WO2019062822A1 - Resource allocation method and server - Google Patents

Resource allocation method and server Download PDF

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Publication number
WO2019062822A1
WO2019062822A1 PCT/CN2018/108061 CN2018108061W WO2019062822A1 WO 2019062822 A1 WO2019062822 A1 WO 2019062822A1 CN 2018108061 W CN2018108061 W CN 2018108061W WO 2019062822 A1 WO2019062822 A1 WO 2019062822A1
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Prior art keywords
sbs
subchannel
group
user
allocated
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PCT/CN2018/108061
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French (fr)
Chinese (zh)
Inventor
彭焦阳
叶兵
高莎莎
孙学真
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中兴通讯股份有限公司
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Publication of WO2019062822A1 publication Critical patent/WO2019062822A1/en

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    • HELECTRICITY
    • H04ELECTRIC COMMUNICATION TECHNIQUE
    • H04WWIRELESS COMMUNICATION NETWORKS
    • H04W16/00Network planning, e.g. coverage or traffic planning tools; Network deployment, e.g. resource partitioning or cells structures
    • H04W16/02Resource partitioning among network components, e.g. reuse partitioning
    • H04W16/04Traffic adaptive resource partitioning
    • HELECTRICITY
    • H04ELECTRIC COMMUNICATION TECHNIQUE
    • H04WWIRELESS COMMUNICATION NETWORKS
    • H04W16/00Network planning, e.g. coverage or traffic planning tools; Network deployment, e.g. resource partitioning or cells structures
    • H04W16/14Spectrum sharing arrangements between different networks

Definitions

  • the present disclosure relates to the field of wireless communication technologies, for example, to a resource allocation method and a server.
  • Ultra Dense Heterogeneous Network is one of the hotspots in recent years. It effectively solves the problem of signal coverage under dense user distribution, but it also causes more network interference. Since UDNs share the same spectrum resources as macro cells, they may cause severe co-channel interference when they use the same channel.
  • SBS small cell base station
  • Co-channel interference has a great relationship with the access mode of SBS.
  • closed access mode allows only authorized small cell users (SUEs) to access, and unauthorized users cannot access them.
  • open access mode if the SBS has sufficient resources, the operator allows all users to access the SBS arbitrarily. However, in this access mode, the unlicensed user equipment can use all spectrum resources. Greatly reduce the performance of authorized SUEs within the SBS.
  • hybrid access mode the SBS allows unauthorized users to access, but only uses resources that are not used by authorized users, which not only ensures the communication quality of authorized users, but also improves spectrum utilization, thereby improving system capacity.
  • MBS macro base station
  • MBS macro base station
  • MBS macro base station
  • each MBS has three transmitting antennas, the angle between the transmitting antennas is 120 degrees, and the coverage area of each antenna is a sector of 120 degrees.
  • the MBS has a large transmission power and a large coverage area.
  • the MBS service object is a large number of macro cell users (MPUs) existing in the macro cell.
  • the transmit power of the SBS is extremely small compared to the MBS, the SBS uses an omnidirectional antenna, and the SBS serves the 2-8 authorized SUEs in their respective coverage areas.
  • the number of subchannels is constant, if more subchannels are allocated to the SBS, many SBSs may share the same subchannel, resulting in strong interference within the network. If a small number of subchannels are allocated to each SBS, the spectrum utilization is reduced, and although the interference is avoided, the throughput of the system is lost.
  • the resource allocation strategy in the hybrid access mode is generally combined with the radio technology allocation method, but the allocation method combined with the radio technology has high computational complexity, and the allocation strategy with low computational complexity causes many SBSs to share the same subchannel. As a result, interference within the network is strong.
  • the present disclosure provides a resource allocation method and a server, which are used to solve the problem that the computational complexity of the related technology resource allocation strategy is high, and the allocation strategy with low computational complexity is likely to cause strong co-channel interference between different SBSs.
  • the present disclosure provides a resource allocation method, including:
  • the directed graph grouping a plurality of SBSs in the SBS network according to a set grouping policy to obtain a plurality of SBS groups;
  • a subchannel is assigned to each of the SBS groups.
  • grouping a plurality of SBSs in the SBS network according to a set grouping policy includes:
  • the switched grouping matrix is output.
  • a subchannel is allocated for each of the SBS groups, including:
  • the throughput of the subchannel allocated to the first SBS group is greater than the throughput when the subchannel is allocated to the second SBS group and the number of subchannels that the first SBS group has been allocated is smaller than the first SBS The number of subchannels required by the group is then assigned to the first SBS group.
  • the second SBS group may be a group other than the first SBS group.
  • determining the number of subchannels required for each of the SBS groups includes:
  • the number of subchannels required for each of the SBS groups is determined based on the user rate requirements.
  • calculating the throughput of the subchannels to be allocated in each of the SBS groups includes:
  • each SBS group For each SBS group, calculating a signal to interference plus noise ratio of each SBS in the SBS group for the subchannel to be allocated;
  • the throughput of the SBS team is calculated as:
  • B is the channel bandwidth
  • j is the SBS in the SBS group
  • k is the subchannel assigned to j
  • n is the user connected to j
  • F is the total number of SBSs.
  • ⁇ k,l is a pointer variable
  • the value of the pointer variable is 0 or 1
  • the method further comprises: allocating the subchannels to which the SBS group is assigned to a plurality of users of the SBS service in the SBS group.
  • the subchannels to which each of the SBS groups are assigned are allocated to a plurality of users of the SBS service in the SBS group, including:
  • the subchannels having the largest throughput among the plurality of idle subchannels and the plurality of users are allocated to users corresponding to the subchannels having the highest throughput.
  • the subchannels to which each of the SBS groups are assigned are allocated to a plurality of users of the SBS service in the SBS group, including:
  • Subchannels of the SBS in the SBS group are divided into an authorized subchannel and an unlicensed subchannel according to a preset ratio
  • a subchannel that has the largest throughput among the plurality of first idle subchannels and the authorized user is allocated to the authorized user;
  • the preset user is an unauthorized user, check whether the unlicensed subchannel has a second idle subchannel;
  • the present disclosure further provides a resource allocation server, comprising at least a memory, a processor, wherein the memory stores a computer program, and the steps implemented by the processor when executing the computer program on the memory include: :
  • the directed graph grouping a plurality of SBSs in the SBS network according to a set grouping policy to obtain a plurality of SBS groups;
  • a subchannel is assigned to each of the SBS groups.
  • the step of implementing includes: determining an initial grouping matrix according to the directed graph; The elements in the initial divided group matrix are swapped; when the exit condition of the simulated annealing algorithm is satisfied, the switched grouping matrix is output.
  • the steps implemented include: determining a number of subchannels required by each of the SBS groups; and calculating subchannels to be allocated in each The throughput of the SBS group; if the throughput when the subchannel is allocated to the first SBS group is greater than the throughput when the subchannel is allocated to the second SBS group and the first SBS group has been allocated The number of channels is less than the number of subchannels required by the first SBS group, and the subchannels are allocated to the first SBS group.
  • the steps of implementing include: measuring a user rate requirement of each of the SBS groups; determining, according to the user rate requirements, The number of subchannels required for each of the SBS groups.
  • the step of implementing includes: calculating, for each SBS group, the subchannel to be allocated in the SBS group The signal-to-interference plus noise ratio of each SBS; the minimum value of all signal-to-interference plus noise ratios in the SBS group is used as the signal-to-interference plus noise ratio of the SBS group; according to the signal and interference of the SBS group The noise ratio is calculated, and the throughput of the subchannel to be allocated in the SBS group is calculated.
  • the processor calculates a throughput formula for the SBS group to use:
  • B is the channel bandwidth
  • j is the SBS in the SBS group
  • k is the subchannel assigned to j
  • n is the user connected to j
  • F is the total number of SBSs.
  • ⁇ k,l is a pointer variable
  • the value of the pointer variable is 0 or 1
  • the step further includes: allocating a subchannel to which each SBS group is assigned to an SBS in the SBS group. Serving multiple users.
  • the implemented steps include: viewing the SBS group Whether there is an idle subchannel; in the case where there are a plurality of the free subchannels, a child that maximizes the user rate in a case where the plurality of idle subchannels meet the minimum rate requirement of each user among the plurality of users
  • the channel is assigned to a user corresponding to the subchannel.
  • the achievable steps include: The subchannels of the SBS in the SBS group are divided into an authorized subchannel and an unlicensed subchannel according to a preset ratio; whether the user is an authorized user; and if the user is an authorized user, whether the authorized subchannel is viewed There is a first idle subchannel; if there are a plurality of the first idle subchannels in the authorized subchannel, the minimum of each authorized user is satisfied between the plurality of the first idle subchannels and the authorized user The subchannel that maximizes the user rate in the case of rate demand is allocated to the authorized user; if the preset user is an unauthorized user, whether the unlicensed subchannel exists to have a second idle subchannel; If there are a plurality of the second idle subchannels in the unlicensed subchannel, satisfying the minimum rate requirement of each unauthorized user among the plurality of the second idle subchannels and the unauthorized user Maxim
  • FIG. 1 is a flowchart of a resource allocation method in an embodiment of the present disclosure
  • FIG. 2 is a graph showing an average throughput trend of a macro cell user in a case where an SBS arrangement density is increased under different algorithms according to an embodiment of the present disclosure
  • 3 is an average signal to interference plus noise ratio of a SUE in different SBS deployment densities according to an embodiment of the present disclosure
  • FIG. 5 is a satisfaction degree in a case where a user uses a different algorithm in an embodiment of the present disclosure
  • FIG. 6 is a structural block diagram of a resource allocation server according to an embodiment of the present disclosure.
  • the present disclosure provides a resource allocation method.
  • the present invention will be described below in conjunction with the drawings and embodiments. The embodiments described herein are merely illustrative of the disclosure and are not limiting of the disclosure.
  • FIG. 1 is a flowchart of a resource allocation method according to an embodiment of the present disclosure.
  • Step 110 Obtain a directed graph of the SBS network.
  • Step 120 According to the directed graph, grouping a plurality of SBSs in the SBS network according to the set grouping policy to obtain a plurality of SBS groups.
  • Step 130 assigning a subchannel to each SBS group.
  • the small cell Small cell is a small cell in which an SBS is deployed, that is, one Small cell corresponds to one SBS, and the SBS is grouped, that is, the Small cell is grouped.
  • Each small cell in which the SBS is deployed has a small cell gateway, and is configured to receive a user data measurement report fed back by the SUE, where the content of the user data measurement report includes location information of the SUE, power information sent by the SBS in the small cell to the SUE, and the like.
  • the set of vertices, each element in the collection represents an SBS.
  • E is a set of edges between vertices, also called a potential interference matrix.
  • the value of the element e i,j in the latent interference matrix is 0 or 1.
  • the interference and the interference value exceed the preset interference threshold I th .
  • e i,j 0, it means that there is no interference or interference value between SBS i and SBS j does not exceed the preset interference threshold I th .
  • SBS i and SBS j are respectively different SBSs in the SBS network.
  • W is the weight of the directed graph edge, also called the interference matrix.
  • the elements in W are the greater of the ratio of the average power of the signal transmitted by the user to the plurality of neighboring SBSs to the signal power sent to it by the SBS.
  • the elements in W are the average power of the signal sent to it by the neighboring SBS and the signal sent to it by the self-authorized SBS.
  • the ratio of power if the user receives the average power of a signal sent to it by a neighboring SBS, the elements in W are the average power of the signal sent to it by the neighboring SBS and the signal sent to it by the self-authorized SBS. The ratio of power.
  • the elements in the initial grouping matrix are exchanged according to the simulated annealing algorithm to obtain a better grouping matrix to meet the minimum interference requirement between the SBSs in the group, which is the grouping result of the SBS.
  • the steps of translating the elements in the initial grouping matrix according to the simulated annealing algorithm to obtain a better grouping matrix are as follows:
  • step 110 the initial temperature Tem and the number of iterations IN are set, and Tem and IN can take appropriate large initial values according to actual problems, and the settings of Tem and IN can prevent infinite iteration.
  • V (v il ) F*L
  • v il represents an element in the grouping matrix
  • F represents a matrix of F rows and F columns
  • L represents the number of packets.
  • Step 130 constructing the interference function as Where v il and v jl respectively represent different elements in the grouping matrix.
  • Step 140 Transfer one SBS in any one SBS group to another group under the preset constraint condition, that is, change one element in V.
  • the default constraints are:
  • This formula indicates that the same base station cannot be in a different SBS group.
  • Step 160 Determine whether the preset exit condition is reached. If the exit condition is reached, the packet matrix that is the new solution of the interference function is output, otherwise step 170 is performed; wherein the exit condition is one of the following conditions: the number of iterations has exceeded IN times The change value of the disturbance function lasts ⁇ t' ⁇ 0; the temperature Tem reaches the threshold.
  • step 170 the temperature Tem is decreased, and step 140 is performed.
  • a subchannel is allocated for each SBS group, and the throughput of the group is maximized under the premise of satisfying the user rate requirement in the group, so the orthogonal subchannel is allocated between the groups, and the allocation thereof is performed.
  • the steps for the subchannel are as follows:
  • Step 210 passing the formula Measuring the user rate requirement of SBS Team 1, where For the minimum rate requirement of the user of SBS group 1,
  • Step 220 determining the number of subchannels Y l required by the SBS group 1 according to the user rate requirement, and Where K is the number of all subchannels that can be assigned to the SBS team.
