CS200148B1 - Substituted n-(4-/phenoxy/butyl)piperidin-n-oxides and process for preparing them - Google Patents

Substituted n-(4-/phenoxy/butyl)piperidin-n-oxides and process for preparing them Download PDF

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CS200148B1
CS200148B1 CS36379A CS36379A CS200148B1 CS 200148 B1 CS200148 B1 CS 200148B1 CS 36379 A CS36379 A CS 36379A CS 36379 A CS36379 A CS 36379A CS 200148 B1 CS200148 B1 CS 200148B1
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butyl
piperidine
phenoxy
substituted
oxides
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CS36379A
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Czech (cs)
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Ivan Lacko
Ferdinand Devinsky
Ludovit Krasnec
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Ivan Lacko
Ferdinand Devinsky
Ludovit Krasnec
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Publication of CS200148B1 publication Critical patent/CS200148B1/en

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Description

Vynález sa týká substituovaných lí-( 4-(fenoxy)butyl)piperidín-N-oxidov obecného vzorcaThe invention relates to substituted 1- (4- (phenoxy) butyl) piperidine-N-oxides of the general formula

Oo-|C»2)4-0 .O - | C 2 2 4 -0.

R kde R znaiči: orto- metyl, metoxy, n-butyl, sec.butyl, terc.butyl, fenyl, cyklohexyl; meta- metoxy; para- metyl, metoxy, n-butyl, sec.butyl, terc.butyl, fenyl, cyklohexyl, terč. oktyl, n-nonyl a chlór a spósobu ich přípravy. Amínoxidy majú aj v priemyselnom meradle významné použitie. Používajú sa ako detergenčné a povrchovoaktlvne látky, stabilizátory pien, antioxidanty, antimikrobiáltfeúčlnné látky, kancerostatiká apod.. U zlúčenín, ktoré sú podstatou vynálezu, sa zistili doteraz neznáme účinky na mikroorganizmy B.subtilis a S,aureus, Ich antimikrobiálna aktivita bola vyššia alebo zrovnatelná s dezinfekčnými prostriedkami používanými v súčasnosti u nás.R wherein R is: ortho-methyl, methoxy, n-butyl, sec-butyl, tert-butyl, phenyl, cyclohexyl; methoxy; para-methyl, methoxy, n-butyl, sec-butyl, tert-butyl, phenyl, cyclohexyl, tert. octyl, n-nonyl and chloro and a process for their preparation. Amine oxides are also of significant industrial use. They are used as detergents and surfactants, foam stabilizers, antioxidants, antimicrobial agents, carcinostatics, etc. The compounds of the present invention have hitherto unknown effects on B.subtilis and S, aureus, whose antimicrobial activity was higher or comparable with disinfectants currently used in our country.

Amínoxidy je možné pripraviť niekolkými spósobmi, najvýhodnejáia je oxidácia peroxidom vodíka. Nové zlúčeniny sa pripravujú spósobom podía vynálezu, ktorého podstatou je, že sa oxiduje příslušný terciárny amin - substituovaný N-(4-(fenoxy)butyl)piperidín /význam sub'· stituentov je ten istý ako vyššie/ - 30% vodným roztokem peroxidu vodíka v metanole, pri teplote 60 °C počas 3 hodin. Oxidácia má oproti iným spósobom přípravy aminoxidov obecne tú výhodu, že vznikajú produkty vo vysokom výťažku, vysokej čistoty, za použitia len malé200 148The amine oxides can be prepared in several ways, most preferably oxidation with hydrogen peroxide. The novel compounds are prepared by a process according to the invention which comprises oxidizing the corresponding tertiary amine - substituted N- (4- (phenoxy) butyl) piperidine / the meaning of the substituents is the same as above / - 30% aqueous hydrogen peroxide solution in methanol at 60 ° C for 3 hours. Oxidation generally has the advantage over other methods for the preparation of amine oxides that they produce products in high yield, high purity, using only a small amount.

ZOO 148 ha množstva rozpúšťadla a reakčná doba je v porovnaní s inými metódami přípravy amínoxidov podstatné kratšia.The amount of solvent and the reaction time is substantially shorter compared to other methods for the preparation of amine oxides.

Na ilustráciu spósobu přípravy ako i niektorých fyzikálnych konštánt sú uvedené následovně příklady.To illustrate the preparation method as well as some physical constants, the following examples are given.

