TW201104399A - Power suplly system and method - Google Patents
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201104399 六、發明說明: 【發明所屬之技術領域】 [0001] 本發明係關於一種電源供應系統及方法。 【先前技術】 [0002] 電腦中主機板的主要電源’如1 2V、5V和3. 3V等均由外 ^ 接的電源供應器來提供。習知之大型電腦伺服器工作站 、 中’電源供應器一般透過子板(Daughter board)的電 源連接器與主機板的電源連接器相連。子板用來作為電 0 源供應器或各種1/0訊號的轉接板。當主機板有較大電流 需求時,經常透過兩個以上的電源連接器將電源供應器 提供的電流提供給主機板上的各負載,以降低過大的電 • 流透過單一電源連接器所造成的溫升。 [〇〇〇3]然’當主機板有複數電源連接器時,因各個電源連接器 與負載在主機板上的相對位置不同,而電流一般又以最 短的路徑流至負載,故造成與負截最近的電源連接器承 受過大的電流,而流經其餘的電源連接器的電流過小, 〇 從而使得電流過大的電源連接器溫升邁高,影響供電品 質,甚至燒毀電源連接器或損壞主機板。 【發明内容】 [0004] 鑒於前述内容,有必要提供一種使電流均衡流經主機板 上各電源連接器的電源供應系統及方法。 [0005] 一種電源供應系統,包括: [0006] —電源供應器,用於提供一卫作電壓; [0007] 一子板,包括一第一VRM連接器、一第二VRM連接器、一 098125857 表單編號A0101 第3頁/共17頁 0982044349-0 201104399 第-電源連接ϋ及-第二電源連接器,該第—VRM連接器 及第-連接H與該電源供應器相連以接收該工作電麼 。亥第一VRM連接器與第一電源連接器透過一第一銅搭相 連,該第二VRM連接器與第二電源連接器透過一第二銅羯 相連;以及 [0008] [0009]201104399 VI. Description of the Invention: [Technical Field of the Invention] [0001] The present invention relates to a power supply system and method. [Prior Art] [0002] The main power supply of the motherboard in the computer, such as 1 2V, 5V, and 3. 3V, is provided by an external power supply. The conventional large computer server workstation, medium power supply is generally connected to the power connector of the motherboard through the power connector of the daughter board. The daughter board is used as an electrical source or a variety of 1/0 signal adapter boards. When the motherboard has a large current demand, the current supplied by the power supply is often supplied to the load on the motherboard through more than two power connectors to reduce the excessive power flow through the single power connector. Temperature rise. [〇〇〇3] However, when the motherboard has multiple power connectors, the relative positions of the power connectors and the load on the motherboard are different, and the current generally flows to the load in the shortest path, thus causing a negative The most recent power connector is subjected to excessive current, and the current flowing through the remaining power connectors is too small, which causes the overcurrent power connector to rise in temperature, affecting the quality of the power supply, or even burning the power connector or damaging the motherboard. . SUMMARY OF THE INVENTION [0004] In view of the foregoing, it is desirable to provide a power supply system and method for balancing current through various power connectors on a motherboard. [0005] A power supply system, comprising: [0006] a power supply for providing a servo voltage; [0007] a daughter board comprising a first VRM connector, a second VRM connector, a 098125857 Form No. A0101 Page 3 of 17 0982044349-0 201104399 First-power connection - and - second power connector, the first VRM connector and the first connection H are connected to the power supply to receive the working power? . The first VRM connector is connected to the first power connector through a first copper connector, and the second VRM connector is connected to the second power connector through a second copper port; and [0008]
一主機板,包括一第三電源連接器、一第四電源連接器 以及複數負載,該第三電源連接器透過一第三銅箔與第 四電源連接器連接,該第三電源連接器與第四電源連接 器分別與該子板上的第一電源連接器及第二電源連接器 相連以接收該工作電壓,其中,讓第一銅箔及第二銅箔 的等效阻抗的差值等於主機板上的第三電源連接器、第 四電源連接器的電位差除以兩者輸出電流的平均值。a motherboard including a third power connector, a fourth power connector, and a plurality of loads, the third power connector being connected to the fourth power connector through a third copper foil, the third power connector and the third power connector The four power connectors are respectively connected to the first power connector and the second power connector on the daughter board to receive the working voltage, wherein the difference between the equivalent impedance of the first copper foil and the second copper foil is equal to the host The potential difference between the third power connector and the fourth power connector on the board is divided by the average of the output currents of the two.
