JP3855568B2 - Drain trap - Google Patents

Description

[0001]
BACKGROUND OF THE INVENTION
The present invention relates to a water-sealed drain trap, and more particularly, to a sanitary equipment drain trap suitable for multi-layer buildings.
[0002]
[Prior art]
Generally, a water-sealed drain trap is provided in a sanitary equipment room such as a bathroom. The sealing water of the drain trap has a role of blocking the air inside the drain pipe and the room. The purpose is to prevent odors, sewage gas or pests from drainage pipes, drainage tanks or sewers from entering the sanitary equipment room through the drainage pipe.
[0003]
Conventionally, as a drain trap of a bathroom unit, a resin-made inverted wrinkle drain trap is often used among water-sealed drain traps. The reason for this is that the use of resin as the material is resistant to corrosion, and the reverse trapping drain trap is normally removable, so the inside of the drain trap can be easily cleaned by removing the partition. In addition, the inside of the drain pipe can be cleaned using a dedicated machine.
[0004]
By the way, multi-layered buildings such as apartment houses and office buildings have at least one drainage standpipe penetrating the building in the vertical direction in order to treat the drainage discharged from each floor. On the other hand, wastewater from multiple floors flows. Drainage from the sanitary equipment room on each floor is drained to a drainage standpipe through a drainage side branch pipe on the floor. In this case, when the water is discharged from a certain floor, the air pressure fluctuates in the drainage stack, and the air pressure tends to increase as the drainage flow rate increases. In general, in the lower layer near the drainage horizontal main pipe located at the bottom, the pressure in the drainage stack is a positive pressure compared to the atmospheric pressure. And the inside of the drainage horizontal branch pipe connected to this part also becomes a positive pressure similarly. On the other hand, the pressure inside the upper and middle drainage stacks is negative compared to the atmospheric pressure. And the inside of the drainage horizontal branch pipe connected to this part also becomes negative pressure.
These fluctuations in the pressure in the drainage stack and the horizontal drainage pipe (hereinafter referred to as the pressure in the drainage pipe) propagate to the drainage trap in the sanitary equipment room and affect the sealing water. This effect is as follows.
[0005]
First, when the pressure in the drain pipe changes to a positive pressure, the level of the sealed water on the outflow leg side (drain pipe side) is lowered by being pushed by the positive pressure, and the amount of the sealed water is reduced by the inflow leg side (chamber). Move to the inside) and increase the water level on the inflow leg side. At this time, if the sealed water level on the outflow leg side falls below the lower end of the partition wall, the air passing through the drain trap makes a squeaking noise or intrudes bad smell in the drain pipe into the room.
[0006]
Next, when the air pressure in the drain pipe changes to negative pressure, the sealed water level on the inflow leg side drops, and the amount of the sealed water that moves down moves to the outflow leg side and flows over the overflow edge. And lose. And the greater the fluctuation to the negative pressure side, the greater the loss of sealed water. Even if the pressure in the drain pipe returns to atmospheric pressure after draining is completed, the sealed water level remains lower than the initial water level by the amount of the sealed water that has been lost. Unless there is, there is no recovery of the sealed water level. At this time, if the level of the remaining sealed water is lower than the lower end of the partition wall, it becomes a sealed state in which air can always pass between the inflow leg side and the outflow leg side, and sewage gas and the like constantly enter the indoor side. As a result, the hygienic environment of the living space cannot be maintained.
[0007]
In the conventional drain trap, the case where the pressure in the drain pipe fluctuates will be described below with reference to FIGS. 7, 8, and 9. FIG.
[0008]
FIG. 7 shows a conventional drain trap, which is a vertical cross-sectional view of a bathroom unit attached to a waterproof pan, and shows a case where the pressure in the drain pipe is equal to the atmospheric pressure.
FIG. 8 shows a case where the pressure in the drain pipe is positive with respect to the atmospheric pressure in the conventional drain trap shown in FIG.
FIG. 9 shows a case where the pressure in the drain pipe is negative with respect to the atmospheric pressure in the conventional drain trap shown in FIG.
[0009]
The conventional drain trap shown in FIG. 7 has the following configuration.