  • Step 230 Calculate a Signal to Interference plus Noise Ratio (SINR) of each SBS of the subchannel k in the SBS group 1, wherein the SINR of the subchannel k on the SBS j in the SBS group 1 is among them, with Representing the transmit power of MBS and SBS j on subchannel k, respectively. with Representing the channel gains of MBS and SBS j to user n on subchannel k, respectively, ⁇ 2 is the noise power.
  • SINR Signal to Interference plus Noise Ratio
  • Step 240 The minimum SINR value of the SINR of each SBS in the SBS group 1 calculated by the subchannel k calculated in step 230 is taken as the SINR of the SBS group 1.
  • Step 250 according to the SINR of the SBS group 1, under the premise that the minimum rate requirement of the user is met, the throughput in the group is maximized, that is, When the throughput when subchannel k is allocated to SBS group 1 is greater than the throughput when subchannel k is allocated to other SBS groups and the number of subchannels that SBS group 1 has allocated is smaller than the number of subchannels required by SBS group 1,
  • step 260 it is determined whether all subchannels are allocated. When all subchannels are allocated, the subchannel allocation matrix of each group is output. When there are still subchannels unallocated, step 250 is repeated until all subchannels are allocated.
  • the throughput within the group in step 250 meets the following constraints in the calculation:
  • the SBS is grouped according to the interference between the SBSs, and the sub-channels are allocated to the SBS group according to the actual needs of the SBS group, which not only reduces the computational complexity, but also minimizes the SBS in the case of ensuring the user rate in the group.
  • the interference between the two technologies solves the problem that the computational complexity of the resource allocation strategy in the hybrid access mode is high, and the allocation strategy with low computational complexity is likely to cause strong co-channel interference between different SBSs.
  • the method provided by this embodiment further includes allocating subchannels allocated to the group to a plurality of users of the SBS in the group to ensure that the user can perform data communication through the subchannels allocated to the user.
  • the method for allocating a subchannel to a user may be: first, whether there is an idle subchannel in the SBS group; and in the case where there is an idle subchannel, the channel condition between the idle subchannel and the user is the best.
  • the subchannels are assigned to users of the SBS within the group.
  • the channel condition is SINR, and the smaller the SINR value between the subchannel and the user, the better the channel condition between the subchannel and the user.
  • the subchannels allocated to the SBS group can be divided into authorized groups according to a preset ratio, in order to ensure the communication quality of the authorized users and the communication requirements of the unlicensed users.
  • the subchannel and the unlicensed subchannel, wherein the preset ratio can be adjusted according to the real-time network environment, and the default may be 1:3.
  • Step 310 Check whether the first idle subchannel exists in the authorized subchannel of the SBS corresponding to the authorized user, and if there is the first idle subchannel, directly allocate the subchannel with the best channel condition among the authorized subchannel and the authorized user to the authorized User, and step 350 is performed, if there is no first idle subchannel, step 320 is performed.
  • Step 320 Check whether there is an idle subchannel in the MBS. If there is an idle subchannel, select the subchannel with the best user channel condition in the idle subchannel of the MBS, assign it to the authorized user, and perform step 350 if there is no free subchannel. Then, step 330 is performed.
  • Step 330 Check whether there is a second idle subchannel in the unlicensed subchannel of the SBS corresponding to the authorized user, and if there is a second idle subchannel, directly allocate the subchannel with the best channel condition among the unlicensed subchannel and the authorized user. To the authorized user, and step 350 is performed, if there is no second idle subchannel, step 340 is performed.
  • step 340 the authorized user is placed in the waiting queue, and when there are available subchannels, the subchannel is allocated to the user in the forefront of the waiting queue.
  • Step 350 Check the communication rate of the authorized user who has been assigned the subchannel, determine whether the communication rate meets the minimum rate requirement, and if the communication rate meets the minimum rate requirement, do not allocate a new subchannel to the authorized user, if the communication If the rate does not meet the minimum rate requirement, step 310 is re-executed to allocate the subchannel to the authorized user.
  • step 310 is re-executed to allocate the subchannel to the authorized user.
  • the execution starts directly from step 320.
  • an unauthorized user can use an unlicensed subchannel under any SBS, and when an authorized user leaves the SBS authorized for it, it becomes an unauthorized user. .
  • the authorized sub-channel and the unlicensed user check whether the sub-channel is idle, if the idle sub-channel is allocated to the user with poor communication quality, it is still regarded as no idle sub-channel.
  • FIG. 2 is a graph showing an average throughput trend of a macro cell user in a case where different SBS layout densities are increased
  • FIG. 3 is an average signal to interference plus noise ratio of a SUE in a different SBS (ie, Small cell) deployment density.
  • Figure 4 shows user fairness under different algorithms
  • Figure 5 shows satisfaction when users use different algorithms.
  • the algorithms used in the above figures are respectively: the resource allocation method provided by the embodiment of the present disclosure in the closed mode (corresponding to the polyline with "diamond” in FIGS. 2 to 5), and the implementation of the present disclosure in the mixed mode.
  • the resource allocation method provided by the example (corresponding to the polyline with "asterisk" in Fig. 2 to Fig.
  • Cluster-based Resource Allocation based on the Hopfield field network (Hopfield) (corresponding to the polyline with "square” in Figures 2 to 5), the intra-group orthogonal grouping algorithm (corresponding to the polyline with "triangle” in Figures 2 to 5) and the cluster-based heuristic based on Hopfield network Heuristic Cluster-based Femto-Femto Interference minimized Subchannels Allocation Algorithm (HCFM) (corresponding to a broken line with "circle” in FIGS. 2 to 5).
  • HCFM Cluster-based Femto-Femto Interference minimized Subchannels Allocation Algorithm
  • FIG. 2 is a graph showing the average throughput of macro cell users in the case where the SBS arrangement density is increased by different algorithms.
  • the SBS layout density is increased, the average throughput of the macro cell user is gradually reduced as the SBS density increases.
  • the reason for this result is that as the SBS arrangement density increases, the number of SBSs around the MUE increases, causing the MUE to suffer from cross-layer interference caused by the SBS layer being larger than when the number of SBSs is small, so the MUE The quality of communication is also reduced.
  • the method provided by the embodiment of the present disclosure uses a user's throughput to be at a higher level than other methods. Since the MUE acts as an unauthorized user, the network can be switched to proximity when subjected to severe interference. The communication quality is better on the SBS, which effectively guarantees the communication quality of the MUE.
  • Figure 3 shows the average signal to interference and noise ratio of SUEs at different SBS deployment densities.
  • the resource allocation method provided by the embodiments of the present disclosure can effectively suppress SBS peer interference in a closed mode, and obtain a higher signal to interference and noise ratio, because the above method effectively prevents resource waste, thereby Improve the quality of user communication.
  • the resource allocation method SBS provided by the embodiment of the present disclosure improves the user communication quality to a greater extent, and the cross-layer interference is more suppressed in the hybrid access mode, so the SUE letter The dry noise ratio is at a higher level.
  • Figure 4 shows user fairness under different algorithms. It can be seen from FIG. 4 that the user fairness of the resource allocation method provided by the embodiment of the present disclosure is the highest in the hybrid access mode, and the user fairness of the resource allocation method provided by the embodiment of the present disclosure is low in the closed mode. The user fairness of the resource allocation method provided by the embodiment of the present disclosure is adopted in the hybrid mode access mode. Since the resource allocation method provided by the embodiment of the present disclosure applies the simulated annealing algorithm to the grouping, the grouping problem is solved more efficiently, and the grouping result is obtained through multiple iterations, so that the ultra-dense network is more effectively suppressed. The same layer of interference also makes the degree of interference between users less different, making the user fairness at a higher level.
  • the resource allocation method is used to suppress cross-layer interference to a greater extent, so that the communication quality of the MUE is greatly improved, and thus the fairness is improved to a greater extent.
  • other comparison algorithms do not consider user fairness too much, and the number of SBSs in each group differs greatly in other grouping schemes, resulting in a large difference in the number of users in different groups, ultimately resulting in The fairness of users in different groups is quite different, and the fairness of users is reduced.
  • Figure 5 shows the user's satisfaction with different algorithms.
  • the user satisfaction of the resource allocation method proposed by the embodiment of the present disclosure is higher. Due to the effective suppression of the same layer interference and cross-layer interference existing in the ultra-dense network, the spectrum resources are utilized more efficiently, and the communication rate obtained by the user is higher, thereby obtaining higher satisfaction.
  • the number of SBSs in each group of the comparison algorithm is quite different, the number of subchannels obtained by different groups is quite different, which results in different numbers of channels that can be multiplexed in the group, and some users cannot allocate enough channels. This leads to poor communication quality and low user satisfaction.
  • the number of SBSs in the closed access mode is relatively consistent, and the channels that can be allocated are not much different, so that the user communication quality is good and the satisfaction is high.
  • the above resource allocation method further adopts a hybrid access mode based on the closed access mode, and better utilizes the spectrum resources, and the user communication quality is further improved, thereby further satisfying the user satisfaction.
  • an embodiment of the present disclosure provides a resource allocation server
  • FIG. 6 is a structural block diagram of a resource allocation server according to an embodiment of the present disclosure.
  • the server includes at least a memory 610 and a processor. 620, a computer program is stored on the memory 610, and the processor 620 implements the steps 110 to 130 in the execution of the computer program on the memory, which is the same as the steps of the embodiment of the present disclosure, and details are not described herein again.
  • the resource allocation server provided by the embodiment of the present disclosure may be disposed on the MBS as an actual device that allocates a subchannel for the SBS.
  • the Small cell is a small cell in which an SBS is deployed, that is, one Small cell corresponds to one SBS, and the SBS is grouped to group the Small cells.
  • Each small cell in which the SBS is deployed has a small cell gateway, and is configured to receive a user data measurement report fed back by the SUE, where the content of the user data measurement report includes location information of the SUE, power information sent by the SBS in the small cell to the SUE, and the like.
  • Each element in the collection represents an SBS.
  • E is a set of edges between vertices, also called a potential interference matrix.
  • the value of the element e i,j in the latent interference matrix is 0 or 1.
  • the interference and the interference value exceed the preset interference threshold I th .
  • e i,j 0, it means that there is no interference or interference value between SBS i and SBS j does not exceed the preset interference threshold I th .
  • SBS i and SBS j are respectively different SBSs in the SBS network.
  • W is the weight of the directed graph edge, also called the interference matrix.
  • the elements in W are the average power of the signal sent to it by the neighboring SBS and the signal sent to it by the self-authorized SBS.
  • the ratio of power if the user receives the average power of a signal sent to it by a neighboring SBS, the elements in W are the average power of the signal sent to it by the neighboring SBS and the signal sent to it by the self-authorized SBS. The ratio of power.
  • the elements in the initial grouping matrix are exchanged according to the simulated annealing algorithm to obtain a better grouping matrix to meet the minimum interference requirement between the SBSs in the group, which is the grouping result of the SBS.
  • the step of the processor operating the simulated annealing algorithm in the computer program to swap the elements in the initial grouping matrix to obtain a better grouping matrix is the same as steps 110 to 170 in the disclosed embodiment. I will not repeat them here.
  • a subchannel is allocated for each SBS group, and the throughput of the group is maximized on the premise of satisfying the user rate requirement in the group, so the orthogonal subchannels are allocated between the groups.
  • the processor allocates a sub-channel to each of the SBS groups, the steps are the same as the steps 210 to 260 in the embodiment of the present disclosure, and details are not described herein again.
  • the SBS is grouped according to the interference between the SBSs, and the sub-channels are allocated to the SBS group according to the actual needs of the SBS group, which not only reduces the computational complexity, but also minimizes the SBS in the case of ensuring the user rate in the group.
  • the inter-channel interference solves the problem that the computational complexity of the resource allocation strategy in the hybrid access mode is high in the related art, and the co-channel interference in the allocation strategy SBS with low computational complexity is strong.
  • the processor of the server in the embodiment further implements the following steps: when the computer program on the memory is executed, the subchannel allocated to the SBS group is allocated to multiple users of the SBS in the group to ensure that the user can Data communication is performed by subchannels assigned to itself.
  • the processor implements the following steps: first, whether there is an idle subchannel in the SBS group; in the case where there is an idle subchannel The subchannels with the best channel conditions among the idle subchannels and the users are allocated to the users of the SBS in the group.
  • the channel condition is SINR, and the smaller the SINR value between the subchannel and the user, the better the channel condition between the subchannel and the user.
  • the subchannels allocated to the SBS group can be divided into authorized groups according to a preset ratio, in order to ensure the communication quality of the authorized users and the communication requirements of the unlicensed users.
  • the subchannel and the unlicensed subchannel, wherein the preset ratio can be adjusted according to the real-time network environment, and the default may be 1:3.
  • the processor performs sub-channel allocation to the authorized user, and the implementation steps are the same as steps 310 to 350 in the embodiment of the present disclosure, and details are not described herein again.
  • execution is directly started from step 320.
  • an unauthorized user can use an unlicensed subchannel under any SBS, and when an authorized user leaves the SBS authorized for it, it becomes an unauthorized user. .
  • the authorized sub-channel and the unlicensed user check whether the sub-channel is idle, if the idle sub-channel is allocated to the user with poor communication quality, it is still regarded as no idle sub-channel.

Abstract

Disclosed is a resource allocation method. The method comprises: acquiring a directed graph of a small cell base station (SBS) network; grouping a plurality of SBSs in the SBS network according to a set grouping strategy and the directed graph to obtain a plurality of SBS groups; and allocating a sub-channel to each SBS group. Also disclosed is a resource allocation server.

