JP2020204512A - Three-phase load proportional division method and unbalanced voltage calculation method - Google Patents

Three-phase load proportional division method and unbalanced voltage calculation method Download PDF

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JP2020204512A
JP2020204512A JP2019112005A JP2019112005A JP2020204512A JP 2020204512 A JP2020204512 A JP 2020204512A JP 2019112005 A JP2019112005 A JP 2019112005A JP 2019112005 A JP2019112005 A JP 2019112005A JP 2020204512 A JP2020204512 A JP 2020204512A
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JP7255384B2 (en
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浩一 八田
Koichi Hatta
浩一 八田
齋藤 哲也
Tetsuya Saito
哲也 齋藤
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Chugoku Electric Power Co Inc
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Abstract

To provide a three-phase load proportional division method and an unbalanced voltage calculation method which generate a relatively low cost only when a current vector of an inter-line load is calculated and which is relatively small in deviation from an actual situation.SOLUTION: A three-phase load proportional division method for obtaining the voltage unbalance of a distribution system having a three-phase distribution line 10, which includes a conversion step of converting a measurement value of a line current at a node, to which an inter-line load 20 of the three-phase distribution line 10 is connected, into a value of an inter-line current flowing through an inter-line load. The conversion step, in a triangle composed of a current vector of a line current, is a step of fixing a single-phase load power factor and using the vector from the center point where reactive power is equal to each vertex as an inter-line current.SELECTED DRAWING: Figure 4

Description

本発明は、三相負荷按分方法及び不平衡電圧計算方法に関する。とりわけ、本発明は配電系統の電圧不平衡を求めるための三相負荷按分方法及び不平衡電圧計算方法に関する。 The present invention relates to a three-phase load apportionment method and an unbalanced voltage calculation method. In particular, the present invention relates to a three-phase load apportionment method and an unbalanced voltage calculation method for obtaining a voltage imbalance in a distribution system.

住宅用太陽光発電の導入量増加に伴い、配電系統において電圧不平衡の拡大が懸念されている。とりわけ、配電系統中で変電所から遠い地点において、配電線が長くなることによりインピーダンスが大きくなると、少しの負荷の偏りでも大きな電圧不平衡が発生する。不平衡率が高くなると、例えば需要先の電力機器が停止したり、モーターが焼損したりする怖れがある。 With the increase in the introduction of residential photovoltaic power generation, there is concern about the expansion of voltage imbalance in the distribution system. In particular, when the impedance increases due to the lengthening of the distribution line at a point far from the substation in the distribution system, a large voltage imbalance occurs even with a slight load bias. If the unbalance rate becomes high, for example, there is a risk that the electric power equipment of the demand destination will stop or the motor will burn out.

電圧不平衡の発生状況は、現状、近年設置が進んでいる計測機能付き開閉器の計測値、具体的には三相間の線間電圧、線電流、力率を取得することにより確認可能である。 The occurrence of voltage imbalance can be confirmed by acquiring the measured values of switches with measurement functions, which are currently being installed in recent years, specifically, the line voltage, line current, and power factor between the three phases. ..

電圧不平衡が拡大し対策が必要になると、一般的に単相柱上変圧器の接続相振替工事が実施される。工事設計時に、計測値に基づく正確な振替量を計算できれば効果的な工事が可能となるが、計測機能付き開閉器は、単相柱上変圧器に流れる電流を直接計測していないため、計測値である系統電流(線電流)を、線間負荷を流れる線間電流(相電流)に変換する計算が必要となる。 When the voltage imbalance expands and countermeasures are required, connection phase transfer work for single-phase pole transformers is generally carried out. Effective construction is possible if the accurate transfer amount can be calculated based on the measured values at the time of construction design, but since the switch with measurement function does not directly measure the current flowing through the single-phase pole transformer, it is measured. A calculation is required to convert the system current (line current), which is a value, into the line current (phase current) flowing through the line load.

