WO2010145374A1 - Method and device for supplementarily reporting data by using buffer - Google Patents

Method and device for supplementarily reporting data by using buffer Download PDF

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Publication number
WO2010145374A1
WO2010145374A1 PCT/CN2010/072825 CN2010072825W WO2010145374A1 WO 2010145374 A1 WO2010145374 A1 WO 2010145374A1 CN 2010072825 W CN2010072825 W CN 2010072825W WO 2010145374 A1 WO2010145374 A1 WO 2010145374A1
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Prior art keywords
teaching
sheep
physical address
same
failure
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PCT/CN2010/072825
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French (fr)
Chinese (zh)
Inventor
李兴国
刘苏建
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中兴通讯股份有限公司
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Publication of WO2010145374A1 publication Critical patent/WO2010145374A1/en

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    • HELECTRICITY
    • H04ELECTRIC COMMUNICATION TECHNIQUE
    • H04LTRANSMISSION OF DIGITAL INFORMATION, e.g. TELEGRAPHIC COMMUNICATION
    • H04L43/00Arrangements for monitoring or testing data switching networks

Definitions

  • each segment has the same ( ) teaching, performance teaching, etc., and will be in the upper operation (C, O COpe a o and a e a ceCe e ). There are many ways to put O C on it, and it will be taught to O C, or on the file.
  • the main purpose of this book is to provide a method and device for using the teaching method to solve the problem of loss due to the same length of the element and the O C.
  • the wood plan is
  • This article provides a method of using the method of teaching, including methods that are pre-emptive , the success in the upper level, and not before, in turn will fail in the middle
  • Step before the specific degree, before the break, to, .
  • the method step includes the existence of the failed upper-level mediation before the decision.
  • the force is empty and will be stored directly
  • the method step consists of following the principle of first-in, followed by the upper one.
  • This device provides a means of teaching, including juice, and ,
  • Step 101 the specificity of the previous degree.
  • Step 102 above, above, succeeded, and not before, in turn, the upper one failed.
  • the storage of the physical address is the same (physical address from low to high), in the storage, full, storage can be divided into multiple or more sheep, the sheep occupy the physical address of the segment, The sheep have a physical address and a physical address, 3 (a) shows a sheep containing more or more, 3 (b), the length of the sheep is ten + length, and the length indicates the effective length. Effective Hugh content.
  • the storage ( ) and ( ) are based on the principle that the physical address of the segment is the same, the storage with the lower physical address is the same, and the storage with the higher physical address is the same, so it will be stored from the beginning until it is sent out until , which can be, first, first.
  • the most recent failure can be stored and the first one, the most recent failure can be stored means that even if it is the same, the most way to cover the latest failure will be C failed "first" refers to the new level, the latest, new, until the most. Among them, the latest is the most armed, the most advanced. It should be pointed out that, in the middle will be cleared, so that. The characteristics of this machine, can be divided happening
  • the middle and the middle are larger than the 3 large (same foot) of the weapon. Therefore, you can store the 2 phase and the physical address is high, then the pointer points to the physical address of 3, 3 is the latest.
  • the most recent ones namely 3 (including the high part and the low part), are 2, 1 in order.
  • the latest ones namely 4 (including the high part and the low part), are 3 .
  • Step 801 Step 801, , .
  • the 1 is small, the one needed inside, the rest of the wood, this no longer.
  • Step 802 send to C .
  • the inside is not in existence, but stored in the storage of the media, and only if it fails internally, it will be stored.
  • step 803 it is successful whether the delivery is successful. If yes, go to step 806. If no, go to step 804.
  • the current process is sent to the O C, and the process used is not described here.
  • the message to the O C is successful, the message of the O C is received, and if the message is not executed, if the message is not received, the process is determined to be a failure.
  • Step 804 805, whether or not before, if yes, executing step 805, failing the result of the failed application, and returning to step 802
  • step 802 If yes, if not, go back to step 802 and resend the failed
  • Step 806 whether before, if yes, the previous process does not perform step 807
  • step 807 If you want to succeed in the delivery, you can't do anything to O CJ before, if the process does not, then go to step 807.
  • Step 807 in the order of .
  • Step 808 809 whether it is successful, if it fails, then whether it is before, if the previous process does not, then return to step 807, and the result is successful. Step 8 0
  • step 808 it is the same as step 803, which is no longer the same. In the failure, and before, you can no longer go to the OC any, if the previous process does not, then go back to step 807. The new one failed.
  • Step 810 whether, if yes, the process is not, return 80
  • step 809 If the success in the result is close to whether all the teachings in the middle have been OC, if all of them have been delivered, if there are some in the process, then go back to step 809, if the result is not before, if the process is not, then the steps are executed. 807, in the middle, until the delivery is finished.
  • this provides a device for using teaching, 9 , including juice ⁇ 10, 20 and

