WO2012088877A1 - Method for sending acknowledgement information and user equipment - Google Patents

Method for sending acknowledgement information and user equipment Download PDF

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Publication number
WO2012088877A1
WO2012088877A1 PCT/CN2011/077494 CN2011077494W WO2012088877A1 WO 2012088877 A1 WO2012088877 A1 WO 2012088877A1 CN 2011077494 W CN2011077494 W CN 2011077494W WO 2012088877 A1 WO2012088877 A1 WO 2012088877A1
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WO
WIPO (PCT)
Prior art keywords
ack
nack response
response information
information
nack
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PCT/CN2011/077494
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French (fr)
Chinese (zh)
Inventor
杨维维
戴博
梁春丽
Original Assignee
中兴通讯股份有限公司
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Application filed by 中兴通讯股份有限公司 filed Critical 中兴通讯股份有限公司
Publication of WO2012088877A1 publication Critical patent/WO2012088877A1/en

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Classifications

    • HELECTRICITY
    • H04ELECTRIC COMMUNICATION TECHNIQUE
    • H04LTRANSMISSION OF DIGITAL INFORMATION, e.g. TELEGRAPHIC COMMUNICATION
    • H04L1/00Arrangements for detecting or preventing errors in the information received
    • H04L1/12Arrangements for detecting or preventing errors in the information received by using return channel
    • H04L1/16Arrangements for detecting or preventing errors in the information received by using return channel in which the return channel carries supervisory signals, e.g. repetition request signals
    • H04L1/1607Details of the supervisory signal
    • H04L1/1614Details of the supervisory signal using bitmaps

Definitions

  • the present invention relates to the field of mobile wireless communications, and in particular to a method for transmitting response information and a user equipment (User Equipment, UE) in a wireless communication system.
  • UE User Equipment
  • the Radio Frame in the Long Term Evolution (LTE) system includes a Frequency Division Duplex (FDD) mode and a Time Division Duplex (TDD) mode frame structure.
  • FDD Frequency Division Duplex
  • TDD Time Division Duplex
  • a 10 msec (ms) radio frame consists of twenty slots of length 0.5 ms and numbers 0-19, slots 2i and 2i. +l constitutes a subframe (frame) i of length 1 ms (where 0 ⁇ i ⁇ 9).
  • a 10 ms radio frame is composed of two half frames of 5 ms length, and one subframe includes five subframes of length 1 ms, and subframes.
  • i is defined as a combination of two time slots 2i and 2i+1 that are 0.5 ms long (where 0 ⁇ i ⁇ 9).
  • one slot contains 7 symbols, and when Extended Cyclic Prefix (Extended CP) is used, one slot contains 6 symbols.
  • LTE TDD supports 5ms and 10ms uplink and downlink switching cycles. If the downlink to uplink transition point period is 5ms, the special subframe will exist in two fields; if the downlink to uplink transition point period is 10ms, the special subframe exists only in the first field; subframe #0 and sub Frame #5 and DwPTS are always used for downlink transmission; UpPTS and subframes immediately following the special subframe are dedicated to uplink transmission.
  • the user terminal since the uplink and downlink subframes are corresponding, when the physical downlink shared channel (PDSCH) contains only one codeword stream, the user terminal needs to feed back a 1-bit ACK. /NACK response information, when the PDSCH includes two codeword streams, the UE needs to feed back 2 bits of ACK/NACK response information, when the UE does not have a PUSCH (Physical Uplink Share Channel) to transmit in the current subframe.
  • PUSCH Physical Uplink Share Channel
  • the UE will transmit the 1-bit or 2-bit ACK/NACK response information in the format la/lb on the PUCCH (Physical Uplink Control Channel); and when the UE has the PUSCH transmission in the current subframe, The UE maps the 1-bit or 2-bit information to a corresponding bit through a certain ACK/NACK state, and performs channel coding, scrambling, and modulation, and then multiplexes with the data, and then transmits the signal on the PUSCH.
  • PUCCH Physical Uplink Control Channel
  • the ACK/NACK response information corresponding to the multiple downlink subframes needs to be sent on the PUCCH/PUSCH channel of one uplink subframe, where the uplink
  • the set of downlink subframes corresponding to the subframe constitutes a bundling window.
  • two types of ACK/NACK response information are defined: one is an ACK/NACK bundling method, and the other is ACK/NACK multiplexing method:
  • the high-level configuration of the UE uses bundling or mulitplexing.
  • the basic idea of the ACK/NACK bundling method is to use the ACK of the codeword stream corresponding to each downlink subframe that needs to be fed back in the uplink subframe.
  • the /NACK message performs a time domain bundling to obtain a 1-bit or bit ACK/NACK response message.
  • the UE When the UE does not transmit a PUSCH in the current subframe, the UE will transmit the format la/lb on the PUCCH.
  • the 1-bit or 2-bit ACK/NACK response information when the UE has a PUSCH transmission in the current subframe, the UE transmits the 1-bit or 2-bit information on the PUSCH after a certain channel coding and channel interleaving.
  • the core idea of the multiplexing method is to use different PUCCH channels and different modulation symbols on the channel to indicate different feedback states of the downlink subframes that need to be fed back in the uplink subframe. If there are multiple transport blocks on the downlink subframe, then The ACK/NACK fed back by the plurality of transport blocks of the downlink subframe is logically (bundled) and then channel selected, and then transmitted using PUCCH format lb.
  • the UE When the UE has no PUSCH to transmit in the current subframe, the UE will transmit the multiple ACK/NACK response information in the format lb with channel selection on the PUCCH; when the UE is in the current subframe When there is PUSCH transmission, the UE transmits a plurality of bit information through a certain ACK/NACK state to a corresponding bit, and performs channel coding, channel interleaving, and data multiplexing, and then transmits on the PUSCH.
  • the encoding process when the response information is transmitted on the PUSCH includes: 4.M c (Formula 1)
  • the number of required coding symbols is calculated according to the above (Formula 1); where ⁇ represents the number of bits of the uplink control information to be transmitted; MTM represents the bandwidth of the current subframe for PUSCH transmission, represented by the number of carriers; N s P y : H - initial indicates that the initial PUSCH transmission is used in addition to the Demodulation Reference Signal (DMRS) and the measurement reference signal (Sounding) The number of symbols outside the Reference Signal, SRS); M S P C USCH - initial indicates the bandwidth of the initial PUSCH transmission, expressed in the number of subcarriers; C indicates the corresponding code block after the CRC and the code block are divided by the transport block.
  • DMRS Demodulation Reference Signal
  • SRS Signal
  • M S P C USCH - initial indicates the bandwidth of the initial PUSCH transmission, expressed in the number of subcarriers; C indicates the corresponding code block after the CRC and the code block are divided by the transport block.
  • LTE-A Long Term Evolution Advanced
  • CA Carrier Aggregation
  • the carrier aggregation LTE system bandwidth can be regarded as a component carrier (CC), and each component carrier frequency can also be referred to as a cell (Cell), that is, one spectrum can be aggregated by n component carriers (Cell).
  • CC component carrier
  • Cell component carriers
  • the resources of one R10 UE are composed of n cells (component carriers) in the frequency domain, where one cell is called a primary cell and the other cells are called secondary cells.
  • multiple downlink subframes correspond to one uplink subframe, and each downlink subframe has multiple cells, and each cell may be transmitted by one transport block according to different transmission modes, or may be composed of two transport blocks.
  • PUCCH format 3 when ACK/NACK response information is sent by using formatlb with channel selection, bundling is not used for ACK/NACK response information of 4 bits or less, and ACK/NACK response information of more than 4 bits can be used.
  • the main purpose of the present invention is to provide a method for transmitting ACK/NACK response information on a physical uplink shared channel and a corresponding user terminal, and solving the problem that the ACK/NACK response information cannot be sent on the PUSCH in the carrier aggregation scenario. .
  • FIG. 3 is a flowchart of a method for sending response information according to the present invention.
  • the response information refers to correct or incorrect (ACK/NACK) response information fed back by the UE to the base station, and the main steps are as follows:
  • Step 302 In a scenario of carrier aggregation, the UE acquires an ACK/NACK response information bit sequence that needs to be sent according to related information.
  • Step 304 The UE calculates a number of coded modulation symbols required to transmit a bit sequence of the ACK/NACK response information on the PUSCH.
  • Step 306 The UE sends an ACK/NACK response message on the PUSCH.
  • the ACK/NACK response information bit sequence that the UE needs to send according to the related information in step 302 refers to: the number of downlink component carriers (or cells) configured by the UE according to the base station, the ratio of the uplink and downlink subframes configured, and each downlink configured.
  • the UE acquires a bit sequence of the ACK/NACK response information to be sent according to the feedback mode of the high layer configuration:
  • the ACK/NACK response information bit sequence to be transmitted is determined according to the ACK/NACK information in the mapping table of the channel selection manner;
  • the upper layer configuration sends the ACK/NACK response information in the manner of the format 3, the number of the downlink component carriers (or cells) configured by the UE, the transmission mode configured for each downlink component carrier (or cell), and the proportional relationship between the uplink and downlink subframes
  • the number of ACK/NACK response information bits that can be transmitted at most on the PUSCH is used to determine ACK/NACK response information to be transmitted, and the ACK/NACK response information to be transmitted is mapped into the bit sequence.
  • the component carrier (or cell) according to the pre-codeword stream, the order of the sub-frames, or the sub-frame of the first codeword stream, and then the component The order of the carriers (or cells), mapping the corresponding ACK/NACK response information into the bit sequence;
  • the ACK/NACK bit sequence can be obtained by one of the following methods:
  • Manner 1 When the ACK/NACK response information is mapped to the bit sequence, logically AND operation is performed on all ACK/NACK response information corresponding to the PDSCH of the two codeword streams, and the logical AND The ACK/NACK response information after operation is mapped into the corresponding bit sequence;
  • Manner 2 logically AND the two ACK/NACK response information corresponding to the PDSCH according to a predefined method, until the total number of bits of the ACK/NACK response information to be sent does not exceed M bits, and then the logical AND operation
  • the ACK/NACK response information is mapped into a corresponding bit sequence, wherein the predefined method is one of the following methods:
  • the ACK/NACK response information corresponding to the PDSCH corresponding to the PDSCH of the two codeword streams in all the secondary component carriers (or cells) is logically AND, the total number of bits of the ACK/NACK response information exceeds M bits, And logically ANDing the ACK/NACK response information corresponding to the PDSCH of the 2 codeword streams in the primary component carrier (or cell);
  • M is a fixed value agreed by the base station and the UE, Me ⁇ 20, 21, 22, 23, 24, 25, 26 ⁇
  • mapping the ACK/NACK response information into a bit sequence is one of the following methods:
  • Method 1 Mapping in accordance with a predefined component carrier (or cell), for the same
  • the ACK/NACK response information of a component carrier (or cell) is mapped according to the sequence of subframes or according to the value of the downlink assignment index (DAI) in the downlink grant information (DL assignment), and the ACK/released by the semi-static persistent scheduling is performed.
  • the NACK response information is located at the front or the end of the ACK/NACK response information fed back by the component carrier (or cell) in which it is located;
  • the predefined component carrier (or cell) sequence is a high-level configuration, or the predefined component carrier (or cell) sequence is a component carrier (or cell) index sequence, or the primary component carrier (or cell) is supplemented.
  • Component carrier (or cell) is a high-level configuration, or the predefined component carrier (or cell) sequence is a component carrier (or cell) index sequence, or the primary component carrier (or cell) is supplemented.
  • the number of ACK/NACK response information fed back by each component carrier (or cell) is determined by the configured number of downlink subframes and the transmission mode, or by the configured number of downlink subframes and the transmission mode, and the uplink grant information (UL grant).
  • the value of the downlink allocation index is determined;
  • Method 2 mapping according to the sequence of subframes, and ACK/NACK response information on the same subframe is sequentially mapped according to a predefined component carrier (or cell);
  • the predefined component carrier (or cell) sequence is a high-level configuration, or the predefined component carrier (or cell) sequence is a component carrier (or cell) index sequence, or the primary component carrier (or cell) is supplemented. Component carrier (or cell).
  • the UE when the UE does not detect the PDSCH on the configured corresponding downlink component carrier (or cell), the corresponding response information is set to NACK;
  • the base station configures that a certain codeword stream (transport block) in the two codeword streams (transport blocks) corresponding to the PDSCH is not enabled and the ACK/NACK response information corresponding to the PDSCH is not logically operated, then The response information of the codeword stream corresponding to the unenabled transport block is set to NACK;
  • the base station configures that a certain codeword stream in the two codeword streams (transport blocks) corresponding to the PDSCH is not enabled and sends the ACK/NACK response information corresponding to the PDSCH to perform logical AND operation, the disabling is disabled.
  • the ACK/NACK response information corresponding to the codeword stream (transport block) is set to ACK, or the logical and operation result of the ACK/NACK response information corresponding to the PDSCH is Enable ACK/NACK response information corresponding to the codeword stream (transport block);
  • the method for obtaining the ACK/NACK response information bit sequence to be transmitted is also applicable to transmitting the ACK/NACK response information in the format 3 on the PUCCH;
  • the correct response information (ACK) corresponds to a binary "1”
  • the error response information (NACK) corresponds to a binary "0.”
  • step 304 if the ACK/NACK response information is transmitted on the PUSCH, it is not encoded by the dual Reed-Muller (Dual RM) method, and the ACK/ is transmitted on the PUSCH.
  • the number of coded modulation symbols required for the bit sequence of the NACK response information is set, the number of bits O of the uplink control information to be transmitted is obtained by one of the following methods:
  • O is equal to the length of the bit sequence of the obtained ACK/NACK response information, where is the downlink assignment index in the uplink grant information UL grant, indicating the PDSCH sent by the base station to the UE.
  • the number of subframes, the maximum number of bits of the correct error response message corresponding to the PDSCH on the downlink component carrier (or cell) of the TB table, or 0 indicates that the ACK/NACK response message is logically and operationally fed back.
  • the code is coded by the Dual RM, and the number of coded modulation symbols required for the calculation is jointly calculated, and the number of bits of the uplink control information to be transmitted is calculated. Get it in one of the following ways:
  • the maximum number of ACK/NACK response messages, O max K * TB x , K indicates the number of downlink subframes in the configured uplink-downlink subframe ratio relationship, and the TB table is configured on the downlink component carrier (or cell) of the UE.
  • the maximum number of bits of the correct error response message corresponding to the PDSCH, or O max represents the maximum number of bits of the ACK/NACK response message that has been logically and operationally fed back;
  • the Dual RM is used.
  • the method of encoding is performed, and the number of coded modulation symbols required for calculation is independently calculated.
  • the number of bits O 1 , O 2 of the uplink control information to be transmitted during calculation is obtained by one of the following methods:
  • C ⁇ O 2 is the number of uplink control information bits to be transmitted when independently calculated, and / represents the maximum value of the total number of PDSCHs allocated to the ACK/NACK response information in the two RMs, where N represents Length of the bit sequence of the ACK/NACK response message;
  • N represents the length of the bit sequence of the obtained ACK/NACK response information
  • N , .
  • W or W min ( TB 0 when the UE
  • N indicates the length of the bit sequence of the obtained ACK/NACK response information, and indicates the number of downlink subframes in which the feedback ACK/NACK response message is scheduled in all component carriers (or cells).
  • C max K * 3 ⁇ 4 TB x
  • K represents the number of downlink subframes in the configured uplink-downlink subframe ratio relationship, and the maximum bit of the correct error response message corresponding to the PDSCH configured on the downlink component carrier (or cell) of the TB table a number, or 0, indicating the maximum number of bits of the ACK/NACK response message that has been logically and operationally fed back;
  • O 1 indicates the number of TB/NACK response information corresponding to the TB received by the UE in one Reed-Muller code
  • O 2 indicates that the TB corresponding to the ACK/NACK response information received by the UE is mapped in another Reed - The number in the Muller code.