従来、線電流を線間電流に変換するために、例えば非特許文献1に記載の方法では、一相の電流を既知とする仮定を置いて計算していた。また、その他の方法として、△結線における電流の零相分はないことを仮定し、線電流の電流ベクトルから構成される三角形の重心から当該三角形の各頂点へのベクトルを線間電流とする方法がある。 Conventionally, in order to convert a line current into an interline current, for example, in the method described in Non-Patent Document 1, the calculation is performed on the assumption that the one-phase current is known. As another method, assuming that there is no zero-phase component of the current in the △ connection, the line current is the vector from the center of gravity of the triangle composed of the current vector of the line current to each vertex of the triangle. There is.

特開昭61−221666号公報Japanese Unexamined Patent Publication No. 61-221666

内川、上村:「配電系統における太陽光発電出力と負荷カーブの分離方法の開発と電圧不平衡対策への適用」、電力中央研究所報告書,2009−07Uchikawa, Uemura: "Development of a method for separating photovoltaic power generation output and load curve in a distribution system and application to measures against voltage imbalance", Central Research Institute of Electric Power Industry Report, 2009-07

しかし、非特許文献1に記載の方法では、一相の電流の値を知るために、別途計測器を取り付ける必要があり、これに伴って長い取付時間及び高いコストが発生する。
また、線電流の電流ベクトルから構成される三角形の重心から当該三角形の各頂点へのベクトルを線間電流の電流ベクトルとする方法では、計算式が簡単であるという利点があるものの、負荷が極端に偏っている場合、各線間の電流の力率が相間毎に大きく異なってしまうので、実態から大きく乖離すると考えられる。
However, in the method described in Non-Patent Document 1, it is necessary to separately attach a measuring instrument in order to know the value of the current of one phase, which causes a long attachment time and a high cost.
In addition, the method of using the vector from the center of gravity of the triangle composed of the current vector of the line current to each vertex of the triangle as the current vector of the line current has the advantage that the calculation formula is simple, but the load is extreme. If it is biased to, the power factor of the current between each line will differ greatly from phase to phase, and it is considered that there will be a large deviation from the actual situation.

本発明は、線間電流の電流ベクトルを計算する際、比較的低いコストしか発生しないと共に、実態からの乖離が比較的小さな三相負荷按分方法及び不平衡電圧計算方法を提供することを目的とする。 An object of the present invention is to provide a three-phase load apportionment method and an unbalanced voltage calculation method, which generate a relatively low cost when calculating a current vector of a line current and have a relatively small deviation from the actual state. To do.

前記目的を達成するため、本発明は、次に記載する構成を備えている。
(1)三相配電線を有する配電系統の電圧不平衡を求めるための三相負荷按分方法において、前記配電系統を構成するノードであって、前記三相配電線の線間負荷が接続されるノードにおける線電流の計測値を、線間負荷を流れる線間電流の値に変換する変換ステップを有し、前記変換ステップは、前記線電流の電流ベクトルから構成される三角形において、単相負荷力率を固定し、無効電力が等しくなる中心点から、各頂点へのベクトルを線間電流とするステップである、三相負荷按分方法。
In order to achieve the above object, the present invention includes the following configurations.
(1) In a three-phase load apportioning method for obtaining a voltage imbalance in a distribution system having a three-phase distribution wire, a node constituting the distribution system and to which a line load of the three-phase distribution wire is connected. It has a conversion step that converts the measured value of the line current into the value of the line current flowing through the line load, and the conversion step converts the single-phase load power factor in a triangle composed of the current vector of the line current. A three-phase load apportionment method, which is a step in which the line current is a vector from a fixed center point at which the negative powers are equal to each apex.

(2) 前記三相負荷按分方法において、前記変換ステップは、計測機能付き開閉器の計測値をベクトル値に変換する第1のサブステップと、前記ベクトル値に含まれる線電流の電流ベクトルで構成される第1の三角形の各頂点から、等力率で直線を延ばして第2の三角形を形成する第2のサブステップと、前記第2の三角形に内接する円の中心を等力率等無効電力点とする第3のサブステップと、前記等力率等無効電力点から前記第1の三角形の各頂点に伸ばしたベクトルを、各線間負荷の電流ベクトルとする第4のサブステップと、を有してもよい。 (2) In the three-phase load apportioning method, the conversion step is composed of a first sub-step for converting the measured value of the switch with a measuring function into a vector value, and a current vector of the linear current included in the vector value. The second sub-step of extending a straight line from each vertex of the first triangle to form a second triangle with an equal power factor, and the center of the circle inscribed in the second triangle are reactive such as the equal power factor. A third sub-step as a power point and a fourth sub-step in which a vector extending from the reactive power factor such as the equal power factor to each vertex of the first triangle is used as a current vector for each line load. You may have.