The drain trap 10 has a sealed chamber 40, a sealed water 40 b, an overflow edge 50 a, a partition wall 30, and a drain pipe 80. By the partition wall 30, the sealed water chamber 40 is separated into an inflow leg 40d and an outflow leg 40e.
Each shape value in the conventional drain trap shown in FIG. 7 is as follows.
D: Sealing depth (vertical distance between overflow edge 50a and partition lower end 30a) [mm]
Si: Inflow leg cross-sectional area (inner flat cross-sectional area of partition wall 30) [mm ² ]
So: Outflow leg cross-sectional area (= area surrounded by overflow edge 50a-outer flat cross-sectional area of partition wall 30) [mm ² ]
F: Leg cross-sectional area ratio (= So / Si)
[0010]
FIG. 8 shows a case where the pressure in the drain pipe is positive in the conventional drain trap shown in FIG. 7, and the contents thereof will be described below. (The unit [mmAq] used below is 1 [mmAq] = 9.8 [Pa].)
When the positive pressure Pp [mmAq] is generated in the drain pipe 80, the sealing water level of the outflow leg 40e is lowered. The amount of the sealed water that has been lowered moves to the inflow leg 40d side and raises the sealed water level of the inflow leg 40d. The value L [mm] of the vertical distance difference between the sealed water levels of the outflow leg 40e and the inflow leg 40d at this time is equal to the positive pressure value Pp [mmAq]. By design, the limit state for the positive pressure of the drain trap 10 is a state where the sealing water level of the outflow leg 40e is lowered to the partition lower end 30a, and therefore the sealing water level of the outflow leg 40e and the inflow leg 40d at this time is The vertical distance difference value Lmax ′ is equal to the critical positive pressure value Pmax ′ of the drain trap 10. The limit positive pressure value Pmax ′ of the conventional drain trap 10 is given by the above-described values and the following equation.
Pmax '
= Lmax '
= (Si x D + So x D) / Si
= D (1 + F) ... ... (1)
Pmax ': Limit positive pressure value for conventional drain traps [mmAq]
Lmax ': Maximum vertical distance difference of the sealing water level between the outflow leg and the inflow leg [mm]
[0011]
FIG. 9 shows a case where the pressure in the drain pipe is negative in the conventional drain trap shown in FIG. 7, and the contents thereof will be described below.
When the negative pressure Pm [mmAq] is generated in the drain pipe 80, the sealing water level of the inflow leg 40d is lowered by Pm [mm]. The amount of the sealed water that has been lowered moves to the outflow leg 40e side, and flows out beyond the overflow edge 50a. By design, the limit state for the negative pressure of the drain trap 10 is a state in which the sealing water level of the inflow leg 40d is lowered to the partition lower end 30a. Therefore, the limit negative pressure value Pmin '[mmAq] of the drain trap 10 is It is equal to the value D [mm] of the sealing depth. Once this limit negative pressure −Pmin ′ (= −D) [mmAq] is generated in the drain pipe 80 and the negative pressure disappears again, the residual sealed water depth d ′ [mm] and the loss sealed water level δz ′ [ mm] is given by the above-described values and the following equations.
Pmin '= D ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・... (2)
d ′ = So × D / (Si + So) = D × F / (1 + F) (3)
δz ′ = D−d ′ = D / (1 + F) ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・······(Four)
Pmin ': Limit negative pressure value in conventional drain trap [mmAq]
d ': The remaining water depth of the conventional drain trap [mm]
δz ': Loss-sealed water level of conventional drain trap [mm]
[0012]
Here, focusing on the above formulas (1), (3), and (4), in order to increase the sealing strength of the drain trap (the ability to hold the sealed water) against fluctuations in the pressure in the drain pipe It can be said that it is effective to increase the sealing depth D or to increase the leg cross-sectional area ratio F (ratio of the outflow leg cross-sectional area to the inflow leg cross-sectional area).
Therefore, in the conventional drain trap, in order to increase the sealing strength, the sealing depth is increased or the leg cross-sectional area ratio is increased.
[0013]
[Problems to be solved by the invention]
However, simply increasing the sealing depth of the drain trap or simply increasing the leg cross-sectional area ratio just to increase the sealing strength as in the past may cause the following problems. It was.
