CN111740410A - A frequency spatiotemporal dynamic prediction method of power system - Google Patents

A frequency spatiotemporal dynamic prediction method of power system Download PDF

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CN111740410A
CN111740410A CN202010573418.7A CN202010573418A CN111740410A CN 111740410 A CN111740410 A CN 111740410A CN 202010573418 A CN202010573418 A CN 202010573418A CN 111740410 A CN111740410 A CN 111740410A
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power system
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distance
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CN111740410B (en
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易建波
黄琦
井实
张真源
李坚
樊益凤
刘振东
田丰勋
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University of Electronic Science and Technology of China
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    • HELECTRICITY
    • H02GENERATION; CONVERSION OR DISTRIBUTION OF ELECTRIC POWER
    • H02JCIRCUIT ARRANGEMENTS OR SYSTEMS FOR SUPPLYING OR DISTRIBUTING ELECTRIC POWER; SYSTEMS FOR STORING ELECTRIC ENERGY
    • H02J3/00Circuit arrangements for AC mains or AC distribution networks
    • HELECTRICITY
    • H02GENERATION; CONVERSION OR DISTRIBUTION OF ELECTRIC POWER
    • H02JCIRCUIT ARRANGEMENTS OR SYSTEMS FOR SUPPLYING OR DISTRIBUTING ELECTRIC POWER; SYSTEMS FOR STORING ELECTRIC ENERGY
    • H02J2203/00Indexing scheme relating to details of circuit arrangements for AC mains or AC distribution networks
    • H02J2203/10Power transmission or distribution systems management focussing at grid-level, e.g. load flow analysis, node profile computation, meshed network optimisation, active network management or spinning reserve management
    • HELECTRICITY
    • H02GENERATION; CONVERSION OR DISTRIBUTION OF ELECTRIC POWER
    • H02JCIRCUIT ARRANGEMENTS OR SYSTEMS FOR SUPPLYING OR DISTRIBUTING ELECTRIC POWER; SYSTEMS FOR STORING ELECTRIC ENERGY
    • H02J2203/00Indexing scheme relating to details of circuit arrangements for AC mains or AC distribution networks
    • H02J2203/20Simulating, e g planning, reliability check, modelling or computer assisted design [CAD]

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Abstract

The invention discloses a method for dynamically predicting the frequency space-time of an electric power system, which comprises the steps of firstly constructing a distance matrix Z and a path matrix L of the electric power system and assigning initial values, then updating the distance matrix Z and the path matrix L through main row and main column elements of the shortest distance matrix Z, and further finding the shortest electrical distance between any two nodes in the electric power system and the path where the shortest electrical distance is located; on the basis, the coupling factors of the test points at the moment of the lowest frequency value under the same fault point are calculated, so that the sequence of the frequency dynamic reaching of the lowest value of each monitoring point after the power system is disturbed is predicted, the time-space dynamic distribution of the power system frequency is predicted, and the safe and stable operation of the power system is better guaranteed.

Description

一种电力系统频率时空动态预测方法A frequency spatiotemporal dynamic prediction method of power system

技术领域technical field

本发明属于电力技术领域,更为具体地讲,涉及一种电力系统频率时空动态预测方法。The invention belongs to the field of electric power technology, and more particularly, relates to a frequency space-time dynamic prediction method of an electric power system.

背景技术Background technique

随着国民经济的快速发展,用电负荷不断增加,电网规模也逐渐扩大,规模电网的频率特性越来越复杂,频率时空分布特性不容忽视。电力系统在扰动下频率的时空分布特征对电力系统安全稳定监视、系统的运行控制及扰动分析等具有重大意义。当电力系统发生故障时,准确的频率动态不但可以帮助确定风电功率渗透率、调频机组的合理配置、备用容量以及自动发电控制(AGC)参数配置,而且准确的频率动态特征有助于整定低频减载方案,避免频率崩溃事故发生。With the rapid development of the national economy, the power load continues to increase, and the scale of the power grid is gradually expanding. The spatial and temporal distribution characteristics of the frequency of the power system under disturbance are of great significance to the security and stability monitoring of the power system, the operation control of the system and the disturbance analysis. When the power system fails, accurate frequency dynamics can not only help determine the penetration rate of wind power, reasonable configuration of frequency-modulating units, reserve capacity, and automatic generation control (AGC) parameter configuration, but also accurate frequency dynamics can help set low-frequency Loading scheme to avoid frequency crash accidents.

电网动态过程中系统各监测点的频率响应存在时空分布特性。机组的不均匀分布及其惯性的差异是影响频率时空分布的重要因素。由于惯性是电力系统的固有属性,其表现为系统对外来干扰引起能量波动的阻抗作用。所以当电力系统受到扰动时,系统中各个节点惯性的不同导致了各个节点频率的不同,由此频率的时空分布特性呈现。掌握复杂电网的频率分布情况,能够准确预测得到系统中各测点频率最低值时刻到达的先后顺序,就能制定更加精准的切控策略,提高电力系统的安全稳定性。In the dynamic process of the power grid, the frequency response of each monitoring point in the system has a spatiotemporal distribution characteristic. The uneven distribution of units and the difference in their inertia are important factors that affect the spatiotemporal distribution of frequencies. Since inertia is an inherent property of the power system, it is manifested as the impedance effect of the system on energy fluctuations caused by external disturbances. Therefore, when the power system is disturbed, the difference in inertia of each node in the system leads to the difference in the frequency of each node, and the spatiotemporal distribution characteristics of the frequency appear. By mastering the frequency distribution of complex power grids, it is possible to accurately predict the order in which the lowest frequency of each measuring point in the system arrives, and then a more accurate cutting control strategy can be formulated to improve the security and stability of the power system.

