JPS63220791A - High speed motor - Google Patents

Abstract

PURPOSE:To rotate a motor in high speed, by a method wherein a magnet rotor is constituted so as to be an inner rotor type while a position detecting signal is processed by a logical operation circuit to provide it with the width of 90 degrees in electric angle from a starting point. CONSTITUTION:In the conduction control circuit of an armature coil 2, the output of a Hall element 10, conducted by a DC power source positive pole 31, is amplified by an operational amplifier 42a, an induction coil 11a obtains an induction output opposing to a magnetic pole and the induction output becomes the differentiated output of a curve of the magnetic field of a magnetic rotor, therefore, a phase difference becomes 90 degrees. Accordingly, a positional difference between the Hall element 10a and the coil 11a is set so as to be 180 degrees whereby the induction output of the coil 11a may be advanced by 90 degrees. The output of the coil 11a is amplified and shaped into rectangular waves by the operational amplifier 42b and is rectified and smoothed by a diode condenser 43, therefore, an output, proportional to a rotating speed, may be obtained from a terminal 30. According to this method, the rise-up of armature current is improved and the generation of a counter torque is eliminated, whereby the output may be increased.

Description

Detailed Description of the Invention (Industrial Field of Application) The drive source of the polygon mirror of the Goreza Beam, the drive source of the drill of the drill machine, etc., rotates at a speed of -0000 to 9000 times per minute.
00,000 rpm) is required.

It is used for the purpose of obtaining the above-mentioned electric motor.

(Prior art) Direct current motors theoretically have difficulties in rotating at high speeds, so an induction motor is used and an inverter is used to
qoo Cyfulle generates an alternating current of about 5 kilocycles, and uses this power source to obtain a high-speed electric motor.

c) Problems to be Solved by the Present Invention] In the case of an induction motor using an inverter and a high frequency, there are the following problems.

First, the power source is large and expensive.

Second, the rotor diameter of the induction motor is set small, resulting in an elongated shape. Therefore, installing the three-phase field winding requires a lot of effort, which increases the price.

No. 7K, the output of the induction motor is a small output, so
It becomes less efficient.

[Means for solving problems]

Since the present invention is a DC motor, it suffers from the drawbacks of induction motors, namely the first and second points mentioned above. The third problem is all solved.

In addition, high-speed rotation is made possible by adopting a new means for controlling the energization of the armature coil.

First, since the control circuit is made of semiconductor, it can rotate at high speed.

Secondly, the position detection signal is generally 1) 0 degrees to l in electrical angle.
-0 degrees, but this is set as 90 degrees.

Third, the stored magnetic energy in the armature coil is returned to the power source for rapid dissipation.

There is.

Second, since the position detection signal is processed by a logic circuit and has a width of 90 degrees in electrical angle from the starting point, it prevents the start of energization from being delayed due to the inductance of the armature coil, and also prevents accumulation. High speed rotation is achieved by preventing the generation of counter torque due to magnetic energy.

Thirdly, the applied voltage is increased to increase the rate of rise of the armature current, and the stored magnetic energy is rapidly dissipated by this voltage, so the torque increases and counter torque is generated. Therefore, high-speed rotation can be performed.

〔Example〕

Next, each embodiment will be explained with reference to FIG. 1 and subsequent figures. Components with the same symbols in each drawing represent the same members or the same representations, so duplicate explanations will be omitted.

FIG. 1 is a developed view of a well-known co-phase semiconductor motor, including a magnet rotor l and an armature coil.

All angles shown below shall be in electrical angles.

The magnetic rotor l has 6 magnetic poles: N, S broken pole/4,
16. ... are magnetized and arranged at equal pitches. Arrow G is the direction of rotation.

Armature coils α and −〇 are in phase and terminal Jα.

3b is energized. Furthermore, armature coils b and d are arranged with a phase shift of 90 degrees from the armature coil described above. Electricity is supplied from terminals t4a and qb.

Both armature coil groups constitute a fixed armature, which may have a core or may be coreless.

If we consider that the coil indicated by the dotted line 2g has moved to the position of the armature coil 2d and the coil indicated by the dotted line 2f has moved to the position of the armature coil b, it should be understood that this is a co-phase armature.

