JPS6452314U - - Google Patents
Info
- Publication number
- JPS6452314U JPS6452314U JP14852087U JP14852087U JPS6452314U JP S6452314 U JPS6452314 U JP S6452314U JP 14852087 U JP14852087 U JP 14852087U JP 14852087 U JP14852087 U JP 14852087U JP S6452314 U JPS6452314 U JP S6452314U
- Authority
- JP
- Japan
- Prior art keywords
- resistor
- capacitor
- operational amplifier
- inverting input
- pass filter
- Prior art date
- Legal status (The legal status is an assumption and is not a legal conclusion. Google has not performed a legal analysis and makes no representation as to the accuracy of the status listed.)
- Pending
Links
- 239000003990 capacitor Substances 0.000 claims description 17
- 238000010586 diagram Methods 0.000 description 2
Landscapes
- Networks Using Active Elements (AREA)
Description
第１図は本考案の一実施例に係るアクテイブフ
イルタ回路の回路図、第２図は従来例のアクテイ
ブフイルタ回路の回路図である。
１２……非反転入力部、１４……反転入力部、
１６……出力部、１８……演算増幅器、２０……
入力端、２２，２４，３６，４２，４４，４６…
…抵抗、２６，２８，３２，４０……コンデンサ
。
FIG. 1 is a circuit diagram of an active filter circuit according to an embodiment of the present invention, and FIG. 2 is a circuit diagram of a conventional active filter circuit. 12...Non-inverting input section, 14...Inverting input section,
16... Output section, 18... Operational amplifier, 20...
Input end, 22, 24, 36, 42, 44, 46...
...Resistor, 26, 28, 32, 40...Capacitor.
補正 昭６３．１．１２
実用新案登録請求の範囲を次のように補正する
。Amendment January 12, 1986 The scope of claims for utility model registration is amended as follows.
【実用新案登録請求の範囲】
入力電圧をＶｉ、出力電圧をＶｏとした場合、
伝達関数がＶｏ／Ｖｉが、
ＶＯ／Ｖｉ＝Ｈ１ω１ ２Ｓ２＋（ω１／Ｑ１）
Ｓ＋ω１ ２・Ｈ２Ｓ２Ｓ２＋（ω２／Ｑ２）Ｓ＋
ω２ ２
＝Ｈω１ ２Ｓ２Ｓ４＋Ｘ１Ｓ３＋Ｘ２Ｓ２
＋Ｘ３Ｓ＋Ｘ４……(1)
ただしＸ１＝ω１／Ｑ１＋ω２／Ｑ２、
Ｘ２＝ω１ ２＋ω２ ２＋ω１ω２／Ｑ１
Ｑ２、
Ｘ３＝（ω２／Ｑ２）ω１ ２＋（ω１／
Ｑ１）ω２ ２、
Ｘ４＝ω１ ２ω２ ２であり、
また、Ｈ１はローパスフイルタの通過域利得、
Ｈ２は、ハイパスフイルタの通過域利得、ＨはＨ
１とＨ２の積、Ｓはｊωであらわされる角周波数
、Ｑ１はローパスフイルタの尖鋭度、Ｑ２はハイ
パスフイルタの尖鋭度、ω１はローパスフイルタ
のカツトオフ角周波数、ω２はハイパスフイルタ
のカツトオフ角周波数であらわされる特性を実現
するアクテイブフイルタ回路であつて、
非反転入力部、反転入力部および出力部を有す
る演算増幅器を用い、入力端と演算増幅器の非反
転入力部との間に第１抵抗、第２抵抗、第３コン
デンサおよび第４コンデンサをこの順で直列接続
したものを接続し、第１抵抗と第２抵抗との接続
部と演算増幅器の出力部との間に第１コンデンサ
を接続し、第３コンデンサと第４コンデンサとの
接続部と演算増幅器の出力部との間に第３抵抗を
接続し、第２抵抗と第３コンデンサとの接続部と
アースとの間に第２コンデンサを接続し、演算増
幅器の非反転入力部とアースとの間に第４抵抗を
接続し、演算増幅器の反転入力部とアースとの間
に第５抵抗を接続し、演算増幅器の反転入力部と
出力部との間に第６抵抗を接続してなり、
前記第１ないし第４コンデンサの容量をそれぞ
れＣ１〜Ｃ４とし、前記第１抵抗〜第６抵抗のコ
ンダクタンス値（抵抗値の逆数であらわされる値
）をそれぞれｇ１〜ｇ６とおいた場合、当該アク
テイブフイルタ回路の伝達関数Ｖｏ／Ｖｉは次式
であらわされ、
Ｖｏ／Ｖｉ＝ＡＳ２Ｓ４＋Ｂ１Ｓ３＋Ｂ２Ｓ２
