JPS60150484A - Perpetuum mobile - Google Patents

Abstract

PURPOSE:To make semipermanent continuance of kinetic energy attainable, by making centrifugal force use the form of a flywheel to function as internal force to the flywheel and simultaneously forming it functionable as external force which rotates and drives the flywheel in the same direction as its rotating direction. CONSTITUTION:Even when a flywheel D rotates and moves in any position on an orbital circle 8 centering on a center point 14, all these forms are rotation symmetrical form with one another centering on the center point 14, and the flywheel D always naturally generates turning force 2 or centrifugal force and external force to rotate the flywheel D in the same direction as its rotating direction, namely, turning force 22 for a while it conducts its rotational motion in the said rotating direction. With this constitution, reaction 37 is offset to turning force 10 while reaction 15 to turning force 30, respectively, thus since external force will not work on the flywheel D all, the flywheel D theoretically comes possible to do perpetual uniform, rotational motion even if there is not external force, namely, no fuel.

Description

DETAILED DESCRIPTION OF THE INVENTION This invention is a prime mover in which the rotary motion generated by using a limited amount of fuel can last forever even with unburnt wood 121' after the fuel is used. Regarding a certain flywheel.

(Problems with acquisition technology) continues to consume fuel.There is only a limited amount of fuel in the earth, so it is only a matter of time before it runs out.This invention uses a limited amount of fuel to start up. After that, the aim is to create a flywheel that is a prime mover that can maintain kinetic energy semi-permanently by generating its own driving force even without fuel.

(1111 Embodiment) The present invention will be explained based on the drawings as follows.

In FIGS. 2, 3 and 4, the ends of the rotating shaft are supported by firmly fixed bearings E and F. In Figures 1 and 4, bent bodies A and B, which are like bent rods, are objects that are the same or nearly identical to each other; An axis 20 centered on the center point 18 of the circular cross section C of the rotation axis, and passing through the center point 18 in FIG.
Rotationally symmetrical positions of 180° with respect to each other or 180°
The axis of rotation is located at a position close to 00 rotational symmetry and includes a straight line that intersects at right angles to the axis 20 in FIGS. A pair of bending bodies A and B are installed on the top, and one tip of each of bending bodies A and B is fixed to the rotation axis.
The tip portion of each of the other rotational parts 1IlIID which is not fixed to the other rotation member 1IlIID is formed in the shape of a weight. Bearing E
The entire body supported by the bearing F represents the shape of a flywheel with a large moment of inertia that attempts to rotate around the axis 2o, and in this specification, this is referred to as a flywheel G as shown in FIG. It is called.

- (Function) In Fig. 1, the flywheel G starts in the direction of arrow 2 due to the action of an external force, and at the same time, the flywheel G moves far and generates force naturally.For all parts of the flywheel G. The centrifugal force that acts evenly is caused by the arrow shown on the extension of the center line 0 with respect to the force point 23 on the center line 10 in FIG. 1, which intersects at right angles to the axis 20 in FIGS. The force that moves in the direction of 1 and the center I C line I
A force acting on the point of force 24 on O in the direction of the arrow 9 shown on the extension of the centerline 10 and intersecting at right angles to the axis 20 in FIG. 3 and at right angles to the centerline 10 in FIG. Point of force 2 which overlaps the center point J8 in FIG. 1 and is located on the axis 20J2 on
2, there is a force acting in the direction of arrow 5 and a force acting in the direction of arrow 15, etc. shown in ``2, extension line of Nakagami-Gen 1G'', and they act on force point 23, force point 2 = 1, and force point 22. arrow] or arrow 9 or arrow 5 or arrow] 5 from a fly other than
A large number of the decomposed forces exist in or on the flywheel G, and those in the same direction combine to form a resultant force, which causes the flywheel G to rotate. The force that the centrifugal force generated by doing this exerts on all parts of the flywheel G is eventually
And the force in four directions is reduced to arrows 9, 5, 0, and 15.

