JPH034673A - Picture forming system - Google Patents

Abstract

PURPOSE:To form an image of a selected picture by reproducing plural pictures selected by a selection means in response to the command of image forming with the reproduction means sequentially, storing them and using the picture read by a storage means as a visual image. CONSTITUTION:When a start key of an operation section 20 of a color reader side is depressed, a registration request is given from the color reader 1 to a picture storage device 3. A track feed of an SV floppy of an SV reproduction device 31, that is, a track change to be reproduced is commanded so as to correspond to the index number designated by the picture storage device 3 and the picture information corresponding to the index number is stored in the memory. After the picture storage device 3 registers all the pictures corresponding to the set index number by the operation section 20, the device 3 sends the registration end message to the color reader 1. The color reader 1 sends the picture print area of each index number, that is, layout information to the picture storage device 3 to send a start request signal.

Description

[Detailed description of the invention]

[Industrial Application Field] The present invention reproduces images from a recording medium capable of recording a plurality of images.
The present invention relates to an image forming system that performs image formation. [Prior art] In recent years, images have been digitally read and the read digital
The desired processing is applied to the digital image signal, and the
Digital copiers that record using digital copy machines have become popular. In addition, the image information input to the digital copier is
This is an image input from the scanner section, such as a still video.
The ability to handle images from cameras, etc. is limited.
It was something. [Problem to be solved by the invention] In such a device, multiple screens of images recorded on a medium
In forming the selected image from the signal, -
Write the image signal to the memory and write it to the memory.
Select the desired image from the imported images and form the image.
It was necessary. Therefore, in such a device, it is necessary to store the image signal.
This requires a very large amount of memory.
As a result, a problem arose in that the configuration of the device became complicated. Ma
Even if you have a large amount of memory,
It is complicated to control the writing of all image memories.
becomes. The present invention has been made in view of these points, and is a simple
An image form that can image the image selected in the configuration.
The purpose is to provide a system for creating [Means for Solving the Problem] In order to achieve the above-mentioned object, the image forming system of the present invention
, play back images from a recording medium that can store multiple images.
a reproduction means, selecting a plurality of desired images from the plurality of images;
a selection means for storing the reproduced image from the reproduction means;
a storage means, a memory selected by the selection means in response to an instruction for image formation;
A plurality of images are sequentially reproduced by the reproduction means, and the previous image is
It is stored in the storage means and read out by the storage means.
and an image forming means for forming the image as a visible image.
. [Example] Hereinafter, an example of the present invention will be described using the drawings. Overall system configuration> Figure 1 shows a color image processing system according to an embodiment of the present invention.
1 is a system configuration diagram showing an example of a schematic internal configuration of a system;
As shown in Figure 1, this embodiment system has a digital
Digital color image reading device (hereinafter referred to as “digital color image reading device”) that reads color images.
1 (referred to as "color reader") and a digital sensor at the bottom.
Digital color image printing that prints out color images
Device (hereinafter referred to as "color printer") 2, image recording
storage device 3, Sv recording/playback device 31, monitor television 32, and
from the host computer 33 and film scanner 34.
configured. The color reader l of this embodiment includes a color separation means, which will be described later,
The reading source is
The color image information of the document is read by color and electronically digitalized.
This is a device that converts it into a digital image signal. The color printer 2 also outputs a digital image signal to be outputted.
Depending on the issue, color images are restricted by color and recorded on the recording paper.
Electronic data is transferred and recorded multiple times in the form of digital dots.
It is a photographic laser beam color printer. The image storage device 3 is a color reader l or a film ski
Digital images read from the scanner 34 and Sv recording/playback device 31
Quantizes the analog video signal from and converts it into a digital image.
This is a device that stores data after converting it. The Sv recording/playback device 31 takes pictures with the Sv camera and records them on the Sv flop.
Plays back the image information recorded on the DVD and converts the analog video
This is a device that outputs it as a number. In addition, the Sv recording/playback device 31
, by inputting an analog video signal in addition to the above
, Sv floppy disk. The monitor television 32 displays the images stored in the image storage device 3.
Image display and analog output from the Sv recording/playback device 31
This is a device that displays the contents of a video signal. The host computer 33 sends image information to the image storage device 3.
color images stored in the image storage device 3.
image of the reader 1, Sv recording/playback device, and film scanner 34.
It has the function of receiving image information. You can also control the color reader 1, color printer 2, etc.
conduct. The film scanner 34 accepts 35mm film (positive/negative).
g) The image on the film is converted into electricity using a photoelectric converter such as COD.
This is a device that converts color image information into vivid color image information. The details of each part will be explained below. Description of Color Reader I> First, the configuration of the color reader I will be explained. In the color reader l shown in Figure 1, 999 is the original, 4 is
The platen glass on which the original is placed, 5 is a halogen exposure run
Collects the reflected light image from the original that has been exposed and scanned by PIO
and a locker for inputting images to the same-size full-color sensor 6.
It is a front array lens. Rod array lens 5, 1x full color sensor 6,
The sensor output signal amplification circuit 7 and the halogen exposure lamp 10 are
This unit constitutes the original scanning unit 11, and the original 999
is exposed and scanned in the direction of the arrow (Al). Reading of manuscript 999
The image information to be acquired is obtained by exposing and scanning the document scanning unit 11.
By doing so, each line is sequentially read. read
The color separated image signals are processed by the sensor output signal amplification circuit 7.
After being amplified to a constant voltage, video processing is performed via signal line 501.
The signals are input to the processing unit, where they are processed. In addition,
The signal line 501 is coaxial to ensure faithful transmission of the signal.
It has a cable configuration. Signal 502 is a full-scale full-scale
This is a signal line that supplies drive pulses for the color sensor 6.
All necessary drive pulses are generated within the video processing unit 12
be done. 8.9 is the white level correction and black level correction of the image signal.
A white plate and a black plate for positive exposure, and halogen exposure lamps.
By irradiating with a pump lO
white level correction of video signal
. Used for black level correction. 13 is the color of this embodiment having a microcomputer.
It is a control unit that controls the entire reader 1.
, the display and keys on the operation panel 20 via the path 508.
- Human control, control of the video processing unit 12, etc.
I do. In addition, the position sensors Sl and S2 provide signals.
The position of the document scanning unit 11 via lines 509 and 510.
Detect location. Furthermore, the signal line 503 is used to move the scanning body 11.
Stepping motor 14 that drives the second stepping motor 14 in pulses
exposure of the driving motor drive circuit 15 via the signal line 504.
The lamp driver 21 sets the halogen exposure lamp 10 to zero.
N10FF control, light amount control, data via signal line 505
Color reader section l for controlling the digitizer 16 and display section, etc.
All controls are in place. In addition, 20 is the operation unit of the color league section 1, and the touch
Provides a liquid crystal display panel that also serves as a panel and various instructions.
Contains the key to download. In addition, the display on such display panel
Examples are shown in Figures 47 onwards. During original exposure scanning, the original scanning unit 11 described above
The color image signal read by the sensor output signal amplification diagram
°Road 7. Video processing unit 12 via signal line 501
is input. Next, referring to FIG.
The details of the video processing unit 12 will be explained. The color image signal input to the video processing unit 12 is
, G (green) is detected by the sample hold circuit S/H43.
Separated into 3 colors: B (Blue), R (Red)
. Each separated color image signal is processed by an A/D converter 44.
Analog/digital converted and digital color image signal
becomes. In this embodiment, the color reading section in the document scanning unit 11 is
The sensor 6 has a staggered pattern divided into five areas as shown in Figure 2.
It is structured like this. This color reading sensor 6 and misalignment
2nd and 4th channels that are pre-scanned using the correction circuit 45
and the remaining l, 3. 5 channel reading position
This is corrected. The positional deviation from the deviation correction circuit 45
The corrected signal is input to the black correction circuit/white correction circuit 46.
According to the reflected light from the white plate 8 and black plate 9 mentioned above,
The signal is used to detect unevenness in the color reading sensor 6 during dark hours and
Uneven light intensity of the rogen exposure lamp 10, variations in sensor sensitivity
Key etc. are corrected. Color image proportional to the input light amount of the color reading sensor 6
Data is input to video interface 201 and the
It is connected to the image storage device 3. This video interface 201 is shown in FIGS. 3 to 6.
It has the functions shown below. That is, (1) black correction/
A signal 559 from the white correction circuit 46 is output to the image storage device 3.
(Fig. 3); (2) image storage device 3;
Function to input image information 563 to selector 119 (Fig. 4)
) (3) Image information 562 from the synthesis circuit 115 is stored as an image
Function to output to device 3 (Fig. 5) (4) Binarized information 206 from image storage device 3 is synthesized
(5) Control 5 between the image storage device 3 and the color reader 1
I: /207 (H8YNC, VSYNC, image enable
communication line 56 between the CPU and the CPU
1 connection. In particular, the CPU communication line
It is connected to the communication controller 162 in the port 13, and
Exchanging commands and area information. It has five functions. The selection of these five functions is CP
As shown in FIGS. 3-6 by the U control line 508.
Switch to . As explained above, the video interface 201
, has five functions, and its signal lines 205°, 206 .
207 is capable of bidirectional transmission. This configuration enables bidirectional transmission, and the signal line
Reduce the number of cables, make the cables thinner, and reduce the cost.
Rukoto can. Also, the input of the image storage device 3 connected to the color reader l
interface connector (4550 in Figure 27(A))
Bidirectional transmission is also possible on the signal line. Therefore, the connection line between each device that makes up the system
can reduce the number of people and even have a high degree of communication with each other.
can be done. Further, the image information 559 from the black correction/white correction circuit 46 is
, performs processing to match the specific luminosity characteristics of the human eye.
It is input to a logarithmic conversion circuit 48 (FIG. 2). Here, white = OOH and black = FFH are converted as much as possible.
, and an image source input to the image reading sensor,
For example, a normal reflective original and a film projector, etc.
Transparent originals, and even the same transparent originals, can be used with negative film or positive film.
The film or the film sensitivity, the input gas at the exposure condition.
Figure 7 (a), (b)
) as shown in (, LUT (Looker) for logarithmic transformation.
It has multiple top tables, which can be used depending on the purpose. Switching is done using signal line I! go, fgl, I! to g2
The operation unit is operated as the I10 port of the CPU 22.
This is done by inputting instructions from etc. Here, each B, G,
The data output for R is the density value of the output image.
B (Blue), G (Green), R (Regular)
yellow and magenta respectively for each signal of
. Since it corresponds to the amount of cyan toner, color images from this point onwards will be
The image data is associated with Y, M, and C. Note that the color conversion circuit 47 converts input color image data into
Detects a specific color from R, B, and G and replaces it with another color
This is the circuit. For example, you can change the red part of the document to blue.
This realizes the function of converting to any other color. Next, each color from the original image obtained by logarithmic transformation 48
Component image data, i.e. yellow component. For magenta and cyan components, the color correction circuit 49
Perform color correction as described below. color reading sensor
Spectral characteristics of color separation filters placed for each pixel in
As shown in Fig. 8, there is an unnecessary transparent area like the shaded area.
On the other hand, for example, color toner (
Y, M, C) also have unnecessary absorption components as shown in Figure 9.
It is well known that In addition, in the figure, R
, G, Y, and M are shown. Therefore, for each color component image data Yi, Mi, Ci,
Masking correction that performs color correction by calculating the linear equation for each color.
Yes (known. Furthermore, Yi, Mi, C4
From, Min (Yi, Mi, Ci) (Yi,
The minimum value of Mi, Ci) is calculated, and this is sumi (minimum value of Mi, Ci).
black) and then add black toner (smearing).
, an undercolor that reduces the amount of each coloring material added according to the added black component.
The removal (OCR) operation is also successfully performed.
, a color correction circuit 49 that performs masking, smearing, and UCR.
The circuit configuration is shown below. The characteristics of this configuration are: ■ It has two masking matrices, and one signal line.
High-speed switching is possible with “Ilo” ■With and without UCR, one signal line “110” allows high-speed switching.
■Equipped with two circuits that determine the amount of smear, and "Ilo" can be switched quickly.
The advantage is that it can be switched quickly. First, prior to image reading, the desired first matrix
Number M0. Connect the second matrix coefficient M2 to the CPU 22
Set from the specified bus. In this example, M1 is
Set M2 to registers 50 to 52, and registers 53 to 55.
has been done. In addition, 56 to 62 are selectors, respectively, and the S terminal
- Select A when "1", select B when "O". follow
When selecting matrix M1, the switching signal MAR
When selecting matrix M2 for EA566="1"
In this case, the result is “O”. Further, 63 is a selector, and a selection signal C0°CI(
567, 568) based on the truth table in Figure 10(b).
Then outputs a, b, and c are obtained. selection signal CG
+ CI and C2 correspond to the color signal to be output
For example, in the order of Y, M, C, Bk (C2°CI + c
o) = (0,0,0), (0,0,1),
(0゜i, o), (1,0,0), and more monochrome
By setting (0, 1, 1) as a signal, the desired color can be obtained.
Obtain a corrected color signal. In addition, CG + C1w C
2 is C depending on the image forming sequence of the color printer 2.
PU22 occurs. Now, (co * Ct + C
2) = (Os0.0), and MAREA566=
When set to '1', the output of the selector 63 (at b,
c) includes registers 50a, 50b, and 50c.
Therefore, (ayt, -bMt. -CCI) is output. On the other hand, input signals Yi, M
i. Min from Ci (Yi, Mi, Ci) ==
The black component signal 570 calculated as Y=
It undergoes the -order transformation ax-b (a. b is a constant), and then passes through the selector 60.
ri) Input to B input of subtractors 65a, 65b, 65c
be done. Each subtractor 65a, b, c performs undercolor removal.
Y = Y i −(ak − b ),
M = M i - (ak - b). C=C1-(ak-b) is calculated, and the signal line 571a. 571b, 571c for masking operations
are input to multipliers 66a, 66b, 66c of
. Selector 60 is controlled by signal UAREA572.
UAREA572 has UCR (undercolor removal),
The configuration allows for high-speed switching between “No” and “Ilo”.
ing. The multipliers 66a, 66b, and 66c each have an A input.
is (ays, -bMl, -CC1), B input
Niha mentioned above (Yi-(ak-b), Mi-(ak-b
), Ci − (ak − b)) = (Yi, Mi,
It is clear from the figure that Ci) is input.
Then, the condition of C2=0 (Y or M
or C selection) and Yout=Yix (aYl) +M
ix (-bMl) +Cix (-cal) is obtained.
, masking color correction, and yellow with undercolor removal processing.
- Image data can be obtained. Similarly, Mout=YiX(-aY2)+MiX(bM2)+C
1X(-CC2)Cout==YiX(-aY3)+M
iX(-bM3)+C1X(cca) output to Dout
be done. Color selection is based on the output to the color printer.
(Co, Ci. C2) to the CPU 22 according to the table in Figure 1(b)
More controlled. Registers 67a, b, c, 6
8a. b and c are registers for monochrome image formation, as described above.
Based on the same principle as masking color correction, MONO=k
HYi+ f I Mi+m I Ci for each color
Weighting is obtained by addition. Switching signal MAREA566, UAREA572°K
AREA573 is a masking color correction as mentioned above.
Fast switching of coefficient matrices M and M2, UAREA
572 is high-speed switching with and without UCR, KARE
A573 is the black component signal (signal line 574 → selector 6
1 and output to Dout), the primary conversion switching, all
That is, K = M i (Y i , M i
. Ci), Y=ck-d or Y=ek-f (c
. d, e, f are constant parameters).
This is a signal that changes the area, for example -
You can change the king coefficient or change the UCR amount or the amount of smear.
The configuration is such that it is possible to switch between regions.
Ru. Therefore, it is possible to obtain images from image input sources with different color separation characteristics.
images with different black tones, or multiple images with different black tones.
As in the embodiment (this is a configuration that can be applied in the case of combining). Note that these area signals MAREA, UAREA, KAR
EA (566°572, 573) is the region generation described later.
It is generated by the circuit (69 in FIG. 2). Next, we will focus on reproducing black characters and thin lines in the original, and
Black text processing that improves color bleeding at the edges of text and black lines
The logic circuit will be explained according to Figures 11 and 12.
Ru. The black level/white correction circuit 46 shown in FIG.
R, G, B (red, green, blue) color signals 559R, 559G with white level correction. 559B is LOG conversion 48, masking, under color removal 49
After receiving the color signal, the color signal to be output to the printer is selected.
, is output to signal line 565. In parallel with this, the signal R
, G, and B are the achromatic parts of the manuscript and the edges.
In order to detect the part that is a black character (that is, the part that is a black thin line), the luminance signal Y1 color is detected.
Difference signal 1. Q by Y, I, Q calculation circuit 70
Calculate (Figure 11). The luminance signal Y575 is often used to extract edge signals.
A known digital second-order differential circuit 72 with a 5x5 matrix
Calculate the risk (, line buffer circuit for 5 lines 7
1, and as described above (, Laplace calculation is performed in the arithmetic circuit 72).
An operation is performed. In other words, the input luminance signal Y is
Step-like input (e.g. i) in Figure 12(d)
character part), the output 576 after Laplacian is the same.
(hereinafter referred to as an edge signal). le
Backup tables LUTA73a and LUTB73b are
Printing amount at the edges of black characters (or thin black lines)
For example, a lookup table for determining toner IIk).
as shown in Figures 12(a) and (b), respectively.
It consists of a lookup table with certain characteristics.
. In other words, LUTA acts on the edge signal 576.
Then, the amplitude becomes large as shown in Figure 12(d)(iii).
As will be explained later, this is due to the black edge part
– Determine the amount. In addition, LUTB is added to the edge signal 576.
When the effect occurs, the absolute value appears as negative, which is the black edge.
Y, M, C (yellow magenta, cyan) toner
Determine the amount. This is as shown in Figure 12 (d) (iV).
It is a signal that passes through a smoothing (averaging) circuit 74.
This results in a signal as shown in (V) in the same figure. On the other hand, the achromatic color detection circuit 75 outputs a completely achromatic color, for example.
Force = 1. For chromatic colors, for example, the 12th
This is a circuit that outputs a signal according to the characteristics shown in the figure.
The signal is based on signal 577 which becomes "1" when printing black toner.
When printing black toner, it is selected by the selector 76 and the signal 5 is selected.
78 and before the multiplier 77 determines the amount of black toner.
The above signal 579 (Fig. 12(d)(iii)) and the multiplication are
After that, the adder 78 adds it to the original image signal. On the other hand, Y, M, C (yellow, magenta, cyan) toner
-When printing, mark Y, M, and C on black characters and black lines.
Since it is desirable that toner not be printed,
The color selection signal 577 causes the selector 76 to select “l”.
It is output to the multiplier, and from the selector 79 it is output to the LUTB 73.
The signal obtained by smoothing the output from 6 (Fig. 12(d)
(V)) is output, and the adder 78 outputs (V) (
The same signal as V) is input, and the black edge part is detected from the original signal.
The signal is reduced only when In other words, what this means is that the black edge is
The signal that determines the amount of black toner is strong (that is, increases the amount of black toner).
and reduce the amount of Y, M, and C toner for the same part.
By making the black part darker,
be. Signal obtained by binarizing the achromatic color signal 580 by the binarizing circuit 80b
581 is “1” for achromatic color and “0” for chromatic color.
. That is, as mentioned above, in the selector 79
When printing with black toner (when 577 = "l") S input = "l"
, input to 579 (Fig. 12(d)(i
ii)) is output and the black edges are emphasized. Y, M,
C) When printing a car (when 577 = 'O'), signal 581
="1", so if it is an achromatic color, <Y, M,
Reduce the amount of toner in C (S input is selected, Fig. 12).
(d) (v) is output, but if it is a chromatic color, the signal 5
81=0, therefore polishing=1, that is, selector 79
The S input of becomes 1 and A is selected, and as shown in Fig. 12(d) (
The signal iii) is output to the adder 78 and
It becomes a known edge emphasis. LUTA73a has <, edge as shown in Figure 12(a).
A LUT that is zero when the signal value is less than ±n and ±
There are two types of LUTs that are zero below n.
, the level of the original signal 565, that is, the original signal at this time.
Select the value to clamp to zero depending on the density of the document.
It has become. The density level of the original is set by the CPU 22.
When larger than the value set via 508, i.e., dark
In this case, the output of the comparator 81 becomes “l”, and the 12th
The LUT clamped to zero at A'B' in figure (a) is
, and below a certain concentration, that is, when the comparator 81
When output = '0'', L is clamped to zero at A and B.
Noise removal according to concentration range by selecting UT
changing the effect of Furthermore, the output 583 of the AND gate 82 is
Further improvements have been made to the surrounding area, and the black text is
584 (B
input), otherwise switch to select 585.
It's a signal. Signal 58 input to AND gate 584
6 is the LUTC (Fig. 12 (C)) for the edge signal mentioned above.
The signal on which the characteristics of are applied is binarized by the binarization circuit 80a.
In other words, the absolute value of the edge signal is
When the value is greater than or equal to the value, it is "1", and when it is less than the value, it is "0". Therefore, 5
87 = “l” 581 = “l”, 588 = 'L'
is achromatic, and when the edge signal is large, that is, the black signal is
At the edge of the issue, and when printing with Y, M, and C toners
Only. Therefore, at this time, as explained earlier,
Only the parts corresponding to the black edges from the original signal are Y and M. The signal that determines the amount of toner in C is reduced, and the remaining
The averaging circuit 84 smoothes the signal.
, when the signal ER="l" passes through the selector 83 and goes to 589.
Output. At other times, the edges were emphasized normally.
Signal 585 is output at output 589. The signal ER is controlled by the CPU 22, and the signal ER is
When the output of the averaging circuit 84 is the output 589, ER=aO
”, “0” is output to output 589. This is black
Complete the color toner (Y, M, C) signals around the edges of the characters.
To further eliminate the color bleeding, these
has a selectable configuration. FIG. 13 shows area signal generation (
The aforementioned MAREA566, UAREA572. KARE
A573, etc.). What is a region?Example
For example, it refers to the shaded area in Figure 13(e).
In other words, for each line in the sub-scanning direction, HS
Timing chart AR in Figure 13(e) for each YNC
It is distinguished from other areas by a signal such as EA. Note that such an area is specified by, for example, the digitizer 16, etc.
Ru. FIGS. 13(a) to 13(d) show the generation position 1 of this area signal.
Section length 2 The number of sections is programmable by the CPU 22
, and shows a configuration that can be obtained in large numbers. In this configuration
In this case, one area signal is a CPU-accessible RAM area signal.
For example, n area signals A R
n bits to obtain E A O-A RE A n
It has two RAMs for the configuration (Fig. 13(d) 85
A, 85B). Now, the area signal AREAO as shown in FIG. 13(b). and AREAn, the RAM address X
Set “B” to bit 0 of I*x3 and read the remaining address.
Set all bits 0 to “0”. On the other hand, the RAM address
sL xl l X2 r Put “l” on 14
Then, all bits n of other addresses are set to "0". H.S.
The RAM is synchronized with a constant clock using YNC as a reference.
For example, if you read out data sequentially,
For example, as shown in Fig. 13(C), the ζ address X and the point x3
Data “1” is read out. This read data
13(d) 86-0 to 86-n J-.
J of flop. Since it is connected to both K terminals, the output is a toggle operation, that is,
Then, '1' is read from the RAM and CLK is input.
Then, the output changes from “0” to “l”, “bi” to “0”, and A
Interval signals such as REAO and therefore area signals are generated.
Ru. Also, if data = “0” across all addresses
, no area section is generated and no area is set. Figure 13(d) shows this circuit configuration, and 85A and 85B are
This is the RAM mentioned above. This cuts the region interval quickly.
For example, data is transferred from RAMA35A every time.
While reading for each input,
On the other hand, memory for different area settings than the CPU 22
As a write operation is performed, interval generation and C
Switch memory writing from PU. Therefore, the first
If you specify the shaded area in Figure 3 <1>, A-B→A→B
→ RAMA and RAMB are switched as shown in A, and this
In FIG. 13(d), (C3, C4, C3)=
(0°l, 0), the number counted by vCLK is
The counter output is passed through selector 87A as an address.
Given to RAMA35A (Aa), gate 88A opens,
Gate 88B is closed and data is read from RAM 35A.
, total bit width, n bits to J- flip-flop 86
-0 to 86-n and AR according to the set value.
Interval signals EAO to AREAn are generated. During this time, writing from the CPU to B is via address bus A-
Bus, data bus D-Bus, and access signal R
/W is used. Conversely, the data set in RAMA35A
When generating interval signals based on data (c3.c4.
By setting c, ) = (i, o, t), the line
Eh, writing data from the CPU to RAM35A
I can do it. Therefore, for example, an image can be cut out based on this area signal.
Easily perform image processing such as trimming) and removing borders.
be able to. That is, in FIG.
As described above (the area signal 590 generated is I10
Area switching signal ECH591 output from port 25
is selected by the selector 89, and the AND gate 9
0 input. This is clear from the figure
, for example, in FIG. 13(b), signal 59 like AREAO
If 0 is formed, the image between Xl and X3 will be cut out.