The Hall element serving as the position detection element is indicated by the symbol S1゜5b, and is fixed to the armature side at the position shown in the figure, and the pixel element faces each magnetic pole of the magnet rotor l and outputs an output in response to the magnetic field. Explain what you get. From DC power supply positive terminal 3/,
Hall element Ha! rbst is supplied, and a rectangular wave output is obtained from each of the operational amplifiers go 4 and go b. These outputs are shown in the time chart of Fig. 3 by the curve 241), :IA b , @”
The curves λ71°kokub, . . . The phase difference between the two is 90 degrees, and the width of each curve is 1) 0 degrees. In the case of a normal two-phase electric motor, the position detection signal 26
The armature coil is energized by a width of 4, but when the speed becomes high, the rise of the armature current becomes K as shown by the dotted line 26 due to the inductance, and the fall part becomes K as shown by the dotted line 26. Dotted line 21. The energization of the part A results in a counter-torque, which suppresses the increase in speed, which is generally around 3,000 to 1,000 revolutions per minute.

The present invention is characterized in that it solves the above-mentioned problems and provides an electric motor with a rotation speed of 20,000 rotations or more.

The upper inputs of the AND circuit kl eL are the curves 26α, 2A b, . . . , and the lower inputs are the curves 27 a, 2? The curves 29 K, J?
0 'l, , 70 b, . . . and the width is 90 degrees.

The upper input of the AND circuit Slb is as shown in curve 2 in Figure 5.
I, 27b1 '''I lower input is curve 26a.

The curves 2t1.26b, . . . are inverted by an inversion circuit. Kot
b.

...becomes... AND circuit! The output of r/A is curve 3
/a.

...becomes...

AND circuit! //= ,! ;/(Each upper input of L is curved core 4..2 squirrel, . . . and curved core 4
．． Rich b.

The curve 2qi, 29 b, which is the inversion of ...
, each lower input is the curve sb @, J
A b , ... and curves 21' cL, 26 b
, 1. , the curve 218. Hh.

...becomes... AND circuit! rlI? The output of curve 3
132b, . . . And circuit again! The output of rld is a curve 33 CL , . . . .

Transistors lIta, lIgb,...
Armature coil, 14, 2n is the DC power supply positive terminal! It is a transistor bridge circuit that is powered by /.

At the same time as energizing to drive the motor, standard voltage terminal i
A voltage is applied to t and capacitor ! through resistor s; b. r! $ is charged.

Therefore, at the beginning of energization, the AND circuit! ;'I I! , Enter the review by /S
Curve rollers LL, , 2/, b, respectively in Figure S
. . . and curved cores a, , 27 b, .

After a predetermined period of time, the AND circuit, rp rL, y<
Zener diode of c b&j l? The input through is at a low level, and one curve 24g, 751... and the curve λ rises.

Core +6. OR circuit 3 based on the electric signal of...J'
Z,! ;, 3 b's t reference input disappears.

Therefore, the OR circuit "",! ;3 The output of A is curve 3 which is the output of AND circuit S/rL,,j-/b
0m, 3tyb.

...and curve 3/4. ...becomes...

Due to the output of the OR circuit S3, the transistor R is conductive, and the armature coils 2a and 2 are energized to the right.
By the output of the OR circuit sr b, the transistor Rl')
, 4(,f d conducts and the armature coils 4.
is energized in the opposite direction.

Therefore, at the beginning of the drive, the armature coil 24. B is reciprocated and energized at ltO degrees, and then energized at 90 degrees.

AND circuit! r/f! , j/d terminal 3 a,
The energization of armature coils B and d is controlled by the output of 3 coils B by a circuit having exactly the same configuration as the transistor bridge circuit described above, so at the beginning of energization,
In Fig. 3, the curve core υ1 core b, ... is energized to the right by the position detection signal, and the curve! ? 4°29b, . . . energized to the left by the position detection signal.

Therefore, it starts as a well-known co-phase electric motor.

When the rotation speed increases in this state, the dotted line in Figure S shows the waste.
As explained in section h, counter torque is mixed in and there is a limit to the lift.