種使用一電源供應器透過一子板給一主機板供電的電 源供應方法,該子板包括一第一VRM連接器、一第二VRMA power supply method for supplying power to a motherboard through a power supply board, the daughter board including a first VRM connector and a second VRM
連接恣、一第一電源連接器及一第二電源連接器,該主 機板包括一第三電源連接器、—第四電源連接器以及複 數負栽’該第一VRM連接器以及第二VRM連接器與該電源 供應器相連以接收一工作電壓,該主機板上第三電源連 接器與第四電源連接器分別與該子板上的第一電源連接 器及第二電源連接器相連以接收該工作電壓為該等負載 供電,該第一VRM連接器與第一電源連接器透過一第一銅 箔相連,該第二VRM連接器與第二電源連接器透過—第二 銅羯相連’該第三電源連接器透過一第三銅箔與第四電 源連接器連接,該電源供電方法包括: [0010] 098125857 巡過類比仿真提供該工作電 壓給該 H喊號A0101 茁4百/丘17百 第4頁/共17頁 0982044349-0 201104399 連接器'第四電源連接器以得到該第三及第 益的輸出電流; 四電源連接 [0011] [0012] [0013]Ο [0014] [0015]Ο 根據該第三電源連接器 出平均電流; 透過模擬仿真求出該 第四電源連接器的輸出電流求 主機板上的第三銅箔的等效阻抗; ㈣主機板上的第三銅㈣等效阻抗乘以該第三電源連 接盗、第四電源連接器的輸出電流與平均電流的差值, 從而求出第三電源連接器、第四電源連接器之間的電廢 差; 疋義》亥第—電源連接器的電壓值’將輔源供應器提供 的工作電Μ與該第三電源連接器的電壓值的差值除以該 平均電從而得出該子板上第—電源連接器與第一伽 連接器之間第~_的等效阻抗;以犮 將所疋義的第二電源連接11的職值減去第三電源連接 \第四電源連接器之間的電壓差求出該第四電源連接 .值將該電源供應器提供的工作電壓與第四電 原連接器的電壓值的差值除以該平均電流,從而得出該 子板上第—電源連接器與第二VRM連接器之間第二銅箱的 等效阻抗。 [0016] 098125857 H供應系統及方法透過類比仿真求出主機板上 各電源連接器的輪出電流及相互間㈣的等效阻抗,並 疋義其中一個電源連接器的電壓值,從而透過計算分別 求出子板上的各電源連接器和與之相連的VRM連接器之間 銅名的等效阻抗’以此設計該子板使得流經主機板上的 表單編號A0101 第 5 頁/共 17 頁 0982044349-0 201104399 各電源連接器的電流相等》 【實施方式】 [0017] [0018] [0019] 098125857 睛參閱圖1,本發明電源供應系統1〇〇的較佳實施方式包 括一電源供應器10、一子板20以及一主機板3 〇。該子板 20 包括一第一 VRM(Voltage Regulator Module,電壓 調整模塊)連接器VRC1、一第二VRM連接器VRC2、一第一 電源連接器PWC1及一第二電源連接器PWC2。該主機板30 包括一第三電源連接器PWC3、一第四電源連接器pwc4及 四個負載LI、L2、L3和L4。 該子板20透過第一VRM連接器VRC1、第土VRM連接器 VRC2與該電源供應器1〇相連。該子板2〇的第一電源連接 器PWC1、第二電源連接器PWC2對應與該主機板3〇的第三 電源連接器PWC3、第四電源連接器PWC4相連。該電源供 應器10透過第一VRM連接器VRC1、第二VRM連接器VRC2 、第一電源連接器PWC1、第二電源連接器PWC2、第三電 源連接器PWC3及第四電源連接器PWC4為該主機板30上的 負載U-L4供電。 其中’該子板20上的第一VRM連接器VRC1透過第一銅箔 21與第一電源連接器PWC1相連’該第二VRM連接器VRC2 透過第二銅箔22與第二電源連接器PWC2相連。該第一銅 箔21的等效阻抗為R1,該第二銅箔22的等效阻抗為R2。 該第三電源連接器PWC3、第四電源連接器PWC4透過第三 銅箔31相連’該第三銅箔31的等效阻抗為RC。 本發明透過設定子板20上第一銅箔21的等效阻抗R1以及 第二銅箔22的等效阻抗R2,使得該子板20上的第一電源 表單編號A0101 第6頁/共17頁 0982044349-0 [0020] 201104399 連接器PWC1及第二電源連接器pwc2的輸出電流相等,從 而使得流經該主機板30上的第三電源連接器pwc3和第四 電源連接器PWC4的電流相等,避免主機板3〇上的第三電 源連接器PWC3與第四電源連接器PWC4流經的電流相差過 大。 [0021] 如圖2所示’本發明提供一種電源供電方法,該方法以反 推的方式詳細闡述了如何得到第一銅箔21及第二銅箔2 2 的等效阻抗R1及R2的值,從而使得流經該PWC3及PWC4的 Ο [0022] 電流相等,該電源供電方法包括以下步驟。 ... : ..... .... . . . 步驟S1 :如圖3所亲’透過類比仿真軟體仿真該主機板30 的第三電源連接器PWC3及第四電源連接器Pff4均加入12V 工作電壓。本實施方式中,設定負載L1_L4的額定工作電 流均為20. 6A、額定工作電壓均為12V。該電源供應器10 提供的工作電壓為12Ve [0023] ❹ 由此,透過仿真軟艎可得到此時該第三電論連接器PWC3 的輸出電流為11=33· 7A,第四電源連接器PWC4的輸出電 流為12=48. 7A。由於必須衩得流經該第三電源連接器 PWC3及第四電源連接器PWC4相等,故流經該第三電源連 接器PWC3、第四電源連接器PWC4的電流即為該第三電源 連接器PWC3的輸出電流II和第四電源連接器PWC4的輸出 電流12的平均電流I = ( 11 +12 ) / 2 = (33. 7A+48. 7Α)/2=41· 2A。此時,可得到該第三電源 連接器PWC3流向該第四電源連接器PWC4的電流 1041. 2-33. 7 = 48. 7-41. 2 = 7. 5Α。 098125857 表單編號Α0101 第7頁/共17頁 0982044349-0 201104399 [麵]步驟S2 :透過類比仿真軟體得到該第三電源連接器PWC3 及第四電源連接器PWC4之間第三銅箔31的等效阻抗 代=0· 634422ιηΩ。故’該第三電源連接器PWC3與該第 四電源連接器PWC4之間的電壓差 Δ V=RC木lc = 〇. 634422 ιηΩ*7. 5A = 4. 