JPH0126119B2 - - Google Patents

Description

DETAILED DESCRIPTION OF THE INVENTION [Field of Industrial Application] The present invention relates to a data processing device that sequentially stores input data.

[Conventional technology]

Generally, for example, an electronic register is equipped with two printers, one that prints on the receipt and one that prints on the journal.The arithmetic processing unit executes predetermined arithmetic processing in accordance with key operations. The processed data is printed by both printers, a receipt is immediately given to the customer, and the journal is stored as a document on the store side.

In other words, conventionally, the department key is as shown in Figure 5.
01, number key 123, department key 02, and number key 456 (123 yen item in department 1 and 123 yen item in department 2)
When the product data of 456 yen is input), a receipt with printed contents as shown in Fig. 7 is created. Then, when the %-key indicating the discount or the cash/deposit key is operated, the discount amount, subtotal amount, change amount, etc. are calculated and the contents are additionally printed on the journal, and this journal is stored on the store side. Saved as a document.

However, the journal is only used when all the registrations for the day have been completed, and although it is rarely used during registration, it is possible to print on the receipt and the journal at the same time.
Since having multiple printers would be wasteful in terms of price and mounting space, we decided to use only one printer, which only prints receipts during registration, and stores data for the journal as described above in memory. It is being considered to print the journal at the time of inspection, checkout, and checkout.

[Problem to be solved by the invention]

By the way, if journal data such as input data and calculation data as described above are stored as they are, an enormous capacity of memory is required, leading to problems such as high costs and an increase in the size of the memory device.

An object of the present invention is to reduce costs without increasing memory capacity and to downsize the memory device by storing codes indicative of key operation contents in memory.

[Means to solve the problem]

The means of this invention are as follows.

Arithmetic processing means (CPU5
etc.), a memory means (equivalent to the journal memory 8, etc.) for storing codes indicating the operation contents of the input operation section in the order of operations, and a time when reading out the code in the memory means is specified, for example, when specifying inspection or payment. , an arithmetic processing control means (step S ₅₅ processed by the CPU 5,
S ₅₆ , S _{57 ,} etc.), and a printing unit (printing unit) that prints the arithmetic processing data by the arithmetic processing unit on a receipt according to the operation of the input operation unit or on a journal under the control of the arithmetic processing control unit. 8
etc.).

Note that the symbols in brackets are added for reference in order to clarify how the above-mentioned means were realized in the embodiment.

[Effect]

The operation of the means of this invention is as follows.

For example, codes indicating the contents of operations on the input operation section, such as products, deposit amounts, discount rates, etc., for each customer are stored in the storage means in the order of operations on the input operation section. Also,
When reading out the code in the storage means is instructed, such as when an inspection mode is specified, the arithmetic processing control means causes the arithmetic processing means to sequentially execute arithmetic processing according to the code read out from the storage means. In this arithmetic processing, for example, the change amount based on the product code and deposit amount for each customer stored above, the discount amount based on the product code and discount rate, etc. are calculated as arithmetic processing data, and the data is printed in a journal or the like by a printing means. The arithmetic processing data is printed.

Therefore, costs can be reduced without increasing memory capacity, and the memory device can be made smaller.

〔Example〕

An embodiment of the present invention will be described below with reference to FIGS. 1 to 8.
This will be explained with reference to the figures.

FIG. 1 shows a schematic system configuration diagram of an electronic register, and this input section 1 is equipped with an amount key, a department key, etc.

A timing signal KP is given to this input section 1 from an I/O port 2, and when a key operation is performed on the input section 1, the timing signal KP is selected according to the operation key, and is used as a key input signal KI. Input buffer provided on I/O port 2
Entered into IB. In addition to the input buffer IB, the I/O port 2 is provided with a display buffer HB and a print buffer PB.The display buffer HB is connected to the display section 3, and the print buffer PB is connected to the print section 4. has been done.

The display section 3 displays amount data and the like in accordance with the segment signal SG obtained by decoding the digit signal DG from the I/O port 2 and the data in the display buffer HB. The printing unit 4 is also equipped with one printer that prints on receipt paper, and receives a print position signal TP from a print drum (not shown) as an I/O.
Send to port 2, and from I/O port 2,
A print drive signal is generated by matching the print position signal TP with the data in the print buffer PB.
The MG is sent to the printing unit 4, and amount data and the like are printed on receipt paper.

