CN107508556A - A kind of DE classes frequency multiplier and design method - Google Patents

A kind of DE classes frequency multiplier and design method Download PDF

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Publication number
CN107508556A
CN107508556A CN201710748598.6A CN201710748598A CN107508556A CN 107508556 A CN107508556 A CN 107508556A CN 201710748598 A CN201710748598 A CN 201710748598A CN 107508556 A CN107508556 A CN 107508556A
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inductance
fet
frequency
load resistance
msub
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CN107508556B (en
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花再军
陈钊
李建霓
黄凤辰
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Hohai University HHU
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    • HELECTRICITY
    • H03ELECTRONIC CIRCUITRY
    • H03BGENERATION OF OSCILLATIONS, DIRECTLY OR BY FREQUENCY-CHANGING, BY CIRCUITS EMPLOYING ACTIVE ELEMENTS WHICH OPERATE IN A NON-SWITCHING MANNER; GENERATION OF NOISE BY SUCH CIRCUITS
    • H03B19/00Generation of oscillations by non-regenerative frequency multiplication or division of a signal from a separate source
    • H03B19/06Generation of oscillations by non-regenerative frequency multiplication or division of a signal from a separate source by means of discharge device or semiconductor device with more than two electrodes
    • H03B19/14Generation of oscillations by non-regenerative frequency multiplication or division of a signal from a separate source by means of discharge device or semiconductor device with more than two electrodes by means of a semiconductor device

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Abstract

The invention discloses a kind of DE classes frequency multiplier and design method, including direct voltage source, first FET, second FET, first inductance, second inductance, capacitance, Shunt compensation capacitor, LC parallel-tuned circuits and load resistance, capacitance one terminates one end of the first inductance and the second inductance, the other end connects LC parallel-tuned circuits respectively, one end of Shunt compensation capacitor and load resistance, the other end of first inductance concatenates the drain electrode of the first FET, the other end of second inductance concatenates the drain electrode of the second FET, LC parallel-tuned circuits, another termination power of Shunt compensation capacitor and load resistance, first FET S1With connecing power supply, grid meets the first driving voltage, the second FET S to source electrode2Source electrode connects direct voltage source, and grid connects the second driving voltage.The component value that the present invention only adjusts passive device in the case where not changing former DE class A amplifier As structure and drive signal waveform can obtain frequency-doubled signal.