＋Ｂ３Ｓ＋Ｂ４……(2)
ただし、
Ａ＝Ｋ（ｇ１ｇ２／Ｃ１Ｃ２）、
Ｂ１＝〔｛（ｇ１＋ｇ２）／Ｃ１＋（ｇ２＋ｇ
３＋ｇ４）／Ｃ２＋（ｇ３＋ｇ４）／Ｃ３＋（ｇ
４＋Ｃ４）｝−Ｋ｛（ｇ３／Ｃ３）＋ｇ２＋ｇ３
）／Ｃ２｝〕、
Ｂ２＝〔（ｇ３ｇ４＋ｇ２ｇ４）／Ｃ２Ｃ４＋
（ｇ２ｇ３＋ｇ２ｇ４）／Ｃ２Ｃ３＋ｇ３ｇ４／
Ｃ３Ｃ４＋（ｇ１ｇ４＋ｇ２ｇ４）／Ｃ１Ｃ４＋
（ｇ１ｇ３＋ｇ１ｇ４＋ｇ２ｇ３＋ｇ２ｇ４）／
Ｃ１Ｃ３＋（ｇ１ｇ２＋ｇ１ｇ３＋ｇ１ｇ４＋ｇ
２ｇ３＋ｇ２ｇ４）／Ｃ１Ｃ２−Ｋ｛ｇ２ｇ３／
Ｃ２Ｃ３＋（ｇ１ｇ３＋ｇ２ｇ３）／Ｃ１Ｃ３＋
（ｇ１ｇ３＋ｇ２ｇ３）／Ｃ１Ｃ２｝、
Ｂ３＝｛（ｇ１ｇ２ｇ３＋ｇ１ｇ２ｇ４）／Ｃ
１Ｃ２Ｃ３＋（ｇ１ｇ２ｇ４＋ｇ１ｇ３ｇ４＋ｇ
２ｇ３ｇ４）／Ｃ１Ｃ２Ｃ４＋（ｇ１ｇ３ｇ４＋
ｇ２ｇ３ｇ４）／Ｃ１Ｃ３Ｃ４＋ｇ２ｇ３ｇ４／
Ｃ２Ｃ３Ｃ４−Ｋ（ｇ１ｇ２ｇ３／Ｃ１Ｃ２Ｃ３
）｝、
Ｂ４＝ｇ１ｇ２ｇ３ｇ４／Ｃ１Ｃ２Ｃ３Ｃ４、
Ｋ＝（ｇ５＋ｇ６）／ｇ６
そして、前記両式(1)(2)の少なくとも分母にお
けるＳの係数を満足するように前記容量およびコ
ンダクタンス値を選定していることを特徴とする
アクテイブフイルタ回路。[Scope of claim for utility model registration] When the input voltage is Vi and the output voltage is Vo,
The transfer function Vo/Vi is VO/Vi=H 1 ω 1 2 S 2 + (ω 1 /Q 1 )
S+ω 1 2・H 2 S 2 S 2 + (ω 2 /Q 2 )S+
ω 2 2 =Hω 1 2 S 2 S 4 +X 1 S 3 +X 2 S 2
+ X 3 S + X 4 ...(1) However , X 1 = ω 1 /Q 1 +ω 2 / Q 2 ,
Q 2 , X 3 = (ω 2 /Q 2 )ω 1 2 + (ω 1 /
Q 1 ) ω 2 2 , X 4 = ω 1 2 ω 2 2 , and H 1 is the passband gain of the low-pass filter,
H2 is the passband gain of the high-pass filter, H is H
1 and H2 , S is the angular frequency expressed as jω, Q1 is the sharpness of the low-pass filter, Q2 is the sharpness of the high-pass filter, ω1 is the cut-off angular frequency of the low-pass filter, and ω2 is the angular frequency of the high-pass filter. This is an active filter circuit that realizes a characteristic expressed by a cutoff angular frequency, and uses an operational amplifier having a non-inverting input part, an inverting input part, and an output part, and has a filter circuit between the input end and the non-inverting input part of the operational amplifier. A first resistor, a second resistor, a third capacitor, and a fourth capacitor connected in series in this order are connected, and the first capacitor is connected between the connection part of the first resistor and the second resistor and the output part of the operational amplifier. A third resistor is connected between the connection between the third capacitor and the fourth capacitor and the output of the operational amplifier, and a third resistor is connected between the connection between the second resistor and the third capacitor and the ground. 