CN116383942A - Design method and device for a main arch structure - Google Patents

Design method and device for a main arch structure Download PDF

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CN116383942A
CN116383942A CN202310366220.5A CN202310366220A CN116383942A CN 116383942 A CN116383942 A CN 116383942A CN 202310366220 A CN202310366220 A CN 202310366220A CN 116383942 A CN116383942 A CN 116383942A
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王柏生
龙杰烨
叶灵鹏
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Zhejiang University ZJU
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Abstract

本发明公开了一种木拱廊桥主拱结构的设计方法和装置,基于木拱廊桥传统营造技艺及现代工程学理论,使用本发明提出的设计方法确定在一定跨度下木拱廊桥主拱结构矢跨比与三节苗截面直径及长度,根据几何关系确定上、下小牛头位置及五节苗截面直径及长度。该发明可经济、合理、可靠地设计主拱结构矢跨比、苗杆长度与截面直径。传统木拱廊桥营造技艺存在可靠性不强、依据有限、依赖匠人经验等问题;现有的基于匠作谱系家族传承的设计方法因匠作谱系不同设计理念各不相同,且存在设计流程复杂、未经过现代力学的科学性验证等问题,在实际工程应用中难以保证安全性与经济性。本发明与传统方法相比拥有更高的鲁棒性,更加经济环保可靠,可以便捷可靠地设计出木拱廊桥主拱结构。

Figure 202310366220

The invention discloses a design method and device for the main arch structure of a wooden arched corridor bridge. Based on the traditional construction techniques of wooden arched corridor bridges and modern engineering theory, the design method proposed by the invention is used to determine the main arch structure of the wooden arched corridor bridge under a certain span. The arch structure rise-span ratio and the diameter and length of the section of the three-section seedling are determined according to the geometric relationship. The invention can economically, reasonably and reliably design the rise-span ratio of the main arch structure, the length of the stalk and the diameter of the section. The construction techniques of traditional wooden arch bridges have problems such as low reliability, limited basis, and dependence on the experience of craftsmen; the existing design methods based on the family inheritance of craftsmen's pedigree have different design concepts due to different craftsman's pedigree, and the design process is complicated. , have not been scientifically verified by modern mechanics, etc., it is difficult to guarantee safety and economy in practical engineering applications. Compared with the traditional method, the present invention has higher robustness, is more economical, environmentally friendly and reliable, and can conveniently and reliably design the main arch structure of the wooden arch bridge.

Figure 202310366220

Description

一种主拱结构的设计方法和装置Design method and device for a main arch structure

技术领域technical field

本发明涉及木结构拱桥设计领域,尤其涉及一种主拱结构的设计方法和装置。The invention relates to the design field of wooden arch bridges, in particular to a design method and device for a main arch structure.

背景技术Background technique

目前在自然因素和人为因素的影响下已有万安桥、文兴桥等数座珍贵的木拱廊桥被损伤与破坏。自2003年以来,寿宁、景宁与泰顺等地为复原地区历史人文气息原貌,更好地保护和传承木拱廊桥,重拾文化信仰,带动旅游产业,有选择的开始修复和重建木拱廊桥。但掌握木拱廊桥传统营造技艺的工匠人因多种原因锐减,营造技艺面临失传风险,且木拱廊桥的传统营造技艺仅通过匠人家族的经验积累口口相传而来,结构设计安全性缺乏现代科学理论的验证,无法充分展示中国木拱廊桥作为世界文化遗产的核心价值。At present, under the influence of natural factors and human factors, several precious wooden arched bridges such as Wan'an Bridge and Wenxing Bridge have been damaged and destroyed. Since 2003, Shouning, Jingning, Taishun and other places have selectively started repairing and rebuilding in order to restore the original appearance of the historical and cultural atmosphere of the area, better protect and inherit the wooden arch bridge, regain cultural beliefs, and drive the tourism industry. Wooden arcade bridge. However, the number of craftsmen who have mastered the traditional construction skills of wooden arched bridges has decreased sharply due to various reasons, and the construction skills are facing the risk of being lost. Moreover, the traditional construction skills of wooden arched bridges are only passed on through word of mouth through the experience of craftsmen's families, and the structural design is safe. It lacks the verification of modern scientific theory and cannot fully demonstrate the core value of Chinese wooden arched bridges as world cultural heritage.

因此,本发明结合传统营造技艺应用现代结构工程学理论,对木拱廊桥主拱结构开展设计。这个发明不仅是对木拱廊桥传统营造技艺的挖掘,也是保护目前遗存下的木拱廊桥的迫切需要,更是对木拱廊桥传统营造技艺的一种传承。本发明可以为将来木拱廊桥主拱结构重建设计、施工、修复加固等工程实际问题提供参考依据,具有较大的工程应用价值。Therefore, the present invention combines traditional construction techniques and applies modern structural engineering theory to design the main arch structure of the wooden arch bridge. This invention is not only an excavation of the traditional construction techniques of wooden arched corridor bridges, but also an urgent need to protect the remaining wooden arched corridor bridges, and it is also an inheritance of the traditional construction techniques of wooden arched corridor bridges. The invention can provide a reference basis for engineering practical problems such as reconstruction design, construction, repair and reinforcement of the main arch structure of the wooden arch corridor bridge in the future, and has great engineering application value.

发明内容Contents of the invention

本发明的目的在于针对现有技术的不足,提供了一种主拱结构的设计方法和装置。The object of the present invention is to provide a design method and device for a main arch structure aiming at the deficiencies of the prior art.

本发明的目的是通过以下技术方案来实现的:一种主拱结构的设计方法,包括以下步骤:The purpose of the present invention is achieved through the following technical solutions: a design method for the main arch structure, comprising the following steps:

步骤1:根据交通、景观需求及岸基条件选取合适的桥址,并根据桥址处河流宽度确定主拱结构的净跨L;Step 1: Select a suitable bridge site according to traffic, landscape requirements and shore foundation conditions, and determine the clear span L of the main arch structure according to the width of the river at the bridge site;

所述主拱结构包含三节苗系统和五节苗系统,所述三节苗系统包括第一三节苗斜苗S1、三节苗平苗S2、第二三节苗斜苗S3,其中,第一三节苗斜苗S1、三节苗平苗S2和第二三节苗斜苗S3的长度相同;所述五节苗系统包括第一五节苗下斜苗W1、第一五节苗上斜苗W2、五节苗平苗W3、第二五节苗上斜苗W4、第二五节苗下斜苗W5,其中,第一五节苗下斜苗W1和第二五节苗下斜苗W5的长度相同,第一五节苗上斜苗W2和第二五节苗上斜苗W4的长度相同;The main arch structure includes a three-section seedling system and a five-section seedling system, and the three-section seedling system includes the first three-section seedling inclined seedling S 1 , the three-section seedling flat seedling S 2 , and the second three-section seedling inclined seedling S 3 , wherein, The first three-section seedling inclined seedling S 1 , the three-section seedling flat seedling S 2 and the second three-section seedling inclined seedling S 3 have the same length; the five-section seedling system includes the first five-section seedling downward inclined seedling W 1 , the first Five-section seedlings with upward slope W 2 , five-section seedlings with flat seedlings W 3 , second and fifth-section seedlings with upward slopes W 4 , second-fifth-section seedlings with downward slopes W 5 , among them, first-fifth-section seedlings with downward slopes W 1 and the second and fifth section seedlings have the same length as the lower inclined seedling W 5 , the upper inclined seedling W 2 of the first and fifth section seedlings and the upper inclined seedling W 4 of the second and fifth section seedlings have the same length;

步骤2:设定初值矢跨比f1为0.17,计算第一三节苗斜苗S1、三节苗平苗S2和第二三节苗斜苗S3的长度和截面直径;Step 2: Set the initial rise-to-span ratio f 1 as 0.17, and calculate the length and cross-sectional diameter of the first three-section inclined seedling S 1 , the three-section flat seedling S 2 and the second three-section inclined seedling S 3 ;

步骤3:计算三节苗平苗S2的跨中应力σ与矢跨比f的关系,取三节苗平苗S2的跨中应力最小时对应的矢跨比作为矢跨比f2;使用矢跨比f2重新计算第一三节苗斜苗S1、三节苗平苗S2和第二三节苗斜苗S3的长度;Step 3: Calculate the relationship between the mid-span stress σ of the three-section flat seedling S 2 and the rise-span ratio f, and take the corresponding rise-span ratio when the mid-span stress of the three-section flat seedling S 2 is the smallest as the rise-span ratio f 2 ; Span ratio f 2 recalculates the lengths of the first three-section seedling inclined seedling S 1 , the three-section seedling flat seedling S 2 and the second three-section seedling inclined seedling S 3 ;