(3) (1)又は(2)の三相負荷按分方法を用いて、線間電流の電流ベクトルを求めるステップと、一次側の第1ノードでの前記線間電流と、二次側の第2ノードでの前記線間電流とから、前記第1ノードと前記第2ノードとの間の区間の通過電力を求めて該通過電力の差分をとり、前記区間の区間消費電力を求めるステップと、前記区間消費電力を用いて不平衡電圧を計算するステップと、を有する不平衡電圧計算方法。 (3) Using the three-phase load apportionment method of (1) or (2), the step of obtaining the current vector of the line current, the line current at the first node on the primary side, and the second on the secondary side. From the line current at the two nodes, the passing power of the section between the first node and the second node is obtained, the difference between the passing powers is taken, and the section power consumption of the section is obtained. An unbalanced voltage calculation method comprising a step of calculating an unbalanced voltage using the section power consumption.

本発明によれば、線間電流の電流ベクトルを計算する際、比較的低いコストしか発生しないと共に、実態からの乖離が比較的小さな三相負荷按分方法及び不平衡電圧計算方法を提供することが可能となる。 According to the present invention, it is possible to provide a three-phase load apportionment method and an unbalanced voltage calculation method in which a relatively low cost is incurred when calculating the current vector of the line current and the deviation from the actual state is relatively small. It will be possible.

本発明の実施形態に係る三相負荷按分方法を適用する配電系統の例を示す図である。It is a figure which shows the example of the distribution system which applies the three-phase load apportioning method which concerns on embodiment of this invention. 本発明の実施形態に係る三相負荷按分方法で用いる電流・電圧ベクトル図の例を示す図である。It is a figure which shows the example of the current / voltage vector figure used in the three-phase load apportionment method which concerns on embodiment of this invention. 本発明の実施形態に係る三相負荷按分方法で用いる線電流の計測値から相電流の電流ベクトルへの変換方法の例を示す図である。It is a figure which shows the example of the conversion method from the measured value of the line current to the current vector of a phase current used in the three-phase load apportionment method which concerns on embodiment of this invention. 本発明の実施形態に係る三相負荷按分方法で用いる線電流の計測値から相電流の電流ベクトルへの変換方法の例を示す図である。It is a figure which shows the example of the conversion method from the measured value of the line current to the current vector of a phase current used in the three-phase load apportionment method which concerns on embodiment of this invention.

〔1.発明の概要〕
配電系統の不平衡電圧を計算するためには、区間消費電力の値が必要となる。この区間消費電力の計算には、線間負荷(相電流)の電流ベクトルが必要となり、線間負荷の電流ベクトルを求めるためには、線電流の計測値を線間負荷の電流ベクトルに変換する手順が必要となる。この変換として、線電流の電流ベクトルから構成される三角形において等力率等無効電力点を求め、この等力率等無効電力点から当該三角形の各頂点に伸ばしたベクトルを線間負荷の電流ベクトルとするのが、本発明の骨子である。
[1. Outline of the invention]
In order to calculate the unbalanced voltage of the distribution system, the value of the section power consumption is required. The calculation of the section power consumption requires the current vector of the line load (phase current), and in order to obtain the current vector of the line load, the measured value of the line current is converted into the current vector of the line load. Steps are needed. As this conversion, the reactive power point such as the equal power factor is obtained in the triangle composed of the current vector of the linear current, and the vector extended from the reactive power factor such as the equal power factor to each vertex of the triangle is the current vector of the line load. Is the gist of the present invention.

〔2.区間消費電力の計算〕
上記のように、不平衡電圧は、計測機能付き開閉器の測定値から、各区間の線間負荷を求め、この線間負荷を潮流計算の入力値とすることにより求める。
[2. Calculation of section power consumption]
As described above, the unbalanced voltage is obtained by obtaining the line load in each section from the measured value of the switch with a measurement function and using this line load as the input value for the power flow calculation.