Further, reference numeral 5 denotes a CPU, and an I/O port 2, a clock circuit 6, and a total memory 7 are connected to the CPU 5 via a data bus DB, an address bus AB, and a control bus CB. Furthermore, a journal memory 8 of the required capacity is detachably connected to each bus DB, AB, and CB.

The clock circuit 6 stores current hour and minute data in a register CLK, and also stores year, month, and date data in a register DATE, and updates the data every second, for example. During the update operation, a busy signal BY is output to the CPU 5.
In addition, the total memory 7 also contains “Payment” and “Inspection”.
At this time, the total data read from the journal memory 8 is temporarily stored.

FIG. 2 is a circuit configuration diagram showing the CPU 5 in detail, and reference numeral 9 in the figure is a program storage section consisting of a ROM, in which various microinstructions are stored. This program storage section 9 is connected to line l ₁
It outputs an address signal to the address control unit 10 via line _l2 , and outputs a next address signal specifying the next address of the operation code and program storage unit 9 to the control unit 11 via line l2.
Then, the next address signal is input from the control unit 11 to the program storage unit 9 via line _l3 ,
Addresses the next microinstruction.

The address control unit 10 specifies the address of the storage unit 12, and also controls the I/O port 2, the clock circuit 6, and the total memory 7 via the address bus AB.
and specify the address of journal memory 8,
When the address specification is completed, a completion signal is output to the control section 11 via line _l4 . Furthermore, data read out from the storage section 12 is input to the address control section 10 via line _l5 , and so-called index addressing is performed.

The storage unit 12 is provided with flag areas F ₁ , F ₂ , F ₃ in addition to A register, B register, C register, D register, X register, Y register, Z register, IX register, etc. The data read from this storage section 12 is stored in the calculation section 13.
It is also output to the I/O via the data bus DB.
O port 2, total memory 7 and journal memory 8. The arithmetic unit 13 performs various specified arithmetic operations, and the results of these arithmetic operations are input to the storage unit 12 via line _l6 .

The control section 11 decodes the input operation code, outputs a designation signal for specifying addition or subtraction to the calculation section 13 via line _l7 , and outputs an R/W signal via line _l8 . Output to the storage unit 12. Further, the control unit 11 changes the next address according to the data input via line _l9 and the presence or absence of a carry, and causes the address counter in the address control unit 8 to count up or count down via line _l10 . Outputs the specified signal. In addition, the control unit 11 outputs an R/W signal and a chip designation signal to the I/O port 2, the clock circuit 6, the total memory 7, and the journal memory 8 via the control bus CB, and also outputs the R/W signal and the chip designation signal from the clock circuit 6. Busy signal BY is input.

The journal memory 8 has a storage capacity for 16 digits in which the storage area of each row corresponds to column addresses 0 to 15, and 4-bit data is sequentially stored in each digit in response to each key operation on the input section 1. be remembered. That is, as shown in FIG. 3, codes "0" to "9" are stored in response to operations on the amount keys 0 to 9.
In order to explain this key code in an easy-to-understand manner by associating it with each operation key, it will be described below using a menu for convenience. That is, the codes "0" to "9" and the news symbols "0" to "9"
"9" corresponds. Similarly, departmental keys 01 to 04 are codes "A" to "D" and news codes 01 to 04.
04 respectively. Similarly, a currency exchange key, a cash/deposit key, a credit sale key, a credit sale key, which are operated at the end of registration, are used as termination keys.
The deposit key and withdrawal key are the 8-bit code "E0"
- Corresponds to "E5" and news NS - PD. Similarly, the tax key ~ minus key is the code "E6" ~ "ED", and the news TX ~ □-
They correspond to each other. Also, date data, data of responsible persons A to F, receipt NO, "REG" ~
"SET" mode data, time, power failure recovery, END
Each data corresponds to 8 bits "F0" to "FD" and the news signals DA to END.

Next, the operation of this invention will be explained.

At present, a journal memory 8 of the required capacity is connected to the electronic register, and at this time, when the power to the electronic register is turned on, the operation according to the flow shown in FIG. 4 is executed. First, in executing step _S1 , the contents of each register provided in the storage section 12 are cleared and set to initial values. Next, the process moves to step _S2 , where the register of the clock circuit 6 is
The current year, month, and date data stored in DATE is read out, and the storage area M of the journal memory 8 specified by the IX register of the storage unit 12 is read out.
(IX), and the contents of the IX register are updated. Next, in step _S2 , the date code DA is written into the storage area M(IX). Thereafter, the contents of the IX register will be updated every time a write is executed.