Description

资源分配方法及服务器Resource allocation method and server
本申请要求在2017年9月27日提交中国专利局、申请号为201710890195.5的中国专利申请的优先权,该申请的全部内容通过引用结合在本申请中。The present application claims the priority of the Chinese Patent Application, filed on Sep. 27, 2017, the priority of
技术领域Technical field
本公开涉及无线通信技术领域,例如涉及一种资源分配方法及服务器。The present disclosure relates to the field of wireless communication technologies, for example, to a resource allocation method and a server.
背景技术Background technique
超密集异构网络(Ultra Dense Heterogeneous Network,UDN)是近年来研究的热点之一,它有效地解决了用户密集分布情况下信号覆盖的问题,但是同时也造成了更多的网络干扰。由于UDN与宏蜂窝(Macrocell)共用相同的频谱资源,因此当它们使用相同的信道时,可能带来严重的共信道干扰。同时,由于超密集网络的小小区基站(Small cell Base Station,SBS)通常是用户根据自身需求安装的,通信网络运营商难以获得准确的基站位置,所以很难进行有效的网络规划来解决复杂的干扰问题。Ultra Dense Heterogeneous Network (UDN) is one of the hotspots in recent years. It effectively solves the problem of signal coverage under dense user distribution, but it also causes more network interference. Since UDNs share the same spectrum resources as macro cells, they may cause severe co-channel interference when they use the same channel. At the same time, since the small cell base station (SBS) of the ultra-dense network is usually installed by the user according to his own needs, it is difficult for the communication network operator to obtain an accurate base station location, so it is difficult to carry out effective network planning to solve the complicated Interference problem.
共信道干扰与SBS的接入方式有很大的关系,目前存在着三种SBS接入通信核心网的方式:封闭式接入方式、开放式接入方式和混合式接入方式。封闭式接入方式只允许授权的小小区用户(Small cell User,SUE)接入,非授权的用户不能接入。在开放接入方式下,如果SBS有足够的资源,运营商允许所有的用户可以任意的接入该SBS,但是在这种接入方式下,非授权用户设备可以使用所有的频谱资源,会极大降低SBS内授权SUE的性能。在混合接入方式下,SBS允许非授权用户接入,但仅能够使用授权用户没有使用的资源,既保证了授权用户的通信质量,又同时也提升了频谱利用率,从而提升了系统容量。Co-channel interference has a great relationship with the access mode of SBS. At present, there are three ways of SBS accessing the communication core network: closed access mode, open access mode and hybrid access mode. The closed access mode allows only authorized small cell users (SUEs) to access, and unauthorized users cannot access them. In the open access mode, if the SBS has sufficient resources, the operator allows all users to access the SBS arbitrarily. However, in this access mode, the unlicensed user equipment can use all spectrum resources. Greatly reduce the performance of authorized SUEs within the SBS. In the hybrid access mode, the SBS allows unauthorized users to access, but only uses resources that are not used by authorized users, which not only ensures the communication quality of authorized users, but also improves spectrum utilization, thereby improving system capacity.
超密集网络混合接入方式场景中存在一个宏基站(Macrocell Base Station,MBS),在MBS的覆盖范围内有多个小小区(Small cell)同时处于运行状态。 为使得MBS对其覆盖区域无死角覆盖,采用蜂窝网的配置模式,即每个MBS有三根发射天线,发射天线之间的角度为120度,每根天线的覆盖区域为一个120度的扇区。MBS的发射功率较大,且覆盖范围较大,MBS的服务对象为宏小区内存在的大量宏小区用户(Macro User,MUE)。SBS的发射功率相对于MBS是极小的,SBS采用全向天线,SBS的服务对象为各自覆盖范围内的2-8个授权SUE。在子信道数目一定的情况下,如果将更多的子信道分配给SBS,则可能会导致很多SBS共用相同的子信道,从而导致网络内的干扰强烈。若给每个SBS分配极少的子信道,则又会导致频谱利用率降低,虽然避免了干扰,但是却损失系统的吞吐量。In the hyper-dense network hybrid access mode, there is a macro base station (MBS). In the coverage area of the MBS, multiple small cells (Small cells) are in the running state at the same time. In order to make the MBS have no dead angle coverage for its coverage area, the configuration mode of the cellular network is adopted, that is, each MBS has three transmitting antennas, the angle between the transmitting antennas is 120 degrees, and the coverage area of each antenna is a sector of 120 degrees. . The MBS has a large transmission power and a large coverage area. The MBS service object is a large number of macro cell users (MPUs) existing in the macro cell. The transmit power of the SBS is extremely small compared to the MBS, the SBS uses an omnidirectional antenna, and the SBS serves the 2-8 authorized SUEs in their respective coverage areas. In the case where the number of subchannels is constant, if more subchannels are allocated to the SBS, many SBSs may share the same subchannel, resulting in strong interference within the network. If a small number of subchannels are allocated to each SBS, the spectrum utilization is reduced, and although the interference is avoided, the throughput of the system is lost.
相关技术中混合接入方式下的资源分配策略常用结合无线电技术的分配方法,但是结合无线电技术的分配方法计算复杂度高,而计算复杂度低的分配策略会导致很多SBS共用相同的子信道,从而导致网络内的干扰强烈。In the related art, the resource allocation strategy in the hybrid access mode is generally combined with the radio technology allocation method, but the allocation method combined with the radio technology has high computational complexity, and the allocation strategy with low computational complexity causes many SBSs to share the same subchannel. As a result, interference within the network is strong.
发明内容Summary of the invention
本公开提供一种资源分配方法及服务器,用以解决相关技术资源分配策略的计算复杂度高,而计算复杂度低的分配策略易造成不同SBS之间的共信道干扰强烈的问题。The present disclosure provides a resource allocation method and a server, which are used to solve the problem that the computational complexity of the related technology resource allocation strategy is high, and the allocation strategy with low computational complexity is likely to cause strong co-channel interference between different SBSs.
在一实施例中,本公开提供一种资源分配方法,包括:In an embodiment, the present disclosure provides a resource allocation method, including:
获取小小区基站SBS网络的有向图;Obtaining a directed graph of a small cell base station SBS network;
根据所述有向图,按照设定的分组策略,对所述SBS网络中的多个SBS进行分组,得到多个SBS小组;According to the directed graph, grouping a plurality of SBSs in the SBS network according to a set grouping policy to obtain a plurality of SBS groups;
为每个所述SBS小组分配子信道。A subchannel is assigned to each of the SBS groups.
在一实施例中,按照设定的分组策略,对所述SBS网络中的多个SBS进行分组,包括:In an embodiment, grouping a plurality of SBSs in the SBS network according to a set grouping policy includes:
根据所述有向图,确定初始的分组矩阵;Determining an initial grouping matrix according to the directed graph;
根据模拟退火算法对所述初始的分组矩阵中的元素进行调换;Interchanging elements in the initial grouping matrix according to a simulated annealing algorithm;
当满足所述模拟退火算法的退出条件时,输出调换后的分组矩阵。When the exit condition of the simulated annealing algorithm is satisfied, the switched grouping matrix is output.
在一实施例中,为每个所述SBS小组分配子信道,包括:In an embodiment, a subchannel is allocated for each of the SBS groups, including:
确定每个所述SBS小组所需的子信道数;Determining the number of subchannels required for each of the SBS groups;
计算待分配的子信道在每个所述SBS小组的吞吐量;Calculating the throughput of the subchannel to be allocated in each of the SBS groups;
如果所述子信道分配至第一SBS小组时的吞吐量大于所述子信道分配至第二SBS小组时的吞吐量且所述第一SBS小组已被分配的子信道数小于所述第一SBS小组所需的子信道数,则将所述子信道分配至所述第一SBS小组。If the throughput of the subchannel allocated to the first SBS group is greater than the throughput when the subchannel is allocated to the second SBS group and the number of subchannels that the first SBS group has been allocated is smaller than the first SBS The number of subchannels required by the group is then assigned to the first SBS group.
在一实施例中,第二SBS小组可以为除第一SBS小组之外的其他小组。In an embodiment, the second SBS group may be a group other than the first SBS group.
在一实施例中,确定每个所述SBS小组所需的子信道数,包括:In an embodiment, determining the number of subchannels required for each of the SBS groups includes:
测算每个所述SBS小组的用户速率需求;Measuring user rate requirements for each of the SBS teams;
根据所述用户速率需求,确定每个所述SBS小组所需的子信道数。The number of subchannels required for each of the SBS groups is determined based on the user rate requirements.
在一实施例中,计算待分配的子信道在每个所述SBS小组的吞吐量,包括:In an embodiment, calculating the throughput of the subchannels to be allocated in each of the SBS groups includes:
对于每个SBS小组,计算待分配的子信道在所述SBS小组中每个SBS的信号与干扰加噪声比;For each SBS group, calculating a signal to interference plus noise ratio of each SBS in the SBS group for the subchannel to be allocated;
将所述SBS小组中所有信号与干扰加噪声比的最小值作为所述SBS小组的信号与干扰加噪声比;Using the minimum value of all signal to interference plus noise ratios in the SBS group as the signal to interference plus noise ratio of the SBS group;
根据所述SBS小组的信号与干扰加噪声比,计算待分配的子信道在所述SBS小组的吞吐量。Calculating the throughput of the subchannel to be allocated in the SBS group according to the signal to interference plus noise ratio of the SBS group.
在一实施例中,所述SBS小组的吞吐量的计算公式为:In an embodiment, the throughput of the SBS team is calculated as:
Figure PCTCN2018108061-appb-000001
Figure PCTCN2018108061-appb-000001
其中,B为信道带宽,j为所述SBS小组内的SBS,k为分配给j的子信道,n为连接在j上的用户,F为SBS的总数,
Figure PCTCN2018108061-appb-000002
为所述SBS小组的信号与干扰加噪声比,λ k,l为指针变量,所述指针变量的值为0或1,当λ k,l=1时,表示将子信道k分配至所述第一SBS小组,当λ k,l=0时,表示不将子信道k分配至所述第一SBS小组。
Where B is the channel bandwidth, j is the SBS in the SBS group, k is the subchannel assigned to j, n is the user connected to j, and F is the total number of SBSs.
Figure PCTCN2018108061-appb-000002
For the signal-to-interference plus noise ratio of the SBS group, λ k,l is a pointer variable, the value of the pointer variable is 0 or 1, and when λ k,l =1, indicating that the subchannel k is allocated to the The first SBS group, when λ k, l =0, indicates that subchannel k is not allocated to the first SBS group.
在一实施例中,在为每个所述SBS小组分配子信道之后,还包括:将每个 所述SBS小组分配到的子信道分配至所述SBS小组内的SBS服务的多个用户上。In an embodiment, after allocating the subchannels for each of the SBS groups, the method further comprises: allocating the subchannels to which the SBS group is assigned to a plurality of users of the SBS service in the SBS group.
在一实施例中,将每个所述SBS小组分配到的子信道分配至所述SBS小组内的SBS服务的多个用户上,包括:In an embodiment, the subchannels to which each of the SBS groups are assigned are allocated to a plurality of users of the SBS service in the SBS group, including:
查看所述SBS小组内是否存在空闲子信道;Checking whether there are free subchannels in the SBS group;
在存在多个所述空闲子信道的情况下,将多个所述空闲子信道中与所述多个用户间吞吐量最大的子信道分配至与所述吞吐量最大的子信道对应的用户。When there are a plurality of the idle subchannels, the subchannels having the largest throughput among the plurality of idle subchannels and the plurality of users are allocated to users corresponding to the subchannels having the highest throughput.
在一实施例中,将每个所述SBS小组分配到的子信道分配至所述SBS小组内的SBS服务的多个用户上,包括:In an embodiment, the subchannels to which each of the SBS groups are assigned are allocated to a plurality of users of the SBS service in the SBS group, including:
将所述SBS小组内的SBS的子信道按预设比例分为授权子信道和非授权子信道;Subchannels of the SBS in the SBS group are divided into an authorized subchannel and an unlicensed subchannel according to a preset ratio;
判断所述用户是否为授权用户;Determining whether the user is an authorized user;
在所述用户为授权用户的情况下,查看所述授权子信道是否存在第一空闲子信道;If the user is an authorized user, check whether the authorized subchannel has a first idle subchannel;
在所述授权子信道存在多个所述第一空闲子信道的情况下,将多个所述第一空闲子信道中与所述授权用户间吞吐量最大的子信道分配至所述授权用户;And if a plurality of the first idle subchannels exist in the authorized subchannel, a subchannel that has the largest throughput among the plurality of first idle subchannels and the authorized user is allocated to the authorized user;
在所述预设用户为非授权用户的情况下,查看所述非授权子信道是否存在第二空闲子信道;If the preset user is an unauthorized user, check whether the unlicensed subchannel has a second idle subchannel;
在所述非授权子信道存在多个所述第二空闲子信道的情况下,将多个所述第二空闲子信道中与所述非授权用户间吞吐量最大的子信道分配至所述非授权用户。And assigning, in the non-authorized subchannel, a plurality of the second idle subchannels, the subchannels that have the largest throughput among the plurality of second idle subchannels and the unlicensed users to the non Authorized user.
在一实施例中,本公开还提供一种资源分配服务器,至少包括存储器、处理器,所述存储器上存储有计算机程序,所述处理器在执行所述存储器上的计算机程序时实现的步骤包括:In an embodiment, the present disclosure further provides a resource allocation server, comprising at least a memory, a processor, wherein the memory stores a computer program, and the steps implemented by the processor when executing the computer program on the memory include: :
获取小小区基站SBS网络的有向图;Obtaining a directed graph of a small cell base station SBS network;
根据所述有向图,按照设定的分组策略,对所述SBS网络中的多个SBS进行分组,得到多个SBS小组;According to the directed graph, grouping a plurality of SBSs in the SBS network according to a set grouping policy to obtain a plurality of SBS groups;
为每个所述SBS小组分配子信道。A subchannel is assigned to each of the SBS groups.
