Summary of the invention
It is an object of the invention to overcome deficiency in the prior art, a kind of Steel Reinforcing Bar Material method is provided, can significantly be dropped
Low material cost and cost of labor.
In order to achieve the above objectives, the present invention adopts the following technical solutions realization: a kind of Steel Reinforcing Bar Material method, the side
Method includes the following steps:
Acquisition to blanking reinforcing bar length and raw material reinforcing bar length, will to blanking reinforcing bar length and raw material reinforcing bar length into
Row compares one by one:
Situation 1: if be not more than raw material reinforcing bar length to blanking reinforcing bar length, and after cutting remaining raw material reinforcing bar length
Degree is less than or equal to given threshold, then matching result of the output to blanking reinforcing bar and raw material reinforcing bar;
Situation 2: for according to situation 1 fail match blanking to blanking reinforcing bar, be combined blanking using following methods:
Length to combine remaining raw material reinforcing bar after cutting is minimum and is less than or equal to given threshold as target, building shaped like
AeqX=BeqData matrix model;Wherein: AeqIt is to consider that welding node loses the matrix constructed according to raw material reinforcing bar length,
X is whether to participate in patrolling for combination blanking by the length minimum value and characterization raw material reinforcing bar of raw material reinforcing bar remaining after combination cutting
Collect the matrix that vector is constituted, BeqIt is to consider welding node loss according to the matrix to the building of blanking reinforcing bar length;
Solve X using the intlinprog function in matlab, obtain the combination of corresponding raw material Steel Reinforcing Bar Material, output to
Blanking reinforcing bar and corresponding raw material Steel Reinforcing Bar Material combined result;
Situation 3: for failed according to situation 1 and 2 match blanking to blanking reinforcing bar, be combined using following methods
Blanking:
It is constructed first to the minimum target of blanking reinforcing bar length shaped like A ' with residue after cuttingeqY=B 'eqData matrix
Model;Wherein: A 'eqIt is to consider that welding node loses the matrix constructed according to raw material reinforcing bar length, Y is by remaining after combination cutting
It is remaining that the matrix that the vector logic of combination blanking is constituted whether is participated in blanking reinforcing bar length minimum value and characterization raw material reinforcing bar,
B′eqIt is according to the matrix to the building of blanking reinforcing bar length;
Y is solved using the intlinprog function in matlab, obtains corresponding raw material Steel Reinforcing Bar Material combination;And judge
Whether welding node is in girder span: solder joint problem in girder span if it does not exist, then output is to blanking reinforcing bar and corresponding raw material
Steel Reinforcing Bar Material combined result, otherwise, blanking result are invalid, into next step;
" with the minimum target of reinforcing bar waste rate, with welding node not in girder span for constraint, with residue after every cutting to
Blanking reinforcing bar is at most combined into hard constraint by two section reinforcing bar groups " or " with the minimum target of reinforcing bar waste rate, to be remained after every cutting
It is remaining that hard constraint is only combined by a section reinforcing bar group to blanking reinforcing bar ", using remaining after pre-established corresponding lingo model solution cutting
It is combined to blanking Steel Reinforcing Bar Material, residue is to blanking reinforcing bar and corresponding blanking combined result after output cutting;
Wherein: raw material steel of the residue to blanking reinforcing bar length=to the combination of blanking reinforcing bar length-participation blanking after cutting
Muscle length+reinforcing bar number of nodes * s, s indicates welding node loss.
The method that the combination of raw material Steel Reinforcing Bar Material is sought in situation 2 includes the following steps:
Using to blanking reinforcing bar length, divided by minimum value in raw material reinforcing bar, round up number, as every kind of length former material
Material reinforcing bar participates in the maximum possible radical M of blanking combination in this calculating;
For every kind of raw material reinforcing bar length, M are replicated, and welding node loss is individually subtracted, building row vector, and
Last column of row vector increase element -1, as vector Aeq,
In formula: p indicates the length type total amount of raw material reinforcing bar under present case;A1、A2……ApIt is respectively used to indicate p
The raw material reinforcing bar length of kind length;
Reinforcing bar combination blanking whether is participated in as column vector using raw material reinforcing bar, and will combine remaining raw material steel after cutting
The minimum value of muscle length constructs column vector X as last line,
X=[x1 x2 … xp*M xp*M+1]T
In formula: x1、x2……xp*MValue be 1 or 0: value indicates A when being 1eqMiddle corresponding raw material reinforcing bar participates in blanking
Combination;Value indicates A when being 0eqMiddle corresponding raw material reinforcing bar is not involved in blanking combination;xp*M+1Residue is former after indicating combination cutting
The minimum value of material reinforcing bar length;
To subtract welding node loss building B to blanking reinforcing bar lengtheqVector, Beq=B-s, B is indicated to blanking steel in formula
Muscle length;
According to AeqX=Beq, column vector X is calculated using the intlinprog function in matlab, is exported according to column vector X
Raw material Steel Reinforcing Bar Material combined result.