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  • Engineering & Computer Science (AREA)
  • Computer Networks & Wireless Communication (AREA)
  • Signal Processing (AREA)
  • Management, Administration, Business Operations System, And Electronic Commerce (AREA)
  • Techniques For Improving Reliability Of Storages (AREA)
  • Data Exchanges In Wide-Area Networks (AREA)

Abstract

A method for supplementarily reporting data by using buffer is provided by the invention, and the method includes: starting a transmission process at a specific time of current collection granularity; when the transmission process is started, reporting the data collected in the last collection granularity; when the data reporting is successful and the current collection granularity is not ended, in turn reporting the data which is reported unsuccessfully and saved in a cycle stack buffer. A device for supplementarily reporting data by using buffer is provided by the invention. Based on the method and the device, the problem can be resolved that the disconnection time between a network element and an operation maintaining centre is too long so that the reported data is lost.

Description

利用 的方法和裝置 木領域  Method and apparatus for use
本 涉及教 木, 特別是指 利用 行教 的方 法和裝置。 背景 木  This refers to teaching wood, especially the methods and devices that use teaching. Background
在 通信 統中, 各 每隔 段 同 ( )就 行教 、 性能教 等, 且 將 的 上 操作 中 ( C, O COpe a o 及 a e a ceCe e )。 將 上 O C的方式有 多 , 用教 方式將 上 到 O C,或者 用文件上 的方式等。  In the communication system, each segment has the same ( ) teaching, performance teaching, etc., and will be in the upper operation (C, O COpe a o and a e a ceCe e ). There are many ways to put O C on it, and it will be taught to O C, or on the file.
以 用教 方式將 上 到 O C 每隔 介 將 的 按照 方式上 O C, O C 行解析 。 上 中 O C和 , 則教 的上 就 失敗, 神情況, 般的 理方式 在 介 內 , 不 上 的方法, 在 仍然 將性能教 上O C 但是, 同 介 或更多 , 就 出現 丟失。 內容  In the way of teaching, O C, O C will be parsed in the way that O C will be used every other way. On the O C and , the teaching fails, the God situation, the general way of thinking in the medium, not on the way, still teach the performance O C, but the same or more, there is a loss. Content
有 于此, 本 的主要目的在于提供 利用 行教 的 方法和裝置, 解決由于 元和O C 同 長而 的上 丟 失的 。  In view of this, the main purpose of this book is to provide a method and device for using the teaching method to solve the problem of loss due to the same length of the element and the O C.
到上 目的, 本 的 木方案是 的  For the purpose of the purpose, the wood plan is
本 提供了 利用 行教 的方法, 方法包括 在占前 度的特定 , 上 上 介 內 的 在上 成功, 且 前 沒有 , 依次將 中 的上 失敗的 This article provides a method of using the method of teaching, including methods that are pre-emptive , the success in the upper level, and not before, in turn will fail in the middle
上 。 On.
步 , 在 前 度的特定 , 休 前 , 的 到 , 。  Step, before the specific degree, before the break, to, .
上 上 介 內 的 失敗 , 方法 步包括 判定 前 , 將 失敗的上 介 內 的 存 中。  In the above-mentioned failure, the method step includes the existence of the failed upper-level mediation before the decision.
步 , 將 存 中, 休  Step, will save, rest
械力空 , 將 直接 存  The force is empty and will be stored directly