However, after the set time, the armature coil becomes 90 degrees during energization, so the rise curve of the armature current becomes like the dotted line 301 in FIG. 5, and the fall curve becomes like the dotted line 3o. This is the diode 99a in FIG. 3(g),
This is due to the action of uq b...

If the constants are set so that the width to the saturation point on the right side of the dotted line 3θf is 90 degrees, the dotted line 3θ at the descending part will also be 90 degrees.
It is within 0 degrees and no counter torque is generated. Therefore, the rotational speed increases and the object of the present invention is achieved.

Other position sensing signals? / rL, 31 b,...
The other parts are also energized as shown by dotted lines to prevent the generation of counter torque.

The output torque can be increased by changing the base control of the transistor IIA'h in this embodiment as shown in FIG.

The output of the OR circuit of FIG.
are the armature coils 24. − Connected to the right end of 〇.

When the output of the OR circuit S3 is changed from high level to low level, the capacitor! Due to the voltage B, the conduction of the transistor +txb continues for a set time, so the output torque increases. At this time, a counter torque occurs at the right end of the dotted line 3θh in FIG. 3, but since the current value is small, a large counter torque is not generated.

Exactly the same circuit is attached to transistor y and transistor d. Next, the time chart shown in FIG. 6 will be explained.

In this case, the number of position sensing elements is t. In Figure 1, the Hall element! n,! rg (phase difference of 90 degrees) and Hall elements zcL and sf are fixed to the armature while being shifted to the left by a set angle smaller than 90 degrees from Hall elements j; c and 1g, respectively.

Hall element! e,! d is obtained by the circuit in Fig. g (CC),
Output is obtained from operational amplifiers ss a and sg h,
Their outputs are shown on the curve ζ1. in the time chart of FIG. Misu... and curve 3! ;4,3! b.

..., and their phase difference is made smaller than 90 degrees by a set value.

The outputs of the terminal sq i of the AND circuit j9 are shown as curves 34 m , 74 b , . . . in FIG. 6 .

FIG. 3 (The input of the bow AND circuit 60 is the curve 314°3
ub, ... and curve 3A; 4, ? Jb,
.
It is indicated as S...

The output of the terminal S94 makes the transistors ga and Rh of the transistor bridge circuit of Figure (4) conductive, and the output of the terminal 60'L makes the transistor y of the transistor bridge circuit conductive.
It is configured to make t e and ttg d conductive.

Therefore, the armature coils 2a and Je are energized back and forth.

Although not shown, the outputs of the Hall elements za and sj in FIG. 1 are also amplified by operational amplifiers. The output is shown in the curve 1g 4 , 31 h, ·
. . . and the curve J9, 39 h, . . The output of these position detection signals via the AND circuit is
In FIG. 6, the curve <90 a.

at) b,...

Also, if the position detection signal is inverted by an inverting circuit and used as λ inputs of an AND circuit, its output will be the curve Q/a,...
・It is shown as .

By the same means as in the transistor bridge circuit shown in Fig.
) 4 , u A , ... and the curve qlα, ...
armature coil 2.
b and λd are also energized back and forth. Therefore, it can be operated as a λ-phase electric motor.

At this time, the position detection signal ao a , <to 75
,...

Since there is no point where the output torque due to U/α, . . . becomes zero, self-starting is possible.

Is this the curve UO? , to succeed,..., II/cg
, . . . Since the width is configured to be 90 degrees or more, there is no point of zero torque.

As the rotational speed increases, the armature current in the case of curve 364 in Fig. 1 becomes the dotted line JA! I'm busy like j4, but
As in the previous embodiment, one conduction angle has a width of tgo degrees.

Therefore, there is no generation of counter torque and there is an effect that a high speed electric motor can be obtained.

At this time, the Hall element 3C and jtL are connected to the armature.
The angle at which they are separated is less than 90 degrees, so the width of the position sensing signal is greater than 90 degrees by a set value.

The development diagram shown in Figure 1 is for a three-phase electric motor. The magnet rotor 7 serves as magnetic poles, and is provided with magnetic poles fL, squirrels, . . . of equal width.

