CN109798729A - Refrigerator with hothouse and the method for refrigerator - Google Patents
Refrigerator with hothouse and the method for refrigerator Download PDFInfo
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- CN109798729A CN109798729A CN201711135371.0A CN201711135371A CN109798729A CN 109798729 A CN109798729 A CN 109798729A CN 201711135371 A CN201711135371 A CN 201711135371A CN 109798729 A CN109798729 A CN 109798729A
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- cold source
- source room
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Abstract
The embodiment of the present invention is about a kind of refrigerator and for the method for refrigerator.A method of for refrigerator, the refrigerator includes the channel (4) of cold source room, hothouse (3), connection cold source room and hothouse so that the cold air of cold source room is introduced into hothouse and the Ventilation Control portion (5) in the channel.It includes: detecting whether that the humidity in the presence of the air humidity that can increase cold source room increases factor according to the method for the embodiment of the present invention, and the Ventilation Control portion is controlled based on the testing result.Enter hothouse from cold source room so as to reduce the air of high humility.
Description
[technical field]
Method more particularly to a kind of refrigerator with hothouse the present invention relates to a kind of refrigerator and for refrigerator and
Method for this refrigerator.
[background technique]
In order to store the food (such as dried food and nuts etc.) of suitable low humidity storage ambient, a kind of known method is in refrigerator
The hothouse that humidity is lower than other regions is provided.For example, by introducing low humidity cold air in the warm area from temperature lower than zero degree
And take away it is dry it is indoor compared with humid air so that the humidity of hothouse keeps low-level.
However, it has been found that in the market in the refrigerator with hothouse, dry indoor humidity level can not one
Directly keep desired level.
[summary of the invention]
One of the embodiment of the present invention is designed to provide a kind of improved method for refrigerator, is provided in particular in one kind
Be conducive to the method for refrigerator for making hothouse keep desired low moisture levels.
Another of the embodiment of the present invention is designed to provide a kind of refrigerator for being adapted for carrying out the above method.
The purpose of the present invention can be realized by the feature in corresponding independent claims.The preferred embodiment of the present invention is attached
The theme of figure, specification and dependent claims.
For the one side of the embodiment of the present invention about a kind of method for refrigerator, refrigerator includes cold source room, hothouse, connection
Cold source room and the channel of hothouse the cold air of cold source room is introduced into hothouse and the Ventilation Control portion in channel,
It is characterized in that, which comprises detect whether that the humidity in the presence of the air humidity that can increase cold source room increases factor, Yi Jiji
The Ventilation Control portion is controlled in the testing result.
The embodiment of the present invention whether there is the humidity increase factor that can increase air humidity by detection cold source room and combine
The testing result conveys air to control from cold source room to hothouse, can prevent/reduce the cold source that humidity may be increased
The air of room enters in hothouse, so as to reduce humidity of the air to hothouse for the cold source room that humidity may be increased
It is horizontal and to the influence of dry indoor article is stored at, so that being more advantageous to the dry indoor humidity of holding is in desired
Level is also beneficial to food in the indoor storage of drying, and this is without going through in the air humidity for accurately detecting cold source room
It can be achieved.
Other features that are independent or being considered characteristic of the invention in conjunction with other features will be in following additional right
It is illustrated in it is required that.
In a possible embodiment, detect whether there are humidity increase factor include: judge cold source room door whether
It is in the open state；And/or judge whether reach first time threshold values from when the door closing apart from cold source room；And/or judge cold
Whether the temperature of source chamber is greater than the first threshold temperature；And/or whether cold source room is in defrost program；And/or apart from defrost journey
Sequence has terminated whether reach the second time threshold.By the opening and closing situation of the door with cold source room, the indoor temperature of cold source, and/or
The defrost situation of cold source room is conducive to accurately control Ventilation Control portion to determine whether increasing factor there are humidity.
In a possible embodiment, the humidity increase factor includes: that the door of cold source room is in the open state；With/
Or, the door apart from cold source room has closed not up to first time threshold values；And/or the door of cold source room is closed the temperature of rear cold source room
Degree is greater than the first threshold temperature；And/or cold source room is in defrost program；And/or apart from the defrost EP (end of program) of cold source room when
Between not up to the second time threshold.By reference to one or more humidity increase factor, can be effectively reduced from cold source room to
A possibility that introducing the air of higher levels of humidity in hothouse and influencing the humidity of hothouse and be stored in dry indoor food.
It should be appreciated that " humidity increase factor " described in the embodiment of the present invention not necessarily causes the humidity of cold source room to increase
Add/dramatically increase, however the embodiment of the present invention by detection may cause cold source room humidity increased " humidity increase factor " come
Ventilation Control portion is controlled, a possibility that damp atmosphere of cold source room enters hothouse can be effectively reduced.
In a possible embodiment, if controlling the Ventilation Control based on the testing result includes: detection
Humidity to the air humidity that can increase cold source room increases factor, then does not allow to introduce via channel from cold source room to hothouse cold
Air.It is thus possible to effectively avoid the air for introducing higher levels of humidity in hothouse and influence the air humidity and storage of hothouse
In the indoor food of drying.