步骤4:基于矢跨比f2及净跨L,计算第一五节苗下斜苗W1、第一五节苗上斜苗W2、五节苗平苗W3、第二五节苗上斜苗W4、第二五节苗下斜苗W5的长度和截面直径;Step 4: Based on the rise-to-span ratio f 2 and the clear span L, calculate W 1 for the first and fifth section seedlings, W 2 for the first and fifth section seedlings, W 3 for the fifth section seedlings, and W 3 for the second and fifth section seedlings The length and cross-sectional diameter of the upward inclined seedling W 4 and the second fifth joint seedling downward inclined seedling W 5 ;

步骤5:根据步骤3求得的第一三节苗斜苗S1、三节苗平苗S2和第二三节苗斜苗S3的长度、步骤2求得的第一三节苗斜苗S1、三节苗平苗S2和第二三节苗斜苗S3的截面直径以及步骤4求得的第一五节苗下斜苗W1、第一五节苗上斜苗W2、五节苗平苗W3、第二五节苗上斜苗W4、第二五节苗下斜苗W5的长度和截面直径建立主拱结构的有限元模型,计算主拱结构所有杆件的应力及挠度,若主拱结构的部分杆件的应力或挠度超过《木结构设计标准》GB50005-2017所规定的限值时,增大超限杆件的截面直径后再次计算主拱结构所有杆件的应力及挠度,直到主拱结构所有杆件的应力及挠度均小于规范限值。Step 5: According to the lengths of the first three-node oblique seedling S 1 , the three-node flat seedling S 2 and the second three-node oblique seedling S 3 obtained in step 3, and the first three-node oblique seedling obtained in step 2 S 1 , the cross-sectional diameters of the flat seedlings S 2 of the three-section seedlings and the inclined seedlings S 3 of the second and third-section seedlings, and the lower inclined seedlings W 1 of the first and fifth section seedlings, the upper inclined seedlings W 2 of the first and fifth section seedlings obtained in step 4, Establish the finite element model of the main arch structure based on the length and cross-sectional diameter of the five-section flat seedling W 3 , the second-fifth-section up-slope W 4 , and the second-fifth-section down-slope W 5 , and calculate all the members of the main arch structure If the stress or deflection of some members of the main arch structure exceeds the limit specified in the "Standards for Design of Timber Structures" GB50005-2017, increase the cross-sectional diameter of the overrunning members and recalculate all the members of the main arch structure. The stress and deflection of the members until the stress and deflection of all the members of the main arch structure are less than the specification limit.

进一步地,所述步骤2具体包括以下子步骤:Further, the step 2 specifically includes the following sub-steps:

步骤2.1:设定主拱结构的初值矢跨比f1为0.17,利用公式(1)计算得到第一三节苗斜苗S1、三节苗平苗S2和第二三节苗斜苗S3的长度l1Step 2.1: Set the initial rise-span ratio f 1 of the main arch structure to 0.17, and use the formula (1) to calculate the first three-section inclined seedling S 1 , the three-section flat seedling S 2 and the second three-section inclined seedling The length l 1 of S 3 :

Figure BDA0004166798170000021
Figure BDA0004166798170000021

步骤2.2:所述第一三节苗斜苗S1和第二三节苗斜苗S3的截面直径均为D1,所述三节苗平苗S2的截面直径为D2;设计第一三节苗斜苗S1和第二三节苗斜苗S3的截面直径不小于11.4l1+226,以及三节苗平苗S2的截面直径不小于10.8l1+211。Step 2.2: The cross-sectional diameters of the first three-section seedling S1 and the second three-section seedling S3 are both D1 , and the cross-section diameter of the three-section flat seedling S2 is D2 ; design the first The cross-section diameters of the three-section oblique seedling S 1 and the second three-section oblique seedling S 3 are not less than 11.4l 1 +226 , and the cross-section diameter of the three-section flat seedling S 2 is not less than 10.8l 1 +211 .

进一步地,所述步骤3具体包括以下子步骤:Further, the step 3 specifically includes the following sub-steps:

步骤3.1:取三节苗系统的左半部作为力法基本体系,通过以下公式计算三节苗平苗S2的跨中应力σ:Step 3.1: Take the left half of the three-section seedling system as the basic system of the force method, and calculate the mid-span stress σ of the three-section seedling flat seedling S 2 by the following formula:

Figure BDA0004166798170000022
Figure BDA0004166798170000022

其中,M为三节苗平苗S2的跨中弯矩,计算公式如下:Among them, M is the mid-span bending moment of the three-section flat seedling S2 , and the calculation formula is as follows:

Figure BDA0004166798170000023
Figure BDA0004166798170000023

其中,系数δ11的计算公式为

Figure BDA0004166798170000024
自由项Δ1P的计算公式为/>
Figure BDA0004166798170000031
Among them, the calculation formula of the coefficient δ11 is
Figure BDA0004166798170000024
The calculation formula of the free term Δ 1P is />
Figure BDA0004166798170000031

其中,l为当矢跨比为f时第一三节苗斜苗S1、三节苗平苗S2和第二三节苗斜苗S3的长度;θ为当矢跨比为f时第一五节苗下斜苗W1与水平面的夹角以及第一三节苗斜苗S1与水平面的夹角;θ=arcsin(H/l),H=f*L,H为主拱结构的矢高;E为弹性模量;I1为第一三节苗斜苗S1和第二三节苗斜苗S3的截面惯性矩,I2为三节苗平苗S2的截面惯性矩;q为均布荷载值;Among them, l is the length of the first three-section oblique seedling S 1 , the three-section flat seedling S 2 and the second three-section oblique seedling S 3 when the rise-span ratio is f; The included angle between the inclined seedling W 1 of the first five-section seedling and the horizontal plane and the angle between the inclined seedling S 1 of the first three-section seedling and the horizontal plane; θ=arcsin(H/l), H=f*L, and H is the main arch structure E is the modulus of elasticity; I 1 is the section moment of inertia of the first three-section inclined seedling S 1 and the second three-section inclined seedling S 3 , and I 2 is the section moment of inertia of the three-section flat seedling S 2 ; q is the uniform load value;

通过第一三节苗斜苗S1的底部与水平面的交点为原点建立力矩平衡方程,推导得三节苗平苗S2的轴力F:The moment balance equation is established by using the intersection point of the bottom of the inclined seedling S 1 of the first three-section seedling and the horizontal plane as the origin, and the axial force F of the three-section flat seedling S 2 is derived:

Figure BDA0004166798170000032
Figure BDA0004166798170000032

式中,F1为三节苗系统的受外荷载,其值为0.135qL,作用位置为三节苗平苗S2左右各1/4位置处;F2为三节苗系统的受外荷载,其值为0.205qL,作用位置为第一三节苗斜苗S1与三节苗平苗S2交点处;In the formula, F 1 is the external load of the three-section seedling system, its value is 0.135qL, and the acting position is the 1/4 position of the three-section seedling flat seedling S 2 ; F 2 is the external load of the three-section seedling system, and its value is 0.205qL, and the action position is at the intersection of the first three-section seedling oblique seedling S 1 and the three-section flat seedling S 2 ;

通过公式(2)-公式(4),得到三节苗平苗S2的跨中应力σ与矢跨比f的关系;Through the formula (2) - formula (4), the relationship between the mid-span stress σ and the rise-span ratio f of the three-section seedling flat seedling S2 is obtained;

步骤3.2:基于步骤3.1确定的三节苗平苗S2的跨中应力σ与矢跨比f的关系,取三节苗平苗S2的跨中应力最小时对应的矢跨比作为矢跨比f2;使用矢跨比f2通过公式(1)重新计算第一三节苗斜苗S1、三节苗平苗S2和第二三节苗斜苗S3的长度,为l2Step 3.2: Based on the relationship between the mid-span stress σ of the three-section flat seedling S 2 determined in step 3.1 and the rise-span ratio f, take the corresponding rise-span ratio when the mid-span stress of the three-section flat seedling S 2 is the smallest as the rise-span ratio f 2 ; recalculate the lengths of the first three-section oblique seedling S 1 , the three-section flat seedling S 2 , and the second three-section oblique seedling S 3 through formula ( 1 ) using the rise-span ratio f 2 , which is l 2 .