In Figures 1 and 4, centrifugal force 1 and centrifugal force 9 do not deform or are difficult to deform in response to external force A'1.
Interview flywheel G by i-curved body A and lli-curved body B
Center line 16 within or within the flywheel G'-
-1. ', transmitted to force point 6 and force point 13, center line 1G
The force acting on the force point 6 and force +, ', j 13 in the direction of arrows 7 and 12 perpendicular to j1 which is enlarged and tries to act in the directions of arrows 8 and 11
This results in a rotational force that is a driving force that attempts to rotate the flywheel G in the direction of arrow 2. In iiL, the centrifugal force 1 and the centrifugal force 9 become Ijf acting on the flywheel G as an external force which is a rotational force. On the other hand, the first
The extension line -1 of the center line 16 in Fig. I, and the extension line -1 of the center line 16 in Fig. The arrows 5 and 15 in FIGS. 3 and 4 are the centrifugal forces acting on the flywheel G, respectively, and the centrifugal forces 5 and 15 are Jl, respectively, and the centrifugal forces 15 are relative to the point of force 22 on the center line 16. In this case, the resultant force of centrifugal force 5 and centrifugal force 15 is zero, and centrifugal force 5 and centrifugal force 15 act inwardly on flywheel G. The centrifugal force 5 and the centrifugal force 15 do not need to be used to drive the flywheel G in the direction. So flywheel G or rotating motion in the direction of arrow 2? The reason why it is possible to simultaneously generate the rotational force to drive the flywheel G in the direction of arrow 2 is due to the shape of the flywheel G. Conceivable.

Incidentally, in conventional known flywheels that are not of the present invention, the centrifugal force generated by the rotation of the flywheel acts only inwardly on the flywheel, due to the shape of the flywheel. There is.

The axis line 20 at the first, first and second creases passing through the center point 18 of the cross section C in Figure 1 is inside! The flywheel G is rotated in the orbit 1 and 1 in Figure 1 and 2 in the orbit in Figure 1. As the wheel G moves rotationally, the shape of the flywheel G is shown in FIG. 1 (centered on the center point 18), and in FIG. Therefore, in Fig. 1, the rotational force 8 and the rotational force 1 are continuously applied.
(Niheru.

) 5 Neuwheel G is rotating at a speed 11 much slower than the speed of light, and the phenomenon of mass increasing with speed hardly occurs, so in Figure 1 C flywheel The drag force 3 and the drag force 19 used for continuous u, ', and f'1 for G are the flywheel G.
Rotation II%b D due to the action of the il'i force that is 7・1
is only the frictional resistance received from the bearing 111> and the bearing F, the flywheel Go) quality 1i1, and the moment of inertia 1 of the flywheel G. Even if the angular velocity of the rotational motion performed by the sleeping flywheel G increases, it does not increase beyond a certain limit. Compared to drag force 3 and drag force 19, the flywheel G acting on the flywheel G generates a far-reaching force.
increases in proportion to the square of the angular velocity of rotational motion. Therefore, the centrifugal force 1 and the centrifugal force 9 cause the rotational force 8 and the rotational force 11 that are generated at the time of the rotational movement of the flywheel G to exert a force 3 on the rotational movement of the flywheel G.
When the angular velocity of the flywheel G is accelerated by an external force (the force used when the flywheel G was first started from a stationary state) and the external force is removed, the rotational force becomes the rotational force. 8 and rotational force] 1
The drag force 3 and the drag force 19 against each other are 4 (1
be played a role. Therefore, according to New's first law of motion, as long as there is no change over time such as a change in the shape or weight h1 due to breakage, deformation, or wear of the flywheel G, the flywheel G will remain at a constant constant speed even if no external force is applied. The small part that performs rotational movement becomes O' function. Applying the external force to the 7-71 wheel G under the same conditions as above, and then taking the external force of 11J when the rotational force becomes greater than the drag, then 2...= The second law of 17 movements
Due to l+, the flywheel l-G generates an angular acceleration ((11 rotations) even though no external force nII is applied.Moreover, the rotational force also increases by the square of the angular acceleration. go.

l (Effect of the invention 11 Riko's invention C1 door east σ) The shape is different from the known one-no-one wheel. In addition, there are few difficulties in 10, and when the present invention is in operation, IF is expected to have almost no failures. 1f also has limited 111 when starting up. ``Kana fuel 41 hours...consumption 11) 1] After that, even without fuel, ``1' water cycle -1ν, while exercising l) r Commercially (11 use range of use ( 7J is also an effective means to solve the problems of energy and pollution, which are widely sought after by people; ff 1
”lj ball! - In every place I9i, ``fF can be easily installed'' 10 is also used (11) These things listed in 11 Due to the snow, 4\ Inventions 4 - Humanity and its r
The positive influence on the i-kai is 1.1 unknown.