758165mV。 [0025] 步驟S3 :取該第三電源連接器PWC3的電壓^為^. 92V。 理論上,該第三電源連接器pWC3的電壓V1應該等於負載 τ ! T , L 、 f、 -L4的額定工作電壓1 gv,赛,由於電源供應器1 〇提供 ’ 的工作電壓12V經過子板2G時會存在電壓降,故,該第三 電源連接器PWC3的實際電壓VI將會小於12V,本實施方 式中,該第三電源連接器PWC3的電壓VI取11. 92V,其他 實施方式中亦可設定其他值。由此,可求得子板2〇上的 第一電源連接器PWC1與第一 VRM連接器VRC1之間的第一 銅箔21的等效阻抗a first power connector and a second power connector, the motherboard includes a third power connector, a fourth power connector, and a plurality of the first VRM connector and the second VRM connector The device is connected to the power supply to receive an operating voltage, and the third power connector and the fourth power connector on the motherboard are respectively connected to the first power connector and the second power connector on the daughter board to receive the The working voltage is supplied to the loads, the first VRM connector is connected to the first power connector through a first copper foil, and the second VRM connector is connected to the second power connector through the second copper port. The three power connector is connected to the fourth power connector through a third copper foil, and the power supply method includes: [0010] 098125857 Patrol analog simulation provides the working voltage to the H call number A0101 茁 4 hundred / mound 17 hundred 4 pages/total 17 pages 0982044349-0 201104399 Connector 'fourth power connector to get the third and the first output current; four power connection [0011] [0013] [0014] [0015] According to the third power connection Average current is obtained; the output current of the fourth power connector is obtained through simulation to obtain the equivalent impedance of the third copper foil on the motherboard; (4) the third copper (four) equivalent impedance on the motherboard is multiplied by the third The difference between the output current of the power connection thief and the fourth power connector and the average current, thereby determining the electrical waste difference between the third power connector and the fourth power connector; 疋义》海第—Power connector The voltage value 'divides the difference between the operating voltage provided by the auxiliary source supply and the voltage value of the third power connector by the average electric power to obtain the first power connector and the first gamma connector on the daughter board The equivalent impedance of the first ~_; the fourth power connection is obtained by subtracting the voltage difference between the third power connection and the fourth power connector by the value of the second power connection 11 Dividing the difference between the operating voltage provided by the power supply and the voltage value of the fourth electrical connector by the average current, thereby obtaining a second between the first power connector and the second VRM