Next, the process moves to step _S4 , and the data of the mode specified by the mode switch is stored in A of the storage section 12.
written to the register. Next, the process moves to step _S5 , where the current mode data in the A register and the B
A determination is made as to whether or not the previous mode data stored in the register are equal, and if it is determined that they are not, the process moves to step _S6 . At step _S6 , the mode data in the A register is transferred to the B register as new mode data. Next, the process moves to step _S7 , and " ₁ " is written in the flag area F1 of the storage section 12.
In other words, it is determined whether or not the end key indicating the end of registration for one customer has been operated. If it is determined that there has been an operation, the process moves to step _S8 . In executing step _S8 ,
"1" is set in the flag area _F2 to indicate that the mode data has been switched, and then the process moves to step _S9 . Note that even if it is determined in step _S5 that the contents of the A register and the contents of the B register are equal, the process moves to step _S9 , and the person in charge data specified by the person in charge switch is written in the C register. Next, proceed to step S10, and proceed to step _S10 .
A judgment is made as to whether or not the current responsible person data stored in the register and the _previous responsible person data stored in the D register are equal. The current responsible person data is transferred to the D register as new responsible person data. Next, the process moves to step _S12 , where it is determined whether or not "1" indicating the end of registration is set in the flag area _F1 . If it is determined not, the process moves to step _S13 . In the execution of step _S13 , "1" is set in the flag area _F3 to indicate that the person in charge has been replaced, and then the process returns to step _S4 . Note that if "0" is stored in the flag area F ₁ in steps S ₇ and S ₁₂ ,
If it is detected that the mode switch is switched or the person in charge is changed during registration, the process moves to step _S14 , where an error handling operation is executed, and then the process returns to step _S4 .

If it is determined in step _S10 that the responsible person data in the C register and the responsible person data in the D register match, the process moves to step _S15 , and the data stored in the input buffer IB is transferred to the storage section. 12 X registers. Next, the process moves to step _S16 , and the contents of the X register are set to "0".
In other words, it is determined whether an input operation has been performed or not. If it is determined to be "0", the process moves to step _S4 , and if it is determined not to, the process moves to step _S17 . In the execution of step _S17 , it is determined whether or not the amount key has been operated. If it is determined to be YES, the process moves to step _S18 , and the operated amount key is entered as the first numeric key in the series of numeric keys to be input. A determination is made as to whether or not it is the first digit that has been manipulated, and if it is determined that it is not, the process moves to step _S19 . In step _S19 , the number data in the Y register of the storage section 12 is carried up by one digit. step
In _S18 , if it is determined that it is the first set number, the process moves to step _S20 , where it is determined whether "1" indicating the previous registration end key operation is set in the flag area _F1 . If it is determined that there is a set, the process moves to step _S21 . At step _S21 , "0" is written in the flag area _F1 . Next, the process moves to step _S22 , where it is determined whether or not "1" indicating a mode switch switching operation has been set in the flag area _F2 . If it is determined that the mode switch has been set, the process moves to step _S23 . In executing step _S23 , the mode data stored in the A register in step _S4 is written to the storage area M(IX) of the journal memory 8, and then in step _S24.
Move to. In the step _S22 , the flag area _F2
If "0" is stored in step _S24 ,
Move to. In executing step _S24 , it is determined whether "1" indicating a change in the person in charge has been set in the flag area _F3 , and if it is determined that it has been set, the process moves to step _S25 . In executing step _S25 , the responsible person data stored in the C register in step _S9 is stored in the journal memory 8.
The data is written to the storage area M(IX) of , and then the process moves to step _S26 . Note that even if it is determined in steps S ₂₀ and S ₂₄ that "0" is stored in the flag areas F ₂ and F ₃ , the process moves to step S ₂₆ . In step _S26 , the numerical data stored in digit X ₀ of the X register is written to digit Y ₀ of the Y register,
Performs numeric processing using amount key operations. Next, the process moves to step _S27 , where the contents of the Y register are transferred to the display buffer HB and displayed on the display section 4.

If it is determined in step _S17 that the amount key has not been operated, the process moves to step _S28 .
In executing step _S28 , press the clear key (C
It is determined whether or not the key) has been operated, and if it is determined to be YES, the process moves to step _S29 . In executing step _S29 , the contents of the Y register are cleared,
After this, the process moves to step _S27 .