[Brief explanation of the drawing]

Figure 1 shows -fXll 1. IJ cross-sectional view Figure 2 is 1]
Figure 3 is an elevation view and Figure 4 is 1'1. Between bodies■...-Centrifugal force A ・41i curved body 1) --l"I
'l'l: Axis B... ]111 Bent body 9 ・Centrifugal force
3 Drag force 19... - Drag force procedure amendment (Kanhatsu) Showa Daj I 1 January 4 11 ('1.
1. Indication of tenant works 1981, ] Information Request No. 18998 2. Invention-To-Go) Title 1. Key = = ≠ 4, t #li, +1-instruction with 11 n(+ (, u
11] Details of the invention 1, Name of the invention Centrifugal force motor 2, Claim 1 Flywheel 3 provided with a bent protrusion on the rotating shaft, Detailed description of the invention) This invention performs rotational motion. The shape of the flywheel that naturally generates centrifugal force is 111 centrifugal force 1)
1) so that the centrifugal force acts on the flywheel as an internal force and at the same time acts as an external force as a rotational force to rotate the flywheel in the same direction as the rotational direction of the rotational motion; The flywheel, which is characterized by its unique structure, can not only maintain rotational motion semi-permanently even without fuel after being activated by a small amount of limited fuel energy, but can also maintain rotational motion semi-permanently even without fuel.
This invention relates to a prime mover that is a special flywheel that can also increase rotational kinetic energy. (?+1 next technology) jail '=I(L-'i) Most of the known prime movers currently in practical use depend on fuel for their power source, and 1) II. Freezing prime mover rotation 1 Military energy It continues to consume solvent while it is being generated. There is only a limited amount of fuel on Earth, so it is only a matter of time before it runs out. In conventionally known flywheels, the centrifugal force that is naturally generated by rotational motion acts as an internal force on rc, so rotational motion is performed according to the law of conservation of angular motion. The flywheel has a bearing; "It is constantly subjected to the action of drag, which is the frictional force of motion, from X+X, etc., thereby producing negative angular acceleration." After using a limited amount of J1/a small amount of combustion 44'l to rotate II, not only can the untwisted kinetic energy be maintained semi-permanently, but also the kinetic energy of 1'+il rotation 1i1j can be increased. The first special fly is formed in such a way that JJ simultaneously performs a rotational movement and at the same time converts into rotational force to rotate itself. It is an object of the present invention to provide a centrifugal force motor that is a wheel. (Embodiment) This invention will be explained based on the drawings as follows. The operation of this invention is shown in Fig. 1. It is a plan view of the three-dimensional view shown in FIG. -Ii, (rc is assumed to be an object (same body) with the same shape, volume, and texture. Protrusion with respect to protrusion A) 3 is centered on the center point 14 (axis 14 in Fig. 3) in each phase ri. Rotation of projection A and projection 13 forming a rotationally symmetrical shape of 11'c1800: 111
C 7th. The other 4 parts of the product other than the fixed tip part are a weight 42 and a weight 20, and are formed in a conical shape with a thick weight. The present invention is referred to as a flywheel 1) in the drawings. Kaihosuke Cke1+11
Bearings marked li and 1iii are omitted in the drawings. Figure 3 shows the operation of this invention and the closing of the park, which is similar to Figure 1. Both the projection A and the projection I3 have rotational axes (and the flywheel 1 installed above the axis 14 perpendicularly) of 1lli! ] It represents the shape of a flywheel with a large emotional moment that can be obtained by stable high-speed rotational movement centered on 4. The flywheel 1] is supported by a bearing, but the bearing is omitted in the drawing. Flywheel 1]
is resistant to deformation, wear and tear under the action of any force 4rJ
It is a solid, solid, continuous solid body that does not have any cracks. Flywheel D is entirely made of iron (super strong @A)
It is preferable that the flywheel D is formed of a hard and sturdy metal having a high tensile strength and strong resistance to deformation, such as 1000 .ANG. The inventor of the present invention considers centrifugal force not as a virtual force but as a force that actually acts, and the present invention is constructed based on the concept of centrifugal force as described in rIiI. Figure 4 is an illustration to explain one of the most important principles in constructing this invention (principle of force transmission in a solid body existing in space).