In a possible embodiment, the Ventilation Control portion includes the air door to close or open the channel
And/or the fan in the channel, it is described do not allow from cold source room to hothouse conveying cold air include air door close or
It keeps air door to close the channel and/or stopping or keeps fan out of service.
By rationally designing channel, such as when channel is elongated and narrow shape, it may not be necessary to air door be arranged in channel, and only
It is also possible that the ventilation of cold source room and hothouse is controlled by fan.For example, when fan is not run, then cold source room and
It is flowed substantially without air between hothouse.
In a possible embodiment, if controlling the Ventilation Control portion based on the testing result includes: inspection
The humidity for measuring the air humidity that can increase cold source room increases factor, then with reduced output power operation Ventilation Control portion from
Cold source room conveys cold air to hothouse.
In a possible embodiment, the Ventilation Control portion includes the fan in the channel, the reduction
Speed air flow from from cold source room to hothouse conveying cold air includes running fan or out of service with the first output power
Fan, wherein the first output power is lower than the output power of the fan when humidity is not detected and increases factor.The output work of fan
Rate can be controlled for example by the speed of service and/or runing time.When fan out of service, between cold source room and hothouse
Free convection then depend on depending on the design in channel.
In a possible embodiment, it includes that the first humidity increases factor and the increasing of the second humidity that the humidity, which increases factor,
Add factor, if only detecting that the first humidity increases the first humidity in factor and the second humidity increase factor and increases factor, with
Cold air is conveyed to reduced output power operation Ventilation Control portion from cold source room to hothouse, if detecting that the second humidity increases
Adding factor then does not allow to convey cold air from cold source room to hothouse.Increase factor so as to treat different humidity with a certain discrimination,
And Ventilation Control portion can be controlled more flexiblely.
In a possible embodiment, described to detect whether that the humidity in the presence of the air humidity that increase cold source room increases
Factor includes: whether the door of detection cold source room is opened, if the door of cold source room is opened, determines that presence can increase cold source room
Humidity increases factor.When the door of cold source room is opened, the air humidity of cold source room can be significantly greatly increased in the warm heat air outside cold source room,
The door of cold source room is opened and increases factor as humidity, a possibility that damp atmosphere enters hothouse can be effectively reduced.
In a possible embodiment, described to detect whether that the humidity in the presence of the air humidity that increase cold source room increases
Factor includes: to judge be closed whether reached first time threshold values apart from cold source room, if be closed not up to apart from cold source room
First time threshold values then determines to increase factor in the presence of the humidity that can increase cold source room.First time threshold values can between 10 minutes-
Between 60 minutes, it is preferably ranges between -30 minutes 10 minutes.After the door of cold source room is closed, lag a period of time just permits
Perhaps cold air is introduced from cold source room advantageously reduce a possibility that indoor band humid air of cold source enters hothouse.
In a preferred embodiment, first time threshold values can be according to the environment temperature and/or environment where refrigerator
Humidity and adjust.Such as under the environmental condition of high temperature and/or high humidity, first time threshold values can be adjusted to first time,
Under the environmental condition of low temperature and/or low humidity, first time threshold values can be adjusted to the second time, wherein the secondth time is small
In at the first time.
In a possible embodiment, described to detect whether that the humidity in the presence of the air humidity that increase cold source room increases
Factor includes: to detect the temperature of cold source room；Judge whether the temperature of cold source room detected after self cooling source chamber is closed is greater than first
Threshold temperature；If the temperature of cold source room detected is greater than the first threshold temperature, determine that presence can increase the wet of cold source room
Increase factor is spent, wherein first threshold temperature is greater than or equal to the turn-on temperature of the cold source room.This advantageously reduce because
Refrigerator first powers on, long-time is opened the door or defrost causes to convey air from cold source room to hothouse when the increase of cold source indoor humidity
A possibility that.
So-called turn-on temperature refers to when the temperature in cold source room (such as freezing chamber) reaches at or above turn-on temperature, freezes
System should be freezing chamber refrigeration.Turn-on temperature can become according to the set temperature of freezing chamber.
In a possible embodiment, described to detect whether that the humidity in the presence of the air humidity that increase cold source room increases
Factor includes: to judge that self-closing door signal plays whether have reached third time threshold；If not reaching third time threshold, sentence
The fixed humidity in the presence of the air humidity that can increase cold source room increases factor；If reaching third time threshold, judge detected
Whether the temperature of cold source room is greater than second temperature threshold values, if the temperature of cold source room detected is greater than second temperature threshold values,
Determine that the humidity in the presence of the air humidity that can increase cold source room increases factor.That is, the temperature regardless of cold source room,
In third time threshold, do not allow to input cold air from cold source room to hothouse.After third time threshold, then according to cold source
Indoor temperature judges.This can more accurately reduce the indoor humidity air of cold source and enter hothouse.
Preferably, third time threshold can be between -5 minutes 1 minute.
In a possible embodiment, second temperature threshold values can be the turn-on temperature of cold source room.
In a possible embodiment, whether the temperature for judging cold source room detected is greater than second temperature threshold values
In cold source room, the lockup of door reaches third time threshold but do not reach carries out between first time threshold values, with more acurrate
Ground judges to be associated between the temperature and humidity of cold source room.
