CN109063890B - A heat load distribution method based on the maximization of the peak shaving capacity of the whole thermal power plant - Google Patents

A heat load distribution method based on the maximization of the peak shaving capacity of the whole thermal power plant Download PDF

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CN109063890B
CN109063890B CN201810644679.6A CN201810644679A CN109063890B CN 109063890 B CN109063890 B CN 109063890B CN 201810644679 A CN201810644679 A CN 201810644679A CN 109063890 B CN109063890 B CN 109063890B
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祝令凯
王勇
赵岩
丁俊齐
游大宁
辛刚
郭俊山
郑威
韩悦
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Electric Power Research Institute of State Grid Shandong Electric Power Co Ltd
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Abstract

本发明公开了一种基于热电厂全厂调峰能力最大化的热负荷分配方法。本发明从研究火电厂不同热电机组之间热电关系差异入手,建立机组抽汽量和电功率上下限的数学模型,进而给出全厂总功率上、下限的目标函数,在保证供热量不变的前提下,利用MATLAB工具的fmincon函数进行优化计算,给出最佳的热负荷分配方案,使得全厂的总调峰能力得到最大化。本发明的研究成果可以对热电厂的运行工况进行在线优化,通过合理分配各机组抽汽量,提高全厂调峰上限,降低全厂调峰下限。

Figure 201810644679

The invention discloses a heat load distribution method based on the maximization of the whole plant peak regulation capacity of a thermal power plant. The invention starts from studying the difference of thermoelectric relationship between different thermal power units in thermal power plants, establishes a mathematical model of the steam extraction volume and the upper and lower limits of the electric power of the unit, and then gives the objective functions of the upper and lower limits of the total power of the whole plant, so as to ensure that the heat supply remains unchanged. Under the premise of , the fmincon function of MATLAB tool is used for optimization calculation, and the best heat load distribution scheme is given, so that the total peak shaving capacity of the whole plant can be maximized. The research results of the present invention can optimize the operating conditions of the thermal power plant on-line, increase the upper limit of peak regulation in the whole plant, and reduce the lower limit of peak regulation in the whole plant by rationally distributing the steam extraction amount of each unit.

Figure 201810644679

Description

一种基于热电厂全厂调峰能力最大化的热负荷分配方法A heat load distribution method based on the maximization of the peak shaving capacity of the whole thermal power plant

技术领域technical field

本发明涉及火力发电技术领域,具体涉及一种基于热电厂全厂调峰能力最大化的热负荷分配方法。The invention relates to the technical field of thermal power generation, in particular to a heat load distribution method based on maximizing the peak-shaving capacity of the whole plant of a thermal power plant.

背景技术Background technique

近年来,随着环保压力的增大,国家加大发展新能源发电力度,其中新能源包括常规水电、风电、太阳能发电等。但是部分区域新能源机组发展过快,由于新能源机组发电的特殊性尤其是风电机组的反调峰特性,给电网的调峰带来严峻的挑战,导致新能源消纳问题日益突出。风电机组的反调峰特性表现为白天出力在一定范围内不断波动、夜晚风电出力开始逐渐上升的日出力特点和冬季平均出力最高、夏季平均出力最低的季节出力特点,导致了风电上网在相当程度上增大了系统调峰难度,因此风力发电弃风严重,2015年全国弃风率高达15%,2016年更是达到21%,2017年有所好转,但也达到12%。与此同时,火电机组的利用小时数也逐渐下降,2015年火电利用小时数为4329h,2016年火电利用小时数为4165h,2017年预计在4000h左右,火电机组基本处在调峰状态下运行;另一方面北方地区供热机组比例越来越高,热电机组作为主要的热源需优先满足热负荷,存在着“以热定电”工况运行约束,导致采暖季调峰能力受到严重制约,甚至无法调峰,“风热冲突”加剧了调峰难度。In recent years, with the increasing pressure of environmental protection, the state has stepped up efforts to develop new energy power generation, including conventional hydropower, wind power, solar power and so on. However, the development of new energy units in some regions is too fast. Due to the particularity of the power generation of new energy units, especially the anti-peak shaving characteristics of wind turbines, it brings severe challenges to the peak shaving of the power grid, resulting in an increasingly prominent problem of new energy consumption. The anti-peak shaving characteristics of wind turbines are characterized by the daily output fluctuating within a certain range during the day, and the wind power output gradually rising at night, and the seasonal output characteristics of the highest average output in winter and the lowest average output in summer, resulting in a considerable degree of wind power grid connection. In 2015, the national wind abandonment rate was as high as 15%, in 2016 it reached 21%, and it improved in 2017, but it also reached 12%. At the same time, the utilization hours of thermal power units have also gradually decreased. In 2015, the utilization hours of thermal power were 4,329h, in 2016, they were 4,165h, and are expected to be around 4,000h in 2017. Thermal power units are basically running under peak regulation; On the other hand, the proportion of heating units in the northern region is getting higher and higher. As the main heat source, the thermal power unit needs to meet the heat load first, and there are operating constraints under the operating condition of "fixing electricity by heat", which leads to serious restrictions on the peak-shaving capacity in the heating season, and even Peak shaving is impossible, and the "wind and heat conflict" aggravates the difficulty of peak shaving.

过去对热电机组调峰能力的研究多集中于机组本身的电热特性研究,对于全厂调峰能力的研究比较少,对于涵盖多种类型热电机组的热电厂来说,不同机组的运行特性和调峰能力不尽相同,在全厂供热量一定的条件下,通过合理分配热负荷,可以得到最大的全厂调峰能力,机组之间热电关系个体差异越大,热负荷分配对提升全厂整体调峰性能的效果越明显。对全厂的热负荷分配必须充分考虑到不同类型机组调峰能力的差异性,确定不同类型机组之间热负荷分配方案,使得全厂机组总的调峰能力最大。In the past, the research on the peak shaving capacity of thermal power units mostly focused on the study of the electrical and thermal characteristics of the unit itself, while the research on the peak shaving capacity of the whole plant was relatively small. The capacity varies. Under the condition of a certain heat supply in the whole plant, the maximum peak shaving capacity of the whole plant can be obtained by rationally distributing the heat load. The effect of peak shaving performance is more obvious. For the heat load distribution of the whole plant, it is necessary to fully consider the differences in the peak shaving capacity of different types of units, and determine the heat load distribution scheme between different types of units, so that the total peak shaving capacity of the whole plant's units is maximized.

发明内容SUMMARY OF THE INVENTION

针对上述问题,本发明从供热机组的电热特性出发,考虑机组之间的调峰能力差异,给出一种全厂热负荷分配方法使得全厂调峰能力最大化。In view of the above problems, the present invention proposes a plant-wide heat load distribution method to maximize the plant-wide peak-shaving capability based on the electrical and thermal characteristics of the heating units and considering the difference in peak-shaving capacity between units.