The Hall elements /θm, 90b, /θt are fixed to the armature with a distance of ixo degrees from each other, and the induction coil,
//b, //e are also fixed to the armature 1c, and the Hall element ios and the induction coil /1α are separated by /90 degrees. The situation is exactly the same for the other Hall elements 90b, 90e and induction coils //b, //C.

Armature coil g4. gb and 0 are attached to the armature at the positions shown in the figure. Since the armature coil indicated by the dotted line gd has moved to the position of the armature coil fe, the motor is a three-phase motor.

The Hall elements 904, 90b, 90tp and the induction coils //b, //e are opposed to the magnetic pole surface of the magnet rotor to obtain an output.

Since the output of the induction coil is a differential output, the phase difference between the outputs of the Hall element 901 and the induction coil //4 is 90 degrees. Other Hall element IOA and induction coil //b and Hall element 90 /? The situation is the same for the induction coil and the induction coil.

Next, the energization control circuit for armature coils gq, gh, and go will be explained.

In FIG. 7, the output of the Hall element tOa (indicated by the same symbol in FIG. 2), which is energized by the positive electrode 3/ of the DC power supply, is amplified by the operational amplifier, and the output waveform at point A is as shown in FIG. Time chart song 1)! /4t 4,
/41 b , indicated by -.

As shown in the Isλ diagram, the induction coil //a faces the magnetic poles, squirrels, . . . , so that its induction output can be obtained.

The output through the inverting circuit 1) 7n, that is, the electric signal at 8 points, is outputted from the circuit lslda 4. /dab,... is inverted.

The induction output of S (hereinafter referred to as I~7) is a differential output of the curve of the magnetic field of the magnet rotor, so it has a phase difference of 90 degrees.

Therefore, as shown in FIG. 2, by setting the difference in position between the Hall element 90 and the coil //n to 1) 0 degrees,
The induced output of the coil tta can be obtained by advancing the phase of the output of the Hall element IOIK by 90 degrees. Symbol '12 b is an operational amplifier, and the output is a square wave curve / &
Is, /&h,...

The Hall element 904 and the coil //1% are fixed to the main body side facing the magnetic pole face or end face of the magnet rotor 7, but in practice, they are mounted on a printed circuit board on which the electric circuit shown in Figure 7 is installed. Fixed.

For example, as shown in 1), on the plastic substrate 6,
The Hall element IO@ and the coil //1m can be attached at a predetermined distance apart, and then attached on the above-mentioned printed circuit board.

By setting the thickness of the substrate base to a predetermined value, the distance between the Hall element 90@, the coil //4, and the pole end face of the magnet rotor can be adjusted.

In addition, the Hall element 904 and the coil placed on the substrate 6
4 can be manufactured as an integrated chip component, which is an effective means for mass production.

Returning to Figure 1, the output of the coil //1m is amplified and shaped into a rectangular wave by the operational amplifier 02h. In Fig. 9, the electrical signal at point 0 is represented by the curve /! @ , /, 1b,
..., and the curves /41g, /41b
, −@* has a phase lead of 90 degrees.

The output of the coil /l@ is rectified by a diode, smoothed by a capacitor +13, and from the terminal Jθ.

Dotted line symbol 4I, where output is proportional to rotation speed
j eL is a linear amplification circuit. If the output of coil ii is double-wave rectified and output from terminals 1 and b, a speed signal with good characteristics can be obtained.

The electrical signal at point D in Figure 9 is the electrical signal at point C inverted by the inversion circuit 4!7 cL, so the curve /! 1B, l! b, . . . are inverted.

At the beginning of startup, the induced output of the coil //Is is small, so the input signal to one terminal of the operational amplifier is smaller than that of the child terminal (input signal of the standard voltage terminal q4), and the output of the operational amplifier tIS is high. level.

Therefore, the lower power of the AND circuit Q4 @, 94 A via the OR circuit tlq 4 , 1) 1) b is also at a high level.

The output of the AND circuit pam, 41bh, that is, E, F
The electrical signal at point has the same waveform as the electrical signal at points A and B, and the curve lda, /4(b,... and curve /41)m, 741 b, a@@ in Figure 9 is reversed. It becomes what it is.