In a possible embodiment, described to detect whether that the humidity in the presence of the air humidity that increase cold source room increases
Factor includes: to judge whether cold source room is in defrost program；If cold source room is in defrost program, determine that presence can increase
The humidity of cold source room is added to increase factor.It is the situation of evaporator room for cold source room, increases factor for this condition as humidity
It is particularly advantageous to that damp atmosphere is avoided to enter hothouse.In the case of being freezing chamber for cold source room, it is also beneficial to reduce wet
A possibility that air that spending may increase enters hothouse.
In a possible embodiment, described to detect whether that the humidity in the presence of the air humidity that increase cold source room increases
Factor includes: to judge whether the defrost EP (end of program) apart from cold source room has reached the second time threshold；If apart from cold source room
Defrost terminates not up to the second time threshold, then determines to increase factor in the presence of the humidity that can increase cold source room.Second time valve
Value can be preferably ranges between 30 minutes to 60 minutes for example between 15 minutes to 90 minutes.
In a possible embodiment, comprising: judge whether hothouse needs to introduce cold sky from cold source room via channel
Gas；When determining that hothouse needs to introduce cold air from cold source room via channel, and when the humidity is not detected increasing factor, control
Ventilation Control portion processed is to input cold air from cold source room to hothouse.
In a possible embodiment, control Ventilation Control portion includes: to introduce cold air to hothouse from cold source room
It is at least partially opened the valve to open or close channel；And/or operation is located at the fan in channel.
In a possible embodiment, being at least partially opened to the valve for opening or closing channel includes: intermittently
It is at least partially opened channel.
In a possible embodiment, the operation fan includes operation fan at the first time and to close fan with the
Two times were run fan and are run time-interleavedly with first time and closing fan with second.
The embodiment of the present invention is on the other hand about a kind of refrigerator, including cold source room, hothouse, connection cold source room and hothouse
Channel the cold air of cold source room is introduced hothouse and the Ventilation Control portion in channel, the refrigerator is suitable for holding
Method described in one claim of row any of the above.
In a possible embodiment, cold source room is freezing chamber or the evaporator room with evaporator.The evaporator room
It can be used to cool down freezing chamber, refrigerating chamber and/or other storerooms.
Construction and its other goals of the invention and beneficial effect of the invention will be in conjunction with the accompanying drawings to preferred reality
Apply the description of example and more obvious and easy to understand.
[Detailed description of the invention]
As part of the specification and to provide a further understanding of the present invention, the following drawings illustrates of the invention
Specific embodiment, and be used to illustrate principle of the invention together with specification.Wherein,
Fig. 1 is the schematic perspective view of refrigerator in accordance with a preferred embodiment of the present invention；
Fig. 2 is the flow diagram for being used for the method for refrigerator in accordance with a preferred embodiment of the present invention；
Fig. 3-6 is the flow diagram of method of the different embodiments for refrigerator according to the present invention；
Fig. 7 be according to the present invention another preferred embodiment for refrigerator method flow diagram；
[specific embodiment]
The perspective view of the signal of refrigerator 100 is shown in Fig. 1.Refrigerator 1 may include the master with freezing chamber 1 and refrigerating chamber 11
Body 101.Freezing chamber 1 and refrigerating chamber 11 can be closed by door 2,21 respectively.In the present embodiment, freezing chamber 1 and refrigerating chamber 11 be simultaneously
Row's distribution.It should be appreciated that present invention may apply to the refrigerators of different configuration.
Refrigerator 1 includes the hothouse 3 in refrigerating chamber 11.Hothouse 3 can be connected to by channel 4 with freezing chamber 1.Pass through
Dry cold air is inputted into hothouse 3 from freezing chamber 1, and while obtaining dry cold air from freezing chamber 1, hothouse
The higher air of 3 humidity can return to freezing chamber 1 by another channel or be discharged into refrigerating chamber 11.With this, in hothouse 3
Air humidity be lowered and be suitable for refrigeration warm area storage be suitable for low moisture environments article (such as dried food and nuts).In another implementation
In example, hothouse 3 can also be arranged independently of refrigerating chamber 11.
The Ventilation Control portion 5 that control freezing chamber 1 conveys cold air to hothouse 3 can be equipped in channel 4.Ventilation Control portion
5 may include the air door to turn on or off channel 4, thus not needing to convey cold air from freezing chamber 1 to hothouse 3
When, closing passage 4.Ventilation Control portion 5 may include the fan in the channel 4, with whenever necessary will be cold in freezing chamber 1
Air is drawn into hothouse 3.
In the embodiment above, hothouse 3 introduces cold air out of freezing chamber 1.In an alternative embodiment, it is dry
Room 3 can also introduce cold air from other cold source rooms, such as the evaporator room that hothouse 3 can be equipped with evaporator 6 from one obtains
Take dry cold air.The evaporator room can be configured to freezing chamber and/or refrigerating chamber input cold air with by freezing chamber and/
Or refrigerating chamber is cooled to set temperature.As the cold source of hothouse 3, the room (example of dry cold air will be provided to hothouse 3 below
Such as freezing chamber or evaporator room) it is known as cold source room.