进一步地,所述步骤4具体包括以下子步骤:Further, the step 4 specifically includes the following sub-steps:

步骤4.1:基于矢跨比f2,求得θ2=arcsin(H2/l2),H2=f2*L;以第一三节苗斜苗S1与水平面的交点为原点,纵桥向为x轴,竖桥向为y轴建立平面坐标系,确定第一三节苗斜苗S1与三节苗平苗S2的交点的坐标为(x3,y3),其中,

Figure BDA0004166798170000033
y3=f2L;Step 4.1 : Calculate θ 2 =arcsin(H 2 /l 2 ), H 2 =f 2 *L based on the span ratio f 2 The bridge direction is the x axis, and the vertical bridge direction is the y axis to establish a plane coordinate system, and it is determined that the coordinates of the intersection point of the oblique seedling S 1 of the first three-section seedling and the flat seedling S 2 of the three-section seedling are (x 3 , y 3 ), wherein,
Figure BDA0004166798170000033
y 3 =f 2 L;

步骤4.2:确定第一五节苗下斜苗W1与第一五节苗上斜苗W2的交点的坐标为(x6,y6),其中,

Figure BDA0004166798170000034
Step 4.2: Determine the coordinates of the intersection point of the downward slanting seedling W 1 of the first fifth section seedling and the upward slanting seedling W 2 of the first fifth section seedling as (x 6 , y 6 ), where,
Figure BDA0004166798170000034

式中,β为第一五节苗下斜苗W1与第一五节苗上斜苗W2的长度比,计算公式如下:In the formula, β is the length ratio of the downward slanting seedling W 1 of the first fifth section seedling to the upper slanting seedling W 2 of the first fifth section seedling, and the calculation formula is as follows:

Figure BDA0004166798170000035
Figure BDA0004166798170000035

随后确定第一五节苗下斜苗W1与竖直面的交点的坐标为(x5,y5),其中,x5=0,

Figure BDA0004166798170000041
Determine subsequently that the coordinates of the intersection point of the inclined seedling W 1 and the vertical plane of the first fifth section seedling are (x 5 , y 5 ), wherein, x 5 =0,
Figure BDA0004166798170000041

再确定第一五节苗上斜苗W2与五节苗平苗W3的交点的坐标为(x8,y8),其中,

Figure BDA0004166798170000042
y8=y3+h;其中,k为第一五节苗上斜苗W2的斜率,
Figure BDA0004166798170000043
h为第一五节苗上斜苗W2与五节苗平苗W3的交点到第一三节苗斜苗S1的垂直距离,h=L/80;Determine again that the coordinates of the intersection of the first five-section seedling on the oblique seedling W 2 and the five-section seedling flat seedling W 3 are (x 8 , y 8 ), wherein,
Figure BDA0004166798170000042
y 8 =y 3 +h; among them, k is the slope of the slope seedling W 2 of the first and fifth seedlings,
Figure BDA0004166798170000043
h is the vertical distance from the intersection point of the first five-section seedling on the inclined seedling W 2 and the fifth-section seedling flat seedling W 3 to the first three-section seedling inclined seedling S1, h=L/80;

计算得到第一五节苗下斜苗W1和第二五节苗下斜苗W5的长度P1

Figure BDA0004166798170000044
Calculate the length P 1 of the first and fifth section seedlings with downward slope W 1 and the second fifth section with downward slope W 5 ,
Figure BDA0004166798170000044

计算得到第一五节苗上斜苗W2和第二五节苗上斜苗W4的长度P2

Figure BDA0004166798170000045
Calculate the length P 2 of the slanting seedling W 2 of the first fifth section seedling and the slanting seedling W 4 of the second fifth section seedling,
Figure BDA0004166798170000045

计算得到五节苗平苗W3的长度P3,P3=L-2x8Calculate the length P 3 of the five-section seedling flat seedling W 3 , P 3 =L-2x 8 ;

步骤4.3:所述第一五节苗下斜苗W1和第二五节苗下斜苗W5的截面直径均为D3,所述第一五节苗上斜苗W2和第二五节苗上斜苗W4的截面直径均为D4,所述五节苗平苗W3的截面直径均为D5;设计第一五节苗下斜苗W1和第二五节苗下斜苗W5的截面直径D3不小于9.4P1+217,第一五节苗上斜苗W2和第二五节苗上斜苗W4的截面直径D4不小于11.5P2+183,以及五节苗平苗W3的截面直径D5不小于13.3P3+230。Step 4.3: The section diameters of the first and fifth section seedlings W 1 and the second fifth section seedlings W 5 are both D 3 , and the first and fifth section seedlings W 2 and the second fifth section are both D 3 . The cross-section diameters of the upper inclined seedlings W 4 of the section seedlings are all D 4 , and the cross-sectional diameters of the flat seedlings W 3 of the five-section seedlings are all D 5 ; The cross-sectional diameter D 3 of the oblique seedling W 5 is not less than 9.4P 1 +217, the cross-sectional diameter D 4 of the oblique seedling W 2 of the first and fifth section seedlings and the upper oblique seedling W 4 of the second fifth section seedling is not less than 11.5P 2 +183 , and the cross-sectional diameter D 5 of the five-section seedling flat seedling W 3 is not less than 13.3P 3 +230.

本发明还提供了一种主拱结构的设计装置,包括一个或多个处理器,用于实现上述主拱结构的设计方法。The present invention also provides a design device for a main arch structure, including one or more processors for realizing the above-mentioned design method for a main arch structure.

本发明还提供一种计算机可读存储介质,其上存储有程序,该程序被处理器执行时,用于实现上述主拱结构的设计方法。The present invention also provides a computer-readable storage medium, on which a program is stored, and when the program is executed by a processor, it is used to realize the design method of the above-mentioned main arch structure.

本发明的有益效果在于:The beneficial effects of the present invention are:

(1)本发明中的矢跨比确定方法,能快速确定主拱结构矢跨比取值,在减小主拱结构建造耗材的同时,使主拱结构在相同荷载作用下三节苗平苗应力最小;(1) The method for determining the rise-span ratio in the present invention can quickly determine the value of the rise-span ratio of the main arch structure, and while reducing the construction consumables of the main arch structure, the stress of the three-section seedling flat seedling of the main arch structure can be made under the same load minimum;

(2)本发明中确定牛头坐标的方法,有利于主拱结构受力。此外用数学式表达主拱结构各节点间的关系,便于快速准确地计算出五节苗系统各苗杆长度;(2) The method for determining the coordinates of the bull's head in the present invention is beneficial to the stress of the main arch structure. In addition, the relationship between the nodes of the main arch structure is expressed by mathematical expressions, which is convenient for quickly and accurately calculating the length of each seedling stem of the five-section seedling system;

(3)本发明中的苗杆截面直径设计公式实现了苗杆构件截面的快速设计选取;(3) the seedling stalk section diameter design formula among the present invention has realized the rapid design selection of the stalk component section;

附图说明Description of drawings

图1为一种主拱结构的设计方法的流程图;Fig. 1 is the flowchart of a kind of design method of main arch structure;

图2为主拱结构的示意图;Fig. 2 is a schematic diagram of the main arch structure;

图3为三节苗系统的示意图;Fig. 3 is the schematic diagram of three section seedling system;

图4为三节苗系统的力法求解弯矩图,其中,图4(a)为三节苗系统半结构示意图,图4(b)为单位力作用下结构静定基的弯矩图,图4(c)为原结构荷载作用在该结构静定基上的弯矩图;Fig. 4 is the bending moment diagram solved by the force method of the three-section seedling system, wherein, Fig. 4 (a) is a schematic diagram of the semi-structure of the three-section seedling system, Fig. 4 (b) is the bending moment diagram of the statically determinate foundation of the structure under the action of unit force, and Fig. 4 ( c) is the bending moment diagram of the original structure load acting on the statically determinate foundation of the structure;

图5为三节苗平苗S2的跨中应力σ与矢跨比f的关系图;Fig. 5 is a relationship diagram between mid-span stress σ and rise-span ratio f of three-section seedling flat seedling S2 ;

图6为主拱结构的有限元模型的示意图;Fig. 6 is a schematic diagram of the finite element model of the main arch structure;

图7为一种主拱结构的设计装置的结构图。Fig. 7 is a structural diagram of a design device for a main arch structure.

具体实施方式Detailed ways

为了使本发明的目的、技术方案及优点更加明白清楚,结合附图和实施例,对本发明进一步的详细说明,应当理解,此处所描述的具体实施例仅仅用以解释本发明,而不是全部的实施例。基于本发明中的实施例,本领域普通技术人员在没有做出创造性劳动前提下所获得的所有其他实施例,均在本发明保护范围。In order to make the objectives, technical solutions and advantages of the present invention clearer, the present invention will be further described in detail in conjunction with the accompanying drawings and embodiments. It should be understood that the specific embodiments described here are only used to explain the present invention, rather than all Example. Based on the embodiments of the present invention, all other embodiments obtained by persons of ordinary skill in the art without making creative efforts are within the protection scope of the present invention.

如图1所示,本发明提供了一种木拱廊桥主拱结构的设计方法,包括以下步骤:As shown in Figure 1, the present invention provides a kind of design method of the main arch structure of wooden arched corridor bridge, comprises the following steps:

步骤1:根据交通、景观需求及岸基条件选取合适的桥址,并根据桥址处河流宽度确定主拱结构的净跨L,净跨L与桥址处河流宽度基本相同。Step 1: Select a suitable bridge site according to traffic, landscape requirements and shore foundation conditions, and determine the clear span L of the main arch structure according to the width of the river at the bridge site. The clear span L is basically the same as the width of the river at the bridge site.

