JPS62135963A - Electronic equipment - Google Patents

Abstract

PURPOSE:To easily confirm input data while eyes stare at the cursor position by displaying alphabetical input data before converting the KANA (Japanese syllabary) character from a key input means at a cursor position by a half pitch and displaying a character after converting to the cursor position with the whole width for KANA character conversion. CONSTITUTION:When the alphabet is inputted from a key input means 10 by pressing down an alphabetical character key, the alphabet is displayed at a displaying device 30, and at such a time, the character composed of the alphabetical string is displayed as a half width character. On the other hand, when the character is converted to the KANA character, the character after conversion is displayed with a whole width.

Description

DETAILED DESCRIPTION OF THE INVENTION [Industrial Field of Application] The present invention relates to an electronic device that executes Roman to Kana conversion processing in response to alphabetic key input from a key input means.

[Prior Art] Conventionally, when converting input alphabetic character key data into Romaji-kana in this type of electronic equipment such as a personal computer or a Japanese word processor, input alpha-het characters are used until converted to Kana. is not displayed at all, or is displayed not at the cursor position where the input data is displayed, but at a fixed display position away from the cursor position, such as at the bottom of the display screen.

[Problems to be Solved by the Invention] In the above case, since the input key data is not displayed at all, it is impossible to confirm that it is a human key, and a feeling of anxiety about the input cannot be avoided.

In addition, in the latter case, the display position of the input key data is moved from the cursor position, so you have to move your eyes violently to check the input data, which not only causes fatigue, but also causes fatigue. There was a problem in that it was not favorable in terms of operational efficiency.

[Means for Solving the Problems] The present invention has been made in view of the above-mentioned problems, and as a means for solving the above-mentioned problems, the present embodiment includes, for example, a key input means having alphabetic keys. , a display means for displaying information from the key input means, a conversion means for converting Roman character input data from the alphabetic keys of the input means into kana character data, and kana conversion by the conversion means of the key input characters. Move the cursor to display the previous Oxilactor 'L+
, ' /iI · Display means for displaying alphabetic characters at a pitch of 2゛P (half width).

[Operation] With the above configuration, the alpha head input data from the key input means before kana character conversion is displayed at the cursor position with half pitch, and when the kana character is converted, the converted character is displayed at the cursor position in full width. This makes it very easy to check input data while keeping your eyes fixed on the cursor position.

EMBODIMENT OF THE INVENTION An embodiment of the present invention will be described in detail below with reference to the drawings.

[Configuration of Embodiment (Fig. 1)] 'fS1 is a block diagram of an embodiment according to the present invention, in which 10 is a keyboard, and 2o is a microprocessor-type controller that controls the entire embodiment. Department (hereinafter referred to as CPtJ
The CPU 20 includes a sequence control circuit including a clock pulse generation circuit, a delay circuit, a gate circuit, and other logic circuits.

Reference numeral 30 denotes a display stand consisting of a dot matrix type liquid crystal display, which displays and outputs various information (for example, characters input from the keyboard 10) based on a display control signal 31 from the CPU 20.

The display screen of the display device 30 consists of a text display area and a menu display area, and one line at the bottom of the display screen is the menu display area. 40 is a serial type printer,
Based on a print control signal 41 from the CPU 20, output information is printed out on a recording medium. Further, 50 is a RAM for temporarily storing processing information, etc., 60 is a ROM, and 70 is a system bus that connects the CPtJ 20, the RAM 50, and the ROM 60.

The keyboard 10 has "alphanumeric characters" and "r kana" in JIS layout.
key (character key) and rRETURNJ key 11
, rINSJ key, rDELJ key, rHOMEJ key, rESCJ key, rTABJ key, rcTRLJ key, rsHIFT" key, and a "cursor movement" key for moving a cursor displayed and output on a display device. "F" ~ rF as function keys for inputting instructions to execute processing specific to this embodiment.
10J key] 2. An rsTOPJ key 13 is provided for instructing to interrupt the execution of the program currently being executed on the device. An rMODE switch 14 is provided for instructing mode switching between the second mode and the second mode for executing the word processor function.

Further, the RAM 50 is an area for storing the operating status of each component device, and a text memory area 5 for storing character data input from the keyboard 10 and for executing editing processing.
1. A display memory area 52 that stores display data to be displayed on the display device 30; A print memory area 53 that stores print data to be printed out to the printer 40;
and a menu storage area 62 stored in the ROM 60
MCTl, which is a menu counter for selecting the display menu in the menu display wi area of display ¥, position 30
(55), MCT2 (56), EXCT57, etc.