The indoor air of cold source controllably transfers to hothouse 3.A kind of method for refrigerator 100 described in detail below is to control
System conveys cold air from cold source room to hothouse 3.
Fig. 2 is the flow diagram for being used for the method for refrigerator 100 in accordance with a preferred embodiment of the present invention.As shown in Fig. 2,
In step s 11, judge whether to need to convey cold air from cold source room to hothouse 3.
In one embodiment, the humidity sensor that refrigerator 100 can be set to detect 3 humidity of hothouse (is not schemed
Show) it determines the need for obtaining dry cold air from cold source room with the air humidity based on the hothouse 3 measured.Another
In a embodiment, it can also determine the need for obtaining dry cold air from cold source room by time setting.For example, can
Periodically to obtain dry cold air from cold source room.
When determining that needs obtain cold air from cold source room in step s 11, according to embodiments of the present invention, in step S12
In, detect whether that the humidity in the presence of the air humidity that can increase cold source room increases factor.
According to embodiments of the present invention, judging whether there is humidity to increase the foundation of factor may include: that the door 2 of cold source room is
It is no in the open state；Whether the time that the door apart from cold source room is closed reaches first time threshold values T1；After cold source room is closed,
Whether the temperature of cold source room is greater than threshold temperature；Whether cold source room is in defrost program；And/or apart from cold source room defrost journey
Whether the time that sequence terminates reaches the second time threshold T2.
Preferred embodiment according to the present invention, meet the following conditions one or more can be considered as there are humidity increase because
Element: the door of cold source room is in the open state；The time that door apart from cold source room is closed is not up to first time threshold values；Cold source room quilt
After closing, the temperature of cold source room is greater than threshold temperature；Cold source room is in defrost program；And/or apart from cold source room defrost program
The time of end is not up to the second time threshold.
Increase factor with the presence or absence of above one or more humidity by detection cold source room, and is controlled based on the testing result
Ventilation Control portion 5 processed.
Increasing factor in humidity includes in cold source room door embodiment in the open state, then detection is in step s 12
It may include: to judge whether the door 2 of cold source room is opened that the humidity that no presence can increase the air humidity of cold source room, which increases factor, such as
Shown in step S310, S31, S41 in Fig. 3-5 Fig. 4.This can by the door sensor that is arranged between door 2 and cold source room 1/
The state of door switch obtains, such as when receiving door sensor/door switch opening signal, judges that the door of cold source room is beaten
It opens.
As shown in step S320, S32, S33 of Fig. 3-Fig. 5, if the door 2 of cold source room is opened, determine that presence can increase
The humidity of cold source room is added to increase factor D.
Using the time closed apart from the door of cold source room whether reach first time threshold values as judge whether humidity increase
In the embodiment of the foundation of one of factor or humidity increase factor, then detect whether in step s 12 in the presence of cold source room can be increased
Air humidity humidity increase factor may include: to judge to be closed whether reached first time threshold values T1 apart from cold source room.
If pent lockup t is not up to the first predetermined time T1 apart from cold source room, determine that presence can increase cold source room
Humidity increases factor DT1.
Wherein, judge cold source room be closed whether reached first time threshold values T1 may include: when by door sensor or
Person's door switch detects to be started when the door 2 of cold source room closes (such as by receiving door sensor/door switch door signal)
Timing, and determine whether timing time t reaches first time threshold values T1, shown in step S330 as shown in Figure 3.In timing time
Before reaching first time threshold values T1, determine to increase factor in the presence of the humidity that can increase cold source room in step S340.At the first time
Threshold values can be preferably ranges between -30 minutes 15 minutes between -60 minutes 10 minutes.When the door of cold source room is closed
Afterwards, lag a period of time, which just allows to advantageously reduce the indoor damp atmosphere of cold source from cold source room introducing cold air, enters drying
A possibility that room.In the embodiment shown in fig. 3, the lockup t for starting timing after self cooling source chamber door is closed reaches first
When time threshold T1, determine that there is no humidity to increase factor DT1.
Using cold source room door be closed after cold source room temperature as judge humidity increase factor or humidity increase factor it
In the embodiment of one foundation, detect whether in step s 12 in the presence of can increase cold source room air humidity humidity increase because
Element includes: the temperature w for detecting cold source room；Judge whether the temperature w of cold source room detected is greater than the first threshold temperature W1；If
The temperature of cold source room detected is greater than the first threshold temperature W1, then determines to increase factor in the presence of the humidity that can increase cold source room
YW, wherein the first threshold temperature W1 is greater than the turn-on temperature of the cold source room.Since the temperature anomaly heating of freezing chamber is logical
Often with opening time is too long, new food is put into, defrost program is associated with, and these situations may cause cold source room humidity increase,
Cold source room is estimated by the temperature anomaly with cold source room, and there are humidity to increase factor YW, it is easy to realize that cold source room high humility is empty
Influence of the gas to hothouse.
In a preferred embodiment, can judge in conjunction with the temperature of the lockup and cold source room that judge cold source room
Increase factor with the presence or absence of the humidity.