The page is an explanatory text of the illustration. (Function) In Fig. 1, the flywheel I) l rotates around the center point 14 in the directions of arrows 3 and 24 due to the action of external force 9, and at the same time all parts of the flywheel 1) Naturally generates centrifugal force. When the centrifugal force is considered as gravity, the center line 18' passes through the center point 14 corresponding to the center of gravity in the flywheel 1) for the centrifugal force, and the weight 42 1) The resultant vector 1, which is the resultant force of the centrifugal force (parallelogram law of forces) acting on all parts of the centrifugal force, acts on an extension of the center line 18, and at the same time The force II that acts on all parts of the weight 20 with respect to the force point 23, which is the center of mass of the weight 20, on the center line 18 passing through the center point 14 corresponding to the center point 14 in [J]
A resultant vector 21, which is the resultant force of the centrifugal force (parallelogram law of forces), acts on an extension line of the center line 18. The force points 23 are mutually equidistant from the center point 1/I with respect to the center point 40. In other words, the flywheel D performs the rotational movement and at the same time naturally generates a resultant vector 1 to the force point 40 in the weight 12 and a resultant vector 21 to the force point 23 in the weight 20. 1 protrusion for 1 tNA
3 simultaneously attempt to perform a straight motion in opposite directions on the same straight line as the center line 18 with respect to the center points 1 and 1 in phase q with the same propulsion force, which is the same far-reaching force. According to the explanatory text on pages 22 and 23 and the illustration shown in FIG. Working point Il1 point 7 and center point 14 inside and point of action 1 inside protrusion 13
2 If the t-C composite vector 1 is in the same direction as 1 in one row, and the same force is generated by the composite vector I, the same u! 7. The resultant vector 21 generated within the weight 20 is the point of action within the protrusion 1): 32, the center point 1.1, and the protrusion 1).
A force parallel to and in the same direction as the resultant vector 21 is transmitted to the point of action 7 in A at the same time as the resultant vector I.L 21 is generated. The resultant vector 2I is the same sword as the resultant vector 1, and since they occur at the same time, they are vectors that are the same forces in opposite directions that act on the point of action 7, which is the same straight line. 6 and vector I2 simultaneously act on phase q, respectively, and the straight line portion I- of protrusion A'- formed by vector 6 and vector 12.
are all solids and /1116, so the vector (
The resultant force of i and vector 12 is the point of action 7-1. and protrusion A1
- is zero in all of the above-mentioned linear section publications. For vector I7, vector I・ru: 39 is the center/point 111''-
At the center point 14 J, the same forces in opposite directions acting on the same straight line 17 and 9 act on the same line 11 and 'j, so vector 17 and vector : 1 for the resultant force of 5)
．． It becomes zero at the center point 14-. Above center point 14 (
/(In this case, the resultant vector 1 of the centrifugal force is the same in opposite directions on the same straight line with respect to the center point 14 acting on the same straight line as the center line II that intersects the center line 18 at right angles;
The resultant vector 36 of 3 and centrifugal force is its phase 14-
It occurred on 11J1. The resultant force of resultant vector 1 and resultant vector; 36 is zero. Since the resultant vector 21 is simultaneously generated on each phase 11, the point of action; vector 2
8 and vector 3.1 act on each other at the same time, and vector 28 and vector: 3.1 or 1.
Since the straight line part -1- of country 13F is all solid and is expressed as ii:14, the resultant force of the vector 28 and Betaru 3.1 is all of the said straight line part '2' on the point of action 32'2 and the protrusion 5+3. It becomes zero in the part. Point of action 32-j-, 1
51 connecting vector 28 and vector i・le: Slightly away from the straight line formed by 4 in the direction of weight 200) + - bulge +
Point of action 29 on 1L41j
7 is the resultant vector 2 acting on the force point 23 J-
1 is the transmitted force, which is parallel and in the same direction as the resultant vector 2j acting on the force points 2:3, and is the same force. The force of the vector 27 is not transmitted from the partial point 31 on the protrusion 13 to the partial point 33 of the protrusion J (j-) through the broken line 35 drawn in space, which is an extension of the vector 27, and is not transmitted to the point of action 32-J. 2 vector 34 is vector ] Le 2