The ROM 60 is connected to the CPU 20 in FIGS.
It is comprised of a program storage area 61 that stores the control procedure shown in the flowchart of D), a menu storage area 62 that stores menu data for the display device 30, a Romanji-kana conversion table 63, and the like.

[Operation of the embodiment (Figs. 2 (A) to (D), Fig. 3)] The operation of this embodiment with the above configuration is shown in Figs. 2 (A) to 3.
This will be explained below with reference to the flowchart in (D) and the key input procedure shown in FIG.

The following explanation will be made in accordance with the key input procedure using the keyboard 10 shown in FIG.

First, as shown in step 1 in Figure tS3 (hereinafter omitted), the keyboard 100r100r switch 14 is set to the second mode for executing the Nippon Rigo word processor function, and the power switch is turned on. When the power is turned on, the CPIJ 20 executes step S1 in FIG. 2(A), and executes initialization processing to clear all contents of the RAM 50. Then, in the next step S2, the (MODE) switch 14 is set to (
1st mode) or (fS2 mode) is detected.

If the mode is set (second mode), the process advances to step S3, and thereafter the word processor program stored in the ROM 60 is executed. First, initial values are set in the display equipment control information storage section in the RAM 50, etc. Here, "1" is placed on two cursor pointers 54, cpx, which stores the X-direction position of the cursor displayed on the display screen of the display device 30, and CPY, which stores the Y-direction position.
” and the first menu counter MCT 1 (
55), MCT2 (56) which is the second menu counter
, "1" is stored in EXCT57, which is a special symbol menu counter. Next, the process proceeds to step S4, in which the contents of the text memory 51 are stored in the text display area of the display memory 52, and in step S5, the command menu instructed by MCT1 (55) in the menu storage area 62 in the ROM 60 is stored in the display memory. 9. Immediately after the power is turned on, no input data is stored in the text memory 51, and "space" is stored in the menu display area of the text memory 52. And in the menu display area, “ of (λ(CTC)55)
1'' is stored. Then, in step S6, the contents of the display memory 52 are displayed on the display device 3o.

The state at the time of execution of step S6 in this procedure 1 is shown in the right column of procedure 1 in FIG. Note that the upper row of the display column shows the display state of the text display area, and the lower row shows the display state of the menu display area. Hereinafter, for each procedure in FIG. 3, the same states at the end of execution of each procedure are shown in the right column.

Then, in the next step S7, it waits for a key on the keyboard 10 to be input.

Now follow step 2 and enter the alphabetic (S) key.
The process advances from step S7 to step S8, and in step S8 it is determined whether or not the 5TOP key 13 is input. Here 5T
Since the input is not OP-i-13, the process proceeds to step S15, and it is checked whether the input is the function keys (Fl key to F5 key) 12 or not. Here too, since there is no input from the function key 12, the process advances to step S35. Step S35
Then, it is checked whether the CTRL key 16 and the 5TOP key 13 are being pressed at the same time, and since the input is an alphabetic key (S key), the process advances from step S35 to step S50.

In step S50, it is determined whether the input is an input from an alphabetic key. Since the input here is an alphabetic character, the process advances to step S52, and the pressed inputted alphabetic key is (
A), (1), (U).

It is checked whether one of the keys (E) and (0) (hereinafter collectively referred to as (vowel keys)) has been input. If these (vowel keys) are not input, the process advances to step S60.

In step S60, it is checked whether a half-pitch character code is already stored at the position indicated by the cursor pointer 54 in the text memory 510.

In this case, since nothing is stored, step S60
The process then proceeds to step S61, where an input is made to the right half of the position indicated by the cursor pointer 54 in the text memory 51, and a half-pitch code for an alphabetic character is stored, and a space code is stored in the left half. In this case, the code "S" is stored. Then, the process returns to step S4, and this text memory 51
The contents are stored in the display memory 52 and displayed on the display device 30. Therefore, the display state at this time is as shown in the right column of step 2.

Next, when the alphabetic character (A) key is input as shown in step 3, the process proceeds from step S7 to step S52 in the same manner as described above, and here the (A) key is input. Therefore, the process advances to step S53. In step S53, it is checked whether or not there is a pre-paid character code at the position currently indicated by the cursor pointer 54 in the text memory 51. Here, since "S" previously input in step 2 is stored, the process advances to step S56, where the half-pitch code stored at the cursor position and the input alphabetic code are combined, and Matching with the data is performed, and the matched kana character code is stored in the text memory 51 at the location indicated by the cursor pointer. In this case, it becomes "SA", which is converted into kana "sa". Then, in step S57, the cursor pointer 54 is incremented by one, and the process returns to step S4.

