CN110361632A - A kind of part coupling asynchronous fault distance-finding method of double-circuit line on same pole - Google Patents
A kind of part coupling asynchronous fault distance-finding method of double-circuit line on same pole Download PDFInfo
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- G01R—MEASURING ELECTRIC VARIABLES; MEASURING MAGNETIC VARIABLES
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Abstract
The invention discloses a kind of parts to couple the asynchronous fault distance-finding method of double-circuit line on same pole, it is related to double loop ranging field, the positive sequence of line fault voltage and current is obtained first, negative phase-sequence, zero-sequence component, calculate the end coupling unit common-tower double-circuit lines M, the positive sequence of the voltage and current of N-terminal, negative phase-sequence, zero sequence, then decoupling is carried out to coupling unit double circuits on same tower line impedence and is decomposed into positive sequence impedance, negative sequence impedance, zero sequence impedance, zero sequence impedance is full decoupled at new zero-sequence component, finally utilize double-circuit line on same pole both end voltage and current sequence components, double circuits on same tower line impedence and admittance order components obtain fault localization equation, solution obtains fault distance.The present invention is unrelated with fault type, fault point transition resistance, coupling line lengths in principle, suitable for voltage class difference, conductor material, division number, space length have differences and the asymmetric non-whole double circuits on same tower transmission line of electricity of line parameter circuit value, and do not need both-end and synchronize, ranging is convenient and efficient effectively.
Description
Technical field
The present invention relates to double loop ranging fields, survey more particularly to a kind of asynchronous failure of part coupling double-circuit line on same pole
Away from method.
Background technique
The existing distance measuring method for double loop has very much, can be divided into fault analytical method, traveling wave method by principle, by required
The source of electric information can be divided into single-ended method and both-end method again.Fault analytical method is obtained using the electrical quantities measurement element of line port
The related parameter of voltage and current component and system that takes constructs fault localization equation, is then solved and is had to equation
The fault distance of body.Traveling wave method is exactly that the traveling wave that fault point generates can be along line propagation, and in wave when line failure
It is reflected at impedance discontinuity, the speed of traveling wave is finally combined according to the time that the traveling wave that route both ends measure reaches, so that it may
Accurately determine the position of failure generation.
Previous double circuit lines location algorithm, either single-ended algorithm or two side inputs, are essentially all needle
To whole process with bar route, it is desirable that the both ends of double loop all connect on same bus, and line voltage distribution grade is identical, line parameter circuit value pair
Claim, route whole process parallel lines on same tower.But with the development of technology of transmission of electricity, many various forms of joint uses are continuously emerged,
Wherein more it is typically part coupling power transmission line, including identical voltage class and different voltages grade.Previous failure is surveyed
It will be unable to the double loop for being applied to the coupling of this part and parameter unbalance away from algorithm.
Summary of the invention
To solve the above-mentioned problems, the present invention provides a kind of parts to couple the asynchronous fault localization side of double-circuit line on same pole
Method, specific technical solution are as follows:
A kind of part coupling asynchronous fault distance-finding method of double-circuit line on same pole, comprising the following steps:
Step S1, obtains six phase fault components of route, and six phase fault components include voltage positive-sequence component, voltage negative phase-sequence point
Amount, voltage zero-sequence component and electric current positive-sequence component, electric current negative sequence component, current zero sequence component；
Step S2 calculates the positive sequence voltage at the end coupling portion wire M, negative phase-sequence according to the six phase fault components that step S1 is obtained
Voltage, residual voltage and forward-order current, negative-sequence current, zero-sequence current；
Step S3 calculates the positive sequence voltage of coupling portion wire N-terminal, negative phase-sequence according to the six phase fault components that step S1 is obtained
Voltage, residual voltage and forward-order current, negative-sequence current, zero-sequence current；
The impedance matrix of the end double-circuit line on same pole M, N-terminal is decomposed into positive sequence impedance z using decoupling matrices Q by step S4I1、
zII1, negative sequence impedance zI2、zII2, zero sequence impedance zI0、zII0；
Step S5, the zero sequence impedance z that step S4 is decomposedI0、zII0It is full decoupled to become new zero-sequence component z01、z02；
Step S6, fault localization formula can be obtained by calculating the equal property of fault point voltage according to the end M, N-terminal；
Step S7 is solved to obtain specific fault distance to the fault localization formula that step S6 is obtained.