図1は、配電系統の例を示す。図1に示すように、配電系統1が6つのノードから構成され、各ノードにおいて三相配電線10に線間負荷20が接続するとする。また、各ノードに計測機能付き開閉器30が設置され、当該計測機能付き開閉器30で、三相配電線10を流れる線電流の値が計測される。各ノードでの区間消費電力に含まれる有効電力をΔP、無効電力をΔQとすると、線間負荷はΔPΔQとなる。逆に言えば、各区間の線間負荷ΔPΔQを求めるためには、各ノードでの区間消費電力に含まれる有効電力ΔP、及び無効電力ΔQを求めればよい。 FIG. 1 shows an example of a distribution system. As shown in FIG. 1, it is assumed that the distribution system 1 is composed of six nodes, and the line load 20 is connected to the three-phase distribution wire 10 at each node. Further, a switch 30 with a measurement function is installed at each node, and the value of the line current flowing through the three-phase distribution wire 10 is measured by the switch 30 with the measurement function. Assuming that the active power included in the section power consumption at each node is ΔP i and the reactive power is ΔQ i , the line load is ΔP i ΔQ i . Conversely, in order to obtain the line load ΔP i ΔQ i of each section, the active power ΔP i and the reactive power ΔQ i included in the section power consumption at each node may be obtained.

図1に示すように、ノードiでの通過電力を、P+jQとすると、このP+jQは、ノードiからノード6までの消費電力である。また、ノードi−1での通過電力は、Pi−1+jQi−1となるが、これはノードi−1からノード6までの消費電力である。 As shown in FIG. 1, the passing electric power at node i, when the P i + jQ i, the P i + jQ i is the power consumption from node i to node 6. Further, the passing power at the node i-1 is Pi -1 + jQ i-1 , which is the power consumption from the node i-1 to the node 6.

したがって、区間iの消費電力を求めるためには、ノードi−1での通過電力から、ノードiでの通過電力を差し引けばよい。すなわち、区間iでの消費電力ΔP+jΔQは、
ΔP+jΔQ=(Pi−1−P)+j(Qi−1−Q) (1)
であり、P=(Piabibcica)、Q=(Qiabibcica)とすると、以下の数式(2)及び(3)が成立する。
ΔP=(P(i−1)ab−Piab(i−1)bc−Pibc(i−1)ca−Pica) (2)
ΔQ=(Q(i−1)ab−Qiab(i−1)bc−Qibc(i−1)ca−Qica) (3)
Therefore, in order to obtain the power consumption of the section i, the passing power at the node i may be subtracted from the passing power at the node i-1. That is, the power consumption ΔP i + jΔQ i in the section i is
ΔP i + jΔQ i = (P i-1- P i ) + j (Q i-1- Q i ) (1)
In and, P i = (P iab P ibc P ica), when Q i = a (Q iab Q ibc Q ica) , the following equation (2) and (3) is satisfied.
ΔP i = (P (i-1) ab- P iab P (i-1) bc- P ibc P (i-1) ca- Pica ) (2)
ΔQ i = (Q (i-1) ab −Q iab Q (i-1) bc −Q ibc Q (i-1) ca −Q ica ) (3)

〔3.区間通過電力の計算〕
上記のように、区間iの消費電力を求めるためには、ノードiの区間通過電力を求める必要がある。ここで、ノードiでの区間通過電力P+jQは、以下の数式(4)〜((7)に示すように、線間電圧と線間電流との積となる。

Figure 2020204512
[3. Calculation of section passing power]
As described above, in order to obtain the power consumption of the section i, it is necessary to obtain the section passing power of the node i. Here, the section passing power P i + jQ i at node i, as shown in the following equation (4) - ((7), the product of the line voltage and the line current.
Figure 2020204512

したがって、ノードiの区間通過電力を求めるためには、ノードiの線間電流を求める必要があり、ノードiの線間電流を求めるためには、ノードiの計測機能付き開閉器の計測値であるスカラ量を、図2に示す電流・電圧ベクトル図を用いてベクトル量に変換した上で、線電流の電流ベクトル

Figure 2020204512
を線間電流の電流ベクトル
Figure 2020204512
に変換する必要がある。
この線電流の電流ベクトルから線間電流の電流ベクトルへの変換の際、次項で説明する按分方法を用いる。 Therefore, in order to obtain the section passing power of node i, it is necessary to obtain the line current of node i, and in order to obtain the line current of node i, the measured value of the switch with the measurement function of node i is used. After converting a certain scalar quantity into a vector quantity using the current / voltage vector diagram shown in FIG. 2, the current vector of the line current.
Figure 2020204512
The line current current vector
Figure 2020204512
Need to be converted to.
When converting the current vector of the line current to the current vector of the line current, the apportionment method described in the next section is used.