Naori-Sorbo inter is CPX indicating the X direction (column) address and CP indicating the Y direction (row) address of the display unit 30.
It is composed of Y. If the X direction (column direction) address is the last address in a row, then [CP
X]=1, and [CPY=([CPX+1)].

Here, when the matching in step S56 converts into two kana characters, for example, if "VA" is input, it will be converted to "bua", and if "FA" is input, it will be converted to "fua". If it is necessary to do so, "bu" or "0fu" is stored at the cursor pointer 54 position, the cursor pointer 54 is incremented by one, and "a" is stored at the next position.

If you subsequently input a vowel key such as the (A) key for an alphabetic character, the process advances from step S52 to step S53, and since there is no half-pitch code at the cursor position in step S53, the process advances to step S54.Here, the input character code is not entered. Immediately refer to the Romaji-Kana conversion table 63 and perform matching. For example, if it is a (A) key input,
A” is stored at the cursor pointer position and step S57
and increments the cursor pointer by one.

On the other hand, if the input alphabetic key is the same code as the alphabetic key input immediately before, for example, in step 3, instead of (A), the code will be changed again (
S), step S52. S60
The process then proceeds to step S62, where the text memory 51
Since the input code is the same as the character code at the position indicated by the cursor pointer 54, the process advances to step S63 to check whether the input code is (N). Input code is (N)
If not, a lowercase code "-" is stored at the cursor pointer 54 position of the text memory 51 in step S66, the cursor pointer 54 is incremented by one in step S65, and the process proceeds to step S61. Step S61
Then, the input code, in this case (S), is stored in the right half position of the incremented cursor pointer 54 in the text memory 51, in half-pitch.

Here, if the character code on the cursor and the input character code are both (N), it means that the character code on the cursor that was input earlier was "n", and the process advances from step S63 to step S61. The code for "n" is stored at the position indicated by the cursor pointer 54 in the text memory 51, that is, the location where "N" is stored in half pitch, and the process advances to step S65.

Further, if there is an already paid character code on the cursor and the next character code input is neither the (@ sound) key nor the same key, the process advances from step S62 to step S70, and the cursor pointer 54 position of the text memory 51 is Check whether two half-pitch codes are already displayed, and select 1.
If only one is displayed, in step S71, the code on the right half of the text memory 51 at the cursor pointer 54 position is moved to the left half, the current input code is stored in the right half, and the process returns to step S4.

If two character codes are already displayed at the position indicated by the cursor pointer 54 in step S70, it is an input error, and the operator is notified of the input error in step S72 and the process returns to step S4. This notification may be made by, for example, not using a buzzer or the like.

After executing step 3, press the 5TOP key 13 as in step 4.
If you press and input, step S7 to step S8
, and since this is the input of the 5TOP key 13, the process advances from step S8 to step S9, and MCT1 (55)
Increment the contents by one. Then, in the following step S10, it is checked whether the content of MCT1 (55) is "5" or not. If it is not "5", the process returns to step S4, and if it is "5", MCT1 (55) is set to 1'' in step S11. After doing so, the process returns to step S4.

As a result, what is stored in the display memory 52 in step S5 is MCTl (
55), and if MCTl (55) is “2”, step 4
This is the menu area display data shown in the right column.

Next, in hand 5, function exclusive] 2 (Fl
key) is pressed to input, step S7-38→S15
Then, in step S15, function key 1 is pressed.
Since the input is 2, the process advances to step 316. Step S
16, MCT 1 (55) is “2” and F1
Check whether there is a key input. Here, MCTl (5
Since 5) is "2" and the Fl key is input, the process proceeds to step 818, stores the contents of the text memory 51 in the text display tilt of the display memory 52, and in the subsequent step S19, the menu entry t! λ4CT2 (56) in region 62
The menu (ruled line menu) instructed by is stored in the menu display area of the display memory 52, and in step S20, the contents of the display memory 52 are read out and sent to the display device a30 via the control line 31, and displayed on the display screen. do.

In this embodiment, the ruled line menu when MCT2 (56) is "1" is displayed as shown in the menu display example of step S.

Then, in the following step S21, the next key input is awaited.

