TWI326055B - - Google Patents

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TWI326055B
TWI326055B TW95141068A TW95141068A TWI326055B TW I326055 B TWI326055 B TW I326055B TW 95141068 A TW95141068 A TW 95141068A TW 95141068 A TW95141068 A TW 95141068A TW I326055 B TWI326055 B TW I326055B
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user
central air
temperature
conditioning
calculating
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TW95141068A
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TW200821975A (en
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1326055 九、發明說明: 【發明所屬之技術領域】 本發明係關於-種計算方法,尤指-種計算各用戶之 中央空調使用比例的方法。 【先前技術】 隨著社會經濟的繁榮發展,今曰的都市大街上商業大 樓林立,料商業大樓内通常有多個公司單位,而且整棟 大樓内邰會聚集為數眾多的工作人員,若不開啟空調,只 要極短時間即會令空氣品f變得很若每—房間均 裝設有一獨立的空調裝置,除安裝費用龐大之外,對於電 能的消耗亦極為可觀。 因此大部分的商業大樓均使用中央空調裝置,以冷氣 ,例,該中央空調裝置製作冷卻水並將冷卻水送至各:司 單位’ s-單位開啟空調後,該單位之送風機即開始運轉 7工氣"IL通,空氣經冷卻水降溫後被吹送到室内,即成為 所謂的冷氣。 Μ 早期計算各公司單位之中央空調使用比例的方法,係 按照各公司單位之建坪數為基準而計算所需分攤金額,惟 此種計算方法之缺點在於建坪數較大的單位未必需要較強 的工調’而建坪數較小的公司單位亦可能使用較強的空 調因此單以建坪數計算各公司單位之中央空調使用比例 實不甚公平。 為解決上述以建坪數計异所需分攤之中央空調費用的 不公平缺點,產業界目前有下列三種計算方式: 3 1326055 1 ·根據能量守恆定律,根據冷卻水的能量變化量來 計算,係以一計算裝置設於各公司單位之送風機處,取得 冷卻水流經該計算裝置之瞬間流量與冷卻空氣前後之溫 差’即可明破計算出冷卻水的實際能量變化量。 2 ·各公司單位的送風機啟動後量測送風機處冷卻水 的入水溫度,待冷卻水之溫度達一設定值時開始計時,配 合送風機運轉之熱功率以求得各公司單位使用中央空調之 比例。 3 ·當開啟冷卻水的水閥令冷卻水流入送風機時,即 計异各公司單位之送風機耗電量,以作為中央空調之使用 比例。 准上述叶舁方法皆有其缺點: 方法1雖有計費公平且合理之優點,惟由於方法1需 要a十里多種參數’且為了提高量測溫差所需之精準度,所 需要的溫度測量儀器亦必須較為精密,故整體而言,方法 1之成本過高’尚難以在市面上普及; 方法2相較於方法1,則有著成本較低的優點,惟成 本較低’準確度自然就打了折扣,且當冷卻水尚未達溫度 設疋值時,能量雖已有消耗,卻不在使用比例的計算範圍 内’更會產生計費不公平之問題; 方法3之成本介於方法1與方法2之間’但室内送風 機馬達之耗電量並沒有辦法確實掌握室内負載之變化情 形,仍舊會產生計費不公平之問題。 由上述可知,現有中央空調之使用比例計算方法尚有 4 1326055 待改進之處。 【發明内容】 為解決目前 J叶异中央空調使用比例方法不夠 及相關搭配設備僧故,a 一 貝格過尚之缺點,本發明之主要 供一種計算各用戶之由± 罟目的在如 之中央工調使用比例的方法,盆 地計算各用戶之办 /、J A十 合。 I調使用比例,且毋需高成本的設備配 •為達成則述目的所採取之主要技術手段係令前述計算 法,用於巾失空調裝置’該中央空調裝置係連接各用 戶之至内运風機,^分戶計算中央空調使用比例之方法包 括下列步驟: 疋義各用戶之使用參數,係定義中央空調裝置之製冷/ 製熱百分比例Α ^ ’"、Vw以及中央空調裝置之額定製冷/製埶能 力為wunit; …、 , 鬥迗風機出風口與用戶室内一處之溫差值△ τ,係於室内说门 風機啟動時,偵知室内送風機出風口與用 戶室内任一虛 ' 之/皿度為Τ!以及τ2,並求得該兩溫度(Τ, τ2)的差值為Λτ; 15 什异各用戶之單位使用量Q,係將Vw、Wunit、△丁以 及送風機運轉時間t相乘而得; oa 求出各用戶使用中央空調之比例,係將各用戶之所有 平位· ^ ffl ^ r\ 用里Q相加而得到各用戶之中央空調總使用量1326055 IX. Description of the invention: [Technical field to which the invention pertains] The present invention relates to a calculation method, and more particularly to a method for calculating a usage ratio of a central air conditioner for each user. [Prior Art] With the prosperity of the social economy, there are many commercial buildings on the streets of the city. There are usually a number of company units in the commercial building, and there are many staff members in the whole building. Air conditioning, as long as it is very short, will make the air product f very much. If each room is equipped with a separate air conditioning unit, in addition to the huge installation cost, the consumption of electric energy is also very considerable. Therefore, most commercial buildings use central air-conditioning units to cool air. For example, the central air-conditioning unit produces cooling water and sends the cooling water to each unit: the unit's unit opens the air conditioner, and the unit's blower starts to run. The gas is “IL”, and the air is blown into the room after being cooled by the cooling water, which becomes so-called air-conditioning.早期 The method of calculating the proportion of central air-conditioning used by each company unit in the early stage is based on the number of flats of each company unit. The shortcoming of this calculation method is that the unit with a large number of construction units does not necessarily need to be strong. It is not fair to calculate the proportion of central air-conditioning used by each company unit by the number of construction units. In order to solve the unfair shortcomings of the above-mentioned central air-conditioning expenses that need to be allocated according to the number of constructions, the industry currently has the following three calculation methods: 3 1326055 1 · According to the law of conservation of energy, according to the energy variation of cooling water, A computing device is provided at the blower of each company unit, and the temperature difference between the instantaneous flow rate of the cooling water flowing through the computing device and the cooling air is obtained, and the actual energy change amount of the cooling water can be calculated clearly. 