在一实施例中,所述处理器在对所述SBS网络中的多个SBS进行分组时,实现的步骤包括:根据所述有向图,确定初始的分组矩阵;根据模拟退火算法对所述初始分的组矩阵中的元素进行调换;当满足所述模拟退火算法的退出条件时,输出调换后的分组矩阵。In an embodiment, when the processor groups the multiple SBSs in the SBS network, the step of implementing includes: determining an initial grouping matrix according to the directed graph; The elements in the initial divided group matrix are swapped; when the exit condition of the simulated annealing algorithm is satisfied, the switched grouping matrix is output.
在一实施例中,所述处理器为每个所述SBS小组分配子信道时,实现的步骤包括:确定每个所述SBS小组所需的子信道数;计算待分配的子信道在每个所述SBS小组的吞吐量;如果所述子信道分配至第一SBS小组时的吞吐量大于所述子信道分配至第二SBS小组时的吞吐量且所述第一SBS小组已被分配的子信道数小于所述第一SBS小组所需的子信道数,则将所述子信道分配至所述第一SBS小组。In an embodiment, when the processor allocates a subchannel for each of the SBS groups, the steps implemented include: determining a number of subchannels required by each of the SBS groups; and calculating subchannels to be allocated in each The throughput of the SBS group; if the throughput when the subchannel is allocated to the first SBS group is greater than the throughput when the subchannel is allocated to the second SBS group and the first SBS group has been allocated The number of channels is less than the number of subchannels required by the first SBS group, and the subchannels are allocated to the first SBS group.
在一实施例中,所述处理器确定每个所述SBS小组所需的子信道数时,实现的步骤包括:测算每个所述SBS小组的用户速率需求;根据所述用户速率需求,确定每个所述SBS小组所需的子信道数。In an embodiment, when the processor determines the number of subchannels required by each of the SBS groups, the steps of implementing include: measuring a user rate requirement of each of the SBS groups; determining, according to the user rate requirements, The number of subchannels required for each of the SBS groups.
在一实施例中,所述处理器计算待分配的子信道在每个所述SBS小组的吞吐量时,实现的步骤包括:对于每个SBS小组,计算待分配的子信道在所述SBS小组中每个SBS的信号与干扰加噪声比;将所述SBS小组中所有信号与干扰加噪声比的最小值作为所述SBS小组的信号与干扰加噪声比;根据所述SBS小组的信号与干扰加噪声比,计算待分配的子信道在所述SBS小组的吞吐量。In an embodiment, when the processor calculates the throughput of the subchannel to be allocated in each of the SBS groups, the step of implementing includes: calculating, for each SBS group, the subchannel to be allocated in the SBS group The signal-to-interference plus noise ratio of each SBS; the minimum value of all signal-to-interference plus noise ratios in the SBS group is used as the signal-to-interference plus noise ratio of the SBS group; according to the signal and interference of the SBS group The noise ratio is calculated, and the throughput of the subchannel to be allocated in the SBS group is calculated.
在一实施例中,所述处理器计算所述SBS小组的吞吐量使用的计算公式为:In an embodiment, the processor calculates a throughput formula for the SBS group to use:
Figure PCTCN2018108061-appb-000003
Figure PCTCN2018108061-appb-000003
其中,B为信道带宽,j为所述SBS小组内的SBS,k为分配给j的子信道,n为连接在j上的用户,F为SBS的总数,
Figure PCTCN2018108061-appb-000004
为所述SBS小组的信号与干扰加噪声比,λ k,l为指针变量,所述指针变量的值为0或1,当λ k,l=1时,表示将子信道k分配至所述第一SBS小组,当λ k,l=0时,表示不将子信道k分配至所述第二SBS小组。
Where B is the channel bandwidth, j is the SBS in the SBS group, k is the subchannel assigned to j, n is the user connected to j, and F is the total number of SBSs.
Figure PCTCN2018108061-appb-000004
For the signal-to-interference plus noise ratio of the SBS group, λ k,l is a pointer variable, the value of the pointer variable is 0 or 1, and when λ k,l =1, indicating that the subchannel k is allocated to the The first SBS group, when λ k, l =0, indicates that subchannel k is not allocated to the second SBS group.
在一实施例中,所述处理器在为每个所述SBS小组分配子信道之后,实现的步骤还包括:将每个所述SBS小组分配到的子信道分配至所述SBS小组内的SBS服务的多个用户上。In an embodiment, after the processor allocates a subchannel for each of the SBS groups, the step further includes: allocating a subchannel to which each SBS group is assigned to an SBS in the SBS group. Serving multiple users.
在一实施例中,所述处理器将每个所述SBS小组分配到的子信道分配至所述SBS小组内的SBS服务的多个用户上时,实现的步骤包括:查看所述SBS小组内是否存在空闲子信道;在存在多个所述空闲子信道的情况下,将多个所述空闲子信道中与所述多个用户间满足每个用户最低速率需求情况下最大化用户速率的子信道分配至与所述子信道对应的用户。In an embodiment, when the processor allocates a subchannel to which each SBS group is assigned to multiple users of the SBS service in the SBS group, the implemented steps include: viewing the SBS group Whether there is an idle subchannel; in the case where there are a plurality of the free subchannels, a child that maximizes the user rate in a case where the plurality of idle subchannels meet the minimum rate requirement of each user among the plurality of users The channel is assigned to a user corresponding to the subchannel.
在一实施例中,所述处理器在将每个所述SBS小组分配到的子信道分配至所述SBS小组内的SBS服务的多个用户上时,还可以实现的步骤包括:将所述SBS小组内的SBS的子信道按预设比例分为授权子信道和非授权子信道;判断所述用户是否为授权用户;在所述用户为授权用户的情况下,查看所述授权子信道是否存在第一空闲子信道;在所述授权子信道存在多个所述第一空闲子信道的情况下,将多个所述第一空闲子信道中与所述授权用户间满足每个授权用户最低速率需求情况下最大化用户速率的子信道分配至所述授权用户;在所述预设用户为非授权用户的情况下,查看所述非授权子信道是否存在第二空闲子信道;在所述非授权子信道存在多个所述第二空闲子信道的情况下,将多个所述第二空闲子信道中与所述非授权用户间满足每个非授权用户最低速率需求情况下最大化用户速率的子信道分配至所述非授权用户。In an embodiment, when the processor allocates a subchannel to which each SBS group is assigned to multiple users of the SBS service in the SBS group, the achievable steps include: The subchannels of the SBS in the SBS group are divided into an authorized subchannel and an unlicensed subchannel according to a preset ratio; whether the user is an authorized user; and if the user is an authorized user, whether the authorized subchannel is viewed There is a first idle subchannel; if there are a plurality of the first idle subchannels in the authorized subchannel, the minimum of each authorized user is satisfied between the plurality of the first idle subchannels and the authorized user The subchannel that maximizes the user rate in the case of rate demand is allocated to the authorized user; if the preset user is an unauthorized user, whether the unlicensed subchannel exists to have a second idle subchannel; If there are a plurality of the second idle subchannels in the unlicensed subchannel, satisfying the minimum rate requirement of each unauthorized user among the plurality of the second idle subchannels and the unauthorized user Maximizing the user rate of the subchannel allocated to the non-authorized user.
附图说明DRAWINGS
图1是本公开一实施例中资源分配方法的流程图;1 is a flowchart of a resource allocation method in an embodiment of the present disclosure;
图2是本公开一实施例中不同算法下SBS布置密度增大的情况下宏小区用户的平均吞吐量走势图;2 is a graph showing an average throughput trend of a macro cell user in a case where an SBS arrangement density is increased under different algorithms according to an embodiment of the present disclosure;
图3是本公开一实施例中SUE在不同SBS部署密度情况下的平均信号与干扰加噪声比;3 is an average signal to interference plus noise ratio of a SUE in different SBS deployment densities according to an embodiment of the present disclosure;
图4是本公开一实施例中不同算法下用户公平性;4 is a user fairness under different algorithms in an embodiment of the present disclosure;
图5是本公开一实施例中用户使用不同算法的情况下的满意度;FIG. 5 is a satisfaction degree in a case where a user uses a different algorithm in an embodiment of the present disclosure; FIG.
图6是本公开一实施例中资源分配服务器的结构框图。FIG. 6 is a structural block diagram of a resource allocation server according to an embodiment of the present disclosure.
具体实施方式Detailed ways
为了解决相关技术中混合接入方式下资源分配策略的计算复杂度高,而计算复杂度低的分配策略易造成不同SBS之间的共信道干扰强烈的问题,本公开提供了一种资源分配方法及服务器,以下结合附图以及实施例,对本公开进行说明。此处所描述的实施例仅仅用以解释本公开,并不限定本公开。In order to solve the problem that the resource allocation strategy in the hybrid access mode has high computational complexity and the computational complexity is low, the co-channel interference between different SBSs is strong, and the present disclosure provides a resource allocation method. The present invention will be described below in conjunction with the drawings and embodiments. The embodiments described herein are merely illustrative of the disclosure and are not limiting of the disclosure.
本公开的一实施例提供了一种资源分配方法,图1为本公开一实施例中资源分配方法的流程图,如图1所示,包括:An embodiment of the present disclosure provides a resource allocation method. FIG. 1 is a flowchart of a resource allocation method according to an embodiment of the present disclosure.
步骤110,获取SBS网络的有向图。Step 110: Obtain a directed graph of the SBS network.
步骤120,根据该有向图,按照设定的分组策略,对SBS网络中的多个SBS进行分组,得到多个SBS小组。Step 120: According to the directed graph, grouping a plurality of SBSs in the SBS network according to the set grouping policy to obtain a plurality of SBS groups.
步骤130,为每个SBS小组分配子信道。 Step 130, assigning a subchannel to each SBS group.
在本实施例中,小小区Small cell即是部署有SBS的小小区,即一个Small cell对应一个SBS,对SBS进行分组即对Small cell进行分组。每个部署有SBS的小小区均有一个Small cell网关,设置为接收SUE反馈的用户数据测量报告,该用户数据测量报告的内容包括SUE的位置信息、小小区内SBS发送至SUE的功率信息等。在步骤110中,首先根据图论获取SBS网络的有向图G,G=[T,E,W],其中,T={t 1,t 2,...,t F}为网络中所有的顶点集合,集合里面的每个元素均代表一个SBS。E为顶点间的边的集合,也称为潜在干扰矩阵,潜在干扰矩阵中元素e i,j的值为0或1,当e i,j=1时,表示SBS i和SBS j之间存在干扰且干扰值超过预设的干扰阈值I th,当e i,j=0时,表示SBS i和SBS j之间不存在干扰或干扰值没有超过预设的干扰阈值I th。其中,SBS i和SBS j分别为SBS网络中不同的SBS。W为有向图边的权重,也称为干扰矩阵,干扰矩阵中元素 w ij=w ji=max(p ij/p ii,p ji/p jj),其中,p ij为SBS j发送到SBS i内用户的信号的平均功率,p ii为SBS i发送给自身用户的信号的平均功率,p ji为SBS i发送到SBS j内用户的信号的平均功率,p jj为SBS j发送给自身用户的信号的平均功率。因此,W中的元素为用户接收到多个相邻SBS发送给它的信号的平均功率和自身授权的SBS发送给它的信号功率的比值中的较大者。在一实施例中,如果用户接收到一个相邻SBS发送给它的信号的平均功率,则W中的元素为相邻SBS发送给它的信号的平均功率和自身授权的SBS发送给它的信号功率的比值。 In this embodiment, the small cell Small cell is a small cell in which an SBS is deployed, that is, one Small cell corresponds to one SBS, and the SBS is grouped, that is, the Small cell is grouped. Each small cell in which the SBS is deployed has a small cell gateway, and is configured to receive a user data measurement report fed back by the SUE, where the content of the user data measurement report includes location information of the SUE, power information sent by the SBS in the small cell to the SUE, and the like. . In step 110, the directed graph G of the SBS network is first obtained according to the graph theory, G=[T, E, W], where T={t 1 , t 2 , . . . , t F } is all in the network. The set of vertices, each element in the collection represents an SBS. E is a set of edges between vertices, also called a potential interference matrix. The value of the element e i,j in the latent interference matrix is 0 or 1. When e i,j =1, it means that there exists between SBS i and SBS j . The interference and the interference value exceed the preset interference threshold I th . When e i,j =0, it means that there is no interference or interference value between SBS i and SBS j does not exceed the preset interference threshold I th . Among them, SBS i and SBS j are respectively different SBSs in the SBS network. W is the weight of the directed graph edge, also called the interference matrix. The element w ij =w ji =max(p ij /p ii ,p ji /p jj ) in the interference matrix, where p ij is sent to SBS for SBS j the average power of the signal i of the user, the average power of the signal p ii addressed to own user as SBS i, p ji transmitted to the SBS j user signal is the SBS i mean power, p jj addressed to own user SBS j The average power of the signal. Thus, the elements in W are the greater of the ratio of the average power of the signal transmitted by the user to the plurality of neighboring SBSs to the signal power sent to it by the SBS. In an embodiment, if the user receives the average power of a signal sent to it by a neighboring SBS, the elements in W are the average power of the signal sent to it by the neighboring SBS and the signal sent to it by the self-authorized SBS. The ratio of power.
