CN102480109A - Method for replacing 10kV distribution line lead under load - Google Patents

Abstract

A method for replacing a 10kV distribution line conductor under load belongs to the technical field of live working in an electric power system and adopts a bypass working technology. A wire-releasing device is mainly installed in a faulty tension section to release a short-circuit wire and a new conductor. The device is used to replace the old and new conductors. Compared with the known conductor replacement method, this method does not require cutting off the load and can complete the conductor replacement work without affecting the normal power consumption of users.

Description

A Method of Replacing Conductors of 10kV Distribution Lines with Load

technical field

The invention belongs to the technical field of live work in electric power systems, in particular to a method for replacing conductors of 10kV overhead power distribution lines with load.

Background technique

The 10kV overhead distribution line is exposed to nature for a long time to cause aging. Due to many factors such as construction quality problems, insufficient daily maintenance, excessive load, and external force damage, the contacts are prone to burnout, thereby damaging the main line of the distribution line. Situations happen from time to time. If the wire is replaced due to a power outage, due to the heavy workload, the power outage maintenance time will be too long, which will seriously affect the power supply reliability index. It will cause large economic losses to power supply companies, and the power outage will be too long at the same time, and the negative impact on the society brought to enterprises is even more immeasurable, especially if it occurs in double-circuit or multi-circuit parallel lines, its impact and loss will also become multiplied.

Contents of the invention

In order to solve the above problems, a method for replacing the wires of 10kV distribution lines with load is invented. When the distribution lines fail, the damaged insulated wires are replaced with the load current of the 10kV distribution lines.

The technical solution adopted by the present invention to solve its technical problems is:

1. Install a pay-off device in the faulty tension section to release short wires and new wires. At the same time, the device is used to complete the replacement of old and new wires.

2. After short-circuiting the faulty phase conductor, check the fault point, and reinforce it if necessary to prevent disconnection.

3. At the short-circuit point on both sides, after cutting off the faulty phase wire to make it out of operation, install an insulating pay-off block at the cross-arm of the straight pole in the fault section, and guide the faulty phase wire into the pay-off block.

4. Connect the new and old wires with the wire connector through the shaft insulation pay-off device, apply traction, the new wires are passed to the rod, and the old wires are retreated under the rod to realize the replacement of the new and old wires.

5. When the new wire is put into operation, disconnect the temporary short-circuit wire, disassemble and recycle.

This method is also applicable to the replacement of bare wires with insulated wires, and the replacement of running lines with large-scale insulated wires.

The benefits produced by the present invention are: at present, a 10 kV power distribution line with an average load greater than 300 amperes, if the power outage moves the line, it takes 8-10 hours from going through the power outage procedure to ordering power transmission; according to the current electricity price, the loss Electricity, equivalent to RMB 19098.8. At present, the application of this technology has successfully migrated 20 10kV power distribution lines, which is equivalent to creating more output value for power supply enterprises: 382,000 yuan. At present, the social benefit of 1 kilowatt-hour of electricity is 30 yuan, and the economic loss is about 1,122,336 yuan. In terms of comprehensive social benefits: while the reliability of the power grid has been greatly improved, the social image of the power company has been improved, the electricity demand of the society has been greatly met, a new growth point of the social economy has been opened up, and the preliminary work has been done for the economic development of the power supply area. . At the same time, it plays an important role in maintaining and improving the image of the government.

Detailed ways

(1) When the wire is damaged and needs to be replaced, it is generally necessary to replace the one-phase wire of the entire tension section. Therefore, the short-circuit points should be respectively selected on the lead wires of the two tension rods in the tension section, and their positions should be close to the side other than the faulty section. In this way, the sheath of the main line of the non-faulty section can not be damaged, and at the same time, it is convenient for paralleling and splitting. If any of the short-circuit points is limited by conditions, you can choose a straight rod that is closer to the fault point, change it to a tension rod and set it as a short-circuit point.

(2) After the short-circuit point is set, an insulating pay-off trolley is installed on each pole cross arm in the tension section, and an insulating pay-off device is installed on each pole body 3.0 meters from the ground.

(3) Release the short wiring and the new wire to be replaced to the short contact point through the insulation release device on the pole body.

(4) By connecting the lead wires, empty-charge the short-circuit wires, and after checking the phase sequence, put the short-circuit wires in parallel with the faulty phase wires to achieve the purpose of short-circuiting the fault point.

(5) Use the current tester to confirm that the short-circuit current is good, and cut off the lead wires on the tension rods on both sides of the fault phase of the tension section by breaking the lead wire. The load current of the line flows through the temporary short-circuit. There is no voltage in the faulty phase conductor.

(6) Use wire connectors to connect the old and new wires. Open the insulator binding wire that fixes the old wire (faulty phase) on each pole, and put it into the insulation pay-off trolley. Apply traction to replace old and new wires. Secure the new wires to the insulators on each pole.

(7) Connect the new wire to the line, disconnect the temporary short-circuit wire, and transfer all the load current of the line to the new wire belt distribution, and finally realize the replacement of the faulty phase wire.

Claims (5)

1. A method for replacing 10kV distribution line conductors with load, characterized in that: the bypass operation technology is adopted, the load does not need to be cut off, and the replacement of the conductors can be completed without affecting the normal power consumption of users. 2. A method for replacing 10kV distribution line conductors with load according to claim 1, characterized in that: a wire release device is installed in the strain-resistant section of the fault to release the short wiring and new conductors, and at the same time use the The device completes the replacement of old and new wires. 3. A method for replacing the wires of a 10kV distribution line with load according to claim 1, characterized in that: after the faulty phase wires are short-circuited, the fault point is checked and reinforced if necessary to prevent disconnection. 4. A method for replacing the wires of a 10kV distribution line with load according to claim 1, characterized in that: after the faulty phase wires are cut off at the short-circuit points on both sides to make them quit running, the straight lines in the faulty section respectively An insulating pay-off block is installed at the cross-arm of the pole, and the faulty phase conductor is guided into the pay-off block. 5. A method for replacing the wires of a 10kV distribution line with load according to claim 1, characterized in that: the new wire and the old wire are connected by a wire connector through a shaft insulation release device, and traction is applied to the new wire. The wire is passed to the rod, and the old wire is retreated under the rod to realize the replacement of the old and new wire.