If 8fZ is canceled by this, the vector: 1 is transmitted through the broken line 26 at the old point 20￥18,
Since there is no force d that cancels out the vector 27, the vector 27 becomes an external force in one direction. Therefore, of course, the resultant vector 21 acting on the force point 23j- within the weight 2° has a 7.1 point in the space.
-C force is not transmitted through line 18, so power point 23-1
-71, no centripetal force that cancels out the resultant vector 21 acts on the resultant vector 21. The resultant vector 211-1 becomes an external force in one direction. Therefore, the centripetal force that cancels out the resultant vector 1 does not act on the resultant vector]/le l that is acting on the force point /j O, , I= in the weight 12, nor does the resultant vector 1. It becomes an external force in one direction. Since the respective I) HE long lines of the composite vector 1 and the composite vector 21 are on the same straight line as the center line 18, the composite vectors (i) which are external forces are (
, the rotational force does not attempt to rotate it in any direction around the axis 14) shown in Figure A3. Since the center line 18 and the broken line 5 form an acute angle 4 with each other, the line 117 is an extension of the composite vector 1.
8 does not intersect with the point of action 7, so rotate the broken line 5 to make the resultant vector 1 which is an external force (point of action 7, which is similar to the fact that no force is acting in any direction at the same time as I'i is generated) A vector 2, which is an external force, is generated at a force point 4Uj- that acts perpendicularly to the broken line 5. Junior high school 7
The line 18 and the broken line 20 each form an acute angle 25 in the phase rj, so the center line 18, which is an extension of the resultant vector 21, is the point of action; At the same time, no force is acting in any direction at the same point of action; an external force is applied at the point of force 231- which acts perpendicularly to the broken line 26, which attempts to rotate the broken line 20 around 32. A vector 22 is generated. The extension lines 19d of vectors 2 and 22 are parallel to each other and do not intersect on the center point 14 with respect to the extension lines 41 indicated by broken lines. Each mutually centered 1%! Since they are the same forces acting simultaneously in opposite directions on 18, the external force vector 2 and the external force vector 22 center the entire flywheel 1) at the center point 14 (in Fig. 3: 1Ili line 1/l). This is a rotational force that attempts to rotate the object in the direction of the arrow 24 around the center. Note that Fig. 2 is a force distribution diagram showing the effects of internal and external forces acting on the entire flywheel 1). /1j11 The part that is not shown d
, is the part () acting as an external force.In the flywheel 1) which is performing rotational movement in the directions of arrows 3 and 2/l in Fig. 1, vector I-1, vector 2, and vector )・ru(5 and vector 12
and vector 10 and vector '9 and vector 37
and vector I3 and vector: U(] and vector 1
5 and vector 17 and vector 30 and vector 34
and vector 28 and vector 27 and vector 22 and vector 2] 1d, since these are forces that occur simultaneously with each other, flywheel 1] is at the middle + lff point 14
(In Fig. 3, rotational movement is performed in one direction shown by arrows 3 and 24 around axis 14, and at the same time, centrifugal force is naturally generated. At the same time, the centrifugal force nil simultaneously moves the flywheel D in the one direction. In other words, it can be said that the flywheel J] is designed to naturally generate rotational force while performing rotational movement in one direction.The flywheel 1) is The reason why it is possible to perform rotational movement in one direction and simultaneously generate rotational force naturally is due to the shape of the flywheel 1). The flywheel 1] moves in the orbit around the center point 14 (axis 14 in Figure 3).
No matter which position on the flywheel (1) it rotates, all of their shapes are rotationally symmetrical in phase q around the center point 14 (axis +4 in Figure 3), so the flywheel 1] While rotating in one direction, the flywheel J constantly generates centrifugal forces such as rotational force 2 and rotational force 22.Although the flywheel J] is rotating at a high speed, it is moving at the speed of light. 1) [f
Ain/Yutai/