  • the determining, according to the DAI in the uplink authorization information is that when a plurality of uplink authorization information is sent to the UE, the value of the DAI in the uplink authorization information is the same.
  • the UE sends the ACK/NACK response information on the PUSCH to: the UE encodes the generated ACK/NACK bit sequence according to the corresponding coding manner, and obtains the coded according to the number of the modulated modulation symbols.
  • the sequence is multiplexed with the data by channel interleaving and then transmitted on the PUSCH.
  • a user terminal provided by the present invention includes: an obtaining module, a calculating module, and a sending module, where the acquiring module is configured to acquire a bit sequence of ACK/NACK response information to be sent; and the calculating module is configured to calculate the ACK sent on the PUSCH. /NACK The number of coded modulation symbols required for the bit sequence of the response information; the transmitting module is configured to transmit the ACK/NACK response information on the PUSCH.
  • the foregoing modules are all configured to implement the ACK/NACK response information sending method provided by the present invention, and the specific technical solutions of the foregoing methods may be embodied in the functions of the modules and the interaction relationship between the modules, where No longer.
  • step 304 When the step 304 is not related to the step 302, the order of the two may be interchanged; the method for transmitting the ACK/NACK response information on the physical uplink shared channel according to the present invention effectively solves the carrier aggregation scenario.
  • FIG. 1 is a schematic diagram of a frame structure in a prior art FDD system
  • FIG. 2 is a schematic diagram of a frame structure in a prior art TDD system
  • FIG. 3 is a schematic flow chart of a method for transmitting response information according to the present invention.
  • Embodiment 1 of the present invention is a schematic diagram of Embodiment 1 of the present invention.
  • FIG. 5 is a schematic diagram of determining an ACK/NACK bit sequence according to Embodiment 1 of the present invention
  • FIG. 6 is a schematic diagram of determining an ACK/NACK bit sequence according to Embodiment 2 of the present invention
  • FIG. 7 is a third embodiment of the present invention.
  • FIG. 8 is a schematic diagram of determining an ACK/NACK bit sequence according to Embodiment 4 of Embodiment 2 of the present invention
  • FIG. 9 is a schematic diagram of determining an ACK/NACK bit sequence according to Embodiment 5 of Embodiment 2 of the present invention.
  • Embodiment 1 is a diagrammatic representation of Embodiment 1:
  • the base station configures 4 downlink component carriers (or cells) ⁇ DL CC#0, DL CC#1, DL CC#2, DL CC#3 ⁇ for the UE, and both need
  • the 2-bit ACK/NACK response information is fed back, and it is assumed that an uplink subframe needs to simultaneously feed back downlink subframes #n #n+1 and #n+2 - ACK/NACK response information of 3 downlink subframes; PUSCH
  • the ACK/NACK response information that can be transmitted at most is 40 bits; the ACK/NACK response information is not encoded by the Dual RM code when transmitted on the PUSCH, and the PUSCH is transmitted according to the UL grant, and corresponds to only one transport block.
  • Step 402 The UE determines the ACK/NACK response information that needs to be fed back according to the number of downlink component carriers (or cells) configured by the base station, the configured uplink-downlink ratio, and the configured transmission mode of each downlink component carrier (or cell).
  • Bit sequence The terminal maps the corresponding ACK/NACK response information to the bit sequence according to the sub-frame of the pre-codeword stream, and then the component carrier (or cell), wherein the length of the bit sequence is 24;
  • Step 404 The UE calculates, according to the related information, the number of coding symbols required to send the ACK/NACK response information bit sequence, and calculates the number of coding symbols, (the value is determined according to the following manner:
  • the UE calculates the required code modulator according to the length of the obtained bit sequence Number of numbers;
  • Step 406 The UE encodes the generated bit sequence of the ACK/NACK response information according to the corresponding coding manner, obtains the encoded sequence according to the number of the modulated modulation symbols, and multiplexes the data by channel interleaving, and then Sent on PUSCH.
  • Embodiment 2 is a diagrammatic representation of Embodiment 1:
  • Step 602 The UE according to the number of downlink component carriers (or cells) configured by the base station, the configured uplink-downlink ratio, and the configured transmission mode of each downlink component carrier (or cell). Determining a bit sequence of ACK/NACK response information that needs to be fed back, since the ACK/NACK response information that can be transmitted at the PUSCH is 20 bits; the ACK/NACK bit sequence is obtained according to the following manner;
  • Manner 1 As shown in Figure 5, after logically ANDing the ACK/NACK response information corresponding to all PDSCHs containing 2 codeword streams, the obtained ACK/ is obtained according to the order of the sub-subcarriers (or cells). NACK response information is mapped into the corresponding bit sequence;
  • Manner 2 As shown in FIG. 6, where DL CC#0 is a primary component carrier (or primary cell), and DL CC#l/2/3 is a secondary component carrier (or cell), and the secondary component carrier (or cell) After performing logical AND operation on the ACK/NACK response information corresponding to the PDSCH of the 2 codeword streams, the obtained ACK/NACK response information is mapped to the corresponding bit sequence according to the order of the sub-subframe component carrier (or cell). ;
  • Mode 3 As shown in FIG. 7, it is assumed that DL CC#0 has the highest priority, and DL CC#3 has the lowest priority, because only the PDSCH including 2 codeword streams in the lowest priority DL CC3 needs to be corresponding.
  • the logical AND operation of the ACK/NACK response information can make the information bits not exceed M, so the ACK/NACK response information corresponding to the PDSCH of the two codeword streams in the DL CC#3 is logically operated, according to the first subframe.
  • the sequence of the post-component carrier (or cell) maps the obtained ACK/NACK response information into the corresponding bit sequence;
  • Manner 4 As shown in FIG. 8, it is only necessary to logically AND operate the ACK/NACK response information corresponding to the PDSCH of the 2 codeword streams in all component carriers (or cells) corresponding to the subframe #n. Not more than 20, all the ACK/NACK response information corresponding to the PDSCH including the 2 codeword streams in the subframe #n is logically ANDed, and the obtained ACK/ is obtained in the order of the sub-subframe component carrier (or cell). The NACK response information is mapped into the corresponding bit sequence.
  • Method 5 As shown in FIG.
  • the information bit does not exceed 20, so according to the preamble
  • the order of the post-frame component carriers (or cells) sorts all PDSCHs, in order from back to front.
  • DL CC#3 the ACK/NACK response information corresponding to the PDSCH on the subframe #n+2 is logically ANDed, and the obtained ACK/NACK response information is mapped to the corresponding one in the order of the first subframe after the component carrier (or cell).
  • Step 604 The UE calculates, according to the related information, the number of coding symbols required to send the ACK/NACK response information bit sequence, and calculates the number of coding symbols:
  • the number of coded modulation symbols required for the calculation is jointly calculated, and the value of O can be determined according to one of the following ways:
  • the maximum number of bits of the ACK/NACK response message, O max K* TB x , where K is the number of downlink subframes in the configured uplink-downlink subframe ratio relationship, and the TB table is configured for each downlink component carrier of the UE (or The maximum error number of the correct error response message corresponding to the PDSCH on the cell, or O max indicates the maximum number of bits of the ACK/NACK response message that is fed back through the logical AND operation; if the ACK/NACK response message is transmitted on the PUSCH, the calculation is performed.
  • the number of coded modulation symbols required is calculated independently (the value can be determined according to one of the following ways:
  • C ⁇ O 2 is the number of uplink control information bits to be transmitted when independently calculated, and / represents the maximum value of the total number of PDSCHs allocated to the ACK/NACK response information in the two RMs, where N represents Length of the bit sequence of the ACK/NACK response message;
  • N represents the length of the bit sequence of the obtained ACK/NACK response information
  • N , .
  • W or W min ( TB 0
  • C max K * 3 ⁇ 4 TB x
  • K represents the number of downlink subframes in the configured uplink-downlink subframe ratio relationship, and the maximum bit of the correct error response message corresponding to the PDSCH configured on the downlink component carrier (or cell) of the TB table a number, or 0, indicating the maximum number of bits of the ACK/NACK response message that has been logically and operationally fed back;
  • O 1 indicates that the TB corresponding to the ACK/NACK response information received by the UE is mapped in a Reed - the number in the Muller code; 0 2 indicates the number of TB/NACK response information corresponding to the TB received by the UE in another Reed-Muller code.
  • Step 606 The UE encodes the generated ACK/NACK bit sequence according to a corresponding coding manner, obtains a coded sequence according to the number of coded modulation symbols, and multiplexes the data by channel interleaving, and then transmits the data on the PUSCH. .
  • embodiments of the present invention also provide a user terminal. Since the embodiments described below are for implementing the foregoing method embodiments, the modules in the user terminal are all designed to implement the foregoing method, and the modules in the user terminal can be unambiguously derived from the foregoing method.
  • the present invention is not limited to the embodiments described below, and any apparatus and modules that can implement the above methods should be included in the scope of the present invention. Also, in the following description, the same contents as the foregoing methods are omitted here to save space.
  • a user terminal provided by the present invention includes: an obtaining module, a calculating module, and a sending module, where the acquiring module is configured to acquire a bit sequence of ACK/NACK response information to be sent; and the calculating module is configured to calculate the ACK sent on the PUSCH. /NACK The number of coded modulation symbols required for the bit sequence of the response information; the transmitting module is configured to transmit the ACK/NACK response information on the PUSCH.
  • the foregoing modules are all configured to implement the ACK/NACK response information sending method provided by the present invention, and the specific technical solutions of the foregoing methods may be embodied in the functions of the modules and the interaction relationship between the modules, where No longer.
  • the ACK/NACK response information provided by the present invention is transmitted on a physical uplink shared channel.
  • the UE first acquires a bit sequence of ACK/NACK response information to be transmitted, and then calculates the ACK to be sent on the PUSCH.
  • /NACK The number of coded modulation symbols required for the bit sequence of the response information, and finally the ACK/NACK response information is transmitted on the PUSCH.
  • the invention effectively solves the problem that the ACK/NACK response information is sent on the PUSCH in the carrier aggregation scenario.

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Abstract

Disclosed are a method for sending acknowledgement information and a user equipment, for solving the problem that ACK/NACK acknowledgement information cannot be transmitted on a PUSCH in a carrier aggregation scenario. According to the present invention, in the carrier aggregation scenario, a UE first acquires a bit sequence of the ACK/NACK acknowledgement information to be transmitted, then calculates the number of code modulation symbols required for transmitting the bit sequence of the ACK/NACK acknowledgement information on the PUSCH, and finally sends the ACK/NACK acknowledgement information on the PUSCH. The present invention effectively solves the problem that the ACK/NACK acknowledgement information cannot be transmitted on the PUSCH in the carrier aggregation scenario.

Description

一种应答信息的发送方法及用户终端 技术领域  Method for transmitting response information and user terminal
本发明涉及移动无线通信领域, 特别是涉及无线通信系统中应答信息 的发送方法及用户终端 (User Equipment, UE )。 背景技术  The present invention relates to the field of mobile wireless communications, and in particular to a method for transmitting response information and a user equipment (User Equipment, UE) in a wireless communication system. Background technique
长期演进 ( Long Term Evolution, LTE )系统中的无线帧( Radio Frame ) 包括频分双工 ( Frequency Division Duplex, FDD )模式和时分双工 ( Time Division Duplex, TDD )模式的帧结构。 如图 1所示, 在 FDD模式的帧结 构中, 一个 10 毫秒(ms ) 的无线帧由二十个长度为 0.5ms、 编号为 0~19 的时隙 (slot )组成, 时隙 2i和 2i+l组成长度为 1ms的子帧 ( subframe ) i (其中, 0≤i≤9 )。 如图 2所示, 在 TDD模式的帧结构中, 一个 10ms的无 线帧由两个长为 5ms的半帧 ( half frame )组成, 一个半帧中包括 5个长度 为 1ms的子帧, 子帧 i定义为 2个长为 0.5ms的时隙 2i和 2i+l的组合(其 中, 0≤i≤9 )。  The Radio Frame in the Long Term Evolution (LTE) system includes a Frequency Division Duplex (FDD) mode and a Time Division Duplex (TDD) mode frame structure. As shown in Figure 1, in the FDD mode frame structure, a 10 msec (ms) radio frame consists of twenty slots of length 0.5 ms and numbers 0-19, slots 2i and 2i. +l constitutes a subframe (frame) i of length 1 ms (where 0 ≤ i ≤ 9). As shown in FIG. 2, in the frame structure of the TDD mode, a 10 ms radio frame is composed of two half frames of 5 ms length, and one subframe includes five subframes of length 1 ms, and subframes. i is defined as a combination of two time slots 2i and 2i+1 that are 0.5 ms long (where 0 ≤ i ≤ 9).
在上述两种帧结构中,釆用标准循环前缀( Normal Cyclic Prefix , Normal In the above two frame structures, the standard cyclic prefix (Normal Cyclic Prefix, Normal) is used.
CP ) 时, 一个时隙中包含 7个符号, 釆用扩展循环前缀(Extended Cyclic Prefix, Extended CP ) 时, 一个时隙中包含 6个符号。 In CP), one slot contains 7 symbols, and when Extended Cyclic Prefix (Extended CP) is used, one slot contains 6 symbols.
各子帧支持的上下行配置如表 1所示。 其中, "D"表示专用于下行传输 的子帧, "U"表示专用于上行传输的子帧, "S"表示用于 DwPTS ( Downlink Pilot Time Slot, 下行导频时隙)、 保护间隔 ( Guard Period, GP )和 UpPTS ( Uplink Pilot Time Slot , 上行导频时隙)这三个域的特殊子帧。 表 1 各子帧支持的上下行配置示意表 The uplink and downlink configurations supported by each subframe are shown in Table 1. Wherein, "D" denotes a subframe dedicated to downlink transmission, "U" denotes a subframe dedicated for uplink transmission, and "S" denotes for DwPTS (Downlink Pilot Time Slot), guard interval (Guard) Special sub-frames of the three fields, Period, GP) and UpPTS (Uplink Pilot Time Slot). Table 1 Schematic diagram of the uplink and downlink configuration supported by each sub-frame
Figure imgf000003_0001
Figure imgf000003_0001
从上表可以看出, LTE TDD支持 5ms和 10ms的上下行切换周期。 如 果下行到上行转换点周期为 5ms, 特殊子帧会存在于两个半帧中; 如果下 行到上行转换点周期为 10ms, 特殊子帧只存在于第一个半帧中; 子帧 #0和 子帧 #5 以及 DwPTS总是用于下行传输; UpPTS和紧跟于特殊子帧后的子 帧专用于上行传输。  As can be seen from the above table, LTE TDD supports 5ms and 10ms uplink and downlink switching cycles. If the downlink to uplink transition point period is 5ms, the special subframe will exist in two fields; if the downlink to uplink transition point period is 10ms, the special subframe exists only in the first field; subframe #0 and sub Frame #5 and DwPTS are always used for downlink transmission; UpPTS and subframes immediately following the special subframe are dedicated to uplink transmission.