For example, in one embodiment, as shown in figure 4, if after determining that cold source room door is closed in step S31,
Judge whether the lockup t from the door signal for receiving cold source room has reached third time threshold in step S33
T3；If the lockup t of cold source room does not reach third time threshold T3, determine in step S34 cold in the presence of that can increase
The humidity of the air humidity of source chamber increases factor DT3；If the lockup t of cold source room reaches third time threshold T3, sentence
Whether the temperature w of cold source room detected of breaking is greater than second temperature threshold values W2.If determining cold source detected in step s 35
The temperature w of room is greater than second temperature threshold values W2, then determines the humidity in the presence of the air humidity that can increase cold source room in step s 35
Increase factor T3W2.If determining that the temperature w of cold source room detected is less than second temperature threshold values W2 in step s 35,
Determine that there is no the humidity for the air humidity that can increase cold source room to increase factor T3W2 in step S36.
Third time threshold T3 can be for example between -5 minutes 1 minute.Second temperature threshold values W2 may, for example, be
The turn-on temperature of cold source room.
For another example, in another embodiment, as shown in figure 5, being judged in step S43 from the shutdown for receiving cold source room
Signal t plays whether have reached first time threshold values T1.If the lockup of cold source room does not reach first time threshold values T1,
Then judge whether the temperature w of cold source room detected is greater than second temperature threshold values W2 in step S45, if cold source detected
The temperature t of room is greater than second temperature threshold values W2, then is judged as that there are humidity to increase factor T2W2 in step S46, if examined
The temperature t of the cold source room of survey is less than second temperature threshold values W2, then determines that there is no the humidity to increase factor T2W2.If in step
The lockup t of cold source room has reached first time threshold values T1 in S43, then determines that there is no the humidity to increase in step S44
Add factor DT1.First time threshold values T1 can between -60 minutes 10 minutes, be preferably ranges between -30 minutes 15 minutes it
Between.
In cold source room to be in the embodiment for increasing one of factor or humidity increase factor as humidity in defrost program,
Detecting whether that the humidity in the presence of the air humidity that can increase cold source room increases factor in step s 12 may include: such as Fig. 6 institute
Show, judges whether cold source room is in defrost program in step S51；If cold source room is in defrost program, in step S52
It is middle to determine to increase factor DF1 in the presence of the humidity that increase cold source room.
In one embodiment, cold source room is not in defrost program, then determines that there is no humidity to increase factor DF1.For
Influence of the defrost program to hothouse is further decreased, it in a preferred embodiment, will be apart from cold source room defrost program
Terminate to be not up to the second time threshold as humidity increase one of factor or humidity increase factor.It detects whether cold in the presence of that can increase
It may include: the defrost EP (end of program) judged in step S53 apart from cold source room that the humidity of the air humidity of source chamber, which increases factor,
Whether second time threshold T2 is had reached；If terminating not up to the second time threshold T2 apart from the defrost of cold source room, in step
Determine to increase factor DF2 in the presence of the humidity that can increase cold source room in rapid S54.If terminating to have reached apart from the defrost of cold source room
Second time threshold T2 then determines that there is no humidity to increase factor DF2 in step S55.
Judging whether the defrost EP (end of program) apart from cold source room has reached the second time threshold T2 may include from defrost
Start timing when EP (end of program), judges whether timing time has reached the second time threshold T2.Reach second in timing time
Before time threshold T, determine to increase factor DF2 in the presence of the humidity that can increase cold source room.
As it appears from the above, in various embodiments, refrigerator can detect whether to exist in step s 12 with next or more
A humidity increases factor:
Humidity increases factor D: the door of cold source room is in the open state；
Humidity increases factor DT1: the door apart from cold source room has closed not up to first time threshold values T1；
Humidity increases factor YW: the temperature of cold source room is greater than the first threshold temperature W1；
Humidity increases factor DT3: being closed not up to third time threshold T3 apart from cold source room；
Humidity increases factor T3W2: apart from cold source room, the pent shut-in time has reached third time threshold T3, but cold source
The temperature of room is higher than second temperature threshold values W2；
Humidity increases factor T1W2: apart from cold source room, the pent shut-in time does not reach first time threshold values T1, but cold source
The temperature of room is lower than second temperature threshold values W2；
Humidity increases factor DF1: cold source room is in defrost program；And
Humidity increases factor DF2: the time apart from the defrost EP (end of program) of cold source room is not up to the second time threshold T2.
When detecting that one or more humidity increase factor in step s 12, it is judged to detecting that humidity increases factor.
When detecting multiple humidity increase factors in step s 12, then in the absence of only all humidity increase factors all,
Just determine that the humidity that the air humidity that can increase cold source room is not detected increases factor in step s 12.
For example, if humidity increases, factor includes " door of cold source room is in the open state ", " cold source room is closed rear cold source
The temperature of room is greater than the first threshold temperature ", then only when the door of cold source room is in close state and the temperature of cold source room is less than the
In the case where one threshold temperature, just it can be determined that as the humidity for the air humidity that can increase cold source room is not detected and increases factor.