[0014]
First, the case where the sealing depth of the drain trap is increased will be described below.
FIG. 11 shows an example of a conventional drain trap with an increased sealing depth.
The sealing depth of the conventional drain trap 10 shown in FIG. 11 is D ′, and the sealing depth is larger by t than the sealing depth D of the conventional drain trap 10 shown in FIG. Accordingly, the thickness T ′ of the drain trap 10 in FIG. 11 is thicker by t than the thickness T of the drain trap 10 shown in FIG. These relationships are as follows.
D '= D + t ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・·············(Five)
T '= T + t ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・... (6)
D ′: Sealing depth of the conventional drain trap shown in FIG. 11 [mm]
t: Thickening value of sealed water depth (or drain trap) [mm]
T: Thickness [mm] of the conventional drain trap shown in FIG.
T ′: thickness of the conventional drain trap shown in FIG. 11 [mm]
[0015]
Thus, when the sealing depth of the drain trap is increased, the thickness of the entire drain trap increases. When installing a bathroom unit in an architectural slab in an apartment house, etc., the clearance between the bottom surface of the drain trap provided in the waterproof pan and the building slab is originally small. That is, the installation height of the bathroom unit floor surface must be increased, and as a result, the level difference between the bathroom unit floor surface and the dressing room becomes large, resulting in poor usability.
In general, in apartment buildings, in order to eliminate the level difference between the bathroom unit floor and the dressing room, a pit is provided on the building slab in the area where the bathroom unit is installed, or the entire dwelling unit has a double floor structure. However, the bathroom unit using the drain trap shown in FIG. 11 is deeper than the bathroom unit using the drain trap shown in FIG. As a result, the floor height must be raised, leading to an increase in construction costs.
[0016]
Next, the case where the leg cross-sectional area ratio is increased will be described below.
There are two ways to increase the leg cross-sectional area ratio: reducing the cross-sectional area of the inflow leg or increasing the cross-sectional area of the outflow leg, but both tend to reduce the drainage capacity of the drain trap.
First, when reducing the cross-sectional area of the inflow leg, the amount of water flowing into the drain trap is limited, and the drain capacity of the drain trap is reduced.
In addition, when the cross-sectional area of the outflow leg is enlarged, the drainage capacity of the drainage trap is lowered for the following reason.
Generally, when water flows over a weir or the like, the flow rate q is given by the following formula and each value.
q = K × b × h ^(3/2) ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・・ (7)
q: Flow rate flowing over the weir [water volume per unit time]
K: Flow coefficient
b: Length of weir
h: Water level from the weir
[0017]
When this is applied to the drainage trap, the flow rate flowing over the overflow edge on the outflow leg side corresponds to the flow rate q, and the magnitude of this flow rate affects the superiority or inferiority of the drainage capacity of the drain trap. For this reason, the drainage capacity of the drainage trap can be determined using the flow rate flowing over the overflow edge as an index. Below, this flow is used as an index to compare the effect of the difference in the cross-sectional area of the outflow leg on the drainage capacity of the drain trap.
[0018]
FIG. 10 shows a conventional drain trap.
FIG. 12 shows an example of a conventional drain trap in which the leg cross-sectional area ratio is increased by enlarging the outflow leg cross-sectional area.
The relationship of each shape value of the conventional drain trap shown in FIG. 10 and FIG. 12 is as follows.
So ''> So ................................................ (8)
So: Outflow leg cross-sectional area of the conventional drain trap shown in FIG. ² ]
So '': Outflow leg cross-sectional area of the conventional drain trap shown in FIG. ² ]
Si: Inflow leg cross-sectional area of conventional drain trap (equal to FIG. 10 and FIG. 12) [mm ² ]
[0019]
Here, in the conventional drain trap shown in FIG. 10 and FIG. 12, the amount of water flowing into the drain trap is Qi, and the flow rates flowing over the overflow edge are Qo ′ and Qo ″, respectively. Assuming that the values corresponding to h, i.e., the water levels from the overflow edge, are H ′ and H ″, respectively, these relationships can be obtained from the equation (7) and the above values as follows.