在频分双工 FDD系统中, 由于上下行子帧是——对应的, 所以当物理 下行共享信道 ( Phyasical Downlink Shared Channel, PDSCH )只包含一个 码字流时, 用户终端要反馈 1比特的 ACK/NACK应答信息, 当 PDSCH包 含两个码字流时, UE要反馈 2比特的 ACK/NACK应答信息, 当 UE在当 前子帧没有 PUSCH ( Physical Uplink Share Channel, 物理上行共享信道) 要发送时, UE将在 PUCCH ( Physical Uplink Control Channel, 物理上行控 制信道 )上釆用格式 la/lb来发送这 1比特或 2比特的 ACK/NACK应答信 息; 而当 UE在当前子帧有 PUSCH发送时, 则 UE将这 1比特或 2比特信 息, 经过一定的 ACK/NACK状态到相应比特的映射, 信道编码、 加扰、 调 制后与数据复用在一起, 然后在 PUSCH上发送。  In the frequency division duplex FDD system, since the uplink and downlink subframes are corresponding, when the physical downlink shared channel (PDSCH) contains only one codeword stream, the user terminal needs to feed back a 1-bit ACK. /NACK response information, when the PDSCH includes two codeword streams, the UE needs to feed back 2 bits of ACK/NACK response information, when the UE does not have a PUSCH (Physical Uplink Share Channel) to transmit in the current subframe. The UE will transmit the 1-bit or 2-bit ACK/NACK response information in the format la/lb on the PUCCH (Physical Uplink Control Channel); and when the UE has the PUSCH transmission in the current subframe, The UE maps the 1-bit or 2-bit information to a corresponding bit through a certain ACK/NACK state, and performs channel coding, scrambling, and modulation, and then multiplexes with the data, and then transmits the signal on the PUSCH.
在时分双工 TDD 系统中, 由于上下行子帧不是——对应的, 也就是 说多个下行子帧对应的 ACK/NACK 应答信息需要在一个上行子帧的 PUCCH/PUSCH信道上发送, 其中上行子帧对应的下行子帧集合组成了绑 定窗口 ( bundling window )。 在 LTE TDD里, 定义两种 ACK/NACK应答信 息的发送: 一种是 ACK/NACK绑定( ACK/NACK bundling )方法, 一种是 ACK/NACK复用 (multiplexing ) 方法: 高层配置 UE釆用 bundling还是 mulitplexing的方法反馈 ACK/NACK bundling方法的基本思想是将需要在 该上行子帧反馈的各个下行子帧对应的码字流的 ACK/NACK 消息进行逻 辑与运算(time domain bundling ), 得到 1比特或 比特的 ACK/NACK应 答信息, 当 UE在当前子帧没有 PUSCH要发送时, UE将在 PUCCH上釆 用格式 la/lb来发送这 1比特或 2比特的 ACK/NACK应答信息; 当 UE在 当前子帧有 PUSCH发送时, UE将这 1比特或 2比特信息, 经过一定的信 道编码、 信道交织后在 PUSCH上发送。 multiplexing方法的核心思想是利 用不同的 PUCCH信道和该信道上不同的调制符号来表示需要在该上行子 帧反馈的下行子帧的不同反馈状态, 如果下行子帧上有多个传输块, 那么 先将下行子帧的多个传输块反馈的 ACK/NACK 进行逻辑与 ( spatial bundling )后再进行信道选择, 然后使用 PUCCH format lb发送。 当 UE在 当前子帧没有 PUSCH要发送时, UE将在 PUCCH上釆用格式 lb联合信道 选择 ( format lb with channel selection )的方式来发送这多个 ACK/NACK应 答信息; 当 UE在当前子帧有 PUSCH发送时, 则 UE将多个比特信息, 经 过一定的 ACK/NACK状态到相应比特的映射, 信道编码、信道交织后与数 据复用在一起, 然后在 PUSCH上发送。 In the time division duplex TDD system, since the uplink and downlink subframes are not corresponding, that is, the ACK/NACK response information corresponding to the multiple downlink subframes needs to be sent on the PUCCH/PUSCH channel of one uplink subframe, where the uplink The set of downlink subframes corresponding to the subframe constitutes a bundling window. In LTE TDD, two types of ACK/NACK response information are defined: one is an ACK/NACK bundling method, and the other is ACK/NACK multiplexing method: The high-level configuration of the UE uses bundling or mulitplexing. The basic idea of the ACK/NACK bundling method is to use the ACK of the codeword stream corresponding to each downlink subframe that needs to be fed back in the uplink subframe. The /NACK message performs a time domain bundling to obtain a 1-bit or bit ACK/NACK response message. When the UE does not transmit a PUSCH in the current subframe, the UE will transmit the format la/lb on the PUCCH. The 1-bit or 2-bit ACK/NACK response information; when the UE has a PUSCH transmission in the current subframe, the UE transmits the 1-bit or 2-bit information on the PUSCH after a certain channel coding and channel interleaving. The core idea of the multiplexing method is to use different PUCCH channels and different modulation symbols on the channel to indicate different feedback states of the downlink subframes that need to be fed back in the uplink subframe. If there are multiple transport blocks on the downlink subframe, then The ACK/NACK fed back by the plurality of transport blocks of the downlink subframe is logically (bundled) and then channel selected, and then transmitted using PUCCH format lb. When the UE has no PUSCH to transmit in the current subframe, the UE will transmit the multiple ACK/NACK response information in the format lb with channel selection on the PUCCH; when the UE is in the current subframe When there is PUSCH transmission, the UE transmits a plurality of bit information through a certain ACK/NACK state to a corresponding bit, and performs channel coding, channel interleaving, and data multiplexing, and then transmits on the PUSCH.
其中, 应答信息在 PUSCH上传输时的编码过程包括: 4.M c (公式 1 )
Figure imgf000004_0001
The encoding process when the response information is transmitted on the PUSCH includes: 4.M c (Formula 1)
Figure imgf000004_0001
首先根据上述(公式 l )计算所需编码符号的个数 ; 其中 Ο表示待 发送的上行控制信息的比特数; M ™表示当前子帧用于 PUSCH传输的带 宽, 以载波个数表示; Ns P y:H- initial表示初始 PUSCH传输中用于除了解调参考 信号 ( Demodulation Reference Signal, DMRS )和测量参考信号 ( Sounding Reference Signal, SRS )外的符号个数; MS P C USCH- initial表示初始 PUSCH传输时 的带宽, 以子载波个数表示; C表示该传输块经 CRC和码块分割后对应的 码块个数; 表示该传输块的每个码块对应的比特数; 对于相同的传输块, C 、 和 MS P C USCH-INITIAL从初始的 PDCCH中获得; 当没有初始的 DCI格式 0的 PDCCH 时, MS P C USCH- INITIAL、 C和 可以通过以下两种方式获取: (1 ) 当初始 PUSCH釆用半静态调度时,可以从最近的半静态调度配置的 PDCCH获取; ( 2 ) 当 PUSCH由随机接入响应授权触发时, 则从相同传输块对应的随机 接入响应授权获取;
Figure imgf000005_0001
该值由高层配置; 然后进 行信道编码, 将 ACK/NACK应答信息编码后的比特重复, 直到满足目标长 度 2^ = 2^ * 为止, 编码后的信息比特分别记为 [^ ,^ …,^]、 根据调制阶数, 生成对应的编码调制序列 [ ^, …, ^ ] , 将
First, the number of required coding symbols is calculated according to the above (Formula 1); where Ο represents the number of bits of the uplink control information to be transmitted; MTM represents the bandwidth of the current subframe for PUSCH transmission, represented by the number of carriers; N s P y : H - initial indicates that the initial PUSCH transmission is used in addition to the Demodulation Reference Signal (DMRS) and the measurement reference signal (Sounding) The number of symbols outside the Reference Signal, SRS); M S P C USCH - initial indicates the bandwidth of the initial PUSCH transmission, expressed in the number of subcarriers; C indicates the corresponding code block after the CRC and the code block are divided by the transport block. Number; indicates the number of bits corresponding to each code block of the transport block; for the same transport block, C and M S P C USCH - INITIAL are obtained from the initial PDCCH; when there is no PDCCH of the initial DCI format 0, M S P C USCH - INITIAL , C and can be obtained in the following two ways: (1) When the initial PUSCH is used for semi-persistent scheduling, it can be obtained from the PDCCH of the most recent semi-persistent scheduling configuration; (2) When the PUSCH is randomly When the access response authorization is triggered, the access is obtained from the random access response authorization corresponding to the same transport block;
Figure imgf000005_0001
The value is configured by the upper layer; then channel coding is performed, and the bits encoded by the ACK/NACK response information are repeated until the target length 2^ = 2^* is satisfied, and the encoded information bits are respectively recorded as [^, ^ ..., ^ ], according to the modulation order, generate a corresponding coded modulation sequence [^, ..., ^],
[qACK,qACK,qACK,...,qACK ]和编码后的数据和 /或其他编码后的上行控制信息进 行信道交织后传输。 [q ACK , q ACK , q ACK , . . . , q ACK ] and the encoded data and/or other encoded uplink control information are channel interleaved and transmitted.
为 了 满足高级国 际电信联盟 ( International Telecommunication Union- Advanced, ITU-Advanced ) 的要求, 作为 LTE演进标准的高级长期 演进( Long Term Evolution Advanced, LTE-A )系统需要支持更大的系统带 宽(最高可达 100MHz ), 并需要后向兼容 LTE现有的标准。 在现有 LTE系 统的基础上, 可以通过将 LTE系统的带宽进行合并来获得更大的带宽, 这 种技术称为载波聚合(Carrier Aggregation, CA )技术。 该技术能够提高 IMT-Advance系统的频谱利用率、緩解频谱资源紧缺,进而优化频谱资源的 利用。所述载波聚合的 LTE系统带宽可以看作分量载波( Component Carrier, CC ), 每个分量载频也可以称为一个小区 (Cell ), 也就是说一个频谱可以 由 n个分量载波(Cell ) 聚合而成。 一个 R10 UE的资源由频域的 n个小区 (分量载波)构成, 其中, 一个小区称为主小区 (Primary cell ), 其余小区 称为辅小区 ( Secondary cell )。 载波聚合场景下, 多个下行子帧对应一个上行子帧, 并且, 每个下行 子帧上有多个小区, 每个小区根据传输模式不同可以由一个传输块传输, 也可以由两个传输块传输, 现有技术中规定: LTE-A 时分双工系统中, 当 ACK/NACK应答信息在 PUCCH上发送时, 定义了两种发送方式: 釆用 PUCCH format lb with channel selection以及 DFT-s-OFDM方式(PUCCH format3 ),釆用 formatlb with channel selection发送 ACK/NACK应答信息时, 对于小于等于 4比特的 ACK/NACK应答信息, 不釆用 bundling, 对于大于 4比特的 ACK/NACK应答信息, 可以釆用 spatial bundling 和 time-domain bundling, 釆用 format3发送 ACK/NACK应答信息时, 发送的 ACK/NACK 应答信息的最大负载是 20比特, 但是现有技术没有给出 ACK/NACK应答 信息在 PUSCH传输时的映射关系和负载大小的确定方法, 从而无法实现 ACK/NACK应答信息在 PUSCH上的传输。 发明内容 In order to meet the requirements of the International Telecommunication Union-Advanced (ITU-Advanced), the Long Term Evolution Advanced (LTE-A) system, which is an LTE evolution standard, needs to support a larger system bandwidth (up to 100MHz), and need to be backward compatible with LTE existing standards. On the basis of the existing LTE system, a larger bandwidth can be obtained by combining the bandwidths of the LTE system. This technology is called Carrier Aggregation (CA) technology. This technology can improve the spectrum utilization of the IMT-Advance system, alleviate the shortage of spectrum resources, and optimize the utilization of spectrum resources. The carrier aggregation LTE system bandwidth can be regarded as a component carrier (CC), and each component carrier frequency can also be referred to as a cell (Cell), that is, one spectrum can be aggregated by n component carriers (Cell). Made. The resources of one R10 UE are composed of n cells (component carriers) in the frequency domain, where one cell is called a primary cell and the other cells are called secondary cells. In a carrier aggregation scenario, multiple downlink subframes correspond to one uplink subframe, and each downlink subframe has multiple cells, and each cell may be transmitted by one transport block according to different transmission modes, or may be composed of two transport blocks. Transmission, as defined in the prior art: In the LTE-A time division duplex system, when the ACK/NACK response information is transmitted on the PUCCH, two transmission modes are defined: PUPUCCH format lb with channel selection and DFT-s-OFDM In the mode (PUCCH format3), when ACK/NACK response information is sent by using formatlb with channel selection, bundling is not used for ACK/NACK response information of 4 bits or less, and ACK/NACK response information of more than 4 bits can be used. With spatial bundling and time-domain bundling, when sending ACK/NACK response information using format3, the maximum payload of the ACK/NACK response message sent is 20 bits, but the prior art does not give ACK/NACK response information during PUSCH transmission. The mapping relationship and the method of determining the load size, so that the transmission of the ACK/NACK response information on the PUSCH cannot be implemented. Summary of the invention
有鉴于此,本发明的主要目的在于提供一种 ACK/NACK应答信息在物 理上行共享信道上的传输方法及相应的用户终端, 解决载波聚合场景下无 法在 PUSCH上发送 ACK/NACK应答信息的问题。  In view of this, the main purpose of the present invention is to provide a method for transmitting ACK/NACK response information on a physical uplink shared channel and a corresponding user terminal, and solving the problem that the ACK/NACK response information cannot be sent on the PUSCH in the carrier aggregation scenario. .
为达到上述目的, 本发明的技术方案是这样实现的:  In order to achieve the above object, the technical solution of the present invention is achieved as follows:
图 3 为本发明提供的一种应答信息的发送方法的流程图, 所述应答信 息指 UE向基站反馈的正确或错误(ACK/NACK )应答信息, 主要步骤如 下所示:  FIG. 3 is a flowchart of a method for sending response information according to the present invention. The response information refers to correct or incorrect (ACK/NACK) response information fed back by the UE to the base station, and the main steps are as follows:
步骤 302 : 载波聚合的场景下, UE 根据相关信息获取需要发送的 ACK/NACK应答信息比特序列;  Step 302: In a scenario of carrier aggregation, the UE acquires an ACK/NACK response information bit sequence that needs to be sent according to related information.
步骤 304: UE计算在 PUSCH上发送所述 ACK/NACK应答信息的比特 序列所需的编码调制符号个数;  Step 304: The UE calculates a number of coded modulation symbols required to transmit a bit sequence of the ACK/NACK response information on the PUSCH.
步骤 306: UE在 PUSCH上发送 ACK/NACK应答信息; 其中步骤 302中 UE根据相关信息获取需要发送的 ACK/NACK应答信 息比特序列是指: UE根据基站配置的下行分量载波(或小区)数、 配置的 上下行子帧比例关系、 配置的每个下行分量载波(或小区) 的传输模式和 PUSCH上至多能发送的 ACK/NACK应答信息比特的个数来确定需要发送 的 ACK/NACK应答信息, 将所述需要发送的 ACK/NACK应答信息映射到 对应的比特序列; Step 306: The UE sends an ACK/NACK response message on the PUSCH. The ACK/NACK response information bit sequence that the UE needs to send according to the related information in step 302 refers to: the number of downlink component carriers (or cells) configured by the UE according to the base station, the ratio of the uplink and downlink subframes configured, and each downlink configured. The transmission mode of the component carrier (or cell) and the number of ACK/NACK response information bits that can be transmitted at the PUSCH to determine the ACK/NACK response information to be transmitted, and mapping the ACK/NACK response information to be transmitted to the corresponding Bit sequence
或步骤 302 中, UE 根据高层配置的反馈模式获取需要发送的 ACK/NACK应答信息的比特序列:  Or in step 302, the UE acquires a bit sequence of the ACK/NACK response information to be sent according to the feedback mode of the high layer configuration:
如果高层配置釆用格式 lb联合信道选择的方式发送 ACK/NACK应答 信息,则根据信道选择方式的映射表中的 ACK/NACK信息来确定需要发送 的 ACK/NACK应答信息比特序列;  If the upper layer configuration sends the ACK/NACK response information in the manner of the format lb joint channel selection, the ACK/NACK response information bit sequence to be transmitted is determined according to the ACK/NACK information in the mapping table of the channel selection manner;
如果高层配置釆用格式 3 的方式发送 ACK/NACK应答信息, 则根据 UE配置的下行分量载波(或小区)数、 每个下行分量载波(或小区)配置 的传输模式、 上下行子帧比例关系和 PUSCH上至多能发送的 ACK/NACK 应答信息比特的个数来确定需要发送的 ACK/NACK应答信息,并将所述需 要发送的 ACK/NACK应答信息映射到比特序列中。  If the upper layer configuration sends the ACK/NACK response information in the manner of the format 3, the number of the downlink component carriers (or cells) configured by the UE, the transmission mode configured for each downlink component carrier (or cell), and the proportional relationship between the uplink and downlink subframes The number of ACK/NACK response information bits that can be transmitted at most on the PUSCH is used to determine ACK/NACK response information to be transmitted, and the ACK/NACK response information to be transmitted is mapped into the bit sequence.
