JPS61215583A - Character pattern rotation system - Google Patents

Abstract

(57) [Summary] This bulletin contains application data before electronic filing, so abstract data is not recorded.

Description

[Detailed Description of the Invention] [Field of Application of the Invention] The present invention is a display device or a printing device used as an output device of an electronic computer, in which patterns such as characters and figures are rotated 90 degrees to the left or right and output. Regarding the method of

(Background of the Invention) Conventional character pattern rotation methods are known, for example, from Japanese Patent Application Laid-Open No. 55-1
As shown in Publication No. 23788, when rotating patterns such as characters and figures to the left or right, it is necessary to rotate each character individually or to divide one page into multiple blocks.
Since each block is rotated, there is a drawback that it takes a long time to process one rotation.

[Purpose of the invention]

An object of the present invention is to shorten the time required for one rotation process when a pattern such as a character or figure is rotated by 90'' and output in a display device or a printing device.

The objective is to reduce the amount of buffer memory used for rotation processing.

[Summary of the invention]

The present invention has the following features: 1. For example, when reading and outputting data from a full dot memory in which one page's worth of data is expanded into dots, the wiring of the data is changed once to the high-speed buffer memory, and then the order is changed when reading the data. This rotates the data by 90''.

(Embodiment of the invention) Figures 2 and 3 are diagrams explaining the rotation of character patterns, Figure 2 is the relationship between the full dot memory and the output result when the character pattern is displayed without rotation, and Figure 3 is the diagram explaining the rotation of the character pattern. shows the relationship between full dot memory and output results when rotated and output.
To rotate the pattern, data is developed into dots in an upright state on the full dot memory, and rotation is applied when sending the data to a printer or display device. Hereinafter, a case will be explained in which one word of the full dot memory is composed of 16 bits, and the data expanded into dots in the full dot memory is printed out by rolling or rotating the data.

As shown in FIG. 2, normally, the data 208 developed in the full dot memory 201 in an upright state is printed as is in the N upright state, so one word 202 in the full dot memory 201 has 16 characters in the horizontal direction. The configuration is one bit in the vertical direction. Print data is read from the full dot memory 201.

In order to serialize the data and send it to the printer 204, the traveling direction 205 of the scanning line such as a laser beam of the printer 204 and the memory readout 203 of the full dot memory 201 are in the same direction. In other words, the memory read order 203 of the full dot memory 201 is as follows after reading one line from left to right.
Read the line below from left to right. At this time, since the l word 202 has 16 bits in the horizontal direction, the printer 204
While the printer is performing 16-bit printing, the next data can be read from the memory.Therefore, the print data can be sent to the printer by selecting one bit at a time from this read data with a selector. As a result, the printed pattern 209 is placed on the paper 206 in an upright state with respect to the paper feeding direction 207.
is printed.

Fig. 3 is an explanation of the state in which data 308, which is developed as dots in the full dot memory 301 in an upright state, is rotated 90 degrees from the full dot and printed on the paper 306. In this figure, rotation by 90 degrees to the left is explained as an example. However, the same is true when rotating 90 degrees to the right.

The print data 30 is stored on the full dot memory 301 in the upright position, as in the non-rotating case as explained in FIG.
8 is expanded into dots. On the other hand, printing pattern 3
In order to rotate 09 by 90" to the left and output it, the memory readout order 303 must be set in the running direction 3 of the scanning line of the laser beam, etc.
05, that is, as shown in FIG.

If you read one column from top to bottom and then read one column to the left, the printer 304 prints a print pattern 309 on paper 306 rotated 90 degrees to the left with respect to the paper feed direction 307. Can be printed.

25, the problem is that 1 of the full dot memory 301
Since word 302 has only 1 bit in the vertical direction, only 1 bit is valid as a print dot in one memory access.
It's a bit unbelievable.

The present invention solves this problem as follows.

FIG. 1 shows the basic structure of the present invention.