以最小化组内干扰为目的,根据有向图中潜在干扰矩阵的元素值,将网络中F个SBS分成L组,表示为χ={1,2,...,L},确定初始的分组矩阵V,满足当SBS i和SBS j之间的e i,j=0时,可以将SBS i和SBS j分到同一个SBS小组中,且任意一个SBS只能被分配到一个SBS小组内。根据模拟退火算法对初始的分组矩阵中的元素进行调换以得出更优的分组矩阵,以满足组内SBS之间干扰最小的需求,该分组矩阵即为SBS的分组结果。 For the purpose of minimizing intra-group interference, according to the element values of the latent interference matrix in the directed graph, the F SBSs in the network are divided into L groups, denoted as χ={1, 2,..., L}, and the initial packet matrix V, meet when e i between I and SBS SBS j, j = 0, the I and may be SBS SBS SBS J assigned to the same team, and can only be assigned to any one SBS SBS into a group . The elements in the initial grouping matrix are exchanged according to the simulated annealing algorithm to obtain a better grouping matrix to meet the minimum interference requirement between the SBSs in the group, which is the grouping result of the SBS.
在一实施例中,根据模拟退火算法对初始的分组矩阵中的元素进行调换以得出更优的分组矩阵的步骤如下:In an embodiment, the steps of translating the elements in the initial grouping matrix according to the simulated annealing algorithm to obtain a better grouping matrix are as follows:
步骤110,设定起始的温度Tem及迭代次数IN,Tem和IN可以根据实际问题取适当大的初始值,Tem和IN的设置可以防止无限迭代。In step 110, the initial temperature Tem and the number of iterations IN are set, and Tem and IN can take appropriate large initial values according to actual problems, and the settings of Tem and IN can prevent infinite iteration.
步骤120,获取初始的分组矩阵V及设定每组最大数Z,其中,分组矩阵为F行F列的矩阵,最大数Z的取值范围是[1,F-1]内的整数,V=(v il) F*L,其中,v il表示分组矩阵中的元素,F表示F行F列的矩阵,L表示分组数。当v il=1时,将SBS i分到SBS小组1,当v il=0时,SBS i不分到SBS小组1,且SBS小组1内的SBS数量C l不超过Z。 Step 120: Acquire an initial grouping matrix V and set a maximum number Z of each group, wherein the grouping matrix is a matrix of F rows and F columns, and the maximum value Z ranges from an integer in [1, F-1], V = (v il ) F*L , where v il represents an element in the grouping matrix, F represents a matrix of F rows and F columns, and L represents the number of packets. When v il = 1, the SBS SBS assigned to Group 1 I, v il = 0 when the time, regardless of the SBS SBS I Group 1 and Group SBS SBS C l in the number of no more than one Z.
步骤130,构建干扰函数为
Figure PCTCN2018108061-appb-000005
其中,v il和v jl分别表示分组矩阵中不同的元素。
Step 130, constructing the interference function as
Figure PCTCN2018108061-appb-000005
Where v il and v jl respectively represent different elements in the grouping matrix.
步骤140,在满足预设的约束条件下,将任意一个SBS小组中的一个SBS 转移到其他组中,即改变了V中的一个元素。其中,预设的约束条件为:Step 140: Transfer one SBS in any one SBS group to another group under the preset constraint condition, that is, change one element in V. Among them, the default constraints are:
Figure PCTCN2018108061-appb-000006
其中,s.t.表示受约束的含义,C l表示SBS小组内的SBS的数量。
Figure PCTCN2018108061-appb-000006
Where st represents the meaning of the constraint and C l represents the number of SBSs within the SBS team.
Figure PCTCN2018108061-appb-000007
该式表示同一基站不能在不同的SBS小组。
Figure PCTCN2018108061-appb-000007
This formula indicates that the same base station cannot be in a different SBS group.
v il∈{0,1}。 v il ∈{0,1}.
步骤150,计算干扰函数的变化值Δt′=C(S′)-C(S),若Δt′<0,则将S′作为干扰函数的新解,若Δt′≥0,则以概率
Figure PCTCN2018108061-appb-000008
将S′作为干扰函数的新解,其中,C(S)为根据初始的分组矩阵计算的干扰函数值,C(S′)为根据调换后的分组矩阵计算的干扰函数值。
Step 150, calculating a variation value of the disturbance function Δt'=C(S')-C(S), and if Δt'<0, then using S' as a new solution of the interference function, if Δt' ≥ 0, then the probability
Figure PCTCN2018108061-appb-000008
S' is taken as a new solution to the interference function, where C(S) is the value of the interference function calculated from the initial grouping matrix, and C(S') is the value of the interference function calculated from the grouping matrix after the switching.
步骤160,判断是否达到预设的退出条件,若达到退出条件,则将作为干扰函数新解的分组矩阵输出,否则执行步骤170;其中,退出条件为以下条件之一:迭代次数已超过IN次;干扰函数的变化值持续Δt′≥0;温度Tem达到阈值。Step 160: Determine whether the preset exit condition is reached. If the exit condition is reached, the packet matrix that is the new solution of the interference function is output, otherwise step 170 is performed; wherein the exit condition is one of the following conditions: the number of iterations has exceeded IN times The change value of the disturbance function lasts Δt' ≥ 0; the temperature Tem reaches the threshold.
步骤170,减小温度Tem,并执行步骤140。In step 170, the temperature Tem is decreased, and step 140 is performed.
在一实施例中,在完成SBS分组后,为每个SBS小组分配子信道,满足组内用户速率需求的前提下,最大化小组的吞吐量,因此对组间分配正交子信道,其分配子信道的步骤如下:In an embodiment, after the SBS packet is completed, a subchannel is allocated for each SBS group, and the throughput of the group is maximized under the premise of satisfying the user rate requirement in the group, so the orthogonal subchannel is allocated between the groups, and the allocation thereof is performed. The steps for the subchannel are as follows:
步骤210,通过公式
Figure PCTCN2018108061-appb-000009
测算SBS小组1的用户速率需求,其中,
Figure PCTCN2018108061-appb-000010
为SBS小组1的用户的最低速率需求,|C l|为SBS小组1内的SBS数量,D j为SBS j上用户的集合。
Step 210, passing the formula
Figure PCTCN2018108061-appb-000009
Measuring the user rate requirement of SBS Team 1, where
Figure PCTCN2018108061-appb-000010
For the minimum rate requirement of the user of SBS group 1, |C l | is the number of SBSs in SBS group 1, and D j is the set of users on SBS j .
步骤220,根据用户速率需求,确定SBS小组1所需的子信道数Y l,且
Figure PCTCN2018108061-appb-000011
其中,K为可以被分配给SBS小组的所有子信道数。
Step 220, determining the number of subchannels Y l required by the SBS group 1 according to the user rate requirement, and
Figure PCTCN2018108061-appb-000011
Where K is the number of all subchannels that can be assigned to the SBS team.
步骤230,计算子信道k在SBS小组1中每个SBS的信号与干扰加噪声比(Signal to Interference plus Noise Ratio,SINR),其中,子信道k在SBS小组1中SBS j上的SINR为
Figure PCTCN2018108061-appb-000012
其中,
Figure PCTCN2018108061-appb-000013
Figure PCTCN2018108061-appb-000014
分别表示MBS和SBS j在子信道k上的发射功率,
Figure PCTCN2018108061-appb-000015
Figure PCTCN2018108061-appb-000016
分别表示MBS和SBS j到用 户n在子信道k上的信道增益,σ 2为噪声功率,在一实施例中,上述所有功率信息均可以从用户数据报告中获得。
Step 230: Calculate a Signal to Interference plus Noise Ratio (SINR) of each SBS of the subchannel k in the SBS group 1, wherein the SINR of the subchannel k on the SBS j in the SBS group 1 is
Figure PCTCN2018108061-appb-000012
among them,
Figure PCTCN2018108061-appb-000013
with
Figure PCTCN2018108061-appb-000014
Representing the transmit power of MBS and SBS j on subchannel k, respectively.
Figure PCTCN2018108061-appb-000015
with
Figure PCTCN2018108061-appb-000016
Representing the channel gains of MBS and SBS j to user n on subchannel k, respectively, σ 2 is the noise power. In one embodiment, all of the above power information can be obtained from the user data report.
步骤240,将步骤230中计算的子信道k在SBS小组1中每个SBS的SINR中最小的SINR值作为SBS小组1的SINR。Step 240: The minimum SINR value of the SINR of each SBS in the SBS group 1 calculated by the subchannel k calculated in step 230 is taken as the SINR of the SBS group 1.
步骤250,根据SBS小组1的SINR,在满足用户的最低速率需求的前提下,最大化组内的吞吐量,即
Figure PCTCN2018108061-appb-000017
当子信道k分配至SBS小组1时的吞吐量大于子信道k分配至其他SBS小组时的吞吐量且SBS小组1已被分配的子信道数小于SBS小组1所需的子信道数时,将子信道k分配给第1组,否则子信道k不分给第1组;其中,λ k,l为指针变量,指针变量的值只能为0或1,当λ k,l=1时,表示将子信道k分配至SBS小组1,当λ k,l=0时,表示不将子信道k分配至SBS小组1。
Step 250, according to the SINR of the SBS group 1, under the premise that the minimum rate requirement of the user is met, the throughput in the group is maximized, that is,
Figure PCTCN2018108061-appb-000017
When the throughput when subchannel k is allocated to SBS group 1 is greater than the throughput when subchannel k is allocated to other SBS groups and the number of subchannels that SBS group 1 has allocated is smaller than the number of subchannels required by SBS group 1, The subchannel k is assigned to the first group, otherwise the subchannel k is not assigned to the first group; wherein λ k,l is a pointer variable, and the value of the pointer variable can only be 0 or 1, when λ k,l =1, Indicates that subchannel k is assigned to SBS group 1, and when λ k,l =0, it means that subchannel k is not allocated to SBS group 1.
步骤260,判断所有子信道是否分配完毕,当所有子信道均分配完毕时,输出每组的子信道分配矩阵,当还有子信道未分配时,重复执行步骤250,直到所有子信道分配完毕。In step 260, it is determined whether all subchannels are allocated. When all subchannels are allocated, the subchannel allocation matrix of each group is output. When there are still subchannels unallocated, step 250 is repeated until all subchannels are allocated.
在一实施例中,步骤250中组内的吞吐量在计算时满足以下约束条件:In an embodiment, the throughput within the group in step 250 meets the following constraints in the calculation:
Figure PCTCN2018108061-appb-000018
Figure PCTCN2018108061-appb-000018
本实施例根据SBS之间的干扰对SBS进行分组,并且根据SBS小组的实际需求为SBS小组分配子信道,既降低了计算复杂度,又能在保证组内用户速率的情况下最小化SBS之间的干扰,解决了相关技术中混合接入方式下资源分配策略的计算复杂度高,而计算复杂度低的分配策略易造成不同SBS之间的共信道干扰强烈的问题。In this embodiment, the SBS is grouped according to the interference between the SBSs, and the sub-channels are allocated to the SBS group according to the actual needs of the SBS group, which not only reduces the computational complexity, but also minimizes the SBS in the case of ensuring the user rate in the group. The interference between the two technologies solves the problem that the computational complexity of the resource allocation strategy in the hybrid access mode is high, and the allocation strategy with low computational complexity is likely to cause strong co-channel interference between different SBSs.
在完成子信道分配后,每组组内SBS使用分配给该组的子信道,避免了不同组之间的干扰。本实施例提供的方法还包括将分配至该组的子信道分配给小组内SBS的多个用户上,以保证用户可以通过分配给自身的子信道进行数据通信。在本实施例中,将子信道分配给用户的方法可以为:首先查看SBS小组内是否存在空闲子信道;在存在空闲子信道的情况下,将空闲子信道中与用户间 信道条件最好的子信道分配至小组内SBS的用户上。在一实施例中,上述信道条件即为SINR,当子信道与用户之间的SINR值越小,即表示子信道与用户间的信道条件越好。After completing the subchannel allocation, the SBSs in each group use the subchannels assigned to the group, avoiding interference between different groups. The method provided by this embodiment further includes allocating subchannels allocated to the group to a plurality of users of the SBS in the group to ensure that the user can perform data communication through the subchannels allocated to the user. In this embodiment, the method for allocating a subchannel to a user may be: first, whether there is an idle subchannel in the SBS group; and in the case where there is an idle subchannel, the channel condition between the idle subchannel and the user is the best. The subchannels are assigned to users of the SBS within the group. In an embodiment, the channel condition is SINR, and the smaller the SINR value between the subchannel and the user, the better the channel condition between the subchannel and the user.
为保证在混合接入方式下既能保证授权用户的通信质量,又能满足非授权用户的通信需求,在本实施例中,可以将分配给SBS小组内的子信道按预设比例分为授权子信道和非授权子信道,其中,预设比例可以根据实时网络环境进行调整,默认可以为1∶3。在完成子信道比例分配后,首先对授权用户进行子信道分配,步骤如下:In this embodiment, the subchannels allocated to the SBS group can be divided into authorized groups according to a preset ratio, in order to ensure the communication quality of the authorized users and the communication requirements of the unlicensed users. The subchannel and the unlicensed subchannel, wherein the preset ratio can be adjusted according to the real-time network environment, and the default may be 1:3. After completing the subchannel proportional allocation, first perform subchannel allocation to the authorized user, as follows:
步骤310,查看授权用户对应的SBS的授权子信道中是否存在第一空闲子信道,如果存在第一空闲子信道,直接将授权子信道中与授权用户间信道条件最好的子信道分配给授权用户,并执行步骤350,如果不存在第一空闲子信道,则执行步骤320。Step 310: Check whether the first idle subchannel exists in the authorized subchannel of the SBS corresponding to the authorized user, and if there is the first idle subchannel, directly allocate the subchannel with the best channel condition among the authorized subchannel and the authorized user to the authorized User, and step 350 is performed, if there is no first idle subchannel, step 320 is performed.