如图2所示,所述主拱结构包含三节苗系统和五节苗系统,所述三节苗系统包括第一三节苗斜苗S1、三节苗平苗S2、第二三节苗斜苗S3,其中,第一三节苗斜苗S1、三节苗平苗S2和第二三节苗斜苗S3的长度相同;所述五节苗系统包括第一五节苗下斜苗W1、第一五节苗上斜苗W2、五节苗平苗W3、第二五节苗上斜苗W4、第二五节苗下斜苗W5,其中,第一五节苗下斜苗W1和第二五节苗下斜苗W5的长度相同,第一五节苗上斜苗W2和第二五节苗上斜苗W4的长度相同。As shown in Figure 2, the main arch structure includes a three-section seedling system and a five-section seedling system, and the three-section seedling system includes the first three-section seedling inclined seedling S 1 , the three-section Seedling S 3 , wherein the lengths of the first three-section seedling inclined seedling S 1 , the three-section seedling flat seedling S 2 and the second three-section seedling oblique seedling S 3 are the same; the five-section seedling system includes the first five-section seedling downward oblique Seedling W 1 , up-slanting seedlings W 2 of the first and fifth joints, flat seedlings of the fifth joints W 3 , upward-slanting seedlings of the second and fifth joints W 4 , downward-slanting seedlings of the second and fifth joints W 5 , of which, the first and fifth joints The lengths of the lower oblique seedlings W 1 of the node seedlings and the lower oblique seedlings W 5 of the second and fifth node seedlings are the same, and the lengths of the upper oblique seedlings W 2 of the first and fifth node seedlings and the upper oblique seedlings W 4 of the second and fifth node seedlings are the same.

本实施例中,所述主拱结构为某预建木拱廊桥的主拱结构,净跨L为29.5m。In this embodiment, the main arch structure is the main arch structure of a pre-built wooden arch bridge, and the clear span L is 29.5m.

步骤2:设定初值矢跨比f1为0.17,计算第一三节苗斜苗S1、三节苗平苗S2和第二三节苗斜苗S3的长度和截面直径。Step 2: Set the initial rise-to-span ratio f 1 as 0.17, and calculate the length and cross-sectional diameter of the first three-section oblique seedling S 1 , the three-section flat seedling S 2 , and the second three-section oblique seedling S 3 .

所述步骤2具体包括以下子步骤:The step 2 specifically includes the following sub-steps:

步骤2.1:设定主拱结构的初值矢跨比f1为0.17,利用公式(1)计算得到第一三节苗斜苗S1、三节苗平苗S2和第二三节苗斜苗S3的长度l1Step 2.1: Set the initial rise-span ratio f 1 of the main arch structure to 0.17, and use the formula (1) to calculate the first three-section inclined seedling S 1 , the three-section flat seedling S 2 and the second three-section inclined seedling The length l 1 of S 3 :

Figure BDA0004166798170000051
Figure BDA0004166798170000051

在本实施例中计算得到第一三节苗斜苗S1、三节苗平苗S2和第二三节苗斜苗S3的长度l1为10.67m。In this embodiment, the length l 1 of the first three-section seedling inclined seedling S 1 , the three-section seedling flat seedling S 2 and the second three-section seedling inclined seedling S 3 is calculated to be 10.67 m.

步骤2.2:所述第一三节苗斜苗S1和第二三节苗斜苗S3的截面直径均为D1,所述三节苗平苗S2的截面直径为D2;设计第一三节苗斜苗S1和第二三节苗斜苗S3的截面直径不小于11.4l1+226,以及三节苗平苗S2的截面直径不小于10.8l1+211。Step 2.2: The cross-sectional diameters of the first three-section seedling S1 and the second three-section seedling S3 are both D1 , and the cross-section diameter of the three-section flat seedling S2 is D2 ; design the first The cross-section diameters of the three-section oblique seedling S 1 and the second three-section oblique seedling S 3 are not less than 11.4l 1 +226 , and the cross-section diameter of the three-section flat seedling S 2 is not less than 10.8l 1 +211 .

在本实施例中设计第一三节苗斜苗S1和第二三节苗斜苗S3的截面直径D1为327mm,并设计三节苗平苗S2的截面直径D2为347mm。In the present embodiment, the cross- sectional diameter D 1 of the first three-section seedling inclined seedling S 1 and the second three-section seedling inclined seedling S 3 is designed to be 327 mm, and the cross-sectional diameter D 2 of the three-section seedling flat seedling S 2 is designed to be 347 mm.

步骤3:计算三节苗平苗S2的跨中应力σ与矢跨比f的关系,取三节苗平苗S2的跨中应力最小时对应的矢跨比作为矢跨比f2;使用矢跨比f2重新计算第一三节苗斜苗S1、三节苗平苗S2和第二三节苗斜苗S3的长度。Step 3: Calculate the relationship between the mid-span stress σ of the three-section flat seedling S 2 and the rise-span ratio f, and take the corresponding rise-span ratio when the mid-span stress of the three-section flat seedling S 2 is the smallest as the rise-span ratio f 2 ; Span ratio f 2 recalculates the lengths of the first three-section seedling inclined seedling S 1 , the three-section seedling flat seedling S 2 and the second three-section seedling inclined seedling S 3 .

所述步骤3具体包括以下子步骤:The step 3 specifically includes the following sub-steps:

步骤3.1:取三节苗系统的左半部作为力法基本体系,通过以下公式计算三节苗平苗S2的跨中应力σ:Step 3.1: Take the left half of the three-section seedling system as the basic system of the force method, and calculate the mid-span stress σ of the three-section seedling flat seedling S 2 by the following formula:

Figure BDA0004166798170000061
Figure BDA0004166798170000061

其中,M为三节苗平苗S2的跨中弯矩,计算公式如下:Among them, M is the mid-span bending moment of the three-section flat seedling S2 , and the calculation formula is as follows:

Figure BDA0004166798170000062
Figure BDA0004166798170000062

其中,系数δ11的计算公式为

Figure BDA0004166798170000063
自由项Δ1P的计算公式为/>
Figure BDA0004166798170000064
Among them, the calculation formula of the coefficient δ11 is
Figure BDA0004166798170000063
The calculation formula of the free term Δ 1P is />
Figure BDA0004166798170000064

其中,l为当矢跨比为f时第一三节苗斜苗S1、三节苗平苗S2和第二三节苗斜苗S3的长度;θ为当矢跨比为f时第一五节苗下斜苗W1与水平面的夹角以及第一三节苗斜苗S1与水平面的夹角,第一五节苗下斜苗W1与第一三节苗斜苗S1平行;θ=arcsin(H/l),H=f*L,H为主拱结构的矢高;E为弹性模量;I1为第一三节苗斜苗S1和第二三节苗斜苗S3的截面惯性矩,I2为三节苗平苗S2的截面惯性矩;q为均布荷载值,可取为1kN/m;f为矢跨比。Among them, l is the length of the first three-section oblique seedling S 1 , the three-section flat seedling S 2 and the second three-section oblique seedling S 3 when the rise-span ratio is f; The angle between W 1 of the first and fifth section seedlings and the horizontal plane, and the angle between the first and third section seedlings S 1 and the horizontal plane, the angle between the first and fifth section seedlings W 1 and the first and third section seedlings S 1 Parallel; θ =arcsin(H/ l ), H=f*L, H is the vector height of the main arch structure; E is the modulus of elasticity; The section moment of inertia of seedling S 3 , I 2 is the section moment of inertia of three-section flat seedling S 2 ; q is the uniformly distributed load value, which can be taken as 1kN/m; f is the rise-span ratio.

通过第一三节苗斜苗S1的底部与水平面的交点为原点建立力矩平衡方程,推导得三节苗平苗S2的轴力F:The moment balance equation is established by using the intersection point of the bottom of the inclined seedling S 1 of the first three-section seedling and the horizontal plane as the origin, and the axial force F of the three-section flat seedling S 2 is derived:

Figure BDA0004166798170000071
Figure BDA0004166798170000071

式中,F1为三节苗系统的受外荷载,其值为0.135qL,作用位置为三节苗平苗S2左右各1/4位置处;F2为三节苗系统的受外荷载,其值为0.205qL,作用位置为第一三节苗斜苗S1与三节苗平苗S2交点处,如图3和图4所示。In the formula, F 1 is the external load of the three-section seedling system, its value is 0.135qL, and the acting position is the 1/4 position of the three-section seedling flat seedling S 2 ; F 2 is the external load of the three-section seedling system, and its value 0.205qL, and the action location is at the intersection of the first three-node oblique seedling S 1 and the three-node flat seedling S 2 , as shown in Figure 3 and Figure 4.

通过公式(2)-公式(4),得到三节苗平苗S2的跨中应力σ与矢跨比f的关系。Through the formula (2) - formula (4), the relationship between the mid-span stress σ and the rise-span ratio f of the three-section seedling and flat seedling S 2 is obtained.

