KR20100041902A - Heating control method making use of open proportion of heating valve - Google Patents
Heating control method making use of open proportion of heating valve Download PDFInfo
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- KR20100041902A KR20100041902A KR1020080100929A KR20080100929A KR20100041902A KR 20100041902 A KR20100041902 A KR 20100041902A KR 1020080100929 A KR1020080100929 A KR 1020080100929A KR 20080100929 A KR20080100929 A KR 20080100929A KR 20100041902 A KR20100041902 A KR 20100041902A
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- F—MECHANICAL ENGINEERING; LIGHTING; HEATING; WEAPONS; BLASTING
- F24—HEATING; RANGES; VENTILATING
- F24D—DOMESTIC- OR SPACE-HEATING SYSTEMS, e.g. CENTRAL HEATING SYSTEMS; DOMESTIC HOT-WATER SUPPLY SYSTEMS; ELEMENTS OR COMPONENTS THEREFOR
- F24D19/00—Details
- F24D19/10—Arrangement or mounting of control or safety devices
- F24D19/1006—Arrangement or mounting of control or safety devices for water heating systems
- F24D19/1009—Arrangement or mounting of control or safety devices for water heating systems for central heating
- F24D19/1015—Arrangement or mounting of control or safety devices for water heating systems for central heating using a valve or valves
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- G—PHYSICS
- G05—CONTROLLING; REGULATING
- G05D—SYSTEMS FOR CONTROLLING OR REGULATING NON-ELECTRIC VARIABLES
- G05D23/00—Control of temperature
- G05D23/19—Control of temperature characterised by the use of electric means
- G05D23/1902—Control of temperature characterised by the use of electric means characterised by the use of a variable reference value
- G05D23/1904—Control of temperature characterised by the use of electric means characterised by the use of a variable reference value variable in time
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- F—MECHANICAL ENGINEERING; LIGHTING; HEATING; WEAPONS; BLASTING
- F24—HEATING; RANGES; VENTILATING
- F24D—DOMESTIC- OR SPACE-HEATING SYSTEMS, e.g. CENTRAL HEATING SYSTEMS; DOMESTIC HOT-WATER SUPPLY SYSTEMS; ELEMENTS OR COMPONENTS THEREFOR
- F24D2220/00—Components of central heating installations excluding heat sources
- F24D2220/04—Sensors
- F24D2220/042—Temperature sensors
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- F—MECHANICAL ENGINEERING; LIGHTING; HEATING; WEAPONS; BLASTING
- F24—HEATING; RANGES; VENTILATING
- F24D—DOMESTIC- OR SPACE-HEATING SYSTEMS, e.g. CENTRAL HEATING SYSTEMS; DOMESTIC HOT-WATER SUPPLY SYSTEMS; ELEMENTS OR COMPONENTS THEREFOR
- F24D2220/00—Components of central heating installations excluding heat sources
- F24D2220/04—Sensors
- F24D2220/044—Flow sensors
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- F—MECHANICAL ENGINEERING; LIGHTING; HEATING; WEAPONS; BLASTING
- F24—HEATING; RANGES; VENTILATING
- F24D—DOMESTIC- OR SPACE-HEATING SYSTEMS, e.g. CENTRAL HEATING SYSTEMS; DOMESTIC HOT-WATER SUPPLY SYSTEMS; ELEMENTS OR COMPONENTS THEREFOR
- F24D2220/00—Components of central heating installations excluding heat sources
- F24D2220/04—Sensors
- F24D2220/046—Pressure sensors
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- Automation & Control Theory (AREA)
- Steam Or Hot-Water Central Heating Systems (AREA)
Abstract
Description
본 발명은 난방밸브의 개도량을 이용한 난방제어방법에 관한 것으로, 더욱 상세하게는 각 방의 난방배관길이가 길수록 각 방에 공급되는 난방유량이 반비례하게 되고, 각 방에 공급되는 난방유량에 클수록 각 방의 난방밸브개도량을 작게하여 난방유량에 따라 설정된 난방시간동안 각 방에 공급되는 난방유량합이 동일하도록 각 방에 공급되는 난방유량을 조절하도록 구성되는 난방밸브의 개도량을 이용한 난방제어방법에 관한 것이다.The present invention relates to a heating control method using the opening amount of the heating valve, more specifically, the longer the heating piping length of each room is inversely proportional to the heating flow rate supplied to each room, the larger the heating flow rate supplied to each room In the heating control method using the opening amount of the heating valve which is configured to reduce the opening amount of the heating valve of the room and adjust the heating flow rate supplied to each room so that the sum of the heating flow rates supplied to each room is the same for the heating time set according to the heating flow rate. It is about.
일반적으로, 각방 난방시스템에 적용되는 온도조절장치는 현재온도와 설정온도를 비교하여 현재온도가 설정온도에 도달하면 난방을 중지하거나, 설정된 일정시간을 주기로 하여 난방의 작동과 중지를 반복적으로 실시하거나, 이러한 두가지 방식을 조합하여 적용하고 있다.In general, the thermostat applied to each room heating system compares the present temperature with the set temperature and stops heating when the present temperature reaches the set temperature, or repeatedly operates and stops the heating at a set time. In addition, these two methods are applied in combination.
그러나, 이러한 종래의 난방온도조절방식은 실내온도의 급격한 변화와 불필요한 난방열의 낭비를 초래하게 되는 문제가 발생되고, 특히, 설정온도와 실내온도의 온도차에 따라 난방시간을 제어하는 난방제어방법의 경우, 실내온도의 측정시 실내바닥온도가 아닌 실내공기온도를 측정하게 된다.However, the conventional heating temperature control method has a problem that causes a sudden change in the room temperature and waste of unnecessary heating heat, in particular, in the case of the heating control method for controlling the heating time according to the temperature difference between the set temperature and the room temperature When measuring indoor temperature, indoor air temperature is measured, not indoor floor temperature.