步骤320,查看MBS是否存在空闲子信道,如果有空闲子信道,选择MBS的空闲子信道中与该用户信道条件最好的子信道,分配给授权用户,并执行步骤350,如果没有空闲子信道,则执行步骤330。Step 320: Check whether there is an idle subchannel in the MBS. If there is an idle subchannel, select the subchannel with the best user channel condition in the idle subchannel of the MBS, assign it to the authorized user, and perform step 350 if there is no free subchannel. Then, step 330 is performed.
步骤330,查看授权用户对应的SBS的非授权子信道中是否存在第二空闲子信道,如果存在第二空闲子信道,直接将非授权子信道中与授权用户间信道条件最好的子信道分配给授权用户,并执行步骤350,如果不存在第二空闲子信道,则执行步骤340。Step 330: Check whether there is a second idle subchannel in the unlicensed subchannel of the SBS corresponding to the authorized user, and if there is a second idle subchannel, directly allocate the subchannel with the best channel condition among the unlicensed subchannel and the authorized user. To the authorized user, and step 350 is performed, if there is no second idle subchannel, step 340 is performed.
步骤340,将该授权用户放置在等待队列中,当存在可用的子信道时,将子信道分配给等待队列中最前列的用户。In step 340, the authorized user is placed in the waiting queue, and when there are available subchannels, the subchannel is allocated to the user in the forefront of the waiting queue.
步骤350,查看已被分配子信道的授权用户的通信速率,判断该通信速率是否满足最低速率需求,若该通信速率满足最低速率需求,则不在为该授权用户分配新的子信道,若该通信速率不满足最低速率需求,则重新执行步骤310为该授权用户分配子信道。在本实施例中,当对非授权用户进行子信道分配时,由于非授权用户无法使用SBS分授权子信道,因此直接从步骤320开始执行。 虽然非授权用户可以使用的SBS下的子信道较少,但实际上非授权用户可以使用任意SBS下的非授权子信道,并且当授权用户离开对其授权的SBS时,即转变为非授权用户。在一实施例中,授权用户及非授权用户在查看子信道是否空闲的时候,如果空闲子信道分配给用户通信质量很差,仍然视为无空闲子信道。Step 350: Check the communication rate of the authorized user who has been assigned the subchannel, determine whether the communication rate meets the minimum rate requirement, and if the communication rate meets the minimum rate requirement, do not allocate a new subchannel to the authorized user, if the communication If the rate does not meet the minimum rate requirement, step 310 is re-executed to allocate the subchannel to the authorized user. In this embodiment, when sub-channel allocation is performed for an unauthorized user, since the unauthorized user cannot use the SBS sub-grant sub-channel, the execution starts directly from step 320. Although there are fewer subchannels under the SBS that an unlicensed user can use, in fact, an unauthorized user can use an unlicensed subchannel under any SBS, and when an authorized user leaves the SBS authorized for it, it becomes an unauthorized user. . In an embodiment, when the authorized sub-channel and the unlicensed user check whether the sub-channel is idle, if the idle sub-channel is allocated to the user with poor communication quality, it is still regarded as no idle sub-channel.
下面结合图2至图5对本实施例的效果进行详细的说明。The effects of the present embodiment will be described in detail below with reference to FIGS. 2 to 5.
图2为不同算法在SBS布置密度增大的情况下宏小区用户的平均吞吐量走势图,图3为SUE在不同SBS(也即Small cell)部署密度情况下的平均信号与干扰加噪声比,图4为不同算法下用户公平性,图5为用户使用不同算法的情况下的满意度。上述附图中使用的算法分别为:在封闭模式下使用本公开的实施例提供的资源分配方法(对应图2至图5中带有“菱形”的折线)、在混合模式下使用本公开实施例提供的资源分配方法(对应图2至图5中带有“星号”的折线)、基于浩斯菲尔德神经网络(Hopfield)的基于聚类的资源分配算法(Cluster-based Resource Allocation,CRA)(对应图2至图5中带有“正方形”的折线)、组内正交分组算法(对应图2至图5中带有“三角形”的折线)以及基于Hopfield网络的基于聚类的启发式家庭基站间干扰最小化的子信道分配算法(Heuristic Cluster-based Femto-femto Interference minimized Subchannels Allocation Algorithm,HCFM)(对应图2至图5中带有“圆形”的折线)。以上算法均在如表1所示的模拟环境下进行仿真。2 is a graph showing an average throughput trend of a macro cell user in a case where different SBS layout densities are increased, and FIG. 3 is an average signal to interference plus noise ratio of a SUE in a different SBS (ie, Small cell) deployment density. Figure 4 shows user fairness under different algorithms, and Figure 5 shows satisfaction when users use different algorithms. The algorithms used in the above figures are respectively: the resource allocation method provided by the embodiment of the present disclosure in the closed mode (corresponding to the polyline with "diamond" in FIGS. 2 to 5), and the implementation of the present disclosure in the mixed mode. The resource allocation method provided by the example (corresponding to the polyline with "asterisk" in Fig. 2 to Fig. 5), Cluster-based Resource Allocation (CRA) based on the Hopfield field network (Hopfield) (corresponding to the polyline with "square" in Figures 2 to 5), the intra-group orthogonal grouping algorithm (corresponding to the polyline with "triangle" in Figures 2 to 5) and the cluster-based heuristic based on Hopfield network Heuristic Cluster-based Femto-Femto Interference minimized Subchannels Allocation Algorithm (HCFM) (corresponding to a broken line with "circle" in FIGS. 2 to 5). The above algorithms were all simulated in the simulation environment as shown in Table 1.
表1Table 1
参数parameter 取值Value
MBS/SBS的最大发送功率Maximum transmit power of MBS/SBS 46dBm,20dBm46dBm, 20dBm
用户数User number 10MUE/扇区,1-4SUEs/SBS10MUE/sector, 1-4SUEs/SBS
MBS/SBS的天线增益MBS/SBS antenna gain 14dBi/5dBi14dBi/5dBi
室内/室外的阴影衰落差Indoor/outdoor shadow fading 8dB,4dB8dB, 4dB
系统带宽System bandwidth 10MHz10MHz
资源块RBs数目Number of resource block RBs 5050
外墙/内墙的穿透损耗Penetration loss of external wall/interior wall 20dB,5dB20dB, 5dB
图2为不同算法在SBS布置密度增大的情况下宏小区用户的平均吞吐量走势图。由图2可知,当SBS布置密度加大时,宏小区用户的平均吞吐量也伴随着SBS密度的加大而逐步降低。造成这一结果的原因在于,随着SBS布置密度增大,MUE周围的SBS数量增大,导致MUE遭受到的由SBS层带来的跨层干扰较SBS数量少的时候更大,因此MUE的通信质量也随之降低。在混合接入方式下使用本公开实施例提供的方法相较于其它方法而言,用户的吞吐量处于较高的水准,由于MUE作为非授权用户时可以在遭受严重干扰时将网络切换到邻近的通信质量较好的SBS上,这样有效地保证了MUE的通信质量。FIG. 2 is a graph showing the average throughput of macro cell users in the case where the SBS arrangement density is increased by different algorithms. As can be seen from FIG. 2, when the SBS layout density is increased, the average throughput of the macro cell user is gradually reduced as the SBS density increases. The reason for this result is that as the SBS arrangement density increases, the number of SBSs around the MUE increases, causing the MUE to suffer from cross-layer interference caused by the SBS layer being larger than when the number of SBSs is small, so the MUE The quality of communication is also reduced. In the hybrid access mode, the method provided by the embodiment of the present disclosure uses a user's throughput to be at a higher level than other methods. Since the MUE acts as an unauthorized user, the network can be switched to proximity when subjected to severe interference. The communication quality is better on the SBS, which effectively guarantees the communication quality of the MUE.
图3是SUE在不同SBS部署密度情况下的平均信干噪比。相对于其它算法,在封闭模式下采用本公开实施例所提供的资源分配方法能够有效地抑制SBS同层干扰,得到更高的信干噪比,由于上述方法有效地预防了资源的浪费,从而提升了用户通信质量。在混合接入方式下,采用本公开实施例所提供的资源分配方法SBS更大程度的提升了用户通信质量,由于在混合接入方式下跨层干扰得到了更大程度的抑制,因此SUE信干噪比处于更高的水平。Figure 3 shows the average signal to interference and noise ratio of SUEs at different SBS deployment densities. Compared with other algorithms, the resource allocation method provided by the embodiments of the present disclosure can effectively suppress SBS peer interference in a closed mode, and obtain a higher signal to interference and noise ratio, because the above method effectively prevents resource waste, thereby Improve the quality of user communication. In the hybrid access mode, the resource allocation method SBS provided by the embodiment of the present disclosure improves the user communication quality to a greater extent, and the cross-layer interference is more suppressed in the hybrid access mode, so the SUE letter The dry noise ratio is at a higher level.
图4展示了不同算法下的用户公平性。由图4可知,在混合接入方式下,采用采用本公开施例所提供的资源分配方法的用户公平性最高,而封闭模式下采用本公开实施例所提供的资源分配方法的用户公平性低于混合方式接入方式下采用本公开实施例所提供的资源分配方法的用户公平性。由于本公开实施例所提供的资源分配方法将模拟退火算法运用到分组中,更高效地解决了分组问题,同时经过多次迭代得到了更好的分组结果,因此更加高效地抑制了超密集网络的同层干扰,同时也使得用户间受到的干扰程度相差较小,使得用户公平 性处于较高的水平。在混合接入方式下使用上述资源分配方法,更大程度的抑制了跨层干扰,使得MUE的通信质量得到了较大的提升,因此公平性获得了更大程度的提升。相较于上述资源分配方法,其它对比算法并没有过多地考虑用户公平性,且其它分组方案中每组内SBS的数目相差较大,从而导致不同组内用户数目差别也很大,最终导致不同组的用户公平性相差较大,用户公平性降低。在一实施例中,图4中的纵坐标值越大,表示公平性越大。Figure 4 shows user fairness under different algorithms. It can be seen from FIG. 4 that the user fairness of the resource allocation method provided by the embodiment of the present disclosure is the highest in the hybrid access mode, and the user fairness of the resource allocation method provided by the embodiment of the present disclosure is low in the closed mode. The user fairness of the resource allocation method provided by the embodiment of the present disclosure is adopted in the hybrid mode access mode. Since the resource allocation method provided by the embodiment of the present disclosure applies the simulated annealing algorithm to the grouping, the grouping problem is solved more efficiently, and the grouping result is obtained through multiple iterations, so that the ultra-dense network is more effectively suppressed. The same layer of interference also makes the degree of interference between users less different, making the user fairness at a higher level. In the hybrid access mode, the resource allocation method is used to suppress cross-layer interference to a greater extent, so that the communication quality of the MUE is greatly improved, and thus the fairness is improved to a greater extent. Compared with the above resource allocation method, other comparison algorithms do not consider user fairness too much, and the number of SBSs in each group differs greatly in other grouping schemes, resulting in a large difference in the number of users in different groups, ultimately resulting in The fairness of users in different groups is quite different, and the fairness of users is reduced. In an embodiment, the larger the ordinate value in FIG. 4, the greater the fairness.
图5为用户在采用不同算法的情况下的满意度。相较于CRA算法、组内正交算法和HCFM算法,本公开实施例提出的资源分配方法的用户满意度更高。有由于有效地抑制超密集网络中存在的同层干扰及跨层干扰,更加高效地利用了频谱资源,用户获得的通信速率更高,从而得到了更高的满意度。由于对比算法每个组的SBS数量相差较大,导致不同组获得的子信道数目相差较大,也就使得组内能够复用的信道数目不一,造成一些用户不能分配到足够的信道,从而导致通信质量较差,用户满意度较低。上述资源分配方法在封闭接入方式下SBS数目较为一致,能够分配到的信道相差不大,从而用户通信质量较好,获得较高的满意度。上述资源分配方法在封闭接入方式基础上进一步采用了混合接入方式,更好地利用了频谱资源,用户通信质量进一步提升,进一步满足了用户的满意度。在一实施例中,图5中的纵坐标值越大,表示用户满意度越高。Figure 5 shows the user's satisfaction with different algorithms. Compared with the CRA algorithm, the intra-group orthogonal algorithm and the HCFM algorithm, the user satisfaction of the resource allocation method proposed by the embodiment of the present disclosure is higher. Due to the effective suppression of the same layer interference and cross-layer interference existing in the ultra-dense network, the spectrum resources are utilized more efficiently, and the communication rate obtained by the user is higher, thereby obtaining higher satisfaction. Because the number of SBSs in each group of the comparison algorithm is quite different, the number of subchannels obtained by different groups is quite different, which results in different numbers of channels that can be multiplexed in the group, and some users cannot allocate enough channels. This leads to poor communication quality and low user satisfaction. In the above resource allocation method, the number of SBSs in the closed access mode is relatively consistent, and the channels that can be allocated are not much different, so that the user communication quality is good and the satisfaction is high. The above resource allocation method further adopts a hybrid access mode based on the closed access mode, and better utilizes the spectrum resources, and the user communication quality is further improved, thereby further satisfying the user satisfaction. In an embodiment, the larger the ordinate value in FIG. 5, the higher the user satisfaction.
