JP2785667B2 - Optical disk recording device - Google Patents

Description

DETAILED DESCRIPTION OF THE INVENTION

[0001]

BACKGROUND OF THE INVENTION 1. Field of the Invention The present invention relates to an optical disk recording apparatus for recording video data and audio data on an optical disk, and more particularly, to a method of transmitting audio data of a plurality of channels (or fields) for n (n is an integer of 1 or more) frames (or fields). The present invention relates to an optical disk recording device that records editably on (n + 1) tracks.

[0002]

2. Description of the Related Art Generally, when recording video data and audio data in an optical disk recording apparatus, the optical disk is rotated at a constant speed synchronized with a frame frequency or a field frequency, and a recording clock is changed according to the peripheral speed of a track. Then, high-density recording is performed with the recording bit wavelength kept constant. For example, when recording video data and audio data of the NTSC system, since the frame frequency of the NTSC system is 30 Hz, the optical disk is rotated 30 times per second.
One frame of video data and audio data is recorded per track.

FIG. 11 is a block diagram showing an example of an optical disk recording device. Here, the optical disk 21 can record on both sides, and rotates at a constant speed of 30 rotations per second to record one frame of the video data Dv1 and the audio data Da1 on one track. Optical heads 22 and 23 are provided on the front side and the back side of the optical disk 21, respectively. The optical head 22 moves from the outer circumference to the inner circumference of the optical disk 21 to record the front side recording data D14. The optical disk 21 is simultaneously moved from the inner circumference to the outer circumference to record back side recording data D15.

Now, the shuffling parts 12v and 12a
Are video data Dv1 and audio data Da1
Is shuffled. The outer correction code units 3v and 3a add an outer error correction code to each of the video data Dv12 and the audio data Da1.
Output as 2. The data integration unit 4 outputs the video data D
v12 and audio data Da12 are received and integrated. The inner correction code unit 5 generates recording data D13 by adding synchronization data, an inner correction code, and the like.

[0005] The data distribution unit 6 divides the recording data D13 into recording data on the front side and the back side of the optical disk. The recording encoders 7 and 8 record-encode the divided recording data and distribute the recording data to the optical heads 22 and 23 as front-side recording data D14 and back-side recording data D15. In this case, the sum of the bit rates of the recording data D14 and D15 is always kept constant, and the data distribution is performed according to the distance from the center of the optical disk 21 to each of the optical heads 22 and 23, so that the recording wavelength is kept constant. I am trying to become.

Auxiliary data is added to audio data comprising a plurality of channels and shuffling is performed by adding AUX data to each channel. Thereafter, an error correction code and the like are added, and editing gaps are provided between the channels. Recorded. The AUX data is data indicating information on audio data, such as a sampling frequency, a quantization bit number, and a channel number. The editing gap is a gap on a recording track inserted between video data and audio data and between each channel of audio data, and absorbs head mounting errors, wow and flutter, etc., and performs data editing operations. This area is used to record meaningless data for ease of use.

When recording PAL video data and audio data on an optical disc, the P
The frame frequency of the AL system is 25 Hz, and the bit rate of video data is 25 times higher than that of the NTSC system.
%, So that recording is performed at substantially the same recording bit wavelength as in the case of the NTSC system.
1.25 times the SC system, that is, 37.5 revolutions per second, which is 1.5 times the PAL frame frequency, and two frames are recorded on three tracks.

For example, when recording PAL video data and 4-channel audio data,
As shown in FIG. 12, two frames are recorded on three tracks. Although FIG. 12 shows three tracks on the front side of the optical disk, the same applies to the back side. Here, a track jump gap (TJ), a track address (TA) indicating a track position on the disc, a preamble (PR), an editing gap (E), and 1/6 frame of video data in order from the beginning of each track. (V
0), four-channel audio data (A1, A2, A3, A4) separated by the editing gap (E),
Video data (V1) for 1/6 frame and finally a postamble (PO).