The transistors a, gb, . . . form a transistor bridge circuit, and the armature coil Z (indicated by the armature coil 1 in FIG. 2) is energized back and forth. The symbol ko l is the positive electrode of the power supply.

The electric signal at point E causes the transistor tI to conduct through the inverting circuit Dak, and the transistor pg b 4
．． Conductivity occurs due to the electrical signal at point E. That is, since the transistors located diagonally are conductive, the armature coil Z
is energized only in an area of 730 electrical degrees to the right.

1) When the magnet rotor rotates 0 degrees, the electric signal at point F causes transistors 1 and e to conduct through the inverting circuit ay b, and the output from point F causes transistor q to conduct.
g d conducts. Armature coil Z is tgo in electrical angle
The magnet rotor is energized back and forth every time the magnet rotor rotates.

After a set time, i.e. when the rotational speed increases, the coil ll
The rumored output also increases, and the input signal of one terminal of operational amplifier q5 becomes larger than that of the child terminal, so operational amplifier lIj
The output becomes low level.

Therefore, the electrical signal at point 0 (curve in Figure 1/, ta).

izb, .

The electrical signal at point E of the AND circuit lIhg is the curve tts in Figure 4. /A b , . . . and their width is 90 degrees. Further, the electric signal at point F of the AND circuit Q&b becomes the curve /r Is , .

Therefore, the armature coil Z (za α) is energized back and forth, but the energization ends at the initial 90 degrees, so the dotted line /? 4./? b and curve /9 L'L, /
It has a shape of 9b. The dotted line /'l b, /9 b is
The stored magnetic energy in the armature coil is transferred to the diode tl?
scratch.

u? A indicates the current discharged by . Since magnetic energy is circulated to the power source, the current flow ends in a short period of time.

Therefore, as in the previous embodiment, the armature coil is energized at 1
Since the rotation ends during gO degrees and no counter torque is generated, high-speed rotation is possible. Naturally, the resistance, inductance, and applied voltage of the armature coil are set in accordance with the rotation speed.

The base input signal is the curve /C in FIG. 4, the armature current is the dotted line l, /b, and the point 1iB is a counter torque, so no increase in rotational speed can be expected. In addition, if a Y-type connection is used, the base input signal becomes the curve /J, the rise of the armature current becomes the dotted line 1, 7a, and the output torque decreases, and the descending part becomes the point 1m/Jb, producing counter torque at the end. Therefore, an increase in rotational speed cannot be expected.

However, according to the means of the present invention, as described above, there is an effect that a high rotational speed can be obtained.

Regarding the armature coils tb and trn in FIG. 2, the control circuit is configured exactly the same as that in FIG.
, 90e and the position detection signal sum of the coils //b, //e, the same energization control is performed, and the effect is also the same.

The armature coil gh will be explained as an example.

The output of the Hall element ta b corresponds to the curve shown in the figure.

20b,..., and the curve /e@, /jib,...
/J (lags behind by 7 degree phase difference.

The output of coil //b is the curve C/4. kotb, . . . and there is a 90 degree phase difference with the curves 2o4, J6b, .

The outputs of the AND circuits corresponding to the AND circuits at a and abb in FIG.
and curved line 4Im... howl.

The energization curve is the dotted line 2Js, uh and the curve α.

It becomes like Mk, and anti-torque browning is prevented.

As can be seen from the above description, a three-phase electric motor can be obtained, and a semiconductor electric motor with no reaction torque and high output and high speed can be obtained.

Further, at the time of starting, since the current is applied at 1 gO degree, the starting characteristics are good. The same idea can also be used to construct a G-phase electric train.

Next, FIG. 9 will be explained.

In FIG. 9 (@), the symbol 63 indicates the transistors shown in FIG. 7 or 3 (in s, at b, .
It shows a transistor bridge circuit according to...

Terminal 63'l, 6. ? h, 43n,
&J d receives, for example, the outputs of the inverting circuit 1 G , the AND circuit lit b , the AND circuit eb b , and the AND circuit q4 m shown in FIG.

Symbol 66 is a rotary encoder device with a rotating shaft.The output pulses are input to the FG conversion circuit 6S, and the output is taken out as a voltage proportional to the rotation speed.This speed signal is sent to one terminal of the operational amplifier 641. has been entered.