在本实施例中,三节苗平苗S2的跨中应力σ与矢跨比f的关系如图5所示。In this embodiment, the relationship between the mid-span stress σ and the rise-span ratio f of the three-section seedling and flat seedling S2 is shown in Fig. 5 .

步骤3.2:基于步骤3.1确定的三节苗平苗S2的跨中应力σ与矢跨比f的关系,取三节苗平苗S2的跨中应力最小时对应的矢跨比作为矢跨比f2;使用矢跨比f2通过公式(1)重新计算第一三节苗斜苗S1、三节苗平苗S2和第二三节苗斜苗S3的长度,为l2Step 3.2: Based on the relationship between the mid-span stress σ of the three-section flat seedling S 2 determined in step 3.1 and the rise-span ratio f, take the corresponding rise-span ratio when the mid-span stress of the three-section flat seedling S 2 is the smallest as the rise-span ratio f 2 ; recalculate the lengths of the first three-section oblique seedling S 1 , the three-section flat seedling S 2 , and the second three-section oblique seedling S 3 through formula ( 1 ) using the rise-span ratio f 2 , which is l 2 .

本实施例中,从图5可以得到,三节苗平苗S2的跨中应力最小时对应的矢跨比的值为0.175,即矢跨比f2=0.175;使用矢跨比f2=0.175通过公式(1)再次计算第一三节苗斜苗S1、三节苗平苗S2和第二三节苗斜苗S3的长度,得到l2=10.72m。In this embodiment, it can be obtained from Fig. 5 that when the mid-span stress of the three-section seedling S2 is the smallest, the corresponding rise-span ratio value is 0.175, that is, the rise-span ratio f 2 =0.175; the use rise-span ratio f 2 =0.175 The lengths of the first three-node oblique seedling S 1 , the three-node flat seedling S 2 and the second three-node oblique seedling S 3 are calculated again by formula (1), and l 2 =10.72m is obtained.

步骤4:基于矢跨比f2及净跨L,计算第一五节苗下斜苗W1、第一五节苗上斜苗W2、五节苗平苗W3、第二五节苗上斜苗W4、第二五节苗下斜苗W5的长度和截面直径;Step 4: Based on the rise-to-span ratio f 2 and the clear span L, calculate W 1 for the first and fifth section seedlings, W 2 for the first and fifth section seedlings, W 3 for the fifth section seedlings, and W 3 for the second and fifth section seedlings The length and cross-sectional diameter of the upward inclined seedling W 4 and the second fifth joint seedling downward inclined seedling W 5 ;

所述步骤4具体包括以下子步骤:The step 4 specifically includes the following sub-steps:

步骤4.1:基于矢跨比f2,求得θ2=arcsin(H2/l2),H2=f2*L;如图3所示,以第一三节苗斜苗S1与水平面的交点为原点,纵桥向为x轴,竖桥向为y轴建立平面坐标系,坐标为(0,0),确定第一三节苗斜苗S1与三节苗平苗S2的交点的坐标为(x3,y3),其中,

Figure BDA0004166798170000072
Step 4.1: Calculate θ 2 =arcsin(H 2 /l 2 ), H 2 =f 2 *L based on the rise-span ratio f 2 ; The point of intersection is the origin, the longitudinal bridge direction is the x-axis, and the vertical bridge direction is the y-axis to establish a plane coordinate system, the coordinates are (0,0), determine the intersection point of the first three-section seedling inclined seedling S 1 and the three-section flat seedling S 2 The coordinates of are (x 3 , y 3 ), where,
Figure BDA0004166798170000072

步骤4.2:确定第一五节苗下斜苗W1与第一五节苗上斜苗W2的交点的坐标为(x6,y6),其中,

Figure BDA0004166798170000073
Step 4.2: Determine the coordinates of the intersection point of the downward slanting seedling W 1 of the first fifth section seedling and the upward slanting seedling W 2 of the first fifth section seedling as (x 6 , y 6 ), where,
Figure BDA0004166798170000073

式中,β为第一五节苗下斜苗W1与第一五节苗上斜苗W2的长度比,计算公式如下:In the formula, β is the length ratio of the downward slanting seedling W 1 of the first fifth section seedling to the upper slanting seedling W 2 of the first fifth section seedling, and the calculation formula is as follows:

Figure BDA0004166798170000074
Figure BDA0004166798170000074

随后确定第一五节苗下斜苗W1与竖直面的交点的坐标为(x5,y5),其中,x5=0,

Figure BDA0004166798170000075
Determine subsequently that the coordinates of the intersection point of the inclined seedling W 1 and the vertical plane of the first fifth section seedling are (x 5 , y 5 ), wherein, x 5 =0,
Figure BDA0004166798170000075

再确定第一五节苗上斜苗W2与五节苗平苗W3的交点的坐标为(x8,y8),其中,

Figure BDA0004166798170000081
y8=y3+h;其中,k为第一五节苗上斜苗W2的斜率,
Figure BDA0004166798170000082
h为第一五节苗上斜苗W2与五节苗平苗W3的交点到第一三节苗斜苗S1的垂直距离,h=L/80;Determine again that the coordinates of the intersection of the first five-section seedling on the oblique seedling W 2 and the five-section seedling flat seedling W 3 are (x 8 , y 8 ), wherein,
Figure BDA0004166798170000081
y 8 =y 3 +h; among them, k is the slope of the slope seedling W 2 of the first and fifth seedlings,
Figure BDA0004166798170000082
h is the vertical distance from the intersection point of the first five-section seedling on the inclined seedling W 2 and the fifth-section seedling flat seedling W 3 to the first three-section seedling inclined seedling S1, h=L/80;

通过坐标(x5,y5)和坐标(x6,y6),计算得到第一五节苗下斜苗W1和第二五节苗下斜苗W5的长度P1

Figure BDA0004166798170000083
By coordinates (x 5 , y 5 ) and coordinates (x 6 , y 6 ), the lengths P 1 of the first and fifth section seedlings W 1 and the second fifth section seedlings W 5 are calculated,
Figure BDA0004166798170000083

通过坐标(x6,y6)和坐标(x8,y8),计算得到第一五节苗上斜苗W2和第二五节苗上斜苗W4的长度P2

Figure BDA0004166798170000084
Through the coordinates (x 6 , y 6 ) and coordinates (x 8 , y 8 ), the length P 2 of the upper inclined seedling W 2 of the first fifth section seedling and the upper inclined seedling W 4 of the second fifth section seedling is calculated,
Figure BDA0004166798170000084

计算得到五节苗平苗W3的长度P3,P3=L-2x8Calculate the length P 3 of the five-section seedling flat seedling W 3 , P 3 =L-2x 8 ;

本实施例中,h=368.75mm;θ2为28.8°;β为0.71;x6=6.490m,y6=3.989m;x5=0m,y5=0.421m;x8=12.143m,y8=5.531m;第一五节苗下斜苗W1和第二五节苗下斜苗W5的长度P1为7.406m;第一五节苗上斜苗W2和第二五节苗上斜苗W4的长度P2为5.860m;五节苗平苗W3的长度P3为5.213m。In this embodiment, h=368.75mm; θ 2 is 28.8°; β is 0.71; x 6 =6.490m, y 6 =3.989m; x 5 =0m, y 5 =0.421m; x 8 =12.143m, y 8 = 5.531m; the length P 1 of the first and fifth section seedlings W 1 and the second and fifth section seedlings W 5 is 7.406m; the first and fifth section seedlings W 2 and the second and fifth section The length P 2 of the inclined seedling W 4 is 5.860 m; the length P 3 of the five-section seedling W 3 is 5.213 m.

步骤4.3:所述第一五节苗下斜苗W1和第二五节苗下斜苗W5的截面直径均为D3,所述第一五节苗上斜苗W2和第二五节苗上斜苗W4的截面直径均为D4,所述五节苗平苗W3的截面直径均为D5;设计第一五节苗下斜苗W1和第二五节苗下斜苗W5的截面直径D3不小于9.4P1+217,第一五节苗上斜苗W2和第二五节苗上斜苗W4的截面直径D4不小于11.5P2+183,以及五节苗平苗W3的截面直径D5不小于13.3P3+230。Step 4.3: The section diameters of the first and fifth section seedlings W 1 and the second fifth section seedlings W 5 are both D 3 , and the first and fifth section seedlings W 2 and the second fifth section are both D 3 . The cross-section diameters of the upper inclined seedlings W 4 of the section seedlings are all D 4 , and the cross-sectional diameters of the flat seedlings W 3 of the five-section seedlings are all D 5 ; The cross-sectional diameter D 3 of the oblique seedling W 5 is not less than 9.4P 1 +217, the cross-sectional diameter D 4 of the oblique seedling W 2 of the first and fifth section seedlings and the upper oblique seedling W 4 of the second fifth section seedling is not less than 11.5P 2 +183 , and the cross-sectional diameter D 5 of the five-section seedling flat seedling W 3 is not less than 13.3P 3 +230.