In this case, for video data, 1 /
After shuffling in units of three frames and adding an error correction code or the like, the data is distributed to the front and back surfaces of the optical disk and two frames are recorded on three tracks. For the four-channel audio data A1, A2, A3, and A4, two frames are shuffled for each channel, divided into three parts, and added with an error correction code and the like, and distributed to the front and back surfaces of the optical disk. An editing gap (E) is provided between each channel, and recording is performed on three tracks.

[0010]

SUMMARY OF THE INVENTION As described above, NT
In the case of video data and audio data of the SC system, one frame is recorded on one track, so that data editing in one frame unit can be performed without any trouble.
However, in the case of PAL video data and audio data, one frame cannot be recorded on one track, and two frames are recorded on three tracks. Therefore, for example, in the case of changing the order of still images or synthesizing fast-moving video, which requires data editing in units of one frame or one field, even if video data can be edited, a plurality of channels can be edited. Editing of audio data is impossible.

That is, as shown in FIG. 12, video data is shuffled and recorded in 1/3 frame units, so that editing processing in track units or frame units can be executed relatively easily. However, since audio data of a plurality of channels is shuffled for two frames for each channel and divided and recorded on three tracks,
Data for two frames is mixed in each track, and therefore, it is not possible to perform editing processing in track units or frame units.

An object of the present invention is to record data of n (n is an integer of 1 or more) frames or n fields of (n + 1) frames, for example, when recording PAL video data and audio data. It is an object of the present invention to provide an optical disk recording apparatus capable of recording audio data of a plurality of channels in a track-by-track or frame-by-field or field-by-field basis when recording data in tracks.

[0013]

An optical disk recording apparatus according to the present invention comprises an n (n is an integer of 1 or more) frame (or field) video data and a plurality of channels of audio data having an editing gap between each data. In an optical disc recording apparatus for recording on (n + 1) tracks, shuffling and adding an error correction code to the audio data of the plurality of channels in data units of n / (n + 1) frames (or fields) for each channel. And the like, and recording on the track.

Further, the optical disk recording apparatus of the present invention has an n
(N is an integer of 1 or more) Frame (or field)
Video data and audio data of a plurality of channels by providing an editing gap between the data (n + 1)
In an optical disk recording apparatus for recording on a track of a book,
The audio data of the plurality of channels is subjected to processing such as shuffling and addition of an error correction code in units of data of one frame (or field) for each channel, and the first and (n + 1) tracks of the (n + 1) tracks are processed. On the (n + 1) th track, data for n / (n + 1) frames (or fields) per channel including the editing gap are recorded, and
The (t is an integer of 2 ≦ t ≦ n) track includes the editing gap of the data of the previous frame (or field) of the adjacent frame (or field) (t−1) / (N + 1) frames (or fields) and subsequent frames (or fields)
(N-t + 1) including the editing gap of the data
/ (N + 1) frames (or fields) are recorded.

[0015]

DESCRIPTION OF THE PREFERRED EMBODIMENTS Next, the present invention will be described with reference to the drawings.

FIG. 1 is a block diagram showing one embodiment of the present invention, and the same reference numerals are given to the same components as those in the conventional example shown in FIG. First, a case where two frames of PAL video data and four-channel audio data are recorded on three tracks so as to be editable in track units will be described.

The input PAL video data Dv1
Is that the number of quantization bits is 8 bits (1 byte) and the effective data amount of one frame is 948 samples × 612 lines = 5
It is assumed that the data is 80176 bytes. As shown in FIG. 6, a 2-byte synchronization signal (SYNC), ID signal (SBID), system data (SCDT),
If a sync block (hereinafter abbreviated as SB) composed of a total of 180 bytes of 58 bytes of data (video data and audio data) and 16 bytes of an inner code correction code is to be recorded, one frame of video The data amount is 3672 (580176 ÷ 158) SB. The amount of video data recorded on one track is 24
48 (3672 SB × 2 frames ÷ 3 tracks) SB.