中有 的 , 且 中有空 同 , 將 存 前 中 最 械的 所占用的 羊 相 的、 且物 理地址高的 羊 中  There are some, and there are all the same in the middle, and the sheep with the highest physical position and the high physical address will be stored in the sheep.
已滿 , 將 覆蓋 前 械所 中最先 械的 。  When it is full, it will cover the most advanced of the front machinery.
方法 步包括 按照 先出的原則, 依次將 中 的 上 。  The method step consists of following the principle of first-in, followed by the upper one.
本 近提供了 利用 行教 的裝置, 包括 汁忖 、 和 ,  This device provides a means of teaching, including juice, and ,
, 于 和 , 近 于 和  , Yuhe , near and
, 于在所 , 上 上 介 內 的 近 于在所 上 介 內 的 上 成功, 且 前 沒有 , 依次將 中 的上 失敗的 上  In the context of the above, in the context of the above, the success in the above, and before, in the middle of the failure
, 于 上 失敗的 。 其中, , 步 于在 , 的 , 在所 到 , 。 , failed on the top. Among them, , , , , , , , , , , , ,
步 于, 在上 上 介 內 的 失敗 , 將 失敗的上 介 內 的 存  In the failure of the upper and lower media, the failure of the upper media
中。  in.
步 于,  Step by,
在所 械力空 , 將 直接 存  In the air force, it will be saved directly
在所 中有 的 , 且 中有空 同 , 將 存 前 中 最 械的 所占用的 羊 相 的, 且 理地址高的 羊 中  In the middle, and in the middle of the same, will be the most armed sheep in the front, and the high address of the sheep
在所 已滿 , 將 覆蓋 前 械所 中最先 械的 。  When it is full, it will cover the most advanced of the front machinery.
步 于, 按照 先出的原則, 依次將 中 的 上 。  Step by, according to the principle of first-in, in turn, the upper one.
本 利用 的方案, 使用 上 失敗 的 , 且本 的 羊 可以存儲的 大小是可 的, 的大小, 可以存儲 介或多 , 因此, 于本 的 行教 的 可以最大程度地利用 的存儲 同, 此可以存儲 多 內 失敗的 同 , 由于 可以 的 非 大, 因此, 元和 C的 同較長 , 也可以 同上 失敗的 不丟失, 而是 存在 中, 元和 C的 接 常 , 再將 中的 上 , 此 了 上 的穩定性。 另外, 在 將 中的 , 依 先 最新 的原則, 可能地保 的 于 效性不強的重要 的上 也很 有參考 。 說明The use of the scheme, the use of the failed, and the size of the sheep can be stored, the size, can be stored or more, therefore, the teaching of this line can be used to maximize the use of the same, this can The same as the failure of the storage, because it can be non-large, therefore, the same length of the yuan and C, can also be the same as the failure to lose, but in the presence of the yuan, and the C, and then the upper, this The stability of the above. In addition, in the middle, the latest principle, it is also important to ensure that the effectiveness is not strong. Description
1力本 利用 行教 的方法流程示意 1 force this way using the method of teaching
2 械的 示意 2
3 械的 示意 3 mechanical indication
4 的示意 4
5 的示意 5
6 的示意 6
7 的示意 7
8力本 利用 行教 的方案 的流程示意 9力本 利用 行教 的裝置 示意 。 休 方式  8 The power flow of the program using the teaching method is shown in the figure. Hugh way
下面結合 和 休 本 的 木方案 步 。 The following is a combination of and the rest of the wood program step.
1 所示力本 利用 行教 的方法流程示意 , 包括以 下步驟  1 shows the flow of the method using the method of teaching, including the following steps
步驟101, 在 前 度的特定 。  Step 101, the specificity of the previous degree.
步驟102, , 上 上 介 內 的 , 在上 成功, 且 前 沒有 , 依次將 中 的上 失敗的 上 。  Step 102, , above, above, succeeded, and not before, in turn, the upper one failed.