According to the special theory of relativity, the natural phenomenon (the mass of an object increases over time in proportion to the speed of motion of the object approaches the speed of light) rarely occurs, so the angular velocity of the flywheel 1) It is considered that the quality h1 of the flywheel 1) does not increase beyond a certain limit +r'5f even if increases, and the amount of shearing 11f'H is considered to not change over time with respect to the change in the angular velocity. On the other hand, the centrifugal force that naturally occurs when the flywheel [) rotates does not change over time and remains constant even if the shape of the flywheel 1) and the radius of the orbit 8 increase. Since it increases in proportion to the increase in the product of the square of the angular velocity and the quality [;:・, it follows that the rotational force 2 and the rotational force 22 also l? As the angular velocity (fl) increases, it will increase proportionally as a change over time. Note that due to the principle of Archimedes' lever, the rotational force 2 and the rotational force 22 become the rotational force 10 and the rotational force 3o, which are magnified by a little more than J times, in the drawing of FIG. 1, resulting in a rotation of 1lal (:
It acts on the point of action of J-, 38 and on the point of action 160. In an attempt to stop the rotational movement of the flywheel 1) in the direction indicated by the arrow 24, 'i:'+
It, 'j ('J point of action at 5°C; anti-crab 37 of 381- and point of action 1 (v1 drag force 15 rotates 'IQ
II The maximum frictional force of the movement due to the bearing against C is ('z-4-7-1 is the maximum frictional force of the forward 1
5 is 1) 1■ Even if the usage of angle notation increases, it is still a flywheel 1)
The moment of inertia and shape of the total bamboo (B is always constant and does not change over time, so it does not increase beyond a certain limit even when the usage + fs increases, and the flywheel 1) The 1liil angular velocity is a constant increasing angular velocity and does not change over time! − to χ・J, rotational force 2 and rotational force 22 are 2 east of the angular velocity and 'I'l'
As the product of II; increases, the rotational force 10 increases proportionally as the product changes over time, so the rotational force 10 becomes a drag force, 37 and 1.
411 The intelligent force that balances It and the rotating force;
) are in phase with the drag force 15! 1. The above angle
'4E l'; L 6 When the external force 9 is removed at the time of input, the anti-crab 37 cancels out each other against the rotational force 10, and at the same time, the rotational force; Since they cancel each other out, this is the same as the fact that no external force is acting on the flywheel I), which exists in a complete vacuum and is rotating in one direction. Therefore, according to the first law of motion of (20, -t), the flywheel 1) can absorb the external force (external force 9's i'r11'l) from the However, the theory is that it performs a perpetual constant rotation motion.The above-mentioned flywheel 1 performs a perpetual uniform rotation motion.
Further apply an external force 9 to the flywheel 1 (continuously accelerate the angular velocity further than the angular velocity in the state of permanent constant rotational motion) and the total 'I'f-f7f of the flywheel 1] 11v exceeding the maximum friction force of anti-crab 37 and drag force 15; when the external force is removed at the time when the rotational force 10 due to force 2 and the rotational crab 30 due to rotational force 22 are generated, the permanent constant velocity Rotation J1
The rotational force due to the rotational force 22 that rotates the flywheel 1) in the direction of the arrow 2/I by further multiplying the flywheel 1) with the 8 motion 'tj<)] ;The rotational force 10 due to the second force 10 on the point of action 16-1- and rotation) is always acting on the point of action 38 at the same time as it performs the permanent uniform rotational motion, that is, it produces angular acceleration. According to the second law of motion, the flywheel 1) is in a state that is equal to
Even when there is no fuel, the angular velocity increases (as the speed increases, the angular motion h1 of the flywheel 1 increases). In addition, the external force from other sources (external force 9 acting on '11) is the same as the centrifugal force in proportion to the product of the square of the increasing angular velocity and the mass l, even without fuel. The rotational force 10 due to the rotational force 2VC having the properties and the rotational force 30 due to the rotational force 22 having the same properties as the far and shi force also increase.In Fig. 1, the total weight of the flywheel D is 10 kg.