本发明采用如下技术方案:一种基于热电厂全厂调峰能力最大化的热负荷分配方法,热电厂有n台抽汽凝汽式汽轮发电机组供热,n≥2,各机组之间容量或供热方式存在不同,其特征在于,包括以下步骤:The invention adopts the following technical scheme: a heat load distribution method based on the maximization of the peak-shaving capacity of the thermal power plant. There are different heating modes, and it is characterized in that it includes the following steps:

步骤1:记录各机组当前运行工况下的抽汽量、抽汽压力、抽汽温度和抽汽疏水温度;Step 1: Record the extraction steam volume, extraction steam pressure, extraction steam temperature and extraction steam drainage temperature under the current operating conditions of each unit;

步骤2:根据步骤1记录的抽汽压力、抽汽温度、抽汽疏水温度,采用工业用水和水蒸气热力性质模型计算得到各机组的抽汽焓和抽汽疏水焓;Step 2: According to the extraction steam pressure, extraction steam temperature, and extraction steam drainage temperature recorded in Step 1, the extraction steam enthalpy and extraction steam drainage enthalpy of each unit are calculated by using the thermal property model of industrial water and steam;

步骤3:根据步骤1中各机组抽汽量和步骤2中的抽汽焓和抽汽疏水焓计算各机组供热量,进而得到全厂当前总供热量;Step 3: Calculate the heat supply of each unit according to the extraction steam volume of each unit in step 1 and the extraction steam enthalpy and extraction steam drainage enthalpy in step 2, and then obtain the current total heat supply of the whole plant;

步骤4:以全厂为单位,收集各机组供热工况图,利用各机组供热工况图绘制热电关系曲线;即各机组功率上限随抽汽量变化曲线和各机组功率下限随抽汽量变化曲线;Step 4: Take the whole plant as a unit, collect the heating condition diagram of each unit, and use the heating condition diagram of each unit to draw the thermoelectric relationship curve; that is, the curve of the upper limit of the power of each unit with the steam extraction volume and the lower limit of the power of each unit with the steam extraction. quantity change curve;

其中,供热工况图是进汽量、抽汽量和有功功率三者的耦合关系图;每一个抽汽量都有一个对应的最大和最小功率,我们把不同抽汽量及对应的最大和最小功率数值分别输入EXCEL,生成热电关系曲线图;Among them, the heating condition diagram is the coupling relationship diagram of the intake steam volume, the extraction steam volume and the active power; each extraction steam volume has a corresponding maximum and minimum power. Enter EXCEL and the minimum power value respectively to generate a thermoelectric relationship curve;

步骤5:分别将各机组功率上限随抽汽量变化曲线和各机组功率下限随抽汽量变化曲线添加趋势线并拟合公式,得到各机组功率上限、功率下限和抽汽量的数学关系式;Step 5: Add trend lines to the curve of the upper limit of power of each unit with the change of steam extraction volume and the curve of the lower limit of power of each unit with the change of steam extraction volume, and fit the formula to obtain the mathematical relationship between the upper limit of power, lower limit of power and extraction volume of each unit ;

步骤6:进一步累加得到全厂总功率上限、下限和抽汽量的数学关系式;Step 6: Further accumulatively obtain the mathematical relationship between the upper and lower limits of the total power of the whole plant and the extraction steam volume;

步骤7:根据步骤6中得到的全厂总功率上限、下限和各机组抽汽量的数学关系式以及设定好的约束条件,以全厂总功率上、下限和各机组抽汽量的数学关系式作为目标函数,利用MATLAB最优化工具箱中的fmincon函数求解,得到各机组基于全厂调峰上限的抽汽量和基于全厂调峰下限的抽汽量,以及对应的全厂总功率上限最大值和下限最小值,从而实现全厂调峰能力最大化的热负荷分配。Step 7: According to the mathematical relationship between the upper limit and lower limit of the total power of the whole plant and the steam extraction volume of each unit obtained in Step 6, and the set constraints, the upper and lower limits of the total power of the whole plant and the mathematical relationship of the steam extraction volume of each unit are calculated. The relational expression is used as the objective function, and is solved by the fmincon function in the MATLAB optimization toolbox to obtain the extraction steam volume based on the upper limit of the whole plant peak regulation and the extraction steam volume based on the lower limit of the whole plant peak regulation, and the corresponding total power of the whole plant. Maximum upper limit and minimum lower limit, so as to realize the heat load distribution that maximizes the peak shaving capacity of the whole plant.

上述约束条件:各机组总供热量等于步骤3中计算的全厂当前总供热量,各机组抽汽量不超过机组允许的最大抽汽量。The above constraints: the total heat supply of each unit is equal to the current total heat supply of the whole plant calculated in step 3, and the steam extraction volume of each unit does not exceed the maximum allowable steam extraction volume of the unit.

所述步骤2利用加载在EXCEL中的IFC-97工业用水和水蒸气热力性质模型计算。The step 2 is calculated using the IFC-97 thermal property model of industrial water and water vapor loaded in EXCEL.

所述步骤3中,各机组当前供热量计算公式如下:In the step 3, the calculation formula of the current heat supply of each unit is as follows:

Qn′=Gn′(hn′-hsn′)Q n ′=G n ′(h n ′-h sn ′)

式中:Qn′是第n台机组当前的供热量,Gn′是第n台机组当前的供热抽汽量,hn′是第n台机组当前的供热抽汽焓,hsn′是第n台机组当前的供热抽汽疏水焓。In the formula: Q n ′ is the current heat supply of the nth unit, G n ′ is the current heat supply and extraction volume of the nth unit, h n ′ is the current heat supply and extraction enthalpy of the nth unit, h sn ' is the current heating extraction steam drainage enthalpy of the nth unit.

Qa=Q1′+Q2′+…+QnQ a =Q 1 ′+Q 2 ′+...+Q n

式中:Qa是全厂当前总供热量,Q1′~Qn′分别为第1台到第n台机组当前供热量。In the formula: Q a is the current total heat supply of the whole plant, and Q 1 ′~Q n ′ are the current heat supply of the first to nth units respectively.