发明内容SUMMARY OF THE INVENTION

本发明的目的在于克服现有技术的不足,提供一种电力系统频率时空动态预测方法,通过频率最低值时刻耦合因子预测出电力系统扰动后各监测点频率动态到达最低值的先后顺序,从而预测出电力系统频率时空动态分布,这样更好地保障电力系统安全稳定运行。The purpose of the present invention is to overcome the deficiencies of the prior art, and to provide a power system frequency spatiotemporal dynamic prediction method, which predicts the order in which the frequency of each monitoring point dynamically reaches the minimum value after the power system is disturbed by the coupling factor at the time of the frequency minimum value, thereby predicting The spatial and temporal dynamic distribution of the frequency of the power system is obtained, so as to better ensure the safe and stable operation of the power system.

为实现上述发明目的,本发明一种电力系统频率时空动态预测方法,其特征在于,包括以下步骤:In order to achieve the above object of the invention, a method for dynamic spatiotemporal frequency prediction of a power system according to the present invention is characterized in that it includes the following steps:

(1)、构建电力系统的距离矩阵Z和路径矩阵L;(1), construct the distance matrix Z and the path matrix L of the power system;

构建电力系统的距离矩阵为Z=[zij]n×n,zij表示任意节点i到节点j之间的电气距离,n是电力系统中的节点个数;The distance matrix for constructing the power system is Z=[z ij ] n×n , where z ij represents the electrical distance between any node i and node j, and n is the number of nodes in the power system;

构建路径矩阵L=[lij]n×n,lij表示不相邻节点i到节点j的最短路径上的中间节点;Construct a path matrix L=[l ij ] n×n , where l ij represents the intermediate node on the shortest path from non-adjacent node i to node j;

(2)、给距离矩阵Z和路径矩阵L赋初值;(2), assign initial values to the distance matrix Z and the path matrix L;

距离矩阵Z赋初值为:

Figure BDA0002550460080000021
其中,
Figure BDA0002550460080000022
最短路径矩阵L赋初值为:
Figure BDA0002550460080000023
其中
Figure BDA0002550460080000024
The initial value of the distance matrix Z is:
Figure BDA0002550460080000021
in,
Figure BDA0002550460080000022
The initial value of the shortest path matrix L is:
Figure BDA0002550460080000023
in
Figure BDA0002550460080000024

(3)、标注最短距离矩阵Z的主行主列元素;(3), mark the main row and main column elements of the shortest distance matrix Z;

从最短距离矩阵Z中任意标注一行一列,记为第k行第k列,k∈[1,n],其中第k行第k列元素记为主行元素和主列元素;Arbitrarily mark one row and one column from the shortest distance matrix Z, denoted as the k-th row and the k-th column, k∈[1,n], where the k-th row and the k-th column element are recorded as the main row element and main column element;

(4)、更新距离矩阵Z和路径矩阵L;(4), update the distance matrix Z and the path matrix L;

更新距离矩阵Z:在距离矩阵Z中,从小到大遍历k的所有取值,并在每一个k的取值中,从不在主行和主列的第一个元素开始,依次比较该元素与主行主列中任意两元素之和,如果zik+zkj≥zij,则保持元素zij的值不变;如果zik+zkj<zij,则用zik+zkj替代元素zijUpdate the distance matrix Z: In the distance matrix Z, traverse all the values of k from small to large, and in each value of k, start from the first element that is not in the main row and main column, and compare the elements in turn with The sum of any two elements in the main row and main column, if z ik +z kj ≥z ij , keep the value of element z ij unchanged; if z ik +z kj <z ij , replace the element with z ik +z kj z ij ;

更新距离矩阵L(k)为:The updated distance matrix L (k) is:

Figure BDA0002550460080000025
Figure BDA0002550460080000025

(5)、计算电力系统中任意两节点间的最短电气距离及所在路径;(5) Calculate the shortest electrical distance and path between any two nodes in the power system;

重复步骤(4),当k遍历到n时,得到更新后的距离矩阵Z(n)和路径矩阵L(n);然后令节点i到节点j的最短电气距离

Figure BDA0002550460080000026
所对应的最短电气距离所在路径记为Li-j-min;Repeat step (4), when k traverses to n, get the updated distance matrix Z (n) and path matrix L (n) ; then make the shortest electrical distance from node i to node j
Figure BDA0002550460080000026
The path where the corresponding shortest electrical distance is located is denoted as L ij-min ;

(6)、计算电力系统中每条线路的惯性时间常数;(6) Calculate the inertia time constant of each line in the power system;

(6.1)、在电力系统的网络拓扑中挑选出所有发电机节点,共计记为n1个;标记其中任意一个发电机节点为发电机始端节点,剩余发电机为发电机终端节点;(6.1), select all generator nodes in the network topology of the power system, and denote a total of n 1 ; mark any one of the generator nodes as the generator start node, and the remaining generators as the generator terminal nodes;

(6.2)、结合步骤(5)计算发电机始端节点到每个发电机终端节点的路径,以及其路径上线路li-j上的惯性时间常数;(6.2), in combination with step (5), calculate the path from the generator start node to each generator terminal node, and the inertia time constant on the line l ij on its path;