By constructing math matrix model, the method for seeking the combination of raw material Steel Reinforcing Bar Material includes the following steps:
Using to blanking reinforcing bar length divided by minimum value in raw material reinforcing bar, downward round numbers, as every kind of raw material steel
Muscle participates in the maximum possible radical N of blanking combination in this calculating;
For every kind of raw material reinforcing bar length, duplication is N number of, and welding node loss is individually subtracted, building row vector, and
Last column of row vector increase element 1, as vector A 'eq,
In formula: q indicates the length type total amount of raw material reinforcing bar under present case;A′1、A′2……A′qIt is respectively used to table
Show the raw material reinforcing bar length of q kind length;
Reinforcing bar combination blanking whether is participated in as column vector using raw material reinforcing bar, and by residue after combination cutting to blanking steel
Muscle length minimum value constructs column vector Y as last line,
Y=[y1 y2 … yq*N yq*N+1]T
In formula: y1、y2……yq*NValue be 1 or 0: when value is 1 indicate A 'eqUnder middle corresponding raw material reinforcing bar participates in
Material combination;A ' is indicated when value is 0eqMiddle corresponding raw material reinforcing bar is not involved in blanking combination;yq*N+1Indicate remaining after combination is cut
To blanking reinforcing bar length minimum value, yq*N+1≥35d+s;D indicates raw material bar diameter;
Using to blanking reinforcing bar length as B 'eqVector;
According to A 'eqY=B 'eq, column vector Y is calculated using the intlinprog function in matlab, it is defeated according to column vector Y
Raw material Steel Reinforcing Bar Material combined result out.
Following step is included using the method that residue after the cutting of lingo model solution is combined to blanking Steel Reinforcing Bar Material in situation 3
It is rapid:
Residue after cutting is split to blanking reinforcing bar according to default fractionation threshold value;
Situation 301: for residue after the cutting of " residue is after blanking reinforcing bar length >=default fractionation threshold value after cutting " under
Reinforcing bar is expected, with the minimum target of reinforcing bar waste rate, with welding node not in girder span for constraint, with residue after every cutting under
Material reinforcing bar is at most combined into hard constraint by two section reinforcing bar groups, using residue after the cutting of corresponding lingo model solution to blanking reinforcing bar
Blanking combination, output cutting after residue to blanking reinforcing bar and corresponding blanking combined result;
Situation 302: for residue after the cutting of " residue is after the default fractionation threshold value of blanking reinforcing bar length < after cutting " under
Expect reinforcing bar, with the minimum target of reinforcing bar waste rate, is only combined into firmly by a section reinforcing bar group with residue after every cutting to blanking reinforcing bar
Constraint is combined using residue after the cutting of corresponding lingo model solution to the blanking of blanking reinforcing bar, and residue is under after output cutting
Expect reinforcing bar and corresponding blanking combined result;
The default fractionation threshold value > 2 (35d+s), d indicate raw material bar diameter.
Differentiate that the method that whether is located in girder span of welding node includes:
Calculate the raw material reinforcing bar joint number that raw material Steel Reinforcing Bar Material combined result is included;
It is greater than 10 raw material Steel Reinforcing Bar Material combined result for reinforcing bar joint number:
It extracts preceding 10 elements and carries out fully intermeshing;
Non-extracted surplus element is added at the end of each arrangement, constitutes 10!A permutation and combination;
Consider welding node loss, judges 10!Meet all welding with the presence or absence of a certain permutation and combination in a permutation and combination
Node is not located at situation in girder span:
If it is present replacing the raw material Steel Reinforcing Bar Material combined result using the permutation and combination;
Otherwise, preceding 10 elements are extracted again since second element, and carry out fully intermeshing, at the end of each arrangement
Surplus element is added in tail, constitutes new 10!A permutation and combination judges new 10!It whether there is a certain arrangement in a permutation and combination
Combination meets all welding nodes and is not located at situation in girder span, and so on, until completing the judgement of all permutation and combination;
If all permutation and combination have welding node situation in girder span, show exist in the reinforcement welding of the beam
Welding node is in girder span;
Be less than or equal to 10 raw material Steel Reinforcing Bar Material combined result for reinforcing bar joint number: directly progress fully intermeshing calculating is sentenced
It is disconnected to meet all welding nodes not situations in girder span with the presence or absence of a certain arrangement: if it is present using the permutation and combination
Replace the raw material Steel Reinforcing Bar Material combined result;Otherwise, show that there are welding nodes in girder span in the reinforcement welding of the beam.