〔線電流から線間電流への按分方法〕
線電流の電流ベクトルを線間電流の電流ベクトルに変換する際、線電流の電流ベクトルで構成される第1の三角形の各頂点から、等力率で直線を延ばして第2の三角形を形成し、第2の三角形の重心(ここでは、「「等力率等無効電力点」と呼称する)から、第1の三角形の各頂点に伸ばしたベクトルを、線間電流の電流ベクトルとする。
具体的な方法については、以下の通りである。
[Proportioning method from line current to line current]
When converting the line current current vector to the line current current vector, a straight line is extended at an equal power factor from each vertex of the first triangle composed of the line current current vector to form a second triangle. , The vector extending from the center of gravity of the second triangle (here, referred to as “invalid power point such as equal power factor”) to each apex of the first triangle is defined as the current vector of the line current.
The specific method is as follows.

図3に示すように、式(8)に示す線電流の電流ベクトルのうち、Iiaを示すベクトルが、
ia=(x,y) (10)
であり、Iicを示すベクトルが、
ic=(−x,−y) (−Iic=(x,y)) (11)
であり、Iibを示すベクトルが、
ib=−I−I (12)
であるとする。また、力率がcosθであるとする。
As shown in FIG. 3, of the current vector of the line current shown in equation (8), the vector indicating the I ia,
I ia = (x 1 , y 1 ) (10)
, And the vector indicating the I ics,
I ic = (-x 2 , -y 2 ) (-I ic = (x 2 , y 2 )) (11)
And the vector indicating I ib is
I ib = -I c- I a (12)
Suppose that Further, it is assumed that the power factor is cos θ.

3つの電流ベクトルIia,Iib,−Iicによって構成される三角形の頂点のうち、Iibと−Iicの交点である頂点(x,y)=(x,y)を通り、傾きがtanθの直線を引く。この直線を表す数式は、以下の式(13)となる。

Figure 2020204512
Three current vectors I ia, I ib, among the vertices of the triangle formed by -I ics, vertex which is the intersection of I ib and -I ic (x, y) = through (x 2, y 2), Draw a straight line with a slope of tan θ. The mathematical formula representing this straight line is the following formula (13).
Figure 2020204512

同様に、Iiaと−Iicの交点である頂点(x,y)=(0,0)を通り、傾きがtan(θ−2π/3)の直線を引く。この直線を表す数式は、以下の式(14)となる。

Figure 2020204512
Similarly, a straight line with a slope of tan (θ-2π / 3) is drawn through the apex (x, y) = (0,0), which is the intersection of I ia and −I ic . The mathematical formula representing this straight line is the following formula (14).
Figure 2020204512

同様に、IiaとIibの交点である頂点(x,y)=(x,y)を通り、傾きがtan(θ+2π/3)の直線を引く。この直線を表す数式は、以下の式(15)となる。

Figure 2020204512
Similarly, a straight line with a slope of tan (θ + 2π / 3) is drawn through the apex (x, y) = (x 1 , y 1 ), which is the intersection of I ia and I ib . The mathematical formula representing this straight line is the following formula (15).
Figure 2020204512

次に、式13で表される直線と式14で表される直線の交点m、式14で表される直線と式15で表される直線の交点m、式15で表される直線と式13で表される直線の交点mを求め、これら3点を頂点とする正三角形の重心mabcを求める。 Next, the intersection m c of the straight line represented by the straight line equation 14 of formula 13, straight intersection m a represented by the straight line equation 15 of formula 14, the straight line of the formula 15 seeking straight intersection m b represented by preparative formula 13, obtaining the center of gravity m abc of an equilateral triangle whose vertices are the three points.

