TW518286B - Method and related apparatus for addressing operations of a printer with single sensor - Google Patents

Method and related apparatus for addressing operations of a printer with single sensor Download PDF

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Publication number
TW518286B
TW518286B TW91108589A TW91108589A TW518286B TW 518286 B TW518286 B TW 518286B TW 91108589 A TW91108589 A TW 91108589A TW 91108589 A TW91108589 A TW 91108589A TW 518286 B TW518286 B TW 518286B
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Taiwan
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cam
sensor
printer
section
flange
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TW91108589A
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Chinese (zh)
Inventor
Sheng-Chih Lin
Tung-Ming Hsieh
Kuan-Chih Huang
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Hi Touch Imaging Tech Co Ltd
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Priority to TW91108589A priority Critical patent/TW518286B/en
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Publication of TW518286B publication Critical patent/TW518286B/en

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Abstract

A method and related apparatus for addressing operations of a printer. The printer includes a sensor and a driving wheel for rotating to drive the printer into different states such as initial, paper-feed and printing states. The driving wheel has a rib with a first section and at least a second section corresponding to the different states of the printer. When the driving wheel rotates and the rib passes the sensor, the sensor is capable of sensing the rib to generate a rib sensing signal and sensing the first and the second sections to generate a section sensing signal. The method includes: determining the rotation position of the driving wheel only according to the sensing signal of the sensor.

Description

518286518286

五、發明說明(1) 發明之領域: 定址的方法及相關裝 定位印表機動作的方法 本發明係提供一種印表機動作 置,尤指一種僅以單一感應器即能 及相關裳置。 背景說明: 丨处百I仅影像擷取、處理的枯 數位影像輸出設備,也已經:nr;界;::: :驅動結ί ^示ί至圖圖一圖C二^為―e鸠—習知印表機10中相 ^明圖一c為圖一A中凸輪2〇的側^見表姓機10驅動結構之側視 的方便,在不影響本發明技:構示意圖。為了後 '舍 B中的部分機械機構已經以:的情形下,圖一 文;,藝者所知’印表機中c設於殼體12上叫 待是紙張、相紙或其他媒c來將待£ 制iV凸輪2〇、-致動輪16、二中設置有-牵: Q 19。牽引輪14、凸輪2〇及致 器W、以及―4 _ 動輪16均以可轉動的方; 518286V. Description of the invention (1) Field of the invention: Method of addressing and related equipment Positioning method of printer operation The present invention provides a printer operation mechanism, especially a device that can be used with a single sensor and related equipment. Background note: 丨 The digital image output device that only captures and processes the image is also available in: nr; jie; FIG. 1c is a side view of the cam 20 in FIG. 1A. See the convenience of the side view of the drive structure of the table name machine 10 without affecting the technical and structural aspects of the present invention. In order to 'part of the mechanical mechanism in the house B has been: in the case, a picture ;, the artist knows' in the printer c is set on the casing 12 to be paper, photo paper or other media c To be controlled iV cam 20,-actuating wheels 16, 2 are provided with-pull: Q 19. The traction wheel 14, the cam 20 and the actuator W, and the _4_ moving wheel 16 are all rotatable; 518286

設置於设體1 2上。當印表機彳 (未圖示)會透過一定的傳動印表機10中的馬達 14轉動。牽引輪14轉動時會—起慨』未圖示)帶動牽引輪 轉動後又會帶動致動輪16轉動。:凸輪20轉動,凸,20 如夹嬙1 η由知μ λα德 而致動輪1 6轉動後就能帶 作業。由於致動輪16旋轉於不同角=紙列印4專相關 機械機構進行不同的作f,要产二時會帶動印表機1 0的 關作業,就要清楚定LLi 控制印表機10的各相 M+史址致動輪16的動作情形。因為定址的 品要,用來帶動致動輪16的凸輪20上,設有凸緣l8A、 yB。配合凸緣18心18B,印表機1〇中還設置了兩個感應 ,S卜S 2。感應器S卜S 2固定於殼體丨2上,通常為光感測 器’皆電連於控制器1 9。如圖一 c所示,凸輪2 0 (部分無 關構造已經省略)的凸緣1 8 A與i 8B呈圓弧形狀,位在不^ 半徑的同心圓周上;凸緣18A的空缺處形成區段PG1,凸緣 18B的空缺處則形成區段PG2。當凸輪20帶動致動輪16轉動 時,凸緣1 8 A及區段P G 1也會被帶動而掠過感應器s 1。當凸 緣1 8 A經過感應器S1時,由感應器S 1發出的光線會被凸緣 1 8 A遮斷,此時感應器S1會產生一對應的凸緣感應訊號, 輸出至控制器1 9 ;相對地,當區段PG 1經過感應器S丨時, 感應器S 1發出的光線不會被凸緣1 8 A遮斷,此時感應器s 1 就會對應地產生一區段感應訊號以輸出至控制器1 9。同 理,感應器S2也會感應凸緣18B及區段PG2,並對應地產生 相異的凸緣感應訊號及區段感應訊號’輸出至控制器1 9。 控制器1 9根據感應器S卜S2的感應訊號’就能分析出凸輪Set on the body 12. When the printer 彳 (not shown) is rotated by a certain motor 14 in the printer 10. When the traction wheel 14 rotates, it will start-not shown) to drive the traction wheel and then to drive the actuation wheel 16 to rotate. : The cam 20 rotates and protrudes. If the 嫱 1 η is known from μ λα and the actuating wheel 16 is rotated, the work can be carried out. Since the actuating wheel 16 rotates at different angles = the relevant mechanical mechanism of the paper printing 4 performs different operations f. If the closing operation of the printer 10 will be driven at the second production, each of the LLi control printer 10 must be clearly determined Phase M + historical site actuation of the actuation wheel 16. Because of the addressing requirements, the cams 20 for driving the actuating wheels 16 are provided with flanges 18A, yB. With the flange 18 core 18B, the printer 10 is also provided with two sensors, S2 and S2. The sensors S2 and S2 are fixed on the housing 2; usually, the light sensors' are electrically connected to the controller 19. As shown in Fig. 1c, the flanges 1 8 A and i 8B of the cam 20 (partially irrelevant structures have been omitted) are in the shape of an arc and are located on a concentric circle with no radius; the vacant portion of the flange 18A forms a section PG1, the vacancy of flange 18B forms section PG2. When the cam 20 drives the actuating wheel 16 to rotate, the flange 18 A and the segment P G 1 are also driven to pass over the sensor s 1. When the flange 1 8 A passes the sensor S1, the light emitted by the sensor S 1 will be blocked by the flange 1 8 A. At this time, the sensor S1 will generate a corresponding flange induction signal and output it to the controller 1. 9; In contrast, when the segment PG 1 passes the sensor S 丨, the light emitted by the sensor S 1 will not be blocked by the flange 1 8 A. At this time, the sensor s 1 will generate a segment induction correspondingly. The signal is output to the controller 19. Similarly, the sensor S2 will also sense the flange 18B and the segment PG2, and correspondingly generate different flange sensing signals and segment sensing signals' to the controller 19. The controller 19 can analyze the cam based on the sensing signals of the sensors S2 and S2.

518286 五、發明說明(3) 2 〇轉動的情況,連帶地也能定位致動輪1 6的轉動情形,達 到控制印表機動作的目的。 更明確地說,凸輪2 0上的凸緣1 8 A、1 8 B分別定義出邊 緣La、Lb、Lc ;各邊緣對應一特定作業的起始位置。請參 考圖二A至圖二c(並一併參考圖一 C)。圖二A至圖二B分 別為印表機1〇進行初始(initialization)作業(即預備開 始列印前的相關作業)、饋紙作業及列印作業時,凸輪2 0 的位置。如圖二A所示,當凸輪2 0轉動而使凸緣1 8 A的邊緣 La恰好對齊感應器s丨之位置時,凸輪2 〇也就可以帶動致動 輪1 6讓印表機丨〇進行初始作業。如圖二B所示,當凸輪2 〇 轉動而使凸緣1 8A的邊緣Lb恰好對應感應器S1之位置時, 凸輪2 0就能帶動致動輪丨6讓印表機丨〇進行饋紙作業。同 理’如圖二C所示,當凸輪2 〇轉動而使凸緣1 8B的邊緣Lc對 應至感應器S2之位置時,凸輪2 〇也就能帶動致動輪1 6讓印 表機1 0進行列印作業。 換句話說,在動力帶動牽引輪1 4 (圖518286 V. Description of the invention (3) In the case of 20 ° rotation, the rotation of the actuating wheel 16 can be positioned even with the purpose of controlling the printer's movement. More specifically, the flanges 18 A, 18 B on the cam 20 define edges La, Lb, Lc, respectively; each edge corresponds to a starting position of a specific job. Please refer to Figure 2A to Figure 2c (also refer to Figure 1C). Figures 2A to 2B are the positions of the cam 20 when the printer 10 is performing an initialization operation (that is, preparing a related job before printing is started), a paper feeding operation, and a printing operation. As shown in FIG. 2A, when the cam 20 is rotated and the edge La of the flange 18 A is exactly aligned with the position of the sensor s 丨, the cam 20 can also drive the actuating wheel 16 to allow the printer 丨 〇 to perform Initial job. As shown in FIG. 2B, when the cam 20 rotates so that the edge Lb of the flange 18A corresponds to the position of the sensor S1, the cam 20 can drive the actuating wheel 丨 6 to allow the printer 丨 〇 to perform the paper feeding operation. . Similarly, as shown in FIG. 2C, when the cam 20 rotates and the edge Lc of the flange 18B corresponds to the position of the sensor S2, the cam 2 can also drive the actuating wheel 16 to let the printer 1 0 Perform a print job. In other words, the traction wheels 1 4 (Figure

A ^ ^ ......〜 “ β)轉動’ 並透過凸輪20帶動致動輪丨6時,印表機丨〇就能進行不同的 作業,最終完成整個列印流程(包含初始作業、饋紙作業 t I:印作業)。為了控制各作業間的動作銜接’控制器1 9 |利用感應器以、S2來感測凸輪2〇上凸緣18Α、ι8β及區段 /1、PG2間父互變換的情形,以分析出凸輪2〇轉動的情 况,連帶定址致動輪16的轉動情形及印表機1〇進行的各種A ^ ^ ...... ~ "β) Turning 'and driving the actuation wheel through the cam 20 丨 6, the printer 丨 〇 can perform different jobs, and finally complete the entire printing process (including the initial job, feed Paper job t I: printing job). In order to control the action of each job, the controller 1 9 | uses the sensor to detect the cam 20, the upper flange 18Α, ι8β, and the section / 1, PG2. The mutual conversion is analyzed to analyze the rotation of the cam 20, the rotation of the addressing actuation wheel 16 and the various operations performed by the printer 10.