이때, 보일러에 의해 난방이 되면 실내바닥이 데워지면서 바닥면에 축열이 서서히 실내공기를 데우게 되고, 어느정도 난방시간이 경과되어야 실내공기가 올라가게 되므로 실내바닥온도가 설정온도보다 훨씬 높게 난방되어야 실내온도가 설정온도에 도달하게 된다.At this time, when heated by the boiler, the indoor floor warms up and the heat storage gradually warms up the indoor air, and the indoor air goes up after a certain heating time, so the indoor floor temperature must be heated much higher than the set temperature. The temperature will reach the set temperature.
결국, 실내온도가 설정온도에 도달하여 보일러의 난방을 정지하여도 실내바닥의 축열에 의해 실내공기를 계속적으로 데우게 되므로 실내온도가 설정온도를 초과하는 과열상태를 이루게 되는 문제가 있다.As a result, even if the indoor temperature reaches the set temperature, even if the heating of the boiler is stopped, the indoor air is continuously heated by the heat storage of the indoor floor, resulting in an overheating condition in which the indoor temperature exceeds the set temperature.
이러한 종래의 문제를 개선하기 위하여 개발된 특허 제371896호에는 온도센서에 의한 실내온도(T1)의 측정주기인 온도측정주기를 설정한 후, 실내온도(T1)≥설정온도(T0)이면 상기 온도측정주기동안 보일러난방을 종료하고, 실내온도(T1) 〈 설정온도(T0)이면 그 온도차(ΔT)의 크기에 따라 설정된 난방시간동안 보일러난방을 하되, 난방시간이 종료되면 상기 온도측정주기중 남은 시간동안 보일러난방을 중단하도록 제어하는 것을 특징으로 하는 온도측정주기를 이용한 난방제어방법이 게시되어 있다.Patent No. 371896, developed to improve this conventional problem, sets a temperature measurement period, which is a measurement period of the indoor temperature T1 by a temperature sensor, and then sets the temperature when the indoor temperature T1 ≥ a set temperature T0. Boiler heating is terminated during the measurement period, and if the room temperature (T1) <set temperature (T0), the boiler is heated for the heating time set according to the magnitude of the temperature difference (ΔT). A heating control method using a temperature measurement cycle has been published, which is characterized by controlling the boiler heating to be stopped for a time.
그러나, 상기한 온도측정주기를 이용한 난방제어방법은 온수분배기의 난방밸브의 개폐에 따른 난방수의 유량변화와, 각 방의 난방배관길이를 고려하지 않고 단순히 온도차(ΔT)의 크기에 따라 난방시간이 결정되기 때문에 난방의 효율성이 떨어지고, 난방시간이 절대적으로 부족하거나 불필요하게 늘어나는 등의 문제가 있다.However, the heating control method using the temperature measurement cycle described above does not consider the change in the flow rate of the heating water according to the opening and closing of the heating valve of the hot water distributor and the heating time according to the magnitude of the temperature difference ΔT without considering the length of the heating piping in each room. Since it is determined that the efficiency of heating is reduced, there is a problem such that the heating time is absolutely insufficient or unnecessary increase.
본 발명은 이러한 종래 온도측정주기를 이용한 난방제어방법의 문제를 개선하기 위하여 안출된 것으로, 각 방의 난방배관길이에 따라 난방밸브의 개도량을 제어하여 설정된 난방시간동안 각 방에 공급되는 난방유량합이 동일하도록 각 방의 난방유량을 조절함으로써 각 방의 불필요한 과다난방이나 과소난방을 최소화하도록 구성되는 난방밸브의 개도량을 이용한 난방제어방법을 제공함에 그 목적이 있다.The present invention has been made to improve the problem of the heating control method using the conventional temperature measurement cycle, the heating flow rate supplied to each room during the set heating time by controlling the opening amount of the heating valve according to the heating pipe length of each room It is an object of the present invention to provide a heating control method using an opening amount of a heating valve configured to minimize unnecessary overheating or underheating of each room by adjusting the heating flow rate of each room so that the same.
상기한 목적을 달성하기 위하여 본 발명은 온도측정주기를 이용한 난방제어방법에 있어서, 각 방의 난방배관길이를 포함하는 난방수순환의 저항과 순환펌프의 양정를 이용하여 각 방의 난방유량을 산출하는 각 방의 난방유량산출단계와, 상기 각 방의 난방유량산출단계에서 산출되는 난방유량에 따라 각 방의 실제온도와 난방설정온도의 온도차 ΔT에 대한 난방시간을 설정하는 온도차 ΔT의 난방시간설정단계와, 각 방에 공급될 난방유량이 클수록 난방밸브개도량이 작아지도록 제어하여 상기 온도차 ΔT의 난방시간설정단계에서 산출된 난방시간동안 각 방에 공급되는 난방유량합이 동일하도록 각 방에 공급되는 난방유량을 보정하는 각 방의 난방유량보정단계;로 구성되는 것을 특징으로 하는 난방밸브의 개도량을 이용한 난방제어방법을 제공하게 된다.In order to achieve the above object, the present invention provides a heating control method using a temperature measuring cycle, wherein each room calculates a heating flow rate of each room using a resistance of a heating water circulation including a heating pipe length of each room and a head of a circulation pump. And a heating time setting step of a temperature difference ΔT for setting a heating time for a temperature difference ΔT between the actual temperature and the heating set temperature of each room according to the heating flow rate calculating step and the heating flow rate calculated in the heating flow rate calculating step of each room, The heating valve opening amount is controlled to be smaller as the heating flow rate to be supplied increases so that the heating flow rate supplied to each room is corrected so that the sum of the heating flow rates supplied to each room is the same during the heating time calculated in the heating time setting step of the temperature difference ΔT. To provide a heating control method using the opening amount of the heating valve, characterized in that consisting of; heating flow rate correction step of the room do.