A reference voltage is input to the positive voltage terminal 61) CL VC.

Therefore, until the rotation speed reaches the set value, the L terminal 6 da
Since the output voltage of the FV conversion circuit 65 is lower than the input voltage of the operational amplifier 641, the output of the operational amplifier 641 becomes high level, and the transistor 62 becomes non-conductive.

However, when the rotational speed exceeds the set value, the output of the operational amplifier 6da is inverted and becomes a low level, so the transistor 62 becomes conductive and the resistor 61 is short-circuited.

Due to the above configuration and operation, when starting the electric motor of the present invention,
Since the armature coil is energized via the resistor 61, excessive armature current is prevented from flowing and burning out the armature coil. Also, as the speed increases, the 6 transistors become conductive, so when the applied voltage increases and the speed becomes high, a sufficient armature current can be passed even if a large back electromotive force is generated. be.

The above-mentioned means are necessary for the following reasons. That is,
Since the electric motor of the present invention is operated at high speed 900,000 times, the back electromotive force is large (therefore, it is necessary to apply a high voltage. Also, the rise shown by the curve /4g dotted line /) in the FGA diagram Since it needs to be rapid, a high voltage power supply is required.Also, the dotted line /7 A needs to fall quickly, so it is a high voltage.

This is because, since a high voltage is being applied, a large armature current is passed during low startup speeds, increasing the possibility of burnout. Also, when an overload occurs, the speed will be low, so a burnout accident is inevitable.
At this time, K also has resistance 4. This prevents accidents due to the voltage drop in /.

Figure 1 (use one resistor corresponding to resistor 47,
That is, resistors A/IS and A/b are used and these are short-circuited by transistors 62 @ and 44 b.

Since the speed signal (output voltage of the FV circuit 6j) is lower than the reference voltage of the terminal 67 until the first set speed is reached after startup, the transistor 6 is kept non-conductive.

Furthermore, since the reference voltage at the terminal 6I@ is higher than the voltage at the terminal bta, the transistor 6b is also held non-conductive.

Symbol 67.61 is an operational amplifier.

When the first set speed is exceeded, the six transistors become conductive and the resistor A/@ is short-circuited, so that the voltage applied to the motor increases.

When the speed exceeds the set speed, the output of the operational amplifier 61 becomes
Since the voltage is changed to low level, the transistor 6b becomes conductive, the voltage drop across the resistor 6c 162b disappears, and the power supply voltage is directly applied.

With the above configuration, the applied voltage increases in stages from the time of startup. Therefore, the rotation speed of the motor increases more smoothly than in the case of a slope, and burnout of the armature coil can be prevented.This is an effective means, especially at high speeds.

It is also possible to further increase the number of series resistors A/ 4 , A/ b , . . . and transistors. diode 6
De4, Harujib, when the armature coil is de-energized,
This is to circulate magnetic energy back into the power source and dissipate it.

〔effect〕

As explained in the example, the device of the present invention can be applied to both cored and coreless devices, and in the case of coreless devices, the inductance of the armature coil is small, so higher speeds can be achieved. Can be done.

Since the generation of counter torque is prevented, high speed (coooo
~tooooo) times per minute can be obtained.

If necessary, starting characteristics can be improved, and a speed signal can be obtained to perform speed control.

By adding the device shown in FIG. 2, burnout of the armature coil can be prevented and even higher speed rotation can be obtained.

Brief explanation of the α drawings Figures 1 and 2 are developed views of the magnet rotor and armature coil of the co-phase and three-phase devices of the present invention, and Figure 3 is an explanation of the configuration of the Hall element and induction coil. 4 are time charts of electrical signals for each part of the energization control circuit of the J-phase motor, and FIGS. 3 and 4 are time charts of electrical signals of each part of the energization control circuit of the co-phase motor. Figure 7 shows the energization control circuit diagram of the J-phase motor, Figure 7 shows the energization control circuit diagram of the Co-phase motor, and Figure 9 shows the electrical circuit diagram for adjusting the applied voltage of the motor. .

" m 'b#"" @ / e gu 4. Squirrel..., Ri... Magnet rotor, Ko α, Ko b
,...#"1gb,...armature coil, za,
zh...