If you form it like AREAn, then from X to
The frame between 2 and 2 is missing, l to XI+ x2 to X4
It is easy to understand that the image is cut out in the section up to
will be done. Figures 14 and 15 are bitmaps for area restriction masks.
It shows the configuration and control timing of the memory 91.
Ru. As can be understood from Figure 2, for example, the color change described below
The detection output 592 of the conversion circuit detects a specific color area in the document.
You can create an area restriction mask that limits the area only to
Video image signal 56 input from external image storage device 3
0, the signal 59 is binarized by the binarization circuit 92.
3, the area corresponding to the density value (or signal level) is
You can create area control masks. Figure 14(a) shows the bit map for area restriction mask.
FIG. 2 is a block diagram showing details of Molly 91 and its control.
Ru. The mask consists of one block of 4x4 pixels as shown in Figure 15.
1 bit of bitmap memory is stored in 1 block.
For example, 16 p
For an image with a pixel density of e l / m m, 297
For mm x 420 mm (A3 size)
So, (297X420X16X16)÷16=2Mb
it. That is, for example, IMBit's dynamic R
A.M. It can be configured with 2 chips. The signal input to the selector 93 in FIG. 14(a)
Nos. 592 and 593 are as described above (for mask generation).
A data input line, for example, by switching line 594.
When the output 593 of the binarization circuit 92 in FIG. 2 is selected,
First, to count the number of “1”s in a 4×4 block,
, 1 bit x 4 line buffers 94A, 94B, 9
It is input to 4C and 94D. FIFO94A~94D
, as shown in the figure, the output of 94A is connected to the input of 94B, and the output of 94B is connected to the input of 94B.
The output is connected to the input of 94C, and so on, and each FI
The output of FO is 4 bits parallel to latches 95A to 95C.
latched by vCLK (timing in Figure 14(d))
(see chart). FIFO output 595A and latch 95A, 95
B. Each output 595B, 595C, 595D of 95C is
Added by adders 96A, 96B, and 96C (signal 5
96), by the CPU 22 in the comparator 97,
The value set via I10 port 25 (for example, “1
2”) and its size is compared. That is, here, 4
Check whether the number of 1s in the block of ×4 is greater than the specified number.
judge. In FIG. 14(d), the number of “1”s in block N is
“14”, the number of 1s in block (N+1) is 4″
, the output 597 of the comparator 97 in FIG. 14(a)
When the signal 597 is "14", it is 'l' When it is "4"
“0#, therefore, the latch pulse in FIG. 14(d)
598, once per 4x4 block with latch 98
The Q output of the latch 98 is the DIN of the memory 99.
This becomes input, that is, mask creation data. 100H is
H address that generates the address in the main scanning direction of the mask memory
It is a response counter, and one address is a 4x4 block.
Since the pixel clock VCLK is assigned to frequency divider 1
Counting up is done using a clock divided by 4 at 01H.
. Similarly, 1OOv is the address of the mask memory in the sub-scanning direction.
It is an address counter that generates responses, and for the same reason
Synchronous signal H3YNC of each line by branching unit 101V
is counted up by the clock divided by 4, and the H address is counted up.
■Address operation is based on “l” in 4x4 block.
Controlled to synchronize with counting (addition) operation. Also, ■lower 2 bits output of address counter, 599
, 600 is NOR'd by NOR gate 102, and 4 minutes
The signal 602 that gates the clock 601 is
, the first timing chart is set by the AND gate 103.
As shown in Figure 4 (C), there is only one latch per 4x4 block.
The latch signal 598 and
, 603 are the devices included in the CPU bus 508 (Fig. 2).
604 is also an address bus,
Signal 605 is write pulse WR from CPU 22
. WR (write) operation from CPU 22 to memory 99
At this time, the light pulse becomes "Lo" and the gate 104,
105 and 106 are opened, and the address bus from the CPU 22
, a data bus is connected to the memory 99, and randomly predetermined
data is written, and the H address counter,
Sequential WR (write) by the dress counter.
), when performing RD read, connect to I10 boat 25
gate 107. Game by control line of 108)1
07,108 will open and the sequential address will be memorized.
99. For example, the output 593 of the binarized output 92 or the color conversion
16th output 592 or the CPU 22
Once the mask as shown in the figure is formed, the area within the bold line frame will be used as the base.
You can cut out images, combine them, etc. Next, the mask created in 4x4 pixel block units is
As shown in (i) of Fig. 17(b), the edge part (boundary part)
, the interpolation shown in Figure 2 results in jaggedness in units of 4 pixels.
By using circuit 109, the jagged parts are smoothed and the appearance is improved.
Makes it smooth on the eyes. FIG. 17(a) shows a block diagram of the interpolation circuit. 110 is
It is a selector, and the A input is a Hi clamp, that is,
If it is 8 bits, FFH is connected to the B input, and GND is connected to the B input.
In other words, 00H is input, and the bitmap map mentioned above is
Switch between them using the output 606 of the screen memory.
. As a result, the input of the interpolation circuit 111 includes a region mask.
FF□ is output for the inside, and 00H is output for the area mask. child
This is as shown in (i) of FIG. 17(b). interpolation times
The path 111 is, for example, a one-fire interval method, a high-order interpolation method, a 5-inch
Any circuit, such as interpolation method, may be used, and the circuit configuration must be well-known.
All you have to do is apply what you learned. The output of the interpolation circuit is multivalued.
Since the input signal is input, the binarization circuit 112 binarizes the signal. to this
Therefore, as shown in (ii) of FIG. 17(b),
For the original boundary A, change the smoothness of the boundary to
I'm trying to secure it. Selector 113 is a mask memo
Either output Lee's output as is (select A), or use the above
Select a mask signal with smooth boundaries after interpolation like
Connected to I10 port of CPU22 to output
A switching signal 608 is used to switch as necessary.
I can do it. Therefore, for example, by selecting the interpolation output with the signal 608,
Furthermore, selector 89 in Fig. 2 outputs the area restriction mask.
Must be selected (when switching ECH, AND gate 90
Therefore, as shown in Figure 18(a), a non-rectangular diagram is created using a mask.
It is possible to cut out shapes. Also, bitmap memory
91 mask memory output from the signal line 607 in FIG.
Take it out and select it with the selector 114, which will be described later.
When synthesized by the synthesis circuit 115, the result is as shown in FIG. 18(b).
It becomes. 116 in FIG. 2 is a density conversion circuit, for example, in FIG.
It became possible to change the density and gradation of each color, as in
It is composed of LUT (lookup table), etc.
Ru. 118 is a repeat circuit (F
Consists of IFO. 609 is H shown in the same figure (b)
3YNC, Lo pulse is applied once per line.
WR (write) inside the FIFO
Initialize a pointer (not shown). 611 is the input image
data, 612 is output image data, Repeat
Signal 6 initializes the FIFO RD (read) pointer
This is a signal to Therefore, the timing of FIG. 20(b)
As per the chart, write sequentially to FIFO
The received data 1-10 are as shown in the figure (Repeat signal 6
By inputting 16, →l→2→3→4→l
→2→3→1→2→3” (reading is performed repeatedly.
. In other words, Repeat
By applying the signal 616 to the FIFO, the result shown in FIG.
It is possible to repeat the same image repeatedly. subordinate
So, in the memory for forming the bitmap mask area mentioned above,
As shown in Figure 21 (A) (write and read data “l”)
By compositing with the compositing circuit 115 in FIG.
, a dotted line (cut line) is formed. The image is as described above (repeated by the repeat circuit 118).
The t signal is generated at points ■ and ■ in Figure 21 (A).
If controlled by the area generation circuit 69, it can be applied to repeated images.
Figure 21 (B)
By writing the data of “B”, the tangent becomes (C
) (By writing, you can shape the black lines (
It becomes possible to accomplish this. (Output from repeat circuit 118
The resulting image signal 612 is input to the image synthesis circuit 115 and each
Seed image processing is performed. Next, synthesize using Figure 25 (A-1), although the figure numbers are different.
The details of the circuit will be explained. The editing process performed here is performed independently for each specified area.
Set in RAM135, 136 shown in Figure (A-1)
Programmable based on data. i.e.
, which will be described in detail later, is obtained from the area code generator 130.
Each code number (hereinafter referred to as area code)
It is processed. Digitizer 1 is used to specify the above areas and specify various editing processes.
6. Instructions obtained from the operation unit 20 and image storage device 3
(command) through the CPU to the CPU bus 508.
Area code generator 130 and R in Figure 25 (A-1)
Editing to AM135.136 and registers 140 to 142
Parameters corresponding to the process are set. Also, in Figure 25 (A-1), 132 is the area code
Generation circuit 130. Set any output of register 131.
Selector to select. In addition, 130 is a synchronization signal HSYN
Area code is automatically generated according to C and CLK.
area code generator, register 131 is connected to CPU bus 5.
This is a register into which the signal from 08 is input. 135,1
36 is an area code and the processing or processing corresponding to the area code.
or image data is stored as a table.
It is AM. In addition, the table of RAM135.136
For details, enter the input address as shown in Figure 25 (F).
The code input via selector 132 as a
and the printer indicates the formed color during surface-sequential image formation.
The code co, C8 is given, and the output is 3 bits.
It has a default function code and 8-bit data. Furthermore, this
The 3-bit function code is decoded via selector 137.
146. Such function codes will be described later.
for example text add-ons or specific image areas.
This is an 8-bit code for giving instructions such as masking.
The data is, for example, density adjustment data of the image signal 612.
It is ta. 139°143.145 are the decoder outputs respectively.
Force SO, Sl, S2°S3. Select according to S4
144 is a selector that changes the state.
143. This is a multiplier that multiplies the outputs of 145. 1
46 is a 6-bit data input via the selector 132.
The most significant bit MSB of the data is 621 (the MSB is
At the edge of each area of the image, as shown in Figure 25 (E),
from the area code generator 130 so that it becomes “1”.
), the second illustrated signal 613 . Indicated by 614
input via the character signal and selector 137
This is a decoder that decodes three function codes. Next, the above-mentioned area code will be explained. Eli
Accord is, for example, a document 147 as shown in Figure 25 (B).
Area 148 is specified using digitizer 16 etc.
When assigning a number or area code to each area.
This is a means of distinguishing each area. In this example, the original
The entire area of the manuscript is set to area code “0” as shown in Figure 25 (B).
Now, let's take a rectangular area with points a and b as diagonals, for example.
Rectangular area with rear code “l”, points c and d as diagonals
A is set as the area code "2". here
For example, when scanning the A-B section shown in the figure,
At the same time, the area code will be issued at the timing shown in the figure below.
I'm keeping it alive. The same applies to the CD and EF sections. this
In this method, an area code is generated at the same time as the document is scanned.
Distinguish areas using area codes and check areas in real time
Different image processing and editing are realized for each. The above settings are made using the digitizer 16 and operation as described above.
Part 20 has been doing this since. The number of areas that can be set is
Depends on the number of bits in the code, for example, do not set it to n bits.
It is possible to set up 21 areas. Next, Fig. 25(C) shows Fig. 25(A-1) 130.
1 shows an example of a schematic internal configuration diagram of an area code generation circuit. This generation circuit 130 converts the above-mentioned area code into the document.
A circuit that generates data in real time simultaneously with operation.
The coordinates of the area obtained by area specifying means such as a digitizer
By setting the area code and
area code. below
The details are explained below. RAM153 and 154 each have a 7-bit word configuration.
This memory has a capacity for one main scanning line. This RAM has CPU address bus 627, data bus 6
25, it is connected to the CPU. 149 is address card
To count Video CLK at counter
A RAM address is generated. Count again
Data 149 has been reset by HSYNC and the new
Selector 151 selects the same address every time a new line is scanned.
, 152 to the RAMs 153 and 154. Okay
RAM 153, 154 stores data in response to a reset.
I am trying to read it from the start. 156 is an interrupt generator that connects the CPU data bus 625 and
and chip select 624 in advance from the CPU.
Count HSYNC input by programmed number
When this occurs, an interrupt signal INT is generated to the CPU.
By toggling the flip-flop 158 to J-,
The RAM read by the address counter 149 is also
Switching. 151.152゜156 is selector
By the output of the flip-flop 158, the A and B inputs are
RAM153,154 by selecting one
Either one is selected. FIG. 25(D) shows the RAM 153. 154 data structures
FIG. M S B 1 b as shown
The MSB is divided into i t and the lower 6 bits, and the MSB is
represents the change point between the specified area and the unspecified area.
However, the lower 6 bits can store changing area codes.
Ru. The RAM address corresponds to the Y coordinate, which is the main scanning direction.
are doing. Figure 25 (D) is shown in Figure 25 (E), for example.
Specified area 159 (area code '20) on original document 150
''') represents the RAM data when scanning between A-8.
are doing. At this time, the entire area of the document has an area code of '0'.
``”.The area set in reverse is the area code “”.
This is an example when the setting is 20".The RAM with the above settings is
FIG. 25(C) Generated from address counter 149
RAM153, 154 sequentially from the address
is read and an area code is generated. For example,
When scanning the section shown in Figure 25 (E) A-H, the scan opening
Immediately after the start, the RAM output and L [MSB “l” lower 6 bits
"o" (area code "0") is read out, and the 25th
As shown in figure (C), MSB627 is used as a latch signal.
The lower 6 bits are latched by the latch 157 and the area
Code “0” is output. It also reaches point a(0,P)
MSB 'l''', lower 6
The bit “20” is read out and is latched as above.
Rear code "20" is output. The address continues to advance.
The area code “20” continues until the next MSB becomes l”.
Output. That is, address r is read and
area code until the data is newly latched.
'20'' continues to be output from the latch 157. The scanning progresses further, and when the main scanning in the Y direction is completed, the
HSYNC advances one step in the direction by the interrupt generator 155.
will be counted. At this time, as mentioned above, the address counter
The controller 149 is reset and the read address is also reset.
and starts from 0. Also, since the area is rectangular
Figure 25 (E) When the scanning of section C-D including point b is completed.
The same data, that is, RAM153. 154 years
One of the RAMs continues to be read out.
The counter of H3YNC in the X direction is input to the interrupt generator 155.
If you set the number of points, in this example (q-o), the interval
It is divided when scanning from A-B to section C-D is completed.
Interrupt generator 155 generates an interrupt signal INT and simultaneously
In FIG. 25(C) J-, the flip-flop 158 is
R read out by the selector 156 by the group operation
AM switches. This allows you to pre-program
The next area information is selected by the selector 156.
The data is output from the RAM. Also, the occurrence of interrupt INT
This allows the CPU to use the area obtained by the above-mentioned means.
From the coordinates and area code, an interrupt generator 155;
In addition, the idle RAM, that is, the selector 156
The unselected RAM is filled with a new and different specified area.
Set the signal. Such a set receives data from the CPU.
bus 625, and chip select signals C2 and C3.
done by control. The configuration described above, i.e. two
The remaining RAM is switched sequentially, and the idle RAM is used by the CPU.
By reprogramming documents, you can write documents with less memory capacity.
Area code 626 can be generated for the entire screen. As mentioned above, the area code shown in Figure 25 (A-1)
The area code 626 output from the generation circuit 130 is
It is input to the rectifier 132 together with the image signal, and the area
Editing is performed for each area based on the code. The area code generator 130 generates an error code only for rectangular areas.
Accord could be generated, but in this example, a non-rectangular area
It is designed to be able to handle the area. Such a configuration
131 and 132 are provided. 131 shown in Figure 25 (A-1) is a register and the CPU
It is connected to bus 508. In this register in advance
Set the area code corresponding to the non-rectangular area (. At this time, as will be described later, the area code corresponding to the non-rectangular area
When the signal 615 is input, the signal 615 is selected.
The signal is set in the register 131 by the selector 132.
The specified value is selected and corresponds to the non-rectangular area signal.
You can now obtain a non-rectangular area code. As mentioned above, the area code is 6 bits in this embodiment.
Yes, MSB621 1bit is decoder 146 and
and selector 137, and other signals are input to RAM 13.
5.136 is input in parallel. The RAMs 135 and 136 are connected to the CPU bus (data bus 62
5. CP by 508 (generally refers to address bus 627)
It is connected to U and has a programmable configuration. FIG. 25(F) shows RAM 135. 136 data structures
shows. 133 is a schematic diagram of the RAM configuration, with address input and
area code 4 bits and color select signal 6
29.2 bits, a total of 6 bits, are input. At this time, color select signal C8+ CI+ C2
File sequential by using 2bit CG + CI from LSB
Which of the four color signals is the image signal sent by
Select and thereby access by area code and color.
You are changing the address you are using. In this embodiment, as will be described later, the printer 2 does not form an image.
M (magenta), C (cyan), Y (yellow) for each color
, Bk (black) images are transferred in sequential order. child
, the type of color to be transferred is shown in Figure 25 (A).
-Select 629 signals C0, C. (This is the same signal as C0 and C shown in Figure 10(a))
This is done by Data in 134 of Figure 25 (F)
A detailed structural drawing is shown. As shown in the figure, the 3 bits start from the MSB.
function code, and by decoding this code,
, perform different image processing according to the code.
ing. In this example, the function code is represented by 3 bits.
by area code or color by
Six types of image editing are possible. The lower 8 bits are
Stores various parameters during image processing and editing according to the function code.
I have paid. Selected from area code and color select signal
The data is 3 bits starting from the MSB, that is, the function code is the second
Input to the selector 137 shown in FIG. 5 (A) 137,
Two RAs with area code MSB 621
Switch the 3-bit function code output from M.
There is. On the other hand, the lower 8 bits of data are also sent to the decoder 146.
Selected by selector 139 by select signal Sl from
and output. The function code selected above is input to the decoder 146.
character signal 622, and area code M S B b
i t621 to perform editing processing.
A control signal 623 is generated for this purpose. Each control signal
Used as a selector signal to change the signal flow
Edited by. In this embodiment, the control signal
This realizes the six editing functions described below. ■In-area through Specified area is output without performing any processing on the image signal.
This is a function to The input image signal is the one shown in 138.
Passes through the Gaposi inversion circuit (described later) and is selected by S2.
is selectively outputted from the filter 143 and inputted to the multiplier 144.
. On the other hand, RAM data is transferred to selector 139 by Sl.
One of them is selected, and then in S3. determined by S4
is passed through the selector 145, and by the multiplier 144.
The image signal is calculated and output. At this time, the multiplier 14
The density of the image is determined from the RAM data input in step 4.
, and set a different count for each color that is sent in field sequential order.
Once set, the density and color balance can be changed independently for each area.
It is possible. In other words, if the user sets the area using the operation panel.
Later, when you set the color balance for the area, the CPU will
The setting values are stored in the RAM 135 or R via the bus 508.
Write to AM136. Furthermore, the B input of the selector 145
The force is selected and multiplied by image signal 612 and multiplier 144.
All you have to do is calculate. ■Intra-area masking: Paint uniformly with any other color over the entire specified area.
This is a function that outputs a crushed image. For example, when scanning a certain area with this function set, S2
The RAM data is selected instead of the image signal and multiplied by
It is input to the calculator 144. On the other hand, the coefficient is the control signal S3.
Select register 142 from S4, although not shown.
It is connected to the CPU by a bus, and from the CPU in advance.
Store an appropriate coefficient, for example 1'' (in the multiplier 144).
is calculated and output. ■Insertion of characters within the area (1) For example, as shown in Figure 25 (G), the specified area of the image
Mode to insert characters like 160 into 159
It is. For example, as shown in 161 in advance,
Store character data in a memory, etc. (specified area
The binary value of the character is scanned at the same time as the timing shown in the figure.
Data is scanned and read from memory and character signal 6
22. This signal is expressed by the sentence shown in Fig. 25 (A) 622.
Input as a character signal and switch selector 143
. That is, when the character signal 622 is High, the select
The controller 143 stores data in the RAM 135 or 136.
5o that selects the image signal and selects the image signal when it is Low.
- The decoder 146 performs insertion by outputting S4.
ing. In addition to the above character signal, 83. S4
also changes, and the coefficient of the multiplier 144 becomes high when the character signal 622
At h, register 140 is selected. This was also mentioned earlier
Similar to the above, it is connected to the CPU bus and has been configured in advance.
Set appropriate coefficients. Normally, register 140 is set to 1.
Set it. In particular, change the coefficient set in register 140.
You can freely change the density of inserted characters by
I can do it. ■Insertion of characters within the area (2) As shown in Figure 25 (H), insert text into the specified area in a specified color.
and also as described above for that same area.
This function allows you to insert text in a different specified color. designated territory
While scanning the area, the selector 143 is set to R as described above.
AM data is selected. As mentioned earlier, at this time,
Obtained from the bitmap memory shown in Figure 25 (G)
The selector 139 is switched based on the character signal. Sunawa
If it is not a character, the data in RAM 135 is output and the text is
When it is a character, it is executed by selecting RAM136.
ing. Note that the RAM 136 is stored in advance in the area, for example.
For example, 135 is the density data of characters other than characters in the area.
concentration data is written via the CPU bus 508.
There is. Similarly to the above, registers are also available for coefficients as well as character signals.
Tar142. 140 is selectively output. The multiplier 144 calculates and outputs the result. In other words, since registers 140 and 142 are provided separately,
You can set the density for text and literature sections independently. ■ Negative/positive reversal within the area This is a function that outputs only the negative/positive images within the area.
The negative/positive inversion circuit 138 is switched by the control signal SO.
This is done by switching. The output from 138 is output with the same settings as the through function.
It will be done. ■ Inserting negative/positive inverted characters within an area The character insertion function (1) within an area described above and
Negative/positive inversion within the area by combining negative/positive inversion
This is a function to insert text into images. The character insertion method is
Since it is the same as the notation method, the explanation will be omitted. In the embodiment described above, the decoder shown in FIG. 25(A)
The operation of 146 is shown in FIG. 25 (1). 1 to 6 shown in the leftmost column in the map reading correspond to the above ■ to ■
It shows each function. It is also shown as “input” in the diagram.
The left side is the input of the decoder 146, and as the "output"
The right side shown is the outputs SO to S4 of the decoder 146. Images processed by the video processing unit 12 as described above
Information is sent to the color printer via the printer interface 56.
output to the printer 2. Description of color printer 2> Next, the configuration of the color printer 2 will be explained using FIG.
Ru. In the configuration of the printer 2 in FIG. 1, 711 is a scanner.
and converts the image signal from the color reader l into an optical signal.
Laser output part, polygon of polyhedron (e.g. octahedron)
Mirror 712, rotate this polygon mirror 712
Motor (not shown) and f/θ lens (imaging lens) 7
It has 13 mag. 714 is the gap indicated by the dashed line in the figure.
Reflection mirror that changes the optical path of the laser beam from scanner 711
, 715 is a photosensitive drum. The laser beam emitted from the laser output section is passed through a polygon mirror.
712 and is reflected by f/θ lens 713 and reflection mirror.
-714 scans the surface of the photosensitive drum 715 in a linear manner.
star scan) to form a latent image corresponding to the original image.
Ru. In addition, 717 is a primary charger, 718 is a full exposure lamp,
723 is a cleaner that collects residual toner that was not transferred.
The inner part 724 is a pre-transfer charger, and these members are
It is arranged around the optical drum 715. 726 is Ray
formed on the surface of the photosensitive drum 715 by the exposure.
It is a developer unit that develops an electrostatic latent image, and is 731Y.
(for yellow), 731M (for magenta), 731C (
(for cyan) and 731Bk (for black) are photosensitive drums.
Developing sleeve that directly develops in contact with 715, 730Y
, 730M, 730C, 730Bk have spare toner.
The toner hopper 732 that holds the toner transports the developer.
It is a screw to do. These sleeves 731Y~7
31Bk1) Ner hopper-730Y to 7308 and
A developing unit 726 is configured by the screw 732.
These members are connected to the rotation axis P of the developing unit 726.
are placed around the area. For example, when forming a yellow toner image, use the position shown in this figure.
Develop with yellow toner. magenta toner image
When forming, center the developing unit 726 on the axis P in the figure.
and develop magenta at the position touching the photoreceptor 715.
The developing sleeve 731M inside the container is arranged. cyan, blue
Similarly, for rack development, move the developing unit Unisitoff 26 to the axis shown
It operates by rotating around P. Further, 716 is a toner formed on the photosensitive drum 715.
719 is a transfer drum that transfers an image onto paper.
Actuator for detecting the moving position of ram 716
The plate 720 is in close proximity to this actuator plate 719.
As a result, the transfer drum 716 moves to the home position.
The position sensor 725 detects the movement of the transfer drive.
Ram cleaner, 727 is paper press roller, 728 is static neutralizer
729 is a transfer charger, and these members 719,
720, 725, 727° 729 are the transfer roller 716
are placed around the area. On the other hand, 735.736 is a paper feeder that collects paper (paper sheets)
Is cassette 737, 738 cassette 735, 736?
Paper feed roller that feeds paper from 739.740.741
is a timing roller that takes the timing of paper feeding and conveyance.
