesized, and the decoder 14 shown in FIG. 25 (A)
FIG. 26 is a diagram showing the timing of the signal 207 and image signal 205 output from the color reader I, and FIG. 27 (A)
, (B) is a block diagram showing the configuration of the image storage device 3, FIG. 27(C) is a diagram showing the configuration of memories A to D shown in FIG. 27(A), and FIG. 27(D-1) is a block diagram showing the configuration of the image storage device 3. Figure 27 (D-2-) is a diagram showing the configuration of bitmap memory E, Figure 27 (D-2-) is a diagram showing the relationship between the original and data written in bitmap memory E, and Figure 271M (E) is Figure 27 (A). 27(F) is a diagram showing a part of the internal configuration of the system controller shown in FIGS. 27(A) and (B); FIG. 28(A) is a diagram showing the configuration of the monitor memory M shown in FIG. Filter 950 shown in FIG. 27(A)
A block diagram showing the internal configuration of 0, FIG. 28(B),
(C) is a block diagram showing the internal configuration of the selector 4250 shown in FIG. 27(A), and FIG. 29 is a block diagram showing the configuration of the system controller 421O shown in FIG.
A diagram showing the relationship with the FIFO memory in ~M, Figure 30 is a timing chart when trimming processing is performed, Figure 31 is a timing chart when trimming processing and scaling processing are performed, and Figure 32 is a memory A's internal memory 4060A-R. A block diagram showing the relationship between G and B, the counter controller, and the counter. Fig. 33 is a diagram showing the capacity of memories 4060R, G, and B when memories A, B, C, and D are connected. Fig. 34 is a diagram showing the capacity of memories 4060R, G, and B when memories A, B, C, and D are connected. FIG. 35 is a timing chart explaining the operation of the circuits in FIGS. 27(A) and (B); FIG. 36 is a diagram showing the state in which the image in the storage device 3 is formed by the color printer 2; FIG. 36 is the memory 4060A-R; FIG. , G, and B; FIG. 37 (A) and (B) are diagrams showing an example of image synthesis; FIG. 37 (C) is a timing chart showing the timing during image synthesis; D) and (E) are diagrams showing other examples of image composition, Figures 37 (F) and (, G) are diagrams explaining enlarged continuous shooting from memory, and Figure 38 is Figure 37 (A). 27th in the 11th line of
39 is a timing chart explaining the operation of each part in the figure.
40 is a timing chart showing the sequence of screen-sequential color image formation in the color printer 2; FIG. 41 is an internal configuration of the selector 4230 in FIG. 27(B); FIG. Figure 42 shows the memory M (2) shown in Figures 27 (A) and (B).
407) and image memories A, B, C,
D (corresponding to 2406), FIG. 43 is a diagram for explaining the operation of the circuit shown in FIG. 42, FIG. 44 is a flowchart for explaining the operation of the circuit shown in FIG. 42, and FIG. is a block diagram showing the structure of the film scanner 34 shown in FIG. 1, FIG. 46 is a perspective view showing the structure of the film carrier shown in FIG. 45, and FIGS. 51 is a block diagram showing the configuration of the storage device 3 when viewed from the host computer 33 shown in FIG. 1; FIG. 52 is a diagram showing a display example;
55 shows the coordinate system of each device, FIG. 56 shows the structure of the image file name, and FIG. 57 shows the classification of data transferred between the host computer 33 and the image storage device 3. Figure 58 is a diagram showing an example of the configuration of commands, Figure 59 is a diagram showing the flow of image data generated by various commands, Figure 60 is the state of storage of R, G, and 8 image inputs in memory. Figure 61 is a diagram showing the form during data transfer, Figure 62 is a diagram showing the Y
, M, C, K image inputs are stored in the memory; FIG. 63 is a diagram showing the format at the time of data transfer; FIG. 64 is a diagram showing the storage state of palette image data in the memory; The figure shows the format during data transfer, Figure 66 shows the correspondence between palette image data and data showing the R, G, and B components of each palette, and Figure 67 shows how binary input is stored in memory. FIG. 68 is a diagram showing the format during data transfer. FIG. 69 is a diagram showing the structure of response data. FIG. 70 is a diagram showing the classification of each command. Figures explaining each command; Figures 81 to 87 are diagrams showing the execution procedure of each command; Figures 88, 89, and 90 are diagrams showing an example of image synthesis in the system of this embodiment; FIG. 91 is a diagram showing the structure of a color palette, FIG. 92 is a diagram showing the remote and local relationship between the color league 11 image storage device 3 and the host computer 33, and FIGS. 93 to 98 are diagrams showing the host computer 33 and the image 3 is a diagram showing the exchange of commands with the storage device 3,
Ru. In the diagram, 1... Color reader 2...
・・・・・・・・・・・・Color printer 3・・・・・・
...... Image storage device 32 ......
...Monitor TV host computer Original scanning unit Video processing unit Digitizer operation section g LIJT
I Sifabbura "-7)" I,)F3LIJ7QRe7
Atsubtefu;suC (d;n, n (b) (C) Fig. 13 is) 7 main poor enterprises C all Fig. 13 (b) Part 730 (c) CLK Fig. 74 (c) 4 fields 4 shells Figure 18 (b) Mask memory qI and “Okema Doto 10′? /l output ATA UT RDr) ATA! Rod 20W (C) Sugar 21 factor Adorne (Vctx) θ /Z and (2 (δP) k (S・r) Figure 25 (S Figure 25 (1) 270CF) Same) Figure 2q System de A comptoir Ramemory (R) Memory (G) Memory CB) 4060R Memory (R) 060G Memory (G) 060B Memory (B) Figure 3G Madres picture 4 (1 mm, 1 layer x 7th odd spray Y Mori view J , Figure 55 (Command IsJ row 1 row (16,) Image 7

