JP2003090334A - Manufacturing method of hub unit for supporting wheel - Google Patents

Abstract

PROBLEM TO BE SOLVED: To prevent generation of cracks, burrs, etc., in a caulked part 9a to suppress an inner ring 3 to a shaft member 2. SOLUTION: The caulked part 9a is formed by plastically deforming a cylindrical part 8a with the wall thickness reduced toward a tip thereof which is formed on an inner end part of the shaft member 2 so as to be expanded outwardly in the diameter direction. The force required to form the caulked part 9a is reduced, the damages less prone to occur, and the supporting force of the inner ring 3 by the caulked part 9a is ensured.

Description

DETAILED DESCRIPTION OF THE INVENTION [0001] BACKGROUND OF THE INVENTION 1. Field of the Invention
Knits allow the wheels of a car to rotate freely relative to the suspension
Use to support. [0002] 2. Description of the Related Art Wheels of automobiles are provided with hub units for supporting wheels.
To the suspension system. FIG. 8 shows a U.S. Pat.
No. 90732, a wheel supporting hub unit
1 shows an example of a knit. This wheel support hub unit
1 includes a shaft member 2, a pair of inner rings 3a and 3b, and an outer ring 4
And a plurality of rolling elements 5 and 5. Shaft of this
The outer end of the outer peripheral surface of material 2
In this state, the outer side in the width direction is the left side in FIG.
Conversely, the side closer to the center in the width direction is called in, and the right side of FIG.
It becomes. ) Has a flange (first
Flange) 6 is formed. The base of this flange 6
A step 7 is formed at the end near the center of the shaft member 2.
are doing. [0003] The pair of inner rings 3a and 3b are connected to the shaft member.
2 from the middle part to the inner end part, of which the outer part
The outer end surface of the inner ring 3a is set on the stepped surface of the step 7 and the inner inner ring
3b to the inner end surface of the outer inner ring 3a.
It is hitting. A cylindrical portion 8 is provided at the inner end of the shaft member 2.
And the inner half of the inner ring 3b is formed at the first half of the cylindrical portion 8.
Fold the part protruding inward from the inner end face outward in the diametric direction.
The swaged portion 9 is formed by bending. Soshi
Between the caulking portion 9 and the step surface of the step portion 7,
The pair of inner rings 3a and 3b are sandwiched. A pair of outer rings 4 are provided on an inner peripheral surface of the outer ring 4.
(First and second) outer raceways 10 and 10 and the inner races 3
(1st, 2nd) inner ring track 1 provided on the outer peripheral surface of a, 3b
The rolling elements 5 and 5 are respectively provided between
Each is provided. In the illustrated example, the rolling elements 5, 5 and
And use balls, but the wheel supports for heavy automobiles
In the case of a portable hub unit, these rolling elements
In some cases, rollers are used. Also, the flange 6
The (first) inner raceway is formed directly on the outer peripheral surface of the shaft member 2.
In some cases, the outer inner ring 3a may be omitted. This place
In this case, the stepped portion 7 is located inside the outer inner ring 3a shown in FIG.
Is formed at a position corresponding to. The hub unit 1 for supporting the wheel as described above is
In order to assemble to the motor vehicle, it was formed on the outer peripheral surface of the outer ring 4
By the outward flange-shaped mounting portion (second flange) 12
The outer ring 4 is fixed to a suspension device, and
Fix the wheels. As a result, this wheel is
It can be rotatably supported. [0006] The conventional structure shown in FIG.
In the case of, the inner rings 3a and 3b are connected and fixed to the shaft member 2.
When forming the caulked portion 9 for caulking, the caulked portion 9
Not only is it easy to cause damage, but it is also
Diametrically outward on the inner peripheral surface of the inner inner ring 3b
Power is added. That is, in the case of the conventional structure, the caulking portion 9 is
In order to form, the inside of the cylindrical portion 8 formed at the inner end of the shaft member 2
Both outer peripheral surfaces are simply cylindrical surfaces that are concentric with each other,
The thickness of the cylindrical portion 8 was the same over the entire length. Because of this,
The first half of the cylindrical portion 8 is swaged and spread, and the swaged portion 9 and
Work requires a lot of power and caulking work is troublesome
In addition to the crimping process, the leading edge of this caulked portion 9
Large tensile stress is applied to the
It will be easier. [0007] Also, a large force is applied during the caulking operation.
Accordingly, the force applied to the inner peripheral surface of the inner inner ring 3b is increased.
Thus, the diameter of the inner ring 3b changes, albeit slightly. Soshi
When the amount of change becomes large, a crack or the like is formed in the inner ring 3b.
This inner ring not only creates the potential for damage
The diameter of the inner ring raceway 11 formed on the outer peripheral surface of 3b has changed.
Shape accuracy (roundness, accuracy of cross-sectional shape)
You. The inner ring raceway 1 provided on the outer peripheral surface of the inner ring 3b
1 and the outer raceway 10 where the inner raceway 11 faces.
The preload applied to the provided rolling elements 5, 5 is maintained at an appropriate value.
The work becomes troublesome, and the durability of the wheel supporting hub unit 1 is improved.
May be difficult to secure. The wheel supporting hub unit according to the present invention
In consideration of various circumstances, the crimping part breaks when fixing the inner ring
(Cracks) and other damage are less likely to occur,
Due to the mounting work, the inner diameter of the inner ring and the outer peripheral surface of this inner ring
The diameter of the inner ring raceway formed in
To ensure that they do not [0009] SUMMARY OF THE INVENTION A hub for supporting a wheel according to the present invention.
The unit is the same as the conventional wheel support hub unit described above.
Similarly, a shaft part having a first flange formed on an outer peripheral surface at one end.
Material on the outer peripheral surface of the intermediate part of this shaft
A first inner raceway formed through an inner race separate from the material,
This first inner raceway formed at the other end of the shaft member
A step portion whose outer diameter is smaller than the portion where the is formed,
A second inner raceway is formed on the outer peripheral surface and is externally fitted to the step.
Inner ring and an inner peripheral surface facing the first inner ring raceway.
Outer raceway and a second outer race facing the second inner raceway
A ring raceway and a second flange on the outer peripheral surface.
Outer ring, the first and second inner ring raceways and the first and second
Between the outer raceway of
A moving body. And at the other end of the shaft member,
Both are formed on the protruding part from the inner ring fitted on the step
Formed by caulking and spreading the cylindrical part
The caulking part allows the inner ring fitted over the step
Hold down the inner ring against the end face and fit the outer ring
It is connected and fixed to the shaft member. In particular, the wheel supporting hub unit of the present invention
In this case, the wall thickness of the cylindrical part is determined by
Smaller toward the leading edge before crimping outward
It's getting worse. In addition, this cylindrical part is swept diametrically outward.
Of the inner ring fitted over the step
The thickness of the swaged part that holds down the end face is the base end of the cylindrical part.