Figure BDA0002550460080000031
Figure BDA0002550460080000031

Figure BDA0002550460080000032
Figure BDA0002550460080000032

Figure BDA0002550460080000033
Figure BDA0002550460080000033

其中,

Figure BDA0002550460080000034
为第q个发电机始端节点
Figure BDA0002550460080000035
到第p个发电机终端节点
Figure BDA0002550460080000036
间的最短电气距离所在路径上的线路集合,q=1,2,…,n1,p=1,2,…,n1-1;
Figure BDA0002550460080000037
为第q个发电机始端节点分布在线路li-j上的惯性时间常数;zij表示线路li-j的节点i到节点j的电气距离;
Figure BDA0002550460080000038
表示第q个发电机始端节点
Figure BDA0002550460080000039
到第p个发电机终端节点
Figure BDA00025504600800000310
间最短电气距离;
Figure BDA00025504600800000311
表示第q个始端发电机的惯性时间常数;in,
Figure BDA0002550460080000034
is the starting node of the qth generator
Figure BDA0002550460080000035
to the pth generator terminal node
Figure BDA0002550460080000036
The set of lines on the path where the shortest electrical distance between them is, q=1,2,...,n 1 , p=1,2,...,n 1 -1;
Figure BDA0002550460080000037
is the inertia time constant of the qth generator start node distributed on the line l ij ; z ij represents the electrical distance from the node i of the line l ij to the node j;
Figure BDA0002550460080000038
Represents the start node of the qth generator
Figure BDA0002550460080000039
to the pth generator terminal node
Figure BDA00025504600800000310
the shortest electrical distance between
Figure BDA00025504600800000311
Represents the inertia time constant of the qth starting generator;

(6.3)、计算电力系统中每条线路li-j上的惯性时间常数Tli-j(6.3), calculate the inertia time constant T li-j on each line l ij in the power system:

Figure BDA00025504600800000312
Figure BDA00025504600800000312

(7)、计算频率最低值时刻的耦合因子;(7), calculate the coupling factor at the moment of the lowest frequency value;

(7.1)、计算阻抗基准值Zbase与惯性基准值Tbase(7.1), calculate impedance reference value Z base and inertia reference value T base :

Figure BDA00025504600800000313
Figure BDA00025504600800000313

Figure BDA00025504600800000314
Figure BDA00025504600800000314

其中,N为电力系统中线路的条数;Among them, N is the number of lines in the power system;

(7.2)在电力系统的网络拓扑中标记其中任意一个发电机节点为故障节点,剩余为测试节点;(7.2) Mark any one of the generator nodes as faulty nodes in the network topology of the power system, and the rest are test nodes;

(7.3)、标幺化故障节点到每个测试节点间的最短电气距离以及惯性:(7.3), the shortest electrical distance and inertia between the per-unit fault node and each test node:

Figure BDA0002550460080000041
Figure BDA0002550460080000041

Figure BDA0002550460080000042
Figure BDA0002550460080000042

Figure BDA0002550460080000043
Figure BDA0002550460080000043

其中,

Figure BDA0002550460080000044
为故障节点vfault到第λ个测试节点
Figure BDA0002550460080000045
间的最短电气距离,λ=1,2,…,n1-1;
Figure BDA0002550460080000046
为故障节点vfault到第λ个测试节点
Figure BDA0002550460080000047
间的最短电气距离的标幺值;
Figure BDA0002550460080000048
为故障节点vfault到第λ个测试节点
Figure BDA0002550460080000049
间的惯性标幺值;in,
Figure BDA0002550460080000044
For the faulty node v fault to the λth test node
Figure BDA0002550460080000045
The shortest electrical distance between λ=1,2,...,n 1 -1;
Figure BDA0002550460080000046
For the faulty node v fault to the λth test node
Figure BDA0002550460080000047
per unit value of the shortest electrical distance between;
Figure BDA0002550460080000048
For the faulty node v fault to the λth test node
Figure BDA0002550460080000049
The per-unit value of inertia between ;

(7.4)、计算每个测试节点在频率最低值时刻的耦合因子

Figure BDA00025504600800000410
(7.4), calculate the coupling factor of each test node at the moment of the lowest frequency value
Figure BDA00025504600800000410

Figure BDA00025504600800000411
Figure BDA00025504600800000411

(8)、预测电力系统频率时空动态(8) Predict the frequency and space-time dynamics of the power system

将同一故障点下,测试点在频率最低值时刻的耦合因子

Figure BDA00025504600800000412
值越小,则该测试点频率最先到达最低值,因此将所有的
Figure BDA00025504600800000413
按照从小到大的顺序组成序列Td,记为
Figure BDA00025504600800000414
从而预测出电力系统的频率时空动态分布。Under the same fault point, the coupling factor of the test point at the time of the lowest frequency
Figure BDA00025504600800000412
The smaller the value is, the frequency of the test point reaches the lowest value first, so all the
Figure BDA00025504600800000413
According to the sequence T d from small to large, denoted as
Figure BDA00025504600800000414
Thereby, the frequency space-time dynamic distribution of the power system is predicted.

本发明的发明目的是这样实现的:The purpose of the invention of the present invention is achieved in this way:

本发明一种电力系统频率时空动态预测方法,先构建电力系统的距离矩阵Z和路径矩阵L并赋初值,然后通过最短距离矩阵Z的主行主列元素来更新距离矩阵Z和路径矩阵L,进而找到电力系统中任意两节点间的最短电气距离及所在路径;在此基础之上,通过计算同一故障点下各个测试点在频率最低值时刻的耦合因子,从而预测出电力系统扰动后各监测点频率动态到达最低值的先后顺序,进而预测出电力系统频率时空动态分布,这样更好地保障电力系统安全稳定运行。The present invention is a frequency spatiotemporal dynamic prediction method of a power system. First, a distance matrix Z and a path matrix L of the power system are constructed and initial values are assigned, and then the distance matrix Z and the path matrix L are updated through the main row and main column elements of the shortest distance matrix Z. , and then find the shortest electrical distance and path between any two nodes in the power system; on this basis, by calculating the coupling factor of each test point under the same fault point at the time of the lowest frequency value, it is possible to predict the power system after disturbance. The order in which the frequency of the monitoring point dynamically reaches the lowest value, and then the time-space dynamic distribution of the frequency of the power system is predicted, so as to better ensure the safe and stable operation of the power system.