H '= Qi / (Si + So) ... ... (9)
H ″ = Qi / (Si + So ″) ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・·······(Ten)
Qo ′ = K × b × H ′ ^(3/2) = K × b × {Qi / (Si + So)} ^(3/2) ... (11)
Qo ″ = K × b × H ″ ^(3/2) = K × b × {Qi / (Si + So ″)} ^(3/2) ... (12)
∴Qo ''<Qo'... ·············(13)
(∵So ''> So, from formula (8))
Qi: The amount of water flowing into the drain trap [mm ^Three ]
Qo ': Flow rate that flows over the overflow edge of the conventional drain trap shown in Fig. 10 [mm ^Three / sec.]
Qo ″: Flow rate that flows over the overflow edge of the conventional drain trap shown in FIG. ^Three / sec.]
H ': Water level from the overflow edge of the conventional drain trap shown in Fig. 10 [mm]
H ″: Water level from the overflow edge of the conventional drain trap shown in FIG. 12 [mm]
[0020]
Accordingly, the conventional drain trap having a larger leg cross-sectional area ratio due to the enlargement of the cross-sectional area of the outflow leg shown in FIG. 12 has a smaller flow rate that flows beyond the overflow edge than the conventional drain trap shown in FIG. Is low.
[0021]
As can be seen from the above, simply increasing the sealing depth and leg cross-sectional area ratio as conventionally used to increase the sealing strength of the drain trap increases the thickness of the drain trap and decreases the drain capacity. There was a risk of causing a malfunction.
[0022]
The present invention has been made to solve the above-mentioned problems, and the object of the present invention is to increase the pressure of the drain pipe without increasing the thickness of the drain trap and without causing a decrease in drain capacity. It is to provide a drain trap with high sealing strength.
[0023]
[Means for Solving the Problems]
In order to achieve the above object, in claim 1, a reverse chamber having a sealed chamber, a sealed water and an overflowing edge, and a substantially cylindrical partition wall separating the sealed water into an inflow leg and an outflow leg and removable upward. In the trapezoidal drain trap, a flat section where the sealing chamber is wider than the area of the uppermost surface of the sealing water in at least one range within the height below the overflow edge and the height above the lower end of the partition wall. Has area And at least a portion of the flat cross-sectional area portion has a lower flat cross-sectional area larger than the upper flat cross-sectional area. It was characterized by that. For this reason, this drain trap can have a strong sealing strength against the fluctuation of the atmospheric pressure in the drain pipe to the positive pressure side without increasing the thickness and without causing a decrease in drainage capacity. At the same time, when the sealed water of the drain trap freezes, when the sealed water near 0 ° C convects due to its specific gravity, it rises smoothly without staying above the sealed water chamber. The freezing of the sealed water surely starts from the top surface, and the feature also pushes the already frozen sealed water upwards without stressing the sealed chamber as the freezing progresses sequentially, Even if the sealing water of the drain trap freezes, the drain trap will not be destroyed by expansion due to freezing. .
[0024]
In claim 2, The drain trap according to claim 1, When the sealed water depth is D, the inflow leg cross-sectional area is Si, the outflow leg cross-sectional area is So, the leg cross-sectional area ratio is F = So / Si, and the value derived from the following equation using these is Z A plane cross-sectional area in which the sealed chamber is wider than the area of the uppermost surface of the sealed water in at least one range within the range of the height below the overflow edge and the height of the point below Z from the overflow edge Have And at least a portion of the flat cross-sectional area portion has a lower flat cross-sectional area larger than the upper flat cross-sectional area. It was characterized by that. For this reason, the drain trap does not increase in thickness and does not cause a decrease in drainage capacity, and has a strong sealing strength against fluctuations in both the positive pressure side and the negative pressure side of the pressure inside the drain pipe. it can.
Z = D− {So × D / (Si + So)} = D / (1 + F)
[0026]
DETAILED DESCRIPTION OF THE INVENTION
Embodiments of the present invention will be described below with reference to the drawings.
Example 1 is shown in FIGS. 1, 2, 3, and 4 and will be described below.
FIG. 1 is a drainage trap of Example 1, and is a longitudinal sectional view of a state where the drainage trap is attached to a waterproof pan of a bathroom unit.