本 明中 械的 2所示, 上是 介物理地址 的 存儲 同 (物理地址由低到高、 ) 在存 , 滿 , 存儲的 可以將 分力 介或多 羊 , 羊 占用 段物理地址 的 同, 則 羊 都有 介起 始物理地址和 介 物理地址, 3 (a) 所示 羊 包含有 介或多 , 3 (b) 所示, 羊 的 長度十 + 長度, 其中 長度表示 的有效 的長度 即 的有效 的 休內容。 In the description of the machine 2, the storage of the physical address is the same (physical address from low to high), in the storage, full, storage can be divided into multiple or more sheep, the sheep occupy the physical address of the segment, The sheep have a physical address and a physical address, 3 (a) shows a sheep containing more or more, 3 (b), the length of the sheep is ten + length, and the length indicates the effective length. Effective Hugh content.
存 ( )和 ( ) 依 " 先 的原則 由于 是 段物理地址 的存儲 同, 物理地址較 低的存儲 同, 物理地址較高的存儲 同 因此在 , 將 由 始存儲直到 , 先將 的 送出去, 直到 的 , 由此可 , 的 的 、 先 。 The storage ( ) and ( ) are based on the principle that the physical address of the segment is the same, the storage with the lower physical address is the same, and the storage with the higher physical address is the same, so it will be stored from the beginning until it is sent out until , which can be, first, first.
3 (a) 所示, 滿 , 其中 1 羊 于 械的 (物理地址較低), 其存儲的 最先 羊 于 械的 (物理地址較高 ), 其存儲的 最 。 此 指針指向 羊 的起始物理地址, 指針指向 羊 的 物理地 址。  3 (a) As shown, full, of which 1 sheep are mechanical (low physical address), the first sheep stored in it (physical address is higher), which stores the most. This pointer points to the starting physical address of the sheep, and the pointer points to the physical address of the sheep.
需要指出的是, 指針和 指針的指向 看 中存儲 的 情況而 , 但是, 指針 指向最 械的 所占用 同 的 物理地址, 指針 指向最先 械的 所占用 同的起始 理地址。 休的 有多神情況, 將在 的 中 說明。  It should be noted that the pointer and the pointer point to the stored condition, but the pointer points to the most physically occupied physical address, and the pointer points to the same initial address occupied by the weapon. There are many god situations in Hugh, which will be explained in .
本 明中教 和 除了遵循 " 先 的規則, 近需要遵 循以下原則 最近 失敗 可存儲且最 先 其中, 最近 失 敗 可存儲" 是指即使 同滿 , 也可以 覆蓋 中的最 的方式將最新 失敗的 ( C 失敗的 ) "最 先 "是指按照 的新 程度, 先 最新 , 再 新 , 直到最 。 其中, 最新 即 最 械的 , 最 即 最先 械的 。 需要指 出的是, , 在 中將 清除, 以 于 的 。 本 明中 械的 特性, 在 可以分力 情況 In addition to following the "first rule, the following rules must be followed by the following principles: the most recent failure can be stored and the first one, the most recent failure can be stored" means that even if it is the same, the most way to cover the latest failure will be C failed "first" refers to the new level, the latest, new, until the most. Among them, the latest is the most armed, the most advanced. It should be pointed out that, in the middle will be cleared, so that. The characteristics of this machine, can be divided Happening
1、 至 至 足, 不需要 存儲, 4的 其中分 存儲是指 介 需要存儲在物理地址不連 的多 羊 1, to the full, do not need to store, 4 of which the storage refers to the need to store more than the physical address of the sheep
2、 至 至 足, 需分 存儲, 5的  2, to the full, need to be divided into storage, 5
3、 至 至 不足, 不需要 存儲, 6的 4、 至 至 不足, 需分 存儲, 7的 。 3, to the point of insufficient, do not need to store, 6 of 4, to the point is insufficient, need to be divided into storage, 7 of.
4所示 的示意 , 其中 3  The indication shown in 4, where 3
最新 失敗的 。 中可以看出, 在 3 械 前, The latest failed. It can be seen that before 3,
中已 了 1 和第 2 , 則 1 最  1 and 2, then 1
, 2 最新的 , 指針指向 1 的 起始物理地址 指針指向 2 的 物理地址。  , 2 The latest, the pointer points to the starting physical address of 1 The pointer points to the physical address of 2.