进一步说明, 如果在 PUSCH上至多能发送 40比特的 ACK/NACK应 答信息, 则根据先码字流后分量载波(或小区), 再子帧的顺序, 或先码字 流后子帧, 再分量载波(或小区)的顺序, 将相应的 ACK/NACK应答信息 映射到比特序列中去;  Further, if at most 40 bits of ACK/NACK response information can be transmitted on the PUSCH, the component carrier (or cell) according to the pre-codeword stream, the order of the sub-frames, or the sub-frame of the first codeword stream, and then the component The order of the carriers (or cells), mapping the corresponding ACK/NACK response information into the bit sequence;
进一步说明,如果在 PUSCH上至多能发送 M比特的 ACK/NACK应答 信息, 且当前需要发送的 ACK/NACK应答信息超过 M比特时, 可以通过 以下方式之一得到 ACK/NACK比特序列:  Further, if the M-bit ACK/NACK response information can be transmitted at most on the PUSCH, and the ACK/NACK response information that needs to be transmitted exceeds the M-bit, the ACK/NACK bit sequence can be obtained by one of the following methods:
方式一: ACK/NACK应答信息映射到比特序列时, 将所有包含 2个码 字流的 PDSCH对应的 ACK/NACK应答信息进行逻辑与操作后, 将逻辑与 操作后的 ACK/NACK应答信息映射到对应比特序列中; Manner 1: When the ACK/NACK response information is mapped to the bit sequence, logically AND operation is performed on all ACK/NACK response information corresponding to the PDSCH of the two codeword streams, and the logical AND The ACK/NACK response information after operation is mapped into the corresponding bit sequence;
方式二: 按照预定义的方法将 PDSCH对应的 2个 ACK/NACK应答信 息进行逻辑与操作,直到需要发送的 ACK/NACK应答信息的总比特数不超 过 M比特为止, 然后将逻辑与操作后的 ACK/NACK应答信息映射到对应 比特序列中, 其中所述的预定义的方法为以下方法之一:  Manner 2: logically AND the two ACK/NACK response information corresponding to the PDSCH according to a predefined method, until the total number of bits of the ACK/NACK response information to be sent does not exceed M bits, and then the logical AND operation The ACK/NACK response information is mapped into a corresponding bit sequence, wherein the predefined method is one of the following methods:
( 1 )将所有辅分量载波(或小区) 中包含 2个码字流的 PDSCH对应 的 ACK/NACK应答信息进行逻辑与操作;  (1) logically AND operation the ACK/NACK response information corresponding to the PDSCH of the two codeword streams in all the secondary component carriers (or cells);
更进一步说明, 如果将所有辅分量载波(或小区) 中包含 2个码字流 的 PDSCH对应的 ACK/NACK应答信息进行逻辑与操作后的 ACK/NACK 应答信息的总比特数还超过 M比特, 再将主分量载波(或小区) 中包含 2 个码字流的 PDSCH对应的 ACK/NACK应答信息进行逻辑与操作;  Further, if the ACK/NACK response information corresponding to the PDSCH corresponding to the PDSCH of the two codeword streams in all the secondary component carriers (or cells) is logically AND, the total number of bits of the ACK/NACK response information exceeds M bits, And logically ANDing the ACK/NACK response information corresponding to the PDSCH of the 2 codeword streams in the primary component carrier (or cell);
( 2 )按照分量载波(或小区)优先级从低到高的顺序, 将所述分量载 波(或小区) 中所有包含 2个码字流的 PDSCH对应的 ACK/NACK应答信 息进行逻辑与操作, 直到 ACK/NACK应答信息的总比特数不超过 M为止; (2) logically and operatively ACK/NACK response information corresponding to all PDSCHs of the two codeword streams in the component carrier (or cell) according to the order of the component carrier (or cell) from low to high. Until the total number of bits of the ACK/NACK response message does not exceed M;
( 3 )按照子帧先后顺序, 将子帧对应的所有分量载波(或小区) 中包 含 2个码字流的 PDSCH对应的 ACK/NACK应答信息进行逻辑与操作, 直 到 ACK/NACK应答信息的总比特数不超过 M为止; (3) logically AND-operating the ACK/NACK response information corresponding to the PDSCH of the two codeword streams in all component carriers (or cells) corresponding to the subframe according to the sequence of the subframes until the total of the ACK/NACK response information The number of bits does not exceed M;
( 4 )按照先子帧后分量载波(小区)或先分量载波(或小区)后子帧 的顺序将所有 PDSCH排序,按照从后向前或从前向后的顺序, 逐个的将包 含 2个码字流的 PDSCH对应的 ACK/NACK应答信息进行逻辑与操作, 直 到 ACK/NACK应答信息的总比特数不超过 M为止;  (4) Sort all PDSCHs according to the order of the sub-frame post-component carrier (cell) or the first component carrier (or cell) sub-frame, and include 2 codes one by one in the order from back to front or from front to back. The ACK/NACK response information corresponding to the PDSCH of the word stream is logically ANDed until the total number of bits of the ACK/NACK response information does not exceed M;
更进一步说明 , M 是基站和 UE 约定好的 固定的值, Me {20,21,22,23,24,25,26}  Further, M is a fixed value agreed by the base station and the UE, Me {20, 21, 22, 23, 24, 25, 26}
在将所述 ACK/NACK应答信息映射到比特序列中时,所述映射的方法 为以下方法之一:  When mapping the ACK/NACK response information into a bit sequence, the mapping method is one of the following methods:
方法一: 按照预先定义的分量载波(或小区)顺序进行映射, 对于同 一分量载波(或小区)的 ACK/NACK应答信息按照子帧先后顺序映射或者 按照下行授权信息( DL assignment )中的下行分配索引 ( DAI )的取值进行 映射, 半静态持续调度释放的 ACK/NACK应答信息位于其所在分量载波 (或小区 )反馈的 ACK/NACK应答信息最前面或最后面; Method 1: Mapping in accordance with a predefined component carrier (or cell), for the same The ACK/NACK response information of a component carrier (or cell) is mapped according to the sequence of subframes or according to the value of the downlink assignment index (DAI) in the downlink grant information (DL assignment), and the ACK/released by the semi-static persistent scheduling is performed. The NACK response information is located at the front or the end of the ACK/NACK response information fed back by the component carrier (or cell) in which it is located;
其中, 预定义的分量载波(或小区)顺序为高层配置, 或者, 预定义 的分量载波(或小区)顺序为分量载波(或小区) 索引顺序, 或者, 先主 分量载波(或小区)再辅分量载波(或小区);  The predefined component carrier (or cell) sequence is a high-level configuration, or the predefined component carrier (or cell) sequence is a component carrier (or cell) index sequence, or the primary component carrier (or cell) is supplemented. Component carrier (or cell);
每个分量载波(或小区 )反馈的 ACK/NACK应答信息数量由配置的下 行子帧数量和传输模式确定, 或者, 由配置的下行子帧数量和传输模式、 上行授权信息 (UL grant ) 中的下行分配索引的取值确定;  The number of ACK/NACK response information fed back by each component carrier (or cell) is determined by the configured number of downlink subframes and the transmission mode, or by the configured number of downlink subframes and the transmission mode, and the uplink grant information (UL grant). The value of the downlink allocation index is determined;
方法二: 按照子帧的先后顺序进行映射, 同一个子帧上的 ACK/NACK 应答信息按照预定义的分量载波(或小区)顺序映射;  Method 2: mapping according to the sequence of subframes, and ACK/NACK response information on the same subframe is sequentially mapped according to a predefined component carrier (or cell);
其中, 预定义的分量载波(或小区)顺序为高层配置, 或者, 预定义 的分量载波(或小区)顺序为分量载波(或小区) 索引顺序, 或者, 先主 分量载波(或小区)再辅分量载波(或小区)。  The predefined component carrier (or cell) sequence is a high-level configuration, or the predefined component carrier (or cell) sequence is a component carrier (or cell) index sequence, or the primary component carrier (or cell) is supplemented. Component carrier (or cell).
进一步说明, 当 UE在配置的相应下行分量载波(或小区)上没有检测 到 PDSCH时, 则其相应的应答信息设置为 NACK;  Further, when the UE does not detect the PDSCH on the configured corresponding downlink component carrier (or cell), the corresponding response information is set to NACK;
进一步地, 当基站配置 PDSCH对应的两个码字流(传输块)中某个码 字流(传输块)不使能且发送该 PDSCH对应的 ACK/NACK应答信息不进 行逻辑与操作时, 那么所述不使能的传输块对应的码字流的应答信息设置 为 NACK;  Further, when the base station configures that a certain codeword stream (transport block) in the two codeword streams (transport blocks) corresponding to the PDSCH is not enabled and the ACK/NACK response information corresponding to the PDSCH is not logically operated, then The response information of the codeword stream corresponding to the unenabled transport block is set to NACK;
进一步地, 当基站配置 PDSCH对应的两个码字流(传输块)中某个码 字流不使能且发送该 PDSCH对应的 ACK/NACK应答信息进行逻辑与操作 时, 那么所述不使能的码字流(传输块)对应的 ACK/NACK应答信息设置 为 ACK, 或者,该 PDSCH对应的 ACK/NACK应答信息逻辑与操作结果为 使能码字流(传输块)对应的 ACK/NACK应答信息; Further, when the base station configures that a certain codeword stream in the two codeword streams (transport blocks) corresponding to the PDSCH is not enabled and sends the ACK/NACK response information corresponding to the PDSCH to perform logical AND operation, the disabling is disabled. The ACK/NACK response information corresponding to the codeword stream (transport block) is set to ACK, or the logical and operation result of the ACK/NACK response information corresponding to the PDSCH is Enable ACK/NACK response information corresponding to the codeword stream (transport block);
进一步说明,所述获取需要发送的 ACK/NACK应答信息比特序列的方 法也可适用于在 PUCCH上釆用格式 3发送 ACK/NACK应答信息;  Further, the method for obtaining the ACK/NACK response information bit sequence to be transmitted is also applicable to transmitting the ACK/NACK response information in the format 3 on the PUCCH;
进一步说明, 本发明中正确应答信息(ACK )对应于二进制的 " 1" , 错 误应答信息 (NACK )对应于二进制的" 0"。  Further, in the present invention, the correct response information (ACK) corresponds to a binary "1", and the error response information (NACK) corresponds to a binary "0."
其中步骤 304中, 如果 ACK/NACK应答信息在 PUSCH上传输时不釆 用双里德-穆勒码 ( Dual Reed-Muller, Dual RM ) 的方式进行编码, 在计算 在 PUSCH上发送所述 ACK/NACK应答信息的比特序列所需的编码调制符 号个数时, 待发送的上行控制信息的比特数 O通过以下方式之一得到: In step 304, if the ACK/NACK response information is transmitted on the PUSCH, it is not encoded by the dual Reed-Muller (Dual RM) method, and the ACK/ is transmitted on the PUSCH. When the number of coded modulation symbols required for the bit sequence of the NACK response information is set, the number of bits O of the uplink control information to be transmitted is obtained by one of the following methods:
( 1 ) 当 UE根据上行授权 UL grant信息传输 PUSCH时, 0 = VD U A L 1 , 或 (1) When the UE transmits the PUSCH according to the uplink grant UL grant information, 0 = V D U A L 1 , or
C = TBmax , 或 O = min( TBmax ,O 0 = VD U^TB ); 当 UE不是根 c=0 C = TB max , or O = min( TB max , O 0 = V D U ^TB ); when UE is not root c=0
据上行授权信息 UL grant信息传输 PUSCH时, O等于得到的 ACK/NACK 应答信息的比特序列的长度; 其中, 是指上行授权信息 UL grant中的下 行分配索引,表示的是基站发送给 UE的 PDSCH的总数或所有分量载波(或 小区)中调度反馈 ACK/NACK应答消息的下行子帧个数中的最大值; 只要 有一个 PDSCH 对应 2 个传输块, TB = 2 ; 否则, TBmax = l ; 7¾max (c),c = 0,l,...C - l表示分量载波(或小区) c中传输块的最大值, C为 UE 配置的分量载波(或小区 ) 的个数; Omax表示 UE反馈 ACK/NACK应答消 息的最大比特数, , Κ表示配置的上下行子帧比例关系中下行
Figure imgf000010_0001
When the PUSCH is transmitted according to the uplink grant information UL grant information, O is equal to the length of the bit sequence of the obtained ACK/NACK response information, where is the downlink assignment index in the uplink grant information UL grant, indicating the PDSCH sent by the base station to the UE. The total number or the maximum number of downlink subframes in the feedback ACK/NACK response message in all component carriers (or cells); as long as one PDSCH corresponds to 2 transport blocks, TB = 2; otherwise, TB max = l; 73⁄4 max ( c ), c = 0,l,...C - l represents the maximum value of the transport block in the component carrier (or cell) c, and C is the number of component carriers (or cells) configured by the UE; O max Indicates the maximum number of bits that the UE feeds back the ACK/NACK response message, and Κ indicates that the configured uplink-downlink subframe ratio is in the downlink.