2 capacitors are connected, a fourth resistor is connected between the non-inverting input of the operational amplifier and the ground, a fifth resistor is connected between the inverting input of the operational amplifier and the ground, and the inverting input of the operational amplifier is connected. A sixth resistor is connected between the section and the output section, and the capacitances of the first to fourth capacitors are C1 to C4 , respectively, and the conductance values (resistance values) of the first to sixth resistors are When the values expressed by reciprocal numbers are respectively set as g 1 to g 6 , the transfer function Vo/Vi of the active filter circuit is expressed by the following formula, Vo/Vi=AS 2 S 4 +B 1 S 3 +B 2 S 2
+B 3 S+B 4 ...(2) However, A=K(g 1 g 2 /C 1 C 2 ), B 1 = [{(g 1 +g 2 )/C 1 +(g 2 +g
3 + g 4 )/C 2 + (g 3 + g 4 )/C 3 + (g
4 + C4 )}-K{( g3 / C3 )+ g2 + g3
)/C 2 }], B 2 = [(g 3 g 4 +g 2 g 4 )/C 2 C 4 +
(g 2 g 3 +g 2 g 4 )/C 2 C 3 +g 3 g 4 /
C 3 C 4 + (g 1 g 4 + g 2 g 4 )/C 1 C 4 +
(g 1 g 3 +g 1 g 4 +g 2 g 3 +g 2 g 4 )/
C 1 C 3 +(g 1 g 2 +g 1 g 3 +g 1 g 4 +g
2 g 3 +g 2 g 4 )/C 1 C 2 −K{g 2 g 3 /
C 2 C 3 + (g 1 g 3 + g 2 g 3 )/C 1 C 3 +
(g 1 g 3 + g 2 g 3 )/C 1 C 2 }, B 3 = {(g 1 g 2 g 3 + g 1 g 2 g 4 )/C
1 C 2 C 3 + (g 1 g 2 g 4 +g 1 g 3 g 4 +g
2 g 3 g 4 )/C 1 C 2 C 4 + (g 1 g 3 g 4 +
g 2 g 3 g 4 )/C 1 C 3 C 4 +g 2 g 3 g 4 /
C2C3C4 - K ( g1g2g3 / C1C2C3
)}, B 4 = g 1 g 2 g 3 g 4 / C 1 C 2 C 3 C 4 , K = (g 5 + g 6 )/g 6 and at least in the denominator of both formulas (1) and (2) above. An active filter circuit characterized in that the capacitance and conductance values are selected so as to satisfy a coefficient of S.
Claims (1)
伝達関数Ｖｏ／Ｖｉが、 Ｖｏ／Ｖｉ＝Ｈ１ω１ ２Ｓ２＋（ω１／Ｑ１）
Ｓ＋ω１ ２・Ｈ２Ｓ２Ｓ２＋（ω２／Ｑ２）＋ω
２ ２ Ｈω１ ２Ｓ２Ｓ４＋Ｘ１Ｓ３＋Ｘ２Ｓ２＋Ｘ
３Ｓ＋Ｘ４……(1) ただし、Ｘ１＝ω１／Ｑ１＋ω２／Ｑ２、 ×２＝ω１ ２＋ω２ ２＋ω１ω２／Ｑ１
Ｑ２、 Ｘ３＝（ω２／Ｑ２）ω１ ２＋（ω１／
Ｑ１）ω２ ２、 Ｘ４＝ω１ ２ω２ ２であり、 また、Ｈ１はローパスフイルタの通過域利得、
Ｈ２は、ハイパスフイルタの通過域利得、ＨはＨ
１とＨ２の積、Ｓはｊωであらわされる角周波数
、Ｑ１はローパスフイルタの尖鋭度、Ｑ２はハイ
パスフイルタの尖鋭度、ω１はローパスフイルタ
のカツトオフ角周波数、ω２はハイパスフイルタ
のとカツトオフ角周波数であらわされる特性を実
現するアクテイブフイルタ回路であつて、 非反転入力部、反転入力部および出力部を有す
る演算増幅器を用い、入力端と演算増幅器の非反
転入力部との間に第１抵抗、第２抵抗、第３コン
デンサおよび第４コンデンサをこの順で直列接続
したものを接続し、第１抵抗と第２抵抗との接続
部と演算増幅器の出力部との間に第１コンデンサ
を接続し、第３コンデンサと第４コンデンサとの
接続部と演算増幅器の出力部との間に第３抵抗を
接続し、第２抵抗と第３コンデンサとの接続部と
アースとの間に第２コンデンサを接続し、演算増
幅器の非反転入力部とアースとの間に第４抵抗を
接続し、演算増幅器の反転入力部とアースとの間
に第５抵抗を接続し、演算増幅器の反転入力部と
の出力部との間に第６抵抗を接続してなり、 前記第１ないし第４コンデンサの容量をそれぞ
れＣ１〜Ｃ４とし、前記第１抵抗〜第６抵抗のコ
ンダクタンス値（抵抗値の逆数であらわされる値
）をそれぞれｇ１〜ｇ６とおいた場合、当該アク
テイブフイルタ回路の伝達関数Ｖｏ／Ｖｉは次式
であらわされ、 Ｖｏ／Ｖｉ＝ＡＳ２Ｓ４＋Ｂ１Ｓ３＋Ｂ２Ｓ２