518286 五、發明說明(4) 作業。除了在印表機1 〇運作期間定址相關作業外,印表機 1 0還要能將凸輪2 0回歸至初始作業的位置(也就是圖二A 中所示的情形)。因為在印表機1 0作業期間,可能會因電 力中斷、使用者操作失誤或人為中斷等情形而中斷作業, 導致凸輪2 0的位置也停在不明的位置。當凸輪2 0作業中斷 而停止轉動時,很有可能就會像谓一 C中所示的例子,此 時邊緣La、Lb、及Lc都沒有恰好對應至感應器S卜S2的位 置。當印表機1 0由中斷後再度開始運作的時候,一定要先 將凸輪2 0帶動至一特定的位置(通常就是要使凸輪2 0轉動 至初始作業的位置,即圖二A所示的位置),才能正常進 行後續的作業。而習知印表機1 0就是以兩個感應器S卜S1 分別感應凸緣18A、區段PG1及凸緣18B、區段PG2交替經過 感應器的情形,以控制器1 9來控制凸輪2 0轉動,以定址至 圖二A中所示的情形。 在習知印表機1 0中,各感應器僅對應至單一凸緣及區 段,要定址凸輪2 0於圖二A、二B及二C中三種作業時的位 置,勢必要以兩個感應器提供的感應訊號才能搭配分析出 凸輪2 0轉動的位置。這樣一來,就會增加習知印表機1 0生 產製造的成本。而習知印表機1 0中的兩個感應器中,只要 有一個故障,就會無法定址凸輪2 0轉動的情形,連帶地也 使印表機1 0無法正常運作。這也使得習知印表機1 〇的維修 成本增加,無法提升印表機的妥善率。518286 V. Description of Invention (4) Homework. In addition to addressing related jobs during the operation of the printer 10, the printer 10 also needs to be able to return the cam 20 to the original job position (the situation shown in Figure 2A). During the operation of the printer 10, the operation may be interrupted due to power interruption, user error or human interruption, etc., and the position of the cam 20 also stops at an unknown position. When the operation of the cam 20 is stopped and the rotation is stopped, it is likely to be like the example shown in C. At this time, the edges La, Lb, and Lc do not correspond to the positions of the sensors S2 and S2. When the printer 10 starts to operate again after being interrupted, it is necessary to first drive the cam 20 to a specific position (usually to rotate the cam 20 to the initial operation position, as shown in Figure 2A Location) in order to follow up normally. The conventional printer 10 uses two sensors S1 and S1 to sense the flange 18A, the segment PG1 and the flange 18B, and the segment PG2 alternately pass the sensors, and the controller 2 controls the cam 2 0 turns to address to the situation shown in Figure 2A. In the conventional printer 10, each sensor corresponds to only a single flange and section. To locate the position of the cam 20 in the three operations shown in Figures A, B and C, it is necessary to use two. Only the sensing signal provided by the sensor can be used to analyze the position where the cam 20 rotates. As a result, the cost of manufacturing and manufacturing the conventional printer 10 will increase. However, as long as one of the two sensors in the printer 10 is faulty, the addressing cam 20 cannot rotate, and the printer 10 cannot operate normally. This also increases the maintenance cost of the conventional printer 10, which fails to improve the printer's availability.

518286 ________ —- -------— 五、發明說明(5) 發明概述· 因此,本發明之主要目的在於提供一種僅需單一感應 器即能定址凸輪轉動情形的印表機及相關方法,以解決習 知技術的缺點。 發明之詳細說明: 請參考圖三Α及圖三β。圖三Α為本發明印表機3 0中相 關驅動結構的示意圖;圖三B則為印表機3 0驅動結構的側 視示意圖。類似於習知印表機丨〇的配置,本發明印表機3 0 中也設有一控制印表機3 〇之控制器3 9,以及一牽引輪3 4、 一凸輪40、一致動器36,分別以可轉動的方式設置於印表 機3 0的殼體Μ上。印表機3〇會以動力帶動牽引輪34轉動, 進一步帶動凸輪4 0轉動;而凸輪4〇的圓弧狀的輪緣41就會 連帶地帶動致動為3 6 ’使印表機3 〇能進行不同的作業。與 習知印表機1 〇不同的是,本發明印表機3 0僅設有單一感應 器S ’固定於殼體1 2上;控制器3 9在接收感應器S的感應訊 號後,就能分析出凸輪4 〇轉動的情形,進而定址印表機3 0 的作業動作。雖然圖三A、三b中的實施例是以凸輪40特殊 設計的輪緣41來帶動致動器36,並連帶地驅動印表機30進 行不同的作業,但本發明中的凸輪也可以是像圖一 A中一 樣以齒輪齧合來帶動致動輪、驅動印表機作業。進一步的 說,本發明的重點在於如何僅以單一感應器S就能精確定518286 ________ —- -------— 5. Description of the invention (5) Summary of the invention · Therefore, the main purpose of the present invention is to provide a printer and related method that can address the cam rotation situation with only a single sensor. To address the shortcomings of conventional techniques. Detailed description of the invention: Please refer to FIG. 3A and FIG. 3β. FIG. 3A is a schematic diagram of a related driving structure in the printer 30 of the present invention; FIG. 3B is a schematic side view of the driving structure of the printer 30. Similar to the configuration of the conventional printer 丨 〇, the printer 30 of the present invention is also provided with a controller 39 for controlling the printer 30, and a traction wheel 34, a cam 40, and an actuator 36. Are respectively rotatably arranged on the casing M of the printer 30. The printer 30 will drive the traction wheel 34 to rotate, and further drive the cam 40 to rotate; and the arc-shaped rim 41 of the cam 40 will be actuated to act as a 3 6 'to make the printer 3 〇 Capable of different operations. Different from the conventional printer 10, the printer 30 of the present invention is only provided with a single sensor S 'fixed on the housing 12; the controller 39 receives the sensor S signal, and then It can analyze the rotation of the cam 40, and then address the operation of the printer 30. Although the embodiment in FIGS. 3A and 3b uses the rim 41 specially designed by the cam 40 to drive the actuator 36 and drives the printer 30 to perform different operations, the cam in the present invention may also be As in Figure 1A, the gear meshing is used to drive the actuation wheel and drive the printer. Further, the point of the present invention is how to precisely determine with a single sensor S

518286 五、發明說明(6) 址凸輪4 0轉動的情形;至於凸輪4 0如何帶動印表機3 0進行 各種作業,則可有多種不同的設計;在不影響本發明技術 揭露之情形下,以下仍將重點放在感應器S對凸輪4 0定址 的技術。 類似於習知技術的配置,凸輪4 0也設有凸緣3 8以配合 感應器S感應凸輪4 0的轉動情形;請繼續參考圖三C、三 D。圖三C為本發明中凸輪4 0的外視示意圖,圖三D則為凸 輪4 0的側視示意圖(為求圖示之清晰,部分與技術揭露無 關的結構已適當地省略)。與習知技術不同的是,如圖三 D所示,本發明中的凸輪4 0上的凸緣3 8是呈等半徑之圓弧 分佈,環繞凸輪4 0轉動之圓心0 ;而在本實施例中,配合 印表機3 0的三種作業(初始作業、饋紙作業及列印作業 )’凸緣38上也設有二個空缺處’形成區段Gl、G2、G3。 區段G1為第一區段,與圓心0呈現A1的夾角;區段G2為第 二區段,與圓心0呈現A2的夾角;區段G3則為第三區段, 於圓心0呈現A3的夾角。其中,夾角A1大於夾角A2及A3 ; 在較佳實施例中,夾角A2則與夾角A3相等。區段G1至G3則 分別定義出邊緣P 1至P3,對應於印表機3 0的三種作業。在 凸輪4 0轉動時,當凸緣3 8經過感應器S時,感應器可發出 一凸緣感應訊號;當空缺處的區段G卜G 2及G 3經過感應器 S時,感應器S則能發出一區段感應訊號。根據感應器S相 異的凸緣感應訊號及區段感應訊號,控制器3 9就能控制凸 輪4 0定址。518286 V. Description of the invention (6) The situation where the address cam 40 rotates; as for how the cam 40 drives the printer 30 to perform various operations, there can be many different designs; without affecting the technical disclosure of the present invention, The following will focus on the technology of the sensor S addressing the cam 40. Similar to the configuration of the conventional technology, the cam 40 is also provided with a flange 38 to cooperate with the sensor S to sense the rotation of the cam 40; please continue to refer to FIGS. 3C and 3D. Fig. 3C is a schematic diagram of the external view of the cam 40 in the present invention, and Fig. 3D is a schematic diagram of the side view of the cam 40 (for clarity of the illustration, some structures not related to technical disclosure have been appropriately omitted). Different from the conventional technology, as shown in FIG. 3D, the flanges 38 on the cam 40 of the present invention are distributed in a circular arc of equal radius, and the center of rotation 0 of the cam 40 is rotated; In the example, the three operations (initial operation, paper feeding operation, and printing operation) of the printer 30 are provided with two vacancies on the flange 38 to form sections G1, G2, and G3. Segment G1 is the first segment and presents an angle of A1 with circle center 0; segment G2 is the second segment and presents an angle of circle A2 with circle center 0; segment G3 is the third segment and presents A3 at circle center 0 Angle. The included angle A1 is greater than the included angles A2 and A3. In a preferred embodiment, the included angle A2 is equal to the included angle A3. Segments G1 to G3 define edges P 1 to P 3 respectively, which correspond to the three jobs of printer 30. When the cam 40 rotates, when the flange 38 passes the sensor S, the sensor can send out a flange induction signal; when the vacant sections G 2 and G 3 pass the sensor S, the sensor S It can send a segment of induction signal. The controller 39 can control the addressing of the cam 40 according to the different flange induction signals and section induction signals of the sensor S.