FIG. 1(a) shows a case where the pattern is printed as it is developed in the full dot memory 101 without rotating it. That is, the data stored in the full dot memory 101 is sequentially read out horizontally in units of one word 102 in the same direction as the running direction 105 of a scanning line such as a printing laser beam of a printer.

The read data is stored in the register and selected by selector 1.
At step 04, the data is narrowed down to 1 bit and sent to the printer.

On the other hand, FIG. 1(b) shows a case where the pattern is printed by rotating it, and from the full dot memory 1.1, the direction 109 of the scanning line of the printer's printing laser beam, etc.
Similarly, the data is written vertically from top to bottom by one word (16
Dot) at a time, register 10 once.
3, the selector 104 selects two dots at a time until the next 16 dots are read out, and writes them into the high-speed rotation buffers 105 and 106.
106 are memories each having a width of 1 bit, and the combined capacity of both is equal to or larger than that of two columns of the full dot memory 101. Prepare two sides of this buffer 1°5.106, 0 side and 1 side.

While writing on one side, the other side is read-only, and after the 16 rask lines have been scanned, the writing and reading sides are swapped. The 0th side and 1st side are switched by the most significant bit of the address of the high-speed rotation buffers 105 and 106. In other words.

The line 108 in FIG. 1(b) is the boundary line of the oWl, i-plane. While data is being written to surface 0, surface 1 is used for reading, but data for 16 rusks has already been written to surface 1. Two dots are read out from one side at a time, and these are narrowed down to one dot by the selector 107 and sent to the printer.

The fourth WI shows how to store and read printed dots in the high-speed rotation buffers 105 and 106 for rotation with the configuration shown in FIG. 1(b).

In FIG. 4, one word is arranged as 102 in a full dot memory 101. In FIG.

The position of this bit is 00, 01, 02.0 from the left.
3. ......As OE and OF, the bit positions of one word below are 10.11, 12.13...
・If IE or IF, high-speed rotation buffer 105.1
When writing to the full dot memory 101, first write to the full dot memory 101.
00,01. ...Write the even bits of OF to 105 and the odd bits to 106. At this time, the two bits in the dotted line shown at 406 are the bits written at once to the high-speed rotation buffers 105 and 106. One word read from the 0th order full dot memory 101 with 10.11.12. ...When writing IF to high-speed rotation bits 105 and 106, write 106 for even bits and 10 for odd bits, contrary to the previous word.
The operation of reversing this write bit is performed by the selector 104 shown in FIG. 1(b). The next word of full dot memory 101 is.

Contrary to the previous word, the even bits are 105. Odd bits are written to 106.

Reading from the high-speed rotation buffers 105 and 106 is performed as follows.0 For example, when reading out the rightmost column in one word sequentially, that is, OF.

When reading in the order of 1F, 2F, 3F, etc.,
As shown by a dotted line 407, by reading out the OF and IF simultaneously and selecting one dot at a time using the selector 107 in FIG. 1(b), the OF and IF can be sent to the printer in that order. Next, all you have to do is read out as shown by the dotted line 408, but in order to read out in this way, consider the eight addresses of the high-speed rotation buffers 105 and 106 as one block (405 in Figure 4 is the block). ),
The last three digits of the address are fixed, and the fourth digit from the bottom is buffer 1.
The inverted value of 05 can be used as the address of the buffer 106. Then, if the bits from the fifth digit or higher from the bottom are sequentially added one by one, the dotted line 407 is followed by the dotted line 4.
Two bits of 08 are read out.

After reading out the rightmost column in one word in the above manner, the next step is to invert the fourth bit from the bottom (of the address of the high-speed rotation buffer memory) and read the fifth and higher bits. After resetting, add l in sequence. In this way, OE, IE.

2E, 3E are read out, and 1 of the full dot memory 101
The second column from the right in the word is now being read. When the reading of the two columns is completed in this manner, the lower three digits of the fixed intra-block address, that is, the address of the high-speed rotation bits 105 and 106, are subtracted by 1. If reading is repeated in the same manner in this state, the full dot memory 101 will be read out one column at a time.