The thickness gradually decreases toward the tip with respect to the thickness of the part. [0011] More preferably, one or more of the following requirements:
Shall have both.   At the other end opening of the inner ring, a flat surface of this inner ring
The other end surface and the inner peripheral surface of this inner ring
An arc-shaped chamfered section is formed.
The outer periphery of the chamfered portion is formed over the entire periphery with the outer periphery of the chamfered portion.
Positioned diametrically inward from the intersection with the inner peripheral edge of the other end surface
I do.   Bisection of the difference between the outer diameter of the caulked portion and the inner diameter of the inner ring
The other end of the inner ring is 1.26 times the swaging width that is one of
The point closer to the center of this inner ring from the surface is the first axial position
And the inner peripheral surface of the cylindrical part for forming the caulking part
The back end position is the second axial position, and the outer end surface of the inner ring is
Of the provided second inner raceway, the other end surface side of the inner race
When the end is in the third axial position, the caulked portion is
In the formed state, the second axial position is the axis of the shaft member.
Regarding the direction, the first axial position and the third axial direction
Position between the two. [0012] The wheel supporting hub of the present invention configured as described above.
Unit allows wheels to rotate freely relative to the suspension
The function itself has the same function as the conventional wheel support hub unit.
It is like. Particularly, in the case of the wheel supporting hub unit of the present invention.
In the case, the thickness of the cylindrical part for forming the caulked part is
This caulking part is formed because it is smaller toward
The power required for the work does not increase unnecessarily. Because of this
Damage such as cracks in the swaged part due to
Alternatively, the diameter of the inner ring fixed to the inner ring
To the extent that it affects durability such as preload and rolling fatigue life.
There is no force that greatly changes. [0013] If the above condition is satisfied,
Cracks, burrs, underfill, etc.
Can be more effectively prevented. In addition, if
Gap between the outer peripheral surface of the caulked portion and the inner peripheral surface of the inner ring.
The strength of support of the inner ring by the caulking
And deformation of the inner raceway can be prevented. [0014] 1 to 7 show an embodiment of the present invention.
Are shown. The feature of the present invention is that the shaft member 2
On the other hand, there is a structure of a portion for fixing the inner ring 3. Also, in this example
In the case, unlike the case of the conventional structure shown in FIG.
One of the inner races 11, 11
The ring track 11 is formed directly on the outer peripheral surface of the shaft member 2.
Therefore, the step 7 is formed at the inner end of the shaft member 2.
You. For the structure and operation of other parts,
8 is the same as the conventional structure shown in FIG.
Omitted or simplified, the following description focuses on the features of the present invention.
Will be described. The inner member formed at the inner end of the shaft member 2
Cylindrical part for forming swaging part 9a for fixing wheel 3
The thickness of the cylindrical portion 8a shown in FIG.
In the state before crimping outward, as you approach the leading edge
It is getting smaller. For this reason, in the case of the illustrated example,
The inner diameter of the inner end surface of the shaft member 2 gradually decreases toward the back.
A tapered hole 13 is formed. The inner ring 3 is fixed to the inner end of the shaft member 2.
In order to crimp the tip of the cylindrical portion 8a as described above,
Is fixed so that the shaft member 2 does not move in the axial direction.
As shown in FIG. 7, as shown in FIG.
3 is pressed down on the outer peripheral surface of the shaft 3
In the state shown in FIG.
Press the pressing die 15 strongly against the tip of the cylindrical portion 8a.
wear. The center of the tip end surface (lower end surface in FIG. 7) of this pressing die 15
Has a truncated cone shape that can be pushed into the inside of the cylindrical portion 8a.
Is formed, and an arc-shaped cross section is formed around the convex portion 16.
Is formed so as to surround the entire circumference of the projection 16.
ing. The shape and size of the cylindrical portion 8a,
In addition, the cross-sectional shape, the outer diameter and the depth of the recess 17 are:
The cylindrical portion 8a is plastically deformed to form the caulked portion 9a.
When forming, the metal (steel) constituting the cylindrical portion 8a is pressed.
While applying a force in the contraction direction, a predetermined shape and
It is regulated to form the caulked portion 9a having a size.
You. The inner end of the shaft member 2 is formed by the caulking portion 9a.
(Right end of FIG. 1, upper end of FIGS. 2, 4, 5, 6, 7)
Around the inner end opening of the inner ring 3
By providing an inner end surface 18 which is a flat surface orthogonal to the center axis,
I have. The inner peripheral edge of the inner end surface 18 and the cylindrical surface
The inner peripheral surface 19 of the inner ring 3 is a curved surface having an arc-shaped cross section.
The chamfered portion 20 is continuous. The inner ring 3 having an inner end shape as described above.
To hold the shaft on the step 7 of the shaft member 2.
The portion 9a expands the cylindrical portion 8a by diametrically outward.
The thickness of the cylinder
Thickness a of the base end of the portion 8a₀ (Fig. 2)
Gradually decrease. That is, as shown in FIG.
The thickness of the base end of the₀ And then head towards the tip
Therefore, the thickness of the caulked portion 9a is a₀ , A₁ , A_Two −−
-A_n , But the relationship between the thicknesses of these parts is a
₀ > A₁ > A_Two > ----> a_n And the above
The thickness a of the tip edge of the caulked portion 9a_n So that it does not become zero
(A_n > 0), for forming the caulked portion 9a,
The cross-sectional shapes of the convex portion 16 and the concave portion 17 are regulated. In order to form the cylindrical portion 8a, the shaft
The inner diameter of the inner end surface of the member 2 becomes gradually smaller toward the back.
The tapered hole 13 is formed by the caulking portion 9 as described above.
This is for forming a. That is, the cylindrical portion 8a is
Of the caulking portion 9a formed by caulking outward
Volume V_9aIs constant, the height H of the cylindrical portion 8a is
_8a(FIG. 6) and the inner peripheral surface 21 of the cylindrical portion 8a is
Angle θ inclined with respect to the central axis of the portion 8a_{twenty one}(FIG. 6)
Is as shown by the curve α in FIG. The above circle
Height H of the cylindrical portion 8a_8aMeans that the caulked portion 9a is formed.
When forming the tapered hole 13
In addition, a mortar-shaped portion formed at the far end of the tapered hole 13
It refers to the axial dimension of the portion excluding 22. The capacity V of the caulked portion 9a is_9aAbove
Significantly affects the strength with which the inner ring 3 is pressed against the shaft member 2
You. That is, this volume V_9aThe larger the is, the stronger the above-mentioned strength
However, the formation of the caulked portion 9a is troublesome.
And the weight of the hub unit for supporting wheels increases.
No. Therefore, the volume V of the caulked portion 9a is_9aThe required strength
Defects are formed in the swaged portion 9a while ensuring a size that can secure
It is necessary to avoid it. Look at the curve α from this surface
The height H_8aAnd angle θ_{twenty one}The smaller the
In other words, the axial length of the cylindrical portion 8a is small,
As the inner peripheral surface 21 of the cylindrical portion 8a becomes closer to the cylindrical surface (FIG. 3).