It is specific as follows that non-linear lingo model is established in situation 301:
0≤Tj≤1
Xij=KijYij+(1-Kij)Zij
Kij=0 or 1
Or Zij=0
Yi,jResidue is to ratio used in blanking reinforcing bar after expression jth root raw material reinforcing bar is cut at i-th;ZijIt indicates
Residue is to the first segment reinforcing bar of blanking reinforcing bar and the lenth ratio of jth root raw material reinforcing bar after i-th cutting;TjIndicate jth root
The ratio that raw material reinforcing bar is used;PjIndicate jth root raw material reinforcing bar length;Residue is under after Q (i) indicates i-th cutting
Expect reinforcing bar length;Total radical of m expression raw material reinforcing bar;N indicates total radical of the residue to blanking reinforcing bar after cutting;H indicates beam
It is high;KijIt is 0,1 variable;D indicates raw material bar diameter.
It is specific as follows that situation 302 establishes non-linear lingo model:
0≤Tj≤1
(35d+s)/Pj≤Xij≤ 1 or Xij=0
In formula: Xi,jResidue is to length used in blanking reinforcing bar after expression jth root raw material reinforcing bar is cut at i-th
Ratio;TjIndicate the ratio that jth root raw material reinforcing bar is used;PjIndicate jth root raw material reinforcing bar length;Q (i) indicates i-th
Residue is to blanking reinforcing bar length after cutting;Total radical of m expression raw material reinforcing bar;Residue is to blanking reinforcing bar after n indicates cutting
Total radical;D indicates raw material bar diameter.
Following processing should be done before establishing non-linear lingo model in situation 301:
Statistics " residue is after blanking reinforcing bar length after cutting >=is default to split threshold value " cutting after residue in blanking reinforcing bar
Residue is to blanking reinforcing bar length and its corresponding number of steel bars after the cutting for being included;
Residue after raw material reinforcing bar length and above-mentioned cutting is saved to blanking reinforcing bar length into the same excel file
Two column, and respectively arrange in descending order;
Residue is several to the excel file cutting of blanking reinforcing bar length after raw material reinforcing bar length will be preserved and cut
Subfile, it is desirable that: each subfile is comprising residue after 50~60 cuttings to blanking reinforcing bar length data, each subfile Central Plains
Residue is less than or equal to 10 to the difference of blanking reinforcing bar length summation after material reinforcing bar length summation and cutting.
Following processing should be done before establishing non-linear lingo model in situation 302:
Residue is in blanking reinforcing bar after the cutting of statistics " residue is after the default fractionation threshold value of blanking reinforcing bar length < after cutting "
Residue is to blanking reinforcing bar length and its corresponding number of steel bars after the cutting for being included;
Residue after raw material reinforcing bar and cutting is saved to blanking reinforcing bar into the same excel file;
By the excel file declustering at several subfiles, it is desirable that: each subfile includes residue after 50~60 cuttings
To blanking reinforcing bar length data;
With residue after cutting to the corresponding number of steel bars of blanking reinforcing bar divided by the Ziwen number of packages, after obtaining each cutting
Residue should get number of steel bars to blanking reinforcing bar in subfile;To aliquant situation, complementing part is given the last one
Subfile.
The given threshold is that w%* waits for blanking reinforcing bar length, 35d+s, the minimum value in 0.4 3 numerical value, wherein w%
For the reinforcing bar waste rate of preresearch estimates, d is raw material bar diameter.
Compared with prior art, the beneficial effects obtained by the present invention are as follows being: remaining raw material reinforcing bar is long after considering cutting
Degree, reinforcing bar waste rate, the medium multiple problems of girder span can utilize whole reinforcing bar to greatest extent, significantly reduce cutting times and
Welding times reduce cost of labor;It can make full use of remaining raw material reinforcing bar after cutting, significantly saving material cost.
Specific embodiment
Steel Reinforcing Bar Material method provided in an embodiment of the present invention, it is contemplated that two reinforcing bar length of remaining former material, reinforcing bar wave after cutting
The medium multiple problems of rate, girder span can utilize whole reinforcing bar to greatest extent, reduce reinforcing bar waste rate, significantly reduce and cut
Number and welding times are cut, material and cost of labor are reduced.
The invention will be further described below in conjunction with the accompanying drawings.Following embodiment is only used for clearly illustrating the present invention
Technical solution, and not intended to limit the protection scope of the present invention.