The input audio data Da1 is quantized to 20 bits (2.5 bytes) at a sampling frequency of 48 kHz for each channel as generally used in broadcast VTRs (D-2 VTR, D-3 VTR) and the like. Data. Here, since the rotation speed of the optical disk 21 is 37.5 rotations per second, a sample of audio data of each channel recorded on one track (hereinafter referred to as AS)
The number is 48000 / 37.5 = 1280A
It becomes S. Since 1AS is 2.5 bytes, 1AS
280AS = 1280 × 2.5 = 3200 bytes. Since AUX data is further added to this audio data by 64 AS (160 bytes) per channel, 1344 AS (3360 bytes) audio data is recorded on one track for each channel.

Now, the data unit constituting units 1v and 1a
Are video data Dv1 and audio data Da1
Thus, a data unit for one track, that is, ２ frame is constituted. In this case, AUX is included in the audio data (1280AS) of each channel for one track.
Since the data (64AS) is respectively added, the data amount of the audio data A1, A2, A3, and A4 of four channels is 1344 AS. The shuffling units 2v and 2a shuffle video data and audio data for one track, respectively. Note that shuffling of audio data in the shuffling unit 2a will be described later.

The outer correction code units 3v and 3a add an outer error correction code to the shuffled data and output the video data Dv2 and the audio data Da2. The data integration unit 4 receives and integrates the video data Dv2 and the audio data Da2. The inner correction code unit 5 generates recording data D3 by adding synchronization data, an inner correction code, and the like. The data distribution unit 6 distributes the recording data D3 to the recording data on the front side and the rear side of the optical disc such that the recording wavelength is constant, as in the conventional example. The recording encoders 7 and 8 record-encode the distributed recording data, and send the recording data to the optical heads 22 and 23 as front-side recording data D4 and back-side recording data D5, respectively, for recording.

FIG. 2 shows a data arrangement when video data of two frames and audio data of four channels are recorded on three tracks on the front side of the optical disk, and the rear side has the same arrangement. Here, the track jump gap (T
J), a track address (TA) indicating a track position on the disc, a preamble (PR: 2SB), an editing gap (E: 4SB), 1/6 frame of video data (V0), and an editing gap (E: 4SB), the audio data of four channels (A1, A2,
A3, A4), video data (V
1) Finally, a postamble (PO: 2SB) is arranged. The track jump gap (TJ) and track address (TA) are 380 μm.
It is defined by a time width of sec and 150 μsec.

As described above, in the video data, one track is divided into V0 and V1 corresponding to a frame.
It is distributed to the front and back surfaces of the optical disc and recorded on each track. Also, audio data A1, A of four channels
2, A3, and A4 are shuffled on a track basis for each channel, separated by an editing gap (E), and recorded on each track on the front and back surfaces of the optical disc.

Next, the shuffling of audio data in the shuffling section 2a will be described in detail.

As described above, the amount of audio data of each channel for one track is 1344 AS (3360).
Bytes) and the data area per SB is 15
Since it is 8 bytes, the number of SBs required to record the audio data of each channel on one track is 3360 ÷
Since 158 ≒ 21.26, 22 SBs are required.
Therefore, the shuffling of the audio data is executed for each channel by a shuffling map of 158 rows × 22 columns as shown in FIG.

Here, m indicates the byte number (0 to 157) of the sync block, n indicates the SB number (0 to 21), and the number in the shuffling map indicates the audio data of one track. The sample number (#AS) is shown. By the way, since 1AS is 2.5 bytes,
All write areas in the shuffling map are (158１５
2.5) × 22 = 1390.4 AS. On the other hand, the audio data amount of each channel for one track is 134
4AS, the write area of audio data to be shuffled is set to 1364 AS (m: 0 to 155).
“0” is written in all the remaining areas (m: 155 to 157).