connector on the daughter board The equivalent impedance of the copper box. [0016] 098125857 H supply system and method through the analog simulation to find the output current of each power connector on the motherboard and the equivalent impedance of each other (four), and deny the voltage value of one of the power connectors, thereby calculating the difference Find the equivalent impedance of the copper name between each power connector on the daughter board and the VRM connector connected to it'. Design the daughter board so that it flows through the form number on the motherboard A0101 Page 5 of 17 0982044349-0 201104399 The currents of the power connectors are equal. [Embodiment] [0019] [0019] 098125857 Referring to FIG. 1, a preferred embodiment of the power supply system 1A of the present invention includes a power supply 10 , a daughter board 20 and a motherboard 3 〇. The daughter board 20 includes a first VRM (Voltage Regulator Module) connector VRC1, a second VRM connector VRC2, a first power connector PWC1, and a second power connector PWC2. The motherboard 30 includes a third power connector PWC3, a fourth power connector pwc4, and four loads LI, L2, L3, and L4. The daughter board 20 is connected to the power supply unit 1 through the first VRM connector VRC1 and the soil VRM connector VRC2. The first power connector PWC1 and the second power connector PWC2 of the daughter board 2 are connected to the third power connector PWC3 and the fourth power connector PWC4 of the motherboard 3A. The power supply 10 passes through the first VRM connector VRC1, the second VRM connector VRC2, the first power connector PWC1, the second power connector PWC2, the third power connector PWC3, and the fourth power connector PWC4. The load U-L4 on board 30 is powered. The first VRM connector VRC1 on the daughter board 20 is connected to the first power connector PWC1 through the first copper foil 21. The second VRM connector VRC2 is connected to the second power connector PWC2 through the second copper foil 22. . The equivalent impedance of the first copper foil 21 is R1, and the equivalent impedance of the second copper foil 22 is R2. The third power connector PWC3 and the fourth power connector PWC4 are connected by a third copper foil 31. The equivalent impedance of the third copper foil 31 is RC. The present invention transmits the first power supply form number A0101 on the sub-board 20 by setting the equivalent impedance R1 of the first copper foil 21 on the sub-board 20 and the equivalent impedance R2 of the second copper foil 22. 