同时,本发明一种电力系统频率时空动态预测方法还具有以下有益效果:At the same time, the method for frequency spatiotemporal dynamic prediction of the power system of the present invention also has the following beneficial effects:

(1)、针对系统惯性的分布提出了一种新的分布方法:将系统中每台发电机的惯性均匀地分布到与系统中其余发电机最短电气距离路径所在线路上,这样的处理有利于模拟实际电网的特性,提高了频率时空动态预测的精度;(1) A new distribution method is proposed for the distribution of the inertia of the system: the inertia of each generator in the system is evenly distributed to the line where the shortest electrical distance from the rest of the generators in the system is located. Such processing is beneficial to Simulate the characteristics of the actual power grid and improve the accuracy of frequency spatiotemporal dynamic prediction;

(2)、系统中扰动的传播是以输电线路为载体的,而在实际电网中两节点间的线路并非地理空间中的直线,因此,本发明以系统中两节点间的电气距离来度量发电机在电力系统中的地理分布,这样能够更加准确预测电力系统频率时刻动态;(2) The propagation of disturbance in the system is carried by the transmission line, and the line between the two nodes in the actual power grid is not a straight line in the geographic space. Therefore, the present invention uses the electrical distance between the two nodes in the system to measure the power generation. Geographical distribution of machines in the power system, which can more accurately predict the dynamic frequency of the power system;

(3)、本发明通过构建频率最低值时刻耦合因子,可以快速预测出电力系统扰动后的频率时空动态。(3) The present invention can quickly predict the frequency space-time dynamics after the disturbance of the power system by constructing the coupling factor at the time of the lowest frequency value.

附图说明Description of drawings

图1是本发明一种电力系统频率时空动态预测方法流程图;Fig. 1 is a flow chart of a power system frequency spatiotemporal dynamic prediction method of the present invention;

图2是IEEE 10机39节点仿真系统图;Fig. 2 is IEEE 10 machine 39 node simulation system diagram;

图3是距离矩阵Z的初值;Figure 3 is the initial value of the distance matrix Z;

图4是更新完成后的距离矩阵Z(n)Fig. 4 is the distance matrix Z (n) after updating is completed;

图5是更新完成后的路径矩阵L(n)Fig. 5 is the path matrix L (n) after the update is completed;

图6是发电机G9切机故障后系统频率时空分布图;Fig. 6 is the time-space distribution diagram of the system frequency after the generator G9 is cut off;

图7是发电机G7切机故障后系统频率时空分布图。Figure 7 is a time-space distribution diagram of the system frequency after the generator G7 is switched off.

具体实施方式Detailed ways

下面结合附图对本发明的具体实施方式进行描述,以便本领域的技术人员更好地理解本发明。需要特别提醒注意的是,在以下的描述中,当已知功能和设计的详细描述也许会淡化本发明的主要内容时,这些描述在这里将被忽略。The specific embodiments of the present invention are described below with reference to the accompanying drawings, so that those skilled in the art can better understand the present invention. It should be noted that, in the following description, when the detailed description of known functions and designs may dilute the main content of the present invention, these descriptions will be omitted here.

实施例Example

在本实施例中,如图1所示,对IEEE 10机39节点电力系统仿真数据为例,故障描述:t=5s时发电机G9因故障切机41%,仿真时间取50s,仿真步长为0.0001s,则电力系统中两监测点之间频率最低值时刻相差0.001秒可视为出现时空分布现象。In this embodiment, as shown in Figure 1, taking the IEEE 10-machine 39-node power system simulation data as an example, the fault description: when t=5s, the generator G9 is cut off by 41% due to the fault, the simulation time is 50s, and the simulation step size is 50s. If it is 0.0001s, then the difference of 0.001s between the two monitoring points in the power system at the time of the lowest frequency can be regarded as the phenomenon of spatiotemporal distribution.

本实施例不计入变压器对动态频率时空分布传播的影响,即在计算两台发电机间的最短电气距离及其所在路径时,不考虑变压器的影响而选择监测节点为发电机经过变压器之后的母线节点29。本实例选取监测节点为39(发电机G1)、19(发电机G4)、23(发电机G7)、25(发电机G8)和2(发电机G10)。This embodiment does not take into account the influence of the transformer on the propagation of the dynamic frequency space-time distribution, that is, when calculating the shortest electrical distance between the two generators and their path, the influence of the transformer is not considered and the monitoring node is selected after the generator passes through the transformer. Bus node 29. In this example, the monitoring nodes are selected as 39 (generator G1), 19 (generator G4), 23 (generator G7), 25 (generator G8) and 2 (generator G10).

下面我们结合图2对本发明一种电力系统频率时空动态预测方法进行详细说明,如图1所示,具体包括以下步骤:Hereinafter, we will describe in detail a method of the present invention for a power system frequency spatiotemporal dynamic prediction method, as shown in Fig. 1, which specifically includes the following steps:

S1、构建电力系统的距离矩阵Z和路径矩阵L;S1. Construct the distance matrix Z and path matrix L of the power system;

构建电力系统的距离矩阵为Z=[zij]n×n,zij表示任意节点i到节点j之间的电气距离,n是电力系统中的节点个数,取值为39;The distance matrix for constructing the power system is Z=[z ij ] n×n , where z ij represents the electrical distance between any node i and node j, and n is the number of nodes in the power system, which is 39;

构建路径矩阵L=[lij]n×n,lij表示不相邻节点i到节点j的最短路径上的中间节点;Construct a path matrix L=[l ij ] n×n , where l ij represents the intermediate node on the shortest path from non-adjacent node i to node j;

S2、给距离矩阵Z和路径矩阵L赋初值;S2, assign initial values to the distance matrix Z and the path matrix L;

距离矩阵Z赋初值为:

Figure BDA0002550460080000061
其中,
Figure BDA0002550460080000062
结合图2,距离矩阵Z的具体赋初值如图3所示,由于矩阵太大,图3中为代码中矩阵的截图,其中,inf代表∞,0.00025+0.0125i代表0.0005+j0.0125;The initial value of the distance matrix Z is:
Figure BDA0002550460080000061
in,
Figure BDA0002550460080000062
Combined with Figure 2, the specific initial value of the distance matrix Z is shown in Figure 3. Since the matrix is too large, Figure 3 is a screenshot of the matrix in the code, where inf represents ∞, 0.00025+0.0125i represents 0.0005+j0.0125;

路径矩阵L赋初值为:

Figure BDA0002550460080000063
其中
Figure BDA0002550460080000064
The initial value of the path matrix L is:
Figure BDA0002550460080000063
in
Figure BDA0002550460080000064

S3、标注最短距离矩阵Z的主行主列元素;S3. Mark the main row and main column elements of the shortest distance matrix Z;

从最短距离矩阵Z中任意标注一行一列,记为第k行第k列,k∈[1,n],其中第k行第k列元素记为主行元素和主列元素;Arbitrarily mark one row and one column from the shortest distance matrix Z, denoted as the k-th row and the k-th column, k∈[1,n], where the k-th row and the k-th column element are recorded as the main row element and main column element;

S4、更新距离矩阵Z和路径矩阵L;S4, update the distance matrix Z and the path matrix L;

更新距离矩阵Z:在距离矩阵Z中,从小到大遍历k的所有取值,并在每一个k的取值中,从不在主行和主列的第一个元素开始,依次比较该元素与主行主列中任意两元素之和,如果zik+zkj≥zij,则保持元素zij的值不变;如果zik+zkj<zij,则用zik+zkj替代元素zijUpdate the distance matrix Z: In the distance matrix Z, traverse all the values of k from small to large, and in each value of k, start from the first element that is not in the main row and main column, and compare the elements in turn with The sum of any two elements in the main row and main column, if z ik +z kj ≥z ij , keep the value of element z ij unchanged; if z ik +z kj <z ij , replace the element with z ik +z kj z ij ;

更新距离矩阵L(k)为:The updated distance matrix L (k) is:

Figure BDA0002550460080000065
Figure BDA0002550460080000065

在本实施例中,标注距离矩阵Z的主行主列元素为第一行第一列开始。In this embodiment, the main row and main column elements of the labeling distance matrix Z start from the first row and the first column.

S5、计算电力系统中任意两节点间的最短电气距离及所在路径;S5. Calculate the shortest electrical distance and the path between any two nodes in the power system;

重复步骤S4,当k遍历到n时,得到更新后的距离矩阵Z(n)如图4所示和路径矩阵L(n)如图5所示;在图4中,矩阵中的0.5代表0.00025+j0.00625、1代表0.0005+j0.0125、2代表0.001+j0.025,以此类推;然后令节点i到节点j的最短电气距离

Figure BDA0002550460080000071
以及节点i到节点j的最短电气距离所在路径记为Li-j-min;Step S4 is repeated, when k traverses to n, the updated distance matrix Z (n) is obtained as shown in Figure 4 and the path matrix L (n) is shown in Figure 5; in Figure 4, 0.5 in the matrix represents 0.00025 +j0.00625, 1 represents 0.0005+j0.0125, 2 represents 0.001+j0.025, and so on; then let the shortest electrical distance from node i to node j
Figure BDA0002550460080000071
And the path where the shortest electrical distance from node i to node j is located is denoted as L ij-min ;

在本实施例中,结合图2和图4,计算出电力系统中发电机G9节点29到测点节点39、19、23、25和2之间的最短电气距离所在路径为:In this embodiment, with reference to FIG. 2 and FIG. 4 , the path of the shortest electrical distance between the generator G9 node 29 and the measuring point nodes 39, 19, 23, 25 and 2 in the power system is calculated as:

L29-39-min={29→26→25→2→1→39};L 29-39-min = {29→26→25→2→1→39};

L29-19-min={29→26→27→17→16→19};L 29-19-min = {29→26→27→17→16→19};

L29-23-min={29→26→27→17→16→24→23};L 29-23-min = {29→26→27→17→16→24→23};

L29-25-min={29→26→25};L 29-25-min = {29→26→25};

L29-2-min={29→26→25→2};)L 29-2-min = {29→26→25→2};)

S6、计算电力系统中惯性的分布;S6. Calculate the distribution of inertia in the power system;

S6.1、以发电机的惯性时间常数来度量惯性,对每一台发电机计算其惯性分布;在电力系统的网络拓扑中挑选出所有发电机节点,共计记为n1个;标记其中任意一个发电机节点为发电机始端节点,剩余发电机为发电机终端节点;S6.1. Use the inertia time constant of the generator to measure the inertia, and calculate its inertia distribution for each generator; select all generator nodes in the network topology of the power system, and record them as n 1 in total; mark any of them One generator node is the generator start node, and the remaining generators are the generator terminal nodes;

S6.2、计算始端节点到每个终端节点的路径及其路径上线路li-j上的惯性时间时间常数;S6.2. Calculate the path from the starting node to each terminal node and the inertial time constant on the line l ij on the path;

Figure BDA0002550460080000072
Figure BDA0002550460080000072

Figure BDA0002550460080000073
Figure BDA0002550460080000073

Figure BDA0002550460080000074
Figure BDA0002550460080000074

例如,计算第9台发电机始端节点29到第1台发电机终端节点39间的线路集合li-jFor example, the line set l ij between the start node 29 of the ninth generator and the terminal node 39 of the first generator is calculated.