第10頁 518286 五、發明說明(7) 請參考圖四A至圖四C。圖四A至圖四C分別為凸輪4 0帶 動印表機3 0進行初始作業、饋紙作業及列印作業時,凸輪 轉動位置的示意圖。如圖四A所示,當邊緣P1正對感應器S 的位置時,凸輪4 0就帶動印表機3 0進入初始作業。同理, 如圖四B所示,當邊緣P 2正對感應器S之位置時,凸輪4 0就 能帶動印表機進行饋紙作業。如圖四C所示,當邊緣P 3正 對感應器S之位置時,凸輪4 0就能帶動印表機進行列印作 業。 如前面所討論過的,印表機的重要動作之一,是要能 將凸輪轉回至初始作業的狀態(即圖四A的情形),以便 在列印中斷後再恢復時,能繼續正常地進行後續作業。當 印表機3 0的作業因故中斷時,凸輪4 0就會停在不明的位 置;當印表機3 0要重新開始運作時,首先就要根據感應器 S的感應結果,來帶動凸輪4 0轉動至初始作業狀態,以帶 動印表機3 0重新由初始狀態開始作業。為了根據單一感應 器S的感應訊號來控制凸輪4 0轉動至圖四A中初始作業的位 置,本發明中也設計有特殊的流程。請參考圖五。圖五為 本發明中將凸輪4 0轉回至初始作業位置的流程1 0 0之流程 圖。在實際實作時,流程100可以是用狀態機制(state machine)的方式進行,隨著各步驟的進行推進至不同的狀 態。圖五中的流程1 0 0包括有下列步驟: 步驟1 0 2 :開始。要將凸輪4 0回歸至圖四A中的初始作業位Page 10 518286 V. Description of the invention (7) Please refer to Figure 4A to Figure 4C. Figures 4A to 4C are schematic diagrams of the rotation positions of the cams when the cam 40 drives the printer 30 to perform initial operations, paper feeding operations, and printing operations, respectively. As shown in FIG. 4A, when the edge P1 faces the position of the sensor S, the cam 40 drives the printer 30 to enter the initial operation. Similarly, as shown in FIG. 4B, when the edge P 2 is facing the position of the sensor S, the cam 40 can drive the printer to perform the paper feeding operation. As shown in Fig. 4C, when the edge P 3 is facing the position of the sensor S, the cam 40 can drive the printer to perform a printing job. As discussed earlier, one of the important actions of the printer is to be able to turn the cam back to the original job state (the situation in Figure 4A) so that it can continue normal when printing resumes after it is interrupted Follow-up operations. When the operation of the printer 30 is interrupted for some reason, the cam 40 will stop at an unknown position; when the printer 30 is to restart operation, it must first drive the cam according to the sensing result of the sensor S 40 turns to the initial working state to drive the printer 30 to start working again from the initial state. In order to control the rotation of the cam 40 to the position of the initial operation in FIG. 4A according to the sensing signal of the single sensor S, a special process is also designed in the present invention. Please refer to Figure 5. FIG. 5 is a flowchart of a process 100 for turning the cam 40 back to the initial working position in the present invention. In actual implementation, the process 100 may be performed in a state machine manner, and progressed to different states as each step proceeds. The process 100 in FIG. 5 includes the following steps: Step 102: Start. To return the cam 40 to the initial operating position in Figure 4A

第11頁 518286 五、發明說明(8) 置時,就可進行流程1 0 0。 步驟1 0 4 :根據感應器S的感應訊號決定進行的步驟。若感 應器S的感應訊號為凸緣感應訊號(也就是凸緣3 8轉到了 感應器S的位置),則進行至步驟1 1 0 ;若感應器S發出的 是區段感應訊號(也就是區段G卜G 2或G 3轉到了感應器S 的位置),則進行至步驟1 0 6。 步驟 106:使凸輪 40反時鐘(CCW,counter clockwise)轉 動。 步驟1 0 8 :在步驟1 0 6中讓凸輪4 0反時鐘轉動時,不斷地檢 查感應器的感應訊號是否有變化。若感應訊號一直為區段 感應訊號,則繼續檢查後續的感應訊號,直到感應訊號轉 為凸緣感應訊號,則進行至步驟11 0。在實際實作時,可 依據一特定的高頻時脈來定時檢查在凸輪4 0旋轉時感應訊 號是否發生了改變。 步驟110:使凸輪40順時鐘(CW,clockwise)旋轉。 步驟1 1 2 :在凸輪4 0轉動期間不斷地檢查感應訊號的情 況。若感應訊號為凸緣感應訊號,則持續檢查後續的感應 訊號,直到感應器的感應訊號改變為區段感應訊號,則進 行至步驟1 1 4。 步驟1 1 4 :設定一預設角度A 0。此預設角度A 0大於區段 G2、G3的夾角A2、A3,但小於區段G1的夾角A卜 步驟1 1 6 :將凸輪4 0順時鐘轉動;並在凸輪4 0轉動時,開 始累計凸輪4 0在此步驟後轉動過的角度。 步驟1 1 8 :在凸輪4 0順時鐘旋轉時,檢查凸輪4 0已經轉動Page 11 518286 V. Description of the invention (8) When the time is set, the process 1 0 0 can be performed. Step 104: Determine the steps to be performed according to the sensing signal of the sensor S. If the sensing signal of the sensor S is a flange sensing signal (that is, the flange 38 is turned to the position of the sensor S), proceed to step 1 10; if the sensor S sends a segment sensing signal (that is, The segments G and G 2 or G 3 are turned to the position of the sensor S), then proceed to step 106. Step 106: The cam 40 is rotated counterclockwise (CCW). Step 108: In step 106, when the cam 40 is rotated counterclockwise, continuously check whether the sensing signal of the sensor has changed. If the sensing signal is always a segment sensing signal, continue to check subsequent sensing signals until the sensing signal turns into a flange sensing signal, then proceed to step 110. In actual implementation, a specific high-frequency clock can be used to periodically check whether the sensing signal has changed when the cam 40 rotates. Step 110: Rotate the cam 40 clockwise (CW). Step 1 12: Continuously check the condition of the induction signal during the rotation of the cam 40. If the sensing signal is a flange sensing signal, continue to check subsequent sensing signals until the sensing signal of the sensor changes to a segment sensing signal, then proceed to step 1 1 4. Step 1 1 4: Set a preset angle A 0. The preset angle A 0 is larger than the included angles A2 and A3 of the segments G2 and G3, but smaller than the included angle A of the segment G1. Step 1 6: Turn the cam 40 clockwise; and when the cam 40 rotates, the accumulation starts The angle by which the cam 40 has rotated after this step. Step 1 1 8: When the cam 40 rotates clockwise, check that the cam 40 has rotated

518286 五、發明說明(9) 過的角度。若凸輪4 0由步驟1 1 6後轉動過的角度仍未大於 該預設角度A 0,則進行至步驟1 2 4 ;若是,則進行至步驟 120° 步驟1 2 0 :使凸輪4 0反時鐘轉動。 步驟1 2 2 :在凸輪4 0反時鐘轉動期間,不斷檢查感應器發 出的感應訊號。若感應訊號為區段感應訊號’則持績檢查 後續的感應訊號,直到感應訊號由區段感應訊號變化為凸 緣感應訊號,就進行至步驟1 3 0。518286 V. Explanation of invention (9). If the rotation angle of the cam 4 0 after step 1 16 is not greater than the preset angle A 0, proceed to step 1 2 4; if yes, proceed to step 120 °. Step 1 2 0: Invert the cam 4 0 The clock rotates. Step 12: During the counterclockwise rotation of the cam 40, continuously check the induction signal from the sensor. If the sensing signal is a segment sensing signal, then the performance check is performed on subsequent sensing signals until the sensing signal changes from the segment sensing signal to the flange sensing signal, and then proceed to step 130.

