JPH04112420U - Door lock switch detection device - Google Patents

Abstract

(57) [Summary] [Purpose] The purpose of this invention is to prevent dark current from flowing to the door lock switch when the ignition switch is turned off in a door lock switch detection device. [Configuration] When the ignition switch is turned off, the ECU
When the door lock switch 5 enters the sleep state, the switching control section 13 turns off the transistor on the side where the door lock switch 1 is switched, and the power to the pull-up resistor 2 or 3 and the door lock switch 1 is cut off. [Effect] Therefore, when the ignition switch is off, a large dark current similar to that when the ignition switch is on can be prevented from flowing through the door lock switch 1.

Description

[Detailed explanation of the idea]

0001

[Industrial application field]

This invention is a door lock switch detection device that detects the state of the door lock switch. Regarding the location.

0002

[Conventional technology]

FIG. 3 is a wiring diagram of a conventional door lock switch detection device.

0003 As shown in FIG. 3, the lock terminal lck and unlock terminal of the door lock switch 1 are The child ulck is connected to the power supply line +B via pull-up resistors 2 and 3, respectively. , the common terminal com is grounded, and the interface circuit (hereinafter referred to as I/F) 4 is connected to the ground. The potential state of the lock terminal lck and unlock terminal ulck is at high level ( EC which is a control unit as a signal of low level (hereinafter referred to as H) or low level (hereinafter referred to as L) It is input to the lock/unlock detection terminals 5a and 5b of U5.

0004 By the way, the ECU 5 normally operates with low current consumption when the ignition switch is turned off. Although it is not shown in Fig. 3, the ECU 5 has a so-called sleep function that has a sleep terminal, and for example, an H signal is sent from this sleep terminal during the sleep state. is output, and the required control is performed using the output of the sleep terminal. Ru.

[0005] Then, as shown in Fig. 3, the door lock switch 1 is turned to the lock terminal lck side. If the lock terminal lck and unlock terminal ulck are switched, the potentials of the lock terminal lck and unlock terminal ulck are They become L and H, respectively, and both detection terminals 5a and 5b of the ECU 5 have L and H, respectively. Since the signal is input, the door lock switch 1 is switched to the lock terminal lck side. is detected.

[0006] On the other hand, door lock switch 1 has been switched to the unlock terminal ulck side. In this case, the potentials of the lock terminal lck and unlock terminal ulck are H and L, respectively. Therefore, H and L signals are input to both detection terminals 5a and 5b of the ECU 5, respectively. Therefore, the ECU 5 switches the door lock switch 1 to the unlock terminal ulck side. It is detected that the

[0007]

[Problem that the idea aims to solve]

However, in the conventional case, when the ECU 5 is in the sleep state, it is different from the normal operating state. Similarly, current from power line +B flows to door lock switch 1, for example As shown in Figure 3, the door lock switch 1 is switched to the lock terminal lck side. When the ECU 5 enters the sleep state, the pull-up resistor 2, lock terminal lck, The same current flows through the path of the common terminal com as when the ignition switch is on. Therefore, a large dark current exceeding the standard 10mA flows through the door lock switch 1. There was a problem.

[0008] Therefore, this idea was devised to solve the problems mentioned above. Prevents dark current from flowing to the door lock switch when the ignition switch is turned off. The purpose is to make it possible to

[0009]

[Means to solve the problem]

The door lock switch detection device according to this invention detects the ignition switch The control unit has a low current consumption operation function when the power is off, so the common terminal is grounded and locked , each unlock terminal is connected to the power supply via a pull-up resistor. detects the state of the lock switch based on the potentials of the lock terminal and unlock terminal. , a door lock switch detection device that controls locking and unlocking of the door. and both pullers are connected between the power source and the lock terminal and unlock terminal, respectively. The switching element provided in series with each of the up resistors and the control section have low power consumption. a detection unit that detects that the current is being operated and outputs a detection signal; The switch on the side of the door lock switch that is being switched is activated by inputting the code. and a switching control section that outputs an off control signal to the switching element.

0010

[Effect]

In this device, the detection unit detects that the control unit is in a low current consumption operating state. The side that is detected and the door lock switch is switched by the switching control unit The switching element is turned off, and the pull-up resistor and door lock switch are energized. When the ignition switch is turned off, the power supply circuit is cut off as before. This prevents dark current from flowing from the input to the pull-up resistor and door lock switch.