이상과 같이 구성되는 본 발명은 각 방의 난방배관길이에 따라 각 방에 적정 한 공급유량이 공급되도록 난방밸브의 개도량을 제어함으로써 불필요한 과다난방이나 과소난방을 최소화할 수 있는 등의 효과를 제공하게 된다.The present invention configured as described above provides an effect of minimizing unnecessary overheating or underheating by controlling the opening amount of the heating valve so that an appropriate supply flow rate is supplied to each room according to the heating piping length of each room. do.
이하에서는 첨부된 도면을 참조하여 본 발명의 바람직한 실시예를 상세히 설명하기로 한다.Hereinafter, with reference to the accompanying drawings will be described a preferred embodiment of the present invention;
도1은 본 발명에 따른 난방밸브개폐에 따른 난방시간보정제어방법을 예시하는 제어공정도이다.1 is a control process diagram illustrating a heating time compensation control method according to the opening and closing of a heating valve according to the present invention.
일반적으로, 온도측정주기를 이용한 각 방의 난방제어시스템에 있어서 각 방의 난방시간은 설정된 온도측정주기동안 각 방에 공급되는 유량합을 의미하고, 각 방의 난방밸브가 개폐되면서 각 방에 공급되는 유량이 증가하거나 감소하게 되므로 유량의 변화에 따라 난방밸브의 개도량이 보정되지 않을 경우 각 방에 공급되어야할 유량합에 못 미치거나 초과하게 되는데, 방에 공급된 유량합이 부족할 경우 방의 난방이 충분치 못해 추울 것이고, 방에 공급된 유량합이 과다할 경우 방의 난방이 과다하여 덥게 되는 문제가 있다.In general, in the heating control system of each room using the temperature measurement cycle, the heating time of each room means the sum of the flow rates supplied to each room during the set temperature measurement cycle, and the flow rate supplied to each room as the heating valve of each room opens and closes. If the opening amount of the heating valve is not corrected according to the change of the flow rate, it will fall or exceed the sum of the flow rate to be supplied to each room. If the sum of the flow rates supplied to the room is excessive, there is a problem in that the heating of the room is excessive.
따라서, 본 발명은 각 방의 난방밸브개도량을 제어하여 온도측정주기중 각 방의 난방시간동안 각 방에 최적의 유량을 공급하도록 구성되는데, 다시 말하면 각 방은 설정된 난방시간에 의해 난방되도록 제어되지만 난방중 어느 방의 난방밸브가 개폐되면서 각 방에 공급되는 난방유량이 변하게 되고, 난방밸브의 개도량을 제어하여 각 방에 공급되는 난방유량을 보정하도록 구성되어 있다.Therefore, the present invention is configured to supply the optimum flow rate to each room during the heating time of each room during the temperature measurement cycle by controlling the opening amount of the heating valve in each room, that is, each room is controlled to be heated by the set heating time, but heating As the heating valve of any one of the rooms is opened and closed, the heating flow rate supplied to each room is changed, and the opening flow rate of the heating valve is controlled to correct the heating flow rate supplied to each room.
구체적으로 설명하면, 본 발명은 도1에 도시한 바와 같이 난방수순환의 저항 과 순환펌프의 양정를 이용하여 각 방의 난방유량을 산출하는 각 방의 난방유량산출단계(S100)와, 상기 각 방의 난방유량산출단계(S100)에서 산출되는 각 방의 난방유량에 따라 각 방의 실제온도와 난방설정온도의 온도차 ΔT에 대한 난방시간을 설정하는 온도차 ΔT의 난방시간설정단계(S200)와, 상기 온도차 ΔT의 난방시간설정단계(S200)에서 산출된 난방시간동안 각 방에 공급될 난방유량을 난방밸브개도량(HVo1~HVo4)에 따라 보정하는 각 방의 난방유량보정단계(S300);로 구성되어 있다.Specifically, the present invention is the heating flow rate calculation step (S100) of each room to calculate the heating flow rate of each room using the resistance of the heating water circulation and the head of the circulation pump as shown in Figure 1, the heating flow rate of each room The heating time setting step (S200) of the temperature difference ΔT for setting the heating time for the temperature difference ΔT between the actual temperature and the heating preset temperature of each room according to the heating flow rate of each room calculated in the calculating step (S100), and the heating time of the temperature difference ΔT The heating flow rate correction step of each room (S300) for correcting the heating flow rate to be supplied to each room during the heating time calculated in the setting step (S200) according to the heating valve opening amount (HVo1 ~ HVo4).
이하에서는 본 발명에 따른 난방제어방법을 실시예를 통해 구체적으로 설명하고자 한다.Hereinafter, the heating control method according to the present invention will be described in detail by way of examples.