中, 中的 同大于將要 械的 3 的大 ( 同足), 因此, 可以將 3 存 2 相 的且物理地址高的 同即可, 則 指針指向 3 的 物 理地址, 3 最新 。  The middle and the middle are larger than the 3 large (same foot) of the weapon. Therefore, you can store the 2 phase and the physical address is high, then the pointer points to the physical address of 3, 3 is the latest.
此 , 若要將 中的 送出去、 即 , 則按照 的新 程度, 先 最新的 、 即 3 , 依次是 2 、 1 。 Therefore, if you want to send the out, that is, according to the new degree, the latest, that is, 3, followed by 2, 1 .
5所示 的示意 , 其中 3  The indication shown in 5, where 3
最新 失敗的 。 3 前的 可以看出, 前的 最 1 , 此 指針指向 1 的起始物 理地址 2 最新的 , 指針指向 2 的 物理地址。 于 的 已 清除, 則 械的起始物理 地址和第 1 的起始物理地址 同的存儲至 至 至 ( 同 2 的 物理地址和 械的 物理地址 同的 同 力空 同 ( 同 ) The latest failure. 3 can be seen before, the first one, this pointer points to the starting physical address of 2, the latest, the pointer points to the physical address of 2. The cleared physical, the starting physical of the device The address and the first physical address of the first store are stored to the same (the same physical address and physical address of the same power) (same)
此神情況下, 若要將 3 存 , 需要將 3 存 最新 ( 2 ) 所占用的 羊 相 的, 且 物理地址高的 羊 中、 即靠近 的 同 但是此  In this case of God, if you want to save 3, you need to save 3 of the latest ( 2 ) occupied sheep phase, and the physical address of the sheep is close, but the same
同 小于 3 的大小,而空 同 和 同 足 容納 3 Same size less than 3, while the same and the same foot accommodate 3
( 同足), 則可以將 3 分力 部分 ( 存儲), 前半部分 存 同 后半部分 存 同 中。 此 , 指針依 指向最 、 1 的起始物理地址, 而 指針則指向最新 、 3 的 物理地址。  (Same foot), you can divide the 3 component (storage), the first half and the second half. Thus, the pointer points to the starting physical address of the most 1, and the pointer points to the most recent physical address of 3.
此 , 若要將 中的 送出去, 則 先 最新的 、 即 3 (包括高 部分和低 部分), 依次是 2 、 1 。 Therefore, to send out the ones, the most recent ones, namely 3 (including the high part and the low part), are 2, 1 in order.
6所示 的示意 , 其中 4  The indication shown in 6 , where 4
最新 失敗的 , 中 占用了 介 羊 。The latest failure, the middle occupied the sheep.
4 前的 可以看出, 前的最 1 , 最新 3 , 且 3 的 物理地址 和第 1 的起始物理地址 同的至 至 至 。  4 It can be seen that the former 1st, the latest 3, and the physical address of 3 are the same as the first physical address of the first.
至 至用小于 4 的大 ( 同不足), 此 需要用 4 覆蓋最 , 果 前 同、 1 的大小 和第 2 的大 ( 部分 同 的) 足以容納 4 , 則 4 覆蓋 1 、 2 以及上 至 至 中 物理地址較低的部分, 多出 的 同力新的 同。 此 , 指針 向最 、 3 的起始物理地址, 指針指向最新 、 4 的 物理地址。 To use a large (same deficiency) of less than 4, this needs to cover the most with 4, the same as before, the size of 1 and the 2nd large (partially the same) is enough to accommodate 4, then 4 covers 1, 2 and up to The part with the lower physical address is the same as the new one. Thus, the pointer points to the starting address of the most, 3, and the pointer points to the latest , 4 physical address.
此 , 若要將 中的 送出去, 則 先 最新的 、 即 4 , 然 是 3 。 Therefore, if you want to send out the one, then the latest one, that is, 4, is 3 .
7所示 的示意 , 其中 4  The indication shown in 7 , where 4