[The flow is the same (Theta Order-11) RGB R1γ (Image 1 of RGBI11 surface) CMY, Tie 7° ('YMCKt!
xa data 臥) 8 Hi, Ntope, Ntoku 1, A, 1, Fig. 65 (8 Gotsutobe, Soto's Teita Ushikibe) Binary Value - 7 Tomatsu Aqui γ (? Ilbi, Toma, )(1
1 part time job! , MSB end left, LSB end A rule)
(2 [Hishitomafu) - 〇Data 狽》Weight) 3-byte PET type (4-inch end handling village response,) (Yingko-go゛-Even +8 formation) Command゛-Jiji 77 commands 曽1 cost ￥Shiokoguchi 1】KINIT, (no) 口

[JKO INITBIT, (tV) initialization, ;mashiF Figure 73 [EEKODAREA, (electrony) 噌し> (ax) jsvノ (hThght) mouth []KO DARIA (tvm), (sx ) (sy), (width) (h@1aht) 口!] 口5M0DE, (tyo*), (mx), <my) 口 ``Eco RPMODE, (flai) A sudden apology for joining the company《Rin〉parable Figure 75 Exit 1] Ko5SEL<no) (fram@> Exit 1] KoDSEL (no) Enter the entrance to the station.

[jko5CAN, (filesme), (width) (h
eight+ri U-co PRINT, (+il*na+vv) U-co MPRINT, (filsnams>mouth "]ko DR5CAN, (filenanns), (width
), (h*io?n+enter = sword refreshing;?nd man 76 figure mouth 1] KOεLE, <filaname) [Checks the registered capacity of the image storage device. [DKCI-IEcK, (type), <wi
dth>, <height) 口1] こFNCHECK, (filename>[N] Transfer information of all registered image files in the image storage device to the host computer. [] []

[FNLIST [EU] Change the image file name. [j[][ko REN, <5fil@name>
, <Dfilsname) File O Shibajikin Command No. 77 Riro 1] BALANCE, <type) <cl> (C2), (C3>(C4> Mouth 1] KOBITCOLOR, C5x), (sy> (widt
h) (height) (index> 口[]KOGAMMA, (tYN) Color setting command P 77th 口[]口LOAD, (filename) 口[]KO5AVE, (filename) <width>, (height>) [ nkoLJT (filename) <sx), (sy) (width), <height) mouth

[Cut out only a portion of the image stored in the image storage device and transfer it to the host computer. (filename) <sx><sy)<width><height> File gorge Y frame>de Figure 73 mouth 11 PPRSEL (no> mouth 1] ko5ENSε-(d@w), (type) Ai-no-baku-coman attack Figure 8θ Irieka basic form] Figure 81 (Toad vermilion form of the sword code), 5CAN command three changes 17th input child] Around 4th edition No. 8
Figure 4 PRINT command and I Sarate L pa self = phantom chi ^1 Boku example No. 8
Figure 5 DR3CAN command and convenience ni Shichiriko 1' Go ε (? Figure (14 to 7 isle B Spendar file γ I combination - father force and 41 to 1k) Column 9 No. 7-do vice-gyo line 'L-ro 1 entry, local control 1st tJA) pattern. L tablet L
・ζ end, Jj Bond 1; Maotome Kaburu JAVE, -P2. , "r, i #, 672 thickness cheetah hair z, ?'s Y 銖 q5 ro] Town B Sosuku and ° 畦 Teizaki Chi ° - 2i: Image recording device 1; Shinko L /aS Uh, that's it. Figure 9 (?7 Figure 7)

Claims (1)

[Claims] An electronic device that controls an input device that inputs image information, an image forming device that forms an image on a medium according to the image information from the input device, and an image storage device that stores the input image from the input device. 2 created with the electronic device.
means for generating a command to transfer and register a value image to the image storage device; and control to combine the image stored in the image storage device and the registered binary image and output it from the image forming device. An electronic device comprising means for generating a command.