When the menu shown in the right column of step 4 is being displayed (when MCTI (55) = 2), if a key other than the F1 key is pressed, [[
Since the input is not MC1]M2 and the F1 key, the process advances to step S17, and the process corresponding to the input function key position is executed.

The menu area is divided into five blocks as shown in the diagram, the F1 key selects "°' ruled lines", the F2 key selects "48 width",
The F3 key is associated with "underline," the F4 key is associated with "tab set," and the F5 key is associated with "reset2." Therefore, if, for example, the F2 key is input in this display state, it indicates that the subsequent input characters will be in the double width mode.

After executing the process in step S17, the process returns to step S4.

Here, F1 is pressed again from the keyboard 10 as shown in hand XI6.
When a key is input, the process proceeds from step S21 to step S22, and since this is an F1 key input of the function key 12, the process proceeds to step S23.In step S23, MCT2 (56) is incremented by one, and in the following step S24, MCT2 (56) is input. ) is "4".

If MCT2 (56) is “4”, step S25
Set MCT2 (56) to “1” and proceed to step S.
1B, and if MCT2 (56) is not "4", the process directly returns to step S18. part, step S1
CT to N of 0] The first menu display by (55) is 4
Three types of second menu display by the MCT2 (56) are stored in the menu storage area 62, and these can be sequentially selected and displayed.

If MCT2 (56) is changed from 1" to "2" and the process returns to step 318, the display menu data stored in the display memory 52 from the menu storage area 62 in step S19 is stored in the menu display column in step 6. This is the display data shown in .

In the display state at the end of step 6, press F2 in step 7.
If the key is input, step S21 is followed by step S.
Proceed to step 22, and since the F1 key is not input here, step S
22, the process proceeds to step S26. In step S26, 5
Check whether the input is from the TOP key 13 or not. Here, the 5TOP key 13 is not input, but the F2 key is input, so the process advances to step S27, where the function key 12 is input.
It is checked whether any of the keys (F2 key to F5 key) has been input. (F2 key to F5 key), the process advances from step S27 to step 328, where the ruled line corresponding to the input key is stored at the position indicated by the cursor pointer 54 in the text memory 51, and in the following step S29, the cursor pointer is Increment 54 and step 3
Return to 1B. In this example, when the F2 key is pressed on the ruled line menu and the input key is not the function key 12, the process returns from step S27 to step S18, and the key input is invalidated.

Next, input the 5TOP key 13 as shown in step 8.
In step S26, the 5TOP key 13 input is detected, and the process returns from step S26 to step S4. Then, in step S5, the menu data in the menu storage area 62 specified by the MCTI (55) is stored in the menu display area of the display memory 52. Since MCT1 (55) is "2" here, the menu display is the same as in step 4, as shown in the right display column of step 8.

Next, in step 9, if you press the CTRL key 16 and the 5TOP key 13 at the same time (press the 5TOP key 13 while the CTRL key 16 is pressed), the process goes to step S35 via steps S7→S8→S15. Proceed to step S35, judgment '1-(CTRL key 16 and 5TO
Since the P key 13 is being pressed at the same time, the process advances to step S36. In step S36, the text memory 5
1 is stored in the text display area of the display memory 52, and in the next step S37, EX of the menu storage area 62 is stored.
The special character menu data instructed by the CT 57 is stored in the menu display ramp of the display memory 52. Then, in the following step S38, the contents of the display memory 52 are displayed on the display device 30, and a key input from the keyboard 10 is awaited in step S39.

The menu displayed when EXCT57 is "1" is the menu shown in the menu display column on the right side of step 9. Get it here!
When the input shown in iio is pressed again (CTRL key 16 and 5TOP key 13 at the same time), the process advances from step S39 to step S40 to step S41.In step S41, the content of EXCT57 is incremented by one, and the following step is performed. As a result of increment in S42, E
Check whether the XCT57 has reached 15 degrees or not, and if it has not reached "5", immediately return to step 336 and set it to "5".
”, in step S43, “1” is stored in EXCT57 and the process returns to step S36. Therefore, in step S3
The menu data read from the menu storage area 62 in step 7 is special character menu data "2", and step 1
Menu data shown in the menu display column in the right column of 0 is displayed on the display device 30. This special character menu screen has four types in this embodiment.

Here, as shown in step 11, press the function key 12 (
When the F5 key is pressed, the process advances from step S39 to step S40, and since it is not (81 inputs with CTRL key 6 and 5 TOP key) 3), the process advances to step S44, where it is checked whether or not only the 5 TOP key 13 is input. . 5TO
If the input is not the P key 13, the process advances to step S45, and it is checked whether the input is the function key 12 or not.