本实施例中,第一五节苗下斜苗W1和第二五节苗下斜苗W5的截面直径D3为286mm,第一五节苗上斜苗W2和第二五节苗上斜苗W4的截面直径D4为250mm;五节苗平苗W3的截面直径D5五节苗平苗W3的截面直径D5为286mm。In the present embodiment, the cross-sectional diameter D 3 of the first and fifth section seedlings W 1 and the second and fifth section seedlings W 5 is 286mm, and the first and fifth section seedlings W 2 and the second and fifth section seedlings are 286mm. The cross-section diameter D 4 of the inclined seedling W 4 is 250 mm; the cross-section diameter D 5 of the five-section flat seedling W 3 is 286 mm.

步骤5:根据步骤3求得的第一三节苗斜苗S1、三节苗平苗S2和第二三节苗斜苗S3的长度、步骤2求得的第一三节苗斜苗S1、三节苗平苗S2和第二三节苗斜苗S3的截面直径以及步骤4求得的第一五节苗下斜苗W1、第一五节苗上斜苗W2、五节苗平苗W3、第二五节苗上斜苗W4、第二五节苗下斜苗W5的长度和截面直径建立主拱结构的有限元模型,计算主拱结构所有杆件的应力及挠度,若主拱结构的部分杆件的应力或挠度超过《木结构设计标准》GB50005-2017所规定的限值时,增大超限杆件的截面直径后再次计算主拱结构所有杆件的应力及挠度,直到主拱结构所有杆件的应力及挠度均小于规范限值。Step 5: According to the lengths of the first three-node oblique seedling S 1 , the three-node flat seedling S 2 and the second three-node oblique seedling S 3 obtained in step 3, and the first three-node oblique seedling obtained in step 2 S 1 , the cross-sectional diameters of the flat seedlings S 2 of the three-section seedlings and the inclined seedlings S 3 of the second and third-section seedlings, and the lower inclined seedlings W 1 of the first and fifth section seedlings, the upper inclined seedlings W 2 of the first and fifth section seedlings obtained in step 4, Establish the finite element model of the main arch structure based on the length and cross-sectional diameter of the five-section flat seedling W 3 , the second-fifth-section up-slope W 4 , and the second-fifth-section down-slope W 5 , and calculate all the members of the main arch structure If the stress or deflection of some members of the main arch structure exceeds the limit specified in the "Standards for Design of Timber Structures" GB50005-2017, increase the cross-sectional diameter of the overrunning members and recalculate all the members of the main arch structure. The stress and deflection of the members until the stress and deflection of all the members of the main arch structure are less than the specification limit.

本实施例中,主拱结构的有限元模型如图6所示,在恒活荷载共同作用下,主拱结构最大应力位于五节苗平苗W3的跨中,为-8.8MPa,小于材料抗弯强度设计值11MPa。最大挠度位于五节苗平苗W3的跨中,挠度比为1/359,小于规范限值1/250。In this embodiment, the finite element model of the main arch structure is shown in Figure 6. Under the joint action of dead and live loads, the maximum stress of the main arch structure is located at the mid-span of Wujie Miaopingmiao W 3 , which is -8.8MPa, which is less than the material The design value of bending strength is 11MPa. The maximum deflection is located in the mid-span of Wujiemiaopingmiao W 3 , and the deflection ratio is 1/359, which is less than the specification limit of 1/250.

实施例2Example 2

参见图7,本发明实施例提供的一种主拱结构的设计装置,包括一个或多个处理器,用于实现上述实施例中的主拱结构的设计方法。Referring to FIG. 7 , an apparatus for designing a main arch structure provided by an embodiment of the present invention includes one or more processors for implementing the method for designing a main arch structure in the above-mentioned embodiments.

本发明主拱结构的设计装置的实施例可以应用在任意具备数据处理能力的设备上,该任意具备数据处理能力的设备可以为诸如计算机等设备或装置。装置实施例可以通过软件实现,也可以通过硬件或者软硬件结合的方式实现。以软件实现为例,作为一个逻辑意义上的装置,是通过其所在任意具备数据处理能力的设备的处理器将非易失性存储器中对应的计算机程序指令读取到内存中运行形成的。从硬件层面而言,如图7所示,为本发明主拱结构的设计装置所在任意具备数据处理能力的设备的一种硬件结构图,除了图7所示的处理器、内存、网络接口、以及非易失性存储器之外,实施例中装置所在的任意具备数据处理能力的设备通常根据该任意具备数据处理能力的设备的实际功能,还可以包括其他硬件,对此不再赘述。The embodiment of the device for designing the main arch structure of the present invention can be applied to any device with data processing capability, and any device with data processing capability can be a device or device such as a computer. The device embodiments can be implemented by software, or by hardware or a combination of software and hardware. Taking software implementation as an example, as a device in a logical sense, it is formed by reading the corresponding computer program instructions in the non-volatile memory into the memory for operation by the processor of any device capable of data processing. From the hardware level, as shown in Figure 7, it is a hardware structure diagram of any device with data processing capability where the design device of the main arch structure of the present invention is located, except for the processor, memory, network interface, In addition to the non-volatile memory, any device with data processing capability where the device in the embodiment is usually based on the actual function of any device with data processing capability may also include other hardware, which will not be repeated here.

上述装置中各个单元的功能和作用的实现过程具体详见上述方法中对应步骤的实现过程,在此不再赘述。For the implementation process of the functions and effects of each unit in the above device, please refer to the implementation process of the corresponding steps in the above method for details, and will not be repeated here.

对于装置实施例而言,由于其基本对应于方法实施例,所以相关之处参见方法实施例的部分说明即可。以上所描述的装置实施例仅仅是示意性的,其中所述作为分离部件说明的单元可以是或者也可以不是物理上分开的,作为单元显示的部件可以是或者也可以不是物理单元,即可以位于一个地方,或者也可以分布到多个网络单元上。可以根据实际的需要选择其中的部分或者全部模块来实现本发明方案的目的。本领域普通技术人员在不付出创造性劳动的情况下,即可以理解并实施。As for the device embodiment, since it basically corresponds to the method embodiment, for related parts, please refer to the part description of the method embodiment. The device embodiments described above are only illustrative, and the units described as separate components may or may not be physically separated, and the components shown as units may or may not be physical units, that is, they may be located in One place, or it can be distributed to multiple network elements. Part or all of the modules can be selected according to actual needs to achieve the purpose of the solution of the present invention. It can be understood and implemented by those skilled in the art without creative effort.

本发明实施例还提供一种计算机可读存储介质,其上存储有程序,该程序被处理器执行时,实现上述实施例中的主拱结构的设计方法。An embodiment of the present invention also provides a computer-readable storage medium, on which a program is stored. When the program is executed by a processor, the method for designing the main arch structure in the above-mentioned embodiments is realized.

所述计算机可读存储介质可以是前述任一实施例所述的任意具备数据处理能力的设备的内部存储单元,例如硬盘或内存。所述计算机可读存储介质也可以是任意具备数据处理能力的设备的外部存储设备,例如所述设备上配备的插接式硬盘、智能存储卡(Smart Media Card,SMC)、SD卡、闪存卡(Flash Card)等。进一步的,所述计算机可读存储介质还可以既包括任意具备数据处理能力的设备的内部存储单元也包括外部存储设备。所述计算机可读存储介质用于存储所述计算机程序以及所述任意具备数据处理能力的设备所需的其他程序和数据,还可以用于暂时地存储已经输出或者将要输出的数据。The computer-readable storage medium may be an internal storage unit of any device capable of data processing described in any of the foregoing embodiments, such as a hard disk or a memory. The computer-readable storage medium may also be an external storage device of any device with data processing capabilities, such as a plug-in hard disk, a smart memory card (Smart Media Card, SMC), an SD card, a flash memory card, etc. (Flash Card) etc. Further, the computer-readable storage medium may also include both an internal storage unit of any device capable of data processing and an external storage device. The computer-readable storage medium is used to store the computer program and other programs and data required by any device capable of data processing, and may also be used to temporarily store data that has been output or will be output.

本领域普通技术人员可以理解,以上所述仅为发明的优选实例而已,并不用于限制发明,尽管参照前述实例对发明进行了详细的说明,对于本领域的技术人员来说,其依然可以对前述各实例记载的技术方案进行修改,或者对其中部分技术特征进行等同替换。凡在发明的精神和原则之内,所做的修改、等同替换等均应包含在发明的保护范围之内。Those of ordinary skill in the art can understand that the above description is only a preferred example of the invention, and is not intended to limit the invention. Although the invention has been described in detail with reference to the foregoing examples, for those skilled in the art, it can still be understood. The technical solutions described in the foregoing examples are modified, or some of the technical features are equivalently replaced. All modifications, equivalent replacements, etc. within the spirit and principles of the invention shall be included in the scope of protection of the invention.