2 · After the blower of each company unit starts, measure the inlet water temperature of the cooling water at the blower. When the temperature of the cooling water reaches a set value, start timing, and match the heat power of the blower operation to obtain the ratio of the central air conditioner used by each company unit. 3 • When the water valve that turns on the cooling water causes the cooling water to flow into the blower, the power consumption of the blower of each company unit is used as the ratio of the use of the central air conditioner. The above-mentioned leafhopper method has its shortcomings: Although the method 1 has the advantages of fair and reasonable billing, the temperature measuring instrument required for the method 1 requires a plurality of parameters of a ten-in order and the accuracy required for measuring the temperature difference is required. It must also be more sophisticated, so overall, the cost of Method 1 is too high's to be popular in the market; Method 2 has the advantage of lower cost compared to Method 1, but the cost is lower. Discount, and when the cooling water has not reached the temperature set value, although the energy has been consumed, but it is not within the calculation range of the use ratio, the billing unfair problem will occur; the cost of the method 3 is between the method 1 and the method. Between 2, but the power consumption of the indoor blower motor does not have a way to really grasp the change of the indoor load, and the billing unfair problem will still occur. It can be seen from the above that there are still some ways to calculate the usage ratio of the existing central air conditioner. SUMMARY OF THE INVENTION In order to solve the shortcomings of the current J-leaf central air-conditioning use ratio method and related collocation equipment, a-Belg has a shortcoming, and the present invention is mainly used for calculating a user's purpose. The method of using the ratio is adjusted, and the basin calculates the operation of each user/JA. I use the ratio, and the equipment that is in need of high cost. The main technical means adopted to achieve the stated purpose is to use the above calculation method for the air conditioner of the towel. The central air conditioner is connected to each user. The method of calculating the proportion of the central air conditioner by the households includes the following steps: The usage parameters of each user are defined as the percentage of cooling/heating of the central air-conditioning unit Α ^ '", Vw and the rated cooling of the central air-conditioning unit / 埶 埶 w w ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... , , , , , , , , , , , , , , , , The degree of the dish is Τ! and τ2, and the difference between the two temperatures (Τ, τ2) is Λτ; 15 The unit usage Q of each user is Vw, Wunit, △ and the blower running time t phase Oa finds the ratio of the central air conditioner used by each user, and adds all the flat positions of each user · ^ ffl ^ r\ plus Q to obtain the total central air conditioning usage of each user.

Qt ,i、 以各用戶之QTotal除以所有用戶QT()tal之總和而 得的百分比例。 5 丄 WOU:):) 利用上述技術手段,本發明 戶室内送風機出風口與室内任意處的法错由計算各用 裝置之製冷/製熱能力納入計 ;^,以將中央空調 空調用戶使用量,進而可精準地算出各2一準確的中央 之比例,以公平地計算各用戶 戶使用中央空調 【實施方式】 1才之費用。 本發明係應用於—中央空 連接各用戶之室内送風機,且可為^央空調裝置係 空調裝置(俗稱室内機)或一二次交換:式一對多的多聯 第一圖所示,本發明之第裝置;請參閱 作之中央空調而包括下列步驟: 、;以冷乳模式運 定義各用戶之使用參 定義有兩個參數Vw與w •糸針對該中央空調裝置 之製冷/製熱百分比:’、(通;二係指中央靖^ 數除以室内送風機之額定最大、風機運轉時之運轉段 中央空調裝置之額又),而Wunit則是該 之額疋製冷/製熱能力。 偵測室内送風機出 儀於室内送風機送風二與内至广本實施例 控制器、室内中央處 I田處(例如中央空調之 測器,該溫声咸:卜 機之回風口)分設有-溫度感 ° 又卩》、丨器可測量乾球溫度或溼球、.田产n a# 測量乾球與漫球溫 …球…或同時 時測量乾球與座球溫声,、ί貫施例中該溫度感測器係可同 利用溫度感心心又卜用戶之室内送風機啟動時,Qt, i, the percentage of each user's QTotal divided by the sum of all users QT() tal. 5 丄WOU:):) Using the above technical means, the method of calculating the cooling/heating capacity of each device by the air outlet of the indoor air blower of the present invention is calculated by calculating the cooling/heating capacity of each device; In addition, the ratio of each of the 2 accurate centers can be accurately calculated to fairly calculate the cost of using the central air conditioner [Embodiment] 1 for each user. The invention is applied to the indoor air blower connecting the central air to each user, and can be an air conditioner device (commonly known as an indoor unit) or a second exchange: a one-to-many multi-connection first diagram, this The device of the invention; please refer to the central air conditioning and the following steps: 、; define the usage of each user in the cold milk mode. There are two parameters Vw and w • 百分比 The percentage of cooling/heating for the central air conditioner : ', (pass; second refers to the central Jing number divided by the maximum rated indoor air blower, the central air conditioning unit of the operating section when the fan is running), and Wunit is the amount of cooling / heating capacity. Detecting the indoor blower is provided in the indoor blower air supply 2 and the inside to the wide controller of the embodiment, and the indoor center I field (such as the central air conditioner tester, the warm sound salt: the air return of the machine) is provided - Temperature sense ° 卩 丨 丨 丨 丨 丨 丨 丨 丨 丨 丨 丨 丨 丨 丨 丨 丨 丨 丨 丨 丨 丨 丨 丨 丨 丨 可 可 可 可 可 可 可 可 可 可 可 可 可 可 可 可 可 可 可 可 可 可 可The temperature sensor can be activated when the indoor air blower is used with the sense of temperature and the user.