Further, six phase fault voltages are obtained according to protective device in the step S1Electric currentWherein, i=A, B, C；A, B, C are respectively that three-phase is separate；
According to formulaCalculate line fault voltage positive-sequence component, voltage negative sequence component, voltage
Zero-sequence component, wherein j=0,1,2,A is unit phasor operator,
According to formulaCalculating current positive-sequence component, electric current negative sequence component, current zero sequence component,
Wherein, j=0,1,2,A is unit phasor operator,
Further, in the step S2 positive sequence voltage, negative sequence voltage, residual voltage at the end coupling portion wire M meter
Calculate formula are as follows:Wherein, j=0,1,2, UMIj、UMIIjFor I, II loop line
The route sequence voltage of the end M coupling unit, UmIj、UmIIjThe route sequence voltage at respectively I, the II non-coupled part in the end loop line M, ImIj、
ImIIjThe route sequence electric current at respectively I, the II non-coupled part in the end loop line M, YmIj、YmIIjRespectively I, the II non-coupled portion in the end loop line M
The route sequence admittance divided, ZmIj、ZmIIjThe route sequence impedance at respectively I, the II non-coupled part in the end loop line M；Coupling portion wire M
The calculation formula of the forward-order current at end, negative-sequence current, zero-sequence current are as follows:
Wherein, j=0,1,2, IMIj、IMIIjRespectively I, II
The route sequence electric current of the end loop line M coupling unit.
4, a kind of part according to claim 1 couples the asynchronous fault distance-finding method of double-circuit line on same pole, feature
It is: the calculation formula of the positive sequence voltage of coupling portion wire N-terminal, negative sequence voltage, residual voltage in the step S3 are as follows:
Wherein, j=0,1,2, UNIj、UNIIjFor I, II loop line N
Hold the route sequence voltage of coupling unit, UnIj、UnIIjThe route sequence voltage of respectively I, the II non-coupled part of loop line N-terminal, InIj、
InIIjThe route sequence electric current of respectively I, the II non-coupled part of loop line N-terminal, YnIj、YnIIjRespectively I, the II non-coupled portion of loop line N-terminal
The route sequence admittance divided, ZnIj、ZnIIjThe route sequence impedance of respectively I, the II non-coupled part of loop line N-terminal；Coupling portion wire N
The calculation formula of the forward-order current at end, negative-sequence current, zero-sequence current are as follows:
Wherein, j=0,1,2, INIj、INIIjThe route sequence electric current of respectively I, II loop line N-terminal coupling unit.