Claims (6)

1.一种主拱结构的设计方法,其特征在于,包括以下步骤:1. a design method of main arch structure, is characterized in that, comprises the following steps: 步骤1:根据交通、景观需求及岸基条件选取合适的桥址,并根据桥址处河流宽度确定主拱结构的净跨L;Step 1: Select a suitable bridge site according to traffic, landscape requirements and shore foundation conditions, and determine the clear span L of the main arch structure according to the width of the river at the bridge site; 所述主拱结构包含三节苗系统和五节苗系统,所述三节苗系统包括第一三节苗斜苗S1、三节苗平苗S2、第二三节苗斜苗S3,其中,第一三节苗斜苗S1、三节苗平苗S2和第二三节苗斜苗S3的长度相同;所述五节苗系统包括第一五节苗下斜苗W1、第一五节苗上斜苗W2、五节苗平苗W3、第二五节苗上斜苗W4、第二五节苗下斜苗W5,其中,第一五节苗下斜苗W1和第二五节苗下斜苗W5的长度相同,第一五节苗上斜苗W2和第二五节苗上斜苗W4的长度相同;The main arch structure includes a three-section seedling system and a five-section seedling system, and the three-section seedling system includes the first three-section seedling inclined seedling S 1 , the three-section seedling flat seedling S 2 , and the second three-section seedling inclined seedling S 3 , wherein, The first three-section seedling inclined seedling S 1 , the three-section seedling flat seedling S 2 and the second three-section seedling inclined seedling S 3 have the same length; the five-section seedling system includes the first five-section seedling downward inclined seedling W 1 , the first Five-section seedlings with upward slope W 2 , five-section seedlings with flat seedlings W 3 , second and fifth-section seedlings with upward slopes W 4 , second-fifth-section seedlings with downward slopes W 5 , among them, first-fifth-section seedlings with downward slopes W 1 and the second and fifth section seedlings have the same length as the lower inclined seedling W 5 , the upper inclined seedling W 2 of the first and fifth section seedlings and the upper inclined seedling W 4 of the second and fifth section seedlings have the same length; 步骤2:设定初值矢跨比f1为0.17,计算第一三节苗斜苗S1、三节苗平苗S2和第二三节苗斜苗S3的长度和截面直径;Step 2: Set the initial rise-to-span ratio f 1 as 0.17, and calculate the length and cross-sectional diameter of the first three-section inclined seedling S 1 , the three-section flat seedling S 2 and the second three-section inclined seedling S 3 ; 步骤3:计算三节苗平苗S2的跨中应力σ与矢跨比f的关系,取三节苗平苗S2的跨中应力最小时对应的矢跨比作为矢跨比f2;使用矢跨比f2重新计算第一三节苗斜苗S1、三节苗平苗S2和第二三节苗斜苗S3的长度;Step 3: Calculate the relationship between the mid-span stress σ of the three-section flat seedling S 2 and the rise-span ratio f, and take the corresponding rise-span ratio when the mid-span stress of the three-section flat seedling S 2 is the smallest as the rise-span ratio f 2 ; Span ratio f 2 recalculates the lengths of the first three-section seedling inclined seedling S 1 , the three-section seedling flat seedling S 2 and the second three-section seedling inclined seedling S 3 ; 步骤4:基于矢跨比f2及净跨L,计算第一五节苗下斜苗W1、第一五节苗上斜苗W2、五节苗平苗W3、第二五节苗上斜苗W4、第二五节苗下斜苗W5的长度和截面直径;Step 4: Based on the rise-to-span ratio f 2 and the clear span L, calculate W 1 for the first and fifth section seedlings, W 2 for the first and fifth section seedlings, W 3 for the fifth section seedlings, and W 3 for the second and fifth section seedlings The length and cross-sectional diameter of the upward inclined seedling W 4 and the second fifth joint seedling downward inclined seedling W 5 ; 步骤5:根据步骤3求得的第一三节苗斜苗S1、三节苗平苗S2和第二三节苗斜苗S3的长度、步骤2求得的第一三节苗斜苗S1、三节苗平苗S2和第二三节苗斜苗S3的截面直径以及步骤4求得的第一五节苗下斜苗W1、第一五节苗上斜苗W2、五节苗平苗W3、第二五节苗上斜苗W4、第二五节苗下斜苗W5的长度和截面直径建立主拱结构的有限元模型,计算主拱结构所有杆件的应力及挠度,若主拱结构的部分杆件的应力或挠度超过《木结构设计标准》GB50005-2017所规定的限值时,增大超限杆件的截面直径后再次计算主拱结构所有杆件的应力及挠度,直到主拱结构所有杆件的应力及挠度均小于规范限值。Step 5: According to the lengths of the first three-node oblique seedling S 1 , the three-node flat seedling S 2 and the second three-node oblique seedling S 3 obtained in step 3, and the first three-node oblique seedling obtained in step 2 S 1 , the cross-sectional diameters of the flat seedlings S 2 of the three-section seedlings and the inclined seedlings S 3 of the second and third-section seedlings, and the lower inclined seedlings W 1 of the first and fifth section seedlings, the upper inclined seedlings W 2 of the first and fifth section seedlings obtained in step 4, Establish the finite element model of the main arch structure based on the length and cross-sectional diameter of the five-section flat seedling W 3 , the second-fifth-section up-slope W 4 , and the second-fifth-section down-slope W 5 , and calculate all the members of the main arch structure If the stress or deflection of some members of the main arch structure exceeds the limit specified in the "Standards for Design of Timber Structures" GB50005-2017, increase the cross-sectional diameter of the overrunning members and recalculate all the members of the main arch structure. The stress and deflection of the members until the stress and deflection of all the members of the main arch structure are less than the specification limit. 2.根据权利要求1所述的一种主拱结构的设计方法,其特征在于,所述步骤2具体包括以下子步骤:2. the design method of a kind of main arch structure according to claim 1, is characterized in that, described step 2 specifically comprises the following sub-steps: 步骤2.1:设定主拱结构的初值矢跨比f1为0.17,利用公式(1)计算得到第一三节苗斜苗S1、三节苗平苗S2和第二三节苗斜苗S3的长度l1Step 2.1: Set the initial rise-span ratio f 1 of the main arch structure to 0.17, and use the formula (1) to calculate the first three-section inclined seedling S 1 , the three-section flat seedling S 2 and the second three-section inclined seedling The length l 1 of S 3 :
Figure FDA0004166798160000021
Figure FDA0004166798160000021
步骤2.2:所述第一三节苗斜苗S1和第二三节苗斜苗S3的截面直径均为D1,所述三节苗平苗S2的截面直径为D2;设计第一三节苗斜苗S1和第二三节苗斜苗S3的截面直径不小于11.4l1+226,以及三节苗平苗S2的截面直径不小于10.8l1+211。Step 2.2: The cross-sectional diameters of the first three-section seedling S1 and the second three-section seedling S3 are both D1 , and the cross-section diameter of the three-section flat seedling S2 is D2 ; design the first The cross-section diameters of the three-section oblique seedling S 1 and the second three-section oblique seedling S 3 are not less than 11.4l 1 +226 , and the cross-section diameter of the three-section flat seedling S 2 is not less than 10.8l 1 +211 .
3.根据权利要求2所述的一种主拱结构的设计方法,其特征在于,所述步骤3具体包括以下子步骤:3. the design method of a kind of main arch structure according to claim 2, is characterized in that, described step 3 specifically comprises the following sub-steps: 步骤3.1:取三节苗系统的左半部作为力法基本体系,通过以下公式计算三节苗平苗S2的跨中应力σ:Step 3.1: Take the left half of the three-section seedling system as the basic system of the force method, and calculate the mid-span stress σ of the three-section seedling flat seedling S 2 by the following formula:
Figure FDA0004166798160000022
Figure FDA0004166798160000022
其中,M为三节苗平苗S2的跨中弯矩,计算公式如下:Among them, M is the mid-span bending moment of the three-section flat seedling S2 , and the calculation formula is as follows:
Figure FDA0004166798160000023
Figure FDA0004166798160000023
其中,系数δ11的计算公式为
Figure FDA0004166798160000024
自由项Δ1P的计算公式为/>
Figure FDA0004166798160000025
Among them, the calculation formula of the coefficient δ11 is
Figure FDA0004166798160000024
The calculation formula of the free term Δ 1P is />
Figure FDA0004166798160000025