Td、τ :以:俄知該用戶送風機出風口之乾、澄球溫度 W2 ……該用戶室内之乾、澄 6 判斷室内溫度是否大於室内送 (1〇2):係分別計算△ Td=Td2_ τ〇丨和 別判斷ATD與aTws否大於〇。 味若至内/现度係大於室内送風機出風口處之溫度,則計 昇用戶之單位使用量(103):於本實施例中係每秒將與 wu…之乘積分別乘上ΛΤΙ)與ATW,以得到用戶每秒之單 位使用量QDunit和QWunit〇Td, τ: to: the Russian knows the user's blower outlet, the clear ball temperature W2 ... the user's indoor dry, Cheng 6 to determine whether the indoor temperature is greater than indoor delivery (1 〇 2): the system calculates △ Td = Td2_ Τ〇丨 and do not judge whether ATD and aTws are greater than 〇. If the inside/out of the taste is greater than the temperature at the air outlet of the indoor blower, the unit usage of the user is increased (103): in this embodiment, the product of wu is multiplied by 每秒, respectively, and ATW. To get the user's unit usage per second QDunit and QWunit〇

,於汁每單位時間内用戶之單位使用量(i03)步驟之 後二或當室内溫度小於/等於室内送風機出風口處溫度時, 進,V確。忍至内送風機是否停止運轉(1〇4) ··係藉由判斷室 送風機疋否仍在運作以確^是否要結算此次中央空調之 使用比例。 出風口溫度與室内之溫度(1〇1)步驟 右至内迗風機已停止運轉,則求得用戶之總使用量In the case of the user's unit usage per unit time (i03), or when the indoor temperature is less than/equal to the temperature at the outlet of the indoor blower, V is correct. Tolerate whether the internal fan is stopped (1〇4) ·· Is it still working by judging whether the blower is still in operation to determine whether the central air conditioner is to be used? Air outlet temperature and indoor temperature (1〇1) step Right to the internal fan has stopped running, then the total user usage is obtained.

風機出風口處之溫度 △ TW=TW2—TW1,且分 右至内送風機尚在運轉,則繼續進行偵 (5 )·係將各用戶之單位使用旦 里QDunit和QWunit相加而得 央空調總使用量為QT。…; 求出各用戶使用中本& ,^ 用T央工調之比例(1〇6):係先將各用戶 之中央空調總使用| ^ 里Qt〇u丨相加而得一總用量υ,再將 FH ci y-vThe temperature at the air outlet of the fan is △ TW=TW2—TW1, and the right to the inner blower is still running, then continue to detect (5)·The unit of each user uses the QDunit and QWunit to add the central air conditioner. The amount used is QT. ...; Find the proportion of each user's use of this & , ^ with the T-central adjustment (1〇6): the first use of the central air-conditioning total use of each user | ^ Qt〇u丨 add a total amount Oh, then FH ci yv

Tou丨除以U所得的百分比例即是各用戶使用中央 工《周之比例,利用 各用戶使用中央空調之比例即可精確 地^各用戶所需缴交之冷氣使用費用。 以暖閱第二圖所示’本發明之第二實施例係應用於 一式運作之中央空調,包括下列步驟: 7 疋義各用戶之使用參數 偵喷卜h 数(00)(與第-實施例相同)。 偵測至内送風機出風口與 施例相同)。 興至内之-度(101)(與第一實 由於本實施例係應用於以 因此於^模式運作之中央空調, 至内送風機出風口盘它 係判斷室内逆風U 溫度(101)步驟後, 广風機出風口處之溫度是否大於 (102 )’即是分別計算 =τ 度 且分別妇齒“ D1 Td2 和△ TW’ = TW1-TW2, 且“」判斷ΔΤ。,與’是否大於〇。 :至内送風機出風口處之溫度係大於室内溫度 异用戶之單位使用量⑽):係每 ㉞ 別桊!_ Λ 丁,如A W /、W unit I艰積分 D 一 W’,以得到用戶每秒之單位使用量Qd , 和 Qwunit,。 VDunit 於計算每單位時間内用$ „ ^ +丄 吁门内用戶之早位使用量(103)步驟之 後,或“内送風機出風口處溫度小於/等於室内溫度時, 進一步確認室内送風機是否停止運轉(1〇4)。 右室内送風機尚在運轉,則繼續進行谓測室内送風機 出風口溫度與室内之溫度(1〇1)步驟。 右至内送風機已停止運轉,則求得用戶之總使用量 (1〇5):係將各用戶之單位使用* Q—’和QWunit,相加而得 用戶之中央空調總使用量為Qt。…,; 求出各用戶使用中央空調之比例(i〇6),係先將各用戶 之中央空調總使用量QT〇ta|,相加而得一總用量U,,再將各 用戶之QT〇tal’除以u,所得的百分比例即是各用戶使用中央 空調之比例’寿|J用此各用戶使用中央空調之比例即可精確 1^26055 之中央空調總使用量Qw’相加而得一總用量u,,,再將各 用戶之QT〇tal除以u,所得的百分比例即是各用戶使用中央 空調之比例’制此各用戶使用中央^調之比例即可精確 地求出各用戶所需繳交之送風使用費用。 此外,請參閱第四圖所示,上述計算用戶之單 ,003)003^^The percentage of Tou丨 divided by U is that each user uses the central laborer's “percentage of the week, and the proportion of the central air conditioner used by each user can accurately calculate the air-conditioning usage fee that each user needs to pay. As shown in the second figure, the second embodiment of the present invention is applied to a central air conditioner operated in a single mode, and includes the following steps: 7 使用 各 各 各 各 各 各 各 各 各 各 各 各 各 各 各 各 各 各 各 各 各 各The same example). The air outlet of the internal fan is detected as the same as the example). Since the first embodiment is applied to the central air conditioner operating in the ^ mode, the inner air blower outlet is determined by the step of determining the indoor upwind U temperature (101). Whether the temperature at the air outlet of the wide fan is greater than (102)' is calculated separately = τ degrees and the teeth "D1 Td2 and △ TW' = TW1-TW2, respectively, and "" judges ΔΤ., and 'is greater than 〇. The temperature at the air outlet of the air blower is greater than the indoor temperature (10) of the user's unit temperature: every 34! _ Λ, such as A W /, W unit I difficult to integrate D a W ', in order to get the user's unit usage per second Qd, and Qwunit,. VDunit further confirms whether the indoor blower is stopped after calculating the unit usage (103) step of the user in the door per unit time, or when the temperature at the outlet of the air blower is less than/equal to the indoor temperature. (1〇4). When the right indoor blower is still running, continue to measure the temperature of the indoor blower outlet and the indoor temperature (1〇1). When the right-to-inner blower has stopped running, the total usage of the user is obtained (1〇5): the unit Q_’ and QWunit are used for each user's unit, and the total central air-conditioning usage of the user is Qt. ...,; Find the proportion of each user's use of central air conditioning (i〇6), first add the total central air conditioning usage QT〇ta| of each user, and get a total usage U, and then the QT of each user 〇tal' is divided by u, and the percentage obtained is the ratio of the central air conditioner used by each user. 