所述步骤5中,各机组功率上限、功率下限计算公式分别如下:In the step 5, the calculation formulas of the upper power limit and the lower power limit of each unit are as follows:

PMAXn=fmax(Gn)PMAX n =f max (G n )

式中:PMAXn是第n台机组的功率上限,fmax(Gn)是供热抽汽量的一元函数,由EXCEL拟合得到;In the formula: PMAX n is the upper limit of the power of the nth unit, f max (G n ) is the unary function of the heating and extraction steam, which is obtained by EXCEL fitting;

PMINn=fmin(Gn)PMIN n =f min (G n )

式中:PMINn是第n台机组的功率下限,fmax(Gn)是供热抽汽量的一元函数,由EXCEL拟合得到;In the formula: PMIN n is the power lower limit of the nth unit, f max (G n ) is the unary function of the heating and extraction steam, which is obtained by EXCEL fitting;

Gn为第n台机组的抽汽量。G n is the extraction steam volume of the nth unit.

所述步骤6中,全厂总功率上限、总功率下限的计算公式分别为:In the step 6, the calculation formulas of the upper limit of the total power and the lower limit of the total power of the whole plant are respectively:

PMAXa=PMAX1+PMAX2+…+PMAXn PMAX a =PMAX 1 +PMAX 2 +...+PMAX n

=fmax(G1)+fmax(G2)+…+fmax(Gn)=f max (G 1 )+f max (G 2 )+…+f max (G n )

式中:PMAXa是全厂总功率上限;In the formula: PMAX a is the upper limit of the total power of the whole plant;

PMINa=PMIN1+PMIN2+…+PMINn PMIN a =PMIN 1 +PMIN 2 +…+PMIN n

=fmin(G1)+fmin(G2)+…+fmin(Gn)=f min (G 1 )+f min (G 2 )+…+f min (G n )

式中:PMINa是全厂总功率下限;In the formula: PMIN a is the lower limit of the total power of the whole plant;

所述步骤7中,求解全厂总功率上限、下限极值的表达式如下:因fmincon函数只能求解最小值,因此我们将求解功率上限的最大值问题转化为求解功率上限负函数最小值问题,目标函数如下:In the step 7, the expressions for solving the upper limit and lower limit of the total power of the whole plant are as follows: Since the fmincon function can only solve the minimum value, we transform the problem of solving the maximum value of the power upper limit into the problem of solving the minimum value of the negative function of the power upper limit. , the objective function is as follows:

min(-PMAXa)=min(-(fmax(G1)+fmax(G2)+…+fmax(Gn)))min(-PMAX a )=min(-(f max (G 1 )+f max (G 2 )+...+f max (G n )))

全厂总功率下限目标函数如下:The objective function of the lower limit of the total power of the whole plant is as follows:

minPMINa=min(fmin(G1)+fmin(G2)+…+fmin(Gn))minPMIN a = min(f min (G 1 )+f min (G 2 )+…+f min (G n ))

求解全厂总功率上限、下限极值的约束条件表达式如下:The constraint expression for solving the upper limit and lower limit of the total power of the whole plant is as follows:

Qa=G1(h1-hs1)+G2(h2-hs2)+…+Gn(hn-hsn)Q a =G 1 (h 1 -h s1 )+G 2 (h 2 -h s2 )+...+G n (h n -h sn )

0≤G1≤G1max 0≤G 1 ≤G 1max

0≤G2≤G2max 0≤G 2 ≤G 2max

0≤Gn≤Gn max 0≤Gn≤Gnmax _

式中:Qa是步骤3计算的全厂当前总供热量,是一个定值;G1,G2,…,Gn分别是第一台到第n台机组在全厂功率上限和功率下限下分别对应的抽汽量;G1max,G2max,Gn max分别是第一台到第n台机组的最大抽汽量,是定值,从各机组供热工况图查得;h1,h2……hn分别是第一台到第n台机组的供热抽汽焓;hs1、hs2……hsn分别是第一台到第n台机组的供热抽汽疏水焓。In the formula: Q a is the current total heat supply of the whole plant calculated in step 3, which is a fixed value; G 1 , G 2 ,..., G n are the upper limit and power of the first to nth units in the whole plant respectively. The corresponding extraction steam volumes under the lower limit; G 1max , G 2max , and G n max are the maximum extraction steam volumes of the first to nth units respectively, which are fixed values and are obtained from the heating condition diagram of each unit; h 1 , h 2 ...... h n are the heating extraction enthalpy of the first to n units respectively; h s1 , h s2 ...... h sn are the heating extraction steam drains of the first to n units respectively enthalpy.

本发明的有益效果是:本发明从研究火电厂不同热电机组之间热电关系差异入手,建立机组抽汽量和电功率上下限的数学模型,进而给出全厂总功率上、下限的目标函数,在保证供热量不变的前提下,利用MATLAB工具的fmincon函数进行优化计算,给出最佳的热负荷分配方案,使得全厂的总调峰能力得到最大。本发明的研究成果可以对热电厂的运行工况进行在线优化,通过合理分配各机组抽汽量,提高全厂调峰上限,降低全厂调峰下限。The beneficial effects of the present invention are as follows: the present invention starts from studying the difference in the thermoelectric relationship between different thermal power units in a thermal power plant, establishes a mathematical model of the steam extraction volume and the upper and lower limits of the electric power of the unit, and then provides the objective functions of the upper and lower limits of the total power of the whole plant, Under the premise of ensuring the constant heat supply, the fmincon function of the MATLAB tool is used for optimization calculation, and the best heat load distribution scheme is given, so that the total peak shaving capacity of the whole plant can be maximized. The research results of the present invention can optimize the operating conditions of the thermal power plant on-line, increase the upper limit of peak regulation in the whole plant, and reduce the lower limit of peak regulation in the whole plant by rationally distributing the steam extraction amount of each unit.

通过对各热电厂的在线优化,提升电网的调峰能力,促进新能源的消纳,带来显著的经济效益和社会效益,应用前景非常广泛。Through the online optimization of each thermal power plant, the peak shaving capacity of the power grid is improved, and the consumption of new energy is promoted, which brings significant economic and social benefits, and has a very broad application prospect.

附图说明Description of drawings

图1为某机组供热工况图;Figure 1 is a diagram of the heating condition of a unit;

图2为某机组热电关系曲线图;Figure 2 is a graph of the thermoelectric relationship of a unit;

图3为某机组热电关系曲线拟合公式图。Figure 3 is a fitting formula diagram of the thermoelectric relationship curve of a unit.