步驟1 2 4 :檢查感應訊號。若感應訊號為區段感應訊號’ 則進行至步驟11 6 ;若為凸緣感應訊號,則進行至步驟 126° 步驟1 2 6 :使凸輪4 0順時鐘轉動。 步驟128:在凸輪4 0順時鐘轉動期間,持續檢查感應訊 號。若感應訊號為凸緣感應訊號,則持續檢查後續的感應 訊號,直到感應訊號轉變為區段感應訊號,就進行至步驟 114。 步驟1 3 0 :進行至此步驟,表示凸輪4 0已經轉動到初始作 業的位置(也就是圖四A中的位置)。此時就可結束流程 100°Step 1 2 4: Check the induction signal. If the sensing signal is a segment sensing signal, then proceed to step 1 16; if the sensing signal is a flange sensing signal, proceed to step 126 °. Step 1 2 6: Turn the cam 40 clockwise. Step 128: During the clockwise rotation of the cam 40, the induction signal is continuously checked. If the sensing signal is a flange sensing signal, the subsequent sensing signals are continuously checked until the sensing signal is converted into a segment sensing signal, and then proceed to step 114. Step 13: Go to this step, which means that the cam 40 has been rotated to the position of the initial job (that is, the position in Fig. 4A). You can end the process at 100 °

為更具體地描述流程1 0 0進行的情形,現例舉數種情 形來實際解說。請先參考圖六A至圖六D。圖六A至圖六D為 流程1 0 0進行時,將凸輪4 0轉動至初始作業位置的過程示 意圖。假設在流程1 0 0開始時,凸輪4 0的位置如圖六A所In order to more specifically describe the situation in which the process 100 is performed, several cases are now given to explain it practically. Please refer to FIG. 6A to FIG. 6D first. Figures 6A to 6D are schematic diagrams of the process of turning the cam 40 to the initial working position during the process 100. Assume that at the beginning of process 100, the position of cam 40 is as shown in Fig. 6A.

第13頁 518286 五、發明說明(ίο) 示;也就是說,凸輪4 0的凸緣停在感應器S的位置。此時 步驟1 0 4檢查出感應器S發出的是凸緣感應訊號,就在步驟 1 1 0中以控制器3 9 (見圖三A)控制致動輪3 6帶動凸輪4 0順 時鐘轉動(如圖六A中箭頭CW所示的方向);步驟11 2也持 續檢查感應訊號,直到凸輪4 0轉動到圖六B中的位置,使 得感應訊號變為區段感應訊號。接下來進行至步驟1 1 4、 步驟1 1 6,開始將凸輪4 0順時鐘旋轉(如圖六B中箭頭CW所 示的方向);在凸輪4 0轉動的過程中,流程1 0 0會一直在 步驟1 2 4、步驟1 1 6、步驟1 1 8間循環。就如圖六B中所示, 區段G1的夾角A1其實大於預設角度A0,所以凸輪40在由圖 六B中的位置順時鐘轉動時,感應器S會一直發出區段感應 訊號,流程1 0 0也一直在步驟11 8、1 2 4及11 6間循環進行, 直到步驟1 1 8累計凸輪4 0轉動的角度已經到達預設角度A0 (如圖六C所示),接下來就要進行至步驟1 2 0。當凸輪4 0 由圖六B中的位置轉動預設角度A0後到達圖六C中的位置, 步驟1 2 0會使凸輪4 0反方向轉動(即反時鐘轉動,如圖六C 中箭頭CCW的方向),並在步驟122中持續檢查感應器S的 感應訊號,直到感應訊號由區段感應訊號轉變為凸緣感應 訊號,也就能將凸輪4 0轉動至初始作業的位置,如圖六D (也就是圖四A)所不。而這樣也就達成流程1 0 0將凸輪4 0 轉動至初始作業位置的目的。 請繼續參考圖七A至圖七D。圖七A至圖七D為流程1 0 0 在另一種情況下將凸輪4 0轉回至初始作業位置的過程示意Page 13 518286 V. Description of the invention (ίο); that is, the flange of the cam 40 is stopped at the position of the sensor S. At this time, step 104 detects that the sensor S sends a flange induction signal. In step 110, the controller 39 (see Fig. 3A) controls the actuation wheel 3 6 to drive the cam 40 to rotate clockwise ( (Shown in the direction indicated by arrow CW in FIG. 6A); step 11 2 also continues to check the induction signal until the cam 40 rotates to the position in FIG. 6B, so that the induction signal becomes a segment induction signal. Then proceed to step 1 1 4 and step 1 1 6 and start to rotate the cam 40 clockwise (as shown by the arrow CW in FIG. 6B); during the rotation of the cam 40, the process 1 0 0 will Always cycle through steps 1 2 4, steps 1 1 6 and steps 1 1 8. As shown in FIG. 6B, the included angle A1 of the segment G1 is actually larger than the preset angle A0, so when the cam 40 rotates clockwise from the position in FIG. 6B, the sensor S will always send out a segment induction signal. 1 0 0 has also been cyclically performed between steps 11 8, 1 2 4 and 116, until the cumulative rotation of the cam 40 in step 1 8 has reached the preset angle A0 (as shown in FIG. 6C). To proceed to step 1 2 0. When the cam 40 is rotated from the position in FIG. 6B by the preset angle A0 and reaches the position in FIG. 6C, step 1 2 0 will cause the cam 40 to rotate in the opposite direction (that is, counterclockwise, as shown by the arrow CCW in FIG. 6C) Direction), and in step 122, continuously check the induction signal of the sensor S until the induction signal is changed from the segment induction signal to the flange induction signal, and the cam 40 can be rotated to the initial operation position, as shown in Figure 6. D (that is, Figure 4A) does not. In this way, the purpose of turning the cam 40 to the initial working position in the process 100 is achieved. Please continue to refer to FIGS. 7A to 7D. Figures 7A to 7D show the process of turning the cam 40 back to the initial working position in another case.

第14頁 518286 五、發明說明(11) 圖。假設流程1 0 0剛開始進行時,凸輪4 0的位置如圖七A戶斤 示。當流程1 0 0開始運作後,會由步驟1 0 4進行至步驟11 0 (因為圖七A中感應器S感應到凸緣),並使凸輪4 0順時鐘 轉動。同時步驟1 1 2也不斷檢查感應訊號的變化,直到感 應訊號由凸緣感應訊號轉變為區段感應訊號,就如圖七B 所示。在圖七B中,感應器S的感應訊號剛好由凸緣感應訊 號轉變為區段感應訊號(因為遇到了區段G2),在步驟 114中設定預設角度A0,並在步驟116中開始讓凸輪4 0順時 鐘轉動,同時也開始累計轉動的角度。請注意,如前所 述,區段G 2的夾角A 2小於預設角度A0。當凸輪40由圖七B 的位置開始順時鐘轉動時,會由步驟1 1 8進行至步驟1 2 4再 回到步驟1 1 6,直到步驟1 2 4檢查到的感應訊號由區段感應 訊號轉變為凸緣感應訊號,此時凸輪4 0轉動到圖七C所示 的位置(也就是由區段G 2的一個邊緣順時鐘轉動到另一個 邊緣)。換句話說,凸輪4 0在步驟1 1 4開始順時鐘後,其 轉動的角度尚未超過預設角度A 0,感應訊號就已經由區段 感應訊號轉變為凸緣感應訊號;這也就是因為區段G 2的夾 角A 2小於預設角度A 0的緣故。到了圖七C的位置,流程1 0 0 就會因為感應器S感應到凸緣而由步驟1 2 4進行至步驟 1 2 6,使凸輪4 0繼續順時鐘轉動,直到感應訊號再度由凸 緣感應訊號轉變為區段感應訊號,就再度進行至步驟 1 1 4。也就是說,凸輪4 0由圖七C順時鐘轉動,就會轉動至 圖七D的位置;再由圖七D的位置繼續轉動,直到感應器S 遇到下一個區段(也就是區段G 1 ),又會重複回到步驟Page 14 518286 V. Description of the invention (11) Figure. Assume that when the process 100 starts, the position of the cam 40 is shown in Figure 7A. After the process 100 starts to operate, it will go from step 104 to step 110 (because the sensor S in FIG. 7A senses the flange), and make the cam 40 rotate clockwise. At the same time, steps 1 1 2 also continuously check the change of the sensing signal until the sensing signal changes from the flange sensing signal to the segment sensing signal, as shown in Figure 7B. In FIG. 7B, the sensing signal of the sensor S is just changed from the flange sensing signal to the segment sensing signal (because the segment G2 is encountered), the preset angle A0 is set in step 114, and the starting of The cam 40 rotates clockwise, and at the same time starts to accumulate the rotation angle. Please note that, as mentioned above, the included angle A 2 of the segment G 2 is smaller than the preset angle A 0. When the cam 40 starts to rotate clockwise from the position of FIG. 7B, it will proceed from step 1 1 to step 1 2 4 and then return to step 1 16 until the sensing signal detected in step 1 2 4 is the segment sensing signal. It turns into a flange sensing signal, and at this time, the cam 40 is rotated to the position shown in FIG. 7C (that is, clockwise from one edge of the segment G 2 to the other edge). In other words, after the clock of cam 40 starts clockwise in step 114, its rotation angle has not exceeded the preset angle A0, and the sensing signal has been changed from the zone sensing signal to the flange sensing signal; this is because the zone The reason that the included angle A 2 of the segment G 2 is smaller than the preset angle A 0. At the position of FIG. 7C, the process 1 0 0 will proceed from step 1 2 4 to step 1 2 6 because the sensor S senses the flange, so that the cam 4 0 continues to rotate clockwise until the induction signal again from the flange The sensing signal is changed to a segment sensing signal, and then proceeds to step 1 1 4 again. That is to say, the cam 40 is rotated clockwise from FIG. 7C to rotate to the position of FIG. 7D; and then continues to rotate from the position of FIG. 7D until the sensor S meets the next segment (that is, the segment G 1), and will repeat the steps again