For example, if humidity increase factor " door of cold source room is in the open state ", " door apart from cold source room close when
Between not up to first time threshold values ", then only when the door of cold source room is in close state and cold source room has been reached from being closed
To first time threshold values, just can be determined that as the humidity for the air humidity that can increase cold source room is not detected and increases factor.
For another example, if humidity increases, factor includes " door of cold source room is in the open state ", " cold source room is in defrost program
In ", " when cold source room is closed the temperature of cold source room be greater than the first threshold temperature ", then only the door of cold source room is in and closes shape
State just can be determined that in the case that cold source room is not in defrost program, the temperature of cold source room is less than the first threshold temperature as not
Detect that the humidity for the air humidity that can increase cold source room increases factor.
As shown in Fig. 2, next, Ventilation Control portion 5 is controlled based on the testing result of step S12 to control cold source room
It is conveyed to the cold air of hothouse 3.
In the present embodiment, if detect in step s 12 the air humidity that can increase cold source room humidity increase because
Element does not allow then to introduce cold air from cold source room to hothouse 3 via channel 4.If being not detected can increase in step s 12
The humidity of the air humidity of cold source room increases factor, just allows to draw via channel 4 from cold source room to hothouse 3 in step s 13
Enter cold air.
If the humidity that the air humidity that can increase cold source room is not detected in step s 12 increases factor, in step
Cold air is introduced from cold source room to hothouse 3 via channel 4 in S13.Introducing cold air to hothouse 3 from cold source room may include
It is at least partially opened the air door to open or close channel 4；And/or starting is located at the fan in channel 4.
Air door is set in channel 4 without in the embodiment of fan, can according to need the opening by controlling air door
Time and/or open angle and come control from cold source room to hothouse 3 introduce cold air.
Fan is only arranged in channel 4 to be also possible that without air door.In such embodiments it is possible to by reasonable
The ventilation being arranged when channel runs fan not between cold source room and hothouse 3 is very small.It is thus possible to as needed
Cold air is introduced by controlling opening and closing time/speed of service of fan to control from cold source room to hothouse 3.
It is equipped in channel 4 in the embodiment of air door and fan, can according to need the opening time and wind by air door
Fan whether run or the speed of service come control cold source room to hothouse 3 introduce cold air.
Being at least partially opened air door may include intermittently being at least partially opened channel 4.
Starting fan may include starting fan to start fan with first at the first time with closing fan with the second time
Time and closing fan are with the second time-interleaved operation.
As shown in Fig. 2, still detecting whether exist in step S14 when conveying cold air to hothouse 3 from cold source room
The humidity that the air humidity of cold source room can be increased increases factor.Step S14 can be identical as step S12, and therefore not to repeat here.
If the humidity for detecting the presence of the air humidity that can increase cold source room in step S14 increases factor, in step
It controls Ventilation Control portion 5 in rapid S15 and stops conveying cold air from cold source room to hothouse 3.Ventilation Control portion 5 is controlled to stop
Conveying cold air to hothouse 3 from cold source room may include closing passage 4 and/or fan out of service.
Fig. 7 is schematic flow chart of the another embodiment of the present invention for the method for refrigerator.In this embodiment, it closes
In judging whether to need from cold source room to the step S21 of hothouse conveying cold air and about detecting whether in the presence of cold source can be increased
The step S22 that the humidity of the air humidity of room increases factor can embodiment relevant to step S11 and S12 described above respectively
Identical, this will not be repeated here.It is with embodiment difference shown in Fig. 2, cold source room can be increased when detecting in step S22
When the humidity of air humidity increases factor, then ventilation opening control unit 5 is controlled with reduced output power from cold source room to hothouse 3
Convey cold air.
In the present embodiment, when the humidity for detecting the air humidity that can increase cold source room in step S22 increases factor
When, then S24 is entered step, with the fan in the first output power operation Ventilation Control portion 5.If cold source can be increased by not detecting
The humidity of room air humidity increases factor, then enters step S23 with the fan in the second output power operation Ventilation Control portion 5.Its
In, the second output power is greater than the first output power.The output power of fan can pass through the runing time and/or operation of fan
Speed is adjusted.
In another embodiment, control Ventilation Control portion 5 is conveyed with reduced output power from cold source room to hothouse 3
Cold air may include fan out of service.Specifically, if being opened when detecting that humidity increases factor in step S22
Or channel 4 is stayed open, but stop or keep fan out of service；If humidity, which is not detected, in step S22 increases factor,
Then while opening or staying open channel 4, fan is run to improve efficiency of the cold source room to hothouse input cold air.
When the humidity of hothouse 3 reaches preset level or Ventilation Control portion 5 has run the predetermined time, can close
Ventilation Control portion 5 and stop from cold source room to hothouse 3 input cold air.