図4に示されるように、この重心mabcから、元の三角形の頂点である、(x,y)=(x,x)、(x,y)=(x,y)、(x,y)=(0,0)へのベクトルを、それぞれ、線間電流の電流ベクトルである、Iiab,Iibc,Iicaとする。 As shown in FIG. 4, from this center of gravity mabc , the vertices of the original triangle, (x, y) = (x 1 , x 2 ), (x, y) = (x 2 , y 2 ), Let the vectors to (x, y) = (0,0) be I iab , I ibc , and I ica , which are the current vectors of the line currents, respectively.

以下、数式展開の詳細について説明する。
式(14)及び式(15)に加法定理を適用すると、以下の式(14’)及び式(15’)となる。

Figure 2020204512
The details of the mathematical expression expansion will be described below.
Applying the addition theorem to equations (14) and (15) yields the following equations (14') and (15').
Figure 2020204512

は、式(13)及び式(14)=式(14’)の交点であるから、mの座標は、以下の連立方程式(16)の解となる。

Figure 2020204512
m c, since the intersection of the formula (13) and (14) = expression (14 '), the coordinates of m c is a solution of the following simultaneous equations (16).
Figure 2020204512

の座標(x,y)は、連立方程式(16)から求まる以下の式(17)によって表される。

Figure 2020204512
coordinates (, x y) of m c is expressed by the following equation obtained from the simultaneous equations (16) (17).
Figure 2020204512

同様にmは、式(14)=式(14’)及び式(15)=式(15’)の交点であるから、mの座標は、以下の連立方程式(18)の解となる。

Figure 2020204512
Similarly m a, since the intersection of the formula (14) = expression (14 ') and (15) = expression (15'), the coordinates of m a is a solution of the following simultaneous equations (18) ..
Figure 2020204512

の座標(x,y)は、連立方程式(18)から求まる以下の式(19)によって表される。

Figure 2020204512
coordinates (, x y) of m a is represented by the following equation obtained from the simultaneous equations (18) (19).
Figure 2020204512

同様にmは、式(13)及び式(15)=式(15’)の交点であるから、mの座標は、以下の連立方程式(20)の解となる。

Figure 2020204512
Similarly m b, since the intersection of the formula (13) and (15) = expression (15 '), the coordinates of m b is a solution of the following simultaneous equations (20).
Figure 2020204512

の座標(x,y)は、連立方程式(20)から求まる以下の式(21)によって表される。

Figure 2020204512
coordinates (, x y) of m b is expressed by the following equation obtained from the simultaneous equations (20) (21).
Figure 2020204512

,m,mを頂点とする三角形の重心mabcは、
abc=1/3×(m+m+m) (22)
であるから、mabcの座標は、以下の式(23)によって表される。

Figure 2020204512
m a, m b, the center of gravity m abc triangle whose vertices m c is
m abc = 1/3 × ( m a + m b + m c) (22)
Therefore, the coordinates of mabc are expressed by the following equation (23).
Figure 2020204512

このmabcを用いると、力率cosθのときの線間電流の電流ベクトルであるIiab,Iibc,Iicaは、以下の式となる。
iab=mabc−Iia=mabc−(x,y) (24)
ibc=mabc−Iic=mabc−(x,y) (25)
ica=mabc (26)
With this m abc, I iab a current vector of the line current when the power factor cos [theta], I ibc, I ica can be expressed as the following formula.
I iab = m abc -I ia = m abc - (x 1, y 1) (24)
I ibc = m abc -I ic = m abc - (x 2, y 2) (25)
I ica = mabc (26)

式(24)、式(25)、及び式(26)を用いて、力率cosθのときの線間電流の電流ベクトルであるIiab,Iibc,Iicaを求めたら、上記の説明のフローを逆順に辿る、すなわち、ノードiの線間電流を用いてノードiの区間通過電力を求め、ノードiの区間通過電力を用いて区間iの区間消費電力を求め、区間iの区間消費電力に含まれる有効電力ΔP及び無効電力ΔQからノードiの線間負荷を求め、ノードiの線間負荷を潮流計算の入力値とすることにより、不平衡電圧を求めることが可能となる。更には、この不平衡電圧に基づいて、振り替えるべき単相負荷の振替量を求めることが可能となる。 Equation (24), equation (25), and using equation (26), I iab a current vector of the line current when the power factor cos [theta], I ibc, After determining the I ica, flow of the description In other words, the line current of node i is used to obtain the section passing power of node i, the section passing power of node i is used to obtain the section power of section i, and the section power of section i is calculated. The unbalanced voltage can be obtained by obtaining the line load of the node i from the included active power ΔP i and the reactive power ΔQ i and using the line load of the node i as an input value for the power flow calculation. Further, based on this unbalanced voltage, it is possible to obtain the transfer amount of the single-phase load to be transferred.