Steel Reinforcing Bar Material method provided in an embodiment of the present invention, includes the following steps:
Step 1: acquisition is to blanking reinforcing bar length and raw material reinforcing bar length:
Specifically, the length type and correspondence of the statistics function statistics raw material reinforcing bar in matlab can be called
Quantity, as a kind of the first row into one liang of column matrix is saved for raw material reinforcing bar length is identical, by corresponding reinforcing bar
Quantity is saved to secondary series.As shown in table 1 it is current raw material reinforcing bar relevant information:
Table 1
Reinforcing bar length type |
Quantity (root) |
Remarks |
20.59 |
957 |
Customize reinforcing bar |
12 |
1000 |
Standard reinforcing bar |
9 |
1000 |
Standard reinforcing bar |
4.51 |
1907 |
The left reinforcing bar of last project, owner wish to be finished in this project |
Corresponding constructed raw material rebar matrix is as follows:
Step 2: former according to corresponding matching compared with being carried out one by one to blanking reinforcing bar length with raw material reinforcing bar length
Then blanking matching result of the output to blanking reinforcing bar and raw material reinforcing bar;
Situation 1: if being not more than raw material reinforcing bar length to blanking reinforcing bar length, and the residue of raw material reinforcing bar is grown after blanking
Degree is less than or equal to given threshold, then blanking matching result of the output to blanking reinforcing bar and raw material reinforcing bar;
The given threshold is that w%* waits for blanking reinforcing bar length, the minimum value in tri- numerical value of 35d+s, 0.4m, wherein w%
For the reinforcing bar waste rate of preresearch estimates, such as 1%~4%;D is raw material bar diameter, and d value is in embodiments of the present invention
32mm;S is welding node loss, generally takes 0.06m.
Assuming that table 2 is to blanking reinforcing bar relevant information:
Table 2:
To blanking reinforcing bar length |
Quantity (root) |
11.87 |
20 |
11.71 |
12 |
4.43 |
4 |
4.37 |
4 |
4.36 |
10 |
Using information provided by table 1 as raw material reinforcing bar information, matching blanking is carried out to blanking reinforcing bar in table 2,
It is specifically compared, discriminates whether with the first row in raw material rebar matrix one by one to blanking reinforcing bar length as shown in Figure 1:
Less than or equal to given threshold: if it is, the raw material reinforcing bar compared therewith and being stored in blanking reinforcing bar with column vector is cut
In segmentation method matrix, while this reinforcing bar is deleted in blanking reinforcing bar vector, and by the reinforcing bar number in raw material rebar matrix
Amount subtracts 1, if corresponding raw material number of steel bars is equal to 0, the row is deleted, if not, continuing to take out next to blanking steel
Muscle starts another circulation, until traversal is entirely to blanking reinforcing bar column vector.As shown in table 3, for according to acquired in table 1, table 2
Steel Reinforcing Bar Material method table:
Table 3:
Raw material reinforcing bar length |
To blanking reinforcing bar length |
Residue length |
Explanation |
12 |
11.87 |
0.13 |
11.87m reinforcing bar totally 20 |
12 |
11.71 |
0.29 |
11.71m reinforcing bar totally 12 |
4.51 |
4.43 |
0.08 |
4.43m reinforcing bar totally 4 |
4.51 |
4.37 |
0.14 |
4.37m reinforcing bar totally 4 |
4.51 |
4.36 |
0.15 |
4.36m reinforcing bar totally 10 |
Situation 2: matched cannot carry out blanking by the way of the combination of raw material reinforcing bar to blanking reinforcing bar for situation 1,
Using the length minimum of remaining raw material reinforcing bar after combination cutting and it is less than or equal to given threshold as target, building is shaped like AeqX=Beq
Data matrix model, in which: AeqIt is to consider that welding node loses the matrix constructed according to raw material reinforcing bar length, X is by group
Close the vector logic structure whether remaining raw material reinforcing bar length minimum value and characterization raw material reinforcing bar after cutting participate in combination blanking
At matrix, BeqIt is to consider welding node loss according to the matrix to the building of blanking reinforcing bar length;
Solve X using the intlinprog function in matlab, obtain the combination of corresponding raw material Steel Reinforcing Bar Material, output to
Blanking reinforcing bar and corresponding raw material Steel Reinforcing Bar Material combined result;
Length (hereinafter referred to as " difference ")=all involved raw material of remaining raw material reinforcing bar after combination cutting
The sum of reinforcing bar length-(quantity -1 for participating in raw material reinforcing bar) * welding node loss-is to blanking reinforcing bar length.As shown in figure 3,
Assuming that being 24.93m to blanking reinforcing bar length, involved two raw material reinforcing bar length is respectively 20.59m, 4.51m, weldering
It connects node loss and removes 0.06m, then difference=20.59+4.51-0.06-24.93=0.11m.