Part of the inner ring 3).
So-called underfilling, which is separated from the surface, is likely to occur. Like this
In the underfill, the inner ring 3 is restrained by the caulking portion 9a.
It is not preferable because it lowers the breaking strength. Conversely, the height H_8aAnd angle θ_{twenty one}Is large
(B in FIG. 3), in other words, the cylindrical part
8a has a large axial length, and the inner peripheral surface 2 of the cylindrical portion 8a
The more the 1 becomes a conical concave surface from the cylindrical surface, the more the caulked portion 9a
The inner ring 3 is suppressed to the stepped portion 7 with a thin wall at the outer peripheral edge portion.
Burr that is not very useful for installation, or
Is the strength of the part that holds the inner ring 3 toward the step 7
Cracks are likely to occur. Follow
And a predetermined volume V_9aWith the inner ring 3 held down to the shaft member 2 most
In order to secure the strength of_8aAnd angle θ_{twenty one}
Is preferably in a predetermined range between the c-line and the d-line in FIG.
New According to the study of the present inventors, the angle θ_{twenty one}20
Degree, the predetermined volume V_9aThen, the inner ring 3 is the shaft part
It is considered that the strength to suppress the material 2 can be secured. The outer peripheral edge of the caulked portion 9a extends over the entire circumference.
Across the inner peripheral surface of the inner end face 18 in the diametrical direction.
I try to exist. In other words, as shown in FIG.
The outer peripheral edge of the caulked portion 9a is
Intersection between the outer peripheral edge of the chamfered portion 20 and the inner peripheral edge of the inner end surface 18
It is located diametrically inward from point I. Like this
The outer peripheral edge of the caulked portion 9a is set at the intersection I
The reason for positioning it inward in the diameter direction is also
Prevents burrs and cracks from occurring at the outer edge of 9a
To do it. Further, a circle for forming the caulking portion 9a
The back end position of the inner peripheral surface 21 of the cylindrical portion 8a is
Staking width W_9a(FIG. 5) and formed on the outer peripheral surface of the inner ring 3
End of the inner raceway 11 (second inner raceway) on the inner end face 18 side
Regulated in relation to the department. In this regard, FIG.
Will be described. First, the outer diameter D of the caulked portion 9a_9aAnd above
Inner ring 3 inner diameter R_Three Caulking width W which is half of the difference from_9a
｛= (D_9a-R_Three ) / 2｝ 1.26 times (1.26W_9a
= L_9a) Only from the inner end face 18 of the inner ring 3
A point closer to the center in the axial direction is referred to as a first axial position A.
You. Further, the inner end surface 21 is located at the rear end position at the second axial position.
C, and the inner raceway 11 provided on the outer peripheral surface of the inner race 3
Of which, the end of the inner ring 3 on the inner end face 18 side is in the third axial direction.
Position B. In this case, the caulked portion 9a is formed.
The second axial position C is in the axial direction of the shaft member 2
The first axial position A and the third axial direction
Between the first axial position A and the second axial position B.
The height H of the cylindrical portion 8a_8aIs regulated. As described above, the second axial position C is
Reason for regulating in relation to first and third axial positions A and B
Is, again, the pressing of the inner ring 3 by the swaging portion 9a.
In order to maximize the attachment effect,
This is to prevent deformation. First, the second axial position
C is greater than the first axial position A of the cylindrical portion 8a.
When it is located near the tip, the cylindrical portion 8a is swaged and widened.
The outer peripheral surface of a part of the caulking part 9a
Of the inner ring 3 with a chamfered portion 20 formed on the peripheral edge of the inner end opening.
Gaps easily occur between them. And such a gap emerges
In the case where the inner ring 3 is formed, the caulking portion 9a holds down the inner ring 3.
The attaching force is weakened. Conversely, the second axial position C
Is located on the inner raceway 11 side of the third axial position B.
, When the caulked portion 9a is formed,
The part of the ring 3 where the inner raceway 11 is formed has a diameter
An outwardly directed force acts, and the dimensions of this inner raceway 11
Easy to change. Therefore, the second axial position C is
In relation to the first and third axial positions A and B,
It is preferable to regulate as follows. The cylindrical portion 8a having the size and shape as described above.
Plastic deformation to have the shape as described above
In order to form the tightening portion 9a, the inner peripheral surface of the cylindrical portion 8a is required.
21 inclination angle θ_{twenty one}Is preferably about 20 degrees.
Also, the cross-sectional shape of the concave portion 17 constituting the pressing die 15
Makes the tip of the cylindrical portion 8a plastic by the recess 17.
Cross-sectional shape of caulked portion 9a obtained by deforming
However, the thickness decreases gradually from the base end to the tip.
In particular, this thickness dimension decreases sharply at the tip.
As the radius of curvature decreases toward the outer diameter
Face. Also, the outer diameter R of the recess 17₁₇(Figs. 2 and 4)
Is the outer diameter D of the swaged portion 9a to be formed._9aSame as or this
Outer diameter D of caulking portion 9a_9aSlightly smaller than (R₁₇
≤D_9a)I have to. Further, the depth D of the recess 17
₁₇(FIGS. 2 and 4) show an inner peripheral surface and an inner end of the inner end of the inner ring 3.
The front end of the cylindrical portion 8a is sandwiched between the
With the caulked portion 9a formed, the tip surface of the pressing die 15
A gap 23 remains between the inner ring 3 and the inner end surface 18 of the inner ring 3.
Regulations. The projections 16 and the depressions having the above-described shapes and dimensions are provided.
The pressing die 15 having the portion 17 is attached to the tip of the cylindrical portion 8a.
When pressed, the tip of the cylindrical portion 8a is moved outward in the diameter direction.
It is possible to form the caulked portion 9a by caulking and spreading.
You. The caulked portion 9a and the inner end of the shaft member 2 are shaped.
The inner ring 3 is sandwiched between the formed step portion 7 and the step surface 24.
Thus, the inner ring 3 can be fixed to the shaft member 2. Illustrated example
In the case of, the inner end face of the cylindrical portion 8a is plastically deformed.
In the final stage of forming the caulked portion 9a by the
From the inner surface of the concave portion 17 to the outer peripheral surface of the caulked portion 9a,
A compressive force acts inward in the direction. Therefore, this caulking
Effectively prevent damage such as cracks on the outer peripheral edge of the portion 9a
Can be prevented. Also, the outer peripheral surface of the base end of the caulked portion 9a is
In contact with the inner peripheral edge of the inner end of the inner ring 3, an arc-shaped cross section
Is formed. Therefore, the caulking part
The radius of curvature at the base end of 9a does not decrease,
Unnecessary stress is less likely to be applied to the end. As described above, the wheel supporting hub unit of the present invention
In the case of ト, the cylindrical portion 8a for forming the caulked portion 9a
The thickness of this cylinder is reduced toward the leading edge, so this cylinder
The tip of the portion 8a is plastically deformed by the pressing die 15 as described above.