具体实施方式Detailed ways

某电厂基本情况如下,一期工程#1、#2机组为两台亚临界,一次中间再热、抽汽凝汽式机组,型号为NC330/242-16.7/0.8/535/535,抽汽位置是中压缸排汽,设计额定供热压力0.8MPa,额定抽汽流量340t/h,最大抽汽流量400t/h;二期工程#3、#4机组为两台超临界、一次中间再热、抽汽凝汽式机组,型号为C350/294-24.2/0.43/566/566,抽汽位置是中压缸排汽,设计额定抽汽压力为0.43MPa,额定抽汽流量400t/h,最大抽汽流量500t/h。The basic situation of a power plant is as follows, the first phase project #1 and #2 units are two subcritical, one-time intermediate reheat, extraction and condensing units, the model is NC330/242-16.7/0.8/535/535, the steam extraction position It is a medium-pressure cylinder exhaust steam, the design rated heating pressure is 0.8MPa, the rated steam extraction flow rate is 340t/h, and the maximum extraction steam flow rate is 400t/h; the second-phase project #3 and #4 units are two supercritical units with one intermediate reheating. , Extraction condensing unit, model is C350/294-24.2/0.43/566/566, steam extraction position is medium pressure cylinder exhaust, design rated extraction pressure is 0.43MPa, rated extraction flow is 400t/h, the maximum The extraction steam flow is 500t/h.

电厂当前全厂运行工况为#1、#3、#4机组运行,#2机组停机,各机组及全厂当前抽汽量和调峰上下限如下表所示:The current operating conditions of the power plant are that #1, #3, and #4 units are running, and #2 unit is shut down. The current extraction steam volume and peak shaving upper and lower limits of each unit and the entire plant are shown in the following table:

表1各机组及全厂当前抽汽量和调峰上下限Table 1 The current steam extraction volume and peak shaving upper and lower limits of each unit and the whole plant

Figure GDA0001750458330000061
Figure GDA0001750458330000061

利用本发明提出的热负荷分配方法对热电厂进行全厂调峰能力在线优化,通过重新分配各机组抽汽量,提高全厂的总调峰上限,降低总调峰下限。其热负荷分配方法包括以下步骤:The thermal load distribution method proposed by the invention is used to optimize the peak shaving capacity of the thermal power plant on-line, and by redistributing the steam extraction amount of each unit, the upper limit of the total peak shaving of the whole plant is increased, and the lower limit of the total peak shaving is lowered. Its heat load distribution method includes the following steps:

步骤1:从热电厂DCS系统中记录各机组当前运行工况下的抽汽量、抽汽压力、抽汽温度和抽汽疏水温度,具体如表2所示;Step 1: Record the extraction steam volume, extraction steam pressure, extraction steam temperature and extraction steam drainage temperature under the current operating conditions of each unit from the DCS system of the thermal power plant, as shown in Table 2;

表2各机组抽汽参数Table 2 Extraction parameters of each unit

类型type 抽汽压力(MPa)Extraction pressure (MPa) 抽汽温度(℃)Extraction steam temperature (℃) 抽汽流量(t/h)Extraction steam flow (t/h) 抽汽疏水温度(℃)Extraction steam drain temperature (℃) #1#1 0.640.64 340.81340.81 152.84152.84 90.2890.28 #3#3 0.20.2 227.11227.11 252.45252.45 84.1484.14 #4#4 0.160.16 272.14272.14 379379 80.3280.32

其中,抽汽疏水温度为热网加热器疏水温度,热网加热器进汽压力为默认的饱和压力。Among them, the extraction steam drain temperature is the drain temperature of the heat network heater, and the inlet steam pressure of the heat network heater is the default saturation pressure.

步骤2:根据步骤1记录的抽汽压力、抽汽温度、抽汽疏水温度,利用加载在EXCEL中的IFC-97工业用水和水蒸气热力性质计算模型计算得到各机组的抽汽焓和抽汽疏水焓,如表3所列;Step 2: According to the extraction steam pressure, extraction steam temperature, and extraction steam drainage temperature recorded in Step 1, use the IFC-97 thermal property calculation model of industrial water and steam loaded in EXCEL to calculate the extraction enthalpy and extraction steam of each unit Hydrophobic enthalpy, as listed in Table 3;

表3各机组抽汽焓值Table 3 Extraction enthalpy of each unit

Figure GDA0001750458330000062
Figure GDA0001750458330000062

Figure GDA0001750458330000071
Figure GDA0001750458330000071

步骤3:根据步骤1中各机组抽汽量和步骤2中的抽汽焓和抽汽疏水焓计算各机组供热量,进而得到全厂当前总供热量。Step 3: Calculate the heat supply of each unit according to the extraction steam volume of each unit in step 1 and the extraction steam enthalpy and extraction steam drainage enthalpy in step 2, and then obtain the current total heat supply of the whole plant.

各机组当前供热量计算公式如下:The calculation formula of the current heat supply of each unit is as follows:

Qn′=Gn′(hn′-hsn′)Q n ′=G n ′(h n ′-h sn ′)

式中:Qn′是第n台机组当前的供热量(GJ/h),Gn′是第n台机组当前的供热抽汽量(t/h),hn′是第n台机组当前的供热抽汽焓(kJ/kg),hsn′是第n台机组当前的供热抽汽疏水焓(kJ/kg)。In the formula: Q n ′ is the current heat supply of the nth unit (GJ/h), G n ′ is the current heat supply and steam extraction of the nth unit (t/h), and h n ′ is the nth unit. The current heating and extraction enthalpy of the unit (kJ/kg), h sn ′ is the current heating and extraction steam drainage enthalpy (kJ/kg) of the nth unit.

Qa=Q1′+Q2′+…+QnQ a =Q 1 ′+Q 2 ′+...+Q n

式中:Qa是全厂当前总供热量(GJ/h),Q1′~Qn′分别为第1台到第n台机组当前供热量。In the formula: Q a is the current total heat supply (GJ/h) of the whole plant, and Q 1 ′~Q n ′ are the current heat supply of the first to nth units respectively.

根据上面的计算公式和表2和表3中所列数据和可以得到各机组的供热量和全厂总供热量,如表4所示。According to the above calculation formula and the data listed in Table 2 and Table 3, the heat supply of each unit and the total heat supply of the whole plant can be obtained, as shown in Table 4.

表3各机组供热量值Table 3 Heat supply value of each unit

类型type 供热量(GJ/h)Heat supply (GJ/h) #1#1 643064.26643064.26 #3#3 1009915.571009915.57 #4#4 429456.91429456.91 全厂The whole plant 2082436.732082436.73

步骤4:以全厂为单位,收集各热电机组供热工况图,利用各机组供热工况图绘制热电关系曲线。供热工况图通常是进汽量、抽汽量和有功功率三者的耦合关系图,不能直观显示供热量和有功功率的对应关系,如图1所示。从图中可见,每一个抽汽量都有一个对应的最大和最小功率,我们把不同抽汽量及对应的最大和最小功率数值分别输入EXCEL,可以生成如图2所示的热电关系曲线图,图中上方曲线是机组功率上限随抽汽量变化曲线,下方曲线是机组功率下限随抽汽量变化曲线。Step 4: Take the whole plant as a unit, collect the heating condition diagram of each thermal power unit, and draw the thermoelectric relationship curve using the heating condition diagram of each unit. The heating condition diagram is usually the coupling relationship diagram of the steam intake, the extraction steam and the active power. As can be seen from the figure, each extraction steam volume has a corresponding maximum and minimum power. We input the different extraction steam volumes and the corresponding maximum and minimum power values into EXCEL respectively, and the thermoelectric relationship curve as shown in Figure 2 can be generated. , the upper curve in the figure is the change curve of the upper limit of the unit power with the steam extraction volume, and the lower curve is the change of the lower limit of the unit power with the steam extraction volume.