FIG. 2 shows a case where a positive pressure is generated in the drain pipe in the drain trap of the first embodiment.
FIG. 3 shows a case where a negative pressure is generated in the drain pipe in the drain trap of the first embodiment.
FIG. 4 shows the water level from the overflow edge of the water flowing into the drain trap in the drain trap of Example 1.
[0027]
With reference to FIG. 1, the structure of the drain trap 1 of Example 1 will be described below.
The drain trap body 2 is made of ABS resin. The overflow edge member 5 is made of ABS resin. The overflow edge member 5 includes an overflow edge 5a, an overflow water receiving portion 5b, and a fitting portion 5c. The fitting portion 2a of the drain trap body 2 and the fitting portion 5c of the overflow edge member 5 are bonded with an organic solvent adhesive. This adhesion may be ultrasonic welding. At this time, in any bonding method, the bonded portion is bonded in an airtight and watertight state, and the drain trap body 2 and the overflow edge member 5 are integrated. In the state where the drain trap body 2 and the overflow edge member 5 are integrated, the sealed chamber 4 is formed. The sealed water chamber 4 is filled with the sealed water 4b. The drain trap body 2 is attached to the waterproof pan 6 by the drain trap mounting flange 2b through the packing 2c. The substantially cylindrical partition wall 3 is detachably attached to the drain trap mounting flange 2b via the packing 3b from the washing place 7 side. Thus, the partition wall 3 is detachably attached to the drain trap body 2, and the direction in which the partition wall 3 can be removed is the washing room 7 side. In a state where the partition wall 3 is attached to the drain trap body 2, the sealed water chamber 4 is separated into an inflow leg 4d and an outflow leg 4e. The hair catcher 2d is detachably attached to the drain trap attachment flange 2b. A drain pipe 8 is connected to the drain pipe connection port 2e.
The shape characteristics of the above configuration will be described below.
In the state where the partition wall 3 is attached to the drain trap body 2, the drain trap 1 obtains the following values.
D: Sealed depth (vertical distance between overflow edge 5a and partition lower end 3a) [mm]
Sw: Area of the top surface 4c of the sealed water (area surrounded by the overflow edge 5a) [mm ² ]
Si: Inflow leg cross-sectional area (inner flat cross-sectional area of bulkhead 3) [mm ² ]
So: Outflow leg cross-sectional area (= Sw-outer flat cross-sectional area of bulkhead 3) [mm ² ]
Sb: Flat cross-sectional area of the sealed chamber 4 (however, the cross-sectional area of the portion where Sb> Sw) [mm ² ]
Sx: Area difference between Sb and Sw (Sx = Sb−Sw) [mm ² ]
Zb: Vertical distance [mm] between the uppermost part of the plane cross-sectional area Sb of the sealed chamber 4 and the overflow edge 5a
F: Leg cross-sectional area ratio (= So / Si)
Further, the sealed water chamber 4 has a plane cross-sectional area Sb wider than the area Sw of the sealed water uppermost surface 4c in at least one range within the overflow edge 5a or less and the height of the partition lower end 3a or more. When Z is a value derived from the above values and the following formula, the Z and the value Zb have the following relationship.
Z> Zb ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・···············(14)
Z = D− {So × D / (Si + So)} = D / (1 + F) (15)
[0028]
The flow of drainage from the drain trap 1 will be described below.
Hot water from the washing place 8 flows into the sealed water chamber 4 from the inflow leg 4d, reaches the outflow leg 4e through the bottom of the lower end 3a of the partition wall, flows over the overflow edge 5a to the overflow water receiving portion 5b, and overflows. Water is drained from the water receiving portion 5b to the drain pipe 8.
[0029]
The effects brought about by the above configuration and shape will be described below.
The thickness of the drain trap will be described below with reference to FIG.
When the sealing depth of the drain trap 1 is compared with the sealing depth of the conventional drain trap shown in FIGS. 7 and 11, the size is equal or less. Therefore, the thickness of the drain trap 1 of Example 1 is equal to or less than that of the conventional drain trap.
The operation when a positive pressure is generated in the drain pipe in FIG. 2 will be described below.