The force required to form the caulked portion 9a
It does not grow. For this reason, caulking is accompanied by caulking work
Damage such as a crack may occur in the caulking portion 9a or the caulking portion 9
a, the diameter of the inner ring 3
Changes greatly to affect durability such as rolling fatigue life
There is no force to act. In particular, in the example shown
Is applied when compressive stress is applied to the tip of the caulked portion 9a.
The radius of curvature at the base end of the caulked portion 9a is increased.
Therefore, it is possible to more effectively prevent the damage of the caulked portion 9a.
You. Incidentally, the plurality of rolling elements 5, 5
Action line of the applied load (the chain in FIG. 1 showing the contact angle of the rolling element 5)
The line β coincides with the inner peripheral surface of the inner race 3 and the shaft member 2.
It passes through the fitting surface with the tip and passes through the caulking portion 9a
It is preferable to avoid such a situation. Regulations that regulate this way
The reason is that the above load causes the caulked portion 9a to
This caulking part 9 does not work as a deforming force.
This is to prevent breakage of a. Next, of the inner races 3, the inner raceway 1
Cross-sectional area of a portion closer to the outside than 1 (XX line in FIG. 2)
S_Three And the sectional area S of the shaft member 2 in the portion_Two Relationship with
For the person in charge, S_Three <S_Two And more preferably S_Three ≤
0.94S_Two And The cross-sectional area of each part is regulated in this way.
The reason for this is that the inner ring 3 is supported on the shaft member 2.
This is to ensure strength. That is, the caulking portion 9a and the front
With the inner ring 3 held between the stepped surface 24 and the
To prevent the inner ring 3 from rotating.
The axial force of the shaft member 2 and the inner ring 3 extends in the axial direction.
Determined by the difference in the amount of distortion. That is, during caulking, the inner ring 3
Is larger than the elastic deformation of the shaft member 2. So
After completion of the caulking, the inner ring 3 and the shaft member 2
Is elastically restored, and an axial force (axial force) is applied to the inner ring 3.
Given. Material of the inner ring 3 and the shaft member 2
Since the material has almost the same elastic modulus, as described above, S
_Three<S_Two Then, the amount of elastic deformation during the caulking process is
Inner ring 3 is larger than 2. Therefore, the cross-sectional area of each part
With this restriction, a sufficient compressive load is applied to the inner ring 3.
While the inner ring 3 rotates with respect to the shaft member 2,
So-called creep can be effectively prevented. [0030] DESCRIPTION OF THE PREFERRED EMBODIMENTS Next, a case for realizing a structure as shown in FIGS.
An example of the appropriate value of the dimensions of each part in the case
You. In addition, the material of the shaft member 2 and the inner ring 3 is carbon 0.4 to
0.6% by weight structural carbon steel (S53C)
Induction hardening is performed on required portions such as the track 11 portion. Destination
, The inner diameter R of the inner ring 3 to be fixed to the shaft member 2_Three (Fig. 5)
It is 26.0 mm. Also, is it the axial end edge of the caulked portion 9a?
The cylindrical portion 8a for forming the caulked portion 9a (see FIG.
6) The second axial position C which is the innermost position of the inner peripheral surface 21
Axial distance L to_C Is set to 7.5 mm. In addition,
From the inner end surface 18 of the ring 3 to the outer peripheral surface of the inner ring 3
Third axial direction which is the inner end surface 18 side end of the inner ring raceway 11
Distance L to position B₁₁Is 9.36 mm. In addition,
The inner diameter of the inner peripheral surface 21 at the position C in the second axial direction
r_{twenty one}Is set to 11.4 mm. Also, the second and third axial directions
Axial distance L between positions B and C_BCIs 3.86 mm. This
In the case of the first axial position A described above and the second axial direction
Axial distance L from direction position C _AC(Not shown) is 0.5mm
I do. In addition, at the first axial position A,
Thickness a of female part 9a₀ Is 7.3 mm. Further, the inner end
The continuous point I between the surface 18 and the chamfered portion 20 and the caulked portion 9a
Is 0.96 mm. The cylindrical portion 8a formed at the inner end of the shaft member 2 is
Work for plastic deformation to form the caulking portion 9a as described above
Is performed by a swing press process as shown in FIG. this
The rocking press working is performed, for example, in a lock having a capacity of about 100 t.
Uses an oscillating press machine called King Press
And the swing angle θ of the pressing die 15₁₅About 2 seconds, about 5 seconds
Processing in a swinging time of degrees. [0032] The wheel supporting hub unit according to the present invention has the following features.
Cracks in the swaged section as configured and acts as described above
To prevent the occurrence of damage such as
To prevent the occurrence of underfill that is not used for inner ring support.
You. Also, the inner ring fixed to the shaft member by the caulking part
It is possible to prevent the diameter from changing so much that it becomes a practical problem. So
Then, fix the inner ring to the inner ring and the caulking section
To reduce the likelihood of defects and damage
In both cases, the preload can be maintained at an appropriate value.

BRIEF DESCRIPTION OF THE DRAWINGS FIG. 1 is a sectional view showing an example of an embodiment of the present invention. FIG. 2 is a partial cross-sectional view showing a state where an inner end portion of a shaft member is swaged and widened in order to fix an inner ring during manufacturing. FIG. 3 is a diagram showing the relationship between the height of a cylindrical portion and the angle at which the inner peripheral surface of the cylindrical portion is inclined with respect to the center axis of the cylindrical portion, when the volume of the caulked portion is constant. . FIG. 4 is a partial cross-sectional view for explaining the thickness of a caulked portion. FIG. 5 is a partial sectional view for explaining a positional relationship between a caulked portion and an inner ring. FIG. 6 is a partial cross-sectional view showing a state before the inner end of the shaft member is swaged and widened. FIG. 7 is a partial cross-sectional view showing a state where a caulked portion is formed. FIG. 8 is a sectional view showing an example of a conventional structure. DESCRIPTION OF SYMBOLS 1 Wheel support hub unit 2 Shaft member 3, 3a, 3b Inner ring 4 Outer ring 5 Rolling element 6 Flange 7 Step 8, 8a Cylindrical section 9, 9a Caulking section 10 Outer raceway 11 Inner raceway 12 Mounting section 13 Taper hole 14 Suppression piece 15 Press mold 16 Convex portion 17 Recess 18 Inner end surface 19 Inner peripheral surface 20 Chamfered portion 21 Inner peripheral surface 22 Mortar-shaped portion 23 Gap 24 Step surface

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[Procedure amendment] [Submission date] August 7, 2002 (2002.8.7) [Procedure amendment 1] [Document name to be amended] Statement [Correction target item name] Full text [Correction method] Change [Correction contents] [Document Name] Statement [Title of the Invention] Hub unit for supporting wheelsManufacturing method [Claims] 1. A first flange is formed on an outer peripheral surface at one end.