In an embodiment of the invention, multiple humidity be can detecte and increase factor, and detecting any one humidity
When increase factor, then do not allow to convey cold air from cold source room to hothouse, alternatively, with reduced output power operation ventilation control
Portion processed cold air is conveyed from cold source room to hothouse.It should be appreciated that the present invention should not be first in this, but it can be different
Embodiment.For example, in another embodiment, it can detecte multiple humidity and increase factors (such as the first humidity increases factor
Increase factor with the second humidity), and treat different humidity with a certain discrimination and increase factor.For example, when only detecting the increase of the first humidity
The first humidity in factor and the second humidity increase factor increases factor, and (the first humidity, which increases factor, may, for example, be: apart from cold
The door of source chamber is closed the not up to temperature of first time threshold values and/or cold source room and is higher than threshold temperature) when, allow defeated with first
Power operation Ventilation Control portion 5 out, when detect the second humidity increase factor (the second humidity increase factor may, for example, be cold source
The door of room is opened, and/or, cold source room is in defrost program or apart from when the time that the defrost of cold source room has terminated being not up to second
Between threshold values) when, then do not allow from cold source room to hothouse 3 convey cold air.With this, the detection of factor can be increased based on humidity
As a result Ventilation Control portion 5 is controlled more flexiblely.First humidity increases factor and the second humidity increase factor can be respectively
More than one or two.
First humidity increase factor can include but is not limited to following humidity increase factor any one or it is multiple, the
Two humidity, which increase factor, can include but is not limited to following humidity increase factor other than as the first humidity increase factor
Any one is multiple:
Humidity increases factor D: the door of cold source room is in the open state；
Humidity increases factor DT1: the door apart from cold source room has closed not up to first time threshold values T1；
Humidity increases factor YW: the temperature of cold source room is greater than the first threshold temperature W1；
Humidity increases factor DT3: being closed not up to third time threshold T3 apart from cold source room；
Humidity increases factor T3W2: apart from cold source room, the pent shut-in time has reached third time threshold T3, but cold source
The temperature of room is higher than second temperature threshold values W2；
Humidity increases factor T1W2: apart from cold source room, the pent shut-in time does not reach first time threshold values T1, but cold source
The temperature of room is lower than second temperature threshold values W2；
Humidity increases factor DF1: cold source room is in defrost program；And
Humidity increases factor DF2: the time apart from the defrost EP (end of program) of cold source room is not up to the second time threshold T2.
It can be combined with each other in conjunction with Fig. 1 to Fig. 7 various embodiments illustrated in any given mode, it is of the invention to realize
Advantage.Additionally, this invention is not limited to illustrated embodiments, other means outside shown means can also be used under normal conditions, as long as
These means also can reach identical effect.
Claims (16)
1. a kind of method for refrigerator, the refrigerator includes the logical of cold source room, hothouse (3), connection cold source room and hothouse
The cold air of cold source room is introduced into hothouse and the Ventilation Control portion (5) in the channel, feature exists in road (4)
In, which comprises
Detect whether in the presence of can increase cold source room air humidity humidity increase factor (D, DT1, YW, DT3, T3W2, T1W2,
DF1, DF2), and
The Ventilation Control portion is controlled based on the testing result.
2. the method as described in claim 1, which is characterized in that detect whether that increasing factor there are humidity includes:
Judge whether the door (2) of cold source room is in the open state；And/or
Judge whether reach first time threshold values from when the door apart from cold source room is closed；And/or
Judge whether the temperature of cold source room is greater than the first threshold temperature, the first threshold temperature is higher than the turn-on temperature of cold source room；With/
Or
Judge whether cold source room is in defrost program；And/or
Judge to play whether reach the second time threshold apart from defrost EP (end of program).
3. method according to claim 2, which is characterized in that humidity increases factor and includes:
The door (2) of cold source room is in the open state；And/or
Not up to first time threshold values from when door apart from cold source room is closed；And/or
The temperature of cold source room is greater than the first threshold temperature, and the first threshold temperature is higher than the turn-on temperature of cold source room；And/or
Cold source room is in defrost program；And/or
Not up to the second time threshold is played apart from defrost EP (end of program).
4. the method as described in claim 1, which is characterized in that control the Ventilation Control portion packet based on the testing result
It includes: if detecting that the humidity for the air humidity that can increase cold source room increases factor, not allowing defeated from cold source room to hothouse
Cold air is sent, or, conveying cold air from cold source room to hothouse with reduced output power operation Ventilation Control portion.
5. method as claimed in claim 4, which is characterized in that the Ventilation Control portion includes described logical to close or open
The air door in road and/or the fan in the channel, it is described do not allow from cold source room to hothouse conveying cold air include wind
Door is closed or is kept air door to close the channel and/or stopping or keeps fan out of service.
6. method as claimed in claim 4, which is characterized in that the Ventilation Control portion includes the wind in the channel
Fan, described with reduced output power operation Ventilation Control portion includes running fan or wind out of service with the first output power
Fan, wherein the first output power is lower than the output power of the fan when humidity is not detected and increases factor.
7. method as claimed in claim 4, which is characterized in that the humidity increase factor include the first humidity increase factor and
Second humidity increases factor, if only detecting that the first humidity increases the first humidity in factor and the second humidity increase factor and increases
Add factor, cold air is conveyed from cold source room to hothouse with reduced output power operation Ventilation Control portion, if detected
Second humidity, which increases factor, not to be allowed then to convey cold air from cold source room to hothouse.