When the positive pressure Pp [mmAq] is generated in the drain pipe 8, the sealing water level of the outflow leg 4e is lowered. The amount of the sealed water that has been lowered moves to the inflow leg 4d side and raises the sealed water level of the inflow leg 4d. The value L [mm] of the vertical distance difference between the sealed water levels of the outflow leg 4e and the inflow leg 4d at this time is equal to the positive pressure value Pp [mmAq]. By design, the limit state for the positive pressure of the drain trap 1 is a state in which the sealing water level of the outflow leg 4e is lowered to the lower end 3a of the partition wall. Therefore, the sealing water level of the outflow leg 4e and the inflow leg 4d at this time The value Lmax of the vertical distance difference is equal to the limit positive pressure value Pmax of the drain trap 1. The limit positive pressure value Pmax is given by the shape values of the first embodiment described above and the following equation.
Pmax
= Lmax
= {Sx (D−Zb) + Si × D + So × D} / Si
= D (1 + F) + {Sx (D-Zb) / Si} ...・ (16)
Pmax: Limit positive pressure value [mmAq] in the drain trap of Example 1
Lmax: Maximum vertical distance difference of the sealing water level between the outflow leg and the inflow leg [mm]
Here, in the drain trap 1 of Example 1 and the conventional drain trap shown in FIG. 8, the limits for the case where the pressure in the drain pipe is positive are compared as follows.
Formula (16)-Formula (1)
= Pmax-Pmax '
= Sx (D-Zb) / Si ... ... (17)
> 0
(From Formulas (14) and (15), (D−Zb)> 0)
∴Pmax> Pmax '...・ ・ ・ ・ ・ ・ ・ ・ ・ (18)
Therefore, when the atmospheric pressure in the drain pipe becomes positive, it can be said that the drain trap 1 of Example 1 has a higher limit than the conventional drain trap. .
[0030]
The operation when a negative pressure is generated in the drain pipe in FIG. 3 will be described below.
When negative pressure −Pm [mmAq] is generated in the drain pipe 8, the sealing water level of the inflow leg 4d is lowered by Pm [mm]. The amount of the sealed water that has been lowered moves to the outflow leg 4e side and flows over the overflow edge 5a. By design, the limit state for the negative pressure of the drain trap 1 is a state where the sealing water level of the inflow leg 4d is lowered to the lower end 3a of the partition wall, so that the limit negative pressure value Pmin [mmAq] of the drain trap 1 is It is equal to the water depth value D [mm]. Once this critical negative pressure -Pmin (= -D) [mmAq] is generated in the drain pipe 8 and the negative pressure disappears again, the residual sealed water depth d [mm] and the loss sealed water level δz [mm] Is given by the shape values of the first embodiment described above and the following equations.
Pmin = D ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・... (19)
d = {Sx (D−Zb) + So × D} / (Sx + Si + So) (20)
δz = D-d ... ·············(twenty one)
Pmin: limit negative pressure value of Example 1 [mmAq]
d: Residual water depth [mm] of the drain trap of Example 1
δz: Loss seal water level of drain trap of Example 1 [mm]
[0031]
Here, in the drain trap 1 of Example 1 and the conventional drain trap shown in FIG. 9, the residual water depth and the loss water level are compared as follows.
First, the remaining water depth is compared.
Formula (20)-Formula (3)
= Dd−d ′
= [{Sx (D−Zb) + So × D} / (Sx + Si + So)] − {So × D / (Si + So)}
= {Sx * Si * D-Sx * Zb (Si + So)} / {(Sx + Si + So) (Si + So)}
= {Si × D−Zb (Si + So)} / {(Sx + Si + So) (Si + So) / Sx}
= {D−Zb (1 + F)} / {(Sx + Si + So) (Si + So) / (Sx × Si)}
= {(1 + F) (Z−Zb)} / {(Sx + Si + So) (Si + So) / (Sx × Si)} (22)
> 0
(From equations (14) and (15), {D- (1 + F) Zb} = {(1 + F) (Z-Zb)}> 0)
∴d> d '... ···············(twenty three)
Therefore, when the atmospheric pressure in the drain pipe becomes negative, it can be said that the drain trap 1 of Example 1 has a stronger seal water strength than the conventional drain trap because the remaining seal water depth is larger.
[0032]
Next, the loss sealing water level is compared.