Directly or on the outer peripheral surface of the shaft member
A first inner ring gauge formed through an inner ring separate from the shaft member of
A road and the first inner portion formed at the other end of the shaft member.
A step whose outer diameter is smaller than the part where the wheel raceway is formed
And a second inner raceway formed on the outer peripheral surface and
The inner ring fitted is opposed to the inner raceway on the inner peripheral surface.
The first outer raceway and the second inner raceway facing the second inner raceway.
The second outer ring raceway, the second flange on the outer peripheral surface, respectively
The formed outer ring, the first and second inner ring raceways and the
Provide multiple pieces between the first and second outer ring raceways
Provided at the other end of the shaft member.
Is also formed at the part protruding from the inner ring fitted to the step
Was formed by caulking and expanding the cylindrical part that was
The inner ring fitted to the step is fitted to the end of the step
Surface of the inner ring,
Wheel support hub unit fixedly connected to memberManufacture
For this reason, the wheel support c for processing the cylindrical part into the caulked part
Manufacturing methodAtThe above inner ring by the holding piece
The outer peripheral surface of the shaft member and the shaft member
Press the die strongly against the tip of the cylindrical part.
And process this cylindrical part into the above caulked partFeatures
Wheel support hub unitManufacturing method. [Claim 2An inner ring having a small diameter portion on the outer peripheral surface of the end
A cylindrical part formed on the other end of this shaft member after externally fitting
The diameter including the part existing in the radial direction inside of this small diameter part
2. A caulked portion formed by caulking outward in the direction.
3. The method for manufacturing a wheel supporting hub unit according to item 1. DETAILED DESCRIPTION OF THE INVENTION [0001] BACKGROUND OF THE INVENTIONTarget of manufacturing method
BecomeThe wheel supporting hub unit suspends the wheels of the automobile.
It is used to rotatably support the device. [0002] 2. Description of the Related Art Wheels of automobiles are provided with hub units for supporting wheels.
To the suspension system. FIG. 8 shows a U.S. Pat.
No. 90732, a wheel supporting hub unit
1 shows an example of a knit. This wheel support hub unit
1 includes a shaft member 2, a pair of inner rings 3a and 3b, and an outer ring 4
And a plurality of rolling elements 5 and 5. Shaft of this
The outer end of the outer peripheral surface of material 2
In this state, the outer side in the width direction is the left side in FIG.
Conversely, the side closer to the center in the width direction is called in, and the right side of FIG.
It becomes. ) Has a flange (first
Flange) 6 is formed. The base of this flange 6
A step 7 is formed at the end near the center of the shaft member 2.
are doing. [0003] The pair of inner rings 3a and 3b are connected to the shaft member.
2 from the middle part to the inner end part, of which the outer part
The outer end surface of the inner ring 3a is set on the stepped surface of the step 7 and the inner inner ring
3b to the inner end surface of the outer inner ring 3a.
It is hitting. A cylindrical portion 8 is provided at the inner end of the shaft member 2.
And the inner half of the inner ring 3b is formed at the first half of the cylindrical portion 8.
Fold the part protruding inward from the inner end face outward in the diametric direction.
The swaged portion 9 is formed by bending. Soshi
Between the caulking portion 9 and the step surface of the step portion 7,
The pair of inner rings 3a and 3b are sandwiched. A pair of outer rings 4 are provided on an inner peripheral surface of the outer ring 4.
(First and second) outer raceways 10 and 10 and the inner races 3
(1st, 2nd) inner ring track 1 provided on the outer peripheral surface of a, 3b
The rolling elements 5 and 5 are respectively provided between
Each is provided. In the illustrated example, the rolling elements 5, 5 and
And use balls, but the wheel supports for heavy automobiles
In the case of a portable hub unit, these rolling elements
In some cases, rollers are used. Also, the flange 6
The (first) inner raceway is formed directly on the outer peripheral surface of the shaft member 2.
In some cases, the outer inner ring 3a may be omitted. This place
In this case, the stepped portion 7 is located inside the outer inner ring 3a shown in FIG.
Is formed at a position corresponding to. The hub unit 1 for supporting the wheel as described above is
In order to assemble to the motor vehicle, it was formed on the outer peripheral surface of the outer ring 4
By the outward flange-shaped mounting portion (second flange) 12
The outer ring 4 is fixed to a suspension device, and
Fix the wheels. As a result, this wheel is
It can be rotatably supported. [0006] [Problems to be solved by the invention]Wheel support c of the present invention
The manufacturing method of the wheel unit is as described above with reference to FIG.
Improvement of manufacturing method of support hub unit. [0007] [0008] [0009] SUMMARY OF THE INVENTIONTarget of manufacturing method
BecomesThe wheel supporting hub unit is the conventional wheel described above.
Like the supporting hub unit, the first flange is provided on the outer peripheral surface at one end.
A shaft member having a flange and an outer peripheral surface of an intermediate portion of the shaft member
Formed directly or through an inner ring separate from this shaft member.
First inner raceway, and formed at the other end of the shaft member
In addition, the outer diameter dimension is larger than the part where this first inner raceway is formed.
Formed a smaller inner step and a second inner ring raceway on the outer peripheral surface
And the inner ring externally fitted to the step portion and the first peripheral surface on the inner peripheral surface.
A first outer raceway facing the inner raceway and the second inner race
A second outer ring raceway facing the raceway is provided with a second flange on the outer peripheral surface.
The outer ring formed respectively with the first and second inner rings.
Between the ring raceway and the first and second outer raceways, respectively
And a plurality of rolling elements provided. And the above
At least the inner ring fitted to the step at the other end of the shaft member
The cylindrical part formed at the protruding part
The caulking part formed by squeezing and spreading
Hold the fitted inner ring toward the end face of this step
The inner race fitted to the outer part is connected and fixed to the shaft member. [0010]The wheel supporting hub unit of the present invention
To manufacture a hub unit for wheel support like
This is a method of processing a part into the above-mentioned caulked part.In particular, the invention
Wheel support hub unitManufacturing methodInRestraint
The outer surface of the inner ring is held down by a piece, and the shaft
Push the die into the above cylindrical part while preventing radial deflection.
Press the cylinder part firmly against the tip of
Process. [0011] [0012] According to the present invention constructed as described above,Made by manufacturing method
WasThe wheel support hub unit allows the vehicle to be
The function of supporting the wheel rotatably is the same as the conventional wheel support
Same as the hub unit. In particular, for wheel support of the present invention
Hub unitManufacturing methodIf necessary, form a swage
ToAt this time, the shaft member does not move in the diameter direction. [0013] [0014] 1 to 7 show an embodiment of the present invention.
Are shown. still,This exampleThe feature of
To fix the inner ring 3And processing this structure
Manufacturing methodIt is in. Also, in the case of this example, the prior art shown in FIG.