[실시예]EXAMPLE
1.각 방의 난방유량산출단계(S100)에서는 난방수순환에 있어 각종 저항과 순환펌프의 양정를 이용하여 각 방의 난방유량을 산출하게 되는데, 1. The heating flow rate calculation step of each room (S100) is to calculate the heating flow rate of each room by using the resistance of the various resistance and circulation pump in the heating water circulation,
예컨대, 실내에서 각각 100m(Rp1),80m(Rp2),60m(Rp3),40m(Rp4)의 난방배관길이를 갖는 4개의 방(ro1~ro4)에 대하여 4구형의 온수분배기를 이용하여 난방을 실시할 경우, 800mbar의 양정(V)을 갖는 순환펌프를 사용하면서 보일러의 내부저항과 송환수관의 저항인 R1을 15mm의 직경을 갖는 파이프의 등가길이로 환산하여 총 30m로 계산하고, 동시에 각 방(ro1~ro4)의 밸브, 분배기, 접속구 등에서 발생되는 저항인 R2을 각각 20m로 환산하면서, 순환펌프의 양정(V)은 1mbar를 1Volt로,저항(R1,R2)과 난방배관길이(Rp1~Rp4)는 1m를 1Ω으로, 그리고 유량(Q)은 1LPM를 1A로 가정하면, [순환펌프의 양정(V)=유량(Q)×{저항(R1,R2)+난방배관길이(또는 난방 면적)(Rp1~Rp4)}]와 같은 관계식이 성립하는 다음과 같은 난방수순환의 전기회로식 등가회로를 만들 수 있게 된다.For example, four rooms (ro1 ~ ro4) with heating piping lengths of 100m (Rp1), 80m (Rp2), 60m (Rp3), and 40m (Rp4), respectively, are heated using a four-hole hot water distributor. In this case, using a circulating pump having a head of 800 mbar (V), calculate R1, which is the internal resistance of the boiler and the resistance of the return pipe, to be equivalent to the equivalent length of a pipe with a diameter of 15 mm. While converting R2, which is the resistance generated from (ro1 to ro4) valves, distributors, and connections, to 20 m each, the head of the circulation pump (V) is 1 mbar to 1 Volt, the resistances (R1, R2) and the heating piping length (Rp1 to Assuming that 1 m is 1 Ω and 1 L is 1 LPM, Rp4 is the head of the circulating pump (V) = flow rate (Q) × {resistance (R1, R2) + heating pipe length (or heating area). ) (Rp1 ~ Rp4)}] can make an electric circuit equivalent circuit of heating water circulation as follows.
이때, 상기 등가회로에서 모든 방의 전체저항 Rm를 구하면,At this time, if the total resistance Rm of all rooms is obtained from the equivalent circuit,
1/Rm=1/Rm1+1/Rm2+1/Rm3+1/Rm4=1/120+1/100+1/80+1/60=0.0475이므로1 / Rm = 1 / Rm1 + 1 / Rm2 + 1 / Rm3 + 1 / Rm4 = 1/120 + 1/100 + 1/80 + 1/60 = 0.0475
Rm≒21m가 되고, Rm ≒ 21m,
난방유량Q=전체양정(V)/전체저항(R1+Rm)에서Heating flow rate Q = Total head lift (V) / Total resistance (R1 + Rm)
Q=800/(21+30)m이므로 Q=15.7LPM을 구할 수 있다.Since Q = 800 / (21 + 30) m, Q = 15.7LPM can be obtained.
이때, 전체양정(V)/전체저항(R1+Rm)=방의 양정(Vr)/방의 부하(저항)(Rm)의 관계로부터 Vr=800×21/51≒329mbar이며, At this time, Vr is 800 × 21/51 ≒ 329 mbar from the relationship between total head (V) / total resistance (R1 + Rm) = room head (Vr) / room load (resistance) (Rm),
또한, 각 방에 동일하게 공급되는 난방수의 양정값 Vr=329mbar에 따른 각 방(ro1~ro4)의 난방유량 Q1,Q2,Q3,Q4을 구하면,In addition, if the heating flow rate Q1, Q2, Q3, Q4 of each room (ro1 to ro4) according to the head value Vr = 329mbar of the heating water supplied to each room equally is calculated | required,
Q1=Vr/Rm1=329/120≒2.8LPMQ1 = Vr / Rm1 = 329/120 ≒ 2.8LPM
Q2=Vr/Rm2=329/100≒3.3LPMQ2 = Vr / Rm2 = 329/100 ≒ 3.3LPM
Q3=Vr/Rm3=329/80≒4.1LPMQ3 = Vr / Rm3 = 329/80 ≒ 4.1LPM
Q4=Vr/Rm4=329/60≒5.5LPM이 되고,Q4 = Vr / Rm4 = 329/60 ≒ 5.5LPM,
상기 난방유량 Q1,Q2,Q3,Q4의 값은 각 방의 난방밸브(v1~v4)가 100% 개방된 상태에서 각 방에 공급되는 유량값이다.The values of the heating flow rates Q1, Q2, Q3, and Q4 are flow rate values supplied to each room in a state where the heating valves v1 to v4 of each room are 100% open.
2. 온도차 ΔT의 난방시간설정단계(S200)에서는 각 방의 난방유량산출단계(S100)에서 산출되는 각 방의 난방유량(Q1,Q2,Q3,Q4)중 난방배관길이 Rp1이 가장 길면서 그 난방유량값이 가장 작으므로 이 난방유량(Q1)을 기준으로 각 방의 실제온도와 난방설정온도의 온도차 ΔT에 대한 난방시간을 설정하게 되는데,2. In the heating time setting step (S200) of the temperature difference ΔT, the heating pipe length Rp1 of the heating flow rates (Q1, Q2, Q3, Q4) of each room calculated in the heating flow rate calculation step (S100) of each room is the longest and the heating flow rate. Since the value is the smallest, the heating time for the temperature difference ΔT between each room's actual temperature and the heating set temperature is set based on this heating flow rate (Q1).
방1(ro1)의 난방배관길이인 100m에 난방유량 Q1=2.8LPM이 공급되는 경우, 각 방의 실제온도와 난방설정온도의 온도차 ΔT에 대해 ΔT=0.5℃당 난방시간을 5분으로 설정하기로 하면,If the heating flow rate Q1 = 2.8LPM is supplied to the heating piping length of room 1 (ro1), the heating time per ΔT = 0.5 ℃ is set to 5 minutes for the temperature difference ΔT between the actual temperature and the heating set temperature of each room. if,
예컨대, 방1의 온도차 ΔT가 1℃, 방2의 온도차 ΔT가 1.5℃, 방3의 온도차 ΔT가 2℃, 방4의 온도차 ΔT가 2.5℃가 발생되었다고 가정하는 경우, 각 방의 난방시간은 각각 10분, 15분, 20분, 25분으로 설정할 수 있게 된다.For example, assuming that the temperature difference ΔT of room 1 is 1 ° C, the temperature difference ΔT of room 2 is 1.5 ° C, the temperature difference ΔT of room 3 is 2 ° C, and the temperature difference ΔT of room 4 is 2.5 ° C. 10 minutes, 15 minutes, 20 minutes, and 25 minutes can be set.