'Shou|J uses the ratio of the central air conditioner for each user to accurately calculate the total central air conditioning usage Qw' of 1^26055. Get a total amount of u,, and then divide each user's QT〇tal by u, the percentage of the obtained example is the ratio of the central air conditioner used by each user's system. The air usage fee payable by each user. In addition, please refer to the fourth figure, the above calculation user list, 003) 003 ^ ^

(其中㈣’2’ 3.·. n’其中n為任意常數),記錄與 △TWm之持續時間分別為^與^(即是Α持續^、、、 =D2持續t2秒…持續L秒;持續tl秒、ΔΤμ ^2Γ.ΔΤνη持續w,並將乘積分 。。乘 k與、以及與tWm,以得到用戶每秒之 單位使用量QDunit和Qw_〇 由上述可知本發明僅需於室内送風機之送風口以及 室内裝設有溫度感測器,並取得各用戶使用中央空調裝置 之參數,即可利關單的加減乘除運算求得各用戶使用中 央空=比例,因此毋需精密的測量儀器以及配備,故可 有y郎省成本;再者’由於本發明係於室内送風機開始運 轉時’只要室内送風機之送風口與用戶室内溫度有溫差的 έ卩曰開始&十費’因此不致有漏算或多算之問題,進而 有較佳的精準度。 惟本發明雖已於前述實施例中所揭露,但並不僅限於 前述實施例中所提及之内容,在不脫離本發明之精神和範 内斤作之任何變化與修改,均屬於本發明之保護範圍。 綜上所述,本發明相較既有中央空調使用比例之計算 1326055 方法已具備顯著功效增進,並符合發明專利要件,爰依法 提起申請。 【圖式簡單說明】 第一圖:係本發明第一實施例之流程圖。 第二圖:係本發明第二實施例之流程圖。 第三圖:係本發明第三實施例之流程圖。 第四圖:係本發明又一實施例中該溫差值△ TDm與△ TWm所持續時間L之關係示意圖。 【主要元件符號說明】 無 11(Where (4) '2' 3.·. n' where n is an arbitrary constant), the duration of the record and ΔTWm are ^ and ^ respectively (that is, Α continues ^, ,, = D2 for t2 seconds... for L seconds; For tl seconds, ΔΤμ^2Γ.ΔΤνη lasts w, and multiplies the integral. Multiply k and , and tWm to obtain the user's unit usage per second QDunit and Qw_〇 From the above, the present invention only needs to be used in the indoor blower. The air supply port and the indoor temperature sensor are installed, and the parameters of the central air-conditioning device are obtained by each user, so that the user can use the central air=ratio for the addition, subtraction, multiplication and division of the profit order, so that a precise measuring instrument is needed. And equipped, so you can have the cost of ylang province; in addition, 'because the invention is used when the indoor blower starts running, as long as there is a temperature difference between the air supply port of the indoor blower and the user's indoor temperature, the start and the ten charges will not be The problem of missing or multi-calculating, and thus better precision. However, the present invention has been disclosed in the foregoing embodiments, but is not limited to the contents mentioned in the foregoing embodiments, without departing from the spirit of the present invention. Fan Fanjin Any changes and modifications are within the scope of protection of the present invention. In summary, the present invention has a significant improvement in the calculation of the ratio of the use of the central air-conditioning ratio of the 1325055 method, and complies with the invention patent requirements, and filed an application according to law. BRIEF DESCRIPTION OF THE DRAWINGS The first drawing is a flow chart of a first embodiment of the present invention. The second drawing is a flow chart of a second embodiment of the present invention. The third drawing is a flow chart of a third embodiment of the present invention. Fourth figure is a schematic diagram showing the relationship between the temperature difference Δ TDm and the duration L of Δ TWm in another embodiment of the present invention. [Main component symbol description] None 11

Claims (1)

Ϊ326055 申請專利範圍 1 * 一種計算各用戶之中央空調使用比例的 應用於一中央空調裝置,該中央空調裝置係連接各用戶之 室内送風機,並具有複數溫度感測器,該分戶計算中央空 調使用比例之方法包括下列步驟: 定義各用戶之使用參數,係定義該中央空調裝置的實 際製冷/製熱百分比例係為Vw以及定義該中央空調裝置之 額定製冷/製熱能力係為Wunit; 偵測室内送風機出風口與用戶室内任一處之溫差值八 T,係於室内送風機啟動時’由該溫度感測器偵知室内送 風機出風口與用戶室内任一處之溫度為Τι以及τ2,並求 得該兩溫度(TBT2)的差值為Δτ; 計算各用戶之單位使用量Q,係將H、Δτ以 及送風機運轉時間t相乘而得; 求出各用戶使用中央空調之比例,係將各用戶之所有 單位使用* Q相加而得到各用戶之中央空調總使用量 QTotal ’ 再以各用戶之 QTot , F4s I'i m >· 仏。⑴除以所有用戶Qt之總和而 得的百分比例》 2 ·如申請專利範圍第1項所述計算各用戶之中央空 調使用比例的方法,其中該偵測室内送風機出風口與用戶 室内-處之溫差值ΔΤ步驟進—步包括下列程序: 偵測室内送風機出風口與室内之溫度; 判斷室内溫度是否大於室二二’ 送風機出風口處之溫唐; 當室内溫度係大於室内送風 處之胤度, 機出風口處之溫度,則進 12 行計算用戶之單位使用量步驟; “於Ϊ算每翠值時間内用戶之單位使用量步驟之後,或 ::内·度小於/等於室内送風機出風口處溫度 行 未出各用戶使用中央空調之比例步驟。 !進仃 :申請專利範圍第2項所述計算各用戶之中央空 量步驟之後,或.室=早位時間内用戶之單位使用 溫产時田内'皿度小於/等於室内送風機出風口處 '皿度%,進一步包括下列步驟: 確 < 至内送風機是否停止運轉; 若室内送風機已停止運 央空調之比例步驟; _貝…了求出各用戶使用中 若室=送風機尚在運轉,則繼續進 出風口溫度與室内之溫度步驟。 i内送風機 1你H h申°月專利範圍第1項所述計算各用戶之中央办 调使用比例的方法,盆 尸之宁央工 室内-處之m 貞測室内送風機出風口與用戶 夕,差值Δτ步驟進-步包括下列程序: 偵測室内送風播+ 風機出風口與室内之溫度; 判斷室内送風檣 去室内、、, 處之溫度是否大於室内溫度; 田至内达風機出風口處 行計算用戶之單位使用量步驟至溫度,則進 於汁异每單位時間内 〇〇 當室内送風機出風口處^之早位使用量步驟之後’或 求出各用戶使用中卜::广等於室内溫度時,則進行 、二調之比例步驟。 5 .如申請專利範圍第4項所述計算各用戶之中央空 13 1326055 ^吏用比例的方法,於計算每單位時間内用戶 ^步驟之後’或當室内送風機出風口處溫声— 溫度時,進-步包括下列步驟:'皿/等於室内 確認室内送風機是否停止運轉; 若㈣送風機已停止運轉,則進行求 央空調之比例步驟; 州尸便用甲 若室内送風機尚在運轉,則姨 一 出風口溫度與室内之溫度步驟。