The specific method for obtaining raw material Steel Reinforcing Bar Material combined result is as shown in Figure 2 and Figure 4:
With the minimum target of difference, establishes and optimizes following optimized mathematical model:
In formula: p indicates the length type total amount of raw material reinforcing bar under present case;xjIndicate the raw material of jth kind length
Whether reinforcing bar is used, and is to take 1, no to take 0;xp+1Indicate the minimum value of remaining raw material reinforcing bar length after combination is cut, B is indicated
To blanking reinforcing bar length;AjIndicate jth kind raw material reinforcing bar length;
It is calculated to carry out optimization, mathematical model is write as shaped like AeqX=BeqMatrix form, the specific method is as follows:
Using to blanking reinforcing bar length, divided by minimum value in raw material reinforcing bar, round up number, as every kind of length former material
Material reinforcing bar participates in the maximum possible radical M of blanking combination in this calculating;
For every kind of raw material reinforcing bar length, M are replicated, and welding node loss is individually subtracted, building row vector, and
Last column of row vector increase element -1, as vector Aeq,
In formula: p indicates the length type total amount of raw material reinforcing bar under present case;A1、A2……ApIt is respectively used to indicate p
The raw material reinforcing bar length of kind length;
Reinforcing bar combination blanking whether is participated in as column vector using raw material reinforcing bar, and will combine remaining raw material steel after cutting
The minimum value of the length of muscle constructs column vector X as last line;
X=[x1 x2 … xp*M xp*M+1]T
In formula: x1、x2……xp*MValue be 1 or 0: value indicates A when being 1eqMiddle corresponding raw material reinforcing bar participates in blanking
Combination;Value indicates A when being 0eqMiddle corresponding raw material reinforcing bar is not involved in blanking combination;xp*M+1Residue is former after indicating combination cutting
The minimum value of material reinforcing bar length;
To subtract welding node loss building B to blanking reinforcing bar lengtheqVector, Beq=B-s, B is indicated to blanking steel in formula
Muscle length;
According to AeqX=Beq, column vector X is calculated using the intlinprog function in matlab, is exported according to column vector X
Raw material Steel Reinforcing Bar Material combined result.
Explanation is further explained below with reference to specific example:
Assuming that being 55.63m to blanking reinforcing bar length, constructed raw material rebar matrix is following (unit: m):
Under current state in raw material reinforcing bar length minimum value be 4.51m, using to blanking reinforcing bar length 55.63m divided by
4.51m takes ceiling function ceil, and obtaining each raw material reinforcing bar, the maximum applied can in the combination of raw material Steel Reinforcing Bar Material
Can radical be 13,13 are replicated side by side for the raw material reinforcing bar of each length, and be individually subtracted welding node loss (assuming that
For 0.06m), and in row vector, last column increases element -1, can obtain row vector Aeq=[20.53 20.53 20.53 20.53
20.53 20.53 20.53 20.53 20.53 20.53 20.53 20.53 20.53 11.94 11.94 11.94 11.94
11.94 11.94 11.94 11.94 11.94 11.94 11.94 11.94 11.94 8.94 8.94 8.94 8.94
8.94 8.94 8.94 8.94 8.94 8.94 8.94 8.94 8.94 4.45 4.45 4.45 4.45 4.45 4.45
4.45 4.45 4.45 4.45 4.45 4.45 4.45 -1]。
The x in column vector X1~xmTotally 52 variables, for indicating whether the raw material reinforcing bar participates in combination blanking, value
It is 1 or 0;The last one element x in column vector Xm+1Indicate minimal difference, value interval be [0 ,+∞).
By a whole optimum organization of more reinforcing bars, 714 are spent in total, account for the 71.4% of sum 1000, it is full
Foot owner is finished the requirement for criticizing remaining 4.51m reinforcing bar as far as possible.15 198.19m, 14 197.38m, 14
195.55m, 14 194.738m in total 57 to blanking reinforcing bar, after optimum organization, residue to blanking reinforcing bar length all
It is 0, that is to say, that after optimum organization, do not waste situation, save material cost to greatest extent;Due to being entirely whole
Reinforcing bar combination, does not cut, thus in entire blanking process, cutting times can be effectively reduced, and reduce welding times, sufficiently
Reduce cost of labor.
To sum up, it is using the advantage that this method carries out more raw material reinforcing bar combination blankings:
1) with the waste reinforcing bar (X under cuttingm+1) minimum target, it is calculated by optimization, material can be reduced to greatest extent
Waste rate.
2) in optimization calculating process, in order to reach XmMinimum, optimization program will automatically select some length less than 9m (work
Working standard raw material reinforcing bar length in journey) relatively bar dowel, realize that the length of reinforcing bar is best " gradation ".And these are less than 9m's
Reinforcing bar is usually that last project cuts remaining reinforcing bar, and project consigner requires these remaining reinforcing bars as far as possible in next item
It uses, owns in mesh, this method just meets project consigner requirement, solves remaining reinforcing bar after the cutting of project consigner
It is difficult to the problem of " digesting ".