3. 각 방의 난방유량보정단계(S300)에서는 상기 온도차 ΔT의 난방시간설정단계(S200)에서 설정된 각 방의 난방시간동안 각 방(ro1~ro4)에 공급될 난방유량을 각 방의 조건에 따라 보정하게 된다.3. In the heating flow rate correcting step S300 of each room, the heating flow rate to be supplied to each room ro1 to ro4 during the heating time of each room set in the heating time setting step S200 of the temperature difference ΔT is corrected according to the conditions of each room. do.
다시 말하면, 각 방에 설정된 난방시간은 1번방(ro1)의 난방밸브(v1)가 100% 완전 개방된 상태에서 난방유량 Q1=2.8LPM이 공급되는 경우를 기준으로 설정된 시간이므로, 설정된 난방시간동안 방2내지4(ro2~ro4)에 각 난방밸브(v2~v4)가 완전 개방된 상태에서 Q1=2.8LPM보다 많은 Q2,Q3,Q4의 난방유량이 공급되면서 방2 내지 방4(ro2~ro4)의 경우 과도난방이 이루어지게 된다.In other words, the heating time set in each room is set based on the case where the heating flow rate Q1 = 2.8LPM is supplied while the heating valve v1 of the first room ro1 is 100% completely open, When the heating valves (v2 to v4) are completely open in the rooms 2 to 4 (ro2 to ro4), the heating flow rates of Q2, Q3 and Q4 are more than Q1 = 2.8 LPM, and the rooms 2 to 4 (ro2 to ro4) are supplied. ) Is overheating.
따라서, 본 발명에서는 난방밸브(v2~v4)의 개도량을 조절하여 방2~4(ro2~ro4)로 공급되는 난방유량을 보정함으로써 과도난방을 방지하도록 구성되어 있다.Therefore, the present invention is configured to prevent excessive heating by adjusting the opening amount of the heating valves v2 to v4 to correct the heating flow rate supplied to the rooms 2 to 4 (ro2 to ro4).
즉, (난방시간설정을 위한 기준난방유량)/[각 방의 난방유량(Q1,Q2,Q3,Q4)]의 수식을 이용하여 난방밸브의 개도량을 다음과 같이 산출하여 각 방의 난방유량을 보정하게 된다. That is, the opening flow rate of the heating valve is calculated by using the formula (Standard heating flow rate for heating time setting) / [Heating flow rate of each room (Q1, Q2, Q3, Q4)] as follows to correct the heating flow rate of each room. Done.
방1의 난방밸브개도량(HVo1) = 2.8LPM/Q1 = 2.8LPM/2.8LPM = 100%Heating valve opening amount of room 1 (HVo1) = 2.8LPM / Q1 = 2.8LPM / 2.8LPM = 100%
방2의 난방밸브개도량(HVo2) = 2.8LPM/Q2 = 2.8LPM/3.3LPM ≒ 85%Heating valve opening amount of room 2 (HVo2) = 2.8LPM / Q2 = 2.8LPM / 3.3LPM ≒ 85%
방3의 난방밸브개도량(HVo3) = 2.8LPM/Q3 = 2.8LPM/4.1LPM ≒ 68%Heating valve opening amount of room 3 (HVo3) = 2.8LPM / Q3 = 2.8LPM / 4.1LPM ≒ 68%
방4의 난방밸브개도량(HVo4) = 2.8LPM/Q4 = 2.8LPM/5.5LPM ≒ 51%Heating valve opening amount of room 4 (HVo4) = 2.8LPM / Q4 = 2.8LPM / 5.5LPM ≒ 51%
결국, 본 발명에서는 각 방의 온도차 ΔT에 따라 설정된 각 방의 난방시간동안 방1(ro1)의 난방밸브개도량(HVo1) 100%로 난방밸브(v1)를 완전 개방한 상태에서 방2(ro2)의 난방밸브개도량(HVo2) 85%, 방3(ro3)의 난방밸브개도량(HVo3) 68%, 방4(ro4)의 난방밸브개도량(HVo4) 51%로 각 난방밸브(v2,v3,v4)를 개방하여 각 방에 공급되는 난방유량을 제어함으로써 최적의 난방상태를 유지시키게 된다.As a result, in the present invention, the heating valve v1 is 100% of the heating valve opening amount HVo1 of the room 1 ro1 during the heating time of each room set according to the temperature difference ΔT of each room. Heating valve opening amount (HVo2) 85%, room 3 (ro3) heating valve opening amount (HVo3) 68%, room 4 (ro4) heating valve opening amount (HVo4) 51%, respectively, heating valves (v2, v3, v4) is opened to control the heating flow rate supplied to each room to maintain the optimal heating condition.
4.각 방의 난방중 방1의 난방시간이 종료되었다고 가정하면,4. Assuming that the heating time of Room 1 has expired while heating each room,
방1(ro1)의 난방밸브(v1)가 닫히게 되고, 방1에 공급되던 난방유량은 방2,3,4에 공급되므로 상기와 같은 제어방법으로 난방유량을 재보정하게 된다.The heating valve v1 of the room 1 ro1 is closed, and the heating flow rate supplied to the room 1 is supplied to the rooms 2, 3, and 4 so that the heating flow rate is recalibrated by the control method as described above.
방2,3,4에 대한 난방유량을 보정하게 되는데, 방2,3,4의 보정저항 Rm'를 구하면,The heating flow rate for the rooms 2, 3, and 4 is corrected.