步骤5:在EXCEL中分别将生成功率上限曲线和功率下限曲线添加趋势线并拟合公式,功率上限曲线一般为近似直线,可以采用线性拟合;功率下限曲线一般为折线,可以采取多项式拟合,大多数情况下四阶多项式拟合可以满足精度要求,趋势线及拟合公式如图3所示,这样我们就得到了各机组功率上限、功率下限和抽汽量的数学关系式。Step 5: Add trend lines to the generated power upper limit curve and power lower limit curve in EXCEL and fit the formula. The power upper limit curve is generally an approximate straight line, and linear fitting can be used; the power lower limit curve is generally a broken line, and polynomial fitting can be adopted. , in most cases, the fourth-order polynomial fitting can meet the accuracy requirements. The trend line and fitting formula are shown in Figure 3. In this way, we have obtained the mathematical relationship between the upper power limit, lower power limit and extraction volume of each unit.

各机组功率上限、功率下限计算公式分别如下:The calculation formulas for the upper limit and lower power limit of each unit are as follows:

PMAXn=fmax(Gn)PMAX n =f max (G n )

式中:PMAXn是第n台机组的功率上限(MW),Gn为是第n台机组当前的供热抽汽量(t/h);fmax(Gn)是供热抽汽量的一元函数,由EXCEL拟合得到;In the formula: PMAX n is the upper limit of the power of the nth unit (MW), G n is the current heat supply and extraction volume (t/h) of the nth unit; f max (G n ) is the heat supply and extraction volume The unary function of , obtained by EXCEL fitting;

PMINn=fmin(Gn)PMIN n =f min (G n )

式中:PMINn是第n台机组的功率下限,fmax(Gn)是供热抽汽量的一元函数,由EXCEL拟合得到;In the formula: PMIN n is the power lower limit of the nth unit, f max (G n ) is the unary function of the heating and extraction steam, which is obtained by EXCEL fitting;

根据#1机组供热工况图拟合出#1机组功率上限和供热抽汽量关系式如下:According to the heating condition diagram of the #1 unit, the relationship between the upper limit of the power of the #1 unit and the heat supply and extraction volume is as follows:

PMAX1=-0.2261G1+341.96PMAX 1 = -0.2261G 1 +341.96

#1机组功率下限和供热抽汽量关系式如下:The relationship between the power lower limit of the #1 unit and the amount of heating and extraction steam is as follows:

PMIN1=1.47*10-8G1 4-1.1069*10-5G1 3+2.7366*10-3G1 2-0.47985G1+220.03PMIN 1 =1.47*10 -8 G 1 4 -1.1069*10 -5 G 1 3 +2.7366*10 -3 G 1 2 -0.47985G 1 +220.03

#3、#4机组为同类型机组,因此根据机组供热工况图拟合出的功率上限、下限和供热抽汽量的关系式相同,功率上限和供热抽汽量关系式如下:Units #3 and #4 are of the same type. Therefore, the relationship between the upper limit and lower limit of power and the amount of heating and extraction steam fitted according to the unit’s heating condition diagram is the same. The relationship between the upper limit of power and the amount of heating and extraction steam is as follows:

PMAX3=-0.2003G3+391.57PMAX 3 = -0.2003G 3 +391.57

功率下限和供热抽汽量关系式如下:The relationship between the lower limit of power and the amount of heating and extraction steam is as follows:

PMIN3=1.2083*10-8G3 4+1.1009*10-5G3 3-1.9486*10-3G3 2-0.17934G3+235.44PMIN 3 =1.2083*10 -8 G 3 4 +1.1009*10 -5 G 3 3 -1.9486*10 -3 G 3 2 -0.17934 G 3 +235.44

步骤6:根据步骤5得到的各机组功率上限、功率下限和抽汽量的数学关系式,累加得到全厂总功率上限、总功率下限和抽汽量的数学关系式。Step 6: According to the mathematical relationship between the upper limit of power, lower limit of power and steam extraction volume of each unit obtained in step 5, the mathematical relationship between the upper limit of total power, lower limit of total power and extraction volume of the whole plant is obtained by accumulating.

其中,全厂总功率上限、总功率下限的计算公式分别为:Among them, the calculation formulas of the upper limit of the total power and the lower limit of the total power of the whole plant are:

PMAXa=PMAX1+PMAX2+…+PMAXn PMAX a =PMAX 1 +PMAX 2 +...+PMAX n

=fmax(G1)+fmax(G2)+…+fmax(Gn)=f max (G 1 )+f max (G 2 )+…+f max (G n )

式中:PMAXa是全厂总功率上限;In the formula: PMAX a is the upper limit of the total power of the whole plant;

PMINa=PMIN1+PMIN2+…+PMINn PMIN a =PMIN 1 +PMIN 2 +…+PMIN n

=fmin(G1)+fmin(G2)+…+fmin(Gn)=f min (G 1 )+f min (G 2 )+…+f min (G n )

式中:PMINa是全厂总功率下限。In the formula: PMIN a is the lower limit of the total power of the whole plant.