Příklad 1Example 1

Do roztoku 0,1 mol N-( 4-(o-metylfenoxy)butyl)piperidínu v 20 ml metanolu sa pri teplote 60 °C přidá 0,12 mol 30 % vodného roztoku peroxidu vodíka. Po přidaní oxidačného činidla sa nechá zmes reagovat ešte 3 hodiny. Po rozložení přebytečného peroxidu vodíka, odpaření vody a rozpúšťadla sa surový produkt prekryštalizuje niekolkokrát do konštantnej teploty topenia. Výťažok N-(4-(o-metylfenoxy)butyl)piperidín-N-oxidu je 87 X, t.t. 115 až 116 °C, elementárna analýza (vypočitané/nájdené X): 0=72,97/73,18, H=9,57/9,75, »=5,32/4,99, =219,273 nm.To a solution of 0.1 mol of N- (4- (o-methylphenoxy) butyl) piperidine in 20 ml of methanol at 60 ° C was added 0.12 mol of a 30% aqueous solution of hydrogen peroxide. After addition of the oxidizing agent, the mixture is allowed to react for a further 3 hours. After decomposition of excess hydrogen peroxide, evaporation of water and solvent, the crude product is recrystallized several times to a constant melting point. The yield of N- (4- (o-methylphenoxy) butyl) piperidine-N-oxide is 87%, m.p. 115-116 ° C, elemental analysis (calculated / found X):? = 72.97 / 73.18, H = 9.57 / 9.75,? = 5.32 / 4.99, = 219.273 nm.

ΙΙαΧΙΙαΧ

Příklad 2Example 2

Pracovný postup je ten istý ako v příklade 1, na oxidáciu sa však použil N-(4-(m-metoxyfenoxy)butyl)piperidín. Výťažok produktu je 88 X, t.t. 102 až 103 °C, elementárna analýza (vypočitané/nájdené X): 0=68,79/68,69, H=9,02/9,00, M«5,01/4,98, «221,277 nm.The procedure is the same as in Example 1, but N- (4- (m-methoxyphenoxy) butyl) piperidine was used for the oxidation. Yield: 88%, m.p. 102-103 ° C, elemental analysis (calculated / found X): δ = 68.79 / 68.69, H = 9.02 / 9.00, M δ 5.01 / 4.98, 221 221.277 nm.

Příklad 3Example 3

Pracovný postup je ten istý ako v příklade 1, na oxidáciu sa však použil N-(4-(p-n-butylfenoxy)butyl)piperidín. Výťažok produktu je 87 X, t.t. 116 až 117 °C, elementárna analýza (vypočitané/nájdené X): 0=74,71/74,58, H=10,23/10,421, N=4,58/4,41, λΒβχχ225,279 nm.The procedure is the same as in Example 1, but N- (4- (p-butylphenoxy) butyl) piperidine was used for the oxidation. The product yield is 87%, mp 116-117 ° C, elemental analysis (calculated / found X): 0 = 74.71 / 74.58, H = 10.23 / 10.42 1 , N = 4.58 / 4 , 41, λ ββ χ 225.279 nm.

Přiklad 4 ' Pracovný poetup je ten istý ako v příklade 1, na oxidáciu sa však použil N-(4-(o-sec. butylfenoxy)butyl)piperidín. Výťažok produktu je 84 X, t.t. 101 až 102 °C, elementárna analýza (vypočitané/nájdené X): 0=74,71/74,68, B*10,23/10,35, N=4,58/4,45,λ *218,272 nm.Example 4 The working procedure is the same as in Example 1, but N- (4- (o-sec. Butylphenoxy) butyl) piperidine was used for the oxidation. Yield: 84%, m.p. M.p. 101-102 ° C, elemental analysis (calculated / found X): 0 = 74.71 / 74.68, B * 10.23 / 10.35, N = 4.58 / 4.45, λ * 218.272 nm.

DHxDHx

Příklad 5Example 5

Pracovný postup je ten istý ako v příklade 1, na oxidáciu sat však použil N-(4-(p-terc.The procedure is the same as in Example 1, but using N- (4- (p-tert.

butylfenoxy)butyl)piperidín. Výťažok produktu je 85 % vo formě oleja, elementárna analýza (vypočitané/nájdené X)i 0=74,71/74,50, H=10,23/10,28, N=4,58/4,52,Λ„= 225,277 nm.butylphenoxy) butyl) piperidine. The product yield is 85% as an oil, elemental analysis (calculated / found X) 10 = 74.71 / 74.50, H = 10.23 / 10.28, N = 4.58 / 4.52, Λ " = 225.277 nm.