3) in the Steel Reinforcing Bar Material inventory obtained, only final section xmIt is the reinforcing bar after cutting, other are all whole reinforcing bars, this
The workload of cutting is substantially reduced, while decreasing welding workload, reaches the target for reducing cost of labor to greatest extent.
Situation 3: for 2 residue of situation to blanking reinforcing bar:
It is constructed first to the minimum target of blanking reinforcing bar length shaped like A ' with residueeqY=B 'eqData matrix model,
Wherein A 'eqIt is to consider that welding node loses the matrix constructed according to raw material reinforcing bar length;It is specific: using long to blanking reinforcing bar
For degree divided by minimum value in raw material reinforcing bar, downward round numbers, as every kind of raw material reinforcing bar participate in blanking group in this calculating
The maximum possible radical N of conjunction;
For every kind of raw material reinforcing bar length, duplication is N number of, and welding node loss is individually subtracted, building row vector, and
Last column of row vector increase element 1, as vector A 'eq,
In formula: q indicates the length type total amount of raw material reinforcing bar under present case;A′1、A′2……A′qIt is respectively used to table
Show the raw material reinforcing bar length of q kind length;
Whether Y is to be participated under combination by residue after combination cutting to blanking reinforcing bar length minimum value and characterization raw material reinforcing bar
The matrix that the vector logic of material is constituted;It is specific: to combine blanking as column vector so that whether raw material reinforcing bar participates in reinforcing bar, and will
Residue constructs column vector Y to the minimum value of blanking reinforcing bar length as last line after combination cutting,
Y=[y1 y2 … yq*N yq*N+1]T
In formula: y1、y2……yq*NValue be 1 or 0: when value is 1 indicate A 'eqUnder middle corresponding raw material reinforcing bar participates in
Material combination;A ' is indicated when value is 0eqMiddle corresponding raw material reinforcing bar is not involved in blanking combination;yq*N+1Indicate remaining after combination is cut
To blanking reinforcing bar length minimum value, yq*N+1≥35d+s;D indicates raw material bar diameter;
B′eqIt is according to the matrix to the building of blanking reinforcing bar length;
According to A 'eqY=B 'eq, column vector Y is calculated using the intlinprog function in matlab, it is defeated according to column vector Y
Raw material Steel Reinforcing Bar Material combined result out.
" with the minimum target of reinforcing bar waste rate, with welding node not in girder span for constraint, with residue after every cutting to
Blanking reinforcing bar is at most combined into hard constraint by two section reinforcing bar groups " or " with the minimum target of reinforcing bar waste rate, to be remained after every cutting
It is remaining that hard constraint is only combined by a section reinforcing bar group to blanking reinforcing bar ", using remaining after pre-established corresponding lingo model solution cutting
It is combined to blanking Steel Reinforcing Bar Material, residue is to blanking reinforcing bar and corresponding blanking combined result after output cutting;The specific method is as follows:
It is further explained explanation combined with specific embodiments below:
Assuming that being 25.74m, raw material rebar matrix constructed by remaining raw material reinforcing bar length to blanking reinforcing bar length
It is as follows:
20.59 887
12 366
9 423
Show from statistical data: current raw material shortest length is 9m, thus, it is possible to participate in every kind of whole reinforcing bar combination
Raw material reinforcing bar is up to floor (25.74/9)=2;
Replicate corresponding every kind of raw material reinforcing bar vectormatrix [9 9], [12 12], [20.59 20.59], combination above-mentioned three
It is a to measuring [9 9 12 12 20.59 20.59];
Each component subtracts reinforcement welding loss 0.06, and finally adds one-component 1 in vector, obtains vector A=
[8.94 8.94 11.94 11.94 20.53 20.53 1];
The upper infimum vector of each vector is set, and supremum vector is lb=[0 00000 1.11], ub=[1 1
1 1 1 1 inf];
It calls Matlab built-in function intlinprog to carry out optimization, obtains variable YT=[0 01100 1.86].
The result shows that only variable y3、y4Corresponding raw material reinforcing bar participates in whole reinforcing bar combination, i.e. raw material vector [9
9 12 12 20.59 20.59] only have the 3rd, 4 feeling in and participate in combination, thus whole reinforcing bar group is combined into [12 12], addition
Residue is to known to the optimal solution 1.86 of blanking reinforcing bar length after cutting: 25.74m waits for that blanking reinforcing bar is combined by 12m, 12m, 1.86m
It forms, continues to take out to blanking reinforcing bar, until whole of traversal is to blanking reinforcing bar vector.
According to above-described embodiment, it is known that be using the advantage that this method carries out reinforcing bar combination blanking:
1) from the point of view of the service condition of Cong Zhenggen reinforcing bar statistics, raw material reinforcing bar 3268 is used in whole reinforcing bar anabolic process
Root accounts for entire project uses raw material reinforcing bar sum 3936 83%, this shows in blanking inventory, whole reinforcing bar use ratio
It is very high, cutting and welding times are effectively reduced in this way;
2) it is calculated by optimization, ensure that batch remaining 4.51m reinforcing bar is exhausted, meet wanting for owner's proposition
It asks;
3) the reinforcing bar waste of entire project is 0.58%, is significantly less than the 5% of existing business software.