Unlike the case of the structure, one inner ring 3 is used and one pair of inner rings
The outer inner raceway 11 of the raceways 11, 11 is a shaft member 2
Is formed directly on the outer peripheral surface of. Therefore, the stepped portion 7 is
It is formed at the inner end of the member 2. Other parts structure and
The effect is the same as that of the conventional structure shown in FIG.
Therefore, duplicate explanations are omitted or simplified, and
under,This exampleThe following description focuses on the characteristic portions of The inner member formed at the inner end of the shaft member 2
Cylindrical part for forming swaging part 9a for fixing wheel 3
The thickness of the cylindrical portion 8a shown in FIG.
In the state before crimping outward, as you approach the leading edge
It is getting smaller. For this reason, in the case of the illustrated example,
The inner diameter of the inner end surface of the shaft member 2 gradually decreases toward the back.
A tapered hole 13 is formed. The inner ring 3 is fixed to the inner end of the shaft member 2.
In order to crimp the tip of the cylindrical portion 8a as described above,
Is fixed so that the shaft member 2 does not move in the axial direction.
As shown in FIG., 14By
The outer peripheral surface of the inner ring 3 is pressed down, and the inner ring 3 is externally fitted.
In the state where the shaft member 2 is prevented from diametrically moving,
As shown in the figure, the pressing die 15 is firmly attached to the tip of the cylindrical portion 8a.
Press firmly. Tip surface of this press die 15 (lower end surface in FIG. 7)
In the center, a circle that can be pushed inside the cylindrical portion 8a
A frustum-shaped protrusion 16 is formed, and a cross section is formed around the protrusion 16.
The concave portion 17 having an arc shape is placed around the entire circumference of the convex portion 16.
Has formed. In addition,In the illustrated example, the outer periphery of the end of the inner ring 3
A small diameter portion 25 is provided on the surface. And this inner ring 3
After being externally fitted to the shaft member 2, the outer ring
The part closer to the inner ring raceway 11 than the diameter part 25 is the holding piece 1
Formed on the inner end of this shaft member 2 while holding down by 4 and 14
The pressing die 15 is pressed against the formed cylindrical portion 8a. Soshi
The lever cylindrical portion 8a is located radially inside the small diameter portion 25.
Caulking out radially outward including the existing part,
The recess 9a is formed. or,The shape and size of the cylindrical portion 8a
Size, the cross-sectional shape of the concave portion 17, and the outer diameter and
The depth is determined by plastically deforming the cylindrical portion 8a and crimping the cylindrical portion 8a.
When forming the cylindrical portion 9a, the metal forming the cylindrical portion 8a
While applying a force in the compression direction to (steel), the specified
To form the caulked portion 9a having the shape and size described above.
Regulations. Note that the shaft member is formed by the caulking portion 9a.
2 inner end (right end in FIG. 1, upper end in FIGS. 2, 4, 5, 6, and 7)
Around the inner end opening of the inner ring 3 for fixing to the
Inner end surface 18 which is a flat surface orthogonal to the central axis of wheel 3
Is provided. Then, the inner peripheral edge of the inner end face 18 and the circle
The inner peripheral surface 19 of the inner ring 3 which is a cylindrical surface is
It is continued by a chamfered portion 20 which is a curved surface. The inner ring 3 having an inner end shape as described above.
To hold the shaft on the step 7 of the shaft member 2.
The portion 9a expands the cylindrical portion 8a by diametrically outward.
The thickness of the cylinder
Thickness a of the base end of the portion 8a₀ (Fig. 2)
Gradually decrease. That is, as shown in FIG.
The thickness of the base end of the₀ And then head towards the tip
Therefore, the thickness of the caulked portion 9a is a₀ , A₁ , A_Two −−
-A_n , But the relationship between the thicknesses of these parts is a
₀ > A₁ > A_Two > ----> a_n And the above
The thickness a of the tip edge of the caulked portion 9a_n So that it does not become zero
(A_n > 0), for forming the caulked portion 9a,
The cross-sectional shapes of the convex portion 16 and the concave portion 17 are regulated. In order to form the cylindrical portion 8a, the shaft
The inner diameter of the inner end surface of the member 2 becomes gradually smaller toward the back.
The tapered hole 13 is formed by the caulking portion 9 as described above.
This is for forming a. That is, the cylindrical portion 8a is
Of the caulking portion 9a formed by caulking outward
Volume V_9aIs constant, the height H of the cylindrical portion 8a is
_8a(FIG. 6) and the inner peripheral surface 21 of the cylindrical portion 8a is
Angle θ inclined with respect to the central axis of the portion 8a_{twenty one}(FIG. 6)
Is as shown by the curve α in FIG. The above circle
Height H of the cylindrical portion 8a_8aMeans that the caulked portion 9a is formed.
When forming the tapered hole 13
In addition, a mortar-shaped portion formed at the far end of the tapered hole 13
It refers to the axial dimension of the portion excluding 22. The capacity V of the caulked portion 9a is_9aAbove
Significantly affects the strength with which the inner ring 3 is pressed against the shaft member 2
You. That is, this volume V_9aThe larger the is, the stronger the above-mentioned strength
However, the formation of the caulked portion 9a is troublesome.
And the weight of the hub unit for supporting wheels increases.
No. Therefore, the volume V of the caulked portion 9a is_9aThe required strength
Defects are formed in the swaged portion 9a while ensuring a size that can secure
It is necessary to avoid it. Look at the curve α from this surface
The height H_8aAnd angle θ_{twenty one}The smaller the
In other words, the axial length of the cylindrical portion 8a is small,
As the inner peripheral surface 21 of the cylindrical portion 8a becomes closer to the cylindrical surface (FIG. 3).
Part of the inner ring 3).
So-called underfilling, which is separated from the surface, is likely to occur.Like this
WhatThe underfill is suppressed by the caulking portion 9a of the inner ring 3.
It is not preferable because it lowers the breaking strength. Conversely, the height H_8aAnd angle θ_{twenty one}Is large
(B in FIG. 3), in other words, the cylindrical part
8a has a large axial length, and the inner peripheral surface 2 of the cylindrical portion 8a
The more the 1 becomes a conical concave surface from the cylindrical surface, the more the caulked portion 9a
The inner ring 3 is suppressed to the stepped portion 7 with a thin wall at the outer peripheral edge portion.
Burr that is not very useful for installation, or
Is the strength of the part that holds the inner ring 3 toward the step 7
Cracks are likely to occur. Follow
And a predetermined volume V_9aWith the inner ring 3 held down to the shaft member 2 most
In order to secure the strength of_8aAnd angle θ_{twenty one}
Is preferably in a predetermined range between the c-line and the d-line in FIG.
New According to the study of the present inventors, the angle θ_{twenty one}20
Degree, the predetermined volume V_9aThen, the inner ring 3 is the shaft part
It is considered that the strength to suppress the material 2 can be secured. The outer peripheral edge of the caulked portion 9a extends over the entire circumference.