在一实施例中,本公开的实施例提供了一种资源分配服务器,图6是本公开一实施例中资源分配服务器的结构框图,如图6所示,该服务器至少包括存储器610和处理器620,存储器610上存储有计算机程序,处理器620在执行存储器上的计算机程序时实现步骤110至步骤130,与本公开实施例的步骤相同,在此不再赘述。在实际使用时,本公开实施例提供的资源分配服务器可以布置在MBS上,作为为SBS分配子信道的实际装置使用。In an embodiment, an embodiment of the present disclosure provides a resource allocation server, and FIG. 6 is a structural block diagram of a resource allocation server according to an embodiment of the present disclosure. As shown in FIG. 6, the server includes at least a memory 610 and a processor. 620, a computer program is stored on the memory 610, and the processor 620 implements the steps 110 to 130 in the execution of the computer program on the memory, which is the same as the steps of the embodiment of the present disclosure, and details are not described herein again. In actual use, the resource allocation server provided by the embodiment of the present disclosure may be disposed on the MBS as an actual device that allocates a subchannel for the SBS.
在本实施例中,Small cell即是部署有SBS的小小区,即一个Small cell对应一个SBS,对SBS进行分组即对Small cell进行分组。每个部署有SBS的小 小区均有一个Small cell网关,设置为接收SUE反馈的用户数据测量报告,该用户数据测量报告的内容包括SUE的位置信息、小小区内SBS发送至SUE的功率信息等。处理器在运行计算机程序时,首先根据图论获取SBS网络的有向图G,G=[T,E,W],其中,T={t 1,t 2,...,t F}为网络中所有的顶点集合,集合里面的每个元素均代表一个SBS。E为顶点间的边的集合,也称为潜在干扰矩阵,潜在干扰矩阵中元素e i,j的值为0或1,当e i,j=1时,表示SBS i和SBS j之间存在干扰且干扰值超过预设的干扰阈值I th,当e i,j=0时,表示SBS i和SBS j之间不存在干扰或干扰值没有超过预设的干扰阈值I th。其中,SBS i和SBS j分别为SBS网络中不同的SBS。W为有向图边的权重,也称为干扰矩阵,干扰矩阵中元素w ij=w ji=max(p ij/p ii,p ji/p jj),其中,p ij为SBS j发送到SBS i内用户的信号的平均功率,p ii为SBS i发送给自身用户的信号的平均功率,p ji为SBS i发送到SBS j内用户的信号的平均功率,p jjSBS j发送给自身用户的信号的平均功率。因此,W中的元素为用户接收到多个相邻SBS发送给它的信号的平均功率和自身授权的SBS发送给它的信号功率的比值中的较大者。在一实施例中,如果用户接收到一个相邻SBS发送给它的信号的平均功率,则W中的元素为相邻SBS发送给它的信号的平均功率和自身授权的SBS发送给它的信号功率的比值。 In this embodiment, the Small cell is a small cell in which an SBS is deployed, that is, one Small cell corresponds to one SBS, and the SBS is grouped to group the Small cells. Each small cell in which the SBS is deployed has a small cell gateway, and is configured to receive a user data measurement report fed back by the SUE, where the content of the user data measurement report includes location information of the SUE, power information sent by the SBS in the small cell to the SUE, and the like. . When the processor runs the computer program, it first obtains the directed graph G of the SBS network according to the graph theory, G=[T, E, W], where T={t 1 , t 2 ,..., t F } is A collection of all the vertices in the network. Each element in the collection represents an SBS. E is a set of edges between vertices, also called a potential interference matrix. The value of the element e i,j in the latent interference matrix is 0 or 1. When e i,j =1, it means that there exists between SBS i and SBS j . The interference and the interference value exceed the preset interference threshold I th . When e i,j =0, it means that there is no interference or interference value between SBS i and SBS j does not exceed the preset interference threshold I th . Among them, SBS i and SBS j are respectively different SBSs in the SBS network. W is the weight of the directed graph edge, also called the interference matrix. The element w ij =w ji =max(p ij /p ii ,p ji /p jj ) in the interference matrix, where p ij is sent to SBS for SBS j the average power of the signal within the user i, an average power, p ji signal p ii addressed to own user to SBS i transmitted as SBS i to the average power of the signal within the user's SBS j, p jj SBS j addressed to own user The average power of the signal. Thus, the elements in W are the greater of the ratio of the average power of the signal transmitted by the user to the plurality of neighboring SBSs to the signal power sent to it by the SBS. In an embodiment, if the user receives the average power of a signal sent to it by a neighboring SBS, the elements in W are the average power of the signal sent to it by the neighboring SBS and the signal sent to it by the self-authorized SBS. The ratio of power.
以最小化组内干扰为目的,处理器在运行计算机程序时根据有向图中潜在干扰矩阵的元素值,将网络中F个SBS分成L组,表示为χ={1,2,...,L},确定初始的分组矩阵V,满足当SBS i和SBS j之间的e i,j=0时,可以将SBS i和SBS j分到同一个SBS小组中,且任意一个SBS只能被分配到一个SBS小组内。根据模拟退火算法对初始的分组矩阵中的元素进行调换以得出更优的分组矩阵,以满足组内SBS之间干扰最小的需求,该分组矩阵即为SBS的分组结果。 For the purpose of minimizing intra-group interference, the processor divides the F SBSs in the network into L groups according to the element values of the potential interference matrix in the directed graph when running the computer program, which is expressed as χ={1,2,... , L}, an initial packet is determined matrix V, meet when e i between I and SBS SBS j, j = 0, the I and may be SBS SBS SBS J assigned to the same team, and only any one SBS Assigned to an SBS team. The elements in the initial grouping matrix are exchanged according to the simulated annealing algorithm to obtain a better grouping matrix to meet the minimum interference requirement between the SBSs in the group, which is the grouping result of the SBS.
在一实施例中,处理器运行计算机程序中的模拟退火算法对初始的分组矩阵中的元素进行调换以得出更优的分组矩阵的步骤余本公开实施例中的步骤110至步骤170相同,在此不再赘述。In an embodiment, the step of the processor operating the simulated annealing algorithm in the computer program to swap the elements in the initial grouping matrix to obtain a better grouping matrix is the same as steps 110 to 170 in the disclosed embodiment. I will not repeat them here.
在一实施例中,在完成SBS分组后,为每个SBS小组分配子信道,满足组内用户速率需求的前提下,最大化小组的吞吐量,因此对组间分配正交子信道。在一实施例中,处理器在为每个所述SBS小组分配子信道时,实现的步骤与本公开实施例中步骤210至步骤260相同,在此不再赘述。In an embodiment, after the SBS packet is completed, a subchannel is allocated for each SBS group, and the throughput of the group is maximized on the premise of satisfying the user rate requirement in the group, so the orthogonal subchannels are allocated between the groups. In an embodiment, when the processor allocates a sub-channel to each of the SBS groups, the steps are the same as the steps 210 to 260 in the embodiment of the present disclosure, and details are not described herein again.
本实施例根据SBS之间的干扰对SBS进行分组,并且根据SBS小组的实际需求为SBS小组分配子信道,既降低了计算复杂度,又能在保证组内用户速率的情况下最小化SBS之间的干扰,解决了相关技术中混合接入方式下资源分配策略的计算复杂度高,而计算复杂度低的分配策略SBS之间的共信道干扰强烈的问题。In this embodiment, the SBS is grouped according to the interference between the SBSs, and the sub-channels are allocated to the SBS group according to the actual needs of the SBS group, which not only reduces the computational complexity, but also minimizes the SBS in the case of ensuring the user rate in the group. The inter-channel interference solves the problem that the computational complexity of the resource allocation strategy in the hybrid access mode is high in the related art, and the co-channel interference in the allocation strategy SBS with low computational complexity is strong.
在完成子信道分配后,每组组内SBS只能使用分配给该组的子信道,避免了不同组之间的干扰。在一实施例中,本实施例中服务器的处理器在执行存储器上的计算机程序时还实现以下步骤:将分配至SBS小组的子信道分配给小组内SBS的多个用户上,以保证用户可以通过分配给自身的子信道进行数据通信。在将每个所述SBS小组分配到的子信道分配至小组内SBS的多个用户上时,处理器实现以下步骤:首先查看SBS小组内是否存在空闲子信道;在存在空闲子信道的情况下,将空闲子信道中与用户间信道条件最好的子信道分配至小组内SBS的用户上。在一实施例中,上述信道条件即为SINR,当子信道与用户之间的SINR值越小,即表示子信道与用户间的信道条件越好。After completing the subchannel allocation, the SBS in each group can only use the subchannels allocated to the group, avoiding interference between different groups. In an embodiment, the processor of the server in the embodiment further implements the following steps: when the computer program on the memory is executed, the subchannel allocated to the SBS group is allocated to multiple users of the SBS in the group to ensure that the user can Data communication is performed by subchannels assigned to itself. When assigning the subchannel to which each SBS group is assigned to multiple users of the SBS in the group, the processor implements the following steps: first, whether there is an idle subchannel in the SBS group; in the case where there is an idle subchannel The subchannels with the best channel conditions among the idle subchannels and the users are allocated to the users of the SBS in the group. In an embodiment, the channel condition is SINR, and the smaller the SINR value between the subchannel and the user, the better the channel condition between the subchannel and the user.
为保证在混合接入方式下既能保证授权用户的通信质量,又能满足非授权用户的通信需求,在本实施例中,可以将分配给SBS小组内的子信道按预设比例分为授权子信道和非授权子信道,其中,预设比例可以根据实时网络环境进行调整,默认可以为1∶3。在完成子信道比例分配后,处理器对授权用户进行子信道分配,实现的步骤与本公开实施例中步骤310至步骤350相同,在此不再赘述。在一实施例中,当对非授权用户进行子信道分配时,由于非授权用户无法使用SBS的授权子信道,因此直接从步骤320开始执行。虽然非授权用户可以使用的SBS下的子信道较少,但实际上非授权用户可以使用任意SBS下的非 授权子信道,并且当授权用户离开对其授权的SBS时,即转变为非授权用户。在一实施例中,授权用户及非授权用户在查看子信道是否空闲的时候,如果空闲子信道分配给用户通信质量很差,仍然视为无空闲子信道。In this embodiment, the subchannels allocated to the SBS group can be divided into authorized groups according to a preset ratio, in order to ensure the communication quality of the authorized users and the communication requirements of the unlicensed users. The subchannel and the unlicensed subchannel, wherein the preset ratio can be adjusted according to the real-time network environment, and the default may be 1:3. After the sub-channel ratio allocation is completed, the processor performs sub-channel allocation to the authorized user, and the implementation steps are the same as steps 310 to 350 in the embodiment of the present disclosure, and details are not described herein again. In an embodiment, when sub-channel allocation is performed for an unauthorized user, since the unauthorized sub-channel of the SBS cannot be used by the unauthorized user, execution is directly started from step 320. Although there are fewer subchannels under the SBS that an unlicensed user can use, in fact, an unauthorized user can use an unlicensed subchannel under any SBS, and when an authorized user leaves the SBS authorized for it, it becomes an unauthorized user. . In an embodiment, when the authorized sub-channel and the unlicensed user check whether the sub-channel is idle, if the idle sub-channel is allocated to the user with poor communication quality, it is still regarded as no idle sub-channel.

Claims (18)

  1. 一种资源分配方法,包括:A resource allocation method, including:
    获取小小区基站SBS网络的有向图;Obtaining a directed graph of a small cell base station SBS network;
    根据所述有向图,按照设定的分组策略,对所述SBS网络中的多个SBS进行分组,得到多个SBS小组;According to the directed graph, grouping a plurality of SBSs in the SBS network according to a set grouping policy to obtain a plurality of SBS groups;
    为每个所述SBS小组分配子信道。A subchannel is assigned to each of the SBS groups.
  2. 如权利要求1所述资源分配方法,其中,按照设定的分组策略,对所述SBS网络中的多个SBS进行分组,包括:The resource allocation method according to claim 1, wherein the grouping the plurality of SBSs in the SBS network according to the set grouping policy comprises:
    根据所述有向图,确定初始的分组矩阵;Determining an initial grouping matrix according to the directed graph;
    根据模拟退火算法对所述初始的分组矩阵中的元素进行调换;Interchanging elements in the initial grouping matrix according to a simulated annealing algorithm;
    当满足所述模拟退火算法的退出条件时,输出调换后的分组矩阵。When the exit condition of the simulated annealing algorithm is satisfied, the switched grouping matrix is output.
  3. 如权利要求1所述资源分配方法,其中,为每个所述SBS小组分配子信道,包括:The resource allocation method according to claim 1, wherein assigning a subchannel to each of said SBS groups comprises:
    确定每个所述SBS小组所需的子信道数;Determining the number of subchannels required for each of the SBS groups;
    计算待分配的子信道在每个所述SBS小组的吞吐量;Calculating the throughput of the subchannel to be allocated in each of the SBS groups;
    如果所述子信道分配至第一SBS小组时的吞吐量大于所述子信道分配至第二SBS小组时的吞吐量且所述第一SBS小组已被分配的子信道数小于所述第一SBS小组所需的子信道数,则将所述子信道分配至所述第一SBS小组。If the throughput of the subchannel allocated to the first SBS group is greater than the throughput when the subchannel is allocated to the second SBS group and the number of subchannels that the first SBS group has been allocated is smaller than the first SBS The number of subchannels required by the group is then assigned to the first SBS group.
  4. 如权利要求3所述资源分配方法,其中,确定每个所述SBS小组所需的子信道数,包括:The resource allocation method according to claim 3, wherein the number of subchannels required for each of said SBS groups is determined, including:
    测算每个所述SBS小组的用户速率需求;Measuring user rate requirements for each of the SBS teams;
    根据所述用户速率需求,确定每个所述SBS小组所需的子信道数。The number of subchannels required for each of the SBS groups is determined based on the user rate requirements.