L29-39-min{29→26→25→2→1→39}L 29-39-min {29→26→25→2→1→39}

li-j={L29-39-min}={l29-26,l26-25,l25-2,l2-1,l1-39}l ij ={L 29-39-min }={l 29-26 ,l 26-25 ,l 25-2 ,l 2-1 ,l 1-39 }

Figure BDA0002550460080000081
Figure BDA0002550460080000081

计算第9台发电机始端节点29分布在路径集合li-j中所有线路上的惯性时间常数;Calculate the inertia time constant of the ninth generator start-end node 29 distributed on all lines in the path set l ij ;

Figure BDA0002550460080000082
Figure BDA0002550460080000082

S6.3、由上述步骤计算得到系统中所有发电机的惯性分布后,计算电力系统中每条线路li-j上的惯性时间常数Tli-jS6.3. After the inertia distribution of all generators in the system is calculated by the above steps, calculate the inertia time constant T li-j on each line l ij in the power system:

Figure BDA0002550460080000083
Figure BDA0002550460080000083

以线路l29-26为例,Take line l 29-26 as an example,

Figure BDA0002550460080000084
Figure BDA0002550460080000084

在本实施例中,如图1所示,n1=10,计算得到电力系统中每条线路上的惯性分布如表1所示。In this embodiment, as shown in FIG. 1 , n 1 =10, and the inertia distribution on each line in the power system is calculated as shown in Table 1.

表1是电力系统线路惯性分布结果。Table 1 shows the results of the inertia distribution of the power system lines.

线路line 惯性inertia 线路line 惯性inertia 线路line 惯性inertia L<sub>29-26</sub>L<sub>29-26</sub> 18.9918.99 L<sub>1-39</sub>L<sub>1-39</sub> 14.6414.64 L<sub>5-6</sub>L<sub>5-6</sub> 15.215.2 L<sub>26-25</sub>L<sub>26-25</sub> 18.9918.99 L<sub>2-3</sub>L<sub>2-3</sub> 20.120.1 L<sub>26-27</sub>L<sub>26-27</sub> 14.8514.85 L<sub>25-2</sub>L<sub>25-2</sub> 21.4821.48 L<sub>3-4</sub>L<sub>3-4</sub> 8.268.26 L<sub>27-17</sub>L<sub>27-17</sub> 14.8514.85 L<sub>2-1</sub>L<sub>2-1</sub> 14.6414.64 L<sub>1-5</sub>L<sub>1-5</sub> 11.3111.31 L<sub>17-16</sub>L<sub>17-16</sub> 26.726.7 L<sub>16-15</sub>L<sub>16-15</sub> 13.7813.78 L<sub>14-13</sub>L<sub>14-13</sub> 9.579.57 L<sub>16-19</sub>L<sub>16-19</sub> 33.1533.15 L<sub>15-14</sub>L<sub>15-14</sub> 13.7813.78 L<sub>13-10</sub>L<sub>13-10</sub> 9.579.57 L<sub>16-21</sub>L<sub>16-21</sub> 14.9414.94 L<sub>21-22</sub>L<sub>21-22</sub> 14.9414.94 L<sub>16-24</sub>L<sub>16-24</sub> 14.9414.94 L<sub>24-23</sub>L<sub>24-23</sub> 14.9414.94

表1Table 1

S7、计算频率最低值时刻的耦合因子;S7. Calculate the coupling factor at the moment of the lowest frequency value;

S7.1、计算阻抗基准值Zbase与惯性基准值TbaseS7.1. Calculate the impedance reference value Z base and the inertia reference value T base :

Figure BDA0002550460080000091
Figure BDA0002550460080000091

Figure BDA0002550460080000092
Figure BDA0002550460080000092

其中,N为电力系统中线路的条数;在本实施例中,n1=10,N=21,从而计算得到:Zbase=0.0005+j0.0125,Tbase=42;Wherein, N is the number of lines in the power system; in this embodiment, n 1 =10, N = 21, so as to calculate: Z base =0.0005+j0.0125, T base =42;

S7.2、结合图2,发电机节点29为故障节点,39、19、23、25和2为测试节点;S7.2. With reference to Figure 2, the generator node 29 is the faulty node, and 39, 19, 23, 25 and 2 are the test nodes;

S7.3、标幺化故障节点故障点29到测试节点39、19、23、25和2间的最短电气距离以及惯性:S7.3. The shortest electrical distance and inertia between the fault point 29 of the per-unit fault node and the test nodes 39, 19, 23, 25 and 2:

Figure BDA0002550460080000093
Figure BDA0002550460080000093

Figure BDA0002550460080000094
Figure BDA0002550460080000094

Figure BDA0002550460080000095
Figure BDA0002550460080000095

其中,

Figure BDA0002550460080000096
为故障节点vfault到第λ个测试节点
Figure BDA0002550460080000097
间的最短电气距离,λ=1,2,…,5;
Figure BDA0002550460080000098
为故障节点vfault到第λ个测试节点
Figure BDA0002550460080000099
间的最短电气距离的标幺值;
Figure BDA00025504600800000910
表示故障节点vfault到第λ个测试节点
Figure BDA00025504600800000911
间最短电气距离所在路径
Figure BDA00025504600800000912
为故障节点vfault到第λ个测试节点
Figure BDA00025504600800000913
间的惯性标幺值;in,
Figure BDA0002550460080000096
For the faulty node v fault to the λth test node
Figure BDA0002550460080000097
The shortest electrical distance between λ=1,2,…,5;
Figure BDA0002550460080000098
For the faulty node v fault to the λth test node
Figure BDA0002550460080000099
per unit value of the shortest electrical distance between;
Figure BDA00025504600800000910
Represents the faulty node v fault to the λth test node
Figure BDA00025504600800000911
The path where the shortest electrical distance between
Figure BDA00025504600800000912
For the faulty node v fault to the λth test node
Figure BDA00025504600800000913
The per-unit value of inertia between ;

以故障节点29与测试节点39为例,Taking the faulty node 29 and the test node 39 as examples,

Figure BDA00025504600800000914
Figure BDA00025504600800000914

Figure BDA00025504600800000915
Figure BDA00025504600800000915

Figure BDA00025504600800000916
Figure BDA00025504600800000916

在本实施例中,标幺化故障节点29与测试节点39、19、23、25和2间的最短电气距离及惯性结果如表2所示。In this embodiment, the shortest electrical distance and inertia results between the per-unit failure node 29 and the test nodes 39, 19, 23, 25 and 2 are shown in Table 2.