Next, reading from the full dot memory described above,
Writing to the high-speed rotation buffer, 1! An example for realizing the protrusion will be described.

FIG. 5 shows the structure of an address counter for reading data from the full dot memory 101.

The control device has a counter and monitors time in order to know where the laser beam, etc. is located on the scanning line (hereinafter referred to as raster). These are called H counter and B counter. The B counter consists of 4 bits and prints 1
1 is added at the same clock as dots. The H counter is composed of 8 bits, and is incremented by 1 when the B counter overflows. The H counter and B counter are reset at the beginning of every raster. The V counter monitors the position of the raster within one page, is reset at the beginning of the page, and is incremented by 1 at the start of each raster. The J counter consists of 12 bits, is reset at the beginning of the page, and is incremented by 1 for every 16 bits printed. 16 rasters are added as above.

It is reset at the beginning of the 17th raster. The VR counter is composed of 12 bits and operates at the same timing as the V counter, but is decremented by 1. The initial value of the VR counter is loaded at the beginning of the page and is the value that selects the rightmost column of full dot memory 101. As mentioned above, the V counter and VR counter move at the same timing, and 1
If it is something that performs an addition operation when it is not rotating and a subtraction operation when it is rotating, it can be shared by one piece of hardware.

Figure 5(a) shows the full dot memory 10 when not rotating.
This shows the address structure of No. 1. As described above, the H counter is incremented by 1 for every 16 dots, and this becomes the horizontal word address of the full dot memory 101. On the other hand, the V counter is an address in the vertical direction of the full dot memory 101. As a result, the full dot memory 101 is read from left to right every 16 printed dots.

When one raster is completed, the line moves to the line below it and is read out again from left to right.

Figure 5(b) shows the full dot memory 10 when rotating.
This shows the address structure of No. 1. The horizontal address of the full dot memory 101 is determined by the VR counter. The upper 8 bits of the VR counter are used as the horizontal address. As a result, the horizontal address is subtracted by 1 every 16 rusks. Full dot memory 101
The vertical address is determined by the J counter. J counter is 1
1 is added for every 6 dots. As a result, the full dot memory 101 is first read from top to bottom in every 16 dots from the rightmost column, reaching the bottom at the 16th raster, and then reading the 17th raster from the left column again. Read from the top.

Figure 6 shows how the data read from the full dot memory is written to the high-speed buffer in the arrangement shown in Figure 4, read out, serialized into 1-bit data, and sent to the printer. It is.

Data read from full dot memory 101 is once stored in register 801 (corresponding to 103 in FIG. 1). Register 801 has two selectors 804 and 80
5, even bits of register 801 go to selector 804, and odd bits go to selector 805. In the figure, 802 indicates a byte, and 803 indicates a bit. Selectors 804 and 805 each select one bit from the upper three bits of the B counter. In other words, selectors 804 and 8 select the leftmost bit when the B counter (0, 1, 2) bit is 0, and move to the right every time it increases by 1.
The bit selected at 05 enters selector 806. When the least significant bit (B) of the J counter is 0, the selector 806 selects the high-speed buffer 807 (for 105 in FIG. 1).
The input of the selector 804 is connected to the high speed buffer 808
(corresponding to 106 in FIG. 1) is input to selector 805
When the least significant bit (B) of the J counter is 1, the input of 807 becomes the output of 805, and the input of 808 becomes 8.
04 output.

The high-speed buffers 807 and 808 each have 1 bit per word, and the total number of bits combined with the high-speed buffers 807 and 808 should be greater than the number of bits read vertically from the full dot memory 101 for two columns.6 In this embodiment, the high-speed buffers 807,808
are 64 bits each.

The high-speed buffers 807 and 808 each have two addresses at the highest address.
The first half is called the 0th side and the second half is called the 1st side. While the read data from the full dot memory 101 is being written to the 0th side, the data is read from the 1st side and sent to the printer. The roles of the 0th and 1st sides change every 16 rasters.