5, a kind of part according to claim 1 couples the asynchronous fault distance-finding method of double-circuit line on same pole, feature
It is: in the step S4, according to the relationship of double-circuit line on same pole voltage and current:
It is abbreviated as UABC=ZIABC, wherein zI、zmI
The respectively self-impedance of I loop line and mutual impedance, zII、zmIIThe respectively self-impedance of II loop line and mutual impedance, zpBetween double loop mutually
Sense, Z are double-circuit line on same pole impedance matrix,
Using symmetrical component method byRelease U012=Q-1ZQI012=Z012I012, U012、I012、Z012Point
Not Wei double back line voltage, electric current, the positive sequence of impedance, negative phase-sequence, zero-sequence component, expansion is
Obtain positive sequence impedance zI1、zII1It
Between without coupling, negative sequence impedance zI2、zII2Between without coupling, zero sequence impedance zI0、zII0Between there is coupling, wherein zI1=zI2=zI-
zmI, zII1=zII2=zII-zmII, zI0=zI+2zmI、zII0=zII+2zmII。
Further, the step S5 byRelease U'012=P-1Z012PI'012=Z'012I'012,
In,For zero sequence decoupling matrices, U'012、I'012、Z'012Respectively double back line voltage, electric current, resistance
Anti- positive sequence, negative phase-sequence, 01 sequence, 02 order components, expansion areZero
Sequence impedance zI0、zII0It is decoupled into new zero-sequence component Wherein, The zero sequence impedance z of I loop lineI0=zI+2zmI, II loop line zero sequence
Impedance zII0=zII+2zmII, zI、zmIThe respectively self-impedance of I loop line and mutual impedance, zII、zmIIThe respectively self-impedance of II loop line
And mutual impedance, zpThe mutual inductance between double loop.
Further, the equation of the step S6 are as follows:
|UMk-(IMk-UMkDYk)DZk|=| UNk-[INk-UNk(L-D)Yk](L-D)Zk|, in formula, UMkFor the end M false voltage
Order components, UNkFor N-terminal false voltage order components, IMkFor the end M fault current sequence component, INkFor N-terminal fault current sequence component, D is
Coupling circuit starting point is the distance between to fault point F, YkFor each sequence admittance, ZkFor each sequence impedance of coupling circuit, L is coupling
The total length of route.
Beneficial effects of the present invention
Using parameter unbalance double loop decoupling matrices, it can be adapted for the double loop of more connection types, including identical
Voltage class and different voltages grade；Using the order components after decoupling, according to each sequence voltage spy equal in fault point amplitude
Property, fault localization equation is obtained, the advantages of which not only inherits traditional both-end distance measuring algorithm, but also be suitable for non-
Whole double-circuit line on same pole, it is unrelated with fault type, fault point transition resistance, coupling line lengths in principle, and do not need double
End synchronizes, and has fairly good application prospect.
Detailed description of the invention
Fig. 1 is I, II loop line sequence diagrams of the invention.
Fig. 2 is failure sequence diagrams of the invention.
Wherein, zk: each sequence impedance of coupling circuit；Yk: each sequence admittance；D: coupling circuit starting point is between the F of fault point
Distance；L: the total length of coupling circuit；zMk: the system impedance at the revised end M；zNk: the resistance of the system of the revised end M and N-terminal
It is anti-；Rf: transition resistance；K: kth order components.
Fig. 3 is I1 sequence distance measurement result figure of the invention.
Fig. 4 is I2 sequence distance measurement result figure of the invention.
Fig. 5 is 01 sequence distance measurement result figure of the invention.
Specific embodiment
In order to better understand the present invention, the present invention will be further explained below with reference to the attached drawings and specific examples:
In order to better understand the present invention, the present invention will be further explained below with reference to the attached drawings and specific examples:
For example, the long 100km of coupling circuit, line impedance setting be see the table below；Non-coupled I loop line M side 60km of part, the side N
70km, II loop line M side 80km, the side N 90km, I revolving line voltage grade are 220kV, and II revolving line voltage grade is 500kV, and failure is set
It sets in coupling portion wire distance M side 65kM.