〔4.本実施形態の効果〕
本実施形態による三相負荷按分方法は、三相配電線を有する配電系統の電圧不平衡を求めるための三相負荷按分方法であって、前記三相配電線の線間負荷が接続されるノードにおける線電流の計測値を、線間負荷を流れる線間電流の値に変換する変換ステップを有し、前記変換ステップは、前記線電流の電流ベクトルから構成される三角形において、単相負荷力率を固定し、無効電力が等しくなる中心点から、各頂点へのベクトルを線間電流とするステップである。
これにより、線間電流の電流ベクトルを計算する際、比較的低いコストしか発生しないと共に、実態からの乖離が比較的小さな三相負荷按分方法を提供することが可能となる。
[4. Effect of this embodiment]
The three-phase load apportionment method according to the present embodiment is a three-phase load apportionment method for obtaining a voltage imbalance of a distribution system having a three-phase distribution line, and is a line at a node to which the line-to-line load of the three-phase distribution line is connected. It has a conversion step that converts the measured value of the current into the value of the line current flowing through the line load, and the conversion step fixes the single-phase load power factor in the triangle composed of the current vector of the line current. Then, the step is to set the vector from the center point where the invalid powers are equal to each vertex as the line current.
This makes it possible to provide a three-phase load apportionment method in which a relatively low cost is incurred when calculating the current vector of the line current and the deviation from the actual state is relatively small.

また、本実施形態による三相負荷按分方法において、上記の線電流の値を線間負荷の電流ベクトルに変換するステップは、計測機能付き開閉器の計測値をベクトル値に変換する第1のサブステップと、このベクトル値に含まれる線電流の電流ベクトルで構成される第1の三角形の各頂点から、等力率で直線を延ばして第2の三角形を形成する第2のサブステップと、第2の三角形の重心を等力率等無効電力点とする第3のサブステップと、等力率等無効電力点から第1の三角形の各頂点に伸ばしたベクトルを、各線間負荷の電流ベクトルとする第4のサブステップと、を有する。
これにより、計測点通過電力の無効電力と区間内消費電力の無効電力を、三相平衡にできる。
Further, in the three-phase load apportionment method according to the present embodiment, the step of converting the above-mentioned line current value into the current vector of the line load is the first sub-setting of converting the measured value of the switch with measurement function into a vector value. A step and a second sub-step to form a second triangle by extending a straight line with an equal power factor from each vertex of the first triangle composed of the current vector of the linear current included in this vector value, and the second The third sub-step with the center of gravity of the triangle of 2 as the ineffective power point such as the equal power factor, and the vector extending from the ineffective power factor such as the equal power factor to each apex of the first triangle are used as the current vector of the interline load. It has a fourth sub-step to be performed.
As a result, the reactive power of the power passing through the measurement point and the reactive power of the power consumption in the section can be in three-phase equilibrium.

また、本実施形態による不平衡電圧計算方法は、上記の三相負荷按分方法を用いて、線間電流の電流ベクトルを求めるステップと、一次側の第1ノードでの前記線間電流と、二次側の第2ノードでの前記線間電流とから、前記第1ノードと前記第2ノードとの間の区間の通過電力を求めて該通過電力の差分をとり、前記区間の区間消費電力を求めるステップと、この区間消費電力を用いて不平衡電圧を計算するステップと、を有する。
これにより、高価な電圧不平衡対策機器を設置する必要なく、相間に電圧の偏りがない良質の電気を供給可能になると共に、電圧管理業務が容易になる。
Further, the unbalanced voltage calculation method according to the present embodiment includes a step of obtaining the current vector of the line current by using the above-mentioned three-phase load apportionment method, and the line current at the first node on the primary side. From the line current at the second node on the next side, the passing power of the section between the first node and the second node is obtained, the difference between the passing powers is taken, and the section power consumption of the section is calculated. It has a step of obtaining and a step of calculating an unbalanced voltage using this section power consumption.
This makes it possible to supply high-quality electricity with no voltage bias between the phases without the need to install expensive voltage imbalance countermeasure equipment, and facilitates voltage management work.