8. method according to claim 1 or 2, which is characterized in that described to detect whether in the presence of the air that increase cold source room
The humidity of humidity increases factor
Whether the door of detection cold source room is opened, if the door of cold source room is opened, determines in the presence of the air that can increase cold source room
The humidity of humidity increases factor.
9. the method as described in claim 1,2 or 8, which is characterized in that described to detect whether in the presence of the sky that increase cold source room
The humidity of air humidity degree increases factor
Judge be closed whether reached first time threshold values apart from cold source room, if be closed not up to first apart from cold source room
Between threshold values, then determine in the presence of can increase cold source room humidity increase factor.
10. the method as described in method as described in claim 1,2,8 or 9, which is characterized in that described to detect whether that presence increase
Add the air humidity of cold source room humidity increase factor include:
Detect the temperature of cold source room；
Judge whether the temperature of cold source room detected after self cooling source chamber is closed is greater than the first threshold temperature；
If the temperature of cold source room detected is greater than the first threshold temperature, determine in the presence of the air humidity that can increase cold source room
Humidity increase factor, wherein first threshold temperature be greater than or equal to the cold source room turn-on temperature.
11. the method as described in method as described in claim 1,2,8 or 9, which is characterized in that described to detect whether that presence increase
Add the air humidity of cold source room humidity increase factor include:
Receive the door signal of cold source room door；
Judge third time threshold whether is had reached from receiving door signal；
If not reaching third time threshold, determine that the humidity in the presence of the air humidity that can increase cold source room increases factor；
If reaching third time threshold, judge whether the temperature of cold source room detected is greater than second temperature threshold values；If institute
The temperature of the cold source room of detection is greater than second temperature threshold values, then determines that the humidity in the presence of the air humidity that can increase cold source room increases
Factor.
12. the method as described in method as described in claim 1,2,8,9,10 or 11, which is characterized in that described to detect whether to deposit
Increasing factor in the humidity that can increase the air humidity of cold source room includes:
Judge whether cold source room is in defrost program；
If cold source room is in defrost program, determine that the humidity in the presence of the air humidity that can increase cold source room increases factor.
13. method as claimed in claim 12, which is characterized in that it is described detect whether in the presence of can increase cold source room air it is wet
The humidity of degree increases factor
If cold source room is not in defrost program, when judging whether the defrost EP (end of program) apart from cold source room has reached second
Between threshold values；
If terminating not up to the second time threshold apart from the defrost of cold source room, determine in the presence of the air humidity that can increase cold source room
Humidity increase factor.
14. method as claimed in any of claims 1 to 7 in one of claims characterized by comprising
Judge whether hothouse needs to introduce cold air from cold source room via channel；
When determining that hothouse needs to input cold air from cold source room via channel, and when the humidity is not detected increasing factor,
The Ventilation Control portion is controlled to introduce cold air from cold source room to hothouse.
15. method as claimed in claim 14, which is characterized in that control the Ventilation Control portion from cold source room to hothouse
Introducing cold air includes:
It is at least partially opened the valve to open or close channel；And/or
Operation is located at the fan in channel.
16. a kind of refrigerator, the channel including cold source room, hothouse, connection cold source room and hothouse is with by the cold air of cold source room
It is introduced into hothouse and the Ventilation Control portion in the channel, the refrigerator is adapted for carrying out one claim of any of the above
The method.
Priority Applications (1)
| Application Number | Priority Date | Filing Date | Title |
|---|---|---|---|
| CN201711135371.0A CN109798729A (en) | 2017-11-16 | 2017-11-16 | Refrigerator with hothouse and the method for refrigerator |
Applications Claiming Priority (1)
| Application Number | Priority Date | Filing Date | Title |
|---|---|---|---|
| CN201711135371.0A CN109798729A (en) | 2017-11-16 | 2017-11-16 | Refrigerator with hothouse and the method for refrigerator |
Publications (1)
| Publication Number | Publication Date |
|---|---|
| CN109798729A true CN109798729A (en) | 2019-05-24 |
Family
ID=66555310
Family Applications (1)
| Application Number | Title | Priority Date | Filing Date |
|---|---|---|---|
| CN201711135371.0A Pending CN109798729A (en) | 2017-11-16 | 2017-11-16 | Refrigerator with hothouse and the method for refrigerator |
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Cited By (1)
| Publication number | Priority date | Publication date | Assignee | Title |
|---|---|---|---|---|
| CN110906644A (en) * | 2019-10-09 | 2020-03-24 | 合肥晶弘电器有限公司 | Dry goods storage method for freezing area of refrigerator and refrigerator |
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| CN205383833U (en) * | 2016-03-04 | 2016-07-13 | 合肥美菱股份有限公司 | Direct -cooled refrigerator with drying chamber |
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| JP2009287817A (en) * | 2008-05-28 | 2009-12-10 | Hitachi Appliances Inc | Refrigerator |
| CN106152673A (en) * | 2013-01-31 | 2016-11-23 | 松下电器产业株式会社 | Drying device and the refrigerator possessing this drying device |
| CN105276912A (en) * | 2014-05-30 | 2016-01-27 | 海尔集团技术研发中心 | Control method of drying chamber and refrigerator |
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