Figure imgf000010_0001
子帧个数, TB 表各个配置给 UE的下行分量载波(或小区 )上的 PDSCH 对应的正确错误应答消息最大比特数, 或者, 0皿表示所述 ACK/NACK应 答消息经过逻辑与操作反馈的最大比特数; The number of subframes, the maximum number of bits of the correct error response message corresponding to the PDSCH on the downlink component carrier (or cell) of the TB table, or 0 indicates that the ACK/NACK response message is logically and operationally fed back. Maximum number of bits;
( 2 ) ( 等于得到的比特序列长度;  (2) (equal to the length of the obtained bit sequence;
( 3 )( 等于 UE接收到的 TB对应 ACK/NACK应答信息和半静态持续 调度释放的 ACK/NACK应答信息的数量; (3) (equal to the TB corresponding to the ACK/NACK response message received by the UE and semi-static persistent Scheduling the number of ACK/NACK response messages released;
进一步地,如果 ACK/NACK应答信息在 PUSCH上传输时釆用 Dual RM 的方式进行编码, 且计算所需的编码调制符号个数是联合计算的, 计算时 待发送的上行控制信息的比特数 O通过以下方式之一得到:  Further, if the ACK/NACK response information is transmitted on the PUSCH, the code is coded by the Dual RM, and the number of coded modulation symbols required for the calculation is jointly calculated, and the number of bits of the uplink control information to be transmitted is calculated. Get it in one of the following ways:
( 1 ) 当 UE根据上行授权 UL grant信息传输 PUSCH时, 0 = 2 , 当 UE不是根据 UL grant信息传输 PUSCH时, O等于得到的 ACK/NACK 应答信息的比特序列的长度; 7表示的是分配到两个 RM中 ACK/NACK 应答信息对应的 PDSCH总数的最大值; (1) When the UE transmits the PUSCH according to the uplink grant UL grant information, 0 = 2, when the UE does not transmit the PUSCH according to the UL grant information, O is equal to the length of the bit sequence of the obtained ACK/NACK response information; 7 indicates the allocation The maximum number of PDSCHs corresponding to the ACK/NACK response information in the two RMs;
( 2 ) 当 UE根据上行授权 UL grant信息传输 PUSCH时, 0 = VD U A L 1 , 或 (2) When the UE transmits the PUSCH according to the uplink grant UL grant information, 0 = V D U A L 1 , or
C = TBmax , 或 O = min( TBmax ,O 0 = VD U^TB ); 当 UE不是根 据上行授权信息 UL grant信息传输 PUSCH时, O等于得到的 ACK/NACK 应答信息的比特序列的长度;其中, 表示的是基站发送给 UE的 PDSCH 的总数或所有分量载波(或小区)中调度反馈 ACK/NACK应答消息的下行 子帧个数中的最大值; 只要有一个 PDSCH对应 2个传输块, TBmax = 2 ; 否 则, TB = 1 ; 7¾max (c),c = 0,l,...C - 1表示分量载波 (或小区) c中传输块的最 大值, C 为 UE 配置的分量载波(或小区) 的个数; Omax表示 UE反馈 C = TB max , or O = min( TB max , O 0 = V D U ^TB ); when the UE does not transmit the PUSCH according to the uplink grant information UL grant information, O is equal to the bit sequence of the obtained ACK/NACK response information Length, where is the maximum number of PDSCHs sent by the base station to the UE or the number of downlink subframes in which all the component carriers (or cells) are scheduled to feed back ACK/NACK response messages; as long as there is one PDSCH corresponding to 2 transmissions Block, TB max = 2; otherwise, TB = 1 ; 73⁄4 max ( c ), c = 0,l,...C - 1 represents the maximum value of the transport block in the component carrier (or cell) c, C is the UE configuration Number of component carriers (or cells); O max indicates UE feedback
ACK/NACK应答消息的最大比特数, Omax=K* TBx , K表示配置的上下行 子帧比例关系中下行子帧个数, TB 表各个配置给 UE的下行分量载波(或 小区)上的 PDSCH对应的正确错误应答消息最大比特数, 或者, Omax表示 所述 ACK/NACK应答消息经过逻辑与操作反馈的最大比特数; The maximum number of ACK/NACK response messages, O max = K * TB x , K indicates the number of downlink subframes in the configured uplink-downlink subframe ratio relationship, and the TB table is configured on the downlink component carrier (or cell) of the UE. The maximum number of bits of the correct error response message corresponding to the PDSCH, or O max represents the maximum number of bits of the ACK/NACK response message that has been logically and operationally fed back;
( 3 ) ( 等于得到的 ACK/NACK应答信息的比特序列的长度;  (3) (equal to the length of the bit sequence of the obtained ACK/NACK response message;
( 4 )( 等于 UE接收到的 TB对应 ACK/NACK应答信息和半静态持续 调度释放的 ACK/NACK应答信息的数量。  (4) (equal to the TB corresponding to the ACK/NACK response information received by the UE and the number of ACK/NACK response information released by the semi-static persistent scheduling.
进一步地,如果 ACK/NACK应答信息在 PUSCH上传输时釆用 Dual RM 的方式进行编码, 且计算所需的编码调制符号个数是独立计算的, 计算时 待发送的上行控制信息的比特数 O1, O2通过以下方式之一得到: Further, if the ACK/NACK response message is transmitted on the PUSCH, the Dual RM is used. The method of encoding is performed, and the number of coded modulation symbols required for calculation is independently calculated. The number of bits O 1 , O 2 of the uplink control information to be transmitted during calculation is obtained by one of the following methods:
( 1 )当 UE根据上行授权 UL grant信息传输 PUSCH时, O1 = O2 = VD U A L 1 , 当 UE 不是根据上行授权 UL grant 信息传输 PUSCH 时,
Figure imgf000012_0001
, 其中, C^O2分别是独立计算时, 待发送的上行 控制信息比特数, /表示的是分配到两个 RM中 ACK/NACK应答信息对 应的 PDSCH总数的最大值, N表示的是得到的 ACK/NACK应答信息的比 特序列的长度;
(1) When the UE transmits the PUSCH according to the uplink grant UL grant information, O 1 = O 2 = V D U A L 1 , when the UE does not transmit the PUSCH according to the uplink grant UL grant information,
Figure imgf000012_0001
Wherein, C^O 2 is the number of uplink control information bits to be transmitted when independently calculated, and / represents the maximum value of the total number of PDSCHs allocated to the ACK/NACK response information in the two RMs, where N represents Length of the bit sequence of the ACK/NACK response message;
(2)
Figure imgf000012_0002
, N表示的是得到的 ACK/NACK应答信 息的比特序列的长度;
(2)
Figure imgf000012_0002
, N represents the length of the bit sequence of the obtained ACK/NACK response information;
( 3 ) O1 =「N/2],O2 =N-「N/2] , 当 UE根据上行授权 UL grant信息传 输 PUSCH时, N = ,.| W或 W = min( TB 0 当 UE不是根据 上行授权 UL grant信息传输 PUSCH时, N表示的是得到的 ACK/NACK应 答信息的比特序列的长度, 表示所有分量载波(或小区) 中调度反馈 ACK/NACK应答消息的下行子帧个数中的最大值; 只要有一个 PDSCH对 应 2个传输块, TB =2; 否则, TB =1; 7¾max(C),C = 0,l,...C- 1表示分量载 波(或小区) C中传输块的最大值, C为配置的分量载波(或小区)的个数;(3) O 1 = "N/2], O 2 = N - "N/2] , when the UE transmits the PUSCH according to the uplink grant UL grant information, N = , .| W or W = min ( TB 0 when the UE When the PUSCH is not transmitted according to the uplink grant UL grant information, N indicates the length of the bit sequence of the obtained ACK/NACK response information, and indicates the number of downlink subframes in which the feedback ACK/NACK response message is scheduled in all component carriers (or cells). Maximum value in ; as long as there is one PDSCH corresponding to 2 transport blocks, TB = 2; otherwise, TB =1; 73⁄4 max ( C ), C = 0, l, ... C-1 represents component carrier (or cell) The maximum value of the transport block in C, where C is the number of configured component carriers (or cells);
Cmax=K*¾TBx , K表示配置的上下行子帧比例关系中下行子帧个数, TB 表各个配置给 UE的下行分量载波(或小区)上的 PDSCH对应的正确错误 应答消息最大比特数, 或者, 0皿表示所述 ACK/NACK应答消息经过逻辑 与操作反馈的最大比特数; C max = K * 3⁄4 TB x , K represents the number of downlink subframes in the configured uplink-downlink subframe ratio relationship, and the maximum bit of the correct error response message corresponding to the PDSCH configured on the downlink component carrier (or cell) of the TB table a number, or 0, indicating the maximum number of bits of the ACK/NACK response message that has been logically and operationally fed back;
( 4 ) O1表示 UE接收到的 TB对应 ACK/NACK应答信息映射在一个 里德-穆勒码中的数量; O2表示 UE接收到的 TB对应 ACK/NACK应答信息 映射在另一个里德-穆勒码中的数量。 进一步地, 所述 根据上行授权信息中 DAI确定, 其中, 当有多个上 行授权信息发送给 UE时, 上行授权信息中 DAI取值相同。 (4) O 1 indicates the number of TB/NACK response information corresponding to the TB received by the UE in one Reed-Muller code; O 2 indicates that the TB corresponding to the ACK/NACK response information received by the UE is mapped in another Reed - The number in the Muller code. Further, the determining, according to the DAI in the uplink authorization information, is that when a plurality of uplink authorization information is sent to the UE, the value of the DAI in the uplink authorization information is the same.
进一步地, 其中步骤 306中, UE在 PUSCH上发送 ACK/NACK应答 信息是指: UE将生成的 ACK/NACK比特序列根据相应的编码方式进行编 码, 根据编码后的调制符号个数得到编码后的序列, 通过信道交织后与数 据复用在一起, 然后在 PUSCH上发送。  Further, in step 306, the UE sends the ACK/NACK response information on the PUSCH to: the UE encodes the generated ACK/NACK bit sequence according to the corresponding coding manner, and obtains the coded according to the number of the modulated modulation symbols. The sequence is multiplexed with the data by channel interleaving and then transmitted on the PUSCH.
本发明提供的一种用户终端包括: 获取模块、 计算模块和发送模块, 所述获取模块用于获取需要发送的 ACK/NACK应答信息的比特序列;计算 模块用于计算在 PUSCH上发送所述 ACK/NACK应答信息的比特序列所需 的编码调制符号个数;所述发送模块用于在 PUSCH上发送所述 ACK/NACK 应答信息。上述模块都是为实现本发明提供的 ACK/NACK应答信息的发送 方法而设, 所述方法的具体技术方案均可体现于所述各模块的功能及各模 块之间的交互关系中, 此处不再赘述。  A user terminal provided by the present invention includes: an obtaining module, a calculating module, and a sending module, where the acquiring module is configured to acquire a bit sequence of ACK/NACK response information to be sent; and the calculating module is configured to calculate the ACK sent on the PUSCH. /NACK The number of coded modulation symbols required for the bit sequence of the response information; the transmitting module is configured to transmit the ACK/NACK response information on the PUSCH. The foregoing modules are all configured to implement the ACK/NACK response information sending method provided by the present invention, and the specific technical solutions of the foregoing methods may be embodied in the functions of the modules and the interaction relationship between the modules, where No longer.
注: 当步骤 304与步骤 302不相关的时候, 二者顺序可以互换; 根据本发明提供的一种 ACK/NACK应答信息在物理上行共享信道上 的传输方法,有效的解决了载波聚合场景下 ACK/NACK应答信息在 PUSCH 上发送的问题。 附图说明  Note: When the step 304 is not related to the step 302, the order of the two may be interchanged; the method for transmitting the ACK/NACK response information on the physical uplink shared channel according to the present invention effectively solves the carrier aggregation scenario. The problem that the ACK/NACK response message is sent on the PUSCH. DRAWINGS
图 1为现有技术 FDD系统中帧结构示意图;  1 is a schematic diagram of a frame structure in a prior art FDD system;
图 2为现有技术 TDD系统中帧结构示意图;  2 is a schematic diagram of a frame structure in a prior art TDD system;
图 3为本发明应答信息的发送方法的流程示意图;  3 is a schematic flow chart of a method for transmitting response information according to the present invention;
图 4为本发明实施例一的示意图;  4 is a schematic diagram of Embodiment 1 of the present invention;
图 5为本发明实施例二方式一的确定 ACK/NACK比特序列的示意图; 图 6为本发明实施例二方式二的确定 ACK/NACK比特序列的示意图; 图 7为本发明实施例二方式三的确定 ACK/NACK比特序列的示意图; 图 8为本发明实施例二方式四的确定 ACK/NACK比特序列的示意图; 图 9为本发明实施例二方式五的确定 ACK/NACK比特序列的示意图。 具体实施方式 5 is a schematic diagram of determining an ACK/NACK bit sequence according to Embodiment 1 of the present invention; FIG. 6 is a schematic diagram of determining an ACK/NACK bit sequence according to Embodiment 2 of the present invention; FIG. 7 is a third embodiment of the present invention. A schematic diagram of determining an ACK/NACK bit sequence; FIG. 8 is a schematic diagram of determining an ACK/NACK bit sequence according to Embodiment 4 of Embodiment 2 of the present invention; FIG. 9 is a schematic diagram of determining an ACK/NACK bit sequence according to Embodiment 5 of Embodiment 2 of the present invention. detailed description
为使本发明的目的、 技术方案和优点更加清楚明白, 以下举实施例并 参照附图, 对本发明进一步详细说明。  The present invention will be further described in detail below with reference to the accompanying drawings.
实施例一:  Embodiment 1:
如图 4所示, TDD系统中, 假设基站给 UE配置了 4个下行分量载波 (或小区) {DL CC#0, DL CC#1 , DL CC#2, DL CC#3} , 且都需要反馈 2 比特的 ACK/NACK应答信息,同时假设某一上行子帧需要同时反馈下行子 帧 #n #n+l以及 #n+2—共 3个下行子帧的 ACK/NACK应答信息; PUSCH 上至多能发送的 ACK/NACK应答信息是 40比特; ACK/NACK应答信息在 PUSCH上传输时不釆用 Dual RM码进行编码, PUSCH的传输时根据 UL grant进行的, 且对应只有一个传输块。  As shown in FIG. 4, in the TDD system, it is assumed that the base station configures 4 downlink component carriers (or cells) {DL CC#0, DL CC#1, DL CC#2, DL CC#3} for the UE, and both need The 2-bit ACK/NACK response information is fed back, and it is assumed that an uplink subframe needs to simultaneously feed back downlink subframes #n #n+1 and #n+2 - ACK/NACK response information of 3 downlink subframes; PUSCH The ACK/NACK response information that can be transmitted at most is 40 bits; the ACK/NACK response information is not encoded by the Dual RM code when transmitted on the PUSCH, and the PUSCH is transmitted according to the UL grant, and corresponds to only one transport block.
步骤 402: UE根据基站给终端配置的下行分量载波(或小区)数、 配 置的上下行比例关系以及配置的每个下行分量载波(或小区)的传输模式, 确定需要反馈的 ACK/NACK应答信息的比特序列。终端根据先码字流后子 帧, 再分量载波(或小区)顺序将相应的得到的 ACK/NACK应答信息映射 到比特序列中去, 其中比特序列的长度是 24;  Step 402: The UE determines the ACK/NACK response information that needs to be fed back according to the number of downlink component carriers (or cells) configured by the base station, the configured uplink-downlink ratio, and the configured transmission mode of each downlink component carrier (or cell). Bit sequence. The terminal maps the corresponding ACK/NACK response information to the bit sequence according to the sub-frame of the pre-codeword stream, and then the component carrier (or cell), wherein the length of the bit sequence is 24;
步骤 404: UE根据相关信息计算发送上述 ACK/NACK应答信息比特 序列时所需的编码符号个数, 计算编码符号个数时, ( 值根据以下方式之 确定:  Step 404: The UE calculates, according to the related information, the number of coding symbols required to send the ACK/NACK response information bit sequence, and calculates the number of coding symbols, (the value is determined according to the following manner:
( 1 ) 因为传输的 PUSCH是根据 UL grant进行的, 计算编码调制符号个 数 时 , 0 = V AI 或 O = i *TB 或 O = min( *TB ,M* TBX) 或 x=0 (1) Since the transmitted PUSCH is performed according to the UL grant, when calculating the number of coded modulation symbols, 0 = V AI or O = i *TB or O = min( *TB , M* TB X ) or x=0
0 = VD U M L -∑TBm c) , UE根据得到的比特序列的长度计算所需的编码调制符 号个数; 0 = V D U M L -∑TB m c) , the UE calculates the required code modulator according to the length of the obtained bit sequence Number of numbers;
( 2 ) (9=比特序列长度;  (2) (9=bit sequence length;
( 3 ) (9=接收到的传输块个数;  (3) (9=Number of transmitted blocks received;
其中, 表示的是基站发送给 UE的 PDSCH的总数或所有分量载波 (或小区) 中下行子帧个数中的最大值, 当任一 PDSCH对应 2个传输块, TB = 2; 否则, TB = 1 ; 7¾ = 0,1,. -1表示分量载波(或小区) 中传输块的最大值, 即如果该分量载波(或小区) C中任一 PDSCH对应 2 个传输块, TBmax(C) = 2 , 否则 TBmax(C) = l , M代表配置的上下行子帧比例关 系中下行子帧个数, N代表的是下行分量载波(或小区)个数, TBx代表各 个配置给 UE的下行分量载波(或小区)需要发送 ACK/NACK应答信息的 比特数; Wherein, the total number of PDSCHs sent by the base station to the UE or the maximum number of downlink subframes in all component carriers (or cells) is indicated, when any PDSCH corresponds to 2 transport blocks, TB = 2 ; otherwise, TB = 1 ; 73⁄4 = 0,1,. -1 indicates the maximum value of the transport block in the component carrier (or cell), that is, if any PDSCH in the component carrier (or cell) C corresponds to 2 transport blocks, TB max (C) = 2 , otherwise TB max (C) = l , M represents the number of downlink subframes in the ratio of the uplink and downlink subframes configured, N represents the number of downlink component carriers (or cells), and TB x represents each configuration to the UE. The number of bits of the downlink component carrier (or cell) that needs to send ACK/NACK response information;
步骤 406: UE将生成的 ACK/NACK应答信息的比特序列根据相应的 编码方式进行编码、 根据编码后的调制符号个数得到编码后的序列, 通过 信道交织后与数据复用在一起, 然后在 PUSCH上发送。  Step 406: The UE encodes the generated bit sequence of the ACK/NACK response information according to the corresponding coding manner, obtains the encoded sequence according to the number of the modulated modulation symbols, and multiplexes the data by channel interleaving, and then Sent on PUSCH.