It is. Paper fed and conveyed via these
The tip is guided by the id 749 and held by the gripper described later.
while wrapping around the transfer drum 716 and moving on to the image forming process.
do. Further, 550 is a drum rotation motor, and the photosensitive drum 7
15 and the transfer drum 716 are rotated synchronously. 750 transfers the paper to the transfer drum 716 after the image forming process is completed.
The peeling claw 742 removes the removed paper from the
Conveyor belt 743 is conveyed by conveyor belt 742
This is the image fixing unit that fixes the paper that has been
In section 743, the motor is attached to section 748.
The rotational force of the motor 747 is transmitted through the transmission gear 746.
is transmitted to a pair of thermal pressure rollers 744 and 745,
The material transported between the heat pressure rollers 744 and 745
Fixes the image on paper. Printout processing of printer 2 with the above configuration
will be explained below with reference to the timing chart in Figure 22.
I will clarify. First, when the first ITOP arrives, the photosensitive dome is exposed to laser light.
A Y latent image is formed on the ram 715, and this is the developing unit.
731Y, and then the paper on the transfer drum.
Transfer is performed to perform magenta printing processing. So
Then, the developing unit 726 rotates around the axis P in the figure.
. When the next ITOP551 arrives, the photosensitive drive is exposed to laser light.
An M latent image is formed on the image, and the same operation is performed thereafter to form an M latent image.
processing is performed. ITOP5 following this movement
Corresponding to 51, do the same for C and Bk, and
-Print processing and black print processing are performed. child
After the image forming process is completed, the peeling claw 7
50, the paper is peeled off, and the image fixing unit 743 fixes the paper.
The garment is put on, and the series of color images/images are printed.
. Next, description of the film scanner 34> Using FIG. 45 of the film scanner 34 shown in FIG.
explain. 3001 is a light source (lamp) for illuminating a transparent original; 3002
is a heat ray absorption that removes heat rays from the light rays from the light source 3001.
Filter, 3003 is the illumination that passed through filter 3002
This is an illumination optical system that converts light into a parallel beam. 3004 is transparent
A sub-scanning drive table 3005 moves the original in the sub-scanning direction.
A rotating table for rotating transparent originals, 3006 stores transparent originals.
The 3007 is a film holder for 35mm photo frames.
It is a transparent original like a film. 3008 is transparent original 3
A movable mirror that switches the optical path of the light beam (original image) transmitted through 007.
3009 is a mirror that deflects the optical path of the original image.
10 is an imaging lens that forms an image of the original that has passed through the mirror 3009;
It is 3017 is a lamp holding member that supports the light source 3001.
Ru. 3064 is a COD positioning mechanism and an imaging record, respectively.
The transparent original image formed by the lens 301O is photoelectrically converted.
It has R, G, and B color separation filters for
CCD line using CCD (charge coupled device) array
These are sensors 3061, 3062, and 3063. 3025 is CCD line sensor 3061, 3062.3
Amplify the analog output of 063 and convert it to A/D (analog/
Analog circuit that performs digital) conversion, 3026 is analog
The adjustment circuit 3025 generates a standard signal for adjustment.
The adjustment signal generation source 3027 is from the analog circuit section 3025.
The obtained R, G, and B digital image signals are
Dark correction circuit that performs dark correction, 3028 is dark correction
A system that applies shading correction to the output signal of the circuit 3027
Fading correction circuit, 3029 is shading correction
Pixel shift in the main scanning direction with respect to the output signal of the circuit 3028
This is an image shift correction circuit that corrects. 3030 is R2O that passes through the image shift correction circuit 3029;
For example, change the B signal to Y (yellow) or M (major) depending on the output device.
zenta) and C (cyan) color signals.
It is a conversion circuit. 3031 also performs LOG conversion of signals.
This is a lookup table (LUT) that performs γ conversion. The output of the lookup table (LUT) 3031 is
interface circuit 3038 and minimum value detection circuit 3032.
It is connected. 3032 is the output signal of the lookup table 3031
A minimum value detection circuit that detects the minimum value of , 3033 is the minimum value
Undercolor removal (UGR) according to the detection value of the detection circuit 3032
Look-up table (LUT) to obtain the control amount for
, 3034 is the output signal of the lookup table 3031
a masking circuit 303 that performs masking processing on
5 is a look for the output signal of the masking circuit 3034.
Undercolor removal processing is performed based on the output value of up table 3033.
This is a UCR circuit (undercolor removal circuit) that performs this. 3036 is U
Specify the recording density for the output signal of the CR circuit 3035.
3037 is a density conversion circuit 30
36 output signals are converted to the specified magnification ratio.
This is a variable magnification processing circuit. 3038 is the color reader l and image storage device 3 shown in Fig. 1.
Interface circuit (1/1) that transmits signals between this device
F), 3039 is a controller that controls the entire device
There is a microcomputer inside the controller 3039.
CPU (Central Processing Unit) of computer, processing procedure
ROM (read-only) where is stored in program form.
memory), R used as data storage and work area
AM (Random Access Memory), etc. 3040 is an interface circuit from the scaling processing circuit 3037.
3038 and an output input via the controller 3039.
The peak detection circuit 3041 detects the peak value of the force value.
an operation unit 30 for giving various instructions to the controller 3039;
42 is a table displaying the control status of the controller 3039, etc.
This is the exhibition section. 3034 performs aperture control of the above-mentioned imaging lens 3010
A lens aperture control unit 3044 controls the focus of the imaging lens 301O.
Lens distance ring control unit that performs point adjustment, 3045 is a movable mirror
-3008. 3048 is a film feed control section, and a film holder
-3006 to feed the film. 3049 is a secondary runner
a sub-scanning control unit 30 that controls scanning of the scanning drive table 3004;
50 is a light source (lamp); a lamp that controls the amount of light of 3001;
The lamp light amount control circuit 3051 is the lamp holding member 3017.
a lamp position driving source that adjusts the position of the light source 3001 through
It is. 3052 is a timing control based on the control of the controller 3039.
Timing generator that generates clock signals (clocks)
, 3053 are the above-mentioned control units, processing circuits, and controllers.
3039 is connected to the bus, 3054 is for the output device.
Data line 3055 is an output device for inputting and outputting image data.
synchronization signal Hsync for the device. Synchronous signal line for inputting and outputting Vsync etc., and 3056
is a command with a given protocol between interfaces.
This is a communication line for exchanging codes. Next, the operation of each part will be explained. The light source 3001 is a light source such as a halogen lamp, for example.
The light emitted from the light source 3001 is passed through the heat absorption filter 30.
02 and the film holder through the illumination optical system 3003.
- Like the 35mm photographic film on 3006
A transparent original 3007 is illuminated. Image of transparent original 3007
The optical path is switched by the movable mirror 3008.
Through the projection lens 3011 and mirrors 3012 and 3013,
on a screen (not shown), or (2) mirror 3009, imaging lens 3010. and 3 colors
The CCD line sensor 302 passes through the resolution prism 3021.
2 to 3024. In the case of the above mode ■, the CCD line sensor
3022 to 3024 are timing generators 3052
Each CCD light is driven synchronously by the clock of
The output signal of the sensor is input to the analog circuit 3025.
Ru. The analog circuit 3025 includes an amplifier and an A/D converter.
The signal amplified by the amplifier is
For A/D conversion output from generator 3052
A/D converter performs A/D conversion in synchronization with the timing clock.
exchange. Next, R2O, H output from the analog circuit 3025
to the dark processing circuit 3027 for each digital signal.
Apply level correction for darker signals, then shading
The correction circuit 3028 performs shading correction in the main scanning direction.
The pixel shift correction circuit 3029 performs correction in the main scanning direction.
For example, FIFO (first-in-first)
Shifting the buffer write timing
Corrected by Next, in the color conversion circuit 3030, the color separation optical system 3021
You can perform color correction on RlG and B signals depending on the output device.
to Y, M, C color signals, Y, I,
It is converted into a Q color signal. next lookup table
In the table 3031, the brightness linear signal can be obtained by referring to the table.
Convert the code to LOG or perform arbitrary γ conversion. 3032 to 3037 are mainly used for color laser copying machines.
Y, M, C, Bk (black) used in Una printer
Configures an image processing circuit to output images using four colors.
do. Here, the minimum value detection circuit 3032, the masking circuit
path 3034, lookup table 3033, and U
CR circuit 3035 combination, printer masking
and perform UCR (undercolor removal). Next, the density conversion circuit 3036 creates a table of each density signal.
After that, the magnification processing circuit 3037 performs main
Perform magnification processing in the scanning direction, and after the magnification processing Y',
Interface M', C', Bk' signals
is sent to the color reader l via the base circuit 3038. Further, the interface circuit 3038 has the above-mentioned Y',
In addition to the M', C', and Bk' signals,
Image information R (red) from backup table 3031
, G (green), and B (blue) can also be output. This depends on the device to which this film scanner 34 is connected.
Y' if determined and connected to color reader l
In the format of M'C',Bk', also image storage
When connecting to device 3, image data is sent in R, G, H format.
Output the data. Further, in the embodiment shown in FIG. 45, the film scanner 34
As shown in Figure 46, how to set the film on the
Two types are possible. The above figure shows the fill installed in mount M using auto change.
Image sample that you want to read by setting many images at once
If you enter which sample and how many sheets to read in the initial settings,
It is intended to operate automatically. The figure below shows how carriers are transferred to the magazine using autoloader M2.
Sensor for aligning the feeding mechanism and its carrier
It has been established. Description of the image storage device 3> First, the image storage device 3 starts from the color reader l in this embodiment.
How to store data in device 3 and Sv, which is one of the input video devices.
Recording of video information from the recorder/player 31 into the image storage device 3
Let's talk about how to memorize. Also, film scanner 34
Regarding the method of storing the image information in the image storage device 3,
state Next, image information is read from the image storage device 3 and processed.
The present invention then forms an image using a color printer 2.
An example of this will be described in detail. (Image storage from color reader l) Setting the reading area using color reader l is described below.
This is done with a digitizer. An external view of this digitizer 16 is shown in FIG. Transfer image data from color reader l to image storage device 3
The operating method for sending will be described later. The mode setting screen 420
, is for setting an arbitrary area on the scanned document.
be. The point pen 421 is used to specify the coordinates.
be. Transfer the image data of any area on the document to the image storage device 3.
To send images, first set the image registration mode using the operation unit 20.
, indicates the position to be read using the point pen 421. The operating method will be described later. The information in this reading area is transmitted to the communication line 505 in FIG.
to the video processing unit 12 via. In the video processing unit 12, this signal is sent to the CPU control
from the video interface 201 by the input 508;
Send it to the image storage device 3. Sends information on the specified area of the original 999 to the image storage device 3.
Describe the process. Figure 24 shows the point pen 421 of the digitizer 16.
An example of the address of the area information (points A and B) specified by
show. Color reader 1 has VCLK signal, ITOP, EN signal
etc., along with the image data 205 on the signal line 207.
Output to image storage device 3. These output signal lines
A timing chart is shown in FIG. 26. The video interface 201 also includes the device shown in FIG.
The flow of data is as follows. As shown in FIG. 26, press the start button on the operation unit 20.
By pressing, the stepping motor 14 is driven,
The document scanning unit 11 starts scanning and reaches the leading edge of the document.
When the ITOP signal becomes “L”, the original scanning unit
11 reaches the area specified by the digitizer 16, and this
While scanning the area, the EN signal becomes l''. Therefore,
Read color image information (DATA2) between numbers “l”
05). As shown in FIG. 26 above, the image from color reader 1 is
Image data transfer is performed using the video interface 201 as the third
By controlling as shown in the figure, ITOP, 1 signal
control signal and VCLK as signal 207.
Output from interface 201 and synchronize with said 207
R data 205R, G data 205G, B data 2
05B is sent to the image storage device 3 in real time. Next, using these image data and control signals, the image storage device
Figure 27 (A) ~ shows how 3 is specifically memorized.
This will be explained with reference to (F). The connector 4550 is connected to the bit inside the color reader l shown in FIG.
connected to the video interface 201 via a cable.
R data 205R, G data 205G. B data 205B are 9430R and 9430G, respectively.
. Connected to selector 4250 via 9430B
Ru. VCL sent from video interface 201
K, ■signal, ITOP passes through signal line 9450S.
It is input to selector 4250. Also, reading the manuscript
The area specified by the digitizer 16 before picking
Information passes through communication line 9460 to reader controller 4
270 and from there via the CPU bus 9610.
and is read by the CPU 4360. input to selector 4250 via connector 4550
R data 9430R, G data 9430G, B data
Selector 9430B is selected by selector 4250.
Signal lines 9421R, 9421G, 9421B
and input to the filter circuit 9500. FIG. 28(A) shows the filter circuit 9500 in detail.
FIG. Image signals 9421R, 9421G, 9421B are FI
Input to FO memory 4252R, 4252G, 4252B
be done. In addition, the timing control received from the system controller
Controlled by signal 9450. FIFO memory 4252R, 4252G, 4252B?
The outputs are image information 9421R, 9421G, 942
1B, it is a signal with a delay of 1 sub-scanning, and the signal line 9
422R, 9422G, 9422B, adder 42
53R. It is input to 4253G and 4253B. Adder 4253
R. 4253B and 4253G have 2 pixels in the main scanning direction and 2 pixels in the sub-scanning direction.
The average of two pixels in the direction, that is, four pixels, is taken, and the signal line 9
Output to 423R, 9423G, 9423B. Selectors 4254R, 4254G, 4254B are
Image signal 9421R, 9421G, 9421B or addition
Averaged signals 9423R, 9423G, 9423B
and select signals 9420R, 9420G, 942
0B and input to each image memory. Above selector 4254R, 4254G, 4254B
Although not shown, the select signal is provided by the CPU 4360.
It is controlled and programmable. As explained above, the filter circuit 9500, for example,
When a halftone image, etc. is read from a color reader, the model
Images are averaged to prevent image deterioration due to cracks.
It will be done. 28(B) and (C) show the internal structure of the selector 4250.
A block diagram showing the configuration is shown. Color reader as shown
1 or as described later, various video equipment such as still video
Any image signal from a video player or film scanner
It is now possible to switch to . These switching
Signal is programmable from CPU via decoder DC
It can be controlled. For example, an image from the color reader l to the image storage device i13
When storing information, control signal 5ELECT-A. Set 5ELECT-D and 5ELECT-E to O.
Tri-state buffer 4251R, G, B, H8゜
VS, CK, EN and 4252R, G, B, H3
,VS. Utilizing only CK and EN, other tri-state buffers
Color reader l by making all high impedance
Image signals 9430R, G, B and control signals 94 from
505 are 9421R, G, B and 9420 respectively
Combined with S. The image selected by selector 4250 as described above
The signal passes through filter 9500 and is sent to the system controller.
The information is stored in each memory under the control of the controller 421O. below
For example, we will explain the details by taking the case of storing data in memory A as an example.
I will clarify. The system controller 421O controls the filter 9500.
Image data 9420R, 9420G, 9420B
Of these, only the effective area of the image is stored in the FIFO memory 4050.
A.R. Transfer to 4050AG and 4050AB. Also, the system
At this time, the program controller 4210 performs trimming processing and
The scaling process is also performed at the same time. Furthermore, FIFO memories 4050AR and 4050AG. 4050AB is the color reader l7 image storage device 3
absorb differences in the market. These processes of this embodiment are shown in the circuit diagrams of FIGS. 27 and 29.
, and the timing chart in Figure 30 below.
explain. From the selector 4250 shown in FIG. 27 (-A'),
FIFO memory 4050AR via filter 9500
. Prior to data transfer to 4050AG and 4050AB,
Effective area in the main scanning direction of the area specified by the digitizer 16
The area is connected to the computer shown in FIG. 29 by the CPU bus 961O.
Write to parators 4232 and 4233. Furthermore, Figure 29
is the configuration of system controller 4210 and memory A
It is a figure showing the structure of FIFO memory in ~M. Comparator 4232 is instructed by digitizer 16
Compare the start address of the area in the main scanning direction.
A stop address is set in the controller 4233. Also, the sub-scanning direction of the area specified by the digitizer 16 is
, controls the selector 4213 to select the CPU bus 9610 side.
Select and enable the area specified in RAM4212.
Write “0” data to the valid area, and write '0' to the invalid area.
1” data is written. The scaling process in the main scanning direction is performed using the rate map shown in Figure 29.
The change is made to the multiplier 4234 via the CPU bus 9610.
Set the magnification. Also, the magnification processing in the sub-scanning direction is
This is possible depending on the data written to the RAM 4212. Figure 30 shows the timing chart when trimming processing is applied.
It is a chart. As mentioned above, use the digitizer 16 to
To store only the indicated area in memory (trimming)
processing), the trimming position in the main scanning direction is shown in Figure 29.
Set in comparators 4232 and 4233, sub-scanning direction
The trimming position in the direction is set by selecting the selector 4213 from the CPU bus.
9610 side and write to RAM4212 by CPU
((Example) Main scan the trimming area from 1000 to 3047
, sub-scan too~5095). That is, R.A.
M4212 is a counter 42 input via a selector.
14. In the area corresponding to each address output, "l"
Or "0" is written by the CPU. here
As will be described later, 'l' indicates memory 4050AR, AG, A.
B reading is prohibited, and “0” is the data that causes reading.
It is Ta. The trimming section signal 9100 in the main scanning direction is the control line
“Uma T” ball 9452 and CLKIN9 from N9420S
Counter 4230 operates in synchronization with 456, and this counter
When the printer output 9103 becomes 1000, the comparator
The output of the flip-flop 4232 becomes l, and the flip-flop 423
The output Q of 5 becomes 1. Next, the counter output 9103
3047, the output of comparator 4233 becomes 1.
Therefore, the output of flip-flop 4235 changes from 1 to O.
Become. Also, in the timing chart in Figure 30,
Since processing is being performed, rate multiplier 4234
The output of is l. The trimming section signal 9100
FIFO memory 4050AR,AG. 3 from address 1000 of color image information
FIFO memory 4050AR,AG up to address 047. Written to As. Also, from the comparator 4231, a control line 9420
1 pixel delay from HYN lN9452 from S
A signal 9107 is output. FIFO memory like this
4050AR, AG, AB old filter input, R5TR input
By giving a phase difference to the FIFO memory 405
Control line 94 input to 0AR, AG, AB
Circumstances of CLKrN9456 and CLK9453 from 20S
Absorb differences in periods. Next, for trimming in the sub-scanning direction, first
Control the receiver 4213 and select the counter 4214 side.
ff1945 from control line 9420S
5. Section signal 91 synchronized with H3YN lN9452
04 is output from the RAM 4212. Section signal 9104
is synchronized with signal 9107 by flip-flop 4211.
FIFO memory 4050AR, AG, AB board
Enter enable. That is, FIFO memory 405
The image information stored in 0AR, AG, AB is trimmed.
The output signal 9101A is output only during the period when it is “0” (n
-m'). In addition, the signal 9101A is a counter signal as shown in FIG.
Input to controller 9141A and counter enable
signal and the memory 4060A-R, G, B memory
This is a toy enable signal, and as mentioned above, the FIF
Image information output from O memory 4050A-R, G, B
The information is sent to the address output from counter 4080A-0.
Therefore, memory 4060A-R immediately. Written to G and B. The signal 9101 explained above is independent for memories A-M.
It has 6 systems, and signal 9100 is independent only for memory M.
I have a total of 2 systems. In the above explanation, only the trimming process was explained.
However, scaling processing is also possible at the same time as trimming. Main scan
To change the magnification in the direction, set the magnification rate to the rate multiplier 4234.
Set via CPU bus 9610. Also, sub-scanning is RA
Variable magnification processing is possible depending on the data written to M4212.
Ru. Figure 31 shows the cropping process and scaling process (50%).
A timing chart is shown below. Figure 31 shows image data from selectors 4254R, G, and B.
The data is scaled and reduced by 50%, and FIFO memory 40
Timing chart when transferring to 50AR, AG, AB
FIG. The CPU bus is connected to the rate multiplier 4234 in Figure 29.
9610 to set a setting value of 50% reduction. At this time, the output 9106 of the rate multiplier is the 31st
As shown in the figure, 0” and “1” are repeated for each pixel in the main scanning direction.
This is the repeated waveform. This signal 9106 and comparator
Ta4232. Section signal 9105 created by 4233 and
The AND signal 9100 of the FIFO memory 4050AR,
By controlling write enable to AG and AB
Perform reduction. Also, sub-scanning is performed on the RAM 4212 as shown in Figure 31.
Write data (FIFO memory 4050AR, AG
. Transfer to AB - enable signal) to image data valid area
50% by setting “l” (reading prohibited) within
Only the reduced image data is stored in the image memory 4060AR,
Sent to AG and AB. In the case of Figure 31, the link
The field enable call 9101 exchanges “1” and “0” data.
A 50% reduction is achieved by repeating each other. In other words, trimming and scaling processing in the main scanning direction are performed using F.
Write enable of IFO memory 4050AR, AG, AB
control, cropping and scaling in the sub-scanning direction
is FIFO memory 4050AR,AG. Controls AB read enable. Next, FIFO memory 4050AR, 4050AG,
4050AB to memory 4060AR, 4060AG,
Transfer of image data to 4060AB is shown in Figure 27 (C).
Counter control 9141A and counter 4 shown
Performed by 080A-0~3 and control line 9101A
It will be done. Note that 9101A is the flip-flop 42 shown in FIG.
11 outputs and FIFO4050R, G, B glue
Enable ■, memory 4060A-R-B shown in Figure 32
It is used as the write enable W1 of the. Counter control 9141A shown in FIG. 27(C)
issues an address to memory 406OA-R, G, B.
control counters 4080A-0 to 3
The following three main types are generated by commands from the CPU in the circuit.
It has the following functions. 1. CPU read/write mode → data at any address can be referenced by the CPU
. 2. Read mode → Read the stored image data by the control signal of the system controller.
Read the data and transfer it to the color reader l to obtain a printout.
. 3. Light mode → Color reader by control signal of system controller
Store the image from l. In either case, count of counter 4080A-0 to 3
The start address can be set arbitrarily from the CPU.
. This allows reading and writing from any address.
becomes possible. Normally the start address is address θ. Control line 9101A is FIFO memory, 4050AR
. This is a read enable signal for AG and AB, and also a counter
is input to the counter control 9141A and the counter is controlled.
It will be done. Furthermore, write memory 4060AR, AG, AB
It is also an enable signal. Counter control 9141A is in light mode
, input control signal 9101A to counter 4080A
It is used as a counter enable signal for -0 to 3. In addition, counter control responds to CPU commands.
Selecting counters and selecting all counters
There are cases. 9140A is a counter control signal.
Select the counter to be operated when line 9101 is “0”
(Counter enable signal 4080A-0 to 3)
Enable. At this time, from the FIFO memory 4050AR, AG, AB
The read image data is stored in memories 4060AR and AG. input into AB and indicated by the respective counters.
stored in the dress. At this time, for example, counter 4080A-0 is selected.
If so, the enable of counter 4080A-0 is “0”.
”, and the count u is synchronized with CLK9453.
pl, the signal 912OA-0 is output to the counter 408OA-0.
is output from the memory 406 through the selector 4070A.
0AR. It is input to the address lines 9110 of AG and AB. Also, at this time, the memory 4060AR, AG, AB write
Toy enable W″v9101A is also “0”
Images input into memories 4060R, G, and B from
Data 9090R, G, B are stored. Note that the memory capacity in this example is 1M bytes for each color.
Therefore, the image data of the reading area in Fig. 24
By reducing the size of the image by 50%, the read image data becomes
Convert data to maximum capacity of memory of image storage device 3
and is remembered. Further, in the above embodiment, the CPU 4360 handles the A3 document.
The effective area is determined from the area information specified by the digitizer 16.
The comparators 4231 to 423 shown in FIG.
3. Rate multiplier 4234 and RAM 42
Set the data corresponding to 12. In this embodiment, the image data capacity of the read image is
Since it is larger than the image memory capacity, it can be reduced and stored.
After converting it to a certain capacity, it was stored in the image memory. However, reading
The data capacity of the captured image is based on the image memory capacity.
If the area is small, take a note of the area specified by the digitizer 16.
Comparators 4232, 42 that control writing to the
33, set the trimming information data and set the rate mark.
The chipplier 4234 is set to equal magnification. Also, R.A.
The data written to M4212 is all valid image area.
Set it to "0" and set it to "1" otherwise, setting the same size. It also preserves the aspect ratio (vertical/width ratio) of the scanned image.
In order to store it in memory as it is, first the CPU 4360
is valid from the area information sent from the digitizer 16.
Find the number of pixels “X”. Next, the maximum capacity of image storage memory
From "y", calculate 2 using the following formula. -X 100 = z As a result, (1) When z≧lOO, rate multiplier 42
The setting of 34 is 100% of the effective image area in RAM4212.
Set all to 0'' and store at the same size. (2) When z<100, rate multiplier 423
4 settings and RAM4212 are both reduced by 2%.
