JPH04272073A - Elevator system - Google Patents

Abstract

PURPOSE:To provide a clean elevator possible to effectively utilize energy with saving of energy and resource by providing a power converter for converting power of a battery, which accumulates power generated by a solar cell, supplied to a hoist of the elevator. CONSTITUTION:A solar cell 14, reverse current-preventing diode 15 and a battery 16 are provided, and the battery 16 is set to a value possible to compensate induced voltage of a motor. For instance, the value is set to about 283V when the motor has a 200V rated value, and in the solar cell 14, single electromotive force is 4 to 5V in the case of silicone, now when assumed 4, 5V, 63 cells are connected in series to obtain predetermined voltage. A module of containing the solar cell 14 is set up in a roof of a building and on a roof of a house, and the battery 16 is charged with energy generated from the module. An elevator is driven operated by supplying power from this battery 16, and also energy at the time of regeneration is absorbed by this battery 16.

Description

[Detailed description of the invention]

[Purpose of the invention]

0001

BACKGROUND OF THE INVENTION 1. Field of the Invention The present invention relates to an elevator system that does not require commercial power.

0002

2. Description of the Related Art FIG. 5 shows a system configuration diagram of a conventional elevator. 1 is commercial power supply, 2 is diode bridge, 3
is a smoothing capacitor, 4 is a flywheel diode, 5
is a regenerative resistor, 6 is a regenerative power absorption transistor, 7 is an inverter, 8 is a hoisting induction motor, 9 is a speed reducer, 10 is a main sheave, 11 is a deflection sheave, 12 is a counterweight, 13 It's a basket.

[0003] Elevators connect one commercial power source to two diode
After rectifying it with a double bridge and making it smooth DC using the smoothing capacitor 3, it is converted to AC of any voltage and frequency using an inverter device composed of power transistors 7, and then converted into an inductive current of 8 By being supplied to the electric motor, the car is moved and a predetermined operation is performed.

[0004] When the electric motor is running, power is supplied from the inverter to the electric motor in this way, but during regeneration, the induction motor becomes a generator and the regenerated energy is returned to the inverter. - is absorbed into capacitor 3 through the diode bridge in the inverter, and the voltage across this increases. Therefore, when the temperature exceeds a certain level, transistor 6 is turned on, and this regenerated energy is consumed by resistor 5.

[0005] Normally, the counterweight of an elevator is set to a weight that balances the car's rated load by about half, so if the car is heavier than this, power running will occur in the UP mode, and regeneration will be reduced in the DOWN mode. Get into mode. In addition, if the basket is lighter than the counterweight, use DOWN for powering and UP.
It goes into regeneration mode.

[0006] As described above, the operation mode of an elevator generally changes to the power running mode repeatedly depending on the loading of the elevator car. Therefore, if all the passengers who used the elevator returned from the same floor, for example, the passengers who went up once would get down again, so they would give energy once by power running, and that amount would be converted into potential energy. When passengers get off the train again, the energy will be returned to them through regeneration. Therefore, if there were no losses at all, the exchange of energy would be zero when viewed as a whole.

[0007]

[Problem to be solved by the invention] However, in reality, regenerated energy is not used effectively.
As shown in the figure, a regenerative resistor is used to convert heat loss, or in large elevators, a converter is installed in place of diode 2 to regenerate power, but this effect directly affects the amount of electricity. The reality is that it is not reflected.

The present invention aims to provide an independent elevator system that does not require a commercial power source by effectively utilizing regenerated energy and supplying mechanical and electrical losses from the outside. purpose. [Structure of the invention]

[0009]

[Means and operations for solving the problem] In order to achieve the above-mentioned purpose, a battery is provided to store energy for the transfer and reception of energy, and solar cells are used to replenish losses and serve as an energy supply source. By using
No other external power supply is required.

0010

Embodiment FIG. 1 shows an embodiment of the present invention. 14 is a solar cell, 15 is a diode for preventing backflow, and 16 is a battery. The rest is the same as FIG. 5. The battery number 16 is set to a value that can compensate for the induced voltage of the motor, for example, if the motor is rated at 200V. Regarding solar cells, the electromotive force of one solar cell is 4V to 5V in the case of silicon, and if it is now 4.5V, it becomes as follows, and 63 solar cells are connected in series to obtain a predetermined voltage. A module containing 14 solar cells on the roof of a building or house.
The energy generated there will be used to charge 16 batteries. Power is supplied from this battery to drive the elevator, and energy during regeneration is also absorbed by this battery.