0982044349-0 [0020] 201104399 The output currents of the connector PWC1 and the second power connector pwc2 are equal, so that the current flowing through the third power connector pwc3 and the fourth power connector PWC4 on the motherboard 30 are equal, avoiding The current flowing through the third power connector PWC3 on the motherboard 3A and the fourth power connector PWC4 are too large. [0021] As shown in FIG. 2, the present invention provides a power supply method, which explains in detail how to obtain the equivalent impedances R1 and R2 of the first copper foil 21 and the second copper foil 2 2 in a reverse thrust manner. Therefore, the current flowing through the PWC3 and the PWC4 is equal, and the power supply method includes the following steps. ... : ..... .... . . . Step S1: As shown in Figure 3, through the analog simulation software simulation, the third power connector PWC3 and the fourth power connector Pff4 of the motherboard 30 are added. 12V operating voltage. In the present embodiment, the rated operating current of the load L1_L4 is set to be 20. 6A, and the rated operating voltage is 12V. The power supply 10 provides an operating voltage of 12Ve [0023] ❹ Thus, the output current of the third electromagnetism connector PWC3 is 11=33·7A, and the fourth power connector PWC4 is obtained through the simulation software. The output current is 12=48. 7A. Since the third power connector PWC3 and the fourth power connector PWC4 must be equal, the current flowing through the third power connector PWC3 and the fourth power connector PWC4 is the third power connector PWC3. The average current of the output current II and the output current 12 of the fourth power connector PWC4 is I = (11 +12) / 2 = (33. 7A+48. 7Α)/2=41· 2A. At this time, the current flowing through the third power connector PWC3 to the fourth power connector PWC4 is obtained 1041. 2-33. 7 = 48. 7-41. 2 = 7. 5Α. 098125857 Form No. 1010101 Page 7 of 17 0982044349-0 201104399 [Surface] Step S2: Equivalent of the third copper foil 31 between the third power connector PWC3 and the fourth power connector PWC4 through the analog simulation software Impedance = 0 · 634422ιηΩ. Therefore, the voltage difference between the third power connector PWC3 and the fourth power connector PWC4 is Δ V = RC wood lc = 〇. 634422 ιηΩ * 7. 5A = 4. 758165 mV. [0025] Step S3: taking the voltage of the third power connector PWC3 ^ ^ 92V. Theoretically, the voltage V1 of the third power connector pWC3 should be equal to the rated operating voltage of the load τ ! T , L , f , -L4 , 1 gv , because the power supply 1 〇 provides the operating voltage of 12V through the daughter board The voltage of the third power connector PWC3 is 11.92V. In other embodiments, the voltage of the third power connector PWC3 is also less than 12V. Other values can be set. Thereby, the equivalent impedance of the first copper foil 21 between the first power connector PWC1 on the daughter board 2A and the first VRM connector VRC1 can be obtained.