S仃偵测室内送風機 6 ·如申請專利範圍第i項所 調使用比例的方法,其中…卜“各用戶之中央空 室内一處之⑺差’、〜至内送風機出風口與用戶 内= 皿差值ΔΤ步驟進一步包括下列程序: 谓測至内送風機出風口與室内之溫度; 判斷室内送風機出 ^ 否不為0; 處與至内溫度之絕對溫差值是 當室内送風機出風口處盥 〇,則進^算用戶之單位使用量步^之絕對溫差值不為 於„十算每單位時間内用戶之單位 至内送風機出風H 吏用里步驟之後,或 進行求出各用:使用中央二=差值為"’則 調使:比二:==!所述計算各用戶之中央空 量步驟之後,或室内、,,彳早位時間内用戶之單位使用 差值為〇時,進—牛运風機出風口處與室内溫度之絕對溫 步包括下列步驟: 確認室内送風機是否停止ϋ轉; 1326055 若室内送風機已停止運轉 央空調之比例步驟; 若室内送風機尚在運轉, 出風口溫度與室内之溫度步驟 ’則進行求出各用戶使用中 則繼續進行偵測室内送風機Ϊ 326055 Patent Application No. 1 * A central air conditioning unit for calculating the proportion of central air conditioners used by each user, the central air conditioning unit is connected to the indoor air blower of each user, and has a plurality of temperature sensors, which calculate the central air conditioner The method of proportion includes the following steps: Defining the usage parameters of each user, defining the actual cooling/heating percentage of the central air conditioning unit as Vw and defining the rated cooling/heating capacity of the central air conditioning unit as Wunit; The temperature difference between the air outlet of the indoor blower and any part of the user's room is eight T, which is when the indoor blower is started. 'The temperature sensor detects the temperature of the indoor blower outlet and any part of the user's room is Τι and τ2, and asks The difference between the two temperatures (TBT2) is Δτ; the unit usage amount Q of each user is calculated by multiplying H, Δτ, and the blower operation time t; and the ratio of the central air conditioner used by each user is determined. All units of the user use * Q to add the total amount of central air conditioning for each user QTotal ' and then QTot for each user , F4s I'i m >· 仏. (1) A percentage example obtained by dividing the sum of all users Qt. 2 · A method for calculating the usage ratio of the central air conditioner of each user as described in the first item of the patent application, wherein the indoor air outlet of the air blower is detected and the user indoors The temperature difference ΔΤ step further includes the following procedures: detecting the temperature of the indoor blower outlet and the indoor; determining whether the indoor temperature is greater than the temperature at the air outlet of the chamber 22; when the indoor temperature is greater than the indoor air supply , at the temperature of the air outlet, enter the user's unit usage step in 12 rows; “After the user's unit usage step in each time value, or :: inner degree is less than/equal to the indoor blower air outlet The temperature line does not show the proportion of each user using the central air conditioner. ! 仃 仃: After calculating the central emptiness step for each user as described in item 2 of the patent application scope, or the unit = early time, the user's unit uses the temperature production. The time in the field is less than / equal to the % of the air outlet of the indoor blower, and further includes the following steps: YES < Whether the air blower is stopped Operation; If the indoor blower has stopped the proportioning step of the central air conditioner; _Bei... Find out if the user is using the room = the blower is still running, then continue to enter and exit the air outlet temperature and the indoor temperature step. i Internal blower 1 you H h The method of calculating the usage ratio of the central office of each user mentioned in the first paragraph of the patent scope of the application of the month is the method of the central office of the pelvic corpse, and the m-measurement of the indoor air blower outlet and the user eve, the difference Δτ steps into the step Including the following procedures: Detect indoor air supply + fan air outlet and indoor temperature; determine whether indoor air supply goes indoors, and the temperature at room is greater than indoor temperature; Tian to Nida fan air outlet to calculate user unit usage Step to temperature, then enter the juice every unit time 〇〇 When the indoor blower outlet is at the early use step of the ^, or find the user in use:: wide is equal to the indoor temperature, then proceed, two Step of adjusting the ratio. 5. Calculate the method of calculating the ratio of the central air 13 1326055 ^ for each user as described in item 4 of the patent application scope. After the user ^ step or 'When the indoor blower outlet is warm-sound-temperature, the step-by-step includes the following steps: 'Dish/equal to the indoor to confirm whether the indoor blower stops running; If (4) the blower has stopped running, proceed to the center Air-conditioning ratio step; State corpse is used when the indoor air blower is still running, then the temperature of the air outlet and the temperature of the room are stepped. S仃Detecting the indoor blower 6 · The method of using the proportion of the i-th item of the patent scope , wherein...b"the (7) difference in the central empty room of each user, ~ to the inner fan outlet