Description

A kind of DE classes frequency multiplier and design method
Technical field
The present invention relates to a kind of DE classes frequency multiplier and design method, belong to frequency multiplier technical field.
Background technology
Frequency multiplier is the important devices in communication, and the source signal frequency of several times can be obtained by frequency multiplier.Transistor times For frequency device except that can realize frequency multiplication, its output signal generally also has power gain.Transistor frequency multiplier amplifies with switching regulator Device is similar, there is D classes, E classes, DE classes etc., generally all has higher efficiency.
The content of the invention
The technical problems to be solved by the invention are the defects of overcoming prior art, there is provided a kind of DE classes frequency multiplier and design Method, the component value of passive device is only adjusted in the case where not changing former DE class A amplifier As structure and drive signal waveform to be obtained Frequency-doubled signal.
In order to solve the above technical problems, the present invention provides a kind of DE classes frequency multiplier, including direct voltage source Vdd, first effect Should pipe S1, the second FET S2, the first inductance L1, the second inductance L2, capacitance CDC, Shunt compensation capacitor C, LC and joint debugging Humorous circuit and load resistance RL
The capacitance CDCOne the first inductance L of termination1With the second inductance L2One end, capacitance CDCThe other end point LC parallel-tuned circuits, Shunt compensation capacitor C and load resistance R are not metLOne end;The first inductance L1The other end concatenation First FET S1Drain electrode;The second inductance L2The other end concatenate the second FET S2Drain electrode;The LC is in parallel Tuning circuit, Shunt compensation capacitor C and load resistance RLAnother termination power;
The first FET S1With connecing power supply, grid connects the first driving voltage to source electrode;
The second FET S2Source electrode meets direct voltage source Vdd, grid connects the second driving voltage.
Foregoing LC parallel-tuned circuits include tuning capacitance CpWith tuning coil Lp, wherein, tuning capacitance CpBoth ends connect Tuning coil LpBoth ends, resonance is in frequency multiplication target frequency.
The design method of DE class frequency multipliers, comprises the following steps:
1) the drive signal dutycycle of DE classes frequency multiplier is 25%, as the first fet switch S1During disconnection, the first electricity Feel L1In electric current drop to 0, and electric current changes with time rate as 0 so that the first inductance L1Power attenuation be 0;When first Fet switch S2During disconnection, the second inductance L2In electric current drop to 0, and electric current changes with time rate as 0 so that the Two inductance L2Power attenuation be 0;According to this inductance zero-current switching and zero current derivative switch condition, obtain in N frequency multipliers Parameters relationship:
Wherein,
It is multiple of the output voltage amplitude relative to direct current power source voltage,
It is the phase of output voltage,
For load resistance RLInverse,
B=N ω C are Shunt compensation capacitor C susceptance,
X=ω L1=ω L2It is series inductance L1And L2Induction reactance,
The π f of ω=2;
2) design parameter of DE class frequency multipliers, including direct voltage source V are givendd, power output Po, loaded quality factor QLC, driving signal frequency f and frequency multiple N;
3) parameters relationship of step 1), the expression formula of load resistance and the design parameter of DE class frequency multipliers are combined, obtains N times The component parameters of frequency device:Load resistance RL, the first inductance L1, the second inductance L2, Shunt compensation capacitor C, parallel resonant electric capacity CpWith Parallel resonant inductance Lp
4) the result of calculation design DE class frequency multipliers of step 3) are utilized.
N in foregoing N frequency multipliers is odd number.
Foregoing load resistance RLMeet:
Foregoing parallel resonant electric capacity CpWith parallel resonant inductance LpCalculation formula it is as follows:
What the present invention was reached has the beneficial effect that:In the case where not changing former DE class A amplifier As structure and drive signal waveform only The component value of adjustment passive device can obtain frequency-doubled signal, and keep very high efficiency.
Brief description of the drawings
Fig. 1 is a kind of circuit diagram of DE classes frequency multiplier;
Fig. 2 is a kind of equivalent circuit of DE classes frequency multiplier;
Fig. 3 is drive signal dutycycle when being 25%, N=3, each current-voltage waveform figure of the frequency multiplier of DE classes 3;Fig. 3 (a) is The driving voltage waveform v of first FETDr1(θ);Fig. 3 (b) is the driving voltage waveform v of the second FETDr2(θ);Fig. 3 (c) it is to flow through the first FET S1Electric current is1The oscillogram of (θ);Fig. 3 (d) is to flow through the second FET S2Electric current is2 The oscillogram of (θ);Fig. 3 (e) is the voltage waveform v of the first FET drainD1(θ);Fig. 3 (f) is the second FET drain Voltage waveform vD2(θ);Fig. 3 (g) is output voltage waveforms vo(θ)。
Embodiment
The invention will be further described below.Following examples are only used for the technical side for clearly illustrating the present invention Case, and can not be limited the scope of the invention with this.
As shown in figure 1, the DE classes frequency multiplier of the present invention includes direct voltage source Vdd, the first FET S1, second effect Should pipe S2, the first inductance L1, the second inductance L2, capacitance CDC, Shunt compensation capacitor C, LC parallel-tuned circuit and load resistance RL.In Fig. 1, vDr1(θ) and vDr2(θ) is first and second FET driving voltage, vs2(θ), is2(θ) is the leakage of the second FET Source voltage and the electric current for flowing through it, i1(θ) is the alternating current for flowing through capacitance, vm(θ) is the first inductance L1With the second electricity Feel L2The voltage of tie point, vs1(θ) and is1(θ) is the first FET drain-source voltage and flows through its electric current, ix(θ) is simultaneously Join the electric current in compensating electric capacity C, io(θ) is load resistance RLIn electric current, vo(θ) is the voltage on load resistance, when θ is angle Between, θ=ω t.
Capacitance CDCOne the first inductance L of termination1With the second inductance L2One end, the other end connect respectively LC parallel resonants electricity Road, Shunt compensation capacitor C and load resistance RLOne end.
LC parallel-tuned circuits, Shunt compensation capacitor C and load resistance RLAnother termination power.