第15頁 518286 五、發明說明(12) 1 1 4。此後的控制步驟就會和圖六B至圖六D進行的控制步 驟相同,最後使凸輪4 0轉動至圖四A(也就是圖六D)的初 始作業位置,達到流程1 0 0控制的目的。 請再參考圖八A、八B。圖八A、八B為流程1 0 0在另一 種狀況下控制過程的示意圖。假設流程1 0 0剛開始要進行 之初,凸輪4 0的位置如圖八A所示,區段G 1停留在感應器S 的位置;在流程1 0 0進行後,感應器S會偵測到區段,並產 生區段感應訊號,而由步驟1 0 4進行至步驟1 0 6,將凸輪4 0 反時鐘轉動,並在轉動過程中不斷檢查感應訊號,直到感 應訊號由區段感應訊號轉變為凸緣感應訊號,此時凸輪4 0 也就轉動到了圖八B中所示的位置。接下來流程1 0 0就進行 至步驟1 1 0,請注意圖八B實際上就和圖六B相同;換句話 說,流程1 0 0在圖八B後進行的控制步驟,就和圖六B至圖 六D進行的控制步驟相同,最後將凸輪4 0轉動至初始作業 的位置。另外,請參考圖九A、九B。圖九A、九B為流程 1 0 0在另一種狀況下控制凸輪轉動之過程示意圖。類似圖 八A中的狀況,假設流程1 0 0在開始進行之初,凸輪4 0停留 在圖九A所示之位置(也就是區段G 2停留在感應器S的位置 );流程1 0 0也會經由步驟1 0 4、1 0 6、1 0 8而將凸輪4 0轉動 到圖九B所示的位置。此後進行的步驟就會和圖七B至圖七 D (再加上圖六B至圖六D)進行的步驟相同,最後都能使 凸輪4 0轉動至初始作業的位置(也就是圖四A所示的位置Page 15 518286 V. Description of the invention (12) 1 1 4 The subsequent control steps will be the same as the control steps in Figure 6B to Figure 6D. Finally, the cam 40 will be rotated to the initial operating position in Figure 4A (that is, Figure 6D) to achieve the purpose of flow 100 0 control. . Please refer to Figure 8A and 8B again. Figures 8A and 8B are schematic diagrams of the control process of the process 100 in another situation. Assume that at the beginning of the process 100, the position of the cam 40 is shown in Fig. 8A, and the segment G 1 stays at the position of the sensor S. After the process 100 is performed, the sensor S will detect To the segment and generate the segment induction signal, and from step 104 to step 106, the cam 40 is rotated counterclockwise, and the induction signal is continuously checked during the rotation until the induction signal from the segment induction signal It turns into a flange sensing signal, and at this time, the cam 40 is rotated to the position shown in FIG. 8B. Next, the process 1 0 0 proceeds to step 1 1 0. Please note that FIG. 8B is actually the same as FIG. 6B; in other words, the control steps performed by process 1 0 0 after FIG. 8B are the same as those in FIG. 6 The control steps from B to FIG. 6D are the same. Finally, the cam 40 is rotated to the initial operation position. In addition, please refer to Figure 9A and 9B. Figures 9A and 9B are schematic diagrams of the process of controlling the rotation of the cam under another condition. Similar to the situation in FIG. 8A, suppose that at the beginning of the process 100, the cam 40 stays at the position shown in FIG. 9A (that is, the segment G 2 stays at the position of the sensor S); the process 1 0 0 also rotates the cam 40 to the position shown in FIG. 9B through steps 104, 106, 108. The subsequent steps will be the same as those performed in Figure 7B to Figure 7D (plus Figure 6B to Figure 6D). In the end, the cam 40 can be rotated to the initial operation position (that is, Figure 4A). Shown position

第16頁 518286 五、發明說明(13) 總結來說,流程1 0 0在使凸輪4 0順時鐘轉動後,當感 應器S的感應訊號由凸緣感應訊號轉變為區段感應訊號 時,就代表感應器S已經遇到一個區段。此時凸輪4 0會再 度順時鐘轉動一預設角度A 0,以進一步確認這個區段是否 是夾角較大的第一區段G卜由於區段G2、G3的夾角A2、A3 都小於預設角度A 0,凸輪4 0還沒轉完整個預設角度A 0就會 跨過整個區段,而使感應訊號由區段感應訊號轉為凸緣感 應訊號。此時流程1 0 0就會繼續使凸輪4 0順時鐘轉動,直 到再度遇到下一個區段。另一方面,若感應遇到的區段為 夾角較大的第一區段G 1,則凸輪4 0即使轉動完整個預設角 度A0,感應器S遇到的仍是區段,此時就可確定凸輪40已 經轉動到區段G 1 了;由於區段G 1的邊緣P 1就對應於初始作 業的位置,接下來只要將凸輪4 0反向(反時鐘方向)轉 動,使凸輪40轉動回第一區段G1的邊緣,就能讓凸輪40轉 動回初始作業的位置了。換句話說,本發明是將初始作業 的位置對應至一夾角為A1的區段,其他作業(如饋紙、列 印作業)的位置對應至夾角為A2、A3的區段;再利用夾角 A1、預設角度A0及夾角A2、A3間大小相異的關係,來以單 一感應器S定址凸輪4 0的位置。這樣一來,不論凸輪4 0的 位置中斷於何處,本發明都能以流程1 0 0來將凸輪4 0回復 至初始作業的位置。 除了上述將凸輪4 0定址至初始作業位置的流程1 0 0Page 16 518286 V. Description of the invention (13) In summary, after turning the cam 40 clockwise in the process 100, when the sensing signal of the sensor S changes from the flange sensing signal to the segment sensing signal, Indicates that the sensor S has encountered a segment. At this time, the cam 40 will rotate clockwise again by a preset angle A 0 to further confirm whether this section is the first section G with a larger included angle. Because the included angles A2 and A3 of the sections G2 and G3 are smaller than the preset The angle A 0, the cam 40 has not yet rotated through the entire preset angle A 0, will span the entire segment, and the sensing signal is changed from the segment sensing signal to the flange sensing signal. At this time, the process 100 will continue to make the cam 40 rotate clockwise until it encounters the next segment again. On the other hand, if the segment encountered by induction is the first segment G 1 with a large included angle, even if the cam 40 rotates a full preset angle A0, the sensor S still encounters the segment. It can be determined that the cam 40 has been rotated to the segment G 1; since the edge P 1 of the segment G 1 corresponds to the initial operation position, then as long as the cam 40 is rotated in the reverse direction (counterclockwise), the cam 40 is rotated By returning to the edge of the first section G1, the cam 40 can be rotated back to the initial operation position. In other words, the present invention maps the position of the initial job to a section with an included angle A1, and the positions of other jobs (such as paper feeding and printing jobs) correspond to the sections with an included angle A2 and A3; and then uses the included angle A1 The relationship between the preset angle A0 and the included angles A2 and A3 is different, so as to address the position of the cam 40 with a single sensor S. In this way, no matter where the position of the cam 40 is interrupted, the present invention can return the cam 40 to the initial operation position by using the flow 100. In addition to the above process of addressing the cam 40 to the initial working position 1 0 0