, store to maximum memory capacity while maintaining aspect ratio
do. Even in this case, the data written to RAM4212 is
, apply the data of “l” and “0” corresponding to the reduction rate “z”.
Just write the time. By controlling in this way, only the image storage device 3
control to maintain the aspect ratio of the input image.
Enables variable magnification processing with easy control, improving the effectiveness of scanned images.
effective recognition becomes possible. At the same time, memory capacity usage
It is possible to maximize efficiency. The settings described above also apply to the image storage memory (memory A).
, B, C, D) and the data shown in Figure 27(E).
The screen display (memory M) can also be set independently.
When storing images, the same image can be stored at different magnifications at the same time.
Separate memories, for example memories A, B, C, as mentioned above,
It can be stored in memory D, memory M, etc. Description of Memory E> The memory E in FIG. 27(A) will be described. No.
Figure 27 (D-1) shows a schematic diagram of its internal configuration. memory
E is a binary image memory (hereinafter referred to as bitmap memory).
), and its operation is similar to memory A described in the previous section. bits in the image data loaded from Color League
The image data written to map memory E is explained in the previous section.
Similar selector 4250. Memo passed through filter 9500
FIFO4050E shown in Figure 27 (D-1) in the
-Written to R. In such a case, please refer to Figure 29.
Similarly, writing is performed by write enable 9100.
controlled. At this time, in the embodiment, only the R signal is used as an image signal.
If it is represented by a luminance signal, what else is it?
Good too. For example, if the G signal or R, G, and B are set to a predetermined ratio,
The signal may be a weighted average signal. FIFO40
The image data written to 50E-R is the same as the explanation in the previous section.
is read out by the control signal 9101E, and the 4055-R
It is binarized by the binarization circuit shown in and sequentially written to the memory.
It gets sucked in. At this time, black is 11 and white is ``O''.
Write to register 4053. For example, Fig. 27 (D-2
) A heart-shaped manuscript with a certain density on a white background
Prepare area A and specify area B as shown by the dotted line in the figure. this territory
By reading the area into bitmap memory E,
The map memory contains a binary image of “0” and “B” as shown in the figure.
is stored. 4080E is the read/write access for memory 4060ER.
9141E is a counter for controlling the address.
A counter for controlling the counting state of the counter 4080E.
system controller 421O
to the CPU in the same way as explained in Figure 29.
The read and write positions are controlled by this
The second data is read out sequentially as shown by the arrow.
The non-rectangular area signal as shown in F in Figure 7 (D-2) is the signal
Output to line 4072 and selector 4071 select
Used as a signal. One input of selector 4071
has an 8-bit capacity register connected to the CPU bus.
4074 is provided, and a predetermined output density value is set in advance.
For example, 80H is input.
. Therefore, the signal 4072 indicates that the 1 o'clock selector has been set as described above.
A certain density value is output to 4172, resulting in the heart of the figure.
The set density value is output to the square area. Also, the most significant bit (MSB) of 4172 becomes 4173.
It is output (referred to as Bl signal) and used as a non-rectangular area signal.
I can stay. Also, the above-mentioned 4171.4172 is ■D in Figure 27 (B)
is output to the part in FIG. 2 via the selector 4230.
A video interface 201 shown in FIG. In the bitmap E shown in Fig. 27, the output is
For the binary image stored in the memory 4060E-R
FIG. 27 (D-1) The register 4074 shown in FIG.
By rewriting the density to be printed via the CPU,
It can be set at will. In addition, “
If you write data of 80H' or more, the signal shown in 4173 will be generated.
A bit image is output on the line. <Image storage from the SV recording/playback device 31> The system of this embodiment uses the SV recording/playback device 31 as shown in FIG.
The video images from 31 are stored in the image storage device 3 and monitored.
It is also possible to output to a digital TV 32 or color printer 2.
It is. The image processing device 3 also handles the input image.
We also do rings. Below, the video image from the Sv recorder/player 31 is stored as an image.
Importing into the device 3 will be explained. First, an image storage device for storing video images from the Sv recording/playback device 31
Figure 27 (A-1) regarding the control of import into the device 3.
Blocks of image storage device 3 in (A-2) and (B)
This will be explained below with reference to a block diagram. Figure 27 (A-2) shows the analog interface 453
FIG. 2 is a diagram for explaining the internal configuration of 0. The video image from the Sv recording/playback device 31 is input to the video input terminal.
NTSC composite signal type 9000 via 4500
input, and the decoder 4000 separates R, G
, B signal, and composite 5YNC signal.
The signals are separated into 9015R, G, B, and S signals. The decoder 4000 also has a video input terminal 4510.
The Y (luminance)/C (chroma) signal 9010 is also the same as above.
decode it accordingly. 902 OR to selector 4010. Each signal of 9020G, 9020B, 9020S is separated.
Rate R, G, B signals and composite 5YNC
The input signal is in the form of a signal. Selector 401O is connected to CPU bus 9610.
The signal 9030R~S and 902OR-8 (7) selection is
This can be done programmably from the CPU. Separate R and G selected by selector 4010
, as B signal (7) 9049R, 9049G, 90
Each signal of 49B is gated by the CPU 4360, which will be described later.
Amplifier 9050R, G that allows you to freely control the input
. B, and then A/D converter 402OR, 40
20G. Input to 4020B and analog/digital conversion
. At this time, as will be described later, depending on the capacity of the image storage memory, C
Sampling clock can be selected on PU4360
It has become. Also, the composite selected by the selector 401O
5YNC signal 9050S is the TBC/HV separation circuit 40
30 and is input to the TBC/HV separation circuit 4030.
Composite, S Y N C signal from 9050S
Clock signal 9060C, horizontal synchronization signal 9060H and
and vertical synchronization signal 9060V are further shown in Fig. 28(C).
An image enable signal 9060EN is generated to indicate the selector
4250 is input. Note that there is an enable signal EN.
This is a signal indicating an image area. Selector 4250 selects the color image source as described above.
Images from the reader l and various video devices (in this example,
Images and film skis from (temporarily using an Sv playback machine)
This is a selector that selectively outputs images from the scanner 34. No.
28 Explain the specific operation using Figures (B) and (C)
do. For example, when selecting an image on the video equipment side, the control signal 5
Set ELECT-A and 5ELCT-B to 0 and try
Steady Pa'/774253R, G, B, H3°VS,
CK, EN and 4252R, G, B, H3, VS
. Taking advantage of CK, EN (7), 5ELECT-C, D,
E. F, set to l and all other trisler buffers
By setting all of them to high impedance, it is possible to
image signals 9051R, G, B and synchronization signal 90
51S are respectively 9420R, G, B, 9420S
is combined with The same applies when inputting image data from other devices.
. Furthermore, in this embodiment, the color reader 11 or the file
A two-way communication line is required for connection with the lume scanner 34.
To use the trislurt in selector 4250
It is characterized by the use of a buffer. The output from the TBC/HV separation circuit 4030 of this embodiment is
For example, in the case of NTSC standard, TVCL
K9060C signal is clocked at 12, 27 MHz
No. I, r1 chome a9060 H signal H < /I/X
Width 63, 5μs signal, 9060V signal at m is pulse
This is a signal with a width of 16.7 mS. Selector 42 is configured so that such a video image signal is input.
50, the CPU switches between each of the filters 9500.
Switches 4254R, G, and B are shown in Fig. 28 (A) on the upper middle side.
Switch to . Therefore, there is virtually no fill time.
Memory A, B, C, D, E, M
It is input in either direction. You can also import images from the reader.
Images with moiré, such as images with halftone dots,
Therefore, the above-mentioned switches 4 correspond to such images.
254Prevents moiré by switching R, G, and B to the lower side.
Stop. Next, the explanation will be given again using FIG. 27(C). FIFO memory 4050AR, 4050AG, 4050
AB is reset by the 9060B signal on the r tube 1.
and synchronized with TVCLK9060C signal from address '02
and write data 9060R, 9060G, 9060B.
Get into it. This FIFO memory 4050AR, 4050A
G. 4050AB is written by the system controller 42.
The W1 signal 9100 output from 1O is activated.
It is done from time to time. This FIFO memory 4050 by this ■ signal 9100
Details of write control of AR, 4050AG, 4050AB
The details are explained below. The Sv recording/playback device 31 in this embodiment is, for example, based on the NTSC standard.
In the case of a digital
The converted pixel capacity is 640 pixels (H) x 480,480
This is the screen capacity in pixels. Therefore, first, the image storage device 3
The CPU 4360 sends a message to the comparators 4232 and 4233.
Write the setting value so that there are 640 pixels in the main scanning direction. Next, input the selector 4213 to the CPU bus 9610 side.
Then, this RAM 4213 stores 0 for 480 pixels in the sub-scanning direction.
” is written. Also, rate multiply, which sets the magnification in the main scanning direction.
100% data is set in the layer 4234. The image information of the SV recorder/player 31 is stored in the memory 4060AR. When storing data in AG and AB, the system controller 42
10 is output from the TBC/HV separation circuit 4030
9060V for rW Mouth 1, 9060H for TVH3YN. T V CL K 9060 C11 f shown in Figure 29
fi 9455. H3YN 9452. CLKIN94561. :Contact
Continued. As mentioned above, the image control signal is transferred to the SV recorder/player interface.
By placing it on the face side, the A/D converter 402
This is the output signal from 0R, 4020G, 4020B.
9051R, 9051G, 9051B video images
Data for one main scan is input to the filter circuit 9500.
, its output signals 9420R, G, B are FIFO memory
Written on 4050AR, 4050AG, 4050AB at the same size.
be remembered. The memory capacity of this embodiment is, for example, per memory A,
The above-mentioned NTSC standard video still image (640 pixels (H
) x 480,480 pixels) can store up to 4 images.
, and when stored at the same size in memories A to D, a total of 1
Six types of images can be stored. These memories A, B, C, and D can be easily installed in the main body of the device.
It is removable and can be expanded.
In some cases, high band specifications (768 pixels (H) x 48048
0 pixel) video images can be stored in the same way.
Ru. Details will be explained below. In this device, the CPU 4360 runs as soon as the power is turned on.
A program that detects the capacity of each memory starts, and each
The CPU 436 detects the capacity of each memory, although it is not shown in the figure.
The result is stored in the work register in 0. 32nd
Figures (B) and (C) are the algorithms of the program mentioned above.
FIG. For example, for simplicity, 4060A-R in memory A is shown in the figure.
When shown in a schematic diagram in correspondence with the address, the shaded area is
It becomes an extension part, and there is a memo at the corresponding address aH.
If the CPU 4360 is not
Data cannot be stored even if accessed. On the other hand, after adding memory in the area corresponding to the shaded area,
The memory capacity per image has increased compared to the old GH band specifications.
It is now possible to correspond to the above address aH as well.
data access on CPU4360.
access is also possible. Here, the CPU 4360 starts from a fixed address aH by b bytes.
Write the specified data for 1, then continue from address aH
Reading the data and comparing it with the written data
It detects the memory capacity. FIG. 32(C) shows a flowchart of such operation. In other words, if the memory is not expanded, the terminal at address aH
becomes an oven, so the CPU 4360 reads the data.
When outputting, the high level continues to be output, so the above
The memory capacity can be detected by the operation of . memory capacity
The result of detecting the amount is determined by the CPU 4360 as described above.
The 27th
As shown in figure (A-1), 03C4031 is connected to CPU436
A/D conversion 4020R, G, B by controlling
The sampling clock is changed, and the memory capacity is
Support with high band input or low band input depending on the
The sampling clock is being switched. Furthermore, in this embodiment, the Sv control connector 442
By connecting 0 and Sv player (player) 31,
Sv player 31 via Sv controller 4420
It is possible to exchange commands between and the CPU4360.
Become. At this time, the Sv player (player) will
Is the video image recorded in high band mode or the rover?
Detects whether the image was recorded in mode. Such detection
Since the means are well known, they will not be specifically described. Then Sv play
controller 4420.
By sending command to CPU4360, CPO43
60 is an image memory stored in the work register
Sampling from the above command with data about the remaining amount of
The clock can be controlled for more precise response.
It will look like this. For example, if the memory supports high band and
When the video is in high band, the sampling clock is in high band.
It will become a nd. Also, if the memory supports low band or
When the audio device is in low band, the sampling clock is low.
Compatible with bands. In addition, the CPU 43
Gain of video amplifier 4011R, G, B by 60
The best image can be obtained by adjusting the image optimally and storing it in memory again.
It is possible to store the image (hereinafter referred to as AGC (auto game)).
In Control). The details are explained below.
Ru. Figure 32 (D) shows the algorithm flowchart.
vinegar. Also, the operation is shown in Figure H in Figure 47 or Figure 50.
It functions by pressing the AGC key in Figure 6 in (A).
. When storing video images, first of all
Amplifier 4011R that can control the tone in 8 stages. Set G and B to the minimum gain (St). Se
After the video image is stored in memory (S2), the CP
The following check is performed by U (S3). to S3
If the image data is, for example, 8 bits, check
, the data of the stored image is the maximum value FFH (in this example, the maximum value is FFH).
Check whether the brightness value is set to (high brightness value). this is
Check the entire image area or a certain area
conduct. In this example, a part of the central area of the stored image is used as a substitute for the entire area.
This is done as a table. This reduces the check time.
Can be shortened. These checks are performed on each of R, G, and B of the stored image.
I'll follow you. In S4, which one is R, G, or H?
For example, if the value is 8-bit image data, it is FF. If there is no FFH pixel, check if it is
Increase the gain of amplifiers 4011R, G, and B by one step and try again.
The data is stored in memory and the processing from S2 is repeated. F
If FH is found, the process ends. By performing the above processing, communication between various video devices is possible.
The recording level (brightness) is always the same even if the recording level (brightness) is different.
It is now possible to store images at levels. The AGC described above is performed via the CPU 4360.
However, the A/D converter 402O shown in FIG. 27 (A-1)
Add a comparator to the R, G, and H outputs and check whether the output
Change the amplifier gain of video amplifier 4011R, G, B.
It is also possible by In addition, by using the AGC function, the input
In addition to controlling the gain of the video signal, R, G
, the color balance of the B signal is also automatically corrected. The color balance function will be explained in detail later. <From the Sv recording/playback device 31 at the time of Sv index
(Image storage) When using Sv index, the image from Sv recording/playback device 31 is stored.
25 pages each are stored in memory. From analog I/F4530 in Figure 27(A)
SV image information 9421R, G, B is at the time of indexing.
In this case, 320 x 240 pixels are treated as one image unit.
One memory board in MoriAND stores 25 pages.
do. Image storage at the time of Sv index is performed by a video machine.
The size of the normal image from the container is 640 x 480 pixels.
/2 and store it in memory at 320 x 240 pixels.
. Let this 320 x 240 pixels be the size of one pixel.
Memory board 1 with 25 screens and 2M pixels
It is possible to store it in one sheet. This situation is shown in FIG. 33(b). Image 1 ~ Image 2
Image signals for 25 screens up to 5 are recorded in a 2M pixel memory.
I remember. Image information from SV recording/playback device 31 640 x 480 images
The element is halved and 320 x 240 pixels is considered as information of one image.
and store it in memory. 87 Image information can be reduced from the image from the color reader l mentioned above.
For control of writing and reading of FIFO as well as image storage
Therefore, it is omitted because it is done. One screen of image information from the Sv recorder/player 31 was memorized.
CPU in the image storage device 31 (FIG. 27(B)(D)
4360) IJ SV:2 controller 4400
A track-up signal is sent to the SV recording/reproducing device 31 via the SV recording/reproducing device 31. The Sv recording/playback device 31 receives the Sv jacket pair by this signal.
the track being accessed by the playhead.
move it toward the inner circumference. Perform the following access
Plays back the image signal recorded on the track and stores the image.
Send to device 3. The image storage device 3 operates in the same manner as described above.
Move the head 2 troughs again and record on the next track.
The recorded image signal is stored in memory. By repeating this operation, the image signals of 25 screens are
Store in memory. (Images from the SV playback device 31 at the time of SV index)
Image display) Image from the Sv playback device 31 at the time of Sv index
Information is transferred to the Sv player from the playback head for the Sv jacket.
sequentially change the tracks that the code is accessing, specifically
Display on monitor TV 32 while tracking up
. This display is shown in FIG. 33(C). From analog I/F4350 in Figure 27(A)
87 Image information 9421R, G, B are memory M+, :12
25 screens of 8 x 96 pixels can be stored as a single device unit.
Ru. Monitor display in Sv index is from video equipment.
The normal image size of 640 x 480 pixels is set to 115.
Reduce and store in 128 x 966 pixel memory. 87 image information can be reduced from the color reader l mentioned above.
Writing/reading of FIFO memory as well as image storage
This is done through the control of One screen of image information from the Sv player 31 is recorded in the memory M.
After storing, the CPU in the image storage device 31 (Fig.
(B) 4360) is connected via the SV controller 4400.
, sends a track-up signal to the Sv recording/playback device 31. The Sv recording/reproducing device 31 receives the Sv jacket from this signal.
Changing the playhead access position for rackups
and sends the next track image to the image storage device. The image storage device 3 stores the next image in the memory M in the same way as described above.
to be memorized. By repeating this action, you can memo the images on 25 screens.
Store it in RiM. The image information stored in the memory M is stored in the LUT (Figure 27 (
Pass through 442OR of E), G, B), D/A converter 44
30R, G, B convert to analog signal and monitor
The image of the index is displayed on the television 32. <Reading process from image storage device> Next, the memory 4060A of the image storage device 3 described above
Image data from R, 4060-AG, 4060AB
Read processing will be explained. The image output from this memory is converted into an image by color printer 2.
Instructions for inputting instructions when performing configuration are mainly shown in Figure 23 above.
This is performed by the digitizer 16 and operation unit 20 shown in
Ru. For example, use a digitizer to mark the area where you want to form an image as shown in Figure 37.
Color reader 1 will copy the position coordinates.
Control line 9460 connected to connector 4550
The data is sent to the CPU 4360 of the image storage device 3 via the image storage device 3. It takes
The position coordinates are output as 8-bit data, for example. The CPU 4360 is a system controller shown in FIG. 27(F).
Area signal generator 4210-2 (first
12 (same as shown in Figure 12(d)) shows the sent coordinate information.
Based on the information, the area signal generator should be activated to obtain the desired image output.
program. Specifically, R shown in FIG. 12(d)
AM555. 556, set the data corresponding to the coordinate information.
cut. Figure 27 (F) shows the output from the area signal generator.
Each signal is shown below. Each has a control signal for each area.
Become. When the above-mentioned program is finished, the image storage device 3 is
- It will wait for a command from the reader L, and then copy copy.
Image formation starts by pressing the start button.
. When the start button is pressed, color reader 1 connects the signal line
4550 to the CPU 4360 of the image storage device t3.
The CPU 43 that sent the command and received the command
60 instantaneously switches the selector 4250. Second
In Figure 8 (B) and (C), the color image is output from the image storage device 3.
The settings for sending images to reader 1 are 5ELECT-C,
Set 5ELECT-E and 5ELECT-F to “0”
All other try-sert buffers are high.
Let it be impedance. Furthermore, CPU4360 is desired.
counter controller for the memory where the image is stored
Set to read mode. Timing to start from color reader L with the above settings
Signal 1 - Receives TOP and BD. On the other hand, color reader l
The image storage device 3 outputs an image in synchronization with the timing signal.
Image signal, CLK, image enable signal can now be obtained.
ing. First, image formation is performed according to the size of the recording paper.
Example, then form an image in the area indicated by the digitizer
An example will be explained. Image forming process that corresponds to the size of recording paper> In this example
In this case, there are two color printers 2 as shown in FIG.
It has two cassette trays 735 and 736, and two types of recording.
Paper is loaded. Here, A4 size in the upper row,
A3 size recording paper is set in the lower row. This record
The recording paper is selected using the LCD touch panel of the scanning unit 20.
is input. The following explanation is based on multiple images on A4 size recording paper.
This is done in case of formation. First, prior to image formation, use the color reader l or film described above.
Image storage device from film scanner 34 or Sv recording/playback device
By inputting the read image data to
Memory 4060AR, 4060AG. 4060AB, for example, as shown in FIG. 33(A).
A total of 16 image data from “Image 0” to “Image 15”
memorize the data. Next, press the start key on the operation panel. As a result, the CPU 22 shown in the second diagram detects this key human power.
automatically adjusts the image forming position on A4 size recording paper.
Configure settings. When forming the 16 images shown in FIG.
For example, if the image forming position is changed as shown in Fig. 34(A),
Set. FIG. 27 shows details of the above image forming process in this embodiment.
The block diagram and timing chart shown in FIG.
This will be explained below with reference to the following. Printer interface from color printer 2 shown in Figure 2.
IT sent to color reader l via face 56
The OP signal 511 is the video signal in the video processing unit 12.
It is input to the interface 201 and the image is stored from here.
Sent to device 3. This ITOP signal is stored in the image storage device 3.
Image forming processing is started by No. 551. And the image
Each image sent to the storage device 3 is stored in the
The system controller 42 shown in FIGS. 27(A) and 27(B)
The image is read out from the memory ABCD etc. under the control of 10.
. Area signal generator located within system controller 4210
(FIG. 27(F)) Control signal 9102-
Q~3 should be the counter enable signal (for example,
When reading from memory A, use counter control 914.
It is input to 1A. Counter control 9141A
Enables the counter based on the input control signal.
and select signal 91 of selector 4070A.
Controls 40A. At the same time, the counter control 9141A beam
Outputs enable signal 9103A, and this signal
Write enable signal for FIFO4140-0 to 3 in the stage
becomes. With this access, each memory 4060AR, 4060A
G. The image data stored in the 4060AB is read out, and each
Read image signals 9160AR, 9160A from memory
G. 9160AB has a lookup table shown in Fig. 27(C).
Table (LUT) 4110AR, 4110AG, 4
110AB, where the specific luminous efficiency characteristics of the human eye are determined.
Logarithmic transformation is performed to match. At this time, 4111
A is a signal for LUT selection and is generated from the area signal generator 4210.
LUTs can be selected arbitrarily for each area.
There is. In this embodiment, 16 types of LUTs can be selected. this
9200AR of conversion data from each LUT. 9200AG and 9200AB are masking/black extraction/
It is input to the UCR circuit 4120A. And this square
Image storage device with King/Black extraction/UCR circuit 412OA
In addition to color correction of the color image signal in step 3, black recording is also performed.
At this time, UCR/black extraction is performed. And these consecutively connected masking/black
The image signal 9210 from the extraction/UCR circuit 412OA is
The area is selected by the selector 4130 shown in FIG. 27(B).
Based on the select signal 9230 output from the signal generator
and is input to each FIFO memory 4140-0 to 4140-3.
. This allows the sequence to be changed as shown in Figure 33(A).
Each image that was lined up in a row is stored in this FIFO4140-0
Parallel processing becomes possible due to the effects of ~3. Figure 35 is a timing chart showing the flow of the images mentioned above.
It is expressed as 9240-0 to 3 in Figure 27 (B) are FIFO4140
Write operation with reset write signal for -0 to 3
Reset the FIFO address before doing so. Also 93
20-0 to 3 are enable signals for the expansion interpolation circuit;
9340 is used for select signal of selector 4190
Select the enlarged interpolator. All from the area signal generator
The output can be expanded independently up to 4 for each area.
It is now possible to process. For example, the enable signal 9320-0 enables the enlarged interpolation circuit.
When circuit 4150-0 is enabled, expansion interpolator 4
150-0 read enable to FIFO4140-0
Outputs signal 9280-0 and receives image data from FIFO.
The receiver is set to perform enlargement processing. In addition, the true truth
In the example, the one-fire interval method is used. Other expansion interpolation circuits
Similarly, read to FIFO when enabled.
Issue an enable signal and read the FIFO data. No.
Figure 35 shows a timing chart. At this point, as mentioned above, the sequential
The image data read out is processed in parallel, and the final
Image layout is completed using selector 4190.
Then, each image data that has been processed in parallel so far is serialized again.
Al image data signal. By selector 4190
The image signal 9330 converted to serial image data is
The edge filter circuit 4180 performs edge enhancement and
and smoothing processing is performed. And L
through UT4200 and via signal line 9380.
4230. The selector 4230 has the bitmap memory data described above.
data <W and image data from memory are input. mosquito
The details of these two types of switching will be described later using Fig. 41.
. The image signal 9380 output from the selector 4230 is
The data is inputted as
a video enable signal generated from the area signal generator;
, and the clock are sent to the color reader l. Below, all image data formats of "Image O" to "Image 3" are shown below.
When the configuration is completed, next “Image 4” to “Image 7” and “Image
8” to [Image 11J, “Image 12” to [Image 15J]
The images are sequentially formed, and the "image O" shown in FIG. 34(A) is formed.
~ [16 images of image 15J are formed. As mentioned above, in this embodiment, 16 images are stored.
Lay out and print as shown in Figure 34 (A).
However, the number of images can be set arbitrarily. In addition, in the case of images from the SV recording/playback device 31, the SV flop
It is possible to print out consecutive images of the
It also functions as an index print. When printing this Sv index, please use the sv play
The method of achieving color balance differs depending on the camera model.