First FET S1With connecing power supply, grid connects the first driving voltage to source electrode, and drain series meet the first inductance L1It is another One end.
Second FET S2Source electrode meets direct voltage source Vdd, grid connects the second driving voltage, and drain series connect the second electricity Feel L2The other end.
LC parallel-tuned circuits include tuning capacitance CpWith tuning coil Lp, wherein, tuning capacitance CpBoth ends connection tuning electricity Feel LpBoth ends, resonance is in frequency multiplication target frequency.
Fig. 2 is the equivalent circuit of DE class frequency multipliers.By the first FET S1, the second FET S2It is equivalent to two electricity Press controlling switch.
The drive signal dutycycle of DE class frequency multipliers is 25%.As the first fet switch S1During disconnection, the first inductance L1 In electric current drop to 0, and electric current changes with time rate (i.e. the slope of electric current) as 0 so that the first inductance L1Power damage Consume for 0.As the first fet switch S2During disconnection, the second inductance L2In electric current drop to 0, and electric current changes with time Rate (i.e. the slope of electric current) is 0 so that the second inductance L2Power attenuation be 0.
With above inductance zero-current switching and zero current derivative switch condition, the ginseng in N frequency multipliers (N is odd number) is obtained Number relation:
Wherein:
It is multiple of the output voltage amplitude relative to direct current power source voltage,
It is the phase of output voltage,
For load resistance RLInverse,
B=N ω C are Shunt compensation capacitor C susceptance,
X=ω L1=ω L2It is series inductance L1And L2Induction reactance.
The π f of ω=2.
In order to facilitate the design of N frequency multipliers, design parameter corresponding to odd number N=3,5,7 is listed in table 1:
The parameters relationship of table 1N frequency multipliers
N B/G GX
3 3.562 0.0474
5 10.94 0.0091
7 9.445 0.0076
When Fig. 3 is drive signal dutycycle D=25%, the course of work of the frequency multiplier example of DE classes 3 within a 2 π cycles For:
(1) in the π of 0 < θ≤0.5, as Fig. 3 (a) drive signals make the first FET S1Closure;Such as Fig. 3 (b) drive signals Make the second FET S2Disconnect;As Fig. 3 (c) flows through the first FET S1Electric current iS1(and flow through the first inductance L1Electricity Stream) there is the process of a rising, rise to after peak value and the process of a decline occur, finally to 0, electric current i when reaching 0S1At any time Between derivative also be 0;Such as Fig. 3 (e), the first FET drain voltage is 0, i.e. the first FET S1Both end voltage vS1For 0; Such as Fig. 3 (d), the second FET S is flowed through2Electric current iS2(and flow through the second inductance L2Electric current) be 0;Such as Fig. 3 (f), Two FET S2Disconnect, the second FET drain voltage vD2Change with output voltage.
(2) the first FET S is made in 0.5 π < θ≤π, such as Fig. 3 (a) drive signals1Disconnect;Such as Fig. 3 (b) drive signals Make the second FET S2Disconnect.Fig. 3 (c) flows through the first FET electric current iS1(and flow through the first inductance L1Electric current) be 0;Such as Fig. 3 (e), the first FET S1Disconnect, the first FET drain voltage vD1Change with output voltage;Fig. 3 (d) flows through Second FET electric current iS2(and flow through the second inductance L2Electric current) be 0;Such as Fig. 3 (f), the second FET S2Disconnect, Second FET drain voltage vD2Change with output voltage.
(3) in the π of π < θ≤1.5, as Fig. 3 (a) drive signals make the first FET S1Disconnect;Such as Fig. 3 (b) drive signals Make the second FET S2Closure;Fig. 3 (c) flows through the first FET electric current iS1(and flow through the first inductance L1Electric current) be 0;Such as Fig. 3 (e), the first FET S1Disconnect, the first FET drain voltage vD1Change with output voltage;Fig. 3 (d), stream Cross the second FET S2Electric current iS2(and flow through the second inductance L2Electric current) have one rising process, rise to peak value Occur the process of a decline afterwards, finally to 0, electric current i when reaching 0S2Derivative with the time is also 0;Fig. 3 (f), the second field-effect Pipe drain voltage is equal to direct current power source voltage, i.e. the second FET S2Both end voltage vS2For 0.
(4) in the π of 1.5 π < θ≤2, this operated within range process is the same as (2).As Fig. 3 (a) drive signals make the first FET S1Disconnect;As Fig. 3 (b) drive signals make the second FET S2Disconnect.Fig. 3 (c) flows through the first FET electric current iS1(and Flow through the first inductance L1Electric current) be 0;Such as Fig. 3 (e), the first FET S1Disconnect, the first FET drain voltage vD1With Output voltage changes;Fig. 3 (d) flows through the second FET electric current iS2(and flow through the second inductance L2Electric current) be 0;Such as Fig. 3 (f), the second FET S2Disconnect, the second FET drain voltage vD2Change with output voltage.
Fig. 3 (g) is output voltage waveforms, and output electrical signal voltage is direct voltage source Vdd2.9 times, frequency be driving letter Number 3 times, realize 3 frequencys multiplication.
The design parameter of given DE class frequency multipliers, including direct voltage source Vdd, power output Po, loaded quality factor QLC, The expression formula of driving signal frequency f and frequency multiple N, incorporating parametric relation and load resistance, obtain DE class frequency multiplier elements Each parameter:
Wherein, load resistance meets:
LC parallel-tuned circuits are used to extract required frequency, and the component parameters of LC parallel-tuned circuits are:
The π f of ω=2
Output voltage is:
When drive signal dutycycle is 25%, as N=3, i.e. DE-1The frequency multiplier of class 3, output signal voltage are direct currents Source voltage Vdd2.9 times, frequency is 3 times of drive signal, realizes 3 frequencys multiplication.Its load resistance RL, the first inductance L1, second Inductance L2, Shunt compensation capacitor C, parallel resonant electric capacity CpWith parallel resonant inductance LpCalculation formula (capacitance CDCOnly need foot It is enough big, it is not necessary to especially to calculate);
Quality factor are QLCLC parallel resonant component parameters:
Wherein, the π f of ω=2.
Finally, DE class frequency multipliers are designed using result of calculation.
Described above is only the preferred embodiment of the present invention, it is noted that for the ordinary skill people of the art For member, without departing from the technical principles of the invention, some improvement and deformation can also be made, these are improved and deformation Also it should be regarded as protection scope of the present invention.