Different times raw material reinforcing bar usage quantity is as shown in table 4 below:
There is weldering to blanking reinforcing bar length and the optimized column vector to blanking reinforcing bar composition for residue after solution cutting
Node this problem in girder span is connect, the application optimizes calculating with the following method:
Residue after cutting is split to blanking reinforcing bar length according to default fractionation threshold value;
Situation 301: for residue after the cutting of " residue is after blanking reinforcing bar length >=default fractionation threshold value after cutting " under
Reinforcing bar is expected, with the minimum target of reinforcing bar waste rate, with welding node not in girder span for constraint, with residue after every cutting under
Material reinforcing bar length is at most combined into hard constraint by two section reinforcing bar groups, using residue after the cutting of corresponding lingo model solution to blanking
Steel Reinforcing Bar Material combination, residue is to blanking reinforcing bar and corresponding blanking combined result after output cutting;
Such as: assuming that welding node loss is 0.06m, residue is 4.5m, remaining former material to blanking reinforcing bar length after cutting
Expect that there are the raw material reinforcing bars of 9m and 12m in reinforcing bar length, then with the minimum target of reinforcing bar waste rate, with welding node not in beam
Span centre is constraint, and the reinforcing bar optimum organization of acquisition can be with are as follows: 3m is intercepted from the raw material reinforcing bar of 9m long, from the former material of 12m long
1.56m is intercepted in material reinforcing bar.
Concrete measure is: wherein a reinforcing bar length is fallen in section [35d+s, L/2-H], and another root long degree falls in section
[L/2+H, L], wherein L is beam span, and H is deck-molding;
Specifically, the lingo model being applicable in is as follows:
0≤Tj≤1
Xij=KijYij+(1-Kij)Zij
Kij=0 or 1
Or Zij=0
Yi,jResidue is to ratio used in blanking reinforcing bar after expression jth root raw material reinforcing bar is cut at i-th;ZijIt indicates
Residue is to the first segment reinforcing bar of blanking reinforcing bar and the ratio of jth root raw material reinforcing bar length after i-th cutting;TjIndicate jth root
The ratio that raw material reinforcing bar is used;PjIndicate jth root raw material reinforcing bar length;Residue is under after Q (i) indicates i-th cutting
Expect reinforcing bar length;Total radical of m expression raw material reinforcing bar;N indicates total radical of the residue to blanking reinforcing bar after cutting;H indicates beam
It is high;KijIt is 0,1 variable;D indicates raw material bar diameter.
Following processing should be done before establishing non-linear lingo model:
Statistics " residue is after blanking reinforcing bar length after cutting >=is default to split threshold value " cutting after residue in blanking reinforcing bar
Residue is to blanking reinforcing bar length and its corresponding number of steel bars after the cutting for being included;
Residue after raw material reinforcing bar length and above-mentioned cutting is saved to blanking reinforcing bar length into the same excel file
Two column, and respectively arrange in descending order;
Residue is several to the excel file cutting of blanking reinforcing bar length after raw material reinforcing bar length will be preserved and cut
Subfile, it is desirable that: each subfile is comprising residue after 50~60 cuttings to blanking reinforcing bar length data, each subfile Central Plains
Residue is less than or equal to 10 to the difference of blanking reinforcing bar length summation after material reinforcing bar length summation and cutting.
Situation 302: for residue after the cutting of " residue is after the default fractionation threshold value of blanking reinforcing bar length < after cutting " under
Expect reinforcing bar, with the minimum target of reinforcing bar waste rate, is only combined by a section reinforcing bar with residue after every cutting to blanking reinforcing bar length
For hard constraint, combined using residue after the cutting of corresponding lingo model solution to blanking Steel Reinforcing Bar Material, after output cutting residue to
Blanking reinforcing bar and corresponding blanking combined result.
Used lingo model is specific as follows:
0≤Tj≤1
(35d+s)/Pj≤Xij≤ 1 or Xij=0
In formula: Xi,jResidue in blanking reinforcing bar length to be made after expression jth root raw material reinforcing bar length is cut at i-th
Ratio;TjIndicate the ratio that jth root raw material reinforcing bar is used;PjIndicate jth root raw material reinforcing bar length;Q (i) is indicated
Residue is to blanking reinforcing bar length after i-th cutting;Total radical of m expression raw material reinforcing bar;Residue is to blanking steel after n indicates cutting
Total radical of muscle;D indicates raw material bar diameter.