1/Rm'=1/Rm2+1/Rm3+1/Rm4=1/100+1/80+1/60=0.0392이므로1 / Rm '= 1 / Rm2 + 1 / Rm3 + 1 / Rm4 = 1/100 + 1/80 + 1/60 = 0.0392
Rm'≒25.5m가 되고, Rm '≒ 25.5m
난방유량Q'=전체양정(V)/보정된 전체저항(R1+Rm')에서Heating flow rate Q '= total lift (V) / corrected total resistance (R1 + Rm')
Q'=800/(25.5+30)m이므로 Q'=14.4LPM이고,Q '= 1800LPM since Q' = 800 / (25.5 + 30) m,
방의 보정양정(Vr')=전체양정(V)×방의 보정저항(Rm')/보정된 전체저항(R1+Rm')의 관계식으로부터 Vr'=800×25.5/55.5=368mbar를 구할 수 있다. Vr '= 800 x 25.5 / 55.5 = 368 mbar can be obtained from the relational expression of the room's correction head (Vr') = total head (V) x room's correction resistance (Rm ') / room correction (R1 + Rm').
또한, 각 방에 동일하게 공급되는 난방수의 보정양정 Vr'=368mbar에 따른 각 방(2~4)의 각 난방유량 Q2', Q3', Q4'을 구하면,In addition, when each heating flow rate Q2 ', Q3', Q4 'of each room 2-4 according to the correction head Vr' = 368 mbar of the heating water supplied to each room is calculated | required,
Q2'=Vr'/Rm2=368/100≒3.7LPMQ2 '= Vr' / Rm2 = 368/100 ≒ 3.7LPM
Q3'=Vr'/Rm3=368/80=4.6LPMQ3 '= Vr' / Rm3 = 368/80 = 4.6LPM
Q4'=Vr'/Rm4=368/60=6.1LPM이 되고,Q4 '= Vr' / Rm4 = 368/60 = 6.1LPM,
각 방의 보정난방시간1 = (각 방의 설정난방시간 - 방1의 난방시간)으로 설정하게 된다.The set heating time for each room 1 = (Setting heating time for each room-heating time for room 1).
방2의 난방밸브개도량(HVo2') = 3.7LPM/Q2' = 3.7LPM/3.7LPM = 100%Heating valve opening amount of room 2 (HVo2 ') = 3.7LPM / Q2' = 3.7LPM / 3.7LPM = 100%
방3의 난방밸브개도량(HVo3') = 3.7LPM/Q3' = 3.7LPM/4.6LPM ≒ 80%Heating valve opening amount of room 3 (HVo3 ') = 3.7LPM / Q3' = 3.7LPM / 4.6LPM ≒ 80%
방4의 난방밸브개도량(HVo4') = 3.7LPM/Q4' = 3.7LPM/6.1LPM ≒ 61%이므로,Since the heating valve opening amount of room 4 (HVo4 ') = 3.7LPM / Q4' = 3.7LPM / 6.1LPM ≒ 61%,
각 방의 보정난방시간1동안 방2(ro2)의 난방밸브개도량(HVo2') 100%로 난방밸브(v2)를 완전 개방한 상태에서 방3(ro3)의 난방밸브개도량(HVo3') 80%, 방4(ro4)의 난방밸브개도량(HVo4') 61%로 각 난방밸브(v3,v4)를 개방하도록 제어하게 된다.Heating valve opening amount (HVo3 ') of room 3 (ro3) with the heating valve (v2) fully open at 100% heating valve opening amount (HVo2') of room 2 during the corrected heating time 1 of each room. %, The heating valve opening amount HVo4 'of room 4 (ro4) 61% to control the opening of each heating valve (v3, v4).
5. 이어서, 방2(ro2)의 난방시간이 종료되었다고 가정하면, 5. Then, assuming that the heating time of room 2 (ro2) has ended,
방2의 난방밸브(v2)가 닫히게 되고, 방2에 공급되던 난방유량은 방3,4에 공급되므로 난방유량을 재보정하게 된다.The heating valve v2 of the room 2 is closed, and the heating flow rate supplied to the room 2 is supplied to the rooms 3 and 4, thereby recalibrating the heating flow rate.
방3,4에 대한 난방유량을 보정하게 되는데, 방3,4의 보정저항 Rm''를 구하면,The heating flowrates for rooms 3 and 4 are corrected.
1/Rm''=1/Rm3+1/Rm4=1/80+1/60≒0.029이므로1 / Rm '' = 1 / Rm3 + 1 / Rm4 = 1/80 + 1/60 ≒ 0.029
Rm'≒34.5m가 되고, Rm '≒ 34.5m,
난방유량Q''=전체양정(V)/보정된 전체저항(R1+Rm'')에서Heating flow rate Q '' = at total head (V) / corrected total resistance (R1 + Rm '')
Q''=800/(30+34.5)m이므로 Q''=12.4LPM이고,Since Q '' = 800 / (30 + 34.5) m, Q '' = 12.4LPM ,
방의 보정양정(Vr'')=전체양정(V)×방의 보정저항(Rm'')/보정된 전체저항(R1+Rm'')의 관계식으로부터 Vr''=800×34.5/64.5=428mbar를 구할 수 있다. Vr '' = 800 x 34.5 / 64.5 = 428 mbar from the relationship between the room's correction head (Vr '') = total head (V) x room's correction resistance (Rm '') and room correction (R1 + Rm ''). You can get it.