The difference in the environment at the time of the Sv left camera shadow, that is,
There are many differences in color temperature, etc., so it is difficult to adjust the color balance.
In order to correct this, this example automatically adjusts the color balance.
It has the functions that it has. This color balance function
AG in diagram H in Figure 47 or diagram 0 in Figure 50(a)
It works by pressing the C key. Details are explained below.
Ru. Data from multiple screens of image data stored in memory.
N pixels for each (l≦N≦total number of pixels), in this example, the total
Data is captured while importing a total of 256 pixels into the CPU4360.
The CPU 4360 processes the
Although the appropriate correction table is not shown in the figure, it is
Lookup table 4 by selecting or creating from ROM
Set to 110A-R, G, B. For example, select and set
If so, one of the curves from ■ to ■ in Figure 35 (B),
Mori M lookup table 4420R, G, B
Select and set one from ■ to ■ in Figure 35 (C). As will be described later, this also allows correction of the monitor display image. Next, select a correction table using the image data in memory.
We will explain how to choose. Next, selection of a correction table will be explained. Figure 35 (D) is the slope of Figure 35 (C) of the correction table.
Figure 35 (E) is a diagram for calculating the correction table.
FIG. 3 is a flowchart for determining the slope. First, the CPU 7 sequentially reads N pieces of image data in the memory 3.
While reading (step St), R, G, H signal values
Ri, Gi, Bi (l≦i in i-th pixel data
≦N) - The signal value is not saturated (for example, the image
If the data is 8 bits, pure white is 255 and black is O.
, not saturated means not 255) pixels
Extract data. This is Ri, Gi. If even one of Bi is saturated, the color of the original data
Since the data is out of balance, the color bar
This is because it is not possible to accurately determine the lance. In addition, sequential import of N pieces of image data in the memory 3
For example, this is done as follows. That is, multiple
For example, if 20 screens of data have been imported,
sequentially outputs color image data from each of these 20 screens.
This is done by sampling. That is, this example
In this case, data from multiple screens in memory 3 is averaged.
Hue among multiple screens by sampling
Even if the screen is skewed, the hue will be skewed.
Color balance correction that is averaged overall without being affected by the screen.
I can do the right thing. The minimum value among Ri, Gi, and Bi among the captured signal values
is the largest pixel RlG among N pixels,
Let the B component be RMAX, GMAX, BMAX (step
Step S2). The minimum value among Ri, Gi, and Bi is the
Represents the characteristics of raw data. In other words, for reddish pixels
The minimum value of Ri, Gi, and Bi is Ri. The pixel with the largest minimum value among Ri, Gi, and Bi
is the pixel with the weakest component representing the characteristics of the pixel data.
It is. Therefore, RMAX, GMAX, BMAX are
Ri, Gi, Bi of the pixel representing white in the SV image
Possible acid component. Maximum of RMAX, GMAX, BMAX
The maximum value is DMAX, and the difference between the maximum and minimum values is DSA.
(Step S3). DMAX is an image that is considered white.
It is the thinnest component among the basic R, G, and B components. D
If SA=0, the color balance of a pixel that is considered white (
This means that the white balance) is correct, but the DSA
, if 60C' is not present, correction is required so that DSA=0.
It is. Next, the Ri, Gi, and Bi of the N image data are
Calculate the respective average values AVER, AVEG, AVEB
. Then, the maximum value of AVER, AVEG, AVEB (7)
AVEMAX. The difference between the maximum value and the minimum value is set as AVESA (step S4
). AVEMAX is average pixel data (F)R,G. It is the thinnest component among the B components. With AVESA=0
If there is, the average density of 87 images will be achromatic, and to some extent
This shows that the colors are well balanced. this
is the epoxy used when printing transparent film with silver halide.
This is an application of Vance's theorem to 87 images. AVE
If SA=0, the color balance is out of order.
, correction is required to set AVESA=0. Maximum value DMAX of each component of white level, all image data
The maximum of the average values of Ri, Gi, and Bi of
value AVHMAX, white level chromaticity DSA, all image data
Members about the chromaticity AVESA of the average value of data
The ship function is 1-a shown in FIG. 35(D). 1-b, 1-c, and 1-d. Membership
The functions 1-a, 1-b, 1-c, and 1-d are
Each is registered in advance in ROM13 as a table.
It is. The CPU 7 changes the white level from the maximum value DMAX by l-a.
Find the grade of white level dependence WDMAX of brightness correction.
(Step S5). Maximum value of white level DMAX value
If is large, the white level will be set higher than the average value of all image data.
This means that the brightness should be corrected with emphasis. i.e.
, it was determined that a large DMAX indicates white.
It means that the pixel was actually close to white.
Ru. Conversely, a small DMAX means white.
The pixel that was determined to be white is actually a pixel that is far from white.
It means something. Therefore, from N image data
This means that it is not possible to emphasize the extracted white level.
. Next, by 1-b, the brightness is calculated from the average maximum value AVEMAX.
The grade of the correction degree WAVE is determined (step S6). The average maximum value AVEMAX is smaller than the center, and
The larger the value, the smaller the degree of brightness correction (the more
It means that In other words, the input image is
Performs correction to brighten the image when it is already dark
This may result in changing the characteristics of the input image more than necessary.
It becomes. Therefore, in this embodiment, AVEMAX is
If it is less than D1 of 6, gradually reduce the brightness correction degree WAVE.
On the other hand, if the input image is bright to begin with,
In this case, there is no need to brighten it any further, so
If AX is D2 or higher, gradually increase the brightness correction level WAVE.
In addition, by l-c, the color can be changed from the chromaticity DSA of the white level.
- White level dependence WDSA grade of balance correction
(step S7). White level chromaticity DSA
If the value is large, the white level may not be white.
data used for color balance correction.
emphasizes the average value of all image data rather than the white level.
It means. Next, by 1-d, the chromaticity of the average value of all image data is
Color balance correction degree WSA grade from AVESA
Find kudzu (step S8). Average chromaticity AVES
If the value of A is large (if the value of A becomes large, originally from Evans' theorem,
The image may be out of alignment, so color balance
This means that the degree of correction will be reduced. Furthermore, the CPU 7 determines the white level based on the white level dependence WDSA.
Ratio and average value of color balance correction using levels
Use to calculate the rate of color balance correction. Change
Then, calculate the color balance correction ratio by the sum of these values.
(Step S9). In step S9, DMAX
/RMAX is a correction term based on the R component of the white level,
AVEMAX/AVER is a correction based on the R component of the average value.
It is a term. Then, for each dependence WDSA, (1-
BALR by adding the weights of WDSA)
seek. BALG. The same applies to BALB. However, the color balance ratio BALR, BALG, BAL
B needs to be one of 1, so normalize it (step
510). Furthermore, from the color balance correction degree WSA
A color balance correction amount is determined (step 5ll). On the other hand, in the case of brightness correction, the CPU 7
Brightness compensation using white level from level dependence WDMAX
The brightness correction ratio using the positive ratio and the average value, all
That is, the brightness correction ratio AE is determined. In addition, brightness compensation
The brightness correction amount WAE is determined from the accuracy WAVE. here
When DMAX, which represents the white level, is set to 255, the average of all pixels is
so that the average value corresponds to 127 (i.e. 255/2)
do. and for each of the white level and average level.
Dependency WDMAX on the based correction amount, (1-WDMAX)
The brightness correction amount WAE is calculated by applying the weight. Then, the brightness correction amount WAE and the color balance correction amount
Color balance and brightness correction finally determined by product
Quantity γ3, γ. , γ8 represents the slope in FIG. CPU7 is the closest of (1) to (8) in Figure 35 (C)
Select the slope for R, G, and B and use the looka
Top table 4420R,G. Set to B. Corresponding to (1) to (8), Fig. 35 (B
) is also selected, and the lookup table 411
Set to OA-R, G, H. In this way, the method of this example
Are the R, G, and B image signals imported into memory from the PC?
R and G, which are considered to be the average value and white level. Find the B signal, and further calculate the average value and white level of R and G. Members prepared in advance from characteristic values obtained from B values
Find the grade using the -ship function, and depending on the grade
to correct image brightness and color balance.
This is what I did. Differences between manufacturers and models of SV cameras
Discrepancies in color balance and recording levels caused by differences in
It is possible to correct differences in brightness. Furthermore, it prevents over-correction.
The correction may be made due to slight differences in the level of the input image.
Extreme corrections such as being applied or not applied may occur.
It has the effect of preventing Therefore, the correction
It has a more natural effect. Create the LUT as above and print it out.
This allows for more faithful image reproduction (color conversion).
(referred to as Troll). The color balance function described above is the initial color balance.
The video signal input from the state (shown in Figure 49E)
Using Evans' theorem, R,G. It is to change the balance of B. For example, color balance
As a result, the redness (R) is strengthened and the blueness (B) is strengthened.
), the color balance display is as shown in Figure 49F.
It changes like this. After using this color balance function, the user
If you want to achieve the desired color tone, use the color shown in Figure 49A.
Change the color balance by pressing and operating the color balance key.
Is possible. How to operate this color balance is as follows.
Omitted as it will be explained later. In addition, in this example, when adjusting the color balance,
When sampling pixel data from multiple screens,
Automatically adjusts color balance across multiple screens stored in memory.
I try to adjust it dynamically. Therefore, depending on this example,
(Automatic adjustment of color balance is possible)
come. Film scanner 34 also uses an autochanger,
Automatically stores images one after another and prints 24 or 36 pages
Index print of film images by doing
is possible. Forming an image using a layout in any position〉Explanation above
can automatically form an image as shown in Figure 34 (A).
Although the control for developing and forming an image has been explained, this example describes the following.
This is not limited to the above example (you can place any image in any position).
It can also be developed to form an image. Below, as an example of this case, "Image 0" shown in FIG.
When "Image 3" is developed and formed as shown in the figure,
explain. First, control similar to the image input control to memory described above.
Color reader L or film scanner 34 or S
The four image information read from the v-recording/playback device 31 are
4060AR, 4060AG which are memory. 4060AB as shown in FIG. Then, operate the point pen 421 to detect the coordinates on the coordinate detection plate 42.
Specify and input the desired deployment position from 0. For example, development area
is specified and input as shown in FIG. The image forming process in this case is shown in the blocks of FIGS. 27(A) to (F).
The lock configuration diagram and the timing shown in Figures 38 and 39
This will be explained below with reference to a running chart. Figure 38 shows the image on the "lI" line shown in Figure 37.
Timing chart during image formation, Figure 39 is shown in Figure 37.
Timing of image formation on the “12′ line”
It is a chart. The ITOP signal 551 is output from the printer 2 in the same way as described above.
Forced 1. The system controller 421O receives this signal.
Start operation synchronously. Note that in the image layout shown in FIG. 37(A),
, "Image 3" is the color reader 1 or film scanner 34
Or the image from the Sv recorder/player 31 rotated 90 degrees.
It has become. This image rotation process is performed in the following steps. First, the DMAC (direct memory access) shown in Figure 27
access controller) 4060AR by 4380. Work memory 4390 from 4060AG, 4060AB
Transfer images to. Next, the CPU 4360
After performing known image rotation processing in the memory 4390
, the work memory 4390 by the DMAC4380
Images to 4060AR, 4060AG, 4060AB
will be transferred and image rotation processing will be performed. The layout is done by the digitizer 16, and instructions are input.
The position information of each image is stored in the video processing unit 1 in FIG.
2 to the image storage device 3 via the route described above.
It will be done. The above position information is transmitted to the CPU 4 via a signal line 9460.
360. The CPU 4360 uses the position information
Programming a domain signal generator based on
As mentioned above. The system controller that received the unfolding position information for each image
The controller 421O performs an enlargement/interpolation process corresponding to each image.
Operation permission signals 9320-0-3 and 4150-0-3
and counter enable signal 9102-0~3, LUT
Generates selection signals 4111A to 4111D and each selector control signal
However, the desired image can be obtained. At this time 8
When printing 7 images, L is
Configure UT. In the layout at any position in this example,
For example, counter 0 (4080-0) is
counter 1 (4080-1) is in image l, counter 2 (
4080-2) is image 2, counter 3 (40803
) operate corresponding to image 3. Controls during image formation on line “11” shown in Figure 37
The control will be explained with reference to FIG. Image memory 4060AR, 4060AG, 4060A
Reading “image O” from B is performed using counter 0 (40
80AO) from address “0” to address “0.5M”
(Storage area for “Image 0” shown in Figure 36)
vinegar. The switching of the output of this counter 4080A-0 to 3 is
, select under the control of counter controller 9141A.
This is performed by the controller 4070A. Similarly, when reading “Image 1”, counter 1 (40
80A-1) from “0.5M” address to “IM” number
The area up to the bottom (storage area of “Image l” shown in Figure 36) is readable.
Served. The timing of this readout is shown in Figure 38.
Shown as 60AR,AG,AB. The data of “Image 0” and “Image l” are stored in LUT411
Maskin via 0AR, 4110AG, 4110AB
is sent to the black extraction/UCR circuit 4120A, where the
Sequential color signal 92! It becomes O. This frame sequential color signal 921
O is parallelized by the selector 4120, and for each pixel
FIFO memory 4140-0゜4140-
Sent to 1. And system controller-7421
Enlargement/interpolation circuit from 0 to 4150-0.4150-1
Operation enable signal 9320-0.9320-1 is enabled.
When it comes to the expansion/interpolation circuit 4150-0.4150-
1 is FIFO read signal 9280-0.9280-1
is enabled and read control is started. FIFO memory 4140-0. 4140-1 is this
Signal 9280-0. Enlarge and interpolate with 9280-1
Transfer of image data to circuit 4150-0.4150-1
Start. And this enlargement/interpolation circuit 4150-0
゜4150-1, the digitizer 16 first indicates
Layout and interpolation calculations are performed according to the specified area.
. This timing is 9300-0°9300 in Figure 38.
-1. The “Image OJ” data that has undergone layout and interpolation calculations is selected by the selector 4190.
After passing through the edge filter circuit 4180, the LUT4
200 is input. After that, up to connector 455o
Since the processing is the same as described above, the explanation will be omitted. Next, referring to FIG. 39, “12” shown in FIG. 37(D)
”Explain the line timing. Image memory 4060AR, 4060AG, 4060
From AB to enlargement/interpolation circuit 4150-1.4150-2
The processing is almost the same as described above. However, in the “12 line,” “Image 1” and “Image 1”
Since "Image 2" is output, counter 1 (4080-
1) and counter 2 (4080-2), FIFO414
0-1, 4140-2, enlarged φ interpolation circuit 4150-1°
4150-2 operates. These controls are
This is performed according to a control signal from the controller 421O. As shown in FIG. 37, in the "12" line, "Image l"
and “Image 2” overlap. In this overlapping part
to image either image, or both.
The system controller 421 determines whether to form an image of
It can be selected by a control signal 934o from 0. The specific control is the same as in the above case. The signal from connector 4550 is colored by a cable.
- Connected to reader l. For this reason, color readers
4. The video interface 201 of
The image signal 205R from the image storage device 3 on the line path
is selectively output to the printer interface 56. Image storage device in image formation in this embodiment described above
Transfer processing of image information from printer 3 to color printer 2
Details are below with reference to the timing chart in Figure 40.
explain. As mentioned above, press the start button on the operation unit 20.
The printer 2 starts operating and starts conveying the recording paper.
Ru. When the recording paper reaches the tip of the image forming section, the IT
An OP signal 551 is output. This ITOP signal 551 is
, and sent to the image storage device 3 via the color reader l. The image storage device 3 stores each image file under set conditions.
Mori 4060AR. Image data stored in 4060AG and 4060AB
Read the data and perform the layout, enlargement, interpolation, etc. described above.
do the same thing. Memory expansion continuous shooting> The image data sent from the host computer 33 is transferred to the GP
Input via IB4580 and work memory 4390
The image is expanded once and written to image memories A, B, C, and D.
It is read out in the same way by the above-mentioned means, and printed on the printer.
output. For example, as shown in Figure 43
The image transferred to the image storage memory is shown in Figure 27 (C).
It is read out by the counter O (4080A-〇) shown.
If the memory area is
) is printed in the area of image 0. In addition, layout coordinate information and enlargement can be obtained from the host computer.
By sending magnification and print commands,
It supports image formation with any layout as well as the
This can be done by computer control. Furthermore, since the magnification ratio can be set arbitrarily, printing paper
It is possible to obtain an enlarged output image beyond the limitations of . Figure 37 (G) shows, for example, that images stored in memory are printed on four
The following is an example of enlarged printing after dividing into two sheets of paper.
(referred to as continuous shooting). Details will be explained below. FIG. 37(F) is the counter 040 shown in FIG. 27(C).
stored in the memory area read by 80A-0.
FIG. Stored in memory according to magnification and paper size as shown in the figure.
The territory can be divided arbitrarily. host compilation
When the enlarged continuous shooting command is received from the computer, the CPU is
Calculate memory division size from paper size and magnification
and set the system controller and read counter to 0.
set. In the figure, the division size is a in the H direction and b in the V direction.
These are used to calculate the first address that the counter reads.
I can stay. Also, for simplicity, in the figure, each of the four divided areas is
It is designed to support 4 printouts. Image formation processing is performed using the ITOP signal 551 shown in FIG.
is started and the counter is sent from the system controller 421O.
By tie enable signal 9102-0,
The image is read out, enlarged, and sent to a color reader.
Ru. The read counter starts reading the next line after reading is completed.
Calculate the start address of the file and repeat the readout b
Reads up to the line and finishes printing the first page.
Ru. 2 until the second ITOP signal 551 arrives.
Calculate the first address 2 of the sheet, repeat sequentially and count the first address.
Continuously print up to the fourth page while counting. lastly
The enlarged image is enlarged by stitching the printed images together.
It is now possible to obtain images with <Non-rectangular image synthesis using memory E> Next, non-rectangular image synthesis processing using bitmap memory E
I will explain about it. For example, as shown in FIG. 37(B), the output area of image 0 is
A case of outputting a heart-shaped composite on a document will be explained. As mentioned above, first determine the size of the area of image 0 that you want to output.
Taking into consideration, a heart-shaped binary image is stored in Bitmap memory E.
expand. Next, as in the previous section, use the color reader l to
Specify and input the image development area using the digitizer 16
. At this time, click the non-rectangular area selection button for image O only in C.
Select from the operation panel. Location information for each of these specified images
The information and processing information is sent to the first video processing unit 12.
The image is sent to the image storage device 3 via the image storage device 3. The information sent is
, the signal line 9460 is read by the CPU 4360,
Program the image output timing based on this information
What to do is as already stated. When the I-TOP signal from the color reader is received, the image is recorded.
The storage device 3 starts reading the image from the memory, and the 27th
Image synthesis is actually performed when passing through the selector 4230 in the figure.
It will be done. FIG. 41 shows an internal outline of the selector 4230 in FIG. 27(B).
It is a schematic configuration diagram. 301O is the register that takes register 1.
bit by controlling the data set in the star.
8bit density data or BI times from tomap memory
The signal can be selected programmably from the CPU. 3020
．． 3030 is a gate for such selection. For example 8b
When the concentration data of it is selected, the OR gate 3040
The image signal and bitmap are combined. On the other hand, when the Bl signal is selected, the selector 3050 select signal
number, and the register shown at 3050 is entered with the Bl signal.
The image data of the density of the data to be set and the image from memory are
Image data 9380 can be selectively output. When performing non-rectangular image composition, register 2 is normally set to “O”.
” (.Image data 938 that is read out sequentially
0 is the non-rectangular area signal B output from the bitmap
The selector 3050 is used as the l select signal to select a non-rectangular shape.
This enables the synthesis of hollow, non-rectangular images. The above BI double signal is sent alone to the color reader
It is also possible to perform processing using the Bl signal in the carder l. In other words, the video interface of the above-mentioned BI multiplied signal in Figure 2
used as the signal 206 input to the base circuit 201, and
The video interface circuit 201 is configured as shown in FIG.
If used in the
I can do it. In addition, in this embodiment, the reader 1 reads
The image storage device 3 stores the color images in real time.
It is also possible to combine images. In other words, as mentioned above, the ITOP signal of the color printer 2
551, the image is read from the image storage device 3.
However, at the same time, color reader 1 also receives the above ITOP signal.
Full color sensor for reflective original 999 in synchronization with 551
Reading starts at 6. Color reader 1 processing is above
Since this is the same as described above, the explanation will be omitted. The image information from the image storage device 3 mentioned above and the color
Synthesis with the image information from the data is performed at the timing shown in Figure 37 (C).
This will be explained below with reference to a running chart. Figure 37(C) shows images 0 to 4 in Figure 37(A).
The other parts of the reflective original read by beamer 1 are
Reflection original 999 in 11 when combined and image memory
3 is a timing chart in which signals from device 3 are synthesized. Color correction read out in synchronization with ITOP signal 551
The image information of the radar L is the output signal 5 of the point correction/white correction circuit.
59RGB, H8YNC at 11 in Figure 20
is output in sync with. Also, from the image storage device 3
The image information 205RGB is indicated by the digitizer 16.
Only the area that was filled in is output. These two types of image information are
input to the digital interface 101 and the digitizer 1
The image of the color original is synthesized by the circuit except for the area specified in step 6.
Area output from 115 and designated by digitizer 16
The information from the image storage device 3 is output. In the above embodiment, as a means of setting a non-rectangular area, the desired
Prepare a mask pattern of the shape of the area in advance,
By loading it into the reader, Bitmatupume
It was expanding rapidly. Furthermore, in this embodiment, as shown in FIG. 27 (D-1),
Connect the bitmap memory to the CPU bus and
mask pattern can be developed in bitmap memory.
I have to. For example, frequency of use of star, diamond, hexagon, etc.
In the case of a standard mask pattern that seems to have a high
or a program that generates data on a CPU processor.
Stored in gram ROM or font ROM4070
Leave it as it is, and when you use it, start the program and automatically
A mask pattern can be generated automatically. In the above configuration, a mask pattern is created and read.
Easily store mask patterns in bitmap memory without the need for
can be created, and an image like the one shown in Figure 37 (B) can be created.
Synthesis can be carried out even more easily. Further, in this embodiment, for example, from the computer 33,
The CPU 4360 generates a sentence from the sent code data.
Font ROM 4070 shown in Figure 27 (D-1)
Bitmap memory that refers to the character font and shows the character font in E.
It can also be expanded upwards. In this way, you can freely store character fonts in bitmap memory.
can be written, and furthermore, the AND of Fig. 41 mentioned above can be written.
Activate gate 3020 and AND gate 303
0 is inactive, image data 9380 and bitmap
The image on the memory is combined using the OR gate 3040.
Character composition with various stored image data
can be done easily. In addition, the CPU 4360 executes, for example, a bang generation program.
By starting the program, bitmaps can be added to the borders etc.
can be written to, and it takes as shown in Figure 37 (D).
It is also easy to combine ruled lines and image data. Various other
A fixed pattern can be stored as a CPU program.
. In addition, fonts written in advance in bitmap memory
Combine character data and image data from ROM4070
As shown in FIG. 37(E), each of the steps shown in FIG.
Now you can get an image with a message on the bottom of the image.
It has become. As mentioned above, these characters
Send the character code from the host computer to the
It is also possible to read the set from the reader
It is also possible to leave it as is. Explanation of the monitor TV interface
The stem is connected to the image memory in the image storage device as shown in Figure 1.
The contents of the log can be output to the monitor television 32. Also
, it is also possible to output video images from the Sv recording/playback device 31.
It is possible. This will be explained in detail below. Image memory 4060AR. Video images stored in 4060AG and 4060AB
The image data is read out by DMAC4380 and
Ispray Memory 4060M-R, 4060M-G. 4060M-B and stored. On the other hand, as described above, the system controller 421
Controls the control signal output from 0 to each memory
By storing the desired image in the image memory,
At the same time, it can also be stored in the display memory M. In addition, FIG. 27 (E
) as shown in the display memory 4060M-R,4
Video images stored in 060M-G and 4060M-H
Image data is LUT4420R, 4420G, 4420
D/A converters 4430R, 4430G through B,
4430B, where the display controller
Alerts in synchronization with the 5YNC signal 4590S from the controller 4440.
Analog R signal 4590R, G signal 4590G, B signal
It is converted to 4590B and output. On the other hand, from the display controller 4440, these
Synchronizing with the output timing of the analog signal of S Y
An NC signal 9600 is output. This analog R signal
4590RSG signal 4590GSB signal 4590B. By connecting 5YNC signal 4590S to monitor 4
The contents stored in the image storage device 3 can be displayed.
. In addition, in this embodiment, the host computer shown in FIG.
4580, GPI shown in FIG. 27(B) from the computer 33
Control to image storage device 3 via B controller 4310
The displayed image can be adjusted by sending commands.
Rimming is possible. The CPU 4360 is controlled by the host computer 33.