Formula (21)-Formula (4)
= Δz−δz ′
= (Dd)-(Dd ')
=-(D-d ') ... ·············(twenty four)
<0
(From equation (23), d> d ′)
∴δz <δz '・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・ ・·············(twenty five)
Therefore, when the atmospheric pressure in the drain pipe becomes negative, it can be said that the drain trap 1 of Example 1 has stronger seal water strength than the conventional drain trap because the loss seal water level is smaller.
From the above, it can be said that the drainage trap 1 of Example 1 has stronger sealing strength than the conventional drainage trap, regardless of whether the pressure in the drainage pipe is positive or negative.
[0033]
The drainage capacity of the drain trap 1 will be described below with reference to FIG.
In general, when water flows over a weir or the like, the flow rate q is given by equation (7).
When this is applied to the drain trap, the flow rate that flows over the overflow edge on the outflow leg side corresponds to the flow rate q, and the drain rate of the drain trap increases as the flow rate increases. For this reason, the drainage capacity of the drainage trap can be determined using the flow rate flowing over the overflow edge as an index.
In the drain trap shown in FIG. 4, when Qi is the amount of water flowing into the drain top, Qo is the flow rate that flows over the overflow edge, and H is the water level from the overflow edge, these values are obtained from equation (7) and the above values. It is required as follows.
H = Qi / (Si + So) ...・ ・ ・ ・ ・ ・ ・ (26)
Qo = K × b × H ^(3/2) = K × b × {Qi / (Si + So)} ^(3/2) ... (27)
Qi: The amount of water flowing into the drain trap [mm ^Three ]
Qo: Flow rate flowing over the overflow edge of the drain trap of Example 1 [mm ^Three / sec.]
H: Water level from overflow edge of drain trap of Example 1 [mm]
Here, when the flow rate flowing over the overflow edge is compared between the drain trap of the first embodiment and the conventional drain trap shown in FIG. 10 and FIG.
Qo = K × b × {Qi / (Si + So)} ^(3/2) = Qo '>Qo''... 28 (28)
(From equations (11), (13), (27))
Therefore, it can be said that the drainage trap of Example 1 has a drainage capacity equal to or higher than that of the conventional drainage trap because the flow rate flowing over the overflow edge is equal or higher.
[0034]
Example 2 is shown in FIG. 5 and will be described below.
FIG. 5 is a vertical cross-sectional view of the drain trap of Example 2 attached to a waterproof pan of a bathroom unit.
The configuration of the second embodiment is the same as that of the first embodiment.
The shape characteristics of Example 2 will be described below.
The flat cross-sectional area in the inclined portion 5d of the sealed water chamber 4 is larger than the area of the top surface 4c of the sealed water. Other geometric features are the same as those in the first embodiment.
The effects brought about by the above configuration and shape will be described below.
The inclined portion 5d has a truncated cone-like inclined surface with a lower flat cross-sectional area larger than that of the upper flat cross-sectional area. For this reason, under circumstances where the sealing water in the drain trap 1 is frozen, the sealing water near zero degrees Celsius smoothly flows without stagnation above the sealing chamber 4 when convection is caused by its specific gravity. As it rises, the freezing of the sealed water will surely start from the top. Further, as the freezing progresses successively, the already-sealed water is pushed upward without applying stress to the water-sealing chamber 4. Therefore, even if the sealing water of the drain trap 1 freezes, the drain trap 1 is not destroyed by expansion due to freezing. Other functions are the same as those in the first embodiment.
[0035]
Example 3 is shown in FIG. 6 and will be described below.
FIG. 6 is a vertical cross-sectional view of the drain trap according to the third embodiment attached to the waterproof pan 6 of the bathroom unit.
The configuration and shape features of Example 3 will be described below.
The drain trap 1 has an inflow pipe 9 communicating with the inside and outside of the sealed water chamber 4 on the side surface 4a of the sealed water chamber. Other configurations and shape features are the same as those of the second embodiment.
The effects brought about by the above configuration and shape will be described below.
In the third embodiment, drainage from the instrument can be guided to the sealed water chamber 4 through the inflow pipe 9. Other operations are the same as those in the second embodiment.