根据步骤5中各机组功率上、下限和供热抽汽量的拟合关系式可以得到全厂总功率上下限和各机组供热抽汽量的拟合关系式,全厂总功率上限和各机组供热抽汽量关系式如下:According to the fitting relationship between the upper and lower limits of the power of each unit and the heating and extraction volume in step 5, the fitting relationship between the upper and lower limits of the total power of the whole plant and the heating and extraction volume of each unit can be obtained. The relationship between the heat supply and steam extraction of the unit is as follows:

PMAXa=PMAX1+PMAX2+PMAX3=-0.2261G1+341.96-0.2003G3+391.57-0.2003G4+391.57PMAXa=PMAX 1+ PMAX 2+ PMAX 3 =-0.2261G 1 +341.96-0.2003G 3 +391.57-0.2003G 4 +391.57

全厂总功率下限和各机组供热抽汽量关系式如下:The relationship between the lower limit of the total power of the whole plant and the heating and extraction volume of each unit is as follows:

PMINa=PMIN1+PMIN3+PMIN4=1.47*10-8G1 4-1.1069*10-5G1 3+2.7366*10-3G1 2-0.47985G1+220.03+1.2083*10-8G3 4+1.1009*10-5G3 3-1.9486*10-3G3 2-0.17934G3+PMINa=PMIN 1+ PMIN 3+ PMIN 4 =1.47*10 -8 G 1 4 -1.1069*10 -5 G 1 3 +2.7366*10 -3 G 1 2 -0.47985G 1 +220.03+1.2083*10 -8 G 3 4 +1.1009*10 -5G 3 3 -1.9486*10 -3G 3 2 -0.17934G 3 +

235.44+1.2083*10-8G4 4+1.1009*10-5G4 3-1.9486*10-3G4 2-0.17934G4+235.44235.44+1.2083*10 -8 G 4 4 +1.1009*10 -5 G 4 3 -1.9486*10 -3 G 4 2 -0.17934G 4 +235.44

步骤7:根据步骤6中得到的全厂总功率上、下限和各机组抽汽量的的数学关系式以及设定好的约束条件:各机组总供热量等于步骤3中计算的全厂当前总供热量,各机组抽汽量不超过机组允许的最大抽汽量,以全厂总功率上、下限和各机组抽汽量的数学关系式作为目标函数,利用MATLAB最优化工具箱中的fmincon函数求解,得到各机组基于全厂调峰上限的抽汽量和基于全厂调峰下限的抽汽量,以及对应的全厂总功率上限最大值和下限最小值。Step 7: According to the mathematical relationship between the upper and lower limits of the total power of the whole plant and the steam extraction volume of each unit obtained in step 6, and the set constraints: the total heat supply of each unit is equal to the current value of the whole plant calculated in step 3. The total heat supply, the steam extraction volume of each unit does not exceed the maximum allowable steam extraction volume of the unit, and the mathematical relationship between the upper and lower limits of the total power of the whole plant and the extraction steam volume of each unit is used as the objective function. The fmincon function is solved to obtain the extraction steam volume based on the upper limit of the whole plant peak regulation and the extraction steam volume based on the lower limit of the whole plant peak regulation, as well as the corresponding maximum upper limit and minimum lower limit of the total power of the whole plant.

上述求解全厂总功率上限、下限极值的表达式如下:The above expressions for solving the upper limit and lower limit of the total power of the whole plant are as follows:

因fmincon函数只能求解最小值,因此我们将求解功率上限的最大值问题转化为求解功率上限负函数最小值问题,目标函数如下:Since the fmincon function can only solve the minimum value, we transform the problem of solving the maximum value of the upper power limit into the problem of solving the minimum value of the negative function of the upper power limit. The objective function is as follows:

min(-PMAXa)=min(-(fmax(G1)+fmax(G2)+…+fmax(Gn)))min(-PMAX a )=min(-(f max (G 1 )+f max (G 2 )+...+f max (G n )))

全厂总功率下限目标函数如下:The objective function of the lower limit of the total power of the whole plant is as follows:

minPMINa=min(fmin(G1)+fmin(G2)+…+fmin(Gn))minPMIN a = min(f min (G 1 )+f min (G 2 )+…+f min (G n ))

求解全厂总功率上限、下限极值的约束条件表达式如下:The constraint expression for solving the upper limit and lower limit of the total power of the whole plant is as follows:

Qa=G1(h1-hs1)+G2(h2-hs2)+…+Gn(hn-hsn)Q a =G 1 (h 1 -h s1 )+G 2 (h 2 -h s2 )+...+G n (h n -h sn )

0≤G1≤G1max 0≤G 1 ≤G 1max

0≤G2≤G2max 0≤G 2 ≤G 2max

0≤Gn≤Gn max 0≤Gn≤Gnmax _

式中:Qa是步骤3计算的全厂当前总供热量(GJ/h),是一个定值;G1,G2,…,Gn分别是第一台到第n台机组在全厂功率上限和功率下限下分别对应的抽汽量(t/h);G1max,G2max,Gn max分别是第一台到第n台机组的最大抽汽量(t/h),是定值,从各机组供热工况图查得;h1,h2……hn分别是第一台到第n台机组的供热抽汽焓;hs1、hs2……hsn分别是第一台到第n台机组的供热抽汽疏水焓。In the formula: Q a is the current total heat supply (GJ/h) of the whole plant calculated in step 3, which is a fixed value; G 1 , G 2 ,..., G n are the first to nth units in the whole plant respectively. The extraction steam volume (t/h) corresponding to the upper limit and lower power limit of the plant respectively; G 1max , G 2max , G n max are the maximum extraction volume (t/h) of the first to nth units respectively, and are The fixed value is obtained from the heating condition diagram of each unit; h 1 , h 2 ……h n are the heating extraction enthalpy of the first to nth units respectively; h s1 , h s2 …… h sn are respectively is the heating extraction steam drainage enthalpy of the first to nth units.

利用上述方法对该热电厂进行在线优化,重新分配各机组抽汽量,优化后的各机组及全厂抽汽量和调峰上下限如表4所示:The thermal power plant is optimized online by the above method, and the steam extraction volume of each unit is redistributed. The optimized steam extraction volume of each unit and the whole plant and the upper and lower limits of peak regulation are shown in Table 4:

表4优化后的各机组及全厂抽汽量和调峰上下限Table 4 The optimized steam extraction volume and peak shaving upper and lower limits of each unit and the whole plant

Figure GDA0001750458330000111
Figure GDA0001750458330000111

优化前后全厂总调峰上、下限对比如表5所示:The comparison between the upper and lower limits of the total peak shaving of the whole plant before and after optimization is shown in Table 5:

表5优化前后全厂总调峰上、下限对比表Table 5 Comparison table of upper and lower limits of total peak shaving in the whole plant before and after optimization

全厂The whole plant 调峰下限(MW)Peak shaving lower limit (MW) 调峰上限(MW)Peak shaving upper limit (MW) 优化前Before optimization 606.72606.72 873.65873.65 优化后Optimized 512.61512.61 964.28964.28

由表5可以看出,利用本发明提出的方法对热电厂进行在线优化,重新分配各机组热负荷后,全厂的总调峰下限明显降低,总调峰上限也明显升高,全厂总调峰能力显著提高。It can be seen from Table 5 that the method proposed by the present invention is used to optimize the thermal power plant online, and after redistributing the heat load of each unit, the lower limit of the total peak regulation of the whole plant is significantly reduced, and the upper limit of the total peak regulation is also significantly increased. Peak capacity is significantly improved.