  5. 如权利要求3所述资源分配方法,其中,计算待分配的子信道在每个所述SBS小组的吞吐量,包括:The resource allocation method according to claim 3, wherein calculating the throughput of the subchannel to be allocated in each of the SBS groups comprises:
    对于每个SBS小组,计算待分配的子信道在所述SBS小组中每个SBS的信号与干扰加噪声比;For each SBS group, calculating a signal to interference plus noise ratio of each SBS in the SBS group for the subchannel to be allocated;
    将所述SBS小组中所有信号与干扰加噪声比的最小值作为所述SBS小组的信号与干扰加噪声比;Using the minimum value of all signal to interference plus noise ratios in the SBS group as the signal to interference plus noise ratio of the SBS group;
    根据所述SBS小组的信号与干扰加噪声比,计算待分配的子信道在所述SBS小组的吞吐量。Calculating the throughput of the subchannel to be allocated in the SBS group according to the signal to interference plus noise ratio of the SBS group.
  6. 如权利要求5所述资源分配方法,其中,所述SBS小组的吞吐量的计算公式为:The resource allocation method according to claim 5, wherein the calculation formula of the throughput of the SBS group is:
    Figure PCTCN2018108061-appb-100001
    Figure PCTCN2018108061-appb-100001
    其中,B为信道带宽,j为所述SBS小组内的SBS,k为分配给j的子信道,n为连接在j上的用户,F为SBS的总数,
    Figure PCTCN2018108061-appb-100002
    为所述SBS小组的信号与干扰加噪声比,λ k,l为指针变量,所述指针变量的值为0或1,当λ k,l=1时,表示将子信道k分配至所述第一SBS小组,当λ k,l=0时,表示不将子信道k分配至所述第一SBS小组。
    Where B is the channel bandwidth, j is the SBS in the SBS group, k is the subchannel assigned to j, n is the user connected to j, and F is the total number of SBSs.
    Figure PCTCN2018108061-appb-100002
    For the signal-to-interference plus noise ratio of the SBS group, λ k,l is a pointer variable, the value of the pointer variable is 0 or 1, and when λ k,l =1, indicating that the subchannel k is allocated to the The first SBS group, when λ k, l =0, indicates that subchannel k is not allocated to the first SBS group.
  7. 如权利要求1所述资源分配方法,其中,在为每个所述SBS小组分配子信道之后,还包括:The resource allocation method according to claim 1, wherein after allocating the subchannels for each of the SBS groups, the method further comprises:
    将每个所述SBS小组分配到的子信道分配至所述SBS小组内的SBS服务的多个用户上。A subchannel to which each of the SBS groups is assigned is allocated to a plurality of users of the SBS service within the SBS group.
  8. 如权利要求7所述资源分配方法,其中,将每个所述SBS小组分配到的子信道分配至所述SBS小组内的SBS服务的多个用户上,包括:The resource allocation method according to claim 7, wherein the subchannel to which each of the SBS groups is allocated is allocated to a plurality of users of the SBS service in the SBS group, including:
    查看所述SBS小组内是否存在空闲子信道;Checking whether there are free subchannels in the SBS group;
    在存在多个所述空闲子信道的情况下,将多个所述空闲子信道中与所述多个用户间吞吐量最大的子信道分配至与所述吞吐量最大的子信道对应的用户。When there are a plurality of the idle subchannels, the subchannels having the largest throughput among the plurality of idle subchannels and the plurality of users are allocated to users corresponding to the subchannels having the highest throughput.
  9. 如权利要求7或8所述的资源分配方法,其中,将每个所述SBS小组分配到的子信道分配至所述SBS小组内的SBS服务的多个用户上,包括:The resource allocation method according to claim 7 or 8, wherein the subchannel to which each of the SBS groups is allocated is allocated to a plurality of users of the SBS service in the SBS group, including:
    将所述SBS小组内的SBS的子信道按预设比例分为授权子信道和非授权子信道;Subchannels of the SBS in the SBS group are divided into an authorized subchannel and an unlicensed subchannel according to a preset ratio;
    判断所述用户是否为授权用户;Determining whether the user is an authorized user;
    在所述用户为授权用户的情况下,查看所述授权子信道是否存在第一空闲子信道;If the user is an authorized user, check whether the authorized subchannel has a first idle subchannel;
    在所述授权子信道存在多个所述第一空闲子信道的情况下,将多个所述第一空闲子信道中与所述授权用户间吞吐量最大的子信道分配至所述授权用户;And if a plurality of the first idle subchannels exist in the authorized subchannel, a subchannel that has the largest throughput among the plurality of first idle subchannels and the authorized user is allocated to the authorized user;
    在所述预设用户为非授权用户的情况下,查看所述非授权子信道是否存在第二空闲子信道;If the preset user is an unauthorized user, check whether the unlicensed subchannel has a second idle subchannel;
    在所述非授权子信道存在多个所述第二空闲子信道的情况下,将多个所述第二空闲子信道中与所述非授权用户间吞吐量最大的子信道分配至所述非授权用户。And assigning, in the non-authorized subchannel, a plurality of the second idle subchannels, the subchannels that have the largest throughput among the plurality of second idle subchannels and the unlicensed users to the non Authorized user.
  10. 一种资源分配服务器,至少包括存储器、处理器,所述存储器上存储有计算机程序,所述处理器在执行所述存储器上的计算机程序时实现的步骤包括:A resource allocation server includes at least a memory, a processor, and a computer program stored thereon, and the steps implemented by the processor when executing the computer program on the memory include:
    获取小小区基站SBS网络的有向图;Obtaining a directed graph of a small cell base station SBS network;
    根据所述有向图,按照设定的分组策略,对所述SBS网络中的多个SBS进行分组,得到多个SBS小组;According to the directed graph, grouping a plurality of SBSs in the SBS network according to a set grouping policy to obtain a plurality of SBS groups;
    为每个所述SBS小组分配子信道。A subchannel is assigned to each of the SBS groups.
  11. 如权利要求10所述资源分配服务器,其中,所述处理器对所述SBS网络中的多个SBS进行分组时,实现的步骤包括:The resource allocation server according to claim 10, wherein when the processor groups a plurality of SBSs in the SBS network, the implementing steps include:
    根据所述有向图,确定初始的分组矩阵;Determining an initial grouping matrix according to the directed graph;
    根据模拟退火算法对所述初始分的组矩阵中的元素进行调换;The elements in the group matrix of the initial points are exchanged according to a simulated annealing algorithm;
    当满足所述模拟退火算法的退出条件时,输出调换后的分组矩阵。When the exit condition of the simulated annealing algorithm is satisfied, the switched grouping matrix is output.
  12. 如权利要求10所述资源分配服务器,其中,所述处理器为每个所述SBS小组分配子信道时,实现的步骤包括:The resource allocation server according to claim 10, wherein when the processor allocates a subchannel for each of the SBS groups, the implementing steps include:
    确定每个所述SBS小组所需的子信道数;Determining the number of subchannels required for each of the SBS groups;
    计算待分配的子信道在每个所述SBS小组的吞吐量;Calculating the throughput of the subchannel to be allocated in each of the SBS groups;
    如果所述子信道分配至第一SBS小组时的吞吐量大于所述子信道分配至第 二SBS小组时的吞吐量且所述第一SBS小组已被分配的子信道数小于所述第一SBS小组所需的子信道数,则将所述子信道分配至所述第一SBS小组。If the throughput of the subchannel allocated to the first SBS group is greater than the throughput when the subchannel is allocated to the second SBS group and the number of subchannels that the first SBS group has been allocated is smaller than the first SBS The number of subchannels required by the group is then assigned to the first SBS group.
  13. 如权利要求12所述资源分配服务器,其中,所述处理器确定每个所述SBS小组所需的子信道数时,实现的步骤包括:The resource allocation server according to claim 12, wherein when said processor determines the number of subchannels required for each of said SBS groups, the steps of implementing include:
    测算每个所述SBS小组的用户速率需求;Measuring user rate requirements for each of the SBS teams;
    根据所述用户速率需求,确定每个所述SBS小组所需的子信道数。The number of subchannels required for each of the SBS groups is determined based on the user rate requirements.
  14. 如权利要求12所述资源分配服务器,其中,所述处理器计算待分配的子信道在每个所述SBS小组的吞吐量时,实现的步骤包括:The resource allocation server according to claim 12, wherein said processor calculates a throughput of the subchannel to be allocated in each of said SBS groups, and the steps of implementing:
    对于每个SBS小组,计算待分配的子信道在所述SBS小组中每个SBS的信号与干扰加噪声比;For each SBS group, calculating a signal to interference plus noise ratio of each SBS in the SBS group for the subchannel to be allocated;
    将所述SBS小组中所有信号与干扰加噪声比的最小值作为所述SBS小组的信号与干扰加噪声比;Using the minimum value of all signal to interference plus noise ratios in the SBS group as the signal to interference plus noise ratio of the SBS group;
    根据所述SBS小组的信号与干扰加噪声比,计算待分配的子信道在所述SBS小组的吞吐量。Calculating the throughput of the subchannel to be allocated in the SBS group according to the signal to interference plus noise ratio of the SBS group.
  15. 如权利要求14所述资源分配服务器,其中,所述处理器计算所述SBS小组的吞吐量使用的计算公式为:The resource allocation server of claim 14 wherein said processor calculates a throughput formula for said SBS team to use:
    Figure PCTCN2018108061-appb-100003
    Figure PCTCN2018108061-appb-100003
    其中,B为信道带宽,j为所述SBS小组内的SBS,k为分配给j的子信道,n为连接在j上的用户,F为SBS的总数,
    Figure PCTCN2018108061-appb-100004
    为所述SBS小组的信号与干扰加噪声比,λ k,l为指针变量,所述指针变量的值为0或1,当λ k,l=1时,表示将子信道k分配至所述第一SBS小组,当λ k,l=0时,表示不将子信道k分配至所述第一SBS小组。
    Where B is the channel bandwidth, j is the SBS in the SBS group, k is the subchannel assigned to j, n is the user connected to j, and F is the total number of SBSs.
    Figure PCTCN2018108061-appb-100004
    For the signal-to-interference plus noise ratio of the SBS group, λ k,l is a pointer variable, the value of the pointer variable is 0 or 1, and when λ k,l =1, indicating that the subchannel k is allocated to the The first SBS group, when λ k, l =0, indicates that subchannel k is not allocated to the first SBS group.
  16. 如权利要求10所述资源分配服务器,其中,所述处理器在为每个所述SBS小组分配子信道之后,实现的步骤还包括:The resource allocation server according to claim 10, wherein after the processor allocates a subchannel for each of the SBS groups, the implementing step further comprises:
    将每个所述SBS小组分配到的子信道分配至所述SBS小组内的SBS服务的多个用户上。A subchannel to which each of the SBS groups is assigned is allocated to a plurality of users of the SBS service within the SBS group.
  17. 如权利要求16所述资源分配服务器,其中,所述处理器将每个所述SBS小组分配到的子信道分配至所述SBS小组内的SBS服务的多个用户上时,实现的步骤包括:The resource allocation server according to claim 16, wherein when said processor allocates a subchannel to which said each SBS group is assigned to a plurality of users of an SBS service within said SBS group, the steps of implementing:
    查看所述SBS小组内是否存在空闲子信道;Checking whether there are free subchannels in the SBS group;
    在存在多个所述空闲子信道的情况下,将多个所述空闲子信道中与所述多个用户间满足每个用户最低速率需求情况下最大化用户速率的子信道分配至与所述子信道对应的用户。And in a case where there are a plurality of the idle subchannels, a subchannel that maximizes a user rate in a case where the plurality of users are satisfied with a minimum rate requirement for each user among the plurality of idle subchannels is allocated to The user corresponding to the subchannel.
  18. 如权利要求16或17所述的资源分配服务器,其中,所述处理器将每个所述SBS小组分配到的子信道分配至所述SBS小组内的SBS服务的多个用户上时,还可以实现的步骤包括:The resource allocation server according to claim 16 or 17, wherein when the processor allocates a subchannel to which each of the SBS groups is allocated to a plurality of users of the SBS service in the SBS group, The steps to achieve include:
    将所述SBS小组内的SBS的子信道按预设比例分为授权子信道和非授权子信道;Subchannels of the SBS in the SBS group are divided into an authorized subchannel and an unlicensed subchannel according to a preset ratio;
    判断所述用户是否为授权用户;Determining whether the user is an authorized user;
    在所述用户为授权用户的情况下,查看所述授权子信道是否存在第一空闲子信道;If the user is an authorized user, check whether the authorized subchannel has a first idle subchannel;
    在所述授权子信道存在多个所述第一空闲子信道的情况下,将多个所述第一空闲子信道中与所述授权用户间满足每个授权用户最低速率需求情况下最大化用户速率的子信道分配至所述授权用户;And in a case that the authorized subchannel has a plurality of the first idle subchannels, maximizing a user in a case where a plurality of the first idle subchannels and the authorized user meet each authorized user minimum rate requirement a subchannel of the rate is allocated to the authorized user;
    在所述预设用户为非授权用户的情况下,查看所述非授权子信道是否存在第二空闲子信道;If the preset user is an unauthorized user, check whether the unlicensed subchannel has a second idle subchannel;
    在所述非授权子信道存在多个所述第二空闲子信道的情况下,将多个所述第二空闲子信道中与所述非授权用户间满足每个非授权用户最低速率需求情况下最大化用户速率的子信道分配至所述非授权用户。If a plurality of the second idle subchannels exist in the unlicensed subchannel, the minimum rate requirement of each unauthorized user is met between the plurality of the second idle subchannels and the unlicensed user A subchannel that maximizes the user rate is assigned to the unauthorized user.
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