When shuffling, sample numbers # AS0 to # AS1363 are assigned to audio data (1364AS) of each channel, for example, 0 ≦ # AS ≦ 1279 indicates audio valid data,
1280 ≦ # AS ≦ 1299 is “0”, 1300 ≦ #
AS ≦ 1363 is assumed to be AUX data.

Then, shuffling is performed by a shuffling algorithm defined by the following equations (1) to (6).
In this case, since 1AS of the audio data is 20 bits (2.5 bytes), as shown in FIG.
9 (MSB) to b0 (LSB) are converted into 1-byte unit symbols.

N = # AS mod 22... (1) Bits b19 to b12 in [INT (# AS / 22) mod 2 = 0] m = [5 · INT (# AS / 44) + 5 · n] mod 155 (2) bits b11 to b4 in [INT (# AS / 22) mod 2 = 0] m = [5 · INT (# AS / 44) + 5 · n + 1] mod 155 (3) [INT (# AS / 22) bits b3 to b0 in mod 2 = 0] + bits b3 to b0 in [INT (# AS / 22) mod 2 = 1] m = [5 · INT (# AS / 44) + 5 · n + 2] mod 155... (4) bits b19 to b12 in [INT (# AS / 22) mod 2 = 1] m = [5.INT (# AS / 44) + 5.n + 3] mod 155... (5) [INT ( AS / 22) mod 2 = 1 bit b11~b4 in] m = [5 · INT (# AS / 44) +5 · n + 4] mod 155 ...... (6) of the 4-channel audio data A1, A2, A3, A
4, after shuffling for each channel in the shuffling unit 2a based on the above equations (1) to (6), an outer error correction code and an inner error correction code are added, respectively, as shown in FIG. It is a data structure. Here, since the outer error correction code (8SB) is added to the audio data (22SB) of each channel, respectively.
It becomes audio data of each 30SB.

The data distribution section 5 distributes each of the 30 SBs of audio data to the front side and the back side of the optical disk in a ratio of 1: 1 by 15 SBs. That is, 30SB
If the audio data is serially numbered, for example, even-numbered SBs are distributed on the front side, and odd-numbered SBs are distributed on the rear side, and are written simultaneously on both sides of the optical disk. In this way, one track of the four-channel audio data is recorded on the optical disc by performing shuffling processing or the like for each channel. By recording in this manner, data editing processing can be performed in track units.

Next, a method for recording the audio data of four channels in a frame unit so as to be editable will be described.

As described above, the input audio data Da1 has a sampling frequency of 48 for each channel.
The data is quantized to 20 bits (2.5 bytes) at kHz and the frame frequency of the PAL system is 25
Hz. Therefore, the number of audio data samples of each channel per frame is 48000/25 =
1920 AS (4800 bytes). The 1984 AS (4960 bytes) obtained by adding 64 AS (160 bytes) of AUX data to the audio data is shuffled.

In this case, the number of SBs required to record 1984AS (4960 bytes) audio data is as follows:
Since 4960 ÷ 158 ≒ 31.39, 32 SB is required. Therefore, the shuffling of the audio data is executed for each channel by a shuffling map of 158 rows × 32 columns as shown in FIG.

Here, m indicates the byte number (0 to 157) of the sync block, and n indicates the SB number (0 to 31). The number in the shuffling map is the sample number of audio data for one frame (#AS).
Is shown. Incidentally, 1AS is 2.5 bytes, and the entire write area in the shuffling map is (158).
Since (2.5) × 32 = 2022.4 AS, the shuffling map write area is 1984 AS (m: 0 to 0).
155), and “0” is written in all the remaining areas (m: 155 to 157).

At the time of shuffling, sample numbers # AS0 to # AS1983 are respectively assigned to audio data 1984AS for one frame.
0 ≦ # AS ≦ 1919 is audio valid data, 19
20 ≦ # AS ≦ 1983 is AUX data.