Across the inner peripheral surface of the inner end face 18 in the diametrical direction.
I try to exist. In other words, as shown in FIG.
The outer peripheral edge of the caulked portion 9a is
Intersection between the outer peripheral edge of the chamfered portion 20 and the inner peripheral edge of the inner end surface 18
It is located diametrically inward from point I. Like this
The outer peripheral edge of the caulked portion 9a is set at the intersection I
The reason for positioning it inward in the diameter direction is also
Prevents burrs and cracks from occurring at the outer edge of 9a
To do it. Further, a circle for forming the caulking portion 9a
The back end position of the inner peripheral surface 21 of the cylindrical portion 8a is
Staking width W_9a(FIG. 5) and formed on the outer peripheral surface of the inner ring 3
End of the inner raceway 11 (second inner raceway) on the inner end face 18 side
Regulated in relation to the department. In this regard, FIG.
Will be described. First, the outer diameter D of the caulked portion 9a_9aAnd above
Inner ring 3 inner diameter R_Three Caulking width W which is half of the difference from_9a
｛= (D_9a-R_Three ) / 2｝ 1.26 times (1.26W_9a
= L_9a) Only from the inner end face 18 of the inner ring 3
A point closer to the center in the axial direction is referred to as a first axial position A.
You. Further, the inner end surface 21 is located at the rear end position at the second axial position.
C, and the inner raceway 11 provided on the outer peripheral surface of the inner race 3
Of which, the end of the inner ring 3 on the inner end face 18 side is in the third axial direction.
Position B. In this case, the caulked portion 9a is formed.
The second axial position C is in the axial direction of the shaft member 2
The first axial position A and the third axial direction
Between the first axial position A and the second axial position B.
The height H of the cylindrical portion 8a_8aIs regulated. As described above, the second axial position C is
Reason for regulating in relation to first and third axial positions A and B
Is, again, the pressing of the inner ring 3 by the swaging portion 9a.
In order to maximize the attachment effect,
This is to prevent deformation. First, the second axial position
C is greater than the first axial position A of the cylindrical portion 8a.
When it is located near the tip, the cylindrical portion 8a is swaged and widened.
The outer peripheral surface of a part of the caulking part 9a
Of the inner ring 3 with a chamfered portion 20 formed on the peripheral edge of the inner end opening.
Gaps easily occur between them. And such a gap emerges
In the case where the inner ring 3 is formed, the caulking portion 9a holds down the inner ring 3.
The attaching force is weakened. Conversely, the second axial position C
Is located on the inner raceway 11 side of the third axial position B.
, When the caulked portion 9a is formed,
The part of the ring 3 where the inner raceway 11 is formed has a diameter
An outwardly directed force acts, and the dimensions of this inner raceway 11
Easy to change. Therefore, the second axial position C is
In relation to the first and third axial positions A and B,
It is preferable to regulate as follows. The cylindrical portion 8a having the size and shape as described above.
Plastic deformation to have the shape as described above
In order to form the tightening portion 9a, the inner peripheral surface of the cylindrical portion 8a is required.
21 inclination angle θ_{twenty one}Is preferably about 20 degrees.
Also, the cross-sectional shape of the concave portion 17 constituting the pressing die 15
Makes the tip of the cylindrical portion 8a plastic by the recess 17.
Cross-sectional shape of caulked portion 9a obtained by deforming
However, the thickness decreases gradually from the base end to the tip.
In particular, this thickness dimension decreases sharply at the tip.
As the radius of curvature decreases toward the outer diameter
Face. Also, the outer diameter R of the recess 17₁₇(Figs. 2 and 4)
Is the outer diameter D of the swaged portion 9a to be formed._9aSame as or this
Outer diameter D of caulking portion 9a_9aSlightly smaller than (R₁₇
≤D_9a)I have to. Further, the depth D of the recess 17
₁₇(FIGS. 2 and 4) show an inner peripheral surface and an inner end of the inner end of the inner ring 3.
The front end of the cylindrical portion 8a is sandwiched between the
With the caulked portion 9a formed, the tip surface of the pressing die 15
A gap 23 remains between the inner ring 3 and the inner end surface 18 of the inner ring 3.
Regulations. The projections 16 and the depressions having the above-described shapes and dimensions are provided.
The pressing die 15 having the portion 17 is attached to the tip of the cylindrical portion 8a.
When pressed, the tip of the cylindrical portion 8a is moved outward in the diameter direction.
It is possible to form the caulked portion 9a by caulking and spreading.
You. The caulked portion 9a and the inner end of the shaft member 2 are shaped.
The inner ring 3 is sandwiched between the formed step portion 7 and the step surface 24.
Thus, the inner ring 3 can be fixed to the shaft member 2. Illustrated example
In the case of, the inner end face of the cylindrical portion 8a is plastically deformed.
In the final stage of forming the caulked portion 9a by the
From the inner surface of the concave portion 17 to the outer peripheral surface of the caulked portion 9a,
A compressive force acts inward in the direction. Therefore, this caulking
Effectively prevent damage such as cracks on the outer peripheral edge of the portion 9a
Can be prevented. Also, the outer peripheral surface of the base end of the caulked portion 9a is
In contact with the inner peripheral edge of the inner end of the inner ring 3, an arc-shaped cross section
Is formed. Therefore, the caulking part
The radius of curvature at the base end of 9a does not decrease,
Unnecessary stress is less likely to be applied to the end. As described aboveThis exampleWheel support hub unit
In the case of, the cylindrical portion 8a for forming the caulked portion 9a is
Because the wall thickness is reduced toward the leading edge, this cylindrical part
8a is plastically deformed by the pressing die 15 as described above.
The force required to form the caulked portion 9a
It doesn't get any better. For this reason, caulking with caulking work
The portion 9a may be damaged such as a crack, or the caulked portion 9a
The inner ring 3 to be fixed by the
Large enough to affect durability such as strip fatigue life
There is no force to act. In particular, in the illustrated example,
While applying compressive stress to the tip of the caulking portion 9a,
The radius of curvature of the base end of the caulked portion 9a is increased.
Therefore, damage of the caulked portion 9a can be more effectively prevented. Incidentally, the plurality of rolling elements 5, 5
Action line of the applied load (the chain in FIG. 1 showing the contact angle of the rolling element 5)
The line β coincides with the inner peripheral surface of the inner race 3 and the shaft member 2.
It passes through the fitting surface with the tip and passes through the caulking portion 9a
It is preferable to avoid such a situation. Regulations that regulate this way
The reason is that the above load causes the caulked portion 9a to
This caulking part 9 does not work as a deforming force.
This is to prevent breakage of a. Next, of the inner races 3, the inner raceway 1
Cross-sectional area of a portion closer to the outside than 1 (XX line in FIG. 2)
S_Three And the sectional area S of the shaft member 2 in the portion_Two Relationship with
For the person in charge, S_Three <S_Two And more preferably S_Three ≤
0.94S_Two And The cross-sectional area of each part is regulated in this way.