R1=(12V-V1)/I=(12V-11 92)/41.2A=1.94175 mQ 。 ο [0026] 步驟S4 :該主機板30上第四電源連接器pwC4的電壓值 V2=V1- Δ ν = 11· 758165mV=ll. 915242V,故子板20上的R1=(12V-V1)/I=(12V-11 92)/41.2A=1.94175 mQ. [0026] Step S4: The voltage value of the fourth power connector pwC4 on the motherboard 30 is V2=V1- Δ ν = 11· 758165mV=ll. 915242V, so on the daughter board 20
第二電源連接器PWC2與第二VRM連接器VRC2之間第二銅 箔22的等效阻抗R2= (12V-V2)/I = (12V-1 1. 915242V)/41.2A = 2.057234 W。 098125857 表單編號Α0101 第8頁/共17頁 0982044349-0 201104399 [0027] 如此,將子板20上的第一電源連接器連接器 V R C1之間的第一銅箔21的等效阻抗R1設定為1. 9 417 5 m Ω,將第二電源連接器PWC4與VRM2連接器VRC2之間的第 二銅箱22的等效阻抗R2設定為2. 057234 πιΩ,可使得流 經主機板30上的第三電源連接器PWC3及第四電源連接器 PWC4的電流均為41. μ。 [0028] 在其他實施方式中,上述電源供應方法的步驟可以調換 ,而不局限於上述次序。比如,可先透過類比仿真軟體 〇 得到主機板3 〇上第三電源、填接器P C 3和第四電源連接器 PWC4之間第三銅箔31的等效睢抗RC,或先設定主機板3〇 上第三電源連接器PWC上的電壓值VI,之後透過類比仿真 軟體得出主機板30上第三電源連接器PWC3和第四電源連 接器PWC4的輸出電流II、12,最後透過計算求出子板2〇 上第一電源連接器PWC 1與第一 VRM連接器VRC1之間第一 銅箱21的等效阻抗R1以及第二電源連接器pwC2與第二 VRM連接器VRC2之間第二銅箔22的等效阻抗R2。 〇 [0029]另’亦可得到子板£〇上第一銅箔21的等效阻抗R1與第二 銅箔22的等效阻抗R2的關係為R2-R1 =The equivalent impedance of the second copper foil 22 between the second power connector PWC2 and the second VRM connector VRC2 is R2 = (12V - V2) / I = (12V - 1. 1. 915242V) / 41.2A = 2.057234 W. 098125857 Form No. 1010101 Page 8 of 17 0982044349-0 201104399 [0027] Thus, the equivalent impedance R1 of the first copper foil 21 between the first power connector VR C1 on the daughter board 20 is set to 1. 9 417 5 m Ω, the equivalent impedance R2 of the second copper box 22 between the second power connector PWC4 and the VRM2 connector VRC2 is set to 2.057234 πιΩ, so that the flow through the motherboard 30 The current of the three power connector PWC3 and the fourth power connector PWC4 are both 41. μ. [0028] In other embodiments, the steps of the power supply method described above may be reversed without being limited to the above order. For example, the analog RC of the third copper foil 31 between the third power supply of the motherboard 3, the filler PC 3 and the fourth power connector PWC4 can be obtained through the analog simulation software, or the motherboard can be set first. 3, the voltage value VI on the third power connector PWC, and then through the analog simulation software to obtain the output current II, 12 of the third power connector PWC3 and the fourth power connector PWC4 on the motherboard 30, and finally through calculation The equivalent impedance R1 of the first copper box 21 between the first power connector PWC 1 and the first VRM connector VRC1 and the second between the second power connector pwC2 and the second VRM connector VRC2 The equivalent impedance R2 of the copper foil 22. 〇 [0029] Alternatively, the relationship between the equivalent impedance R1 of the first copper foil 21 on the daughter board and the equivalent impedance R2 of the second copper foil 22 is R2-R1 =
AA
V/I,即子板2〇上第一銅箔21的等效阻抗ri與第二銅箔 22的等效阻抗R2的差值等於主機板30上的電源連接器 PWC3、PWC4的電位差除以輸出電流11、12的平均電流IV/I, that is, the difference between the equivalent impedance ri of the first copper foil 21 on the daughter board 2 and the equivalent impedance R2 of the second copper foil 22 is equal to the potential difference of the power connectors PWC3, PWC4 on the motherboard 30 divided by Average current I of output currents 11, 12