and the user inside the dish difference ΔΤ step further includes the following procedure: pre-measured to the temperature of the air outlet of the inner blower and the room; Judging whether the indoor blower is not 0; the absolute temperature difference between the temperature and the internal temperature is when the indoor air blower outlet is 盥〇, then the absolute temperature difference of the user's unit usage step is not „ After the user's unit to the internal fan blower H in each unit of time, or after the steps are used, use the central two = difference is "' : than two: ==! After the calculation of the central air volume of each user, or indoor,,, 彳, the user's unit use difference is 〇 in the early time, the inlet and outlet temperature of the inlet and the cattle fan The absolute temperature step includes the following steps: Confirm whether the indoor blower stops to turn; 1326055 If the indoor blower has stopped operating, the proportion of the central air conditioner; If the indoor blower is still running, the outlet temperature and the indoor temperature step ' The user continues to detect the indoor blower while in use. 8 ·如f請專利範圍第項中任―項所述計算各 用戶之中央空調使用比例的方法,該偵測室内送風機出風 口與用戶室内任-處之溫差值Λτ步驟係偵知室内送風機 出風口與用戶室内任一處之乾球溫度。 9如申吻專利範圍第1至7項中任一項所述計算各 用戶之中央空調使用比例的方法,該偵測室内送風機出風 口與用戶室内任-處之溫差值“步驟係镇知室内送風機 出風口與用戶至内任一處之澄球溫度。 1 0 .如申§青專利範圍第1至7項中任一項所述計算 各用戶之中央空調使用比例的方法,該偵測室内送風機出 風口與用戶室内任一處之溫差值Δτ步驟係偵知室内送風 機出風口與用戶室内任一處之乾球與溼球溫度。 11·如申請專利範圍第1至7項中任一項所述計算 各用戶之中央空調使用比例的方法,該計算各用戶之單位 使用量Q步驟係每一秒鐘將Vw、Wunit以及△ τ相乘而得。 12·如申請專利範圍第8項所述計算各用戶之中央 空調使用比例的方法,該計算各用戶之單位使用量q步驟 係每一秒鐘將Vw ' wunit以及δτ相乘而得。 13·如申請專利範圍第9項所述計算各用戶之中央 空調使用比例的方法,該計算各用戶之單位使用量Q步驟 15 1326055 係每一秒鐘將vw、wun“以及△ τ相乘而得。 1 4 ·如申請專利範圍第i 〇項所述計算各用戶之中 央空調使用比例的方法,該計算各用戶之單位使用量Q步 驟係每一秒鐘將Vw、wunit以及Δτ相乘而得。 1 5 .如巾請專利範圍第項中任—項所述計算 各用戶之中央空調使用比例的方法,該計算各用戶之單位 使用量Q步驟係於每次改變時,記錄Δτ之持續時間 為t,並將乂…與W-之乘積分別乘上δτ與卜以得到用 戶之單位使用量Q。 1 6 ·如中請專利範㈣8項所述計算各用戶之中央 空調使用比例的方法,該計算各用戶之單位使用量q步驟 係於每次△丁改變時’記錄Μ之持續時間為t,並將Vw 乘積分別乘上,以得到用戶之單位使用 篁Q 0 1 7 .如申請專利範圍第9項所述計算各用戶之中央 空調使用比例的方法,該計算各 係於每次ΔΤ改變時,替Δτ *早位使用量Q步驟 愈w 步 —§己錄ΔΤ之持續時間為卜並將VW Wunit之乘積分別乘上△ τ與〖, 量Q。 X仵到用戶之單位使用 1 8 .如申請專利範圍第"項 央空調使用比例的方法,該計算各各用戶之中 驟係於每時,記錄Δτ之持=使用量Q步 與之乘積分別乘上^與t, J為t,並將〜 量Q。 件到用戶之單位使用 1326055 19 ·如申請專利範圍第1至7項令任一項所述计算 各用戶之中央空調使用比例方法,係用以作為計算分攤中 央空調總費用之依據。 20.如申請專利範圍第8項所述計算各用戶之十央 空調使用比例方法,係用以作為計算分攤令央空調總費用 之依據。 21·如申凊專利範圍第9項所述計算各用戶之中央8 ·If f is required to calculate the proportion of the central air-conditioning usage of each user as described in the item in the scope of the patent scope, the temperature difference between the air outlet of the indoor blower and the user room is 侦τ step to detect the indoor blower The dry bulb temperature at the tuyere and anywhere in the user's room. 9 The method for calculating the usage ratio of the central air conditioner of each user according to any one of the items 1 to 7 of the patent application scope, the temperature difference between the air outlet of the indoor air blower and the user room is “steps of the town interior” The air outlet of the blower and the temperature of the ball at any point in the user. 1 0. The method for calculating the proportion of the central air conditioner of each user as described in any one of claims 1 to 7 of the claim §, the detection room The temperature difference between the air outlet of the blower and any part of the user's room Δτ is to detect the dry bulb and wet bulb temperature of the indoor blower outlet and any part of the user's room. 11·If you apply for any of the patent scopes 1 to 7 The method for calculating the usage ratio of the central air conditioner of each user, wherein the unit usage amount Q step of each user is obtained by multiplying Vw, Wunit, and Δτ every second. 12) The method for calculating the usage ratio of the central air conditioner of each user is described. The unit usage amount q step of each user is obtained by multiplying Vw 'wunit and δτ every second. 13· Calculated as described in claim 9 Each user Central air-conditioning method used in a proportion of the amount of each unit of the user based every Q steps 151,326,055 seconds vw, wun "and △ τ obtained by multiplying. 1 4 · The method of calculating the usage ratio of the central air conditioner of each user as described in the scope of the patent application section i, the calculation of the unit usage amount Q step of each user is obtained by multiplying Vw, wunit and Δτ every second. 