Assume that the diameter of the inner orbit 8 is 50+a. It is assumed that the weight 20 and the weight 42 each weigh 2 kg. Using a conventional, well-known motor or prime mover, etc., the centrifugal effects of the centrifugal force, the resultant vector 21, and the centrifugal force, the resultant vector 1, acting on the weights 20 and 42 are so powerful that they are both +000 times greater. It is very easy to accelerate the angular velocity of the wheel. The centrifugal effect is IO (J) At the time of 0 times, the resultant vector 21 acting on the weight 20 is 21, the resultant Petter-Lue acting on the weight 42 is 21, and the rotational force Petter-Lue 22 or the resultant vector 2I If the force is −, I J4+−, then the Beta 1 − force is (]5[, and if it is the − force of vector 2, which is the rotational force, or the resultant vector −, then the first vector 2 is 051. Therefore, zu/[River fish, rotational force 10 of 45t against 38 and rotating crab 30 of 151 against the point of action 1G is generated, but the total smallness 11X of the flywheel 1) is I O/, :91. 11 does not change, so the drag force 15 and the drag force;
t+m. 11 does not change and flywheel D or orbit 8''-
The shape of each of the VCs when rotated and moved is also rotationally symmetrical with respect to the center point 14 (axis 14 in FIG. 3). Therefore, the flywheel 1) is the resultant vector 1 and the resultant vector 2
When the centrifugal effect of 1 reaches I 000 times during rotational movement in the directions of arrows 3 and 24 at I8'', even if the action of the external force from the engine or prime mover is removed, the rotational force 10 is always a drag. ;37 and rotational force 30
The drag force 15 is not only rotating, but also the rotation force 1 () and the rotation force; 3 () exceeds the total quality of the flywheel 1:, 1 and the moment of inertia. (Neaton's second law of motion) allows the flywheel 1 to increase the angular velocity as it changes over time even without fuel. Moreover, it increases in proportion to the product of the square of the angular velocity and the mass, 1.k.
1.・Rotational force 10 and I due to rotational force 2 having the same property and age as force: 3 no L ・Rotational force due to rotational force 22 having +<1: IPr, which is the same as force; 3. The flywheel 1) deforms in response to the action of force, and if it does not break, the angular velocity can be increased without limit even when untwisted > 1. It is also possible to increase the rotating force. (Effects of the Invention) Since this invention is a single flywheel with a very simple structure that differs from conventionally known flywheels in shape, there is little difficulty in manufacturing it, and the invention is easy to use during operation. It is expected that there will be almost no breakdowns or noise during the operation. Moreover, only when starting up No. 1. Only by consuming a small amount of fuel Rf, it is possible to not only perform semi-permanent rotational movement even with 1, no twisting; 1) but also to increase the rotational kinetic energy of iJ rotational movement. Its utility value in industrial applications is extremely large, and it is also an effective means for solving the energy and pollution problems facing humanity. Second, since the present invention does not involve combustion during operation, it also has the advantage of not causing global warming due to the so-called greenhouse effect caused by carbon dioxide. Also, due to its structure, it is extremely convenient that it can be easily installed anywhere on the earth. List of these 1. The positive influence that the present invention will have on humanity and its society due to the fJI pattern etc. is immeasurable. 71 Brief Description of the Drawings Figures 1 and 2 are horizontal views, and Figure 3 is a one-piece view. Figure 4 is an illustration to explain the principle of force transmission in a solid that exists in space. Weight 42 - Weight principle) A weight applied to one solid, amorphous solid IC that does not contain a space, and which shall not be damaged, deformed, or worn out even under the action of any force existing in the space. When an external force 1) acts in a certain direction, at the same time the vector that shows the action of the external force is the external wall i/+i-J of a solid 1 on an extended gentleman in one direction and in the same straight line: The point of force may be 20 1) 11 Solid I at the point of force 6 cm on the outer wall surface of 1 tll + opposite to the outer wall surface.
・]The force is transmitted so that 11 passes through the inside, and at the same time the force point 20 and the force point 0 form a vector]. A vector representing the force transmitted to h is generated throughout the solid-state IC. In Figure 4''2, the number of vectors is limited to avoid complexity. Emphasis 1.2.3.4.5.6.7.8. εl, 10.
II, 12. ]3. +4.15.16.17.18
, 19.20.21,22,2:(271,25,26
, 27, 28, 2930, 31, respectively.
The time when the force is transmitted and the magnitude of the transmitted force are the same as the time when the external force IJ acts on the force point 20VC lI4
