DE2653497A1

DE2653497A1 - Reciprocating electromagnetic motor - has rotor moving linearly between stator electromagnets and linked to crankshaft

Info

Publication number: DE2653497A1
Application number: DE19762653497
Authority: DE
Inventors: Wilhelm Klinsing
Original assignee: Individual
Current assignee: Individual
Priority date: 1976-11-25
Filing date: 1976-11-25
Publication date: 1978-06-01

Abstract

The motor consists of a reciprocating electromagnetic rotor driving a crankshaft (4) (which in turn drives a vehicle). The reciprocating rotor winding (3) interacts with two stator windings (1, 2) such that at one end like poles repel and the rotor is driven towards the other end. At the other end the polarity of either the rotor winding or the stator windings is reversed so that the rotor is repelled back again to the first end. The linear motion of the rotor is converted into rotary motion by a normal connecting rod and crankshaft.

Description

MagnetmotorMagnetic motor

Elt. Motor ohne Gegen BMK Der Aufbau des Magnetmotors entspricht im wesentlichen dem einea Binzinmotors im Kfz. Lediglich die Kolben müßen seitlich 2 sich gegenüber liegende Schlitze als Führung für die 2 Pleuelatangenverbindungen aufweisen.Elt. Motor without counter BMK The structure of the magnet motor corresponds to essentially the one Binzin engine in the vehicle. Only the pistons have to be on the side 2 opposing slots as a guide for the 2 connecting rods exhibit.

Wenn lt. folgender Berechnung eine Spule 0,15 Watt verbraucht, ergibt das einen Verbrauch von 3 X 0,15 = 0,45 Watt für einen Zylinder. Ein 4 Zylindermotor mit umgerechnet ca 100 PS würde demnach einen Stromverbrauch von nur 1,8 Watt haben.If, according to the following calculation, a coil consumes 0.15 watts, the result is that is a consumption of 3 X 0.15 = 0.45 watts for one cylinder. A 4 cylinder engine with the equivalent of around 100 hp, it would have a power consumption of only 1.8 watts.

Bei Annahme, daß die Berechnung annähernd richtig ist, müßte ein PKW mit einem derartigen Magnetmotor ohne weiterer mit 1 oder 2 Sutobatterien zu betreiben sein. Durch die vorhandene Lichtmaschine würden die Batterien zusätzlich noch nachgeladen.Assuming that the calculation is approximately correct, a car would have to to operate with such a magnetic motor without another with 1 or 2 Sutobatteries be. The batteries would also be recharged by the existing alternator.

Arbeitsweise eines Kolbens Der Kolben (W3) hat die gleiche Wicklung wie die obere und untere Statorwicklung (W1 u. W2). Der Kolben stellt den Rotor dar.How a piston works The piston (W3) has the same winding like the upper and lower stator winding (W1 and W2). The piston represents the rotor represent.

Abbildung 1) W3 ist als konstanter magnet geschaltet. Im oberen Scheitelpunkt wird W1 u. wa durch Drehung der Kurbelwelle über einen Verteilerfinger eingeschaltet. Jetzt stoßen sich oben zwei gleiche Pole ab und unten ziehen sich zwei ungleiche Pole an.Figure 1) W3 is connected as a constant magnet. In the upper vertex W1 and wa are switched on by turning the crankshaft via a distributor finger. Now two identical poles repel each other at the top and two unequal poles pull each other at the bottom Pole on.

Abbildung 2) Im unteren Drittel wird der Strom durch den Verteilerfinger ausgeschaltet. Durch die Stromunterbrechnung erfelgt eine wesentliche Kraftverstärkung. (Lenzache Regel) Abbildung 3) Im unteren Scheitelpunkt erfolgt erneut die Einschaltung wie in Abbildung 1, jedoch ia ungekehrten Sinn, sodaß aus dem Nordpool der Südpool wird.Figure 2) In the lower third, the current is through the distributor finger switched off. The power interruption results in a significant increase in force. (Lenzache rule) Figure 3) In the lower vertex, the activation takes place again As in Figure 1, but in general the opposite sense, so that the north pool becomes the south pool will.