As described above, by providing a solar cell and a battery, an elevator system that does not require an external power supply can be realized. This means that the energy
It can be said that we have come close to the ideal situation of using effectively. In addition, since energy is not supplied from outside, the cleaner
It not only improves the clean image of the company, but also contributes to energy and resource conservation. Furthermore, it is possible to create a system that does not affect power consumption even during peak power consumption in the summer, and is not affected by power outages.

[0012] Let us now calculate the cost of this system. 5.5Kw used for general condominiums
In the case of an elevator using a motor, assuming a maximum startup of 180 times/h as the operation mode, one operation is 20 times/hour.
It is assumed that the engine stops for 10 seconds when the door is opened and closed, and to further simplify the calculation, it is assumed that power running and regenerative operation are performed alternately. Then, the energy as shown in Figure 2
Transfers will be made during two operations.

[0013] Power during power running is PF, power during regeneration is P
Now, PF is set to 5.5Kw, which is the same as the motor capacity, and PB is ideally the same value as PF, but realistically it should be the value obtained by multiplying the regeneration efficiency of 7B by the battery charging efficiency of 7BT. do. Then, the average energy required during this power running and regeneration is expressed by equation (1). PF = 5.5Kw, 7B = 0.8, 7BT =
If 0.8, PA = 5.5Kw (1-0.64
)×10/40=0.48 Kw. Therefore, this loss can be supplemented by solar cells. Therefore, one data is 100 solar modules.
Use the data 0 yen/W.

[0014] Calculating from this, the solar cell that can compensate for this loss will cost 480W x 1000 yen = 480,000 yen. On the other hand, in the case of the current system, regenerative power is not used, so in order to supply power for power running, the average PA
= 5.5Kw x 10/40 = 1.375Kw is required and if used for 8 hours a day 1.375Kw x 8 =
It becomes 11Kwh. Current electricity rate is 20 yen/Kwh
That's about it.

[0015] Therefore, 11Kwh x 20 yen = 220 yen per day - 220 yen. Dividing 480,000 yen by 220 yen means that it can be depreciated in 2,182 days (5.97 years) or about 6 years. This is a very rough calculation and only takes into account solar cells, but considering that the efficiency of solar cells will continue to improve and prices will fall, and that the target lifespan of elevators is 17 years, it will become more costly in the future. It is also believed that there will be benefits.

[0016] When driving at night, the battery capacity alone may be insufficient. In this case, as a supplement, a commercial power supply 19 is connected to the battery via 18 contactors and 17 diode rectifiers as shown in FIG.
Another possible method is to charge the battery and simultaneously supply power to the elevator. However, if you limit this to late at night, you can use cheap late-night electricity.

On the other hand, if surplus power is generated by the solar cells during the day, as shown in FIG.
It is also possible to connect 20 converters instead of a bridge and regenerate power to the power supply.

[0018]

[Effects of the invention] As mentioned above, by installing solar cells and batteries in the elevator, it is possible to minimize the external power supply, resulting in effective use of energy by saving energy and resources. We can provide clean elevators that can. It is also thought to be advantageous in terms of cost in the long run. Further benefits are expected to emerge in the future as solar cells become more efficient and cost-reduced, and elevator efficiency improves.

[Brief explanation of the drawing]

FIG. 1 is a circuit diagram showing the configuration of an embodiment of the present invention.

FIG. 2 is a time chart diagram of power transfer in the present invention.

FIG. 3 is a configuration diagram of another embodiment of the present invention.

FIG. 4 is a configuration diagram of another embodiment of the present invention.

FIG. 5 is a circuit diagram of a conventional elevator.

[Explanation of symbols]

1...Commercial power supply 2...Diode bridge 3...Smoothing capacitor 4...
flywheel diode

Claims (1)

[Claims] [Claim 1] A solar cell that generates electricity by receiving sunlight, and a battery that stores the electricity generated by the solar cell.
and a power converter that converts the battery power into power and supplies power to the hoisting machine of the elevator.