[0036]
【The invention's effect】
The present invention exhibits the following effects by the above configuration. In claim 1, the drain trap does not increase in thickness and does not cause a decrease in drainage capacity, and has a strong sealing strength against fluctuation of the pressure in the drain pipe to the positive pressure side. At the same time, even if the sealing water of the drain trap freezes, the drain trap will not be destroyed. .
[0037]
In claim 2, The drain trap according to claim 1, The drain trap can have a strong sealing strength against fluctuations in both the positive pressure side and the negative pressure side of the air pressure in the drain pipe without increasing the thickness and without causing a decrease in drainage capacity.
[Brief description of the drawings]
FIG. 1 is a longitudinal sectional view of a drain trap according to a first embodiment attached to a waterproof pan of a bathroom unit, showing a case where the pressure in the drain pipe is equal to the atmospheric pressure.
FIG. 2 shows a case where the pressure in the drain pipe is positive with respect to the atmospheric pressure in the drain trap of the first embodiment.
FIG. 3 shows a case where the atmospheric pressure in the drain pipe is negative with respect to atmospheric pressure in the drain trap of the first embodiment.
FIG. 4 shows the water level from the overflow edge of the water flowing into the drain trap in the drain trap of Example 1.
FIG. 5 is a longitudinal sectional view showing a state in which the drain trap according to the second embodiment is attached to a waterproof pan of a bathroom unit.
FIG. 6 is a longitudinal sectional view showing a state in which the drain trap according to the third embodiment is attached to a waterproof pan of a bathroom unit.
FIG. 7 is a longitudinal sectional view of a conventional drain trap attached to a waterproof pan of a bathroom unit, showing a case where the atmospheric pressure in the drain pipe is equal to the atmospheric pressure.
FIG. 8 shows a case where the pressure in the drain pipe is positive with respect to the atmospheric pressure in the conventional drain trap.
FIG. 9 shows a case where the pressure in the drain pipe is negative with respect to the atmospheric pressure in the conventional drain trap.
FIG. 10 shows the water level from the overflow edge of the water flowing into the drain trap in the conventional drain trap.
FIG. 11 is an example in which the sealing depth is increased in a conventional drain trap.
FIG. 12 is a conventional drainage trap, showing an example in which the leg cross-sectional area ratio is increased by enlarging the outflow leg cross-sectional area, and shows the water level from the overflow edge of the water flowing into the drain trap.
[Explanation of symbols]
1. Drain trap
2 .... Drain trap body
2a: Fitting part
2b: Drain trap mounting flange
2c: Packing
2d ...... hair catcher
2e: Drain pipe connection port
3 ...
3a: Lower end of bulkhead
3b Packing
4 .... Sealing room
4a: Side of sealed water chamber
4b: Sealed water
4c: Sealed water top
4d ... Inflow leg
4e: Outflow leg
5 .... Overflow edge member
5a ... overflowing edge
5b ... overflowing water receiver
5c: Fitting part
5d: Inclined part
6 .... Waterproof pan
7. Washing area
8. Drain pipe
9, ... Inflow pipe

Claims (2)

In the inverted trapezoidal drain trap having a sealing chamber, a sealing water and an overflow edge, and a substantially cylindrical partition wall separating the sealing water into an inflow leg and an outflow leg and removable upward, height at and at least a range within the range of the lower end above the height of the partition wall, the water seal chamber have a large planar cross-sectional area portion than the area of the top surface of the water seal, of the flat cross-sectional area portion A drain trap characterized in that at least in part, a lower cross-sectional area is larger than an upper flat cross-sectional area . When the sealed water depth is D, the inflow leg cross-sectional area is Si, the outflow leg cross-sectional area is So, the leg cross-sectional area ratio is F = So / Si, and the value derived from the following equation using these is Z A plane cross-sectional area in which the sealed chamber is wider than the area of the uppermost surface of the sealed water in at least one range within the range of the height below the overflow edge and the height of the point below Z from the overflow edge have at, at least a portion of the flat cross section part, according to claim 1 drainage trap, wherein the wider planar cross-sectional area of the lower than the plane sectional area of the upper.
Z = D− {So × D / (Si + So)} = D / (1 + F)

Images