If it is determined in step _S28 that the key is not the C key, the process moves to step _S30 . step
In executing S ₃₀ , it is determined whether or not a departmental key has been operated, and if it is determined to be YES, the step
Move on to _S31 . In step _S31 , subtotal addition of the input sales data is performed, and the addition result is stored in the Z register. Next, the process moves to step _S32 , where the department data stored in the X register is transferred to the print buffer PB and the display buffer HB, where it is printed on receipt paper in the print section 4 and displayed on the display section 3. Next, the process moves to step _S33 , where the numerical data stored in the Y register is transferred to the storage area M of the journal memory 8.
Transferred to (IX). Next, the process moves to step _S34 , where the department key code corresponding to the operated department key is stored in the storage area M of the journal memory 8.
After being transferred to (IX), return to step _S4 .

If it is determined in step _S30 that the department key has not been operated, step S30 is performed.
Move on to _S35 . In executing step _S35 , other processing operations corresponding to key operations other than the amount key, C key, and departmental key are performed and displayed or printed, or a key code corresponding to the operation key is stored in the journal memory 8. A write operation is performed. Next, the process moves to step _S36 , and when it is determined whether or not the registration end key has been operated, the process moves to step _S37 . In executing step _S37 , "1" indicating the end of registration is set in the flag area _F1 . Next, the process moves to step _S38 , where the current hour and minute data stored in the register CLK of the clock circuit 6 are stored in the X register. Then step
Proceeding to _S39 , when the minute data is stored in the X register, the minute data is written to the storage area M(IX) of the journal memory 8. Next, proceed to step _S40 ,
The time code TM is written in the storage area M(IX) of the journal memory 8. Next, the process moves to step _S41 , and the storage area M of the journal memory 8 is
END code END is written to (IX). Next, the process moves to step _S42 , where the contents of the IX register are reversely updated to the address value indicating the storage area of the journal memory 8 where the END code is stored, and then the process returns to step _S4 . In addition, after pressing the end key,
A stamp and date are printed on the receipt paper in the printing section 4.

However, as shown in Figure 5, POWER ON
Then, steps _S1 to _S3 are executed, and as shown in FIG.
DATE data "800610" indicating June 10, 1980 is stored, and then the date code is stored in the 0th row, 6th and 7th columns.
DA is memorized. Next, when the mode switch is set to "REG" mode and the person in charge switch is set to A, steps _S1 to _S13 , _S4 , _S5 , _S9 ,
Steps S ₁₀ and S ₁₅ are executed in sequence, and then when the amount key 123 is operated, steps S ₁₆ to S ₂₇ are executed, and as a result, the values are displayed in the 0th row, 8th, and 9th column of the journal memory 8.
The REG code REG and code □A of responsible person A are stored in the 10th and 11th columns. Next, when the department key 01 is operated, steps S ₁₇ , S ₂₈ , S ₃₀ to _{S 34} are executed in sequence, and numerical data "123" is stored in the 0th row and 12th to 14th columns of the journal memory 8. row 15
Code 01 of department 01 is stored in column 1, row 1, column 1, and at the same time, the same data is printed on the receipt as shown in FIG. Next, when the amount key 456 and the department key 02 are operated, the data is stored in the journal memory 8 in the same way, and when the correction key □ correction is operated, as a result of executing step _S35 , the correction code VD is written in the 1st row, 6th and 7th columns. At the same time, correction printing is performed on the receipt. Similarly, each key code is stored in the journal memory 8 in response to each key operation of the department key, percent key □%, and minus key □-, and is also printed on the receipt. Next, after operating the amount key 700, when the cash/deposit key CASH/DEPOSIT is operated, steps _S36 to _S41 are sequentially executed, and lines 2, 6, and 6 of the journal memory 8 are
Code CA indicating cash/deposit key operation in the 7th column
is memorized. After this, the hour and minute data "0815" is stored in row 2, columns 10 to 13, then the time code TM is stored in row 2, columns 12 and 13, and then the code END is stored in row 2, columns 14 and 15. be remembered. After this, step
The process moves to _S42 , where the IX register is reversely updated, and the next data is written from the 2nd row, 14th column of the journal memory 8. Further, in step _S35 , the subtotal data "614" stored in the Z register is printed on the receipt, and the deposit amount "700" is printed.
``614'' is subtracted from ``614'' and change ``86'' is printed. After this, a receipt with the receipt number, person in charge symbol, and time data printed in sequence is issued.