第17頁 518286Page 17 518286

五、發明說明(14) 外,本發明也只要依靠單一感應器S就能將凸輪4 0定址至 饋紙作業及列印作業的位置。在以流程1 0 0將凸輪4 〇定土止 至初始作業位置後,依據印表機3 0實際作業的需要,| \ 又 要能 分別將凸輪4 0由初始作業位置(圖四Α所示位置)轉動到 饋紙作業位置(即圖四B所示位置)、由饋紙作業位置轉 動到列印作業位置(圖四C所示位置)、由列印作業位置 回到饋紙作業位置、由饋紙作業位置回到初始作業位置。 清參考圖十之流程圖(並一併參考圖四A至圖四c)。圖十 中之流程2 0 0即能控制凸輪4 0,達到上述四種於各作業位 置間轉換的目的。流程2 0 0中有下列步驟: 步騍2 0 2 :開始控制凸輪4 0在各作業位置間轉換,以帶動 印表機3 0做出對應的作業。要將凸輪4 0由初始作業位置轉 動到饋紙作業位置,或由饋紙作業位置轉動到列印作業位 置,要使凸輪40反時鐘轉動。相對地,要將凸輪40由饋紙 作業位置轉動至初始作業位置,或是由列印作業位置轉動 至饋纟氏作業位置,則要將凸輪4 0順時鐘轉動。 步驟2 〇 4 :在步驟2 0 2將凸輪4 0轉動後,檢查累計轉動的角 度是否大於預設角度A〇 ;若尚未大於預設角度,則持續檢 查累計轉動的角度,直到凸輪40於步驟2 0 2後轉動的角度 已麵大於預設角度A 〇 ’則進行至步驟2 〇 6。 步驟2 〇 6 :檢查感應訊號為何。在正常情況下’不論步驟 2〇2開始時凸輪40在圖四A、四B或四C的位置’在步驟204 轉動預設角度A0後,感應器S遇到的都應该疋凸緣。若感 應訊號的確也是凸緣’則繼續進行至步驟2 1 〇,若感應訊 518286 五、發明說明(15) 號為區段感應訊號,就要進行至步驟2 0 8了。 步驟2 0 8 :到此步驟表示流程有錯誤發生,可進行對應的 錯誤處理,像是提示使用者等等。 步驟2 1 0 :在凸輪4 0轉動時,持續檢查感應訊號2 1 0。若感 應訊號為凸緣,則持續檢查感應訊號,直到感應訊號轉變 為區段感應訊號,則進行至步驟2 1 2。5. Description of the invention (14) In addition, the present invention can also address the cam 40 to the position of the paper feeding operation and the printing operation by relying on a single sensor S. After the cam 40 has been fixed to the initial operation position by the process 100, according to the actual operation requirements of the printer 30, it must be possible to separate the cam 40 from the initial operation position (shown in Figure 4A). Position) to the paper feed operation position (the position shown in Figure 4B), from the paper feed operation position to the print operation position (the position shown in Figure 4C), from the print operation position to the paper feed operation position, Return to the initial work position from the paper feed work position. Refer to the flowchart of FIG. 10 (refer to FIG. 4A to FIG. 4c together). The flow of 200 in Fig. 10 can control the cam 40 to achieve the above-mentioned four purposes of switching between various operating positions. The process 2 0 0 has the following steps: Step 2 0 2: Start the control cam 4 0 to switch between the various work positions to drive the printer 3 0 to make the corresponding job. To rotate the cam 40 from the initial work position to the paper feed work position, or from the paper feed work position to the print work position, the cam 40 must be rotated counterclockwise. In contrast, to rotate the cam 40 from the paper feeding operation position to the initial operation position, or from the printing operation position to the feeding operation position, the cam 40 must be rotated clockwise. Step 2 04: After turning the cam 40 in step 202, check whether the cumulative rotation angle is greater than the preset angle A. If it is not greater than the preset angle, continue to check the cumulative rotation angle until the cam 40 is in step After the angle of rotation after 202 has been greater than the preset angle A 0 ′, the process proceeds to step 2 06. Step 2 〇 6: Check the induction signal. Under normal circumstances, 'whether the cam 40 is at the position of Fig. 4A, 4B, or 4C at the beginning of step 202', after rotating the preset angle A0 in step 204, the sensor S should encounter the flange. If the sensing signal is indeed a flange ’, then proceed to step 2 10. If the sensing signal 518286 V. Invention Description (15) is a segment sensing signal, proceed to step 208. Step 208: To this step indicates that there is an error in the process, and corresponding error handling can be performed, such as prompting the user and so on. Step 2 1 0: When the cam 40 rotates, continuously check the sensing signal 2 1 0. If the sensing signal is a flange, continue to check the sensing signal until the sensing signal turns into a segment sensing signal, then proceed to step 2 1 2.

步驟2 1 2 :檢查前一作業為何。流程2 0 0執行時,是要將凸 輪4 0由某一作業位置轉動到另一作業的位置。若凸輪4 0原 本在初始作業位置,則進行至步驟2 1 4 ;若凸輪4 0原本不 是在初始作業位置,則進行至步驟2 1 8。 步驟2 1 4 :繼續在凸輪4 0轉動期間持續檢查感應訊號,直 到感應訊號由區段感應訊號轉變為凸緣感應訊號,就能進 行至步驟2 1 6。 步驟2 1 6 :到達饋紙作業的位置(即圖四B所示的位置)。 步驟2 1 8 :檢查前一作業位置為何。若在步驟2 0 2開始時, 凸輪4 0在饋紙作業的位置,則進行至步驟2 2 0 ;若否,則 進行至步驟2 2 2。Step 2 1 2: Check the previous job. When the process 2 00 is executed, the cam 40 is rotated from one work position to another work position. If the cam 40 is originally in the initial operating position, proceed to step 2 1 4; if the cam 40 is not originally in the initial operating position, proceed to step 2 1 8. Step 2 1 4: Continue to check the sensor signal during the rotation of the cam 40 until the sensor signal changes from the zone sensor signal to the flange sensor signal, and then proceed to step 2 1 6. Step 2 1 6: Reach the position of the paper feeding operation (that is, the position shown in Figure 4B). Step 2 1 8: Check the previous work position. If at the beginning of step 202, the cam 40 is at the position of the paper feeding operation, proceed to step 2 2 0; if not, proceed to step 2 2 2.

步驟2 2 0 :檢查步驟2 0 2以來凸輪轉動的方向。若為順時鐘 方向,則進行至步驟2 2 6 ;若為反時鐘方向,則進行至步 驟 2 24。 步驟2 2 2 :凸輪4 0轉動到達饋紙作業的位置(如圖四B所示 )° 步驟224:凸輪4 0轉動到達初始作業的位置(如圖四A所示Step 2 2 0: Check the direction of cam rotation since step 2 2. If it is clockwise, go to step 2 2 6; if it is clockwise, go to step 2 24. Step 2 22: The cam 40 rotates to the position of the paper feeding operation (as shown in Figure 4B) ° Step 224: the cam 40 rotates to the position of the initial operation (as shown in Figure 4A)

第19頁 518286 五、發明說明(16) 步驟2 2 6 :凸輪4 0轉動到達列印作業的位置(如圖四C所示 配合圖四A至圖四C,可進一步說明流程2 0 0進行的情 形。首先,當凸輪4 0要由初始作業位置(圖四A)轉動到 饋紙作業的位置(圖四B),則步驟2 0 2會設定凸輪4 0反時 鐘轉動,經過步驟2 0 4、2 0 6、2 1 0轉動到區段G 2的一個邊 緣;步驟2 1 2會決定前一作業位置確為初始作業位置,進 行至步驟2 1 4,再不斷轉動直到感應器S跨過整個區段G 2, 到達區段G 2的邊緣P 2,也就讓凸輪4 0轉動到饋紙作業的位 置,停止於步驟2 1 6。若凸輪4 0要由饋紙作業的位置轉動 到列印作業的位置(圖四C所示的位置),流程2 0 0也是在 步驟20 2中設定凸輪4 0反時鐘轉動,經由步驟204、206、 2 1 0 (轉動到邊緣P 3)再到步驟2 1 2 ;由於步驟2 0 2開始時 凸輪4 0的位置是饋紙作業的位置,並非初始作業的位置, 故由步驟2 1 2進行至步驟2 1 8,再由步驟2 1 8至步驟2 2 0。因 為步驟2 0 2設定的轉動方向為反時鐘轉動,就由步驟2 2 0進 行至步驟2 2 4,流程2 0 0就可在步驟2 2 4中判斷此時凸輪4 0 已經轉動到圖四C列印作業的位置了。 同理,當凸輪4 0要由列印作業的位置轉回饋紙作業的 位置,流程2 0 0在步驟2 0 2中會設定凸輪4 0順時鐘轉動,經 由步驟204、206、210至步驟212;因為步驟20 2時凸輪40 的位置在列印作業的位置,故流程2 0 0會進行至步驟2 1 8再Page 19 518286 V. Description of the invention (16) Step 2 2 6: The cam 40 rotates to reach the position of the printing operation (as shown in Figure 4C and Figures 4A to 4C, which can further explain the process of 2 0 0 First, when the cam 40 is to be rotated from the initial operation position (Figure 4A) to the paper feeding position (Figure 4B), step 2 0 2 will set the cam 40 to rotate counterclockwise, and after step 2 0 4, 2 0 6, 2 1 0 Turn to an edge of section G 2; Step 2 1 2 will determine that the previous work position is indeed the initial work position, proceed to Step 2 1 4 and continue to rotate until the sensor S crosses After the entire section G 2 reaches the edge P 2 of the section G 2, the cam 40 is rotated to the position of the paper feeding operation and stops at step 2 16. If the cam 40 is to be rotated from the position of the paper feeding operation To the position of the print job (the position shown in Fig. 4C), the flow 2 0 0 is also set in step 20 2 to rotate the cam 4 0 counterclockwise, and through steps 204, 206, 2 1 0 (turn to the edge P 3) Go to step 2 1 2 again; since the position of cam 40 at the beginning of step 2 2 is the position of the paper feeding operation, not the position of the initial operation Therefore, proceed from step 2 1 2 to step 2 1 8 and then from step 2 1 8 to step 2 2 0. Because the rotation direction set in step 2 2 is counterclockwise, proceed from step 2 2 0 to step 2 2 4, the process 2 0 0 can be judged in step 2 2 4 at this time the cam 4 0 has been rotated to the position of the print job in Figure 4C. Similarly, when the cam 4 0 is to be returned to the paper feed from the position of the print job The position of the job. In the flow 2 0 0, the cam 40 is set to rotate clockwise through steps 204, 206, 210 to step 212; because the position of the cam 40 at step 20 2 is the position of the print job, So the process 2 0 0 will proceed to step 2 1 8