Abbildung 4) Es erfolgt erneut die Ausschaltung.Figure 4) It is switched off again.

Nach erneuter Umschaltung erfolgt die Wiedereinschaltung wie in Abbildung 1.After switching over again, it is switched on again as shown in the figure 1.

Da die volle Kraft nur in unmittelbarer Nähe der Wicklungen 1 u 2 auftritt, sind für die Überbrückung des Zwischenraumes mehrere Zylinder (mindeatens 2-3) erforderlich.Since the full force is only available in the immediate vicinity of the windings 1 and 2 occurs, several cylinders (mineatens 2-3) required.

Wenn lt. folgender Berechnung eine Spule ca 650 kg leiatet, dann leistet ein Zylinder 4 X 650 = 2600 kg.If, according to the following calculation, a spool can hold approx. 650 kg, then it performs a cylinder 4 X 650 = 2600 kg.

Verbrauch einer Spule de s Magnetmotors I = 02025 A U = 6 V N = U . I = 6 . 0,025 = 0,15 W Ein herkölicher Elt. Motor würde für die gleiche Leistung einer Spule mit 8,79 PS = 8,79 X 736 W = 6469,44 W verbrauchen.Consumption of a coil of the magnet motor I = 02025 A U = 6 V N = U . I = 6. 0.025 = 0.15 W A traditional parent. Engine would for the same performance a coil with 8.79 HP = 8.79 X 736 W = 6469.44 W.

Berechnung Wicklung 1 d d = 10 cm U = d # = d = 10 cm U = d . # = 10 . 3,14 = 31,4 cm 10 . 3,14 = 31,4cm r = 5 cm F = r² . # = 5² . 3,13 = 78,5 cm 6 v # Drabtlänge = 31,4 . 3520 = 110528 cm = 1105,28 m C für Kupfer 0,017 q = 0,078 qmm # = 22 u 8 654 lt. Tabelle B = 14388 B =4 =g = 654 22 = 14388 = 650,45 = 8,70 PSCalculation of winding 1 dd = 10 cm U = d # = d = 10 cm U = d. # = 10. 3.14 = 31.4 cm 10. 3.14 = 31.4 cm r = 5 cm F = r². # = 5². 3.13 = 78.5 cm 6 v # Drab length = 31.4. 3520 = 110528 cm = 1105.28 m C for copper 0.017 q = 0.078 qmm # = 22 u 8 654 according to table B = 14388 B = 4 = g = 654 22 = 14388 = 650.45 = 8.70 hp

Claims

P a t e n t a n s p r u c h Title: Magnet motor Area of application: Power drive of an electric or gasoline engine.

Purpose: A gasoline engine produces considerable exhaust gases and an electrical engine generates significant back EMF. The magnetic motor does not generate either, state of the art: So far it was not possible to drive a car with one parent. To operate the engine economically.

Task: The magnetic motor can replace any motor.

Solution: Magnetic motor as a drive for every vehicle (PKN and truck) The vehicle would have to get the same or greater range with 1 - 2 normal car batteries like with a full tank of gasoline (thus no exhaust fumes). In addition, the engine could replace any previously common motor, for example. as a drive for a parent. Generator.

For a car engine, for example, the following calculation would result.

Consumption in A. = 1 winding I 0.025 A 1 cyl. - 0.025 A .3 = 0.075 A 4 cyl. = 0.075 A .4 = 0.3 A current consumption in W. = 1 winding i 0.15 W 1 cylinder = 0.15 . 3 = 0.45 W 4 cyl = 0.45. 4 - 1.8 W approx power 1 winding P - 659.45 kg = 8.79 PS 1 cyl. = 8.7 hp. 4 = 34.8 HP 4 cyl. = 34.8 hp. 4 = 139.2 HP Advantages: Because the Magnet motor does not generate any against FNK, it consumes much less electricity than a common parent. Engine.

Description with exemplary embodiment and drawing: is already included before.

Generic term: Magnetic motor as a power drive for all motor vehicles as well as the replacement of all previously known engines (gasoline and electrical engine) is more characteristic Part ; characterized in that this magnetic motor as an Elt.Motor does not have a rotatable Rotor and therefore cannot generate any back EMF.