Writing/reading of high-speed buffers 807 and 808 is performed by a write address register 809 and a read address register 810. The configuration of the write address 809 is such that the most significant bit is the switching bit between the 0th plane and the 1st plane, and the (7) bit of the VR counter is used. lowest 3
The bits are the upper three bits (0, 1, 2) of the B counter, and 1 is added every 2 dots. The rest is called a JD register, and this register is a delay register for the J counter that loads the value of the J counter immediately before the addition when the J counter is incremented by 1. The time during which 16 dots are printed in the JD register is constant. At this time, in parallel, the J counter reads the next data from the full dot memory.

7f, the configuration of the read address register 810 of the speed buffers 807 and 808 is such that the most significant bit is the inverted bit (7) of the VR counter, the next 8 bits are the H counter, and the next 3 bits are the B counter. These are the upper 3 bits (0, 1, 2). 1 is added for every two bits of the top three bits of H and B.

The next 1 bit is the least significant (B) bit of the VR counter for the high speed buffer 807;
, only the middle chain bit of the address is inverted by the inverter 813, and the inverted value of (B) of the VR counter becomes the address. The lowest 3 bits are (8,
9, A) bit. The VR counter is 1 as mentioned above.
Since the bits are subtracted for each rask, the read address 810 as a whole can select bits as described in FIG.

Selectors 811 and 812 are write address register 8
09 and the read address register 810. When the least significant bit (3) of the B counter is 0, the read address register 810 is selected, and when it is 1, the write address register 809 is selected.

The registers 814 are each 1-bit registers that temporarily store the data read from the high-speed buffers 807 and 808, and hold the read data for the time required to print 2 bits. The selector 815 selects one bit from the registers 814 and 817. When the (B) bit of the VR counter is 0, if the (3) bit of the B counter is O, it selects 814, and if it is 1, it selects 817. . When the (B) bit of the VR counter is 1, if the (3) bit of the B counter is O, select 817, and if it is ■, select 814. This allows data to be sent to the printer in the order in which it will be printed. can. Selector 815 also selects another bit when not rotating.

In other words, when the rotation does not occur, when bit (3) of the B counter is O, selector 804 is selected, and when it is 1, selector 804 is selected.
Select 05. As a result, the output of the full dot memory 101 can be sent to the printer without rotation. register 81
6 holds the 1-bit print data selected by the selector 815 for a period of 1 dot, and sends the output to the printer.

〔Effect of the invention〕

According to the present invention, it is possible to significantly reduce the processing time for rotation when a character or pattern is rotated by 90 degrees and output. In addition, the number of bits per word of high-speed rotation buffer memory may be smaller than the number of bits per word of full-dot memory, and there is no high-speed memory that matches the number of bits per word of full-dot memory. To,
There is no need to have unnecessary memory.

[Brief explanation of the drawing]

FIG. 1 is a diagram showing the principle configuration of the present invention, FIGS. 2 and 3 are diagrams explaining pattern rotation, and FIG. 4 is a diagram explaining the principle of writing/reading to and from a high-speed rotation buffer memory according to the present invention. , FIG. 5 is a diagram showing the address structure of a full dot memory, and FIG. 6 is a diagram showing an embodiment of the present invention. 101... Full dot memory, 103... Register, 104, 107... Selector, 105.
106...High speed buffer memory. Fig. τ ((1) When rotating the lung opening (i7) Fig. 3 Fig. 5 (4) ヰI = ω I (ν)

Claims (1)

[Claims] (1) Character pattern expanded into dots in dot memory (
In a method of outputting data after rotating it by 90 degrees (including graphic patterns), a buffer memory is provided to temporarily store the data read from the dot memory, and the data read from the dot memory is rearranged and transferred to the buffer memory. A character pattern rotation method characterized in that character pattern data rotated by 90° of the character pattern data dot-developed in the dot memory is obtained by storing the data stored in the buffer memory, and then reading out the data stored in the buffer memory while changing the address order.