Based on the input area information, the data is
Spray memory 4410R, 4410G. From 4410B to image memory 4060AR, 4060AG
. By transferring only the valid area to 4060AB,
Rimming is possible. Also, in response to area instruction information from the host computer 33,
Accordingly, the CPU 4360 shown in FIG. 27(B) is
Comparators 4232, 4233 and RAM 421
Set the data in the same way as in the case described above in 2, and try again.
Input image data from color reader 1 or Sv recording/playback device 31.
The cropped image data can be converted to 40
Can be stored in 60AR, 4060AG, 4060AB
I can do that. Next, image memory 4060R, 4060G, 4060B
If multiple images are stored in the color printer 2
The layout of each image when recording with Monitor TV 3
2 and the host computer 33. First, display the size of the recording paper on the monitor TV 32, and
Host the laid out location information of each image while looking at the display.
By inputting data through the computer 33,
- It is possible to layout each image recorded with printer 2.
Ru. Image memory at this time 4060AR, 4060AG, 4
Reading of stored information from 060AB to color printer 2
The control and recording control on the color printer 2 are as described above.
Since this is the same as the embodiment, the explanation will be omitted. Description of computer interface゛ of this embodiment
The system consists of a host computer 3 as shown in FIG.
3, and is connected to the image storage device 3. Figure 27
Interfacing with the host computer 33 using (B)
Describe the face. The interface with the host computer 33 is a connector.
GPIB controller connected by Kuta 4580
4310. GPIB controller is CPU
Connected to CPU4360 via bus 9610
, host computer 33 according to a determined protocol.
It is possible to exchange commands and transfer image data with
Ru. For example, from the host computer 33 via GP-IB,
When image data is transferred using
The receipt is accepted by the GP-IB controller 4310.
, - are stored in the work memory 4390. stored
Data is transferred from the work memory to the image storage memory AB,
DMA transfer to CD and monitor display memory M
Then, a new data is sent from the GP-IB controller 4310.
The receiver receives the data and transfers the image by repeating the above steps.
ing. Figure 42 is the work memo shown in Figures 27 (A) and (B).
memory 4369, image storage memory A-C, and monitor data
A block diagram showing the relationship of the spray memory M is shown. In addition, in FIG. 42, each component of the embodiment is shown.
The numbers have been renumbered. From the host computer 33
, First, the image size to be transferred is sent. sand
That is, input terminal 2401. GP-IB controller 24
02 from the host computer 33 to the CPU 240 via
The image size corresponding to 3 is read. Next, the image data
is read line by line, - time work memory 2404
is stored in The image data stored in the work memory is
, DRAM controller 2405 (hereinafter referred to as DMAC)
image storage memory 2406. display memo
are sequentially transferred to R 2407 (for simplicity, R,
G and B are grouped together). Details below
Explain. Image storage memory 2406. display screen
For example, the memory 2407 inputs an address as shown in FIG.
allocated and the image is stored. In the figure, in the H direction
The upper address corresponds to the lower address and ■ direction. For example, point A is 100H in the H direction and 100H in the V direction.
Then, the address of point A becomes 1001001-1. Similarly, the display memory also has lower address, ■ direction.
The upper address is assigned to . Here, for example,
The incoming image is stored in the image storage memory 2402 at the same size,
Reduced to 3/4 and transferred to display memory 2407
It shall be. First, as mentioned above, the host computer sends
The image size and reduction rate of the image are set in DMAC.
On the other hand, the DRAM controllers 2408 and 2409
is the storage start address and the image size when reduced
is set. After completing the above settings, the DMA is executed by the CPU.
A command is sent to the C2405 and image transfer begins.
. The DMAC 2405 adds addresses to the work memory 2404.
The image data is read by giving the response and ■ signals. At this time, the address is incremented sequentially, and l
When the reading of H is completed, the host computer
The next line is picked up and stored in the work memory.
. Meanwhile, at the same time, the DRAM controller 2408.240
9 was given R Sogo and l0W2 by DMAC, and in turn
Image data is now written. At this time,
DRAM controller 2408.2409 sends gate 1 signal
Count and write from the first address set above
The address is incremented sequentially. H direction writing
The address in the V direction increments when the loading is completed.
Then, writing starts from the beginning of the next H. When the above transfer is performed, the DMAC will rate the DI
It has a similar function to a multiplier and therefore r?
Reduction is achieved by thinning out 5”W.For example, the front
If you set the reduction to 3/4 as described above, the DMAC will be
For the H direction, thin out ■1 every four times, and for the ■ direction.
For every 4 lines! Don't give out the section of the line.
As a result, the memory is
Reduction is performed by controlling writing. FIG. 44 shows a timing chart. Read as shown
The output address is input to the work memory 2404, and ■
The signal causes data to appear on the data bus. write at the same time
The current address is input to the storage address, and the "σW times signal
More data is written. At this time, if the 1st signal is thinned out, write as described above.
Write addresses are not incremented or written to.
It is no longer done. <Explanation of man-machine interface> The system of this example
As mentioned above, the system (Figure 1) is a host computer.
33 and can be operated from the operation section 20 of the color reader l.
It has become. The following is a man-machine interface using this operation unit 20.
Let me explain about this. In the color reader l, press the external device key (
By pressing 20-2), the diagram A in Figure 47 is operated.
displayed on the liquid crystal touch panel of section 20. FIG. 47 shows the color reader 11 to the image storage device 3.
from the film scanner 34 or the Sv recording/playback device 31.
FIG. 6 is a diagram showing operations when storing image data. When you press the image registration key in Figure 47A, the LCD touch panel
It looks like C, and is surrounded by the broken line shown as X in the C diagram.
Select the input source displayed in the area using the Imperial key
. In this embodiment, the input source is the color reader 11 screen.
There are three types: Lumskiyana 34 and Sv recording/player 31.
These are selected by operating the rice field key. This situation
Shown below in Figure 0. Next, press the image number key in Figure 0 to proceed to the next step. In the case of figure D, an image is already stored at the specified image number.
Indicates when The image shown in D is shown in FIG.
Displayed by turning on the area shown in . E diagram
, G11l, H figure shows input source selection (Ql) of figure 0.
If the color reader is selected from
If you have selected the film scanner 34, please refer to figure E.
In the figure, when the Sv recording/reproducing device 31 is selected, the diagram becomes H diagram. When you select image registration for color reader l, the screen shown in Figure 47E appears.
The state shown is shown. In such a state, the digital
Color correction with Iza 16's Bointing Pen 421.
The reading error of the original 999 on the platen glass 4 of the printer L
Instruct the rear. When this instruction is completed, the F diagram will be displayed and confirmed.
A diagram for is displayed. There is a change in the reading area
If so, press the key to return to diagram E and set again.
can be determined. When the reading area is OK, press the t+ key to display diagram G.
Next, set the amount of memory to be used. The bar graph of the memory amount in diagram G is a memo in the image storage device 3.
By installing the report (memory AND in Figure 27 (A))
The length of the bar graph changes. The image storage device 3 is the memory board (memory A-D) mentioned above.
) can be installed from one to a maximum of four. In other words, the bar graph is the longest when four memory boards are installed.
becomes. The bar graph in figure G indicates the memory capacity in the image storage device 3.
In addition, you can also set the amount of memory used when registering images.
Ru. Determine the amount of memory used for registration using the country/date key, and
By pressing the start key, the document scanning unit shown in Figure 1
11 is scan 1, and 999 originals are read. The image information from the document scanning unit 11 shown in FIG.
processed by the video processing unit 12 through the cable 501.
After that, the image is displayed via the video interface 201.
Output to image storage device 3. Image storage device 3 stores input images.
The image information is displayed on the monitor television 3. Storage method in the memory of the image storage device 3 (Figure 27 (C))
are the same as those described above, so they are omitted. As mentioned above, the memory amount setting for the G diagram can be made variable.
, even when storing images in the same area, the amount of memory set
By using a large amount of memory, it is possible to store images with high quality.Also, by using a small amount of memory, it is possible to store many images.
It is also possible to input. Next, image registration from the film scanner 34 is shown in Figure G.
The registration method is the same as for color reader l.
Since they are similar, detailed explanation will be omitted. If you select image registration from the Sv player 31, the fourth
The display will be as shown in Figure H in Figure 7, and the direction of rotation will be changed before registration starts.
Whether it is registered or not, AGC (auto gain control and
(7) ONloFF. and field/frame settings. The above settings
After that, press the registration start key to start the Sv recording/playback machine.
The image storage device 3 stores the image information from 31 in the memory (Fig. 27).
(C)) The method of storing images in memory is as described above.
It is omitted because it is the same as the previous one. FIG. 48 shows a color print from the memory in the image storage device 3.
This section shows how to print a layout to a printer.
It is a diagram. Figure 0 in Figure 48 selects three layout patterns.
This is the operation display. Fixed pattern layout is a predetermined pattern.
Print out the contents of the memory of image storage device 3 on the screen.
It is something to do. The free layout is based on the digitizer 16 shown in FIG.
Indicate the area to be printed using the point pen 421
and prints the memory contents of image storage device 3 in that area.
It is something to be done. The composition is performed using the point pen 4 of the digitizer 16 shown in FIG.
The memory of the image storage device 3 is placed in the area indicated by 21.
The area other than the area specified for writing the memory contents will not be colored.
Combine images of original 999 on the platen glass 4 of the printer
and print it out. If the fixed layout is selected, the
Therefore, the number of print pages in fixed layout printing is
Make settings. Each image area of fixed layout has A-P.
Image area names are given, and each area (A-P)
Using the image numbers corresponding to Figures 48, E, and F, respectively.
and configure settings. For example, in the 48th diagram, 16 screens
When selected, the display shown in FIG. 48E is displayed. For example, if you select the area shown in A in Figure 8, the next screen will be displayed.
moves to the diagram shown in F, and displays the image to be formed in the set area.
Set the image number using the numerical keys in FIG. mosquito
By repeating this specification, multiple images can be registered.
I can do it. The number of images to be registered is shown in Figure D.
automatically determined according to the type of fixed pattern selected.
It will be done. When these settings are completed, the color reader's CPU
For example, depending on the type of external device selected in Figure B.
For example, if Sv, the desired image selected on the F diagram of the Sv player
The image corresponding to the surface is stored in the storage device 3. Next, the start key (not shown) of the operation unit 20 in FIG.
Prompts you to specify the corresponding image number. Then the specified number
The fixed layout is fixed by pressing the switch on.
A hard copy is output from the printer 2. Fixed rail
The image output on page 16 of the Ioutprint is shown in Figure 34.
The layout will be printed as shown. Regarding the free layout print shown in Figure 48-1
I will explain. First of all, free layout printing
Each area is marked with the point pen of the digitizer 16 shown in Figure 23.
Each area is set in turn using the button 421. each at the same time
Enter the image number to be printed in the area using the numeric keypad shown in figure L.
and select. After setting each area, start the operation section 20 in Figure 1.
By pressing the key (not shown),
The memory contents of image storage device 3 are printed in the set area.
be outed. The composite layout shown in Figure 48G is based on the above-mentioned free layout.
The layout and area settings are the same. The reflective original image is output for areas other than the color ink area.
A color image is output. Figure 49 shows the state shown in Figure 47A.
If you turn on the "Monitor display" key, that is, the monitor
In the display operation on the television 32 and in the state shown in the reading diagram
If the "Color Balance" key is turned on, that is, the image
The image information in the image storage device 3 is printed by the color printer 2.
This section shows the operations for adjusting the color tone of each image when printing out.
vinegar. When you press the monitor display key in Figure 49 A, a table like Figure 0 will appear.
Select the image number of image storage device 3 and monitor
Select either display on TV 32 or source display.
Ru. The details are omitted as they have been described previously. By pressing the color balance key in Figure 49A,
As shown in the figure, enter the image number for setting the color balance.
select. When you select the image number, the LCD touch panel will display E.
The display will be as shown in the figure, and the colors will be red, green, and blue.
A corresponding bar graph will be displayed. press red country key
The left side of the bar graph indicates a red luminance signal in terms of electrical signals.
The red color shown on the monitor works to amplify the
Ingredients become diluted. This is the monitor memory in Figure 27 (E).
Lookup table (LUT) 4420R within. The monitor screen can be adjusted by changing the G and B curves.
While changing the color of the label, the look in Figure 27 (C)
backup table (LUT) 4110A-R. -G and -B curves are also changed. i.e. color
Communication from the reader's CPU to the CPU in the image storage device
is performed, and as a result, such LUT rewriting is performed using image memory.
This is performed by the CPU within the device 3. As mentioned above, 2
Monitor display by changing the LUT of seeds at the same time
Printed from color printer 2 with the same color tone as the image being printed.
It is possible to log out. Figure 50 (A) shows the "hour" key in the state shown in Figure 47 A.
FIG. 4 is a diagram showing an example of a display displayed when the button is turned on. Kaka
"Sv" in the display shown in B of Figure 50 (A).
It is a figure which shows the example of a display when a key is turned on. That is, S
Contents of the floppy disk played by the v-recording/playback device 31
operation to display on the monitor TV 32 and color printer
This is an operation for printing out from 2. Figure 0 in Figure 50 (A) is an index display or an index display.
The operation for selecting a print sprint is shown below. The Sv disc has 50 field recordings and frame recording.
It is possible to record 25 pages. AGC key is auto gain
Control and color control 0N10FF key
- is. Figure 50 (A) Displays in Figures D When you press the start key, the
In the case of HDD recording, the first 25 screens of the Sv disk are monitored.
By pressing the display start key in diagram E,
The latter 25 screens are displayed. This situation is shown in Figure 33 (C
). In such a case, the CP in the image storage device 3
U puts the Sv regenerator in the remote state. In such a case, the color reader's CPU is an image storage device.
Images of multiple tracks from the Sv player to the CPU within 3
generates an instruction to store sequentially in memory. Then, the picture
The CPU in the image storage device 3 issues the following instructions to the Sv player.
generate an indication. That is, 5 recorded on the Sv disk
The first 25 screens of the 0th screen are stored in the memory of the image storage device 3 in order.
Let me remember next time. In addition, in such a case, the image storage device f3 is transferred to the Sv playback device.
It is only necessary to give an instruction to move the head. Specifically, before storing the image signal in the image storage device 3,
, the playback head of the Sv player is positioned at the outermost circumference of the Sv disc.
Access the rack and then play from the outermost track
The video images to be recorded are stored in the storage device 3 as described above.
Let me remember it. Next, the CPU of storage device 3 is the Sv playback device.
Move the playhead one track inward for
Output instructions. The image storage device 3 then transfers the video image back into the storage device 3.
stored in memory. This operation (repeatedly)
Therefore, the image storage device 3 sequentially stores the image signals in the memory.
and create a multi-index screen in internal memory.
. In addition, in the case of frame recording, press the display start key shown in figure D.
By pressing , all Sv disks are displayed. Figures F and G in Figure 50 (A) are among the indexes mentioned above.
This is an operation to print out the content from color printer 2.
Ru. After making the settings shown in Figure F, press the start key on the operation panel 20.
As a result, as described above, the image storage device 3 first
25 screens worth of images are stored in the memory from the v-recording/playback device 31.
do. At this time, the image storage state in the memory is shown in Figure 33 (B
). Then, use the color printer via the color reader l.
Perform index printing with printer 2. The same goes for diagram G.
Due to this, the explanation is omitted. As mentioned above, the operations shown in Figure 50 (A) F and G can be performed.
This makes it easy to register images and print layouts.
It is possible to do so. An example of the index print output is shown in Figure 34 (B).
. Figure 34 (B) is the 2 stored in Figure 33 (B).
In addition to outputting the images of 5 screens, the data in the image storage device 3 is
Note in Figure 27 (A) created by CPU4360
Characters written to the memory (bitmap memory)
It also outputs the K line. Figure 50 (B) and Figure A select the layout of Sv.
The operation for selecting the type of combination Sv layout is shown. The Sv layout is the desired image and ray in Figure 50(B).
After completing the ARAAT settings, press the start key on the operation unit 20 (Fig.
) to read images from the playback device.
image, store the image in the memory in the image storage device 3, and record it.
Image formation is performed on color printer 2 according to the layout instruction.
. Fixed pattern layouts are preset indexes.
Read out the image from the Sv fish from the Sv player and record the image.
Fixed pattern determined after being stored in the memory of storage device 3
This is a printout that can be printed out. Free layout is a pre-specified index.
The image is read out from the Sv playback device, and the image is stored in the image storage device.
After storing it in the memory of 3, the digitizer 16 of FIG.
in the area indicated by the pointing pen 421 of
It is to be printed out. The synthesis is performed from the index specified in advance to Sv
Read the image from the playback device and store it in the memory of the image storage device 3.
After memorizing the digitizer 16 in Figure 23,
87 images in the area specified by the pen 421.
Composite the image of the reflective original with other areas of the image and print it out.
It is something to do. If fixed layout is selected, B in Figure 50(B)
Print side in fixed layout print by illustration
Set the number. A for each image area in fixed layout
-P image area names are given, and each area (A-
Figure 50 (B) for each index mark corresponding to P).
Make settings using glue and diagram E. For example, Fig. 50 (B
), if you select 4th screen, the 50th
The display shown in Figure 0 of Figure (B) is made. For example in diagram C
When you select the area shown in A, the display will then change to the diagram shown in D.
87 images to be formed in the set area.
Figure 50 (B) glue, the value in Figure B
Set using the key. By repeating such designation,
Then, the index Nα of the plurality of 87 images is specified. Next, by pressing the start key on the operation unit 20, the above
87 images with the set index are stored in the image storage device 3.
Import and print out in a predetermined area
do. This procedure will be explained using FIG. 50(C). Press the start key on the operation section 20 on the color league side to start the color.
A registration request is sent from the color reader l to the image storage device 3. The image storage device 3 stores data corresponding to the specified index.
Send the tracks of the sv floppy of the sv player 31 as shown below.
In other words, it instructs to change the track being played, and
Image information corresponding to the index is stored in memory. The image storage device 3 stores the index set by the operation unit 20.
After registering all images corresponding to Kusu Island, colorize
Send a registration completion message to the reader. Color reader l has image print area for each index
, that is, when the layout information is sent to the image storage device 3.
Sends a start request signal to both. The image storage device 3 receives the synchronization signal from the color printer 2.
At the same time, send the Sv image information to the specified position using the color reader.
Send to 1. The color reader l reads the image from the image storage device 3.
After processing the information, it is sent to color printer 2 and printed in image form.
to accomplish. About the Sv free layout shown in FIG. 50(B)
explain. Sv free layout is a rectangular area layout and non-
A rectangular area layout is possible. First, I will explain the free layout of the rectangular area,
Next, the layout of the non-rectangular area will be explained. Also
These rectangular and non-rectangular areas are mixed and output during image formation.
It is also possible to The Sv free layout of the rectangular area starts with the second
The point pen 421 of the digitizer 16 shown in FIG.
to specify the area. Next, H in Figure 50 (B)
indicates the Sv index Nα as shown in FIG. By repeating these instructions, multiple 87 images can be created in one row.
Indicate the layout position and the corresponding index magnet. Next, by pressing the start key on the operation unit 20, the above
87 images of the set index blood are stored in the image storage device 3.
import and print using predetermined layout information.
Lint out. For details, refer to the fixed layout application mentioned above.
It is omitted because it is the same as the The Sv free layout of the non-rectangular area is shown in Figure 50 (B).
It functions by pressing a non-rectangular key in the F diagram. non-rectangular
There are four types of shape area settings: circle, oval, R rectangle, and free.
Selectable. These selections are shown in Figure 50 (B).
Select by. When laying out a circle, set the center of the circle to figure 0 in Figure 50 (B).
As shown in the figure, the point pen 421 of the digitizer 16
I instruct. Similarly, specify the radius of the circle as shown in figure P.
After displaying the Sv index, press the OK key.
According to H or 1 of Figure 50 (b) selected by the cous fish
select. Here, the information of the circle indicated in Figure 0 and Figure P of Figure 50.
passes through the signal line 505 from the digitizer 16, and the color
The data is stored in the bitmap memory 91 of the printer 1. Next, by pressing the start key on the operation unit 20, the above
87 images of the specified index fish to the image storage device 3
Import, bitmap memory 91 of color reader 1
From the position and size of the circle stored in the image storage device
3 performs layout and scaling, and color reader Sv
transfer image information. Color reader 1 is a bitmap that stores circle information.
From the block memory 91, the circle is synchronized with the color printer 2.
Outputs the area signal and sends it to the video processing unit of color reader 1.
The synthesis circuit 115 in the cut 12 is switched. outside the circle area
In this case, the synthesis circuit 115 outputs 0OH (white) and the area
In the case of , output the image information from the image storage device 3 and
transfer to printer 2. This situation is shown in Figure 50 (D
). At this time, the image storage device 3 stores the bitmap memory 91.
The diameter of the day information is the shorter of the aspect of the image information to be output.
Change the magnification so that it is equal to the length of . As shown in FIG. 50(D), from the image storage device 3,
The output image is divided into circles according to the bitmap area information.
The image is cut out and an image is formed on the color printer 2. Next, a non-rectangular free layout will be explained. In Figure 50 (B), press the free key.
It works by The free layout is a digitizer 16 point pen
421 by tracing the top surface of the digitizer 16.
That information is the bitmap memo of Color Reader L.
It will be written to Re91. This situation is shown in Figure 50 (D).
show. The image formation process is similar to that for the circle described above.
I'll skip it. The Sv composite print shown in Figure 50 (B)
I will explain. The layout area can be specified using the free layer mentioned above.
Like layout, rectangular areas and non-rectangular areas are possible.
Ru. The designation of the layout area and the designation of the index Nα are as follows:
This layout is omitted because it is similar to the Sv free layout described above. Next, by pressing the start key on the operation unit 20, the above
The 87 images with the set index Nα are stored in the image storage device 3.
Both SV images are captured inside the predetermined area.
The image of the reflected original 999 on the original platen 4 in Fig. 1 is placed outside the area.
Combine and print out. Above, S■ index display, Sv index print
I explained about the Sv layout print, but this
An operation that combines these will be explained. The operation flow is shown in FIG. 50(E). This flowchar
To select the index magic during Sv layout
Sv index display or Sv index print
This shows the operations performed using . First, in order to perform the Sv layout, as shown in Fig. 33 (C)
Sv index display shown in Figure 34 (B)
Perform Sv index print. Next, enter the operation to perform Sv layout, and fix Sv.
Layout, Sv free layout, Sv composite layout
Make a selection. The details are omitted as they have been described above. The image of each layout area is the Sv index mentioned above.
Select by screen display or Sv index print.
, shown in Figure 50(B)D,E,H,1. in
Do the dex fish instructions. At this time, the image information of the Sv jacket is changed to the S■ index.
The screen display or Sv index print
The image is formed on the monitor or copy paper.
It is possible to specify a desired image. Repeat this operation to store multiple images in memory.
Afterwards, press the start key on the operation unit 20 to display the image.
Perform formation. Since image formation has been described above, it will be omitted. Control by host computer> The system of this embodiment is controlled by a host computer as shown in Figure 1.
It has a computer 33 and is connected to the image storage device 3.
. The interface with the host computer 33 is shown in FIG.
Describe the interface. The interface with the host computer 33 is a connector.
GP-IB controller connected by Data 4580
431O. GP-IB controller 431
O is connected to CPU4360 via CPU bus 9610
The host computer is
Exchanging commands and transferring image data with the data controller 33
It is possible. The image data of the color reader l and Sv recording/playback device 31 is
GP-IB controller connected by connector 4580
controller 4310 to the host computer 33.
, stored in the storage area of the host computer 33 and expanded.
Enlarge/reduce processing or cut out one part of image data
, layout of multiple image data has traditionally been
It was done. However, in that case, the amount of color image data
has a considerably large capacity, so general-purpose devices such as GP-IB
Also through the interface for color reader l. Data between the Sv recording/playback device 31 and the host computer 33
The data transfer time is very long. So, the host
The input image data is directly sent to the computer 33.
(Determined by host computer 33)
Send command to GP-IB controller of image storage device 3
, CPU 4360 decodes the instruction and reads the color reader.
1 and the input image data of the Sv recording/playback device 31, and
By specifying only the image area you need, other parts can be saved.
minutes are not stored in memory, making efficient use of memory and
image data without having to transfer it to the storage computer 33.
nothing. Also, the input screen is inputted by commands from the host computer 33.
Store the image data in the storage area of the host computer 33
Even if not, the image memory bag M3 can store the image memory 4060A.
-R, 4060A-G, 4060A-B have multiple image data
It is possible to memorize the data and layout of each image.
Image processing such as enlargement/reduction is performed on the host computer 33 side.
(or only commands from the host computer)
Then, the CPU 4360 of the image storage device 3 executes the processing and instructions.
The display is performed on the input image data, so the host computer
Image transfer time between computer 33 and image storage device 3
This makes it possible to reduce processing time.
There is. As mentioned above, according to the instructions from the computer 33,
, how the image storage device 3 stores input and output images,
We will explain in detail how to handle it. All input and output image data stored in the image storage device 3 is
and is handled as an image file in the image storage device. Therefore, the image registration memory memory A (4060A
), Memory B (4060B), Memory C (4060C
), memory D (4060D) is a RAM disk.