第20頁 518286 五、發明說明(17) 到步驟2 2 2,此時流程2 0 0就會判斷凸輪4 0已經轉動到饋紙 作業的位置了。最後,當凸輪4 0要由饋紙作業的位置會到 初始作業的位置,步驟2 0 2會設定讓凸輪4 0順時鐘轉動, 跨過區段G 2,到步驟2 1 0時已經轉動到區段G 1的邊緣P 1 ; 經過步驟2 1 2的判斷進行至步驟2 1 8再到步驟2 2 0、因為步 驟2 0 2設定的轉動方向為順時鐘方向而進行至步驟2 2 6,流 程2 0 0就可判斷此時凸輪4 0已經轉動到初始作業的位置 了。總而言之,只要憑藉單一感應器的感應訊號,流程 2 0 0可讓凸輪4 0在轉動切換於不同的作業位置間,帶動印 表機3 0完成必要的初始、饋紙、列印等作業。 總而言之,在本發明印表機中僅需設置單一的感應器 S,就能配合凸輪4 0上的區段,以流程1 0 0及2 0 0來將凸輪 4 0轉動的位置定址。請注意,上述討論中凸輪4 0是以三個 區段來對應三種不同的印表機作業位置;若印表機要進行 更多種不同的作業(也就是凸輪要定址於更多不同的位置 ),凸輪上也可以設置更多對應的區段。配合印表機所要 進行的各種作業,各個作業都會在凸輪上有一對應的區 段;其中初始作業對應的區段,設其夾角為A1 ;其他作業 對應的區段,其夾角可統一設為A 2。配合大小介於夾角 A 1、A 2間的預設角度A 0,就能利用流程1 0 0將凸輪定址於 初始作業的位置。要在各作業位置間切換,則可以利用流 程2 0 0所教導的原理。Page 20 518286 V. Description of the invention (17) Go to step 2 2 2. At this time, the process 2 0 0 will judge that the cam 4 0 has been turned to the position of paper feeding operation. Finally, when the cam 40 is to be fed from the paper feed job to the initial job position, step 2 0 2 will be set to rotate the cam 4 0 clockwise, across the section G 2 and by step 2 10 The edge P 1 of the segment G 1; proceed to step 2 1 8 and then step 2 2 0 after the judgment of step 2 1 2, and proceed to step 2 2 6 because the rotation direction set in step 2 2 is clockwise, The process 2 0 0 can determine that the cam 4 0 has been rotated to the initial operation position at this time. In a word, as long as the sensor signal from a single sensor is used, the process 200 can allow the cam 40 to switch between different operating positions to drive the printer 30 to complete the necessary initial, paper feeding, and printing operations. In a word, in the printer of the present invention, only a single sensor S is required to match the segment on the cam 40, and the positions of the rotation of the cam 40 can be addressed using the processes 100 and 200. Please note that in the above discussion, the cam 40 has three sections corresponding to three different printer operating positions; if the printer is to perform more different jobs (that is, the cams are to be located in more different positions) ), More corresponding sections can also be set on the cam. In accordance with the various operations to be performed by the printer, each job will have a corresponding section on the cam; the section corresponding to the initial operation is set to an angle of A1; the section corresponding to other operations can be uniformly set to A 2. With the preset angle A 0 between the included angles A 1 and A 2, the cam can be located at the initial operation position by using the process 1 0 0. To switch between working positions, you can use the principles taught in Process 200.

518286 五、發明說明(18) 在習知技術中,帶動印表機作業的凸輪要用兩個感應 器才定位凸輪轉動的位置,會增加習知印表機生產、製造 及維護的時間與成本。相較之下,本發明僅需設置有單一 感應器,就能定址凸輪的轉動位置,就能在低成本、高妥 善率的情形下,精確地控制印表機的動作,發揮印表機的 功能;而本發明之精神則可廣泛運用於熱轉印式、熱感應 式、撞針式、喷墨式、靜電式之印表機。518286 V. Description of the invention (18) In the conventional technology, the cam that drives the printer's operation requires two sensors to locate the position of the cam rotation, which will increase the time and cost of conventional printer production, manufacturing and maintenance. . In contrast, the present invention only needs to be provided with a single sensor, which can address the rotational position of the cam, and can accurately control the printer's actions under the conditions of low cost and high reliability, and exert the advantages of the printer. Function; and the spirit of the present invention can be widely applied to thermal transfer type, thermal induction type, striker type, inkjet type, electrostatic type printer.

以上所述僅為本發明之較佳實施例,凡依本發明申請 專利範圍所做之均等變化與修飾,皆應屬本發明專利之涵 蓋範圍。The above description is only a preferred embodiment of the present invention, and all equivalent changes and modifications made in accordance with the scope of the patent application for the present invention shall fall within the scope of the invention patent.

第22頁 518286 圖式簡單說明 圖式之簡單說明: 圖一 A為一習知印表機的結構示意圖。 圖一 B為圖一 A中印表機之側視圖。 圖一 C為圖一 A中凸輪之側視圖。 圖二A至圖二C為圖一 A中印表機分別於不同作業時凸 輪轉動位置的示意圖。 圖三A為本發明印表機的結構示意圖。 圖三B為圖三A中印表機之側視圖。 圖三C為圖三A中凸輪之示意圖。 圖三D為圖三C中凸輪之側視圖。 圖四A至圖四C為圖三A中凸輪分別於不同作業時凸輪 轉動位置的示意圖。 圖五為本發明中將凸輪回復至圖四A中情形之控制流 程圖。 圖六A至圖六D為圖四流程~^控制例的過程不意圖。 圖七A至圖七D為圖四流程另一控制例的過程示意圖。 圖八A、八B為圖四流程第三控制例的過程示意圖。 圖九A、九B為圖四流程第四控制例的過程示意圖。 圖十為本發明控制凸輪於各作業位置間轉動的控制流 程不意圖。 圖式之符號說明:Page 22 518286 Brief description of the drawings Brief description of the drawings: Figure 1 A is a schematic diagram of the structure of a conventional printer. Figure 1B is a side view of the printer in Figure 1A. FIG. 1C is a side view of the cam in FIG. 1A. Figures 2A to 2C are schematic diagrams of the rotation positions of the cam wheels of the printer in Figure 1A during different operations. FIG. 3A is a schematic structural diagram of a printer according to the present invention. FIG. 3B is a side view of the printer in FIG. 3A. FIG. 3C is a schematic diagram of the cam in FIG. 3A. FIG. 3D is a side view of the cam in FIG. 3C. Figures 4A to 4C are schematic diagrams of the rotation positions of the cams in Figure 3A during different operations. Fig. 5 is a control flow chart for returning the cam to the situation in Fig. 4A according to the present invention. FIG. 6A to FIG. 6D are the processes of the flow chart in FIG. 4 and the control example is not intended. 7A to 7D are schematic process diagrams of another control example of the process of FIG. 4. FIG. 8A and FIG. 8B are process schematic diagrams of the third control example of the process in FIG. FIG. 9A and 9B are process schematic diagrams of the fourth control example of the process in FIG. Fig. 10 is a schematic diagram of a control process for controlling the rotation of the cam between various working positions according to the present invention. Schematic symbol description:

518286 圖式簡單說明518286 Schematic description

120 210 10、30 印表機 12^ 32 殼體 14、34 牽引輪 16 致動輪 18A、 18B、 38 凸緣 19> 39 控制器 20、40 凸輪 36 致動器 41 輪緣 100> 200 流程 La-Lc、P1 -P3 邊緣 PG1-PG2' G1-G3 區段 S卜 S2、 S 感應器 0 圓心 AO 預設角度 A1-A3 夾角 102、 104、 106^ 1 0 8、11 0、 112、 114、 116、 118、 122、 124 、126、 128、 130、 2 0 2 ^ 20[ 2 0 6 〜2 0 8 〜 212、 214 、216、 218、 220、 222、224、226 步驟 第24頁120 210 10, 30 Printer 12 ^ 32 Housing 14, 34 Traction wheel 16 Actuating wheel 18A, 18B, 38 Flange 19 > 39 Controller 20, 40 Cam 36 Actuator 41 Flange 100 > 200 Flow La- Lc, P1-P3 edge PG1-PG2 'G1-G3 segment Sb S2, S sensor 0 circle center AO preset angle A1-A3 angle 102, 104, 106 ^ 1 0 8, 11 0, 112, 114, 116 , 118, 122, 124, 126, 128, 130, 2 0 2 ^ 20 [2 0 6 to 2 0 8 to 212, 214, 216, 218, 220, 222, 224, 226 Step Page 24

Claims (1)