Following processing should be done before establishing non-linear lingo model:
Residue is in blanking reinforcing bar after the cutting of statistics " residue is after the default fractionation threshold value of blanking reinforcing bar length < after cutting "
Residue is to blanking reinforcing bar length and its corresponding number of steel bars after the cutting for being included;
Residue after remaining raw material reinforcing bar length and cutting is saved to blanking reinforcing bar length to the same excel file
In;
By the excel file declustering at several subfiles, it is desirable that: each subfile includes residue after 50~60 cuttings
To blanking reinforcing bar length data;
It is obtained each divided by the Ziwen number of packages to the corresponding number of steel bars of blanking reinforcing bar length with residue after cutting and waited for
Blanking reinforcing bar length should get number of steel bars in subfile;To aliquant situation, complementing part is given into last height
File.
Wherein, it presets and splits threshold value > 2 (35d+s).Differentiate that the method that whether is located in girder span of welding node includes:
Calculate the raw material reinforcing bar joint number that raw material Steel Reinforcing Bar Material combined result is included;
It is greater than 10 raw material Steel Reinforcing Bar Material combined result for reinforcing bar joint number:
It extracts preceding 10 elements and carries out fully intermeshing;
Non-extracted surplus element is added at the end of each arrangement, constitutes 10!A permutation and combination;
Consider welding node loss, judges 10!Meet all welding with the presence or absence of a certain permutation and combination in a permutation and combination
Node is not located at situation in girder span:
If it is present replacing the raw material Steel Reinforcing Bar Material combined result using the permutation and combination;
Otherwise, preceding 10 elements are extracted again since second element, and carry out fully intermeshing, at the end of each arrangement
Surplus element is added in tail, constitutes new 10!A permutation and combination judges new 10!It whether there is a certain arrangement in a permutation and combination
Combination meets all welding nodes and is not located at situation in girder span, and so on, until completing the judgement of all permutation and combination;
If all permutation and combination have welding node situation in girder span, show exist in the reinforcement welding of the beam
Welding node is in girder span;
Be less than or equal to 10 raw material Steel Reinforcing Bar Material combined result for reinforcing bar joint number: directly progress fully intermeshing calculating is sentenced
It is disconnected to meet all welding nodes not situations in girder span with the presence or absence of a certain arrangement: if it is present using the permutation and combination
Replace the raw material Steel Reinforcing Bar Material combined result;Otherwise, show that there are welding nodes in girder span in the reinforcement welding of the beam.
Merge aforementioned combinatorial blanking as a result, as shown in table 5, the part Steel Reinforcing Bar Material that obtains part raw material reinforcing bar cutting method
Inventory is as shown in table 6,
Table 5: part raw material reinforcing bar cutting method table
Raw material reinforcing bar |
20.59 |
20.59 |
20.59 |
20.59 |
12 |
12 |
12 |
12 |
9 |
9 |
Section 1 |
7.08 |
5.14 |
7.77 |
7.08 |
6.17 |
2.5 |
6.17 |
6.17 |
4.78 |
7.54 |
Section 2 |
4.3 |
4.64 |
5.39 |
4.09 |
2.92 |
2.4 |
2.92 |
2.92 |
4.16 |
1.2 |
Section 3 |
4.3 |
4.3 |
3.11 |
3.02 |
2.91 |
2.4 |
2.91 |
2.91 |
|
|
Section 4 |
2.64 |
4.11 |
1.86 |
1.83 |
|
2.4 |
|
|
|
|
Section 5 |
2.2 |
1.2 |
1.2 |
1.59 |
|
|
|
|
|
|
Section 6 |
|
1.2 |
1.2 |
1.49 |
|
2.27 |
|
|
|
|
Section 7 |
|
|
|
1.3 |
|
|
|
|
|
|
Wastage |
0.07 |
0 |
0.06 |
0.19 |
0 |
0.03 |
0 |
0 |
0.06 |
0.26 |
Table 6: partially to blanking Steel Reinforcing Bar Material inventory
To sum up, the present invention can reduce reinforcing bar waste to greatest extent, reduce cutting times and welding times.Reduce material cost
And cost of labor.The optimum results for merging above-mentioned three step, obtain Steel Reinforcing Bar Material inventory and reinforcing bar cutting method.Statistics, which calculates, to be known,
Reinforcing bar waste rate be 0.58%, cutting times 3880 times, welding node 4158.Therefore the present invention not only greatly reduces reinforcing bar
Worker's cost of waste rate and cutting, welding, and efficiently solve the problems, such as welding node in girder span.
The above is only a preferred embodiment of the present invention, it is noted that for the ordinary skill people of the art
For member, without departing from the technical principles of the invention, several improvement and deformations can also be made, these improvement and deformations
Also it should be regarded as protection scope of the present invention.