The reason for this is that the inner ring 3 is supported on the shaft member 2.
This is to ensure strength. That is, the caulking portion 9a and the front
With the inner ring 3 held between the stepped surface 24 and the
To prevent the inner ring 3 from rotating.
The axial force of the shaft member 2 and the inner ring 3 extends in the axial direction.
Determined by the difference in the amount of distortion. That is, during caulking, the inner ring 3
Is larger than the elastic deformation of the shaft member 2. So
After completion of the caulking, the inner ring 3 and the shaft member 2
Is elastically restored, and an axial force (axial force) is applied to the inner ring 3.
Given. Material of the inner ring 3 and the shaft member 2
Since the material has almost the same elastic modulus, as described above, S
_Three<S_Two Then, the amount of elastic deformation during the caulking process is
Inner ring 3 is larger than 2. Therefore, the cross-sectional area of each part
With this restriction, a sufficient compressive load is applied to the inner ring 3.
While the inner ring 3 rotates with respect to the shaft member 2,
So-called creep can be effectively prevented. [0030] DESCRIPTION OF THE PREFERRED EMBODIMENTS Next, a case for realizing a structure as shown in FIGS.
An example of the appropriate value of the dimensions of each part in the case
You. In addition, the material of the shaft member 2 and the inner ring 3 is carbon 0.4 to
0.6% by weight structural carbon steel (S53C)
Induction hardening is performed on required portions such as the track 11 portion. Destination
, The inner diameter R of the inner ring 3 to be fixed to the shaft member 2_Three (Fig. 5)
It is 26.0 mm. Also, is it the axial end edge of the caulked portion 9a?
The cylindrical portion 8a for forming the caulked portion 9a (see FIG.
6) The second axial position C which is the innermost position of the inner peripheral surface 21
Axial distance L to_C Is set to 7.5 mm. In addition,
From the inner end surface 18 of the ring 3 to the outer peripheral surface of the inner ring 3
Third axial direction which is the inner end surface 18 side end of the inner ring raceway 11
Distance L to position B₁₁Is 9.36 mm. In addition,
The inner diameter of the inner peripheral surface 21 at the position C in the second axial direction
r_{twenty one}Is set to 11.4 mm. Also, the second and third axial directions
Axial distance L between positions B and C_BCIs 3.86 mm. This
In the case of the first axial position A described above and the second axial direction
Axial distance L from direction position C _AC(Not shown) is 0.5mm
I do. In addition, at the first axial position A,
Thickness a of female part 9a₀ Is 7.3 mm. Further, the inner end
The continuous point I between the surface 18 and the chamfered portion 20 and the caulked portion 9a
Is 0.96 mm. The cylindrical portion 8a formed at the inner end of the shaft member 2 is
Work for plastic deformation to form the caulking portion 9a as described above
Is performed by a swing press process as shown in FIG. this
The rocking press working is performed, for example, in a lock having a capacity of about 100 t.
Uses an oscillating press machine called King Press
And the swing angle θ of the pressing die 15₁₅About 2 seconds, about 5 seconds
Processing in a swinging time of degrees. [0032] The hub unit for supporting a wheel according to the present invention.Manufacturing of
MethodIs as mentioned aboveWhen forming the caulked part,
The shaft member does not move in the diameter direction. [Brief description of the drawings] FIG. 1 of the present invention.Hub support for wheel support made by manufacturing method
knitFIG. [Fig. 2] The inner end of the shaft member is fixed to fix the inner ring during manufacturing.
FIG. 3 is a partial cross-sectional view showing a state of swaging. FIG. 3 shows a case where the volume of the cylindrical portion is
The height and the inner peripheral surface of this cylindrical part are aligned with the center axis of this cylindrical part.
FIG. 4 is a diagram showing a relationship between the angle and the angle of inclination. FIG. 4 is a partial cross-sectional view for explaining the thickness of a caulked portion. FIG. 5 is a diagram illustrating a positional relationship between a caulking portion and an inner ring.
FIG. FIG. 6 shows a state before the inner end of the shaft member is swaged.
FIG. FIG. 7 is a partial cross-sectional view showing a state where a caulked portion is formed. FIG. 8 is a sectional view showing an example of a conventional structure. [Explanation of symbols] 1 hub unit for wheel support 2 Shaft member 3, 3a, 3b Inner ring 4 Outer ring 5 rolling elements 6 flange 7 steps 8, 8a cylindrical part 9, 9a caulking part 10. Outer ring track 11 Inner ring track 12 Mounting part 13 Taper hole 14 Retainer 15 Press mold 16 convex 17 recess 18 Inner end face 19 Inner circumference 20 chamfer 21 Inner surface 22 Mortar-shaped part 23 gap 24 step surface25 Small diameter part [Procedure amendment 2] [Document name to be amended] Drawing [Correction target item name] Figure 2 [Correction method] Change [Correction contents] FIG. 2[Procedure amendment 3] [Document name to be amended] Drawing [Correction target item name] Fig. 7 [Correction method] Change [Correction contents] FIG. 7

   ────────────────────────────────────────────────── ─── Continuation of front page    (72) Inventor Norifumi Hirano             3814 Ishibe, Ishibe-cho, Koga-gun, Shiga Prefecture NSK Ltd.             In the formula company F term (reference) 3J101 AA03 AA32 AA43 AA62 AA72                       BA53 BA56 DA20 FA41 GA03

Claims (1)

Claims 1. A shaft member having a first flange formed on an outer peripheral surface at one end portion, and an outer peripheral surface at an intermediate portion of the shaft member directly or via an inner ring separate from the shaft member. A first inner raceway formed by the above, a step formed at the other end of the shaft member and having an outer diameter smaller than that of the portion forming the first inner raceway, and a second portion formed on the outer peripheral surface. An inner race formed on the step portion and an outer race facing the first inner race and an outer race facing the second inner race on the inner peripheral surface. A plurality of raceways are provided between the outer races each having a second flange formed on the outer peripheral surface thereof and the first and second inner raceways and the first and second outer raceways. A moving body, and the other end of the shaft member is formed at least in a portion protruding from an inner ring externally fitted to the step portion. The inner ring externally fitted to the step is pressed down toward the end face of the step by the caulking part formed by caulking and expanding the cylindrical part outward in the diameter direction, and the inner ring externally fitted to the step is the shaft member. In the hub unit for wheel support fixed to the
The thickness of the cylindrical portion is reduced toward the leading edge in a state before the cylindrical portion is radially outwardly expanded, and the cylindrical portion is configured by radially outwardly expanding the cylindrical portion. The thickness of the swaged portion for holding down the end surface of the inner ring fitted to the step portion gradually decreases toward the distal end with respect to the thickness of the base end portion of the cylindrical portion. unit.