1 5 . For the method of calculating the central air-conditioning usage ratio of each user as described in the item of the patent scope, the unit usage Q step of each user is calculated, and the duration of recording Δτ is changed for each change. t, and multiply the product of 乂... and W- by δτ and 卜 respectively to obtain the unit usage amount Q of the user. 1 6 · For the method of calculating the proportion of central air-conditioning used by each user as described in the 8th patent (4), the unit usage q step of each user is calculated as the duration of the record 每次 every time the △ is changed, Multiply the Vw product by the user's unit to obtain 用户Q 0 1 7 . The method for calculating the central air-conditioning usage ratio of each user as described in claim 9 of the patent scope is determined by each ΔΤ change. For the Δτ * early use amount Q step more w steps - § recorded Δ Τ duration is b and multiply the product of VW Wunit by Δ τ and 〖, quantity Q. X仵 to the user's unit use 1 8 . If you apply for the patent scope " item central air conditioning use ratio method, the calculation of each user among the various points, record Δτ holding = use quantity Q step with the product Multiply ^ and t respectively, J is t, and ~ is Q. The use of the unit to the user's unit 1326055 19 · The calculation of the central air-conditioning usage ratio method for each user as described in any of the patent applications No. 1 to 7 is used as a basis for calculating the total cost of the central air conditioner. 20. The method for calculating the usage ratio of the ten central air conditioners for each user as described in item 8 of the patent application scope is used as the basis for calculating the total cost of air conditioning for the allocation of the central air conditioner. 21· Calculate the centrality of each user as described in item 9 of the application scope of the application 空調使用比例方法,係用以作為計算分攤中央空調總費用 之依據。 2 2 ·如申請專利範圍第丄〇項所述計算各用戶之中 央空調使用比例方法,係用以作為計算分攤中央空調總費 用之依據。 2 3 ·如申請專利範圍第i 1項所述計算各用戶之中 央空調使用比例方法,係用以作為計算分攤中央空調總費 用之依據。 、 2 4 .如申請專利範圍第i 2項所述計算各用戶之中 央空調使用比例方法,係、用以作為計算分攤中央空調 用之依據。 "、 2 5 .如中請專利範㈣i 3項所述計算各用戶之中 央空調使用比例方法,係 '用以作為計算分攤中央 用之依據。 u 26 .如中請專利範圍第14項所述計算各用戶之中 央空調使用比例方法,係用以作為 用之依據。 作為冲…中央空調總費 17 1326055 27·如f請專利範圍第15項所述計算各用戶之中 央工調使用比例方法’係用以作為計算分攤中央空調總費 用之依據。 2 8 ·如中請專利範圍第1 6項所述計算各用戶之中 央空調使用比例方法,係用以作為計算㈣t央空調總費 用之依據。 2 9 ·如中凊專利範圍第i 7項所述計算各用戶之中 央空調使用比例方法,係用以作為計算分攤中央空調總費 _用之依據。 3 0 .如申請專利範圍第1 8項所述計算各用戶之中 央空調使用比例方法,係用以作為計算分攤中央空調總費 - 用之依據。 • 31.如申請專利範圍第1至7項中任—項所述計算 各用戶之中央空調使用比例的方法,其中一溫度感測器係 設於中央空調控制器處’用以偵測中央空調控制器設置處 ^ 之溫度。 3 2 _如申請專利範圍第8項所述計算各用戶之中央 空調使用比例的方法’其中一溫度感測器係設於中央空調 控制器處’用以偵測中央空調控制器設置處之溫度。 33.如申請專利範圍第9項所述計算各用戶之中央 空調使用比例的方法,其中一溫度感刹器係設於中央空調 控制器處,用以偵測中央空調控制器設置處之溫度。 3 4 .如申請專利範圍第1 〇項所述計算各用戶之中 央空調使用比例的方法,其中一溫度感測器係設於中央空 18 1326055 調控制器設置處,用以偵測中央空調控制器設置處之溫 度。 35·如申請專利範圍第1至7項中任一項所述計算 各用戶之中央空調使用比例的方法,其中一溫度感測器係 設於室内中央處,用以偵測室内中央處之溫度。The air-conditioning use ratio method is used as the basis for calculating the total cost of central air-conditioning. 2 2 · Calculate the proportion of the central air-conditioning usage of each user as described in the scope of the patent application, as a basis for calculating the total cost of central air-conditioning. 2 3 · Calculate the proportion of the central air-conditioning usage of each user as described in item i 1 of the patent application scope, which is used as the basis for calculating the total cost of central air-conditioning. 2. The method for calculating the proportion of central air conditioners used by each user as described in item i 2 of the patent application scope is used as a basis for calculating the central air conditioning. ", 2 5. The method for calculating the proportion of central air-conditioning used by each user as described in the patent scope (4) i, is used as the basis for calculating the central allocation. u 26 . The method for calculating the proportion of central air conditioners used by each user as described in item 14 of the patent scope is used as a basis for use. As a central air-conditioning total fee 17 1326055 27 · If you want to calculate the proportion of the use of the central processing method for each user as described in Item 15 of the patent scope, it is used as the basis for calculating the total cost of central air-conditioning. 2 8 · Calculate the proportion of the central air-conditioning usage of each user as described in item 16 of the patent scope, which is used as the basis for calculating the total cost of (4) t-air conditioning. 2 9 · Calculate the proportion of the central air-conditioning usage of each user as described in item i 7 of the patent scope of Zhongli, which is used as the basis for calculating the total central air-conditioning total cost. 3 0. Calculate the proportion of the central air-conditioning usage of each user as described in item 18 of the patent application scope, which is used as a basis for calculating the total central air-conditioning total cost. • 31. A method for calculating the usage ratio of central air conditioners of each user as described in any one of claims 1 to 7 of the patent application, wherein a temperature sensor is provided at the central air conditioner controller to detect the central air conditioner The temperature at which the controller is set to ^. 