[0030]另,根據R2-R1 = 098125857 表早編號A0101 第9頁/共17頁 0982044349-0 201104399[0030] In addition, according to R2-R1 = 098125857, the table number is A0101, page 9 / page 17 0982044349-0 201104399
A v/卜⑽ RC)/卜[I2—(I1 + I2)/2]*2Rc"ii + i2) ,即當主機板30上第三電源連接器pwC3的電壓值”取值 確定後,透過模擬仿真得到主機板3〇上第三電源連接器 PWC3和第四電源連接器pwc4的輸出電流u、12及兩者間 第三銅則1的等纽抗職便可透過上述方法設計子板 20 〇 [0031]當該主機板30上的電源連接器多於兩個時,該子板別上 的電源連接器與VRM連接器之間銅镇的等效阻抗亦可依據 上述方法進行設定,使得流經該主機板3()上的電源連接 器的電流相等,避免主機板3〇上的某個電源連接器承受 過大的電流而使該電源連接器燒毁或損壞主機板。 闕树明《供電系統⑽及方域賴擬仿真得到主機板 30上的各個電源連接器輸出電流及相互間銅箱的等效阻 抗’並定義其中-個電源連接器的電屋值,從而透過計 算分別求出子板20上❾各個電源速接器和肖之相連的 連接器之間㈣料效阻抗,遞設計該子板2()使得流 經主機板30上的各個電源連接器的電流相等。 剛綜上料,本發明符合發明專财件,纽練出專利 申請。惟,以上所述者僅為本發明之較佳實施例,舉凡 熟悉本案技藝之人士 ’在美依本發明精神所作之等效修 飾或變化,皆應涵蓋於以下之申請專利範圍内。 【圖式簡單說明】 W)34] ® 1疋本發明電源供應纟統的較佳實施方式的方框圖。 098125857 表單編號A0101 第10頁/共17頁 0982044349-0 201104399 [0035] 圖2是本發明電源供應方法的較佳實施方式的流程圖。 [0036] 圖3是本發明電源供應系統類比仿真時的等效電路圖。 【主要元件符號說明】 電源供應系統 100 電源供應器 10 子板 20 主機板 30 第一銅箔 21 第二銅箔 22 第三銅箔 31 ❹ 〇 098125857 表單編號A0101 第11頁/共17頁 0982044349-0A v / 卜 (10) RC) / 卜 [I2 - (I1 + I2) / 2] * 2Rc " ii + i2), that is, when the voltage value of the third power connector pwC3 on the motherboard 30 is determined, The simulation can obtain the output current u, 12 of the third power connector PWC3 and the fourth power connector pwc4 on the motherboard 3, and the third copper resistance of the third copper can be used to design the daughter board 20 by the above method. [0031] When there are more than two power connectors on the motherboard 30, the equivalent impedance between the power connector and the VRM connector on the daughter board can also be set according to the above method, so that The current flowing through the power connector on the motherboard 3() is equal, so that a power connector on the motherboard 3 is subjected to excessive current to cause the power connector to burn or damage the motherboard. (10) and the square domain depends on the simulation to obtain the output current of each power connector on the motherboard 30 and the equivalent impedance of the copper box between each other' and define the electric house value of one of the power connectors, thereby obtaining the daughter boards respectively through calculation 20 between the various power adapters and the connector connected to Xiao (four) Impedance, the sub-board 2 () is designed to make the current flowing through the respective power connectors on the motherboard 30 equal. The invention is in accordance with the invention special wealth, and the patent application is processed. The present invention is only intended to be a preferred embodiment of the present invention, and equivalent modifications or variations made by those skilled in the art of the present invention should be included in the following claims. A block diagram of a preferred embodiment of the power supply system of the present invention. 098125857 Form No. A0101 Page 10 of 17 0982044349-0 201104399 [0035] FIG. 2 is a preferred embodiment of the power supply method of the present invention. [0036] Fig. 3 is an equivalent circuit diagram of the power supply system analogy simulation of the present invention. [Main component symbol description] Power supply system 100 Power supply 10 Sub board 20 Mother board 30 First copper foil 21 Two copper foil 22 Third copper foil 31 ❹ 〇 098125857 Form No. A0101 Page 11 of 17 0982044349-0
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