H(*xH (* x

Příklad 6Example 6

Pracovný poetup je ten istý ako v přiklade 1, na oxidáciu sa však použil N-(4-(o-fenylfenoxy)butyl{piperidín. Výťažok produktu je 90 X, t.t. 134 až 136 °C, elementárna analýza (vypočitané/nájdené X); 0=77,50/77,43, H=8,37/8,40, Ν=4,3β/4,27,λ Μχ“212.248 nm.The operating procedure is the same as in Example 1, but N- (4- (o-phenylphenoxy) butyl {piperidine) is used for the oxidation, yield 90%, m.p. ; 0 = 77.50 / 77.43, H = 8.37 / 8.40, Ν = 4.3β / 4.27, λ χχ 212.248 nm.

200 148200 148

Příklad 7Example 7

Pracovný postup je ten istý ako v příklade 1, na oxidáciu sa však použil N-(4-(p-chlór íenoxy)butyl)piperidín. Výťažok produktu je 81 %, t.t. 136 až 140 °C, elementárna analýza (vypočítané/nájdené %): 0=63,65/63,89, H= 7,83/8,01, N=4,94/4,78, =229,283 nm.The procedure is the same as in Example 1, but N- (4- (p-chlorophenoxy) butyl) piperidine was used for the oxidation. The product yield is 81%, m.p. 136-140 ° C, elemental analysis (calculated / found%): 0 = 63.65 / 63.89, H = 7.83 / 8.01, N = 4.94 / 4.78, = 229.283 nm.

maxmax

Příklad 8Example 8

Pracovný postup je ten istý ako v příklade 1, na oxidáciu sa však použil N-(4-{p-n-nonylíenoxy)butyl)piperidín. Výťažok produktu je 83 %; t.t. 93 až 96 °C; elementárna analýza (vypočítané/nájdené %): 0=76,75/76,50, »=11,00/11,29, N=3,73/3,80, ΛΒβχ=225,276 nm.The procedure is the same as in Example 1, but N- (4- (p-n-nonylphenoxy) butyl) piperidine was used for the oxidation. The yield of the product is 83%; mp 93-96 ° C; elemental analysis (calculated / found%): 0 = 76.75 / 76.50, »= 11.00 / 11.29, N = 3.73 / 3.80, Λβχ = 225.276 nm.

PREDMET VYNALEZUOBJECT OF THE INVENTION

Claims (2)

PREDMET VYNALEZUOBJECT OF THE INVENTION 1. Substituované N-(4-(fenoxy(butyl)piperidín-N-oxidy obecného vzorcaSubstituted N- (4- (phenoxy (butyl) piperidine-N-oxides) of the general formula O>0-|CH2|,.hQ .O> O- | CH 2 |, .hQ. R kde R značí: orto- metyl, metoxy, n-butyl, sec.butyl, terč.butyl, fenyl, cyklohexyl alebo meta- metoxy alebo para- metyl, metoxy, n-butyl, sec.butyl, terč.butyl, fenyl, cyklohexyl, terc.oktyl, n-nonyl a chlér.R where R represents: ortho-methyl, methoxy, n-butyl, sec-butyl, tert-butyl, phenyl, cyclohexyl or methoxy-or para-methyl, methoxy, n-butyl, sec-butyl, tert-butyl, phenyl , cyclohexyl, tert-octyl, n-nonyl and chloro. 2. Spdsob přípravy zlúčenin podlá bodu 1, vyznačujúci sa tým, že sa oxiduje substituovaný N-(4-(fenoxy,butyl)piperidín obecného vzorca2. A process for the preparation of compounds according to claim 1, characterized in that the substituted N- (4- (phenoxy, butyl) piperidine of the formula I) is oxidized. R kde R má ten istý význam ako v bode 1, 30 % vodným roztokom perovidu vodika pri teplote 60 °C, počas 3 hodin v.prostředí metanolu.Wherein R is as defined in point 1, with a 30% aqueous solution of hydrogen peroxide at 60 ° C for 3 hours in methanol.
CS36379A 1979-01-17 1979-01-17 Substituted n-(4-/phenoxy/butyl)piperidin-n-oxides and process for preparing them CS200148B1 (en)

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