以上所述仅为本申请的优选实施例而已,并不用于限制本申请,对于本领域的技术人员来说,本申请可以有各种更改和变化。凡在本申请的精神和原则之内,所作的任何修改、等同替换、改进等,均应包含在本申请的保护范围之内。The above descriptions are only preferred embodiments of the present application, and are not intended to limit the present application. For those skilled in the art, the present application may have various modifications and changes. Any modification, equivalent replacement, improvement, etc. made within the spirit and principle of this application shall be included within the protection scope of this application.

Claims (10)

1.一种基于热电厂全厂调峰能力最大化的热负荷分配方法,热电厂有n台抽汽凝汽式汽轮发电机组供热,n≥2,各机组之间容量或供热方式存在不同,其特征在于,包括以下步骤:1. A heat load distribution method based on maximizing the peak shaving capacity of the thermal power plant. The thermal power plant has n extraction and condensing steam turbine generator sets to supply heat, n≥2, and there are differences in the capacity or heating mode between the units , is characterized in that, comprises the following steps: 步骤1:记录各机组当前运行工况下的抽汽量、抽汽压力、抽汽温度和抽汽疏水温度;Step 1: Record the extraction steam volume, extraction steam pressure, extraction steam temperature and extraction steam drainage temperature under the current operating conditions of each unit; 步骤2:根据步骤1记录的抽汽压力、抽汽温度、抽汽疏水温度,采用工业用水和水蒸气热力性质模型计算得到各机组的抽汽焓和抽汽疏水焓;Step 2: According to the extraction steam pressure, extraction steam temperature, and extraction steam drainage temperature recorded in Step 1, the extraction steam enthalpy and extraction steam drainage enthalpy of each unit are calculated by using the thermal property model of industrial water and steam; 步骤3:根据步骤1中各机组抽汽量和步骤2中的抽汽焓和抽汽疏水焓计算各机组供热量,进而得到全厂当前总供热量;Step 3: Calculate the heat supply of each unit according to the extraction steam volume of each unit in step 1 and the extraction steam enthalpy and extraction steam drainage enthalpy in step 2, and then obtain the current total heat supply of the whole plant; 步骤4:以全厂为单位,收集各机组供热工况图,利用各机组供热工况图绘制热电关系曲线;热电关系曲线为各机组功率上限随抽汽量变化曲线和各机组功率下限随抽汽量变化曲线;Step 4: Take the whole plant as a unit, collect the heating condition diagram of each unit, and use the heating condition diagram of each unit to draw the thermoelectric relationship curve; Variation curve with extraction steam volume; 步骤5:分别将各机组功率上限随抽汽量变化曲线和各机组功率下限随抽汽量变化曲线添加趋势线并拟合公式,得到各机组功率上限、功率下限和抽汽量的数学关系式;Step 5: Add trend lines to the curve of the upper limit of power of each unit with the change of steam extraction volume and the curve of the lower limit of power of each unit with the change of steam extraction volume, and fit the formula to obtain the mathematical relationship between the upper limit of power, lower limit of power and extraction volume of each unit ; 步骤6:进一步累加得到全厂总功率上限、下限和抽汽量的数学关系式;Step 6: Further accumulatively obtain the mathematical relationship between the upper and lower limits of the total power of the whole plant and the extraction steam volume; 步骤7:根据步骤6中得到的全厂总功率上限、下限和各机组抽汽量的数学关系式以及设定好的约束条件,以全厂总功率上、下限和各机组抽汽量的数学关系式作为目标函数,利用最优化工具箱求解,得到各机组基于全厂调峰上限的抽汽量和基于全厂调峰下限的抽汽量,以及对应的全厂总功率上限最大值和下限最小值,从而实现全厂调峰能力最大化的热负荷分配;Step 7: According to the mathematical relationship between the upper limit and lower limit of the total power of the whole plant and the steam extraction volume of each unit obtained in Step 6, and the set constraints, the upper and lower limits of the total power of the whole plant and the mathematical relationship of the steam extraction volume of each unit are calculated. The relational expression is used as the objective function, and the optimization toolbox is used to solve it, and the extraction steam volume based on the upper limit of the whole plant peak shaving and the extraction steam volume based on the lower limit of the whole plant peak shaving, as well as the corresponding upper limit and lower limit of the total power of the whole plant are obtained. The minimum value, so as to realize the heat load distribution that maximizes the peak shaving capacity of the whole plant; 所述约束条件:各机组总供热量等于步骤3中计算的全厂当前总供热量,各机组抽汽量不超过机组允许的最大抽汽量。The constraint conditions: the total heat supply of each unit is equal to the current total heat supply of the whole plant calculated in step 3, and the steam extraction volume of each unit does not exceed the maximum allowable steam extraction volume of the unit. 2.如权利要求1所述的一种基于热电厂全厂调峰能力最大化的热负荷分配方法,其特征是,所述步骤4的供热工况图是进汽量、抽汽量和有功功率三者的耦合关系图;每一个抽汽量都有一个对应的最大和最小功率,把不同抽汽量及对应的最大和最小功率数值分别输入EXCEL,生成热电关系曲线图。2. A heat load distribution method based on maximizing the peak shaving capacity of the thermal power plant as claimed in claim 1, wherein the heating condition diagram of the step 4 is the amount of steam intake, steam extraction and active power. The coupling relationship diagram of the three powers; each extraction steam volume has a corresponding maximum and minimum power. Input the different extraction steam volumes and the corresponding maximum and minimum power values into EXCEL to generate a thermoelectric relationship curve. 3.如权利要求1所述的一种基于热电厂全厂调峰能力最大化的热负荷分配方法,其特征是,所述步骤2利用加载在EXCEL中的IFC-97工业用水和水蒸气热力性质模型计算。3. a heat load distribution method based on maximizing the peak shaving capacity of a thermal power plant as claimed in claim 1, wherein the step 2 utilizes the IFC-97 industrial water and steam thermal properties loaded in EXCEL Model calculation. 4.如权利要求1所述的一种基于热电厂全厂调峰能力最大化的热负荷分配方法,其特征是,所述步骤3中,各机组当前供热量计算公式如下:4. A heat load distribution method based on the maximization of the peak regulation capacity of the thermal power plant as claimed in claim 1, wherein in the step 3, the current calculation formula of the heat supply of each unit is as follows: Qn′=Gn′(hn′-hsn′)Q n ′=G n ′(h n ′-h sn ′) 式中:Qn′是第n台机组当前的供热量,Gn′是第n台机组当前的供热抽汽量,hn′是第n台机组当前的供热抽汽焓,hsn′是第n台机组当前的供热抽汽疏水焓。