其中,l为当矢跨比为f时第一三节苗斜苗S1、三节苗平苗S2和第二三节苗斜苗S3的长度;θ为当矢跨比为f时第一五节苗下斜苗W1与水平面的夹角以及第一三节苗斜苗S1与水平面的夹角;θ=arcsin(H/l),H=f*L,H为主拱结构的矢高;E为弹性模量;I1为第一三节苗斜苗S1和第二三节苗斜苗S3的截面惯性矩,I2为三节苗平苗S2的截面惯性矩;q为均布荷载值;Among them, l is the length of the first three-section oblique seedling S 1 , the three-section flat seedling S 2 and the second three-section oblique seedling S 3 when the rise-span ratio is f; The included angle between the inclined seedling W 1 of the first five-section seedling and the horizontal plane and the angle between the inclined seedling S 1 of the first three-section seedling and the horizontal plane; θ=arcsin(H/l), H=f*L, and H is the main arch structure E is the modulus of elasticity; I 1 is the section moment of inertia of the first three-section inclined seedling S 1 and the second three-section inclined seedling S 3 , and I 2 is the section moment of inertia of the three-section flat seedling S 2 ; q is the uniform load value; 通过第一三节苗斜苗S1的底部与水平面的交点为原点建立力矩平衡方程,推导得三节苗平苗S2的轴力F:The moment balance equation is established by using the intersection point of the bottom of the inclined seedling S 1 of the first three-section seedling and the horizontal plane as the origin, and the axial force F of the three-section flat seedling S 2 is derived:
Figure FDA0004166798160000026
Figure FDA0004166798160000026
式中,F1为三节苗系统的受外荷载,其值为0.135qL,作用位置为三节苗平苗S2左右各1/4位置处;F2为三节苗系统的受外荷载,其值为0.205qL,作用位置为第一三节苗斜苗S1与三节苗平苗S2交点处;In the formula, F 1 is the external load of the three-section seedling system, its value is 0.135qL, and the acting position is the 1/4 position of the three-section seedling flat seedling S 2 ; F 2 is the external load of the three-section seedling system, and its value is 0.205qL, and the action position is at the intersection of the first three-section seedling oblique seedling S 1 and the three-section flat seedling S 2 ; 通过公式(2)-公式(4),得到三节苗平苗S2的跨中应力σ与矢跨比f的关系;Through the formula (2) - formula (4), the relationship between the mid-span stress σ and the rise-span ratio f of the three-section seedling flat seedling S2 is obtained; 步骤3.2:基于步骤3.1确定的三节苗平苗S2的跨中应力σ与矢跨比f的关系,取三节苗平苗S2的跨中应力最小时对应的矢跨比作为矢跨比f2;使用矢跨比f2通过公式(1)重新计算第一三节苗斜苗S1、三节苗平苗S2和第二三节苗斜苗S3的长度,为l2Step 3.2: Based on the relationship between the mid-span stress σ of the three-section flat seedling S 2 determined in step 3.1 and the rise-span ratio f, take the corresponding rise-span ratio when the mid-span stress of the three-section flat seedling S 2 is the smallest as the rise-span ratio f 2 ; recalculate the lengths of the first three-section oblique seedling S 1 , the three-section flat seedling S 2 , and the second three-section oblique seedling S 3 through formula ( 1 ) using the rise-span ratio f 2 , which is l 2 .
4.根据权利要求3所述的一种主拱结构的设计方法,其特征在于,所述步骤4具体包括以下子步骤:4. the design method of a kind of main arch structure according to claim 3, is characterized in that, described step 4 specifically comprises the following sub-steps: 步骤4.1:基于矢跨比f2,求得θ2=arcsin(H2/l2),H2=f2*L;以第一三节苗斜苗S1与水平面的交点为原点,纵桥向为x轴,竖桥向为y轴建立平面坐标系,确定第一三节苗斜苗S1与三节苗平苗S2的交点的坐标为(x3,y3),其中,
Figure FDA0004166798160000031
y3=f2L;
Step 4.1 : Calculate θ 2 =arcsin(H 2 /l 2 ), H 2 =f 2 *L based on the span ratio f 2 The bridge direction is the x axis, and the vertical bridge direction is the y axis to establish a plane coordinate system, and it is determined that the coordinates of the intersection point of the oblique seedling S 1 of the first three-section seedling and the flat seedling S 2 of the three-section seedling are (x 3 , y 3 ), wherein,
Figure FDA0004166798160000031
y 3 =f 2 L;
步骤4.2:确定第一五节苗下斜苗W1与第一五节苗上斜苗W2的交点的坐标为(x6,y6),其中,
Figure FDA0004166798160000032
Step 4.2: Determine the coordinates of the intersection point of the downward slanting seedling W 1 of the first fifth section seedling and the upward slanting seedling W 2 of the first fifth section seedling as (x 6 , y 6 ), where,
Figure FDA0004166798160000032
式中,β为第一五节苗下斜苗W1与第一五节苗上斜苗W2的长度比,计算公式如下:In the formula, β is the length ratio of the downward slanting seedling W 1 of the first fifth section seedling to the upper slanting seedling W 2 of the first fifth section seedling, and the calculation formula is as follows:
Figure FDA0004166798160000033
Figure FDA0004166798160000033
随后确定第一五节苗下斜苗W1与竖直面的交点的坐标为(x5,y5),其中,x5=0,
Figure FDA0004166798160000034
Determine subsequently that the coordinates of the intersection point of the inclined seedling W 1 and the vertical plane of the first fifth section seedling are (x 5 , y 5 ), wherein, x 5 =0,
Figure FDA0004166798160000034
再确定第一五节苗上斜苗W2与五节苗平苗W3的交点的坐标为(x8,y8),其中,
Figure FDA0004166798160000035
y8=y3+h;其中,k为第一五节苗上斜苗W2的斜率,
Figure FDA0004166798160000036
h为第一五节苗上斜苗W2与五节苗平苗W3的交点到第一三节苗斜苗S1的垂直距离,h=L/80;
Determine again that the coordinates of the intersection of the first five-section seedling on the oblique seedling W 2 and the five-section seedling flat seedling W 3 are (x 8 , y 8 ), wherein,
Figure FDA0004166798160000035
y 8 =y 3 +h; among them, k is the slope of the slope seedling W 2 of the first and fifth seedlings,
Figure FDA0004166798160000036
h is the vertical distance from the intersection point of the first five-section seedling on the inclined seedling W 2 and the fifth-section seedling flat seedling W 3 to the first three-section seedling inclined seedling S1, h=L/80;
计算得到第一五节苗下斜苗W1和第二五节苗下斜苗W5的长度P1
Figure FDA0004166798160000037
Calculate the length P 1 of the first and fifth section seedlings with downward slope W 1 and the second fifth section with downward slope W 5 ,
Figure FDA0004166798160000037
计算得到第一五节苗上斜苗W2和第二五节苗上斜苗W4的长度P2
Figure FDA0004166798160000038
Calculate the length P 2 of the slanting seedling W 2 of the first fifth section seedling and the slanting seedling W 4 of the second fifth section seedling,
Figure FDA0004166798160000038
计算得到五节苗平苗W3的长度P3,P3=L-2x8Calculate the length P 3 of the five-section seedling flat seedling W 3 , P 3 =L-2x 8 ; 步骤4.3:所述第一五节苗下斜苗W1和第二五节苗下斜苗W5的截面直径均为D3,所述第一五节苗上斜苗W2和第二五节苗上斜苗W4的截面直径均为D4,所述五节苗平苗W3的截面直径均为D5;设计第一五节苗下斜苗W1和第二五节苗下斜苗W5的截面直径D3不小于9.4P1+217,第一五节苗上斜苗W2和第二五节苗上斜苗W4的截面直径D4不小于11.5P2+183,以及五节苗平苗W3的截面直径D5不小于13.3P3+230。Step 4.3: The section diameters of the first and fifth section seedlings W 1 and the second fifth section seedlings W 5 are both D 3 , and the first and fifth section seedlings W 2 and the second fifth section are both D 3 . The cross-section diameters of the upper inclined seedlings W 4 of the section seedlings are all D 4 , and the cross-sectional diameters of the flat seedlings W 3 of the five-section seedlings are all D 5 ; The cross-sectional diameter D 3 of the oblique seedling W 5 is not less than 9.4P 1 +217, the cross-sectional diameter D 4 of the oblique seedling W 2 of the first and fifth section seedlings and the upper oblique seedling W 4 of the second fifth section seedling is not less than 11.5P 2 +183 , and the cross-sectional diameter D 5 of the five-section seedling flat seedling W 3 is not less than 13.3P 3 +230.
5.一种主拱结构的设计装置,其特征在于,包括一个或多个处理器,用于实现权利要求1-4中任一项所述的主拱结构的设计方法。5. A device for designing a main arch structure, characterized in that it comprises one or more processors for implementing the method for designing a main arch structure according to any one of claims 1-4. 6.一种计算机可读存储介质,其上存储有程序,其特征在于,该程序被处理器执行时,用于实现权利要求1-4中任一项所述的主拱结构的设计方法。6. A computer-readable storage medium with a program stored thereon, characterized in that, when the program is executed by a processor, it is used to realize the design method of the main arch structure according to any one of claims 1-4.
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