3 is engraved, and the force generated at the force point 20 from the action of external force 1) VC is human and lively. The actual size is 1IllJ, hlt, A is 2t:m,,'
Jli separation (゛ba 4 an, ll'l, i separation 11゛ is 1
(The dance distance 11 is l On11., (i is 100 m, However, the sizes are the same.That is, due to the force transmitted through the solid 1. Regardless of the size, the force is drawn in space with velocity and 1/1li111 (l and force without the concept of time 311z). On the other hand, the force transmitted to the force point 26 is not transmitted through the break #i13 to the force point d: (1). ) through the middle 7-
11
1) It is a well-known fact that there is no property that causes the natural phenomenon of movement (f) (weight is universal gravitation, magnetic force), but frost (i-) does not have the property of transmitting the force generated in the solid body. The resultant force of vector A and vector C, which are the same forces in opposite directions, is the zero table. Then, for one solid bone ζ, vector F and vector, C act on the internal force, and the external force 1) becomes 7・J.
At the same time, the vector, A, and the vector, C cancel each other out, so the force of either the vector, A, or d: the vector, C. Only vector, i and vector. The fact that force 1 (i. 6o QZ Tsukino 311 'L'j, l'l' rL, 'l'i'τ-・藺
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・]7 history R+d4/, shij2': to! l'', II nomuichi'L: noe, L'lzu'a noro, supplementary self-answer (principle of force transmission in a solid body existing in space) Action of all forces existing in space An external force 1) acts in the direction of the center of gravity 11 on a solid, amorphous solid body that does not contain any space, and at the same time exhibits the action of external force 1). An extension line in the same direction and on the same straight line as the vector ``2'' passes through the solid 1 from the point of force 20 on the outer wall surface of the solid IC to the point 6 of the outer wall surface opposite the outer wall surface of the solid IC. When the force is transmitted as shown in FIG. occurs throughout the solid. In Figure 4, the number of vectors is limited to avoid confusion. Emphasis 1.2.3, 4.5.6, 7, 8, 9.10.lL
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28.29.30.3+, Noso) 1 The time when the force was transmitted to it and the thickness of the transmitted force It is the same time as the time when the external force I) acts on the force point 2o, and the external force is It is equal to the magnitude of the force generated at the force point 20 by the action. In actual size, distance A is 2α, distance C is 4αn, distance F is] a
m. The distance H is 10co and G is 10a++L. According to the above equation, the forces transmitted to all the force points in the solid IC are mutually transmitted to the same amount H4j, and the magnitude is small. In other words, the force transmitted through a solid 1.] has the concept of velocity, distance, and time, regardless of the temperature and motion of the body 1), volume, quality 111-, shape, and the magnitude of the force. The ζ force that is transmitted to the point of force 31 that is not transmitted passes through the broken line B drawn in space - the force that is not transmitted to the point of force 261, or conversely, the force is transmitted to the point of force 26
The force transmitted to the point 31 is not transmitted to the force point 31 through the broken line B. Transmission of force is carried out through an object (solid), whereas space has the property of causing a natural phenomenon that causes a solid to move (gravity, universal gravitation, magnetic force, etc.). It is a well-known fact that +I'7'i, which means that the force generated in the solid body is transmitted, is 11. - The resultant force of the same force in the opposite direction to the surface line, vector i, l, i, and vector,... becomes zero, and when the solid I...] is 7.1, vector, i, and vector,... are internal forces. At the same time, there is no force acting on the external force 1), and at the same time χ・
The two vectors and C cancel each other in phase 1i/Nime vector, A is a vector, and only the magnetic force of H is a vector, A and vector. C is not transmitted to other vectors parallel to the vector formed by the point of force 21 and point of force 5, which are on the same line 11 as the line 1.

Claims (1)

[Claims] 1 The shape of the flywheel that naturally generates centrifugal force by performing rotational movement is such that the centrifugal force acts on the flywheel as an internal force, and at the same time, the centrifugal force acts in the same direction as the rotational direction of the rotational movement. A flywheel characterized by being formed so as to act as an external force that is a driving force for rotating the flywheel.