In the formula: Q n ′ is the current heat supply of the nth unit, G n ′ is the current heat supply and extraction volume of the nth unit, h n ′ is the current heat supply and extraction enthalpy of the nth unit, h sn ' is the current heating extraction steam drainage enthalpy of the nth unit. 5.如权利要求4所述的一种基于热电厂全厂调峰能力最大化的热负荷分配方法,其特征是,所述步骤3中,全厂当前总供热量计算公式为:5. A heat load distribution method based on maximizing the peak-shaving capacity of the thermal power plant as claimed in claim 4, wherein in the step 3, the current total heat supply calculation formula of the whole plant is: Qa=Q1′+Q2′+…+QnQ a =Q 1 ′+Q 2 ′+...+Q n 式中:Qa是全厂当前总供热量,Q1′~Qn′分别为第1台到第n台机组当前供热量。In the formula: Q a is the current total heat supply of the whole plant, and Q 1 ′~Q n ′ are the current heat supply of the first to nth units respectively. 6.如权利要求1所述的一种基于热电厂全厂调峰能力最大化的热负荷分配方法,其特征是,所述步骤5中,各机组功率上限、功率下限和各机组抽汽量的计算公式分别如下:6. A heat load distribution method based on maximizing the peak shaving capacity of the thermal power plant as claimed in claim 1, wherein in the step 5, the upper limit of the power of each unit, the lower limit of the power and the steam extraction amount of each unit are calculated. The calculation formulas are as follows: PMAXn=fmax(Gn)PMAX n =f max (G n ) 式中:PMAXn是第n台机组的功率上限,fmax(Gn)是供热抽汽量的一元函数,由EXCEL拟合得到;In the formula: PMAX n is the upper limit of the power of the nth unit, f max (G n ) is the unary function of the heating and extraction steam, which is obtained by EXCEL fitting; PMINn=fmin(Gn)PMIN n =f min (G n ) 式中:PMINn是第n台机组的功率下限,fmax(Gn)是供热抽汽量的一元函数,由EXCEL拟合得到。In the formula: PMIN n is the power lower limit of the nth unit, f max (G n ) is the unary function of the heat extraction steam amount, which is obtained by EXCEL fitting. 7.如权利要求1所述的一种基于热电厂全厂调峰能力最大化的热负荷分配方法,其特征是,所述步骤6中,全厂总功率上限、总功率下限的计算公式分别为:7. A heat load distribution method based on maximizing the peak shaving capacity of a thermal power plant as claimed in claim 1, wherein in the step 6, the calculation formulas for the upper limit of the total power and the lower limit of the total power are respectively: : PMAXa=PMAX1+PMAX2+…+PMAXn PMAX a =PMAX 1 +PMAX 2 +...+PMAX n =fmax(G1)+fmax(G2)+…+fmax(Gn)=f max (G 1 )+f max (G 2 )+…+f max (G n ) 式中:PMAXa是全厂总功率上限;In the formula: PMAX a is the upper limit of the total power of the whole plant; PMINa=PMIN1+PMIN2+…+PMINn PMIN a =PMIN 1 +PMIN 2 +…+PMIN n =fmin(G1)+fmin(G2)+…+fmin(Gn)=f min (G 1 )+f min (G 2 )+…+f min (G n ) 式中:PMINa是全厂总功率下限。In the formula: PMIN a is the lower limit of the total power of the whole plant. 8.如权利要求1所述的一种基于热电厂全厂调峰能力最大化的热负荷分配方法,其特征是,所述步骤7中,利用MATLAB最优化工具箱中的fmincon函数求解。8 . The heat load distribution method based on the maximization of the peak shaving capacity of the thermal power plant as claimed in claim 1 , wherein, in the step 7, the fmincon function in the MATLAB optimization toolbox is used to solve the problem. 9 . 9.如权利要求8所述的一种基于热电厂全厂调峰能力最大化的热负荷分配方法,其特征是,所述步骤7中,求解全厂总功率上限、下限极值的表达式如下:因fmincon函数只能求解最小值,将求解功率上限的最大值问题转化为求解功率上限负函数最小值问题,目标函数如下:9. A heat load distribution method based on maximizing the peak shaving capacity of a thermal power plant as claimed in claim 8, wherein in the step 7, the expressions for solving the upper limit and lower limit of the total power of the whole plant are as follows : Since the fmincon function can only solve the minimum value, the problem of solving the maximum value of the power upper limit is transformed into the problem of solving the minimum value of the negative function of the power upper limit. The objective function is as follows: min(-PMAXa)=min(-(fmax(G1)+fmax(G2)+…+fmax(Gn)))min(-PMAX a )=min(-(f max (G 1 )+f max (G 2 )+...+f max (G n ))) 全厂总功率下限目标函数如下:The objective function of the lower limit of the total power of the whole plant is as follows: minPMINa=min(fmin(G1)+fmin(G2)+…+fmin(Gn))。 minPMINa = min (fmin( G1 ) + fmin (G2)+...+ fmin ( Gn )). 10.如权利要求1-9所述的一种基于热电厂全厂调峰能力最大化的热负荷分配方法,其特征是,约束条件表达式如下:10. A heat load distribution method based on the maximization of the peak shaving capacity of the thermal power plant as claimed in claims 1-9, wherein the constraint condition expression is as follows: Qa=G1(h1-hs1)+G2(h2-hs2)+…+Gn(hn-hsn)Q a =G 1 (h 1 -h s1 )+G 2 (h 2 -h s2 )+...+G n (h n -h sn ) 0≤G1≤G1max 0≤G 1 ≤G 1max 0≤G2≤G2max 0≤G 2 ≤G 2max 0≤Gn≤Gnmax 0≤Gn≤Gnmax _ 式中:Qa是步骤3计算的全厂当前总供热量,是一个定值;G1,G2,...,Gn分别是第一台到第n台机组在全厂功率上限和功率下限下分别对应的抽汽量;G1max,G2max,Gnmax分别是第一台到第n台机组的最大抽汽量,是定值,从各机组供热工况图查得;h1,h2......hn分别是第一台到第n台机组供热抽汽焓;hs1、hs2......hsn分别是第一台到第n台机组供热抽汽疏水焓。In the formula: Q a is the current total heat supply of the whole plant calculated in step 3, which is a fixed value; G 1 , G 2 , ..., G n are the upper limit of the power of the first to nth units in the whole plant, respectively and the corresponding extraction steam volume under the lower power limit; G 1max , G 2max , and G nmax are the maximum extraction steam volumes of the first to nth units respectively, which are fixed values and are obtained from the heating condition diagram of each unit; h 1 , h 2 ...... h n are the heating extraction enthalpy of the first to n units respectively; h s1 , h s2 ...... h sn are the first to n units respectively Unit heating extraction steam drainage enthalpy.
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