Here, the input is (F5 key) and function key 12, so the process advances from step S45 to step S46, and the special character code located in the position M corresponding to the input function key in the menu display is stored in the text memory. 510 force - store the sol pointer in the 54 position,
In the following step S47, the cursor pointer is incremented by one, and the process returns to step S4. For this reason, the display device 3
In the text display area of 0, "D" specified by the F5 key of the function key 12 is displayed, as shown in the display field on the right column in step 11, and in the menu area, MCT1 (55
) will be displayed.

Also, step 9 of waiting for key input in steps 53B and S39
In the state shown in the right column of (simultaneous input of CTRL key 16 and 5TOP key 13) or function key 12.5T
If a key other than the OP key 13 is input, the process returns from step S45 to step S36, and the input key is invalidated.

Further, if the 5TOP key 13 is input here, the process returns to step S4 without doing anything, and the state shown in the right column of step 8 is set, for example.

When the key is waiting in step S6 and step S7,
Alphabet keys, function keys 12.5 TOP key 13
If a key other than (simultaneous input of CTRL key 16 and 5TOP key 13) is input, step S17→
Proceed to step s5o via S8→S15→S35,
In step S50, there is no alphabetic key input, so step S5
1, the process corresponding to the input key is executed, and the process returns to step S4.

For example, if a cursor movement key is input, the cursor pointer 54 is changed in response to the key input and the cursor is moved to the specified position. ! If the RETURN key 11 is input, cpx of the cursor pointer 54 is set to "1", CPY is incremented by one, and the cursor is placed at the beginning of the next line.

On the other hand, if the MODE switch 14 is set to MODEI when the power of this embodiment is turned on, the process proceeds from step S2 to step 5100, and the processing program created by the user is executed. When one processing unit is completed, the process advances to step 5101, and the 5TOP key 13 on the keyboard 10 is pressed.
Check to see if it has been entered. Here, if 5TOP key]3 has been input, the process proceeds from step 5IO1 to step 5102, interrupts the user program being executed, and returns to step S2. In addition, if the 5TOP key 13 is not input, step 5101 is followed by step 510.
Returns to 0 and executes the next user program process.

Note that, without relying on step 5tot, when a key on the keyboard 10 is pressed and input in the user program, an interrupt is generated and processing for the input is executed, and if the input key is the STOP key 13, Control may be performed to proceed to step 5102.

Therefore, if the MODE switch 14 is changed from the first mode to the second mode before this time, it is possible to interrupt the user program and execute processing such as text input, editing, and storage in the second mode.

1 or less margin 1 [Effects of the Invention As described above, according to the present invention, the alphabet input data from the key input means before kana character conversion is displayed at half pitch at the cursor position 5, and at the point when the kana character conversion is completed. The converted character will be replaced with the half-pitch alphabetic character at the cursor position, so you can easily check the input alphabetic key data, and you can execute and check the Romaji-Kana conversion while keeping your eyes fixed on the cursor pitch. .

Margin less than one -

[Brief explanation of drawings]

Fig. 1 is a block configuration diagram of an actual journey example according to the present invention, Fig. 2 <A) to (D) is an operation flowchart of this embodiment, and Fig. 3 is an operation example in this embodiment and when the operation is executed. FIG. In the figure, 10...Keyboard, 11...RETURN
Key, 12...Function key, 13...5T
OP key, 14...MODE switch, 16...C
TRL key, 20...CPU, 30...Display device,
50...RAM, 51...Test memory, 52...
・Display memory, 53...Print memory, 54...
・Cursor pointer, 55...MCTl, 56...
MCT2.57 ・EX CT, 60-ROM, 61
. . . program area, 62 . . . menu storage area, 63 . . . romaji-kana conversion table. Patent applicant: Canon Co., Ltd. Figure 2 (B) Figure 2 Figure 2 (C) Figure (D)

Claims (2)

[Claims] (1) A key input means having alphabetic keys, a display means for displaying information from the key input means, a conversion means for converting Roman character input data from the alphabetic keys of the key input means into kana character data, An electronic device comprising: an alphabet display means for displaying a character of input characters before kana conversion by the conversion means at a cursor position of the display means. (2) An electronic device according to claim 1, characterized in that the alphabet display means displays characters before ephemeral conversion as half-width characters.