Step S1 obtains six phase fault voltages of routeElectric currentSix phase fault components include voltage
Positive-sequence component, voltage negative sequence component, voltage zero-sequence component and electric current positive-sequence component, electric current negative sequence component, current zero sequence component；Its
In, i=A, B, C；A, B, C are respectively that three-phase is separate；
According to formulaCalculate line fault voltage positive-sequence component, voltage negative sequence component, voltage
Zero-sequence component, wherein j=0,1,2,A is unit phasor operator,
According to formulaCalculating current positive-sequence component, electric current negative sequence component, current zero sequence component,
In, j=0,1,2,A is unit phasor operator,Distinguish from left to right
The I loop line three-phase component and II loop line three-phase component measured for both ends protective device；
Um_ABC=[89.31+j4.60；-70.24-j112.19；-70.23+j110.72；294.14；-145.48-
j253.83；-145.48+j253.83]；
Un_ABC=[70.03+j5.84；-75.79-j112.88；-75.74+j111.04；293.21；-147.72-
j255.86；-147.75+j255.91]；
Im_ABC=[0.128-j1.046；0.044-j0.009；-0.045-j0.009；j0.159；0.120-
j0.047；-0.118-j0.047]；
In_ABC=[0.095-j0.939；0.032-j0.038；-0.034-j0.037；j0.086；0.090-
j0.072；-0.093-j0.070].
Step S2 calculates the positive sequence voltage at the end coupling portion wire M, negative phase-sequence according to the six phase fault components that step S1 is obtained
Voltage, residual voltageWherein j=0,1,2, UMIj、UMIIjIt is I, II
The route sequence voltage of the end loop line M coupling unit, UmIj、UmIIjThe route sequence voltage at respectively I, the II non-coupled part in the end loop line M,
ImIj、ImIIjThe route sequence electric current at respectively I, the II non-coupled part in the end loop line M, YmIj、YmIIjRespectively I, the II non-coupling in the end loop line M
Close the route sequence admittance of part, ZmIj、ZmIIjThe route sequence impedance at respectively I, the II non-coupled part in the end loop line M；
Forward-order current, negative-sequence current, zero-sequence currentWherein,
IMIj、IMIIjThe route sequence electric current of respectively I, II end loop line M coupling unit.
Step S3 calculates the positive sequence voltage of coupling portion wire N-terminal, negative phase-sequence according to the six phase fault components that step S1 is obtained
Voltage, residual voltageWherein, j=0,1,2, UNIj、UNIIjIt is I, II
The route sequence voltage of loop line N-terminal coupling unit, UnIj、UnIIjThe route sequence voltage of respectively I, the II non-coupled part of loop line N-terminal,
InIj、InIIjThe route sequence electric current of respectively I, the II non-coupled part of loop line N-terminal, YnIj、YnIIjRespectively I, the II non-coupling of loop line N-terminal
Close the route sequence admittance of part, ZnIj、ZnIIjThe route sequence impedance of respectively I, the II non-coupled part of loop line N-terminal；
Forward-order current, negative-sequence current, zero-sequence currentWherein,
INIj、INIIjThe route sequence electric current of respectively I, II loop line N-terminal coupling unit；
Be respectively from left to right, after calculating, obtained coupling portion wire both ends I0 sequence, I1 sequence, I2 sequence, II0 sequence,
II1 sequence, II2 sequence voltage and electric current；
UMD_012=[- 44.40+j0.86；110-j1.57；-19.59-j1.49；3.23-j0.54；296.15-
j0.26；0],
UND_012=[- 57.32+j1.45；105.46-j1.79；-24.46-j1.70；-2.85+j0.56；296.93-
j0.23；0],
IMD_012=[0.042-j0.351；0.042-j0.340；0.042-j0.368；j0.021；j0.066；0],
IND_012=[0.031-j0.333；0.031-j0.304；0.031-j0.315；-j0.018；j0.024；0].