Then, shuffling is performed by a shuffling algorithm defined by the following equations (7) to (12). In this case, since 1AS is 20 bits (2.5 bytes) in the audio data, as shown in FIG.
9 (MSB) to b0 (LSB) are converted into 1-byte unit symbols.

N = # AS mod 32 (7) Bits b19 to b12 in [INT (# AS / 32) mod 2 = 0] m = [5 · INT (# AS / 64) + 5 · n] mod 155 (8) Bits b11 to b4 in [INT (# AS / 32) mod 2 = 0] m = [5 · INT (# AS / 64) + 5 · n + 1] mod 155 (9) [INT (# AS / 32) bits b3 to b0 in mod 2 = 0] + bits b3 to b0 in [INT (# AS / 32) mod 2 = 1] m = [5 · INT (# AS / 64) + 5 · n + 2] mod 155 (10) Bits b19 to b12 in [INT (# AS / 32) mod 2 = 1] m = [5 · INT (# AS / 64) + 5 · n + 3] mod 155 (11) [IN (# AS / 32) bits b11 to b4 in mod 2 = 1] m = [5 · INT (# AS / 64) + 5 · n + 4] mod 155 (12) Four-channel audio data A1, A2, A3 A
4 corresponds to the above equations (7) to (1) in the shuffling portion 2a.
After shuffling for each channel based on 2),
The outer error correction code and the inner error correction code are added, respectively, to form a data configuration as shown in FIG. here,
Since the outer error correction code (8SB) is added to the audio data (32SB) of each channel,
It becomes 0SB audio data. This audio data is equally divided and recorded on the front side and the back side of the optical disk.

FIG. 7 shows a data arrangement for recording two frames of 4-channel audio data on three tracks on the front surface side of the optical disk, and the same is applied to the back surface side. Here, a track jump gap (TJ), a track address (TA) indicating a track position on the disk, and a preamble (PR: 2) are sequentially provided from the beginning of each track.
SB), editing gap (E: 4SB), video data (V0) for 1/6 frame, editing gap (E: 4
SB), four channels of audio data (A1, A2, A3, A4), video data (V1) for 1/6 frame, and finally a postamble (PO: 4SB) are arranged.

In this case, each of the front and back surfaces of the optical disc is 3
In the first track of the tracks, each of the 15 SBs of the 4-channel audio data (A1, A2, A3, A4) corresponding to the first frame of the two frames is stored in the 4th track.
The data is separately recorded by the editing gap (E) of B. On the second track on each of the front and rear surfaces of the optical disk, the remaining 5 SBs of the audio data of each channel corresponding to the first frame and the 5 SSBs of the audio data of each channel corresponding to the second frame are provided.
B are separately recorded by the editing gap (E). Further, on the third track on each of the front and back surfaces of the optical disk, 15 SBs of audio data of each channel corresponding to the second frame are recorded separately by an editing gap (E).

In this case, the audio data amount of the first frame recorded on the first track is a total of 80 SBs of the audio data 60 (15 × 4) SB for four channels and the editing gap 20 (4 × 5) SB. And also
The audio data amount of the first frame recorded on the second track is audio data 20 for four channels.
The total number of (5 × 4) SB and the editing gap 20 (4 × 5) SB is 40 SB. Therefore, 2/3 of the total data amount 120SB of the first frame including the editing gap.
Is recorded on the first track, and the remaining 1/3 is recorded on the first half of the second track.

Similarly, the second track to be recorded on the second track
The audio data amount of the frame is a total of 40 SBs of the audio data 20 SB for four channels and the editing gap 20 SB, and the audio data amount of the second frame recorded on the third track is the audio data for four channels. , And the editing gap 20 (4 × 5) SB is a total of 80 SB. Therefore,
Total data amount of the second frame including the gap for editing 1
One third of the 20 SBs is recorded in the latter half of the second track, and the remaining two thirds are recorded in the third track.