또한, 각 방에 동일하게 공급되는 난방수의 보정양정 Vr''=428mbar에 따른 방3,4의 각 난방유량 Q3'', Q4''을 구하면,In addition, when each heating flow rate Q3 '', Q4 '' of the room 3, 4 according to the correction head Vr '' = 428 mbar of the heating water supplied to each room is obtained,
Q3''=Vr''/Rm3=428/80=5.4LPMQ3 '' = Vr '' / Rm3 = 428/80 = 5.4LPM
Q4''=Vr''/Rm4=428/60=7.1LPM이 되고,Q4`` = Vr '' / Rm4 = 428/60 = 7.1LPM,
각 방의 보정난방시간2 = (각 방의 보정난방시간1 - 방2의 난방시간)으로 설정하게 되며,Each room's corrected heating time 2 = (corrected heating time 1-heating time of room 2),
방3의 난방밸브개도량(HVo3'') = 5.4LPM/Q3'' = 5.4LPM/5.4LPM = 100%Heating valve opening amount of room 3 (HVo3``) = 5.4LPM / Q3 '' = 5.4LPM / 5.4LPM = 100%
방4의 난방밸브개도량(HVo4'') = 5.4LPM/Q4'' = 5.4LPM/7.1LPM ≒ 76%Heating valve opening amount of room 4 (HVo4``) = 5.4LPM / Q4 '' = 5.4LPM / 7.1LPM ≒ 76%
결국, 본 발명에서는 각 방의 보정난방시간2동안 방3(ro3)의 난방밸브개도량(HVo3'') 100%로 난방밸브(v3)를 완전 개방한 상태에서 방4(ro4)의 난방밸브개도량(HVo4'') 76%로 제어하게 된다.As a result, in the present invention, the heating valve opening of the room 4 (ro4) is opened while the heating valve v3 is completely opened at 100% of the heating valve opening amount HVo3 '' of the room 3 (ro3) during the corrected heating time 2 of each room. The control (HVo4 '') is controlled at 76%.
6. 이어서, 방3(ro3)의 난방시간이 종료되었다고 가정하면, 6. Next, assuming that the heating time of room 3 (ro3) has ended,
방3의 난방밸브(v3)가 닫히게 되고, 방3에 공급되던 난방유량은 방4에 공급되므로 난방유량을 재보정하게 된다.The heating valve v3 of the room 3 is closed, and the heating flow rate supplied to the room 3 is supplied to the room 4, thereby recalibrating the heating flow rate.
방4에 대한 난방유량을 보정하게 되는데, 방4의 보정저항 Rm'''를 구하면,The heating flow rate for room 4 is corrected. When the correction resistance Rm '' 'of room 4 is obtained,
1/Rm'''=1/Rm4=1/60≒0.017이므로1 / Rm '' '= 1 / Rm4 = 1/60 ≒ 0.017
Rm'≒58.8m가 되고, Rm '≒ 58.8m,
난방유량Q'''=전체양정(V)/보정된 전체저항(R1+Rm'')에서Heating flow Q '' '= at total head (V) / corrected total resistance (R1 + Rm' ')
Q'''=800/(30+58.8)m이므로 Q''=9.0LPM이고,Q '''= 800 / (30 + 58.8) m, so Q''= 9.0LPM ,
방의 보정양정(Vr''')=전체양정(V)×방의 보정저항(Rm''')/보정된 전체저항(R1+Rm''')의 관계식으로부터 Vr'''=800×58.8/88.8=530mbar를 구할 수 있다. Vr '''= 800 × 58.8 / from the relational equation of room's correction head (Vr''') = total head (V) x room's correction resistance (Rm ''') / room's corrected resistance (R1 + Rm''') 88.8 = 530 mbar .
또한, 각 방에 동일하게 공급되는 난방수의 보정양정 Vr'''=530mbar에 따른 방4의 난방유량 Q4'''을 구하면,In addition, when the heating flow Q4 '' 'of room 4 according to the correction head Vr' '' = 530 mbar of the heating water supplied to each room is obtained,
Q4'''=Vr'''/Rm4=530/60=8.8LPM이 되고,Q4 '' '= Vr' '' / Rm4 = 530/60 = 8.8LPM,
방4의 보정난방시간3 = (각 방의 보정난방시간2 - 방3의 난방시간)으로 설정하게 되며,Room 4's corrected heating time 3 = (corrected heating time 2-heating time of room 3),
방4의 난방밸브개도량(HVo4''') = 8.8LPM/Q4''' = 8.8LPM/8.8LPM = 100%이므로, 방4의 보정난방시간3동안 방4(ro4)의 난방밸브개도량(HVo4''') 100%로 제어하게 된다.Heating valve opening amount of room 4 (HVo4 '' ') = 8.8LPM / Q4' '' = 8.8LPM / 8.8LPM = 100%, so the heating valve opening amount of room 4 (ro4) for room 3's corrected heating time 3 (HVo4 '' ') 100% control.
요컨대, 본 발명에서는 각 방의 난방배관길이가 길수록 각 방에 공급되는 난방유량이 반비례하게 되고, 각 방에 공급되는 난방유량에 클수록 각 방의 난방밸브개도량을 작게하여 난방유량에 따라 설정된 난방시간동안 각 방에 공급되는 난방유량합이 동일하도록 각 방에 공급되는 난방유량을 조절하게 되는데, 이를 위하여 각 방(ro1~ro4)의 난방조건에 따라 각 방에 공급되는 난방유량을 산출한 후, 온도측정주기중 난방시간을 난방할 각 방(ro1~ro4)에 공급되는 난방유량에 따라 설정한 다음, 설정된 난방시간동안 각 방에 공급되는 난방유량합이 동일하도록 각 방의 난방밸브에 대한 개도량을 설정하고, 각 방의 난방밸브개도량을 조절하여 각 방에 보정된 난방유량이 공급되도록 제어됨으로써, 각 방에 대한 불필요한 과다난방이나 부족한 난방을 최소화하는 데에 그 기술적 특징이 있다할 것이다.In other words, in the present invention, the longer the heating piping length of each room is inversely proportional to the heating flow rate supplied to each room, and the larger the heating flow rate to each room is, the smaller the valve opening amount of each room is for the heating time set according to the heating flow rate. The heating flow rate supplied to each room is controlled so that the sum of the heating flow rates supplied to each room is equal. For this purpose, after calculating the heating flow rate supplied to each room according to the heating conditions of each room (ro1 to ro4), the temperature During the measurement cycle, the heating time is set according to the heating flow rate supplied to each room to be heated (ro1 ~ ro4), and then the opening amount of each heating valve is set so that the sum of the heating flow rates supplied to each room is the same during the set heating time. By setting and controlling the opening amount of heating valve in each room, it is controlled to supply the corrected heating flow rate to each room, minimizing unnecessary overheating or insufficient heating for each room. It will have its technical features to help.