The impedance matrix of double-circuit line on same pole is decomposed into positive sequence impedance z using decoupling matrices Q by step S4I1、zII1, negative phase-sequence resistance
Anti- zI2、zII2, zero sequence impedance zI0、zII0；Unit is equal are as follows: Ω/km, according to the relationship of double-circuit line on same pole voltage and current:
It is abbreviated as UABC=ZIABC, wherein zI、zmI
The respectively self-impedance of I loop line and mutual impedance, zII、zmIIThe respectively self-impedance of II loop line and mutual impedance, zpBetween double loop mutually
Sense, Z are double-circuit line on same pole impedance matrix,
Using symmetrical component method byRelease U012=Q-1ZQI012, U012、I012Respectively double loop electricity
Pressure and electric current positive sequence, negative phase-sequence, zero-sequence component, expansion areObtain positive sequence impedance zI1、zII1Between without coupling, bear
Sequence impedance zI2、zII2Between without coupling, zero sequence impedance zI0、zII0Between there is coupling, wherein zI1=zI2=zI-zmI, zII1=zII2
=zII-zmII, zI0=zI+2zmI、zII0=zII+2zmII；
ZI1=zI2=0.03417+j0.37529；ZI2=zII2=0.03478+j0.37519；
Z01=0.58140+j2.02951；Z02=0.03625+j0.45351.
Step S5, the zero sequence impedance z that step S4 is decomposedI0、zII0, utilize zero sequence decoupling matrices
By zero sequence impedance zI0、zII0It is decoupled into new zero-sequence component
Wherein,Ⅰ
The zero sequence impedance z of loop lineI0=zI+2zmI, II loop line zero sequence impedance zII0=zII+2zmII, zI、zmIRespectively I loop line hinders certainly
Anti- and mutual impedance, zII、zmIIThe respectively self-impedance of II loop line and mutual impedance, zpThe mutual inductance between double loop.It is full decoupled to become new
Zero-sequence component z01、z02；
Step S6, utilizes formulaCalculate the end double-circuit line on same pole M false voltage order components, wherein
UMIkFor the end I loop line M false voltage order components, UMIIkFor the end II loop line M false voltage order components,For zero sequence decoupling matrices；UMIj、UMIIjFor the route sequence of I, II end loop line M coupling unit
Voltage,
Utilize formulaCalculate the end double-circuit line on same pole M fault current sequence component, wherein IMIkIt is returned for I
The end line M fault current sequence component, IMIIkFor the end II loop line M fault current sequence component；
Ask N-terminal false voltage and current sequence components method with the end M.
Utilize formulaCalculate double-circuit line on same pole N-terminal false voltage order components, wherein UNIkFor I
Loop line N-terminal false voltage order components, UNIIkFor II loop line N-terminal false voltage order components,
Utilize formulaCalculate double-circuit line on same pole N-terminal fault current sequence component, wherein INIkIt is returned for I
Line N-terminal fault current sequence component, INIIkFor II loop line N-terminal fault current sequence component；
It is from left to right respectively to obtain full decoupled 01 sequence of coupling portion wire both ends after zero sequence decouples, I1 sequence,
I2 sequence, 02 sequence, II1 sequence, II2 sequence voltage and electric current；
UM_012=[- 20.69-j0.50；110-j1.57；-19.59-j1.49；-23.71+j1.36；296.15-
j0.26；0]；
UN_012=[- 30.23+j0.15；105.46-j1.79；-24.46-j1.70；-27.08+j1.30；296.93-
j0.23；0]；
IM_012=[0.026-j 0.165；0.042-j0.340；0.042-j0.368；0.015-j 0.186；
j0.066；0]；
IN_012=[0.020-j 0.176；0.031-j0.304；0.031-j0.315；0.011-j 0.157；
j0.024；0].
According to the equal principle of false voltage on the fault point Tui get of double-circuit line on same pole both ends, double-circuit line on same pole both ends electricity is utilized
Pressure and current sequence components, double circuits on same tower line impedence and admittance order components obtain fault localization equation:
|UMk-(IMk-UMkDYk)DZk|=| UNk-[INk-UNk(L-D)Yk](L-D)Zk|, in formula, UMkFor the end M false voltage
Order components, UNkFor N-terminal false voltage order components, IMkFor the end M fault current sequence component, INkIt is for N-terminal fault current sequence component D
Coupling circuit starting point is the distance between to fault point F, YkFor each sequence admittance of coupling circuit, ZkIt is hindered for each sequence of coupling circuit
Anti-, L is the total length of coupling circuit, length 100km.