最新 失敗的 。 4 前的 可以看出, 前的 最 1 , 最新 3 , 且 3 至 至同小于 4 的大 ( 同不足), 且 至 至 于 , 則可以將 4 分力 部分存儲 ( 存儲), 前 半部分 存 上 至 至 半部分則需要覆蓋最 , 果 1 和第 2 占用的 羊 足以容納 4 的 余 部分 , 4 的 余部分覆蓋 1 和第 2 占 用的 羊 中物理地址較低的 同, 余的力空 同。 此 , 指 針指向最 、 3 的起始物理地址, 指針指向最新 、 4 的 物理地址。 The latest failed. 4 It can be seen from the front that the first one, the newest 3, and the third to the same as less than 4 are large (same deficiency), and as such, the 4 component force part can be stored (stored), and the first half is stored to To the half, you need to cover the most. The 1st and 2nd occupied sheep are enough to accommodate the remainder of 4. The remaining part of 4 covers 1 and the 2nd occupied sheep have the same physical address, and the remaining force is the same. Thus, the pointer points to the starting physical address of the most, 3, and the pointer points to the latest, 4 physical address.
此 , 若要將 中的 送出去, 則 先 最新的 、 即 4 (包括高 部分和低 部分), 然 是 3 。  Therefore, to send out the ones, the latest ones, namely 4 (including the high part and the low part), are 3 .
于上 械的 , 本 利用 行教 的方案 的流程 8所示,  As shown in the process 8 of the program of using the teaching,
步驟801, , 。  Step 801, , .
的 , 1 介小 , 在 內 所需的 , 休 現有 木, 此 不再 。  The 1 is small, the one needed inside, the rest of the wood, this no longer.
步驟中, 在 前 內 的操作 直 到 前 以下步驟802至810是同 的。  In the step, the operations in the front are as straight as before. The following steps 802 to 810 are the same.
步驟802, , 向 C 送上 介 內 的 。 Step 802, , send to C .
較佳 , 可以在 介 , 核定 的 需要 、 5 等 到 、 即特定 , 。  Preferably, it can be referred to, approved, 5, etc., that is, specific.
程力 向 C 的 。 , 先向O C 送上 介 內 的 。 需要指出的是, 上 介  Cheng Li to C. , first send the O C to the inside. It should be pointed out that the introduction
內 的 不是 存在 中, 而是存儲在 介 的存儲 , 只 有在 內 失敗 , 才將 存 中。 The inside is not in existence, but stored in the storage of the media, and only if it fails internally, it will be stored.
步驟803, 送上 介 內 的 是否成功, 果是, 執行步驟806 果否, 執行步驟804  In step 803, it is successful whether the delivery is successful. If yes, go to step 806. If no, go to step 804.
向O C 送上 介 內 的 , 使用的流程力現 有的 上 流程, 此 不再贅述。  The current process is sent to the O C, and the process used is not described here.
果 向O C上 上 介 內 的 成功 , 接收到 O C的 消息, 然 執行步驟806 反 , 果沒有接收到 消息, 則判定 失敗, 執行步驟804  If the message to the O C is successful, the message of the O C is received, and if the message is not executed, if the message is not received, the process is determined to be a failure.
步驟804 805, 前 是否 , 果是, 執行步驟805, 將 失敗的上 介 內 的 存 果否, 返 步驟802  Step 804 805, whether or not before, if yes, executing step 805, failing the result of the failed application, and returning to step 802
送上 介 內 的 失敗 , 前  Sending a failure within the media
是否 , 果沒有 ,則返 步驟802,重新 送上 失敗的 If yes, if not, go back to step 802 and resend the failed
果 前 , 則 前不能再向 O C上 任何數 ( 失敗的上 介 內 的 、 和 中的 ), 將 失敗 的上 介 內 的 存 中, 前流程 , 直到下 介 , 行教 的 。 將 失敗的上 介 內 的 存 中, 其 休的 4至 7 的 , 此 不再 。 步驟806, 前 是否 , 果是, 前流程 果 否執行步驟807 In the past, before the number can not be transferred to the OC (failed in the upper, and in the middle), the failed in the middle of the deposit, the previous process, until the next, teach. Will fail in the middle of the deposit, its off 4 to 7 of this, this no longer. Step 806, whether before, if yes, the previous process does not perform step 807
送上 介 內 的 成功 也需要 前的 是否 果 ,則 前也不能再向O CJ 任何 , 流程 果沒有 , 則執行步驟807  If you want to succeed in the delivery, you can't do anything to O CJ before, if the process does not, then go to step 807.