518286 六、申請專利範圍 1. 一種操控一印表機的方法,該印表機包含有: 一殼體; 一凸輪,以可沿一圓心轉動的方式設置於該殼體上, 該凸輪圍繞該圓心之圓周設有一凸緣,該凸緣上設有一第 一區段及一第二區段; 該第一區段對應該圓心呈一第一夾角,該第二區段對 應該圓心呈一第二夾角; 其中當該凸輪旋轉至對應該殼體之不同角度時,會帶 動該印表機進行不同的作業;以及 一感應器,固定於該殼體内對應該凸輪之凸緣的位 置; 其中當該凸輪旋轉時,會帶動該凸緣掠過該感應器; 當該凸緣掠過該感應器時,該感應器會產生一凸緣感 應訊號; 而當該第一區段及該第二區段掠過該感應器時,該感 應器會產生一區段感應訊號; 而該方法包含有: 當該感應器產生之訊號由凸緣感應訊號變為區段感應 訊號時,使該凸輪轉動一預設角度;以及 在該凸輪轉動該預設角度後,僅根據該感應器產生的 訊號來判斷該凸輪相對於該殼體的角度; 其中該預設角度介於該第一夾角及該第二夾角之間。 2. 如申請專利範圍第1項之方法,其另包含有:518286 6. Scope of patent application 1. A method for controlling a printer, the printer includes: a casing; a cam is arranged on the casing in a manner rotatable along a circle center, and the cam surrounds the A flange is provided on the circumference of the circle center, and the flange is provided with a first section and a second section. The first section corresponds to the circle center at a first angle, and the second section corresponds to the circle center. Two included angles; wherein when the cam rotates to different angles corresponding to the housing, it will drive the printer to perform different operations; and a sensor fixed in the housing corresponding to the position of the flange of the cam; When the cam rotates, it will drive the flange to pass over the sensor; when the flange passes over the sensor, the sensor will generate a flange induction signal; and when the first section and the second section When the segment passes over the sensor, the sensor generates a segment induction signal; and the method includes: when the signal generated by the sensor changes from a flange induction signal to a segment induction signal, the cam is rotated A preset angle And after the cam is rotated the predetermined angle, only in accordance with the signal generated by the sensor to determine the angle of the cam with respect to the housing; wherein the predetermined angle is between the first angle and the second angle. 2. If the method of applying for item 1 of the patent scope includes: 518286 六、申請專利範圍 若該凸輪轉動該預設角度後,該感應器產生之訊號為該區 段感應訊號,則使該凸輪反向轉動,直到該凸輪產生之訊 號轉變為該凸緣感應訊號。 3. 如申請專利範圍第1項之方法,其另包含有: 若該凸輪轉動該預設角度後,該感應器產生之訊號為該凸 緣感應訊號,則繼續使該凸輪轉動,直到該凸輪產生之訊 號轉變為該區段感應訊號。 4. 如申請專利範圍第1項之方法,其中該第一夾角大於 該第二夾角。 5. 如申請專利範圍第1項之方法,其中該凸輪上另包含 有一第三區段,該第三區段對應該圓心呈一第三夾角;其 中該第三夾角小於該預設角度。 6. 如申請專利範圍第1項之方法,其中該感應器為光感 應器。 7. 如申請專利範圍第1項之方法,其中當該凸輪轉動而 帶動該第一區段掠過該感應器時,該凸輪係帶動該印表機 進行一初始化作業。 8. 如申請專利範圍第1項之方法,其中當該凸輪轉動而518286 6. Scope of patent application If the signal generated by the sensor after the cam rotates the preset angle is the section induction signal, the cam is rotated in the reverse direction until the signal generated by the cam is converted into the flange induction signal . 3. If the method of claim 1 of the patent application scope further includes: If the signal generated by the sensor after the cam rotates the preset angle is the flange induction signal, continue to rotate the cam until the cam The generated signal is changed to the induction signal of the segment. 4. The method according to item 1 of the patent application, wherein the first included angle is greater than the second included angle. 5. The method according to item 1 of the patent application scope, wherein the cam further includes a third section, and the third section corresponds to a circle center at a third included angle; wherein the third included angle is smaller than the preset angle. 6. The method according to item 1 of the patent application scope, wherein the sensor is a light sensor. 7. The method according to item 1 of the scope of patent application, wherein when the cam rotates to drive the first section to pass over the sensor, the cam system drives the printer to perform an initialization operation. 8. The method of claim 1 in the patent application range, wherein when the cam rotates, 第26頁 518286 六、申請專利範圍 帶動該第二區段掠過該感應器時,該凸輪係帶動該印表機 進行一饋紙作業。 9. 如申請專利範圍第1項之方法,其中當該凸輪轉動而 帶動該第二區段掠過該感應器時,該凸輪係帶動該印表機 進行一列印作業。 10. —印表機,其包含有: 一殼體; 一凸輪,以可沿一圓心轉動的方式設置於該殼體上, 該凸輪圍繞該圓心之圓周設有一凸緣,該凸緣上設有一第 一區段及一第二區段;該第一區段對應該圓心呈一第一夾 角,該第二區段對應該圓心呈一第二夾角; 其中當該凸輪旋轉至對應該殼體之不同角度時,會帶 動該印表機進行不同的作業; 一感應器,固定於該殼體内對應該凸輪之凸緣的位 置; 其中當該凸輪旋轉時,會帶動該凸緣掠過該感應器; 當該凸緣掠過該感應器時,該感應器會產生一凸緣感 應訊號;而當該第一區段及該第二區段掠過該感應器時, 該感應器會產生一區段感應訊號;以及 一控制器,用來根據該感應器產生的訊號來控制該凸 輪之轉動; 其中當該感應器產生之訊號由凸緣感應訊號變為區段Page 26 518286 6. Scope of patent application When the second section is driven past the sensor, the cam system drives the printer to perform a paper feeding operation. 9. The method according to item 1 of the patent application, wherein when the cam rotates to drive the second section to pass through the sensor, the cam system drives the printer to perform a printing operation. 10. —Printer, comprising: a housing; a cam provided on the housing so as to be rotatable along a circle center, the cam is provided with a flange around the circumference of the circle center, and the flange is provided with There is a first section and a second section; the first section corresponds to the center of the circle at a first angle, and the second section corresponds to the center of the circle at a second angle; when the cam rotates to correspond to the housing When the angle is different, it will drive the printer to perform different operations; an sensor is fixed in the housing corresponding to the position of the flange of the cam; wherein when the cam rotates, it will drive the flange to pass over the flange Sensor; when the flange passes over the sensor, the sensor will generate a flange induction signal; and when the first section and the second section pass through the sensor, the sensor will generate A section induction signal; and a controller for controlling the rotation of the cam according to a signal generated by the sensor; wherein when the signal generated by the sensor changes from a flange induction signal to a section 第27頁 518286 六、申請專利範圍 感應訊號時,該控制器會使該凸輪轉動一預設角度,並僅 根據該感應器產生的訊號來判斷該凸輪相對於該殼體的角 度; 而其中該預設角度介於該第一夾角及該第二夾角之 間。 1 1.如申請專利範圍第1 0項之印表機,其中若該凸輪轉動 該預設角度後,該感應器產生之訊號為該區段感應訊號, 則該控制器會使該凸輪反向轉動,直到該凸輪產生之訊號 轉變為該凸緣感應訊號。 1 2.如申請專利範圍第1 0項之印表機,其中若該凸輪轉動 該預設角度後,該感應器產生之訊號為該凸緣感應訊號, 則該控制器會繼續使該凸輪轉動,直到該凸輪產生之訊號 轉變為該區段感應訊號。 1 3.如申請專利範圍第1 0項之印表機,其中該第一夾角大 於该弟·一爽角。 1 4.如申請專利範圍第1 0項之印表機,其中該凸輪上另包 含有一第三區段,該第三區段對應該圓心呈一第三夾角; 其中該第三夾角小於該預設角度。 1 5.如申請專利範圍第1 0項之印表機,其中該感應器為光Page 27 518286 6. When applying for a patent range sensing signal, the controller will rotate the cam by a preset angle, and judge the angle of the cam relative to the housing only based on the signal generated by the sensor; The predetermined angle is between the first included angle and the second included angle. 1 1. If the printer of the 10th patent application scope, if the signal generated by the sensor after the cam rotates the preset angle is the sensor signal of the section, the controller will reverse the cam Turn until the signal generated by the cam changes to the flange sensing signal. 1 2. If the printer of the 10th patent application scope, if the cam rotates the preset angle, the signal generated by the sensor is the flange induction signal, the controller will continue to make the cam rotate Until the signal generated by the cam is changed to the induction signal of the segment. 1 3. The printer according to item 10 of the patent application scope, wherein the first included angle is greater than the brother Yishuang angle. 14. The printer according to item 10 of the patent application scope, wherein the cam further includes a third section, and the third section corresponds to a circle center with a third included angle; wherein the third included angle is smaller than the Set the angle. 1 5. The printer as claimed in item 10 of the patent application scope, wherein the sensor is light 第28頁 518286 六、申請專利範圍 感應器。 1 6.如申請專利範圍第1 0項之印表機,其中當該凸輪轉動 而帶動該第一區段掠過該感應器時,該凸輪係帶動該印表 機進行一初始化作業。 1 7.如申請專利範圍第1 0項之印表機,其中當該凸輪轉動 而帶動該第二區段掠過該感應器時,該凸輪係帶動該印表 機進行一饋紙作業。Page 28 518286 VI. Patent Application Range Sensor. 16. The printer of claim 10, wherein when the cam rotates to drive the first section past the sensor, the cam drives the printer to perform an initialization operation. 1 7. The printer of claim 10, wherein when the cam rotates to drive the second section to pass through the sensor, the cam drives the printer to perform a paper feeding operation. 1 8.如申請專利範圍第1 0項之印表機,其中當該凸輪轉動 而帶動該第二區段掠過該感應器時,該凸輪係帶動該印表 機進行一列印作業。1 8. The printer of claim 10, wherein when the cam rotates to drive the second section to pass through the sensor, the cam drives the printer to perform a printing operation. 第29頁Page 29
TW91108589A 2002-04-25 2002-04-25 Method and related apparatus for addressing operations of a printer with single sensor TW518286B (en)

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Cited By (1)

* Cited by examiner, † Cited by third party
Publication number Priority date Publication date Assignee Title
US8834045B2 (en) 2011-11-29 2014-09-16 Hiti Digital, Inc. Printer capable of printing two surfaces of a web

Cited By (2)

* Cited by examiner, † Cited by third party
Publication number Priority date Publication date Assignee Title
US8834045B2 (en) 2011-11-29 2014-09-16 Hiti Digital, Inc. Printer capable of printing two surfaces of a web
TWI464075B (en) * 2011-11-29 2014-12-11 Hiti Digital Inc Printer capable of printing two surfaces of a medium

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