As described above, the audio data of four channels is shuffled and error correction codes are added in units of one frame for each channel, an editing gap is provided between the channels, and two frames are recorded on three tracks. By doing so, data editing processing can be performed in units of one frame.

[0042]

As described above, according to the present invention, as in the case of recording PAL video data and audio data, for example, n (n is an integer of 1 or more) frames or n fields are recorded. When recording audio data of a plurality of channels on (n + 1) tracks, one track of the audio data of a plurality of channels is subjected to a shuffling process or the like for each channel, and a gap is provided between channels to be recorded on each track. By doing so, data editing processing can be performed in track units.

Also, by performing a shuffling process or the like for one frame of audio data of a plurality of channels for each channel, and recording each track with a gap between channels, data editing can be performed in frame units. Becomes Therefore, it is possible to edit audio data of a plurality of channels, for example, in the case of changing the order of still images or synthesizing a fast moving image, which requires data editing in units of one frame or one field.

[Brief description of the drawings]

FIG. 1 is a block diagram showing one embodiment of the present invention.

FIG. 2 is a diagram showing an example of an arrangement of PAL video / audio data on a track, which enables data editing processing on a track basis.

FIG. 3 is a diagram showing an example of a shuffling map applied to audio data in track units.

FIG. 4 is a diagram illustrating a shuffling map shown in FIG.
FIG. 9 is a diagram illustrating a process of converting bit audio data into 1-byte symbols.

FIG. 5 is a diagram illustrating a data configuration example of 4-channel audio data in track units.

FIG. 6 is a diagram illustrating a configuration example of a sync block.

FIG. 7 is a diagram showing an example of an arrangement of PAL video / audio data on a track which enables data editing processing in frame units.

FIG. 8 is a diagram illustrating an example of a shuffling map applied to audio data in frame units.

FIG. 9 is a diagram illustrating a 20-bit shuffling map shown in FIG. 8;
FIG. 9 is a diagram illustrating a process of converting bit audio data into 1-byte symbols.

FIG. 10 is a diagram illustrating a data configuration example of audio data of four channels in frame units.

FIG. 11 is a block diagram showing an example of a conventional optical disk recording device.

FIG. 12 is a diagram showing an example of arrangement of conventional PAL video / audio data on a track.

[Explanation of symbols]

 1v, 1a Data unit configuration unit 2v, 2a Shuffling unit 3v, 3a Outer correction code unit 4 Data integration unit 5 Inner correction code unit 6 Data distribution unit 7, 8, Recording coding unit 21 Optical disk Dv1, Dv2 Video data Da1, Da2 Audio data D4 Front side recording data D5 Back side recording data

Claims (2)

(57) [Claims] 1. An optical disk for recording video data of n (n is an integer of 1 or more) frames (or fields) and audio data of a plurality of channels on (n + 1) tracks by providing an editing gap between the data. In the recording apparatus, the audio data of the plurality of channels is subjected to processing such as shuffling and addition of an error correction code in data units of n / (n + 1) frames (or fields) for each channel, and is recorded on the track. An optical disk recording device characterized by the above-mentioned. 2. An optical disk for recording video data of n (n is an integer of 1 or more) frames (or fields) and audio data of a plurality of channels on (n + 1) tracks with an editing gap provided between the data. In the recording apparatus, processing such as shuffling and adding an error correction code is performed on the audio data of the plurality of channels in data units of one frame (or field) for each channel, and the (n + 1) tracks in the (n + 1) tracks are processed. On the first and (n + 1) th tracks, data of n / (n + 1) frames (or fields) per channel including the editing gap are recorded, respectively.
The (t is an integer of 2 ≦ t ≦ n) th track includes the editing gap of the data of the previous frame (or field) of the adjacent frame (or field) (t−1) / (N + 1) frames (or fields) and subsequent frames (or fields)
(N-t + 1) including the editing gap of the data
An optical disk recording apparatus for recording / (n + 1) frames (or fields).