Claims (6)

1. a kind of DE classes frequency multiplier, it is characterised in that including direct voltage source Vdd, the first FET S1, the second FET S2, the first inductance L1, the second inductance L2, capacitance CDC, Shunt compensation capacitor C, LC parallel-tuned circuit and load resistance RL
The capacitance CDCOne the first inductance L of termination1With the second inductance L2One end, capacitance CDCThe other end connect respectively LC parallel-tuned circuits, Shunt compensation capacitor C and load resistance RLOne end;The first inductance L1The other end concatenation first FET S1Drain electrode;The second inductance L2The other end concatenate the second FET S2Drain electrode;The LC parallel resonants Circuit, Shunt compensation capacitor C and load resistance RLAnother termination power;
The first FET S1With connecing power supply, grid connects the first driving voltage to source electrode;
The second FET S2Source electrode meets direct voltage source Vdd, grid connects the second driving voltage.
2. a kind of DE classes frequency multiplier according to claim 1, it is characterised in that the LC parallel-tuned circuits include tuning Electric capacity CpWith tuning coil Lp, wherein, tuning capacitance CpBoth ends connection tuning coil LpBoth ends, resonance is in frequency multiplication target frequency.
3. the design method of the DE class frequency multipliers described in claim 1 or 2, it is characterised in that comprise the following steps:
1) the drive signal dutycycle of DE classes frequency multiplier is 25%, as the first fet switch S1During disconnection, the first inductance L1In Electric current drop to 0, and electric current changes with time rate as 0 so that the first inductance L1Power attenuation be 0;When first effect Should pipe switch S2During disconnection, the second inductance L2In electric current drop to 0, and electric current changes with time rate as 0 so that the second electricity Feel L2Power attenuation be 0;According to this inductance zero-current switching and zero current derivative switch condition, the ginseng in N frequency multipliers is obtained Number relation:
Wherein,
It is multiple of the output voltage amplitude relative to direct current power source voltage,
It is the phase of output voltage,
For load resistance RLInverse,
B=N ω C are Shunt compensation capacitor C susceptance,
X=ω L1=ω L2It is series inductance L1And L2Induction reactance,
The π f of ω=2;
2) design parameter of DE class frequency multipliers, including direct voltage source V are givendd, power output Po, loaded quality factor QLC, drive Dynamic signal frequency f and frequency multiple N,
3) parameters relationship of step 1), the expression formula of load resistance and the design parameter of DE class frequency multipliers are combined, obtains N frequency multipliers Component parameters:Load resistance RL, the first inductance L1, the second inductance L2, Shunt compensation capacitor C, parallel resonant electric capacity CpAnd parallel connection Tuning coil Lp
4) the result of calculation design DE class frequency multipliers of step 3) are utilized.
4. design method according to claim 3, it is characterised in that the N in the N frequency multipliers is odd number.
5. design method according to claim 3, it is characterised in that the load resistance RLMeet:
6. design method according to claim 3, it is characterised in that the parallel resonant electric capacity CpWith parallel resonant inductance LpCalculation formula it is as follows:
<mrow> <msub> <mi>C</mi> <mi>p</mi> </msub> <mo>=</mo> <mfrac> <msub> <mi>Q</mi> <mrow> <mi>L</mi> <mi>C</mi> </mrow> </msub> <mrow> <msub> <mi>N&amp;omega;R</mi> <mi>L</mi> </msub> </mrow> </mfrac> </mrow>
<mrow> <msub> <mi>L</mi> <mi>p</mi> </msub> <mo>=</mo> <mfrac> <mn>1</mn> <mrow> <msup> <mi>N</mi> <mn>2</mn> </msup> <msup> <mi>&amp;omega;</mi> <mn>2</mn> </msup> <msub> <mi>C</mi> <mi>p</mi> </msub> </mrow> </mfrac> <mo>.</mo> </mrow>
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