3 2 _ The method for calculating the proportion of central air conditioners used by each user as described in item 8 of the patent application scope. [One temperature sensor is installed at the central air conditioner controller to detect the temperature at the central air conditioner controller setting. . 33. A method for calculating a central air conditioning usage ratio of each user as described in claim 9 wherein a temperature sensing brake is provided at the central air conditioning controller for detecting a temperature at a central air conditioning controller setting. 3 4. A method for calculating the proportion of central air conditioners used by each user as described in the first paragraph of the patent application, wherein a temperature sensor is provided at the central air conditioner 18 1326055 to adjust the central air conditioning control. The temperature at which the device is set. 35. The method for calculating a central air-conditioning usage ratio of each user according to any one of claims 1 to 7, wherein a temperature sensor is disposed at a center of the room to detect a temperature at a center of the room. . 36·如申請專利範圍第8項所述計算各用戶之中央 空調使用比例的方法,其中一溫度感測器係設於室内中央 處’用以偵測室内中央處之溫度。 37.如申請專利範圍第9項所述計算各用戶之中央 空調使用比例的方法,其中一溫度感測器係設於室内中央 處’用以偵測室内中央處之溫度。 3 8如申°月專利範圍第1 0項所述計算各用戶之中 央空調使用比例的方法,其_—溫度_㈣設於室内中 央處’用以偵測室内中央處之溫度。 39·如申請專利範圍第⑴項中任一項所述計算 各用戶之中央空調使用比例的方法’纟中一溫度感測器係 設於室㈣風機之回風σ處,用以㈣Μ送風機之回風 口處的溫度。 a U v ’S ,’丨<。|升分用戶之中央 玄調使用比例的方法1中一溫度感測器係設於室内送風 機之回風Π處,用貞測室内送風機之回風口處的溫产。 41 專利範圍第9項所述計算各用戶之^央 玄調使用比例的方法’丨中一溫度感測器係設於室内送風 機之回風口處,用〜貞測室内送風機之回風π處的、、田卜 19 1326055 42 ·如中請專㈣圍第10項所述計算各用戶之中 央空調使用比例的方沐,甘士 , ,其 j去’其中一溫度感測器係設於室内β 風機之回風口處,用w扁加—丄 ^ 用以偵測至内送風機之回風口處的冰 度。 …43 ·如申請專利範圍第工、2、3、6或7項所述 計异各用戶之中央空調使用比例方法其中該中央空裯裝 置係為二次熱交換之中央冰水裝置。36. A method of calculating a central air-conditioning usage ratio of each user as described in claim 8 wherein a temperature sensor is disposed at a central portion of the room to detect the temperature at the center of the room. 37. A method of calculating a central air-conditioning usage ratio of each user as described in claim 9 wherein a temperature sensor is disposed at a central portion of the room for detecting a temperature at a center of the room. 3 8 For the method of calculating the proportion of the central air conditioner used by each user as described in item 10 of the patent scope of the application, the temperature_(4) is set at the center of the room to detect the temperature in the center of the room. 39. The method for calculating the usage ratio of the central air conditioner of each user as described in any one of the claims (1) of the patent application, wherein the temperature sensor is disposed at the return air σ of the fan of the chamber (4) for (4) the blower of the fan The temperature at the return air outlet. a U v ’S ,’丨<. |The central point of the user is the method of using the proportion of the Xuan tone. The temperature sensor is installed in the return air of the indoor air blower to measure the temperature output at the air return of the indoor blower. 41 The method for calculating the usage ratio of each user's 玄 玄 所述 丨 丨 丨 丨 丨 丨 丨 丨 丨 丨 丨 丨 丨 温度 温度 温度 温度 温度 温度 温度 温度 温度 温度 温度 温度 温度 温度 温度 温度 温度 温度 温度 温度 温度 温度 温度 温度 温度 温度 温度 温度 温度,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,, At the return air outlet of the fan, use w flat plus 丄^ to detect the ice level at the return air inlet of the internal blower. ...43. The central air conditioning use ratio method for each user as described in the patent application scope, item 2, 3, 6 or 7 wherein the central open space device is a central ice water device for secondary heat exchange. 士 4 4 .如申請專利範圍第1、2、3、6或7項所述 -十算各用戶之中央空調使用比例方法,其中該中央空調装 置為直膨式一對多之多聨冷氣機裝置。 —4 5 如申請專利範圍第1、4、5、6或7項所述 計算各用戶之中央空調使用比例方法,其中該令央空調裝 置係為二次熱交換之中央熱水裝置。 一 4 6 .如申請專利範圍第1 、4、5、6或7項戶斤述 計算各用戶之中央空調使用比例方法’其中該中央空調裝 置係為直膨式一對多之多聨暖氣機裝置。 47.如申請專利範圍第丄至了項中任一項所述計算 各用戶之中央空調使用比例方法,其中該中央空調裝置係 為直膨式一對多之多聨冷暖氣機裝置。 十一、囷式: 如次頁 20士4 4 . As described in the scope of patent application No. 1, 2, 3, 6 or 7 - the central air-conditioning usage ratio method for each user, wherein the central air-conditioning unit is a direct-expansion one-to-many air conditioner Device. — 4 5 Calculate the central air-conditioning usage ratio method for each user as described in the scope of patent application No. 1, 4, 5, 6 or 7. The central air-conditioning unit is a central hot water unit for secondary heat exchange. A 4 6 . If the patent application scope is 1, 4, 5, 6 or 7 to calculate the central air-conditioning usage ratio method for each user', the central air-conditioning unit is a direct-expansion one-to-many heater Device. 47. A method of calculating a central air conditioning usage ratio for each user as described in any one of the preceding claims, wherein the central air conditioning unit is a direct expansion type one-to-many plurality of air-cooling heater units. XI, 囷: as the next page 20
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