实施例二:  Embodiment 2:
如图 5〜图 9所示, TDD系统中, 假设基站给 UE配置了 4个下行分量 载波(或小区){DL CC#0 , DL CC#1 , DL CC#2 , DL CC#3 },其中 DL CC#0/l/3 都需要反馈 2比特的 ACK/NACK应答信息, DL CC#2需要反馈 1比特的 ACK/NACK应答信息, 同时假设某一上行子帧需要同时反馈下行子帧 #n、 #n+ 1以及 #n+2—共 3个下行子帧的 ACK/NACK应答信息; PUSCH上至多 能发送的 ACK/NACK应答信息是 M 比特且基站和 UE 约定好 M=20; ACK/NACK应答信息在 PUSCH 上传输时釆用 Dual RM码进行编码, PUSCH的传输时根据 UL grant进行的, 且对应只有一个传输块。  As shown in FIG. 5 to FIG. 9, in the TDD system, it is assumed that the base station configures four downlink component carriers (or cells) {DL CC#0, DL CC#1, DL CC#2, DL CC#3 }, for the UE, DL CC#0/l/3 needs to feed back 2 bits of ACK/NACK response information, DL CC#2 needs to feed back 1 bit of ACK/NACK response information, and assumes that an uplink subframe needs to simultaneously feed back downlink subframes# n, #n+ 1 and #n+2—the ACK/NACK response information of a total of three downlink subframes; the ACK/NACK response information that can be transmitted at most on the PUSCH is M bits and the base station and the UE agree that M=20; ACK/ When the NACK response information is transmitted on the PUSCH, it is encoded by the Dual RM code, and the PUSCH is transmitted according to the UL grant, and corresponds to only one transport block.
步骤 602: UE根据基站给终端配置的下行分量载波(或小区)数、 配 置的上下行比例关系以及配置的每个下行分量载波(或小区)的传输模式, 确定需要反馈的 ACK/NACK应答信息的比特序列, 因为 PUSCH上至多能 发送的 ACK/NACK应答信息是 20比特; 根据如下方式得到 ACK/NACK 比特序列; Step 602: The UE according to the number of downlink component carriers (or cells) configured by the base station, the configured uplink-downlink ratio, and the configured transmission mode of each downlink component carrier (or cell). Determining a bit sequence of ACK/NACK response information that needs to be fed back, since the ACK/NACK response information that can be transmitted at the PUSCH is 20 bits; the ACK/NACK bit sequence is obtained according to the following manner;
方式一: 如图 5 所示, 将所有包含 2 个码字流的 PDSCH对应的 ACK/NACK应答信息进行逻辑与操作后,按照先子帧后分量载波(或小区) 的顺序将得到的 ACK/NACK应答信息映射到对应的比特序列中;  Manner 1: As shown in Figure 5, after logically ANDing the ACK/NACK response information corresponding to all PDSCHs containing 2 codeword streams, the obtained ACK/ is obtained according to the order of the sub-subcarriers (or cells). NACK response information is mapped into the corresponding bit sequence;
方式二: 如图 6所示, 其中, DL CC#0是主分量载波(或主小区) , DL CC#l/2/3是辅分量载波(或小区) , 将辅分量载波(或小区) 中包含 2 个码字流的 PDSCH对应的 ACK/NACK应答信息进行逻辑与操作后, 按照 先子帧后分量载波(或小区)的顺序将得到的 ACK/NACK应答信息映射到 对应的比特序列中;  Manner 2: As shown in FIG. 6, where DL CC#0 is a primary component carrier (or primary cell), and DL CC#l/2/3 is a secondary component carrier (or cell), and the secondary component carrier (or cell) After performing logical AND operation on the ACK/NACK response information corresponding to the PDSCH of the 2 codeword streams, the obtained ACK/NACK response information is mapped to the corresponding bit sequence according to the order of the sub-subframe component carrier (or cell). ;
方式三: 如图 7所示, 假设 DL CC#0的优先级最高, DL CC#3的优先 级最低, 因为只需要将优先级最低的 DL CC3 中所有包含 2 个码字流的 PDSCH对应的 ACK/NACK应答信息进行逻辑与操作就能使得信息比特不 超过 M,所以将 DL CC#3中的包含 2个码字流的 PDSCH对应的 ACK/NACK 应答信息进行逻辑与操作, 按照先子帧后分量载波(或小区) 的顺序将得 到的 ACK/NACK应答信息映射到对应的比特序列中;  Mode 3: As shown in FIG. 7, it is assumed that DL CC#0 has the highest priority, and DL CC#3 has the lowest priority, because only the PDSCH including 2 codeword streams in the lowest priority DL CC3 needs to be corresponding. The logical AND operation of the ACK/NACK response information can make the information bits not exceed M, so the ACK/NACK response information corresponding to the PDSCH of the two codeword streams in the DL CC#3 is logically operated, according to the first subframe. The sequence of the post-component carrier (or cell) maps the obtained ACK/NACK response information into the corresponding bit sequence;
方式四: 如图 8所示, 只需要将子帧 #n对应的所有分量载波(或小区) 中包含 2个码字流的 PDSCH对应的 ACK/NACK应答信息进行逻辑与操作 就能使得信息比特不超过 20,所有将子帧 #n中的包含 2个码字流的 PDSCH 对应的 ACK/NACK应答信息进行逻辑与操作, 按照先子帧后分量载波 (或 小区) 的顺序将得到的 ACK/NACK应答信息映射到对应的比特序列中; 方式五: 如图 9所示, 因为只需要将一个 PDSCH对应的 ACK/NACK 应答信息进行逻辑与操作就能使得信息比特不超过 20, 所以按照先子帧后 分量载波(或小区) 的顺序将所有 PDSCH排序, 按照从后到前的顺序将 DL CC#3,子帧 #n+2上 PDSCH对应的 ACK/NACK应答信息进行逻辑与操 作, 按照先子帧后分量载波(或小区)的顺序将得到的 ACK/NACK应答信 息映射到对应的比特序列中; Manner 4: As shown in FIG. 8, it is only necessary to logically AND operate the ACK/NACK response information corresponding to the PDSCH of the 2 codeword streams in all component carriers (or cells) corresponding to the subframe #n. Not more than 20, all the ACK/NACK response information corresponding to the PDSCH including the 2 codeword streams in the subframe #n is logically ANDed, and the obtained ACK/ is obtained in the order of the sub-subframe component carrier (or cell). The NACK response information is mapped into the corresponding bit sequence. Method 5: As shown in FIG. 9, since only one PDSCH corresponding ACK/NACK response information needs to be logically operated, the information bit does not exceed 20, so according to the preamble The order of the post-frame component carriers (or cells) sorts all PDSCHs, in order from back to front. DL CC#3, the ACK/NACK response information corresponding to the PDSCH on the subframe #n+2 is logically ANDed, and the obtained ACK/NACK response information is mapped to the corresponding one in the order of the first subframe after the component carrier (or cell). In the bit sequence;
步骤 604: UE根据相关信息计算发送上述 ACK/NACK应答信息比特 序列时所需的编码符号个数, 计算编码符号个数时:  Step 604: The UE calculates, according to the related information, the number of coding symbols required to send the ACK/NACK response information bit sequence, and calculates the number of coding symbols:
如果 ACK/NACK应答信息在 PUSCH上传输时, 计算所需的编码调制 符号个数是联合计算的, O值可以根据以下方式之一确定:  If the ACK/NACK response information is transmitted on the PUSCH, the number of coded modulation symbols required for the calculation is jointly calculated, and the value of O can be determined according to one of the following ways:
( 1 ) 当 UE根据上行授权 UL grant信息传输 PUSCH时, 0 = 2 , 当 UE不是根据 UL grant信息传输 PUSCH时, O等于得到的 ACK/NACK应 答信息的比特序列的长度; ί^/表示的是分配到两个 RM中 ACK/NACK应 答信息对应的 PDSCH总数的最大值;  (1) When the UE transmits the PUSCH according to the uplink grant UL grant information, 0 = 2, when the UE does not transmit the PUSCH according to the UL grant information, O is equal to the length of the bit sequence of the obtained ACK/NACK response information; Is the maximum value of the total number of PDSCHs allocated to the ACK/NACK response information in the two RMs;
(2) ( 等于得到的 ACK/NACK应答信息的比特序列的长度;  (2) (equal to the length of the bit sequence of the obtained ACK/NACK response message;
( 3 ) ( 等于 UE接收到的 TB对应 ACK/NACK应答信息和半静态持续调 度释放的 ACK/NACK应答信息的数量;  (3) (equal to the TB corresponding to the ACK/NACK response information received by the UE and the number of ACK/NACK response information released by the semi-static continuous scheduling;
(4) 当 UE根据上行授权 UL grant信息传输 PUSCH时, 0 = V^, 或  (4) When the UE transmits PUSCH according to the uplink grant UL grant information, 0 = V^, or
C = TBmax, 或 O = min( TBmax,O 或 0 = d ramax(c); 当 UE不是根 据上行授权信息 UL grant信息传输 PUSCH时, O等于得到的 ACK/NACK 应答信息的比特序列的长度;其中, 表示的是基站发送给 UE的 PDSCH 的总数或所有分量载波(或小区)中调度反馈 ACK/NACK应答消息的下行 子帧个数中的最大值; 只要有一个 PDSCH对应 2个传输块, TBmax=2; 否 则, TB =1; 7¾max(c),c = 0,l,...C- 1表示分量载波 (或小区) c中传输块的最 大值, C 为 UE 配置的分量载波(或小区) 的个数; Omax表示 UE反馈 C = TB max , or O = min( TB max , O or 0 = d ra max ( c ); when the UE does not transmit the PUSCH according to the uplink grant information UL grant information, O is equal to the bit sequence of the obtained ACK/NACK response information The length of the PDSCH that is sent by the base station to the UE or the maximum number of downlink subframes in which the feedback ACK/NACK response message is scheduled in all component carriers (or cells); Transport block, TB max =2; otherwise, TB =1; 73⁄4 max ( c ), c = 0,l,...C-1 represents the maximum value of the transport block in the component carrier (or cell) c, C is the UE Number of configured component carriers (or cells); O max indicates UE feedback
ACK/NACK应答消息的最大比特数, Omax=K* TBx , K表示配置的上下行 子帧比例关系中下行子帧个数, TB 表各个配置给 UE的下行分量载波(或 小区)上的 PDSCH对应的正确错误应答消息最大比特数, 或者, Omax表示 所述 ACK/NACK 应答消息经过逻辑与操作反馈的最大比特数; 如果 ACK/NACK应答信息在 PUSCH上传输时, 计算所需的编码调制符号个数 是独立计算的, ( 值可以根据以下方式之一确定: The maximum number of bits of the ACK/NACK response message, O max =K* TB x , where K is the number of downlink subframes in the configured uplink-downlink subframe ratio relationship, and the TB table is configured for each downlink component carrier of the UE (or The maximum error number of the correct error response message corresponding to the PDSCH on the cell, or O max indicates the maximum number of bits of the ACK/NACK response message that is fed back through the logical AND operation; if the ACK/NACK response message is transmitted on the PUSCH, the calculation is performed. The number of coded modulation symbols required is calculated independently (the value can be determined according to one of the following ways:
( 1 ) 当 UE根据上行授权 UL grant信息传输 PUSCH时, O1 = O2 = / , 当 UE 不是根据上行授权 UL grant 信息传输 PUSCH 时,
Figure imgf000018_0001
, 其中, C^O2分别是独立计算时, 待发送的上行 控制信息比特数, /表示的是分配到两个 RM中 ACK/NACK应答信息对 应的 PDSCH总数的最大值, N表示的是得到的 ACK/NACK应答信息的比 特序列的长度;
(1) When the UE transmits the PUSCH according to the uplink grant UL grant information, O 1 = O 2 = / , when the UE does not transmit the PUSCH according to the uplink grant UL grant information,
Figure imgf000018_0001
Wherein, C^O 2 is the number of uplink control information bits to be transmitted when independently calculated, and / represents the maximum value of the total number of PDSCHs allocated to the ACK/NACK response information in the two RMs, where N represents Length of the bit sequence of the ACK/NACK response message;
(2)
Figure imgf000018_0002
, N表示的是得到的 ACK/NACK应答信息 的比特序列的长度;
(2)
Figure imgf000018_0002
, N represents the length of the bit sequence of the obtained ACK/NACK response information;
( 3 ) O1 =「N/2,,O2 =N—「N/2] , 当 UE根据上行授权 UL grant信息传输 (3) O 1 = "N/2,, O 2 = N - "N/2], when the UE transmits according to the uplink grant UL grant information
PUSCH时, N = ,.| W或 W = min( TB 0 当 UE不是根据上行 授权 UL grant信息传输 PUSCH时, N表示的是得到的 ACK/NACK应答信 息的比特序列的长度, 表示所有分量载波 (或小区) 中调度反馈 ACK/NACK应答消息的下行子帧个数中的最大值; 只要有一个 PDSCH对 应 2个传输块, TB =2; 否则, TB =1; 7¾max(C),C = 0 l ...C- 1表示分量载 波(或小区) c 中传输块的最大值, C 为分量载波(或小区) 的个数, When PUSCH, N = , .| W or W = min ( TB 0 When the UE does not transmit the PUSCH according to the uplink grant UL grant information, N represents the length of the bit sequence of the obtained ACK/NACK response information, indicating all component carriers (or cell) the maximum of the number of downlink subframes in which the feedback ACK/NACK response message is scheduled; as long as one PDSCH corresponds to two transport blocks, TB = 2; otherwise, TB = 1; 73⁄4 max ( C ), C = 0 l ... C-1 represents the maximum value of the transport block in the component carrier (or cell) c, and C is the number of component carriers (or cells),
Cmax=K*¾TBx , K表示配置的上下行子帧比例关系中下行子帧个数, TB 表各个配置给 UE的下行分量载波(或小区)上的 PDSCH对应的正确错误 应答消息最大比特数, 或者, 0皿表示所述 ACK/NACK应答消息经过逻辑 与操作反馈的最大比特数; C max = K * 3⁄4 TB x , K represents the number of downlink subframes in the configured uplink-downlink subframe ratio relationship, and the maximum bit of the correct error response message corresponding to the PDSCH configured on the downlink component carrier (or cell) of the TB table a number, or 0, indicating the maximum number of bits of the ACK/NACK response message that has been logically and operationally fed back;
( 4 ) O1表示 UE接收到的 TB对应 ACK/NACK应答信息映射在一个里德 -穆勒码中的数量; 02表示 UE接收到的 TB对应 ACK/NACK应答信息映射 在另一个里德 -穆勒码中的数量。 (4) O 1 indicates that the TB corresponding to the ACK/NACK response information received by the UE is mapped in a Reed - the number in the Muller code; 0 2 indicates the number of TB/NACK response information corresponding to the TB received by the UE in another Reed-Muller code.