＋Ｂ３Ｓ＋Ｂ４……(2) ただし、 Ａ＝Ｋ（ｇ１ｇ２／Ｃ１Ｃ２）、 Ｂ１＝〔｛（ｇ１＋ｇ２）／Ｃ１＋（ｇ２＋ｇ
３＋ｇ４）／Ｃ２＋（ｇ３＋ｇ４）／Ｃ３＋（ｇ
４／Ｃ４）｝−Ｋ｛（ｇ３／Ｃ３）＋（ｇ２＋ｇ
３）／Ｃ２｝〕、 Ｂ２＝〔（ｇ３ｇ４＋ｇ２ｇ４）／Ｃ２Ｃ４＋
（ｇ２ｇ３＋ｇ２ｇ４）／Ｃ２Ｃ３＋ｇ３ｇ４／
Ｃ３Ｃ４＋（ｇ１ｇ４＋ｇ２ｇ４）／Ｃ１Ｃ４＋
（ｇ１ｇ３＋ｇ１ｇ４＋ｇ２ｇ３＋ｇ２ｇ４）／
Ｃ１Ｃ３＋（ｇ１ｇ２＋ｇ１ｇ３＋ｇ１ｇ４＋ｇ
２ｇ３＋ｇ２ｇ４）／Ｃ１Ｃ２―Ｋ｛ｇ２ｇ３／
Ｃ２Ｃ３＋（ｇ１ｇ３＋ｇ２ｇ３）／Ｃ１Ｃ３＋
（ｇ１ｇ３＋ｇ２ｇ３）／Ｃ１Ｃ２｝、 Ｂ３＝｛（ｇ１ｇ２ｇ３＋ｇ１ｇ２ｇ４）／Ｃ
１Ｃ２Ｃ３＋（ｇ１ｇ２ｇ４＋ｇ１ｇ３ｇ４＋ｇ
２ｇ３ｇ４）／Ｃ１Ｃ２Ｃ４＋（ｇ１ｇ３ｇ４＋
ｇ２ｇ３ｇ４）／Ｃ１Ｃ３Ｃ４＋ｇ２ｇ３ｇ４／
Ｃ２Ｃ３Ｃ４−Ｋ（ｇ１ｇ２ｇ３／Ｃ１Ｃ２Ｃ３
）｝、 Ｂ４＝ｇ１ｇ２ｇ３ｇ４／Ｃ１Ｃ２Ｃ３Ｃ４、 Ｋ＝（ｇ５＋ｇ６）／ｇ６ そして、前記両式(1)(2)の少なくとも分母にお
けるＳの係数を満足するように前記容量およびコ
ンダクタンス値を選定していることを特徴とする
アクテイブフイルタ回路。[Scope of claim for utility model registration] When the input voltage is Vi and the output voltage is Vo,
The transfer function Vo/Vi is Vo/Vi=H 1 ω 1 2 S 2 + (ω 1 /Q 1 )
S+ω 1 2・H 2 S 2 S 2 + (ω 2 /Q 2 )+ω
2 2 Hω 1 2 S 2 S 4 +X 1 S 3 +X 2 S 2 +X
3 S+X 4 ...(1) However, X 1 =ω 1 /Q 1 +ω 2 /Q 2 , ×2=ω 1 2 +ω 2 2 +ω 1 ω 2 /Q 1
Q 2 , X 3 = (ω 2 /Q 2 )ω 1 2 + (ω 1 /
Q 1 ) ω 2 2 , X 4 = ω 1 2 ω 2 2 , and H 1 is the passband gain of the low-pass filter,
H2 is the passband gain of the high-pass filter, H is H
1 and H2 , S is the angular frequency expressed as jω, Q1 is the sharpness of the low-pass filter, Q2 is the sharpness of the high-pass filter, ω1 is the cut-off angular frequency of the low-pass filter, and ω2 is the angular frequency of the high-pass filter. This is an active filter circuit that realizes the characteristics expressed by the cut-off angular frequency, and uses an operational amplifier having a non-inverting input part, an inverting input part, and an output part, and has a filter connected between the input terminal and the non-inverting input part of the operational amplifier. A first resistor, a second resistor, a third capacitor, and a fourth capacitor connected in series in this order are connected, and the first resistor is connected between the connection part of the first resistor and the second resistor and the output part of the operational amplifier. A capacitor is connected, a third resistor is connected between the connection between the third capacitor and the fourth capacitor, and the output section of the operational amplifier, and a third resistor is connected between the connection between the second resistor and the third capacitor and the ground. A second capacitor is connected, a fourth resistor is connected between the non-inverting input