At that time, the image file to be stored is
Image file management table 43 using the file name as a key
61 (Fig. 51). Image storage where image files function as RAM disks
When registered and stored in device 3, the registration memory
A basic block in which each of the memories 7A-D is divided into multiple parts.
The minimum image file management unit is the image file. The CPU 4360 uses the image file management table 4361
Therefore, by combining several of these basic blocks, one large
You can also manage to configure large image files.
Ru. At that time, the image file name and the image data size
, file protection, management of registration memory configuration, etc.
All data is stored in the image file management table 4361.
It will be remembered at the time of registration. The image storage device 3 generally stores images in a reader as described above.
- When inputting from l, the image is the same size or reduced
Register it as an image file in the storage device. Therefore
, if you increase the size of the image to be registered and register it, it will be easier to read.
The original size of the original image from the printer is approximated and reduced.
Since the fractional ratio will be smaller, print that registered image file.
When outputting to a computer 2, etc., the quality improves. The CPU 4360 controls input devices such as reader 1 and the computer.
key when inputting image data from the computer 33.
The image file name is determined by the command of the computer 33.
File names are given in the structure shown in Figure 56. this
The file name is entered on the computer 33 and the image storage device 3.
It clarifies the management of image data between output devices.
, the computer 33 attaches an arbitrary image file.
is possible. The image file name consists of 8 characters of the image file name.
(ASCII code) and the image type of the image data
It consists of an extension indicating the . The type of image to be handled is distinguished by the extension.
The registration memory 40 has a structure that matches the image type.
60 and will be managed. The image type is RGB type when the extension is “,R”.
Luminance image data, CMYK type density when “,C”
Image, 167 of 8-bit palette type when “,P”
Image data that allows you to set any 256 colors out of 00,000 colors
means. Also, when “,S” is specified, the special file
has a special meaning in the image storage device 3 and has a special structure.
It shows the image file that is . The coordinate system for handling images in the image storage device is a standard.
the origin and the X direction representing the width direction of the paper,
Height consists of the Y direction representing the > direction.
(Figure 52). The image storage device stores data from each input device into the image storage device.
Processes within the location coordinate system and manages various image data. Analog input terminal (RGB, video) (4500, 4
Input images from 510°452OR, G, B, S)
If the input image is input and registered in the registration memory, the input image is the 53rd
The image will be registered as shown in the figure. Input image at this time
is 600 pixels in the X direction (width) and 600 pixels in the Y direction (width).
height) is input with a size of 450 pixels.
. The coordinate system of the digitizer 16 is as seen from the image storage device.
, as shown in Figure 54. The coordinate system of the image storage device and
The digitizer coordinate system is the same, with each origin and
The X direction and the Y direction correspond. The coordinate system of reader 1 is the fifth coordinate system when viewed from the image storage device.
It will look like Figure 5. Image storage device coordinate system and reader
- The origin, X direction, and Y direction of each coordinate correspond to each other.
Ru. Next, we will explain the data exchange via GP-IB.
do. Image storage device 3 and computer are connected through GP-IB4310.
Types of data exchanged between computers 33
is classified as follows. ■Command (instruction) Command from the computer 33 to the image storage device 3 ■Paper
Various arguments accompanying the parameter command ■Data section/Image data Binary of color (monochrome) images such as RGB, CMYK, etc.
Redata/extended data Obtaining and setting the data set in the image storage device 3
This is data transferred when rewriting data.
. ■Response data: ACK/NAK, response with additional information (RET), i.e.
This is a response returned from the image storage device to a command. The above four types of data are stored in the computer 33 and image memory.
with device 3 via GP-IB controller 4310.
and exchanged. Below, using Figure 57 for these four types of data,
explain. As shown in FIG. 57, the image storage device 3 and each input/output device
controller 11 analog input 4500, 4510° 452O
R, G, B, S, between printer 2, and image
Image data handled between the storage device and the computer 33
Data is classified into the following four types. ■ RGB data type ■ CMYK data type ■ 8-bit palette data type ■ Binary bitmap data type These image data are extensions of the image file names mentioned above.
They are distinguished by their child parts. For example, on the computer 33 side
RGB image in the image file name accompanying the 5CAN command
When the extension “,R” indicating image data is attached,
, the CPU 4360 of the image storage device 3 receives the input from the input device.
The input is controlled as an RGB luminance image,
Registered as RGB type image data in the image storage device.
Record. Figure 60.61 shows the structure of RGB type image data.
vinegar. In the image storage device, registration is performed as shown in FIG. 27(A).
Basic block of memory A to D (4060A to D)
Configure the lock as shown in Fig. 60, memory A (40
60A), R image (4060A-R), 6 images
(4060A-G), 3 images (4060A-B),
Combine each basic block. Image composition of the image
is the horizontal length width and the vertical length
The number of pixels (dots) of height
ing. Specifically, it is an RGB color image, R, G, B.
Each pixel has a depth of 8 bits (1 byte).
I have one, and it has a 3-frame configuration of R, G, and H.
ing. Therefore, one pixel on the R surface has 256 gradations (θ ~ 255).
So, 3 sides of RG fist B are 256 x 256 x 2
It has a data structure of 56ζ16.7 million colors. Note that 0 represents low brightness and 255 represents high brightness. The data structure is arranged in order from the top left on the R side, and this structure is called RGB.
Continuing in order (. Image storage device 3, input/output device, computer 33
Image data is transferred using the transfer format shown in Figure 61.
It's summery. In other words, data is transferred in frame sequential order. Figure 62.63 shows the image of CMYK type image data.
The table below shows the page structure and its transfer format. C is cyan, M
represents magenta, Y represents yellow, and K represents black. mosquito
In such a case, the memory for registration in the image storage device 3
The basic blocks of A-D (shown in Figure 27A) are shown in Figure 31.
Create an image structure like this, and add basic blocks to each.
Assign. Specifically, it is a CMYK color image, C, M, Y. 8 bits (1 byte) per pixel for each K
It has four depths: C, M, Y, and K.
It has a frame structure. Therefore, 256 tones can be expressed with 1 pixel on the 0th plane.
The same applies to the M, Y, and other surfaces hereinafter. 0 represents low density and 255 represents high density. (Margin below) The data structure is arranged in order from the top left on page 0, and this structure is called CMYK.
Continued in order. Figures 64 and 65 show 8-bit palette type image data.
The image structure and its transfer format are shown. Memories A-D (27th memory) of the registration memory of the image storage device 3
The basic block in Figure A) is configured as shown in Figure 64, and the basic block is
Assign this block. An image with a depth of 8 bits (1 byte) per pixel.
It has a page configuration. The 8-bit data value of l pixel is as shown in Figure 66.
Color index of color palette table 4391
It corresponds to the color of the user and can be set arbitrarily by the user.
Can be attached. Therefore, 256 colors can be expressed per l pixel.
It is possible. FIG. 85 shows the relationship between image data and color palette. The data structure is in order of data starting from the top left of the image.
are lined up. Figures 67 and 68 show binary bitmap type image data.
The image structure and its transfer format are shown. The 200 million bit map is stored in memory E (27th memory) of the registration memory.
Figure A). This image data has an image file name extension of S''.
It is a special file, and the image file name is “B”.
ITMAP, S” and is a binary bit map type.
For memory E (Fig. 27A) that can only register
be registered. Memory E (Fig. 27A) has basic blocks whose memory
It is not possible to register multiple items because the
stomach. Binary bitmap type image data is
It has an image structure with a depth of 1 bit. Therefore, there are two expressions per l pixel: 'O' and 'l'.
Become. “0” means white (no printing), “1” means maximum darkness.
Expresses degree (black). The data structure consists of 8 bits starting from the top left of the image.
In other words, to set data in 1 byte per 8 pixels.
Therefore, binary bitmap type image data is
It must be a multiple of 8 in the h direction. he
The light direction is arbitrary. The image file size is set in pixels.
Therefore, the amount of data transferred is as follows: d <Width>: Width of the image file (width)
<height>: Height of the image file (heig
ht) 8: 8 pixels makes 1 byte of data
For. Next, a command is sent from the computer 33 to the image storage device 3.
Figure 69 is used for the structure of the response data to the code transmission.
I will explain.・Basically, image data is excluded (response data is of the following types)
There is. FIG. 69 shows the structure of response data. As you can see from the figure, which response data depends on the type of command.
The difference is whether data is received. ACK and NAK are paired and are used for most commands.
takes either of these as the response data.・ACK type response data is an affirmative response to each command, and is
This indicates that the data has been successfully transmitted and decoded to the storage device 3 side. head
3 bytes: 1 byte is 2EH, remaining 2 bytes are OOH
The fixed value, NAK tie, and response data of BU are negative responses to each command, and there is no error
In response to the occurrence, the first byte is 3DH.
The last 2 bytes are an error code. (Error code) = (upper byte) x (100 (H
EX) + (lower byte)・RET type (attached information
The response data of the attached response) is the frame from the computer 33.
In response to a command, the image storage device is
It is sent from station 3. The structure is 8 bytes in total.
The first byte is the fixed value of the header (02H).
ing. Following the header, the first data to the seventh data
Continuing byte by byte, the data content of each is the command
It depends. The command is sent by the computer 33 to the image storage device 3.
You can control image data input/output, image file management, etc.
There is a command like the one shown in Figure 70 for this purpose.
. Commands are divided into those that perform a function with a single instruction, and those that perform a function with a single command.
The parameters following the command are divided into necessary ones. FIG. 58 shows an example of the configuration of command parameters. Commands and parameters are recorded as image strings.
Send to storage device 3 via GPIB controller 4310
If there is a numerical value in the parameter section,
It is necessary to convert the numerical value to a character string representing the 1O base number. Also, among the parameters is a string indicating the image file name.
There is also. These commands transfer image data to your computer.
33, image storage device 3, input device 1, 31° output device 2
, 32 devices is shown in Figure 59.
vinegar. Command from computer 33 to image storage device 3
It is classified into seven types. (Figures 70 to 72) ■Initialization command: Performs various initializations. ■I/O selection command: Selects input/output devices. ■I/O mode setting command: Sets conditions for image input/output. ■I/O execution command: Executes image input/output operations. ■File operation commands: Perform operations related to image files ■Color setting commands: Configure color-related conditions ■Other commands: Other Each command will be explained below. The initialization command will be explained using FIG. 73. The INIT command sends initial data to the image storage device 3.
This is a command to set the data. The INITBIT command specifies a binary bitmap.
Clear the image of the digital file 'BITMAP, S'
It is a command. The INITPALET command is used to change the palette of image storage device 3.
This is a command to initialize the cut table. The input/output selection command will be explained using Figure 74.
. 5SEL command is color reader 11 analog input
4500, 4510.452OR, 4520G, 452
0B. Select the input system of 452O3. CPU4360 is n
. Selects the input system specified by the parameter when it is an analog input.
Kuta 4250. With Selecta 401O, only one leader can do it.
This is a command to be input and selected by the time selector 4250. The DSEL command is an image storage device for color printer 2.
This command sets the output of image data from the device. Explanation of input/output status setting command using Figure 75
do. DAREA command outputs from image storage device to printer
The upper left coordinate position (sx, sy) and output size when
command to set the width (width x height)
It is de. Also, set the unit at that time with type, m
Units such as m, i n ch, d o, etc.
can be set. 5AREA command is input from color reader l.
This is a command that sets the rear in the same way as the DAREA command.
be. 5AREA/DAREA input/output range setting
is performed by the system controller 421O. DMODE command (the mode specified by the DAREA command)
Change magnification when outputting (for rear) 4150-0 to 41
This is a command to set the enlargement/interpolation circuit of 50-3.
. The 5M0DE command is specified by the 5AREA command.
The system controller changes the reading magnification when inputting to the area.
This is a command controlled by the controller 421O. The ASMODE command reads an image from the analog input terminal.
Input as field signal or frame signal.
Ru. The system controller 4210 and counter controller
Set what to do with Troll 9141 on CPU 4360
do. In addition, field signals, signals, and frame signals are television signals.
Since this method is well known in the art, its explanation will be omitted. The input/output execution command will be explained using Figure 76.
. The copy command reads the reflective original on reader 1,
without registering it as an image file in the image storage device 3.
This is a command that causes the printer 2 to output directly. At that time
Printer by the parameter indicated as <count>
2. You can specify the number of sheets to be output. The 5CAN command causes the CPU 43 to
60 is from the input device specified by the 5SEL command
Load the image data and show it as <filename>.
The image file name specified by the specified parameter, with the extension
WidthXheight pixel support for image type
The data is read in the image memory 4060 and stored in the image memory 4060.
. At that time, the CPU 4360 selects the image file name, image
Information on type, image size, and which image memory it was registered in
Image file management table 4361 shown in FIG.
Set to . The PRINT command is the opposite of the 5CAN command.
Image file data already registered in storage device 3
With the parameter indicated as <filename>
This is a command to specify the image file.
From the file management table 4361, the image memory 4060
and output the data via the video interface 201.
output to the printer. At that time, it is indicated as <Count>.
The number of times specified by the parameter
Output. The MPRINT command is registered in the image storage device 3.
The parameter indicated as <filename>
Virtually output the specified image file data by
It is a command. This is a composite of multiple layouts and output.
This command allows multiple image files to be
are specified sequentially, and each time the CPU 4360 specifies the memory 4
Image file specified by MPRINT command in 370
Store the name and print or copy the frame.
By specifying the command, the CPU 4360
Image by MPRINT stored in Mori 4370
Combine files into multiple layouts and output to printer 2.
Ru. The PRPRINT command is sent from the computer 33 to the GP
Image data sent via IB interface
(width X height (size), <f
The file specified by the parameter indicated as ilename>
The CPU 4360 registers the file name in the image memory 4060.
Then print it using the same operation as the PRINT command.
This is a command that outputs directly to the linter. The DR3CAN command displays the image from the color reader l.
Data of specified size (width
) <filename> on the read image memory 4060
Register the image file with the specified file name shown as
Set attribute data in the management table like the SCAM command.
cut. And further GPIB interface 4
Transfer data to computer 33 via 580
. Next, the file operation commands shown in Figure 77 will be explained.
. The DELE command has already been registered in the image storage device 3.
Shown as <filename> in the image file that is
The image file specified by the specified parameter is converted into an image file.
Command to delete from management table 4361
It is. At that time, the free space in the image memory after deletion is
The PU 4360 determines from the management table 4361 that the RE
Set free size data to T type response data.
GP sends 8 bytes of RET response to computer 33.
Send via IB. The DKCHECK command checks the image memory in the image storage device 3.
The image file type specified by the type parameter is
type (CMYK, RGB, 8-bit palette, binary bit)
The image of Tomatopu) is the image of widthXheight
The CPU 4360 determines whether the image file size can be secured.
Judging from the file management table 4361, the RET type response
Set the availability of reservation in the answer data and calculate the remaining capacity after reservation.
The party sending the DKCHECK command, for example
The data is sent to the computer 33 via GPIB as RET response data.
and send. For example, by such a command or specific code, FIG.
The display shown in G can be performed. The FNCHECK command is specified as <filename>.
The image file specified by the parameter shown in
Check whether it exists in the file management table 4361.
, set existence/absence to RET response data and copy
It is returned to the computer 33. The FNLIST command sends the current image file to your computer.
This is a command to send the contents of the file management table.
. The REN command is set in the image file management table.
This command renames the image file that is
, the image file name before change < Sfilename
Command to change > to the changed <Dfilename>
It is. Next, use the file operation command to create the image data using Figure 78.
This section explains commands that involve data input and output. The LOAD command loads frames registered in the image storage device.
The parameter indicated as <filename> in the
The data of the image file specified by the data is stored in the image memory 40.
60 to the computer 33 via GPIB.
It is a command. 5AVE command is the opposite of LOAD and is
widthXheight image size data, <
filename>Image by name in parameter filename
Image data is registered in the storage device 3. First, C
The PU4360 stores information in the image file management table 4361.
Set the file name, image type, and image size,
Data is sent from the computer to the free space in the image memory 4060.
This is a command to set the image data that has been sent. The PUT command has already been registered in the image storage device 3.
specified by the parameter indicated as <filename>.
The upper left coordinates (sx,
sy) to widthXheight size range
, you can insert image data sent from the computer.
I can do that. The GET command is the opposite of PUT.
The image data of the image file with name> is located at the upper left coordinates (s
x, sy) widthXheight image range
to transfer the image data to the cutting computer 33.
can be done. FIG. 80 shows other commands. MONITOR command has <type> parameter
to the analog input specified by the 5SEL command according to
On the other hand, analog output 459OR, G, B, S
You can set the through display setting to directly flow and display data.
to the spray controller 4440. In addition, type
Examples of variables include "0" (through display is set), "
1" (sets monitor mute), etc. Furthermore, the MONITOR command is
lower than the command and other DSCAN and 5CAN commands.
Therefore, the through display setting is canceled. The PPRREQ command indicates that the CPU 4360 has video input.
Control unit 1 via interface 201
3, for the one currently set in color printer 2.
Obtain the paper size information and enter the paper discrimination data on the computer side.
send data. The PPR5EL command is executed by the control unit in the same way as above.
For knit 13, specified with the <no> parameter,
Command for selecting among multiple paper trays.
Yes, the image is output to the color printer 21 via the image storage device 3.
Powered. The 5ENSE command connects image storage device 3 and color reader.
-11 Regarding the status of each device of color printer 2, CP
U4360 controls via video interface.
Communicate with roll unit 13, obtain it, and send it to the computer side.
This is the command to send the data to. Next, data from the computer 33 to the image storage device 3 is
The command sending procedure will be described. A group of commands that are the basics of image input/output.
(i) Input/output selection commands 5SEL, DSEL (ii) Input/output status setting commands 5M0DE, 5AREA, DMODE, DAREA. RPMODE, ASMODE (iii) Input/output execution commands 5CAN, DRSCAN, PRINT, MPRINT. It becomes DRPRINT. As shown in Figure 82, the input/output of image data is
There is a basic procedure for sending commands. First, use the input/output selection command to select the input/output
Select the device and select C of the image storage device 3.
PU4360 analyzes the command and responds accordingly.
ACK/NAK of the response data is returned to the computer 33.
vinegar. Next, the computer 33 issues an input/output status setting command.
, to the image storage device 3, and send the result to the CPU 4360.
computes the ACK/NAK response data in the same way as above.
data 33. The input/output status setting command is executed by the input/output execution command.
Once the
Ru. Therefore, the input/output status setting command is not executed.
If the input/output execution command is executed, input/output status settings
is set to the default value. When performing input/output
If you want to set the input/output status, set it for each input/output execution (basic).
(for each type), it is necessary to execute the input/output status setting command.
be. Then, input/output that actually performs input/output of image data.
The CPU 4360 sends the execution command and in response
Return RET type response data and acknowledge (ACK)
In this case, the actual image data input/output is performed by the input/output device
-der 1,5V31. Printer 2, monitor 32, etc. and images
It takes place between storage devices. This input/output is the same as in the above-mentioned embodiment and will not be explained here.
The following is a guide to registering image files from a computer.
Checks image file attributes in advance for commands.
or check the memory capacity (memo) that can be used to store files.
(A-D) Check the steps in Figure 27 A))
It is possible to perform the process and notify the computer 33 side.
be. The command for pre-checking this image file is:
There are FNCHECK and DKCHECK commands. The procedure for checking this image file is described in Section 82.
As shown in Figure 83, first, select the specified file for the image file.
The existence of the file and its file attributes are determined by the RET type.
It is sent to the computer 33 side as response data of the
Additionally, check the remaining capacity of the image file or the desired image size.
The response as to whether the size of the image file can be secured is the RET data.
It is returned as data. The basic form of this file check is the input/output frame described above.
Incorporate it into the basic form of the
It is also possible to check and respond to image files in advance.
It has become a Noh performance. Next, the composition of image files will be explained. Image files are stored in the registration memory 4060 of the image storage device 3.
Create a color print by combining multiple registered images.
To output to Data 2, use MPRINT from the computer side.
This is possible by sending a command to the image storage device 3.
. The MPRINT command is registered in the image storage device as an argument.
Specify the image file name. MPRINT
The CPU 4360 interprets the command string
analysis and temporarily register the file name on the memory 4370.
Ru. This is for laying out multiple MPRINT command strings.
The data is sequentially transmitted from the computer 33 on the RAM.
The specified file name will be temporarily registered and multiple layouts will be created.
When printing the last image, the computer uses the PRINT command.
Send the code string. The CPU 4360
When the command is parsed, the MPRINT command in RAM is
CPU in the order of image file names sent to the commands.
From the image file management table 4361, the image memory
From above, transfer the specified image data to the color printer and output it.
do. The combined output at that time is as described above. Sending MPRINT from computer and PRIN
The superiority and inferiority of image composition using the T command is shown in Figure 88.
The image specified later on the street takes priority. In addition, a binary bitmap memory (memory shown in FIG. 27A)
) and registered in the image storage device.
To combine the image file with the above-mentioned MP
Multiple specified image files for RINT and PRINT commands
The special file “BITMAP, S” appears in the file name.
If you set the file name on the computer side and send it, the CPU4
360, as mentioned above, combines multiple image files and
Performs synthesis with binary bitmap data. Please note that this implementation
In the example, an image of 200 million bitmaps has a dot of “1”.
” is basically black, and the ’O” part is different from other pictures.
The output of the image file is switched to have priority. Such an example is shown in FIG. Such switching is performed by the video interface 2 of the reader 1.
Since 01 is used, the configuration of the image storage device is simplified.
. As an image composition function, image files and binary bits are
MAP's "BITMAP, S" special file and
, it is possible to combine and output the reflected originals of one copy of the reader.
function, performs the compositing operation described above. The above-mentioned operations based on commands from the computer are performed by M
Execute with PRINT command and copy command
can be done. Command to specify multiple image files using MPRINT
Finally, send the copy command to complete the process.
The CPU 4360 copies the data to the color reader's CPU.
- gives instructions for the operation and also uses the MPRINT command
The image file created by the card and the original reflected in the reader are combined.
can be output. At that time, the “BITMAP, S” screen is displayed in MPRINT.
If you specify an image file, you can also combine it with a binary bit map.
It can be carried out. In this embodiment, reader 1 is
Reflective originals are automatically given the lowest priority.
, can be the background of the image. Commands sent from the computer and the actual printer
The output result from the data processor is as shown in FIG. In this embodiment, the color adjustment function is as shown in Fig. 79.
, color palette function, color balance function, gamma
As a command from a computer that supports the correction function.
, PALETTE command, BALANC command, respectively.
E command, GAMMA command, BITOOLOR command
There is a mando. The color palette is an 8-bit palette tie as described above.
You can set the color of the map and the image of the binary bit map type.
Used to color data. To do this, add the color code to the palette number in the color palette.
Set the data. Specifically, 256 color data can be set.
and set 8-bit data for each of RGB. It is set in the color palette 4362 in the image storage device 3.
Transfer the color data stored in the host computer to the color data stored in the host computer.
- By making the image storage device 3 the same as the palette,
The color of the image to be output on the color printer via the host
It can be the same as a computer. The color palette table in the image storage device 3 is PAL.
Save the palette table as an image memory using the ETTE command.
Set for each image file registered in location 3.
I can do it. Therefore, the 8-bit palette with the extension "P"
Print or MPRINT image files of type
When outputting with the command, the PALETTE command is
settings from the computer, and then after that, for example, as shown in Figure 91.
RGB palette of 256X3 (768) bytes like
The table data is transferred to the image via GP-IB4580.
PRINT set on the pallet table of storage device 3
/MPRINT When the command is executed, the current settings are
R, G, B of the specified palette table 4362
The components are LUT4110A-R and 4110A-G, respectively.
. 4110A-B and convert from brightness to density.
Perform the calculation for each table. At that time, if specified by the PRINT/MPRINT command,
Convert palette type image file data to a palette template.
LUT4110A-R, 4110A-G with bull set
, 4110A-B to 8-bit palette brightness information.
is converted into density information and sequentially output to the image output system described above.
The image is then output using a color printer. 8-bit palette type images are sent via GP-IB.
Work memory 439 when sent from the computer
It is set to 0 one line at a time, and the registered memo is registered by DMA.
same data to 4060-R, 4060-G, 4060-B.
The 8-bit data that can be set using the PALETTE command is
The maximum number of let tables is 16, allowing multiple lay tables.
When compositing by out, each 8-bit palette
It can be set for type image data. MPRINT multiple 8-bit palette type images
Before performing virtual output using the command, use the PALETTE command.
The color palette data (768 bytes) is
The CPU 4360 is stored in the memory 4370 of the image storage device 3.
Register at the time. Multiple 8-bit palette images that combine this into a layout
Repeat this and print PRIN when outputting the last image.
Execute the actual output using the T command. The image storage device 3 can be
The 8-bit data set by each MPRINT command
from the memory 4370,
When sequentially outputting a composite, select the color palette template for output.
4362, and multiple
It is possible to combine the images and output them to printer 2.