Step S7 is solved to obtain specific fault distance to obtained fault localization formula:
Y1 (D)=| UMk-(IMk-UMkDYk)DZk| it is monotonically increasing function,
Y2 (D)=| UNk-[INk-UNk(L-D)Yk](L-D)Zk| be monotonic decreasing function, using matlab draw as Fig. 3,
Shown in Fig. 4, Fig. 5, the joint of two straight lines is fault point；I.e. I1 sequence, I2 sequence, 01 sequence distance measurement result are respectively 65.04km,
64.96km, 64.86km, error 0.06%, -0.06%, 0.21%, meet ranging requirement.
The present invention is not limited to above-described specific embodiment, and the foregoing is merely preferable case study on implementation of the invention
, it is not intended to limit the invention, any modification done within the spirit and principles of the present invention and changes equivalent replacement
Into etc., it should all be included in the protection scope of the present invention.
Claims (7)
1. a kind of part couples the asynchronous fault distance-finding method of double-circuit line on same pole, which comprises the following steps:
Step S1, obtains six phase fault components of route, six phase fault components include voltage positive-sequence component, voltage negative sequence component,
Voltage zero-sequence component and electric current positive-sequence component, electric current negative sequence component, current zero sequence component；
Step S2 calculates the positive sequence voltage at the end coupling portion wire M, negative phase-sequence electricity according to the six phase fault components that step S1 is obtained
Pressure, residual voltage and forward-order current, negative-sequence current, zero-sequence current；
Step S3 calculates the positive sequence voltage of coupling portion wire N-terminal, negative phase-sequence electricity according to the six phase fault components that step S1 is obtained
Pressure, residual voltage and forward-order current, negative-sequence current, zero-sequence current；
The impedance matrix of the end double-circuit line on same pole M, N-terminal is decomposed into positive sequence impedance z using decoupling matrices Q by step S4I1、zII1, it is negative
Sequence impedance zI2、zII2, zero sequence impedance zI0、zII0；
Step S5, the zero sequence impedance z that step S4 is decomposedI0、zII0It is full decoupled to become new zero-sequence component z01、z02；
Step S6, fault localization formula can be obtained by calculating the equal property of fault point voltage according to the end M, N-terminal；
Step S7 is solved to obtain specific fault distance to the fault localization formula that step S6 is obtained.
2. a kind of part according to claim 1 couples the asynchronous fault distance-finding method of double-circuit line on same pole, it is characterised in that:
Six phase fault voltages are obtained in the step S1 according to protective deviceElectric currentWherein, i=A, B, C；A,
B, C is respectively that three-phase is separate；
According to formulaCalculate line fault voltage positive-sequence component, voltage negative sequence component, voltage zero sequence
Component, wherein j=0,1,2,A is unit phasor operator, a=ej120°；
According to formulaCalculating current positive-sequence component, electric current negative sequence component, current zero sequence component, wherein j
=0,1,2,A is unit phasor operator, a=ej120°。
3. a kind of part according to claim 1 couples the asynchronous fault distance-finding method of double-circuit line on same pole, it is characterised in that:
The calculation formula of the positive sequence voltage, negative sequence voltage, residual voltage at the end coupling portion wire M in the step S2 are as follows:Wherein, j=0,1,2, UMIj、UMIIjFor I, II end loop line M coupling part
The route sequence voltage divided, UmIj、UmIIjThe route sequence voltage at respectively I, the II non-coupled part in the end loop line M, ImIj、ImIIjRespectively
I, the route sequence electric current of the II non-coupled part in the end loop line M, YmIj、YmIIjThe route sequence at respectively I, the II non-coupled part in the end loop line M
Admittance, ZmIj、ZmIIjThe route sequence impedance at respectively I, the II non-coupled part in the end loop line M；The positive sequence electricity at the end coupling portion wire M
The calculation formula of stream, negative-sequence current, zero-sequence current are as follows:
Wherein, j=0,1,2, IMIj、IMIIjRespectively I, II loop line M
Hold the route sequence electric current of coupling unit.