步骤 606: UE将生成的 ACK/NACK比特序列根据相应的编码方式进 行编码、 根据编码后的调制符号个数得到编码后的序列, 通过信道交织后 与数据复用在一起, 然后在 PUSCH上发送。  Step 606: The UE encodes the generated ACK/NACK bit sequence according to a corresponding coding manner, obtains a coded sequence according to the number of coded modulation symbols, and multiplexes the data by channel interleaving, and then transmits the data on the PUSCH. .
为了实现上述的方法实施例, 本发明的其他实施例还提供了一种用户 终端。 由于下述的实施例是为实现前述的方法实施例, 故该用户终端中的 模块都是为了实现前述方法而设, 所述用户终端中的模块都可从前述方法 中毫无疑义的导出, 但本发明并不限于下述的实施例, 任何可实现上述方 法的装置和模块都应包含于本发明的保护范围。 并且在下面的描述中, 与 前述方法相同的内容在此省略, 以节约篇幅。  In order to implement the above method embodiments, other embodiments of the present invention also provide a user terminal. Since the embodiments described below are for implementing the foregoing method embodiments, the modules in the user terminal are all designed to implement the foregoing method, and the modules in the user terminal can be unambiguously derived from the foregoing method. However, the present invention is not limited to the embodiments described below, and any apparatus and modules that can implement the above methods should be included in the scope of the present invention. Also, in the following description, the same contents as the foregoing methods are omitted here to save space.
本发明提供的一种用户终端包括: 获取模块、 计算模块和发送模块, 所述获取模块用于获取需要发送的 ACK/NACK应答信息的比特序列;计算 模块用于计算在 PUSCH上发送所述 ACK/NACK应答信息的比特序列所需 的编码调制符号个数;所述发送模块用于在 PUSCH上发送所述 ACK/NACK 应答信息。上述模块都是为实现本发明提供的 ACK/NACK应答信息的发送 方法而设, 所述方法的具体技术方案均可体现于所述各模块的功能及各模 块之间的交互关系中, 此处不再赘述。  A user terminal provided by the present invention includes: an obtaining module, a calculating module, and a sending module, where the acquiring module is configured to acquire a bit sequence of ACK/NACK response information to be sent; and the calculating module is configured to calculate the ACK sent on the PUSCH. /NACK The number of coded modulation symbols required for the bit sequence of the response information; the transmitting module is configured to transmit the ACK/NACK response information on the PUSCH. The foregoing modules are all configured to implement the ACK/NACK response information sending method provided by the present invention, and the specific technical solutions of the foregoing methods may be embodied in the functions of the modules and the interaction relationship between the modules, where No longer.
本领域普通技术人员可以理解上述方法中的全部或部分步骤可通过程 序来指令相关硬件完成, 所述程序可以存储于计算机可读存储介质中, 如 只读存储器、 磁盘或光盘等。 可选地, 上述实施例的全部或部分步骤也可 以使用一个或多个集成电路来实现。 相应地, 上述实施例中的各模块 /单元 可以釆用硬件的形式实现, 也可以釆用软件功能模块的形式实现。 本发明 不限制于任何特定形式的硬件和软件的结合。  One of ordinary skill in the art will appreciate that all or a portion of the above steps may be accomplished by instructions to the associated hardware, which may be stored in a computer readable storage medium, such as a read only memory, a magnetic disk, or an optical disk. Alternatively, all or part of the steps of the above embodiments may also be implemented using one or more integrated circuits. Correspondingly, each module/unit in the above embodiment may be implemented in the form of hardware or in the form of a software function module. The invention is not limited to any specific form of combination of hardware and software.
以上所述, 仅为本发明的较佳实施例而已, 并非用于限定本发明的保 护范围 工业实用性 The above description is only a preferred embodiment of the present invention and is not intended to limit the present invention. Industrial scope
本发明提供的 ACK/NACK应答信息在物理上行共享信道上的传输方 法, 在载波聚合的场景下, UE首先获取需要发送的 ACK/NACK应答信息 的比特序列, 然后计算在 PUSCH上发送所述 ACK/NACK应答信息的比特 序列所需的编码调制符号个数, 最后在 PUSCH上发送所述 ACK/NACK应 答信息。 本发明有效的解决了载波聚合场景下 ACK/NACK应答信息在 PUSCH上发送的问题。  The ACK/NACK response information provided by the present invention is transmitted on a physical uplink shared channel. In a scenario of carrier aggregation, the UE first acquires a bit sequence of ACK/NACK response information to be transmitted, and then calculates the ACK to be sent on the PUSCH. /NACK The number of coded modulation symbols required for the bit sequence of the response information, and finally the ACK/NACK response information is transmitted on the PUSCH. The invention effectively solves the problem that the ACK/NACK response information is sent on the PUSCH in the carrier aggregation scenario.

Claims

权利要求书 Claim
1、 一种应答信息的发送方法, 其特征在于, 该方法包括:  A method for transmitting response information, the method comprising:
载波聚合的场景下, 用户终端 UE获取需要发送的 ACK/NACK应答信 息的比特序列;  In the scenario of carrier aggregation, the user terminal UE acquires a bit sequence of ACK/NACK response information that needs to be sent;
UE计算在 PUSCH上发送所述 ACK/NACK应答信息的比特序列所需 的编码调制符号个数;  The UE calculates the number of coded modulation symbols required to transmit the bit sequence of the ACK/NACK response information on the PUSCH;
UE在 PUSCH上发送所述 ACK/NACK应答信息。  The UE transmits the ACK/NACK response information on the PUSCH.
2、 根据权利要求 1 所述的方法, 其中, 所述 UE 获取需要发送的 ACK/NACK应答信息的比特序列的方法为:  2. The method according to claim 1, wherein the method for the UE to acquire a bit sequence of ACK/NACK response information to be transmitted is:
UE根据基站配置的下行分量载波数、 配置的上下行子帧比例关系、 配 置的每个下行分量载波的传输模式和物理上行共享信道 PUSCH 上至多能 发送的正确或错误 ACK/NACK应答信息比特的个数来确定需要发送的 ACK/NACK应答信息, 并将所述需要发送的 ACK/NACK应答信息映射到 比特序列中。  The UE may, according to the number of downlink component carriers configured by the base station, the configured uplink-downlink subframe ratio, the configured transmission mode of each downlink component carrier, and the correct or incorrect ACK/NACK response information bits that can be transmitted on the physical uplink shared channel PUSCH. The number is used to determine the ACK/NACK response information that needs to be sent, and the ACK/NACK response information that needs to be transmitted is mapped into the bit sequence.
3、 根据权利要求 1 所述的方法, 其中, 所述 UE 获取需要发送的 ACK/NACK应答信息的比特序列的方法为:  3. The method according to claim 1, wherein the method for the UE to acquire a bit sequence of ACK/NACK response information to be transmitted is:
UE根据高层配置的反馈模式获取需要发送的 ACK/NACK应答信息的 比特序列:  The UE obtains a bit sequence of the ACK/NACK response information to be sent according to the feedback mode of the high layer configuration:
如果高层配置釆用格式 lb联合信道选择的方式发送 ACK/NACK应答 信息,则根据信道选择方式的映射表中的 ACK/NACK信息来确定需要发送 的 ACK/NACK应答信息的比特序列;  If the upper layer configuration sends the ACK/NACK response information in the manner of the format lb joint channel selection, the bit sequence of the ACK/NACK response information to be transmitted is determined according to the ACK/NACK information in the mapping table of the channel selection manner;
如果高层配置釆用格式 3 的方式发送 ACK/NACK应答信息, 则根据 UE配置的下行分量载波数、 每个下行分量载波配置的传输模式、 上下行子 帧比例关系和 PUSCH上至多能发送的 ACK/NACK应答信息比特的个数来 确定需要发送的 ACK/NACK应答信息, 并将所述需要发送的 ACK/NACK 应答信息映射到比特序列中。 If the upper layer configuration sends the ACK/NACK response information in the manner of the format 3, the number of the downlink component carriers configured by the UE, the transmission mode configured for each downlink component carrier, the ratio of the uplink and downlink subframes, and the ACK that can be sent on the PUSCH. /NACK replies the number of information bits to determine the ACK/NACK response information that needs to be sent, and sends the ACK/NACK that needs to be sent. The response information is mapped into the bit sequence.
4、 根据权利要求 2或 3所述的方法, 其中, 所述方法还包括: 在获取需要发送的 ACK/NACK应答信息的比特序列时, 若在 PUSCH 上至多能发送 40比特的 ACK/NACK应答信息, 则根据码字流、 分量载波、 子帧的顺序, 或码字流、 子帧、 分量载波的顺序, 将所述需要发送的 ACK/NACK应答信息映射到比特序列中去。  The method according to claim 2 or 3, wherein the method further comprises: when acquiring a bit sequence of ACK/NACK response information to be transmitted, if at most, a 40-bit ACK/NACK response can be sent on the PUSCH For information, the ACK/NACK response information to be transmitted is mapped into the bit sequence according to the order of the codeword stream, the component carrier, the subframe, or the order of the codeword stream, the subframe, and the component carrier.
5、 根据权利要求 2或 3所述的方法, 其中, 所述方法还包括: 在获取需要发送的 ACK/NACK应答信息的比特序列时, 若在 PUSCH 上至多能发送基站和 UE约定的 M比特的 ACK/NACK应答信息, 且当前 需要发送的 ACK/NACK应答信息的总比特数超过 M比特,则将所有包含 2 个码字流的物理下行共享信道 PDSCH对应的 ACK/NACK应答信息进行逻 辑与操作后,将逻辑与操作后的 ACK/NACK应答信息映射到对应比特序列 中, 其中, M的取值为 {20,21,22,23,24,25,26}。  The method according to claim 2 or 3, wherein the method further comprises: when acquiring a bit sequence of ACK/NACK response information to be transmitted, if at most, the M-bit agreed by the base station and the UE can be transmitted on the PUSCH ACK/NACK response information, and the total number of bits of the ACK/NACK response information that needs to be sent exceeds M bits, and logically combines ACK/NACK response information corresponding to all physical downlink shared channel PDSCHs including 2 codeword streams. After the operation, the logical and operational ACK/NACK response information is mapped into the corresponding bit sequence, where the value of M is {20, 21, 22, 23, 24, 25, 26}.
6、 根据权利要求 2或 3所述的方法, 其中, 所述方法还包括: 在获取需要发送的 ACK/NACK应答信息的比特序列时, 若在 PUSCH 上至多能发送基站和 UE约定的 M比特的 ACK/NACK应答信息, 且当前 需要发送的 ACK/NACK应答信息的总比特数超过 M比特, 则按照预置方 法将 PDSCH对应的 2 个 ACK/NACK应答信息进行逻辑与操作, 直到 ACK/NACK应答信息的总比特数不超过 M比特为止,然后将逻辑与操作后 的 ACK/NACK 应答信息映射到对应比特序列中, 其中, M 的取值为 {20,21,22,23,24,25,26}„  The method according to claim 2 or 3, wherein the method further comprises: when acquiring a bit sequence of ACK/NACK response information to be transmitted, if at most, the M-bit agreed by the base station and the UE can be transmitted on the PUSCH ACK/NACK response information, and the total number of bits of the ACK/NACK response information that needs to be sent exceeds M bits, and logically AND operations the two ACK/NACK response information corresponding to the PDSCH according to a preset method until ACK/NACK The total number of bits of the response message does not exceed M bits, and then the logical and operational ACK/NACK response information is mapped into the corresponding bit sequence, where the value of M is {20, 21, 22, 23, 24, 25 , 26}„
7、根据权利要求 6所述的方法, 其中, 所述预置方法为以下方法之一: 将所有辅分量载波中包含 2个码字流的 PDSCH对应的 ACK/NACK应 答信息进行逻辑与操作; 若 ACK/NACK应答信息的总比特数仍超过 M比 特, 则再将主分量载波中包含 2个码字流的 PDSCH对应的 ACK/NACK应 答信息进行逻辑与操作; 或 The method according to claim 6, wherein the preset method is one of the following methods: logically AND operation of ACK/NACK response information corresponding to a PDSCH of two codeword streams in all secondary component carriers; If the total number of bits of the ACK/NACK response message still exceeds M bits, the ACK/NACK corresponding to the PDSCH including the 2 codeword streams in the primary component carrier should be Answer information for logic and operation; or
按照分量载波优先级从低到高的顺序, 将所述分量载波中所有包含 2 个码字流的 PDSCH对应的 ACK/NACK应答信息进行逻辑与操作, 直到 ACK/NACK应答信息的总比特数不超过 M为止; 或  According to the order of the component carrier priorities from low to high, the ACK/NACK response information corresponding to all PDSCHs of the 2 codeword streams in the component carrier is logically ANDed until the total number of bits of the ACK/NACK response information is not More than M; or
按照子帧先后顺序, 将所述子帧对应的所有分量载波中包含 2个码字 流的 PDSCH 对应的 ACK/NACK 应答信息进行逻辑与操作, 直到 ACK/NACK应答信息的总比特数不超过 M为止; 或  Performing logical AND operations on the ACK/NACK response information corresponding to the PDSCH of the two codeword streams in all component carriers corresponding to the subframe according to the sequence of the subframes until the total number of bits of the ACK/NACK response information does not exceed M So far; or
按照先子帧后分量载波或先分量载波后子帧的顺序将所有 PDSCH排 序,按照从后向前或从前向后的顺序, 逐个将包含 2个码字流的 PDSCH对 应的 ACK/NACK应答信息进行逻辑与操作, 直到总信息比特不超过 M为 止。  All PDSCHs are sorted according to the order of the pre-subframe post component carrier or the first component carrier post subframe, and the ACK/NACK response information corresponding to the PDSCH of the 2 codeword streams is successively arranged in the order from the back to the front or the back to the back. Perform logic and operations until the total information bits do not exceed M.
8、 根据权利要求 2或 3所述的方法, 其中, 在将所述 ACK/NACK应 答信息映射到比特序列中时, 所述映射的方法为以下方法之一:  The method according to claim 2 or 3, wherein, when mapping the ACK/NACK response information into a bit sequence, the mapping method is one of the following methods:
方法一: 按照预先定义的分量载波顺序进行映射, 对于同一分量载波 的 ACK/NACK应答信息按照子帧先后顺序映射或者按照下行授权信息 DL assignment中的下行分配索引 DAI的取值进行映射, 半静态持续调度释放 的 ACK/NACK应答信息位于其所在分量载波反馈的 ACK/NACK应答信息 最前面或最后面;  Method 1: mapping according to a predefined component carrier sequence, mapping ACK/NACK response information of the same component carrier according to a subframe order or mapping according to a value of a downlink assignment index DAI in a downlink grant information DL assignment, semi-static The ACK/NACK response information released by the persistent scheduling is located at the front or the end of the ACK/NACK response information fed back by the component carrier in which it is located;
其中, 预定义的分量载波顺序为高层配置, 或者, 预定义的分量载波 顺序为分量载波索引顺序, 或者, 先主分量载波再辅分量载波;  The pre-defined component carrier sequence is a high-level configuration, or the predefined component carrier sequence is a component carrier index sequence, or the first primary component carrier and the secondary component carrier;
每个分量载波反馈的 ACK/NACK应答信息数量由配置的下行子帧数 量和传输模式确定, 或者, 由配置的下行子帧数量和传输模式、 上行授权 信息 UL grant中的下行分配索引的取值确定;  The number of ACK/NACK response information fed back by each component carrier is determined by the configured number of downlink subframes and the transmission mode, or the number of configured downlink subframes and the transmission mode, and the value of the downlink allocation index in the uplink grant information UL grant. Determine
方法二: 按照子帧的先后顺序进行映射, 同一个子帧上的 ACK/NACK 应答信息按照预定义的分量载波顺序映射; 其中, 预定义的分量载波顺序为高层配置, 或者, 预定义的分量载波 顺序为分量载波索引顺序, 或者, 先主分量载波再辅分量载波。 Method 2: mapping according to the sequence of subframes, and ACK/NACK response information on the same subframe is mapped according to a predefined component carrier sequence; The pre-defined component carrier sequence is a high-level configuration, or the predefined component carrier sequence is a component carrier index sequence, or the first primary component carrier and the secondary component carrier.