, t f , 90 @ , IOA , 90 e
, -・I Hall element, /I a , // b ,
/l e-...Induction carp A/, A, one board, l co, l co @, pass, , 13, /3
Is, ..., / da kan, lq b, ・
....

/! r @ , 1g b , ・e , /A Is
, /rub, s-, 1qtx, i'ib.

..., it 4, it b, ..., tq 8
．． lq b, ..., niq.

2oA *, -, Ko/ @, J/ b, ・I
, 228, ! jb,ug.

JJ b, ..., review, Kot
, b, ..., n Is, a
b...

Electrical signal curves of each part of the control circuit in Figure 7,
Ko To, ..., -7 cheer, Koku b,
..., Koga, Kogb.

..., Ko9a, Ko? b, a-@
, 30 m, 30 b,
・ 、 、? /8.

3/ h,..., 3 pieces 1.3 pieces b,..., 33
1! , ,7. ? H...

3 daba, ye b,..., 3! 4. J.J.
b,...,3&@,3bh.

..., ,7? 4, J7 h,..., 3zaex, 3r b,..., 3wo1゜39b,...
-, tt-o@, yoh,..., &/G,...
・Electrical signal curves of each part of the control circuit in Figure g, '12
LLQ2' * 3rd, IOs, RIOA,! ;g
喀, sgh... operational amplifier, Hachiko, qdab, 53
喀, 53b fist...or circuit, 4161B, da' b*
! / ”, j/ h, ..., kid,! Da 6.!
Da b, 39.60...AND circuit, tua, governs...

Claims (6)

[Claims] (1) In a multi-phase DC motor with a magnetic rotor, the electrical angle corresponding to each phase is 18
In order to energize the plurality of position detection elements that obtain the first position detection signal with a width of 0 degrees and the armature coils of each phase in the positive direction, approximately In order to energize the logic circuit that outputs the second position detection signal with a width of 90 degrees and the armature coils of each phase in the opposite direction, a width of approximately 90 degrees in electrical angle from the starting end of the first position detection signal is applied. So, the second
A logic circuit that outputs a third position detection signal that is 180 degrees apart in electrical angle from the position detection signal, and the second and third position detection signals reciprocate and energize the armature coils of each corresponding phase. It consists of multiple sets of transistor bridge circuits that cause the armature current to flow, and diodes that are connected in reverse in parallel to the transistors of the transistor bridge circuit so that the stored magnetic energy is returned to the power supply when the armature current is cut off. Features a high-speed electric motor. (2) In the claim set forth in paragraph (1), two Hall elements are fixed at a predetermined position of a fixed armature, are sensitive to the magnetic field of a magnet rotor, and are separated from each other by 90 electrical degrees. , the second and third phases of two phases are generated by the output of the Hall element.
A two-phase high-speed electric motor characterized by comprising a logic circuit for obtaining a position detection signal. (3) In the claim set forth in paragraph (1), the fixed armature is fixed at a predetermined position in correspondence to each phase, is sensitive to the magnetic field of the magnet rotor, and is 90 degrees electrical angle from each other. A two-phase high-speed electric motor characterized in that it is configured with two sets of position detecting elements each of which generates a two-phase first position detecting signal having a phase difference by an angle smaller than the preset angle. . (4) In the claim set forth in item (1), the fixed armature is fixed at a predetermined position corresponding to each phase, is sensitive to the magnetic field of the magnet rotor, and is approximately 90 degrees electrical angle from each other. What is claimed is: 1. A multi-phase high-speed electric motor, characterized in that the motor generates a first position detection signal having a phase difference of 100 degrees, and is comprised of a plurality of sets of position detection elements each consisting of a Hall element and an induction coil. (5) A multi-phase high-speed motor according to claim (4), characterized in that an electric circuit for rectifying and smoothing the output of the induction coil to obtain a speed signal is provided. (6) In the scope of the claim set forth in paragraph (1), the energization of the transistor bridge circuit by the second and third position detection signals is held inactive only during the set time at startup, and the 1. A high-speed electric motor comprising a control circuit that energizes a transistor bridge circuit using a position detection signal.