4. a kind of part according to claim 1 couples the asynchronous fault distance-finding method of double-circuit line on same pole, it is characterised in that:
The calculation formula of the positive sequence voltage of coupling portion wire N-terminal, negative sequence voltage, residual voltage in the step S3 are as follows:Wherein, j=0,1,2, UNIj、UNIIjFor I, II loop line N-terminal coupling part
The route sequence voltage divided, UnIj、UnIIjThe route sequence voltage of respectively I, the II non-coupled part of loop line N-terminal, InIj、InIIjRespectively
I, the route sequence electric current of the II non-coupled part of loop line N-terminal, YnIj、YnIIjThe route sequence of respectively I, the II non-coupled part of loop line N-terminal
Admittance, ZnIj、ZnIIjThe route sequence impedance of respectively I, the II non-coupled part of loop line N-terminal；The positive sequence electricity of coupling portion wire N-terminal
The calculation formula of stream, negative-sequence current, zero-sequence current are as follows:Wherein, j=0,
1,2, INIj、INIIjThe route sequence electric current of respectively I, II loop line N-terminal coupling unit.
5. a kind of part according to claim 1 couples the asynchronous fault distance-finding method of double-circuit line on same pole, it is characterised in that:
In the step S4, according to the relationship of double-circuit line on same pole voltage and current:
It is abbreviated as UABC=ZIABC, wherein zI、zmIPoint
Not Wei I loop line self-impedance and mutual impedance, zII、zmIIThe respectively self-impedance of II loop line and mutual impedance, zpBetween double loop mutually
Sense, Z are double-circuit line on same pole impedance matrix；
Using symmetrical component method byRelease U012=Q-1ZQI012=Z012I012, U012、I012、Z012Respectively
Double back line voltage, electric current, the positive sequence of impedance, negative phase-sequence, zero-sequence component, expansion areObtain positive sequence impedance zI1、zII1Between without coupling,
Negative sequence impedance zI2、zII2Between without coupling, zero sequence impedance zI0、zII0Between exist coupling, wherein zI1=zI2=zI-zmI, zII1=
zII2=zII-zmII, zI0=zI+2zmI、zII0=zII+2zmII。
6. a kind of part according to claim 1 couples the asynchronous fault distance-finding method of double-circuit line on same pole, it is characterised in that:
The step S5 byRelease U'012=P-1Z012PI'012=Z'012I'012, whereinFor zero sequence decoupling matrices, U'012、I'012、Z'012Respectively double back line voltage, electric current, impedance
Positive sequence, negative phase-sequence, 01 sequence, 02 order components, expansion areZero sequence resistance
Anti- zI0、zII0It is decoupled into new zero-sequence component Wherein, The zero sequence impedance z of I loop lineI0=zI+2zmI, II loop line zero sequence resistance
Anti- zII0=zII+2zmII, zI、zmIThe respectively self-impedance of I loop line and mutual impedance, zII、zmIIRespectively the self-impedance of II loop line and
Mutual impedance, zpThe mutual inductance between double loop.
7. a kind of part according to claim 1 couples the asynchronous fault distance-finding method of double-circuit line on same pole, it is characterised in that:
The equation of the step S6 are as follows:
|UMk-(IMk-UMkDYk)DZk|=| UNk-[INk-UNk(L-D)Yk](L-D)Zk|, in formula, UMkFor the end M false voltage sequence point
Amount, UNkFor N-terminal false voltage order components, IMkFor the end M fault current sequence component, INkFor N-terminal fault current sequence component, D is coupling
Route starting point is the distance between to fault point F, YkFor each sequence admittance, ZkFor each sequence impedance of coupling circuit, L is coupling circuit
Total length.
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