9、 根据权利要求 1所述的方法, 其中, 所述方法还包括:  9. The method according to claim 1, wherein the method further comprises:
当 UE在配置的相应下行分量载波上没有检测到 PDSCH时, 则其相应 的应答信息设置为 NACK;  When the UE does not detect the PDSCH on the configured downlink component carrier, the corresponding response information is set to NACK;
当基站配置 PDSCH对应的两个传输块中某个传输块不使能且发送该 PDSCH对应的 ACK/NACK应答信息不进行逻辑与操作时, 那么所述不使 能的传输块对应的码字流的应答信息设置为 NACK;  When the base station configures that one of the two transport blocks corresponding to the PDSCH is not enabled and the ACK/NACK response information corresponding to the PDSCH is not logically operated, the codeword stream corresponding to the unenabled transport block The response information is set to NACK;
当基站配置 PDSCH对应的两个传输块中某个传输块不使能且发送该 PDSCH对应的 ACK/NACK应答信息进行逻辑与操作时, 那么所述不使能 的传输块对应的码字流的 ACK/NACK应答信息设置为 ACK, 或者, 该 PDSCH对应的 ACK/NACK应答信息逻辑与操作结果为使能传输块对应的 ACK/NACK应答信息。  When the base station configures that one of the two transport blocks corresponding to the PDSCH is not enabled and sends the ACK/NACK response information corresponding to the PDSCH for logical AND operation, then the codeword stream corresponding to the unenabled transport block is The ACK/NACK response information is set to ACK, or the ACK/NACK response information corresponding to the PDSCH and the operation result are ACK/NACK response information corresponding to the enabled transport block.
10、 根据权利要求 1 所述的方法, 其中, 所述获取需要发送的 ACK/NACK应答信息比特序列的方法适用于在 PUCCH上釆用格式 3发送 ACK/NACK应答信息。  10. The method according to claim 1, wherein the method for obtaining an ACK/NACK response information bit sequence to be transmitted is adapted to use the format 3 to send ACK/NACK response information on the PUCCH.
11、 根据权利要求 1所述的方法, 其中, 如果 ACK/NACK应答信息在 PUSCH上传输时不釆用双里德-穆勒码 Dual RM的方式进行编码, 在计算 在 PUSCH上发送所述 ACK/NACK应答信息的比特序列所需的编码调制符 号个数时, 待发送的上行控制信息的比特数 O通过以下方式之一得到: 当 UE 根据上行授权 UL grant信息传输 PUSCH 时, 0 = V^ , 或  11. The method according to claim 1, wherein if the ACK/NACK response information is transmitted on the PUSCH without encoding in a dual Reed-Muller code Dual RM, the ACK is transmitted on the PUSCH. When the number of coded modulation symbols required for the bit sequence of the /NACK response message is set, the number of bits O of the uplink control information to be transmitted is obtained by one of the following methods: When the UE transmits the PUSCH according to the uplink grant UL grant information, 0 = V^ , or
C = TBmax , 或 O = min( TBmax ,O 或 0 = d ramax(c); 当 UE不是根 据上行授权信息 UL grant信息传输 PUSCH时, O等于得到的 ACK/NACK 应答信息的比特序列的长度;其中, 表示的是基站发送给 UE的 PDSCH 的总数或所有分量载波中调度反馈 ACK/NACK应答消息的下行子帧个数 中的最大值;只要有一个 PDSCH对应 2个传输块, TB = 2;否则, TB 1; 7¾max (c),c = 0 l ...C-l表示分量载波 c中传输块的最大值, C为 UE配置的分 量载波的个数; Omax表示 UE反馈 ACK/NACK应答消息的最大比特数, C = TB max , or O = min( TB max , O or 0 = d ra max ( c ); when the UE does not transmit the PUSCH according to the uplink grant information UL grant information, O is equal to the bit sequence of the obtained ACK/NACK response information The length of the PDSCH sent by the base station to the UE or the number of downlink subframes in which the feedback ACK/NACK response message is scheduled in all component carriers Maximum value in ; as long as there is one PDSCH corresponding to 2 transport blocks, TB = 2 ; otherwise, TB 1; 73⁄4 max ( c ), c = 0 l ... Cl represents the maximum value of the transport block in component carrier c, C The number of component carriers configured for the UE; O max represents the maximum number of bits that the UE feeds back the ACK/NACK response message,
Cmax=K*¾TBx , K表示配置的上下行子帧比例关系中下行子帧个数, TB 表各个配置给 UE的下行分量载波上的 PDSCH对应的正确错误应答消息最 大比特数, 或者, 0皿表示所述 ACK/NACK应答消息经过逻辑与操作反馈 的最大比特数; 或, C max = K * 3⁄4 TB x , K represents the number of downlink subframes in the configured uplink-downlink subframe ratio relationship, and the maximum number of correct error response messages corresponding to the PDSCH on the downlink component carrier configured in the TB table, or 0 indicates the maximum number of bits of the ACK/NACK response message that has been logically and operationally fed back; or,
( 等于得到的比特序列长度; 或,  (equal to the length of the obtained bit sequence; or,
( 等于 UE接收到的 TB对应 ACK/NACK应答信息和半静态持续调度 释放的 ACK/NACK应答信息的数量。  (Equivalent to the TB received by the UE corresponding to the ACK/NACK response information and the number of ACK/NACK response information released by the semi-static persistent scheduling.
12、 根据权利要求 1所述的方法, 其中, 如果 ACK/NACK应答信息在 PUSCH上传输时釆用 Dual RM的方式进行编码,且计算所需的编码调制符 号个数是联合计算的, 计算时待发送的上行控制信息的比特数 O通过以下 方式之一得到:  12. The method according to claim 1, wherein, if the ACK/NACK response information is transmitted on the PUSCH, the method is performed by using a Dual RM, and the number of coded modulation symbols required for the calculation is jointly calculated. The number of bits O of the uplink control information to be sent is obtained by one of the following methods:
当 UE根据上行授权 UL grant信息传输 PUSCH时, o = 2 * V , 当 UE 不是根据 UL grant信息传输 PUSCH时, O等于得到的 ACK/NACK应答信 息的比特序列的长度; ¾^表示的是分配到两个 RM中 ACK/NACK应答信 息对应的 PDSCH总数的最大值; 或,  When the UE transmits the PUSCH according to the uplink grant UL grant information, o = 2 * V, when the UE does not transmit the PUSCH according to the UL grant information, O is equal to the length of the bit sequence of the obtained ACK/NACK response information; 3⁄4^ indicates the allocation The maximum number of PDSCHs corresponding to the ACK/NACK response information in the two RMs; or,
当 UE 根据上行授权 UL grant信息传输 PUSCH 时, 0 = V^ , 或  When the UE transmits PUSCH according to the uplink grant UL grant information, 0 = V^, or
C = TBmax , 或 O = min( TBmax ,O 或 0 = d ramax(c); 当 UE不是根 据上行授权信息 UL grant信息传输 PUSCH时, O等于得到的 ACK/NACK 应答信息的比特序列的长度;其中, 表示的是基站发送给 UE的 PDSCH 的总数或所有分量载波中调度反馈 ACK/NACK应答消息的下行子帧个数 中的最大值;只要有一个 PDSCH对应 2个传输块, TB = 2;否则, TB 1; 7¾max (C),C = 0 l ...C - l表示分量载波 C中传输块的最大值, C为 UE配置的分 量载波的个数; Omax表示 UE反馈 ACK/NACK应答消息的最大比特数, C = TB max , or O = min( TB max , O or 0 = d ra max ( c ); when the UE does not transmit the PUSCH according to the uplink grant information UL grant information, O is equal to the bit sequence of the obtained ACK/NACK response information The length of the PDSCH that is sent by the base station to the UE or the maximum number of downlink subframes in which the feedback ACK/NACK response message is scheduled in all component carriers; as long as one PDSCH corresponds to two transport blocks, TB = 2 ; otherwise, TB 1; 73⁄4 max ( C ), C = 0 l ... C - l represents the maximum value of the transport block in the component carrier C, C is the number of component carriers configured by the UE; O max represents the maximum of the ACK/NACK response message fed back by the UE Number of bits,
Cmax=K*¾TBx , K表示配置的上下行子帧比例关系中下行子帧个数, TB 表各个配置给 UE的下行分量载波上的 PDSCH对应的正确错误应答消息最 大比特数, 或者, 0皿表示所述 ACK/NACK应答消息经过逻辑与操作反馈 的最大比特数; 或, C max = K * 3⁄4 TB x , K represents the number of downlink subframes in the configured uplink-downlink subframe ratio relationship, and the maximum number of correct error response messages corresponding to the PDSCH on the downlink component carrier configured in the TB table, or 0 indicates the maximum number of bits of the ACK/NACK response message that has been logically and operationally fed back; or,
O等于得到的 ACK/NACK应答信息的比特序列的长度; 或,  O is equal to the length of the bit sequence of the obtained ACK/NACK response message; or,
( 等于 UE接收到的 TB对应 ACK/NACK应答信息和半静态持续调度 释放的 ACK/NACK应答信息的数量。  (Equivalent to the TB received by the UE corresponding to the ACK/NACK response information and the number of ACK/NACK response information released by the semi-static persistent scheduling.
13、 根据权利要求 1所述的方法, 其中, 如果 ACK/NACK应答信息在 13. The method according to claim 1, wherein if the ACK/NACK response message is
PUSCH上传输时釆用 Dual RM的方式进行编码,且计算所需的编码调制符 号个数是独立计算的, 计算时待发送的上行控制信息的比特数 C^ O2通过以 下方式之一得到: When transmitting on the PUSCH, the code is coded by the Dual RM, and the number of coded modulation symbols required for the calculation is independently calculated. The number of bits of the uplink control information to be transmitted when calculating C^O 2 is obtained by one of the following methods:
当 UE根据上行授权 UL grant信息传输 PUSCH时, O1 = O2 = / , 当 UE 不 是根据上行授权 UL grant 信 息传输 PUSCH 时 ,
Figure imgf000026_0001
, 其中, C^ O2分别是独立计算时, 待发送的上行 控制信息比特数, /表示的是分配到两个 RM中 ACK/NACK应答信息对 应的 PDSCH总数的最大值, N表示的是得到的 ACK/NACK应答信息的比 特序列的长度; 或,
When the UE transmits the PUSCH according to the uplink grant UL grant information, O 1 = O 2 = / , when the UE does not transmit the PUSCH according to the uplink grant UL grant information,
Figure imgf000026_0001
Wherein, C^O 2 is the number of uplink control information bits to be transmitted when independently calculated, and / represents the maximum value of the total number of PDSCHs allocated to the ACK/NACK response information in the two RMs, where N represents Length of the bit sequence of the ACK/NACK response message; or,
Figure imgf000026_0002
, N表示的是得到的 ACK/NACK应答信息的 比特序列的长度; 或,
Figure imgf000026_0002
, N represents the length of the bit sequence of the obtained ACK/NACK response information; or,
Figure imgf000026_0003
, 当 UE 根据上行授权 UL grant 信息传输
Figure imgf000026_0003
When the UE transmits according to the uplink grant UL grant information
PUSCH时, N = , .| W或 W = min( TB 0 当 UE不是根据上行 授权 UL grant信息传输 PUSCH时, N表示的是得到的 ACK/NACK应答信 息的比特序列的长度, ^表示所有分量载波中调度反馈 ACK/NACK应答 消息的下行子帧个数中的最大值; 只要有一个 PDSCH对应 2个传输块, TBmax = 2; 否则, TB腿 = 1 ; 7¾max (C),C = 0,l,...C- 1表示分量载波 C中传输块的 最大值, C为 UE配置的分量载波的个数; , K表示配置的上
Figure imgf000027_0001
When PUSCH, N = , .| W or W = min ( TB 0 When the UE does not transmit the PUSCH according to the uplink grant UL grant information, N indicates the obtained ACK/NACK response message. The length of the bit sequence of the interest, ^ represents the maximum of the number of downlink subframes in the component feedback ACK/NACK response message in all component carriers; as long as one PDSCH corresponds to 2 transport blocks, TB max = 2; otherwise, the TB leg = 1 ; 73⁄4 max ( C ), C = 0, l, ... C-1 represents the maximum value of the transport block in component carrier C, C is the number of component carriers configured by the UE;
Figure imgf000027_0001
下行子帧比例关系中下行子帧个数, TB 表各个配置给 UE的下行分量载 波上的 PDSCH对应的正确错误应答消息最大比特数, 或者, 0皿表示所述 ACK/NACK应答消息经过逻辑与操作反馈的最大比特数; 或, The number of downlink subframes in the downlink subframe ratio relationship, and the maximum number of correct error response messages corresponding to the PDSCH configured on the downlink component carrier of the UE in the TB table, or 0 indicates that the ACK/NACK response message is logically AND The maximum number of bits of operation feedback; or,
O1表示 UE接收到的 TB对应 ACK/NACK应答信息映射在一个里德- 穆勒码中的数量; 02表示 UE接收到的 TB对应 ACK/NACK应答信息映射 在另一个里德 -穆勒码中的数量。 O 1 represents the number of TB/NACK response information corresponding to the TB received by the UE in a Reed-Muller code; 0 2 indicates that the TB corresponding to the ACK/NACK response information received by the UE is mapped in another Reed-Muller The number in the code.
14、 根据权利要求 11、 12或 13所述的方法, 其中, 所述 ¾^根据上行 授权信息中 DAI确定, 其中, 当有多个上行授权信息发送给 UE时, 上行 授权信息中 DAI取值相同。  The method according to claim 11, 12 or 13, wherein the determining is based on the DAI in the uplink grant information, wherein when there are multiple uplink grant information to be sent to the UE, the value of the DAI in the uplink grant information is the same.
15、 根据权利要求 1所述的方法, 其中, 所述 UE在 PUSCH上发送所 述 ACK/NACK应答信息的方法为:  The method according to claim 1, wherein the method for the UE to send the ACK/NACK response information on the PUSCH is:
UE将生成的 ACK/NACK应答信息的比特序列根据相应的编码方式进 行编码, 根据编码后的调制符号个数得到编码后的序列, 通过信道交织后 与数据复用在一起, 然后在 PUSCH上发送。  The UE encodes the generated bit sequence of the ACK/NACK response information according to the corresponding coding manner, obtains the encoded sequence according to the number of the modulated modulation symbols, multiplexes the data by channel interleaving, and then transmits the data on the PUSCH. .
16、 一种用户终端, 其特征在于, 该用户终端包括:  16. A user terminal, the user terminal comprising:
获取模块, 用于在载波聚合的场景下, 获取需要发送的 ACK/NACK应 答信息的比特序列;  An obtaining module, configured to obtain a bit sequence of ACK/NACK response information to be sent in a scenario of carrier aggregation;
计算模块, 用于计算在 PUSCH上发送所述 ACK/NACK应答信息的比 特序列所需的编码调制符号个数;  a calculation module, configured to calculate a number of coded modulation symbols required to transmit a bit sequence of the ACK/NACK response information on the PUSCH;
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