of the operational amplifier and ground, a fifth resistor is connected between the inverting input of the operational amplifier and ground, and the inverting input of the operational amplifier is connected. A sixth resistor is connected between the input part and the output part, the capacitances of the first to fourth capacitors are respectively C1 to C4 , and the conductance values (resistances) of the first to sixth resistors are The transfer function Vo/Vi of the active filter circuit is expressed by the following formula, Vo/Vi= AS2S4 + B1S3 + B2 . S2
+B 3 S+B 4 ...(2) However, A=K(g 1 g 2 /C 1 C 2 ), B 1 = [{(g 1 +g 2 )/C 1 +(g 2 +g
3 + g 4 )/C 2 + (g 3 + g 4 )/C 3 + (g
4 /C 4 )}-K{(g 3 /C 3 )+(g 2 +g
3 )/C 2 }], B 2 = [(g 3 g 4 + g 2 g 4 )/C 2 C 4 +
(g 2 g 3 +g 2 g 4 )/C 2 C 3 +g 3 g 4 /
C 3 C 4 + (g 1 g 4 + g 2 g 4 )/C 1 C 4 +
(g 1 g 3 +g 1 g 4 +g 2 g 3 +g 2 g 4 )/
C 1 C 3 +(g 1 g 2 +g 1 g 3 +g 1 g 4 +g
2 g 3 +g 2 g 4 )/C 1 C 2 -K{g 2 g 3 /
C 2 C 3 + (g 1 g 3 + g 2 g 3 )/C 1 C 3 +
(g 1 g 3 + g 2 g 3 )/C 1 C 2 }, B 3 = {(g 1 g 2 g 3 + g 1 g 2 g 4 )/C
1 C 2 C 3 + (g 1 g 2 g 4 +g 1 g 3 g 4 +g
2 g 3 g 4 )/C 1 C 2 C 4 + (g 1 g 3 g 4 +
g 2 g 3 g 4 )/C 1 C 3 C 4 +g 2 g 3 g 4 /
C2C3C4 - K ( g1g2g3 / C1C2C3
)}, B 4 = g 1 g 2 g 3 g 4 / C 1 C 2 C 3 C 4 , K = (g 5 + g 6 )/g 6 and at least in the denominator of both formulas (1) and (2) above. An active filter circuit characterized in that the capacitance and conductance values are selected so as to satisfy a coefficient of S.
Priority Applications (1)
| Application Number | Priority Date | Filing Date | Title |
|---|---|---|---|
| JP14852087U JPS6452314U (en) | 1987-09-28 | 1987-09-28 |
Applications Claiming Priority (1)
| Application Number | Priority Date | Filing Date | Title |
|---|---|---|---|
| JP14852087U JPS6452314U (en) | 1987-09-28 | 1987-09-28 |
Publications (1)
| Publication Number | Publication Date |
|---|---|
| JPS6452314U true JPS6452314U (en) | 1989-03-31 |
Family
ID=31419913
Family Applications (1)
| Application Number | Title | Priority Date | Filing Date |
|---|---|---|---|
| JP14852087U Pending JPS6452314U (en) | 1987-09-28 | 1987-09-28 |
Country Status (1)
| Country | Link |
|---|---|
| JP (1) | JPS6452314U (en) |
-
1987
- 1987-09-28 JP JP14852087U patent/JPS6452314U/ja active Pending
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