[0011]

【Example】

FIG. 1 is a wiring diagram of an embodiment of the door lock switch detection device of this invention. Ta However, in FIG. 1, the same reference numerals as in FIG. 3 indicate the same or equivalent parts.

0012 As shown in Figure 1, the ECU 5 outputs an H signal during sleep operation. The input terminal of the inverter 6 as a detection unit is connected to the terminal 5c, and the power line +B A first NPN type switching element is connected between the pull-up resistors 2 and 3, respectively. , second transistors 7, 8 are provided, both transistors 7, 8 are connected to resistors 2, 3 and It is installed in series with it.

[0013] Further, first and second OR gates 9 and 10 are provided, and both OR gates 9 and 10 are connected to each other. One input terminal is connected to the output terminal of inverter 6, and the other input terminal is connected to resistor 2. , 3 through pull-up resistors 11 and 12, respectively, which have a higher resistance value than the power supply line + B, and the output terminals are connected to the bases of both transistors 7 and 8, respectively. Switching is performed by both OR gates 9, 10 and pull-up resistors 11, 12. A control unit 13 is configured, and an inverter is activated by the H output of the sleep terminal 5c of the ECU 5. Due to the L detection signal from 6, one input of both OR gates 9 and 10 becomes L, If the door lock switch 1 is switched to the lock terminal lck side as shown in Figure 1, In this case, since the lock terminal lck is grounded, the other input terminal of the first OR gate 9 output becomes L, the output of the first OR gate 9 becomes L, and the door lock switch 1 turns off. An L off control signal is output to the base of the first transistor 7 on the side being switched. Then, the first transistor 7 is turned off.

[0014] At this time, pull-up resistors 11 and 12 are much larger than pull-up resistors 2 and 3. The resistance value is set so that the current value is less than 10mA. ing.

[0015] Furthermore, as shown in FIG. 1, an interrupt generation circuit 1 consisting of a mono-multivibrator, 4 is provided, and both input terminals of this interrupt generation circuit 14 are connected to both input terminals of I/F 4. are connected to each other, and when one input falls to L, an L interrupt of pulse width t is generated. The pulse is output to the interrupt terminal 5d of the ECU 5, and the L interrupt pulse The ECU 5 wakes up at the timing when the trailing edge of the signal rises to H.

[0016] Next, the operation of FIG. 1 will be explained with reference to the time chart of FIG. 2.

[0017] Now, as shown in Figure 1, the door lock switch 1 is switched to the lock terminal lck side. If the ignition switch is turned off while the In the sleep state, the sleep terminal 5c becomes H as shown in FIG. 2(a), so the input The output of the converter 6 becomes L, and the door lock switch 1 is switched to the lock terminal lck side. Because of this, the lock terminal lck is grounded as shown in Figure 2(b). The potential of becomes L, both inputs of the first OR gate 9 become L, and its output becomes L. , the first transistor 7 is turned off as shown in FIG. 2(c).

[0018] By the way, one input of the second OR gate 10 becomes L due to the L output of the inverter 6. However, the other input of the second OR gate 10 becomes H via the pull-up resistor 12. Therefore, the output of the second OR gate 10 is H, as shown in FIG. 2(e). As shown, the second transistor 8 is in the on state, and the door lock switch 1 is unlocked. The potential of the terminal ulck becomes H as shown in FIG. 2(d).

[0019] Therefore, when the ECU 5 is in the sleep state, the door lock switch 1 is connected to the lock terminal. If it is switched to the lck side, the lock terminal lck and unlock terminal ulck are The potentials become L and H, respectively, and both detection terminals 5a, 5 of the ECU 5 are connected via the I/F 4. L and H signals are input to b, and the ECU 5 sets the door lock switch 1 to the lock end. Although it is detected that the door lock switch 1 has been switched to the slave lck side, the door lock switch 1 itself There is no large dark current flowing through the device as in the conventional case.

[0020] Meanwhile, the door lock switch 1 must be switched to the unlock terminal ulck side. For example, H and L signals are input to both detection terminals 5a and 5b of the ECU 5, and the ECU 5 outputs the signals. Check that the door lock switch 1 has been switched to the unlock terminal ulck side. Detected.