表2是故障点与测点间最短电气距离与惯性标幺值。Table 2 is the shortest electrical distance and inertia per unit value between the fault point and the measuring point.

29-3929-39 28-1928-19 29-2329-23 29-2529-25 29-229-2 Z<sup>*</sup>/puZ<sup>*</sup>/pu 55 55 66 22 33 T<sup>*</sup>/puT<sup>*</sup>/pu 2.11292.1129 2.58432.5843 2.50642.5064 0.90190.9019 1.41571.4157

表2Table 2

S7.4、计算每个测试节点在频率最低值时刻的耦合因子

Figure BDA0002550460080000101
S7.4. Calculate the coupling factor of each test node at the moment of the lowest frequency
Figure BDA0002550460080000101

Figure BDA0002550460080000102
Figure BDA0002550460080000102

在本实施例中,计算得到故障点29到测点39、19、23、25和2间频率最低值耦合因子如表3所示。In this embodiment, the coupling factor of the lowest frequency value between the fault point 29 and the measuring points 39, 19, 23, 25 and 2 is calculated and obtained as shown in Table 3.

表3是故障点到测点间频率最低值耦合因子。Table 3 is the coupling factor of the lowest frequency value between the fault point and the measuring point.

29-3929-39 29-1929-19 29-2329-23 29-2529-25 29-229-2 t<sub>d</sub>t<sub>d</sub> 7.1127.112 7.58437.5843 8.50648.5064 2.90192.9019 4.41574.4157

表3table 3

S8、预测电力系统频率时空动态S8. Predict the frequency and space-time dynamics of the power system

如表3所示,在故障点29下,测试节点39、19、23、25和2在频率最低值时刻的耦合因子由小到大的顺序为25→2→39→19→23,其值越小,则该测试点频率最先到达最低值,因此,各测点频率动态到达最低值的先后顺序为:G8→G10→G1→G4→G7,从而预测出电力系统的频率时空动态。As shown in Table 3, under fault point 29, the coupling factors of test nodes 39, 19, 23, 25 and 2 at the time of the lowest frequency value are in the order of 25→2→39→19→23, and the value of the coupling factor is 25→2→39→19→23 The smaller the value is, the frequency of the test point reaches the lowest value first. Therefore, the order of the frequency dynamic of each test point reaching the lowest value is: G8→G10→G1→G4→G7, so as to predict the frequency space-time dynamics of the power system.

在本实施例中,结合图2,通过PASAP软件进行精细化仿真得到个监测点频率存在明显的时空分布现象,监测点的频率最低值时刻的先后顺序为:G8→G10→G1→G4→G7,与本发明预测得到的顺序一致,仿真结果如图6所示。In this embodiment, combined with Fig. 2, it is obtained that the frequency of monitoring points has obvious spatiotemporal distribution phenomenon through refined simulation with PASAP software. The order of the time of the lowest frequency of monitoring points is: G8→G10→G1→G4→G7 , which is consistent with the sequence predicted by the present invention, and the simulation results are shown in Figure 6.

另外,本实例还提供另外一种故障情况,t=5s时发电机G7节点23因故障损失发电40%,选取监测点为节点39(发电机G1)、节点19(发电机G4)、节点22(发电机G6)和节点29(发电机G9)。根据本发明提供的方法可以得计算到发电机G7到各测点39、19、22和29之间最短电气距离路径为:In addition, this example also provides another fault situation. When t=5s, the generator G7 node 23 loses 40% of power generation due to the fault. The monitoring points are selected as node 39 (generator G1), node 19 (generator G4), and node 22. (generator G6) and node 29 (generator G9). According to the method provided by the present invention, it can be calculated that the shortest electrical distance path between the generator G7 and each measuring point 39, 19, 22 and 29 is:

L23-39-min={23→24→16→17→18→3→2→1→39}L 23-39-min = {23→24→16→17→18→3→2→1→39}

L23-19-min={23→24→16→19}L 23-19-min = {23→24→16→19}

L23-22-min={23→22}L 23-22-min = {23→22}

L23-29-min={23→24→16→17→27→26→29}L 23-29-min = {23→24→16→17→27→26→29}

标幺化故障点23与各测点39、19、22和29间的最短电气距离及其惯性、频率最低值耦合因子结果如表4所示。Table 4 shows the shortest electrical distance between fault point 23 and each measuring point 39, 19, 22 and 29 and the coupling factor results of inertia and frequency minimum value.

表4是故障点与测点间最短电气距离及其惯性、耦合因子标幺值。Table 4 is the shortest electrical distance between the fault point and the measuring point and its inertia and coupling factor per unit value.

23-3923-39 23-1923-19 23-2223-22 23-2923-29 Z<sup>*</sup>/puZ<sup>*</sup>/pu 88 33 11 66 T<sup>*</sup>/puT<sup>*</sup>/pu 3.08673.0867 1.50071.5007 0.22140.2214 2.50642.5064 t<sub>d</sub>t<sub>d</sub> 11.086711.0867 4.50074.5007 1.22141.2214 8.50648.5064

表4Table 4

通过PASAP软件进行精细化仿真,其时域仿真结果如图7所示,其时空分布特性与本发明算法判断出的时空特性一致。The refined simulation is carried out by PASAP software, and the time-domain simulation result is shown in Fig. 7, and its time-space distribution characteristics are consistent with the space-time characteristics determined by the algorithm of the present invention.