한편, 본 발명의 다른 실시예에 따르면, 각 방의 난방유량산출단계(S100)에서 4개의 방(ro1~ro4)에 대한 난방수순환에 있어 각종 저항(R1,R2,Rp)과 순환펌프의 양정(V)을 이용하여 각 방의 난방유량을 산출하게 되는데, On the other hand, according to another embodiment of the present invention, in the heating flow calculation step (S100) of each room in the heating water circulation for the four rooms (ro1 ~ ro4) in the various resistances (R1, R2, Rp) and the head of the circulation pump Using (V) to calculate the heating flow rate of each room,
4개의 방(ro1~ro4)의 난방배관길이(Rp1~4)와 보일러의 내부저항과 송환수관의 저항인 R1, 각 방(ro1~ro4)의 밸브, 분배기, 접속구 등에서 발생되는 저항인 R2를 알 수 없는 경우, 난방수의 공급압력(Pi)과, 각 방의 출구측에서 난방수의 회수압력(Po1~Po4)을 측정하여 그 압력차 △P를 산출하거나 또는, 방(ro1~ro4)에 유량계를 설치하여 각 방의 유량값 Q를 산출하게 된다.Heating pipe length (Rp1 ~ 4) of 4 rooms (ro1 ~ ro4), internal resistance of boiler and R1 which is resistance of return water pipe, resistance R2 generated from valve, distributor, connection port etc. of each room (ro1 ~ ro4) If unknown, the supply pressure Pi of the heating water and the recovery pressure Po1 to Po4 of the heating water are measured at the outlet side of each room to calculate the pressure difference ΔP, or to the room ro1 to ro4. A flowmeter is installed to calculate the flow rate value Q for each room.
이때, 난방수의 공급압력(Ps)과 각 방의 회수압력(Pe1~Pe4)에 대한 압력차 △P는 각 방의 난방배관길이(Rp1~4)에 비례하게 되고, 난방유량의 산출시 저항값으 로 대체하게 되고, 각 방의 유량값Q는 상기 각 방의 난방유량 Q로 대체되어 사용된다.At this time, the pressure difference ΔP between the supply pressure Ps of the heating water and the recovery pressures Pe1 to Pe4 of each room is proportional to the heating piping length Rp1 to 4 of each room, and is calculated as a resistance value when calculating the heating flow rate. The flow rate value Q of each room is replaced with the heating flow rate Q of each room and used.
이와 같이, 본 발명의 상세한 설명에서는 구체적인 실시예에 관해 설명하였으나, 이는 본 발명의 범주에서 벗어나지 않는 한도내에서 여러가지 변형이 가능함은 물론이다.As described above, in the detailed description of the present invention, specific embodiments have been described, but various modifications may be made without departing from the scope of the present invention.
그러므로, 본 발명의 실질적인 범위는 상술된 실시예에 의해 한정되어져서는 안되며, 후술하는 청구범위 뿐만 아니라 청구범위와 균등한 구성에 의해 정해져야 함은 당연하다.Therefore, the substantial scope of the present invention should not be limited by the above-described embodiment, but should be defined by the same structure as the claims as well as the claims described below.
도1은 본 발명에 따른 난방밸브개폐에 따른 난방시간보정제어방법을 예시하 는 제어공정도이다.1 is a control process diagram illustrating a heating time compensation control method according to the opening and closing of a heating valve according to the present invention.
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KR101101772B1 (en) * | 2011-08-31 | 2012-01-19 | 주식회사 에코로직 | The heating water flow control system by flow detection |
KR101308915B1 (en) * | 2011-10-13 | 2013-09-23 | 주식회사 경동원 | Method for controlling heating system |
KR101466901B1 (en) * | 2014-02-28 | 2014-12-04 | 주식회사 개운테크노 | Uniform Heating Method and Uniform Room Heating System |
CN109163375A (en) * | 2018-09-11 | 2019-01-08 | 哈尔滨顺易天翔热力技术开发有限公司 | Heat supply the whole network balances self-optimizing control system and method |
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KR100611899B1 (en) | 2005-02-21 | 2006-08-11 | 린나이코리아 주식회사 | Warm circulation water temperature control method and system of each room temperature control system |
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KR101101772B1 (en) * | 2011-08-31 | 2012-01-19 | 주식회사 에코로직 | The heating water flow control system by flow detection |
KR101308915B1 (en) * | 2011-10-13 | 2013-09-23 | 주식회사 경동원 | Method for controlling heating system |
KR101466901B1 (en) * | 2014-02-28 | 2014-12-04 | 주식회사 개운테크노 | Uniform Heating Method and Uniform Room Heating System |
CN109163375A (en) * | 2018-09-11 | 2019-01-08 | 哈尔滨顺易天翔热力技术开发有限公司 | Heat supply the whole network balances self-optimizing control system and method |
CN109163375B (en) * | 2018-09-11 | 2023-09-26 | 哈尔滨顺易天翔热力技术开发有限公司 | Heat supply whole network balance self-optimizing control system and method |
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