步驟807, 依次 中 的 。  Step 807, in the order of .
此神情況即 在 前 必須在將上 介 內 的 送完成 , 才能 中 的 。 中 的 數 , 有 定的 順序、 即按照 的新日程度 先 最新 , 休 4 7所示的 , 此 不再 。  This divine situation must be completed before the completion of the submission. The number in the order has a certain order, that is, according to the degree of new day, the latest is shown in Hugh 4, which is no longer.
需要指出的是, 在依次 中 的 , 首先需要將 依次取出存 介 的 存儲 解析成 介完整的 才能 It should be pointed out that, in order, the storage that is sequentially taken out of the storage needs to be parsed into a complete talent.
O C。 于同 介 存儲在 或多 物理地址不連 的 羊 ( 5、 6中的 3 、 7中的 4 ), 需要 整合工作 即 中依次取出 的各 部分, 在 上 的 存儲 中 組合, 介完整的 , 然 上 多次提到的依次 按照 在 中存儲的新日程度, 先操作最新 。  O C. In the same store, the sheep (or 4 of 5, 7 of 5, 6) that are not connected to the physical address need to be integrated, that is, the parts that are sequentially taken out, combined in the upper storage, and the complete, The number of times mentioned above is followed by the latest level of the new day stored in the file.
步驟808 809, 是否成功, 果失敗, 則 前 是 否 , 果 , 前流程 果沒有 , 則返 步驟807, 重新 果 成功 步驟8 0  Step 808 809, whether it is successful, if it fails, then whether it is before, if the previous process does not, then return to step 807, and the result is successful. Step 8 0
步驟808中 是否成功的 同步驟803, 此 不再 。在 中的 失敗 ,且 前 , 則 不能再向O C上 任何 , 前流程 果 沒有 , 則返 步驟807, 新 中 失敗的 。 In step 808, it is the same as step 803, which is no longer the same. In the failure, and before, you can no longer go to the OC any, if the previous process does not, then go back to step 807. The new one failed.
步驟810, 是否 , 果是, 流程 果否, 返 80  Step 810, whether, if yes, the process is not, return 80
果 中 的 成功 , 近需要 是否已 將 中 的所有教 都已 O C, 果所有的 都已 送 完 , 則 流程 果 中近有 的 , 則返 步驟809, 前 是否 果 , 流程 果 沒有 , 則執行步驟807, 中 的 , 直到 中 的 送完 或者 。  If the success in the result is close to whether all the teachings in the middle have been OC, if all of them have been delivered, if there are some in the process, then go back to step 809, if the result is not before, if the process is not, then the steps are executed. 807, in the middle, until the delivery is finished.
了 上 的方法, 本 提供了 利用 行教 的裝置, 9 , 包括 汁忖 10、 20和  In the above method, this provides a device for using teaching, 9 , including juice 忖 10, 20 and
30,30,
10, 于 和 ,近 于 和 10, Yuhe, near and
20, 于在 , 上 上 介 內 的 近 于在上 介 內 的 上 成功, 且 前 沒有 , 依次 (按照 先出的原則 )將循 30中 的上 失敗的 上 20, in the upper, upper and lower, in the context of the success, and not before, in turn (according to the principle of first-in, the next failure in 30)
30, 于 上 失敗的 。 30, failed on the top.
10, 步 于在 , 的 , 在 到 , 。 10, step by, in, to, .
20 步 于, 在上 上 介 內 的 失 敗 , 將 失敗的上 介 內 的 存 30中。 In the 20 steps, the failure in the upper and lower levels will be lost in the upper 30.
20 步 于, 在 30力空 , 將 直接 存 30 在 30中有 的 , 且 30中有空 同 , 將 存 前 30中 最 械的 所占用的 羊 相 的, 物理地址高的 羊 在 30已滿 , 將 覆蓋 前 30 中最先 械的 。 20 steps in, at 30 force, will directly save 30 in 30, and there will be the same in 30, will save the most armed sheep in the first 30 The sheep with a high physical address is full at 30 and will cover the first 30 of the top.
以上 , 力本 的較佳 而已, 非 于限定本 的保 固。  Above, the strength of the book is better than the limit.