〔5.変形例〕
上記の実施形態では、数式を用いて等力率等無効電力点を求めたが、これとは異なる方法、例えば、作図をすることにより幾何学的に等力率等無効点を求めてもよい。
[5. Modification example]
In the above embodiment, the reactive power point such as the equal power factor is obtained by using a mathematical formula, but a different method, for example, the reactive point such as the equal power factor may be geometrically obtained by drawing. ..

1 配電系統
10 三相配電線
20 線間負荷
30 計測機能付き開閉器
abc 等力率等無効電力点
iab,Iibc,Iica 相電流の電流ベクトル
1 distribution system 10 Three-phase between distribution line 20 wire loads 30 instrumented switch m abc such power factor etc. the reactive power point I iab, I ibc, current vector I ica phase current

Claims (3)

三相配電線を有する配電系統の電圧不平衡を求めるための三相負荷按分方法において、
前記三相配電線の線間負荷が接続されるノードにおける線電流の計測値を、線間負荷を流れる線間電流の値に変換する変換ステップを有し、
前記変換ステップは、前記線電流の電流ベクトルから構成される三角形において、単相負荷力率を固定し、無効電力が等しくなる中心点から、各頂点へのベクトルを線間電流とするステップである、三相負荷按分方法。
In the three-phase load apportionment method for obtaining the voltage imbalance of a distribution system having a three-phase distribution wire,
It has a conversion step of converting the measured value of the line current at the node to which the line load of the three-phase distribution wire is connected into the value of the line current flowing through the line load.
The conversion step is a step in which the single-phase load power factor is fixed in a triangle composed of the current vectors of the line currents, and the vector from the center point where the reactive powers are equal to each vertex is used as the line current. , Three-phase load apportionment method.
前記変換ステップは、
計測機能付き開閉器の計測値をベクトル値に変換する第1のサブステップと、
前記ベクトル値に含まれる線電流の電流ベクトルで構成される第1の三角形の各頂点から、等力率で直線を延ばして第2の三角形を形成する第2のサブステップと、
前記第2の三角形の重心を等力率等無効電力点とする第3のサブステップと、
前記等力率等無効電力点から前記第1の三角形の各頂点に伸ばしたベクトルを、各線間負荷の電流ベクトルとする第4のサブステップと、
を有する、請求項1に記載の三相負荷按分方法。
The conversion step
The first sub-step to convert the measured value of the switch with measurement function into a vector value,
A second sub-step to form a second triangle by extending a straight line with an equal power factor from each vertex of the first triangle composed of the current vector of the linear current included in the vector value.
A third sub-step in which the center of gravity of the second triangle is a reactive power point such as the equal power factor, and
In the fourth substep, the vector extending from the reactive power point such as the equal power factor to each vertex of the first triangle is used as the current vector of the interline load.
The three-phase load apportionment method according to claim 1.
請求項1又は2に記載の三相負荷按分方法を用いて、線間電流の電流ベクトルを求めるステップと、
一次側の第1ノードでの前記線間電流と、二次側の第2ノードでの前記線間電流とから、前記第1ノードと前記第2ノードとの間の区間の通過電力を求めて該通過電力の差分をとり、前記区間の区間消費電力を求めるステップと、
前記区間消費電力を用いて不平衡電圧を計算するステップと、を有する不平衡電圧計算方法。
The step of obtaining the current vector of the line current by using the three-phase load apportionment method according to claim 1 or 2.
From the line current at the first node on the primary side and the line current at the second node on the secondary side, the passing power in the section between the first node and the second node is obtained. The step of taking the difference of the passing power and obtaining the section power consumption of the section, and
An unbalanced voltage calculation method comprising a step of calculating an unbalanced voltage using the section power consumption.
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