Ru. Next, set the color balance by RGB type and CMY
It is possible to set two types of color balance for K type.
They can be distinguished by the ype parameter. This setting
can be set using the BALANCE command. RGB color balance is LUT411 OA-R
. Luminance slope for 4110A-G and 4110-B
CI, C2, C3 parameters of BALANCE command
Conversion from brightness to density
Calculate. CMYK color balance is 1 for LUT4200
BALANCE:ffV:/de(7)C1,
C2゜Set by C3, C4 parameter ±50% value.
Ru. Each image file data is converted by the above LUT,
Image quality can be changed from low to high brightness and low to high density. The GAMMA command is set to RG by the type parameter.
The B type image file data shows the CRT's light emitting characteristics.
For the data with γ=0.45 correction being considered, the
In order to be able to reproduce colors on CRT using linter 2 output,
of the LUT registered in the memory 4370 in advance.
Data 4110A-R. Set to 4110A-G, 4110A-B, and from the brightness
By adding the conversion operation to concentration, γ = 0.45.
Color reproduction of CRT-corrected RGB image data
It can be output. BITOOLOR command is a binary bitmap memory
(Special file “BITMAP, S”) (No. 27
For memory E) in figure (A), the upper left (sx. sy) coordinates, in the range of size widthXheight
, the color palette specified by the 1ndex parameter.
Change the color of the index number of 4362 to “BITMAP
. S'' binary bitmap output to color printer 2
Coloring can be done from the computer as mentioned above
This is possible with the command. BITOOLOR command
sx, sy, width, hei by code
ght. The parameter of 1ndex is that the CPU 4360 uses memory 4.
It is possible to hold more than one on 370. And the fruit
When using the MPRINT or PRINT command,
Set the file name “BITMAP, S” to ilename.
When specified, the CPU 4360 uses color reader 1/color
- CPU 22 of the control unit 13 of the printer 2
Image storage via video interface
From device 3, sx, sy, width, heig
ht area parameters and associated color parameters.
Let index number (index parameter)
RGB in color palette table 4362 corresponding to
Sends 3 bytes of color data of the component (multiple
is specified by the BITOOLOR command.
(repeat sequentially), the control unit 13
Those parameters are sent to the programmable synthesis unit 115.
Set the data and print it on a binary bitmap color printer.
Enables coloring of a specified area in a specified color when outputting. In this way, you can change the area and color on the control unit 12 side.
After making the settings, the CPU 4360 of the image storage device 3
“BIT” by RINT or MPRINT command
Binary bitmap data of MAP, S'' (Figure 27 (A)
)'s memory E) via the video interface.
Colored output can be output in accordance with commands from the computer.
It becomes more possible. The coloring is applied to the part where the bit of the binary bitmap is “l”.
will be carried out. Color reader/color printer with remote function
and image storage device 3 can be controlled by the host computer.
can be set to The above command from the computer doing the remote
There is a REMOTE command, and this command
, can be put into four states (Fig. 92). The system remote status is the color reader/color printer.
printer and image storage device 3 according to commands from the computer.
Therefore, it becomes possible to control. In the image recording device remote state, only image storage device 3 is
Controlled by commands from the host computer 33
can be done. At this time, color leader/color pre-
The printer can perform copying operations by itself as a copier.
Ru. The local state can also be accessed from the host computer.
local status (control) from both the printer/color reader
), and the color reader cannot be operated.
Remote specification from the production department or host computer
Instructions by REMOTE command from the controller
The remote state will be established as soon as possible. When the copying machine is in the remote state, the image storage device 3 is connected to the color reader.
-1 to control it in remote mode according to the instructions from the operation panel.
It becomes possible to control the At this time, the computer
The command cannot execute the functions of the image storage device 3.
I can't. These remote/local states are
The type parameter of the REMOTE command from the
It can be specified by the data. The type parameter of the REMOTE command allows C
PU4360 is color printer 2, color league goo 1
CPU 22 of control unit 13 and video interface
-By communicating via the face 201, the above-mentioned
Instruct 4 remote/local states from computer
can do. Controls related to remote/local> Switching between remote/local status and
Regarding system control, use Figures 99 to 101.
explain. Figure 99 shows control unit 1 in the color league.
3 (hereinafter abbreviated as Color League Controller) remote
/ Control flow for local state. First, p
When the power is on, the system in the image storage device is set to 5IOI.
Communication is performed with the stem controller 4210-2, and at that time
Receives the state of the system at a point. Next, 5102
Determine if the system is in system remote state, and if so
, 5103 sends a message as shown in A in Figure 101.
displayed on the LCD touch panel on the operation unit 20 of the color reader.
Show. At this time, the keys on the operation unit 20 are
Keys other than key 20-1 will not be accepted. Then at 5104
, remote/router from system controller 4210-2.
Determine whether a command to switch the local state has arrived, and
If so, 5109 is the system controller 421〇
-2 to the specified state. This switching
The color league is already operating in a predetermined state during processing.
For example, if it is operating as a copier, switch it off.
can't do it. Also, when I try to switch,
In some cases, the operation becomes abnormal and malfunctions occur. the spot
If the system controller 4210
Inform -2 of the failure. 5105, the system controller 4210-2 sends the
Figure 71 Reverse mold Check whether other commands shown in Figure 80 have arrived.
If it has come, call 8108 to check the color league and color.
Control the color printer and send commands such as image registration and
Executes image printing, composite printing, etc. At 5106, the remote key on the color league side was pressed.
If pressed, the system controller
Remote/local status switching for La4210-2
request. This toggle displays the system remote status.
Change the storage device to remote status from the color league
The system controller 4210-2 switches
If possible, try switching, and if it fails, use Color League Gooco.
The controller 13 is notified of the failure. Colorly
If the programming controller 13 fails, the method shown in FIG.
Show sage. Next, in 5102, the system status is changed to system remote status.
When it is determined that the
The key becomes valid. In 5IIO, the system controller
If a remote/local status switching command has been received from the
If it has come, check 5109 with Sl 16.
Similarly, switching to the specified state is performed. 5ill, on the operation unit 20 (when using the image recording device)
Determine whether the key for These keys are external device keys 20-2 on the operation unit 20.
This is the key on the operation screen that is called, and when this key is pressed.
When the remote/local state is first copied in 5112,
Determine whether the machine is in a remote state, and if so, call 511.
4 to control the image storage device 3 and respond to input key operations.
Performs similar processing. On the other hand, if the copier is not in remote mode
, 5113 communicates with system controller 4210-2.
and performs switching processing to the copying machine remote state. this
If switching is successful, proceed to 5114; if unsuccessful, proceed to step 5114.
Issue the message shown in Figure 101C. 5115 determines whether any other key was pressed.
, if pressed, the color reader at 5114. Controls the color printer and performs key processing. FIG. 100 shows the system controller in the image storage device 3.
Controls on the remote/local state of the controller 4210-2
It's a flow. First, 5201 is the host computer.
Determine whether the command was received, and confirm that it was received.
If so, check 5203 to determine if it is a REMOTE command.
If so, in 5204, the controller on the color league side
Communicate with the troller 31 and switch to remote/local status
Perform switching processing. Next, in 3205, the received command
Commands where the code uses only image storage, e.g.
Determine whether it is an AVE command, LOAD command, etc.
If so, the remote/local state is displayed in 5206.
Image storage remote state or system remote state
Determine whether During these conditions, the image storage device
Since it can be used by host, 5208 can be used by host.
Executes the command sent from. On the other hand, when these conditions are not present, color recovery is performed with 5207.
communicates with the device and performs remote/local state switching processing.
conduct. If the switching is successful, it will go to 5208, but if it is unsuccessful, it will go to 5208.
Inform the host that it has failed and do not execute the command
. 5209 means that the command received from the host is in color.
Commands also used by readers/color printers, e.g. P
Determine whether it is a RINT command, 5CAN command, etc.
If so, 5210 indicates remote/local status.
Determine whether the system is in remote status. In this state, the color reader/color printer is
Since it can be used with
Execute commands while communicating with the controller
do. At this time, image data is transferred between the color reader and the image storage device.
, or move between an image storage device and a color printer
only, and its control depends on commands from the host above.
Therefore, system controller 4210-2, reader
This is done by the controller 13, so during this time the host
There is no need to control this system (or to do other work).
I can do that. In addition, the host supports the system controller as necessary.
and communicates to check if the job is finished.
I do. On the other hand, if this condition is not present, use 5211 to control the color leader.
Communicate with the controller and switch the remote/local state.
Perform replacement processing. At 5202, there was a command from the color reader.
If so, check 5213 if it is remote/robot.
Determine whether it is a request to switch the local state, and if so,
At step 5214, switching processing is performed. For other commands
If the remote/local status is 5215, the copier remote
Determine whether it is in the default state. In this state, Color Lee
The image storage device 3 is enabled by the image controller.
Therefore, from the color league controller with 5216
Execute a command. On the other hand, when not in this state, 52
In step 17, the error is notified to the color reader. In this embodiment described above, for example, the image storage from the host is
During image transfer with device 3, the color reader side
can operate in local mode in
. Therefore, images are transferred between the host and the image storage device 3.
Even if time is required for the
Copying operations can be performed at any time. Also, conversely, data is transferred from the host to the image storage device 3.
Control the image storage device 3 from the color reader while you are away.
Rukoto can. Even if the color reader is the image storage device 3
Even if you are not controlling the color reader,
Host the image storage device by turning on the default key
It can be set to remote status regardless of the Also, the Sv playback device is sent from the color reader to the image storage device.
Store the image signal, for example, as described above in the Sv multi-index
outputs an instruction to memorize the image, and such memorization is performed.
The color reader is in normal local mode while
You can perform the following actions. Next, the command transmission procedure described above is shown in Figures 84 to 87.
Here are some examples. Figure 84 shows the screen displayed from the input device using the 5CAN command.
Register the image data to the image storage device 3 as an image file.
This is the procedure. Basic part of file check in the diagram
As mentioned above, check in advance by performing the steps shown in Figure 83.
It is also possible to etch. Figure 85 shows how the image storage device is printed by the PRINT command.
Output the image data of the image file that has already been registered in 3.
This is an example of the procedure for Figure 86 shows how the input device is activated by the DR3CAN command.
input the image data into the image storage device, register it, and then
The procedure for transferring image data to the computer 33 is shown below.
vinegar. Figure 87 is the reverse of the DR3CAN command in Figure 86,
Output the image data on the computer 33 using the output device
This is an example. Next, we will give an example of an actual command. An image in the host computer as an example of a single image output
FIG. 93 shows an example of outputting to a color printer. example
For example, a 1024x768 pixel RGB type image
277X190 from the top left (10,10) mm position of the paper
An example of printing by centering within the mm range.
explain about. As an example of layout output of multiple images, the host computer
2 RGB type image data in Data 3 on one sheet of paper
This is an example of laying out and outputting with color printer 2 (
Figure 94). In this example, 1280X1024 and 1024X768 pixels
Set each of the two RGB type images of the cell within the range shown in the diagram.
An example of how to interpret and print out is shown below. When outputting multiple images, one image at a time is sent from the host 3.
Register in storage device 3, perform virtual output, and output to printer 2
(as shown in Figure 96), and if the image data is
It is registered to the image storage device, and all virtual outputs are summarized.
There are cases where the data is output (the case shown in FIG. 95). Which
The output result is the same. Also, as an example of importing images from reader 1 to host 3,
This is shown in FIGS. 97 and 98. In such a case, first, for example, A4 size paper on the reader 1.
RGB tag a corresponding area (297x210mm)
The image data of 1000 x 707 pixels is
Read the size and import the data to host computer 3.
Get into it. As described above, according to this embodiment, the computer 3
3. Do not hold image data for input/output on the
Instructions (commands) between the image storage device 3 and the computer 33
Image data can be input and output simply by exchanging
Computers and input/output devices (reader 11 printer 2, etc.)
) can be reduced. In the above explanation, in this example, the target image is photoelectrically converted.
As a means of
Although a bed-type sensor was used, the sensor is not limited to this, for example,
A spot type sensor may be used, and the sensor
It is not limited to the type of In addition, in this embodiment, a so-called means for image formation is used.
A model that forms full-color images by plane-sequential image formation.
I used a color printer, but it is not compatible with such a color printer.
If you are using a non-plane sequential printer such as an inkjet printer,
It may be a printer, a thermal transfer printer, or a computer.
It may also be a printer called a color printer. In addition, in this embodiment, a host computer, an image storage device,
Color readers communicate with each other as independent devices
Since the various functions mentioned above are realized by performing
system can be provided. As explained above, in this example, multiple
Track number of the Sv floppy whose image information is desired
and layout information during image formation using a digitizer.
Set in advance, and then turn on the copy start key.
Image of the track number of the Sv floppy specified by
are played and stored in memory one after another. Then select the desired destination.
Once all images of the rack are stored in memory, the
Start the printer each time and perform the above steps to synchronize the printer.
Layout information preset from memory
Make a hard copy according to the instructions. That is, in this embodiment, image registration in memory and printer
image formation is performed continuously by pressing the copy start key.
Always easy to use. Furthermore, image registration in memory is done using a tracker.
This is done only for images selected by the number
Therefore, the memory capacity is relatively small.
The effect is that writing to image memory can be easily controlled.
play. In this embodiment explained above, multiple images can be stored.
The storage medium that can be used is called Sv floppy as shown in
) is a timing chart explaining the operation of the repeat circuit 118.
20(C) is a diagram showing an example of the output of the repetition circuit 118.
, FIGS. 21(A), (B), and (C) show the repeating circuit 118.
Figure 22 is a diagram showing another output example of the printer 2.
Figure 23 is a plan view of the digitizer 16, Figure 24 is the point pen of the digitizer 16.
Figure 25 (A) showing the address of information in the area
is a block diagram showing the configuration of the synthesis circuit 115 in FIG. 2, and FIG.
Figure 25 (C) is the area code shown in Figure 25 (A).
A diagram showing the configuration of the generator 130, FIG. 25(D) shows the RAM 153 shown in FIG. 25(C).
Figure 25 (E) corresponds to the data shown in Figure 25 (D).
Figure 25 (F) shows the RAM 135 shown in Figure 25 (A).
Figure 25 (G) shows the data structure of ゜136. Figure 25 (G) shows the state of synthesis shown in Figure 25 (A).
The diagram to explain, Figure 25 (H), masks the specified area with the specified color,
Furthermore, it shows the state in which characters from bitmap memory are synthesized.
Figure 25 (represents the decoder 146 shown in Figure 25(A))
26 is a diagram explaining the operation of the signal 207 output from the color reader l.
A diagram showing the timing of the image signal 205, FIG. 27 (A-
1), (A-2), and (B) show the configuration of the image storage device 3.
Figure 27 (C) is a block diagram of memories A to D shown in Figure 27 (A).
Figure 27 (D-1) shows the configuration of bitmap memory E.
Figure 27 (D-2) shows the original and bitmap memory.
Figure 27 (E) is a diagram showing the relationship between data written to E. Figure 27 (E) is the monitor memory shown in Figure 27 (A).
Figure 27 (F) is a diagram showing the configuration of M.
A diagram showing a part of the internal configuration of the system controller, FIG. 28 (A) is a filter 950 shown in FIG. 27 (A).
28 (B) and (C) are block diagrams showing the internal configuration of 0.
) is the internal configuration of the selector 4250 shown in FIG. 27(A).
29 is a block diagram showing the system shown in FIG. 27(A).
Configuration of stem controller 4210 and memory ANM
Figure 30 is a diagram showing the relationship with the FIFO memory in Figure 30.
Figure 31 shows the case after cropping and scaling processing.
The timing chart of FIG. 32(A) is the internal memory 4060A- of memory A.
R, G, B, counter controller, and counter
32 (B) and (C) are block diagrams showing the relationship between the
A flowchart showing the method and operation in such a case, FIG. 32(D) is a flowchart explaining the operation of AGC.
Figure 33 (A) shows memories A, B, C, and D connected.
Figure 3 showing the capacities of memories 4060R, G, and B in the case of
Figure 3 (B) and Figure 33 (C) are when creating the SV index.
storage status of image signals in memory and playback on monitor
Figures 34(A) and 34(B) are diagrams showing the state of the image being displayed.
The image in the storage device 3 is formed into an image by the color printer 2.
Diagrams showing the state, Fig. 35 (A) is Fig. 27 (A),
35 (B), (C), (D), and (E) are timing charts explaining the operation of the circuit in (B).
A diagram explaining the color balance adjustment of the image, Figure 36 is a memo.
37(A) and 37(B) are diagrams showing an example of image synthesis.
Figure 37 (C) shows the timing when composing images.
Figure 37 (D) and (E) show other examples of image composition.
Figure 37 (F) and (G) explain enlarged continuous shooting from memory.
Figure 38 shows the 27th line on the 11th line of Figure 37(A).
39 is a timing chart explaining the operation of each part in the figure.
40 is a timing chart explaining the operation of each part in the figure.
A timing chart showing the formation sequence, FIG. 41 shows the internal structure of the selector 4230 in FIG. 27(B).
Figure 42 is a diagram showing the configuration of the memory M shown in Figures 27 (A) and (B).
(corresponding to 2407) and image memories A, B, C,
A diagram showing the relationship with D (corresponding to 2406), FIG. 43
is a diagram for explaining the operation of the circuit shown in Fig. 42, and Fig. 44 is a flowchart for explaining the operation of the circuit shown in Fig. 42.
Figure 45 shows the configuration of the film scanner 34 shown in Figure 1.
The block diagram shown in Fig. 46 shows the structure of the film carrier shown in Fig. 45.
Figures 47 to 50 (A) and (B) are the operations shown in Figure 1.
Figures 50 (C) and 50 (E) showing examples of display in section 20 display images for which the layout has been specified.
Flowchart for freezing and printing, Figure 50 (D) is a diagram showing an example of image composition, Figure 51 is a diagram showing an example of image composition.
Notes from the host computer 33 shown in Figure 1
Block diagrams showing the configuration of the storage device 3, FIGS. 52 to 55
The figure shows the coordinate system of each device, and Figure 56 is an image file.
Figure 57 shows the structure of the host computer 33.
and the image storage device 3.
Figure 58 is a diagram showing an example of the configuration of a command.
Figure 9 shows the flow of image data generated by various commands.
Figure 60 shows how R, G, and 8 image inputs are stored in memory.
Fig. 61 is a diagram showing the form during data transfer, Fig. 62 is a diagram showing the form during data transfer.
, M, C, K indicates the storage state of image input in memory.
Figure 63 is a diagram showing the format during data transfer, Figure 64 is a diagram showing the format during data transfer.
Figure 65 is a diagram showing the state of storing image data in memory, Figure 65 is a diagram showing the format during data transfer, and Figure 66 is a diagram showing the state of storing image data in memory.
Let image data and R, G, B components of each palette
A diagram showing the correspondence with the data shown in Figure 67 is a binary input method.
Figure 68 is a diagram showing the storage state in the memory, Figure 68 is a diagram showing the format during data transfer, and Figure 69 is a diagram showing the storage state in the memory.
Figure 70 shows the structure of the response data, and the classification of each command.
Figures 71 to 80 explain each command.
Figures 81 to 87 show the execution procedure of each command.
The diagrams shown in Fig. 88, Fig. 89, and Fig. 90 are for the system of this embodiment.
Figure 91 is a diagram showing the structure of a color palette, Figure 92 is a diagram showing an example of image composition in
Color reader 1, image storage device 3, host computer
Figures 93 to 98 show the remote and local relationships between the host computer 33 and the image
A diagram showing the exchange of commands with the storage device 3, FIG. 99 shows the control unit 13 of the color reader.
Control flow diagram 1OO shows the control of the system controller 4210-2.
Flow Figure 101 is a diagram showing messages on the liquid crystal panel.
. In the figure, 1......Color reader 2...
・・・・・・ ・・・Color printer 3・・・・・・
..... Image storage device 32 .....
...Monitor TV host computer Original scanning unit Video processing unit Digitizer operation section g 1JJT (Luffup tape ib'3 ALUTO
Fa-N-F'-7;v) BLu-rQ-7 Asop
Tefunri O (α) (b) (C) Fig. 13 ridge) 7 main foot amount ε combination Fig. 73 (b) Fig. 73 < C) Fig. 73 (e) Fig. 73 (Zira LK Fig. 74 (c) 4 rate 4 2 words 4 JIJ vote meeting address color 157 gρg T (lθ Mast memory 91 and output of ``capable to'?'' ATA 1JT 78th Th (b) RDN TA 20'J2L (C ) A3. Figure 24 Address (V(tx) θ !? and A(δ P) k(sr) H Figure 25') (er) 4ρσθ 4necessary ψ Figure 27 (f)-2 Ji No. q Figure Shizu Roku Hundwara, tl) it) A-R Δθ Me M-R No. 32 (3) Memory (R) Memory (G) Memory (B) No. 33 A) Oval 53? Figure (T) Memory (R) Memory (G) Memory (B) Figure 35 (E) (so θ/) 4060R Memory (R) 060G Memory (G) 36th frame 060B Memory (B) Figure 37 CB) 7 Dress Hi・2 Tomasopue Soa All Indication Slikl (Words Y, H% 3 Kaud) Tokuto dI-I
'l < 5th θ section HD) tjL (Structure of file 55 k (4 irregular, file, b-tsu 1' 1y et ξ) See Dong Yi 55 (A group U breasts that complete the leeter) ( Theta minute 10 Figure 5q (Command l - Yoro 1 Ilonely ζri no 5.Za) To the CM engineer
Thailand 7゜ (YMCKJi, 6n Image゛ax) (Tele for CM work)
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ζ (1υ command division command command ゛-Kaku. Figure 77)

[Ko INIT, ? no + 口1j こ INITBIT (type) Initial value = machine ゛Fig. 73 fig. 2 Exit [ ] ko 5 SEL 1] KODAREA, (type) (sx) (sv), !w-dIh) (heiam) 口] [Korko Performing 1 stroke specific force from the scanner to the printer] [] 1 KOPY, ( coun+j
mouth []ko;'hetgh+) =1]ko(w-d+h+, (heigm) mouth

[jkoMODE +ypa) 'mx) my) 口[]ko[][koIko Set size conversion conditions when inputting 1 image][](ko5M0DE,:+vc+e),tmx)
,(my)mouth

[1 piece MPRINT,! fil@name) [] [koI] Analog image input mode setting [I
ASMOCIE, 01p2 0[j DRSCAN, (ilanam@) (width), (heiaht) [1[ko Iko Repeat the image and output it to the Blurta. mouth][]K]RPMODE,+lag)[][
ko [ko computer --output[]:]:][::
[]]]:];;i::]]]]I DRPRINT
, (filename), fwidth+,
(h@igh?), (eount) Input status stage fixed exit? ＞Entered Figure 75 = Powerful Blue;? Figure 76 [ ] [] "K Deletes the registered image file in image record 1 bag 1. Mouth] [] [K D day-E, <filename)
Mouth 1] KoLOAD. filename) [Check the registered capacity of the picture editor group i [U2r DKCI-IEcK Vtyoej, (
width (height) 11 mouths 5 AVE, ;' (ilename (width) (height) [Check the X-sexuality information of the image refile in image storage bag 1. [] []

[To FNCHEC, filena
me) Rororo UT <1;+ename) (sx) (sy) (width) (h6iQht> [1[koIko] Transfer 1@ of all registered image files in the image storage device to the host computer. [][][ ko FNLIST [] [ko Change the image file name. [REN, (Sfilename, (Df
ilename) file gorge hill top > dofaino l/side (-y cloak Fig. 77 Fig. 73 [1] Ko BALANCε, <type) <cl) <c2><c3),<c4) [1] Ko BITCOLOR, <sx>, (sy>, <width
) <hsiQht) (index> 口] GAMMA <type) 口1】KOPALETTE j: J-Ra house command 72nd I input/output basic form] Figure 81 (Basic form of input/output command) 口11 MONITOR, (+ycm) 口1】koPPRRε0 口[]koPPR5EL
``Figure 84 DRδtAN command to make it easier to use the 17th power delivery'' Figure 86 PRINT command again and rC=Gen-; Banfu Figure 85 DRPF? So3 who received the INT command'
Figure 87 of column 0 (1, Reverse Fa Ilhif O's Anzu and the seven points and the position) Nomo, -do system 4 〒Σ go 7 (
T! Law, control fL line LfA (1) qθ diagram (49B of 11th notice of color valence) (f6Jb Irimisakiji "ko") 1; Gentle quantity 3
Compare the competition. V,'? 1. VM tya/R @Image data 4. ? 'gf* All doubts are floating! power 1
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14 j

Claims (1)

[Scope of Claims] Reproducing means for reproducing images from a recording medium capable of storing a plurality of images; selection means for selecting a plurality of desired images from the plurality of images; and a memory for storing reproduced images from the reproducing means. Means: in response to an instruction for image formation, the plurality of images selected by the selection means are sequentially reproduced by the reproduction means, stored in the storage means, and the images read by the storage means are formed as visible images. An image forming system comprising an image forming means.