Claims

要求 Claim
1、 利用 行教 的方法, 其特 在于, 方法包括 在占前 度的特定  1. Using the method of teaching, which is characterized in that the method includes a specific
, 上 上 介 內 的 在上 成功, 且 前 沒有 , 依次將 中 的上 失敗的  In the above, the upper one succeeded, and the previous one did not, in turn, the upper one failed
上 。 On.
2、 要求 1所述利用 行教 的方法, 其特 在于, 在 前 度的特定 , 休 前 , 的 到 , 。 2. Requirement 1 The method of using the teaching method is characterized by the specificity of the previous degree, before the break, and to the .
3、 要求 1所述利用 行教 的方法, 其特 在于, 上 上 介 內 的 失敗 , 方法 步包括  3. The method of using the teaching method described in claim 1 is characterized in that the failure in the upper and lower levels, the method step includes
判定 前 , 將 失敗的上 介 內 的 存 中。  Before the decision, the failed ones will be saved.
4、 要求3所述利用 行教 的方法, 其特 在于, 將 存 中, 休  4. The method of using the teaching method described in claim 3, which is characterized in that
械力空 , 將 直接 存  The force is empty and will be stored directly
中有 的 , 且 中有空 同 , 將 存 前 中 最 械的 所占用的 羊 相 的、 且物 理地址高的 羊 中  There are some, and there are all the same in the middle, and the sheep with the highest physical position and the high physical address will be stored in the sheep.
已滿 , 將 覆蓋 前 械所 中最先 械的 。  When it is full, it will cover the most advanced of the front machinery.
5、 要求 1至4任 所 利用 行教 的方法, 其特 在于, 方法 步包括 按照 先出的原則, 依次將 中 的 上 。 5. Require the use of the method of teaching from 1 to 4, in particular, the method step consists of following the principle of first-in, followed by the upper one.
6、 利用 的裝置, 其特 在于, 包括 汁忖 、 和 , 6, the device used, its special features, including juice, with,
, 于 和 , 近 于 和  , Yuhe , near and
, 于在所 , 上 上 介 內 的 近 于在所 上 介 內 的 上 成功, 且 前 沒有 , 依次將 中 的上 失敗的 上 , 于 上 失敗的 。  In the context of the above, the above is successful in the above-mentioned mediation, and there is no prior, in which the upper one fails, and the upper one fails.
7、 要求6 利用 行教 的裝置, 其特 在于, , 步 于在 , 的 , 在所 到 , 。 7. Requirement 6 The use of the device of teaching, which is characterized by, step by, and where it is.
8、 要求6 利用 行教 的裝置, 其特 在于, 步 于, 在上 上 介 內 的 失敗 , 將 失敗的上 介 內 的 存  8. Requirement 6 The use of the device of teaching, which is characterized by the failure of the upper and lower media, and the failure of the upper media.
中。  in.
9、 要求8 利用 行教 的裝置, 其特 在于, 步 于,  9. Requirement 8 to use the device of teaching, which is characterized by
在所 械力空 , 將 直接 存  In the air force, it will be saved directly
在所 中有 的 , 且 中有空 同 , 將 存 前 中 最 械的 所占用的 羊 相 的, 且物 理地址高的 羊 中  In the middle, and in the middle of the same, will be the most armed sheep in the front, and the sheep with high physical address
在所 已滿 , 將 覆蓋 前 械所 中最先 械的 。  When it is full, it will cover the most advanced of the front machinery.
10、 要求 6至 8任 所 利用 行教 的裝置, 其 特 在于, 步 于, 按照 先出的原則, 依次將 中 的 上 。  10. Requirements 6 to 8 Any device used for teaching, the special feature is that, in accordance with the principle of first-in-first, the upper one is sequentially.
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Citations (3)

* Cited by examiner, † Cited by third party
Publication number Priority date Publication date Assignee Title
CN1747397A (en) * 2004-09-08 2006-03-15 中兴通讯股份有限公司 Performance data additional collecting system and method in telecommunication network management
CN101159634A (en) * 2007-10-25 2008-04-09 中兴通讯股份有限公司 Alarm recovery message reporting method
CN101699897A (en) * 2009-10-12 2010-04-28 中兴通讯股份有限公司 Method for complementarily reporting data with buffer memory and device thereof

Patent Citations (3)

* Cited by examiner, † Cited by third party
Publication number Priority date Publication date Assignee Title
CN1747397A (en) * 2004-09-08 2006-03-15 中兴通讯股份有限公司 Performance data additional collecting system and method in telecommunication network management
CN101159634A (en) * 2007-10-25 2008-04-09 中兴通讯股份有限公司 Alarm recovery message reporting method
CN101699897A (en) * 2009-10-12 2010-04-28 中兴通讯股份有限公司 Method for complementarily reporting data with buffer memory and device thereof

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