尽管上面对本发明说明性的具体实施方式进行了描述,以便于本技术领域的技术人员理解本发明,但应该清楚,本发明不限于具体实施方式的范围,对本技术领域的普通技术人员来讲,只要各种变化在所附的权利要求限定和确定的本发明的精神和范围内,这些变化是显而易见的,一切利用本发明构思的发明创造均在保护之列。Although illustrative specific embodiments of the present invention have been described above to facilitate the understanding of the present invention by those skilled in the art, it should be clear that the present invention is not limited to the scope of the specific embodiments. For those skilled in the art, As long as various changes are within the spirit and scope of the present invention as defined and determined by the appended claims, these changes are obvious, and all inventions and creations utilizing the inventive concept are included in the protection list.

Claims (1)

1. A power system frequency space-time dynamic prediction method is characterized by comprising the following steps:
(1) constructing a distance matrix Z and a path matrix L of the power system;
the distance matrix for constructing the power system is Z ═ Zij]n×n,zijRepresenting the electrical distance between any node i and a node j, wherein n is the number of nodes in the power system;
constructing a path matrix L ═ Lij]n×n,lijRepresenting intermediate nodes on the shortest path from the non-adjacent node i to the node j;
(2) assigning initial values to the distance matrix Z and the path matrix L;
the distance matrix Z has an initial value:
Figure FDA0002550460070000011
wherein,
Figure FDA0002550460070000012
the shortest path matrix L is assigned with an initial value:
Figure FDA0002550460070000013
wherein
Figure FDA0002550460070000014
(3) Marking main row and main column elements of the shortest distance matrix Z;
marking a row and a column from the shortest distance matrix Z at will, marking as the kth row and the kth column, wherein k belongs to [1, n ], and elements of the kth row and the kth column are marked as main row elements and main column elements;
(4) updating the distance matrix Z and the path matrix L;
updating the distance matrix Z: in the distance matrix Z, traversing all values of k from small to large, and in each value of k, starting from the first element which is not in the main row and the main column, sequentially comparing the element with the sum of any two elements in the main row and the main column, if Z isik+zkj≥zijThen element z is maintainedijThe value of (d) is unchanged; if z isik+zkj<zijThen use zik+zkjAlternative element zij
Updating the distance matrix L(k)Comprises the following steps:
Figure FDA0002550460070000015
(5) calculating the shortest electrical distance between any two nodes in the power system and the path where the shortest electrical distance is located;
repeating the step (3), and when k traverses to n, obtaining an updated distance matrix Z(n)Sum path matrix L(n)(ii) a Then let node i to node j have the shortest electrical distance
Figure FDA0002550460070000016
The corresponding shortest electrical distance path is marked as Li-j-min
(6) Calculating an inertia time constant of each line in the power system;
(6.1) selecting all generator nodes in the network topology of the power system, and recording the nodes as n in total1A plurality of; marking any one generator node as a generator starting end node, and marking the rest generators as generator terminal nodes;
(6.2) calculating the path from the starting end node of the generator to the terminal end node of each generator in combination with the step (5) and the line l on the pathi-jAn inertial time constant of (c);
Figure FDA0002550460070000021
Figure FDA0002550460070000022
Figure FDA0002550460070000023
wherein,
Figure FDA0002550460070000024
is the starting end node of the q-th generator
Figure FDA0002550460070000025
To the p-th generator terminal node
Figure FDA0002550460070000026
Q is 1,2, …, n is the line set on the path of the shortest electrical distance between them1,p=1,2,…,n1-1;
Figure FDA0002550460070000027
For the q-th starting generator distributed on line li-jAn inertial time constant of (c); z is a radical ofijRepresents a line li-jThe electrical distance from node i to node j;
Figure FDA0002550460070000028
representing the qth generator start node
Figure FDA0002550460070000029
To the p-th generator terminal node
Figure FDA00025504600700000210
The shortest electrical distance between the two;
Figure FDA00025504600700000211
represents an inertia time constant of the qth start-end generator;
(6.3) calculating each line l in the power systemi-jTime constant of inertia of
Figure FDA00025504600700000212
Figure FDA00025504600700000213
(7) Calculating the coupling factor at the moment of the lowest frequency value;
(7.1) calculating an impedance reference value ZbaseWith a reference value of inertia Tbase
Figure FDA00025504600700000214
Figure FDA00025504600700000215
Wherein N is the number of lines in the power system;
(7.2) marking any one generator node as a fault node and the rest as test nodes in the network topology of the power system;
(7.3) the shortest electrical distance from each per unit fault node to each test node and inertia:
Figure FDA0002550460070000031
Figure FDA0002550460070000032
Figure FDA0002550460070000033
wherein,
Figure FDA0002550460070000034
for failed node vfaultTo the lambda test node
Figure FDA0002550460070000035
The shortest electrical distance between them, λ 1,2, …, n1-1;
Figure FDA0002550460070000036
For failed node vfaultTo the lambda test node
Figure FDA0002550460070000037
Per unit value of the shortest electrical distance therebetween;
Figure FDA0002550460070000038
for failed node vfaultTo the lambda test node
Figure FDA0002550460070000039
The per unit value of inertia between;
(7.4) calculating the coupling factor of each test node at the moment of the lowest frequency value
Figure FDA00025504600700000310
Figure FDA00025504600700000311
(8) Predicting power system frequency space-time dynamics
Coupling factor of test point at the moment of lowest frequency value under the same fault point
Figure FDA00025504600700000312
The smaller the value, the lowest the test point frequency is reached first, so all will be
Figure FDA00025504600700000313
The sequence T is formed from small to largedIs marked as
Figure FDA00025504600700000314
Therefore, the frequency space-time dynamic distribution of the power system is predicted.
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