[0021] Next, when the ECU 5 is in the sleep state, the door lock switch 1 is locked. When switching from terminal lck to unlock terminal ulck, as shown in Figure 2(d), uni, because the unlock terminal ulck is grounded and its potential is reversed from H to L. , one input of the interrupt generation circuit 14 is inverted from H to L, and this fall to L causes Therefore, as shown in FIG. 2(f), a signal is sent from the interrupt circuit 14 to the interrupt terminal 5d of the ECU 5. An L interrupt pulse with pulse width t is input, and the trailing edge of this interrupt pulse rises from L to H. At the rising timing, the ECU 5 is woken up and activated, as shown in Figure 2(a). The sleep terminal 5c of the ECU 5 is inverted to L as shown in FIG.

[0022] Then, as the sleep terminal 5c is inverted to L, the output of the inverter 6 is inverted to H. Then, the outputs of the first and second OR gates 9 and 10 become H, which was in the off state until then. The first transistor 7 turned on as shown in FIG. 2(c), and both transistors 7 and 8 are both turned on as shown in FIGS. 2(c) and 2(e), and the first transistor 7 is turned on. When turned on, the lock terminal lck of the door lock switch 1 is turned on as shown in FIG. 2(b). The potential of becomes H, and the unlock terminal ulck is grounded and its potential is held at L. Then, H and L signals are sent to both detection terminals 5a and 5b of ECU 5 via I/F 4, respectively. is input, and the ECU 5 sets the door lock switch 1 to the unlock terminal ulck side. It is detected that the

[0023] Also, when the ECU 5 is in the sleep state, the door lock switch 1 is unlocked. When switching from the terminal ulck side to the lock terminal lck side, do the same as above. ECU 5 is released from sleep, and both detection signals 5a and 5b of ECU 5 are L and H signals. are respectively input, and the ECU 5 sets the door lock switch 1 to the lock terminal lck. It is detected that the camera is switching to the side.

[0024] By the way, when the ECU 5 is started, both transistors 7 and 8 are activated as described above. Since it is in the on state, door lock switch 1 is connected via pull-up resistor 2 or 3. As in the conventional case, current flows from the power supply line +B.

[0025] Therefore, when the ignition switch is turned off, the ECU 5 goes into sleep mode. Then, the door lock switch 1 is switched by the switching control section 13 described above. When the transistor on the side where the door lock switch is turned off, the pull-up resistor 2 or 3 Since the power to H1 is cut off, you cannot turn off the ignition switch as before. When the door lock switch 1 is turned on, a large dark current flows through the door lock switch 1. It can be prevented.

[0026] Note that in the above embodiment, an NPN transistor is used as the switching element. , the case where the detection unit is configured by the inverter 6 has been described, but the present invention is limited to this. It's not a thing.

[0027] Furthermore, the switching control unit 13 is not limited to the configuration described above; The switch on the side where the door lock switch is switched is activated by the input of the detection signal from the intelligence part. Any configuration may be used as long as it outputs an off control signal to the switching element.

[0028]

[Effect of the idea]

As described above, according to the door lock switch detection device of this invention, the detection part It is detected that the control unit is in a low current consumption operating state, and the switching control unit The switching element on the switched side of the door lock switch is turned off and the switch is turned off. The power path to the pull-up resistor and door lock switch is cut off, so the , when the ignition switch is off, the same large dark current flows through the door lock as when it is on. This prevents the battery from flowing to the power switch, effectively reducing battery consumption. It becomes possible.

[Brief explanation of drawings]

FIG. 1 is a wiring diagram of an embodiment of the door lock switch detection device of this invention.

FIG. 2 is a time chart for explaining the operation of FIG. 1;

FIG. 3 is a wiring diagram of a conventional door lock switch detection device.

[Explanation of symbols]

1 Door lock switch lck lock terminal ulck unlock terminal 2,3 Pull-up resistor 5 ECU (control unit) 6 Inverter 7, 8 First and second transistors 13 Switching control section

Claims (1)

[Scope of utility model registration request] Claim 1: A door lock switch whose common terminal is grounded and whose lock terminal and unlock terminal are each connected to a power supply via a pull-up resistor, by a control unit with a low current consumption operation function when the ignition switch is off. In the door lock switch detection device that detects the state based on the potential of the lock terminal and the unlock terminal and performs locking and unlocking control of the door, a a switching element provided in series with each of the pull-up resistors; a detection unit that detects that the control unit is in a low current consumption operating state and outputs a detection signal; and a detection unit that outputs a detection signal when the control unit is in a low current consumption operating state; A door lock switch detection device comprising: a switching control section that outputs an off control signal to the switching element on the side where the switch is being switched.