In exactly the same manner as described above, each key code is sequentially stored in the journal memory 8 as shown in FIG. 6 in correspondence with each key operation shown in FIG.

Next, after setting the mode switch to the "settlement" mode, when the cash/deposit key is operated, the settlement operation according to the flow shown in FIG. 8 is executed. That is, in executing step _S51 , the contents of the IX register of the storage section 12 are set to the initial value, and as a result, the address is initialized. Next, in step _S52 , the contents of the IX register are rewritten and the address is updated. Next, the process moves to step _S53 , where the key code stored in the storage area of the journal memory 8 specified by the IX register is read out. Next, the process moves to step _S54 , where the arithmetic unit 13 judges whether or not there is an END code in the key code read out from the journal memory 8. If it is determined that there is no END code, the process moves to _{step S55} . In the execution of step _S55 , the code-specific calculation corresponding to the read key code is performed, i.e., if there is amount data before the CA code, change is calculated, or a discount is applied according to the □%□- code. , □%□+ code, and performs other calculations such as discount, addition, and tax. Next, the process moves to step _S56 , where subtotal addition of the read sales data is executed to obtain subtotal data. Next, the process moves to step _S57 , where the calculated subtotal data is classified by department, transaction, person in charge, and time period, and the total data for each classification is accumulated in the corresponding storage area of the total memory 7. . Next, proceed to step _S58 ,
A determination is made as to whether the data read from the journal memory 8 is an end key code or not, and if it is determined not, the process returns to step _S52 .

If it is determined in step _S58 that it is the end key code, the process moves to step _S59 . In the execution of step _S59 , the read data and code-specific calculation data stored in the journal memory 8 are transferred to the print buffer PB and printed in the printing section 4, after which the process returns to step _S52 .

If it is determined in step _S52 that the key code read from the journal memory 8 is an END code, the process moves to step _S60 .
In executing step _S60 , the total of the classification data stored in the total memory 7 is printed. Next, the process moves to step _S61 , where the data stored in the total memory 7 and the journal memory 8 are cleared.

In the embodiment described above, the journal memory 8 was configured to be detachably connected to the electronic register, but the journal memory 8 may be fixedly provided to the electronic register.

Furthermore, if key codes corresponding to frequently used keys are represented by a smaller number of bits, and key codes corresponding to less frequently used keys are represented by a larger number of bits, they can be stored more efficiently.

Further, in the above embodiment, the case where the information is printed for inspection, payment, etc. is shown, but the case where the information is outputted to a data collector or the like can be implemented in the same way.

Further, in the embodiment described above, key codes corresponding to the operation keys are stored, but when input by OCR, OMR, etc., a code indicating the contents of the operation may be stored.

〔Effect of the invention〕

According to the present invention, by storing a code indicating the contents of a key operation in the memory, cost reduction can be achieved without increasing the memory capacity (in the case of a memory cassette or the like, the quantity). Furthermore, since the number of memory cassettes and the like does not increase, storage space can be reduced. Moreover, these memory devices can be made smaller without increasing the size of internal devices incorporating memory elements or memory cassettes in order to increase memory capacity.

[Brief explanation of drawings]

Fig. 1 is a schematic system configuration diagram of the embodiment, Fig. 2 is a detailed circuit diagram of the CPU of the embodiment, and Fig. 3 is the key type and memory corresponding to each key operation of the embodiment. Figure 4 is a flowchart of the same embodiment;
6 is a diagram showing the input operation sequence in the same embodiment, FIG. 6 is a storage state diagram of the journal memory in which key codes corresponding to the input operations shown in FIG. 5 are stored, FIG. 7 is a receipt printing state diagram, and FIG. FIG. 8 is a flowchart executed at the time of payment in the same embodiment. 1...Input unit, 5...CPU, 7...Total memory, 8...Journal memory, 11...Control unit,
12...Storage unit, 13...Arithmetic unit.

Claims (1)

[Claims] 1. An arithmetic processing means for executing predetermined arithmetic processing in accordance with the operation of the input operation section, a storage means for storing codes indicating the operation contents of the input operation section in the order of operations, and a time when the reading of the code in this storage means is specified. A data processing device comprising: arithmetic processing control means for causing the arithmetic processing means to sequentially execute arithmetic processing according to the read code; and a printing means for printing the arithmetic processing data by the arithmetic processing means.